2011 China Open – Men's doubles
# 2011 China Open – Men's doubles

Bob Bryan and Mike Bryan were the defending champions, but Michaël Llodra and Nenad Zimonjić eliminated them in the semifinals.

Llodra and Zimonjić won the tournament beating Robert Lindstedt and Horia Tecău in the final, $7–6^{(7–2)},$ $7–6^{(7–4)}.$

## Seeds

* Bob Bryan / Mike Bryan (semifinals)
* Max Mirnyi / Daniel Nestor (quarterfinals)
* Michaël Llodra / Nenad Zimonjić (champions)
* Mahesh Bhupathi / Leander Paes (quarterfinals)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Draw

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | B Bryan M Bryan | 6 | 6 | | | | | | | | | | | | | | | |
| | L Dlouhý A Dolgopolov | 2 | 2 | | 1 | B Bryan M Bryan | 6 | 6 | | | | | | | | | | |
| | T Berdych F Mayer | 7 | 6 | | | T Berdych F Mayer | 0 | 3 | | | | | | | | | | |
| | M Fyrstenberg M Matkowski | 5 | 3 | | | | | | | 1 | B Bryan M Bryan | 6 | $6^4$ | [3] | | | | |
| 3 | M Llodra N Zimonjić | 6 | 6 | | | | | | | 3 | M Llodra N Zimonjić | 3 | $7^7$ | [10] | | | | |
| | R de Voest A Fisher | 3 | 3 | | 3 | M Llodra N Zimonjić | 6 | 6 | | | | | | | | | | |
| | M Granollers O Marach | 6 | 2 | [10] | | M Granollers O Marach | 1 | 4 | | | | | | | | | | |
| | S Lipsky R Ram | 4 | 6 | [4] | | | | | | | | | | | 3 | M Llodra N Zimonjić | $7^7$ | $7^7$ |
| | M Čilić I Ljubičić | 6 | 6 | | | | | | | | | | | | | R Lindstedt H Tecău | $6^2$ | $6^4$ |
| | M Knowles J Melzer | 3 | 4 | | | M Čilić I Ljubičić | 6 | 6 | | | | | | | | | | |
| WC | M Gong Z Li | 2 | 6 | [3] | 4 | M Bhupathi L Paes | 2 | 3 | | | | | | | | | | |
| 4 | M Bhupathi L Paes | 6 | 3 | [10] | | | | | | | M Čilić I Ljubičić | 4 | $7^{11}$ | [6] | | | | |
| Alt | N Almagro T Robredo | 3 | 5 | | | | | | | | R Lindstedt H Tecău | 6 | $6^9$ | [10] | | | | |
| | R Lindstedt H Tecău | 6 | 7 | | | R Lindstedt H Tecău | $7^8$ | 2 | [10] | | | | | | | | | |
| | F López F Verdasco | 6 | $6^5$ | [5] | 2 | M Mirnyi D Nestor | $6^6$ | 6 | [6] | | | | | | | | | |
| 2 | M Mirnyi D Nestor | 2 | $7^7$ | [10] | | | | | | | | | | | | | | |
