2018 Canberra Challenger – Doubles
# 2018 Canberra Challenger – Doubles

Andre Begemann and Jan-Lennard Struff were the defending champions but chose not to defend their title.

Jonathan Erlich and Divij Sharan won the title after defeating Hans Podlipnik-Castillo and Andrei Vasilevski $7–6^{(7–1)},$ 6–2 in the final.

## Seeds

* Hans Podlipnik-Castillo / Andrei Vasilevski (final)
* Jonathan Erlich / Divij Sharan (champions)
* Adil Shamasdin / Neal Skupski (first round)
* Steven de Waard / Ben McLachlan (semifinals)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | H Podlipnik-Castillo A Vasilevski | $7^{11}$ | 6 | | | | | | | | | | | | | | | |
| | E Benchetrit G Blancaneaux | $6^9$ | 3 | | 1 | H Podlipnik-Castillo A Vasilevski | 2 | | | | | | | | | | | |
| | H Grenier M Janvier | $7^7$ | 6 | | | H Grenier M Janvier | $1^r$ | | | | | | | | | | | |
| | N Lammons A Lawson | $6^3$ | 4 | | | | | | | 1 | H Podlipnik-Castillo A Vasilevski | 6 | $7^7$ | | | | | |
| 4 | S de Waard B McLachlan | 6 | 6 | | | | | | | 4 | S de Waard B McLachlan | 4 | $6^5$ | | | | | |
| | D Propoggia S Puodziunas | 4 | 2 | | 4 | S de Waard B McLachlan | 6 | $7^7$ | | | | | | | | | | |
| WC | Alexander Crnokrak M Romios | 5 | 0 | | | J Chaplin L Saville | 4 | $6^4$ | | | | | | | | | | |
| | Jarryd Chaplin L Saville | 7 | 6 | | | | | | | | | | | | 1 | H Podlipnik-Castillo A Vasilevski | $6^1$ | 2 |
| | S Bangoura N Pasha | w/o | | | | | | | | | | | | | 2 | J Erlich D Sharan | $7^7$ | 6 |
| | H Nys T Pütz | | | | | S Bangoura N Pasha | 6 | 4 | [10] | | | | | | | | | |
| | Z Li Yo Watanuki | 4 | $7^7$ | [10] | | Z Li Yo Watanuki | 4 | 6 | [12] | | | | | | | | | |
| 3 | A Shamasdin N Skupski | 6 | $6^5$ | [7] | | | | | | | Z Li Yo Watanuki | 4 | $7^7$ | [4] | | | | |
| | A Seppi Gavin van Peperzeel | w/o | | | | | | | | 2 | J Erlich D Sharan | 6 | $6^5$ | [10] | | | | |
| WC | H Bourchier A Harris | | | | | A Seppi G van Peperzeel | 4 | 3 | | | | | | | | | | |
| WC | J Beale T Fancutt | 3 | 1 | | 2 | J Erlich D Sharan | 6 | 6 | | | | | | | | | | |
| 2 | J Erlich D Sharan | 6 | 6 | | | | | | | | | | | | | | | |
