Challenger de Tianjin 2014 (dobles masculino)
# Challenger de Tianjin 2014 (dobles masculino)

Tianjin Health Industry Park :

| Campeón: | Robin Kern Josselin Ouanna | Robin Kern Josselin Ouanna | Robin Kern Josselin Ouanna | Robin Kern Josselin Ouanna | Robin Kern Josselin Ouanna | Robin Kern Josselin Ouanna | Robin Kern Josselin Ouanna | Robin Kern Josselin Ouanna | Robin Kern Josselin Ouanna |
| - | - | - | - | - | - | - | - | - | - |
| Subcampeón: | Jason Jung Evan King | Jason Jung Evan King | Jason Jung Evan King | Jason Jung Evan King | Jason Jung Evan King | Jason Jung Evan King | Jason Jung Evan King | Jason Jung Evan King | Jason Jung Evan King |
| Resultado: | $6-7^3,$ 7-5, 10-8 | $6-7^3,$ 7-5, 10-8 | $6-7^3,$ 7-5, 10-8 | $6-7^3,$ 7-5, 10-8 | $6-7^3,$ 7-5, 10-8 | $6-7^3,$ 7-5, 10-8 | $6-7^3,$ 7-5, 10-8 | $6-7^3,$ 7-5, 10-8 | $6-7^3,$ 7-5, 10-8 |
| Modalidades |||||||||||
| Individuales | Masculino | | | |
| Dobles | Masculino | |

## Presentación previa

No hay campeones defensores ya que se trata de la primera edición del torneo.

La pareja germano-francesa Robin Kern y Josselin Ouanna ganaron el título, derrotando a los estadounidenses Jason Jung y Evan King en la final, $6–7^3,$ 7–5, [10–8].

## Cabezas de serie

* Jordan Kerr / Fabrice Martin (Semifinales)
* Hiroki Kondo / Lee Hsin-han (Cuartos de final)
* Chen Ti / Lim Yong-kyu (Primera ronda)
* Ryan Agar / Huang Liang-chi (Primera ronda)

## Cuadro

| Primera ronda | Primera ronda | Primera ronda | Primera ronda | Primera ronda | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Semifinales | Semifinales | Semifinales | Semifinales | Semifinales | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | J Kerr F Martin | 6 | 6 | |
| | N Meister J Nedunchezhiyan | 3 | 3 | |
| | N Meister J Nedunchezhiyan | 3 | 3 | | 1 | J Kerr F Martin | 6 | 6 | |
| | | | | | | T Matsui J-s Nam | 2 | 2 | |
| | A Kudryavtsev D Zhyrmont | 3 | 6 | [12] | | T Matsui J-s Nam | 2 | 2 | |
| | T Matsui J-s Nam | 6 | 2 | [14] | | | | | |
| | T Matsui J-s Nam | 6 | 2 | [14] | | | | | | 1 | ' J Kerr F Martin | 3 | 6 | [9] |
| | | | | | | | | | | | R Kern J Ouanna | 6 | 4 | [11] |
| 3 | T Chen Y-k Lim | 5 | 2 | | | | | | | | R Kern J Ouanna | 6 | 4 | [11] |
| | R Kern J Ouanna | 7 | 6 | | | | | | | | | | | |
| | R Kern J Ouanna | 7 | 6 | | | R Kern J Ouanna | 6 | 6 | | | | | | |
| | | | | | | N Kadchapanan D Udomchoke | 3 | 3 | | | | | | |
| | N Kadchapanan D Udomchoke | 6 | 6 | | | N Kadchapanan D Udomchoke | 3 | 3 | | | | | | |
| WC | Ning Yuqing Ouyang Bowen | 1 | 2 | | | | | | | | | | | |
| WC | Ning Yuqing Ouyang Bowen | 1 | 2 | | | | | | | | | | | | R Kern J Ouanna | $6^3$ | 7 | 10 |
| | | | | | | | | | | | | | | | J Jung E King | 7 | 5 | 8 |
| WC | Y Bai D Wu | 6 | 7 | | | | | | | | | | | | J Jung E King | 7 | 5 | 8 |
| WC | Gao Xin Wang Chuhan | 1 | 5 | | | | | | | | | | | |
| WC | Gao Xin Wang Chuhan | 1 | 5 | | WC | Y Bai D Wu | $6^5$ | 6 | [5] | | | | | |
| | | | | | | M Gong Z Li | $7^7$ | 3 | [10] | | | | | |
| | M Gong Z Li | 3 | $7^7$ | [10] | | M Gong Z Li | $7^7$ | 3 | [10] | | | | | |
| 4 | R Agar L-c Huang | 6 | $6^4$ | [7] | | | | | | | | | | |
| 4 | R Agar L-c Huang | 6 | $6^4$ | [7] | | | | | | | M Gong Z Li | $6^1$ | 6 | [5] |
| | | | | | | | | | | | J Jung E King | $7^7$ | 4 | [10] |
| | H-y Peng T-h Yang | $6^4$ | 4 | | | | | | | | J Jung E King | $7^7$ | 4 | [10] |
| | J Jung E King | $7^7$ | 6 | | | | | | |
| | J Jung E King | $7^7$ | 6 | | | J Jung E King | 2 | 6 | [10] |
| | | | | | 2 | H Kondo H-h Lee | 6 | 4 | [5] |
| | N.Sriram Balaji B Sato | 4 | 3 | | 2 | H Kondo H-h Lee | 6 | 4 | [5] |
| 2 | H Kondo H-h Lee | 6 | 6 | |
