2022 Open Harmonie mutuelle – Doubles
# 2022 Open Harmonie mutuelle – Doubles

Jonathan Erlich and Fabrice Martin were the defending champions but chose not to defend their title.

Sander Arends and David Pel won the title after defeating Jonathan Eysseric and Robin Haase 6–3, 6–3 in the final.

## Seeds

* Jonathan Eysseric / Robin Haase (final)
* Sander Arends / David Pel (champions)
* Marek Gengel / Michail Pervolarakis (semifinals)
* Neil Oberleitner / David Pichler (first round)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| | | | | | 1 | J Eysseric R Haase | 6 | 6 | | | | | | | | | |
| | Davide Pozzi Augusto Virgili | 3 | 3 | | WC | E Furness Q Gueydan | 2 | 3 | | | | | | | | | |
| WC | E Furness Quentin Gueydan | 6 | 6 | | | | | | | 1 | J Eysseric R Haase | $7^7$ | 6 | | | | |
| 4 | N Oberleitner David Pichler | 7 | 2 | [8] | | | | | | | T Arribagé H Mayot | $6^4$ | 3 | | | | |
| | A Chandrasekar VS Prashanth | 5 | 6 | [10] | | A Chandrasekar VS Prashanth | 1 | 6 | [6] | | | | | | | | |
| | T Arribagé H Mayot | 4 | 6 | [11] | | T Arribagé H Mayot | 6 | 3 | [10] | | | | | | | | |
| WC | Arthur Bouquier Martin Breysach | 6 | 3 | [9] | | | | | | | | | | 1 | J Eysseric R Haase | 3 | 3 |
| | H Jebens Niklas Schell | $6^3$ | 2 | | | | | | | | | | | 2 | S Arends D Pel | 6 | 6 |
| | A Gray R Peniston | $7^7$ | 6 | | | A Gray R Peniston | 5 | 6 | [8] | | | | | | | | |
| | Mats Hermans M Torpegaard | 2 | 4 | | 3 | M Gengel M Pervolarakis | 7 | 2 | [10] | | | | | | | | |
| 3 | M Gengel M Pervolarakis | 6 | 6 | | | | | | | 3 | M Gengel M Pervolarakis | 5 | $6^2$ | | | | |
| | Z Babić A Donski | 6 | 7 | | | | | | | 2 | S Arends D Pel | 7 | $7^7$ | | | | |
| | Quentin Folliot M Janvier | 4 | 5 | | | Z Babić A Donski | $6^5$ | 3 | | | | | | | | | |
| | | | | | 2 | S Arends D Pel | $7^7$ | 6 | | | | | | | | | |
