Challenger de Bangkok 2014 (dobles masculino)
# Challenger de Bangkok 2014 (dobles masculino)

Chang-Sat Bangkok Open :

| Campeón: | Pruchya Isarow Nuttanon Kadchapanan | Pruchya Isarow Nuttanon Kadchapanan | Pruchya Isarow Nuttanon Kadchapanan | Pruchya Isarow Nuttanon Kadchapanan | Pruchya Isarow Nuttanon Kadchapanan | Pruchya Isarow Nuttanon Kadchapanan | Pruchya Isarow Nuttanon Kadchapanan | Pruchya Isarow Nuttanon Kadchapanan | Pruchya Isarow Nuttanon Kadchapanan |
| - | - | - | - | - | - | - | - | - | - |
| Subcampeón: | Chen Ti Peng Hsien-yin | Chen Ti Peng Hsien-yin | Chen Ti Peng Hsien-yin | Chen Ti Peng Hsien-yin | Chen Ti Peng Hsien-yin | Chen Ti Peng Hsien-yin | Chen Ti Peng Hsien-yin | Chen Ti Peng Hsien-yin | Chen Ti Peng Hsien-yin |
| Resultado: | 6-4, 6-4 | 6-4, 6-4 | 6-4, 6-4 | 6-4, 6-4 | 6-4, 6-4 | 6-4, 6-4 | 6-4, 6-4 | 6-4, 6-4 | 6-4, 6-4 |
| Modalidades |||||||||||
| Individuales | Masculino | | | |
| Dobles | Masculino | |

La pareja tailandesa Pruchya Isarow y Nuttanon Kadchapanan ganaron el título, siendo también para ambos su primer título en la categoría ATP Challenger Series. Derrotaron en la final a la pareja taiwanesa formada por Chen Ti y Peng Hsien-yin por un marcador de 6–4, 6–4.

## Cabezas de serie

* Sanchai Ratiwatana / Sonchat Ratiwatana (Cuartos de final)
* Chen Ti / Peng Hsien-yin (Final)
* Lee Hsin-han / Danai Udomchoke (Primera ronda)
* Divij Sharan / Yasutaka Uchiyama (Semifinales)

## Cuadro

### Claves

| Q = Clasificado/a (Qualifier) WC = Invitación (Wild Card) LL = Perdedor/a afortunado/a (Lucky Loser) Alt = Suplente (Alternate) | SE = Exención especial (Special Exempt) PR = Ranking protegido (Protected Ranking) s = Partido suspendido (Suspended) | r = Retirado/a (Retired) w/o = No presentación (Walkover) d = Descalificado/a (Defaulted) |
| - | - | - |

### Cuadro

| Primera ronda | Primera ronda | Primera ronda | Primera ronda | Primera ronda | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Semifinales | Semifinales | Semifinales | Semifinales | Semifinales | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | S Ratiwatana S Ratiwatana | 1 | | |
| | M Reid J Thompson | 0r | | |
| | M Reid J Thompson | 0r | | | 1 | S Ratiwatana S Ratiwatana | $6^4$ | 6 | [10] |
| | | | | | | P Isarow N Kadchapanan | $7^7$ | 4 | [12] |
| | P Isarow N Kadchapanan | $7^7$ | 7 | | | P Isarow N Kadchapanan | $7^7$ | 4 | [12] |
| | C Rungkat K Wachiramanowong | $6^6$ | 5 | | | | | | |
| | C Rungkat K Wachiramanowong | $6^6$ | 5 | | | | | | | | P Isarow N Kadchapanan | 2 | 6 | [11] |
| | | | | | | | | | | 4 | D Sharan Y Uchiyama | 6 | 4 | [9] |
| 4 | D Sharan Y Uchiyama | 6 | 6 | | | | | | | 4 | D Sharan Y Uchiyama | 6 | 4 | [9] |
| | J Jung N Meister | 3 | 2 | | | | | | | | | | | |
| | J Jung N Meister | 3 | 2 | | 4 | D Sharan Y Uchiyama | 6 | 6 | | | | | | |
| | | | | | WC | C Tanasugarn W Udomsuk | 0 | 1 | | | | | | |
| WC | C Kaewsuto P Siriluethaiwattana | 3 | 6 | [9] | WC | C Tanasugarn W Udomsuk | 0 | 1 | | | | | | |
| WC | C Tanasugarn W Udomsuk | 6 | 1 | [11] | | | | | | | | | | |
| WC | C Tanasugarn W Udomsuk | 6 | 1 | [11] | | | | | | | | | | | | P Isarow N Kadchapanan | 6 | 6 |
| | | | | | | | | | | | | | | | 2 | T Chen H-y Peng | 4 | 4 |
| | L-c Huang T Matsui | 4 | 7 | [10] | | | | | | | | | | | 2 | T Chen H-y Peng | 4 | 4 |
| | T Fabbiano L Vanni | 6 | 5 | [3] | | | | | | | | | | |
| | T Fabbiano L Vanni | 6 | 5 | [3] | | L-c Huang T Matsui | $6^3$ | 3 | | | | | | |
| | | | | | | J Cluskey K Edmund | $7^7$ | 6 | | | | | | |
| | J Cluskey K Edmund | 4 | 6 | [10] | | J Cluskey K Edmund | $7^7$ | 6 | | | | | | |
| 3 | H-h Lee D Udomchoke | 6 | 3 | [8] | | | | | | | | | | |
| 3 | H-h Lee D Udomchoke | 6 | 3 | [8] | | | | | | | J Cluskey K Edmund | 4 | 4 | |
| | | | | | | | | | | 2 | T Chen H-y Peng | 6 | 6 | |
| | B Sato G Soeda | 6 | 6 | | | | | | | 2 | T Chen H-y Peng | 6 | 6 | |
| WC | P Burapharitta S Wattanakul | 3 | 2 | | | | | | |
| WC | P Burapharitta S Wattanakul | 3 | 2 | | | B Sato G Soeda | $6^5$ | 4 | |
| | | | | | 2 | T Chen H-y Peng | $7^7$ | 6 | |
| | J Pulgar-García R Ramanathan | 6 | 2 | [6] | 2 | T Chen H-y Peng | $7^7$ | 6 | |
| 2 | T Chen H-y Peng | 3 | 6 | [10] |
