2021 ATP Finals – Doubles
# 2021 ATP Finals – Doubles

Pierre-Hugues Herbert and Nicolas Mahut defeated Rajeev Ram and Joe Salisbury in the final, 6–4, $7–6^{(7–0)}$ to win the doubles tennis title at the 2021 ATP Finals. It was their second ATP Finals title.

Wesley Koolhof and Nikola Mektić were the reigning champions, but only Mektić qualified this season after playing with Mate Pavić. Mektić and Pavić lost in the semifinals to Ram and Salisbury.

Pavić secured the individual year-end No. 1 ranking after winning two round-robin matches. Salisbury was also in contention for the top ranking.

For the first time since 2007, the top four seeded teams reached the semifinals.

## Seeds

* Nikola Mektić / Mate Pavić (semifinals)
* Rajeev Ram / Joe Salisbury (final)
* Pierre-Hugues Herbert / Nicolas Mahut (champions)
* Marcel Granollers / Horacio Zeballos (semifinals)
* Juan Sebastián Cabal / Robert Farah (round robin)
* Ivan Dodig / Filip Polášek (round robin)
* Jamie Murray / Bruno Soares (round robin)
* Kevin Krawietz / Horia Tecău (round robin)

## Alternates

* Simone Bolelli / Máximo González (Did not play)
* Tim Pütz / Michael Venus (Did not play)

## Draw

### Finals

| Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - |
| 4 | Marcel Granollers Horacio Zeballos | 3 | 4 | | | | | |
| 3 | Pierre-Hugues Herbert Nicolas Mahut | 6 | 6 | | | | | |
| 3 | Pierre-Hugues Herbert Nicolas Mahut | 6 | 6 | | 3 | Pierre-Hugues Herbert Nicolas Mahut | 6 | $7^7$ |
| | | | | | 2 | Rajeev Ram Joe Salisbury | 4 | $6^0$ |
| 2 | Rajeev Ram Joe Salisbury | 4 | $7^7$ | [10] | 2 | Rajeev Ram Joe Salisbury | 4 | $6^0$ |
| 1 | Nikola Mektić Mate Pavić | 6 | $6^3$ | [4] | | | | |

### Green group

| | | Mektić Pavić | Granollers Zeballos | Dodig Polášek | Krawietz Tecău | RR W–L | Set W–L | Game W–L | Standings |
| - | - | - | - | - | - | - | - | - | - |
| 1 | Nikola Mektić Mate Pavić | | 4–6, $6–7^{(4–7)}$ | 6–4, $7–6^{(8–6)}$ | 6–4, 6–4 | 2–1 | 4–2 (67%) | 35–31 (53%) | 2 |
| 4 | Marcel Granollers Horacio Zeballos | 6–4, $7–6^{(7–4)}$ | | 4–6, $7–6^{(12–10)},$ [10–6] | 3–6, $7–6^{(7–1)},$ [6–10] | 2–1 | 5–3 (63%) | 35–35 (50%) | 1 |
| 6 | Ivan Dodig Filip Polášek | 4–6, $6–7^{(6–8)}$ | 6–4, $6–7^{(10–12)},$ [6–10] | | $7–6^{(7–2)},$ 7–5 | 1–2 | 3–4 (43%) | 36–36 (50%) | 3 |
| 8 | Kevin Krawietz Horia Tecău | 4–6, 4–6 | 6–3, $6–7^{(1–7)},$ [10–6] | $6–7^{(2–7)},$ 5–7 | | 1–2 | 2–5 (29%) | 32–36 (47%) | 4 |

### Red group

| | | Ram Salisbury | Herbert Mahut | Cabal Farah | Murray Soares | RR W–L | Set W–L | Game W–L | Standings |
| - | - | - | - | - | - | - | - | - | - |
| 2 | Rajeev Ram Joe Salisbury | | $6–7^{(7–9)},$ 6–0, [13–11] | 7–5, 2–6, [11–9] | 6–1, $7–6^{(7–5)}$ | 3–0 | 6–2 (75%) | 36–25 (59%) | 1 |
| 3 | Pierre-Hugues Herbert Nicolas Mahut | $7–6^{(9–7)},$ 0–6, [11–13] | | $7–6^{(7–1)},$ 6–4 | 6–3, $7–6^{(7–5)}$ | 2–1 | 5–2 (71%) | 33–32 (51%) | 2 |
| 5 | Juan Sebastián Cabal Robert Farah | 5–7, 6–2, [9–11] | $6–7^{(1–7)},$ 4–6 | | 6–2, 6–4 | 1–2 | 3–4 (43%) | 33–29 (53%) | 3 |
| 7 | Jamie Murray Bruno Soares | 1–6, $6–7^{(5–7)}$ | 3–6, $6–7^{(5–7)}$ | 2–6, 4–6 | | 0–3 | 0–6 (0%) | 22–38 (37%) | 4 |

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-teams-ties, head-to-head records; 4. in three-teams-ties, percentage of sets won, then percentage of games won; 5. ATP rankings.

