2019 Maia Challenger – Doubles
# 2019 Maia Challenger – Doubles

This was the first edition of the tournament.

Andre Begemann and Daniel Masur won the title after defeating Guillermo García López and David Vega Hernández $7–6^{(7–2)},$ 6–4 in the final.

## Seeds

* Romain Arneodo / Nicholas Monroe (first round)
* Tomislav Brkić / Ante Pavić (quarterfinals)
* Luca Margaroli / Andrea Vavassori (first round)
* Scott Clayton / Purav Raja (first round)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | R Arneodo N Monroe | 3 | 7 | [8] | | | | | | | | | | | | |
| | K Drzewiecki S Walków | 6 | 5 | [10] | | K Drzewiecki S Walków | $6^5$ | 7 | [7] | | | | | | | |
| | T Gabashvili P Kotov | 6 | 3 | [10] | | T Gabashvili P Kotov | $7^7$ | 5 | [10] | | | | | | | |
| WC | N Borges F Cabral | 4 | 6 | [4] | | | | | | T Gabashvili P Kotov | 3 | 4 | | | | |
| 4 | S Clayton P Raja | 3 | 2 | | | | | | | G García López D Vega Hernández | 6 | 6 | | | | |
| WC | Gonçalo Falcão P Sousa | 6 | 6 | | WC | G Falcão P Sousa | 1 | 4 | | | | | | | | |
| Alt | A Çelikbilek V Kopřiva | 4 | 2 | | | G García López D Vega Hernández | 6 | 6 | | | | | | | | |
| | G García López D Vega Hernández | 6 | 6 | | | | | | | | | | | G García López D Vega Hernández | $6^2$ | 4 |
| WC | T Cação João Monteiro | $7^7$ | 3 | [10] | | | | | | | | | | A Begemann D Masur | $7^7$ | 6 |
| | T Draganja Z Kolář | $6^4$ | 6 | [3] | WC | T Cação J Monteiro | $6^6$ | 4 | | | | | | | | |
| | S Mukund VS Prashanth | 0 | 6 | [11] | | S Mukund VS Prashanth | $7^8$ | 6 | | | | | | | | |
| 3 | L Margaroli A Vavassori | 6 | 4 | [9] | | | | | | S Mukund VS Prashanth | $7^7$ | 3 | [9] | | | |
| | A Begemann D Masur | 6 | 4 | [10] | | | | | | A Begemann D Masur | $6^3$ | 6 | [11] | | | |
| | S Martos Gornés S Puodziunas | 4 | 6 | [7] | | A Begemann D Masur | $7^7$ | 4 | [10] | | | | | | | |
| | I Nedelko D Yevseyev | 1 | 4 | | 2 | T Brkić A Pavić | $6^4$ | 6 | [7] | | | | | | | |
| 2 | T Brkić A Pavić | 6 | 6 | | | | | | | | | | | | | |
