"{\"inputs\":\"Solve in Python:\\nYou are a rebel leader and you are planning to start a revolution in your country. But the evil Government found out about your plans and set your punishment in the form of correctional labor.\\n\\nYou must paint a fence which consists of $10^{100}$ planks in two colors in the following way (suppose planks are numbered from left to right from $0$):   if the index of the plank is divisible by $r$ (such planks have indices $0$, $r$, $2r$ and so on) then you must paint it red;  if the index of the plank is divisible by $b$ (such planks have indices $0$, $b$, $2b$ and so on) then you must paint it blue;  if the index is divisible both by $r$ and $b$ you can choose the color to paint the plank;  otherwise, you don't need to paint the plank at all (and it is forbidden to spent paint on it). \\n\\nFurthermore, the Government added one additional restriction to make your punishment worse. Let's list all painted planks of the fence in ascending order: if there are $k$ consecutive planks with the same color in this list, then the Government will state that you failed the labor and execute you immediately. If you don't paint the fence according to the four aforementioned conditions, you will also be executed.\\n\\nThe question is: will you be able to accomplish the labor (the time is not important) or the execution is unavoidable and you need to escape at all costs.\\n\\n\\n-----Input-----\\n\\nThe first line contains single integer $T$ ($1 \\\\le T \\\\le 1000$) — the number of test cases.\\n\\nThe next $T$ lines contain descriptions of test cases — one per line. Each test case contains three integers $r$, $b$, $k$ ($1 \\\\le r, b \\\\le 10^9$, $2 \\\\le k \\\\le 10^9$) — the corresponding coefficients.\\n\\n\\n-----Output-----\\n\\nPrint $T$ words — one per line. For each test case print REBEL (case insensitive) if the execution is unavoidable or OBEY (case insensitive) otherwise.\\n\\n\\n-----Example-----\\nInput\\n4\\n1 1 2\\n2 10 4\\n5 2 3\\n3 2 2\\n\\nOutput\\nOBEY\\nREBEL\\nOBEY\\nOBEY\",\"targets\":\"from math import gcd\\nt = int(input())\\nfor i in range(t):\\n    r, b, k = [int(x) for x in input().split()]\\n    if b > r:\\n        b, r = r, b\\n    g = gcd(r, b)\\n    c = (r - g - 1) \\/\\/ b + 1\\n    if (c >= k):\\n        print(\\\"REBEL\\\")\\n    else:\\n        print(\\\"OBEY\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n Imagine a standard chess board with only two white and two black knights placed in their standard starting positions: the white knights on b1 and g1; the black knights on b8 and g8.\\n\\n There are two players: one plays for `white`, the other for `black`. During each move, the player picks one of his knights and moves it to an unoccupied square according to standard chess rules. Thus, a knight on d5 can move to any of the following squares: b6, c7, e7, f6, f4, e3, c3, and b4, as long as it is not occupied by either a friendly or an enemy knight.\\n\\n The players take turns in making moves, starting with the white player. Given the configuration `positions` of the knights after an unspecified number of moves, determine whose turn it is.\\n\\n# Example\\n\\n For `positions = \\\"b1;g1;b8;g8\\\"`, the output should be `true`.\\n\\n The configuration corresponds to the initial state of the game. Thus, it's white's turn.\\n\\n# Input\\/Output\\n\\n\\n - `[input]` string `positions`\\n\\n    The positions of the four knights, starting with white knights, separated by a semicolon, in the chess notation.\\n\\n\\n - `[output]` a boolean value\\n\\n    `true` if white is to move, `false` otherwise.\",\"targets\":\"import re\\ndef whose_turn(positions):\\n  return len(re.sub(r\\\"[1357;aceg]\\\", \\\"\\\",positions))%2==0\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/arc109\\/tasks\\/arc109_b:\\nSnuke is visiting a shop in Tokyo called 109 to buy some logs.\\nHe wants n logs: one of length 1, one of length 2, ..., and one of length n.\\nThe shop has n+1 logs in stock: one of length 1, one of length 2, \\\\dots, and one of length n+1. Each of these logs is sold for 1 yen (the currency of Japan).\\nHe can cut these logs as many times as he wants after buying them. That is, he can get k logs of length L_1, \\\\dots, L_k from a log of length L, where L = L_1 + \\\\dots + L_k. He can also throw away unwanted logs.\\nSnuke wants to spend as little money as possible to get the logs he wants.\\nFind the minimum amount of money needed to get n logs of length 1 to n.\\n\\n-----Constraints-----\\n - 1 \\\\leq n \\\\leq 10^{18}\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nn\\n\\n-----Output-----\\nPrint the minimum amount of money needed to get n logs of length 1 to n.\\n\\n-----Sample Input-----\\n4\\n\\n-----Sample Output-----\\n3\\n\\nOne way to get the logs he wants with 3 yen is:\\n - Buy logs of length 2, 4, and 5.\\n - Cut the log of length 5 into two logs of length 1 each and a log of length 3.\\n - Throw away one of the logs of length 1.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n=int(input())\\nok=10**20\\nng=0\\nwhile ok-ng>1:\\n    m=(ok+ng)\\/\\/2\\n    if m*(m+1)<=2*(n+1):\\n        ng=m\\n    else:\\n        ok=m\\nprint(n+1-ng)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nToday Pari and Arya are playing a game called Remainders.\\n\\nPari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value $x \\\\text{mod} k$. There are n ancient numbers c_1, c_2, ..., c_{n} and Pari has to tell Arya $x \\\\operatorname{mod} c_{i}$ if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value $x \\\\text{mod} k$ for any positive integer x?\\n\\nNote, that $x \\\\text{mod} y$ means the remainder of x after dividing it by y.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers n and k (1 ≤ n,  k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.\\n\\nThe second line contains n integers c_1, c_2, ..., c_{n} (1 ≤ c_{i} ≤ 1 000 000).\\n\\n\\n-----Output-----\\n\\nPrint \\\"Yes\\\" (without quotes) if Arya has a winning strategy independent of value of x, or \\\"No\\\" (without quotes) otherwise.\\n\\n\\n-----Examples-----\\nInput\\n4 5\\n2 3 5 12\\n\\nOutput\\nYes\\n\\nInput\\n2 7\\n2 3\\n\\nOutput\\nNo\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, Arya can understand $x \\\\operatorname{mod} 5$ because 5 is one of the ancient numbers.\\n\\nIn the second sample, Arya can't be sure what $x \\\\text{mod} 7$ is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.\",\"targets\":\"from math import gcd\\nn, k = list(map(int, input().split()))\\nans = 1\\nfor e in input().split():\\n  e = int(e)\\n  ans = ans \\/\\/ gcd(ans, e) * e % k\\nprint('No' if ans else 'Yes')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a02e9c19f8e2dbd50000167:\\nCreate a function that takes any sentence and redistributes the spaces (and adds additional spaces if needed) so that each word starts with a vowel. The letters should all be in the same order but every vowel in the sentence should be the start of a new word. The first word in the new sentence may start without a vowel. It should return a string in all lowercase with no punctuation (only alphanumeric characters).\\n\\n\\n\\nEXAMPLES\\n'It is beautiful weather today!' becomes 'it isb e a ut if ulw e ath ert od ay'\\n'Coding is great' becomes 'c od ing isgr e at'\\n'my number is 0208-533-2325' becomes 'myn umb er is02085332325'\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from re import sub\\ndef vowel_start(st):\\n    return sub(r'(?<=.)([aeiou])', r' \\\\1', sub(r'[^a-z0-9]', '', st.lower()))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLet's denote a function \\n\\n$d(x, y) = \\\\left\\\\{\\\\begin{array}{ll}{y - x,} & {\\\\text{if}|x - y|> 1} \\\\\\\\{0,} & {\\\\text{if}|x - y|\\\\leq 1} \\\\end{array} \\\\right.$\\n\\nYou are given an array a consisting of n integers. You have to calculate the sum of d(a_{i}, a_{j}) over all pairs (i, j) such that 1 ≤ i ≤ j ≤ n.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer n (1 ≤ n ≤ 200000) — the number of elements in a.\\n\\nThe second line contains n integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9) — elements of the array. \\n\\n\\n-----Output-----\\n\\nPrint one integer — the sum of d(a_{i}, a_{j}) over all pairs (i, j) such that 1 ≤ i ≤ j ≤ n.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 2 3 1 3\\n\\nOutput\\n4\\n\\nInput\\n4\\n6 6 5 5\\n\\nOutput\\n0\\n\\nInput\\n4\\n6 6 4 4\\n\\nOutput\\n-8\\n\\n\\n\\n-----Note-----\\n\\nIn the first example:\\n\\n  d(a_1, a_2) = 0;  d(a_1, a_3) = 2;  d(a_1, a_4) = 0;  d(a_1, a_5) = 2;  d(a_2, a_3) = 0;  d(a_2, a_4) = 0;  d(a_2, a_5) = 0;  d(a_3, a_4) =  - 2;  d(a_3, a_5) = 0;  d(a_4, a_5) = 2.\",\"targets\":\"N = 2 * 10**5 + 3\\nn = int(input())\\nA, cnt = list(map(int,input().split(' '))), {}\\n\\ns, a = 0, 0\\n\\nfor i in range(n-1,-1,-1):\\n    a += s\\n    if (A[i]-1) in cnt:\\n        a += cnt[A[i]-1]\\n    if (A[i]+1) in cnt:\\n        a -= cnt[A[i]+1]\\n    a -= (n-(i+1))*A[i]\\n    s += A[i]\\n    if A[i] not in cnt:\\n        cnt[A[i]]=0\\n    cnt[A[i]] += 1\\n\\nprint(a)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58a3a735cebc0630830000c0:\\n# Task\\n You are given two string `a` an `s`. Starting with an empty string we can do the following two operations:\\n```\\nappend the given string a to the end of the current string.\\nerase one symbol of the current string.```\\nYour task is to find the least number of operations needed to construct the given string s. Assume that all the letters from `s` appear in `a` at least once.\\n\\n# Example\\n\\n For `a = \\\"aba\\\", s = \\\"abbaab\\\"`, the result should be `6`.\\n \\n Coinstruction:\\n \\n `\\\"\\\" -> \\\"aba\\\" -> \\\"ab\\\" -> \\\"ababa\\\" -> \\\"abba\\\" -> \\\"abbaaba\\\" -> \\\"abbaab\\\".`\\n \\n So, the result is 6.\\n\\n For `a = \\\"aba\\\", s = \\\"a\\\"`, the result should be `3`.\\n \\n Coinstruction:\\n \\n `\\\"\\\" -> \\\"aba\\\" -> \\\"ab\\\" -> \\\"a\\\".`\\n \\n So, the result is 3.\\n\\n For `a = \\\"aba\\\", s = \\\"abaa\\\"`, the result should be `4`.\\n \\n Coinstruction:\\n \\n `\\\"\\\" -> \\\"aba\\\" -> \\\"abaaba\\\" -> \\\"abaab\\\" -> \\\"abaa\\\".`\\n \\n So, the result is 4.\\n\\n# Input\\/Output\\n\\n\\n - `[input]` string `a`\\n\\n  string to be appended. Contains only lowercase English letters. \\n  \\n  1 <= a.length <= 20\\n\\n\\n - `[input]` string `s`\\n\\n  desired string containing only lowercase English letters.\\n  \\n  1 <= s.length < 1000\\n\\n\\n - `[output]` an integer\\n\\n  minimum number of operations\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def string_constructing(a, s):\\n    current = \\\"\\\"\\n    step = 0\\n    while current != s:\\n        for i in range(len(current)):\\n            if i >= len(s):\\n                return step + len(current) - len(s)\\n            if current[i] != s[i]:\\n                current = current[i+1:]\\n                s = s[i:]\\n                break\\n        else:\\n            current += a\\n        step += 1\\n                \\n    return step\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5ad29cd95e8240dd85000b54:\\nAndrzej was given a task:\\nThere are n jars with pills. In every jar there is a different type of pill and the amount of pills in each jar is infinite. One type of pill makes a person glow about 30 minutes after taking and none of the other types has any effect.\\nHis job is to determine, in which jar are the pills that make a person glow.\\nBut there is one catch, he only has 35 minutes to do so.(so he can't take a pill, wait for the results and then take another one, because he wouldn't be able to see the results)\\nFortunetely, he can take any number of friends he needs with him.\\nOn completing the task Andrzej receives one million dollars. You know that Andrzej is very honest, so he will split the money equally with his friends.\\nYour job is to determine how many friends does Andrzej need to complete the task.(He also wants to make the highest amount of money.)\\nFor example for n = 2\\nThe answer is 0 because he doesn't need any friends, he just needs to take a pill from the first jar and wait for the effects.\\nFor another example for n = 4\\nThe answer is 1 because having pills A B C D Andrzej can take pills A B and the friend can take pills B C\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\ndef friends(n):\\n    print(n)\\n    if n <= 2:\\n        return 0\\n    elif math.log(n,2)==int(math.log(n,2)):\\n        return int(math.log(n,2)) -1\\n    else:\\n        return int(math.log(n,2))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n## Task\\nIn this kata you'll be given a string of English digits \\\"collapsed\\\" together, like this:\\n\\n`zeronineoneoneeighttwoseventhreesixfourtwofive`\\n\\nYour task is to split the string back to digits:\\n\\n`zero nine one one eight two seven three six four two five`\\n\\n## Examples\\n```\\nthree -> three\\neightsix -> eight six\\nfivefourseven -> five four seven\\nninethreesixthree -> nine three six three\\nfivethreefivesixthreenineonesevenoneeight -> five three five six three nine one seven one eight\\n```\",\"targets\":\"import re\\n\\ndef uncollapse(digits):\\n    return ' '.join(re.findall('zero|one|two|three|four|five|six|seven|eight|nine', digits))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMartha — as a professional problemsetter — proposed a problem for a world-class contest. This is the problem statement:\\n\\nTomorrow is Nadia's birthday, and Bardia (her brother) is assigned to make the balloons ready!\\n\\nThere are n balloons (initially empty) that are tied to a straight line on certain positions x_1, x_2, ..., x_{n}. Bardia inflates the balloons from left to right. As a result, i-th balloon gets bigger and bigger until its radius reaches the pressure endurance p_{i} or it touches another previously-inflated balloon. [Image] \\n\\nWhile Bardia was busy with the balloons, he wondered \\\"What will be the sum of radius of balloons after all of the balloons are inflated?\\\". Being a nerdy type of guy, he is now thinking about the problem instead of preparing his sister's birthday. Calculate the answer to Bardia's problem so that Nadia's birthday won't be balloon-less.\\n\\nArtha — Martha's student — claimed his solution got accepted. Martha (being his teacher for a long time!) knew he couldn't have solved the problem for real and thus thinks there is something wrong with the testcases. Artha isn't anyhow logical, which means there is no way for Martha to explain the wrong point in his algorithm. So, the only way is to find a testcase to prove him wrong!\\n\\nArtha's pseudo-code is shown below: [Image] \\n\\nYou should output a small testcase for the problem such that Artha's algorithm is incorrect. The algorithm's output is considered correct if it differs from the correct value by no more than 1.\\n\\n\\n-----Input-----\\n\\nPlease pay attention! No input will be given to your program for this problem. So you do not have to read from the input anything.\\n\\n\\n-----Output-----\\n\\nYou should output the generated small testcase (which Artha's solution doesn't get it right). It should be in the following format:  First line must contain the only number n (1 ≤ n ≤ 500).  The i-th of the next n lines should contain the description of the i-th balloon — two space-separated integers x_{i}, p_{i} (1 ≤ p_{i} ≤ 10^6, 0 ≤ x_1 < x_2 < ... < x_{n} ≤...\",\"targets\":\"print(302)\\nprint(\\\"0 1000000\\\")\\ncoord, rad = 17321*2, 300\\nfor i in range(300):\\n    print(coord, rad)\\n    coord, rad = coord+600, rad-1\\nprint(\\\"1000000 1000000\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n Let's say that number a feels comfortable with number b if a ≠ b and b lies in the segment` [a - s(a), a + s(a)]`, where `s(x)` is the sum of x's digits.\\n\\n How many pairs (a, b) are there, such that a < b, both a and b lie on the segment `[L, R]`, and each number feels comfortable with the other?\\n\\n# Example\\n\\n For `L = 10 and R = 12`, the output should be `2`\\n\\n Here are all values of s(x) to consider:\\n```\\ns(10) = 1, so 10 is comfortable with 9 and 11;\\ns(11) = 2, so 11 is comfortable with 9, 10, 12 and 13;\\ns(12) = 3, so 12 is comfortable with 9, 10, 11, 13, 14 and 15.\\nThus, there are 2 pairs of numbers comfortable \\nwith each other within the segment [10; 12]: \\n(10, 11) and (11, 12).\\n```\\n# Input\\/Output\\n\\n - `[input]` integer `L`\\n\\n    Constraints: `1 ≤ L ≤ R ≤ 1000`\\n\\n - `[input]` integer `R`\\n\\n    Constraints: `1 ≤ L ≤ R ≤ 1000`\\n\\n - `[output]` an integer\\n\\n    The number of pairs satisfying all the above conditions.\",\"targets\":\"def comfortable_numbers(l, r):\\n    c=0\\n    d={}\\n    for a in range(l,r+1):\\n        s=sum(int(d) for d in str(a))\\n        d[a]=set(range(a-s,a+s+1))\\n        for i in range(l,a):\\n            if a in d[i] and i in d[a]:\\n                c+=1\\n    return c\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1017\\/E:\\nAfter the war, the supersonic rocket became the most common public transportation.\\n\\nEach supersonic rocket consists of two \\\"engines\\\". Each engine is a set of \\\"power sources\\\". The first engine has $n$ power sources, and the second one has $m$ power sources. A power source can be described as a point $(x_i, y_i)$ on a 2-D plane. All points in each engine are different.\\n\\nYou can manipulate each engine separately. There are two operations that you can do with each engine. You can do each operation as many times as you want. For every power source as a whole in that engine: $(x_i, y_i)$ becomes $(x_i+a, y_i+b)$, $a$ and $b$ can be any real numbers. In other words, all power sources will be shifted. For every power source as a whole in that engine: $(x_i, y_i)$ becomes $(x_i \\\\cos \\\\theta - y_i \\\\sin \\\\theta, x_i \\\\sin \\\\theta + y_i \\\\cos \\\\theta)$, $\\\\theta$ can be any real number. In other words, all power sources will be rotated.\\n\\nThe engines work as follows: after the two engines are powered, their power sources are being combined (here power sources of different engines may coincide). If two power sources $A(x_a, y_a)$ and $B(x_b, y_b)$ exist, then for all real number $k$ that $0 \\\\lt k \\\\lt 1$, a new power source will be created $C_k(kx_a+(1-k)x_b,ky_a+(1-k)y_b)$. Then, this procedure will be repeated again with all new and old power sources. After that, the \\\"power field\\\" from all power sources will be generated (can be considered as an infinite set of all power sources occurred).\\n\\nA supersonic rocket is \\\"safe\\\" if and only if after you manipulate the engines, destroying any power source and then power the engine, the power field generated won't be changed (comparing to the situation where no power source erased). Two power fields are considered the same if and only if any power source in one field belongs to the other one as well.\\n\\nGiven a supersonic rocket, check whether it is safe or not.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$, $m$ ($3 \\\\le n, m \\\\le 10^5$) — the number of power sources in each...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n\\n\\n# > 0 anti-clock, < 0 clockwise, == 0 same line\\ndef orientation(p1, p2, p3):\\n    return (p2[0] - p1[0])*(p3[1] - p1[1]) - (p2[1] - p1[1])*(p3[0] - p1[0])\\n\\n\\ndef dot(p1, p2, p3, p4):\\n    return (p2[0]-p1[0])*(p4[0]-p3[0]) + (p2[1]-p1[1])*(p4[1]-p3[1])\\n\\n\\ndef theta(p1, p2):\\n    dx = p2[0] - p1[0]\\n    dy = p2[1] - p1[1]\\n    if abs(dx) < 0.1 and abs(dy) < 0.1:\\n        t = 0\\n    else:\\n        t = dy\\/(abs(dx) + abs(dy))\\n        if abs(t) < 0.1 ** 10:\\n            t = 0\\n    if dx < 0:\\n        t = 2 - t\\n    elif dy < 0:\\n        t = 4 + t\\n\\n    return t*90\\n\\n\\ndef dist_sq(p1, p2):\\n    return (p1[0] - p2[0])*(p1[0] - p2[0]) + (p1[1] - p2[1])*(p1[1] - p2[1])\\n\\n\\ndef chull(points):\\n    # let 0 element to be smallest, reorder elements\\n    pi = [x for x in range(len(points))]\\n    min_y = points[0][1]\\n    min_x = points[0][0]\\n    min_ind = 0\\n    for i in range(len(points)):\\n        if points[i][1] < min_y or points[i][1] == min_y and points[i][0] < min_x:\\n            min_y = points[i][1]\\n            min_x = points[i][0]\\n            min_ind = i\\n    pi[0] = min_ind\\n    pi[min_ind] = 0\\n    th = [theta(points[pi[0]], points[x]) for x in range(len(points))]\\n    pi.sort(key=lambda x: th[x])\\n    # process equals\\n    unique = [pi[0], pi[1]]\\n    for i in range(2, len(pi)):\\n        if th[pi[i]] != th[unique[-1]]:\\n            unique.append(pi[i])\\n        else:\\n            if dist_sq(points[pi[0]], points[unique[-1]]) < dist_sq(points[pi[0]], points[pi[i]]):\\n                unique[-1] = pi[i] # put max\\n    pi = unique\\n    stack = []\\n    for i in range(min(len(pi), 3)):\\n        stack.append(points[pi[i]])\\n    if len(stack) < 3:\\n        return stack\\n    for i in range(3, len(pi)):\\n        while len(stack) >= 2:\\n            o = orientation(stack[-2], stack[-1], points[pi[i]])\\n            if o > 0:\\n                stack.append(points[pi[i]])\\n                break\\n            elif o < 0:\\n                stack.pop()\\n            else:  # ==\\n                if dist_sq(stack[-2], stack[-1]) < dist_sq(stack[-2], points[pi[i]]):\\n            ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Story\\n\\nThose pesky rats have returned and this time they have taken over the Town Square.\\n\\nThe Pied Piper has been enlisted again to play his magical tune and coax all the rats towards him.\\n\\nBut some of the rats are deaf and are going the wrong way!\\n\\n# Kata Task\\n\\nHow many deaf rats are there?\\n\\n## Input Notes\\n\\n* The Town Square is a rectangle of square paving stones (the Square has 1-15 pavers per side)\\n* The Pied Piper is always present\\n\\n## Output Notes\\n* Deaf rats are those that are moving to paving stone **further away** from the Piper than where they are now\\n* Use Euclidian distance for your calculations\\n\\n## Legend\\n\\n* `P` = The Pied Piper\\n* `←` `↑` `→` `↓` `↖` `↗` `↘` `↙` = Rats going in different directions\\n* space = Everything else\\n\\n\\n\\n# Examples\\n\\nex1 - has 1 deaf rat\\n\\n\\n↗ P              \\n  ↘   ↖\\n  ↑              \\n↗        \\n\\n\\n---\\n\\nex2 - has 7 deaf rats\\n\\n\\n    ↗            \\nP ↓   ↖ ↑\\n    ←   ↓\\n  ↖ ↙   ↙\\n↓ ↓ ↓\",\"targets\":\"rat_dirs = {\\n  '←': (-1, 0),\\n  '↑': (0, -1),\\n  '→': (1, 0),\\n  '↓': (0, 1),\\n  '↖': (-1, -1),\\n  '↗': (1, -1),\\n  '↘': (1, 1),\\n  '↙': (-1, 1)\\n }\\n  \\ndef find_piper(town_square, width, height):\\n  for y in range(height):\\n    for x in range(width):\\n      if town_square[y][x] == 'P':\\n        return x, y\\n  return -1, -1 \\n  \\ndef is_rat_deaf(rx, ry, px, py, c):\\n  dx, dy = px - rx, py - ry\\n  cx, cy = rat_dirs[c]\\n  return cx * dx + cy * dy <= 0\\n  \\ndef count_deaf_rats(town_square):\\n  width, height = len(town_square[0]), len(town_square)\\n  px, py = find_piper(town_square, width, height)\\n  num_deaf = 0\\n  \\n  for y in range(height):\\n    for x in range(width):\\n      c = town_square[y][x]\\n      if c in rat_dirs and is_rat_deaf(x, y, px, py, c):\\n        num_deaf += 1\\n  \\n  return num_deaf\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc060\\/tasks\\/abc060_a:\\nYou are given three strings A, B and C. Check whether they form a word chain.\\nMore formally, determine whether both of the following are true:\\n - The last character in A and the initial character in B are the same.\\n - The last character in B and the initial character in C are the same.\\nIf both are true, print YES. Otherwise, print NO.\\n\\n-----Constraints-----\\n - A, B and C are all composed of lowercase English letters (a - z).\\n - 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B C\\n\\n-----Output-----\\nPrint YES or NO.\\n\\n-----Sample Input-----\\nrng gorilla apple\\n\\n-----Sample Output-----\\nYES\\n\\nThey form a word chain.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a, b, c = list(map(str, input().split()))\\nif a[-1] == b[0] and b[-1] == c[0]:\\n    print('YES')\\nelse:\\n    print('NO')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1209\\/A:\\nYou are given a sequence of integers $a_1, a_2, \\\\dots, a_n$. You need to paint elements in colors, so that:   If we consider any color, all elements of this color must be divisible by the minimal element of this color.  The number of used colors must be minimized. \\n\\nFor example, it's fine to paint elements $[40, 10, 60]$ in a single color, because they are all divisible by $10$. You can use any color an arbitrary amount of times (in particular, it is allowed to use a color only once). The elements painted in one color do not need to be consecutive.\\n\\nFor example, if $a=[6, 2, 3, 4, 12]$ then two colors are required: let's paint $6$, $3$ and $12$ in the first color ($6$, $3$ and $12$ are divisible by $3$) and paint $2$ and $4$ in the second color ($2$ and $4$ are divisible by $2$). For example, if $a=[10, 7, 15]$ then $3$ colors are required (we can simply paint each element in an unique color).\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $n$ ($1 \\\\le n \\\\le 100$), where $n$ is the length of the given sequence.\\n\\nThe second line contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 100$). These numbers can contain duplicates.\\n\\n\\n-----Output-----\\n\\nPrint the minimal number of colors to paint all the given numbers in a valid way.\\n\\n\\n-----Examples-----\\nInput\\n6\\n10 2 3 5 4 2\\n\\nOutput\\n3\\n\\nInput\\n4\\n100 100 100 100\\n\\nOutput\\n1\\n\\nInput\\n8\\n7 6 5 4 3 2 2 3\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, one possible way to paint the elements in $3$ colors is:\\n\\n  paint in the first color the elements: $a_1=10$ and $a_4=5$,  paint in the second color the element $a_3=3$,  paint in the third color the elements: $a_2=2$, $a_5=4$ and $a_6=2$. \\n\\nIn the second example, you can use one color to paint all the elements.\\n\\nIn the third example, one possible way to paint the elements in $4$ colors is:\\n\\n  paint in the first color the elements: $a_4=4$, $a_6=2$ and $a_7=2$,  paint in the second color the elements: $a_2=6$, $a_5=3$ and $a_8=3$,  paint in the third color the element $a_3=5$,  paint in the fourth color the element $a_1=7$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\nn = int(input())\\na = sorted(list(set(map(int, input().split()))))\\nn = len(a)\\nused = [0] * n\\ncnt = 0\\nfor i in range(n):\\n    if not used[i]:\\n        used[i] = 1\\n        cnt += 1\\n        for j in range(i + 1, n):\\n            if a[j] % a[i] == 0:\\n                used[j] = 1\\nprint(cnt)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef has many friends, but his best friend is Hemant. They both love to watch anime.\\nIn fact, their weekends are meant for that only. Also, Hemant is highly into games, of which Chef is unaware. Hemant once gave a game to Chef and asked him to determine the winner of the game. Since the Chef is busy, and you are also his friend, he asked you to help him.\\nThe Game is played between two players, $A$ and $B$. There are $N$ marbles. $A$ and $B$ plays alternately, and $A$ goes first. Each player can choose $1$ marble or $even$ number of marbles in his turn. The player who is not able to choose any marbles loses the game.\\n\\n-----Input:-----\\n- The first line consists of a single integer $T$ denoting the number of test cases.\\n- The Second line contains an integers $N$, denoting the number of marbles.\\n\\n-----Output:-----\\nFor each test case, print the name of the player who loses the game.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 10^5$\\n- $1 \\\\leq N \\\\leq 10^9$\\n\\n-----Sample Input:-----\\n3\\n1 \\n3\\n7 \\n\\n-----Sample Output:-----\\nB\\nA\\nB\",\"targets\":\"# cook your dish here\\nfor _ in range(int(input())):\\n     n=int(input())\\n     if(n==1 or n%2==0):\\n          print('B')\\n          continue\\n     elif(n==3):\\n          print('A')\\n          continue\\n     else:\\n          if((n-3)%2==0):\\n               print('B')\\n          else:\\n               print('A')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/381\\/A:\\nSereja and Dima play a game. The rules of the game are very simple. The players have n cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.\\n\\nSereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.\\n\\nInna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 ≤ n ≤ 1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000.\\n\\n\\n-----Output-----\\n\\nOn a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game.\\n\\n\\n-----Examples-----\\nInput\\n4\\n4 1 2 10\\n\\nOutput\\n12 5\\n\\nInput\\n7\\n1 2 3 4 5 6 7\\n\\nOutput\\n16 12\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"num=int(input())\\ntxt=input()\\npoints=txt.split(\\\" \\\")\\nscore=[0,0]\\nturn=0\\nwhile len(points)>0:\\n    maxp=max(int(points[0]),int(points[-1]))\\n    score[turn]+=maxp\\n    points.remove(str(maxp))\\n    turn=(turn+1)%2\\nprint(score[0],score[1])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/number-of-subsequences-that-satisfy-the-given-sum-condition\\/:\\nGiven an array of integers nums and an integer target.\\nReturn the number of non-empty subsequences of nums such that the sum of the minimum and maximum element on it is less or equal than target.\\nSince the answer may be too large, return it modulo 10^9 + 7.\\n \\nExample 1:\\nInput: nums = [3,5,6,7], target = 9\\nOutput: 4\\nExplanation: There are 4 subsequences that satisfy the condition.\\n[3] -> Min value + max value <= target (3 + 3 <= 9)\\n[3,5] -> (3 + 5 <= 9)\\n[3,5,6] -> (3 + 6 <= 9)\\n[3,6] -> (3 + 6 <= 9)\\n\\nExample 2:\\nInput: nums = [3,3,6,8], target = 10\\nOutput: 6\\nExplanation: There are 6 subsequences that satisfy the condition. (nums can have repeated numbers).\\n[3] , [3] , [3,3], [3,6] , [3,6] , [3,3,6]\\nExample 3:\\nInput: nums = [2,3,3,4,6,7], target = 12\\nOutput: 61\\nExplanation: There are 63 non-empty subsequences, two of them don't satisfy the condition ([6,7], [7]).\\nNumber of valid subsequences (63 - 2 = 61).\\n\\nExample 4:\\nInput: nums = [5,2,4,1,7,6,8], target = 16\\nOutput: 127\\nExplanation: All non-empty subset satisfy the condition (2^7 - 1) = 127\\n \\nConstraints:\\n\\n1 <= nums.length <= 10^5\\n1 <= nums[i] <= 10^6\\n1 <= target <= 10^6\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def numSubseq(self, nums: List[int], target: int) -> int:\\n        nums = sorted(nums)\\n        result = 0\\n        l, r = 0, len(nums) - 1\\n        while l <= r:\\n            if nums[l] + nums[r] > target:\\n                r -= 1\\n            else:\\n                result = (result + 2 ** (r-l)) % (10**9 + 7)\\n                l += 1\\n                \\n        return result\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5d9f95424a336600278a9632:\\n# Description\\n\\nGiven a number `n`, you should find a set of numbers for which the sum equals `n`. This set must consist exclusively of values that are a power of `2` (eg: `2^0 => 1, 2^1 => 2, 2^2 => 4, ...`).\\n\\nThe function `powers` takes a single parameter, the number `n`, and should return an array of unique numbers.\\n\\n## Criteria\\n\\nThe function will always receive a valid input: any positive integer between `1` and the max integer value for your language (eg: for JavaScript this would be `9007199254740991` otherwise known as `Number.MAX_SAFE_INTEGER`).\\n\\nThe function should return an array of numbers that are a **power of 2** (`2^x = y`).\\n\\nEach member of the returned array should be **unique**. (eg: the valid answer for `powers(2)` is `[2]`, not `[1, 1]`)\\n\\nMembers should be sorted in **ascending order** (small -> large). (eg: the valid answer for `powers(6)` is `[2, 4]`, not `[4, 2]`)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def powers(n):\\n    return [d<<p for p,d in enumerate(map(int,reversed(f'{n:b}'))) if d]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLet $n$ be an integer. Consider all permutations on integers $1$ to $n$ in lexicographic order, and concatenate them into one big sequence $p$. For example, if $n = 3$, then $p = [1, 2, 3, 1, 3, 2, 2, 1, 3, 2, 3, 1, 3, 1, 2, 3, 2, 1]$. The length of this sequence will be $n \\\\cdot n!$.\\n\\nLet $1 \\\\leq i \\\\leq j \\\\leq n \\\\cdot n!$ be a pair of indices. We call the sequence $(p_i, p_{i+1}, \\\\dots, p_{j-1}, p_j)$ a subarray of $p$. Its length is defined as the number of its elements, i.e., $j - i + 1$. Its sum is the sum of all its elements, i.e., $\\\\sum_{k=i}^j p_k$. \\n\\nYou are given $n$. Find the number of subarrays of $p$ of length $n$ having sum $\\\\frac{n(n+1)}{2}$. Since this number may be large, output it modulo $998244353$ (a prime number). \\n\\n\\n-----Input-----\\n\\nThe only line contains one integer $n$ ($1 \\\\leq n \\\\leq 10^6$), as described in the problem statement.\\n\\n\\n-----Output-----\\n\\nOutput a single integer — the number of subarrays of length $n$ having sum $\\\\frac{n(n+1)}{2}$, modulo $998244353$.\\n\\n\\n-----Examples-----\\nInput\\n3\\n\\nOutput\\n9\\n\\nInput\\n4\\n\\nOutput\\n56\\n\\nInput\\n10\\n\\nOutput\\n30052700\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, there are $16$ subarrays of length $3$. In order of appearance, they are:\\n\\n$[1, 2, 3]$, $[2, 3, 1]$, $[3, 1, 3]$, $[1, 3, 2]$, $[3, 2, 2]$, $[2, 2, 1]$, $[2, 1, 3]$, $[1, 3, 2]$, $[3, 2, 3]$, $[2, 3, 1]$, $[3, 1, 3]$, $[1, 3, 1]$, $[3, 1, 2]$, $[1, 2, 3]$, $[2, 3, 2]$, $[3, 2, 1]$. \\n\\nTheir sums are $6$, $6$, $7$, $6$, $7$, $5$, $6$, $6$, $8$, $6$, $7$, $5$, $6$, $6$, $7$, $6$. As $\\\\frac{n(n+1)}{2} = 6$, the answer is $9$.\",\"targets\":\"MOD = 998244353\\n\\nlist_size = 1000001\\n\\nf_list = [1] * list_size\\nf_r_list = [1] * list_size\\n\\nfor i in range(list_size - 1):\\n\\tf_list[i + 1] = int((f_list[i] * (i + 2)) % MOD)\\n\\ndef power(n, x):\\n\\tif x == 1:\\n\\t\\treturn n\\n\\telif x % 2 == 0:\\n\\t\\treturn power(int((n * n) % MOD), int(x \\/ 2))\\n\\telse:\\n\\t\\treturn int((n * power(n, x - 1)) % MOD)\\n\\nf_r_list[-1] = power(f_list[-1], MOD - 2)\\n\\nfor i in range(2, list_size + 1):\\n\\tf_r_list[-i] = int((f_r_list[-i + 1] * (list_size + 2 - i)) % MOD)\\n\\ndef comb(n, r):\\n\\tif n < r:\\n\\t\\treturn 0\\n\\telif n == 0 or r == 0 or n == r:\\n\\t\\treturn 1\\n\\telse:\\n\\t\\treturn (((f_list[n - 1] * f_r_list[n - r - 1]) % MOD) * f_r_list[r - 1]) % MOD \\n\\nn = int(input())\\nans = f_list[n-1]\\nfor i in range(2, n):\\n\\tans = (ans + comb(n, i) * (f_list[i-1] - 1) * f_list[n-i-1]) % MOD\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/280\\/C:\\nMomiji has got a rooted tree, consisting of n nodes. The tree nodes are numbered by integers from 1 to n. The root has number 1. Momiji decided to play a game on this tree.\\n\\nThe game consists of several steps. On each step, Momiji chooses one of the remaining tree nodes (let's denote it by v) and removes all the subtree nodes with the root in node v from the tree. Node v gets deleted as well. The game finishes when the tree has no nodes left. In other words, the game finishes after the step that chooses the node number 1.\\n\\nEach time Momiji chooses a new node uniformly among all the remaining nodes. Your task is to find the expectation of the number of steps in the described game.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 ≤ n ≤ 10^5) — the number of nodes in the tree. The next n - 1 lines contain the tree edges. The i-th line contains integers a_{i}, b_{i} (1 ≤ a_{i}, b_{i} ≤ n; a_{i} ≠ b_{i}) — the numbers of the nodes that are connected by the i-th edge.\\n\\nIt is guaranteed that the given graph is a tree.\\n\\n\\n-----Output-----\\n\\nPrint a single real number — the expectation of the number of steps in the described game.\\n\\nThe answer will be considered correct if the absolute or relative error doesn't exceed 10^{ - 6}.\\n\\n\\n-----Examples-----\\nInput\\n2\\n1 2\\n\\nOutput\\n1.50000000000000000000\\n\\nInput\\n3\\n1 2\\n1 3\\n\\nOutput\\n2.00000000000000000000\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, there are two cases. One is directly remove the root and another is remove the root after one step. Thus the expected steps are: 1 × (1 \\/ 2) + 2 × (1 \\/ 2) = 1.5\\n\\nIn the second sample, things get more complex. There are two cases that reduce to the first sample, and one case cleaned at once. Thus the expected steps are: 1 × (1 \\/ 3) + (1 + 1.5) × (2 \\/ 3) = (1 \\/ 3) + (5 \\/ 3) = 2\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# https:\\/\\/codeforces.com\\/problemset\\/problem\\/280\\/C\\nfrom collections import defaultdict, deque\\nimport sys\\n\\nnodes = int(sys.stdin.readline())\\nedges = defaultdict(list)\\nfor line in sys.stdin:\\n    a, b = line.split()\\n    a = int(a)\\n    b = int(b)\\n    edges[a].append(b)\\n    edges[b].append(a)\\nbfs = deque([(1, 1)])\\ndepths = {}\\nwhile bfs:\\n    nid, depth = bfs.popleft()\\n    if nid in depths:\\n        continue\\n    depths[nid] = depth\\n    for n2 in edges[nid]:\\n        bfs.append((n2, depth + 1))\\nprint(sum(1.0 \\/ d for d in sorted(depths.values(), reverse=True)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe define $x \\\\bmod y$ as the remainder of division of $x$ by $y$ ($\\\\%$ operator in C++ or Java, mod operator in Pascal).\\n\\nLet's call an array of positive integers $[a_1, a_2, \\\\dots, a_k]$ stable if for every permutation $p$ of integers from $1$ to $k$, and for every non-negative integer $x$, the following condition is met:\\n\\n $ (((x \\\\bmod a_1) \\\\bmod a_2) \\\\dots \\\\bmod a_{k - 1}) \\\\bmod a_k = (((x \\\\bmod a_{p_1}) \\\\bmod a_{p_2}) \\\\dots \\\\bmod a_{p_{k - 1}}) \\\\bmod a_{p_k} $ \\n\\nThat is, for each non-negative integer $x$, the value of $(((x \\\\bmod a_1) \\\\bmod a_2) \\\\dots \\\\bmod a_{k - 1}) \\\\bmod a_k$ does not change if we reorder the elements of the array $a$.\\n\\nFor two given integers $n$ and $k$, calculate the number of stable arrays $[a_1, a_2, \\\\dots, a_k]$ such that $1 \\\\le a_1 < a_2 < \\\\dots < a_k \\\\le n$.\\n\\n\\n-----Input-----\\n\\nThe only line contains two integers $n$ and $k$ ($1 \\\\le n, k \\\\le 5 \\\\cdot 10^5$).\\n\\n\\n-----Output-----\\n\\nPrint one integer — the number of stable arrays $[a_1, a_2, \\\\dots, a_k]$ such that $1 \\\\le a_1 < a_2 < \\\\dots < a_k \\\\le n$. Since the answer may be large, print it modulo $998244353$.\\n\\n\\n-----Examples-----\\nInput\\n7 3\\n\\nOutput\\n16\\n\\nInput\\n3 7\\n\\nOutput\\n0\\n\\nInput\\n1337 42\\n\\nOutput\\n95147305\\n\\nInput\\n1 1\\n\\nOutput\\n1\\n\\nInput\\n500000 1\\n\\nOutput\\n500000\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nn,k=map(int,input().split())\\nmod=998244353\\nfac=[1]*n\\nfor i in range(1,n):\\n    fac[i]=i*fac[i-1]\\n    fac[i]%=mod\\ni=1\\nsol=0\\nwhile ((n-i)\\/\\/i)>=(k-1):\\n    mul=fac[(n-i)\\/\\/i]\\n    div=fac[k-1]\\n    div*=fac[1+(n-i)\\/\\/i-k]\\n    div%=mod\\n    s=pow(div,mod-2,mod)\\n    s*=mul\\n    s%=mod\\n    sol+=s\\n    sol%=mod\\n    i+=1\\nprint(sol)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/617\\/A:\\nAn elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point x(x > 0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make in order to get to his friend's house.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains an integer x (1 ≤ x ≤ 1 000 000) — The coordinate of the friend's house.\\n\\n\\n-----Output-----\\n\\nPrint the minimum number of steps that elephant needs to make to get from point 0 to point x.\\n\\n\\n-----Examples-----\\nInput\\n5\\n\\nOutput\\n1\\n\\nInput\\n12\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample the elephant needs to make one step of length 5 to reach the point x.\\n\\nIn the second sample the elephant can get to point x if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach x in less than three moves.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\nprint(math.ceil(int(input()) \\/ 5))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven the values at the leaf nodes of a complete binary tree. The total number of nodes in the binary tree, is also given. Sum of the values at both the children of a node is equal to the value of the node itself. You can add any value or subtract any value from a node. Print the minimum change(difference made) in the sum of values of all the nodes in the tree, such that all the leaf nodes have the same value.\\n\\nNote: If a value transfers from one node to another, then that is not a change, but if an extra is needed to be added or subtracted to the entire total value of the nodes, then that is a change.\\n\\nInput Description:\\n\\nInput will contain an integer N, the number of nodes in the tree on a newline, followed by N space separated integers representing the values at the leaf nodes of the tree.\\n\\nOutput Description:\\n\\nPrint the required value on a newline.\\n\\nConstraints:\\n\\n1<=N<=20000\\n1<=Value at each node in the leaves<=1000\\n\\nExample 1:\\nInput:\\n\\n1\\n\\n50\\nOutput:\\n\\n0\\n\\nExplanation: Since there is only one node, it is a leaf node itself and no change needs to be made.\\n\\nExample 2:\\nInput:\\n\\n3\\n\\n200 800\\nOutput:\\n\\n0 \\n\\nExplanation: There are two leaf nodes, and they can be made to 500 500, since no change in the total was made so difference made is 0. \\n\\nExample 3:\\nInput:\\n\\n30\\n\\n29 33 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17\\nOutput:\\n\\n6\\n\\nOutput: A total change of 6 needs to be changed to the entire value of the nodes, to get the leaf nodes equal.\",\"targets\":\"print(0)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nDZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value w_{c}. For each special string s = s_1s_2... s_{|}s| (|s| is the length of the string) he represents its value with a function f(s), where $f(s) = \\\\sum_{i = 1}^{|s|}(w_{s_{i}} \\\\cdot i)$\\n\\nNow DZY has a string s. He wants to insert k lowercase letters into this string in order to get the largest possible value of the resulting string. Can you help him calculate the largest possible value he could get? \\n\\n\\n-----Input-----\\n\\nThe first line contains a single string s (1 ≤ |s| ≤ 10^3).\\n\\nThe second line contains a single integer k (0 ≤ k ≤ 10^3).\\n\\nThe third line contains twenty-six integers from w_{a} to w_{z}. Each such number is non-negative and doesn't exceed 1000.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the largest possible value of the resulting string DZY could get.\\n\\n\\n-----Examples-----\\nInput\\nabc\\n3\\n1 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\\n\\nOutput\\n41\\n\\n\\n\\n-----Note-----\\n\\nIn the test sample DZY can obtain \\\"abcbbc\\\", value = 1·1 + 2·2 + 3·2 + 4·2 + 5·2 + 6·2 = 41.\",\"targets\":\"st=input()\\nk=int(input())\\nw=list(map(int,input().split()))\\nw2={chr(ord('a')+i):w[i] for i in range(26)}\\nm=max(w)\\nprint(sum([w2[st[i]]*(i+1) for i in range(len(st))])+sum([i*m for i in range(len(st)+1,len(st)+1+k)]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIahub is a big fan of tourists. He wants to become a tourist himself, so he planned a trip. There are n destinations on a straight road that Iahub wants to visit. Iahub starts the excursion from kilometer 0. The n destinations are described by a non-negative integers sequence a_1, a_2, ..., a_{n}. The number a_{k} represents that the kth destination is at distance a_{k} kilometers from the starting point. No two destinations are located in the same place. \\n\\nIahub wants to visit each destination only once. Note that, crossing through a destination is not considered visiting, unless Iahub explicitly wants to visit it at that point. Also, after Iahub visits his last destination, he doesn't come back to kilometer 0, as he stops his trip at the last destination. \\n\\nThe distance between destination located at kilometer x and next destination, located at kilometer y, is |x - y| kilometers. We call a \\\"route\\\" an order of visiting the destinations. Iahub can visit destinations in any order he wants, as long as he visits all n destinations and he doesn't visit a destination more than once. \\n\\nIahub starts writing out on a paper all possible routes and for each of them, he notes the total distance he would walk. He's interested in the average number of kilometers he would walk by choosing a route. As he got bored of writing out all the routes, he asks you to help him.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (2 ≤ n ≤ 10^5). Next line contains n distinct integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^7).\\n\\n\\n-----Output-----\\n\\nOutput two integers — the numerator and denominator of a fraction which is equal to the wanted average number. The fraction must be irreducible.\\n\\n\\n-----Examples-----\\nInput\\n3\\n2 3 5\\n\\nOutput\\n22 3\\n\\n\\n-----Note-----\\n\\nConsider 6 possible routes:  [2, 3, 5]: total distance traveled: |2 – 0| + |3 – 2| + |5 – 3| = 5;  [2, 5, 3]: |2 – 0| + |5 – 2| + |3 – 5| = 7;  [3, 2, 5]: |3 – 0| + |2 – 3| + |5 – 2| = 7;  [3, 5, 2]: |3 – 0| + |5 – 3| + |2 – 5| = 8;  [5, 2, 3]: |5 – 0| + |2 – 5| + |3 – 2| = 9;  [5, 3,...\",\"targets\":\"import math\\nn = int(input())\\na = list(map(int, input().split()))\\na.sort(reverse = True)\\nk = 0\\ns1 = 0\\ns2 = 0\\nfor i in a:\\n\\ts2 += s1 - k * i\\n\\ts1 += i\\n\\tk += 1\\ns2 *= 2\\ns2 += sum(a)\\ngcd = math.gcd(s2, n)\\nprint(s2 \\/\\/ gcd, n \\/\\/ gcd)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGerald plays the following game. He has a checkered field of size n × n cells, where m various cells are banned. Before the game, he has to put a few chips on some border (but not corner) board cells. Then for n - 1 minutes, Gerald every minute moves each chip into an adjacent cell. He moves each chip from its original edge to the opposite edge. Gerald loses in this game in each of the three cases:  At least one of the chips at least once fell to the banned cell.  At least once two chips were on the same cell.  At least once two chips swapped in a minute (for example, if you stand two chips on two opposite border cells of a row with even length, this situation happens in the middle of the row). \\n\\nIn that case he loses and earns 0 points. When nothing like that happened, he wins and earns the number of points equal to the number of chips he managed to put on the board. Help Gerald earn the most points.\\n\\n\\n-----Input-----\\n\\nThe first line contains two space-separated integers n and m (2 ≤ n ≤ 1000, 0 ≤ m ≤ 10^5) — the size of the field and the number of banned cells. Next m lines each contain two space-separated integers. Specifically, the i-th of these lines contains numbers x_{i} and y_{i} (1 ≤ x_{i}, y_{i} ≤ n) — the coordinates of the i-th banned cell. All given cells are distinct.\\n\\nConsider the field rows numbered from top to bottom from 1 to n, and the columns — from left to right from 1 to n.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum points Gerald can earn in this game.\\n\\n\\n-----Examples-----\\nInput\\n3 1\\n2 2\\n\\nOutput\\n0\\n\\nInput\\n3 0\\n\\nOutput\\n1\\n\\nInput\\n4 3\\n3 1\\n3 2\\n3 3\\n\\nOutput\\n1\\n\\n\\n\\n-----Note-----\\n\\nIn the first test the answer equals zero as we can't put chips into the corner cells.\\n\\nIn the second sample we can place one chip into either cell (1, 2), or cell (3, 2), or cell (2, 1), or cell (2, 3). We cannot place two chips.\\n\\nIn the third sample we can only place one chip into either cell (2, 1), or cell (2, 4).\",\"targets\":\"I=input\\nn,m=list(map(int,I().split()))\\nb=[1]*n*2\\nb[0]=b[n-1]=b[n]=b[2*n-1]=0\\nfor i in range(m):\\n    r,c=list(map(int,I().split()))\\n    b[r-1]=b[n+c-1]=0\\nif n%2 and b[n\\/\\/2] and b[n+n\\/\\/2]:b[n\\/\\/2]=0\\nprint(sum(b))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGenerous sponsors of the olympiad in which Chloe and Vladik took part allowed all the participants to choose a prize for them on their own. Christmas is coming, so sponsors decided to decorate the Christmas tree with their prizes. \\n\\nThey took n prizes for the contestants and wrote on each of them a unique id (integer from 1 to n). A gift i is characterized by integer a_{i} — pleasantness of the gift. The pleasantness of the gift can be positive, negative or zero. Sponsors placed the gift 1 on the top of the tree. All the other gifts hung on a rope tied to some other gift so that each gift hung on the first gift, possibly with a sequence of ropes and another gifts. Formally, the gifts formed a rooted tree with n vertices.\\n\\nThe prize-giving procedure goes in the following way: the participants come to the tree one after another, choose any of the remaining gifts and cut the rope this prize hang on. Note that all the ropes which were used to hang other prizes on the chosen one are not cut. So the contestant gets the chosen gift as well as the all the gifts that hang on it, possibly with a sequence of ropes and another gifts.\\n\\nOur friends, Chloe and Vladik, shared the first place on the olympiad and they will choose prizes at the same time! To keep themselves from fighting, they decided to choose two different gifts so that the sets of the gifts that hang on them with a sequence of ropes and another gifts don't intersect. In other words, there shouldn't be any gift that hang both on the gift chosen by Chloe and on the gift chosen by Vladik. From all of the possible variants they will choose such pair of prizes that the sum of pleasantness of all the gifts that they will take after cutting the ropes is as large as possible.\\n\\nPrint the maximum sum of pleasantness that Vladik and Chloe can get. If it is impossible for them to choose the gifts without fighting, print Impossible.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 2·10^5) — the number of gifts.\\n\\nThe next line contains n integers...\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\noo = 10**20\\nn = int(input())\\na = list(map(int, input().split()))\\nadj = [[] for _ in range(n)]\\nfor _ in range(n-1):\\n    u, v = [int(i) - 1 for i in input().split()]\\n    adj[u].append(v)\\n    adj[v].append(u)\\nsm = [0] * n\\nmx = [-oo] * n\\nbest = [-oo] * n\\n\\ndef dfs(start):\\n    stack = [(start, -1)]\\n    visit = [False] * n\\n    while stack:\\n        u, p = stack[-1]\\n        if not visit[u]:\\n            for v in adj[u]:\\n                if v != p:\\n                    stack.append((v, u))\\n            visit[u] = True\\n        else:\\n            x = [-oo] * 3\\n            for v in adj[u]:\\n                if v != p:\\n                    sm[u] += sm[v]\\n                    mx[u] = max(mx[u], mx[v])\\n                    best[u] = max(best[u], best[v])\\n                    x[0] = mx[v]\\n                    x.sort()\\n            sm[u] += a[u]\\n            mx[u] = max(mx[u], sm[u])\\n            if x[1] > -oo and x[2] > -oo:\\n                cur = x[1] + x[2]\\n                best[u] = max(best[u], cur)\\n            stack.pop()\\n\\ndfs(0)\\nans = max(best)\\nif ans <= -oo:\\n    print('Impossible')\\nelse:\\n    print(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAs you probably know, Fibonacci sequence are the numbers in the following integer sequence:\\n1, 1, 2, 3, 5, 8, 13...\\nWrite a method that takes the index as an argument and returns last digit from fibonacci number. Example:\\n  getLastDigit(15) - 610. Your method must return 0 because the last digit of 610 is 0.\\nFibonacci sequence grows very fast and value can take very big numbers (bigger than integer type can contain), so, please, be careful with overflow.\\n\\n[Hardcore version of this kata](http:\\/\\/www.codewars.com\\/kata\\/find-last-fibonacci-digit-hardcore-version), no bruteforce will work here ;)\",\"targets\":\"def get_last_digit(index):\\n    if index <= 2 : return 1\\n    x, y = 1, 1\\n    for i in range(index - 2):\\n        res = x + y\\n        x, y = y, res\\n    return res % 10\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTakahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \\\\ldots, Dish N) once.\\nThe i-th dish (1 \\\\leq i \\\\leq N) he ate was Dish A_i.\\nWhen he eats Dish i (1 \\\\leq i \\\\leq N), he gains B_i satisfaction points.\\nAdditionally, when he eats Dish i+1 just after eating Dish i (1 \\\\leq i \\\\leq N - 1), he gains C_i more satisfaction points.\\nFind the sum of the satisfaction points he gained.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 2 \\\\leq N \\\\leq 20\\n - 1 \\\\leq A_i \\\\leq N\\n - A_1, A_2, ..., A_N are all different.\\n - 1 \\\\leq B_i \\\\leq 50\\n - 1 \\\\leq C_i \\\\leq 50\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 A_2 ... A_N\\nB_1 B_2 ... B_N\\nC_1 C_2 ... C_{N-1}\\n\\n-----Output-----\\nPrint the sum of the satisfaction points Takahashi gained, as an integer.\\n\\n-----Sample Input-----\\n3\\n3 1 2\\n2 5 4\\n3 6\\n\\n-----Sample Output-----\\n14\\n\\nTakahashi gained 14 satisfaction points in total, as follows:\\n - First, he ate Dish 3 and gained 4 satisfaction points.\\n - Next, he ate Dish 1 and gained 2 satisfaction points.\\n - Lastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.\",\"targets\":\"N = int(input())\\nA = list((int(x) for x in input().split()))\\nB = list((int(x) for x in input().split()))\\nC = list((int(x) for x in input().split()))\\nbonus = 0\\nfor i in range(N-1):\\n  if A[i]+1 == A[i+1]:\\n    bonus += C[A[i]-1]\\nprint(sum(B)+bonus)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are $M$ levels for a building numbered from $1$ to $M$ from top to bottom, each level having $N$ parking spots numbered from $1$ to $N$ from left to right. Some spots might have a car while other may be empty, the information of which is given in form of two dimensional character array $C$ ($C_{i, j}$ denote parking spot at $j$-th position on $i$-th level).\\nThere is a thief who wants to unlock all the cars. Now, he is skilled such that for the first time, he can directly reach in any parking spot in no time. Basically he can reach the first car to be stolen in 0 time.\\nNow, he can move within the parking lot only in following manner, each taking 1 unit of time:\\n- Move down a level. That is, if current position is $(i, j)$, then he reaches $(i+1, j)$\\n- If current position is $(i, j)$ and if\\n- $i$ is odd, then he can move from $(i, j)$ to $(i, j+1)$\\n- $i$ is even, then he can move from $(i, j)$ to $(i, j-1)$\\nNote that he wants to unlock the cars in minimum time and the car is unlocked as soon as the thief reaches that parking spot.If the parking lot is empty, then the time taken is considered to be 0.  \\nFind the minimum time when all the cars would be unlocked. Note that once all cars are unlocked, the thief can escape instantly, so this time does not count.\\n\\n-----Input :-----\\n- The first line of input contains a single integer $T$ (number of test cases).\\n- First liine of each test case contains $M$ and $N$(number of levels and spots per each level)  \\n- Next $M$ line contains $N$ space separated characters $C_{i, 1}, C_{i, 2} \\\\ldots C_{i, N}$  where $(1\\\\leq i\\\\leq M)$ and $C_{i, j}$ is either $'P'$ or $'N'$ (without quotes).\\nIf the spot contains $'P'$, then a car is parked there. else, it’s not parked.\\n\\n-----Output :-----\\nFor each test case print a single integer, the minimum time in which thief can unlock all cars.\\n\\n-----Constraints :-----\\n- $1\\\\leq T \\\\leq100.$ \\n- $1\\\\leq M,N \\\\leq300$ \\n\\n-----Subtasks :-----\\n- \\nSubtask 1 (20 points): $1\\\\leq M \\\\leq2.$ \\n- \\nSubtask 2 (80 points): Original...\",\"targets\":\"for _ in range(int(input())):\\n \\n r,c=map(int,input().split())\\n \\n ans=0\\n \\n last=-1\\n flag=0\\n \\n cnt=0\\n check=1\\n \\n for i in range(r):\\n  \\n  j=0\\n  \\n  values=[]\\n  \\n  for car in input().split():\\n   \\n   if(car==\\\"P\\\"):\\n    values.append(j)\\n    \\n   j+=1\\n   \\n  #print(values)\\n  \\n  \\n  \\n  if(len(values)==0):\\n   if(flag==0):\\n    continue\\n    \\n   if(flag==check):\\n    \\n    cnt+=1\\n    if(i==r-1):\\n     ans-=1\\n    continue\\n    \\n   if(flag>check):\\n    check=flag\\n    ans+=cnt\\n    cnt=0\\n    continue\\n    \\n \\n  \\n  flag+=1\\n\\n  if(i%2==1):\\n\\n   ans+=abs(min(values)-max(values))+1\\n  \\n   if(i==r-1):\\n    ans-=1\\n\\n   if(last==-1):\\n    last=min(values)\\n   else:\\n    \\n    ans+=abs(last-max(values))\\n   \\n   last=min(values)\\n\\n  else:\\n   \\n   ans+=abs(max(values)-min(values))+1\\n   \\n   if(i==r-1):\\n    ans-=1\\n\\n   if(last==-1):\\n    last=max(values)\\n   else:\\n    ans+=abs(last-min(values))\\n\\n   last=max(values)\\n  #print(ans)\\n\\n\\n\\n\\n print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/VACCINE1:\\nIncreasing COVID cases have created panic amongst the people of Chefland, so the government is starting to push for production of a vaccine. It has to report to the media about the exact date when vaccines will be available.\\nThere are two companies which are producing vaccines for COVID. Company A starts producing vaccines on day $D_1$ and it can produce $V_1$ vaccines per day. Company B starts producing vaccines on day $D_2$ and it can produce $V_2$ vaccines per day. Currently, we are on day $1$.\\nWe need a total of $P$ vaccines. How many days are required to produce enough vaccines? Formally, find the smallest integer $d$ such that we have enough vaccines at the end of the day $d$.\\n\\n-----Input-----\\n- The first and only line of the input contains five space-separated integers $D_1$, $V_1$, $D_2$, $V_2$ and $P$.\\n\\n-----Output-----\\nPrint a single line containing one integer ― the smallest required number of days.\\n\\n-----Constraints-----\\n- $1 \\\\le D_1, V_1, D_2, V_2 \\\\le 100$\\n- $1 \\\\le P \\\\le 1,000$\\n\\n-----Subtasks-----\\nSubtask #1 (30 points): $D_1 = D_2$\\nSubtask #2 (70 points): original constraints\\n\\n-----Example Input 1-----\\n1 2 1 3 14\\n\\n-----Example Output 1-----\\n3\\n\\n-----Explanation-----\\nSince $D_1 = D_2 = 1$, we can produce $V_1 + V_2 = 5$ vaccines per day. In $3$ days, we produce $15$ vaccines, which satisfies our requirement of $14$ vaccines.\\n\\n-----Example Input 2-----\\n5 4 2 10 100\\n\\n-----Example Output 2-----\\n9\\n\\n-----Explanation-----\\nThere are $0$ vaccines produced on the first day, $10$ vaccines produced on each of days $2$, $3$ and $4$, and $14$ vaccines produced on the fifth and each subsequent day. In $9$ days, it makes a total of $0 + 10 \\\\cdot 3 + 14 \\\\cdot 5 = 100$ vaccines.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\ntry:\\n d1,v1,d2,v2,p=map(int, input().split())\\n total=0\\n while p>0:\\n  total+=1\\n  if total>=d1:\\n   p=p-v1\\n  if total>=d2:\\n   p=p-v2\\n print(total) \\nexcept:\\n pass\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.\\n\\nInitially the bus is empty. On each of $2n$ stops one passenger enters the bus. There are two types of passengers:   an introvert always chooses a row where both seats are empty. Among these rows he chooses the one with the smallest seats width and takes one of the seats in it;  an extrovert always chooses a row where exactly one seat is occupied (by an introvert). Among these rows he chooses the one with the largest seats width and takes the vacant place in it. \\n\\nYou are given the seats width in each row and the order the passengers enter the bus. Determine which row each passenger will take.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\le n \\\\le 200\\\\,000$) — the number of rows in the bus.\\n\\nThe second line contains the sequence of integers $w_1, w_2, \\\\dots, w_n$ ($1 \\\\le w_i \\\\le 10^{9}$), where $w_i$ is the width of each of the seats in the $i$-th row. It is guaranteed that all $w_i$ are distinct.\\n\\nThe third line contains a string of length $2n$, consisting of digits '0' and '1' — the description of the order the passengers enter the bus. If the $j$-th character is '0', then the passenger that enters the bus on the $j$-th stop is an introvert. If the $j$-th character is '1', the the passenger that enters the bus on the $j$-th stop is an extrovert. It is guaranteed that the number of extroverts equals the number of introverts (i. e. both numbers equal $n$), and for each extrovert there always is a suitable row.\\n\\n\\n-----Output-----\\n\\nPrint $2n$ integers — the rows the passengers will take. The order of passengers should be the same as in input.\\n\\n\\n-----Examples-----\\nInput\\n2\\n3 1\\n0011\\n\\nOutput\\n2 1 1 2 \\n\\nInput\\n6\\n10 8 9 11 13 5\\n010010011101\\n\\nOutput\\n6 6 2 3 3 1 4 4 1 2 5 5 \\n\\n\\n\\n-----Note-----\\n\\nIn the first example the first passenger (introvert) chooses the row $2$, because it has the seats with smallest width. The second...\",\"targets\":\"input()\\nintro = sorted([(-x,i+1) for i,x in enumerate(map(int, input().split()))])\\nextro = []\\nline = input()\\nsol = []\\nfor c in line:\\n    if c == '0':\\n        w, r = intro.pop()\\n        extro.append((w, r))\\n        sol.append(str(r))\\n    else:\\n        w, r = extro.pop()\\n        sol.append(str(r))\\nprint(' '.join(sol))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/404\\/D:\\nGame \\\"Minesweeper 1D\\\" is played on a line of squares, the line's height is 1 square, the line's width is n squares. Some of the squares contain bombs. If a square doesn't contain a bomb, then it contains a number from 0 to 2 — the total number of bombs in adjacent squares.\\n\\nFor example, the correct field to play looks like that: 001*2***101*. The cells that are marked with \\\"*\\\" contain bombs. Note that on the correct field the numbers represent the number of bombs in adjacent cells. For example, field 2* is not correct, because cell with value 2 must have two adjacent cells with bombs.\\n\\nValera wants to make a correct field to play \\\"Minesweeper 1D\\\". He has already painted a squared field with width of n cells, put several bombs on the field and wrote numbers into some cells. Now he wonders how many ways to fill the remaining cells with bombs and numbers are there if we should get a correct field in the end.\\n\\n\\n-----Input-----\\n\\nThe first line contains sequence of characters without spaces s_1s_2... s_{n} (1 ≤ n ≤ 10^6), containing only characters \\\"*\\\", \\\"?\\\" and digits \\\"0\\\", \\\"1\\\" or \\\"2\\\". If character s_{i} equals \\\"*\\\", then the i-th cell of the field contains a bomb. If character s_{i} equals \\\"?\\\", then Valera hasn't yet decided what to put in the i-th cell. Character s_{i}, that is equal to a digit, represents the digit written in the i-th square.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the number of ways Valera can fill the empty cells and get a correct field.\\n\\nAs the answer can be rather large, print it modulo 1000000007 (10^9 + 7).\\n\\n\\n-----Examples-----\\nInput\\n?01???\\n\\nOutput\\n4\\n\\nInput\\n?\\n\\nOutput\\n2\\n\\nInput\\n**12\\n\\nOutput\\n0\\n\\nInput\\n1\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first test sample you can get the following correct fields: 001**1, 001***, 001*2*, 001*10.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"s=input()\\nn=len(s)\\na,b,c,d=1,0,0,0\\nfor i in range(0,n):\\n    if s[i]=='*':\\n        a,b,c,d=0,(a+b+d)% 1000000007,0,0\\n    elif s[i]=='?':\\n        a,b,c,d=(a+b+c)% 1000000007,(a+b+d)% 1000000007,0,0\\n    elif s[i]=='0':\\n        a,b,c,d=0,0,(a+c)% 1000000007,0\\n    elif s[i]=='1':\\n        a,b,c,d=0,0,b,(a+c)% 1000000007\\n    else:\\n        a,b,c,d=0,0,0,(b+d)% 1000000007\\nprint((a+b+c)% 1000000007)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWrite a function called `sumIntervals`\\/`sum_intervals()` that accepts an array of intervals, and returns the sum of all the interval lengths. Overlapping intervals should only be counted once.\\n\\n### Intervals\\n\\nIntervals are represented by a pair of integers in the form of an array. The first value of the interval will always be less than the second value. Interval example: `[1, 5]` is an interval from 1 to 5. The length of this interval is 4.\\n\\n### Overlapping Intervals\\n\\nList containing overlapping intervals:\\n\\n```\\n[\\n   [1,4],\\n   [7, 10],\\n   [3, 5]\\n]\\n```\\n\\nThe sum of the lengths of these intervals is 7. Since [1, 4] and [3, 5] overlap, we can treat the interval as [1, 5], which has a length of 4.\\n\\n### Examples:\\n\\n```C#\\n\\/\\/ empty intervals\\nIntervals.SumIntervals(new (int, int)[]{ });  \\/\\/ => 0\\nIntervals.SumIntervals(new (int, int)[]{ (2, 2), (5, 5)});  \\/\\/ => 0\\n\\n\\/\\/ disjoined intervals\\nIntervals.SumIntervals(new (int, int)[]{\\n  (1, 2), (3, 5)\\n});  \\/\\/ => (2-1) + (5-3) = 3\\n\\n\\/\\/ overlapping intervals\\nIntervals.SumIntervals(new (int, int)[]{\\n  (1, 4), (3, 6), (2, 8)\\n});  \\/\\/ (1,8) => 7\\n```\",\"targets\":\"def sum_of_intervals(intervals):\\n    total = set()\\n    for x,y in intervals:\\n        for i in range(x,y):\\n            total.add(i)    \\n    return(len(total))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5552101f47fc5178b1000050:\\nSome numbers have funny properties. For example:\\n\\n> 89 --> 8¹ + 9² = 89 * 1\\n\\n> 695 --> 6² + 9³ + 5⁴= 1390 = 695 * 2\\n\\n> 46288 --> 4³ + 6⁴+ 2⁵ + 8⁶ + 8⁷ = 2360688 = 46288 * 51\\n\\nGiven a positive integer n written as abcd... (a, b, c, d... being digits) and a positive integer p \\n- we want to find a positive integer k, if it exists, such as the sum of the digits of n taken to the successive powers of p is equal to k * n. \\n\\nIn other words:\\n\\n> Is there an integer k such as : (a ^ p + b ^ (p+1) + c ^(p+2) + d ^ (p+3) + ...) = n * k\\n\\nIf it is the case we will return k, if not return -1.\\n\\n**Note**: n and p will always be given as strictly positive integers.\\n\\n```python\\ndig_pow(89, 1) should return 1 since 8¹ + 9² = 89 = 89 * 1\\ndig_pow(92, 1) should return -1 since there is no k such as 9¹ + 2² equals 92 * k\\ndig_pow(695, 2) should return 2 since 6² + 9³ + 5⁴= 1390 = 695 * 2\\ndig_pow(46288, 3) should return 51 since 4³ + 6⁴+ 2⁵ + 8⁶ + 8⁷ = 2360688 = 46288 * 51\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def dig_pow(n, p):\\n    digit_power = sum(int(x)**pw for pw,x in enumerate(str(n),p))\\n    if digit_power % n == 0:\\n        return digit_power \\/ n\\n    return -1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef has two piles of stones with him, one has n1 stones and the other has n2 stones. Fired up by boredom, he invented a game with the two piles.\\n\\nBefore the start of the game Chef chooses an integer m.\\n\\nIn the j-th move: \\n\\n-  He chooses a number xj such that 1 ≤ xj ≤ m, and removes xj stones from both the piles (this is only possible when both the piles have ≥ xj stones).\\n-  The number chosen must be unique over all the moves in the game. That is, for all k < j, xj ≠ xk. \\n\\nThe game stops when Chef is unable to make any more moves.\\n\\nChef wants to make the moves in such a way that the sum of the number of stones remaining in the two piles is minimized. Please help Chef find this.\\n\\n-----Input-----\\n- The first line of input contains an integer T denoting the number of test cases.\\n- Each test case consists of 1 line with three integers — n1, n2 and m — separated by single spaces.\\n\\n-----Output-----\\nFor each test case, output a single line containing the minimum sum of the number of stones of two piles.\\n\\n-----Constraints-----\\nSubtask 1 : (5 pts)\\n- 1 ≤ T ≤ 100\\n- 0 ≤ m ≤ 18\\n- 0 ≤ n1, n2 ≤ 100\\nSubtask 2 : (25 pts)\\n- 1 ≤ T ≤ 1000\\n- 0 ≤ m ≤ 10000\\n- 0 ≤ n1, n2 ≤ 10000\\nSubtask 3 : (70 pts)\\n- 1 ≤ T ≤ 105\\n- 0 ≤ m ≤ 109\\n- 0 ≤ n1, n2 ≤ 1018\\n\\n-----Example-----\\nInput:3\\n1 1 1\\n1 2 1\\n4 5 2\\n\\nOutput:0\\n1\\n3\\n\\n-----Explanation-----\\nExample case 1. : Remove 1 stone from each of the piles. Now 0 stones are remaining, so chef cannot remove any more stones from the piles. Hence, answer is 0+0 = 0\\nExample case 2. : Again, remove 1 stone from both the piles to get (0,1) stones. Now chef cannot remove any more stones from pile 1, so he stops. Hence, answer is 0+1 = 1.\\nExample case 3. : First remove 1 stone from both the piles to get (3,4) stones. Now, remove 2 stones from both the piles so that (1,2) stones are remaining. Now chef cannot remove any more stones owing to the condition that he cannot remove the same number of stones twice. So, the answer is 1+2 = 3.\",\"targets\":\"import sys\\n\\nn = int(sys.stdin.readline())\\n\\nfor _ in range(n):\\n p1, p2, m = list(map(int, sys.stdin.readline().split()))\\n\\n l = min(p1, p2)\\n\\n #while(m > 0 and l > 0):\\n #    k = min(l, m)\\n #    l -= k\\n #    m -= 1\\n\\n q = min(p1, p2)\\n d = min((m * (m + 1)) \\/ 2, q)\\n\\n print(p1 - d + p2 - d)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA subarray A[i], A[i+1], ..., A[j] of A is said to be turbulent if and only if:\\n\\nFor i <= k < j, A[k] > A[k+1] when k is odd, and A[k] < A[k+1] when k is even;\\nOR, for i <= k < j, A[k] > A[k+1] when k is even, and A[k] < A[k+1] when k is odd.\\n\\nThat is, the subarray is turbulent if the comparison sign flips between each adjacent pair of elements in the subarray.\\nReturn the length of a maximum size turbulent subarray of A.\\n \\n\\nExample 1:\\nInput: [9,4,2,10,7,8,8,1,9]\\nOutput: 5\\nExplanation: (A[1] > A[2] < A[3] > A[4] < A[5])\\n\\n\\nExample 2:\\nInput: [4,8,12,16]\\nOutput: 2\\n\\n\\nExample 3:\\nInput: [100]\\nOutput: 1\\n\\n\\n\\n\\n \\nNote:\\n\\n1 <= A.length <= 40000\\n0 <= A[i] <= 10^9\",\"targets\":\"class Solution:\\n    def maxTurbulenceSize(self, A: List[int]) -> int:\\n        def checksign(A, B):\\n            if A>B:\\n                return 1\\n            if A<B:\\n                return -1\\n            if A==B:\\n                return 0\\n        \\n        n=len(A)\\n        ans=1\\n        start=0\\n        for i in range(1, n):\\n            if checksign(A[i-1],A[i])==0:\\n                start=i\\n            if i==n-1:\\n                ans=max(ans, i-start+1)\\n                break\\n            if checksign(A[i-1],A[i])*checksign(A[i],A[i+1])!=-1:\\n                ans=max(ans,i-start+1)\\n                start=i\\n\\n        return ans\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA frog is initially at position $0$ on the number line. The frog has two positive integers $a$ and $b$. From a position $k$, it can either jump to position $k+a$ or $k-b$.\\n\\nLet $f(x)$ be the number of distinct integers the frog can reach if it never jumps on an integer outside the interval $[0, x]$. The frog doesn't need to visit all these integers in one trip, that is, an integer is counted if the frog can somehow reach it if it starts from $0$.\\n\\nGiven an integer $m$, find $\\\\sum_{i=0}^{m} f(i)$. That is, find the sum of all $f(i)$ for $i$ from $0$ to $m$.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers $m, a, b$ ($1 \\\\leq m \\\\leq 10^9, 1 \\\\leq a,b \\\\leq 10^5$).\\n\\n\\n-----Output-----\\n\\nPrint a single integer, the desired sum.\\n\\n\\n-----Examples-----\\nInput\\n7 5 3\\n\\nOutput\\n19\\n\\nInput\\n1000000000 1 2019\\n\\nOutput\\n500000001500000001\\n\\nInput\\n100 100000 1\\n\\nOutput\\n101\\n\\nInput\\n6 4 5\\n\\nOutput\\n10\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, we must find $f(0)+f(1)+\\\\ldots+f(7)$. We have $f(0) = 1, f(1) = 1, f(2) = 1, f(3) = 1, f(4) = 1, f(5) = 3, f(6) = 3, f(7) = 8$. The sum of these values is $19$.\\n\\nIn the second example, we have $f(i) = i+1$, so we want to find $\\\\sum_{i=0}^{10^9} i+1$.\\n\\nIn the third example, the frog can't make any jumps in any case.\",\"targets\":\"from math import gcd\\nm, a, b = list(map(int, input().split()))\\nlast, x = 0, gcd(a, b)\\ns = [1]*(a+b+1)\\nq1, ans = 0, 1\\nmax1, s[0] = [[0, 1]], 0\\nwhile q1 < a+b:\\n    if q1 > b and s[q1-b]:\\n        ans += 1\\n        q1 -= b\\n        s[q1] = 0\\n    else:\\n        q1 += a\\n        if q1 > last:\\n            max1.append([q1, ans])\\n            last = q1\\n        if s[q1]:\\n            ans += 1\\n            s[q1] = 0\\nans1 = q1 = 0\\nfor q in range(min(m+1, a+b)):\\n    if max1[q1+1][0] == q:\\n        q1 += 1\\n    ans1 += max1[q1+1][1]\\nif m >= a+b:\\n    ans1 += (m\\/\\/x+1)*(m % x+1)\\n    m -= m % x+1\\n    p, t = (a+b)\\/\\/x, (m-a-b)\\/\\/x\\n    ans1 += (t+1)*(t+2)\\/\\/2*x\\n    ans1 += p*(t+1)*x\\nprint(ans1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLittle Artem likes electronics. He can spend lots of time making different schemas and looking for novelties in the nearest electronics store. The new control element was delivered to the store recently and Artem immediately bought it.\\n\\nThat element can store information about the matrix of integers size n × m. There are n + m inputs in that element, i.e. each row and each column can get the signal. When signal comes to the input corresponding to some row, this row cyclically shifts to the left, that is the first element of the row becomes last element, second element becomes first and so on. When signal comes to the input corresponding to some column, that column shifts cyclically to the top, that is first element of the column becomes last element, second element becomes first and so on. Rows are numbered with integers from 1 to n from top to bottom, while columns are numbered with integers from 1 to m from left to right.\\n\\nArtem wants to carefully study this element before using it. For that purpose he is going to set up an experiment consisting of q turns. On each turn he either sends the signal to some input or checks what number is stored at some position of the matrix.\\n\\nArtem has completed his experiment and has written down the results, but he has lost the chip! Help Artem find any initial matrix that will match the experiment results. It is guaranteed that experiment data is consistent, which means at least one valid matrix exists.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers n, m and q (1 ≤ n, m ≤ 100, 1 ≤ q ≤ 10 000) — dimensions of the matrix and the number of turns in the experiment, respectively.\\n\\nNext q lines contain turns descriptions, one per line. Each description starts with an integer t_{i} (1 ≤ t_{i} ≤ 3) that defines the type of the operation. For the operation of first and second type integer r_{i} (1 ≤ r_{i} ≤ n) or c_{i} (1 ≤ c_{i} ≤ m) follows, while for the operations of the third type three integers r_{i}, c_{i} and x_{i} (1 ≤ r_{i} ≤ n, 1 ≤ c_{i} ≤ m,  -...\",\"targets\":\"n, m, q = map(int, input().split())\\nqueries = [tuple(map(lambda x: int(x) - 1, input().split())) for i in range(q)]\\nmatrix = [[0]*m for i in range(n)]\\nwhile queries:\\n    query = queries.pop()\\n    if query[0] == 0:\\n        row = [matrix[query[1]][-1]]\\n        row.extend(matrix[query[1]][:-1])\\n        matrix[query[1]] = row\\n    elif query[0] == 1:\\n        cell = matrix[n-1][query[1]]\\n        for i in range(n):\\n            matrix[i][query[1]], cell = cell, matrix[i][query[1]]\\n    else:\\n        matrix[query[1]][query[2]] = query[3] + 1\\n[print(*row) for row in matrix]\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5416fac7932c1dcc4f0006b4:\\nGeneral primality test are often computationally expensive, so in the biggest prime number race the idea is to study special sub-families of prime number and develop more effective tests for them. \\n\\n[Mersenne Primes](https:\\/\\/en.wikipedia.org\\/wiki\\/Mersenne_prime) are prime numbers of the form: Mn = 2^(n) - 1. So far, 49 of them was found between M2 (3) and M74,207,281 which contains 22,338,618 digits and is (by September 2015) the biggest known prime. It has been found by GIMPS (Great Internet Mersenne Prime Search), wich use the test srudied here. (plus heuristics mentionned below)\\n\\nLucas and Lehmer have developed a [simple test](https:\\/\\/en.wikipedia.org\\/wiki\\/Lucas%E2%80%93Lehmer_primality_test) for Mersenne primes: \\n\\n> for `p` (an odd prime), the Mersenne number Mp is prime if and only if `S(p − 1) = 0 mod Mp`,\\n\\n>where `S(n + 1) = S(n) * S(n) − 2` and `S(1) = 4`\\n\\nThe goal of this kata is to implement this test. Given an integer `>=2`, the program should calculate the sequence `S(n)` up to `p-1` and calculate the remainder modulo `Mp`, then return `True` or `False` as a result of the test. The case `n = 2` should return `True`.\\n\\nYou should take advantage of the fact that:\\n\\n```k = (k mod 2^n + floor(k\\/2^n)) mod Mn```\\n\\nOr in other words, if we take the least significant `n` bits of `k`, and add the remaining bits of `k`, and then do this repeatedly until at most `n` bits remain, we can compute the remainder after dividing `k` by the Mersenne number `2^n−1` without using division.\\n\\nThis test can be improved using the fact that if `n` is not prime, `2^n-1` will not be prime. So in theory you can test for the primality of `n` beforehand. But in practice the test for the primality of `n` will rapidly outgrow in difficulty the Lucas-Lehmer test. So we can only use heuristics to rule out `n` with small factors but not complete factorization algorithm. You don't need to implement such heuristics here. \\n\\nThe rapid growth of `s^2` makes javascript reach its integer limit quickly (coherent result for `n = 13`, but not...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# I mean, if you say we found less than 50 of them, there's no point in computing them again\\nlucas_lehmer = {2, 3, 5, 7, 13, 17, 19, 31, 61, 89,\\n                107, 127, 521, 607, 1279, 2203, 2281,\\n                3217, 4253, 4423, 9689, 9941, 11213, 19937,\\n                21701, 23209, 44497, 86243, 110503, 132049,\\n                216091, 756839, 859433, 1257787, 1398269,\\n                2976221, 3021377, 6972593, 13466917, 20996011,\\n                24036583, 25964951, 30402457, 32582657, 37156667,\\n                42643801, 43112609}.__contains__\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven two positive integers n and k.\\nA factor of an integer n is defined as an integer i where n % i == 0.\\nConsider a list of all factors of n sorted in ascending order, return the kth factor in this list or return -1 if n has less than k factors.\\n \\nExample 1:\\nInput: n = 12, k = 3\\nOutput: 3\\nExplanation: Factors list is [1, 2, 3, 4, 6, 12], the 3rd factor is 3.\\n\\nExample 2:\\nInput: n = 7, k = 2\\nOutput: 7\\nExplanation: Factors list is [1, 7], the 2nd factor is 7.\\n\\nExample 3:\\nInput: n = 4, k = 4\\nOutput: -1\\nExplanation: Factors list is [1, 2, 4], there is only 3 factors. We should return -1.\\n\\nExample 4:\\nInput: n = 1, k = 1\\nOutput: 1\\nExplanation: Factors list is [1], the 1st factor is 1.\\n\\nExample 5:\\nInput: n = 1000, k = 3\\nOutput: 4\\nExplanation: Factors list is [1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000].\\n\\n \\nConstraints:\\n\\n1 <= k <= n <= 1000\",\"targets\":\"class Solution:\\n    def kthFactor(self, n: int, k: int) -> int:\\n        i = 0\\n        for j in range(1, n + 1):\\n            if n%j == 0:\\n                i += 1\\n            if i == k:\\n                return j\\n        return -1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFor the given integer $n$ ($n > 2$) let's write down all the strings of length $n$ which contain $n-2$ letters 'a' and two letters 'b' in lexicographical (alphabetical) order.\\n\\nRecall that the string $s$ of length $n$ is lexicographically less than string $t$ of length $n$, if there exists such $i$ ($1 \\\\le i \\\\le n$), that $s_i < t_i$, and for any $j$ ($1 \\\\le j < i$) $s_j = t_j$. The lexicographic comparison of strings is implemented by the operator < in modern programming languages.\\n\\nFor example, if $n=5$ the strings are (the order does matter):  aaabb  aabab  aabba  abaab  ababa  abbaa  baaab  baaba  babaa  bbaaa \\n\\nIt is easy to show that such a list of strings will contain exactly $\\\\frac{n \\\\cdot (n-1)}{2}$ strings.\\n\\nYou are given $n$ ($n > 2$) and $k$ ($1 \\\\le k \\\\le \\\\frac{n \\\\cdot (n-1)}{2}$). Print the $k$-th string from the list.\\n\\n\\n-----Input-----\\n\\nThe input contains one or more test cases.\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases in the test. Then $t$ test cases follow.\\n\\nEach test case is written on the the separate line containing two integers $n$ and $k$ ($3 \\\\le n \\\\le 10^5, 1 \\\\le k \\\\le \\\\min(2\\\\cdot10^9, \\\\frac{n \\\\cdot (n-1)}{2})$.\\n\\nThe sum of values $n$ over all test cases in the test doesn't exceed $10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case print the $k$-th string from the list of all described above strings of length $n$. Strings in the list are sorted lexicographically (alphabetically).\\n\\n\\n-----Example-----\\nInput\\n7\\n5 1\\n5 2\\n5 8\\n5 10\\n3 1\\n3 2\\n20 100\\n\\nOutput\\naaabb\\naabab\\nbaaba\\nbbaaa\\nabb\\nbab\\naaaaabaaaaabaaaaaaaa\",\"targets\":\"def calc(n, k):\\n    k -= 1\\n    a, b = 0, 1\\n    for i in range(1, n + 2):\\n        if k - i >= 0:\\n            k -= i\\n            b += 1\\n        else:\\n            break\\n    a += k\\n    return \\\"\\\".join([\\\"b\\\" if i == a or i == b else \\\"a\\\" for i in range(n)[::-1]])\\n\\nT = int(input())\\nfor _ in range(T):\\n    n, k = list(map(int, input().split()))\\n    print(calc(n, k))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55b4d87a3766d9873a0000d4:\\nI always thought that my old friend John was rather richer than he looked, but I never knew exactly how much money he actually had. One day (as I was plying him with questions) he said:\\n\\n* \\\"Imagine I have between `m` and `n` Zloty...\\\" (or did he say Quetzal? I can't remember!)\\n* \\\"If I were to buy **9** cars costing `c` each, I'd only have 1 Zloty (or was it Meticals?) left.\\\"\\n* \\\"And if I were to buy **7** boats at `b` each, I'd only have 2 Ringglets (or was it Zloty?) left.\\\"\\n\\nCould you tell me in each possible case:\\n\\n1. how much money `f` he could possibly have ?\\n2. the cost `c` of a car?\\n3. the cost `b` of a boat?\\n\\nSo, I will have a better idea about his fortune. Note that if `m-n` is big enough, you might have a lot of possible answers. \\n\\nEach answer should be given as `[\\\"M: f\\\", \\\"B: b\\\", \\\"C: c\\\"]` and all the answers as `[ [\\\"M: f\\\", \\\"B: b\\\", \\\"C: c\\\"], ... ]`. \\\"M\\\" stands for money, \\\"B\\\" for boats, \\\"C\\\" for cars.\\n\\n**Note:** `m, n, f, b, c` are positive integers, where `0 <= m <= n` or `m >= n >= 0`. `m` and `n` are inclusive.\\n\\n\\n## Examples:\\n```\\nhowmuch(1, 100)      => [[\\\"M: 37\\\", \\\"B: 5\\\", \\\"C: 4\\\"], [\\\"M: 100\\\", \\\"B: 14\\\", \\\"C: 11\\\"]]\\nhowmuch(1000, 1100)  => [[\\\"M: 1045\\\", \\\"B: 149\\\", \\\"C: 116\\\"]]\\nhowmuch(10000, 9950) => [[\\\"M: 9991\\\", \\\"B: 1427\\\", \\\"C: 1110\\\"]]\\nhowmuch(0, 200)      => [[\\\"M: 37\\\", \\\"B: 5\\\", \\\"C: 4\\\"], [\\\"M: 100\\\", \\\"B: 14\\\", \\\"C: 11\\\"], [\\\"M: 163\\\", \\\"B: 23\\\", \\\"C: 18\\\"]]\\n```\\n\\nExplanation of the results for `howmuch(1, 100)`:\\n\\n* In the first answer his possible fortune is **37**:\\n * so he can buy 7 boats each worth 5: `37 - 7 * 5 = 2`\\n * or he can buy 9 cars worth 4 each: `37 - 9 * 4 = 1`\\n* The second possible answer is **100**:\\n * he can buy 7 boats each worth 14: `100 - 7 * 14 = 2`\\n * or he can buy 9 cars worth 11: `100 - 9 * 11 = 1`\\n\\n# Note\\nSee \\\"Sample Tests\\\" to know the format of the return.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def howmuch(m, n):\\n    i = min(m, n)\\n    j = max(m, n)\\n    res = []\\n    while (i <= j):\\n        if ((i % 9 == 1) and (i %7 == 2)):\\n            res.append([\\\"M: \\\" + str(i), \\\"B: \\\" + str(i \\/\\/ 7), \\\"C: \\\" + str(i \\/\\/ 9)])\\n        i += 1\\n    return res\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5888514674b58e929a000036:\\n# Task\\n Consider the following ciphering algorithm:\\n```\\nFor each character replace it with its code.\\nConcatenate all of the obtained numbers.\\n```\\nGiven a ciphered string, return the initial one if it is known that it consists only of lowercase letters.\\n\\n Note: here the character's code means its `decimal ASCII code`, the numerical representation of a character used by most modern programming languages.\\n\\n# Example\\n\\n For `cipher = \\\"10197115121\\\"`, the output should be `\\\"easy\\\"`.\\n\\n Explanation: \\n ```\\n charCode('e') = 101, \\n charCode('a') = 97, \\n charCode('s') = 115 \\n charCode('y') = 121.\\n```\\n# Input\\/Output\\n\\n\\n - `[input]` string `cipher`\\n\\n   A non-empty string which is guaranteed to be a cipher for some other string of lowercase letters.\\n\\n\\n - `[output]` a string\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def decipher(cipher):\\n    s = ''\\n    while cipher != '':\\n        if int(cipher[:3]) <= 122:\\n            s +=  chr(int(cipher[:3]))\\n            cipher = cipher[3:]\\n        else:\\n            s += chr(int(cipher[:2]))\\n            cipher = cipher[2:]\\n    return s\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/JUNE16\\/problems\\/CHEARMY:\\nThe Head Chef is receiving a lot of orders for cooking the best of the problems lately. For this, he organized an hiring event to hire some talented Chefs. He gave the following problem to test the skills of the participating Chefs. Can you solve this problem and be eligible for getting hired by Head Chef.\\n\\nA non-negative number n is said to be magical if it satisfies the following property. Let S denote the multi-set of numbers corresponding to the non-empty subsequences of the digits of the number n in decimal representation. Please note that the numbers in the set S can have leading zeros. Let us take an element s of the multi-set S, prod(s) denotes the product of all the digits of number s in decimal representation. \\nThe number n will be called magical if sum of prod(s) for all elements s in S, is even. \\n\\nFor example, consider a number 246, its all possible non-empty subsequence will be S = {2, 4, 6, 24, 46, 26, 246}. Products of digits of these subsequences will be {prod(2) = 2, prod(4) = 4, prod(6) = 6, prod(24) = 8, prod(46) = 24, prod(26) = 12, prod(246) = 48, i.e. {2, 4, 6, 8, 24, 12, 48}. Sum of all of these is 104, which is even. Hence 246 is a magical number.\\n\\nPlease note that multi-set S can contain repeated elements, e.g. if number is 55, then S = {5, 5, 55}. Products of digits of these subsequences will be {prod(5) = 5, prod(5) = 5, prod(55) = 25}, i.e. {5, 5, 25}. Sum of all of these is 35 which is odd. Hence 55 is not a \\nmagical number.\\n\\nConsider a number 204, then S = {2, 0, 4, 20, 04, 24, 204}. Products of digits of these subsequences will be {2, 0, 4, 0, 0, 8, 0}. Sum of all these elements will be 14 which is even. So 204 is a magical number.\\n\\nThe task was to simply find the Kth magical number.\\n\\n-----Input-----\\n- First line of the input contains an integer T denoting the number of test cases.\\n- Each of the next T lines contains a single integer K.\\n\\n-----Output-----\\nFor each test case, print a single integer corresponding to the Kth magical number.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 105\\n- 1 ≤...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\ndef answer(n):\\n    n-=1\\n    if n>0:\\n        a=int(math.log(n,5))\\n    else:\\n        a=0\\n    total=0\\n    while a!=0:\\n        x=math.pow(5,a)\\n        g=n\\/\\/x\\n        n=int(n%x)\\n        total+=2*math.pow(10,a)*g\\n        if n>0:\\n            a=int(math.log(n,5))\\n        else:\\n            a=0\\n    total+=2*(n)\\n    total=int(total)\\n    return total\\nT=int(input(''))\\nwhile T:\\n    T-=1\\n    n=int(input(''))\\n    print(answer(n))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1154\\/E:\\nThere are $n$ students standing in a row. Two coaches are forming two teams — the first coach chooses the first team and the second coach chooses the second team.\\n\\nThe $i$-th student has integer programming skill $a_i$. All programming skills are distinct and between $1$ and $n$, inclusive.\\n\\nFirstly, the first coach will choose the student with maximum programming skill among all students not taken into any team, and $k$ closest students to the left of him and $k$ closest students to the right of him (if there are less than $k$ students to the left or to the right, all of them will be chosen). All students that are chosen leave the row and join the first team. Secondly, the second coach will make the same move (but all students chosen by him join the second team). Then again the first coach will make such move, and so on. This repeats until the row becomes empty (i. e. the process ends when each student becomes to some team).\\n\\nYour problem is to determine which students will be taken into the first team and which students will be taken into the second team.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $k$ ($1 \\\\le k \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of students and the value determining the range of chosen students during each move, respectively.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le n$), where $a_i$ is the programming skill of the $i$-th student. It is guaranteed that all programming skills are distinct.\\n\\n\\n-----Output-----\\n\\nPrint a string of $n$ characters; $i$-th character should be 1 if $i$-th student joins the first team, or 2 otherwise.\\n\\n\\n-----Examples-----\\nInput\\n5 2\\n2 4 5 3 1\\n\\nOutput\\n11111\\n\\nInput\\n5 1\\n2 1 3 5 4\\n\\nOutput\\n22111\\n\\nInput\\n7 1\\n7 2 1 3 5 4 6\\n\\nOutput\\n1121122\\n\\nInput\\n5 1\\n2 4 5 3 1\\n\\nOutput\\n21112\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the first coach chooses the student on a position $3$, and the row becomes empty (all students join the first team).\\n\\nIn the second example the first coach chooses the student on...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, k = map(int, input().split())\\n\\nlst = map(int, input().split())\\n\\ndef debug():\\n\\n\\tprint('-')\\n\\tlst = [0 for _ in range(n)]\\n\\tfor i in range(n):\\n\\t\\tnode = table[i]\\n\\t\\tlst[node.index] = node.team\\n\\n\\tprint (''.join(str(x) for x in lst))\\n\\tprint('-')\\n\\nclass Node:\\n\\n\\tdef __init__(self, index):\\n\\t\\tself.index = index\\n\\t\\tself.team = 0 \\n\\t\\tself.prev = None\\n\\t\\tself.next = None\\n\\ntable = [None for _ in range(n)]\\n\\nprev_node = None\\nfor index, element in enumerate(lst):\\n\\n\\tnode = Node(index)\\n\\n\\tif prev_node:\\n\\t\\tprev_node.next = node\\n\\n\\tnode.prev = prev_node\\n\\n\\ttable[element - 1] = node\\n\\tprev_node = node\\n\\nteam = 1\\nfor i in reversed(range(n)):\\n\\n\\t# taken\\n\\tif table[i].team != 0:\\n\\t\\tcontinue\\n\\n\\tnode = table[i]\\n\\tnode.team = team\\n\\n\\tnext_node = node.next\\n\\tfor j in range(k):\\n\\n\\t\\tif next_node is None:\\n\\t\\t\\tbreak\\n\\n\\t\\tnext_node.team = team\\n\\t\\tnext_node = next_node.next\\n\\n\\tprev_node = node.prev\\n\\tfor j in range(k):\\n\\n\\t\\tif prev_node is None:\\n\\t\\t\\tbreak\\n\\n\\t\\tprev_node.team = team\\n\\t\\tprev_node = prev_node.prev\\n\\n\\tif prev_node is not None:\\n\\t\\tprev_node.next = next_node\\n\\n\\tif next_node is not None:\\n\\t\\tnext_node.prev = prev_node\\n\\n\\tteam = 1 if team == 2 else 2\\n\\nlst = [0 for _ in range(n)]\\nfor i in range(n):\\n\\tnode = table[i]\\n\\tlst[node.index] = node.team\\n\\nprint (''.join(str(x) for x in lst))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWill you make it?\\n\\nYou were camping with your friends far away from home, but when it's time to go back, you realize that your fuel is running out and the nearest pump is ```50``` miles away! You know that on average, your car runs on about ```25``` miles per gallon. There are ```2``` gallons left. Considering these factors, write a function that tells you if it is possible to get to the pump or not. Function should return ``true`` (`1` in Prolog) if it is possible and ``false`` (`0` in Prolog) if not.\\nThe input values are always positive.\",\"targets\":\"def zero_fuel(distance_to_pump, mpg, fuel_left):\\n    diff = mpg * fuel_left\\n    if distance_to_pump <= diff:\\n        return True\\n    else:\\n        return False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVova, the Ultimate Thule new shaman, wants to build a pipeline. As there are exactly n houses in Ultimate Thule, Vova wants the city to have exactly n pipes, each such pipe should be connected to the water supply. A pipe can be connected to the water supply if there's water flowing out of it. Initially Vova has only one pipe with flowing water. Besides, Vova has several splitters.\\n\\nA splitter is a construction that consists of one input (it can be connected to a water pipe) and x output pipes. When a splitter is connected to a water pipe, water flows from each output pipe. You can assume that the output pipes are ordinary pipes. For example, you can connect water supply to such pipe if there's water flowing out from it. At most one splitter can be connected to any water pipe. [Image] The figure shows a 4-output splitter \\n\\nVova has one splitter of each kind: with 2, 3, 4, ..., k outputs. Help Vova use the minimum number of splitters to build the required pipeline or otherwise state that it's impossible.\\n\\nVova needs the pipeline to have exactly n pipes with flowing out water. Note that some of those pipes can be the output pipes of the splitters.\\n\\n\\n-----Input-----\\n\\nThe first line contains two space-separated integers n and k (1 ≤ n ≤ 10^18, 2 ≤ k ≤ 10^9).\\n\\nPlease, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum number of splitters needed to build the pipeline. If it is impossible to build a pipeline with the given splitters, print -1.\\n\\n\\n-----Examples-----\\nInput\\n4 3\\n\\nOutput\\n2\\n\\nInput\\n5 5\\n\\nOutput\\n1\\n\\nInput\\n8 4\\n\\nOutput\\n-1\",\"targets\":\"import math\\nfrom decimal import Decimal\\n\\ndef sum2(s, e):\\n    return sum1(e) - sum1(s - 1) - (e - s)\\n\\ndef sum1(i):\\n    return i * (i + 1) \\/ 2\\n\\nline = input().split()\\nn = Decimal(line[0])\\nk = Decimal(line[1])\\nif(n == 1):\\n    print(0)\\nelif(k > n):\\n    print(1)\\nelif(sum2(Decimal(2),k) < n):\\n    print(-1)\\nelse:\\n    c = 2 * n + k - k * k\\n    discriminant = (9 - 4 * c).sqrt()\\n    tmp = discriminant \\/ 2\\n    const = Decimal(3\\/2)\\n    res1 = math.floor(const + tmp)\\n    res2 = math.floor(const - tmp)\\n    res1 = max(res1, res2)\\n    print(k - res1 + 1);\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/491\\/A:\\nHiking club \\\"Up the hill\\\" just returned from a walk. Now they are trying to remember which hills they've just walked through.\\n\\nIt is known that there were N stops, all on different integer heights between 1 and N kilometers (inclusive) above the sea level. On the first day they've traveled from the first stop to the second stop, on the second day they've traveled from the second to the third and so on, and on the last day they've traveled from the stop N - 1 to the stop N and successfully finished their expedition.\\n\\nThey are trying to find out which heights were their stops located at. They have an entry in a travel journal specifying how many days did they travel up the hill, and how many days did they walk down the hill.\\n\\nHelp them by suggesting some possible stop heights satisfying numbers from the travel journal.\\n\\n\\n-----Input-----\\n\\nIn the first line there is an integer non-negative number A denoting the number of days of climbing up the hill. Second line contains an integer non-negative number B — the number of days of walking down the hill (A + B + 1 = N, 1 ≤ N ≤ 100 000).\\n\\n\\n-----Output-----\\n\\nOutput N space-separated distinct integers from 1 to N inclusive, denoting possible heights of the stops in order of visiting.\\n\\n\\n-----Examples-----\\nInput\\n0\\n1\\n\\nOutput\\n2 1 \\n\\nInput\\n2\\n1\\nOutput\\n1 3 4 2\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a=int(input())\\nb=int(input())\\nn=a+b+1\\nif(b is 0):\\n    for i in range(n):\\n        print(i+1,end=' ')\\nelif(a is 0):\\n    for i in range(n):\\n        print(n-i,end=' ')\\nelse:\\n    i=1\\n    print(i,end=' ')\\n    i=i+b+1\\n    while(i<=n):\\n        print(i,end=' ')\\n        i=i+1\\n    ct,i=1,1+b\\n    while(ct<=b):\\n        print(i,end=' ')\\n        i=i-1\\n        ct=ct+1\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/493\\/A:\\nVasya has started watching football games. He has learned that for some fouls the players receive yellow cards, and for some fouls they receive red cards. A player who receives the second yellow card automatically receives a red card.\\n\\nVasya is watching a recorded football match now and makes notes of all the fouls that he would give a card for. Help Vasya determine all the moments in time when players would be given red cards if Vasya were the judge. For each player, Vasya wants to know only the first moment of time when he would receive a red card from Vasya.\\n\\n\\n-----Input-----\\n\\nThe first line contains the name of the team playing at home. The second line contains the name of the team playing away. Both lines are not empty. The lengths of both lines do not exceed 20. Each line contains only of large English letters. The names of the teams are distinct.\\n\\nNext follows number n (1 ≤ n ≤ 90) — the number of fouls. \\n\\nEach of the following n lines contains information about a foul in the following form:   first goes number t (1 ≤ t ≤ 90) — the minute when the foul occurs;  then goes letter \\\"h\\\" or letter \\\"a\\\" — if the letter is \\\"h\\\", then the card was given to a home team player, otherwise the card was given to an away team player;  then goes the player's number m (1 ≤ m ≤ 99);  then goes letter \\\"y\\\" or letter \\\"r\\\" — if the letter is \\\"y\\\", that means that the yellow card was given, otherwise the red card was given. \\n\\nThe players from different teams can have the same number. The players within one team have distinct numbers. The fouls go chronologically, no two fouls happened at the same minute.\\n\\n\\n-----Output-----\\n\\nFor each event when a player received his first red card in a chronological order print a string containing the following information:  The name of the team to which the player belongs;  the player's number in his team;  the minute when he received the card. \\n\\nIf no player received a card, then you do not need to print anything.\\n\\nIt is possible case that the program will not print anything to the output (if...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"ht = input()\\nat = input()\\nN = int(input())\\nhc = [0]*100\\nac = [0]*100\\nfor n in range(N):\\n\\tar = input().split()\\n\\tt = int(ar[0])\\n\\tm = int(ar[2])\\n\\tif ar[1] == 'h':\\n\\t\\tif ar[3] == 'r':\\n\\t\\t\\tif hc[m] < 2:\\n\\t\\t\\t\\tprint(ht, m, t)\\n\\t\\t\\t\\thc[m] = 2\\n\\t\\telse:\\n\\t\\t\\thc[m] += 1\\n\\t\\t\\tif hc[m] == 2:\\n\\t\\t\\t\\tprint(ht, m, t)\\n\\tif ar[1] == 'a':\\n\\t\\tif ar[3] == 'r':\\n\\t\\t\\tif ac[m] < 2:\\n\\t\\t\\t\\tprint(at, m, t)\\n\\t\\t\\t\\tac[m] = 2\\n\\t\\telse:\\n\\t\\t\\tac[m] += 1\\n\\t\\t\\tif ac[m] == 2:\\n\\t\\t\\t\\tprint(at, m, t)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1102\\/B:\\nYou are given an array $a$ consisting of $n$ integer numbers.\\n\\nYou have to color this array in $k$ colors in such a way that:   Each element of the array should be colored in some color;  For each $i$ from $1$ to $k$ there should be at least one element colored in the $i$-th color in the array;  For each $i$ from $1$ to $k$ all elements colored in the $i$-th color should be distinct. \\n\\nObviously, such coloring might be impossible. In this case, print \\\"NO\\\". Otherwise print \\\"YES\\\" and any coloring (i.e. numbers $c_1, c_2, \\\\dots c_n$, where $1 \\\\le c_i \\\\le k$ and $c_i$ is the color of the $i$-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $k$ ($1 \\\\le k \\\\le n \\\\le 5000$) — the length of the array $a$ and the number of colors, respectively.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 5000$) — elements of the array $a$.\\n\\n\\n-----Output-----\\n\\nIf there is no answer, print \\\"NO\\\". Otherwise print \\\"YES\\\" and any coloring (i.e. numbers $c_1, c_2, \\\\dots c_n$, where $1 \\\\le c_i \\\\le k$ and $c_i$ is the color of the $i$-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.\\n\\n\\n-----Examples-----\\nInput\\n4 2\\n1 2 2 3\\n\\nOutput\\nYES\\n1 1 2 2\\n\\nInput\\n5 2\\n3 2 1 2 3\\n\\nOutput\\nYES\\n2 1 1 2 1\\n\\nInput\\n5 2\\n2 1 1 2 1\\n\\nOutput\\nNO\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the answer $2~ 1~ 2~ 1$ is also acceptable.\\n\\nIn the second example the answer $1~ 1~ 1~ 2~ 2$ is also acceptable.\\n\\nThere exist other acceptable answers for both examples.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import Counter\\n\\nN, K = map(int, input().split())\\na = list(map(int, input().split()))\\ncounter = Counter(a)\\n\\nif counter.most_common(1)[0][1] > K or N < K:\\n    print(\\\"NO\\\")\\n    return\\n\\ncolor_table = {}\\n\\ncurrent_color = 0\\nfor k, v in counter.items():\\n    color_table[k] = current_color\\n    current_color = (current_color + v) % K\\n\\nans = [0]*N\\nfor i, n in enumerate(a):\\n    ans[i] = (color_table[n] % K) + 1\\n    color_table[n] += 1\\n\\nprint(\\\"YES\\\")\\nprint(*ans, sep=\\\" \\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe purpose of this kata is to work out just how many bottles of duty free whiskey you would have to buy such that the saving over the normal high street price would effectively cover the cost of your holiday. \\n\\nYou will be given the high street price (normPrice), the duty free discount (discount) and the cost of the holiday. \\n\\nFor example, if a bottle cost £10 normally and the discount in duty free was 10%, you would save £1 per bottle. If your holiday cost £500, the answer you should return would be 500.\\n\\nAll inputs will be integers. Please return an integer. Round down.\",\"targets\":\"def duty_free(price, discount, holiday_cost):\\n    discount_total = price\\/100 * discount\\n    result = holiday_cost \\/\\/ discount_total\\n    return result\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/396\\/A:\\nYou are given an integer m as a product of integers a_1, a_2, ... a_{n} $(m = \\\\prod_{i = 1}^{n} a_{i})$. Your task is to find the number of distinct decompositions of number m into the product of n ordered positive integers.\\n\\nDecomposition into n products, given in the input, must also be considered in the answer. As the answer can be very large, print it modulo 1000000007 (10^9 + 7).\\n\\n\\n-----Input-----\\n\\nThe first line contains positive integer n (1 ≤ n ≤ 500). The second line contains space-separated integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nIn a single line print a single number k — the number of distinct decompositions of number m into n ordered multipliers modulo 1000000007 (10^9 + 7).\\n\\n\\n-----Examples-----\\nInput\\n1\\n15\\n\\nOutput\\n1\\n\\nInput\\n3\\n1 1 2\\n\\nOutput\\n3\\n\\nInput\\n2\\n5 7\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the second sample, the get a decomposition of number 2, you need any one number out of three to equal 2, and the rest to equal 1.\\n\\nIn the third sample, the possible ways of decomposing into ordered multipliers are [7,5], [5,7], [1,35], [35,1].\\n\\nA decomposition of positive integer m into n ordered multipliers is a cortege of positive integers b = {b_1, b_2, ... b_{n}} such that $m = \\\\prod_{i = 1}^{n} b_{i}$. Two decompositions b and c are considered different, if there exists index i such that b_{i} ≠ c_{i}.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import defaultdict\\nm = 1000000007\\n\\nf = [0] * 15001\\nf[0] = 1\\nfor i in range(1, 15001): f[i] = (f[i - 1] * i) % m\\n\\ndef c(n, k): return (f[n] * pow((f[k] * f[n - k]) % m, m - 2, m)) % m\\ndef prime(n):\\n    m = int(n ** 0.5) + 1\\n    t = [1] * (n + 1)\\n    for i in range(3, m):\\n        if t[i]: t[i * i :: 2 * i] = [0] * ((n - i * i) \\/\\/ (2 * i) + 1)\\n    return [2] + [i for i in range(3, n + 1, 2) if t[i]]\\n\\np = prime(31650)\\ns = defaultdict(int)\\n\\ndef g(n):\\n    for j in p:\\n        while n % j == 0:\\n            n \\/\\/= j\\n            s[j] += 1\\n        if j * j > n:\\n            s[n] += 1\\n            break\\n\\nn = int(input()) - 1\\na = list(map(int, input().split()))\\n\\nfor i in a: g(i)\\nif 1 in s: s.pop(1)\\n\\nd = 1\\nfor k in list(s.values()): d = (d * c(k + n, n)) % m\\nprint(d)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/847\\/D:\\nA new dog show on TV is starting next week. On the show dogs are required to demonstrate bottomless stomach, strategic thinking and self-preservation instinct. You and your dog are invited to compete with other participants and naturally you want to win!\\n\\nOn the show a dog needs to eat as many bowls of dog food as possible (bottomless stomach helps here). Dogs compete separately of each other and the rules are as follows:\\n\\nAt the start of the show the dog and the bowls are located on a line. The dog starts at position x = 0 and n bowls are located at positions x = 1, x = 2, ..., x = n. The bowls are numbered from 1 to n from left to right. After the show starts the dog immediately begins to run to the right to the first bowl.\\n\\nThe food inside bowls is not ready for eating at the start because it is too hot (dog's self-preservation instinct prevents eating). More formally, the dog can eat from the i-th bowl after t_{i} seconds from the start of the show or later.\\n\\nIt takes dog 1 second to move from the position x to the position x + 1. The dog is not allowed to move to the left, the dog runs only to the right with the constant speed 1 distance unit per second. When the dog reaches a bowl (say, the bowl i), the following cases are possible:  the food had cooled down (i.e. it passed at least t_{i} seconds from the show start): the dog immediately eats the food and runs to the right without any stop,  the food is hot (i.e. it passed less than t_{i} seconds from the show start): the dog has two options: to wait for the i-th bowl, eat the food and continue to run at the moment t_{i} or to skip the i-th bowl and continue to run to the right without any stop. \\n\\nAfter T seconds from the start the show ends. If the dog reaches a bowl of food at moment T the dog can not eat it. The show stops before T seconds if the dog had run to the right of the last bowl.\\n\\nYou need to help your dog create a strategy with which the maximum possible number of bowls of food will be eaten in T seconds.\\n\\n\\n-----Input-----\\n\\nTwo integer...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# using the min-heap \\nfrom heapq import heappush,heappop\\nbowels,Time = map(int,input().split())\\nmyLine = [-int(b) for b in input().split()]\\ngulp = []; eat = 0\\nfor i in range(1,min(bowels+1,Time)):\\n    # redundant (now that i look at it. the min does that already)\\n    if i >= Time:\\n        break\\n    while gulp and -gulp[0] >= Time - i:\\n        # remove the bowel with the highest time penalty \\n        heappop(gulp)\\n    # Check if the option is viable\\n    if -myLine[i-1] < Time:\\n        # Remove the step penalty and store the remaining \\n        heappush(gulp,myLine[i-1] + i)\\n    eat = max(len(gulp),eat)\\nprint (eat)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55fc061cc4f485a39900001f:\\nA high school has a strange principal. On the first day, he has his students perform an odd opening day ceremony:\\n\\nThere are number of lockers \\\"n\\\" and number of students \\\"n\\\" in the school. The principal asks the first student to go to every locker and open it. Then he has the second student go to every second locker and close it. The third goes to every third locker and, if it is closed, he opens it, and if it is open, he closes it. The fourth student does this to every fourth locker, and so on. After the process is completed with the \\\"n\\\"th student, how many lockers are open?\\n\\nThe task is to write a function which gets any number as an input and returns the number of open lockers after last sudent complets his activity. So input of the function is just one number which shows number of lockers and number of students. For example if there are 1000 lockers and 1000 students in school then input is 1000 and function returns number of open lockers after 1000th student completes his action.\\n\\nThe given input is always an integer greater than or equal to zero that is why there is no need for validation.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"num_of_open_lockers=lambda n: int(n**.5)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55849d76acd73f6cc4000087:\\nLet's imagine we have a popular online RPG. A player begins with a score of 0 in class E5. A1 is the highest level a player can achieve.\\n\\nNow let's say the players wants to rank up to class E4. To do so the player needs to achieve at least 100 points to enter the qualifying stage.\\n\\nWrite a script that will check to see if the player has achieved at least 100 points in his class. If so, he enters the qualifying stage. \\n\\nIn that case, we return, ```\\\"Well done! You have advanced to the qualifying stage. Win 2 out of your next 3 games to rank up.\\\"```.\\n\\nOtherwise return, ```False\\/false``` (according to the language n use).\\n\\nNOTE:  Remember, in C# you have to cast your output value to Object type!\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def playerRankUp(pts):\\n    return \\\"Well done! You have advanced to the qualifying stage. Win 2 out\\\" \\\\\\n           \\\" of your next 3 games to rank up.\\\" if pts >= 100 else False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPetya and Vasya decided to play a game. They have n cards (n is an even number). A single integer is written on each card.\\n\\nBefore the game Petya will choose an integer and after that Vasya will choose another integer (different from the number that Petya chose). During the game each player takes all the cards with number he chose. For example, if Petya chose number 5 before the game he will take all cards on which 5 is written and if Vasya chose number 10 before the game he will take all cards on which 10 is written.\\n\\nThe game is considered fair if Petya and Vasya can take all n cards, and the number of cards each player gets is the same.\\n\\nDetermine whether Petya and Vasya can choose integer numbers before the game so that the game is fair. \\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (2 ≤ n ≤ 100) — number of cards. It is guaranteed that n is an even number.\\n\\nThe following n lines contain a sequence of integers a_1, a_2, ..., a_{n} (one integer per line, 1 ≤ a_{i} ≤ 100) — numbers written on the n cards.\\n\\n\\n-----Output-----\\n\\nIf it is impossible for Petya and Vasya to choose numbers in such a way that the game will be fair, print \\\"NO\\\" (without quotes) in the first line. In this case you should not print anything more.\\n\\nIn the other case print \\\"YES\\\" (without quotes) in the first line. In the second line print two distinct integers — number that Petya should choose and the number that Vasya should choose to make the game fair. If there are several solutions, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n4\\n11\\n27\\n27\\n11\\n\\nOutput\\nYES\\n11 27\\n\\nInput\\n2\\n6\\n6\\n\\nOutput\\nNO\\n\\nInput\\n6\\n10\\n20\\n30\\n20\\n10\\n20\\n\\nOutput\\nNO\\n\\nInput\\n6\\n1\\n1\\n2\\n2\\n3\\n3\\n\\nOutput\\nNO\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the game will be fair if, for example, Petya chooses number 11, and Vasya chooses number 27. Then the will take all cards — Petya will take cards 1 and 4, and Vasya will take cards 2 and 3. Thus, each of them will take exactly two cards.\\n\\nIn the second example fair game is impossible because the numbers written on the cards are...\",\"targets\":\"def list_input():\\n    return list(map(int,input().split()))\\ndef map_input():\\n    return map(int,input().split())\\ndef map_string():\\n    return input().split()\\n    \\nn = int(input())    \\na = []\\nfor _ in range(n):\\n\\ta.append(int(input()))\\nb = list(set(a[::]))\\nif(len(b) == 2 and a.count(a[0]) == n\\/\\/2):\\n\\tprint(\\\"YES\\\")\\n\\tprint(b[0],b[1])\\t\\nelse: print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/336\\/B:\\nOne beautiful day Vasily the bear painted 2m circles of the same radius R on a coordinate plane. Circles with numbers from 1 to m had centers at points (2R - R, 0), (4R - R, 0), ..., (2Rm - R, 0), respectively. Circles with numbers from m + 1 to 2m had centers at points (2R - R, 2R), (4R - R, 2R), ..., (2Rm - R, 2R), respectively. \\n\\nNaturally, the bear painted the circles for a simple experiment with a fly. The experiment continued for m^2 days. Each day of the experiment got its own unique number from 0 to m^2 - 1, inclusive. \\n\\nOn the day number i the following things happened:   The fly arrived at the coordinate plane at the center of the circle with number $v = \\\\lfloor \\\\frac{i}{m} \\\\rfloor + 1$ ($\\\\lfloor \\\\frac{x}{y} \\\\rfloor$ is the result of dividing number x by number y, rounded down to an integer).  The fly went along the coordinate plane to the center of the circle number $u = m + 1 +(i \\\\operatorname{mod} m)$ ($x \\\\text{mod} y$ is the remainder after dividing number x by number y). The bear noticed that the fly went from the center of circle v to the center of circle u along the shortest path with all points lying on the border or inside at least one of the 2m circles. After the fly reached the center of circle u, it flew away in an unknown direction. \\n\\nHelp Vasily, count the average distance the fly went along the coordinate plane during each of these m^2 days.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers m, R (1 ≤ m ≤ 10^5, 1 ≤ R ≤ 10).\\n\\n\\n-----Output-----\\n\\nIn a single line print a single real number — the answer to the problem. The answer will be considered correct if its absolute or relative error doesn't exceed 10^{ - 6}.\\n\\n\\n-----Examples-----\\nInput\\n1 1\\n\\nOutput\\n2.0000000000\\n\\nInput\\n2 2\\n\\nOutput\\n5.4142135624\\n\\n\\n\\n-----Note-----\\n\\n[Image]\\n\\nFigure to the second sample\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\nm,R=map(int,input().split())\\ncord=math.sqrt(2*(R**2))\\nli=0\\nunit=int(2*R)\\nx=(m)*(m\\/2)\\nfor i in range(m):\\n    li+=2*R*m\\n    li+=(cord*(m-1))\\n    if(i==0 or i==m-1):\\n        if(m==1):\\n            continue\\n        li+=cord*(m-2)\\n    else:\\n        if(m==1):\\n            continue\\n        li+=cord*(m-3)\\n    left=(i-1)-1\\n    if(left<-1):\\n        left=-1\\n    li+=(left+1)*(left\\/2)*unit\\n    r=(m-1)-(i)-2\\n    if(r<-1):\\n        r=-1\\n    li=li+(r+1)*(r\\/2)*unit\\nli\\/=(m**2)\\nprint(li)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/250\\/A:\\nPolycarpus has been working in the analytic department of the \\\"F.R.A.U.D.\\\" company for as much as n days. Right now his task is to make a series of reports about the company's performance for the last n days. We know that the main information in a day report is value a_{i}, the company's profit on the i-th day. If a_{i} is negative, then the company suffered losses on the i-th day.\\n\\nPolycarpus should sort the daily reports into folders. Each folder should include data on the company's performance for several consecutive days. Of course, the information on each of the n days should be exactly in one folder. Thus, Polycarpus puts information on the first few days in the first folder. The information on the several following days goes to the second folder, and so on.\\n\\nIt is known that the boss reads one daily report folder per day. If one folder has three or more reports for the days in which the company suffered losses (a_{i} < 0), he loses his temper and his wrath is terrible.\\n\\nTherefore, Polycarpus wants to prepare the folders so that none of them contains information on three or more days with the loss, and the number of folders is minimal.\\n\\nWrite a program that, given sequence a_{i}, will print the minimum number of folders.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 ≤ n ≤ 100), n is the number of days. The second line contains a sequence of integers a_1, a_2, ..., a_{n} (|a_{i}| ≤ 100), where a_{i} means the company profit on the i-th day. It is possible that the company has no days with the negative a_{i}.\\n\\n\\n-----Output-----\\n\\nPrint an integer k — the required minimum number of folders. In the second line print a sequence of integers b_1, b_2, ..., b_{k}, where b_{j} is the number of day reports in the j-th folder.\\n\\nIf there are multiple ways to sort the reports into k days, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n11\\n1 2 3 -4 -5 -6 5 -5 -6 -7 6\\n\\nOutput\\n3\\n5 3 3 \\nInput\\n5\\n0 -1 100 -1 0\\n\\nOutput\\n1\\n5 \\n\\n\\n-----Note-----\\n\\nHere goes a way to sort the reports from the first sample into three...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nimport math\\n\\nn = int(sys.stdin.readline())\\nan = [int(x) for x in (sys.stdin.readline()).split()]\\n\\nres = 0\\nv = []\\np = 0\\nk = 0\\nfor i in an:\\n\\tif(i < 0):\\n\\t\\tif(p < 2):\\n\\t\\t\\tp += 1\\n\\t\\telse:\\n\\t\\t\\tp = 1\\n\\t\\t\\tv.append(str(k))\\n\\t\\t\\tres += 1\\n\\t\\t\\tk = 0\\n\\tk += 1\\n\\t\\nif(k != 0):\\n\\tres += 1\\n\\tv.append(str(k))\\n\\t\\nprint(res)\\nprint(\\\" \\\".join(v))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/arc065\\/tasks\\/arc065_c:\\nThere are N pinholes on the xy-plane. The i-th pinhole is located at (x_i,y_i).\\nWe will denote the Manhattan distance between the i-th and j-th pinholes as d(i,j)(=|x_i-x_j|+|y_i-y_j|).\\nYou have a peculiar pair of compasses, called Manhattan Compass.\\nThis instrument always points at two of the pinholes.\\nThe two legs of the compass are indistinguishable, thus we do not distinguish the following two states: the state where the compass points at the p-th and q-th pinholes, and the state where it points at the q-th and p-th pinholes.\\nWhen the compass points at the p-th and q-th pinholes and d(p,q)=d(p,r), one of the legs can be moved so that the compass will point at the p-th and r-th pinholes.\\nInitially, the compass points at the a-th and b-th pinholes.\\nFind the number of the pairs of pinholes that can be pointed by the compass.\\n\\n-----Constraints-----\\n - 2≦N≦10^5\\n - 1≦x_i, y_i≦10^9\\n - 1≦a < b≦N\\n - When i ≠ j, (x_i, y_i) ≠ (x_j, y_j)\\n - x_i and y_i are integers.\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\nN a b\\nx_1 y_1\\n:\\nx_N y_N\\n\\n-----Output-----\\nPrint the number of the pairs of pinholes that can be pointed by the compass.\\n\\n-----Sample Input-----\\n5 1 2\\n1 1\\n4 3\\n6 1\\n5 5\\n4 8\\n\\n-----Sample Output-----\\n4\\n\\nInitially, the compass points at the first and second pinholes.\\nSince d(1,2) = d(1,3), the compass can be moved so that it will point at the first and third pinholes.\\nSince d(1,3) = d(3,4), the compass can also point at the third and fourth pinholes.\\nSince d(1,2) = d(2,5), the compass can also point at the second and fifth pinholes.\\nNo other pairs of pinholes can be pointed by the compass, thus the answer is 4.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nfrom collections import defaultdict\\nimport bisect\\n\\nINF = 10 ** 12\\n\\nN,a,b = map(int,input().split())\\nX_to_Y = defaultdict(lambda: [-INF,INF])\\nY_to_X = defaultdict(lambda: [-INF,INF])\\nfor i in range(1,N+1):\\n    x,y = map(int,input().split())\\n    x,y = x+y,x-y\\n    X_to_Y[x].append(y)\\n    Y_to_X[y].append(x)\\n    if i == a:\\n        sx,sy = x,y\\n    elif i == b:\\n        tx,ty = x,y\\n\\nR = max(abs(sx-tx), abs(sy-ty))\\n\\nfor key, arr in X_to_Y.items():\\n    arr.sort()\\n    L = len(arr)\\n    move_right = list(range(1,L)) + [None]\\n    X_to_Y[key] = [arr,move_right]\\n    \\nfor key, arr in Y_to_X.items():\\n    arr.sort()\\n    L = len(arr)\\n    move_right = list(range(1,L)) + [None]\\n    Y_to_X[key] = [arr,move_right]\\n\\nequiv_class = set([(sx,sy), (tx,ty)])\\n\\nanswer = 0\\ntask = [(sx,sy), (tx,ty)]\\n\\nwhile task:\\n    x,y = task.pop()\\n    # 既出の元も含めて辺の個数を数える\\n    # 未出の元を同値に追加\\n    # x,y両方満たすものは、x側にだけ入れる\\n    for x1 in [x-R,x+R]:\\n        if not (x1 in X_to_Y):\\n            continue\\n        arr, move_right = X_to_Y[x1]\\n        left = bisect.bisect_left(arr, y-R)\\n        right = bisect.bisect_right(arr, y+R)\\n        # [left, right) が辺で結べるターゲット\\n        answer += right - left # 辺の個数\\n        i = left\\n        while i < right:\\n            y1 = arr[i]\\n            if (x1,y1) not in equiv_class:\\n                equiv_class.add((x1,y1))\\n                task.append((x1,y1))\\n            # なるべく、既に居ない元は見ないで済ませるように\\n            next_i = move_right[i]\\n            if next_i >= right:\\n                break\\n            move_right[i] = right\\n            i = next_i\\n    for y1 in [y-R,y+R]:\\n        if not y1 in Y_to_X:\\n            continue\\n        arr, move_right = Y_to_X[y1]\\n        left = bisect.bisect_left(arr, x-R+1)\\n        right = bisect.bisect_right(arr, x+R-1)\\n        # [left, right) が辺で結べるターゲット\\n        answer += right - left # 辺の個数\\n        i = left\\n        while i < right:\\n            x1 = arr[i]\\n            if (x1,y1) not in equiv_class:\\n                equiv_class.add((x1,y1))\\n                task.append((x1,y1))\\n           ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/maximum-score-words-formed-by-letters\\/:\\nGiven a list of words, list of  single letters (might be repeating) and score of every character.\\nReturn the maximum score of any valid set of words formed by using the given letters (words[i] cannot be used two or more times).\\nIt is not necessary to use all characters in letters and each letter can only be used once. Score of letters 'a', 'b', 'c', ... ,'z' is given by score[0], score[1], ... , score[25] respectively.\\n \\nExample 1:\\nInput: words = [\\\"dog\\\",\\\"cat\\\",\\\"dad\\\",\\\"good\\\"], letters = [\\\"a\\\",\\\"a\\\",\\\"c\\\",\\\"d\\\",\\\"d\\\",\\\"d\\\",\\\"g\\\",\\\"o\\\",\\\"o\\\"], score = [1,0,9,5,0,0,3,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0,0]\\nOutput: 23\\nExplanation:\\nScore  a=1, c=9, d=5, g=3, o=2\\nGiven letters, we can form the words \\\"dad\\\" (5+1+5) and \\\"good\\\" (3+2+2+5) with a score of 23.\\nWords \\\"dad\\\" and \\\"dog\\\" only get a score of 21.\\nExample 2:\\nInput: words = [\\\"xxxz\\\",\\\"ax\\\",\\\"bx\\\",\\\"cx\\\"], letters = [\\\"z\\\",\\\"a\\\",\\\"b\\\",\\\"c\\\",\\\"x\\\",\\\"x\\\",\\\"x\\\"], score = [4,4,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,5,0,10]\\nOutput: 27\\nExplanation:\\nScore  a=4, b=4, c=4, x=5, z=10\\nGiven letters, we can form the words \\\"ax\\\" (4+5), \\\"bx\\\" (4+5) and \\\"cx\\\" (4+5) with a score of 27.\\nWord \\\"xxxz\\\" only get a score of 25.\\nExample 3:\\nInput: words = [\\\"leetcode\\\"], letters = [\\\"l\\\",\\\"e\\\",\\\"t\\\",\\\"c\\\",\\\"o\\\",\\\"d\\\"], score = [0,0,1,1,1,0,0,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,0,0]\\nOutput: 0\\nExplanation:\\nLetter \\\"e\\\" can only be used once.\\n \\nConstraints:\\n\\n1 <= words.length <= 14\\n1 <= words[i].length <= 15\\n1 <= letters.length <= 100\\nletters[i].length == 1\\nscore.length == 26\\n0 <= score[i] <= 10\\nwords[i], letters[i] contains only lower case English letters.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import Counter\\nclass Solution:\\n    def subsets(self, words: List[str]) -> List[List[str]]:\\n        def subsetsHelper(words: List[str]) -> List[List[str]]:\\n            if len(words) == 0:\\n                return [[]]\\n            result = subsetsHelper(words[1:])\\n            for i in range(len(result)):\\n               if result[i] != None:\\n                  l = result[i][:]\\n                  l.append(words[0])\\n                  result.append(l)\\n            return result\\n        return subsetsHelper(words)\\n    def maxScoreWords(self, words: List[str], letters: List[str], score: List[int]) -> int:\\n        def getScores(wordSet:List[str])->int:\\n            scoreCount = 0\\n            counter = Counter(letters)\\n            for word in wordSet:\\n                for c in word:\\n                    if not c in counter or counter[c] == 0:\\n                        return 0\\n                    counter[c] -= 1\\n                    scoreCount += score[ord(c)-ord('a')]\\n            return scoreCount\\n                \\n        ans = 0\\n        for wordSet in self.subsets(words):\\n            currentScore = getScores(wordSet)\\n            if currentScore > ans:\\n                ans = currentScore\\n        return ans\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVasily has a deck of cards consisting of n cards. There is an integer on each of the cards, this integer is between 1 and 100 000, inclusive. It is possible that some cards have the same integers on them.\\n\\nVasily decided to sort the cards. To do this, he repeatedly takes the top card from the deck, and if the number on it equals the minimum number written on the cards in the deck, then he places the card away. Otherwise, he puts it under the deck and takes the next card from the top, and so on. The process ends as soon as there are no cards in the deck. You can assume that Vasily always knows the minimum number written on some card in the remaining deck, but doesn't know where this card (or these cards) is.\\n\\nYou are to determine the total number of times Vasily takes the top card from the deck.\\n\\n\\n-----Input-----\\n\\nThe first line contains single integer n (1 ≤ n ≤ 100 000) — the number of cards in the deck.\\n\\nThe second line contains a sequence of n integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 100 000), where a_{i} is the number written on the i-th from top card in the deck.\\n\\n\\n-----Output-----\\n\\nPrint the total number of times Vasily takes the top card from the deck.\\n\\n\\n-----Examples-----\\nInput\\n4\\n6 3 1 2\\n\\nOutput\\n7\\n\\nInput\\n1\\n1000\\n\\nOutput\\n1\\n\\nInput\\n7\\n3 3 3 3 3 3 3\\n\\nOutput\\n7\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Vasily at first looks at the card with number 6 on it, puts it under the deck, then on the card with number 3, puts it under the deck, and then on the card with number 1. He places away the card with 1, because the number written on it is the minimum among the remaining cards. After that the cards from top to bottom are [2, 6, 3]. Then Vasily looks at the top card with number 2 and puts it away. After that the cards from top to bottom are [6, 3]. Then Vasily looks at card 6, puts it under the deck, then at card 3 and puts it away. Then there is only one card with number 6 on it, and Vasily looks at it and puts it away. Thus, in total Vasily looks at 7 cards.\",\"targets\":\"n = int(input())\\ns = list(map(int,input().split(' ')))\\na = []\\nfor i in range(max(s)):\\n    a.append([])    \\nfor i in range(len(s)):\\n    a[s[i]-1].append(i)\\na = list([x for x in a if x != []])\\nif len(a) > 1:\\n    for i in range(1,len(a)):\\n        if len(a[i]) > 1:\\n            s = a[i-1][-1]\\n            if s > a[i][0] and s < a[i][-1]:\\n                for j in range(1,len(a[i])):\\n                    if s < a[i][j]:\\n                        a[i] = a[i][j:] + a[i][:j]\\n                        break\\nt = []\\nfor i in a:\\n    t += i\\nc = 0\\nx = t[0] + 1\\ni = n-1\\nwhile i > 0:\\n    if t[i] < t[i-1]:\\n        k = t[i] - t[i-1] + n\\n    else:\\n        k = t[i] - t[i-1]\\n    c += k\\n    x -= c\\/\\/n \\n    i -= 1\\nprint(c+x)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/580a8f039a90a3654b000032:\\nThe objective is to disambiguate two given names: the original with another\\n\\nThis kata is slightly more evolved than the previous one: [Author Disambiguation: to the point!](https:\\/\\/www.codewars.com\\/kata\\/580a429e1cb4028481000019).\\n\\nThe function ```could_be``` is still given the original name and another one to test\\nagainst. \\n\\n```python\\n# should return True even with 'light' variations (more details in section below)\\n> could_be(\\\"Chuck Norris\\\", u\\\"chück!\\\")\\nTrue\\n\\n# should False otherwise (whatever you may personnaly think)\\n> could_be(\\\"Chuck Norris\\\", \\\"superman\\\")\\nFalse\\n``` \\n\\n**Watch out**: When accents comes into the game, they will enter through **UTF-8 unicodes. **\\n\\nThe function should be tolerant with regards to:\\n\\n * upper and lower cases: ```could_be(A, a) : True```\\n * accents: ```could_be(E, é) : True```\\n * dots: ```could_be(E., E) : True```\\n * same for other ending punctuations in [!,;:?]: ```could_be(A, A!) : True```\\n\\nOn the other hand, more consideration needs to be given to *composed names*...\\nLet's be bold about it: if you have any, they will be considered as a whole :\\n\\n```python\\n# We still have:\\n> could_be(\\\"Carlos Ray Norris\\\", \\\"Carlos Ray Norris\\\")\\nTrue\\n> could_be(\\\"Carlos-Ray Norris\\\", \\\"Carlos-Ray Norris\\\")\\nTrue\\n\\n# But:\\n> could_be(\\\"Carlos Ray Norris\\\", \\\"Carlos-Ray Norris\\\")\\nFalse\\n> could_be(\\\"Carlos-Ray Norris\\\", \\\"Carlos Ray Norris\\\")\\nFalse\\n> could_be(\\\"Carlos-Ray Norris\\\", \\\"Carlos Ray-Norris\\\")\\nFalse\\n```\\n \\nAmong the valid combinaisons of the fullname \\\"Carlos Ray Norris\\\", you will find\\n\\n```python\\ncould_be(\\\"Carlos Ray Norris\\\", \\\"carlos ray\\\") : True\\ncould_be(\\\"Carlos Ray Norris\\\", \\\"Carlos. Ray, Norris;\\\") : True\\ncould_be(\\\"Carlos Ray Norris\\\", u\\\"Carlòs! Norris\\\") : True\\n```\\n\\nToo easy ? Try the next step: [Author Disambiguation: Signatures worth it](https:\\/\\/www.codewars.com\\/kata\\/author-disambiguation-signatures-worth-it)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import re\\nimport string\\ndic1 = {224:97, 244:111, 252:117, 233:101, 239:105}\\ndef could_be(original, another):\\n    if original == '' and another == '': return False\\n    p = \\\"!,;:?\\\"\\n    o, a = re.sub(r\\\"[!,;:\\\\?\\\\.]\\\", ' ', original.lower()), re.sub(r\\\"[!,;:\\\\?\\\\.]\\\", ' ', another.lower())\\n    if o == a: return True\\n    o = o.encode('unicode-escape').decode('unicode-escape')\\n    a = a.encode('unicode-escape').decode('unicode-escape')\\n    o1, a1 = o.split(), a.split()\\n    o2 = [i[:-1] if i[-1] in p else i for i in o1]\\n    ans1 = [''.join([chr(dic1[ord(j)]) if ord(j) in dic1 else j for j in i]) for i in o2]\\n    a2 = [i[:-1] if i[-1] in p else i for i in a1]\\n    ans2 = [''.join([chr(dic1[ord(j)]) if ord(j) in dic1 else j for j in i]) for i in a2]\\n    if ans1 != [] and ans2 == []:\\n        return False\\n    for i in ans2:\\n        for j in ans1:\\n            if i == j: break\\n        else: return False\\n    return True\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are a mayor of Berlyatov. There are $n$ districts and $m$ two-way roads between them. The $i$-th road connects districts $x_i$ and $y_i$. The cost of travelling along this road is $w_i$. There is some path between each pair of districts, so the city is connected.\\n\\nThere are $k$ delivery routes in Berlyatov. The $i$-th route is going from the district $a_i$ to the district $b_i$. There is one courier on each route and the courier will always choose the cheapest (minimum by total cost) path from the district $a_i$ to the district $b_i$ to deliver products.\\n\\nThe route can go from the district to itself, some couriers routes can coincide (and you have to count them independently).\\n\\nYou can make at most one road to have cost zero (i.e. you choose at most one road and change its cost with $0$).\\n\\nLet $d(x, y)$ be the cheapest cost of travel between districts $x$ and $y$.\\n\\nYour task is to find the minimum total courier routes cost you can achieve, if you optimally select the some road and change its cost with $0$. In other words, you have to find the minimum possible value of $\\\\sum\\\\limits_{i = 1}^{k} d(a_i, b_i)$ after applying the operation described above optimally.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers $n$, $m$ and $k$ ($2 \\\\le n \\\\le 1000$; $n - 1 \\\\le m \\\\le min(1000, \\\\frac{n(n-1)}{2})$; $1 \\\\le k \\\\le 1000$) — the number of districts, the number of roads and the number of courier routes.\\n\\nThe next $m$ lines describe roads. The $i$-th road is given as three integers $x_i$, $y_i$ and $w_i$ ($1 \\\\le x_i, y_i \\\\le n$; $x_i \\\\ne y_i$; $1 \\\\le w_i \\\\le 1000$), where $x_i$ and $y_i$ are districts the $i$-th road connects and $w_i$ is its cost. It is guaranteed that there is some path between each pair of districts, so the city is connected. It is also guaranteed that there is at most one road between each pair of districts.\\n\\nThe next $k$ lines describe courier routes. The $i$-th route is given as two integers $a_i$ and $b_i$ ($1 \\\\le a_i, b_i \\\\le n$) — the districts of the $i$-th route. The...\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nimport heapq\\n\\nn,m,k=list(map(int,input().split()))\\nEDGE=[tuple(map(int,input().split())) for i in range(m)]\\nE=[[] for i in range(n+1)]\\n\\nfor x,y,w in EDGE:\\n    E[x].append((y,w))\\n    E[y].append((x,w))\\n\\nANS=0\\n\\nCOST=[[1<<30]*(n+1) for i in range(n+1)]\\nQL=[tuple(map(int,input().split())) for i in range(k)]\\n\\nfor x in range(1,n+1):\\n    COST[x][x]=0\\n\\n    Q=[(0,x)]\\n    while Q:\\n        cost,fr=heapq.heappop(Q)\\n        if cost>COST[x][fr]:\\n            continue\\n        \\n        for to,c in E[fr]:\\n            if COST[x][to]>cost+c:\\n                COST[x][to]=cost+c\\n                heapq.heappush(Q,(COST[x][to],to))\\n\\nANS=1<<60\\n\\nfor x,y,_ in EDGE:\\n    A=0\\n    for fr,to in QL:\\n        A+=min(COST[fr][to],COST[fr][x]+COST[to][y],COST[to][x]+COST[fr][y])\\n    ANS=min(ANS,A)\\n\\nprint(ANS)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe year is 2088 and the Radical Marxist Socialist People's Party (RMSPP) has just seized power in Brazil.\\n\\nTheir first act in power is absolute wealth equality through coercive redistribution.\\n\\nCreate a function that redistributes all wealth equally among all citizens.\\n\\nWealth is represented as an array\\/list where every index is the wealth of a single citizen. The function should mutate the input such that every index has the same amount of wealth. **MUTATE the input array\\/list, don't return anything.**\\n\\nSee example:\\n\\n```python\\nwealth = [5, 10, 6]  # This represents:\\n                     # citizen 1 has wealth 5\\n                     # citizen 2 has wealth 10\\n                     # citizen 3 has wealth 6\\n                     \\nredistribute_wealth(wealth) # mutates wealth list\\nwealth => [7, 7, 7] # wealth has now been equally redistributed\\n\\n```\\n\\nInfo:\\n\\n- **MUTATE the input array\\/list, don't return anything**\\n\\n- Input is garantueed to hold at least 1 or more citizens\\n\\n- Wealth of citizen will an integer with minimum 0 (negative wealth not possible)\\n\\n- Handling of floating point error will not be tested\",\"targets\":\"def redistribute_wealth(w):\\n    w[:] = [sum(w) \\/ len(w)] * len(w)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/CHEFNWRK:\\nChef has $N$ small boxes arranged on a line from $1$ to $N$. For each valid $i$, the weight of the $i$-th box is $W_i$. Chef wants to bring them to his home, which is at the position $0$. He can hold any number of boxes at the same time; however, the total weight of the boxes he's holding must not exceed K at any time, and he can only pick the ith box if all the boxes between Chef's home and the ith box have been either moved or picked up in this trip.\\nTherefore, Chef will pick up boxes and carry them home in one or more round trips. Find the smallest number of round trips he needs or determine that he cannot bring all boxes home.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains two space-separated integers $N$ and $K$.\\n- The second line contains $N$ space-separated integers $W_1, W_2, \\\\ldots, W_N$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer ― the smallest number of round trips or $-1$ if it is impossible for Chef to bring all boxes home.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 100$\\n- $1 \\\\le N, K \\\\le 10^3$\\n- $1 \\\\le W_i \\\\le 10^3$ for each valid $i$\\n\\n-----Example Input-----\\n4\\n1 1 \\n2\\n2 4\\n1 1\\n3 6\\n3 4 2\\n3 6\\n3 4 3\\n\\n-----Example Output-----\\n-1\\n1\\n2\\n3\\n\\n-----Explanation-----\\nExample case 1: Since the weight of the box higher than $K$, Chef can not carry that box home in any number of the round trip.\\nExample case 2: Since the sum of weights of both boxes is less than $K$, Chef can carry them home in one round trip.\\nExample case 3: In the first round trip, Chef can only pick up the box at position $1$. In the second round trip, he can pick up both remaining boxes at positions $2$ and $3$.\\nExample case 4: Chef can only carry one box at a time, so three round trips are required.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for _ in range(int(input())):\\n n, k = list(map(int, input().split()))\\n W = list(map(int, input().split()))\\n W_cp = W.copy()\\n \\n count = 1\\n curr = 0\\n for i, w in enumerate(W):\\n  if w > k:\\n   count = -1\\n   break\\n  \\n  curr += w\\n  \\n  if curr > k:\\n   curr = w\\n   count += 1\\n   \\n print(count)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven n, how many structurally unique BST's (binary search trees) that store values 1 ... n?\\n\\nExample:\\n\\n\\nInput: 3\\nOutput: 5\\nExplanation:\\nGiven n = 3, there are a total of 5 unique BST's:\\n\\n   1         3     3      2      1\\n    \\\\       \\/     \\/      \\/ \\\\      \\\\\\n     3     2     1      1   3      2\\n    \\/     \\/       \\\\                 \\\\\\n   2     1         2                 3\",\"targets\":\"class Solution:\\n     def numTrees(self, n):\\n         \\\"\\\"\\\"\\n         :type n: int\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         dp = [1, 1, 2]\\n         if n < 3:\\n             return dp[n]\\n         for i in range(3, n + 1):\\n             \\n             dp.append(sum(dp[j - 1] * dp[i - j] for j in range(1, i + 1)))\\n         return dp[n]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc055\\/tasks\\/abc055_a:\\nSnuke has a favorite restaurant.\\nThe price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.\\nSo far, Snuke has ordered N meals at the restaurant.\\nLet the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen.\\nFind x-y.\\n\\n-----Constraints-----\\n - 1 ≤ N ≤ 100\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\nN\\n\\n-----Output-----\\nPrint the answer.\\n\\n-----Sample Input-----\\n20\\n\\n-----Sample Output-----\\n15800\\n\\nSo far, Snuke has paid 16000 yen, and the restaurant has paid back 200 yen. Thus, the answer is 15800.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\nprint(800 * n - 200 * (n \\/\\/ 15))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/PTRN2020\\/problems\\/ITGUY42:\\nThe chef is trying to solve some pattern problems, Chef wants your help to code it. Chef has one number K to form a new pattern. Help the chef to code this pattern problem.\\n\\n-----Input:-----\\n- First-line will contain $T$, the number of test cases. Then the test cases follow. \\n- Each test case contains a single line of input, one integer $K$. \\n\\n-----Output:-----\\nFor each test case, output as the pattern.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $1 \\\\leq K \\\\leq 100$\\n\\n-----Sample Input:-----\\n4\\n1\\n2\\n3\\n4\\n\\n-----Sample Output:-----\\n*\\n*\\n*\\n*\\n***\\n***\\n*\\n*\\n***\\n***\\n*****\\n*****\\n*\\n*\\n***\\n***\\n*****\\n*****\\n*******\\n*******\\n\\n-----EXPLANATION:-----\\nNo need, else pattern can be decode easily.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nfor i in range(int(input())):\\n    n=int(input())\\n    p=1\\n    l=n-1\\n    for j in range(n):\\n        for k in range(l):\\n            print(\\\" \\\",end='')\\n        for k in range(p):\\n            print(\\\"*\\\",end='')\\n        print()\\n        for k in range(l):\\n            print(\\\" \\\",end='')\\n        for k in range(p):\\n            print(\\\"*\\\",end='')\\n        print()\\n        p+=2\\n        l-=1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5b165654c8be0d17f40000a3:\\nIn this Kata, you will be given a number and your task will be to rearrange the number so that it is divisible by `25`, but without leading zeros. Return the minimum number of digit moves that are needed to make this possible. If impossible, return `-1` ( `Nothing` in Haskell ).\\n\\nFor example:\\n\\nMore examples in test cases.\\n\\nGood luck!\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import re\\ndef difference(n,s) :\\n    n = str(n)[::-1]\\n    try :\\n        right_index = n.index(s[1])\\n        left_index = n.index(s[0],[0,1 + right_index][s[0] == s[1]])\\n    except : return float('inf')\\n    upper_index = 1 + max(left_index,right_index) == len(n) and '0' == n[-2] and len(re.search('0*.$',n)[0])\\n    return right_index + left_index - 1 + (left_index < right_index) + (upper_index and upper_index - 1 - (len(n) <= min(left_index,right_index) + upper_index))\\ndef solve(n) :\\n    removes = min([difference(n,'00'),difference(n,'25'),difference(n,'50'),difference(n,'75')])\\n    return [-1,removes][int == type(removes)]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/958\\/E1:\\nThe Rebel fleet is afraid that the Empire might want to strike back again. Princess Heidi needs to know if it is possible to assign R Rebel spaceships to guard B bases so that every base has exactly one guardian and each spaceship has exactly one assigned base (in other words, the assignment is a perfect matching). Since she knows how reckless her pilots are, she wants to be sure that any two (straight) paths – from a base to its assigned spaceship – do not intersect in the galaxy plane (that is, in 2D), and so there is no risk of collision.\\n\\n\\n-----Input-----\\n\\nThe first line contains two space-separated integers R, B(1 ≤ R, B ≤ 10). For 1 ≤ i ≤ R, the i + 1-th line contains two space-separated integers x_{i} and y_{i} (|x_{i}|, |y_{i}| ≤ 10000) denoting the coordinates of the i-th Rebel spaceship. The following B lines have the same format, denoting the position of bases. It is guaranteed that no two points coincide and that no three points are on the same line.\\n\\n\\n-----Output-----\\n\\nIf it is possible to connect Rebel spaceships and bases so as satisfy the constraint, output Yes, otherwise output No (without quote).\\n\\n\\n-----Examples-----\\nInput\\n3 3\\n0 0\\n2 0\\n3 1\\n-2 1\\n0 3\\n2 2\\n\\nOutput\\nYes\\n\\nInput\\n2 1\\n1 0\\n2 2\\n3 1\\n\\nOutput\\nNo\\n\\n\\n\\n-----Note-----\\n\\nFor the first example, one possible way is to connect the Rebels and bases in order.\\n\\nFor the second example, there is no perfect matching between Rebels and bases.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a, b = list(map(int, input().split()))\\nif a==b: print(\\\"Yes\\\")\\nelse: print(\\\"No\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/633\\/A:\\nDante is engaged in a fight with \\\"The Savior\\\". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.\\n\\nFor every bullet that hits the shield, Ebony deals a units of damage while Ivory deals b units of damage. In order to break the shield Dante has to deal exactly c units of damage. Find out if this is possible.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers a, b, c (1 ≤ a, b ≤ 100, 1 ≤ c ≤ 10 000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively.\\n\\n\\n-----Output-----\\n\\nPrint \\\"Yes\\\" (without quotes) if Dante can deal exactly c damage to the shield and \\\"No\\\" (without quotes) otherwise.\\n\\n\\n-----Examples-----\\nInput\\n4 6 15\\n\\nOutput\\nNo\\n\\nInput\\n3 2 7\\n\\nOutput\\nYes\\n\\nInput\\n6 11 6\\n\\nOutput\\nYes\\n\\n\\n\\n-----Note-----\\n\\nIn the second sample, Dante can fire 1 bullet from Ebony and 2 from Ivory to deal exactly 1·3 + 2·2 = 7 damage. In the third sample, Dante can fire 1 bullet from ebony and no bullets from ivory to do 1·6 + 0·11 = 6 damage.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"__author__ = 'Utena'\\na,b,c=map(int,map(int,input().split()))\\nwhile True:\\n    if c<0:\\n        print('No')\\n        break\\n    elif c%a==0 or c%b==0:\\n        print('Yes')\\n        break\\n    c-=a\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLet's define the sum of two permutations p and q of numbers 0, 1, ..., (n - 1) as permutation [Image], where Perm(x) is the x-th lexicographically permutation of numbers 0, 1, ..., (n - 1) (counting from zero), and Ord(p) is the number of permutation p in the lexicographical order.\\n\\nFor example, Perm(0) = (0, 1, ..., n - 2, n - 1), Perm(n! - 1) = (n - 1, n - 2, ..., 1, 0)\\n\\nMisha has two permutations, p and q. Your task is to find their sum.\\n\\nPermutation a = (a_0, a_1, ..., a_{n} - 1) is called to be lexicographically smaller than permutation b = (b_0, b_1, ..., b_{n} - 1), if for some k following conditions hold: a_0 = b_0, a_1 = b_1, ..., a_{k} - 1 = b_{k} - 1, a_{k} < b_{k}.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer n (1 ≤ n ≤ 200 000).\\n\\nThe second line contains n distinct integers from 0 to n - 1, separated by a space, forming permutation p.\\n\\nThe third line contains n distinct integers from 0 to n - 1, separated by spaces, forming permutation q.\\n\\n\\n-----Output-----\\n\\nPrint n distinct integers from 0 to n - 1, forming the sum of the given permutations. Separate the numbers by spaces.\\n\\n\\n-----Examples-----\\nInput\\n2\\n0 1\\n0 1\\n\\nOutput\\n0 1\\n\\nInput\\n2\\n0 1\\n1 0\\n\\nOutput\\n1 0\\n\\nInput\\n3\\n1 2 0\\n2 1 0\\n\\nOutput\\n1 0 2\\n\\n\\n\\n-----Note-----\\n\\nPermutations of numbers from 0 to 1 in the lexicographical order: (0, 1), (1, 0).\\n\\nIn the first sample Ord(p) = 0 and Ord(q) = 0, so the answer is $\\\\operatorname{Perm}((0 + 0) \\\\operatorname{mod} 2) = \\\\operatorname{Perm}(0) =(0,1)$.\\n\\nIn the second sample Ord(p) = 0 and Ord(q) = 1, so the answer is $\\\\operatorname{Perm}((0 + 1) \\\\operatorname{mod} 2) = \\\\operatorname{Perm}(1) =(1,0)$.\\n\\nPermutations of numbers from 0 to 2 in the lexicographical order: (0, 1, 2), (0, 2, 1), (1, 0, 2), (1, 2, 0), (2, 0, 1), (2, 1, 0).\\n\\nIn the third sample Ord(p) = 3 and Ord(q) = 5, so the answer is $\\\\operatorname{Perm}((3 + 5) \\\\operatorname{mod} 6) = \\\\operatorname{Perm}(2) =(1,0,2)$.\",\"targets\":\"import sys\\n \\nclass SegmTree():\\n    def __init__(self, array=None):\\n        size = len(array)\\n        N = 1\\n        while N < size:\\n            N <<= 1\\n        self.N = N\\n        self.tree = [0] * (2*self.N)\\n        for i in range(size):\\n            self.tree[i+self.N] = array[i]\\n        self.build()\\n \\n    def build(self):\\n        for i in range(self.N - 1, 0, -1):\\n            self.tree[i] = self.tree[i<<1] + self.tree[i<<1|1]\\n \\n    def add(self, i, value=1):\\n        i += self.N\\n        while i > 0:\\n            self.tree[i] += value\\n            i >>= 1\\n    \\n    def get_sum(self, l, r):\\n        N = self.N\\n        l += N\\n        r += N\\n        result = 0\\n        while l < r:\\n            if l & 1:\\n                result += self.tree[l]\\n                l += 1\\n            if r & 1:\\n                r -= 1\\n                result += self.tree[r]\\n            l >>= 1\\n            r >>= 1\\n        return result\\n    \\n    def find_kth_nonzero(self, k):\\n        i = 1\\n        if k < 1 or k > self.tree[1]:\\n            return -1\\n        while i < self.N:\\n            i <<= 1\\n            if self.tree[i] < k:\\n                k -= self.tree[i]\\n                i |= 1\\n        return i - self.N\\n \\nreader = (line.rstrip() for line in sys.stdin)\\ninput = reader.__next__\\n \\nn = int(input())\\np = list(map(int, input().split()))\\nq = list(map(int, input().split()))\\n \\nord_p = []\\nord_q = []\\n \\nst = SegmTree([1] * n)\\nfor i, val in enumerate(p):\\n    ord_p.append(st.get_sum(0, val))\\n    st.add(val, -1)\\n \\nst = SegmTree([1] * n)\\nfor i, val in enumerate(q):\\n    ord_q.append(st.get_sum(0, val))\\n    st.add(val, -1)\\n \\ntransfer = 0\\nfor i in range(n-1, -1, -1):\\n    radix = n-i\\n    ord_p[i] = ord_p[i] + ord_q[i] + transfer\\n    if ord_p[i] < radix:\\n        transfer = 0\\n    else:\\n        transfer = 1\\n        ord_p[i] -= radix\\n \\nst = SegmTree([1] * n)\\nfor i in range(n):\\n    k = ord_p[i] + 1\\n    ord_q[i] = st.find_kth_nonzero(k)\\n    st.add(ord_q[i], -1)\\n \\nprint(*ord_q)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are planning to buy an apartment in a $n$-floor building. The floors are numbered from $1$ to $n$ from the bottom to the top. At first for each floor you want to know the minimum total time to reach it from the first (the bottom) floor.\\n\\nLet:  $a_i$ for all $i$ from $1$ to $n-1$ be the time required to go from the $i$-th floor to the $(i+1)$-th one (and from the $(i+1)$-th to the $i$-th as well) using the stairs;  $b_i$ for all $i$ from $1$ to $n-1$ be the time required to go from the $i$-th floor to the $(i+1)$-th one (and from the $(i+1)$-th to the $i$-th as well) using the elevator, also there is a value $c$ — time overhead for elevator usage (you need to wait for it, the elevator doors are too slow!). \\n\\nIn one move, you can go from the floor you are staying at $x$ to any floor $y$ ($x \\\\ne y$) in two different ways:  If you are using the stairs, just sum up the corresponding values of $a_i$. Formally, it will take $\\\\sum\\\\limits_{i=min(x, y)}^{max(x, y) - 1} a_i$ time units.  If you are using the elevator, just sum up $c$ and the corresponding values of $b_i$. Formally, it will take $c + \\\\sum\\\\limits_{i=min(x, y)}^{max(x, y) - 1} b_i$ time units. \\n\\nYou can perform as many moves as you want (possibly zero).\\n\\nSo your task is for each $i$ to determine the minimum total time it takes to reach the $i$-th floor from the $1$-st (bottom) floor.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $c$ ($2 \\\\le n \\\\le 2 \\\\cdot 10^5, 1 \\\\le c \\\\le 1000$) — the number of floors in the building and the time overhead for the elevator rides.\\n\\nThe second line of the input contains $n - 1$ integers $a_1, a_2, \\\\dots, a_{n-1}$ ($1 \\\\le a_i \\\\le 1000$), where $a_i$ is the time required to go from the $i$-th floor to the $(i+1)$-th one (and from the $(i+1)$-th to the $i$-th as well) using the stairs.\\n\\nThe third line of the input contains $n - 1$ integers $b_1, b_2, \\\\dots, b_{n-1}$ ($1 \\\\le b_i \\\\le 1000$), where $b_i$ is the time required to go from the $i$-th floor to the $(i+1)$-th one (and from the...\",\"targets\":\"n, c = map(int, input().split())\\n\\nS = list(map(int, input().split()))\\nE = list(map(int, input().split()))\\n\\nlastS = S[0]\\nlastE = E[0] + c\\nprint('0 ',end='')\\nprint(min(lastS, lastE), end= ' ')\\n\\nfor i in range(1, n - 1):\\n    curS = min(lastS + S[i], lastE + S[i])\\n    curE = min(lastS + c + E[i], lastE + E[i])\\n    print(min(curS, curE), end=' ')\\n    lastS = curS\\n    lastE = curE\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a sequence of positive integers a_1, a_2, ..., a_{n}. \\n\\nWhile possible, you perform the following operation: find a pair of equal consecutive elements. If there are more than one such pair, find the leftmost (with the smallest indices of elements). If the two integers are equal to x, delete both and insert a single integer x + 1 on their place. This way the number of elements in the sequence is decreased by 1 on each step. \\n\\nYou stop performing the operation when there is no pair of equal consecutive elements.\\n\\nFor example, if the initial sequence is [5, 2, 1, 1, 2, 2], then after the first operation you get [5, 2, 2, 2, 2], after the second — [5, 3, 2, 2], after the third — [5, 3, 3], and finally after the fourth you get [5, 4]. After that there are no equal consecutive elements left in the sequence, so you stop the process.\\n\\nDetermine the final sequence after you stop performing the operation.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (2 ≤ n ≤ 2·10^5) — the number of elements in the sequence.\\n\\nThe second line contains the sequence of integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nIn the first line print a single integer k — the number of elements in the sequence after you stop performing the operation. \\n\\nIn the second line print k integers — the sequence after you stop performing the operation.\\n\\n\\n-----Examples-----\\nInput\\n6\\n5 2 1 1 2 2\\n\\nOutput\\n2\\n5 4 \\nInput\\n4\\n1000000000 1000000000 1000000000 1000000000\\n\\nOutput\\n1\\n1000000002 \\nInput\\n7\\n4 10 22 11 12 5 6\\n\\nOutput\\n7\\n4 10 22 11 12 5 6 \\n\\n\\n-----Note-----\\n\\nThe first example is described in the statements.\\n\\nIn the second example the initial sequence is [1000000000, 1000000000, 1000000000, 1000000000]. After the first operation the sequence is equal to [1000000001, 1000000000, 1000000000]. After the second operation the sequence is [1000000001, 1000000001]. After the third operation the sequence is [1000000002].\\n\\nIn the third example there are no two equal consecutive elements initially, so the sequence does not change.\",\"targets\":\"n=int(input())\\na=list(map(int,input().split()))\\ni=0\\nb=[]\\nwhile i+1<n:\\n    if a[i]==a[i+1]:\\n        a[i+1]=a[i]+1\\n        if len(b)>0:\\n            a[i]=b.pop()\\n        else:\\n            i=i+1\\n    else:\\n        b.append(a[i])\\n        i=i+1\\nb.append(a[-1])\\nprint(len(b))\\nprint(*b)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are N pinholes on the xy-plane. The i-th pinhole is located at (x_i,y_i).\\nWe will denote the Manhattan distance between the i-th and j-th pinholes as d(i,j)(=|x_i-x_j|+|y_i-y_j|).\\nYou have a peculiar pair of compasses, called Manhattan Compass.\\nThis instrument always points at two of the pinholes.\\nThe two legs of the compass are indistinguishable, thus we do not distinguish the following two states: the state where the compass points at the p-th and q-th pinholes, and the state where it points at the q-th and p-th pinholes.\\nWhen the compass points at the p-th and q-th pinholes and d(p,q)=d(p,r), one of the legs can be moved so that the compass will point at the p-th and r-th pinholes.\\nInitially, the compass points at the a-th and b-th pinholes.\\nFind the number of the pairs of pinholes that can be pointed by the compass.\\n\\n-----Constraints-----\\n - 2≦N≦10^5\\n - 1≦x_i, y_i≦10^9\\n - 1≦a < b≦N\\n - When i ≠ j, (x_i, y_i) ≠ (x_j, y_j)\\n - x_i and y_i are integers.\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\nN a b\\nx_1 y_1\\n:\\nx_N y_N\\n\\n-----Output-----\\nPrint the number of the pairs of pinholes that can be pointed by the compass.\\n\\n-----Sample Input-----\\n5 1 2\\n1 1\\n4 3\\n6 1\\n5 5\\n4 8\\n\\n-----Sample Output-----\\n4\\n\\nInitially, the compass points at the first and second pinholes.\\nSince d(1,2) = d(1,3), the compass can be moved so that it will point at the first and third pinholes.\\nSince d(1,3) = d(3,4), the compass can also point at the third and fourth pinholes.\\nSince d(1,2) = d(2,5), the compass can also point at the second and fifth pinholes.\\nNo other pairs of pinholes can be pointed by the compass, thus the answer is 4.\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nfrom collections import defaultdict\\nimport bisect\\n\\nINF = 10 ** 12\\n\\nN,a,b = map(int,input().split())\\nX_to_Y = defaultdict(lambda: [-INF,INF])\\nY_to_X = defaultdict(lambda: [-INF,INF])\\nfor i in range(1,N+1):\\n    x,y = map(int,input().split())\\n    x,y = x+y,x-y\\n    X_to_Y[x].append(y)\\n    Y_to_X[y].append(x)\\n    if i == a:\\n        sx,sy = x,y\\n    elif i == b:\\n        tx,ty = x,y\\n\\nR = max(abs(sx-tx), abs(sy-ty))\\n\\nfor key, arr in X_to_Y.items():\\n    arr.sort()\\n    L = len(arr)\\n    move_right = list(range(1,L)) + [None]\\n    X_to_Y[key] = [arr,move_right]\\n    \\nfor key, arr in Y_to_X.items():\\n    arr.sort()\\n    L = len(arr)\\n    move_right = list(range(1,L)) + [None]\\n    Y_to_X[key] = [arr,move_right]\\n\\nequiv_class = set([(sx,sy), (tx,ty)])\\n\\nanswer = 0\\ntask = [(sx,sy), (tx,ty)]\\n\\nwhile task:\\n    x,y = task.pop()\\n    # 既出の元も含めて辺の個数を数える\\n    # 未出の元を同値に追加\\n    # x,y両方満たすものは、x側にだけ入れる\\n    for x1 in [x-R,x+R]:\\n        if not (x1 in X_to_Y):\\n            continue\\n        arr, move_right = X_to_Y[x1]\\n        left = bisect.bisect_left(arr, y-R)\\n        right = bisect.bisect_right(arr, y+R)\\n        # [left, right) が辺で結べるターゲット\\n        answer += right - left # 辺の個数\\n        i = left\\n        while i < right:\\n            y1 = arr[i]\\n            if (x1,y1) not in equiv_class:\\n                equiv_class.add((x1,y1))\\n                task.append((x1,y1))\\n            # なるべく、既に居ない元は見ないで済ませるように\\n            next_i = move_right[i]\\n            if next_i >= right:\\n                break\\n            move_right[i] = right\\n            i = next_i\\n    for y1 in [y-R,y+R]:\\n        if not y1 in Y_to_X:\\n            continue\\n        arr, move_right = Y_to_X[y1]\\n        left = bisect.bisect_left(arr, x-R+1)\\n        right = bisect.bisect_right(arr, x+R-1)\\n        # [left, right) が辺で結べるターゲット\\n        answer += right - left # 辺の個数\\n        i = left\\n        while i < right:\\n            x1 = arr[i]\\n            if (x1,y1) not in equiv_class:\\n                equiv_class.add((x1,y1))\\n                task.append((x1,y1))\\n           ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a binary array, find the maximum number of consecutive 1s in this array.\\n\\nExample 1:\\n\\nInput: [1,1,0,1,1,1]\\nOutput: 3\\nExplanation: The first two digits or the last three digits are consecutive 1s.\\n    The maximum number of consecutive 1s is 3.\\n\\n\\n\\nNote:\\n\\nThe input array will only contain 0 and 1.\\nThe length of input array is a positive integer and will not exceed 10,000\",\"targets\":\"class Solution:\\n     def findMaxConsecutiveOnes(self, nums):\\n         \\\"\\\"\\\"\\n         :type nums: List[int]\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         cnt = 0\\n         max_cnt = 0\\n         for x in nums:\\n             if x == 1:\\n                 cnt+=1\\n             else:\\n                 if max_cnt < cnt:\\n                     max_cnt = cnt\\n                 cnt = 0\\n         if max_cnt < cnt:\\n             max_cnt = cnt\\n         return max_cnt\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n\\\"Everything in the universe is balanced. Every disappointment you face in life will be balanced by something good for you! Keep going, never give up.\\\"\\nLet's call a string balanced if all characters that occur in this string occur in it the same number of times.\\nYou are given a string $S$; this string may only contain uppercase English letters. You may perform the following operation any number of times (including zero): choose one letter in $S$ and replace it by another uppercase English letter. Note that even if the replaced letter occurs in $S$ multiple times, only the chosen occurrence of this letter is replaced.\\nFind the minimum number of operations required to convert the given string to a balanced string.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first and only line of each test case contains a single string $S$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer ― the minimum number of operations.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 10,000$\\n- $1 \\\\le |S| \\\\le 1,000,000$\\n- the sum of $|S|$ over all test cases does not exceed $5,000,000$\\n- $S$ contains only uppercase English letters\\n\\n-----Subtasks-----\\nSubtask #1 (20 points):\\n- $T \\\\le 10$\\n- $|S| \\\\le 18$\\nSubtask #2 (80 points): original constraints\\n\\n-----Example Input-----\\n2\\nABCB\\nBBC\\n\\n-----Example Output-----\\n1\\n1\\n\\n-----Explanation-----\\nExample case 1: We can change 'C' to 'A'. The resulting string is \\\"ABAB\\\", which is a balanced string, since the number of occurrences of 'A' is equal to the number of occurrences of 'B'.\\nExample case 2: We can change 'C' to 'B' to make the string \\\"BBB\\\", which is a balanced string.\",\"targets\":\"t = int(input())\\nfor i in range(t):\\n s = input()\\n d = {}\\n min1 = len(s)+1\\n for i in s:\\n  if i not in d:\\n   d[i] = 1\\n  else:\\n   d[i] += 1\\n l = [[x,y] for x,y in d.items()]\\n l.sort(key = lambda j: j[1],reverse = True)\\n for i in range(1,27):\\n  f = len(s)\\/\\/i\\n  c = 0\\n  if len(s)%i != 0:\\n   continue\\n  j = 0\\n  while j < i and j < len(l):\\n   if l[j][1] >= f:\\n    c += f\\n   else:\\n    c += l[j][1]\\n   j += 1\\n  c = len(s)-c\\n  if c<min1:\\n   min1 = c\\n print(min1)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/COMT2020\\/problems\\/BHPORSRP:\\nThe name of our college is \\\"Government College of Engineering and Textile Technology Berhampore\\\". There is another college named \\\"Government College of Engineering and Textile Technology Serampore\\\". As the names are quite similar, those who are unaware of existence of both the colleges, often get confused. And mistake one with other.\\n\\nGiven a string, if it contains the word berhampore (case insensitive), print GCETTB or if it contains serampore(case-insensitive), print GCETTS . If the string contains neither print Others. If it contains both Berhampore and Serampore print Both \\nInput \\n- First line contains single integer T, No. of test case  \\n- Next line for every test contain case a string S \\nOutput\\n\\nPrint GCETTB or GCETTS or Others or Both on a new line\\nConstraints \\n- 1 <= T <= 10 \\n- 0 <= len(S) <= 100  \\n- S contain a-z and A-Z and space only\\nSample Input\\n3\\nGovernment clg Berhampore\\nSeRaMporE textile college \\nGirls college Kolkata\\n\\nSample Output\\n\\nGCETTB\\n\\nGCETTS\\n\\nOthers       \\nExplanation\\n\\nSelf-Explanatory\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nt=int(input())\\nc=0\\nd=0\\nfor i in range(t):\\n    c=0\\n    d=0\\n    s=input()\\n    l=s.split(\\\" \\\")\\n    #l=list(map(str,input().split(\\\" \\\")))\\n    for j in range(len(l)):\\n        if(l[j].lower()==\\\"berhampore\\\"):\\n            c+=1\\n        if(l[j].lower()==\\\"serampore\\\"):\\n            d+=1\\n    if(c>0 and d>0):\\n        print(\\\"Both\\\")\\n    else:\\n        if(c>0):\\n            print(\\\"GCETTB\\\")\\n        else:\\n            if(d>0):\\n                print(\\\"GCETTS\\\")\\n            else:\\n                print(\\\"Others\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/arc099\\/tasks\\/arc099_c:\\nIn the State of Takahashi in AtCoderian Federation, there are N cities, numbered 1, 2, ..., N.\\nM bidirectional roads connect these cities.\\nThe i-th road connects City A_i and City B_i.\\nEvery road connects two distinct cities.\\nAlso, for any two cities, there is at most one road that directly connects them.\\nOne day, it was decided that the State of Takahashi would be divided into two states, Taka and Hashi.\\nAfter the division, each city in Takahashi would belong to either Taka or Hashi.\\nIt is acceptable for all the cities to belong Taka, or for all the cities to belong Hashi.\\nHere, the following condition should be satisfied:\\n - Any two cities in the same state, Taka or Hashi, are directly connected by a road.\\nFind the minimum possible number of roads whose endpoint cities belong to the same state.\\nIf it is impossible to divide the cities into Taka and Hashi so that the condition is satisfied, print -1.\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 700\\n - 0 \\\\leq M \\\\leq N(N-1)\\/2\\n - 1 \\\\leq A_i \\\\leq N\\n - 1 \\\\leq B_i \\\\leq N\\n - A_i \\\\neq B_i\\n - If i \\\\neq j, at least one of the following holds: A_i \\\\neq A_j and B_i \\\\neq B_j.\\n - If i \\\\neq j, at least one of the following holds: A_i \\\\neq B_j and B_i \\\\neq A_j.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M\\nA_1 B_1\\nA_2 B_2\\n:\\nA_M B_M\\n\\n-----Output-----\\nPrint the answer.\\n\\n-----Sample Input-----\\n5 5\\n1 2\\n1 3\\n3 4\\n3 5\\n4 5\\n\\n-----Sample Output-----\\n4\\n\\nFor example, if the cities 1, 2 belong to Taka and the cities 3, 4, 5 belong to Hashi, the condition is satisfied.\\nHere, the number of roads whose endpoint cities belong to the same state, is 4.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N,M=list(map(int,input().split()))\\nROAD=[None]*M\\n\\nfor i in range(M):\\n    ROAD[i]=tuple(sorted(list(map(int,input().split()))))\\n  \\nimport itertools\\n\\nNOROAD=list(itertools.combinations(list(range(1,N+1)),2))\\n\\nNOROAD=set(NOROAD) - set(ROAD)\\n\\nGroup=[[i,[]] for i in range(N+1)]\\n\\ndef find(x):\\n    while Group[x][0] != x:\\n        x=Group[x][0]\\n    return x\\n\\n\\nfor i in NOROAD:\\n    a,b=i\\n    #print(a,b)\\n    Group[a][1]+=[b]\\n    Group[b][1]+=[a]\\n\\n    if find(a) != find(b):\\n        Group[find(a)][0]=min(find(a),find(b))\\n        Group[find(b)][0]=min(find(a),find(b))\\n        Group[a][0]=min(find(a),find(b))\\n        Group[b][0]=min(find(a),find(b))\\n\\nGroupSORT=[[i,j[1]] for i,j in enumerate(Group)]\\nGroupSORT.sort(key=lambda x:len(x[1]))\\nNUMBERING=[[find(i),\\\"none\\\"] for i in range(N+1)]\\nCHECK=[0 for i in range(N+1)]\\n\\nfor i in range(N):\\n    if CHECK[find(GroupSORT[i][0])]==0:\\n        \\n        NUMBERING[GroupSORT[i][0]][1]=0\\n        CHECK[find(GroupSORT[i][0])]=1\\n\\nCONDITION=1\\n#print(NUMBERING)\\n\\n\\nrepeat_condition=1\\nwhile repeat_condition==1:\\n\\n    repeat_condition=0\\n\\n    for i in range(1,N+1):\\n        if NUMBERING[i][1]==0:\\n            for j in Group[i][1]:\\n                if NUMBERING[j][1]==0:\\n                    CONDITION=0\\n                    break\\n                elif NUMBERING[j][1]==\\\"none\\\":\\n                    NUMBERING[j][1]=1\\n                    repeat_condition=1\\n\\n        if NUMBERING[i][1]==1:\\n            for j in Group[i][1]:\\n                if NUMBERING[j][1]==1:\\n                    CONDITION=0\\n                    break\\n                elif NUMBERING[j][1]==\\\"none\\\":\\n                    NUMBERING[j][1]=0\\n                    repeat_condition=1\\n\\n\\nimport sys\\nif CONDITION==0:\\n    print((-1))\\n    return\\n\\nNUMBERS=set()\\nfor i in range(1,len(NUMBERING)):\\n    NUMBERS=NUMBERS|{NUMBERING[i][0]}\\n\\ncount=[]\\nfor i in NUMBERS:\\n    count+=[(i,NUMBERING.count([i,0]),NUMBERING.count([i,1]))]\\n\\nDP=[set() for i in range(len(count))]\\nDP[0]={count[0][1],count[0][2]}\\n\\nfor i in range(1,len(count)):\\n    for k in DP[i-1]:\\n       ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1295\\/A:\\nYou have a large electronic screen which can display up to $998244353$ decimal digits. The digits are displayed in the same way as on different electronic alarm clocks: each place for a digit consists of $7$ segments which can be turned on and off to compose different digits. The following picture describes how you can display all $10$ decimal digits:\\n\\n[Image]\\n\\nAs you can see, different digits may require different number of segments to be turned on. For example, if you want to display $1$, you have to turn on $2$ segments of the screen, and if you want to display $8$, all $7$ segments of some place to display a digit should be turned on.\\n\\nYou want to display a really large integer on the screen. Unfortunately, the screen is bugged: no more than $n$ segments can be turned on simultaneously. So now you wonder what is the greatest integer that can be displayed by turning on no more than $n$ segments.\\n\\nYour program should be able to process $t$ different test cases.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 100$) — the number of test cases in the input.\\n\\nThen the test cases follow, each of them is represented by a separate line containing one integer $n$ ($2 \\\\le n \\\\le 10^5$) — the maximum number of segments that can be turned on in the corresponding testcase.\\n\\nIt is guaranteed that the sum of $n$ over all test cases in the input does not exceed $10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the greatest integer that can be displayed by turning on no more than $n$ segments of the screen. Note that the answer may not fit in the standard $32$-bit or $64$-bit integral data type.\\n\\n\\n-----Example-----\\nInput\\n2\\n3\\n4\\n\\nOutput\\n7\\n11\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nimport math\\nimport itertools\\nimport functools\\nimport collections\\nimport operator\\n\\n\\ndef ii(): return int(input())\\ndef mi(): return list(map(int, input().split()))\\ndef li(): return list(map(int, input().split()))\\ndef lcm(a, b): return abs(a * b) \\/\\/ math.gcd(a, b)\\ndef revn(n): return str(n)[::-1]\\ndef dd(): return collections.defaultdict(int)\\ndef ddl(): return collections.defaultdict(list)\\ndef sieve(n):\\n    if n < 2: return list()\\n    prime = [True for _ in range(n + 1)]\\n    p = 3\\n    while p * p <= n:\\n        if prime[p]:\\n            for i in range(p * 2, n + 1, p):\\n                prime[i] = False\\n        p += 2\\n    r = [2]\\n    for p in range(3, n + 1, 2):\\n        if prime[p]:\\n            r.append(p)\\n    return r\\ndef divs(n, start=2):\\n    r = []\\n    for i in range(start, int(math.sqrt(n) + 1)):\\n        if (n % i == 0):\\n            if (n \\/ i == i):\\n                r.append(i)\\n            else:\\n                r.extend([i, n \\/\\/ i])\\n    return r\\ndef divn(n, primes):\\n    divs_number = 1\\n    for i in primes:\\n        if n == 1:\\n            return divs_number\\n        t = 1\\n        while n % i == 0:\\n            t += 1\\n            n \\/\\/= i\\n        divs_number *= t\\ndef prime(n):\\n    if n == 2: return True\\n    if n % 2 == 0 or n <= 1: return False\\n    sqr = int(math.sqrt(n)) + 1\\n    for d in range(3, sqr, 2):\\n        if n % d == 0: return False\\n    return True\\ndef convn(number, base):\\n    newnumber = 0\\n    while number > 0:\\n        newnumber += number % base\\n        number \\/\\/= base\\n    return newnumber\\ndef cdiv(n, k): return n \\/\\/ k + (n % k != 0)\\n\\n\\nt = ii()\\nfor _ in range(t):\\n    n = ii()\\n    if n % 2:\\n        print('7' + '1' * ((n - 3) \\/\\/ 2))\\n    else:\\n        print('1' * (n \\/\\/ 2))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a string $s$ consisting of lowercase Latin letters \\\"a\\\", \\\"b\\\" and \\\"c\\\" and question marks \\\"?\\\".\\n\\nLet the number of question marks in the string $s$ be $k$. Let's replace each question mark with one of the letters \\\"a\\\", \\\"b\\\" and \\\"c\\\". Here we can obtain all $3^{k}$ possible strings consisting only of letters \\\"a\\\", \\\"b\\\" and \\\"c\\\". For example, if $s = $\\\"ac?b?c\\\" then we can obtain the following strings: $[$\\\"acabac\\\", \\\"acabbc\\\", \\\"acabcc\\\", \\\"acbbac\\\", \\\"acbbbc\\\", \\\"acbbcc\\\", \\\"accbac\\\", \\\"accbbc\\\", \\\"accbcc\\\"$]$.\\n\\nYour task is to count the total number of subsequences \\\"abc\\\" in all resulting strings. Since the answer can be very large, print it modulo $10^{9} + 7$.\\n\\nA subsequence of the string $t$ is such a sequence that can be derived from the string $t$ after removing some (possibly, zero) number of letters without changing the order of remaining letters. For example, the string \\\"baacbc\\\" contains two subsequences \\\"abc\\\" — a subsequence consisting of letters at positions $(2, 5, 6)$ and a subsequence consisting of letters at positions $(3, 5, 6)$.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $n$ $(3 \\\\le n \\\\le 200\\\\,000)$ — the length of $s$.\\n\\nThe second line of the input contains the string $s$ of length $n$ consisting of lowercase Latin letters \\\"a\\\", \\\"b\\\" and \\\"c\\\" and question marks\\\"?\\\".\\n\\n\\n-----Output-----\\n\\nPrint the total number of subsequences \\\"abc\\\" in all strings you can obtain if you replace all question marks with letters \\\"a\\\", \\\"b\\\" and \\\"c\\\", modulo $10^{9} + 7$.\\n\\n\\n-----Examples-----\\nInput\\n6\\nac?b?c\\n\\nOutput\\n24\\n\\nInput\\n7\\n???????\\n\\nOutput\\n2835\\n\\nInput\\n9\\ncccbbbaaa\\n\\nOutput\\n0\\n\\nInput\\n5\\na???c\\n\\nOutput\\n46\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, we can obtain $9$ strings:  \\\"acabac\\\" — there are $2$ subsequences \\\"abc\\\",  \\\"acabbc\\\" — there are $4$ subsequences \\\"abc\\\",  \\\"acabcc\\\" — there are $4$ subsequences \\\"abc\\\",  \\\"acbbac\\\" — there are $2$ subsequences \\\"abc\\\",  \\\"acbbbc\\\" — there are $3$ subsequences \\\"abc\\\",  \\\"acbbcc\\\" — there are $4$ subsequences \\\"abc\\\",  \\\"accbac\\\" — there is $1$ subsequence \\\"abc\\\",  \\\"accbbc\\\" — there are $2$...\",\"targets\":\"n = int(input())\\ns = \\\" \\\" + input()\\nF = [[-1 for i in range(4)] for j in range(n + 1)]\\nF[0] = [1, 0, 0, 0]\\n\\ndiv = (10 ** 9 + 7)\\n\\nfor i in range(1, n + 1):\\n    if s[i] == \\\"?\\\":\\n        F[i][0] = (3 * F[i-1][0]) % div\\n    else:\\n        F[i][0] = F[i-1][0] % div\\n    \\n    if s[i] == \\\"a\\\":\\n        F[i][1] = (F[i-1][1] + F[i-1][0]) % div\\n    elif s[i] == \\\"?\\\":\\n        F[i][1] = (3 * F[i-1][1] + F[i-1][0]) % div\\n    else:\\n        F[i][1] = (F[i-1][1]) % div\\n    \\n    if s[i] == \\\"b\\\":\\n        F[i][2] = (F[i-1][2] + F[i-1][1]) % div\\n    elif s[i] == \\\"?\\\":\\n        F[i][2] = (3 * F[i-1][2] + F[i-1][1]) % div\\n    else:\\n        F[i][2] = F[i-1][2] % div\\n    \\n    if s[i] == \\\"c\\\":\\n        F[i][3] = (F[i-1][3] + F[i-1][2]) % div\\n    elif s[i] == \\\"?\\\":\\n        F[i][3] = (3 * F[i-1][3] + F[i-1][2])  % div\\n    else:\\n        F[i][3] = F[i-1][3] % div\\n    \\n\\nprint(F[-1][3])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/627\\/D:\\nFor his computer science class, Jacob builds a model tree with sticks and balls containing n nodes in the shape of a tree. Jacob has spent a_{i} minutes building the i-th ball in the tree.\\n\\nJacob's teacher will evaluate his model and grade Jacob based on the effort he has put in. However, she does not have enough time to search his whole tree to determine this; Jacob knows that she will examine the first k nodes in a DFS-order traversal of the tree. She will then assign Jacob a grade equal to the minimum a_{i} she finds among those k nodes.\\n\\nThough Jacob does not have enough time to rebuild his model, he can choose the root node that his teacher starts from. Furthermore, he can rearrange the list of neighbors of each node in any order he likes. Help Jacob find the best grade he can get on this assignment.\\n\\nA DFS-order traversal is an ordering of the nodes of a rooted tree, built by a recursive DFS-procedure initially called on the root of the tree. When called on a given node v, the procedure does the following:   Print v.  Traverse the list of neighbors of the node v in order and iteratively call DFS-procedure on each one. Do not call DFS-procedure on node u if you came to node v directly from u. \\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two positive integers, n and k (2 ≤ n ≤ 200 000, 1 ≤ k ≤ n) — the number of balls in Jacob's tree and the number of balls the teacher will inspect.\\n\\nThe second line contains n integers, a_{i} (1 ≤ a_{i} ≤ 1 000 000), the time Jacob used to build the i-th ball.\\n\\nEach of the next n - 1 lines contains two integers u_{i}, v_{i} (1 ≤ u_{i}, v_{i} ≤ n, u_{i} ≠ v_{i}) representing a connection in Jacob's tree between balls u_{i} and v_{i}.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum grade Jacob can get by picking the right root of the tree and rearranging the list of neighbors.\\n\\n\\n-----Examples-----\\nInput\\n5 3\\n3 6 1 4 2\\n1 2\\n2 4\\n2 5\\n1 3\\n\\nOutput\\n3\\n\\nInput\\n4 2\\n1 5 5 5\\n1 2\\n1 3\\n1 4\\n\\nOutput\\n1\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, Jacob can root the tree at node...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nn, k = map(int, input().split())\\na = [int(i) for i in input().split()]\\ng = [[] for _ in range(n)]\\nfor i in range(n - 1):\\n\\tu, v = map(int, input().split())\\n\\tg[u-1].append(v-1)\\n\\tg[v-1].append(u-1)\\n\\nstack = [0]\\ndone = [False] * n\\npar = [0] * n\\norder = []\\nwhile len(stack) > 0:\\n\\tx = stack.pop()\\n\\tdone[x] = True\\n\\torder.append(x)\\n\\tfor i in g[x]:\\n\\t\\tif done[i] == False:\\n\\t\\t\\tpar[i] = x\\n\\t\\t\\tstack.append(i)\\norder = order[::-1]\\nsub = [0] * n\\nfor i in order: \\n\\tsub[i] = 1\\n\\tfor j in g[i]:\\n\\t\\tif par[j] == i:\\n\\t\\t\\tsub[i] += sub[j]\\n\\ndef good(guess):\\n\\tcnt = [0] * n\\n\\tfor i in order:\\n\\t\\tif a[i] < guess:\\n\\t\\t\\tcontinue\\n\\t\\tcnt[i] = 1\\n\\t\\topt = 0\\n\\t\\tfor j in g[i]:\\n\\t\\t\\tif par[j] == i:\\n\\t\\t\\t\\tif cnt[j] == sub[j]:\\n\\t\\t\\t\\t\\tcnt[i] += cnt[j]\\n\\t\\t\\t\\telse:\\n\\t\\t\\t\\t\\topt = max(opt, cnt[j])\\n\\t\\tcnt[i] += opt\\n\\tif cnt[0] >= k:\\n\\t\\treturn True\\n\\tup = [0] * n\\n\\tfor i in order[::-1]:\\n\\t\\tif a[i] < guess:\\n\\t\\t\\tcontinue\\n\\t\\topt, secondOpt = 0, 0\\n\\t\\ttotal = 1\\n\\t\\tfor j in g[i]:\\n\\t\\t\\tval, size = 0, 0\\n\\t\\t\\tif par[j] == i:\\n\\t\\t\\t\\tval = cnt[j]\\n\\t\\t\\t\\tsize = sub[j]\\n\\t\\t\\telse:\\n\\t\\t\\t\\tval = up[i]\\n\\t\\t\\t\\tsize = n - sub[i]\\n\\t\\t\\tif val == size:\\n\\t\\t\\t\\ttotal += val\\n\\t\\t\\telse:\\n\\t\\t\\t\\tif opt < val:\\n\\t\\t\\t\\t\\topt, secondOpt = val, opt\\n\\t\\t\\t\\telif secondOpt < val:\\n\\t\\t\\t\\t\\tsecondOpt = val\\n\\n\\t\\tfor j in g[i]:\\n\\t\\t\\tif par[j] == i:\\n\\t\\t\\t\\tup[j] = total\\n\\t\\t\\t\\tadd = opt\\n\\t\\t\\t\\tif sub[j] == cnt[j]:\\n\\t\\t\\t\\t\\tup[j] -= cnt[j]\\n\\t\\t\\t\\telif cnt[j] == opt:\\n\\t\\t\\t\\t\\tadd = secondOpt\\n\\t\\t\\t\\tup[j] += add\\n\\tfor i in range(n):\\n\\t\\tif a[i] < guess:\\n\\t\\t\\tcontinue\\n\\t\\ttotal, opt = 1, 0\\n\\t\\tfor j in g[i]:\\n\\t\\t\\tval, size = 0, 0\\n\\t\\t\\tif par[j] == i:\\n\\t\\t\\t\\tval = cnt[j]\\n\\t\\t\\t\\tsize = sub[j]\\n\\t\\t\\telse:\\n\\t\\t\\t\\tval = up[i]\\t\\n\\t\\t\\t\\tsize = n - sub[i]\\n\\t\\t\\tif val == size:\\n\\t\\t\\t\\ttotal += val\\n\\t\\t\\telse:\\n\\t\\t\\t\\topt = max(opt, val)\\n\\t\\tif total + opt >= k:\\n\\t\\t\\treturn True\\t\\t\\t\\n\\treturn False\\n\\nl, r = 0, max(a)\\nwhile l < r:\\n\\tmid = (l + r + 1) \\/\\/ 2\\n\\tif good(mid):\\n\\t\\tl = mid\\n\\telse:\\n\\t\\tr = mid - 1\\nprint(l)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/partition-array-into-disjoint-intervals\\/:\\nGiven an array A, partition it into two (contiguous) subarrays left and right so that:\\n\\nEvery element in left is less than or equal to every element in right.\\nleft and right are non-empty.\\nleft has the smallest possible size.\\n\\nReturn the length of left after such a partitioning.  It is guaranteed that such a partitioning exists.\\n \\nExample 1:\\nInput: [5,0,3,8,6]\\nOutput: 3\\nExplanation: left = [5,0,3], right = [8,6]\\n\\n\\nExample 2:\\nInput: [1,1,1,0,6,12]\\nOutput: 4\\nExplanation: left = [1,1,1,0], right = [6,12]\\n\\n \\n\\nNote:\\n\\n2 <= A.length <= 30000\\n0 <= A[i] <= 10^6\\nIt is guaranteed there is at least one way to partition A as described.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def partitionDisjoint(self, A: List[int]) -> int:\\n        mx=[-1]*len(A)\\n        mn=[-1]*len(A)\\n        for i in range(len(A)):\\n            if i==0:\\n                mx[i]=A[i]\\n            else:\\n                mx[i]=max(A[i],mx[i-1])\\n        for j in range(len(A)-1,-1,-1):\\n            if j==len(A)-1:\\n                mn[j]=A[j]\\n            else:\\n                mn[j]=min(A[j],mn[j+1])\\n        #print(mx,mn)\\n        for i in range(len(A)-1):\\n            print(mx[i],mn[i+1])\\n            if mx[i]<=mn[i+1]:\\n                #print('yo')\\n                return i+1\\n        return len(A)-1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a square matrix mat, return the sum of the matrix diagonals.\\nOnly include the sum of all the elements on the primary diagonal and all the elements on the secondary diagonal that are not part of the primary diagonal.\\n \\nExample 1:\\n\\nInput: mat = [[1,2,3],\\n              [4,5,6],\\n              [7,8,9]]\\nOutput: 25\\nExplanation: Diagonals sum: 1 + 5 + 9 + 3 + 7 = 25\\nNotice that element mat[1][1] = 5 is counted only once.\\n\\nExample 2:\\nInput: mat = [[1,1,1,1],\\n              [1,1,1,1],\\n              [1,1,1,1],\\n              [1,1,1,1]]\\nOutput: 8\\n\\nExample 3:\\nInput: mat = [[5]]\\nOutput: 5\\n\\n \\nConstraints:\\n\\nn == mat.length == mat[i].length\\n1 <= n <= 100\\n1 <= mat[i][j] <= 100\",\"targets\":\"class Solution:\\n    def diagonalSum(self, mat: List[List[int]]) -> int:\\n        ans = 0\\n        n = len(mat[0])\\n        for i in range(n):\\n            ans = ans + mat[i][i] + mat[i][n - i - 1]\\n        if n % 2 != 0:\\n            ans = ans - mat[n\\/\\/2][n\\/\\/2]\\n        return ans\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5500d54c2ebe0a8e8a0003fd:\\nFind the greatest common divisor of two positive integers. The integers can be large, so you need to find a clever solution. \\n\\nThe inputs `x` and `y` are always greater or equal to 1, so the greatest common divisor will always be an integer that is also greater or equal to 1.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def mygcd(x,y):\\n    if x == 0:\\n        return y\\n    if y == 0:\\n        return x\\n    else:\\n        return mygcd(y, x%y)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc152\\/tasks\\/abc152_a:\\nTakahashi is participating in a programming contest, AXC001. He has just submitted his code to Problem A.\\n\\nThe problem has N test cases, all of which must be passed to get an AC verdict.\\n\\nTakahashi's submission has passed M cases out of the N test cases.\\n\\nDetermine whether Takahashi's submission gets an AC.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 100\\n - 0 \\\\leq M \\\\leq N\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M\\n\\n-----Output-----\\nIf Takahashi's submission gets an AC, print Yes; otherwise, print No.\\n\\n-----Sample Input-----\\n3 3\\n\\n-----Sample Output-----\\nYes\\n\\nAll three test cases have been passed, so his submission gets an AC.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = map(int, input().split())\\nif n == m:\\n    print('Yes')\\nelse:\\n    print('No')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef has  $N$ doggo (dogs) , Lets number them $1$ to $N$.\\n\\nChef decided to build houses for each, but he soon realizes that keeping so many dogs at one place may be messy. So he decided to divide them into several groups called doggo communities. Let the total no. of groups be $K$ . In a community, paths between pairs of houses can be made so that doggo can play with each other. But there cannot be a path between two houses of different communities for sure. Chef wanted to make maximum no. of paths such that the total path is not greater then $K$.\\nLet’s visualize this problem in an engineer's way :)\\nThe problem is to design a graph with max edge possible such that the total no. of edges should not be greater than the total no. of connected components.\\n\\n-----INPUT FORMAT-----\\n- First line of each test case file contain $T$ , denoting total number of test cases.\\n- $ith$ test case contain only one line with a single integer $N$ , denoting the number of dogs(vertex)\\n\\n-----OUTPUT FORMAT-----\\n- For each test case print a line with a integer , denoting the maximum possible path possible.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 10000$\\n- $1 \\\\leq N \\\\leq 10^9$ \\n\\n-----Sub-Tasks-----\\n- $20 Points$\\n- $1 \\\\leq N \\\\leq 10^6$ \\n\\n-----Sample Input-----\\n1\\n\\n4\\n\\n-----Sample Output-----\\n2\\n\\n-----Explanation-----\\n4 houses can be made with  like this:\\n\\ncommunity #1  : [1 - 2  ]\\n\\ncommunity #2 :  [3 - 4 ]\\n\\nor  [1 - 2 - 3]  , [ 4 ]\\n\\nIn both cases the maximum possible path is 2.\",\"targets\":\"# cook your dish here\\nimport math\\nfor _ in range(int(input())):\\n    n = int(input())\\n    x = (-1 + (8*n + 9)**0.5)*0.5\\n    ans = n - math.ceil(x) + 1\\n    print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55147ff29cd40b43c600058b:\\nGiven a string, you progressively need to concatenate the first letter from the left and the first letter to the right and \\\"1\\\", then the second letter from the left and the second letter to the right and \\\"2\\\", and so on.\\n\\nIf the string's length is odd drop the central element.\\n\\nFor example:\\n```python\\nchar_concat(\\\"abcdef\\\")    == 'af1be2cd3'\\nchar_concat(\\\"abc!def\\\")   == 'af1be2cd3' # same result\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def char_concat(word):\\n    return \\\"\\\".join([word[i] + word[-i-1] + str(i+1) for i in range(len(word)\\/\\/2)])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/376\\/B:\\nImagine that there is a group of three friends: A, B and С. A owes B 20 rubles and B owes C 20 rubles. The total sum of the debts is 40 rubles. You can see that the debts are not organized in a very optimal manner. Let's rearrange them like that: assume that A owes C 20 rubles and B doesn't owe anything to anybody. The debts still mean the same but the total sum of the debts now equals 20 rubles.\\n\\nThis task is a generalisation of a described example. Imagine that your group of friends has n people and you know the debts between the people. Optimize the given debts without changing their meaning. In other words, finally for each friend the difference between the total money he should give and the total money he should take must be the same. Print the minimum sum of all debts in the optimal rearrangement of the debts. See the notes to the test samples to better understand the problem.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (1 ≤ n ≤ 100; 0 ≤ m ≤ 10^4). The next m lines contain the debts. The i-th line contains three integers a_{i}, b_{i}, c_{i} (1 ≤ a_{i}, b_{i} ≤ n; a_{i} ≠ b_{i}; 1 ≤ c_{i} ≤ 100), which mean that person a_{i} owes person b_{i} c_{i} rubles.\\n\\nAssume that the people are numbered by integers from 1 to n.\\n\\nIt is guaranteed that the same pair of people occurs at most once in the input. The input doesn't simultaneously contain pair of people (x, y) and pair of people (y, x).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum sum of debts in the optimal rearrangement.\\n\\n\\n-----Examples-----\\nInput\\n5 3\\n1 2 10\\n2 3 1\\n2 4 1\\n\\nOutput\\n10\\n\\nInput\\n3 0\\n\\nOutput\\n0\\n\\nInput\\n4 3\\n1 2 1\\n2 3 1\\n3 1 1\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, you can assume that person number 1 owes 8 rubles to person number 2, 1 ruble to person number 3 and 1 ruble to person number 4. He doesn't owe anybody else anything. In the end, the total debt equals 10.\\n\\nIn the second sample, there are no debts.\\n\\nIn the third sample, you can annul all the debts.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = list(map(int, input().split()))\\n\\nms = [[0, 0] for i in range(n)]\\nfor i in range(m):\\n    a, b, c = list(map(int, input().split()))\\n    ms[a-1][0] += c\\n    ms[b-1][1] += c\\n\\nsol = 0\\nfor i in range(n):\\n    sol += max(ms[i][0] - ms[i][1], 0)\\n\\nprint(sol)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe are given an array A of N lowercase letter strings, all of the same length.\\nNow, we may choose any set of deletion indices, and for each string, we delete all the characters in those indices.\\nFor example, if we have an array A = [\\\"babca\\\",\\\"bbazb\\\"] and deletion indices {0, 1, 4}, then the final array after deletions is [\\\"bc\\\",\\\"az\\\"].\\nSuppose we chose a set of deletion indices D such that after deletions, the final array has every element (row) in lexicographic order.\\nFor clarity, A[0] is in lexicographic order (ie. A[0][0] <= A[0][1] <= ... <= A[0][A[0].length - 1]), A[1] is in lexicographic order (ie. A[1][0] <= A[1][1] <= ... <= A[1][A[1].length - 1]), and so on.\\nReturn the minimum possible value of D.length.\\n \\n\\nExample 1:\\nInput: [\\\"babca\\\",\\\"bbazb\\\"]\\nOutput: 3\\nExplanation: After deleting columns 0, 1, and 4, the final array is A = [\\\"bc\\\", \\\"az\\\"].\\nBoth these rows are individually in lexicographic order (ie. A[0][0] <= A[0][1] and A[1][0] <= A[1][1]).\\nNote that A[0] > A[1] - the array A isn't necessarily in lexicographic order.\\n\\n\\nExample 2:\\nInput: [\\\"edcba\\\"]\\nOutput: 4\\nExplanation: If we delete less than 4 columns, the only row won't be lexicographically sorted.\\n\\n\\nExample 3:\\nInput: [\\\"ghi\\\",\\\"def\\\",\\\"abc\\\"]\\nOutput: 0\\nExplanation: All rows are already lexicographically sorted.\\n\\n \\n\\n\\n\\nNote:\\n\\n1 <= A.length <= 100\\n1 <= A[i].length <= 100\",\"targets\":\"class Solution:\\n    def minDeletionSize(self, A: List[str]) -> int:\\n        \\n        l = len(A[0])\\n        dp = [1 for _ in range(l)] + [0]\\n        for i in range(len(dp)-1, -1, -1):\\n            for j in range(i+1, l):\\n                if all(A[k][i] <= A[k][j] for k in range(len(A))):\\n                    dp[i] = max(dp[i], dp[j]+1)\\n        \\n        \\n        return l - max(dp)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWrite a function that takes an array of numbers (integers for the tests) and a target number. It should find two different items in the array that, when added together, give the target value. The indices of these items should then be returned in a tuple like so: `(index1, index2)`.\\n\\nFor the purposes of this kata, some tests may have multiple answers; any valid solutions will be accepted.\\n\\nThe input will always be valid (numbers will be an array of length 2 or greater, and all of the items will be numbers; target will always be the sum of two different items from that array).\\n\\nBased on: http:\\/\\/oj.leetcode.com\\/problems\\/two-sum\\/\",\"targets\":\"def two_sum(nums, target):\\n    d = {}\\n    for i, num in enumerate(nums):\\n        diff = target - num\\n        if diff in d:\\n            return [d[diff], i]\\n        d[num] = i\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/MIME2:\\nMany internet protocols these days include the option of associating a\\nmedia type with the content being sent.\\nThe type is usually inferred from the file extension.\\nYou are to write a program that facilitates the lookup of media types for\\na number of files.\\nYou will be given a table of media type associations that associate a certain\\nfile extension with a certain media type.\\nYou will then be given a number of file names, and tasked to determine the correct\\nmedia type for each file.\\nA file extension is defined as the part of the file name after the final period.\\nIf a file name has no periods, then it has no extension and the media type cannot\\nbe determined.\\nIf the file extension is not present in the table, then the media type cannot be\\ndetermined.\\nIn such cases you will print \\\"unknown\\\" as the media type.\\nIf the file extension does appear in the table (case matters), then print the associated\\nmedia type.\\n\\n-----Input-----\\nInput begins with 2 integers N and Q on a line.\\nN is the number of media type associations, and Q is the number of file names.\\nFollowing this are N lines, each containing a file extension and a media type, separated by a space.\\nFinally, Q lines, each containing the name of a file.\\nN and Q will be no greater than 100 each.\\nFile extensions will consist only of alphanumeric characters, will have length at most 10, and will be distinct.\\nMedia types will have length at most 50, and will contain only alphanumeric characters and punctuation.\\nFile names will consist only of alphanumeric characters and periods and have length at most 50.\\n\\n-----Output-----\\nFor each of the Q file names, print on a line the media type of the file.\\nIf there is no matching entry, print \\\"unknown\\\" (quotes for clarity).\\n\\n-----Sample Input-----\\n5 6\\nhtml text\\/html\\nhtm text\\/html\\npng image\\/png\\nsvg image\\/svg+xml\\ntxt text\\/plain\\nindex.html\\nthis.file.has.lots.of.dots.txt\\nnodotsatall\\nvirus.exe\\ndont.let.the.png.fool.you\\ncase.matters.TXT\\n\\n-----Sample Output-----\\ntext\\/html\\ntext\\/plain\\nunknown\\nunknown\\nunknown\\nunknown\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,q=map(int,input().split())\\nl={}\\nfor i in range(n):\\n a,b=input().split()\\n l[a]=b\\nfor i in range(q):\\n s=input().strip()\\n if('.' in s):\\n  s=s.split('.')\\n  x=s[-1]\\n  if(x in l):\\n   print(l[x])\\n  else:\\n   print('unknown')\\n else:\\n  print('unknown')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef is a brilliant university student that does not attend lectures because he believes that they are boring and coding is life! However, his university follows certain rules and regulations, and a student may only take an exam for a course if he has attended at least 75% of lectures for this course.\\nSince you are Chef's best friend, you want to help him reach the attendance he needs to take exams. Unfortunately, Chef is still focused on his code and refuses to attend more lectures, so the only option is to have some of his friends mark him as present by proxy. This trick is well-known in the university, but only few have the talent to pull it off.\\nIn a certain course, there is exactly one lesson per day over the course of $D$ days (numbered $1$ through $D$). You are given a string $S$ with length $D$ describing the lessons Chef attended — for each valid $i$, the $i$-th character of this string is either 'A' if Chef was absent on day $i$ or 'P' if Chef was actually present on day $i$.\\nFor each day $d$ when Chef is absent, one of Chef's friends can mark him as present by proxy on this day only if he was present (if he was really present, not just marked as present) on at least one of the previous two days, i.e. days $d-1$ and $d-2$, and on at least one of the following two days, i.e. days $d+1$ and $d+2$. However, it is impossible to mark him as present by proxy on the first two days and the last two days.\\nFind the minimum number of times Chef has to be marked as present by proxy so that his attendance becomes at least 75% ($0.75$). Chef's attendance is number of days when he was marked as present, either by proxy or by actually being present, divided by $D$.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $D$.\\n- The second line contains a single string $S$ with length $D$.\\n\\n-----Output-----\\nFor each test case, print a single line containing...\",\"targets\":\"# cook your dish here\\ndef ceil(num):\\n if num%1==0:\\n  return int(num\\/\\/1)\\n else:\\n  return int((num\\/\\/1)+1)\\n \\nfor _ in range(int(input())):\\n n=int(input())\\n s=input()\\n p=0\\n a=[]\\n for i in range(n):\\n  if s[i]==\\\"P\\\":\\n   p=p+1\\n req=ceil(0.75*n)\\n requirement=req-p\\n for i in range(2,n-2):\\n  if s[i]==\\\"A\\\":\\n   if (s[i-1]==\\\"P\\\" or s[i-2]==\\\"P\\\") and (s[i+1]==\\\"P\\\" or s[i+2]==\\\"P\\\"):\\n    a.append(i)\\n if requirement>len(a):\\n  print(-1)\\n else:\\n  print(max(requirement,0))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/271\\/A:\\nIt seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.\\n\\nNow you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.\\n\\n\\n-----Input-----\\n\\nThe single line contains integer y (1000 ≤ y ≤ 9000) — the year number.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.\\n\\n\\n-----Examples-----\\nInput\\n1987\\n\\nOutput\\n2013\\n\\nInput\\n2013\\n\\nOutput\\n2014\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input()) + 1\\nwhile len(set(str(n))) != 4:\\n    n += 1\\nprint(n)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nXorgon is an extremely delicious treat formed by the sequence $S$ of binary integers $s_1, s_2,..,s_N$. A really interesting property found in a Xorgon is that the xor of all elements in any contiguous subsequence of length $K$ in $S$ will result in $1$.   \\nChef has been asked to prepare a Xorgon. However, he has at his disposal a binary sequence $X$ containing the binary integers $x_1, x_2, ...x_N$. To prepare a Xorgon, the chef may flip the value of as many binary digits in $X$ as required.(i.e. turn a $1$ to a $0$ and $0$ to a $1$). Unfortunately, flipping a digit takes a lot of time and the chef has to serve many orders. Can you help the chef calculate the minimum number of flips required to cook a Xorgon from the given $X$?\\n\\n-----Input:-----\\n- The first line will contain two space-separated integers $N, K$.\\n- Next line contains N space-separated integers $x_1, x_2, ...,x_N$. \\n\\n-----Output:-----\\nOutput in a single line minimum number of flips required to turn $X$ into a Xorgon.\\n\\n-----Constraints-----\\n- $1 \\\\leq K \\\\leq N \\\\leq 3*10^6$\\n- $0 \\\\leq x_i \\\\leq 1$\\n\\n-----Sample Input:-----\\n7 5\\n1 0 0 1 1 1 1\\n\\n-----Sample Output:-----\\n1\\n\\n-----EXPLANATION:-----\\nFlip the last bit from 1 to 0 to obtain a Xorgon.\",\"targets\":\"# cook your dish here\\nfrom sys import stdin,stdout\\n\\na0=0\\na1=1\\nn,k=stdin.readline().strip().split(' ')\\nn,k=int(n),int(k)\\n\\narr=list(map(int,stdin.readline().strip().split(' ')))\\n\\n\\n\\ndef solve(n,k,arr):\\n sol=[]\\n\\n l=0;u=k;\\n\\n\\n while l!=u:\\n   sol.append(arr[l:min(len(arr),u)])\\n   l=min(l+k,len(arr))\\n   u=min(u+k,len(arr))\\n   \\n tiwari=[]\\n for i in range(k):\\n   titi=0\\n   gao=0\\n   for j in range(len(sol)):\\n    if len(sol[j])>i:\\n     if sol[j][i]==0:\\n      titi+=1\\n     else:\\n      gao+=1\\n   tiwari.append((titi,gao))\\n\\n minflip=(-1,-1)\\n ans=0\\n ctr=0\\n for i in tiwari:\\n   if i[0]<i[1]:\\n    ans+=i[0]\\n    ctr+=(1*a1+a0*a1)*a1\\n    if i[1]<minflip[0] or minflip[0]==-1:\\n     minflip=(i[1],i[0])\\n   else:\\n    ans+=i[1]\\n    if i[0]<minflip[0] or minflip[0]==-1:\\n     minflip=(i[0],i[1])\\n #print(ans,ctr)\\n #print(tiwari)\\n #print(minflip)\\n if ctr%2==0:\\n   ans+=minflip[0]\\n   ans-=minflip[1]\\n\\n\\n stdout.write(str(ans)+\\\"\\\\n\\\")\\n\\nsolve(n,k,arr)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1152\\/C:\\nNeko loves divisors. During the latest number theory lesson, he got an interesting exercise from his math teacher.\\n\\nNeko has two integers $a$ and $b$. His goal is to find a non-negative integer $k$ such that the least common multiple of $a+k$ and $b+k$ is the smallest possible. If there are multiple optimal integers $k$, he needs to choose the smallest one.\\n\\nGiven his mathematical talent, Neko had no trouble getting Wrong Answer on this problem. Can you help him solve it?\\n\\n\\n-----Input-----\\n\\nThe only line contains two integers $a$ and $b$ ($1 \\\\le a, b \\\\le 10^9$).\\n\\n\\n-----Output-----\\n\\nPrint the smallest non-negative integer $k$ ($k \\\\ge 0$) such that the lowest common multiple of $a+k$ and $b+k$ is the smallest possible.\\n\\nIf there are many possible integers $k$ giving the same value of the least common multiple, print the smallest one.\\n\\n\\n-----Examples-----\\nInput\\n6 10\\n\\nOutput\\n2\\nInput\\n21 31\\n\\nOutput\\n9\\nInput\\n5 10\\n\\nOutput\\n0\\n\\n\\n-----Note-----\\n\\nIn the first test, one should choose $k = 2$, as the least common multiple of $6 + 2$ and $10 + 2$ is $24$, which is the smallest least common multiple possible.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a, b = list(map(int, input().split()))\\nif a == b: print(0)\\nelse:\\n    a, b = max(a, b), min(a, b)\\n    x = a-b\\n    if a%x == 0 and b%x == 0: print(0)\\n    else:\\n        if a < 2*b: print(x - b%x)\\n        else:\\n            lis = [i for i in range(1, int(x**0.5)+1) if x%i == 0]\\n            for i in lis[::-1]:\\n                lis.append(x\\/\\/i)\\n            import bisect\\n            y = bisect.bisect(lis, x\\/\\/b)\\n            print(x\\/\\/lis[y-1]-b)\\n# b < a\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/409\\/G:\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 1000) — the number of points on a plane.\\n\\nEach of the next n lines contains two real coordinates x_{i} and y_{i} of the $i^{\\\\text{th}}$ point, specified with exactly 2 fractional digits. All coordinates are between  - 1000 and 1000, inclusive.\\n\\n\\n-----Output-----\\n\\nOutput a single real number θ — the answer to the problem statement. The absolute or relative error of your answer should be at most 10^{ - 2}.\\n\\n\\n-----Examples-----\\nInput\\n8\\n-2.14 2.06\\n-1.14 2.04\\n-2.16 1.46\\n-2.14 0.70\\n-1.42 0.40\\n-0.94 -0.48\\n-1.42 -1.28\\n-2.16 -1.62\\n\\nOutput\\n5.410\\n\\nInput\\n5\\n2.26 1.44\\n2.28 0.64\\n2.30 -0.30\\n1.58 0.66\\n3.24 0.66\\n\\nOutput\\n5.620\\n\\nInput\\n8\\n6.98 2.06\\n6.40 1.12\\n5.98 0.24\\n5.54 -0.60\\n7.16 0.30\\n7.82 1.24\\n8.34 0.24\\n8.74 -0.76\\n\\nOutput\\n5.480\\n\\nInput\\n5\\n10.44 2.06\\n10.90 0.80\\n11.48 -0.48\\n12.06 0.76\\n12.54 2.06\\n\\nOutput\\n6.040\\n\\nInput\\n8\\n16.94 2.42\\n15.72 2.38\\n14.82 1.58\\n14.88 0.50\\n15.76 -0.16\\n16.86 -0.20\\n17.00 0.88\\n16.40 0.92\\n\\nOutput\\n6.040\\n\\nInput\\n7\\n20.62 3.00\\n21.06 2.28\\n21.56 1.36\\n21.66 0.56\\n21.64 -0.52\\n22.14 2.32\\n22.62 3.04\\n\\nOutput\\n6.720\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a=int(input());print(sum([float(input().split(' ')[1]) for i in range(a)])\\/a+5)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe purpose of this problem is to verify whether the method you are using to read input data is sufficiently fast to handle problems branded with the enormous Input\\/Output warning. You are expected to be able to process at least 2.5MB of input data per second at runtime.\\n\\n-----Input-----\\nThe input begins with two positive integers n k (n, k<=107). The next n lines of input contain one positive integer ti, not greater than 109, each.\\n\\n-----Output-----\\nWrite a single integer to output, denoting how many integers ti are divisible by k.\\n\\n-----Example-----\\nInput:\\n7 3\\n1\\n51\\n966369\\n7\\n9\\n999996\\n11\\n\\nOutput:\\n4\",\"targets\":\"#Note that it's python3 Code. Here, we are using input() instead of raw_input().\\n#You can check on your local machine the version of python by typing \\\"python --version\\\" in the terminal.\\n\\n(n, k) = list(map(int, input().split(' ')))\\n\\nans = 0\\n\\nfor i in range(n):\\n\\tx = int(input())\\n\\tif x % k == 0:\\n\\t\\tans += 1\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMutual Recursion allows us to take the fun of regular recursion (where a function calls itself until a terminating condition) and apply it to multiple functions calling each other! \\n\\nLet's use the Hofstadter Female and Male sequences to demonstrate this technique. You'll want to create two functions `F` and `M` such that the following equations are true: \\n\\n```\\nF(0) = 1\\nM(0) = 0\\nF(n) = n - M(F(n - 1))\\nM(n) = n - F(M(n - 1))\\n```\\n\\nDon't worry about negative numbers, `n` will always be greater than or equal to zero.\\n\\n~~~if:php,csharp\\nYou *do* have to worry about performance though, mutual recursion uses up a lot of stack space (and is highly inefficient) so you may have to find a way to make your solution consume less stack space (and time).  Good luck :)\\n~~~\\n\\nHofstadter Wikipedia Reference http:\\/\\/en.wikipedia.org\\/wiki\\/Hofstadter_sequence#Hofstadter_Female_and_Male_sequences\",\"targets\":\"def m(n):\\n    if n <= 0:\\n        return 0\\n    else:\\n        return (n - f(m(n-1)))\\n\\ndef f(n):\\n    if n <= 0:\\n        return 1\\n    else:\\n        return (n - m(f(n-1)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/926\\/G:\\nA flower shop has got n bouquets, and the i-th bouquet consists of a_{i} flowers. Vasya, the manager of the shop, decided to make large bouquets from these bouquets. \\n\\nVasya thinks that a bouquet is large if it is made of two or more initial bouquets, and there is a constraint: the total number of flowers in a large bouquet should be odd. Each of the initial bouquets can be a part of at most one large bouquet. If an initial bouquet becomes a part of a large bouquet, all its flowers are included in the large bouquet.\\n\\nDetermine the maximum possible number of large bouquets Vasya can make. \\n\\n\\n-----Input-----\\n\\nThe first line contains a single positive integer n (1 ≤ n ≤ 10^5) — the number of initial bouquets.\\n\\nThe second line contains a sequence of integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^6) — the number of flowers in each of the initial bouquets.\\n\\n\\n-----Output-----\\n\\nPrint the maximum number of large bouquets Vasya can make. \\n\\n\\n-----Examples-----\\nInput\\n5\\n2 3 4 2 7\\n\\nOutput\\n2\\n\\nInput\\n6\\n2 2 6 8 6 12\\n\\nOutput\\n0\\n\\nInput\\n3\\n11 4 10\\n\\nOutput\\n1\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Vasya can make 2 large bouquets. For example, the first bouquet can contain the first and the fifth initial bouquets (the total number of flowers is then equal to 9), and the second bouquet can consist of the second and the third initial bouquets (the total number of flowers is then equal to 7). The fourth initial bouquet is unused in this scheme. \\n\\nIn the second example it is not possible to form a single bouquet with odd number of flowers.\\n\\nIn the third example Vasya can make one large bouquet. For example, he can make it using all three initial bouquets. The size of the large bouquet is then equal to 11 + 4 + 10 = 25.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\ns = list(map(int, input().split()))\\n\\noddd = 0\\nevend = 0\\n\\nfor i in range(n):\\n if s[i] % 2 == 0:\\n  oddd += 1\\n else:\\n  evend += 1\\nif evend == 0:\\n print(0)\\nelse:\\n if oddd == 0:\\n  print(evend \\/\\/ 3)\\n else:\\n  if oddd < evend:\\n   print(oddd + (evend - oddd) \\/\\/ 3)\\n  else:\\n   print(evend)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFox Ciel is going to publish a paper on FOCS (Foxes Operated Computer Systems, pronounce: \\\"Fox\\\"). She heard a rumor: the authors list on the paper is always sorted in the lexicographical order. \\n\\nAfter checking some examples, she found out that sometimes it wasn't true. On some papers authors' names weren't sorted in lexicographical order in normal sense. But it was always true that after some modification of the order of letters in alphabet, the order of authors becomes lexicographical!\\n\\nShe wants to know, if there exists an order of letters in Latin alphabet such that the names on the paper she is submitting are following in the lexicographical order. If so, you should find out any such order.\\n\\nLexicographical order is defined in following way. When we compare s and t, first we find the leftmost position with differing characters: s_{i} ≠ t_{i}. If there is no such position (i. e. s is a prefix of t or vice versa) the shortest string is less. Otherwise, we compare characters s_{i} and t_{i} according to their order in alphabet.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer n (1 ≤ n ≤ 100): number of names.\\n\\nEach of the following n lines contain one string name_{i} (1 ≤ |name_{i}| ≤ 100), the i-th name. Each name contains only lowercase Latin letters. All names are different.\\n\\n\\n-----Output-----\\n\\nIf there exists such order of letters that the given names are sorted lexicographically, output any such order as a permutation of characters 'a'–'z' (i. e. first output the first letter of the modified alphabet, then the second, and so on).\\n\\nOtherwise output a single word \\\"Impossible\\\" (without...\",\"targets\":\"#import sys\\n#sys.stdin = open('in.txt')\\n#sys.setrecursionlimit(10000)\\ndef isPrefix(sa, sb):\\n    if len(sa) >= len(sb):\\n        return False\\n    return sa == sb[0:len(sa)]\\n\\ndef getOrder(sa, sb):\\n    for i in range(min(len(sa), len(sb))):\\n        if sa[i] != sb[i]:\\n            return sa[i], sb[i]\\n\\ntest = False\\nif test:\\n    fp = open('in.txt', 'r')\\n    n = int(fp.readline().strip())\\n    names = [fp.readline().strip() for _ in range(n)]\\n    fp.close()\\nelse:\\n    n = int(input().strip())\\n    names = [input().strip() for _ in range(n)]\\n\\nres = True\\ng = [[False] * 26 for _ in range(26)]\\n\\\"\\\"\\\"\\nfor i in range(26):\\n    for j in range(26):\\n        g[i][j] = False\\n\\\"\\\"\\\"\\ndef printG():\\n    print(\\\" abcdefghijklmnopqrstuvwxyz\\\")\\n    for i in range(0, 26):\\n        print(chr(ord('a') + i), \\\"\\\".join([\\\"1\\\" if x else \\\"0\\\" for x in g[i]]), sep = \\n\\n\\\"\\\")\\n#get a table\\nfor i in range(n - 1):\\n    if names[i] == names[i + 1] or isPrefix(names[i], names[i + 1]):\\n        continue\\n    elif isPrefix(names[i + 1], names[i]):\\n        res = False\\n        break\\n    else:\\n        ca, cb = getOrder(names[i], names[i + 1])\\n        #print(ca, '<', cb)\\n        if g[ord(cb) - ord('a')][ord(ca) - ord('a')]:\\n            res = False\\n            break\\n        else:\\n            #pass\\n            #printG()\\n            a = ord(ca) - ord('a')\\n            b = ord(cb) - ord('a')\\n            g[a][b] = True\\n            #printG()\\n\\nif not res:\\n    print(\\\"Impossible\\\")\\nelse:\\n    def getZeroIndegreeNode():\\n       for i in range(26):\\n          if not vis[i] and Indegree[i] == 0:\\n              return i\\n       return -1\\n    \\n    #cacl Indegree\\n    strOrder = []\\n    vis = [False] * 26\\n    Indegree = [0] * 26\\n    for i in range(26):\\n        ithIndegree = 0\\n        for j in range(26):\\n            if g[j][i]: ithIndegree += 1\\n        Indegree[i] = ithIndegree\\n    \\n    #get the order string\\n    for i in range(26):\\n        ZeroIndegreeNode = getZeroIndegreeNode()\\n        if ZeroIndegreeNode == -1:\\n            res = False\\n            break\\n        else:\\n           ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc155\\/tasks\\/abc155_a:\\nA triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.\\nYou will be given three integers A, B, and C. If this triple is poor, print Yes; otherwise, print No.\\n\\n-----Constraints-----\\n - A, B, and C are all integers between 1 and 9 (inclusive).\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B C\\n\\n-----Output-----\\nIf the given triple is poor, print Yes; otherwise, print No.\\n\\n-----Sample Input-----\\n5 7 5\\n\\n-----Sample Output-----\\nYes\\n\\nA and C are equal, but B is different from those two numbers, so this triple is poor.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"l= list(map(int,input().split()))\\nla = list(set(l))\\nif len(la)==3 or len(la)==1:\\n  print(\\\"No\\\")\\nelse:\\n  print(\\\"Yes\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/573\\/A:\\nLimak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are n players (including Limak himself) and right now all of them have bids on the table. i-th of them has bid with size a_{i} dollars.\\n\\nEach player can double his bid any number of times and triple his bid any number of times. The casino has a great jackpot for making all bids equal. Is it possible that Limak and his friends will win a jackpot?\\n\\n\\n-----Input-----\\n\\nFirst line of input contains an integer n (2 ≤ n ≤ 10^5), the number of players.\\n\\nThe second line contains n integer numbers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9) — the bids of players.\\n\\n\\n-----Output-----\\n\\nPrint \\\"Yes\\\" (without the quotes) if players can make their bids become equal, or \\\"No\\\" otherwise.\\n\\n\\n-----Examples-----\\nInput\\n4\\n75 150 75 50\\n\\nOutput\\nYes\\n\\nInput\\n3\\n100 150 250\\n\\nOutput\\nNo\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample test first and third players should double their bids twice, second player should double his bid once and fourth player should both double and triple his bid.\\n\\nIt can be shown that in the second sample test there is no way to make all bids equal.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def div23(a):\\n\\twhile (a % 2 == 0):\\n\\t\\ta \\/\\/= 2\\n\\twhile (a % 3 == 0):\\n\\t\\ta \\/\\/= 3\\n\\treturn a\\n\\nn = int(input())\\ns = [int(i) for i in input().split(' ')]\\na = div23(s[0])\\ni = 1\\nwhile i < len(s):\\n\\tif (a != div23(s[i])):\\n\\t\\tbreak\\n\\ti += 1\\n\\nif i == len(s):\\n\\tprint(\\\"Yes\\\")\\nelse:\\n\\tprint(\\\"No\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIlya lives in a beautiful city of Chordalsk.\\n\\nThere are $n$ houses on the street Ilya lives, they are numerated from $1$ to $n$ from left to right; the distance between every two neighboring houses is equal to $1$ unit. The neighboring houses are $1$ and $2$, $2$ and $3$, ..., $n-1$ and $n$. The houses $n$ and $1$ are not neighboring.\\n\\nThe houses are colored in colors $c_1, c_2, \\\\ldots, c_n$ so that the $i$-th house is colored in the color $c_i$. Everyone knows that Chordalsk is not boring, so there are at least two houses colored in different colors.\\n\\nIlya wants to select two houses $i$ and $j$ so that $1 \\\\leq i < j \\\\leq n$, and they have different colors: $c_i \\\\neq c_j$. He will then walk from the house $i$ to the house $j$ the distance of $(j-i)$ units.\\n\\nIlya loves long walks, so he wants to choose the houses so that the distance between them is the maximum possible.\\n\\nHelp Ilya, find this maximum possible distance.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($3 \\\\leq n \\\\leq 300\\\\,000$) — the number of cities on the street.\\n\\nThe second line contains $n$ integers $c_1, c_2, \\\\ldots, c_n$ ($1 \\\\leq c_i \\\\leq n$) — the colors of the houses.\\n\\nIt is guaranteed that there is at least one pair of indices $i$ and $j$ so that $1 \\\\leq i < j \\\\leq n$ and $c_i \\\\neq c_j$.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum possible distance Ilya can walk.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 2 3 2 3\\n\\nOutput\\n4\\n\\nInput\\n3\\n1 2 1\\n\\nOutput\\n1\\n\\nInput\\n7\\n1 1 3 1 1 1 1\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the optimal way is to walk from the first house to the last one, where Ilya can walk the distance of $5-1 = 4$ units.\\n\\nIn the second example the optimal way is to either walk from the first house to the second or from the second to the third. Both these ways have the distance of $1$ unit.\\n\\nIn the third example the optimal way is to walk from the third house to the last one, where Ilya can walk the distance of $7-3 = 4$ units.\",\"targets\":\"#\\t!\\/usr\\/bin\\/env python3\\n#\\tencoding: UTF-8\\n#\\tModified: <06\\/Apr\\/2019 05:10:59 PM>\\n\\n\\n#\\t✪ H4WK3yE乡\\n#\\tMohd. Farhan Tahir\\n#\\tIndian Institute Of Information Technology (IIIT),Gwalior\\n\\n\\n# \\/\\/\\/==========Libraries, Constants and Functions=============\\/\\/\\/\\n\\n\\nimport sys\\n\\n\\ndef get_array(): return list(map(int, sys.stdin.readline().split()))\\n\\n\\ndef get_ints(): return list(map(int, sys.stdin.readline().split()))\\n\\n\\ndef input(): return sys.stdin.readline()\\n\\n# \\/\\/\\/==========MAIN=============\\/\\/\\/\\n\\n\\ndef main():\\n    n = int(input())\\n    arr = get_array()\\n    x = arr[0]\\n    mx = 0\\n    for j in range(n-1, 0, -1):\\n        if arr[j] != x:\\n            mx = j\\n            break\\n    for i in range(1, n):\\n        if arr[i] != x:\\n            next = arr[i]\\n            curr = i\\n            break\\n    for i in range(n-1, curr, -1):\\n        if arr[i] != next:\\n            mx = max(mx, i-curr)\\n            break\\n    print(mx)\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n You are given a string `s`. Let's call its substring a group, if all letters in it are adjacent and the same(such as `\\\"aa\\\",\\\"bbb\\\",\\\"cccc\\\"`..). Let's call the substiring with 2 or more adjacent group a big group(such as `\\\"aabb\\\",\\\"bbccc\\\"`...).\\n \\n Your task is to count the number of `big groups` in the given string.\\n\\n# Example\\n\\n For `s = \\\"ccccoodeffffiiighhhhhhhhhhttttttts\\\"`, the result should be `3`.\\n ```\\nThe groups are \\\"cccc\\\", \\\"oo\\\", \\\"ffff\\\", \\\"iii\\\", \\\"hhhhhhhhhh\\\", \\\"ttttttt\\\"\\nThe big groups are \\\"ccccoo\\\", \\\"ffffiii\\\", \\\"hhhhhhhhhhttttttt\\\", \\n3 substrings altogether.```\\n\\n For `s = \\\"gztxxxxxggggggggggggsssssssbbbbbeeeeeeehhhmmmmmmmitttttttlllllhkppppp\\\"`, the result should be `2`.\\n ```\\nThe big groups are :\\n\\\"xxxxxggggggggggggsssssssbbbbbeeeeeeehhhmmmmmmm\\\"\\nand \\n\\\"tttttttlllll\\\" ```\\n\\n For `s = \\\"soooooldieeeeeer\\\"`, the result should be `0`.\\n \\n There is no `big group` exist.\\n \\n# Input\\/Output\\n\\n\\n - `[input]` string `s`\\n\\n  A string of lowercase Latin letters.\\n\\n\\n - `[output]` an integer\\n\\n  The number of big groups.\",\"targets\":\"def repeat_adjacent(string):\\n    a,b,c,d=0,[],'',0\\n    for i in range(a,len(string)-1):\\n        if string[i]==string[i+1]:\\n            continue\\n        else:\\n            b.append(string[a:i+1])\\n            a=i+1\\n    b.append(string[-(len(string)-a):])\\n    \\n    for j in b:\\n        if len(j)>1:\\n            c+=j\\n        else:\\n            c+='*'\\n    \\n    for k in c.split('*'):\\n        if len(set(k))>1:\\n            d+=1\\n    return d\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVision has finally made it to Wakanda to get his MindStone extracted. The MindStone was linked to his brain in a highly sophisticated manner and Shuri had to solve a complex problem to extract the stone. The MindStone had $n$ integers inscribed in it and Shuri needs to apply the prefix sum operation on the array $k$ times to extract the stone.\\nFormally, given $n$ integers $A[1], A[2] ..... A[n]$ and a number $k$, apply the operation\\n$A[i] = \\\\sum_{j=1}^{i} A[j]$\\non the array $k$ times.\\nFinally Shuri needs to apply $modulo$ $(10^9 + 7)$ operation to each element of the array. Can you help Shuri accomplish this task before Thanos gets to them?\\n\\n-----Input:-----\\n- First line of the input consists of two space separated integers $n$ and $k$. \\n- Second line contains $n$ space separated integers $A[1] .. A[n]$.\\n\\n-----Output:-----\\nIn a single line print $n$ space separated integers, the values of the resultant array after applying all the operations.\\n\\n-----Constraints-----\\n- $1 \\\\leq n \\\\leq 1000$\\n- $1 \\\\leq k \\\\leq 10^{12}$\\n- $1 \\\\leq A[i] \\\\leq 10^9$\\n\\n-----Subtasks-----\\n- 20 Points: $1 \\\\leq k \\\\leq 1000$\\n- 30 Points: $1 \\\\leq k \\\\leq 1000000$\\n- 50 Points: Original Constraints\\n\\n-----Sample Input:-----\\n$4$ $2$\\n$3$ $4$ $1$ $5$\\n\\n-----Sample Output:-----\\n$3$ $10$ $18$ $31$\\n\\n-----EXPLANATION:-----\\nAfter applying the prefix sum operation once the array becomes -> $3$ $7$ $8$ $13$\\nAfter applying the prefix sum operation for the second time, the array becomes -> $3$ $10$ $18$ $31$\\nAfter applying $modulo$ $(10^9 +7)$ operation, array becomes -> $3$ $10$ $18$ $31$\",\"targets\":\"# cook your dish here\\nfrom itertools import accumulate\\nn, k = map(int, input().split())\\nlst = list(map(int, input().split()))\\ntemp = (10**9)+7\\nfor i in range(k):\\n    lst = list(accumulate(lst))\\nfor i in lst:\\n    print(i%(temp), end = ' ')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/725\\/D:\\nOne tradition of ACM-ICPC contests is that a team gets a balloon for every solved problem. We assume that the submission time doesn't matter and teams are sorted only by the number of balloons they have. It means that one's place is equal to the number of teams with more balloons, increased by 1. For example, if there are seven teams with more balloons, you get the eight place. Ties are allowed.\\n\\nYou should know that it's important to eat before a contest. If the number of balloons of a team is greater than the weight of this team, the team starts to float in the air together with their workstation. They eventually touch the ceiling, what is strictly forbidden by the rules. The team is then disqualified and isn't considered in the standings.\\n\\nA contest has just finished. There are n teams, numbered 1 through n. The i-th team has t_{i} balloons and weight w_{i}. It's guaranteed that t_{i} doesn't exceed w_{i} so nobody floats initially.\\n\\nLimak is a member of the first team. He doesn't like cheating and he would never steal balloons from other teams. Instead, he can give his balloons away to other teams, possibly making them float. Limak can give away zero or more balloons of his team. Obviously, he can't give away more balloons than his team initially has.\\n\\nWhat is the best place Limak can get?\\n\\n\\n-----Input-----\\n\\nThe first line of the standard input contains one integer n (2 ≤ n ≤ 300 000) — the number of teams.\\n\\nThe i-th of n following lines contains two integers t_{i} and w_{i} (0 ≤ t_{i} ≤ w_{i} ≤ 10^18) — respectively the number of balloons and the weight of the i-th team. Limak is a member of the first team.\\n\\n\\n-----Output-----\\n\\nPrint one integer denoting the best place Limak can get.\\n\\n\\n-----Examples-----\\nInput\\n8\\n20 1000\\n32 37\\n40 1000\\n45 50\\n16 16\\n16 16\\n14 1000\\n2 1000\\n\\nOutput\\n3\\n\\nInput\\n7\\n4 4\\n4 4\\n4 4\\n4 4\\n4 4\\n4 4\\n5 5\\n\\nOutput\\n2\\n\\nInput\\n7\\n14000000003 1000000000000000000\\n81000000000 88000000000\\n5000000000 7000000000\\n15000000000 39000000000\\n46000000000 51000000000\\n0 1000000000\\n0 0\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nfrom heapq import heappop, heappush, heapify\\n\\nn = int(input())\\nb, _ = list(map(int, input().split()))\\nheap = []\\nheap2 = []\\nfor _ in range(n-1):\\n    t, w = list(map(int, input().split()))\\n    if t > b:\\n        heap.append(w + 1 - t)\\n    else:\\n        heap2.append((-t, -w))\\nheapify(heap)\\nheapify(heap2)\\nans = len(heap) + 1\\nwhile heap:\\n    need = heap[0]\\n    if need > b:\\n        break\\n    b -= need\\n    heappop(heap)\\n    while heap2 and -heap2[0][0] > b:\\n        t, w = heappop(heap2)\\n        t, w = -t, -w\\n        heappush(heap, w + 1 - t)\\n    cur = len(heap) + 1\\n    ans = min(ans, cur)\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1393\\/D:\\nCarousel Boutique is busy again! Rarity has decided to visit the pony ball and she surely needs a new dress, because going out in the same dress several times is a sign of bad manners. First of all, she needs a dress pattern, which she is going to cut out from the rectangular piece of the multicolored fabric.\\n\\nThe piece of the multicolored fabric consists of $n \\\\times m$ separate square scraps. Since Rarity likes dresses in style, a dress pattern must only include scraps sharing the same color. A dress pattern must be the square, and since Rarity is fond of rhombuses, the sides of a pattern must form a $45^{\\\\circ}$ angle with sides of a piece of fabric (that way it will be resembling the traditional picture of a rhombus).\\n\\nExamples of proper dress patterns: [Image] Examples of improper dress patterns: [Image] The first one consists of multi-colored scraps, the second one goes beyond the bounds of the piece of fabric, the third one is not a square with sides forming a $45^{\\\\circ}$ angle with sides of the piece of fabric.\\n\\nRarity wonders how many ways to cut out a dress pattern that satisfies all the conditions that do exist. Please help her and satisfy her curiosity so she can continue working on her new masterpiece!\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $m$ ($1 \\\\le n, m \\\\le 2000$). Each of the next $n$ lines contains $m$ characters: lowercase English letters, the $j$-th of which corresponds to scrap in the current line and in the $j$-th column. Scraps having the same letter share the same color, scraps having different letters have different colors.\\n\\n\\n-----Output-----\\n\\nPrint a single integer: the number of ways to cut out a dress pattern to satisfy all of Rarity's conditions.\\n\\n\\n-----Examples-----\\nInput\\n3 3\\naaa\\naaa\\naaa\\n\\nOutput\\n10\\n\\nInput\\n3 4\\nabab\\nbaba\\nabab\\n\\nOutput\\n12\\n\\nInput\\n5 5\\nzbacg\\nbaaac\\naaaaa\\neaaad\\nweadd\\n\\nOutput\\n31\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, all the dress patterns of size $1$ and one of size $2$ are satisfactory.\\n\\nIn the second example, only the dress patterns of size...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def tc():\\n    n, m = list(map(int, input().split()))\\n    mat = [input() for _ in range(n)]\\n    alpha = 'abcdefghijklmnopqrstuvwxyz'\\n\\n    dp = [[0] * m for _ in range(n)]\\n    ans = 0\\n    for i in range(n):\\n        for j in range(m):\\n\\n            if j == 0 or j == m - 1 or i < 2:\\n                dp[i][j] = 1\\n            elif mat[i][j] == mat[i - 1][j] and mat[i][j] == mat[i - 1][j - 1] and mat[i][j] == mat[i - 1][j + 1] and mat[i][j] == mat[i - 2][j]:\\n                dp[i][j] = min(dp[i - 1][j], dp[i - 1][j - 1], dp[i - 1][j + 1], dp[i - 2][j]) + 1\\n            else:\\n                dp[i][j] = 1\\n            ans += dp[i][j]\\n\\n    print(ans)\\n\\n\\n#################\\ntc()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/designer-door-mat\\/problem:\\n=====Problem Statement=====\\nMr. Vincent works in a door mat manufacturing company. One day, he designed a new door mat with the following specifications:\\nMat size must be NXM. (N is an odd natural number, M and is 3 times N.)\\nThe design should have 'WELCOME' written in the center.\\nThe design pattern should only use |, . and - characters.\\n\\nSample Designs\\n\\n    Size: 7 x 21 \\n    ---------.|.---------\\n    ------.|..|..|.------\\n    ---.|..|..|..|..|.---\\n    -------WELCOME-------\\n    ---.|..|..|..|..|.---\\n    ------.|..|..|.------\\n    ---------.|.---------\\n    \\n    Size: 11 x 33\\n    ---------------.|.---------------\\n    ------------.|..|..|.------------\\n    ---------.|..|..|..|..|.---------\\n    ------.|..|..|..|..|..|..|.------\\n    ---.|..|..|..|..|..|..|..|..|.---\\n    -------------WELCOME-------------\\n    ---.|..|..|..|..|..|..|..|..|.---\\n    ------.|..|..|..|..|..|..|.------\\n    ---------.|..|..|..|..|.---------\\n    ------------.|..|..|.------------\\n    ---------------.|.---------------\\n\\n=====Input Format=====\\nA single line containing the space separated values of N and M.\\n\\n=====Constraints=====\\n5 < N < 101\\n15 < M < 303\\n\\n=====Output Format=====\\nOutput the design pattern.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N, M = list(map(int,input().split())) # More than 6 lines of code will result in 0 score. Blank lines are not counted.\\nfor i in range(1, N, 2): \\n    print(((i*\\\".|.\\\").center(3*N, \\\"-\\\")))\\nprint((\\\"-WELCOME-\\\".center(3*N, \\\"-\\\")))\\nfor i in range(N - 2, -1, -2): \\n    print(((i*\\\".|.\\\").center(3*N, \\\"-\\\")))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPolycarp has a cat and his cat is a real gourmet! Dependent on a day of the week he eats certain type of food:  on Mondays, Thursdays and Sundays he eats fish food;  on Tuesdays and Saturdays he eats rabbit stew;  on other days of week he eats chicken stake. \\n\\nPolycarp plans to go on a trip and already packed his backpack. His backpack contains:  $a$ daily rations of fish food;  $b$ daily rations of rabbit stew;  $c$ daily rations of chicken stakes. \\n\\nPolycarp has to choose such day of the week to start his trip that his cat can eat without additional food purchases as long as possible. Print the maximum number of days the cat can eat in a trip without additional food purchases, if Polycarp chooses the day of the week to start his trip optimally.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three positive integers $a$, $b$ and $c$ ($1 \\\\le a, b, c \\\\le 7\\\\cdot10^8$) — the number of daily rations of fish food, rabbit stew and chicken stakes in Polycarps backpack correspondingly.\\n\\n\\n-----Output-----\\n\\nPrint the maximum number of days the cat can eat in a trip without additional food purchases, if Polycarp chooses the day of the week to start his trip optimally.\\n\\n\\n-----Examples-----\\nInput\\n2 1 1\\n\\nOutput\\n4\\n\\nInput\\n3 2 2\\n\\nOutput\\n7\\n\\nInput\\n1 100 1\\n\\nOutput\\n3\\n\\nInput\\n30 20 10\\n\\nOutput\\n39\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the best day for start of the trip is Sunday. In this case, during Sunday and Monday the cat will eat fish food, during Tuesday — rabbit stew and during Wednesday — chicken stake. So, after four days of the trip all food will be eaten.\\n\\nIn the second example Polycarp can start his trip in any day of the week. In any case there are food supplies only for one week in Polycarps backpack.\\n\\nIn the third example Polycarp can start his trip in any day, excluding Wednesday, Saturday and Sunday. In this case, the cat will eat three different dishes in three days. Nevertheless that after three days of a trip there will be $99$ portions of rabbit stew in a backpack, can cannot eat anything in fourth day...\",\"targets\":\"IN = input\\nrint = lambda: int(IN())\\nrmint = lambda: list(map(int, IN().split()))\\nrlist = lambda: list(rmint())\\n\\nw = [0, 1, 2, 0, 2, 1, 0]\\nh = rlist()\\nans = 0\\n\\n\\ndef g(x):\\n    p = w[x:]\\n    a = h[:]\\n    v = 0\\n    for f in p:\\n        if not a[f]: return v\\n        a[f] -= 1\\n        v += 1\\n    u = min([a[0] \\/\\/ 3, a[1] \\/\\/ 2, a[2] \\/\\/ 2])\\n    a[0] -= u*3\\n    a[1] -= u*2\\n    a[2] -= u*2\\n    v += u * 7\\n    for f in w:\\n        if not a[f]: return v\\n        a[f] -= 1\\n        v += 1\\n    return v\\n\\n\\nfor i in range(7): ans = max(ans, g(i))\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an array A with size N (indexed from 0) and an integer K. Let's define another array B with size N · K as the array that's formed by concatenating K copies of array A.\\nFor example, if A = {1, 2} and K = 3, then B = {1, 2, 1, 2, 1, 2}.\\nYou have to find the maximum subarray sum of the array B. Fomally, you should compute the maximum value of Bi + Bi+1 + Bi+2 + ... + Bj, where 0 ≤ i ≤ j < N · K.\\n\\n-----Input-----\\n\\n- The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.\\n- The first line of each test case contains two space-separated integers N and K.\\n- The second line contains N space-separated integers A0, A1, ..., AN-1.\\n\\n-----Output-----\\nFor each test case, print a single line containing the maximum subarray sum of B.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 10\\n- 1 ≤ N ≤ 105\\n- 1 ≤ K ≤ 105\\n- -106 ≤ Ai ≤ 106 for each valid i\\n\\n-----Subtasks-----\\nSubtask #1 (18 points): N · K ≤ 105\\nSubtask #2 (82 points): original constraints\\n\\n-----Example-----\\nInput:\\n\\n2\\n2 3\\n1 2\\n3 2\\n1 -2 1\\n\\nOutput:\\n\\n9\\n2\\n\\n-----Explanation-----\\nExample case 1: B = {1, 2, 1, 2, 1, 2} and the subarray with maximum sum is the whole {1, 2, 1, 2, 1, 2}. Hence, the answer is 9.\\nExample case 2: B = {1, -2, 1, 1, -2, 1} and the subarray with maximum sum is {1, 1}. Hence, the answer is 2.\",\"targets\":\"# cook your dish here\\nimport math\\ntcases = int(input())\\nmyanswer = []\\ndef programrun(tcases):\\n    if tcases==0:\\n        print(0)\\n        return\\n    \\n    def msumfinder(array, n, k):\\n        msofar = -10000000\\n        mendnow = 0\\n        for i in range(n*k):\\n            mendnow+=array[i%n]\\n            if mendnow>msofar:\\n                msofar = mendnow\\n            if mendnow<0:\\n                mendnow = 0\\n        return msofar\\n        \\n    for _ in range(0,tcases):\\n        fline = input().split()\\n        fline = list(map(int, fline))\\n        k = fline[1]\\n        n = fline[0]\\n        a = [int(x) for x in input().split()]\\n        sa = sum(a)\\n        if sa>0:\\n            if k==1 or k==2:\\n                print(msumfinder(a,n,k))\\n            else:\\n                print(msumfinder(a,n,2) + (k-2)*sa)\\n        else:\\n            print(msumfinder(a,n,2))\\n    \\n        \\n        \\nprogramrun(tcases)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1032\\/A:\\nThe king's birthday dinner was attended by $k$ guests. The dinner was quite a success: every person has eaten several dishes (though the number of dishes was the same for every person) and every dish was served alongside with a new set of kitchen utensils.\\n\\nAll types of utensils in the kingdom are numbered from $1$ to $100$. It is known that every set of utensils is the same and consist of different types of utensils, although every particular type may appear in the set at most once. For example, a valid set of utensils can be composed of one fork, one spoon and one knife.\\n\\nAfter the dinner was over and the guests were dismissed, the king wondered what minimum possible number of utensils could be stolen. Unfortunately, the king has forgotten how many dishes have been served for every guest but he knows the list of all the utensils left after the dinner. Your task is to find the minimum possible number of stolen utensils.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integer numbers $n$ and $k$ ($1 \\\\le n \\\\le 100, 1 \\\\le k \\\\le 100$)  — the number of kitchen utensils remaining after the dinner and the number of guests correspondingly.\\n\\nThe next line contains $n$ integers $a_1, a_2, \\\\ldots, a_n$ ($1 \\\\le a_i \\\\le 100$)  — the types of the utensils remaining. Equal values stand for identical utensils while different values stand for different utensils.\\n\\n\\n-----Output-----\\n\\nOutput a single value — the minimum number of utensils that could be stolen by the guests.\\n\\n\\n-----Examples-----\\nInput\\n5 2\\n1 2 2 1 3\\n\\nOutput\\n1\\n\\nInput\\n10 3\\n1 3 3 1 3 5 5 5 5 100\\n\\nOutput\\n14\\n\\n\\n\\n-----Note-----\\n\\nIn the first example it is clear that at least one utensil of type $3$ has been stolen, since there are two guests and only one such utensil. But it is also possible that every person received only one dish and there were only six utensils in total, when every person got a set $(1, 2, 3)$ of utensils. Therefore, the answer is $1$.\\n\\nOne can show that in the second example at least $2$ dishes should have been served for every guest, so the number...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, k = map(int, input().split())\\nM = list(map(int, input().split()))\\n\\nT = [0] * 100\\nfor i in range (n): T[M[i] - 1] += 1\\n\\nt, b = 0, 0\\nfor i in range (100):\\n    if T[i] != 0:\\n        t += 1\\n        b = max(b, (T[i] + k - 1) \\/\\/ k)\\n\\nprint (b * t * k - n)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVlad likes to eat in cafes very much. During his life, he has visited cafes n times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.\\n\\nFirst of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes he visited in a row, in order of visiting them. Now, Vlad wants to find such a cafe that his last visit to that cafe was before his last visits to every other cafe. In other words, he wants to find such a cafe that he hasn't been there for as long as possible. Help Vlad to find that cafe.\\n\\n\\n-----Input-----\\n\\nIn first line there is one integer n (1 ≤ n ≤ 2·10^5) — number of cafes indices written by Vlad.\\n\\nIn second line, n numbers a_1, a_2, ..., a_{n} (0 ≤ a_{i} ≤ 2·10^5) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, some indices could be omitted.\\n\\n\\n-----Output-----\\n\\nPrint one integer — index of the cafe that Vlad hasn't visited for as long as possible.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 3 2 1 2\\n\\nOutput\\n3\\n\\nInput\\n6\\n2 1 2 2 4 1\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer. \\n\\nIn second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with index 2, so the answer is 2. Note that Vlad could omit some numbers while numerating the cafes.\",\"targets\":\"def ma():\\n    n=int(input())\\n    b=list(map(int,input().split()))\\n    k={b[-1]};last=b[-1]\\n    for i in range(n-1,-1,-1):\\n        if not (b[i] in k):\\n            last=b[i];\\n            k.add(b[i])\\n    print(last)\\nma()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have a set of consecutive numbers from ```1``` to ```n```.\\nWe want to count all the subsets that do not contain consecutive numbers.\\nE.g.\\n\\nIf our set ```S1``` is equal to ```[1,2,3,4,5]```\\nThe subsets that fulfill these property are:\\n```\\n[1],[2],[3],[4],[5],[1,3],[1,4],[1,5],[2,4],[2,5],[3,5],[1,3,5]\\n```\\nA total of      ```12   ``` subsets.\\n\\nFrom the set ```S2``` equals to```[1,2,3]```, it is obvious that we have only ```4``` subsets and are:\\n```\\n[1],[2],[3],[1,3]\\n```\\nMake a code that may give the amount of all these subsets for any integer       ```n >= 2       ```.\\n\\nFeatures of the random tests:\\n```\\nnumber of tests = 100 \\n10 <= n <= 120\\n```\",\"targets\":\"FIBS = [1, 1]\\n\\ndef f(n):\\n    # I dedicate this method to oeis.org :)\\n    while len(FIBS) <= n + 1:\\n        FIBS.append(FIBS[-2] + FIBS[-1])\\n    return FIBS[n + 1] - 1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc123\\/tasks\\/abc123_c:\\nIn 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!\\nThere are five means of transport in this empire:\\n - Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.\\n - Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.\\n - Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.\\n - Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.\\n - Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.\\nFor each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).\\nThere is a group of N people at City 1, and they all want to go to City 6.\\n\\nAt least how long does it take for all of them to reach there? \\nYou can ignore the time needed to transfer.  \\n\\n-----Constraints-----\\n - 1 \\\\leq N, A, B, C, D, E \\\\leq 10^{15}\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA\\nB\\nC\\nD\\nE\\n\\n-----Output-----\\nPrint the minimum time required for all of the people to reach City 6, in minutes.\\n\\n-----Sample Input-----\\n5\\n3\\n2\\n4\\n3\\n5\\n\\n-----Sample Output-----\\n7\\n\\nOne possible way to travel is as follows.\\nFirst, there are N = 5 people at City 1, as shown in the following image:\\n\\nIn the first minute, three people travels from City 1 to City 2 by train. Note that a train can only occupy at most three people.\\n\\nIn the second minute, the remaining two people travels from City 1 to City 2 by train, and two of the three people who were already at City 2 travels to City 3 by bus. Note that a bus can only occupy at most two people.\\n\\nIn the third minute, two people travels from City 2 to City 3 by train, and another two people travels from City 3 to City 4 by taxi.\\n\\nFrom then on, if they continue traveling without stopping until they reach City 6, all of them can reach there in seven minutes.\\n\\nThere is no way for them to reach City 6 in 6 minutes or less.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math as mt\\nn=int(input())\\nlst=[int(input()) for i in range(5)]\\nprint(mt.ceil(n\\/min(lst))+4)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/PCJ18B:\\nChef has recently been playing a lot of chess in preparation for the ICCT (International Chef Chess Tournament).\\nSince putting in long hours is not an easy task, Chef's mind wanders elsewhere. He starts counting the number of squares with odd side length on his chessboard..\\nHowever, Chef is not satisfied. He wants to know the number of squares of odd side length on a generic $N*N$ chessboard.\\n\\n-----Input:-----\\n- The first line will contain a single integer $T$, the number of test cases.\\n- The next $T$ lines will have a single integer $N$, the size of the chess board.\\n\\n-----Output:-----\\nFor each test case, print a integer denoting the number of squares with odd length.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $1 \\\\leq N \\\\leq 1000$\\n\\n-----Sample Input:-----\\n2\\n3\\n8\\n\\n-----Sample Output:-----\\n10\\n120\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nt=int(input())\\nfor _ in range(t):\\n s=0\\n n=int(input())\\n while(n>0):\\n  s+=(n*n)\\n  n-=2\\n print(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a string S  of numbers. Dr. Dragoon has eaten up some numbers of the string. You decide to fix the string by putting the numbers 0 and 1 in the empty spaces. \\nThe base cost for putting the ‘0’  is x  and putting ‘1’  is y . The cost of putting a number is the base cost multiplied by the number of times you use the letter till  that position (including   the position ).  The local mayor is happy with your work and commissions you for every number you put. \\n\\nMore specifically ,  if you put , say 0  in 5th position, the mayor will count the number of occurrences of 0  till 5th   position and pay you the same amount. You wonder what the minimum cost for fixing the string is. Note  – The answer can also be negative, they denote that you got an overall profit.\\n\\nInput Format: \\n\\nThe input consists of 2 lines. First-line consists of the string of numbers S. ‘?’  denotes an empty position. \\n\\nThe second line consists of 2 integers x,y, the base cost of 0 and 1. \\n\\nOutput Format:  \\n\\nOutput 1 integer, the minimum cost of fixing the string.\\n\\nConstraints :  \\n\\n1<=|S|<=100\\n\\n1<=x,y<=100 \\n\\nSample Input:  \\n\\n501?1?\\n\\n6 5\\n\\nSample Output:  \\n\\n6\\n\\nSample Input:  \\n\\n1001?11?\\n\\n5  23\\n\\nSample Output:  \\n\\n8\\n\\nExplanation  :  \\n\\nFill 0 in the first place, the net cost will be 6-2=4. In the second place fill, 1 the net cost will be 5-3=2 Hence total cost is 4+2=6. \\n\\nIn second test case we will fill both spaces with zero , filling first zero costs  1*5-3=2 and filling the other zero costs  2*5  - 4 =6  , so total being 8.\",\"targets\":\"# cook your dish here\\ndef ans(n,a,b):\\n    if n == act:\\n        return 0\\n    if dp[n][a][b] != -1:\\n        return dp[n][a][b]\\n    if l[n] == \\\"0\\\":\\n        dp[n][a][b]\\n        return ans(n+1,a+1,b)\\n    elif l[n] == \\\"1\\\":\\n        dp[n][a][b] = ans(n+1,a,b+1)\\n        return ans(n+1,a,b+1)\\n    elif l[n] == \\\"?\\\":\\n        dp[n][a][b] = min((a-l1[n]+1)*x -(a+1) + ans(n+1,a+1,b),(b-l2[n]+1)*y -(b+1) + ans(n+1,a,b+1))\\n        return(min((a-l1[n]+1)*x -(a+1) + ans(n+1,a+1,b),(b-l2[n]+1)*y -(b+1) + ans(n+1,a,b+1)))\\n    else:\\n        dp[n][a][b] = ans(n+1,a,b)\\n        return ans(n+1,a,b)\\n\\nl = str(input())\\nx,y = map(int,input().split())\\ndp = [[[-1 for i in range(101)]for j in range(101)]for k in range(101)]\\nl1 = []\\nl2 = []\\nc = 0\\nk = 0\\nfor i in l:\\n    if i == \\\"1\\\":\\n        c+=1\\n    if i == \\\"0\\\":\\n        k+=1\\n    l1.append(k)\\n    l2.append(c)\\nact = len(l)\\ndd = ans(0,0,0)\\nprint(dd)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1189\\/C:\\nConsider a sequence of digits of length $2^k$ $[a_1, a_2, \\\\ldots, a_{2^k}]$. We perform the following operation with it: replace pairs $(a_{2i+1}, a_{2i+2})$ with $(a_{2i+1} + a_{2i+2})\\\\bmod 10$ for $0\\\\le i<2^{k-1}$. For every $i$ where $a_{2i+1} + a_{2i+2}\\\\ge 10$ we get a candy! As a result, we will get a sequence of length $2^{k-1}$.\\n\\nLess formally, we partition sequence of length $2^k$ into $2^{k-1}$ pairs, each consisting of 2 numbers: the first pair consists of the first and second numbers, the second of the third and fourth $\\\\ldots$, the last pair consists of the ($2^k-1$)-th and ($2^k$)-th numbers. For every pair such that sum of numbers in it is at least $10$, we get a candy. After that, we replace every pair of numbers with a remainder of the division of their sum by $10$ (and don't change the order of the numbers).\\n\\nPerform this operation with a resulting array until it becomes of length $1$. Let $f([a_1, a_2, \\\\ldots, a_{2^k}])$ denote the number of candies we get in this process. \\n\\nFor example: if the starting sequence is $[8, 7, 3, 1, 7, 0, 9, 4]$ then:\\n\\nAfter the first operation the sequence becomes $[(8 + 7)\\\\bmod 10, (3 + 1)\\\\bmod 10, (7 + 0)\\\\bmod 10, (9 + 4)\\\\bmod 10]$ $=$ $[5, 4, 7, 3]$, and we get $2$ candies as $8 + 7 \\\\ge 10$ and $9 + 4 \\\\ge 10$.\\n\\nAfter the second operation the sequence becomes $[(5 + 4)\\\\bmod 10, (7 + 3)\\\\bmod 10]$ $=$ $[9, 0]$, and we get one more candy as $7 + 3 \\\\ge 10$. \\n\\nAfter the final operation sequence becomes $[(9 + 0) \\\\bmod 10]$ $=$ $[9]$. \\n\\nTherefore, $f([8, 7, 3, 1, 7, 0, 9, 4]) = 3$ as we got $3$ candies in total.\\n\\nYou are given a sequence of digits of length $n$ $s_1, s_2, \\\\ldots s_n$. You have to answer $q$ queries of the form $(l_i, r_i)$, where for $i$-th query you have to output $f([s_{l_i}, s_{l_i+1}, \\\\ldots, s_{r_i}])$. It is guaranteed that $r_i-l_i+1$ is of form $2^k$ for some nonnegative integer $k$.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\le n \\\\le 10^5$) — the length of the sequence.\\n\\nThe second line contains $n$ digits $s_1,...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# Binary Indexed Tree (Fenwick Tree)\\nclass BIT():\\n    def __init__(self, n):\\n        '''n = 要素数\\n        要素の添字iは 0 <= i < n となる\\n        '''\\n        self.n = n\\n        self.bit = [0] * (n + 1)\\n\\n    def add(self, i, val):\\n        '''i番目の要素にvalを加算する O(logN)'''\\n        i = i + 1\\n        while i <= self.n:\\n            self.bit[i] += val\\n            i += i & -i\\n\\n    def _sum(self, i):\\n        s = 0\\n        while i > 0:\\n            s += self.bit[i]\\n            i -= i & -i\\n        return s\\n\\n    def sum(self, i, j):\\n        '''区間[i, j)の和を求める O(logN)'''\\n        return self._sum(j) - self._sum(i)\\n\\n\\nimport sys\\n\\ninput = sys.stdin.readline\\nn = int(input())\\na = list(map(int, input().split()))\\nq = int(input())\\nquery = [list(map(int, input().split())) for i in range(q)]\\n\\nbit = BIT(n)\\nfor i in range(n):\\n    bit.add(i, a[i])\\nfor i in range(q):\\n    l, r = query[i]\\n    l -= 1\\n    print(bit.sum(l, r) \\/\\/ 10)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nJoe has been hurt on the Internet. Now he is storming around the house, destroying everything in his path.\\n\\nJoe's house has n floors, each floor is a segment of m cells. Each cell either contains nothing (it is an empty cell), or has a brick or a concrete wall (always something one of three). It is believed that each floor is surrounded by a concrete wall on the left and on the right.\\n\\nNow Joe is on the n-th floor and in the first cell, counting from left to right. At each moment of time, Joe has the direction of his gaze, to the right or to the left (always one direction of the two). Initially, Joe looks to the right.\\n\\nJoe moves by a particular algorithm. Every second he makes one of the following actions:   If the cell directly under Joe is empty, then Joe falls down. That is, he moves to this cell, the gaze direction is preserved.  Otherwise consider the next cell in the current direction of the gaze.   If the cell is empty, then Joe moves into it, the gaze direction is preserved.  If this cell has bricks, then Joe breaks them with his forehead (the cell becomes empty), and changes the direction of his gaze to the opposite.  If this cell has a concrete wall, then Joe just changes the direction of his gaze to the opposite (concrete can withstand any number of forehead hits).  \\n\\nJoe calms down as soon as he reaches any cell of the first floor.\\n\\nThe figure below shows an example Joe's movements around the house.\\n\\n [Image] \\n\\nDetermine how many seconds Joe will need to calm down.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (2 ≤ n ≤ 100, 1 ≤ m ≤ 10^4).\\n\\nNext n lines contain the description of Joe's house. The i-th of these lines contains the description of the (n - i + 1)-th floor of the house — a line that consists of m characters: \\\".\\\" means an empty cell, \\\"+\\\" means bricks and \\\"#\\\" means a concrete wall.\\n\\nIt is guaranteed that the first cell of the n-th floor is empty.\\n\\n\\n-----Output-----\\n\\nPrint a single number — the number of seconds Joe needs to reach the first floor; or else, print word...\",\"targets\":\"n, m = [int(i) for i in input().split()]\\ncurrent_floor = list(input())\\n\\nx, t, direction = 0, 0, 1\\n\\nfor i in range(n-1):\\n    floor = list(input())\\n    l, r = x, x\\n    wall = 0\\n    while True:\\n        t += 1\\n        if floor[x] == '.':\\n            break\\n        if (x + direction == m) or (x + direction < 0) or (current_floor[x+direction] == '#'):\\n            wall += 1\\n            direction = -direction\\n            if wall == 2:\\n                print(\\\"Never\\\")\\n                return\\n        elif current_floor[x+direction] == '+':\\n            wall = 0\\n            current_floor[x+direction] = '.'\\n            direction = -direction\\n        elif l <= x+direction and x+direction <= r:\\n            if direction == 1:\\n                t += r-x-1\\n                x = r\\n            else:\\n                t += x-l-1\\n                x = l\\n        else:\\n            x += direction\\n            r = max(r, x)\\n            l = min(l, x)\\n    current_floor, floor = floor, current_floor\\nprint(t)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWrite\\n\\n```python\\nfunction combine()\\n```\\n\\nthat combines arrays by alternatingly taking elements passed to it.\\n\\nE.g\\n\\n```python\\ncombine(['a', 'b', 'c'], [1, 2, 3]) == ['a', 1, 'b', 2, 'c', 3]\\ncombine(['a', 'b', 'c'], [1, 2, 3, 4, 5]) == ['a', 1, 'b', 2, 'c', 3, 4, 5]\\ncombine(['a', 'b', 'c'], [1, 2, 3, 4, 5], [6, 7], [8]) == ['a', 1, 6, 8, 'b', 2, 7, 'c', 3, 4, 5]\\n```\\n\\nArrays can have different lengths.\",\"targets\":\"combine = lambda *args: [el[0] for el in args] + combine(*[el[1:] for el in args if len(el)>1]) if args else []\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1027\\/G:\\nThe campus has $m$ rooms numbered from $0$ to $m - 1$. Also the $x$-mouse lives in the campus. The $x$-mouse is not just a mouse: each second $x$-mouse moves from room $i$ to the room $i \\\\cdot x \\\\mod{m}$ (in fact, it teleports from one room to another since it doesn't visit any intermediate room). Starting position of the $x$-mouse is unknown.\\n\\nYou are responsible to catch the $x$-mouse in the campus, so you are guessing about minimum possible number of traps (one trap in one room) you need to place. You are sure that if the $x$-mouse enters a trapped room, it immediately gets caught.\\n\\nAnd the only observation you made is $\\\\text{GCD} (x, m) = 1$.\\n\\n\\n-----Input-----\\n\\nThe only line contains two integers $m$ and $x$ ($2 \\\\le m \\\\le 10^{14}$, $1 \\\\le x < m$, $\\\\text{GCD} (x, m) = 1$) — the number of rooms and the parameter of $x$-mouse. \\n\\n\\n-----Output-----\\n\\nPrint the only integer — minimum number of traps you need to install to catch the $x$-mouse.\\n\\n\\n-----Examples-----\\nInput\\n4 3\\n\\nOutput\\n3\\n\\nInput\\n5 2\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example you can, for example, put traps in rooms $0$, $2$, $3$. If the $x$-mouse starts in one of this rooms it will be caught immediately. If $x$-mouse starts in the $1$-st rooms then it will move to the room $3$, where it will be caught.\\n\\nIn the second example you can put one trap in room $0$ and one trap in any other room since $x$-mouse will visit all rooms $1..m-1$ if it will start in any of these rooms.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import gcd\\ndef powmod(a,b,m):\\n a%=m\\n r=1\\n while b:\\n  if b&1:r=r*a%m\\n  a=a*a%m\\n  b>>=1\\n return r\\n\\ndef f(n):\\n r=[]\\n if (n&1)==0:\\n  e=0\\n  while (n&1)==0:n>>=1;e+=1\\n  yield (2,e)\\n p=3\\n while n>1:\\n  if p*p>n:p=n\\n  if n%p:\\n   p+=2\\n   continue\\n  e=1;n\\/\\/=p\\n  while n%p==0:n\\/\\/=p;e+=1\\n  yield (p,e)\\n  p+=2\\n return r\\nm,x=map(int,input().split())\\np=2\\nr=[(1,1)]\\nfor p,e in f(m):\\n assert e>=1\\n ord=p-1\\n assert powmod(x,ord,p)==1\\n for pi,ei in f(p-1):\\n  while ord % pi == 0 and powmod(x,ord\\/\\/pi,p)==1: ord\\/\\/=pi\\n ords=[(1,1),(ord,p-1)]\\n q=p\\n for v in range(2,e+1):\\n  q*=p\\n  if powmod(x,ord,q)!=1:ord*=p\\n  assert powmod(x,ord,q)==1\\n  ords.append((ord,q\\/\\/p*(p-1)))\\n r=[(a\\/\\/gcd(a,c)*c,b*d) for a,b in r for c,d in ords]\\nprint(sum(y\\/\\/x for x,y in r))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55d410c492e6ed767000004f:\\nWrite a function \\n\\n```python\\nvowel_2_index```\\n\\nthat takes in a string and replaces all the vowels [a,e,i,o,u] with their respective positions within that string. \\nE.g: \\n\\n```python\\nvowel_2_index('this is my string') == 'th3s 6s my str15ng'\\nvowel_2_index('Codewars is the best site in the world') == 'C2d4w6rs 10s th15 b18st s23t25 27n th32 w35rld'\\nvowel_2_index('') == ''\\n```\\n Your function should be case insensitive to the vowels.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def vowel_2_index(string):\\n    return ''.join( [str(i+1) if string[i].lower() in \\\"aeiou\\\" else string[i] for i in range(len(string))])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere is a square grid of size $n \\\\times n$. Some cells are colored in black, all others are colored in white. In one operation you can select some rectangle and color all its cells in white. It costs $\\\\min(h, w)$ to color a rectangle of size $h \\\\times w$. You are to make all cells white for minimum total cost.\\n\\nThe square is large, so we give it to you in a compressed way. The set of black cells is the union of $m$ rectangles.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $m$ ($1 \\\\le n \\\\le 10^{9}$, $0 \\\\le m \\\\le 50$) — the size of the square grid and the number of black rectangles.\\n\\nEach of the next $m$ lines contains 4 integers $x_{i1}$ $y_{i1}$ $x_{i2}$ $y_{i2}$ ($1 \\\\le x_{i1} \\\\le x_{i2} \\\\le n$, $1 \\\\le y_{i1} \\\\le y_{i2} \\\\le n$) — the coordinates of the bottom-left and the top-right corner cells of the $i$-th black rectangle.\\n\\nThe rectangles may intersect.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum total cost of painting the whole square in white.\\n\\n\\n-----Examples-----\\nInput\\n10 2\\n4 1 5 10\\n1 4 10 5\\n\\nOutput\\n4\\n\\nInput\\n7 6\\n2 1 2 1\\n4 2 4 3\\n2 5 2 5\\n2 3 5 3\\n1 2 1 2\\n3 2 5 3\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nThe examples and some of optimal solutions are shown on the pictures below.\\n\\n [Image]\",\"targets\":\"import sys\\nfrom collections import defaultdict\\n\\nclass MaxFlow(object):\\n    def __init__(self):\\n        self.edges = defaultdict(lambda: defaultdict(lambda: 0))\\n\\n    def add_edge(self, u, v, capacity=float('inf')):\\n        self.edges[u][v] = capacity\\n\\n    def bfs(self, s, t):\\n        open_q = [s]\\n\\n        visited = set()\\n        parent = dict()\\n        while open_q:\\n            close_q = []\\n            for node in open_q:\\n                for v, capacity in list(self.edges[node].items()):\\n                    if v not in visited and capacity > 0:\\n                        close_q.append(v)\\n                        parent[v] = node\\n                        visited.add(v)\\n                        if v == t:\\n                            result = []\\n                            n2 = v\\n                            n1 = node\\n                            while n1 != s:\\n                                result.append((n1, n2))\\n                                n2 = n1\\n                                n1 = parent[n1]\\n                            result.append((n1, n2))\\n                            return result\\n\\n            open_q = close_q\\n\\n        return None\\n\\n    def solve(self, s, t):\\n        flow = 0\\n        route = self.bfs(s, t)\\n        while route is not None:\\n            new_flow = float('inf')\\n            for _, (n1, n2) in enumerate(route):\\n                new_flow = min(new_flow, self.edges[n1][n2])\\n            for _, (n1, n2) in enumerate(route):\\n                self.edges[n1][n2] -= new_flow\\n                self.edges[n2][n1] += new_flow\\n            flow += new_flow\\n\\n            route = self.bfs(s, t)\\n\\n        return flow\\n\\n    def __str__(self):\\n        result = \\\"{ \\\"\\n        for k, v in list(self.edges.items()):\\n            result += str(k) + \\\":\\\" + str(dict(v)) + \\\", \\\"\\n        result += \\\"}\\\"\\n        return result\\n\\n\\ndef main():\\n    (n, m) = tuple([int(x) for x in input().split()])\\n    r = []\\n    xs = set()\\n    ys = set()\\n    for i in range(m):\\n        (x1, y1, x2, y2) = tuple(int(x) for x in input().split())\\n       ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/53a1eac7e0afd3ad3300008b:\\nMutual Recursion allows us to take the fun of regular recursion (where a function calls itself until a terminating condition) and apply it to multiple functions calling each other! \\n\\nLet's use the Hofstadter Female and Male sequences to demonstrate this technique. You'll want to create two functions `F` and `M` such that the following equations are true: \\n\\n```\\nF(0) = 1\\nM(0) = 0\\nF(n) = n - M(F(n - 1))\\nM(n) = n - F(M(n - 1))\\n```\\n\\nDon't worry about negative numbers, `n` will always be greater than or equal to zero.\\n\\n~~~if:php,csharp\\nYou *do* have to worry about performance though, mutual recursion uses up a lot of stack space (and is highly inefficient) so you may have to find a way to make your solution consume less stack space (and time).  Good luck :)\\n~~~\\n\\nHofstadter Wikipedia Reference http:\\/\\/en.wikipedia.org\\/wiki\\/Hofstadter_sequence#Hofstadter_Female_and_Male_sequences\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def m(n):\\n    if n <= 0:\\n        return 0\\n    else:\\n        return (n - f(m(n-1)))\\n\\ndef f(n):\\n    if n <= 0:\\n        return 1\\n    else:\\n        return (n - m(f(n-1)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nПамять компьютера состоит из n ячеек, которые выстроены в ряд. Пронумеруем ячейки от 1 до n слева направо. Про каждую ячейку известно, свободна она или принадлежит какому-либо процессу (в таком случае известен процесс, которому она принадлежит).\\n\\nДля каждого процесса известно, что принадлежащие ему ячейки занимают в памяти непрерывный участок. С помощью операций вида «переписать данные из занятой ячейки в свободную, а занятую теперь считать свободной» требуется расположить все принадлежащие процессам ячейки в начале памяти компьютера. Другими словами, любая свободная ячейка должна располагаться правее (иметь больший номер) любой занятой.\\n\\nВам необходимо найти минимальное количество операций переписывания данных из одной ячейки в другую, с помощью которых можно достичь описанных условий. Допустимо, что относительный порядок ячеек в памяти для каждого из процессов изменится после дефрагментации, но относительный порядок самих процессов должен остаться без изменений. Это значит, что если все ячейки, принадлежащие процессу i, находились в памяти раньше всех ячеек процесса j, то и после перемещений это условие должно выполняться.\\n\\nСчитайте, что номера всех процессов уникальны, хотя бы одна ячейка памяти занята каким-либо процессом.\\n\\n\\n-----Входные данные-----\\n\\nВ первой строке входных данных записано число n (1 ≤ n ≤ 200 000) — количество ячеек в памяти компьютера.\\n\\nВо второй строке входных данных следуют n целых чисел a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ n), где a_{i} равно либо 0 (это означает, что i-я ячейка памяти свободна), либо номеру процесса, которому принадлежит i-я ячейка памяти. Гарантируется, что хотя бы одно значение a_{i} не равно 0.\\n\\nПроцессы пронумерованы целыми числами от 1 до n в произвольном порядке. При этом процессы не обязательно пронумерованы последовательными числами.\\n\\n\\n-----Выходные данные-----\\n\\nВыведите одно целое число — минимальное количество операций, которое нужно сделать для дефрагментации памяти.\\n\\n\\n-----Примеры-----\\nВходные данные\\n4\\n0 2 2 1\\n\\nВыходные данные\\n2\\n\\nВходные данные\\n8\\n0 8 8 8 0...\",\"targets\":\"read = lambda: list(map(int, input().split()))\\nn = int(input())\\na = list(read())\\nb = [0] * n\\nj = 0\\nfor i in a:\\n    if i:\\n        b[j] = i\\n        j += 1\\ncnt = sum(i != 0 for i in b)\\nfor i in range(n):\\n    if b[i] == 0: break\\n    if b[i] == a[i]:\\n        cnt -= 1\\nprint(cnt)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc162\\/tasks\\/abc162_b:\\nLet us define the FizzBuzz sequence a_1,a_2,... as follows:\\n - If both 3 and 5 divides i, a_i=\\\\mbox{FizzBuzz}.\\n - If the above does not hold but 3 divides i, a_i=\\\\mbox{Fizz}.\\n - If none of the above holds but 5 divides i, a_i=\\\\mbox{Buzz}.\\n - If none of the above holds, a_i=i.\\nFind the sum of all numbers among the first N terms of the FizzBuzz sequence.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 10^6\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\n\\n-----Output-----\\nPrint the sum of all numbers among the first N terms of the FizzBuzz sequence.\\n\\n-----Sample Input-----\\n15\\n\\n-----Sample Output-----\\n60\\n\\nThe first 15 terms of the FizzBuzz sequence are:\\n1,2,\\\\mbox{Fizz},4,\\\\mbox{Buzz},\\\\mbox{Fizz},7,8,\\\\mbox{Fizz},\\\\mbox{Buzz},11,\\\\mbox{Fizz},13,14,\\\\mbox{FizzBuzz}\\nAmong them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N = int(input())\\n\\nans = 0\\n\\nfor i in range(1, N + 1):\\n    if i % 3 == 0 or i % 5 == 0:\\n        continue\\n    ans += i\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an array $a_1, a_2 \\\\dots a_n$. Calculate the number of tuples $(i, j, k, l)$ such that:   $1 \\\\le i < j < k < l \\\\le n$;  $a_i = a_k$ and $a_j = a_l$; \\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $t$ ($1 \\\\le t \\\\le 100$) — the number of test cases.\\n\\nThe first line of each test case contains a single integer $n$ ($4 \\\\le n \\\\le 3000$) — the size of the array $a$.\\n\\nThe second line of each test case contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le n$) — the array $a$.\\n\\nIt's guaranteed that the sum of $n$ in one test doesn't exceed $3000$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the number of described tuples.\\n\\n\\n-----Example-----\\nInput\\n2\\n5\\n2 2 2 2 2\\n6\\n1 3 3 1 2 3\\n\\nOutput\\n5\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, for any four indices $i < j < k < l$ are valid, so the answer is the number of tuples.\\n\\nIn the second test case, there are $2$ valid tuples:   $(1, 2, 4, 6)$: $a_1 = a_4$ and $a_2 = a_6$;  $(1, 3, 4, 6)$: $a_1 = a_4$ and $a_3 = a_6$.\",\"targets\":\"from sys import stdin\\n\\ntt = int(stdin.readline())\\n\\nfor loop in range(tt):\\n\\n    n = int(stdin.readline())\\n    a = list(map(int,stdin.readline().split()))\\n\\n    l = [0] * (n+1)\\n    ans = 0\\n\\n    for j in range(n):\\n        r = [0] * (n+1)\\n        for k in range(n-1,j,-1):\\n            ans += l[a[k]] * r[a[j]]\\n            r[a[k]] += 1\\n        l[a[j]] += 1\\n\\n    print (ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/odd-even-jump\\/:\\nYou are given an integer array A.  From some starting index, you can make a series of jumps.  The (1st, 3rd, 5th, ...) jumps in the series are called odd numbered jumps, and the (2nd, 4th, 6th, ...) jumps in the series are called even numbered jumps.\\nYou may from index i jump forward to index j (with i < j) in the following way:\\n\\nDuring odd numbered jumps (ie. jumps 1, 3, 5, ...), you jump to the index j such that A[i] <= A[j] and A[j] is the smallest possible value.  If there are multiple such indexes j, you can only jump to the smallest such index j.\\nDuring even numbered jumps (ie. jumps 2, 4, 6, ...), you jump to the index j such that A[i] >= A[j] and A[j] is the largest possible value.  If there are multiple such indexes j, you can only jump to the smallest such index j.\\n(It may be the case that for some index i, there are no legal jumps.)\\n\\nA starting index is good if, starting from that index, you can reach the end of the array (index A.length - 1) by jumping some number of times (possibly 0 or more than once.)\\nReturn the number of good starting indexes.\\n \\nExample 1:\\nInput: [10,13,12,14,15]\\nOutput: 2\\nExplanation: \\nFrom starting index i = 0, we can jump to i = 2 (since A[2] is the smallest among A[1], A[2], A[3], A[4] that is greater or equal to A[0]), then we can't jump any more.\\nFrom starting index i = 1 and i = 2, we can jump to i = 3, then we can't jump any more.\\nFrom starting index i = 3, we can jump to i = 4, so we've reached the end.\\nFrom starting index i = 4, we've reached the end already.\\nIn total, there are 2 different starting indexes (i = 3, i = 4) where we can reach the end with some number of jumps.\\n\\n\\nExample 2:\\nInput: [2,3,1,1,4]\\nOutput: 3\\nExplanation: \\nFrom starting index i = 0, we make jumps to i = 1, i = 2, i = 3:\\n\\nDuring our 1st jump (odd numbered), we first jump to i = 1 because A[1] is the smallest value in (A[1], A[2], A[3], A[4]) that is greater than or equal to A[0].\\n\\nDuring our 2nd jump (even numbered), we jump from i = 1 to i = 2 because A[2] is the largest value in (A[2], A[3],...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def oddEvenJumps(self, A: List[int]) -> int:\\n        '''\\n        Algorithm\\n        ---------\\n        We need to jump alternatively higher and lower until we reach the end of the array.\\n        '''\\n        \\n        stack = []\\n        \\n        n = len(A)\\n        next_higher, next_lower = [0] * n, [0] * n\\n        \\n        for _, i in sorted([val, index] for index, val in enumerate(A)):\\n            # Check if the index at the top of the stack\\n            # is less than the current index i. If it is\\n            # then the current index i is the next greater element for the index at the top of the stack\\n            while stack and stack[-1] < i:\\n                next_higher[stack.pop()] = i\\n            stack.append(i)\\n        \\n        stack = []\\n        for _, i in sorted([-val, index] for index, val in enumerate(A)):\\n            while stack and stack[-1] < i:\\n                next_lower[stack.pop()] = i\\n            stack.append(i)\\n        \\n        higher, lower = [0] * n, [0] * n\\n        \\n        # increment the last index in both the lower and higher\\n        # since we know that the end of the array can be reached from the\\n        # last index\\n        higher[-1] += 1\\n        lower[-1] += 1\\n        \\n        for i in reversed(list(range(n - 1))):\\n            higher[i] = lower[next_higher[i]]\\n            lower[i] = higher[next_lower[i]]\\n        return sum(higher)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given n positive integers a_1, a_2, ..., a_{n}.\\n\\nFor every a_{i} you need to find a positive integer k_{i} such that the decimal notation of 2^{k}_{i} contains the decimal notation of a_{i} as a substring among its last min(100, length(2^{k}_{i})) digits. Here length(m) is the length of the decimal notation of m.\\n\\nNote that you don't have to minimize k_{i}. The decimal notations in this problem do not contain leading zeros.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 2 000) — the number of integers a_{i}.\\n\\nEach of the next n lines contains a positive integer a_{i} (1 ≤ a_{i} < 10^11).\\n\\n\\n-----Output-----\\n\\nPrint n lines. The i-th of them should contain a positive integer k_{i} such that the last min(100, length(2^{k}_{i})) digits of 2^{k}_{i} contain the decimal notation of a_{i} as a substring. Integers k_{i} must satisfy 1 ≤ k_{i} ≤ 10^50.\\n\\nIt can be shown that the answer always exists under the given constraints. If there are multiple answers, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n2\\n8\\n2\\n\\nOutput\\n3\\n1\\n\\nInput\\n2\\n3\\n4857\\n\\nOutput\\n5\\n20\",\"targets\":\"def dlog(x, n):\\n  bigMod = 5 ** n\\n  ans = [None, 0, 1, 3, 2][x % 5]\\n  val = 2 ** ans % bigMod\\n  mod, phi = 5, 4\\n  phiVal = 2 ** phi % bigMod\\n  for i in range(2, n + 1):\\n    nextMod = mod * 5\\n    while val % nextMod != x % nextMod:\\n      val = val * phiVal % bigMod\\n      ans += phi\\n    phi *= 5\\n    phiVal = (phiVal *\\n              phiVal % bigMod *\\n              phiVal % bigMod *\\n              phiVal % bigMod *\\n              phiVal % bigMod)\\n    mod = nextMod\\n  return ans\\n\\ndef main():\\n  inp = input()\\n  n = len(inp)\\n  a = int(inp)\\n  for m in range(n + 1):\\n    l = a * 10 ** m\\n    x, mod = l, 2 ** (n + m)\\n    if x % mod != 0:\\n      x += mod - x % mod\\n    if x % 5 == 0:\\n      x += mod\\n    if x < l + 10 ** m:\\n      assert x % mod == 0 and x % 5 != 0\\n      x = x \\/\\/ mod\\n      mod = 5 ** (n + m)\\n      print(n + m + dlog(x % mod, n + m))\\n      return\\n  assert False\\n\\ndef __starting_point():\\n  cnt = int(input())\\n  for i in range(cnt):\\n    main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA **Seven Segment Display** is an electronic display device, used to display decimal or hexadecimal numerals. It involves seven led segments that are lit in specific combinations to represent a specific numeral. An example of each combination is shown below:\\n\\n![seven segment display](https:\\/\\/upload.wikimedia.org\\/wikipedia\\/commons\\/9\\/97\\/7-segments_Indicator.gif)\\n\\nFor this Kata, you must accept an integer in the range `0 - 999999` and print it as a string (in decimal format), with each digit being represented as its own seven segment display (6x seven segment displays in total). Each of the individual led segments per display should be represented by three hashes `###`. Vertical bars `|` (ASCII 124) represent the edges of each display, with a single whitespace on either side between the edge and the area of the led segments. An example of the expected output is shown below:\\n```\\nsegment_display(123456) = \\n|       |  ###  |  ###  |       |  ###  |  ###  | \\n|     # |     # |     # | #   # | #     | #     |\\n|     # |     # |     # | #   # | #     | #     |\\n|     # |     # |     # | #   # | #     | #     |\\n|       |  ###  |  ###  |  ###  |  ###  |  ###  |\\n|     # | #     |     # |     # |     # | #   # |\\n|     # | #     |     # |     # |     # | #   # |\\n|     # | #     |     # |     # |     # | #   # |\\n|       |  ###  |  ###  |       |  ###  |  ###  |\\n```\\nFor clarity, the entire set of required combinations is provided below:\\n\\n```\\n|  ###  |       |  ###  |  ###  |       |  ###  |  ###  |  ###  |  ###  |  ###  |\\n| #   # |     # |     # |     # | #   # | #     | #     |     # | #   # | #   # |\\n| #   # |     # |     # |     # | #   # | #     | #     |     # | #   # | #   # |\\n| #   # |     # |     # |     # | #   # | #     | #     |     # | #   # | #   # |\\n|       |       |  ###  |  ###  |  ###  |  ###  |  ###  |       |  ###  |  ###  |\\n| #   # |     # | #     |     # |     # |     # | #   # |     # | #   # |     # |\\n| #   # |     # | #     |     # |     # |     # | #   # |     # | #   # |     # |\\n| #   # |     # | #    ...\",\"targets\":\"all_num = \\\\\\n'''|  ###  |       |  ###  |  ###  |       |  ###  |  ###  |  ###  |  ###  |  ###  |\\n| #   # |     # |     # |     # | #   # | #     | #     |     # | #   # | #   # |\\n| #   # |     # |     # |     # | #   # | #     | #     |     # | #   # | #   # |\\n| #   # |     # |     # |     # | #   # | #     | #     |     # | #   # | #   # |\\n|       |       |  ###  |  ###  |  ###  |  ###  |  ###  |       |  ###  |  ###  |\\n| #   # |     # | #     |     # |     # |     # | #   # |     # | #   # |     # |\\n| #   # |     # | #     |     # |     # |     # | #   # |     # | #   # |     # |\\n| #   # |     # | #     |     # |     # |     # | #   # |     # | #   # |     # |\\n|  ###  |       |  ###  |  ###  |       |  ###  |  ###  |       |  ###  |  ###  |'''\\ndef segment_display(num):\\n    all_num_list = all_num.split('\\\\n')\\n    fish_list = []\\n    for val in (all_num_list):\\n        fish_hold_list = []\\n        fish_hold = '' + '|       |'*(6-len(str(num)))\\n        for num2 in str(num):\\n            num3 = int(num2)\\n            beg_col = (num3 * 8)\\n            end_col = beg_col + 9\\n            fish_hold += val[beg_col:end_col]\\n            fish_hold_list.append([fish_hold])\\n        fish_list.append(fish_hold)\\n    retval_list = []\\n    for val in (fish_list):\\n        retval_list.append(val.replace('||','|'))\\n    return '\\\\n'.join(retval_list)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc146\\/tasks\\/abc146_e:\\nGiven are a sequence of N positive integers A_1, A_2, \\\\ldots, A_N, and a positive integer K.\\nFind the number of non-empty contiguous subsequences in A such that the remainder when dividing the sum of its elements by K is equal to the number of its elements. We consider two subsequences different if they are taken from different positions, even if they are equal sequences.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq N \\\\leq 2\\\\times 10^5\\n - 1 \\\\leq K \\\\leq 10^9\\n - 1 \\\\leq A_i \\\\leq 10^9\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN K\\nA_1 A_2 \\\\cdots A_N\\n\\n-----Output-----\\nPrint the number of subsequences that satisfy the condition.\\n\\n-----Sample Input-----\\n5 4\\n1 4 2 3 5\\n\\n-----Sample Output-----\\n4\\n\\nFour sequences satisfy the condition: (1), (4,2), (1,4,2), and (5).\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import Counter\\n\\nN, K = list(map(int, input().split()))\\nAs = list(map(int, input().split()))\\n\\nSs = [0]\\nS = 0\\nfor A in As:\\n    S += A-1\\n    S %= K\\n    Ss.append(S)\\n\\nans = 0\\ncnt = Counter()\\nfor i in range(N+1):\\n    ans += cnt[Ss[i]]\\n    cnt[Ss[i]] += 1\\n    if i >= K-1:\\n        cnt[Ss[i-K+1]] -= 1\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1075\\/B:\\nPalo Alto is an unusual city because it is an endless coordinate line. It is also known for the office of Lyft Level 5.\\n\\nLyft has become so popular so that it is now used by all $m$ taxi drivers in the city, who every day transport the rest of the city residents — $n$ riders.\\n\\nEach resident (including taxi drivers) of Palo-Alto lives in its unique location (there is no such pair of residents that their coordinates are the same).\\n\\nThe Lyft system is very clever: when a rider calls a taxi, his call does not go to all taxi drivers, but only to the one that is the closest to that person. If there are multiple ones with the same distance, then to taxi driver with a smaller coordinate is selected.\\n\\nBut one morning the taxi drivers wondered: how many riders are there that would call the given taxi driver if they were the first to order a taxi on that day? In other words, you need to find for each taxi driver $i$ the number $a_{i}$ — the number of riders that would call the $i$-th taxi driver when all drivers and riders are at their home?\\n\\nThe taxi driver can neither transport himself nor other taxi drivers.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $m$ ($1 \\\\le n,m \\\\le 10^5$) — number of riders and taxi drivers.\\n\\nThe second line contains $n + m$ integers $x_1, x_2, \\\\ldots, x_{n+m}$ ($1 \\\\le x_1 < x_2 < \\\\ldots < x_{n+m} \\\\le 10^9$), where $x_i$ is the coordinate where the $i$-th resident lives. \\n\\nThe third line contains $n + m$ integers $t_1, t_2, \\\\ldots, t_{n+m}$ ($0 \\\\le t_i \\\\le 1$). If $t_i = 1$, then the $i$-th resident is a taxi driver, otherwise $t_i = 0$.\\n\\nIt is guaranteed that the number of $i$ such that $t_i = 1$ is equal to $m$.\\n\\n\\n-----Output-----\\n\\nPrint $m$ integers $a_1, a_2, \\\\ldots, a_{m}$, where $a_i$ is the answer for the $i$-th taxi driver. The taxi driver has the number $i$ if among all the taxi drivers he lives in the $i$-th smallest coordinate (see examples for better understanding).\\n\\n\\n-----Examples-----\\nInput\\n3 1\\n1 2 3 10\\n0 0 1 0\\n\\nOutput\\n3 \\nInput\\n3 2\\n2 3 4 5 6\\n1 0 0 0 1\\n\\nOutput\\n2...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = map(int, input().split())\\ndist = list(map(int, input().split()))\\ntaxists = list(map(int, input().split()))\\nleft = [0] * (n + m)\\nright = [0] * (n + m)\\nMAX = 10000000000000000000\\nvalue = -MAX\\ncnt = 0\\nfor i in range(n + m):\\n    if taxists[i] == 1:\\n        cnt += 1\\n        value = i\\n    left[i] = value\\n\\nvalue = MAX\\nfor i in range(n + m - 1, -1, -1):\\n    if taxists[i] == 1:\\n        value = i\\n    right[i] = value\\n\\n\\nanswer = [0] * (n + m)\\nfor i in range(n + m):\\n    if left[i] == -MAX:\\n        answer[right[i]] += 1\\n        continue\\n    if right[i] == MAX:\\n        answer[left[i]] += 1\\n        continue\\n    if abs(dist[left[i]] - dist[i]) <= abs(dist[i] - dist[right[i]]):\\n        answer[left[i]] += 1\\n    else:\\n        answer[right[i]] += 1\\nfor i in answer:\\n    if i:\\n        print(i - 1, end = \\\" \\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/POINTS:\\nYou are given a set of points in the 2D plane. You start at the point with the least X and greatest Y value, and end at the point with the greatest X and least Y value. The rule for movement is that you can not move to a point with a lesser X value as compared to the X value of the point you are on. Also for points having the same X value, you need to visit the point with the greatest Y value before visiting the next point with the same X value. So, if there are 2 points: (0,4 and 4,0) we would start with (0,4) - i.e. least X takes precedence over greatest Y. You need to visit every point in the plane.\\n\\n-----Input-----\\nYou will be given an integer t(1<=t<=20) representing the number of test cases. A new line follows; after which the t test cases are given. Each test case starts with a blank line followed by an integer n(2<=n<=100000), which represents the number of points to follow. This is followed by a new line. Then follow the n points, each being a pair of integers separated by a single space; followed by a new line. The X and Y coordinates of each point will be between 0 and 10000 both inclusive.\\n\\n-----Output-----\\nFor each test case, print the total distance traveled by you from start to finish; keeping in mind the rules mentioned above, correct to 2 decimal places. The result for each test case must be on a new line.\\n\\n-----Example-----\\nInput:\\n3\\n\\n2\\n0 0\\n0 1\\n\\n3\\n0 0\\n1 1\\n2 2\\n\\n4\\n0 0\\n1 10\\n1 5\\n2 2\\n\\nOutput:\\n1.00\\n2.83\\n18.21\\n\\nFor the third test case above, the following is the path you must take:\\n0,0 -> 1,10  \\n1,10 -> 1,5\\n1,5 -> 2,2\\n= 18.21\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\ndef __starting_point():\\n    TC = int(input())\\n    for _ in range(TC):\\n        line = input()\\n        N = int(input())\\n        arr = []\\n        for _ in range(N):\\n            x, y = list(map(int, input().strip().split()))\\n            arr.append((x, y))\\n        arr.sort(key=lambda a: (a[0], a[1] * -1))\\n        dist = 0\\n        for i in range(1, N):\\n            x1 = arr[i][0]\\n            y1 = arr[i][1]\\n            x2 = arr[i-1][0]\\n            y2 = arr[i-1][1]\\n            d = ((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)) ** 0.5\\n            dist += d\\n\\n        print(\\\"{:0.2f}\\\".format(dist))\\n        \\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n In the Land Of Chess, bishops don't really like each other. In fact, when two bishops happen to stand on the same diagonal, they immediately rush towards the opposite ends of that same diagonal.\\n\\n Given the initial positions (in chess notation) of two bishops, `bishop1` and `bishop2`, calculate their future positions. Keep in mind that bishops won't move unless they see each other along the same diagonal.\\n\\n# Example\\n\\n For `bishop1 = \\\"d7\\\" and bishop2 = \\\"f5\\\"`, the output should be `[\\\"c8\\\", \\\"h3\\\"]`.\\n\\n ![](https:\\/\\/codefightsuserpics.s3.amazonaws.com\\/tasks\\/bishopDiagonal\\/img\\/ex_1.jpg?_tm=1473766087137)\\n\\n For `bishop1 = \\\"d8\\\" and bishop2 = \\\"b5\\\"`, the output should be `[\\\"b5\\\", \\\"d8\\\"]`.\\n\\n The bishops don't belong to the same diagonal, so they don't move.\\n\\n ![](https:\\/\\/codefightsuserpics.s3.amazonaws.com\\/tasks\\/bishopDiagonal\\/img\\/ex_2.jpg?_tm=1473766087425)\\n\\n# Input\\/Output\\n\\n\\n - `[input]` string `bishop1`\\n\\n    Coordinates of the first bishop in chess notation.\\n\\n\\n - `[input]` string `bishop2`\\n\\n    Coordinates of the second bishop in the same notation.\\n\\n\\n - `[output]` a string array\\n\\n    Coordinates of the bishops in lexicographical order after they check the diagonals they stand on.\",\"targets\":\"import re\\n\\ndef moveBishop(bs, deltas):\\n    posBishops = []\\n    for b,coef in zip(bs, [-1,1]):\\n        while True:\\n            tmpPos = ''.join( chr(ord(l) + coef*direc) for l,direc in zip(b, deltas) )\\n            if not bool(re.match(r'[a-h][1-8]', tmpPos)): break\\n            b = tmpPos\\n        posBishops.append(b)\\n    return posBishops\\n    \\ndef bishop_diagonal(*args):\\n    bishops = sorted(args)\\n    deltas = [ ord(b) - ord(a) for a,b in zip(*bishops) ]\\n    return moveBishop(bishops, list(map(lambda v: v\\/\\/abs(v), deltas))) if len(set(map(abs, deltas))) == 1 else bishops\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/280\\/B:\\nBike loves looking for the second maximum element in the sequence. The second maximum element in the sequence of distinct numbers x_1, x_2, ..., x_{k} (k > 1) is such maximum element x_{j}, that the following inequality holds: $x_{j} \\\\neq \\\\operatorname{max}_{i = 1}^{k} x_{i}$.\\n\\nThe lucky number of the sequence of distinct positive integers x_1, x_2, ..., x_{k} (k > 1) is the number that is equal to the bitwise excluding OR of the maximum element of the sequence and the second maximum element of the sequence.\\n\\nYou've got a sequence of distinct positive integers s_1, s_2, ..., s_{n} (n > 1). Let's denote sequence s_{l}, s_{l} + 1, ..., s_{r} as s[l..r] (1 ≤ l < r ≤ n). Your task is to find the maximum number among all lucky numbers of sequences s[l..r].\\n\\nNote that as all numbers in sequence s are distinct, all the given definitions make sence.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 < n ≤ 10^5). The second line contains n distinct integers s_1, s_2, ..., s_{n} (1 ≤ s_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum lucky number among all lucky numbers of sequences s[l..r].\\n\\n\\n-----Examples-----\\nInput\\n5\\n5 2 1 4 3\\n\\nOutput\\n7\\n\\nInput\\n5\\n9 8 3 5 7\\n\\nOutput\\n15\\n\\n\\n\\n-----Note-----\\n\\nFor the first sample you can choose s[4..5] = {4, 3} and its lucky number is (4 xor 3) = 7. You can also choose s[1..2].\\n\\nFor the second sample you must choose s[2..5] = {8, 3, 5, 7}.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"'''\\n    Auther: ghoshashis545 Ashis Ghosh\\n    College: Jalpaiguri Govt Enggineering College\\n'''\\nfrom os import path\\nimport sys\\nfrom functools import cmp_to_key as ctk\\nfrom collections import deque,defaultdict as dd \\nfrom bisect import bisect,bisect_left,bisect_right,insort,insort_left,insort_right\\nfrom itertools import permutations\\nfrom datetime import datetime\\nfrom math import ceil,sqrt,log,gcd\\ndef ii():return int(input())\\ndef si():return input()\\ndef mi():return list(map(int,input().split()))\\ndef li():return list(mi())\\nabc='abcdefghijklmnopqrstuvwxyz'\\nabd={'a': 0, 'b': 1, 'c': 2, 'd': 3, 'e': 4, 'f': 5, 'g': 6, 'h': 7, 'i': 8, 'j': 9, 'k': 10, 'l': 11, 'm': 12, 'n': 13, 'o': 14, 'p': 15, 'q': 16, 'r': 17, 's': 18, 't': 19, 'u': 20, 'v': 21, 'w': 22, 'x': 23, 'y': 24, 'z': 25}\\nmod=1000000007\\n#mod=998244353\\ninf = float(\\\"inf\\\")\\nvow=['a','e','i','o','u']\\ndx,dy=[-1,1,0,0],[0,0,1,-1]\\n\\ndef bo(i):\\n    return ord(i)-ord('a')\\n\\n\\n\\ndef solve():\\n    \\n    \\n    n=ii()\\n    a=li()\\n    b=[]\\n    for j in range(31,-1,-1):\\n        for i in range(n):\\n            if (a[i]>>j)&1:\\n                b.append(i)\\n        if(len(b)<n and len(b)>0):\\n            break\\n        b=[]\\n        \\n    \\n        \\n    if len(b)==n or len(b)==0:\\n        print(0)\\n        return\\n        \\n    ans=0\\n    x=0\\n    \\n    for j in range(len(b)-1):\\n        \\n        mx=0\\n        x1=a[b[j]]\\n        for i in range(b[j]-1,x-1,-1):\\n            mx=max(mx,a[i])\\n            ans=max(ans,x1^mx)\\n        mx=0\\n        for i in range(b[j]+1,b[j+1]):\\n            mx=max(mx,a[i])\\n            ans=max(ans,x1^mx)\\n        x=b[j]+1\\n    \\n    \\n       \\n    mx=0\\n    x1=a[b[len(b)-1]]\\n    for i in range(b[len(b)-1]-1,x-1,-1):\\n        mx=max(mx,a[i])\\n        ans=max(ans,x1^mx)\\n    \\n    mx=0\\n    for i in range(b[len(b)-1]+1,n):\\n            mx=max(mx,a[i])\\n            ans=max(ans,x1^mx)\\n            \\n    print(ans)\\n    \\n    \\n    \\n    \\n    \\n    \\n    \\n    \\ndef __starting_point():\\n    \\n    solve()\\n    \\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/595970246c9b8fa0a8000086:\\nYour coworker was supposed to write a simple helper function to capitalize a string (that contains a single word) before they went on vacation.\\n\\nUnfortunately, they have now left and the code they gave you doesn't work. Fix the helper function they wrote so that it works as intended (i.e. make the first character in the string \\\"word\\\" upper case).\\n\\nDon't worry about numbers, special characters, or non-string types being passed to the function. The string lengths will be from 1 character up to 10 characters, but will never be empty.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def capitalize_word(word):\\n    a = word[0].upper()\\n    b=slice(1,len(word))\\n    y = word[b]\\n    return a+y\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/572caa2672a38ba648001dcd:\\nEvery natural number, ```n```, may have a prime factorization like:\\n\\n\\n\\nWe define the **geometric derivative of n**, as a number with the following value:\\n\\n\\n\\nFor example: calculate the value of ```n*``` for ```n = 24500```.\\n```\\n24500 = 2²5³7²\\nn* = (2*2) * (3*5²) * (2*7) = 4200\\n```\\nMake a function, ```f``` that can perform this calculation\\n```\\nf(n) ----> n*\\n```\\nEvery prime number will have ```n* = 1```.\\n\\nEvery number that does not have an exponent ```ki```, higher than 1, will give a ```n* = 1```, too\\n\\n```python\\nf(24500) == 4200\\n\\nf(997) == 1\\n```\\nDo your best!\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def f(n):\\n    p, n_, m = 2, 1, int(n ** .5)\\n    while n > 1 and p <= m:\\n        k = 0\\n        while not n % p:\\n            k += 1\\n            n \\/\\/= p\\n        if k:\\n            n_ *= k * p ** (k - 1)\\n        p += 1\\n    return n_\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn Berland there are n cities and n - 1 bidirectional roads. Each road connects some pair of cities, from any city you can get to any other one using only the given roads.\\n\\nIn each city there is exactly one repair brigade. To repair some road, you need two teams based in the cities connected by the road to work simultaneously for one day. Both brigades repair one road for the whole day and cannot take part in repairing other roads on that day. But the repair brigade can do nothing on that day.\\n\\nDetermine the minimum number of days needed to repair all the roads. The brigades cannot change the cities where they initially are.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a positive integer n (2 ≤ n ≤ 200 000) — the number of cities in Berland.\\n\\nEach of the next n - 1 lines contains two numbers u_{i}, v_{i}, meaning that the i-th road connects city u_{i} and city v_{i} (1 ≤ u_{i}, v_{i} ≤ n, u_{i} ≠ v_{i}).\\n\\n\\n-----Output-----\\n\\nFirst print number k — the minimum number of days needed to repair all the roads in Berland.\\n\\nIn next k lines print the description of the roads that should be repaired on each of the k days. On the i-th line print first number d_{i} — the number of roads that should be repaired on the i-th day, and then d_{i} space-separated integers — the numbers of the roads that should be repaired on the i-th day. The roads are numbered according to the order in the input, starting from one.\\n\\nIf there are multiple variants, you can print any of them.\\n\\n\\n-----Examples-----\\nInput\\n4\\n1 2\\n3 4\\n3 2\\n\\nOutput\\n2\\n2 2 1\\n1 3\\n\\nInput\\n6\\n3 4\\n5 4\\n3 2\\n1 3\\n4 6\\n\\nOutput\\n3\\n1 1 \\n2 2 3 \\n2 4 5 \\n\\n\\n\\n-----Note-----\\n\\nIn the first sample you can repair all the roads in two days, for example, if you repair roads 1 and 2 on the first day and road 3 — on the second day.\",\"targets\":\"import sys\\nimport threading\\nfrom collections import defaultdict\\n\\ndef put():\\n    return map(int, input().split())\\n\\ndef dfs(i, p, m):\\n    cnt = 1\\n    z = 0\\n    for j in tree[i]:\\n        if j==p: continue\\n        if cnt==m: cnt+=1\\n        index = edge_index[(i,j)]\\n        ans[cnt].append(index)\\n        z = max(dfs(j,i,cnt), z)\\n        cnt+=1\\n    return max(z,cnt-1)\\n\\ndef solve():\\n    l = dfs(1,0,0)\\n    print(l)\\n    for i in range(1, l+1):\\n        print(len(ans[i]), *ans[i])\\n    \\n\\nn = int(input())\\nedge_index = defaultdict()\\nans = [[] for i in range(n+1)]\\ntree = [[] for i in range(n+1)]\\nfor i in range(n-1):\\n    x,y = put()\\n    edge_index[(x,y)]=i+1\\n    edge_index[(y,x)]=i+1\\n    tree[x].append(y)\\n    tree[y].append(x)\\n\\nmax_recur_size = 10**5*2 + 1000\\nmax_stack_size = max_recur_size*500\\nsys.setrecursionlimit(max_recur_size)\\nthreading.stack_size(max_stack_size)\\nthread = threading.Thread(target=solve)\\nthread.start()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/validate-stack-sequences\\/:\\nGiven two sequences pushed and popped with distinct values, return true if and only if this could have been the result of a sequence of push and pop operations on an initially empty stack.\\n \\n\\nExample 1:\\nInput: pushed = [1,2,3,4,5], popped = [4,5,3,2,1]\\nOutput: true\\nExplanation: We might do the following sequence:\\npush(1), push(2), push(3), push(4), pop() -> 4,\\npush(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1\\n\\n\\nExample 2:\\nInput: pushed = [1,2,3,4,5], popped = [4,3,5,1,2]\\nOutput: false\\nExplanation: 1 cannot be popped before 2.\\n\\n\\n\\n \\nConstraints:\\n\\n0 <= pushed.length == popped.length <= 1000\\n0 <= pushed[i], popped[i] < 1000\\npushed is a permutation of popped.\\npushed and popped have distinct values.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    \\n    def validateStackSequences(self, pushed: List[int], popped: List[int]) -> bool:\\n        \\n        j = 0\\n        stack = []\\n        for x in pushed:\\n            stack.append(x)\\n            while stack and j < len(popped) and stack[-1] == popped[j]:\\n                print(j, stack)\\n                stack.pop()\\n                j += 1\\n        \\n        return j == len(popped)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOlya loves energy drinks. She loves them so much that her room is full of empty cans from energy drinks.\\n\\nFormally, her room can be represented as a field of n × m cells, each cell of which is empty or littered with cans.\\n\\nOlya drank a lot of energy drink, so now she can run k meters per second. Each second she chooses one of the four directions (up, down, left or right) and runs from 1 to k meters in this direction. Of course, she can only run through empty cells.\\n\\nNow Olya needs to get from cell (x_1, y_1) to cell (x_2, y_2). How many seconds will it take her if she moves optimally?\\n\\nIt's guaranteed that cells (x_1, y_1) and (x_2, y_2) are empty. These cells can coincide.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers n, m and k (1 ≤ n, m, k ≤ 1000) — the sizes of the room and Olya's speed.\\n\\nThen n lines follow containing m characters each, the i-th of them contains on j-th position \\\"#\\\", if the cell (i, j) is littered with cans, and \\\".\\\" otherwise.\\n\\nThe last line contains four integers x_1, y_1, x_2, y_2 (1 ≤ x_1, x_2 ≤ n, 1 ≤ y_1, y_2 ≤ m) — the coordinates of the first and the last cells.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum time it will take Olya to get from (x_1, y_1) to (x_2, y_2).\\n\\nIf it's impossible to get from (x_1, y_1) to (x_2, y_2), print -1.\\n\\n\\n-----Examples-----\\nInput\\n3 4 4\\n....\\n###.\\n....\\n1 1 3 1\\n\\nOutput\\n3\\nInput\\n3 4 1\\n....\\n###.\\n....\\n1 1 3 1\\n\\nOutput\\n8\\nInput\\n2 2 1\\n.#\\n#.\\n1 1 2 2\\n\\nOutput\\n-1\\n\\n\\n-----Note-----\\n\\nIn the first sample Olya should run 3 meters to the right in the first second, 2 meters down in the second second and 3 meters to the left in the third second.\\n\\nIn second sample Olya should run to the right for 3 seconds, then down for 2 seconds and then to the left for 3 seconds.\\n\\nOlya does not recommend drinking energy drinks and generally believes that this is bad.\",\"targets\":\"from collections import deque\\nn, m, k = map(int, input().split())\\nINF = float(\\\"inf\\\")\\nd = [[INF] * m for _ in range(n)]\\nt = [[] for i in range(n)]\\nfor i in range(n):\\n    a = list(input())\\n    t[i] = a\\n\\nsx, sy, gx, gy = map(int, input().split())\\nsx, sy, gx, gy = sx - 1, sy - 1, gx - 1, gy - 1\\n\\n\\ndef bfs():\\n    que = deque()\\n    que.append((sx, sy))\\n    d[sx][sy] = 0\\n\\n    while len(que):\\n        x, y = que.popleft()\\n        if x == gx and y == gy:\\n            break\\n        for dx, dy in [(0, 1), (1, 0), (-1, 0), (0, -1)]:\\n            for i in range(1, k + 1):\\n                nx, ny = x + i * dx, y + i * dy\\n                if not 0 <= nx < n or not 0 <= ny < m or t[nx][ny] != \\\".\\\" or d[nx][ny] <= d[x][y]:\\n                    break\\n                else:\\n                    if d[nx][ny] > d[x][y] + 1:\\n                        d[nx][ny] = d[x][y] + 1\\n                        que.append((nx, ny))\\n\\n    return d[gx][gy]\\n\\n\\nans = bfs()\\nif ans == INF:\\n    print(-1)\\nelse:\\n    print(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/336\\/A:\\nVasily the bear has a favorite rectangle, it has one vertex at point (0, 0), and the opposite vertex at point (x, y). Of course, the sides of Vasya's favorite rectangle are parallel to the coordinate axes. \\n\\nVasya also loves triangles, if the triangles have one vertex at point B = (0, 0). That's why today he asks you to find two points A = (x_1, y_1) and C = (x_2, y_2), such that the following conditions hold:  the coordinates of points: x_1, x_2, y_1, y_2 are integers. Besides, the following inequation holds: x_1 < x_2;  the triangle formed by point A, B and C is rectangular and isosceles ($\\\\angle A B C$ is right);  all points of the favorite rectangle are located inside or on the border of triangle ABC;  the area of triangle ABC is as small as possible. \\n\\nHelp the bear, find the required points. It is not so hard to proof that these points are unique.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers x, y ( - 10^9 ≤ x, y ≤ 10^9, x ≠ 0, y ≠ 0).\\n\\n\\n-----Output-----\\n\\nPrint in the single line four integers x_1, y_1, x_2, y_2 — the coordinates of the required points.\\n\\n\\n-----Examples-----\\nInput\\n10 5\\n\\nOutput\\n0 15 15 0\\n\\nInput\\n-10 5\\n\\nOutput\\n-15 0 0 15\\n\\n\\n\\n-----Note-----\\n\\n[Image]\\n\\nFigure to the first sample\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"x, y = input().split()\\n\\nx = int(x)\\ny = int(y)\\n\\nif x>0 and y>0:\\n    x1 = 0\\n    y1 = x+y\\n    x2 = x+y\\n    y2 = 0\\n\\nelif x<0 and y>0:\\n    x1 = x-y\\n    y1 = 0\\n    x2 = 0\\n    y2 = -x+y\\n\\nelif x>0 and y<0:\\n    x1 = 0\\n    y1 = -x+y\\n    x2 = x+(-y)\\n    y2 = 0\\n\\nelse:\\n    x1 = x+y\\n    y1 = 0\\n    x2 = 0\\n    y2 = x+y\\n    \\n    \\nprint(x1,' ',y1,' ',x2,' ',y2)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n=====Problem Statement=====\\nYou are given a valid XML document, and you have to print the maximum level of nesting in it. Take the depth of the root as 0.\\n\\n=====Input Format=====\\nThe first line contains N, the number of lines in the XML document.\\nThe next N lines follow containing the XML document.\\n\\n=====Output Format=====\\nOutput a single line, the integer value of the maximum level of nesting in the XML document.\",\"targets\":\"# Enter your code here. Read input from STDIN. Print output to STDOUT\\nxml_str=\\\"\\\"\\nn=int(input())\\nfor i in range(0,n):\\n    tmp_str=input()\\n    xml_str=xml_str+tmp_str\\n    \\nimport xml.etree.ElementTree as etree\\ntree = etree.ElementTree(etree.fromstring(xml_str))\\nroot=tree.getroot()\\nar=[]\\ndef cnt_node(node):\\n    return max( [0] + [cnt_node(child)+1 for child in node])\\ncnt=cnt_node(root)\\nprint(cnt)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nProbably everyone has experienced an awkward situation due to shared armrests between seats in cinemas. A highly accomplished cinema manager named \\\"Chef\\\" decided to solve this problem.\\n\\nWhen a customer wants to buy a ticket, the clerk at the ticket window asks the visitor if they need the armrests, and if so, which of them: left, right, or both. We know that out of the audience expected to show up, L of them only need the left armrest, R of them need just the right one, Z need none and B need both. Your task is to calculate the maximum number of people that can attend the show. In the cinema hall there are N rows with M seats each. There is only one armrest between two adjacent seats. Seats at the beginning and at the end of the row have two armrests\\n\\n-----Input-----\\n\\nInput begins with an integer T: the number of test cases.\\n\\nEach test case consists of a single line with 6 space-separated integers: N, M, Z, L, R, B.\\n\\n-----Output-----\\n\\nFor each test case, output a line containing the answer for the task.\\n\\n-----Constraints and Subtasks-----\\n- 1 ≤ T ≤ 105 \\nSubtask 1 : 10 points \\n- 1 ≤ N, M ≤ 3 \\n- 0 ≤ Z, L, R, B ≤ 3 \\nSubtask 2 : 20 points \\n- 1 ≤ N, M ≤ 30 \\n- 0 ≤ Z, L, R ≤ 30 \\n- 0 ≤ B ≤ 109 \\nSubtask 3 : 30 points\\n- 1 ≤ N, M ≤ 106 \\n- 0 ≤ Z, L, R ≤ 106 \\n- 0 ≤ B ≤ 1016 \\nSubtask 4 : 40 points\\n- 1 ≤ N, M ≤ 108 \\n- 0 ≤ Z, L, R, B ≤ 1016 \\n\\n-----Example-----\\nInput:2\\n2 2 3 2 1 1\\n3 3 1 2 0 9\\n\\nOutput:4\\n8\\n\\n-----Explanation-----\\n'L' - needs left\\n\\n'R - needs right\\n\\n'Z' - doesn't need any\\n\\n'B' - needs both\\n\\n'-' - empty place\\n\\nExample case 1.\\nZZ\\n\\nZB\\nExample case 2.\\nLLB\\n\\nBZB\\n\\nB-B\",\"targets\":\"def mini(a,b):\\n if a>=b:\\n  return b\\n else:\\n  return a\\n\\nt=eval(input())\\nwhile t:\\n m,n,z,l,r,b=list(map(int,input().split()))\\n x=n*m\\n y=m*(n+1)\\n A=min(z,x)\\n ans=A\\n x-=A\\n B=min(l,x)\\n ans+=B\\n x-=B\\n C=min(r,x)\\n ans+=C\\n x-=C\\n p=min(b,x)\\n x=m*((n+1)\\/\\/2)\\n p=min(p,x)\\n x=(y-B-C)\\/\\/2\\n ans+=min(p,x)\\n print(ans)\\n t-=1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n— Hey folks, how do you like this problem?\\n\\n— That'll do it. \\n\\nBThero is a powerful magician. He has got $n$ piles of candies, the $i$-th pile initially contains $a_i$ candies. BThero can cast a copy-paste spell as follows:   He chooses two piles $(i, j)$ such that $1 \\\\le i, j \\\\le n$ and $i \\\\ne j$.  All candies from pile $i$ are copied into pile $j$. Formally, the operation $a_j := a_j + a_i$ is performed. \\n\\nBThero can cast this spell any number of times he wants to — but unfortunately, if some pile contains strictly more than $k$ candies, he loses his magic power. What is the maximum number of times BThero can cast the spell without losing his power?\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $T$ ($1 \\\\le T \\\\le 500$) — the number of test cases.\\n\\nEach test case consists of two lines:   the first line contains two integers $n$ and $k$ ($2 \\\\le n \\\\le 1000$, $2 \\\\le k \\\\le 10^4$);  the second line contains $n$ integers $a_1$, $a_2$, ..., $a_n$ ($1 \\\\le a_i \\\\le k$). \\n\\nIt is guaranteed that the sum of $n$ over all test cases does not exceed $1000$, and the sum of $k$ over all test cases does not exceed $10^4$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print one integer — the maximum number of times BThero can cast the spell without losing his magic power.\\n\\n\\n-----Example-----\\nInput\\n3\\n2 2\\n1 1\\n3 5\\n1 2 3\\n3 7\\n3 2 2\\n\\nOutput\\n1\\n5\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case we get either $a = [1, 2]$ or $a = [2, 1]$ after casting the spell for the first time, and it is impossible to cast it again.\",\"targets\":\"import math\\nt=int(input())\\nfor _ in range(t):\\n    n,k=list(map(int,input().split()))\\n    a=list(map(int,input().split()))\\n    a.sort()\\n    b=a[0]\\n    sumi=0\\n    for i in range(1,n):\\n        c=k-a[i]\\n        sumi+=c\\/\\/b\\n    print(sumi)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/592e2446dc403b132d0000be:\\n# Task\\nGiven an integer array `arr`. Your task is to remove one element, maximize the product of elements. \\n\\nThe result is the element which should be removed. If more than one valid results exist, return the smallest one.\\n\\n\\n# Input\\/Output\\n\\n\\n`[input]` integer array `arr`\\n\\nnon-empty unsorted integer array. It contains positive integer, negative integer or zero.\\n\\n`3 ≤ arr.length ≤ 15`\\n\\n`-10 ≤ arr[i] ≤ 10`\\n\\n`[output]` an integer\\n\\nThe element that should be removed.\\n\\n# Example\\n\\nFor `arr = [1, 2, 3]`, the output should be `1`.\\n\\nFor `arr = [-1, 2, -3]`, the output should be `2`.\\n\\nFor `arr = [-1, -2, -3]`, the output should be `-1`.\\n\\nFor `arr = [-1, -2, -3, -4]`, the output should be `-4`.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from functools import reduce\\nfrom operator import mul\\n\\ndef maximum_product(arr):\\n    omit_prod = lambda i: reduce(mul, arr[:i] + arr[i + 1:])\\n    return sorted([(omit_prod(i), -n, n) for i, n in enumerate(arr)], reverse=True)[0][2]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1369\\/E:\\nLee bought some food for dinner time, but Lee's friends eat dinner in a deadly way. Lee is so scared, he doesn't want to die, at least not before seeing Online IOI 2020...\\n\\nThere are $n$ different types of food and $m$ Lee's best friends. Lee has $w_i$ plates of the $i$-th type of food and each friend has two different favorite types of food: the $i$-th friend's favorite types of food are $x_i$ and $y_i$ ($x_i \\\\ne y_i$).\\n\\nLee will start calling his friends one by one. Whoever is called will go to the kitchen and will try to eat one plate of each of his favorite food types. Each of the friends will go to the kitchen exactly once.\\n\\nThe only problem is the following: if a friend will eat at least one plate of food (in total) then he will be harmless. But if there is nothing left for him to eat (neither $x_i$ nor $y_i$), he will eat Lee instead $\\\\times\\\\_\\\\times$.\\n\\nLee can choose the order of friends to call, so he'd like to determine if he can survive dinner or not. Also, he'd like to know the order itself.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $m$ ($2 \\\\le n \\\\le 10^5$; $1 \\\\le m \\\\le 2 \\\\cdot 10^5$) — the number of different food types and the number of Lee's friends. \\n\\nThe second line contains $n$ integers $w_1, w_2, \\\\ldots, w_n$ ($0 \\\\le w_i \\\\le 10^6$) — the number of plates of each food type.\\n\\nThe $i$-th line of the next $m$ lines contains two integers $x_i$ and $y_i$ ($1 \\\\le x_i, y_i \\\\le n$; $x_i \\\\ne y_i$) — the favorite types of food of the $i$-th friend. \\n\\n\\n-----Output-----\\n\\nIf Lee can survive the dinner then print ALIVE (case insensitive), otherwise print DEAD (case insensitive).\\n\\nAlso, if he can survive the dinner, print the order Lee should call friends. If there are multiple valid orders, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n3 3\\n1 2 1\\n1 2\\n2 3\\n1 3\\n\\nOutput\\nALIVE\\n3 2 1 \\n\\nInput\\n3 2\\n1 1 0\\n1 2\\n1 3\\n\\nOutput\\nALIVE\\n2 1 \\n\\nInput\\n4 4\\n1 2 0 1\\n1 3\\n1 2\\n2 3\\n2 4\\n\\nOutput\\nALIVE\\n1 3 2 4 \\n\\nInput\\n5 5\\n1 1 1 2 1\\n3 4\\n1 2\\n2 3\\n4 5\\n4 5\\n\\nOutput\\nALIVE\\n5 4 1 3 2 \\n\\nInput\\n4 10\\n2 4 1 4\\n3 2\\n4 2\\n4 1\\n3 1\\n4 1\\n1...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import deque\\nimport sys\\n\\nint1 = lambda x: int(x) - 1\\np2D = lambda x: print(*x, sep=\\\"\\\\n\\\")\\ndef II(): return int(sys.stdin.readline())\\ndef MI(): return map(int, sys.stdin.readline().split())\\ndef LI(): return list(map(int, sys.stdin.readline().split()))\\ndef LI1(): return list(map(int1, sys.stdin.readline().split()))\\ndef LLI(rows_number): return [LI() for _ in range(rows_number)]\\ndef LLI1(rows_number): return [LI1() for _ in range(rows_number)]\\ndef SI(): return sys.stdin.readline()[:-1]\\n\\ndef main():\\n    n,m=MI()\\n    ww=LI()\\n    xy=LLI1(m)\\n    fav_mem=[[] for _ in range(n)]\\n    fav_cnt=[0]*n\\n    for j,(x,y) in enumerate(xy):\\n        fav_mem[x].append(j)\\n        fav_mem[y].append(j)\\n        fav_cnt[x]+=1\\n        fav_cnt[y]+=1\\n\\n    q=deque()\\n    for i in range(n):\\n        if ww[i]-fav_cnt[i]>=0:q.append(i)\\n\\n    ans=[]\\n    fini=[False]*n\\n    finj=[False]*m\\n    while q:\\n        i=q.popleft()\\n        for j in fav_mem[i]:\\n            if finj[j]:continue\\n            ans.append(j+1)\\n            finj[j]=True\\n            for i0 in xy[j]:\\n                if fini[i0]:continue\\n                fav_cnt[i0]-=1\\n                if  ww[i0]-fav_cnt[i0]>=0:\\n                    q.append(i0)\\n                    fini[i0]=True\\n    if len(ans)==m:\\n        print(\\\"ALIVE\\\")\\n        print(*ans[::-1])\\n    else:print(\\\"DEAD\\\")\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/PEND2020\\/problems\\/ITGUY00:\\nThe chef is having one array of natural numbers. Cheffina challenges chef that find the sum of weights all the natural numbers present in the array, but the main problem is that all numbers have not original weights. After every 6 natural numbers weight is set to 1 as weight increases by 1 after that. (i.e. weight of 1 is 1, weight of 2 is 2 but the weight of 7 is 1 and weight of 8 is 2 and so on…). Help the chef to find the sum. \\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase contains two lines of input, one integer $N$.\\n- Next line has N space separate natural numbers. \\n\\n-----Output:-----\\nFor each testcase, output in a single line answer.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 10$\\n- $1 \\\\leq N \\\\leq 10^5$\\n- $1 \\\\leq arr[i] \\\\leq 10^6$\\n\\n-----Sample Input:-----\\n1\\n6\\n6 7 9 11 4 16\\n\\n-----Sample Output:-----\\n23\\n\\n-----EXPLANATION:-----\\nArray after conversion = [6, 1, 3, 5, 4, 4]\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nn=int(input())\\nfor _ in range(n):\\n    m=int(input())\\n    lis=list(map(int,input().strip().split()))\\n    res=[]\\n    for ele in lis:\\n        if ele%6==0:\\n            res.append(6)\\n        res.append(ele%6)\\n    print(sum(res))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/POPGATES:\\nYou are Dastan, the great Prince of Persia!\\nAfter searching long for the mysterious 'Sands of Time', you have finally arrived at the gates of the city that hosts the ancient temple of the gods. However, the gate is locked and it can only be opened with a secret code, which you need to obtain by solving the following puzzle:\\nThere is a table in front of you, with $N$ coins placed in a row and numbered $1$ through $N$ from left to right. For each coin, you know whether it is initially showing heads or tails. You have to perform exactly $K$ operations. In one operation, you should remove the rightmost coin present on the table, and if this coin was showing heads right before it was removed, then you should also flip all the remaining coins. (If a coin was showing heads, then after it is flipped, it is showing tails, and vice versa.)\\nThe code needed to enter the temple is the number of coins which, after these $K$ operations are performed, have not been removed and are showing heads. Can you find this number? The fate of Persia lies in your hands…\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains two space-separated integers $N$ and $K$.\\n- The second line contains $N$ space-separated characters. For each valid $i$, the $i$-th of these characters is 'H' if the $i$-th coin is initially showing heads or 'T' if it is showing tails.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer ― the number of coins that are showing heads after $K$ operations.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 200$\\n- $1 \\\\le K < N \\\\le 100$\\n\\n-----Subtasks-----\\nSubtask #1 (100 points): original constraints\\n\\n-----Example Input-----\\n3\\n5 3\\nH T T H T\\n7 4\\nH H T T T H H\\n6 1\\nT H T H T T\\n\\n-----Example Output-----\\n1\\n2\\n2\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for _ in range(int(input())):\\n n,k = list(map(int,input().split()))\\n arr =input().split()\\n\\n for i in range(k):\\n  if arr[-1]==\\\"H\\\":\\n   arr.pop()\\n   n=n-1\\n   for j in range(n):\\n    if arr[j]==\\\"H\\\":\\n     arr[j]=\\\"T\\\"\\n    else:\\n     arr[j]=\\\"H\\\"\\n  else:\\n   arr.pop()\\n   n=n-1\\n print(arr.count(\\\"H\\\"))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/arc103\\/tasks\\/arc103_d:\\nYou are given a sequence D_1, D_2, ..., D_N of length N.\\nThe values of D_i are all distinct.\\nDoes a tree with N vertices that satisfies the following conditions exist?\\n - The vertices are numbered 1,2,..., N.\\n - The edges are numbered 1,2,..., N-1, and Edge i connects Vertex u_i and v_i.\\n - For each vertex i, the sum of the distances from i to the other vertices is D_i, assuming that the length of each edge is 1.\\nIf such a tree exists, construct one such tree.\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 100000\\n - 1 \\\\leq D_i \\\\leq 10^{12}\\n - D_i are all distinct.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nD_1\\nD_2\\n:\\nD_N\\n\\n-----Output-----\\nIf a tree with n vertices that satisfies the conditions does not exist, print -1.\\nIf a tree with n vertices that satisfies the conditions exist, print n-1 lines.\\nThe i-th line should contain u_i and v_i with a space in between.\\nIf there are multiple trees that satisfy the conditions, any such tree will be accepted.\\n\\n-----Sample Input-----\\n7\\n10\\n15\\n13\\n18\\n11\\n14\\n19\\n\\n-----Sample Output-----\\n1 2\\n1 3\\n1 5\\n3 4\\n5 6\\n6 7\\n\\nThe tree shown below satisfies the conditions.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N = int(input())\\nsrc = [int(input()) for i in range(N)]\\nidx = {a:i for i,a in enumerate(src)}\\n\\nsize = [1] * N\\nss = list(sorted(src))\\n\\nes = []\\ngr = [[] for i in range(N)]\\nwhile len(ss) > 1:\\n    a = ss.pop()\\n    k = size[idx[a]]\\n    b = a + 2*k - N\\n    if b == a or b not in idx:\\n        print(-1)\\n        return\\n    size[idx[b]] += k\\n    ai,bi = idx[a],idx[b]\\n    es.append((ai,bi))\\n    gr[ai].append(bi)\\n    gr[bi].append(ai)\\n\\nfrom collections import deque\\ndist = [N] * N\\ndist[idx[ss[0]]] = 0\\nq = deque([idx[ss[0]]])\\nwhile q:\\n    v = q.popleft()\\n    for to in gr[v]:\\n        if dist[to] < N: continue\\n        q.append(to)\\n        dist[to] = dist[v] + 1\\n\\nif all(d<N for d in dist) and sum(dist) == ss[0]:\\n    for a,b in es:\\n        print(a+1, b+1)\\nelse:\\n    print(-1)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1042\\/A:\\nThere are $n$ benches in the Berland Central park. It is known that $a_i$ people are currently sitting on the $i$-th bench. Another $m$ people are coming to the park and each of them is going to have a seat on some bench out of $n$ available.\\n\\nLet $k$ be the maximum number of people sitting on one bench after additional $m$ people came to the park. Calculate the minimum possible $k$ and the maximum possible $k$.\\n\\nNobody leaves the taken seat during the whole process.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ $(1 \\\\le n \\\\le 100)$ — the number of benches in the park.\\n\\nThe second line contains a single integer $m$ $(1 \\\\le m \\\\le 10\\\\,000)$ — the number of people additionally coming to the park.\\n\\nEach of the next $n$ lines contains a single integer $a_i$ $(1 \\\\le a_i \\\\le 100)$ — the initial number of people on the $i$-th bench.\\n\\n\\n-----Output-----\\n\\nPrint the minimum possible $k$ and the maximum possible $k$, where $k$ is the maximum number of people sitting on one bench after additional $m$ people came to the park.\\n\\n\\n-----Examples-----\\nInput\\n4\\n6\\n1\\n1\\n1\\n1\\n\\nOutput\\n3 7\\n\\nInput\\n1\\n10\\n5\\n\\nOutput\\n15 15\\n\\nInput\\n3\\n6\\n1\\n6\\n5\\n\\nOutput\\n6 12\\n\\nInput\\n3\\n7\\n1\\n6\\n5\\n\\nOutput\\n7 13\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, each of four benches is occupied by a single person. The minimum $k$ is $3$. For example, it is possible to achieve if two newcomers occupy the first bench, one occupies the second bench, one occupies the third bench, and two remaining — the fourth bench. The maximum $k$ is $7$. That requires all six new people to occupy the same bench.\\n\\nThe second example has its minimum $k$ equal to $15$ and maximum $k$ equal to $15$, as there is just a single bench in the park and all $10$ people will occupy it.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\nn = int(input())\\nm = int(input())\\na = []\\nfor i in range(n):\\n    a.append(int(input()))\\nmaxs = max(a)\\nm1 = m\\nfor i in a:\\n    m -= (maxs - i)\\n\\nprint(maxs + max(math.ceil(m \\/ n), 0), maxs + m1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/CDVA16\\/problems\\/CDVA1605:\\nThe auditorium of Stanford University is made up of L*R matrix (assume each coordinate has a chair). On the occasion of an event Chef was called as a chief guest. The auditorium was filled with males (M) and females (F), occupying one chair each. Our Chef is very curious guy, so he asks the gatekeeper some queries. The queries were as follows: Is there any K*K sub-matrix in the auditorium which contains all Males or Females.\\n\\n-----Input-----\\n- The first line contains three space-separated integers L, R  and Q describing the dimension of the auditorium and the number of questions Chef will ask.\\n- Each of next L lines contains R characters (M or F).\\n- Next Q lines contains K and a character (M or F).\\n\\n-----Output-----\\n- For each query output \\\"yes\\\" (without quotes) if there exist any K*K sub-matrix in the auditorium which contains all Males (if he asks about Male) or Females (if he asks about Female), otherwise output \\\"no\\\" (without quotes).\\n\\n-----Constraints and Subtasks-----\\n- 1 <= L, R, K <= 1000\\n- 1 <= Q <= 1e6\\nSubtask 1: 30 points\\n- 1 <= L, R, Q <= 200\\nSubtask 2: 70 points\\n- Original Contraints\\n\\n-----Example-----\\nInput:\\n4 3 3\\nMMF\\nMMM\\nFFM\\nFFM\\n2 F\\n3 M\\n1 M\\n\\nOutput:\\nyes\\nno\\nyes\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def chk():\\n for r in range(i+1, i+k):\\n  if m[r][ix:ix+k] != ss:\\n   return False\\n return True \\nl, r, q = list(map(int, input().split()))\\nm = [input().replace(\\\" \\\", \\\"\\\") for _ in range(l)]\\nfor _ in range(q):\\n k, s = input().split()\\n k = int(k)\\n ss = k * s\\n ans = \\\"no\\\"\\n for i in range(l-k+1):\\n  st = 0\\n  while ss in m[i][st:]:\\n   ix = m[i].index(ss, st)\\n   if chk():\\n    ans = \\\"yes\\\"\\n    break\\n   st = ix + 1\\n  if ans == \\\"yes\\\":break \\n print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOne of Arkady's friends works at a huge radio telescope. A few decades ago the telescope has sent a signal $s$ towards a faraway galaxy. Recently they've received a response $t$ which they believe to be a response from aliens! The scientists now want to check if the signal $t$ is similar to $s$.\\n\\nThe original signal $s$ was a sequence of zeros and ones (everyone knows that binary code is the universe-wide language). The returned signal $t$, however, does not look as easy as $s$, but the scientists don't give up! They represented $t$ as a sequence of English letters and say that $t$ is similar to $s$ if you can replace all zeros in $s$ with some string $r_0$ and all ones in $s$ with some other string $r_1$ and obtain $t$. The strings $r_0$ and $r_1$ must be different and non-empty.\\n\\nPlease help Arkady's friend and find the number of possible replacements for zeros and ones (the number of pairs of strings $r_0$ and $r_1$) that transform $s$ to $t$.\\n\\n\\n-----Input-----\\n\\nThe first line contains a string $s$ ($2 \\\\le |s| \\\\le 10^5$) consisting of zeros and ones — the original signal.\\n\\nThe second line contains a string $t$ ($1 \\\\le |t| \\\\le 10^6$) consisting of lowercase English letters only — the received signal.\\n\\nIt is guaranteed, that the string $s$ contains at least one '0' and at least one '1'.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the number of pairs of strings $r_0$ and $r_1$ that transform $s$ to $t$.\\n\\nIn case there are no such pairs, print $0$.\\n\\n\\n-----Examples-----\\nInput\\n01\\naaaaaa\\n\\nOutput\\n4\\n\\nInput\\n001\\nkokokokotlin\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, the possible pairs $(r_0, r_1)$ are as follows:  \\\"a\\\", \\\"aaaaa\\\"  \\\"aa\\\", \\\"aaaa\\\"  \\\"aaaa\\\", \\\"aa\\\"  \\\"aaaaa\\\", \\\"a\\\"  \\n\\nThe pair \\\"aaa\\\", \\\"aaa\\\" is not allowed, since $r_0$ and $r_1$ must be different.\\n\\nIn the second example, the following pairs are possible:   \\\"ko\\\", \\\"kokotlin\\\"  \\\"koko\\\", \\\"tlin\\\"\",\"targets\":\"import sys\\nfrom math import *\\n\\ndef minp():\\n\\treturn sys.stdin.readline().strip()\\n\\ndef mint():\\n\\treturn int(minp())\\n\\ndef mints():\\n\\treturn map(int, minp().split())\\n\\ndef add(a,b):\\n\\treturn (a+b)%1000000007\\n\\ndef sub(a,b):\\n\\treturn (a+1000000007-b)%1000000007\\n\\ndef mul(a,b):\\n\\treturn (a*b)%1000000007\\n\\np = 102367\\ns = list(map(int,minp()))\\nt = list(map(ord,minp()))\\nh = [0]*(len(t)+1)\\npp = [1]*(len(t)+1)\\nfor i in range(len(t)):\\n\\th[i+1] = add(mul(h[i], p), t[i])\\n\\tpp[i+1] = mul(pp[i], p)\\n\\ndef cmp(a, b, l):\\n\\tif a > b:\\n\\t\\ta, b = b, a\\n\\th1 = sub(h[a+l], mul(h[a], pp[l]))\\n\\th2 = sub(h[b+l], mul(h[b], pp[l]))\\n\\treturn h2 == h1\\n\\nc = [0,0]\\nidx = [-1,-1]\\nfor i in range(len(s)):\\n\\tc[s[i]] += 1\\n\\tif idx[s[i]] < 0:\\n\\t\\tidx[s[i]] = i\\nMv = max(c)\\nmv = min(c)\\nMi = c.index(Mv)\\nmi = (Mi^1)\\nlt = len(t)\\nsp = [0,0]\\nres = 0\\nfor k in range(1,lt\\/\\/Mv+1):\\n\\tl = [0,0]\\n\\tx = (lt-k*Mv)\\/\\/mv\\n\\tif x > 0 and x*mv + k*Mv == lt:\\n\\t\\tl[Mi] = k\\n\\t\\tl[mi] = x\\n\\t\\tif idx[0] < idx[1]:\\n\\t\\t\\tsp[0] = 0\\n\\t\\t\\tsp[1] = idx[1]*l[0]\\n\\t\\telse:\\n\\t\\t\\tsp[1] = 0\\n\\t\\t\\tsp[0] = idx[0]*l[1]\\n\\t\\tok = True\\n\\t\\tj = 0\\n\\t\\tfor i in range(len(s)):\\n\\t\\t\\tif not cmp(sp[s[i]], j, l[s[i]]):\\n\\t\\t\\t\\tok = False\\n\\t\\t\\t\\tbreak\\n\\t\\t\\tj += l[s[i]]\\n\\t\\tif l[0] == l[1] and cmp(sp[0], sp[1], l[0]):\\n\\t\\t\\tok = False\\n\\t\\tif ok:\\n\\t\\t\\tres += 1\\nprint(res)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/576bb71bbbcf0951d5000044:\\nGiven an array of integers.\\n\\nReturn an array, where the first element is the count of positives numbers and the second element is sum of negative numbers.\\n\\nIf the input array is empty or null, return an empty array.\\n\\n# Example\\n\\nFor input `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -11, -12, -13, -14, -15]`, you should return `[10, -65]`.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def count_positives_sum_negatives(arr):\\n    if arr:\\n        a = 0\\n        b = 0\\n        for i in arr:\\n            if i > 0:\\n                a += 1\\n            elif i <= 0:\\n                b += i\\n        return [a, b] \\n    \\n    else:\\n        return []\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFarmer John has just given the cows a program to play with! The program contains two integer variables, x and y, and performs the following operations on a sequence a_1, a_2, ..., a_{n} of positive integers:  Initially, x = 1 and y = 0. If, after any step, x ≤ 0 or x > n, the program immediately terminates.  The program increases both x and y by a value equal to a_{x} simultaneously.  The program now increases y by a_{x} while decreasing x by a_{x}.  The program executes steps 2 and 3 (first step 2, then step 3) repeatedly until it terminates (it may never terminate). So, the sequence of executed steps may start with: step 2, step 3, step 2, step 3, step 2 and so on. \\n\\nThe cows are not very good at arithmetic though, and they want to see how the program works. Please help them!\\n\\nYou are given the sequence a_2, a_3, ..., a_{n}. Suppose for each i (1 ≤ i ≤ n - 1) we run the program on the sequence i, a_2, a_3, ..., a_{n}. For each such run output the final value of y if the program terminates or -1 if it does not terminate.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer, n (2 ≤ n ≤ 2·10^5). The next line contains n - 1 space separated integers, a_2, a_3, ..., a_{n} (1 ≤ a_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nOutput n - 1 lines. On the i-th line, print the requested value when the program is run on the sequence i, a_2, a_3, ...a_{n}.\\n\\nPlease do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.\\n\\n\\n-----Examples-----\\nInput\\n4\\n2 4 1\\n\\nOutput\\n3\\n6\\n8\\n\\nInput\\n3\\n1 2\\n\\nOutput\\n-1\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample   For i = 1,  x becomes $1 \\\\rightarrow 2 \\\\rightarrow 0$ and y becomes 1 + 2 = 3.  For i = 2,  x becomes $1 \\\\rightarrow 3 \\\\rightarrow - 1$ and y becomes 2 + 4 = 6.  For i = 3,  x becomes $1 \\\\rightarrow 4 \\\\rightarrow 3 \\\\rightarrow 7$ and y becomes 3 + 1 + 4 = 8.\",\"targets\":\"INF = float('inf')\\nn = int(input())\\naaa = [0, 0] + list(map(int, input().split()))\\ndp = [[0 for _ in range(n+1)] for i in range(2)]\\nvis = [[0 for _ in range(n+1)] for i in range(2)]\\nrs = [0] * (n-1)\\n\\ndef di(d): return 0 if d == 1 else 1\\n\\n\\ndef solve(x, d):\\n    if dp[di(d)][x]:\\n        return dp[di(d)][x]\\n\\n    if vis[di(d)][x]:\\n        return INF\\n\\n    ni = x + aaa[x] * d\\n    if ni < 1 or ni > n:\\n        return aaa[x]\\n\\n    vis[di(d)][x] = 1\\n    r = aaa[x] + solve(ni, -d)\\n    vis[di(d)][x] = 0\\n    return r\\n\\n\\nfor D in [1, -1]:\\n    for x in range(2, n+1):\\n        d = D\\n        if dp[di(d)][x]:\\n            continue\\n\\n        ni = x + aaa[x] * d\\n        path = [x]\\n        values = [aaa[x]]\\n        while ni > 1 and ni <= n:\\n            path.append(ni)\\n            if dp[di(-d)][ni]:\\n                values.append(dp[di(-d)][ni])\\n                d *= -1\\n                break\\n\\n            if vis[di(d)][ni]:\\n                values.append(INF)\\n                d *= -1\\n                break\\n\\n            vis[di(d)][ni] = 1\\n            values.append(aaa[ni])\\n\\n            d *= -1\\n            ni = ni + aaa[ni] * d\\n\\n\\n        if ni == 1:\\n            continue\\n\\n        for i in range(len(values)-2, -1, -1):\\n            values[i] = values[i] + values[i+1]\\n\\n        while path:\\n            dp[di(d)][path.pop()] = values.pop()\\n            d *= -1\\n\\n\\nfor i in range(1, n):\\n    aaa[1] = i\\n    res = solve(1, 1)\\n    rs[i-1] = res if res < INF else -1\\n\\n\\nprint('\\\\n'.join(map(str, rs)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/groups-of-special-equivalent-strings\\/:\\nYou are given an array A of strings.\\nA move onto S consists of swapping any two even indexed characters of S, or any two odd indexed characters of S.\\nTwo strings S and T are special-equivalent if after any number of moves onto S, S == T.\\nFor example, S = \\\"zzxy\\\" and T = \\\"xyzz\\\" are special-equivalent because we may make the moves \\\"zzxy\\\" -> \\\"xzzy\\\" -> \\\"xyzz\\\" that swap S[0] and S[2], then S[1] and S[3].\\nNow, a group of special-equivalent strings from A is a non-empty subset of A such that:\\n\\nEvery pair of strings in the group are special equivalent, and;\\nThe group is the largest size possible (ie., there isn't a string S not in the group such that S is special equivalent to every string in the group)\\n\\nReturn the number of groups of special-equivalent strings from A.\\n \\n\\nExample 1:\\nInput: [\\\"abcd\\\",\\\"cdab\\\",\\\"cbad\\\",\\\"xyzz\\\",\\\"zzxy\\\",\\\"zzyx\\\"]\\nOutput: 3\\nExplanation: \\nOne group is [\\\"abcd\\\", \\\"cdab\\\", \\\"cbad\\\"], since they are all pairwise special equivalent, and none of the other strings are all pairwise special equivalent to these.\\n\\nThe other two groups are [\\\"xyzz\\\", \\\"zzxy\\\"] and [\\\"zzyx\\\"].  Note that in particular, \\\"zzxy\\\" is not special equivalent to \\\"zzyx\\\".\\n\\n\\nExample 2:\\nInput: [\\\"abc\\\",\\\"acb\\\",\\\"bac\\\",\\\"bca\\\",\\\"cab\\\",\\\"cba\\\"]\\nOutput: 3\\n \\n\\n\\n\\n\\n\\n\\nNote:\\n\\n1 <= A.length <= 1000\\n1 <= A[i].length <= 20\\nAll A[i] have the same length.\\nAll A[i] consist of only lowercase letters.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def numSpecialEquivGroups(self, A: List[str]) -> int:\\n        \\n        # set1 = set()\\n        even_set = []\\n        odd_set = []\\n        for i in A:\\n            even = []\\n            odd = []\\n            for j in range(len(i)):\\n                if j %2 == 0:\\n                    even.append(i[j])\\n                else:\\n                    odd.append(i[j])\\n            even.sort()\\n            odd.sort()\\n            if even in even_set:\\n                k = []\\n                for p,values in enumerate(even_set):\\n                    if even == values:\\n                        k += [p]\\n                flag = 0\\n                for p in k:\\n                    if odd_set[p] == odd:\\n                        flag = 1 \\n                        break\\n                if flag == 0:\\n                    even_set.append(even) \\n                    odd_set.append(odd)\\n            else:\\n                even_set.append(even) \\n                odd_set.append(odd)\\n                \\n        return len(even_set)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nSnuke's town has a subway system, consisting of N stations and M railway lines. The stations are numbered 1 through N. Each line is operated by a company. Each company has an identification number.\\nThe i-th ( 1 \\\\leq i \\\\leq M ) line connects station p_i and q_i bidirectionally. There is no intermediate station. This line is operated by company c_i.\\nYou can change trains at a station where multiple lines are available.\\nThe fare system used in this subway system is a bit strange. When a passenger only uses lines that are operated by the same company, the fare is 1 yen (the currency of Japan). Whenever a passenger changes to a line that is operated by a different company from the current line, the passenger is charged an additional fare of 1 yen. In a case where a passenger who changed from some company A's line to another company's line changes to company A's line again, the additional fare is incurred again.\\nSnuke is now at station 1 and wants to travel to station N by subway. Find the minimum required fare.\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 10^5\\n - 0 \\\\leq M \\\\leq 2×10^5\\n - 1 \\\\leq p_i \\\\leq N (1 \\\\leq i \\\\leq M)\\n - 1 \\\\leq q_i \\\\leq N (1 \\\\leq i \\\\leq M)\\n - 1 \\\\leq c_i \\\\leq 10^6 (1 \\\\leq i \\\\leq M)\\n - p_i \\\\neq q_i (1 \\\\leq i \\\\leq M)\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\nN M\\np_1 q_1 c_1\\n:\\np_M q_M c_M\\n\\n-----Output-----\\nPrint the minimum required fare. If it is impossible to get to station N by subway, print -1 instead.\\n\\n-----Sample Input-----\\n3 3\\n1 2 1\\n2 3 1\\n3 1 2\\n\\n-----Sample Output-----\\n1\\n\\nUse company 1's lines: 1 → 2 → 3. The fare is 1 yen.\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nsys.setrecursionlimit(10**9)\\nfrom collections import deque, defaultdict\\nN, M = list(map(int, input().split()))\\nG = defaultdict(list)\\nfor _ in range(M):\\n    p, q, c = list(map(int, input().split()))\\n    G[(p-1, c-1)].append((p-1, -1))\\n    G[(q-1, c-1)].append((q-1, -1))\\n    G[(p-1, -1)].append((p-1, c-1))\\n    G[(q-1, -1)].append((q-1, c-1))\\n    G[(p-1, c-1)].append((q-1, c-1))\\n    G[(q-1, c-1)].append((p-1, c-1))\\n\\n\\ndist = defaultdict(lambda :-1)\\nque = deque([(0, -1)])\\ndist[(0, -1)] = 0\\nwhile que:\\n    v = que.pop()\\n    d = dist[v]\\n    for nv in G[v]:\\n        if dist[nv]<0:\\n            if nv[1] == -1:\\n                dist[nv] = d+1\\n                que.appendleft(nv)\\n            else:\\n                dist[nv] = d\\n                que.append(nv)\\nprint((dist[(N-1, -1)]))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nNowadays, most of the internet advertisements are not statically linked to a web page. Instead, what will be shown to the person opening a web page is determined within 100 milliseconds after the web page is opened. Usually, multiple companies compete for each ad slot on the web page in an auction. Each of them receives a request with details about the user, web page and ad slot and they have to respond within those 100 milliseconds with a bid they would pay for putting an advertisement on that ad slot. The company that suggests the highest bid wins the auction and gets to place its advertisement. If there are several companies tied for the highest bid, the winner gets picked at random.\\n\\nHowever, the company that won the auction does not have to pay the exact amount of its bid. In most of the cases, a second-price auction is used. This means that the amount paid by the company is equal to the maximum of all the other bids placed for this ad slot.\\n\\nLet's consider one such bidding. There are n companies competing for placing an ad. The i-th of these companies will bid an integer number of microdollars equiprobably randomly chosen from the range between L_{i} and R_{i}, inclusive. In the other words, the value of the i-th company bid can be any integer from the range [L_{i}, R_{i}] with the same probability. \\n\\nDetermine the expected value that the winner will have to pay in a second-price auction.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains an integer number n (2 ≤ n ≤ 5). n lines follow, the i-th of them containing two numbers L_{i} and R_{i} (1 ≤ L_{i} ≤ R_{i} ≤ 10000) describing the i-th company's bid preferences.\\n\\nThis problem doesn't have subproblems. You will get 8 points for the correct submission.\\n\\n\\n-----Output-----\\n\\nOutput the answer with absolute or relative error no more than 1e - 9.\\n\\n\\n-----Examples-----\\nInput\\n3\\n4 7\\n8 10\\n5 5\\n\\nOutput\\n5.7500000000\\n\\nInput\\n3\\n2 5\\n3 4\\n1 6\\n\\nOutput\\n3.5000000000\\n\\n\\n\\n-----Note-----\\n\\nConsider the first example. The first company bids a random integer number of...\",\"targets\":\"d = [list(map(int, input().split())) for i in range(int(input()))]\\n\\ns = 0\\n\\nfor k in range(1, 10001):\\n\\n    p = [min(max((k - l) \\/ (r - l + 1), 1e-20), 1) for l, r in d]\\n\\n    u = v = 1\\n\\n    for r in p: u *= r\\n\\n    for r in p:\\n\\n        v *= r\\n\\n        s += (u - v) * (r - 1) \\/ r\\n\\nprint(s)\\n\\n\\n\\n\\n# Made By Mostafa_Khaled\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/556\\/A:\\nAndrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.\\n\\nOnce he thought about a string of length n consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, and the other contains 1, then we are allowed to remove these two digits from the string, obtaining a string of length n - 2 as a result.\\n\\nNow Andreid thinks about what is the minimum length of the string that can remain after applying the described operation several times (possibly, zero)? Help him to calculate this number.\\n\\n\\n-----Input-----\\n\\nFirst line of the input contains a single integer n (1 ≤ n ≤ 2·10^5), the length of the string that Andreid has.\\n\\nThe second line contains the string of length n consisting only from zeros and ones.\\n\\n\\n-----Output-----\\n\\nOutput the minimum length of the string that may remain after applying the described operations several times.\\n\\n\\n-----Examples-----\\nInput\\n4\\n1100\\n\\nOutput\\n0\\n\\nInput\\n5\\n01010\\n\\nOutput\\n1\\n\\nInput\\n8\\n11101111\\n\\nOutput\\n6\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample test it is possible to change the string like the following: $1100 \\\\rightarrow 10 \\\\rightarrow(\\\\text{empty})$.\\n\\nIn the second sample test it is possible to change the string like the following: $01010 \\\\rightarrow 010 \\\\rightarrow 0$.\\n\\nIn the third sample test it is possible to change the string like the following: $11101111 \\\\rightarrow 111111$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\ns = input()\\nstack = []\\nfor c in s :\\n          if stack==[] : stack.append(c)\\n          elif stack[len(stack)-1]+c=='10' or stack[len(stack)-1]+c=='01' : stack.pop(len(stack)-1)\\n          else : stack.append(c)\\nprint(len(stack))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nSpeedcubing is the hobby involving solving a variety of twisty puzzles, the most famous being the 3x3x3 puzzle or Rubik's Cube, as quickly as possible.\\n\\nIn the majority of Speedcubing competitions, a Cuber solves a scrambled cube 5 times, and their result is found by taking the average of the middle 3 solves (ie. the slowest and fastest times are disregarded, and an average is taken of the remaining times).\\n\\nIn some competitions, the unlikely event of a tie situation is resolved by comparing Cuber's fastest times.\\n\\nWrite a function ```cube_times(times)``` that, given an array of floats ```times``` returns an array \\/ tuple with the Cuber's result (to 2 decimal places) AND their fastest solve.\\n\\nFor example:\\n```python\\ncube_times([9.5, 7.6, 11.4, 10.5, 8.1]) = (9.37, 7.6)\\n# Because (9.5 + 10.5 + 8.1) \\/ 3 = 9.37 and 7.6 was the fastest solve.\\n```\\n\\nNote: ```times``` will always be a valid array of 5 positive floats (representing seconds)\",\"targets\":\"def cube_times(times):\\n    return (round((sum(times) - (min(times) + max(times)))\\/3 , 2), min(times))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven are positive integers A and B.\\nLet us choose some number of positive common divisors of A and B.\\nHere, any two of the chosen divisors must be coprime.\\nAt most, how many divisors can we choose?Definition of common divisor\\nAn integer d is said to be a common divisor of integers x and y when d divides both x and y.Definition of being coprime\\nIntegers x and y are said to be coprime when x and y have no positive common divisors other than 1.Definition of dividing\\nAn integer x is said to divide another integer y when there exists an integer \\\\alpha such that y = \\\\alpha x.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq A, B \\\\leq 10^{12}\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B\\n\\n-----Output-----\\nPrint the maximum number of divisors that can be chosen to satisfy the condition.\\n\\n-----Sample Input-----\\n12 18\\n\\n-----Sample Output-----\\n3\\n\\n12 and 18 have the following positive common divisors: 1, 2, 3, and 6.\\n1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.\",\"targets\":\"a,b=map(int,input().split())\\ndef gcd(a,b):\\n  if b==0:\\n    return a\\n  else:\\n    return gcd(b,a%b)\\ndef factorize(x):\\n  i=2\\n  res=[]\\n  while i*i<=x:\\n    while x%i==0:\\n      x\\/\\/=i\\n      res.append(i)\\n    i+=1\\n  if x>1:\\n    res.append(x)\\n  return res\\ng=gcd(a,b)\\nf=factorize(g)\\nprint(len(set(f))+1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nShubham recently learned the lexicographical order in strings.\\n\\nNow, he has two strings s1  and  s2  of the equal size and Shubham wants to compare those two strings lexicographically.\\n\\nHelp Shubham with the strings comparison.\\n\\nNote:\\n\\nLetters are case insensitive. \\n\\n\\n-----Input-----\\n\\nFirst line contains a integer T denoting the number of test cases. Each test case contains two strings of equal size in two separate lines.\\n\\n-----Output-----\\n\\nFor each test case,\\n\\nIf s1 < s2, print \\\"first\\\".\\n\\nIf s1 > s2, print \\\"second\\\".\\n\\nIf s1=s2, print \\\"equal\\\".\\n\\n\\nin separate lines.\\n\\n-----Constraints-----\\n\\n- 1 ≤ T ≤ 10^2\\n- 1 ≤ Length of the string ≤ 500\\n\\n-----Example-----\\nInput:\\n2\\nabc\\nacb\\nAB\\nba\\n\\nOutput:\\nfirst\\nfirst\",\"targets\":\"for t in range(eval(input())) :\\n s, t = input(), input()\\n s = s.lower()\\n t = t.lower()\\n if s < t :\\n  print('first')\\n elif s > t :\\n  print('second')\\n else :\\n  print('equal')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe prime numbers are not regularly spaced. For example from `2` to `3` the gap is `1`.\\nFrom `3` to `5` the gap is `2`. From `7` to `11` it is `4`.\\nBetween 2 and 50 we have the following pairs of 2-gaps primes:\\n`3-5, 5-7, 11-13, 17-19, 29-31, 41-43`\\n\\nA prime gap of length n is a run of n-1 consecutive composite numbers between two **successive** primes (see: http:\\/\\/mathworld.wolfram.com\\/PrimeGaps.html).\\n\\nWe will write a function gap with parameters:\\n\\n`g` (integer >= 2) which indicates the gap we are looking for\\n\\n`m` (integer > 2) which gives the start of the search (m inclusive)\\n\\n`n` (integer >= m) which gives the end of the search (n inclusive)\\n\\nIn the example above `gap(2, 3, 50)` will return `[3, 5] or (3, 5) or {3, 5}` which is the first pair between 3 and 50 with a 2-gap.\\n\\nSo this function should return the **first** pair of two prime numbers spaced with a gap of `g`\\nbetween the limits `m`, `n` if these numbers exist otherwise `nil or null or None or Nothing` (depending on the language). \\n\\nIn C++ return in such a case `{0, 0}`. In F# return `[||]`. In Kotlin return `[]`\\n\\n#Examples:\\n`gap(2, 5, 7) --> [5, 7] or (5, 7) or {5, 7}`\\n\\n`gap(2, 5, 5) --> nil. In C++ {0, 0}. In F# [||]. In Kotlin return `[]`\\n\\n`gap(4, 130, 200) --> [163, 167] or (163, 167) or {163, 167}`\\n\\n([193, 197] is also such a 4-gap primes between 130 and 200 but it's not the first pair)\\n\\n`gap(6,100,110) --> nil or {0, 0}` : between 100 and 110 we have `101, 103, 107, 109` but `101-107`is not a\\n6-gap because there is `103`in between and `103-109`is not a 6-gap because there is `107`in between.\\n\\n# Note for Go\\nFor Go: nil slice is expected when there are no gap between m and n.\\nExample: gap(11,30000,100000) --> nil\\n\\n#Ref\\nhttps:\\/\\/en.wikipedia.org\\/wiki\\/Prime_gap\",\"targets\":\"def check_prime_number(n):\\n    if n % 2 == 0:\\n        return n == 2\\n    d = 3\\n    while d * d <= n and n % d != 0:\\n        d += 2\\n    return d * d > n\\n\\ndef get_next_prime_number(start, end):\\n    for number in range(start, end+1):\\n        if check_prime_number(number) == True:\\n            return number\\n\\ndef gap(g, m, n):\\n    prime_number_left = get_next_prime_number(m, n)\\n    if prime_number_left is None:\\n        return \\n    while True:\\n        prime_number_right = get_next_prime_number(prime_number_left + 1, n)\\n        if prime_number_right is None:\\n            return None\\n        if prime_number_right - prime_number_left == g:\\n            return [prime_number_left, prime_number_right]\\n            \\n        prime_number_left = prime_number_right\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef has recently learned about number bases and is becoming fascinated.\\nChef learned that for bases greater than ten, new digit symbols need to be introduced, and that the convention is to use the first few letters of the English alphabet. For example, in base 16, the digits are 0123456789ABCDEF. Chef thought that this is unsustainable; the English alphabet only has 26 letters, so this scheme can only work up to base 36. But this is no problem for Chef, because Chef is very creative and can just invent new digit symbols when she needs them. (Chef is very creative.)\\nChef also noticed that in base two, all positive integers start with the digit 1! However, this is the only base where this is true. So naturally, Chef wonders: Given some integer N, how many bases b are there such that the base-b representation of N starts with a 1?\\n\\n-----Input-----\\nThe first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows.\\nEach test case consists of one line containing a single integer N (in base ten).\\n\\n-----Output-----\\nFor each test case, output a single line containing the number of bases b, or INFINITY if there are an infinite number of them.\\n\\n-----Constraints-----\\n\\n-----Subtasks-----Subtask #1 (16 points):\\n- 1 ≤ T ≤ 103\\n- 0 ≤ N < 103\\nSubtask #2 (24 points):\\n- 1 ≤ T ≤ 103\\n- 0 ≤ N < 106\\nSubtask #3 (28 points):\\n- 1 ≤ T ≤ 103\\n- 0 ≤ N < 1012\\nSubtask #4 (32 points):\\n- 1 ≤ T ≤ 105\\n- 0 ≤ N < 1012\\n\\n-----Example-----\\nInput:4\\n6\\n9\\n11\\n24\\n\\nOutput:4\\n7\\n8\\n14\\n\\n-----Explanation-----\\nIn the first test case, 6 has a leading digit 1 in bases 2, 4, 5 and 6: 610 = 1102 = 124 = 115 = 106.\",\"targets\":\"# cook your dish here\\nn=int(input())\\ndef dig(num,b):\\n    c=0\\n    mul=b\\n    while(True):\\n        if(num\\/\\/mul!=0):\\n            mul=mul*b\\n            c+=1 \\n        else:\\n            break\\n    return c \\nfor q in range(n):\\n    num=int(input())\\n    res=0\\n    for i in range(3,num):\\n        po=dig(num,i)\\n        if((2*(i**po)-1)>=num):\\n            res+=1 \\n    if(num==2):\\n        res=res+1 \\n    if(num>2):\\n        res=res+2\\n    if(num==1):\\n        print(\\\"INFINITY\\\")\\n    else:\\n        print(res)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn this kata, your task is to identify the pattern underlying a sequence of numbers. For example, if the sequence is [1, 2, 3, 4, 5], then the pattern is [1], since each number in the sequence is equal to the number preceding it, plus 1. See the test cases for more examples.\\n\\nA few more rules :\\n\\npattern may contain negative numbers.\\nsequence will always be made of a whole number of repetitions of the pattern.\\nYour answer must correspond to the shortest form of the pattern, e.g. if the pattern is [1], then [1, 1, 1, 1] will not be considered a correct answer.\",\"targets\":\"def find_pattern(seq):\\n    start, end = [], []\\n    for i in range(len(seq)-1):\\n        start.append(seq[i+1]-seq[i])\\n        end.append(seq[-1-i]-seq[-2-i])\\n        if not (len(seq)-1) % len(start) and start == end[::-1] and not len(set(start)) == 1:\\n            return start\\n    return [start[0]] if len(set(start)) == 1 else []\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/488\\/A:\\nGiga Tower is the tallest and deepest building in Cyberland. There are 17 777 777 777 floors, numbered from  - 8 888 888 888 to 8 888 888 888. In particular, there is floor 0 between floor  - 1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view. \\n\\nIn Cyberland, it is believed that the number \\\"8\\\" is a lucky number (that's why Giga Tower has 8 888 888 888 floors above the ground), and, an integer is lucky, if and only if its decimal notation contains at least one digit \\\"8\\\". For example, 8,  - 180, 808 are all lucky while 42,  - 10 are not. In the Giga Tower, if you write code at a floor with lucky floor number, good luck will always be with you (Well, this round is #278, also lucky, huh?).\\n\\nTourist Henry goes to the tower to seek good luck. Now he is at the floor numbered a. He wants to find the minimum positive integer b, such that, if he walks b floors higher, he will arrive at a floor with a lucky number. \\n\\n\\n-----Input-----\\n\\nThe only line of input contains an integer a ( - 10^9 ≤ a ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nPrint the minimum b in a line.\\n\\n\\n-----Examples-----\\nInput\\n179\\n\\nOutput\\n1\\n\\nInput\\n-1\\n\\nOutput\\n9\\n\\nInput\\n18\\n\\nOutput\\n10\\n\\n\\n\\n-----Note-----\\n\\nFor the first sample, he has to arrive at the floor numbered 180.\\n\\nFor the second sample, he will arrive at 8.\\n\\nNote that b should be positive, so the answer for the third sample is 10, not 0.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"x = int(input())\\ncont = 1\\nx += 1\\nwhile not '8' in str(x):\\n    x += 1\\n    cont += 1\\n\\nprint (cont)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are just some things you can't do on television. In this case, you've just come back from having a \\\"delicious\\\" Barth burger and you're set to give an interview. The Barth burger has made you queezy, and you've forgotten some of the import rules of the \\\"You Can't Do That on Television\\\" set.\\n\\nIf you say any of the following words a large bucket of \\\"water\\\" will be dumped on you:\\n\\\"water\\\", \\\"wet\\\", \\\"wash\\\"\\nThis is true for any form of those words, like \\\"washing\\\", \\\"watered\\\", etc.\\n\\nIf you say any of the following phrases you will be doused in \\\"slime\\\":\\n\\\"I don't know\\\", \\\"slime\\\"\\n\\nIf you say both in one sentence, a combination of water and slime, \\\"sludge\\\", will be dumped on you.\\n\\nWrite a function, bucketOf(str), that takes a string and determines what will be dumped on your head. If you haven't said anything you shouldn't have, the bucket should be filled with \\\"air\\\". The words should be tested regardless of case.\\n\\nExamples:\\n\\n\\nCheck out my other 80's Kids Katas:\\n\\n\\n80's Kids #1: How Many Licks Does It Take\\n80's Kids #2: Help Alf Find His Spaceship\\n80's Kids #3: Punky Brewster's Socks\\n80's Kids #4: Legends of the Hidden Temple\\n80's Kids #5: You Can't Do That on Television\\n80's Kids #6: Rock 'Em, Sock 'Em Robots\\n80's Kids #7: She's a Small Wonder\\n80's Kids #8: The Secret World of Alex Mack\\n80's Kids #9: Down in Fraggle Rock \\n80's Kids #10: Captain Planet\",\"targets\":\"import re\\nbucket_of = lambda said: \\\\\\n    ({ 0: 'air', 1: 'water', 2: 'slime', 3: 'sludge' }) \\\\\\n    [bool(re.search('(?i)(water|wet|wash)', said)) + bool(re.search('(?i)(I don\\\\'t know|slime)', said)) * 2]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55b86beb1417eab500000051:\\nA binary gap within a positive number ```num``` is any sequence of consecutive zeros that is surrounded by ones at both ends in the binary representation of  ```num```. \\n    For example:\\n    ```9``` has binary representation ```1001``` and contains a binary gap of length ```2```.\\n    ```529``` has binary representation ```1000010001``` and contains two binary gaps: one of length ```4``` and one of length ```3```.\\n    ```20``` has binary representation ```10100``` and contains one binary gap of length ```1```.\\n    ```15``` has binary representation ```1111``` and has ```0``` binary gaps.\\n    Write ```function gap(num)```\\nthat,  given a positive ```num```,  returns the length of its longest binary gap. The function should return ```0``` if ```num``` doesn't contain a binary gap.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import re\\n\\ndef gap(num):\\n    num = bin(num)[2:]\\n    return max(map(len, re.findall(\\\"(?<=1)0+(?=1)\\\", num)), default=0)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/681\\/D:\\nSasha lives in a big happy family. At the Man's Day all the men of the family gather to celebrate it following their own traditions. There are n men in Sasha's family, so let's number them with integers from 1 to n.\\n\\nEach man has at most one father but may have arbitrary number of sons.\\n\\nMan number A is considered to be the ancestor of the man number B if at least one of the following conditions is satisfied:   A = B;  the man number A is the father of the man number B;  there is a man number C, such that the man number A is his ancestor and the man number C is the father of the man number B. \\n\\nOf course, if the man number A is an ancestor of the man number B and A ≠ B, then the man number B is not an ancestor of the man number A.\\n\\nThe tradition of the Sasha's family is to give gifts at the Man's Day. Because giving gifts in a normal way is boring, each year the following happens.  A list of candidates is prepared, containing some (possibly all) of the n men in some order.  Each of the n men decides to give a gift.  In order to choose a person to give a gift to, man A looks through the list and picks the first man B in the list, such that B is an ancestor of A and gives him a gift. Note that according to definition it may happen that a person gives a gift to himself.  If there is no ancestor of a person in the list, he becomes sad and leaves the celebration without giving a gift to anyone. \\n\\nThis year you have decided to help in organizing celebration and asked each of the n men, who do they want to give presents to (this person is chosen only among ancestors). Are you able to make a list of candidates, such that all the wishes will be satisfied if they give gifts according to the process described above?\\n\\n\\n-----Input-----\\n\\nIn the first line of the input two integers n and m (0 ≤ m < n ≤ 100 000) are given — the number of the men in the Sasha's family and the number of family relations in it respectively.\\n\\nThe next m lines describe family relations: the (i + 1)^{th} line consists of pair of integers p_{i} and...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = map(int, input().split())\\nadj = [[] for _ in range(n)]\\ncp = [-1] * n\\n\\nfor i in range(m):\\n    p, c = map(int, input().split())\\n    adj[p - 1].append(c - 1)\\n    cp[c - 1] = p - 1\\n\\npres = [i - 1 for i in map(int, input().split())]\\n\\nlevel = [0] * n\\nfrom collections import deque\\ndef bfs(v):\\n    q = deque([v])\\n    while q:\\n        v = q.pop()\\n        if cp[v] >= 0:\\n            level[v] = level[cp[v]] + 1\\n        for nv in adj[v]:\\n            q.append(nv)\\n\\nfor i in range(n):\\n    if cp[i] == -1:\\n        bfs(i)\\n\\nfor i in range(n):\\n    if level[i] > 0:\\n        par = cp[i]\\n        if pres[i] != pres[par] and level[pres[i]] <= level[par]:\\n            print(-1)\\n            return\\n\\npres = list(set(pres))\\npres = sorted(pres, key = lambda i : level[i], reverse = True)\\n\\nprint(len(pres))\\npres = [i + 1 for i in pres]\\nprint(\\\"\\\\n\\\".join(map(str, pres)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/52fe629e48970ad2bd0007e6:\\nYour task is to create a new implementation of `modpow` so that it computes `(x^y)%n` for large `y`. The problem with the current implementation is that the output of `Math.pow` is so large on our inputs that it won't fit in a 64-bit float.\\n\\nYou're also going to need to be efficient, because we'll be testing some pretty big numbers.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def power_mod(x, y, n):\\n    x = x%n\\n    b = bin(y)[2:]\\n    l = len(b)\\n    res = [0]*l\\n    for i in range(l):\\n        res[-i-1] = x\\n        x *= x\\n        x = x%n\\n    prod = 1\\n    for i in range(l):\\n        if b[-i-1] == '1':\\n            prod *= res[-i-1]\\n            prod = prod%n\\n    return prod\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/56242b89689c35449b000059:\\nA grid is a perfect starting point for many games (Chess, battleships, Candy Crush!).\\n\\nMaking a digital chessboard I think is an interesting way of visualising how loops can work together.\\n\\nYour task is to write a function that takes two integers `rows` and `columns` and returns a chessboard pattern as a two dimensional array.\\n\\nSo `chessBoard(6,4)` should return an array like this:\\n\\n\\n    [\\n            [\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\"],\\n            [\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\"],\\n            [\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\"],\\n            [\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\"],\\n            [\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\"],\\n            [\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\"]\\n    ]\\n\\nAnd `chessBoard(3,7)` should return this:\\n\\n\\n    [\\n        [\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\"],\\n        [\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\"],\\n        [\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\",\\\"X\\\",\\\"O\\\"]\\n    ]\\n\\nThe white spaces should be represented by an: `'O'`\\n\\nand the black an: `'X'`\\n\\nThe first row should always start with a white space `'O'`\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def chess_board(a, b):\\n    return [list(\\\"OXXO\\\"[i%2::2] * (b \\/\\/ 2 + 1))[:b] for i in range(a)]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1320\\/D:\\nIn this problem, we will deal with binary strings. Each character of a binary string is either a 0 or a 1. We will also deal with substrings; recall that a substring is a contiguous subsequence of a string. We denote the substring of string $s$ starting from the $l$-th character and ending with the $r$-th character as $s[l \\\\dots r]$. The characters of each string are numbered from $1$.\\n\\nWe can perform several operations on the strings we consider. Each operation is to choose a substring of our string and replace it with another string. There are two possible types of operations: replace 011 with 110, or replace 110 with 011. For example, if we apply exactly one operation to the string 110011110, it can be transformed into 011011110, 110110110, or 110011011.\\n\\nBinary string $a$ is considered reachable from binary string $b$ if there exists a sequence $s_1$, $s_2$, ..., $s_k$ such that $s_1 = a$, $s_k = b$, and for every $i \\\\in [1, k - 1]$, $s_i$ can be transformed into $s_{i + 1}$ using exactly one operation. Note that $k$ can be equal to $1$, i. e., every string is reachable from itself.\\n\\nYou are given a string $t$ and $q$ queries to it. Each query consists of three integers $l_1$, $l_2$ and $len$. To answer each query, you have to determine whether $t[l_1 \\\\dots l_1 + len - 1]$ is reachable from $t[l_2 \\\\dots l_2 + len - 1]$.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the length of string $t$.\\n\\nThe second line contains one string $t$ ($|t| = n$). Each character of $t$ is either 0 or 1.\\n\\nThe third line contains one integer $q$ ($1 \\\\le q \\\\le 2 \\\\cdot 10^5$) — the number of queries.\\n\\nThen $q$ lines follow, each line represents a query. The $i$-th line contains three integers $l_1$, $l_2$ and $len$ ($1 \\\\le l_1, l_2 \\\\le |t|$, $1 \\\\le len \\\\le |t| - \\\\max(l_1, l_2) + 1$) for the $i$-th query.\\n\\n\\n-----Output-----\\n\\nFor each query, print either YES if $t[l_1 \\\\dots l_1 + len - 1]$ is reachable from $t[l_2 \\\\dots l_2 + len - 1]$, or NO otherwise. You may print each letter in any...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\nMOD = 987654103\\n\\nn = int(input())\\nt = input()\\n\\nplace = []\\nf1 = []\\ne1 = []\\n\\ns = []\\ncurr = 0\\ncount1 = 0\\nfor i in range(n):\\n    c = t[i]\\n    if c == '0':\\n        if count1:\\n            e1.append(i - 1)\\n            if count1 & 1:\\n                s.append(1)\\n                curr += 1\\n                e1.append(-1)\\n                f1.append(-1)\\n            count1 = 0\\n        else:\\n            f1.append(-1)\\n            e1.append(-1)\\n\\n        place.append(curr)\\n        curr += 1\\n        s.append(0)\\n    else:\\n        if count1 == 0:\\n            f1.append(i)\\n        count1 += 1\\n        place.append(curr)\\n\\nif count1:\\n    if count1 & 1:\\n        s.append(1)\\n    else:\\n        s.append(0)\\n    curr += 1\\n    e1.append(n - 1)\\n\\n    e1.append(-1)\\n    f1.append(-1)\\nplace.append(curr)\\n\\npref = [0]\\nval = 0\\nfor i in s:\\n    val *= 3\\n    val += i + 1\\n    val %= MOD\\n    pref.append(val)\\n        \\n\\nq = int(input())\\nout = []\\nfor _ in range(q):\\n    l1, l2, leng = list(map(int, input().split()))\\n    l1 -= 1\\n    l2 -= 1\\n\\n    starts = (l1, l2)\\n    hashes = []\\n    for start in starts:\\n        end = start + leng - 1\\n\\n        smap = place[start]\\n        emap = place[end]\\n        if t[end] == '1':\\n            emap -= 1\\n        if s[smap] == 1:\\n            smap += 1\\n\\n        prep = False\\n        app = False\\n\\n        if t[start] == '1':\\n            last = e1[place[start]]\\n            last = min(last, end)\\n            count = last - start + 1\\n            if count % 2:\\n                prep = True\\n        if t[end] == '1':\\n            first = f1[place[end]]\\n            first = max(first, start)\\n            count = end - first + 1\\n            if count % 2:\\n                app = True\\n\\n        preHash = 0\\n        length = 0\\n        if smap <= emap:\\n            length = emap - smap + 1\\n            preHash = pref[emap + 1]\\n            preHash -= pref[smap] * pow(3, emap - smap + 1, MOD)\\n            preHash %= MOD\\n\\n\\n        if length == 0 and prep and app:\\n            app = False\\n\\n        #print(preHash, prep, app,...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nInzane finally found Zane with a lot of money to spare, so they together decided to establish a country of their own.\\n\\nRuling a country is not an easy job. Thieves and terrorists are always ready to ruin the country's peace. To fight back, Zane and Inzane have enacted a very effective law: from each city it must be possible to reach a police station by traveling at most d kilometers along the roads. [Image] \\n\\nThere are n cities in the country, numbered from 1 to n, connected only by exactly n - 1 roads. All roads are 1 kilometer long. It is initially possible to travel from a city to any other city using these roads. The country also has k police stations located in some cities. In particular, the city's structure satisfies the requirement enforced by the previously mentioned law. Also note that there can be multiple police stations in one city.\\n\\nHowever, Zane feels like having as many as n - 1 roads is unnecessary. The country is having financial issues, so it wants to minimize the road maintenance cost by shutting down as many roads as possible.\\n\\nHelp Zane find the maximum number of roads that can be shut down without breaking the law. Also, help him determine such roads.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers n, k, and d (2 ≤ n ≤ 3·10^5, 1 ≤ k ≤ 3·10^5, 0 ≤ d ≤ n - 1) — the number of cities, the number of police stations, and the distance limitation in kilometers, respectively.\\n\\nThe second line contains k integers p_1, p_2, ..., p_{k} (1 ≤ p_{i} ≤ n) — each denoting the city each police station is located in.\\n\\nThe i-th of the following n - 1 lines contains two integers u_{i} and v_{i} (1 ≤ u_{i}, v_{i} ≤ n, u_{i} ≠ v_{i}) — the cities directly connected by the road with index i.\\n\\nIt is guaranteed that it is possible to travel from one city to any other city using only the roads. Also, it is possible from any city to reach a police station within d kilometers.\\n\\n\\n-----Output-----\\n\\nIn the first line, print one integer s that denotes the maximum number of roads that can be shut down.\\n\\nIn the...\",\"targets\":\"import os, sys, bisect, copy\\nfrom collections import defaultdict, Counter, deque\\nfrom functools import lru_cache   #use @lru_cache(None)\\nif os.path.exists('in.txt'): sys.stdin=open('in.txt','r')\\nif os.path.exists('out.txt'): sys.stdout=open('out.txt', 'w')\\n#\\ndef input(): return sys.stdin.readline()\\ndef mapi(arg=0): return map(int if arg==0 else str,input().split())\\n#------------------------------------------------------------------\\n\\nn,k,d = mapi()\\nplc = list(mapi())\\ngr = defaultdict(list)\\nfor i in range(1,n):\\n    u,v = mapi()\\n    gr[u].append([v,i])\\n    gr[v].append([u,i])\\nq = deque()\\nfor i in plc:\\n    q.append((i,0))\\nvis = {}\\nres = [0]*(n+1)\\nwhile q:\\n    tmp,par = q.popleft()\\n    if tmp in vis:\\n        continue\\n    vis[tmp] = 1\\n    for item in gr[tmp]:\\n        if item[0] != par:\\n            if item[0] in vis:\\n                res[item[1]] = 1\\n            else:\\n                q.append((item[0],tmp))\\ncnt = 0\\nans = []\\nfor i in range(1,n+1):\\n    if res[i]==1:\\n        cnt+=1\\n        ans.append(i)\\nprint(cnt)\\nprint(*ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou have $n$ coins, each of the same value of $1$.\\n\\nDistribute them into packets such that any amount $x$ ($1 \\\\leq x \\\\leq n$) can be formed using some (possibly one or all) number of these packets.\\n\\nEach packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single $x$, however it may be reused for the formation of other $x$'s.\\n\\nFind the minimum number of packets in such a distribution.\\n\\n\\n-----Input-----\\n\\nThe only line contains a single integer $n$ ($1 \\\\leq n \\\\leq 10^9$) — the number of coins you have.\\n\\n\\n-----Output-----\\n\\nOutput a single integer — the minimum possible number of packets, satisfying the condition above.\\n\\n\\n-----Examples-----\\nInput\\n6\\n\\nOutput\\n3\\nInput\\n2\\n\\nOutput\\n2\\n\\n\\n-----Note-----\\n\\nIn the first example, three packets with $1$, $2$ and $3$ coins can be made to get any amount $x$ ($1\\\\leq x\\\\leq 6$).  To get $1$ use the packet with $1$ coin.  To get $2$ use the packet with $2$ coins.  To get $3$ use the packet with $3$ coins.  To get $4$ use packets with $1$ and $3$ coins.  To get $5$ use packets with $2$ and $3$ coins  To get $6$ use all packets. \\n\\nIn the second example, two packets with $1$ and $1$ coins can be made to get any amount $x$ ($1\\\\leq x\\\\leq 2$).\",\"targets\":\"from math import log2\\nn  = int(input())\\n\\na = log2(n+1)\\nres = int(a)\\nif a- res > 0:\\n    res +=1\\n\\nprint(res)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1152\\/E:\\nA permutation of length $k$ is a sequence of $k$ integers from $1$ to $k$ containing each integer exactly once. For example, the sequence $[3, 1, 2]$ is a permutation of length $3$.\\n\\nWhen Neko was five, he thought of an array $a$ of $n$ positive integers and a permutation $p$ of length $n - 1$. Then, he performed the following:\\n\\n  Constructed an array $b$ of length $n-1$, where $b_i = \\\\min(a_i, a_{i+1})$.  Constructed an array $c$ of length $n-1$, where $c_i = \\\\max(a_i, a_{i+1})$.  Constructed an array $b'$ of length $n-1$, where $b'_i = b_{p_i}$.  Constructed an array $c'$ of length $n-1$, where $c'_i = c_{p_i}$. \\n\\nFor example, if the array $a$ was $[3, 4, 6, 5, 7]$ and permutation $p$ was $[2, 4, 1, 3]$, then Neko would have constructed the following arrays:\\n\\n  $b = [3, 4, 5, 5]$  $c = [4, 6, 6, 7]$  $b' = [4, 5, 3, 5]$  $c' = [6, 7, 4, 6]$ \\n\\nThen, he wrote two arrays $b'$ and $c'$ on a piece of paper and forgot about it. 14 years later, when he was cleaning up his room, he discovered this old piece of paper with two arrays $b'$ and $c'$ written on it. However he can't remember the array $a$ and permutation $p$ he used.\\n\\nIn case Neko made a mistake and there is no array $a$ and permutation $p$ resulting in such $b'$ and $c'$, print -1. Otherwise, help him recover any possible array $a$. \\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $n$ ($2 \\\\leq n \\\\leq 10^5$) — the number of elements in array $a$.\\n\\nThe second line contains $n-1$ integers $b'_1, b'_2, \\\\ldots, b'_{n-1}$ ($1 \\\\leq b'_i \\\\leq 10^9$).\\n\\nThe third line contains $n-1$ integers $c'_1, c'_2, \\\\ldots, c'_{n-1}$ ($1 \\\\leq c'_i \\\\leq 10^9$).\\n\\n\\n-----Output-----\\n\\nIf Neko made a mistake and there is no array $a$ and a permutation $p$ leading to the $b'$ and $c'$, print -1. Otherwise, print $n$ positive integers $a_i$ ($1 \\\\le a_i \\\\le 10^9$), denoting the elements of the array $a$.\\n\\nIf there are multiple possible solutions, print any of them. \\n\\n\\n-----Examples-----\\nInput\\n5\\n4 5 3 5\\n6 7 4 6\\n\\nOutput\\n3 4 6 5 7 \\n\\nInput\\n3\\n2 4\\n3 2\\n\\nOutput\\n-1\\n\\nInput\\n8\\n2 3 1 1 2 4...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import defaultdict, Counter\\nN = int(input())\\nB = list(map(int, input().split()))\\nC = list(map(int, input().split()))\\nEdge = defaultdict(list)\\nEdc = defaultdict(int)\\nfor b, c in zip(B, C):\\n    if b > c:\\n        print(-1)\\n        return\\n    Edge[b].append(c)\\n    Edc[(b, c)] += 1\\n    if b != c:\\n        Edge[c].append(b)\\nDeg = Counter(B + C)\\neul = 0\\nst = []\\nfor k, v in list(Deg.items()):\\n    if v % 2:\\n        eul += 1\\n        st.append(k)\\ns, e = B[0], B[0]\\nif eul and eul != 2:\\n    print(-1)\\n    return\\nif eul:\\n    s, e = st[0], st[1]\\nans = [s]\\nwhile True:\\n    vn = ans[-1]\\n    while True:\\n        vf = Edge[vn][-1]\\n        if Deg[vf] != 0 and Edc[(vn, vf) if vn < vf else (vf, vn)]:\\n            break\\n        Edge[vn].pop()\\n    vf = Edge[vn].pop()\\n    Deg[vn] -= 1\\n    Deg[vf] -= 1\\n    Edc[(vn, vf) if vn < vf else (vf, vn)] -= 1\\n    ans.append(vf)\\n    if not Deg[vf]:\\n        break\\nloop = defaultdict(list)\\nfor a in ans:\\n    if Deg[a]:\\n        loopa = [a]\\n        while Deg[a]:\\n            vn = loopa[-1]\\n            while True:\\n                vf = Edge[vn][-1]\\n                if Deg[vf] != 0 and Edc[(vn, vf) if vn < vf else (vf, vn)]:\\n                    break\\n                Edge[vn].pop()\\n            vf = Edge[vn].pop()\\n            Deg[vn] -= 1\\n            Deg[vf] -= 1\\n            Edc[(vn, vf) if vn < vf else (vf, vn)] -= 1\\n            loopa.append(vf)\\n            if not Deg[vf]:\\n                break\\n        loop[a] = loopa\\nAns = [] \\nfor a in ans:\\n    if loop[a]:\\n        Ans.extend(loop[a])\\n        loop[a] = []\\n    else:\\n        Ans.append(a)    \\nif len(Ans) != N:\\n    print(-1)\\n    return\\nprint(*Ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have a tree with N vertices numbered 1 to N.\\nThe i-th edge in this tree connects Vertex a_i and Vertex b_i.\\n\\nConsider painting each of these edges white or black. There are 2^{N-1} such ways to paint the edges. Among them, how many satisfy all of the following M restrictions?  \\n - The i-th (1 \\\\leq i \\\\leq M) restriction is represented by two integers u_i and v_i, which mean that the path connecting Vertex u_i and Vertex v_i must contain at least one edge painted black.\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 50\\n - 1 \\\\leq a_i,b_i \\\\leq N\\n - The graph given in input is a tree.\\n - 1 \\\\leq M \\\\leq \\\\min(20,\\\\frac{N(N-1)}{2})\\n - 1 \\\\leq u_i < v_i \\\\leq N\\n - If i \\\\not= j, either u_i \\\\not=u_j or v_i\\\\not=v_j\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\na_1 b_1\\n:\\na_{N-1} b_{N-1}\\nM\\nu_1 v_1\\n:\\nu_M v_M\\n\\n-----Output-----\\nPrint the number of ways to paint the edges that satisfy all of the M conditions.\\n\\n-----Sample Input-----\\n3\\n1 2\\n2 3\\n1\\n1 3\\n\\n-----Sample Output-----\\n3\\n\\nThe tree in this input is shown below:\\n\\n\\n\\n\\n\\nAll of the M restrictions will be satisfied if Edge 1 and 2 are respectively painted (white, black), (black, white), or (black, black), so the answer is 3.\",\"targets\":\"from functools import reduce\\n# https:\\/\\/drken1215.hatenablog.com\\/entry\\/2020\\/01\\/26\\/164200\\n# bit_pathの参考にした\\n# https:\\/\\/atcoder.jp\\/contests\\/abc152\\/submissions\\/9619555\\n# popcnt\\n\\ndef main():\\n    from collections import namedtuple\\n    from functools import reduce\\n    from itertools import combinations\\n    from operator import or_\\n\\n    Edge = namedtuple('Edge', 'to edge_id')\\n\\n    def bit_path(curr, goal, par=-1):\\n        if curr == goal:\\n            return 0\\n        for e in g[curr]:\\n            if e.to == par: continue\\n            res = bit_path(curr=e.to, goal=goal, par=curr)\\n            if ~res:  # -1以外\\n                return res | (1 << e.edge_id)\\n        return -1\\n\\n    def popcnt(n):\\n        \\\"\\\"\\\"https:\\/\\/atcoder.jp\\/contests\\/abc152\\/submissions\\/9619555\\\"\\\"\\\"\\n        c = (n & 0x5555555555555555) + ((n >> 1) & 0x5555555555555555)\\n        c = (c & 0x3333333333333333) + ((c >> 2) & 0x3333333333333333)\\n        c = (c & 0x0f0f0f0f0f0f0f0f) + ((c >> 4) & 0x0f0f0f0f0f0f0f0f)\\n        c = (c & 0x00ff00ff00ff00ff) + ((c >> 8) & 0x00ff00ff00ff00ff)\\n        c = (c & 0x0000ffff0000ffff) + ((c >> 16) & 0x0000ffff0000ffff)\\n        c = (c & 0x00000000ffffffff) + ((c >> 32) & 0x00000000ffffffff)\\n        return c\\n\\n    N = int(input())\\n\\n    g = tuple(set() for _ in range(N))\\n    for edge_id in range(N - 1):\\n        a, b = (int(x) - 1 for x in input().split())\\n        g[a].add(Edge(to=b, edge_id=edge_id))\\n        g[b].add(Edge(to=a, edge_id=edge_id))\\n\\n    M = int(input())\\n\\n    cons = []\\n    for _ in range(M):\\n        u, v = (int(x) - 1 for x in input().split())\\n        b = bit_path(u, v)\\n        cons.append(b)\\n\\n    ans = 1 << (N - 1)\\n    for k in range(1, M + 1):\\n        for comb in combinations(cons, r=k):\\n            b = reduce(or_, comb)\\n            ans += ((-1) ** k) * (1 << (N - 1 - popcnt(b)))\\n    print(ans)\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a m * n matrix of ones and zeros, return how many square submatrices have all ones.\\n \\nExample 1:\\nInput: matrix =\\n[\\n  [0,1,1,1],\\n  [1,1,1,1],\\n  [0,1,1,1]\\n]\\nOutput: 15\\nExplanation: \\nThere are 10 squares of side 1.\\nThere are 4 squares of side 2.\\nThere is  1 square of side 3.\\nTotal number of squares = 10 + 4 + 1 = 15.\\n\\nExample 2:\\nInput: matrix = \\n[\\n  [1,0,1],\\n  [1,1,0],\\n  [1,1,0]\\n]\\nOutput: 7\\nExplanation: \\nThere are 6 squares of side 1.  \\nThere is 1 square of side 2. \\nTotal number of squares = 6 + 1 = 7.\\n\\n \\nConstraints:\\n\\n1 <= arr.length <= 300\\n1 <= arr[0].length <= 300\\n0 <= arr[i][j] <= 1\",\"targets\":\"class Solution:\\n    def countSquares(self, matrix: List[List[int]]) -> int:\\n        for i in range(1, len(matrix)):\\n            for j in range(1, len(matrix[0])):\\n                matrix[i][j] *= min(matrix[i - 1][j], matrix[i][j - 1], matrix[i - 1][j - 1]) + 1\\n        return sum(map(sum, matrix))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nDZY loves chemistry, and he enjoys mixing chemicals.\\n\\nDZY has n chemicals, and m pairs of them will react. He wants to pour these chemicals into a test tube, and he needs to pour them in one by one, in any order. \\n\\nLet's consider the danger of a test tube. Danger of an empty test tube is 1. And every time when DZY pours a chemical, if there are already one or more chemicals in the test tube that can react with it, the danger of the test tube will be multiplied by 2. Otherwise the danger remains as it is.\\n\\nFind the maximum possible danger after pouring all the chemicals one by one in optimal order.\\n\\n\\n-----Input-----\\n\\nThe first line contains two space-separated integers n and m $(1 \\\\leq n \\\\leq 50 ; 0 \\\\leq m \\\\leq \\\\frac{n(n - 1)}{2})$.\\n\\nEach of the next m lines contains two space-separated integers x_{i} and y_{i} (1 ≤ x_{i} < y_{i} ≤ n). These integers mean that the chemical x_{i} will react with the chemical y_{i}. Each pair of chemicals will appear at most once in the input.\\n\\nConsider all the chemicals numbered from 1 to n in some order.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum possible danger.\\n\\n\\n-----Examples-----\\nInput\\n1 0\\n\\nOutput\\n1\\n\\nInput\\n2 1\\n1 2\\n\\nOutput\\n2\\n\\nInput\\n3 2\\n1 2\\n2 3\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, there's only one way to pour, and the danger won't increase.\\n\\nIn the second sample, no matter we pour the 1st chemical first, or pour the 2nd chemical first, the answer is always 2.\\n\\nIn the third sample, there are four ways to achieve the maximum possible danger: 2-1-3, 2-3-1, 1-2-3 and 3-2-1 (that is the numbers of the chemicals in order of pouring).\",\"targets\":\"n, m = map(int, input().split())\\np = list(range(n + 1))\\ns = [{i} for i in p]\\nfor i in range(m):\\n    x, y = map(int, input().split())\\n    x, y = p[x], p[y]\\n    if x != y:\\n        if len(s[x]) < len(s[y]):\\n            for k in s[x]:\\n                p[k] = y\\n                s[y].add(k)\\n            s[x].clear()\\n        else:\\n            for k in s[y]:\\n                p[k] = x\\n                s[x].add(k)\\n            s[y].clear()\\nq = 0\\nfor p in s:\\n    if p: q += len(p) - 1\\nprint(1 << q)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5ab6538b379d20ad880000ab:\\nYou are given the `length` and `width` of a 4-sided polygon. The polygon can either be a rectangle or a square. \\nIf it is a square, return its area. If it is a rectangle, return its perimeter.\\n\\n```\\narea_or_perimeter(6, 10) --> 32\\narea_or_perimeter(4, 4) --> 16\\n```\\n\\n> Note: for the purposes of this kata you will assume that it is a square if its `length` and `width` are equal, otherwise it is a rectangle.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def area_or_perimeter(l , w):\\n    return w**2 if w == l else 2*(l+w)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVasya likes taking part in Codeforces contests. When a round is over, Vasya follows all submissions in the system testing tab.\\n\\nThere are $n$ solutions, the $i$-th of them should be tested on $a_i$ tests, testing one solution on one test takes $1$ second. The solutions are judged in the order from $1$ to $n$. There are $k$ testing processes which test solutions simultaneously. Each of them can test at most one solution at a time.\\n\\nAt any time moment $t$ when some testing process is not judging any solution, it takes the first solution from the queue and tests it on each test in increasing order of the test ids. Let this solution have id $i$, then it is being tested on the first test from time moment $t$ till time moment $t + 1$, then on the second test till time moment $t + 2$ and so on. This solution is fully tested at time moment $t + a_i$, and after that the testing process immediately starts testing another solution.\\n\\nConsider some time moment, let there be exactly $m$ fully tested solutions by this moment. There is a caption \\\"System testing: $d$%\\\" on the page with solutions, where $d$ is calculated as\\n\\n$$d = round\\\\left(100\\\\cdot\\\\frac{m}{n}\\\\right),$$\\n\\nwhere $round(x) = \\\\lfloor{x + 0.5}\\\\rfloor$ is a function which maps every real to the nearest integer.\\n\\nVasya calls a submission interesting if there is a time moment (possibly, non-integer) when the solution is being tested on some test $q$, and the caption says \\\"System testing: $q$%\\\". Find the number of interesting solutions.\\n\\nPlease note that in case when multiple processes attempt to take the first submission from the queue at the same moment (for instance, at the initial moment), the order they take the solutions does not matter.\\n\\n\\n-----Input-----\\n\\nThe first line contains two positive integers $n$ and $k$ ($1 \\\\le n \\\\le 1000$, $1 \\\\le k \\\\le 100$) standing for the number of submissions and the number of testing processes respectively.\\n\\nThe second line contains $n$ positive integers $a_1, a_2, \\\\ldots, a_n$ ($1 \\\\le a_i \\\\le 150$), where $a_i$ is equal to the...\",\"targets\":\"import math\\n\\nn, k = map(int, input().split())\\na = list(map(int, input().split()))\\nnow = [-1] * k\\nt = [0] * k\\nnxt = 0\\nm = 0\\nintr = [False for i in range(n)]\\nwhile m < n:\\n    for i in range(k):\\n        if now[i] != 1005 and (now[i] == -1 or t[i] == a[now[i]]):\\n            if now[i] != -1:\\n                m += 1\\n            if nxt == n:\\n                now[i] == 1005\\n                t[i] = 1000\\n            else:\\n                now[i] = nxt\\n                nxt += 1\\n                t[i] = 0\\n        t[i] += 1\\n    d = (200 * m + n) \\/\\/ (2 * n)\\n    for i in range(k):\\n        if d == t[i]:\\n            intr[now[i]] = True\\nprint(sum(intr))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef is baking delicious cookies today! Since Chef is super hungry, he wants to eat at least $N$ cookies.\\nSince Chef is a messy eater, he drops a lot of crumbs. Crumbs of $B$ cookies can be put together to make a new cookie! \\nGiven $N$ and $B$, help Chef find out the minimum number of cookies he must initially bake, $A$, to satisfy his hunger.\\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase contains of  two space separated integers $N, B$. \\n\\n-----Output:-----\\nFor each test case, print a single integer $A$, the minimum number of cookies Chef must bake initially.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 1000$\\n- $1 \\\\leq N \\\\leq 1000000000$\\n- $2 \\\\leq B \\\\leq 1000000000$\\n\\n-----Sample Input 1:-----\\n1\\n3 2\\n\\n-----Sample Output 1:-----\\n2\\n\\n-----Sample Input 2:-----\\n1\\n11 2\\n\\n-----Sample Output 2:-----\\n6\\n\\n-----Explanation 2:-----\\nChef initially make 6 cookies. From the crumbs, Chef makes 3 new cookies with no crumbs left over. From the crumbs of the new cookies, Chef makes 1 new cookie and have crumbs left from one cookie. From the new cookie, Chef gets more crumbs. He adds the crumbs and gets one last cookie. After eating that, there are not enough crumbs left to make a new cookie. So a total of 11 cookies are consumed!\",\"targets\":\"# cook your dish here\\nfor _ in range(int(input())):\\n N,B = map(int,input().split())\\n ans = N-((N-1)\\/\\/B)\\n print(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/RICHSTR:\\nA string with length $L$ is called rich if $L \\\\ge 3$ and there is a character which occurs in this string strictly more than $L\\/2$ times.\\nYou are given a string $S$ and you should answer $Q$ queries on this string. In each query, you are given a substring $S_L, S_{L+1}, \\\\ldots, S_R$. Consider all substrings of this substring. You have to determine whether at least one of them is rich.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains two space-separated integers $N$ and $Q$.\\n- The second line contains a single string $S$ with length $N$.\\n- Each of the next $Q$ lines contains two space-separated integers $L$ and $R$ describing a query.\\n\\n-----Output-----\\nFor each query, print a single line containing the string \\\"YES\\\" if the given substring contains a rich substring or \\\"NO\\\" if it does not contain any rich substring.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 10$\\n- $1 \\\\le N, Q \\\\le 10^5$\\n- $1 \\\\le L \\\\le R \\\\le N$\\n- $S$ contains only lowercase English letters\\n\\n-----Example Input-----\\n1\\n10 2\\nhelloworld\\n1 3\\n1 10\\n\\n-----Example Output-----\\nNO\\nYES\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def isvalid(s):\\n if(s[0]==s[1] or s[1]==s[2] or s[0]==s[2]):\\n  return 1\\n return 0\\nt=int(input())\\nfor you in range(t):\\n l=input().split()\\n n=int(l[0])\\n q=int(l[1])\\n s=input()\\n count=[0 for i in range(n-2)]\\n fre=0\\n for i in range(n-2):\\n\\n  if(isvalid(s[i:i+3])):\\n   fre+=1\\n  count[i]=fre\\n\\n for i in range(q):\\n  l=input().split()\\n  L=int(l[0])\\n  R=int(l[1])\\n  if(R-L+1<3):\\n   print(\\\"NO\\\")\\n  else:\\n   if(L==1):\\n    if(count[R-3]>0):\\n     print(\\\"YES\\\")\\n    else:\\n     print(\\\"NO\\\")\\n   else:\\n    if(count[R-3]-count[L-2]>0):\\n     print(\\\"YES\\\")\\n    else:\\n     print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/563a631f7cbbc236cf0000c2:\\n## Terminal game move function\\n\\nIn this game, the hero moves from left to right. The player rolls the dice and moves the number of spaces indicated by the dice **two times**.\\n\\n~~~if-not:sql\\nCreate a function for the terminal game that takes the current position of the hero and the roll (1-6) and return the new position.\\n~~~\\n~~~if:sql\\nIn SQL, you will be given a table `moves` with columns `position` and `roll`. Return a table which uses the current position of the hero and the roll (1-6) and returns the new position in a column `res`.\\n~~~\\n\\n### Example:\\n```python\\nmove(3, 6) should equal 15\\n```\\n\\n```if:bf\\n### BF:\\n\\nSince this is an 8kyu kata, you are provided a modified runBF function, numericRunBF, that automatically parses input and output for your ease.\\n\\nSee the sample test cases to see what I mean: You can simply input two numbers and get a number as output (unless you're doing something wrong), so it should be convenient for you to modify the tests as you wish.\\n\\nOh, and you won't have to worry about overflow, the correct answer will never be higher than 255. :)\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"move = lambda a, b: a + 2 * b\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc136\\/tasks\\/abc136_a:\\nWe have two bottles for holding water.\\nBottle 1 can hold up to A milliliters of water, and now it contains B milliliters of water.\\nBottle 2 contains C milliliters of water.\\nWe will transfer water from Bottle 2 to Bottle 1 as much as possible.\\nHow much amount of water will remain in Bottle 2?\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq B \\\\leq A \\\\leq 20\\n - 1 \\\\leq C \\\\leq 20\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B C\\n\\n-----Output-----\\nPrint the integer representing the amount of water, in milliliters, that will remain in Bottle 2.\\n\\n-----Sample Input-----\\n6 4 3\\n\\n-----Sample Output-----\\n1\\n\\nWe will transfer two milliliters of water from Bottle 2 to Bottle 1, and one milliliter of water will remain in Bottle 2.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a,b,c = map(int, input().split())\\n\\nif c>= a-b:\\n    print(c-(a-b))\\nelse:\\n    print(0)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/parse-lisp-expression\\/:\\nYou are given a string expression representing a Lisp-like expression to return the integer value of.\\n\\nThe syntax for these expressions is given as follows.\\n\\nAn expression is either an integer, a let-expression, an add-expression, a mult-expression, or an assigned variable.  Expressions always evaluate to a single integer.\\n\\n(An integer could be positive or negative.)\\n\\nA let-expression takes the form (let v1 e1 v2 e2 ... vn en expr), where let is always the string \\\"let\\\", then there are 1 or more pairs of alternating variables and expressions, meaning that the first variable v1 is assigned the value of the expression e1, the second variable v2 is assigned the value of the expression e2, and so on sequentially; and then the value of this let-expression is the value of the expression expr.\\n\\nAn add-expression takes the form (add e1 e2) where add is always the string \\\"add\\\", there are always two expressions e1, e2, and this expression evaluates to the addition of the evaluation of e1 and the evaluation of e2.\\n\\nA mult-expression takes the form (mult e1 e2) where mult is always the string \\\"mult\\\", there are always two expressions e1, e2, and this expression evaluates to the multiplication of the evaluation of e1 and the evaluation of e2.\\n\\nFor the purposes of this question, we will use a smaller subset of variable names.  A variable starts with a lowercase letter, then zero or more lowercase letters or digits.  Additionally for your convenience, the names \\\"add\\\", \\\"let\\\", or \\\"mult\\\" are protected and will never be used as variable names.\\n\\nFinally, there is the concept of scope.  When an expression of a variable name is evaluated, within the context of that evaluation, the innermost scope (in terms of parentheses) is checked first for the value of that variable, and then outer scopes are checked sequentially.  It is guaranteed that every expression is legal.  Please see the examples for more details on scope.\\n\\n\\nEvaluation Examples:\\n\\nInput: (add 1 2)\\nOutput: 3\\n\\nInput: (mult 3 (add 2 3))\\nOutput: 15\\n\\nInput: (let x 2 (mult x...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution(object):\\n \\tdef parse(self,expression,d,i):\\n \\t\\tcount = 0\\n \\t\\tstart = i\\n \\t\\tif expression[i] == \\\"(\\\":\\n \\t\\t\\tcount += 1\\n \\t\\t\\ti += 1\\n \\t\\t\\twhile count != 0:\\n \\t\\t\\t\\tif expression[i] == \\\"(\\\":\\n \\t\\t\\t\\t\\tcount += 1\\n \\t\\t\\t\\telif expression[i] == \\\")\\\":\\n \\t\\t\\t\\t\\tcount -= 1\\n \\t\\t\\t\\ti += 1\\n \\t\\t\\tval = self.evaluate(expression[start:i],d)\\n \\t\\telse:\\n \\t\\t\\twhile i < len(expression) and expression[i] != \\\" \\\" and expression[i] != \\\")\\\":\\n \\t\\t\\t\\ti += 1\\n \\t\\t\\tval = expression[start:i]\\n \\t\\t\\tif self.isnumber(val):\\n \\t\\t\\t\\tval = int(val)\\n \\t\\treturn i,val\\n \\tdef get_left_right(self,expression,d):\\n \\t\\ti = 0\\n \\t\\tcount = 0\\n \\t\\ti,left = self.parse(expression,d,0)\\n \\t\\tif i == len(expression) or expression[i] == \\\")\\\":\\n \\t\\t\\treturn left,None,i\\n \\t\\ti += 1\\n \\t\\ti,right = self.parse(expression,d,i)\\n \\t\\treturn left,right,i\\n \\tdef isnumber(self,s):\\n \\t\\tfor c in s:\\n \\t\\t\\tif ord(\\\"0\\\") <= ord(c) <= ord(\\\"9\\\") or c == \\\"+\\\" or c == \\\"-\\\":\\n \\t\\t\\t\\tcontinue\\n \\t\\t\\telse:\\n \\t\\t\\t\\treturn False\\n \\t\\treturn True\\n \\tdef evaluate(self, expression,d = {}):\\n \\t\\t\\\"\\\"\\\"\\n \\t\\t:type expression: str\\n \\t\\t:rtype: int\\n \\t\\t\\\"\\\"\\\"\\n \\t\\tif self.isnumber(expression):\\n \\t\\t\\treturn int(expression)\\n \\t\\tnewd = {}\\n \\t\\tfor key in d:\\n \\t\\t\\tnewd[key] = d[key]\\n \\t\\texpression = expression[1:len(expression)-1]\\n \\t\\toper = \\\"\\\"\\n \\t\\tif expression[0:3] == \\\"add\\\" or expression[:3] == \\\"let\\\":\\n \\t\\t\\toper = expression[0:3]\\n \\t\\t\\texpression = expression[4:]\\n \\t\\telse:\\n \\t\\t\\toper = \\\"mult\\\"\\n \\t\\t\\texpression = expression[5:]\\n \\t\\t\\n \\t\\tif oper == \\\"mult\\\" or oper == \\\"add\\\":\\n \\t\\t\\tleft,right,_ = self.get_left_right(expression,newd)\\n \\t\\t\\tif isinstance(left,str):\\n \\t\\t\\t\\tleft = newd[left]\\n \\t\\t\\tif isinstance(right,str):\\n \\t\\t\\t\\tright = newd[right]\\n \\t\\t\\tif oper == \\\"mult\\\":\\n \\t\\t\\t\\treturn left*right\\n \\t\\t\\telse:\\n \\t\\t\\t\\treturn left + right\\n \\t\\ti = 0\\n \\t\\twhile True:\\n \\t\\t\\tleft,right,i = self.get_left_right(expression,newd)\\n \\t\\t\\texpression = expression[i+1:]\\n \\t\\t\\tif right == None:\\n \\t\\t\\t\\tif isinstance(left,str):\\n \\t\\t\\t\\t\\treturn newd[left]\\n \\t\\t\\t\\treturn left\\n \\t\\t\\tif isinstance(right,str):\\n \\t\\t\\t\\tright = newd[right]\\n \\t\\t\\tnewd[left] = right\\n \\t\\t\\t\\n \\t\\t\\t\\n \\t\\t\\t\\n # s = Solution()\\n # print(s.evaluate(\\\"(let x 2 (mult x (let x 3 y 4 (add x y))))\\\"))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLittle chef has just been introduced to the world of numbers! While experimenting with addition and multiplication operations, the little chef came up with the following problem:\\n\\nGiven an array A of non-negative integers, how many pairs of indices i and j exist such that  A[i]*A[j] > A[i]+A[j]  where  i < j .\\n\\nNow being a learner, little chef isn't able to solve this problem efficiently and hence turns to you for help. \\n\\n-----Input-----\\nFirst line of input contains an integer T denoting the number of test cases. For each test case, the first line contains an integer N denoting the number of integers in the array. The next line contains N space separated integers where the ith integer represents A[i]. \\nNote : There may be trailing spaces on each line of input. \\n\\n-----Output-----\\nFor each test, print the required number of pairs in a single line.\\n\\n-----Constraints-----\\n-  1 ≤ T ≤ 10 \\n-  2 ≤ N ≤ 100000 (105) \\n-  0 ≤ A[i] ≤ 1000000 (106)\\n\\n-----Example-----\\nInput:\\n2\\n3\\n3 4 5\\n4\\n1 1 1 1\\n\\nOutput:\\n3\\n0\\n\\n-----Explanation-----\\n\\nExample case 1.\\n\\nAll pairs of numbers satisfy the criteria. Total number of pairs equals 3.\\n\\nExample case 2.\\n\\nNo pair of numbers satisfy the criteria.\",\"targets\":\"from collections import defaultdict\\nfor _ in range(int(input())):\\n n = int(input())\\n ls = [int(x) for x in input().split()]\\n n-=(ls.count(1)+ls.count(0))\\n twos = ls.count(2)\\n rest = twos*(n-twos) + ((n-twos)*(n-twos-1) )\\/\\/ 2\\n print(rest)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAndy got a box of candies for Christmas. In fact, he discovered that the box contained several identical smaller boxes, and they could contain even smaller boxes, and so on. Formally, we say that candies are boxes of level 0, and for 1 ≤ i ≤ n, a level i box contains ai boxes of level i - 1. The largest box has level n. Andy realized that it can take quite a long time to open all the boxes before he actually gets to eat some candies, so he put the box aside in frustration.\\n\\nBut today being his birthday, some friends came to visit Andy, and Andy decided to share some candies with them. In order to do that, he must open some of the boxes. Naturally, Andy can not open a box that is still inside an unopened box. If Andy wants to retrieve X candies, what is the least number of boxes he must open? You must help him answer many such queries. Each query is independent.\\n\\n-----Input-----\\n- The first line contains two integers n and m, which refer to the level of the largest box, and the number of queries respectively.\\n- The second line contains n integers a1, ..., an.\\n- The third line contains m integers X1, ..., Xm.\\n\\n-----Output-----\\n- Print m integers each in a new line, ith of them equal to the smallest number of boxes Andy must open in order to retrieve at least Xi candies.\\n\\n-----Constraints-----\\n- 1 ≤ n,m ≤ 300000\\n- 1 ≤ ai ≤ 109\\n- 1 ≤ Xi ≤ 1012\\n- It is guaranteed that the total number of candies is at least Xi for all i\\n\\n-----Example-----\\nInput 1:\\n5 1\\n1 1 1 1 1\\n1\\n\\nOutput 1:\\n5\\n\\nInput 2:\\n3 3\\n3 3 3\\n2 8 13\\n\\nOutput 2:\\n3\\n5\\n8\\n\\n-----Explanation-----\\nTestcase 1: The only candy is contained in five levels of boxes. \\nTestcase 2: In the third query, for 13 candies, Andy should open the largest box, two level-2 boxes, and finally five of six available level-1 boxes. Each of those boxes will contain 3 level-0 boxes (which are candies). So he'll have 15 candies in total, but he needs only 13 of them.\",\"targets\":\"n,m = map(int,input().split())\\nbox = list(map(int,input().split()))\\nmularr = []\\nqueries = list(map(int,input().split()))\\nqm = max(queries)\\ncnt = 0\\nmularr.append([box[0],1])\\ncandy = box[0]\\nfor b in box[1:]:\\n    if b == 1:\\n     mularr[-1][1] +=1\\n    else:\\n     candy *= b\\n     mularr.append([candy,1])\\n    if qm <= candy:\\n     break\\n#print(mularr)\\nfor query in queries:\\n    cnt = n\\n    test = query\\n    test-=1\\n    for k,v in mularr:\\n     #print(mularr[m],test)\\n     add = (test\\/\\/k)*v\\n     cnt+=add\\n    print(cnt)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nS and T are strings composed of lowercase letters. In S, no letter occurs more than once.\\n\\nS was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occurs before y in S, then x should occur before y in the returned string.\\n\\nReturn any permutation of T (as a string) that satisfies this property.\\n\\n\\nExample :\\nInput: \\nS = \\\"cba\\\"\\nT = \\\"abcd\\\"\\nOutput: \\\"cbad\\\"\\nExplanation: \\n\\\"a\\\", \\\"b\\\", \\\"c\\\" appear in S, so the order of \\\"a\\\", \\\"b\\\", \\\"c\\\" should be \\\"c\\\", \\\"b\\\", and \\\"a\\\". \\nSince \\\"d\\\" does not appear in S, it can be at any position in T. \\\"dcba\\\", \\\"cdba\\\", \\\"cbda\\\" are also valid outputs.\\n\\n\\n \\n\\nNote:\\n\\n\\n       S has length at most 26, and no character is repeated in S.\\n       T has length at most 200.\\n       S and T consist of lowercase letters only.\",\"targets\":\"# Definition for a binary tree node.\\n # class TreeNode:\\n #     def __init__(self, x):\\n #         self.val = x\\n #         self.left = None\\n #         self.right = None\\n \\n class Solution:\\n     def splitBST(self, root, V):\\n         \\\"\\\"\\\"\\n         :type root: TreeNode\\n         :type V: int\\n         :rtype: List[TreeNode]\\n         \\\"\\\"\\\"\\n         if not root:\\n             return [None, None]\\n         if root.val == V:\\n             a = root.right\\n             root.right = None\\n             return [root, a]\\n         elif root.val<V:\\n             small, large = self.splitBST(root.right, V)\\n             root.right = small\\n             return [root, large]\\n         else:\\n             small, large = self.splitBST(root.left, V)\\n             root.left = large\\n             return [root, small]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWell met with Fibonacci bigger brother, AKA Tribonacci.\\n\\nAs the name may already reveal, it works basically like a Fibonacci, but summing the last 3 (instead of 2) numbers of the sequence to generate the next. And, worse part of it, regrettably I won't get to hear non-native Italian speakers trying to pronounce it :(\\n\\nSo, if we are to start our Tribonacci sequence with `[1, 1, 1]` as a starting input (AKA *signature*), we have this sequence:\\n\\n```\\n[1, 1 ,1, 3, 5, 9, 17, 31, ...]\\n```\\n\\nBut what if we started with `[0, 0, 1]` as a signature? As starting with `[0, 1]` instead of `[1, 1]` basically *shifts* the common Fibonacci sequence by once place, you may be tempted to think that we would get the same sequence shifted by 2 places, but that is not the case and we would get:\\n\\n```\\n[0, 0, 1, 1, 2, 4, 7, 13, 24, ...]\\n```\\n\\nWell, you may have guessed it by now, but to be clear: you need to create a fibonacci function that given a **signature** array\\/list, returns **the first n elements - signature included** of the so seeded sequence.\\n\\nSignature will always contain 3 numbers; n will always be a non-negative number; if `n == 0`, then return an empty array (except in C return NULL) and be ready for anything else which is not clearly specified ;)\\n\\nIf you enjoyed this kata more advanced and generalized version of it can be found in the Xbonacci kata\\n\\n*[Personal thanks to Professor Jim Fowler on Coursera for his awesome classes that I really recommend to any math enthusiast and for showing me this mathematical curiosity too with his usual contagious passion :)]*\",\"targets\":\"def tribonacci(signature, n):\\n    s = signature.copy()\\n    while len(s) < n:\\n        s.append(sum(s[-3:]))\\n    return s[:n]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/SIC2016\\/problems\\/NEAR:\\nThere are n cabs in a city numbered from 1 to n. The city has a rule that only one cab can run in the city at a time. Cab picks up the customer and drops him to his destination. Then the cab gets ready to pick next customer. There are m customers in search of cab. First customer will get the taxi first. You have to find the nearest cab for each customer. If two cabs have same distance then the cab with lower number is preferred.\\n\\nYour task is to find out minimum distant cab for each customer.\\n\\nInput:\\n\\nThe first line of the input contains an integer T denoting the number of test cases.\\nThe description of T test cases follows.\\nThe first line of each test case contains two space-separated integers N and M, denoting the number of cabs and the number of customers.\\n\\nThe next N lines contain two space-separated integers x[i] and y[i], denoting the initial position of the ith cab.\\n\\nNext line contains an integer M denoting number of customers.\\nThe next M lines contain four space seperated integers sx[i], sy[i], dx[i], dy[i], denoting the current location and the destination of the ith customer.\\n\\nOutput:\\n\\nOutput the nearest cab number for each customer.\\n\\nConstraints:\\n\\n1<=t<=10\\n\\n1<=n,m<=1000\\n\\n-10^9<=x[i] , y[i] , sx[i] , sy[i] , dx[i] , dy[i]<=10^9\\n\\nExample:\\nInput:\\n\\n1\\n\\n3 2\\n\\n1 3\\n\\n3 2\\n\\n3 5\\n\\n2 3 3 4\\n\\n5 3 4 1\\n\\nOutput:\\n\\n1\\n\\n1\\n\\nExplanation:\\n\\nThe distance of cab1 from customer1 = sqrt((1-2)^2 + (3-3)^2) = 1\\n\\nThe distance of cab2 from customer1 = sqrt(2)\\n\\nThe distance of cab3 from customer1 = sqrt(5)\\n\\nSo output for customer1 is 1\\n\\nNow location of cab1 is (3,4)\\n\\nThe distance of cab1 from customer2 = sqrt((3-5)^2 + (4-3)^2) = sqrt(5)\\n\\nThe distance of cab2 from customer2 = sqrt(5)\\n\\nThe distance of cab3 from customer2 = sqrt(8)\\n\\nSo output for customer2 is 1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\ndef dist(w,x,y,z):\\n return math.hypot(y - w, z - x)\\n\\nt = int(input())\\nwhile (t>0):\\n t = t -1\\n n, m = list(map(int,input().split()))\\n a = []\\n for i in range(0,n):\\n  x,y = list(map(int,input().split()))\\n  a.append([x,y])\\n for j in range(0,m):\\n  p,q,r,s = list(map(int,input().split()))\\n  nearest = -1\\n  distance = 10000000000\\n  for i in range(0,n):\\n   way = dist(a[i][0],a[i][1],p,q)\\n   if way < distance:\\n    distance = way\\n    nearest = i\\n  print(nearest + 1)\\n  a[nearest][0] = r\\n  a[nearest][1] = s\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/CSEP2020\\/problems\\/JOJOA:\\nDio Brando has set  a goal for himself of becoming the richest and the most powerful being on earth.To achieve his goals he will do anything using either manipulation,seduction or plain violence.\\nOnly one guy stands between his goal of conquering earth ,named Jotaro Kujo aka JoJo .Now Dio has a stand (visual manifestation of life energy  i.e, special power )  “Za Warudo” ,which can stop time itself but needs to chant few words to activate the time stopping ability of the stand.There is a code hidden inside the words and if you can decipher the code then Dio loses his power.\\nIn order to stop Dio ,Jotaro asks your help to decipher the code since he can’t do so while fighting Dio at the same time.\\nYou will be given a string as input and you have to find the shortest substring which contains all the characters of itself and then make a number based on the alphabetical ordering of the characters.\\nFor example : “bbbacdaddb”\\nshortest substring will be “bacd” and based on the alphabetical ordering\\nthe answer is 2134\\n\\n-----NOTE:-----\\nA substring is a contiguous subsegment of a string. For example, \\\"acab\\\" is a substring of \\\"abacaba\\\" (it starts in position 3 and ends in position 6), but \\\"aa\\\" or \\\"d\\\" aren't substrings of this string. So the substring of the string s from position l to position r is\\n\\nS[l;r]=SlSl+1…Sr.\\n\\n-----Input :-----\\nThe first line contains $T$,number of test cases.\\nThe second line contains a string $S$.\\n\\n-----Output:-----\\nFor each test cases ,output the number you can get from the shortest string \\n\\n-----Constraints:-----\\n$1 \\\\leq t \\\\leq 100$\\n$1 \\\\leq |S| \\\\leq 10^6$\\n\\n-----Test Cases:-----\\n\\n-----Sample Input:-----\\n6\\n\\nabcdfgh\\n\\nurdrdrav\\n\\njojojojoj\\n\\nbbbbaaa\\n\\ncddfsccs\\n\\ntttttttttttt   \\n\\n-----Sample Output:-----\\n1234678\\n\\n2118418418122\\n\\n1015\\n\\n21\\n\\n46193\\n\\n20\\n\\n-----Explanation:-----\\nTest case 1: abcdfgh is the shortest substring containing all char of itself and the number is 1234678\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nimport sys\\nimport math\\nfrom collections import Counter\\nfrom collections import OrderedDict \\ndef inputt():\\n    return sys.stdin.readline().strip()\\ndef printt(n):\\n    sys.stdout.write(str(n)+'\\\\n')\\ndef listt():\\n    return [int(i) for i in inputt().split()]\\ndef gcd(a,b): \\n   return math.gcd(a,b) \\n \\ndef lcm(a,b): \\n    return (a*b) \\/ gcd(a,b) \\nfrom collections import defaultdict   \\n\\ndef find_sub_string(str): \\n    str_len = len(str) \\n      \\n    # Count all distinct characters. \\n    dist_count_char = len(set([x for x in str])) \\n  \\n    ctr, start_pos, start_pos_index, min_len = 0, 0, -1, 9999999999\\n    curr_count = defaultdict(lambda: 0) \\n    for i in range(str_len): \\n        curr_count[str[i]] += 1\\n \\n        if curr_count[str[i]] == 1: \\n            ctr += 1\\n  \\n        if ctr == dist_count_char: \\n            while curr_count[str[start_pos]] > 1: \\n                if curr_count[str[start_pos]] > 1: \\n                    curr_count[str[start_pos]] -= 1\\n                start_pos += 1\\n  \\n            len_window = i - start_pos + 1\\n            if min_len > len_window: \\n                min_len = len_window \\n                start_pos_index = start_pos \\n    return str[start_pos_index: start_pos_index + min_len]\\nt= int(inputt())\\nfor _ in range(t):\\n    j=[]\\n    str1 =inputt()\\n    s=find_sub_string(str1) \\n    for i in s:\\n        j.append(abs(97-ord(i))+1)\\n    st = [str(i) for i in j]\\n    print(''.join(st))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/59951f21d65a27e95d00004f:\\n# Problem Description\\n\\nLet's imagine a function `F(n)`, which is defined over the integers\\nin the range of `1 <= n <= max_n`, and `0 <= F(n) <= max_fn` for every `n`.\\n\\nThere are `(1 + max_fn) ** max_n` possible definitions of `F` in total.\\n\\nOut of those definitions, how many `F`s satisfy the following equations?\\nSince your answer will be very large, please give your answer **modulo 12345787**.\\n\\n* `F(n) + F(n + 1) <= max_fn` for `1 <= n < max_n`\\n* `F(max_n) + F(1) <= max_fn`\\n\\n# Constraints\\n\\n`1 <= max_n <= 100`\\n\\n`1 <= max_fn <= 5`\\n\\nThe inputs will be always valid integers.\\n\\n# Examples\\n\\n```python\\n# F(1) + F(1) <= 1, F(1) = 0\\ncircular_limited_sums(1, 1) == 1\\n\\n# F = (0, 0), (0, 1), (1, 0)\\ncircular_limited_sums(2, 1) == 3\\n\\n# F = (0, 0, 0), (0, 0, 1), (0, 1, 0), (1, 0, 0)\\ncircular_limited_sums(3, 1) == 4\\n\\n# F = (0, 0, 0, 0), (0, 0, 0, 1), (0, 0, 1, 0), (0, 1, 0, 0),\\n# (0, 1, 0, 1), (1, 0, 0, 0), (1, 0, 1, 0)\\ncircular_limited_sums(4, 1) == 7\\n\\n# F = (0), (1)\\ncircular_limited_sums(1, 2) == 2\\n# F = (0, 0), (0, 1), (0, 2), (1, 0), (1, 1), (2, 0)\\ncircular_limited_sums(2, 2) == 6\\n# F = (0, 0, 0), (0, 0, 1), (0, 0, 2), (0, 1, 0), (0, 1, 1),\\n# (0, 2, 0), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1), (2, 0, 0)\\ncircular_limited_sums(3, 2) == 11\\ncircular_limited_sums(4, 2) == 26\\n```\\n\\n# Acknowledgement\\n\\nThis problem was designed as a hybrid of [Project Euler #209: Circular Logic](https:\\/\\/projecteuler.net\\/problem=209) and [Project Euler #164: Numbers for which no three consecutive digits have a sum greater than a given value](https:\\/\\/projecteuler.net\\/problem=164).\\n\\nIf you enjoyed this Kata, please also have a look at [my other Katas](https:\\/\\/www.codewars.com\\/users\\/Bubbler\\/authored)!\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"mod = 12345787\\nmat = [([1,1],[0,1,3]),\\n       ([2,1,-1],[0,2,6,11]),\\n       ([2,3,-1,-1],[0,2,10,23,70]),\\n       ([3,3,-4,-1,1],[0,3,15,42,155,533]),\\n       ([3,6,-4,-5,1,1],[0,3,21,69,301,1223,5103])]\\n\\nfor i in range(100): [m.append(sum(k*m[-1-i] for i,k in enumerate(c))%mod) for c,m in mat]\\n\\ndef circular_limited_sums(max_n, max_fn): return mat[max_fn-1][1][max_n]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe guessed a permutation $p$ consisting of $n$ integers. The permutation of length $n$ is the array of length $n$ where each element from $1$ to $n$ appears exactly once. This permutation is a secret for you.\\n\\nFor each position $r$ from $2$ to $n$ we chose some other index $l$ ($l < r$) and gave you the segment $p_l, p_{l + 1}, \\\\dots, p_r$ in sorted order (i.e. we rearranged the elements of this segment in a way that the elements of this segment are sorted). Thus, you are given exactly $n-1$ segments of the initial permutation but elements inside each segment are sorted. The segments are given to you in random order.\\n\\nFor example, if the secret permutation is $p=[3, 1, 4, 6, 2, 5]$ then the possible given set of segments can be:  $[2, 5, 6]$  $[4, 6]$  $[1, 3, 4]$  $[1, 3]$  $[1, 2, 4, 6]$ \\n\\nYour task is to find any suitable permutation (i.e. any permutation corresponding to the given input data). It is guaranteed that the input data corresponds to some permutation (i.e. such permutation exists).\\n\\nYou have to answer $t$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 100$) — the number of test cases. Then $t$ test cases follow.\\n\\nThe first line of the test case contains one integer $n$ ($2 \\\\le n \\\\le 200$) — the length of the permutation.\\n\\nThe next $n-1$ lines describe given segments.\\n\\nThe $i$-th line contains the description of the $i$-th segment. The line starts with the integer $k_i$ ($2 \\\\le k_i \\\\le n$) — the length of the $i$-th segment. Then $k_i$ integers follow. All integers in a line are distinct, sorted in ascending order, between $1$ and $n$, inclusive.\\n\\nIt is guaranteed that the required $p$ exists for each test case.\\n\\nIt is also guaranteed that the sum of $n$ over all test cases does not exceed $200$ ($\\\\sum n \\\\le 200$).\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer: $n$ integers $p_1, p_2, \\\\dots, p_n$ ($1 \\\\le p_i \\\\le n$, all $p_i$ should be distinct) — any suitable permutation (i.e. any permutation corresponding to the test...\",\"targets\":\"from collections import Counter\\nfrom itertools import chain\\n\\n\\ndef dfs(n, r, hint_sets, count, removed, result):\\n    # print(n, r, hint_sets, count, removed, result)\\n    if len(result) == n - 1:\\n        last = (set(range(1, n + 1)) - set(result)).pop()\\n        result.append(last)\\n        return True\\n\\n    i, including_r = 0, None\\n    for i, including_r in enumerate(hint_sets):\\n        if i in removed:\\n            continue\\n        if r in including_r:\\n            break\\n    removed.add(i)\\n\\n    next_r = []\\n    for q in including_r:\\n        count[q] -= 1\\n        if count[q] == 1:\\n            next_r.append(q)\\n    if not next_r:\\n        return False\\n\\n    # print(r, next_r, result)\\n\\n    if len(next_r) == 2:\\n        nr = -1\\n        can1, can2 = next_r\\n        for h in hint_sets:\\n            if can1 in h and can2 not in h and not h.isdisjoint(result):\\n                nr = can1\\n                break\\n            if can1 not in h and can2 in h and not h.isdisjoint(result):\\n                nr = can2\\n                break\\n        if nr == -1:\\n            nr = can1\\n    else:\\n        nr = next_r[0]\\n\\n    result.append(nr)\\n    res = dfs(n, nr, hint_sets, count, removed, result)\\n    if res:\\n        return True\\n    result.pop()\\n\\n    for q in including_r:\\n        count[q] += 1\\n\\n    return False\\n\\n\\nt = int(input())\\nbuf = []\\nfor l in range(t):\\n    n = int(input())\\n    hints = []\\n    for _ in range(n - 1):\\n        k, *ppp = list(map(int, input().split()))\\n        hints.append(ppp)\\n\\n    count = Counter(chain.from_iterable(hints))\\n    most_common = count.most_common()\\n\\n    hint_sets = list(map(set, hints))\\n\\n    r = most_common[-1][0]\\n    result = [r]\\n    if dfs(n, r, hint_sets, dict(count), set(), result):\\n        buf.append(' '.join(map(str, result[::-1])))\\n        continue\\n    r = most_common[-2][0]\\n    result = [r]\\n    assert dfs(n, r, hint_sets, dict(count), set(), result)\\n    buf.append(' '.join(map(str, result[::-1])))\\n\\nprint('\\\\n'.join(map(str, buf)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/701\\/A:\\nThere are n cards (n is even) in the deck. Each card has a positive integer written on it. n \\/ 2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player. \\n\\nFind the way to distribute cards such that the sum of values written of the cards will be equal for each player. It is guaranteed that it is always possible.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains integer n (2 ≤ n ≤ 100) — the number of cards in the deck. It is guaranteed that n is even.\\n\\nThe second line contains the sequence of n positive integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 100), where a_{i} is equal to the number written on the i-th card.\\n\\n\\n-----Output-----\\n\\nPrint n \\/ 2 pairs of integers, the i-th pair denote the cards that should be given to the i-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.\\n\\nIt is guaranteed that solution exists. If there are several correct answers, you are allowed to print any of them.\\n\\n\\n-----Examples-----\\nInput\\n6\\n1 5 7 4 4 3\\n\\nOutput\\n1 3\\n6 2\\n4 5\\n\\nInput\\n4\\n10 10 10 10\\n\\nOutput\\n1 2\\n3 4\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8. \\n\\nIn the second sample, all values a_{i} are equal. Thus, any distribution is acceptable.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\ns = [int(i) for i in input().split()]\\nt = []\\nfor i in range(n):\\n\\tt.append((s[i], i+1))\\nr = (sum(s)\\/\\/(n\\/\\/2))\\nt.sort()\\nfor i in range(n\\/\\/2):\\n\\tprint(t[i][1], t[n-i-1][1])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1117\\/B:\\nThere are $n$ emotes in very popular digital collectible card game (the game is pretty famous so we won't say its name). The $i$-th emote increases the opponent's happiness by $a_i$ units (we all know that emotes in this game are used to make opponents happy).\\n\\nYou have time to use some emotes only $m$ times. You are allowed to use any emotion once, more than once, or not use it at all. The only restriction is that you cannot use the same emote more than $k$ times in a row (otherwise the opponent will think that you're trolling him).\\n\\nNote that two emotes $i$ and $j$ ($i \\\\ne j$) such that $a_i = a_j$ are considered different.\\n\\nYou have to make your opponent as happy as possible. Find the maximum possible opponent's happiness.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers $n, m$ and $k$ ($2 \\\\le n \\\\le 2 \\\\cdot 10^5$, $1 \\\\le k \\\\le m \\\\le 2 \\\\cdot 10^9$) — the number of emotes, the number of times you can use emotes and the maximum number of times you may use the same emote in a row.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 10^9$), where $a_i$ is value of the happiness of the $i$-th emote.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the maximum opponent's happiness if you use emotes in a way satisfying the problem statement.\\n\\n\\n-----Examples-----\\nInput\\n6 9 2\\n1 3 3 7 4 2\\n\\nOutput\\n54\\n\\nInput\\n3 1000000000 1\\n1000000000 987654321 1000000000\\n\\nOutput\\n1000000000000000000\\n\\n\\n\\n-----Note-----\\n\\nIn the first example you may use emotes in the following sequence: $4, 4, 5, 4, 4, 5, 4, 4, 5$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,m,k=list(map(int,input().split()))\\nA=list(map(int,input().split()))\\nA.sort(reverse=True)\\n\\nM1=A[0]\\nM2=A[1]\\n\\nprint(M2*(m\\/\\/(k+1))+M1*(m-(m\\/\\/(k+1))))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc093\\/tasks\\/abc093_a:\\nYou are given a string S of length 3 consisting of a, b and c. Determine if S can be obtained by permuting abc.\\n\\n-----Constraints-----\\n - |S|=3\\n - S consists of a, b and c.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nS\\n\\n-----Output-----\\nIf S can be obtained by permuting abc, print Yes; otherwise, print No.\\n\\n-----Sample Input-----\\nbac\\n\\n-----Sample Output-----\\nYes\\n\\nSwapping the first and second characters in bac results in abc.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"S = list(input())\\nS.sort()\\n\\nif S == ['a', 'b', 'c']:\\n    print('Yes')\\nelse:\\n    print('No')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/py-set-difference-operation\\/problem:\\n=====Function Descriptions=====\\n.difference()\\n\\nThe tool .difference() returns a set with all the elements from the set that are not in an iterable.\\nSometimes the - operator is used in place of the .difference() tool, but it only operates on the set of elements in set.\\nSet is immutable to the .difference() operation (or the - operation).\\n\\n>>> s = set(\\\"Hacker\\\")\\n>>> print s.difference(\\\"Rank\\\")\\nset(['c', 'r', 'e', 'H'])\\n\\n>>> print s.difference(set(['R', 'a', 'n', 'k']))\\nset(['c', 'r', 'e', 'H'])\\n\\n>>> print s.difference(['R', 'a', 'n', 'k'])\\nset(['c', 'r', 'e', 'H'])\\n\\n>>> print s.difference(enumerate(['R', 'a', 'n', 'k']))\\nset(['a', 'c', 'r', 'e', 'H', 'k'])\\n\\n>>> print s.difference({\\\"Rank\\\":1})\\nset(['a', 'c', 'e', 'H', 'k', 'r'])\\n\\n>>> s - set(\\\"Rank\\\")\\nset(['H', 'c', 'r', 'e'])\\n\\n=====Problem Statement=====\\nStudents of District College have a subscription to English and French newspapers. Some students have subscribed to only the English newspaper, some have subscribed to only the French newspaper, and some have subscribed to both newspapers.\\n\\nYou are given two sets of student roll numbers. One set has subscribed to the English newspaper, and one set has subscribed to the French newspaper. Your task is to find the total number of students who have subscribed to only English newspapers.\\n\\n=====Input Format=====\\nThe first line contains the number of students who have subscribed to the English newspaper.\\nThe second line contains the space separated list of student roll numbers who have subscribed to the English newspaper.\\nThe third line contains the number of students who have subscribed to the French newspaper.\\nThe fourth line contains the space separated list of student roll numbers who have subscribed to the French newspaper.\\n\\n=====Constraints=====\\n0<Total number of students in college<1000\\n\\n=====Output Format=====\\nOutput the total number of students who are subscribed to the English newspaper only.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"e = int(input())\\neng = set(map(int,input().split())) \\nf = int(input())\\nfre = set(map(int,input().split()))\\nprint((len(eng - fre)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou're given an ancient book that unfortunately has a few pages in the wrong position, fortunately your computer has a list of every page number in order from ``1`` to ``n``.\\n\\nYou're supplied with an array of numbers, and should return an array with each page number that is out of place. Incorrect page numbers will not appear next to each other. Duplicate incorrect page numbers are possible.\\n\\nExample:\\n\\n```Given: list = [1,2,10,3,4,5,8,6,7]\\n```\\n\\n``Return: [10,8]\\n``\\n\\nYour returning list should have the incorrect page numbers in the order they were found.\",\"targets\":\"def find_page_number(pages):\\n    p=pages[:]\\n    x=1\\n    r=[]\\n    while(p):\\n        if p[0]!=x:\\n            r.append(p.pop(0))\\n        else:\\n            x+=1\\n            p.pop(0)\\n    return r\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55af0d33f9b829d0a800008d:\\n## Decode the diagonal. \\n\\nGiven a grid of characters. Output a decoded message as a string.\\n\\nInput\\n\\n```\\n  H Z R R Q\\n  D I F C A E A !\\n  G H T E L A E \\n  L M N H P R F \\n  X Z R P E\\n```\\n  \\nOutput\\n\\n`HITHERE!` (diagonally down right `↘` and diagonally up right `↗` if you can't go further).\\n\\nThe message ends when there is no space at the right up or down diagonal.\\n\\nTo make things even clearer: the same example, but in a simplified view\\n\\n```\\n  H _ _ _ _\\n  _ I _ _ _ _ _ !\\n  _ _ T _ _ _ E \\n  _ _ _ H _ R _\\n  _ _ _ _ E\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def get_diagonale_code(grid: str) -> str:\\n    flag=True\\n    temp=grid.split(\\\"\\\\n\\\")\\n    for i,j in enumerate(temp):\\n        temp[i]=j.split()\\n    res=\\\"\\\"\\n    x=0\\n    y=0\\n    while True:\\n        try:\\n            res+=temp[y][x]\\n            if y==len(temp)-1:\\n                flag=False\\n            elif y==0 and not flag:\\n                flag=True\\n            y+=1 if flag else -1\\n            x+=1\\n        except:\\n            return res\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven is a number sequence A of length N.\\nFind the number of integers i \\\\left(1 \\\\leq i \\\\leq N\\\\right) with the following property:\\n - For every integer j \\\\left(1 \\\\leq j \\\\leq N\\\\right) such that i \\\\neq j , A_j does not divide A_i.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq N \\\\leq 2 \\\\times 10^5\\n - 1 \\\\leq A_i \\\\leq 10^6\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 A_2 \\\\cdots A_N\\n\\n-----Output-----\\nPrint the answer.\\n\\n-----Sample Input-----\\n5\\n24 11 8 3 16\\n\\n-----Sample Output-----\\n3\\n\\nThe integers with the property are 2, 3, and 4.\",\"targets\":\"n=int(input())\\na=list(map(int,input().split()))\\nans=0\\na.sort()\\nnum=a[-1]\\ndp=[True]*num\\nseen=[0]*num\\nfor i in range(n):\\n    num2=a[i]\\n    if dp[num2-1]==True:\\n        if seen[num2-1]==1:\\n            dp[num2-1]=False\\n        for j in range(2,num\\/\\/num2+1):\\n            dp[j*num2-1]=False\\n    seen[a[i]-1]=1\\nans=0\\nfor i in range(n):\\n    if dp[a[i]-1]==True:\\n        ans+=1\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/555b1890a75b930e63000023:\\nJon and Joe have received equal marks in the school examination. But, they won't reconcile in peace when equated with each other. To prove his might, Jon challenges Joe to write a program to find all possible number combos that sum to a given number. While unsure whether he would be able to accomplish this feat or not, Joe accpets the challenge. Being Joe's friend, your task is to help him out.\\n\\n# Task\\n\\nCreate a function `combos`, that accepts a single positive integer `num` (30 > `num` > 0) and returns an array of arrays of positive integers that sum to `num`.\\n\\n# Notes\\n1. Sub-arrays may or may not have their elements sorted.\\n2. The order of sub-arrays inside the main array does not matter.\\n3. For an optimal solution, the following operation should complete within 6000ms.\\n\\n# Sample\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import itertools\\nd = {1:[[1]]}\\ndef combos(n):\\n    if n not in d:\\n        d[n] = list(i for i,_ in itertools.groupby(sorted([[n]] + [sorted(j+[i]) for i in range(1, n) for j in combos(n-i)])))\\n    return d[n]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/MINPERM:\\nA permutation of length n is an array of size n consisting of n distinct integers in the range [1, n]. For example, (3, 2, 4, 1) is a permutation of length 4, but (3, 3, 1, 4) and (2, 3, 4, 5) are not, as (3, 3, 1, 4) contains duplicate elements, and (2, 3, 4, 5) contains elements not in range [1,4].\\nA permutation p of length n is good if and only if for any 1 ≤ i ≤ n, pi ≠ i.\\nPlease find the lexicographically smallest good permutation p.\\nDefinition for \\\"lexicographically smaller\\\":\\nFor two permutations p and q, we say that p is lexicographically smaller than q if and only if there exists a index 1 ≤ l ≤ n such that:\\n- For any 1 ≤ i < l, pi = qi. Note that if l = 1, this constraint means nothing.\\n- and, pl < ql.\\n\\nFor example, (2, 3, 1, 4) < (2, 3, 4, 1) < (3, 4, 1, 2). The lexicographically smallest permutation is, of course, (1, 2, ..., n), though this one is not good.\\n\\n-----Input-----\\nFirst line of the input contains an integer T denoting number of test cases.\\nFor each test case, the only line contains an integer n.\\n\\n-----Output-----\\nFor each test case, output the lexicographically smallest good permutation of length n. It's guaranteed that this permutation exists.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 10\\n- 2 ≤ n ≤ 105\\n\\n-----Subtasks-----\\n- Subtask #1 (17 points): 2 ≤ n ≤ 9\\n- Subtask #2 (83 points): Original Constraints\\n\\n-----Example-----\\nInput:\\n4\\n2\\n3\\n5\\n6\\n\\nOutput:\\n2 1\\n2 3 1\\n2 1 4 5 3\\n2 1 4 3 6 5\\n\\n-----Explanation-----\\nExample case 1. The only good permutation of length 2 is (2, 1).\\nExample case 2. Consider all permutations of length 3, they are(in lexicographically order):\\n- p = (1, 2, 3), it's not good since p[1] = 1, p[2] = 2 and p[3] = 3;\\n- p = (1, 3, 2), it's not good since p[1] = 1;\\n- p = (2, 1, 3), it's not good since p[3] = 3;\\n- p = (2, 3, 1), it's good since p[1] ≠ 1, p[2] ≠ 2 and p[3] ≠ 3;\\n- p = (3, 1, 2), it's good since p[1] ≠ 1, p[2] ≠ 2 and p[3] ≠ 3;\\n- p = (3, 2, 1), it's not good since p[2] = 2.\\nThus the minimum good one is (2, 3, 1).\\nExample case 3. Consider two good permutations for third test...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\ntry:\\n    T=int(input())\\n    while T>0 :\\n        n=int(input())\\n        i=1 \\n        for j in range(n\\/\\/2-1) :\\n            print(i+1,i,end=\\\" \\\")\\n            i+=2 \\n        if n%2==0 :\\n            print(i+1,i)\\n        else :\\n            print(i+1,i+2,i)\\n        T-=1\\nexcept:\\n    pass\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/range-sum-of-sorted-subarray-sums\\/:\\nGiven the array nums consisting of n positive integers. You computed the sum of all non-empty continous subarrays from the array and then sort them in non-decreasing order, creating a new array of n * (n + 1) \\/ 2 numbers.\\nReturn the sum of the numbers from index left to index right (indexed from 1), inclusive, in the new array. Since the answer can be a huge number return it modulo 10^9 + 7.\\n \\nExample 1:\\nInput: nums = [1,2,3,4], n = 4, left = 1, right = 5\\nOutput: 13 \\nExplanation: All subarray sums are 1, 3, 6, 10, 2, 5, 9, 3, 7, 4. After sorting them in non-decreasing order we have the new array [1, 2, 3, 3, 4, 5, 6, 7, 9, 10]. The sum of the numbers from index le = 1 to ri = 5 is 1 + 2 + 3 + 3 + 4 = 13. \\n\\nExample 2:\\nInput: nums = [1,2,3,4], n = 4, left = 3, right = 4\\nOutput: 6\\nExplanation: The given array is the same as example 1. We have the new array [1, 2, 3, 3, 4, 5, 6, 7, 9, 10]. The sum of the numbers from index le = 3 to ri = 4 is 3 + 3 = 6.\\n\\nExample 3:\\nInput: nums = [1,2,3,4], n = 4, left = 1, right = 10\\nOutput: 50\\n\\n \\nConstraints:\\n\\n1 <= nums.length <= 10^3\\nnums.length == n\\n1 <= nums[i] <= 100\\n1 <= left <= right <= n * (n + 1) \\/ 2\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import heapq\\nclass Solution:\\n    def rangeSum(self, nums: List[int], n: int, left: int, right: int) -> int:\\n        if not nums: return 0\\n        \\n        module = 10**9+7\\n        \\n        n = len(nums)\\n        heap = [[nums[i], i] for i in range(n)]\\n        heapq.heapify(heap)\\n        \\n        count = 0\\n        ans = 0\\n    \\n        while heap:    \\n            [val, idx] = heapq.heappop(heap)\\n            count += 1\\n            if count > right:\\n                break\\n            if count >= left:\\n           \\n                ans += val\\n            \\n            if idx+1 < n:\\n                heapq.heappush(heap, [val+nums[idx+1], idx+1])\\n        \\n        return ans % module\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/54b8204dcd7f514bf2000348:\\nThe Challenge\\n-------------\\nYou'll need to implement a simple lexer type. It should take in an input string through the constructor (or the parameter, for Javascript), and break it up into typed-tokens (in python, C# and Java, you'll have to manage `null\\/None` input too, resulting in the same behavior than an empty string). You'll need to implement the necessary methods (aaccording to your language) to make the Simplexer object behave like an iterator, Meaning that it returns a token (assuming one is available) object each time it a `next` (`Current` field in C#) method would be called. If no tokens are available, an exception should be thrown (idealy: `StopIteration` in python, `InvalidOperationException` in C# and `NoSuchElementException` in Java).\\n\\nTokens are represented by Token objects, which define two properties as strings: `text`, and `type`. Constructor is `Token(text, type)`.\\n\\n**C# Notes**:\\n`Iterator` is an extension of `IEnumerator` with default implementations for `Reset()`, `Dispose()` and `IEnumerator.Current` as these are not need to pass the challenge. You only need to override `MoveNext()` and `Current { get; }`.\\n\\nToken Types\\n-----------\\nThere are 7 tokens types that your lexer will need to produce: `identifier`, `string`, `integer`, `boolean`, `keyword`, `operator`, and `whitespace`. To create the token, you'd need to pass in the token value (the text) and the token type as strings, so for example, a simple integer token could be created with `new Token(\\\"1\\\", \\\"integer\\\")` (Note: no default values or default constructor are provided, so use `new Token(\\\"\\\",\\\"\\\")` if you want a default Token object).\\n\\nToken Grammar\\n--------------\\nHere's a table of the grammars for the various token types:\\n```\\ninteger : Any sequence of one or more digits.\\n\\nboolean : true or false.\\n\\nstring : Any sequence of characters surrounded by \\\"double quotes\\\".\\n\\noperator : The characters +, -, *, \\/, %, (, ), and =.\\n\\nkeyword : The following are keywords: if, else, for, while, return, func, and break.\\n\\nwhitespace : Matches standard...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import re \\n\\nclass Simplexer(object):\\n\\n    ORDERED_TOKENS = [ {\\\"type\\\": \\\"integer\\\",     \\\"reg\\\": r'\\\\d+'},\\n                       {\\\"type\\\": \\\"boolean\\\",     \\\"reg\\\": r'true|false'},\\n                       {\\\"type\\\": \\\"string\\\",      \\\"reg\\\": r'\\\\\\\".*\\\\\\\"'},\\n                       {\\\"type\\\": \\\"operator\\\",    \\\"reg\\\": r'[-+*\\/%\\\\)\\\\(=]'},\\n                       {\\\"type\\\": \\\"keyword\\\",     \\\"reg\\\": r'if|else|for|while|return|func|break'},\\n                       {\\\"type\\\": \\\"whitespace\\\",  \\\"reg\\\": r'\\\\s+'},\\n                       {\\\"type\\\": \\\"identifier\\\",  \\\"reg\\\": r'[$_a-zA-Z][$\\\\w]*'}]\\n    \\n    PATTERN = re.compile(r'|'.join( \\\"(?P<{}>{})\\\".format(dct[\\\"type\\\"], dct[\\\"reg\\\"]) for dct in ORDERED_TOKENS ))\\n    \\n    def __init__(self, s): self.iterable = Simplexer.PATTERN.finditer(s)\\n    \\n    def __iter__(self):    return self\\n                \\n    def __next__(self):\\n        for m in self.iterable:\\n            for k,s in m.groupdict().items():\\n                if s is None: continue\\n                return Token(s,k)\\n        raise StopIteration\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1342\\/A:\\nYou are given two integers $x$ and $y$. You can perform two types of operations:   Pay $a$ dollars and increase or decrease any of these integers by $1$. For example, if $x = 0$ and $y = 7$ there are four possible outcomes after this operation:   $x = 0$, $y = 6$;  $x = 0$, $y = 8$;  $x = -1$, $y = 7$;  $x = 1$, $y = 7$. \\n\\n  Pay $b$ dollars and increase or decrease both integers by $1$. For example, if $x = 0$ and $y = 7$ there are two possible outcomes after this operation:   $x = -1$, $y = 6$;  $x = 1$, $y = 8$.  \\n\\nYour goal is to make both given integers equal zero simultaneously, i.e. $x = y = 0$. There are no other requirements. In particular, it is possible to move from $x=1$, $y=0$ to $x=y=0$.\\n\\nCalculate the minimum amount of dollars you have to spend on it.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 100$) — the number of testcases.\\n\\nThe first line of each test case contains two integers $x$ and $y$ ($0 \\\\le x, y \\\\le 10^9$).\\n\\nThe second line of each test case contains two integers $a$ and $b$ ($1 \\\\le a, b \\\\le 10^9$).\\n\\n\\n-----Output-----\\n\\nFor each test case print one integer — the minimum amount of dollars you have to spend.\\n\\n\\n-----Example-----\\nInput\\n2\\n1 3\\n391 555\\n0 0\\n9 4\\n\\nOutput\\n1337\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case you can perform the following sequence of operations: first, second, first. This way you spend $391 + 555 + 391 = 1337$ dollars.\\n\\nIn the second test case both integers are equal to zero initially, so you dont' have to spend money.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import *\\n\\n\\ndef solve():\\n    x, y = list(map(int, input().split()))\\n    a, b = list(map(int, input().split()))\\n\\n    mn = min(abs(x), abs(y))\\n    ans = 0\\n    if b < 2 * a:\\n        ans += b * (mn)\\n        if x == mn:\\n            x = 0\\n            if y > 0:\\n                y -= mn\\n            else:\\n                y += mn\\n            ans += a * abs(y)\\n            print(ans)\\n        else:\\n            y = 0\\n            if x > 0:\\n                x -= mn\\n            else:\\n                x += mn\\n            ans += a * abs(x)\\n            print(ans)\\n    else:\\n        print(a * (abs(x) + abs(y)))\\n\\n\\nfor _ in range(int(input())):\\n    solve()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/py-collections-ordereddict\\/problem:\\n=====Function Descriptions=====\\ncollections.OrderedDict\\n\\nAn OrderedDict is a dictionary that remembers the order of the keys that were inserted first. If a new entry overwrites an existing entry, the original insertion position is left unchanged.\\n\\nExample\\nCode\\n>>> from collections import OrderedDict\\n>>> \\n>>> ordinary_dictionary = {}\\n>>> ordinary_dictionary['a'] = 1\\n>>> ordinary_dictionary['b'] = 2\\n>>> ordinary_dictionary['c'] = 3\\n>>> ordinary_dictionary['d'] = 4\\n>>> ordinary_dictionary['e'] = 5\\n>>> \\n>>> print ordinary_dictionary\\n{'a': 1, 'c': 3, 'b': 2, 'e': 5, 'd': 4}\\n>>> \\n>>> ordered_dictionary = OrderedDict()\\n>>> ordered_dictionary['a'] = 1\\n>>> ordered_dictionary['b'] = 2\\n>>> ordered_dictionary['c'] = 3\\n>>> ordered_dictionary['d'] = 4\\n>>> ordered_dictionary['e'] = 5\\n>>> \\n>>> print ordered_dictionary\\nOrderedDict([('a', 1), ('b', 2), ('c', 3), ('d', 4), ('e', 5)])\\n\\n=====Problem Statement=====\\nYou are the manager of a supermarket.\\nYou have a list of N items together with their prices that consumers bought on a particular day.\\nYour task is to print each item_name and net_price in order of its first occurrence.\\n\\nitem_name = Name of the item.\\nnet_price = Quantity of the item sold multiplied by the price of each item.\\n\\n=====Input Format=====\\nThe first line contains the number of items, N.\\nThe next N lines contains the item's name and price, separated by a space.\\n\\n=====Constraints=====\\n0<N≤100\\n\\n=====Output Format=====\\nPrint the item_name and net_price in order of its first occurrence.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import collections, re\\nn = int(input())\\nitem_od = collections.OrderedDict()\\nfor i in range(n):\\n    record_list = re.split(r'(\\\\d+)$',input().strip())\\n    item_name = record_list[0]\\n    item_price = int(record_list[1])\\n    if item_name not in item_od:\\n        item_od[item_name]=item_price\\n    else:\\n        item_od[item_name]=item_od[item_name]+item_price\\n            \\nfor i in item_od:\\n    print((i+str(item_od[i])))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/LUCKY2:\\nChef loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.\\n\\nLet F(X) equals to the number of lucky digits in decimal representation of X. Chef wants to know the number of such integers X, that L ≤ X ≤ R and F(X) is a lucky number. Help him and calculate that number modulo 109+7.\\n\\n-----Input-----\\nFirst line contains one integer T, the number of test cases. Each of the following T lines contains two space separated positive integers L and R.\\n\\n-----Output-----\\nFor each of the T test cases print one integer, the number of such X, that L ≤ X ≤ R and F(X) is a lucky number, modulo 1000000007.\\n\\n-----Constraints-----\\n\\n1 ≤ T ≤ 10\\n\\n1 ≤ L ≤ R ≤ 101000\\n\\n-----Example-----\\nInput:\\n4\\n1 100\\n1 10000\\n1 100000\\n4444 4447\\n\\nOutput:\\n0\\n16\\n640\\n2\\n\\n-----Notes-----\\nFirst test case: of course, any number of less than 4 digits can't contain lucky number of lucky digits, so the answer is 0.\\n\\nSecond test case: 16 required numbers are 4444 4447 4474 4477 4744 4747 4774 4777 7444 7447 7474 7477 7744 7747 7774 7777.\\n\\nThird test case: there are 640 required lucky numbers. Some of them are 4474, 14747, 41474, 77277, 44407, 74749.\\n\\nFourth test case: the only two required numbers are 4444 and 4447.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"lucky = {4, 774, 7, 744, 777, 74, 747, 44, 77, 47, 474, 444, 477, 447}\\nfrom functools import lru_cache\\nimport sys \\nsys.setrecursionlimit(10 ** 6)\\nmod = 10 ** 9 + 7\\nfact = [1]\\nfor i in range(1, 1001):\\n    fact.append(fact[-1] * i % mod)\\ninv = [pow(i, mod-2, mod) for i in fact]\\nC = lambda k, n: fact[n] * inv[n-k] * inv[k] % mod\\ndef f(n):\\n    n = [int(x) for x in n]\\n    @lru_cache(None)\\n    def dp(pos, cnt, free):\\n        if cnt > 777:\\n            return 0\\n        diff = len(n) - pos \\n        ans = 0\\n        if free:\\n            for i in lucky:\\n                i -= cnt\\n                if 0 <= i <= diff:\\n                    ans += C(i, diff) * pow(2, i, mod) * pow(8, diff - i, mod)\\n                    ans %= mod \\n            return ans\\n        if pos == len(n):\\n            return int(cnt in lucky)\\n        for i in range(10 if free else n[pos]+1):\\n            ans += dp(pos+1, cnt + int(i == 4 or i == 7), free or i < n[pos])\\n            ans %= mod \\n        return ans \\n    return dp(0, 0, 0)\\n    \\nt = int(input())\\nfor _ in range(t):\\n    l, r = input().split()\\n    l = str(int(l) -1) \\n    print((f(r) - f(l)) % mod)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given n strings s_1, s_2, ..., s_{n} consisting of characters 0 and 1. m operations are performed, on each of them you concatenate two existing strings into a new one. On the i-th operation the concatenation s_{a}_{i}s_{b}_{i} is saved into a new string s_{n} + i (the operations are numbered starting from 1). After each operation you need to find the maximum positive integer k such that all possible strings consisting of 0 and 1 of length k (there are 2^{k} such strings) are substrings of the new string. If there is no such k, print 0.\\n\\n\\n-----Input-----\\n\\nThe first line contains single integer n (1 ≤ n ≤ 100) — the number of strings. The next n lines contain strings s_1, s_2, ..., s_{n} (1 ≤ |s_{i}| ≤ 100), one per line. The total length of strings is not greater than 100.\\n\\nThe next line contains single integer m (1 ≤ m ≤ 100) — the number of operations. m lines follow, each of them contains two integers a_{i} abd b_{i} (1 ≤ a_{i}, b_{i} ≤ n + i - 1) — the number of strings that are concatenated to form s_{n} + i.\\n\\n\\n-----Output-----\\n\\nPrint m lines, each should contain one integer — the answer to the question after the corresponding operation.\\n\\n\\n-----Example-----\\nInput\\n5\\n01\\n10\\n101\\n11111\\n0\\n3\\n1 2\\n6 5\\n4 4\\n\\nOutput\\n1\\n2\\n0\\n\\n\\n\\n-----Note-----\\n\\nOn the first operation, a new string \\\"0110\\\" is created. For k = 1 the two possible binary strings of length k are \\\"0\\\" and \\\"1\\\", they are substrings of the new string. For k = 2 and greater there exist strings of length k that do not appear in this string (for k = 2 such string is \\\"00\\\"). So the answer is 1.\\n\\nOn the second operation the string \\\"01100\\\" is created. Now all strings of length k = 2 are present.\\n\\nOn the third operation the string \\\"1111111111\\\" is created. There is no zero, so the answer is 0.\",\"targets\":\"from math import log\\nn = int(input())\\np = [bin(p)[2:] for p in range(0,512)]\\ndef mset(s):\\n    ss = set()\\n    for k in range(0,10):\\n        for pi in range(0,2 ** k):\\n            cs = p[pi]\\n            cs = (k - len(cs)) * \\\"0\\\" + cs\\n            if cs in s:\\n                ss.add(cs)\\n    return ss\\ndef q(s):\\n    for k in range(0,10):\\n        for pi in range(0,2 ** k):\\n            cs = p[pi]\\n            cs = (k - len(cs)) * \\\"0\\\" + cs\\n            if not cs in s:\\n                return k - 1\\ns = [[v[:9], v[-9:], mset(v)] for v in [input() for i in range(n)]]\\nfor qa, qb in [[int(v) - 1 for v in input().split()] for i in range(int(input()))]:\\n    v = [s[qa][0], s[qb][1], mset(s[qa][1] + s[qb][0]) | s[qa][2] | s[qb][2]]\\n    if len(v[0]) < 9:\\n        v[0] = (v[0] + s[qb][0])[:9]\\n    if len(v[1]) < 9:\\n        v[1] = (s[qa][1] + s[qb][1])[-9:]\\n    s += [v]\\n    print(max(q(v[2]),0))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/910\\/A:\\nA frog lives on the axis Ox and needs to reach home which is in the point n. She starts from the point 1. The frog can jump to the right at a distance not more than d. So, after she jumped from the point x she can reach the point x + a, where a is an integer from 1 to d.\\n\\nFor each point from 1 to n is known if there is a lily flower in it. The frog can jump only in points with a lilies. Guaranteed that there are lilies in the points 1 and n.\\n\\nDetermine the minimal number of jumps that the frog needs to reach home which is in the point n from the point 1. Consider that initially the frog is in the point 1. If the frog can not reach home, print -1.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and d (2 ≤ n ≤ 100, 1 ≤ d ≤ n - 1) — the point, which the frog wants to reach, and the maximal length of the frog jump.\\n\\nThe second line contains a string s of length n, consisting of zeros and ones. If a character of the string s equals to zero, then in the corresponding point there is no lily flower. In the other case, in the corresponding point there is a lily flower. Guaranteed that the first and the last characters of the string s equal to one.\\n\\n\\n-----Output-----\\n\\nIf the frog can not reach the home, print -1.\\n\\nIn the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point n from the point 1.\\n\\n\\n-----Examples-----\\nInput\\n8 4\\n10010101\\n\\nOutput\\n2\\n\\nInput\\n4 2\\n1001\\n\\nOutput\\n-1\\n\\nInput\\n8 4\\n11100101\\n\\nOutput\\n3\\n\\nInput\\n12 3\\n101111100101\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).\\n\\nIn the second example the frog can not reach home, because to make it she need to jump on a distance three, but the maximum length of her jump equals to two.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n=[int(i) for i in  input().split()]\\na=str(input())\\nfor i in range(n[1]):\\n    a+='0'\\nd=n[1]\\nskak=0\\npr=d\\nans=0\\nwhile skak<n[0]-1 and pr>0:\\n    pr=d\\n    \\n    while a[pr+skak]!='1' and pr!=0:\\n        \\n        pr-=1\\n    skak=pr+skak\\n    ans+=1\\nif pr==0:\\n    print(-1)\\nelse:\\n    print(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1145\\/C:\\n[Image] \\n\\n\\n-----Input-----\\n\\nThe input contains a single integer $a$ ($0 \\\\le a \\\\le 15$).\\n\\n\\n-----Output-----\\n\\nOutput a single integer.\\n\\n\\n-----Example-----\\nInput\\n3\\n\\nOutput\\n13\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\n\\na = [0] * 4\\n\\ni = 0\\nfor i in range(4):\\n    a[i] = n % 2\\n    n = n \\/\\/ 2\\n\\n\\na[3] = a[3] ^ 1\\na[2] = a[3] ^ a[2]\\na[1] = (a[3] and a[2]) ^ a[1]\\na[0] = (a[3] and a[2] and a[1]) ^ a[0]\\n\\nsum_ = 0\\nfor i in range(4):\\n    sum_ += a[i] * 2 ** i\\n\\nprint(sum_)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou have integer $n$. Calculate how many ways are there to fully cover belt-like area of $4n-2$ triangles with diamond shapes. \\n\\nDiamond shape consists of two triangles. You can move, rotate or flip the shape, but you cannot scale it. \\n\\n$2$ coverings are different if some $2$ triangles are covered by the same diamond shape in one of them and by different diamond shapes in the other one.\\n\\nPlease look at pictures below for better understanding.\\n\\n $\\\\theta$ On the left you can see the diamond shape you will use, and on the right you can see the area you want to fill.\\n\\n[Image] These are the figures of the area you want to fill for $n = 1, 2, 3, 4$. \\n\\nYou have to answer $t$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $t$ ($1 \\\\le t \\\\le 10^{4}$) — the number of test cases.\\n\\nEach of the next $t$ lines contains a single integer $n$ ($1 \\\\le n \\\\le 10^{9}$).\\n\\n\\n-----Output-----\\n\\nFor each test case, print the number of ways to fully cover belt-like area of $4n-2$ triangles using diamond shape. It can be shown that under given constraints this number of ways doesn't exceed $10^{18}$.\\n\\n\\n-----Example-----\\nInput\\n2\\n2\\n1\\n\\nOutput\\n2\\n1\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, there are the following $2$ ways to fill the area:\\n\\n [Image] \\n\\nIn the second test case, there is a unique way to fill the area:\\n\\n [Image]\",\"targets\":\"t = int(input())\\n\\nfor i in range(t) :\\n    n = int(input())\\n    print(n)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1352\\/D:\\nThere are $n$ candies in a row, they are numbered from left to right from $1$ to $n$. The size of the $i$-th candy is $a_i$.\\n\\nAlice and Bob play an interesting and tasty game: they eat candy. Alice will eat candy from left to right, and Bob — from right to left. The game ends if all the candies are eaten.\\n\\nThe process consists of moves. During a move, the player eats one or more sweets from her\\/his side (Alice eats from the left, Bob — from the right).\\n\\nAlice makes the first move. During the first move, she will eat $1$ candy (its size is $a_1$). Then, each successive move the players alternate — that is, Bob makes the second move, then Alice, then again Bob and so on.\\n\\nOn each move, a player counts the total size of candies eaten during the current move. Once this number becomes strictly greater than the total size of candies eaten by the other player on their previous move, the current player stops eating and the move ends. In other words, on a move, a player eats the smallest possible number of candies such that the sum of the sizes of candies eaten on this move is strictly greater than the sum of the sizes of candies that the other player ate on the previous move. If there are not enough candies to make a move this way, then the player eats up all the remaining candies and the game ends.\\n\\nFor example, if $n=11$ and $a=[3,1,4,1,5,9,2,6,5,3,5]$, then:  move 1: Alice eats one candy of size $3$ and the sequence of candies becomes $[1,4,1,5,9,2,6,5,3,5]$.  move 2: Alice ate $3$ on the previous move, which means Bob must eat $4$ or more. Bob eats one candy of size $5$ and the sequence of candies becomes $[1,4,1,5,9,2,6,5,3]$.  move 3: Bob ate $5$ on the previous move, which means Alice must eat $6$ or more. Alice eats three candies with the total size of $1+4+1=6$ and the sequence of candies becomes $[5,9,2,6,5,3]$.  move 4: Alice ate $6$ on the previous move, which means Bob must eat $7$ or more. Bob eats two candies with the total size of $3+5=8$ and the sequence of candies becomes $[5,9,2,6]$.  move 5: Bob...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t = int(input())\\n\\nfor loop in range(t):\\n\\n    n = int(input())\\n\\n    lis = list(map(int,input().split()))\\n\\n    ai = 0\\n    bi = n-1\\n\\n    A = [0]\\n    B = [0]\\n    move = 0\\n\\n    while True:\\n\\n        if ai > bi:\\n            break\\n\\n        na = 0\\n        while na <= B[-1]:\\n\\n            if ai > bi:\\n                break\\n\\n            na += lis[ai]\\n            ai += 1\\n\\n        A.append(na)\\n        if na > 0:\\n            move += 1\\n\\n        nb = 0\\n        while nb <= A[-1]:\\n\\n            if ai > bi:\\n                break\\n\\n            nb += lis[bi]\\n            bi -= 1\\n        B.append(nb)\\n        if nb > 0:\\n            move += 1\\n\\n    print(move,sum(A),sum(B))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou want to form a target string of lowercase letters.\\nAt the beginning, your sequence is target.length '?' marks.  You also have a stamp of lowercase letters.\\nOn each turn, you may place the stamp over the sequence, and replace every letter in the sequence with the corresponding letter from the stamp.  You can make up to 10 * target.length turns.\\nFor example, if the initial sequence is \\\"?????\\\", and your stamp is \\\"abc\\\",  then you may make \\\"abc??\\\", \\\"?abc?\\\", \\\"??abc\\\" in the first turn.  (Note that the stamp must be fully contained in the boundaries of the sequence in order to stamp.)\\nIf the sequence is possible to stamp, then return an array of the index of the left-most letter being stamped at each turn.  If the sequence is not possible to stamp, return an empty array.\\nFor example, if the sequence is \\\"ababc\\\", and the stamp is \\\"abc\\\", then we could return the answer [0, 2], corresponding to the moves \\\"?????\\\" -> \\\"abc??\\\" -> \\\"ababc\\\".\\nAlso, if the sequence is possible to stamp, it is guaranteed it is possible to stamp within 10 * target.length moves.  Any answers specifying more than this number of moves will not be accepted.\\n \\nExample 1:\\nInput: stamp = \\\"abc\\\", target = \\\"ababc\\\"\\nOutput: [0,2]\\n([1,0,2] would also be accepted as an answer, as well as some other answers.)\\n\\n\\nExample 2:\\nInput: stamp = \\\"abca\\\", target = \\\"aabcaca\\\"\\nOutput: [3,0,1]\\n\\n\\n \\nNote:\\n\\n\\n\\n1 <= stamp.length <= target.length <= 1000\\nstamp and target only contain lowercase letters.\",\"targets\":\"class Solution:\\n    def movesToStamp(self, stamp: str, target: str) -> List[int]:\\n        N , M = len(target), len(stamp)\\n        def cor(s):\\n            result = False\\n            for c1, c2 in zip(s,stamp):\\n                if c1 == '?':\\n                    continue\\n                elif c1 != c2:\\n                    return False\\n                else:\\n                    result = True\\n            return result\\n        base, times, max_times, indexes = '?' * N , 0 , 10* N, []                \\n        while times < max_times:\\n            start = times\\n            for i in range(N - M + 1):                \\n                if cor(target[i:i + M  ]):\\n                    times += 1\\n                    indexes.append(i)\\n                    target = target[:i] + '?' *  M + target[i+M:]                \\n            if target == base:\\n                return indexes[::-1]\\n                \\n            if times == start:\\n                break\\n        print(\\\\\\\"here\\\\\\\")\\n        return  []\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1166\\/D:\\nGiven a positive integer $m$, we say that a sequence $x_1, x_2, \\\\dots, x_n$ of positive integers is $m$-cute if for every index $i$ such that $2 \\\\le i \\\\le n$ it holds that $x_i = x_{i - 1} + x_{i - 2} + \\\\dots + x_1 + r_i$ for some positive integer $r_i$ satisfying $1 \\\\le r_i \\\\le m$.\\n\\nYou will be given $q$ queries consisting of three positive integers $a$, $b$ and $m$. For each query you must determine whether or not there exists an $m$-cute sequence whose first term is $a$ and whose last term is $b$. If such a sequence exists, you must additionally find an example of it.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer number $q$ ($1 \\\\le q \\\\le 10^3$) — the number of queries.\\n\\nEach of the following $q$ lines contains three integers $a$, $b$, and $m$ ($1 \\\\le a, b, m \\\\le 10^{14}$, $a \\\\leq b$), describing a single query.\\n\\n\\n-----Output-----\\n\\nFor each query, if no $m$-cute sequence whose first term is $a$ and whose last term is $b$ exists, print $-1$.\\n\\nOtherwise print an integer $k$ ($1 \\\\le k \\\\leq 50$), followed by $k$ integers $x_1, x_2, \\\\dots, x_k$ ($1 \\\\le x_i \\\\le 10^{14}$). These integers must satisfy $x_1 = a$, $x_k = b$, and that the sequence $x_1, x_2, \\\\dots, x_k$ is $m$-cute.\\n\\nIt can be shown that under the problem constraints, for each query either no $m$-cute sequence exists, or there exists one with at most $50$ terms.\\n\\nIf there are multiple possible sequences, you may print any of them.\\n\\n\\n-----Example-----\\nInput\\n2\\n5 26 2\\n3 9 1\\n\\nOutput\\n4 5 6 13 26\\n-1\\n\\n\\n\\n-----Note-----\\n\\nConsider the sample. In the first query, the sequence $5, 6, 13, 26$ is valid since $6 = 5 + \\\\bf{\\\\color{blue} 1}$, $13 = 6 + 5 + {\\\\bf\\\\color{blue} 2}$ and $26 = 13 + 6 + 5 + {\\\\bf\\\\color{blue} 2}$ have the bold values all between $1$ and $2$, so the sequence is $2$-cute. Other valid sequences, such as $5, 7, 13, 26$ are also accepted.\\n\\nIn the second query, the only possible $1$-cute sequence starting at $3$ is $3, 4, 8, 16, \\\\dots$, which does not contain $9$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# https:\\/\\/codeforces.com\\/contest\\/1166\\/problem\\/D\\ndef creat_r(X, k, m, p):\\n    q = X \\/\\/ p[k]\\n    r = X %  p[k]\\n    \\n    R = []\\n    for _ in range(k+1):\\n        R.append(q)\\n        \\n    s = bin(r)[2:]\\n    for i in range(1, len(s)+1):\\n        if s[-i] == '1':\\n            R[-(i+1)] += 1\\n       \\n    return R\\n\\ni = 1\\np = [1]\\nfor _ in range(50):\\n    i*=2\\n    p.append(i)\\n    \\nT   = int(input())\\nans = []\\nfor _ in range(T):\\n    a, b, m = map(int, input().split())\\n    if a == b:\\n        print(1, a)\\n        continue\\n    \\n    flg = False\\n    for i in range(50):\\n        if p[i] * a  >= b: break\\n    \\n        k = i\\n        X = b - (p[i] * a)\\n    \\n        if X >= p[k] and X <= p[k]*m:\\n            flg = True\\n            R   = creat_r(X, k, m, p)\\n            sR  = 0 \\n            A   = [a]\\n        \\n            for _ in range(k+1):\\n                A.append(p[_]*a+sR+R[_])\\n                sR += sR + R[_] \\n            \\n            print(len(A), end=' ')\\n            for x in A:\\n                print(x, end=' ')\\n            print()\\n            break\\n        \\n        \\n    if flg == False:\\n        print(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/265\\/A:\\nThere is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string s. The i-th (1-based) character of s represents the color of the i-th stone. If the character is \\\"R\\\", \\\"G\\\", or \\\"B\\\", the color of the corresponding stone is red, green, or blue, respectively.\\n\\nInitially Squirrel Liss is standing on the first stone. You perform instructions one or more times.\\n\\nEach instruction is one of the three types: \\\"RED\\\", \\\"GREEN\\\", or \\\"BLUE\\\". After an instruction c, if Liss is standing on a stone whose colors is c, Liss will move one stone forward, else she will not move.\\n\\nYou are given a string t. The number of instructions is equal to the length of t, and the i-th character of t represents the i-th instruction.\\n\\nCalculate the final position of Liss (the number of the stone she is going to stand on in the end) after performing all the instructions, and print its 1-based position. It is guaranteed that Liss don't move out of the sequence.\\n\\n\\n-----Input-----\\n\\nThe input contains two lines. The first line contains the string s (1 ≤ |s| ≤ 50). The second line contains the string t (1 ≤ |t| ≤ 50). The characters of each string will be one of \\\"R\\\", \\\"G\\\", or \\\"B\\\". It is guaranteed that Liss don't move out of the sequence.\\n\\n\\n-----Output-----\\n\\nPrint the final 1-based position of Liss in a single line.\\n\\n\\n-----Examples-----\\nInput\\nRGB\\nRRR\\n\\nOutput\\n2\\n\\nInput\\nRRRBGBRBBB\\nBBBRR\\n\\nOutput\\n3\\n\\nInput\\nBRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\\n\\nOutput\\n15\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"s = input()\\nc = input()\\nstep = 0\\nfor i in range(len(c)):\\n    if c[i] == s[step]:\\n        step += 1\\nprint(step+1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nBob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.\\n\\nYou are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't. \\n\\nPlease note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.\\n\\nThe second line contains n integers a_{i} (0 ≤ a_{i} ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.\\n\\n\\n-----Output-----\\n\\nPrint the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.\\n\\n\\n-----Examples-----\\nInput\\n3\\n0 1 0\\n\\nOutput\\n1\\n\\nInput\\n5\\n1 0 1 0 1\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.\\n\\nIn the second sample you can break the bar in four ways:\\n\\n10|10|1\\n\\n1|010|1\\n\\n10|1|01\\n\\n1|01|01\",\"targets\":\"#!\\/usr\\/bin\\/env python3\\n# -*- coding: utf-8 -*-\\n\\nimport time\\n\\n#   = input()\\nn   = int(input())\\na   = [int(i) for i in input().split()]\\n\\nstart = time.time()\\n\\ns = sum(a)\\nif s == 0:\\n    ans = 0\\nelif s == 1:\\n    ans = 1\\nelse:\\n    ans = 1\\n\\n    l = 0\\n    while( a[l] != 1):\\n        l += 1\\n\\n    r = l\\n\\n    while(r < n-1):\\n        r += 1\\n        if a[r] == 1:\\n            ans *= (r-l)\\n            l = r\\n\\nprint(ans)\\nfinish = time.time()\\n#print(finish - start)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are n phone numbers in Polycarp's contacts on his phone. Each number is a 9-digit integer, starting with a digit different from 0. All the numbers are distinct.\\n\\nThere is the latest version of Berdroid OS installed on Polycarp's phone. If some number is entered, is shows up all the numbers in the contacts for which there is a substring equal to the entered sequence of digits. For example, is there are three phone numbers in Polycarp's contacts: 123456789, 100000000 and 100123456, then:\\n\\n  if he enters 00 two numbers will show up: 100000000 and 100123456,  if he enters 123 two numbers will show up 123456789 and 100123456,  if he enters 01 there will be only one number 100123456. \\n\\nFor each of the phone numbers in Polycarp's contacts, find the minimum in length sequence of digits such that if Polycarp enters this sequence, Berdroid shows this only phone number.\\n\\n\\n-----Input-----\\n\\nThe first line contains single integer n (1 ≤ n ≤ 70000) — the total number of phone contacts in Polycarp's contacts.\\n\\nThe phone numbers follow, one in each line. Each number is a positive 9-digit integer starting with a digit from 1 to 9. All the numbers are distinct.\\n\\n\\n-----Output-----\\n\\nPrint exactly n lines: the i-th of them should contain the shortest non-empty sequence of digits, such that if Polycarp enters it, the Berdroid OS shows up only the i-th number from the contacts. If there are several such sequences, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n3\\n123456789\\n100000000\\n100123456\\n\\nOutput\\n9\\n000\\n01\\n\\nInput\\n4\\n123456789\\n193456789\\n134567819\\n934567891\\n\\nOutput\\n2\\n193\\n81\\n91\",\"targets\":\"import math\\nfrom collections import *\\na=int(input())\\nindx=defaultdict(list)\\ndone=defaultdict(list)\\nfor t in range(a):\\n    s=input()\\n    for i in range(len(s)):\\n        for j in range(i,len(s)):\\n            m=s[i:j+1]\\n            \\n            if(len(done[m])==0):\\n                done[m].append(t)\\n                indx[t].append(m)\\n            else:\\n                if(len(done[m])==1 and  done[m][0]!=math.inf and t!=done[m][0]):\\n                    indx[done[m][0]].remove(m)\\n                    done[m][0]=math.inf\\n            \\n \\nfor i in range(a):\\n    af=indx[i]\\n \\n    mini=15\\n    ss=''\\n    for i in range(len(af)):\\n        if(len(af[i])<mini):\\n            mini=len(af[i])\\n            ss=af[i]\\n    print(ss)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nKuro has just learned about permutations and he is really excited to create a new permutation type. He has chosen $n$ distinct positive integers and put all of them in a set $S$. Now he defines a magical permutation to be: A permutation of integers from $0$ to $2^x - 1$, where $x$ is a non-negative integer.  The bitwise xor of any two consecutive elements in the permutation is an element in $S$.\\n\\nSince Kuro is really excited about magical permutations, he wants to create the longest magical permutation possible. In other words, he wants to find the largest non-negative integer $x$ such that there is a magical permutation of integers from $0$ to $2^x - 1$. Since he is a newbie in the subject, he wants you to help him find this value of $x$ and also the magical permutation for that $x$.\\n\\n\\n-----Input-----\\n\\nThe first line contains the integer $n$ ($1 \\\\leq n \\\\leq 2 \\\\cdot 10^5$) — the number of elements in the set $S$.\\n\\nThe next line contains $n$ distinct integers $S_1, S_2, \\\\ldots, S_n$ ($1 \\\\leq S_i \\\\leq 2 \\\\cdot 10^5$) — the elements in the set $S$.\\n\\n\\n-----Output-----\\n\\nIn the first line print the largest non-negative integer $x$, such that there is a magical permutation of integers from $0$ to $2^x - 1$.\\n\\nThen print $2^x$ integers describing a magical permutation of integers from $0$ to $2^x - 1$. If there are multiple such magical permutations, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n3\\n1 2 3\\n\\nOutput\\n2\\n0 1 3 2 \\nInput\\n2\\n2 3\\n\\nOutput\\n2\\n0 2 1 3 \\nInput\\n4\\n1 2 3 4\\n\\nOutput\\n3\\n0 1 3 2 6 7 5 4 \\nInput\\n2\\n2 4\\n\\nOutput\\n0\\n0 \\nInput\\n1\\n20\\n\\nOutput\\n0\\n0 \\nInput\\n1\\n1\\n\\nOutput\\n1\\n0 1 \\n\\n\\n-----Note-----\\n\\nIn the first example, $0, 1, 3, 2$ is a magical permutation since: $0 \\\\oplus 1 = 1 \\\\in S$  $1 \\\\oplus 3 = 2 \\\\in S$  $3 \\\\oplus 2 = 1 \\\\in S$\\n\\nWhere $\\\\oplus$ denotes bitwise xor operation.\",\"targets\":\"def size(k):\\n    return int(math.log2(k))\\ndef v2(k):\\n    if k%2==1:\\n        return 0\\n    else:\\n        return 1+v2(k\\/\\/2)\\nn=int(input())\\ns=list(map(int,input().split()))\\nimport math\\ns.sort()\\nused=[]\\nuse=0\\nfound={0:1}\\ngood=0\\nfor guy in s:\\n    big=size(guy)\\n    if guy not in found:\\n        used.append(guy)\\n        use+=1\\n        new=[]\\n        for boi in found:\\n            new.append(boi^guy)\\n        for guy in new:\\n            found[guy]=1\\n        if use==big+1:\\n            good=use\\nif good==0:\\n    print(0)\\n    print(0)\\nelse:\\n    useful=used[:good]\\n    perm=[\\\"0\\\"]\\n    curr=0\\n    for i in range(2**good-1):\\n        curr^=useful[v2(i+1)]\\n        perm.append(str(curr))\\n    print(good)\\n    print(\\\" \\\".join(perm))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven an array of arguments, representing system call arguments keys and values, join it into a single, space-delimited string. You don't need to care about the application name -- your task is only about parameters.\\n\\nEach element of the given array can be:\\n* a single string,\\n* a single string array,\\n* an array of two strings\\n\\nIn the last case (array of two strings) the first string should have a `\\\"--\\\"` prefix if it is more than one character long; or a `\\\"-\\\"` prefix otherwise; e.g.:\\n  * `[\\\"foo\\\", \\\"bar\\\"]` becomes `\\\"--foo bar\\\"`\\n  * `[\\\"f\\\", \\\"bar\\\"]` becomes `\\\"-f bar\\\"`\\n\\nYou may assume that all strings are non-empty and have no spaces.\\n\\n## Examples\\n\\n```python\\n[\\\"foo\\\", \\\"bar\\\"]                    #  \\\"foo bar\\\"\\n[[\\\"foo\\\", \\\"bar\\\"]]                  #  \\\"--foo bar\\\"\\n[[\\\"f\\\", \\\"bar\\\"]]                    #  \\\"-f bar\\\"\\n[[\\\"foo\\\", \\\"bar\\\"], \\\"baz\\\"]           #  \\\"--foo bar baz\\\"\\n[[\\\"foo\\\"], [\\\"bar\\\", \\\"baz\\\"], \\\"qux\\\"]  #  \\\"foo --bar baz qux\\\"\\n```\",\"targets\":\"def args_to_string(args):\\n    return ' '.join('-'*(len(a)>1 and 1+(len(a[0])>1))+' '.join(a) if type(a)==list else a for a in args)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/ENCMSG:\\nChef recently graduated Computer Science in university, so he was looking for a job. He applied for several job offers, but he eventually settled for a software engineering job at ShareChat. Chef was very enthusiastic about his new job and the first mission assigned to him was to implement a message encoding feature to ensure the chat is private and secure.\\nChef has a message, which is a string $S$ with length $N$ containing only lowercase English letters. It should be encoded in two steps as follows: \\n- Swap the first and second character of the string $S$, then swap the 3rd and 4th character, then the 5th and 6th character and so on. If the length of $S$ is odd, the last character should not be swapped with any other.\\n- Replace each occurrence of the letter 'a' in the message obtained after the first step by the letter 'z', each occurrence of 'b' by 'y', each occurrence of 'c' by 'x', etc, and each occurrence of 'z' in the message obtained after the first step by 'a'.\\nThe string produced in the second step is the encoded message. Help Chef and find this message.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $N$.\\n- The second line contains the message string $S$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one string — the encoded message.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 1,000$\\n- $1 \\\\le N \\\\le 100$\\n- $|S| = N$\\n- $S$ contains only lowercase English letters\\n\\n-----Example Input-----\\n2\\n9\\nsharechat\\n4\\nchef\\n\\n-----Example Output-----\\nshizxvzsg\\nsxuv\\n\\n-----Explanation-----\\nExample case 1: The original message is \\\"sharechat\\\". In the first step, we swap four pairs of letters (note that the last letter is not swapped), so it becomes \\\"hsraceaht\\\". In the second step, we replace the first letter ('h') by 's', the second letter ('s') by 'h', and so on, so the resulting encoded message is \\\"shizxvzsg\\\".\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\ndef generate():\\n dic = {}\\n j = 122\\n for i in range(97 , 123):\\n  dic[chr(i)] = chr(j)\\n  j -= 1\\n return dic\\n\\nletters = generate()\\ndef encode(string):\\n for i in range(0 , len(string) - 1, 2):\\n  temp = string[i] \\n  string[i] = string[i + 1]\\n  string[i + 1] = temp\\n new_string = ''\\n letter = generate()\\n for i in string:\\n  new_string += letter[i]\\n return(new_string)\\n\\nn = int(input())\\nfor i in range(n):\\n k = int(input())\\n string = list(input())\\n print(encode(string))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1209\\/E1:\\nThis is an easier version of the next problem. The difference is only in constraints.\\n\\nYou are given a rectangular $n \\\\times m$ matrix $a$. In one move you can choose any column and cyclically shift elements in this column. You can perform this operation as many times as you want (possibly zero). You can perform this operation to a column multiple times.\\n\\nAfter you are done with cyclical shifts, you compute for every row the maximal value in it. Suppose that for $i$-th row it is equal $r_i$. What is the maximal possible value of $r_1+r_2+\\\\ldots+r_n$?\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $t$ ($1 \\\\le t \\\\le 40$), the number of test cases in the input.\\n\\nThe first line of each test case contains integers $n$ and $m$ ($1 \\\\le n \\\\le 4$, $1 \\\\le m \\\\le 100$) — the number of rows and the number of columns in the given matrix $a$. \\n\\nEach of the following $n$ lines contains $m$ integers, the elements of $a$ ($1 \\\\le a_{i, j} \\\\le 10^5$).\\n\\n\\n-----Output-----\\n\\nPrint $t$ integers: answers for all test cases in the order they are given in the input.\\n\\n\\n-----Example-----\\nInput\\n2\\n2 3\\n2 5 7\\n4 2 4\\n3 6\\n4 1 5 2 10 4\\n8 6 6 4 9 10\\n5 4 9 5 8 7\\n\\nOutput\\n12\\n29\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, you can shift the third column down by one, this way there will be $r_1 = 5$ and $r_2 = 7$.\\n\\nIn the second case you can don't rotate anything at all, this way there will be $r_1 = r_2 = 10$ and $r_3 = 9$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t = int(input())\\nfor i in range(t):\\n    n, m = [int(item) for item in input().split()]\\n    mat = []\\n    col = [[] for _ in range(m)]\\n    for j in range(n):\\n        line = [int(item) for item in input().split()]\\n        for k, item in enumerate(line):\\n            col[k].append(item)\\n        mat.append(line)\\n    colmax = []\\n    for line in col:\\n        colmax.append([max(line), line])\\n    colmax.sort(reverse=True)\\n    colmax = colmax[:n]\\n    ans = 0\\n    for j in range(n ** (n-1)):\\n        index = j\\n        rot = [0]\\n        for k in range(n-1):\\n            rot.append(index % n)\\n            index \\/\\/= n \\n        ret = 0\\n        for l in range(n):\\n            val = 0\\n            for k in range(len(colmax)):\\n                val = max(val, colmax[k][1][(l + rot[k]) % n])\\n            ret += val\\n        ans = max(ans, ret)\\n    print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/742\\/A:\\nThere exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.\\n\\nMehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given n, print the last digit of 1378^{n}. \\n\\n [Image] \\n\\nMehrdad has become quite confused and wants you to help him. Please help, although it's a naive cheat.\\n\\n\\n-----Input-----\\n\\nThe single line of input contains one integer n (0  ≤  n  ≤  10^9).\\n\\n\\n-----Output-----\\n\\nPrint single integer — the last digit of 1378^{n}.\\n\\n\\n-----Examples-----\\nInput\\n1\\n\\nOutput\\n8\\nInput\\n2\\n\\nOutput\\n4\\n\\n\\n-----Note-----\\n\\nIn the first example, last digit of 1378^1 = 1378 is 8.\\n\\nIn the second example, last digit of 1378^2 = 1378·1378 = 1898884 is 4.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n\\nimport math\\n\\n\\nsz=int(input())\\nif sz==0:\\n    print(1)\\n    return\\n\\ns = str(8 ** ((sz - 1) % 4 + 1))\\nprint(s[len(s)-1])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/PBK12020\\/problems\\/ITGUY15:\\nThe chef is having one string of English lower case alphabets only. The chef wants to remove all \\\"abc\\\" special pairs where a,b,c are occurring consecutively. After removing the pair, create a new string and again remove \\\"abc\\\" special pair from a newly formed string. Repeate the process until no such pair remains in a string.\\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase contains of a single line of input, $String$. \\n\\n-----Output:-----\\nFor each testcase, output in a single line answer, new String with no \\\"abc\\\" special pair.\\n\\n-----Constraints:-----\\n$T \\\\leq 2 $\\n$1 \\\\leq String length \\\\leq 1000 $\\n\\n-----Sample Input:-----\\n2\\naabcc\\nbababccc\\n\\n-----Sample Output:-----\\nac\\nbc\\n\\n-----EXPLANATION:-----\\nFor 1) after removing \\\"abc\\\" at middle we get a new string as ac.\\nFor 2) string = bababccc\\nnewString1 = babcc  \\/\\/ After removing middle \\\"abc\\\"\\nnewString2 = bc   \\/\\/After removing \\\"abc\\\"\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nt = int(input())\\nfor i in range(t):\\n    s = input()\\n    while \\\"abc\\\" in s: s = s.replace(\\\"abc\\\",\\\"\\\")\\n    print(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMs. E.T. came from planet Hex. She has 8 fingers in each hand which makes her count in hexadecimal way. When she meets you, she tells you that she came from 7E light years from the planet Earth. You see she means that it is 126 light years far away and she is telling you the numbers in hexadecimal. Now, you are in trouble to understand what those numbers really mean. Therefore, you have to convert the hexadecimal numbers to decimals.\\n\\nInput:\\n\\nFirst line of code contain T test cases.\\n\\nevery line of text case contain a Hex-value \\n\\nOutput:\\n\\nEvery line of output contain a decimal conversion of given nunmber\\n\\nSample Input:\\n\\n3\\n\\nA\\n\\n1A23\\n\\n2C2A\\n\\nSample Output:\\n\\n10\\n\\n6691\\n\\n11306\",\"targets\":\"# cook your dish here\\ntry:\\n    n=int(input())\\n    for i in range(n):\\n        a=input()\\n        \\n        print(int(a, 16))\\nexcept EOFError as e:\\n    pass\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPolycarp wrote on the board a string $s$ containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.\\n\\nAfter that, he erased some letters from the string $s$, and he rewrote the remaining letters in any order. As a result, he got some new string $t$. You have to find it with some additional information.\\n\\nSuppose that the string $t$ has length $m$ and the characters are numbered from left to right from $1$ to $m$. You are given a sequence of $m$ integers: $b_1, b_2, \\\\ldots, b_m$, where $b_i$ is the sum of the distances $|i-j|$ from the index $i$ to all such indices $j$ that $t_j > t_i$ (consider that 'a'<'b'<...<'z'). In other words, to calculate $b_i$, Polycarp finds all such indices $j$ that the index $j$ contains a letter that is later in the alphabet than $t_i$ and sums all the values $|i-j|$.\\n\\nFor example, if $t$ = \\\"abzb\\\", then:  since $t_1$='a', all other indices contain letters which are later in the alphabet, that is: $b_1=|1-2|+|1-3|+|1-4|=1+2+3=6$;  since $t_2$='b', only the index $j=3$ contains the letter, which is later in the alphabet, that is: $b_2=|2-3|=1$;  since $t_3$='z', then there are no indexes $j$ such that $t_j>t_i$, thus $b_3=0$;  since $t_4$='b', only the index $j=3$ contains the letter, which is later in the alphabet, that is: $b_4=|4-3|=1$. \\n\\nThus, if $t$ = \\\"abzb\\\", then $b=[6,1,0,1]$.\\n\\nGiven the string $s$ and the array $b$, find any possible string $t$ for which the following two requirements are fulfilled simultaneously:  $t$ is obtained from $s$ by erasing some letters (possibly zero) and then writing the rest in any order;  the array, constructed from the string $t$ according to the rules above, equals to the array $b$ specified in the input data. \\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $q$ ($1 \\\\le q \\\\le 100$) — the number of test cases in the test. Then $q$ test cases follow.\\n\\nEach test case consists of three lines:  the first line contains string $s$, which has a length from $1$ to $50$ and consists of lowercase English...\",\"targets\":\"from collections import Counter\\nq = int(input())\\nfor _ in range(q):\\n    s = input()\\n    m = int(input())\\n    b = list(map(int, input().split()))\\n    c = Counter(s)\\n    c = list(c.items())\\n    c.sort(key=lambda x: x[0])\\n\\n    ans = [None for _ in range(m)]\\n    while not all(ans):\\n        indices = []\\n        for i in range(m):\\n            if b[i] == 0:\\n                indices.append(i)\\n                b[i] = -1\\n        while True:\\n            if c[-1][1] >= len(indices):\\n                for idx in indices:\\n                    ans[idx] = c[-1][0]\\n                c.pop()\\n                break\\n            else:\\n                c.pop()\\n            \\n        for j in range(m):\\n            for idx in indices:\\n                b[j] -= abs(idx-j)\\n    print(''.join(map(str, ans)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5f70c55c40b1c90032847588:\\n[Generala](https:\\/\\/en.wikipedia.org\\/wiki\\/Generala) is a dice game popular in South America. It's very similar to [Yahtzee](https:\\/\\/en.wikipedia.org\\/wiki\\/Yahtzee) but with a different scoring approach. It is played with 5 dice, and the possible results are:\\n\\n| Result        | Points | Rules                                                                                                                                          | Samples                            |\\n|---------------|--------|------------------------------------------------------------------------------------------------------------------------------------------------|------------------------------------|\\n| GENERALA      | 50     | When all rolled dice are of the same value.                                                                                                    | 66666, 55555, 44444, 11111, 22222, 33333.  |\\n| POKER         | 40     | Four rolled dice are of the same value.                                                                                                        | 44441, 33233, 22262.               |\\n| FULLHOUSE     | 30     | Three rolled dice are of the same value, the remaining two are of a different value, but equal among themselves.                               | 12121, 44455, 66116.               |\\n| STRAIGHT      | 20     | Rolled dice are in sequential order. Dice with value `1` is a wildcard that can be used at the beginning of the straight, or at the end of it. | 12345, 23456, 34561, 13654, 62534. |\\n| Anything else | 0      | Anything else will return `0` points.                                                                                                          | 44421, 61623, 12346.               |\\n\\nPlease note that dice are not in order; for example `12543` qualifies as a `STRAIGHT`. Also, No matter what string value you get for the dice, you can always reorder them any order you need to make them qualify as a `STRAIGHT`. I.E. `12453`, `16543`, `15364`, `62345` all qualify as valid `STRAIGHT`s.\\n\\n\\n\\nComplete...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import Counter\\n\\ndef points(s):\\n    m = tuple(sorted(dict(Counter(list(s))).values()))\\n    d = {(5,):50, (1,4):40, (2,3):30}\\n    try:\\n        return d[m]\\n    except KeyError: \\n        return 20 if \\\"\\\".join(sorted(list(s))) in [\\\"12345\\\",\\\"13456\\\",\\\"23456\\\"] else 0\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/663\\/A:\\nYou are given a rebus of form ? + ? - ? + ? = n, consisting of only question marks, separated by arithmetic operation '+' and '-', equality and positive integer n. The goal is to replace each question mark with some positive integer from 1 to n, such that equality holds.\\n\\n\\n-----Input-----\\n\\nThe only line of the input contains a rebus. It's guaranteed that it contains no more than 100 question marks, integer n is positive and doesn't exceed 1 000 000, all letters and integers are separated by spaces, arithmetic operations are located only between question marks.\\n\\n\\n-----Output-----\\n\\nThe first line of the output should contain \\\"Possible\\\" (without quotes) if rebus has a solution and \\\"Impossible\\\" (without quotes) otherwise.\\n\\nIf the answer exists, the second line should contain any valid rebus with question marks replaced by integers from 1 to n. Follow the format given in the samples.\\n\\n\\n-----Examples-----\\nInput\\n? + ? - ? + ? + ? = 42\\n\\nOutput\\nPossible\\n9 + 13 - 39 + 28 + 31 = 42\\n\\nInput\\n? - ? = 1\\n\\nOutput\\nImpossible\\n\\nInput\\n? = 1000000\\n\\nOutput\\nPossible\\n1000000 = 1000000\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"s = input().split()\\nt = s[::]\\nreq = int(s[-1])\\nlim = req\\nS = 0\\nfor i in range(len(s)):\\n\\tif s[i] == '?':\\n\\t\\ts[i] = '1'\\n\\t\\tS += 1 if i == 0 or s[i - 1] == '+' else -1\\n\\nif S < req:\\n\\tfor i in range(len(s)):\\n\\t\\tif t[i] == '?':\\n\\t\\t\\tsign = 1 if i == 0 or s[i - 1] == '+' else -1\\n\\t\\t\\tif sign == 1:\\n\\t\\t\\t\\td = min(req - S, lim - 1)\\n\\t\\t\\t\\ts[i] = str(d + 1)\\n\\t\\t\\t\\tS += d\\nelse:\\n\\tfor i in range(len(s)):\\n\\t\\tif t[i] == '?':\\n\\t\\t\\tsign = 1 if i == 0 or s[i - 1] == '+' else -1\\n\\t\\t\\tif sign == -1:\\n\\t\\t\\t\\td = min(S - req, lim - 1)\\n\\t\\t\\t\\ts[i] = str(d + 1)\\n\\t\\t\\t\\tS -= d\\nif S == req:\\n\\tprint(\\\"Possible\\\")\\n\\tprint(' '.join(s))\\nelse:\\n\\tprint(\\\"Impossible\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA bus moves along the coordinate line Ox from the point x = 0 to the point x = a. After starting from the point x = 0, it reaches the point x = a, immediately turns back and then moves to the point x = 0. After returning to the point x = 0 it immediately goes back to the point x = a and so on. Thus, the bus moves from x = 0 to x = a and back. Moving from the point x = 0 to x = a or from the point x = a to x = 0 is called a bus journey. In total, the bus must make k journeys.\\n\\nThe petrol tank of the bus can hold b liters of gasoline. To pass a single unit of distance the bus needs to spend exactly one liter of gasoline. The bus starts its first journey with a full petrol tank.\\n\\nThere is a gas station in point x = f. This point is between points x = 0 and x = a. There are no other gas stations on the bus route. While passing by a gas station in either direction the bus can stop and completely refuel its tank. Thus, after stopping to refuel the tank will contain b liters of gasoline.\\n\\nWhat is the minimum number of times the bus needs to refuel at the point x = f to make k journeys? The first journey starts in the point x = 0.\\n\\n\\n-----Input-----\\n\\nThe first line contains four integers a, b, f, k (0 < f < a ≤ 10^6, 1 ≤ b ≤ 10^9, 1 ≤ k ≤ 10^4) — the endpoint of the first bus journey, the capacity of the fuel tank of the bus, the point where the gas station is located, and the required number of journeys.\\n\\n\\n-----Output-----\\n\\nPrint the minimum number of times the bus needs to refuel to make k journeys. If it is impossible for the bus to make k journeys, print -1.\\n\\n\\n-----Examples-----\\nInput\\n6 9 2 4\\n\\nOutput\\n4\\n\\nInput\\n6 10 2 4\\n\\nOutput\\n2\\n\\nInput\\n6 5 4 3\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the bus needs to refuel during each journey.\\n\\nIn the second example the bus can pass 10 units of distance without refueling. So the bus makes the whole first journey, passes 4 units of the distance of the second journey and arrives at the point with the gas station. Then it can refuel its tank, finish the second journey and...\",\"targets\":\"def main():\\n    a, b, f, k = list(map(int, input().split()))\\n    fuels = 0\\n    trips = 0\\n    pos = 0\\n    move = 1\\n    gas = b\\n\\n    while trips < k:\\n        if gas < 0:\\n            print(-1)\\n            return\\n        if move == 1:\\n            if pos == 0:\\n                pos = f\\n                gas -= f\\n            elif pos == f:\\n                needed_gas = (a - f) if trips == k - 1 else 2 * (a - f)\\n                if gas < needed_gas:\\n                    gas = b\\n                    fuels += 1\\n                gas -= (a - f)\\n                pos = a\\n            elif pos == a:\\n                trips += 1\\n                if trips == k:\\n                    break\\n                move = -1\\n        elif move == -1:\\n            if pos == 0:\\n                trips += 1\\n                if trips == k:\\n                    break\\n                move = 1\\n            elif pos == f:\\n                needed_gas = f if trips == k - 1 else 2 * f\\n                if gas < needed_gas:\\n                    gas = b\\n                    fuels += 1\\n                pos = 0\\n                gas -= f\\n            elif pos == a:\\n                pos = f\\n                gas -= (a - f)\\n\\n    print(fuels)\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/331\\/C1:\\nYet another Armageddon is coming! This time the culprit is the Julya tribe calendar. \\n\\nThe beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on it. The translation from Old Beaverish is as follows: \\n\\n\\\"May the Great Beaver bless you! May your chacres open and may your third eye never turn blind from beholding the Truth! Take the magic number, subtract a digit from it (the digit must occur in the number) and get a new magic number. Repeat this operation until a magic number equals zero. The Earth will stand on Three Beavers for the time, equal to the number of subtractions you perform!\\\"\\n\\nDistinct subtraction sequences can obviously get you different number of operations. But the Smart Beaver is ready to face the worst and is asking you to count the minimum number of operations he needs to reduce the magic number to zero.\\n\\n\\n-----Input-----\\n\\nThe single line contains the magic integer n, 0 ≤ n.\\n\\n  to get 20 points, you need to solve the problem with constraints: n ≤ 10^6 (subproblem C1);  to get 40 points, you need to solve the problem with constraints: n ≤ 10^12 (subproblems C1+C2);  to get 100 points, you need to solve the problem with constraints: n ≤ 10^18 (subproblems C1+C2+C3). \\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum number of subtractions that turns the magic number to a zero.\\n\\n\\n-----Examples-----\\nInput\\n24\\n\\nOutput\\n5\\n\\n\\n-----Note-----\\n\\nIn the first test sample the minimum number of operations can be reached by the following sequence of subtractions: \\n\\n 24 → 20 → 18 → 10 → 9 → 0\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,k=int(input()),0\\nwhile n:n-=int(max(str(n)));k+=1\\nprint(k)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nShivam is working on electric circuits. He requires some connecting wires. He needs to make a total of N connections and he has mentioned his wire length requirements for each connection in an integer sequence A. For buying wires, he need to decide the length of each wire piece, and he’ll get as many wire pieces of the chosen length each at unit cost (cost 1 per piece) but he can't get wires of different lengths. Also, he can't cut wire pieces to make new pieces of different (smaller) length(s).\\nBut he can connect any number of wires together to form a new single wire piece whose length is the sum of lengths of the wires connected. So, Shivam needs to choose an integer length for buying wires. Shivam hates to waste anything, and he hates it even more if that thing is money.\\nShivam is weak in mathematics and is asking you to help him in this situation. Help him decide the length of wires and total number of wires so as to minimize the total expenditure.\\nNote: You cannot make a connection which requires a wire piece of length X with a wire piece of length Y if X≠Y.\\nInput:\\n·        The first line of the input contains T = Number of Test cases\\n·        The first line of each test case contains an integer N\\n·        The second line contains N space separated integers A1, A2, …., AN.\\nOutput:\\nFor each test case print a single line containing two space separated integers, length of each wire and the corresponding minimum cost.\\nConstraints:\\n·       1 <= T <= 10\\n·       1 <= N <= 10^5\\n·        1 <= Ai <= 10^5, for each valid i\\nSample Input:\\n1\\n3\\n2 4 8\\nSample Output:\\n2 7\",\"targets\":\"T = int(input())\\n\\ndef get_gcd(x, y):\\n while(y):\\n  x, y = y, x % y\\n return x\\n\\nfor _ in range(T):\\n N = int(input())\\n num = list(map(int, input().split()))\\n gcd = num[0]\\n for n in num[1:]:\\n  gcd = get_gcd(gcd, n)\\n print(gcd, sum(num)\\/\\/gcd)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1133\\/E:\\nYou are a coach at your local university. There are $n$ students under your supervision, the programming skill of the $i$-th student is $a_i$.\\n\\nYou have to form $k$ teams for yet another new programming competition. As you know, the more students are involved in competition the more probable the victory of your university is! So you have to form no more than $k$ (and at least one) non-empty teams so that the total number of students in them is maximized. But you also know that each team should be balanced. It means that the programming skill of each pair of students in each team should differ by no more than $5$. Teams are independent from one another (it means that the difference between programming skills of two students from two different teams does not matter).\\n\\nIt is possible that some students not be included in any team at all.\\n\\nYour task is to report the maximum possible total number of students in no more than $k$ (and at least one) non-empty balanced teams.\\n\\nIf you are Python programmer, consider using PyPy instead of Python when you submit your code.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $k$ ($1 \\\\le k \\\\le n \\\\le 5000$) — the number of students and the maximum number of teams, correspondingly.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 10^9$), where $a_i$ is a programming skill of the $i$-th student.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the maximum possible total number of students in no more than $k$ (and at least one) non-empty balanced teams.\\n\\n\\n-----Examples-----\\nInput\\n5 2\\n1 2 15 15 15\\n\\nOutput\\n5\\n\\nInput\\n6 1\\n36 4 1 25 9 16\\n\\nOutput\\n2\\n\\nInput\\n4 4\\n1 10 100 1000\\n\\nOutput\\n4\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import io\\nimport os\\n#input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline\\nimport sys\\n\\n\\ndef main():\\n    n, k = list(map(int, input().split()))\\n    a = sorted(list(map(int, input().split())))\\n\\n    maxFromI = [0] * n  # max students in the team starting from student i with skill a[i]\\n    end = -1\\n    for i in range(n):\\n        while end+1 < n and a[end+1] <= a[i] + 5:\\n            end += 1\\n        maxFromI[i] = end - i + 1\\n\\n    dp = [[0] * (k+1) for _ in range(n+1)]\\n    for i in range(n):\\n        for j in range(k+1):\\n            dp[i+1][j] = max(dp[i+1][j], dp[i][j])  # skip the student\\n            if j+1 <= k:\\n                dp[i+maxFromI[i]][j+1] = max(dp[i+maxFromI[i]][j+1], dp[i][j] + maxFromI[i])\\n\\n    print(dp[n][k])\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/387\\/B:\\nGeorge decided to prepare a Codesecrof round, so he has prepared m problems for the round. Let's number the problems with integers 1 through m. George estimates the i-th problem's complexity by integer b_{i}.\\n\\nTo make the round good, he needs to put at least n problems there. Besides, he needs to have at least one problem with complexity exactly a_1, at least one with complexity exactly a_2, ..., and at least one with complexity exactly a_{n}. Of course, the round can also have problems with other complexities.\\n\\nGeorge has a poor imagination. It's easier for him to make some already prepared problem simpler than to come up with a new one and prepare it. George is magnificent at simplifying problems. He can simplify any already prepared problem with complexity c to any positive integer complexity d (c ≥ d), by changing limits on the input data.\\n\\nHowever, nothing is so simple. George understood that even if he simplifies some problems, he can run out of problems for a good round. That's why he decided to find out the minimum number of problems he needs to come up with in addition to the m he's prepared in order to make a good round. Note that George can come up with a new problem of any complexity.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (1 ≤ n, m ≤ 3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers a_1, a_2, ..., a_{n} (1 ≤ a_1 < a_2 < ... < a_{n} ≤ 10^6) — the requirements for the complexity of the problems in a good round. The third line contains space-separated integers b_1, b_2, ..., b_{m} (1 ≤ b_1 ≤ b_2... ≤ b_{m} ≤ 10^6) — the complexities of the problems prepared by George. \\n\\n\\n-----Output-----\\n\\nPrint a single integer — the answer to the problem.\\n\\n\\n-----Examples-----\\nInput\\n3 5\\n1 2 3\\n1 2 2 3 3\\n\\nOutput\\n0\\n\\nInput\\n3 5\\n1 2 3\\n1 1 1 1 1\\n\\nOutput\\n2\\n\\nInput\\n3 1\\n2 3 4\\n1\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample the set of the prepared problems meets the requirements for a good round.\\n\\nIn...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = tuple(map(int,input().split(' ')))\\na = list(map(int,input().split(' ')))\\nb = list(map(int,input().split(' ')))\\nwhile len(a)>0 and len(b)>0:\\n    if a[0]<=b[0]: a.pop(0)\\n    b.pop(0)\\nprint(len(a))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nKattapa, as you all know was one of the greatest warriors of his time. The kingdom of Maahishmati had never lost a battle under him (as army-chief), and the reason for that was their really powerful army, also called as Mahasena.\\nKattapa was known to be a very superstitious person. He believed that a soldier is \\\"lucky\\\" if the soldier is holding an even number of weapons, and \\\"unlucky\\\" otherwise. He considered the army as \\\"READY FOR BATTLE\\\" if the count of \\\"lucky\\\" soldiers is strictly greater than the count of \\\"unlucky\\\" soldiers, and \\\"NOT READY\\\" otherwise.\\nGiven the number of weapons each soldier is holding, your task is to determine whether the army formed by all these soldiers is \\\"READY FOR BATTLE\\\" or \\\"NOT READY\\\".\\nNote: You can find the definition of an even number here.\\n\\n-----Input-----\\n\\nThe first line of input consists of a single integer N denoting the number of soldiers. The second line of input consists of N space separated integers A1, A2, ..., AN, where Ai denotes the number of weapons that the ith soldier is holding.\\n\\n-----Output-----\\nGenerate one line output saying \\\"READY FOR BATTLE\\\", if the army satisfies the conditions that Kattapa requires or \\\"NOT READY\\\" otherwise (quotes for clarity).\\n\\n-----Constraints-----\\n- 1 ≤ N ≤ 100\\n- 1 ≤ Ai ≤ 100\\n\\n-----Example 1-----\\nInput:\\n1\\n1\\n\\nOutput:\\nNOT READY\\n\\n-----Example 2-----\\nInput:\\n1\\n2\\n\\nOutput:\\nREADY FOR BATTLE\\n\\n-----Example 3-----\\nInput:\\n4\\n11 12 13 14\\n\\nOutput:\\nNOT READY\\n\\n-----Example 4-----\\nInput:\\n3\\n2 3 4\\n\\nOutput:\\nREADY FOR BATTLE\\n\\n-----Example 5-----\\nInput:\\n5\\n1 2 3 4 5\\n\\nOutput:\\nNOT READY\\n\\n-----Explanation-----\\n\\n- Example 1: For the first example, N = 1 and the array A = [1]. There is only 1 soldier and he is holding 1 weapon, which is odd. The number of soldiers holding an even number of weapons = 0, and number of soldiers holding an odd number of weapons = 1. Hence, the answer is \\\"NOT READY\\\" since the number of soldiers holding an even number of weapons is not greater than the number of soldiers holding an odd number of weapons.\\n\\n- Example 2: For the second...\",\"targets\":\"n = int(input())\\nl = list(map(int, input().split()))\\neven = 0\\nfor i in range(n):\\n\\tif l[i]%2 == 0:\\n\\t\\teven += 1\\nodd = n - even\\nif even > odd:\\n\\tprint('READY FOR BATTLE')\\nelse:\\n\\tprint('NOT READY')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given two integers $n$ and $m$ ($m < n$). Consider a convex regular polygon of $n$ vertices. Recall that a regular polygon is a polygon that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length). [Image] Examples of convex regular polygons \\n\\nYour task is to say if it is possible to build another convex regular polygon with $m$ vertices such that its center coincides with the center of the initial polygon and each of its vertices is some vertex of the initial polygon.\\n\\nYou have to answer $t$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases.\\n\\nThe next $t$ lines describe test cases. Each test case is given as two space-separated integers $n$ and $m$ ($3 \\\\le m < n \\\\le 100$) — the number of vertices in the initial polygon and the number of vertices in the polygon you want to build.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer — \\\"YES\\\" (without quotes), if it is possible to build another convex regular polygon with $m$ vertices such that its center coincides with the center of the initial polygon and each of its vertices is some vertex of the initial polygon and \\\"NO\\\" otherwise.\\n\\n\\n-----Example-----\\nInput\\n2\\n6 3\\n7 3\\n\\nOutput\\nYES\\nNO\\n\\n\\n\\n-----Note----- $0$ The first test case of the example \\n\\nIt can be shown that the answer for the second test case of the example is \\\"NO\\\".\",\"targets\":\"t = int(input())\\nfor i in range(t):\\n\\tn,m = list(map(int, input().split()))\\n\\tif n % m == 0:\\n\\t\\tprint (\\\"YES\\\")\\n\\telse:\\n\\t\\tprint (\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe research center Q has developed a new multi-core processor. The processor consists of n cores and has k cells of cache memory. Consider the work of this processor.\\n\\nAt each cycle each core of the processor gets one instruction: either do nothing, or the number of the memory cell (the core will write an information to the cell). After receiving the command, the core executes it immediately. Sometimes it happens that at one cycle, multiple cores try to write the information into a single cell. Unfortunately, the developers did not foresee the possibility of resolving conflicts between cores, so in this case there is a deadlock: all these cores and the corresponding memory cell are locked forever. Each of the locked cores ignores all further commands, and no core in the future will be able to record an information into the locked cell. If any of the cores tries to write an information into some locked cell, it is immediately locked.\\n\\nThe development team wants to explore the deadlock situation. Therefore, they need a program that will simulate the processor for a given set of instructions for each core within m cycles . You're lucky, this interesting work is entrusted to you. According to the instructions, during the m cycles define for each core the number of the cycle, during which it will become locked. It is believed that initially all cores and all memory cells are not locked.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers n, m, k (1 ≤ n, m, k ≤ 100). Then follow n lines describing instructions. The i-th line contains m integers: x_{i}1, x_{i}2, ..., x_{im} (0 ≤ x_{ij} ≤ k), where x_{ij} is the instruction that must be executed by the i-th core at the j-th cycle. If x_{ij} equals 0, then the corresponding instruction is «do nothing». But if x_{ij} is a number from 1 to k, then the corresponding instruction is «write information to the memory cell number x_{ij}».\\n\\nWe assume that the cores are numbered from 1 to n, the work cycles are numbered from 1 to m and the memory cells are numbered from...\",\"targets\":\"n, m, k = map(int, input().split())\\na = [[0 for i in range(m)] for j in range(n)]\\ninf = [0 for i in range(k + 1)]\\nstat = [True for i in range(n + 1)]\\ntime = [0 for i in range(n + 1)]\\nfor i in range(n):\\n    a[i] = list(map(int, input().split()))\\nfor i in range(m):\\n    for j in range(1, n + 1):\\n        if stat[j]:\\n            current_core = inf[a[j - 1][i]]\\n            if current_core == 0 and a[j - 1][i]  != 0:\\n                inf[a[j - 1][i]] = j\\n            elif current_core == -1:\\n                stat[j], time[j] = False, i + 1\\n            elif a[j - 1][i] != 0:\\n                stat[current_core], time[current_core] = False, i + 1\\n                stat[j], time[j] = False, i + 1\\n                inf[a[j - 1][i]] = -1\\n    for p in range(len(inf)):\\n        if inf[p] != -1:\\n            inf[p] = 0\\nfor i in range(1, n + 1):\\n    print(time[i])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nCreate a function that differentiates a polynomial for a given value of `x`.\\n\\nYour function will receive 2 arguments: a polynomial as a string, and a point to evaluate the equation as an integer.\\n\\n## Assumptions:\\n\\n* There will be a coefficient near each `x`, unless the coefficient equals `1` or `-1`.\\n* There will be an exponent near each `x`, unless the exponent equals `0` or `1`.\\n* All exponents will be greater or equal to zero\\n\\n## Examples:\\n\\n```python\\ndifferenatiate(\\\"12x+2\\\", 3)      ==>   returns 12\\ndifferenatiate(\\\"x^2+3x+2\\\", 3)   ==>   returns 9\\n```\",\"targets\":\"def parse_monom(monom):\\n    if 'x' not in monom: monom = monom + 'x^0'\\n    if monom.startswith('x'): monom = '1' + monom\\n    if monom.startswith('-x'): monom = '-1' + monom[1:]\\n    if monom.endswith('x'): monom = monom + '^1'\\n    coefficient, degree = map(int, monom.replace('x', '').split('^'))\\n    return degree, coefficient\\n\\ndef differentiate(equation, point):\\n    monoms = equation.replace('-', '+-').lstrip('+').split('+')\\n    polynom = dict(map(parse_monom, monoms))\\n    return sum(coefficient * degree * point ** (degree - 1)\\n               for degree, coefficient in polynom.items() if degree)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe local transport authority is organizing an online picture contest.\\nParticipants must take pictures of transport means in an original way, and then post the picture on Instagram using a specific ```hashtag```.\\n\\nThe local transport authority needs your help. They want you to take out the ```hashtag``` from the posted message. Your task is to implement the function\\n\\n```python\\ndef omit_hashtag(message, hashtag):\\n```\\n\\n## Examples \\n\\n```\\n* (\\\"Sunny day! #lta #vvv\\\", \\\"#lta\\\") -> \\\"Sunny day!  #vvv\\\" (notice the double space)\\n* (\\\"#lta #picture_contest\\\", \\\"#lta\\\") -> \\\" #picture_contest\\\"\\n```\\n\\n## Notes\\n\\n* When multiple occurences of the hashtag are found, delete only the first one.\\n\\n* In C, you should modify the ```message```, as the function returns a void type. In Python, you should return the answer.\\n\\n* There can be erroneous messages where the hashtag isn't present. The message should in this case stay untouched.\\n\\n* The hashtag only consists of alphanumeric characters.\",\"targets\":\"def omit_hashtag(s, c):\\n    return s.replace(c,\\\"\\\",1)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven is an integer N.\\nTakahashi chooses an integer a from the positive integers not greater than N with equal probability.\\nFind the probability that a is odd.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 100\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\n\\n-----Output-----\\nPrint the probability that a is odd.\\nYour output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.\\n\\n-----Sample Input-----\\n4\\n\\n-----Sample Output-----\\n0.5000000000\\n\\nThere are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \\\\frac{2}{4} = 0.5.\",\"targets\":\"n=int(input());print(sum(i%2==0 for i in range(n))\\/n)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n#### Task:\\n\\nYour job here is to implement a method, `approx_root` in Ruby\\/Python\\/Crystal and `approxRoot` in JavaScript\\/CoffeeScript, that takes one argument, `n`, and returns the approximate square root of that number, rounded to the nearest hundredth and computed in the following manner.\\n\\n1.      Start with `n = 213` (as an example). \\n2.      To approximate the square root of n, we will first find the greatest perfect square that is below or equal to `n`. (In this example, that would be 196, or 14 squared.) We will call the square root of this number (which means sqrt 196, or 14) `base`.\\n3.      Then, we will take the lowest perfect square that is greater than or equal to `n`. (In this example, that would be 225, or 15 squared.)\\n4.      Next, subtract 196 (greatest perfect square less than or equal to `n`) from `n`. (213 - 196 = **17**) We will call this value `diff_gn`.\\n5.      Find the difference between the lowest perfect square greater than or equal to `n` and the greatest perfect square less than or equal to `n`. (225 – 196 = **29**) We will call this value `diff_lg`.\\n6.      Your final answer is `base` + (`diff_gn` \\/ `diff_lg`). In this example: 14 + (17 \\/ 29) which is 14.59, rounded to the nearest hundredth.\\n\\nJust to clarify, if the input is a perfect square itself, you should return the exact square of the input.\\n\\nIn case you are curious, the approximation (computed like above) for 213 rounded to four decimal places is 14.5862. The actual square root of 213 is 14.5945. \\n\\nInputs will always be positive whole numbers. If you are having trouble understanding it, let me know with a comment, or take a look at the second group of the example cases.\\n\\n#### Some examples:\\n\\n```python\\napprox_root(400) #=> 20\\napprox_root(401) #=> \\n  # smallest perfect square above 401 is 441 or 21 squared\\n  # greatest perfect square below 401 is 400 or 20 squared\\n  # difference between 441 and 400 is 41\\n  # difference between 401 and 400 is 1\\n  # answer is 20 + (1 \\/ 41) which becomes 20.02, rounded to the nearest hundredth\\n  #...\",\"targets\":\"def approx_root(n):\\n    base = int(n ** 0.5)\\n    diff_gn = n - base ** 2\\n    diff_lg = base * 2 + 1\\n    return round(base + diff_gn \\/ diff_lg, 2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1180\\/A:\\nWhile playing with geometric figures Alex has accidentally invented a concept of a $n$-th order rhombus in a cell grid.\\n\\nA $1$-st order rhombus is just a square $1 \\\\times 1$ (i.e just a cell).\\n\\nA $n$-th order rhombus for all $n \\\\geq 2$ one obtains from a $n-1$-th order rhombus adding all cells which have a common side with it to it (look at the picture to understand it better).\\n\\n [Image] \\n\\nAlex asks you to compute the number of cells in a $n$-th order rhombus.\\n\\n\\n-----Input-----\\n\\nThe first and only input line contains integer $n$ ($1 \\\\leq n \\\\leq 100$) — order of a rhombus whose numbers of cells should be computed.\\n\\n\\n-----Output-----\\n\\nPrint exactly one integer — the number of cells in a $n$-th order rhombus.\\n\\n\\n-----Examples-----\\nInput\\n1\\n\\nOutput\\n1\\nInput\\n2\\n\\nOutput\\n5\\nInput\\n3\\n\\nOutput\\n13\\n\\n\\n-----Note-----\\n\\nImages of rhombus corresponding to the examples are given in the statement.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# coding: utf-8\\nimport sys\\nsys.setrecursionlimit(int(1e7))\\n\\ndef main():\\n    n = int(input().strip())\\n    print(2*(n*(n-1))+1)\\n    return\\n\\nwhile 1:\\n    try: main()\\n    except EOFError: break\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nComplete the function `power_of_two`\\/`powerOfTwo` (or equivalent, depending on your language) that determines if a given non-negative integer is a [power of two](https:\\/\\/en.wikipedia.org\\/wiki\\/Power_of_two).  From the corresponding Wikipedia entry:\\n\\n> *a power of two is a number of the form 2^(n) where **n** is an integer, i.e. the result of exponentiation with number two as the base and integer **n** as the exponent.*\\n\\nYou may assume the input is always valid.\\n\\n## Examples\\n\\n~~~if-not:nasm\\n```python\\npower_of_two(1024) ==> True\\npower_of_two(4096) ==> True\\npower_of_two(333)  ==> False\\n```\\n~~~\\n~~~if:nasm\\n```\\nmov edi, 0\\ncall power_of_two    ; returns false (zero)\\nmov edi, 16\\ncall power_of_two    ; returns true (non-zero)\\nmov edi, 100\\ncall power_of_two    ; returns false\\nmov edi, 1024\\ncall power_of_two    ; returns true\\nmov edi, 20000\\ncall power_of_two    ; returns false\\n```\\n~~~\\n\\nBeware of certain edge cases - for example, `1` is a power of `2` since `2^0 = 1` and `0` is not a power of `2`.\",\"targets\":\"import math\\n\\ndef power_of_two(x):\\n    if x == 1:\\n        return True\\n    elif x < 1 or x % 2:\\n        return False\\n    return power_of_two(x\\/\\/2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc157\\/tasks\\/abc157_a:\\nTakahashi wants to print a document with N pages double-sided, where two pages of data can be printed on one sheet of paper.\\nAt least how many sheets of paper does he need?\\n\\n-----Constraints-----\\n - N is an integer.\\n - 1 \\\\leq N \\\\leq 100\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\n\\n-----Output-----\\nPrint the answer.\\n\\n-----Sample Input-----\\n5\\n\\n-----Sample Output-----\\n3\\n\\nBy printing the 1-st, 2-nd pages on the 1-st sheet, 3-rd and 4-th pages on the 2-nd sheet, and 5-th page on the 3-rd sheet, we can print all the data on 3 sheets of paper.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\na = n \\/ 2\\nif n % 2 == 0:\\n    print(int(a))\\nelse:\\n    print(int(a)+1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a05a4d206d5b61ba70000f9:\\nYou have been speeding on a motorway and a police car had to stop you. The policeman is a funny guy that likes to play games. Before issuing penalty charge notice he gives you a choice to change your penalty. \\n\\nYour penalty charge is a combination of numbers like: speed of your car, speed limit in the area, speed of the police car chasing you, the number of police cars involved, etc.  So, your task is to combine the given numbers and make the penalty charge to be as small as possible.      \\n\\nFor example, if  you are given numbers  ```[45, 30, 50, 1]``` your best choice is ```1304550```\\n\\n\\nExamples:\\n```Python\\n['45', '30', '50', '1'] => '1304550'\\n\\n['100', '10', '1'] => '100101'\\n\\n['32', '3'] => '323'\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def penalty(nos):\\n    print(nos)\\n    pos = 0\\n    ret = []\\n    for x in range(len(nos)):\\n        low = 10\\n        tmp = ''\\n        for x in nos:\\n            if int(x[0])<=int(low):\\n                if tmp != '':\\n                    tmp = getLowest(tmp,x)\\n                else:\\n                    tmp = x\\n                low = tmp[0]\\n        ret.append(tmp)\\n        #print(ret,'\\\\t',tmp)\\n        nos.remove(tmp)\\n    return ''.join(ret)\\n        \\ndef getLowest(s1,s2):\\n    res = {s1:s1,s2:s2}\\n    if len(s2)<len(s1):\\n        res[s2] = equalPad(s2,len(s1))\\n    elif len(s2)>len(s1):\\n        res[s1] = equalPad(s1,len(s2))\\n    #print('res',res)\\n    for x in range(len(res[s1])):\\n        if res[s1][x] < res[s2][x]:\\n            return s1\\n        elif res[s2][x] < res[s1][x]:\\n            return s2\\n    return s1\\n\\ndef equalPad(s0,w):\\n    return s0.ljust(w,s0[-1])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5302d846be2a9189af0001e4:\\nCreate a method `sayHello`\\/`say_hello`\\/`SayHello` that takes as input a name, city, and state to welcome a person. Note that `name` will be an array consisting of one or more values that should be joined together with one space between each, and the length of the `name` array in test cases will vary.\\n\\nExample:\\n\\n```python\\nsay_hello(['John', 'Smith'], 'Phoenix', 'Arizona')\\n```\\n\\nThis example will return the string `Hello, John Smith! Welcome to Phoenix, Arizona!`\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def say_hello(name, city, state):\\n    return 'Hello, %s! Welcome to %s, %s!' % (' '.join(name), city, state)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n\\nWrite a function named `sumEvenNumbers`, taking a sequence of numbers as single parameter. Your function must return the sum of **the even values** of this sequence.\\n\\nOnly numbers without decimals like `4` or `4.0` can be even. \\n\\n## Input\\n* sequence of numbers: those numbers could be integers and\\/or floats. \\n\\n\\nFor example, considering this input value : `[4,3,1,2,5,10,6,7,9,8]`, then your function should return `30` (because `4 + 2 + 10 + 6 + 8 = 30`).\",\"targets\":\"def sum_even_numbers(seq):\\n    to_sum = [num for num in seq if num % 2 == 0]\\n    return sum(to_sum)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have an array with string digits that occurrs more than once, for example, ```arr = ['1', '2', '2', '2', '3', '3']```. How many different string numbers can be generated taking the 6 elements at a time?\\n\\nWe present the list of them below in an unsorted way:\\n``` \\n['223213', '312322', '223312', '222133', '312223', '223321', '223231', '132223', '132322', '223132', '322321', '322312', '231322', '222313', '221233', '213322', '122323', '321322', '221332', '133222', '123232', '323221', '222331', '132232', '321232', '212323', '232213', '232132', '331222', '232312', '332212', '213223', '123322', '322231', '321223', '231232', '233221', '231223', '213232', '312232', '233122', '322132', '223123', '322123', '232231', '323122', '323212', '122233', '212233', '123223', '332221', '122332', '221323', '332122', '232123', '212332', '232321', '322213', '233212', '313222']\\n``` \\nThere are ```60``` different numbers and ```122233``` is the lowest one and ```332221``` the highest of all of them.\\n\\nGiven an array, ```arr```, with string digits (from '0' to '9'), you should give the exact amount of different numbers that may be generated with the lowest and highest value but both converted into integer values, using all the digits given in the array for each generated string number.\\n\\nThe function will be called as ```proc_arr()```.\\n```python\\nproc_arr(['1', '2', '2', '3', '2', '3']) == [60, 122233, 332221]\\n```\\n\\nIf the digit '0' is present in the given array will produce string numbers with leading zeroes, that will not be not taken in account when they are converted to integers.\\n```python\\nproc_arr(['1','2','3','0','5','1','1','3']) == [3360, 1112335, 53321110]\\n```\\nYou will never receive an array with only one digit repeated n times.\\n\\nFeatures of the random tests:\\n```\\nLow performance tests:\\nNumber of tests: 100\\nArrays of length between 6 and 10\\n\\nHigher performance tests:\\nNumber of tests: 100\\nArrays of length between 30 and 100\\n```\",\"targets\":\"from collections import Counter\\nfrom operator import floordiv\\nfrom functools import reduce\\nfrom math import factorial\\n\\ndef proc_arr(arr):\\n    count = reduce(floordiv, map(factorial, Counter(arr).values()), factorial(len(arr)))\\n    mini = int(''.join(sorted(arr)))\\n    maxi = int(''.join(sorted(arr, reverse=True)))\\n    return [count, mini, maxi]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format: <protocol>:\\/\\/<domain>.ru[\\/<context>] \\n\\nwhere:  <protocol> can equal either \\\"http\\\" (without the quotes) or \\\"ftp\\\" (without the quotes),  <domain> is a non-empty string, consisting of lowercase English letters,  the \\/<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters. \\n\\nIf string <context> isn't present in the address, then the additional character \\\"\\/\\\" isn't written. Thus, the address has either two characters \\\"\\/\\\" (the ones that go before the domain), or three (an extra one in front of the context).\\n\\nWhen the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters \\\":\\\", \\\"\\/\\\", \\\".\\\".\\n\\nHelp Vasya to restore the possible address of the recorded Internet resource.\\n\\n\\n-----Input-----\\n\\nThe first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only. \\n\\nIt is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.\\n\\n\\n-----Output-----\\n\\nPrint a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.\\n\\n\\n-----Examples-----\\nInput\\nhttpsunrux\\n\\nOutput\\nhttp:\\/\\/sun.ru\\/x\\n\\nInput\\nftphttprururu\\n\\nOutput\\nftp:\\/\\/http.ru\\/ruru\\n\\n\\n\\n-----Note-----\\n\\nIn the second sample there are two more possible answers: \\\"ftp:\\/\\/httpruru.ru\\\" and \\\"ftp:\\/\\/httpru.ru\\/ru\\\".\",\"targets\":\"s=input()\\nn=len(s)\\nif s[0]=='h':\\n\\tprint(s[0:4]+':\\/\\/',end='')\\n\\tprint(s[4],end='')\\n\\tfor i in range(5,n-1):\\n\\t\\tif s[i]=='r' and s[i+1]=='u':\\n\\t\\t\\tbreak\\n\\t\\telse:\\n\\t\\t\\tprint(s[i],end='')\\n\\tprint('.'+'ru',end='')\\n\\tif i+2!=n :\\n\\t\\tprint('\\/'+s[i+2:n])\\nelse:\\n\\tprint(s[0:3]+':\\/\\/',end='')\\n\\tprint(s[3],end='')\\n\\tfor i in range(4,n-1):\\n\\t\\tif s[i]=='r' and s[i+1]=='u':\\n\\t\\t\\tbreak\\n\\t\\telse:\\n\\t\\t\\tprint(s[i],end='')\\n\\tprint('.'+'ru',end='')\\n\\tif i+2!=n :\\n\\t\\tprint('\\/'+s[i+2:n])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/swap-for-longest-repeated-character-substring\\/:\\nGiven a string text, we are allowed to swap two of the characters in the string. Find the length of the longest substring with repeated characters.\\n \\nExample 1:\\nInput: text = \\\"ababa\\\"\\nOutput: 3\\nExplanation: We can swap the first 'b' with the last 'a', or the last 'b' with the first 'a'. Then, the longest repeated character substring is \\\"aaa\\\", which its length is 3.\\n\\nExample 2:\\nInput: text = \\\"aaabaaa\\\"\\nOutput: 6\\nExplanation: Swap 'b' with the last 'a' (or the first 'a'), and we get longest repeated character substring \\\"aaaaaa\\\", which its length is 6.\\n\\nExample 3:\\nInput: text = \\\"aaabbaaa\\\"\\nOutput: 4\\n\\nExample 4:\\nInput: text = \\\"aaaaa\\\"\\nOutput: 5\\nExplanation: No need to swap, longest repeated character substring is \\\"aaaaa\\\", length is 5.\\n\\nExample 5:\\nInput: text = \\\"abcdef\\\"\\nOutput: 1\\n\\n \\nConstraints:\\n\\n1 <= text.length <= 20000\\ntext consist of lowercase English characters only.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def maxRepOpt1(self, text: str) -> int:\\n        c = Counter(text)\\n        window = Counter()\\n        i = 0\\n        ans = 1\\n        for j in range(len(text)):\\n            c[text[j]] -= 1\\n            window[text[j]] += 1\\n            if (len(window) == 1 or\\n                (len(window) == 2 and\\n                 min(window.values()) == 1 and\\n                 c[sorted(window, key=window.get)[1]] > 0)):\\n                ans = max(ans, j - i + 1)\\n            else:    \\n                c[text[i]] += 1\\n                window[text[i]] -= 1\\n                if window[text[i]] == 0:\\n                    del window[text[i]]\\n                i += 1\\n        return ans\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/unique-binary-search-trees-ii\\/:\\nGiven an integer n, generate all structurally unique BST's (binary search trees) that store values 1 ... n.\\n\\nExample:\\n\\n\\nInput: 3\\nOutput:\\n[\\n  [1,null,3,2],\\n  [3,2,null,1],\\n  [3,1,null,null,2],\\n  [2,1,3],\\n  [1,null,2,null,3]\\n]\\nExplanation:\\nThe above output corresponds to the 5 unique BST's shown below:\\n\\n   1         3     3      2      1\\n    \\\\       \\/     \\/      \\/ \\\\      \\\\\\n     3     2     1      1   3      2\\n    \\/     \\/       \\\\                 \\\\\\n   2     1         2                 3\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# Definition for a binary tree node.\\n # class TreeNode:\\n #     def __init__(self, x):\\n #         self.val = x\\n #         self.left = None\\n #         self.right = None\\n \\n class Solution:\\n     def generateTrees(self, n):\\n         \\\"\\\"\\\"\\n         :type n: int\\n         :rtype: List[TreeNode]\\n         \\\"\\\"\\\"\\n         if not n:\\n             return []\\n         all_tress = {}\\n         for r in range(1, n+1):\\n             for start in range(1, n+2-r):\\n                 end = start + r - 1\\n                 all_tress[self.to_key(start, end)] = []\\n                 if r == 1:\\n                     all_tress[str(start) + str(end)] = [TreeNode(start)]\\n                 else:\\n                     for index_root in range(start, end + 1):\\n                         left_trees = all_tress.get(self.to_key(start, index_root - 1), [None])\\n                         right_trees = all_tress.get(self.to_key(index_root + 1, end), [None])\\n                         for left_tree in left_trees:\\n                             for right_tree in right_trees:\\n                                 new_root = TreeNode(index_root)\\n                                 new_root.left = left_tree\\n                                 new_root.right = right_tree\\n                                 all_tress[self.to_key(start, end)].append(new_root)\\n         return all_tress.get(self.to_key(1, n))\\n \\n     def to_key(self, start, end):\\n         return str(start) + str(end)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn this kata we are focusing on the Numpy python package. You must write a function called `looper` which takes three integers `start, stop and number` as input and returns a list from `start` to `stop` with `number` total values in the list.  Five examples are shown below:\\n\\n```\\nlooper(1, 5, 1) = [1.0]\\nlooper(1, 5, 2) = [1.0, 5.0]\\nlooper(1, 5, 3) = [1.0, 3.0, 5.0]\\nlooper(1, 5, 4) = [1.0, 2.333333333333333, 3.6666666666666665, 5.0]\\nlooper(1, 5, 5) = [1.0, 2.0, 3.0, 4.0, 5.0]\\n```\",\"targets\":\"looper=lambda Q,S,R:[Q+(S-Q)\\/(R-1)*V for V in range(R-1)]+[S]if 1<R else[Q]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.\\n\\nYou decided to rob a town's blacksmith and you take a follower with you. You can carry at most $p$ units and your follower — at most $f$ units.\\n\\nIn the blacksmith shop, you found $cnt_s$ swords and $cnt_w$ war axes. Each sword weights $s$ units and each war axe — $w$ units. You don't care what to take, since each of them will melt into one steel ingot.\\n\\nWhat is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases.\\n\\nThe first line of each test case contains two integers $p$ and $f$ ($1 \\\\le p, f \\\\le 10^9$) — yours and your follower's capacities.\\n\\nThe second line of each test case contains two integers $cnt_s$ and $cnt_w$ ($1 \\\\le cnt_s, cnt_w \\\\le 2 \\\\cdot 10^5$) — the number of swords and war axes in the shop.\\n\\nThe third line of each test case contains two integers $s$ and $w$ ($1 \\\\le s, w \\\\le 10^9$) — the weights of each sword and each war axe.\\n\\nIt's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed $2 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.\\n\\n\\n-----Example-----\\nInput\\n3\\n33 27\\n6 10\\n5 6\\n100 200\\n10 10\\n5 5\\n1 19\\n1 3\\n19 5\\n\\nOutput\\n11\\n20\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case:   you should take $3$ swords and $3$ war axes: $3 \\\\cdot 5 + 3 \\\\cdot 6 = 33 \\\\le 33$  and your follower — $3$ swords and $2$ war axes: $3 \\\\cdot 5 + 2 \\\\cdot 6 = 27 \\\\le 27$.  $3 + 3 + 3 + 2 = 11$ weapons in total.\\n\\nIn the second test case, you can take all available weapons even without your follower's help, since $5 \\\\cdot 10 + 5 \\\\cdot 10 \\\\le 100$.\\n\\nIn the third test case, you can't take anything, but your follower can take $3$ war axes: $3...\",\"targets\":\"for t in range(int(input())):\\n    p, f = list(map(int, input().split()))\\n    cs, cw = list(map(int, input().split()))\\n    s, w = list(map(int, input().split()))\\n    res = 0\\n    if s > w:\\n        s, w = w, s\\n        cs, cw = cw, cs\\n    for ns1 in range(cs + 1):\\n        if ns1 * s > p:\\n            continue\\n        ns2 = min(cs - ns1, f \\/\\/ s)\\n        nw1 = min((p - ns1 * s) \\/\\/ w, cw)\\n        nw2 = min((f - ns2 * s) \\/\\/ w, cw - nw1)\\n        res = max(res, ns1 + ns2 + nw1 + nw2)\\n    print(res)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/758\\/A:\\nIn Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury. \\n\\nTotally in Berland there are n citizens, the welfare of each of them is estimated as the integer in a_{i} burles (burle is the currency in Berland).\\n\\nYou are the royal treasurer, which needs to count the minimum charges of the kingdom on the king's present. The king can only give money, he hasn't a power to take away them. \\n\\n\\n-----Input-----\\n\\nThe first line contains the integer n (1 ≤ n ≤ 100) — the number of citizens in the kingdom.\\n\\nThe second line contains n integers a_1, a_2, ..., a_{n}, where a_{i} (0 ≤ a_{i} ≤ 10^6) — the welfare of the i-th citizen.\\n\\n\\n-----Output-----\\n\\nIn the only line print the integer S — the minimum number of burles which are had to spend.\\n\\n\\n-----Examples-----\\nInput\\n5\\n0 1 2 3 4\\n\\nOutput\\n10\\nInput\\n5\\n1 1 0 1 1\\n\\nOutput\\n1\\nInput\\n3\\n1 3 1\\n\\nOutput\\n4\\nInput\\n1\\n12\\n\\nOutput\\n0\\n\\n\\n-----Note-----\\n\\nIn the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.\\n\\nIn the second example it is enough to give one burle to the third citizen. \\n\\nIn the third example it is necessary to give two burles to the first and the third citizens to make the welfare of citizens equal 3.\\n\\nIn the fourth example it is possible to give nothing to everyone because all citizens have 12 burles.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n\\tn = int(input())\\n\\tarr = list(map(int, input().split()))\\n\\tx = max(arr)\\n\\tprint(sum([x - i for i in arr]))\\n\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/774\\/J:\\nWell, the series which Stepan watched for a very long time, ended. In total, the series had n episodes. For each of them, Stepan remembers either that he definitely has watched it, or that he definitely hasn't watched it, or he is unsure, has he watched this episode or not. \\n\\nStepan's dissatisfaction is the maximum number of consecutive series that Stepan did not watch.\\n\\nYour task is to determine according to Stepan's memories if his dissatisfaction could be exactly equal to k.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and k (1 ≤ n ≤ 100, 0 ≤ k ≤ n) — the number of episodes in the series and the dissatisfaction which should be checked. \\n\\nThe second line contains the sequence which consists of n symbols \\\"Y\\\", \\\"N\\\" and \\\"?\\\". If the i-th symbol equals \\\"Y\\\", Stepan remembers that he has watched the episode number i. If the i-th symbol equals \\\"N\\\", Stepan remembers that he hasn't watched the epizode number i. If the i-th symbol equals \\\"?\\\", Stepan doesn't exactly remember if he has watched the episode number i or not.\\n\\n\\n-----Output-----\\n\\nIf Stepan's dissatisfaction can be exactly equal to k, then print \\\"YES\\\" (without qoutes). Otherwise print \\\"NO\\\" (without qoutes).\\n\\n\\n-----Examples-----\\nInput\\n5 2\\nNYNNY\\n\\nOutput\\nYES\\n\\nInput\\n6 1\\n????NN\\n\\nOutput\\nNO\\n\\n\\n\\n-----Note-----\\n\\nIn the first test Stepan remembers about all the episodes whether he has watched them or not. His dissatisfaction is 2, because he hasn't watch two episodes in a row — the episode number 3 and the episode number 4. The answer is \\\"YES\\\", because k = 2.\\n\\nIn the second test k = 1, Stepan's dissatisfaction is greater than or equal to 2 (because he remembers that he hasn't watch at least two episodes in a row — number 5 and number 6), even if he has watched the episodes from the first to the fourth, inclusive.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# from Crypto.Util.number import *\\n# from Crypto.PublicKey import RSA\\n# from Crypto.Cipher import PKCS1_OAEP\\n#\\n#\\n# def gcd(a, b):\\n#     if a == 0:\\n#         return b, 0, 1\\n#     d, x1, y1 = gcd(b % a, a)\\n#     x = y1 - (b \\/\\/ a) * x1\\n#     y = x1\\n#     return d, x, y\\n#\\n#\\n# def find_private_key(p, q, e):\\n#     f = (p - 1) * (q - 1)\\n#     d = gcd(e, f)[1]\\n#     while d < 0:\\n#         d += f\\n#     return d\\n#\\n#\\n# n = 114603416258617277914112950886933842277017613048768896986887063295795075651032133331342538430388087616693581335924733790772692053706860660493046367184589390096319068611843480381499933909451620838321468620579057390519217231379164202675046840772638142625114303262708400933811096588213415014292281310788830121449\\n#\\n# q = 8931970881300680082796820734365022222452747937209215859340339248013322229502496422895802649243487560690551112016430906973314030768362034269763079075131391\\n#\\n# p = 12830697477814509540399242283518279629025340392811455061638565349197540239841408191167449256086467748949090279070442786996339222196995600246150833643209239\\n#\\n# e = 78078409585916972042386784533013985111341440946219174025831418904974306682701\\n#\\n# f = 114603416258617277914112950886933842277017613048768896986887063295795075651032133331342538430388087616693581335924733790772692053706860660493046367184589368333650709496653857185436916026149769360233138599908136411614620020516694858770432777520732812669804663621317314060117126934960449656657765396876111780820\\n#\\n# d = 95617909040393155444786936446642179824041050920013801086828472351343249663960737590719979187458429568264589317317553181803837347371438624774016758221657991995265788792118497392951947899512373618098318332328397239065334523447713343639400315086378757038001615086063906730779984567240713176171007926923058722581\\n#\\n# rsa = RSA.construct((n, e, d))\\n#\\n#\\n# #key = RSA.importKey(open('11.txt', 'r').read())\\n# key = RSA.importKey(open('public_key', 'r').read())\\n#\\n# print(key.__dict__)\\n#\\n# n =...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5ab7ee556a176b1043000047:\\nMr Leicester's cheese factory is the pride of the East Midlands, but he's feeling a little blue. It's the time of the year when **the taxman is coming round to take a slice of his cheddar** - and the final thing he has to work out is how much money he's spending on his staff. Poor Mr Leicester can barely sleep he's so stressed. Can you help? \\n\\n- Mr Leicester **employs 4 staff**, who together make **10 wheels of cheese every 6 minutes**.\\n- Worker pay is calculated on **how many wheels of cheese they produce in a day**. \\n- Mr Leicester pays his staff according to the UK living wage, which is currently **£8.75p an hour**. There are **100 pence (p) to the UK pound (£)**. \\n\\nThe input for function payCheese will be provided as an array of five integers, one for each amount of cheese wheels produced each day.\\n\\nWhen the workforce don't work a nice integer number of minutes - much to the chagrin of the company accountant - Mr Leicester very generously **rounds up to the nearest hour** at the end of the week (*not the end of each day*). Which means if the workers make 574 wheels on each day of the week, they're each paid 29 hours for the week (28.699 hours rounded up) and not 30 (6 hours a day rounded up * 5).\\n\\nThe return value should be a string (with the £ included) of the **total £ of staff wages for that week.**\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\n\\ndef pay_cheese(arr):\\n    return f'L{round(math.ceil(sum(map(lambda x: x \\/ 100, arr))) * 4 * 8.75)}'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/847\\/E:\\nA game field is a strip of 1 × n square cells. In some cells there are Packmen, in some cells — asterisks, other cells are empty.\\n\\nPackman can move to neighboring cell in 1 time unit. If there is an asterisk in the target cell then Packman eats it. Packman doesn't spend any time to eat an asterisk.\\n\\nIn the initial moment of time all Packmen begin to move. Each Packman can change direction of its move unlimited number of times, but it is not allowed to go beyond the boundaries of the game field. Packmen do not interfere with the movement of other packmen; in one cell there can be any number of packmen moving in any directions.\\n\\nYour task is to determine minimum possible time after which Packmen can eat all the asterisks.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (2 ≤ n ≤ 10^5) — the length of the game field.\\n\\nThe second line contains the description of the game field consisting of n symbols. If there is symbol '.' in position i — the cell i is empty. If there is symbol '*' in position i — in the cell i contains an asterisk. If there is symbol 'P' in position i — Packman is in the cell i.\\n\\nIt is guaranteed that on the game field there is at least one Packman and at least one asterisk.\\n\\n\\n-----Output-----\\n\\nPrint minimum possible time after which Packmen can eat all asterisks.\\n\\n\\n-----Examples-----\\nInput\\n7\\n*..P*P*\\n\\nOutput\\n3\\n\\nInput\\n10\\n.**PP.*P.*\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Packman in position 4 will move to the left and will eat asterisk in position 1. He will spend 3 time units on it. During the same 3 time units Packman in position 6 will eat both of neighboring with it asterisks. For example, it can move to the left and eat asterisk in position 5 (in 1 time unit) and then move from the position 5 to the right and eat asterisk in the position 7 (in 2 time units). So in 3 time units Packmen will eat all asterisks on the game field.\\n\\nIn the second example Packman in the position 4 will move to the left and after 2 time units will eat asterisks in positions 3 and 2. Packmen...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from sys import stdin, stdout\\n\\nn = int(stdin.readline())\\ns = stdin.readline().strip()\\n\\nmins = []\\npacks = []\\n\\nfor i in range(len(s)):\\n    if s[i] == '*':\\n        mins.append(i)\\n    elif s[i] == 'P':\\n        packs.append(i)\\n\\nl, r = -1, 2 * len(s) + 1\\nwhile r - l > 1:\\n    m = (l + r) >> 1\\n    \\n    test1 = mins[:]\\n    test2 = packs[:]\\n    \\n    \\n    while test2 and test1:\\n        cnt = m\\n        pos = test2.pop()\\n        \\n        if pos > test1[-1]:\\n            while test1 and abs(pos - test1[-1]) <= cnt:\\n                cnt -= abs(pos - test1[-1])\\n                pos = test1[-1]\\n                test1.pop()\\n        else:\\n            cntl, cntr = 0, 0\\n            \\n            if abs(test1[-1] - pos) > m:\\n                break\\n            \\n            lpos = (m + pos - test1[-1]) \\/\\/ 2\\n            rpos = m - 2 * abs(test1[-1] - pos)\\n            \\n            lb, rb = -1, len(test1)\\n            while rb - lb > 1:\\n                mb = (lb + rb) >> 1\\n                \\n                if pos - test1[mb] <= lpos:\\n                    rb = mb\\n                else:\\n                    lb = mb\\n            \\n            cntl = len(test1) - rb\\n            \\n            lb, rb = -1, len(test1)\\n            while rb - lb > 1:\\n                mb = (lb + rb) >> 1\\n                \\n                if pos - test1[mb] <= rpos:\\n                    rb = mb\\n                else:\\n                    lb = mb\\n            \\n            cntr = len(test1) - rb\\n            \\n            cnt = max(cntl, cntr)\\n            while test1 and cnt:\\n                test1.pop()\\n                cnt -= 1\\n    \\n    \\n    if not test1:\\n        r = m\\n    else:\\n        l = m\\n    \\nstdout.write(str(r))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/749\\/E:\\nYou are given a permutation of integers from 1 to n. Exactly once you apply the following operation to this permutation: pick a random segment and shuffle its elements. Formally:  Pick a random segment (continuous subsequence) from l to r. All $\\\\frac{n(n + 1)}{2}$ segments are equiprobable.  Let k = r - l + 1, i.e. the length of the chosen segment. Pick a random permutation of integers from 1 to k, p_1, p_2, ..., p_{k}. All k! permutation are equiprobable.  This permutation is applied to elements of the chosen segment, i.e. permutation a_1, a_2, ..., a_{l} - 1, a_{l}, a_{l} + 1, ..., a_{r} - 1, a_{r}, a_{r} + 1, ..., a_{n} is transformed to a_1, a_2, ..., a_{l} - 1, a_{l} - 1 + p_1, a_{l} - 1 + p_2, ..., a_{l} - 1 + p_{k} - 1, a_{l} - 1 + p_{k}, a_{r} + 1, ..., a_{n}. \\n\\nInversion if a pair of elements (not necessary neighbouring) with the wrong relative order. In other words, the number of inversion is equal to the number of pairs (i, j) such that i < j and a_{i} > a_{j}. Find the expected number of inversions after we apply exactly one operation mentioned above.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 100 000) — the length of the permutation.\\n\\nThe second line contains n distinct integers from 1 to n — elements of the permutation.\\n\\n\\n-----Output-----\\n\\nPrint one real value — the expected number of inversions. Your answer will be considered correct if its absolute or relative error does not exceed 10^{ - 9}. \\n\\nNamely: let's assume that your answer is a, and the answer of the jury is b. The checker program will consider your answer correct, if $\\\\frac{|a - b|}{\\\\operatorname{max}(1, b)} \\\\leq 10^{-9}$.\\n\\n\\n-----Example-----\\nInput\\n3\\n2 3 1\\n\\nOutput\\n1.916666666666666666666666666667\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# Python3 program to count inversions using  \\n# Binary Indexed Tree  \\n  \\n# Returns sum of arr[0..index]. This function \\n# assumes that the array is preprocessed and  \\n# partial sums of array elements are stored  \\n# in BITree[].  \\ndef getSum( BITree, index): \\n    sum = 0 # Initialize result  \\n      \\n    # Traverse ancestors of BITree[index]  \\n    while (index > 0):  \\n  \\n        # Add current element of BITree to sum  \\n        sum += BITree[index]  \\n  \\n        # Move index to parent node in getSum View  \\n        index -= index & (-index)  \\n  \\n    return sum\\n  \\n# Updates a node in Binary Index Tree (BITree)  \\n# at given index in BITree. The given value \\n# 'val' is added to BITree[i] and all of its \\n# ancestors in tree.  \\ndef updateBIT(BITree, n, index, val): \\n  \\n    # Traverse all ancestors and add 'val'  \\n    while (index <= n):  \\n  \\n        # Add 'val' to current node of BI Tree  \\n        BITree[index] += val  \\n  \\n        # Update index to that of parent \\n        # in update View  \\n        index += index & (-index)  \\n  \\n# Returns count of inversions of size three  \\ndef getInvCount(arr, n): \\n  \\n    invcount = 0 # Initialize result  \\n  \\n    # Find maximum element in arrays  \\n    maxElement = max(arr) \\n  \\n    # Create a BIT with size equal to  \\n    # maxElement+1 (Extra one is used  \\n    # so that elements can be directly  \\n    # be used as index) \\n    BIT = [0] * (maxElement + 1)  \\n    for i in range(1, maxElement + 1):  \\n        BIT[i] = 0\\n    for i in range(n - 1, -1, -1): \\n        invcount += getSum(BIT, arr[i] - 1)  \\n        updateBIT(BIT, maxElement, arr[i], 1)  \\n    return invcount  \\n\\ndef getInvCountAdv(arr, n): \\n  \\n    invcount = 0 # Initialize result  \\n  \\n    # Find maximum element in arrays  \\n    maxElement = max(arr) \\n  \\n    # Create a BIT with size equal to  \\n    # maxElement+1 (Extra one is used  \\n    # so that elements can be directly  \\n    # be used as index) \\n    BIT = [0] * (maxElement + 1)  \\n    for i in range(1, maxElement + 1):  \\n        BIT[i] = 0\\n    for i in range(n - 1, -1, -1): \\n       ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an integer m as a product of integers a_1, a_2, ... a_{n} $(m = \\\\prod_{i = 1}^{n} a_{i})$. Your task is to find the number of distinct decompositions of number m into the product of n ordered positive integers.\\n\\nDecomposition into n products, given in the input, must also be considered in the answer. As the answer can be very large, print it modulo 1000000007 (10^9 + 7).\\n\\n\\n-----Input-----\\n\\nThe first line contains positive integer n (1 ≤ n ≤ 500). The second line contains space-separated integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nIn a single line print a single number k — the number of distinct decompositions of number m into n ordered multipliers modulo 1000000007 (10^9 + 7).\\n\\n\\n-----Examples-----\\nInput\\n1\\n15\\n\\nOutput\\n1\\n\\nInput\\n3\\n1 1 2\\n\\nOutput\\n3\\n\\nInput\\n2\\n5 7\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the second sample, the get a decomposition of number 2, you need any one number out of three to equal 2, and the rest to equal 1.\\n\\nIn the third sample, the possible ways of decomposing into ordered multipliers are [7,5], [5,7], [1,35], [35,1].\\n\\nA decomposition of positive integer m into n ordered multipliers is a cortege of positive integers b = {b_1, b_2, ... b_{n}} such that $m = \\\\prod_{i = 1}^{n} b_{i}$. Two decompositions b and c are considered different, if there exists index i such that b_{i} ≠ c_{i}.\",\"targets\":\"from collections import defaultdict\\nm = 1000000007\\n\\nf = [0] * 15001\\nf[0] = 1\\nfor i in range(1, 15001): f[i] = (f[i - 1] * i) % m\\n\\ndef c(n, k): return (f[n] * pow((f[k] * f[n - k]) % m, m - 2, m)) % m\\ndef prime(n):\\n    m = int(n ** 0.5) + 1\\n    t = [1] * (n + 1)\\n    for i in range(3, m):\\n        if t[i]: t[i * i :: 2 * i] = [0] * ((n - i * i) \\/\\/ (2 * i) + 1)\\n    return [2] + [i for i in range(3, n + 1, 2) if t[i]]\\n\\np = prime(31650)\\ns = defaultdict(int)\\n\\ndef g(n):\\n    for j in p:\\n        while n % j == 0:\\n            n \\/\\/= j\\n            s[j] += 1\\n        if j * j > n:\\n            s[n] += 1\\n            break\\n\\nn = int(input()) - 1\\na = list(map(int, input().split()))\\n\\nfor i in a: g(i)\\nif 1 in s: s.pop(1)\\n\\nd = 1\\nfor k in list(s.values()): d = (d * c(k + n, n)) % m\\nprint(d)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are n people and 40 types of hats labeled from 1 to 40.\\nGiven a list of list of integers hats, where hats[i] is a list of all hats preferred by the i-th person.\\nReturn the number of ways that the n people wear different hats to each other.\\nSince the answer may be too large, return it modulo 10^9 + 7.\\n \\nExample 1:\\nInput: hats = [[3,4],[4,5],[5]]\\nOutput: 1\\nExplanation: There is only one way to choose hats given the conditions. \\nFirst person choose hat 3, Second person choose hat 4 and last one hat 5.\\nExample 2:\\nInput: hats = [[3,5,1],[3,5]]\\nOutput: 4\\nExplanation: There are 4 ways to choose hats\\n(3,5), (5,3), (1,3) and (1,5)\\n\\nExample 3:\\nInput: hats = [[1,2,3,4],[1,2,3,4],[1,2,3,4],[1,2,3,4]]\\nOutput: 24\\nExplanation: Each person can choose hats labeled from 1 to 4.\\nNumber of Permutations of (1,2,3,4) = 24.\\n\\nExample 4:\\nInput: hats = [[1,2,3],[2,3,5,6],[1,3,7,9],[1,8,9],[2,5,7]]\\nOutput: 111\\n\\n \\nConstraints:\\n\\nn == hats.length\\n1 <= n <= 10\\n1 <= hats[i].length <= 40\\n1 <= hats[i][j] <= 40\\nhats[i] contains a list of unique integers.\",\"targets\":\"class Solution:\\n    def numberWays(self, hats: List[List[int]]) -> int:\\n        self.visited = 0\\n        hm = {}\\n        for n,i in enumerate(hats):\\n            for j in i:\\n                if j not in hm:\\n                    hm[j] = [n]\\n                else:\\n                    hm[j].append(n)\\n        keys = list(hm.keys())\\n        self.saved = {}\\n        def helper(index):\\n            if (index, self.visited) in self.saved:\\n                return self.saved[(index, self.visited)]\\n            \\n            if self.visited == ((1 << len(hats)) - 1):\\n                return 1\\n            if index == len(keys):\\n                return 0\\n            count = 0\\n\\n            for i in hm[keys[index]]:\\n                if not self.visited & (1 << i):\\n                    self.visited |= 1 << i\\n                    count += helper(index+1)\\n                    self.visited ^= 1 << i\\n            self.saved[(index, self.visited)] = count+ helper(index+1)\\n            return self.saved[(index, self.visited)]\\n        return helper(0) % (10 **9 + 7)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA new delivery of clothing has arrived today to the clothing store. This delivery consists of $a$ ties, $b$ scarves, $c$ vests and $d$ jackets.\\n\\nThe store does not sell single clothing items — instead, it sells suits of two types:  a suit of the first type consists of one tie and one jacket;  a suit of the second type consists of one scarf, one vest and one jacket. \\n\\nEach suit of the first type costs $e$ coins, and each suit of the second type costs $f$ coins.\\n\\nCalculate the maximum possible cost of a set of suits that can be composed from the delivered clothing items. Note that one item cannot be used in more than one suit (though some items may be left unused).\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $a$ $(1 \\\\le a \\\\le 100\\\\,000)$ — the number of ties.\\n\\nThe second line contains one integer $b$ $(1 \\\\le b \\\\le 100\\\\,000)$ — the number of scarves.\\n\\nThe third line contains one integer $c$ $(1 \\\\le c \\\\le 100\\\\,000)$ — the number of vests.\\n\\nThe fourth line contains one integer $d$ $(1 \\\\le d \\\\le 100\\\\,000)$ — the number of jackets.\\n\\nThe fifth line contains one integer $e$ $(1 \\\\le e \\\\le 1\\\\,000)$ — the cost of one suit of the first type.\\n\\nThe sixth line contains one integer $f$ $(1 \\\\le f \\\\le 1\\\\,000)$ — the cost of one suit of the second type.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the maximum total cost of some set of suits that can be composed from the delivered items. \\n\\n\\n-----Examples-----\\nInput\\n4\\n5\\n6\\n3\\n1\\n2\\n\\nOutput\\n6\\n\\nInput\\n12\\n11\\n13\\n20\\n4\\n6\\n\\nOutput\\n102\\n\\nInput\\n17\\n14\\n5\\n21\\n15\\n17\\n\\nOutput\\n325\\n\\n\\n\\n-----Note-----\\n\\nIt is possible to compose three suits of the second type in the first example, and their total cost will be $6$. Since all jackets will be used, it's impossible to add anything to this set.\\n\\nThe best course of action in the second example is to compose nine suits of the first type and eleven suits of the second type. The total cost is $9 \\\\cdot 4 + 11 \\\\cdot 6 = 102$.\",\"targets\":\"a=int(input())\\nb=int(input())\\nc=int(input())\\nd=int(input())\\ne=int(input())\\nf=int(input())\\nans=0\\nif(f>e):\\n    m=min(b,c,d)\\n    ans+=m*f\\n    d-=m\\n    m=min(d,a)\\n    ans+=m*e\\nelse:\\n    m=min(d,a)\\n    ans+=m*e\\n    d-=m\\n    m=min(b,c,d)\\n    ans+=m*f\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTake a string and return a hash with all the ascii values of the characters in the string.\\nReturns nil if the string is empty.\\nThe key is the character, and the value is the ascii value of the character.\\nRepeated characters are to be ignored and non-alphebetic characters as well.\",\"targets\":\"def char_to_ascii(s):\\n    return {ch:ord(ch) for ch in s if ch.isalpha()} if s else None\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a58d889880385c2f40000aa:\\n# Definition\\n\\nA **number** is called **_Automorphic number_** if and only if *its square ends in the same digits as the number itself*.\\n___\\n\\n# Task\\n\\n**_Given_** a **number** *determine if it Automorphic or not* .\\n___\\n\\n# Warm-up (Highly recommended)\\n\\n# [Playing With Numbers Series](https:\\/\\/www.codewars.com\\/collections\\/playing-with-numbers)\\n___\\n\\n# Notes \\n\\n* The **_number_** passed to the function is **_positive_** \\n\\n* **_Single-digit_** numbers are considered **_Automorphic number_**.\\n___\\n# Input >> Output Examples \\n\\n```\\nautoMorphic (25) -->> return \\\"Automorphic\\\" \\n```\\n## **_Explanation_**:\\n\\n* `25` squared is `625` , **_Ends with the same number's digits which are 25_** .\\n___\\n```\\nautoMorphic (13) -->> return \\\"Not!!\\\"\\n```\\n## **_Explanation_**:\\n\\n* `13` squared is `169` , **_Not ending with the same number's digits which are 69_** .\\n___ \\n```\\nautoMorphic (76) -->> return \\\"Automorphic\\\"\\n```\\n## **_Explanation_**:\\n\\n* `76` squared is `5776` , **_Ends with the same number's digits which are 76_** .\\n___\\n```\\nautoMorphic (225) -->> return \\\"Not!!\\\"\\n```\\n## **_Explanation_**:\\n\\n* `225` squared is `50625` , **_Not ending with the same number's digits which are 225_** .\\n___ \\n```\\nautoMorphic (625) -->> return \\\"Automorphic\\\"\\n```\\n## **_Explanation_**:\\n\\n* `625` squared is `390625` , **_Ends with the same number's digits which are 625_** .\\n___ \\n```\\nautoMorphic (1) -->> return \\\"Automorphic\\\"\\n```\\n## **_Explanation_**:\\n\\n* `1` squared is `1` , **_Ends with the same number's digits which are 1_** .\\n___\\n```\\nautoMorphic (6) -->> return \\\"Automorphic\\\"\\n```\\n## **_Explanation_**:\\n\\n* `6` squared is `36` , **_Ends with the same number's digits which are 6_** \\n___\\n___\\n\\n# [Playing with Numbers Series](https:\\/\\/www.codewars.com\\/collections\\/playing-with-numbers)\\n\\n# [Playing With Lists\\/Arrays Series](https:\\/\\/www.codewars.com\\/collections\\/playing-with-lists-slash-arrays)\\n\\n# [For More Enjoyable Katas](http:\\/\\/www.codewars.com\\/users\\/MrZizoScream\\/authored)\\n___\\n\\n## ALL translations are welcomed\\n\\n## Enjoy Learning !!\\n# Zizou\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def automorphic(n):\\n    end= int(str(n**2)[-len(str(n)):])\\n    return \\\"Automorphic\\\" if end==n else \\\"Not!!\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/PBK22020\\/problems\\/ITGUY22:\\nChef made two laddus with sweetness X and Y respectively. Cheffina comes and sees the chef created two laddus with different sweetness (might be same). Cheffina has the magical power to make the sweetness of laddus equal. Cheffina requires 1 unit of power to increase the sweetness of laddu by its original value i.e. 1 unit to convert Z to 2Z and 2 unit to convert Z to 3Z and so on… How many units of power does cheffina want to make the sweetness equal?\\n\\n-----Input:-----\\n- First-line will contain $T$, the number of test cases. Then the test cases follow. \\n- Each test case contains a single line of input, two integers $X, Y$. \\n\\n-----Output:-----\\nFor each test case, output in a single line answer as power required.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 10^5$\\n- $1 \\\\leq X,Y \\\\leq 10^5$\\n\\n-----Sample Input:-----\\n2\\n2 2\\n4 6\\n\\n-----Sample Output:-----\\n0\\n3\\n\\n-----EXPLANATION:-----\\nFor 1) Sweetness are same so no need to use power.\\nFor 2) \\n1st laddu\\n2 Unit power = 4 -> 12\\n2nd Laddu\\n1 Unit power = 6 -> 12\\nAfter using total 3 unit power sweetness of both laddus are same.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for i in range(int(input())):\\r\\n    def gcd(a,b):\\r\\n        if a == 0:\\r\\n            return b\\r\\n        return gcd(b % a, a)\\r\\n    \\r\\n    def lcm(a,b):\\r\\n        return (a \\/ gcd(a,b))* b\\r\\n    x,y=map(int,input().split())\\r\\n    lc=lcm(x,y)\\r\\n    x=lc\\/x\\r\\n    y=lc\\/y\\r\\n    print(int(x+y-2))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/360\\/A:\\nLevko loves array a_1, a_2, ... , a_{n}, consisting of integers, very much. That is why Levko is playing with array a, performing all sorts of operations with it. Each operation Levko performs is of one of two types:\\n\\n  Increase all elements from l_{i} to r_{i} by d_{i}. In other words, perform assignments a_{j} = a_{j} + d_{i} for all j that meet the inequation l_{i} ≤ j ≤ r_{i}.  Find the maximum of elements from l_{i} to r_{i}. That is, calculate the value $m_{i} = \\\\operatorname{max}_{j = l_{i}}^{r_{i}} a_{j}$. \\n\\nSadly, Levko has recently lost his array. Fortunately, Levko has records of all operations he has performed on array a. Help Levko, given the operation records, find at least one suitable array. The results of all operations for the given array must coincide with the record results. Levko clearly remembers that all numbers in his array didn't exceed 10^9 in their absolute value, so he asks you to find such an array.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (1 ≤ n, m ≤ 5000) — the size of the array and the number of operations in Levko's records, correspondingly.\\n\\nNext m lines describe the operations, the i-th line describes the i-th operation. The first integer in the i-th line is integer t_{i} (1 ≤ t_{i} ≤ 2) that describes the operation type. If t_{i} = 1, then it is followed by three integers l_{i}, r_{i} and d_{i} (1 ≤ l_{i} ≤ r_{i} ≤ n,  - 10^4 ≤ d_{i} ≤ 10^4) — the description of the operation of the first type. If t_{i} = 2, then it is followed by three integers l_{i}, r_{i} and m_{i} (1 ≤ l_{i} ≤ r_{i} ≤ n,  - 5·10^7 ≤ m_{i} ≤ 5·10^7) — the description of the operation of the second type.\\n\\nThe operations are given in the order Levko performed them on his array.\\n\\n\\n-----Output-----\\n\\nIn the first line print \\\"YES\\\" (without the quotes), if the solution exists and \\\"NO\\\" (without the quotes) otherwise.\\n\\nIf the solution exists, then on the second line print n integers a_1, a_2, ... , a_{n} (|a_{i}| ≤ 10^9) — the recovered array.\\n\\n\\n-----Examples-----\\nInput\\n4 5\\n1 2 3 1\\n2 1 2...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = map(int, input().split())\\na = [10**9 for _ in range(n)]\\nextra = [0 for _ in range(n)]\\nquery = list()\\nfor _ in range(m):\\n     t, l, r, x = map(int, input().split())\\n     l -= 1\\n     r -= 1\\n     query.append((t, l, r, x))\\n     if t == 1:\\n          for j in range(l, r + 1):\\n               extra[j] += x\\n     else:\\n          for j in range(l, r + 1):\\n               a[j] = min(a[j], x - extra[j])\\nextra = a.copy()\\nfor t, l, r, x in query:\\n     if t == 1:\\n          for j in range(l, r + 1):\\n               a[j] += x\\n     else:\\n          val = -10**9\\n          for j in range(l, r + 1):\\n               val = max(val, a[j])\\n          if not val == x:\\n               print('NO')\\n               return\\n\\nprint('YES')\\nfor x in extra:\\n     print(x, end=' ')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5886e082a836a691340000c3:\\n# Task\\n A rectangle with sides equal to even integers a and b is drawn on the Cartesian plane. Its center (the intersection point of its diagonals) coincides with the point (0, 0), but the sides of the rectangle are not parallel to the axes; instead, they are forming `45 degree` angles with the axes.\\n\\n How many points with integer coordinates are located inside the given rectangle (including on its sides)?\\n\\n# Example\\n\\n For `a = 6 and b = 4`, the output should be `23`\\n\\n The following picture illustrates the example, and the 23 points are marked green.\\n\\n ![](https:\\/\\/files.gitter.im\\/myjinxin2015\\/raYf\\/blob)\\n\\n# Input\\/Output\\n\\n\\n - `[input]` integer `a`\\n\\n    A positive `even` integer.\\n\\n    Constraints: `2 ≤ a ≤ 10000`.\\n\\n\\n - `[input]` integer `b`\\n\\n    A positive `even` integer.\\n\\n    Constraints: `2 ≤ b ≤ 10000`.\\n\\n\\n - `[output]` an integer\\n\\n    The number of inner points with integer coordinates.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def rectangle_rotation(a, b):\\n    b1 = b\\/\\/(2**(1\\/2))+1\\n    a1 = a\\/\\/(2**(1\\/2))+1\\n    c = a1*b1+(a1-1)*(b1-1)\\n    return c if c % 2 == 1 else c-1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1066\\/F:\\nMaksim walks on a Cartesian plane. Initially, he stands at the point $(0, 0)$ and in one move he can go to any of four adjacent points (left, right, up, down). For example, if Maksim is currently at the point $(0, 0)$, he can go to any of the following points in one move:   $(1, 0)$;  $(0, 1)$;  $(-1, 0)$;  $(0, -1)$. \\n\\nThere are also $n$ distinct key points at this plane. The $i$-th point is $p_i = (x_i, y_i)$. It is guaranteed that $0 \\\\le x_i$ and $0 \\\\le y_i$ and there is no key point $(0, 0)$.\\n\\nLet the first level points be such points that $max(x_i, y_i) = 1$, the second level points be such points that $max(x_i, y_i) = 2$ and so on. Maksim wants to visit all the key points. But he shouldn't visit points of level $i + 1$ if he does not visit all the points of level $i$. He starts visiting the points from the minimum level of point from the given set.\\n\\nThe distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is $|x_1 - x_2| + |y_1 - y_2|$ where $|v|$ is the absolute value of $v$.\\n\\nMaksim wants to visit all the key points in such a way that the total distance he walks will be minimum possible. Your task is to find this distance.\\n\\nIf you are Python programmer, consider using PyPy instead of Python when you submit your code.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of key points.\\n\\nEach of the next $n$ lines contains two integers $x_i$, $y_i$ ($0 \\\\le x_i, y_i \\\\le 10^9$) — $x$-coordinate of the key point $p_i$ and $y$-coordinate of the key point $p_i$. It is guaranteed that all the points are distinct and the point $(0, 0)$ is not in this set.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the minimum possible total distance Maksim has to travel if he needs to visit all key points in a way described above.\\n\\n\\n-----Examples-----\\nInput\\n8\\n2 2\\n1 4\\n2 3\\n3 1\\n3 4\\n1 1\\n4 3\\n1 2\\n\\nOutput\\n15\\n\\nInput\\n5\\n2 1\\n1 0\\n2 0\\n3 2\\n0 3\\n\\nOutput\\n9\\n\\n\\n\\n-----Note-----\\n\\nThe picture corresponding to the first example: [Image]\\n\\nThere is one of the possible answers of length...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n \\ndef minp():\\n\\treturn sys.stdin.readline().strip()\\n \\ndef dist(a,b):\\n\\treturn abs(a[1]-b[1])+abs(a[2]-b[2])\\n \\nn = int(minp())\\na = [None]*n\\nfor i in range(n):\\n\\tx,y = list(map(int,minp().split()))\\n\\ta[i] = (max(x,y),x,-y)\\na.sort()\\n#print(a)\\nd0 = 0\\nd1 = 0\\np0 = (0,0,0)\\np1 = (0,0,0)\\ni = 0\\nk = 1\\nwhile i < n:\\n\\tx = a[i]\\n\\txx = x[0]\\n\\tj = i + 1\\n\\twhile j < n and a[j][0] == xx:\\n\\t\\tj += 1\\n\\ty = a[j-1]\\n\\tdd = dist(x,y)\\n\\td2 = dist(p0,x)\\n\\td3 = dist(p1,x)\\n\\tD0 = min(d0+d2,d1+d3)+dd\\n\\tP0 = y\\n\\td2 = dist(p0,y)\\n\\td3 = dist(p1,y)\\n\\tD1 = min(d0+d2,d1+d3)+dd\\n\\tP1 = x\\n\\tp0 = P0\\n\\tp1 = P1\\n\\td0 = D0\\n\\td1 = D1\\n\\tk += 1\\n\\ti = j\\nprint(min(d0,d1))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPashmak has fallen in love with an attractive girl called Parmida since one year ago...\\n\\nToday, Pashmak set up a meeting with his partner in a romantic garden. Unfortunately, Pashmak has forgotten where the garden is. But he remembers that the garden looks like a square with sides parallel to the coordinate axes. He also remembers that there is exactly one tree on each vertex of the square. Now, Pashmak knows the position of only two of the trees. Help him to find the position of two remaining ones.\\n\\n\\n-----Input-----\\n\\nThe first line contains four space-separated x_1, y_1, x_2, y_2 ( - 100 ≤ x_1, y_1, x_2, y_2 ≤ 100) integers, where x_1 and y_1 are coordinates of the first tree and x_2 and y_2 are coordinates of the second tree. It's guaranteed that the given points are distinct.\\n\\n\\n-----Output-----\\n\\nIf there is no solution to the problem, print -1. Otherwise print four space-separated integers x_3, y_3, x_4, y_4 that correspond to the coordinates of the two other trees. If there are several solutions you can output any of them. \\n\\nNote that x_3, y_3, x_4, y_4 must be in the range ( - 1000 ≤ x_3, y_3, x_4, y_4 ≤ 1000).\\n\\n\\n-----Examples-----\\nInput\\n0 0 0 1\\n\\nOutput\\n1 0 1 1\\n\\nInput\\n0 0 1 1\\n\\nOutput\\n0 1 1 0\\n\\nInput\\n0 0 1 2\\n\\nOutput\\n-1\",\"targets\":\"a=[int(i) for i in input().split()]\\nx1=a[0]\\ny1=a[1]\\nx2=a[2]\\ny2=a[3]\\nl=0\\nif(x1==x2):\\n    l=abs(y1-y2)\\n    print(x1+l,y1,x1+l,y2)\\nelif(y1==y2):\\n    l=abs(x1-x2)\\n    print(x1,y1+l,x2,y1+l)\\nelif(abs(x1-x2)==abs(y1-y2)):\\n    print(x2,y1,x1,y2)\\nelse:\\n    print(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/53837b8c94c170e55f000811:\\nZonk is addictive dice game. In each round player rolls 6 dice. Then (s)he composes combinations from them. Each combination gives certain points. \\n\\nThen player can take one or more dice combinations to his hand and re-roll remaining dice or save his score. Dice in player's hand won't be taken into account in subsequent rolls.\\n\\nIf no combinations can be composed - situation is called \\\"zonk\\\". Player thrown zonk loses all points in this round and next player moves. So it's player decision when to reroll and when to stop and save his score.\\n\\nYour task is simple - just evaluate current roll and return maximum number of points can be scored from it. If no combinations can be made - function must return string ``\\\"Zonk\\\"`` (without quotes).\\n\\nThere are different variations of Zonk. In this kata, we will use most common table of combinations:\\n\\nCombinationExample rollPoints\\nStraight (1,2,3,4,5 and 6)6 3 1 2 5 41000 points\\nThree pairs of any dice2 2 4 4 1 1750 points\\nThree of 11 4 1 11000 points\\nThree of 22 3 4 2 2200 points\\nThree of 33 4 3 6 3 2300 points\\nThree of 44 4 4400 points\\nThree of 52 5 5 5 4500 points\\nThree of 66 6 2 6600 points\\nFour of a kind1 1 1 1 4 62 × Three-of-a-kind score (in example, 2000 pts)\\nFive of a kind5 5 5 4 5 53 × Three-of-a-kind score (in example, 1500 pts)\\nSix of a kind4 4 4 4 4 44 × Three-of-a-kind score (in example, 1600 pts)\\nEvery 14 3 1 2 2100 points\\nEvery 55 2 650 points\\n\\n\\nEach die cannot be used in multiple combinations the same time, so three pairs of 2, 3 and 5 will worth you only ``750`` points (for three pairs), not 850 (for three pairs and two fives). But you can select multiple combinations, ``2 2 2 1 6`` will worth you ``300`` points (200 for three-of-kind '2' plus 100 for single '1' die)\\n\\nExamples:\\n```python\\n  get_score([1,2,3]) # returns 100 = points from one 1\\n  get_score([3,4,1,1,5]) # returns 250 = points from two 1 and one 5\\n  get_score([2,3,2,3,3,2]) # returns 500 = three of 2 + three of 3\\n  get_score([1,1,1,1,1,5]) # returns 3050 = five 1 + one 5\\n  get_score([2,3,4,3,6,6])...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def get_score(dice):\\n    if all(i in dice for i in range(1, 7)):\\n        return 1000\\n    if len(dice) == 6 and all(dice.count(d) == 2 for d in set(dice)):\\n        return 750\\n    score = 0\\n    score += sum((dice.count(d)==n) * d * (n-2) * (1000 if d==1 else 100) for d in set(dice) for n in range(3, 7))\\n    score += 100 * dice.count(1) if dice.count(1) < 3 else 0\\n    score += 50 * dice.count(5) if dice.count(5) < 3 else 0\\n    return score if score else 'Zonk'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nJATC loves Banh-mi (a Vietnamese food). His affection for Banh-mi is so much that he always has it for breakfast. This morning, as usual, he buys a Banh-mi and decides to enjoy it in a special way.\\n\\nFirst, he splits the Banh-mi into $n$ parts, places them on a row and numbers them from $1$ through $n$. For each part $i$, he defines the deliciousness of the part as $x_i \\\\in \\\\{0, 1\\\\}$. JATC's going to eat those parts one by one. At each step, he chooses arbitrary remaining part and eats it. Suppose that part is the $i$-th part then his enjoyment of the Banh-mi will increase by $x_i$ and the deliciousness of all the remaining parts will also increase by $x_i$. The initial enjoyment of JATC is equal to $0$.\\n\\nFor example, suppose the deliciousness of $3$ parts are $[0, 1, 0]$. If JATC eats the second part then his enjoyment will become $1$ and the deliciousness of remaining parts will become $[1, \\\\_, 1]$. Next, if he eats the first part then his enjoyment will become $2$ and the remaining parts will become $[\\\\_, \\\\_, 2]$. After eating the last part, JATC's enjoyment will become $4$.\\n\\nHowever, JATC doesn't want to eat all the parts but to save some for later. He gives you $q$ queries, each of them consisting of two integers $l_i$ and $r_i$. For each query, you have to let him know what is the maximum enjoyment he can get if he eats all the parts with indices in the range $[l_i, r_i]$ in some order.\\n\\nAll the queries are independent of each other. Since the answer to the query could be very large, print it modulo $10^9+7$.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $q$ ($1 \\\\le n, q \\\\le 100\\\\,000$).\\n\\nThe second line contains a string of $n$ characters, each character is either '0' or '1'. The $i$-th character defines the deliciousness of the $i$-th part.\\n\\nEach of the following $q$ lines contains two integers $l_i$ and $r_i$ ($1 \\\\le l_i \\\\le r_i \\\\le n$) — the segment of the corresponding query.\\n\\n\\n-----Output-----\\n\\nPrint $q$ lines, where $i$-th of them contains a single integer — the answer to the...\",\"targets\":\"n,q = list(map(int, input().split()))\\na = input()\\nQ = []\\nfor _ in range(q):\\n    Q.append(list(map(int, input().split())))\\nd = [0]\\nab = 0\\nfor i in a:\\n    if i == '1':\\n        ab += 1\\n    d.append(ab)\\nmod = int(1e9 + 7)\\np = [1]\\ni = 1\\nfor _ in range(n):\\n    i = (i*2)%mod\\n    p.append(i)\\n    \\nfor l,r in Q:\\n    y = r-l + 1\\n    x = d[r] - d[l-1]\\n    y -= x\\n    print(((p[x]-1)*p[y])%mod)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven two strings s1 and s2, we want to visualize how different the two strings are.\\nWe will only take into account the *lowercase* letters (a to z).\\nFirst let us count the frequency of each *lowercase* letters in s1 and s2.\\n\\n`s1 = \\\"A aaaa bb c\\\"`\\n\\n`s2 = \\\"& aaa bbb c d\\\"`\\n\\n`s1 has 4 'a', 2 'b', 1 'c'`\\n\\n`s2 has 3 'a', 3 'b', 1 'c', 1 'd'`\\n\\nSo the maximum for 'a' in s1 and s2 is 4 from s1; the maximum for 'b' is 3 from s2.\\nIn the following we will not consider letters when the maximum of their occurrences\\nis less than or equal to 1.\\n\\nWe can resume the differences between s1 and s2 in the following string:\\n`\\\"1:aaaa\\/2:bbb\\\"`\\nwhere `1` in `1:aaaa` stands for string s1 and `aaaa` because the maximum for `a` is 4.\\nIn the same manner `2:bbb` stands for string s2 and `bbb` because the maximum for `b` is 3.\\n\\nThe task is to produce a string in which each *lowercase* letters of s1 or s2 appears as many times as\\nits maximum if this maximum is *strictly greater than 1*; these letters will be prefixed by the \\nnumber of the string where they appear with their maximum value and `:`. \\nIf the maximum is in s1 as well as in s2 the prefix is `=:`.\\n\\nIn the result, substrings (a substring is for example 2:nnnnn or 1:hhh; it contains the prefix) will be in decreasing order of their length and when they have the same length sorted in ascending lexicographic order (letters and digits - more precisely sorted by codepoint); the different groups will be separated by '\\/'. See examples and \\\"Example Tests\\\".\\n\\nHopefully other examples can make this clearer.\\n\\n```\\ns1 = \\\"my&friend&Paul has heavy hats! &\\\"\\ns2 = \\\"my friend John has many many friends &\\\"\\nmix(s1, s2) --> \\\"2:nnnnn\\/1:aaaa\\/1:hhh\\/2:mmm\\/2:yyy\\/2:dd\\/2:ff\\/2:ii\\/2:rr\\/=:ee\\/=:ss\\\"\\n\\ns1 = \\\"mmmmm m nnnnn y&friend&Paul has heavy hats! &\\\"\\ns2 = \\\"my frie n d Joh n has ma n y ma n y frie n ds n&\\\"\\nmix(s1, s2) --> \\\"1:mmmmmm\\/=:nnnnnn\\/1:aaaa\\/1:hhh\\/2:yyy\\/2:dd\\/2:ff\\/2:ii\\/2:rr\\/=:ee\\/=:ss\\\"\\n\\ns1=\\\"Are the kids at home? aaaaa fffff\\\"\\ns2=\\\"Yes they are here! aaaaa fffff\\\"\\nmix(s1, s2) -->...\",\"targets\":\"def filter_lowercase(character_in_s):\\n    lowercase_alphabet=[\\\"a\\\",\\\"b\\\",\\\"c\\\",\\\"d\\\",\\\"e\\\",\\\"f\\\",\\\"g\\\",\\\"h\\\",\\\"i\\\",\\\"j\\\",\\\"k\\\",\\\"l\\\",\\\"m\\\",\\n    \\\"n\\\",\\\"o\\\",\\\"p\\\",\\\"q\\\",\\\"r\\\",\\\"s\\\",\\\"t\\\",\\\"u\\\",\\\"v\\\",\\\"w\\\",\\\"x\\\",\\\"y\\\",\\\"z\\\"]\\n\\n    if(character_in_s in lowercase_alphabet):\\n        return True\\n    else:\\n        return False\\n\\ndef sort_mix(a):\\n    return len(a)\\n\\ndef order_alphabetically_ascendent(elem):\\n    if elem[:1]==\\\"=\\\":\\n        return 2\\n    elif elem[:1]==\\\"1\\\":\\n        return 0\\n    elif elem[:1]==\\\"2\\\":\\n        return 1\\n\\n\\n\\ndef mix(s1, s2):\\n    lowercase_alphabet=[\\\"a\\\",\\\"b\\\",\\\"c\\\",\\\"d\\\",\\\"e\\\",\\\"f\\\",\\\"g\\\",\\\"h\\\",\\\"i\\\",\\\"j\\\",\\\"k\\\",\\\"l\\\",\\\"m\\\",\\n    \\\"n\\\",\\\"o\\\",\\\"p\\\",\\\"q\\\",\\\"r\\\",\\\"s\\\",\\\"t\\\",\\\"u\\\",\\\"v\\\",\\\"w\\\",\\\"x\\\",\\\"y\\\",\\\"z\\\"]\\n    characters_in_s1=[]\\n    characters_in_s2=[]\\n\\n    amount_of_each_letter_in_s1=[]\\n    amount_of_each_letter_in_s2=[]\\n    where_is_maximum=[]\\n    maximum=[]\\n\\n    letters_used_with_prefix = []\\n    string_to_return=\\\"\\\"\\n\\n    #filter variables\\n    different_lengths=[]\\n    array_of_letters_with_the_same_length=[]\\n\\n\\n\\n    for character in s1:\\n        characters_in_s1.append(character)\\n    for character in s2:\\n        characters_in_s2.append(character)\\n\\n    lowercase_letters_in_s1=list(filter(filter_lowercase, characters_in_s1))\\n    lowercase_letters_in_s2=list(filter(filter_lowercase, characters_in_s2))\\n#Final parte 1: now I got two lists with the lowercase letters of each string\\n\\n#2-para cada letra del abecedario(array), comprueba cuentas hay en cada string. consigue el máximo, y de qué string(1,2). Ten variables sobre cuantas veces aparece la letra en cada string\\n\\n\\n    for alphabet_letter in lowercase_alphabet:\\n        lowercase_letters_in_s=[]\\n        i = len(amount_of_each_letter_in_s1)\\n        string_to_append=\\\"\\\"\\n\\n        amount_of_each_letter_in_s1.append(lowercase_letters_in_s1.count(alphabet_letter))\\n        lowercase_letters_in_s.append(lowercase_letters_in_s1.count(alphabet_letter))\\n\\n        amount_of_each_letter_in_s2.append(lowercase_letters_in_s2.count(alphabet_letter))\\n        lowercase_letters_in_s.append(lowercase_letters_in_s2.count(alphabet_letter))\\n\\n       ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPasha has a wooden stick of some positive integer length n. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be n. \\n\\nPasha likes rectangles but hates squares, so he wonders, how many ways are there to split a stick into four parts so that it's possible to form a rectangle using these parts, but is impossible to form a square.\\n\\nYour task is to help Pasha and count the number of such ways. Two ways to cut the stick are considered distinct if there exists some integer x, such that the number of parts of length x in the first way differ from the number of parts of length x in the second way.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a positive integer n (1 ≤ n ≤ 2·10^9) — the length of Pasha's stick.\\n\\n\\n-----Output-----\\n\\nThe output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. \\n\\n\\n-----Examples-----\\nInput\\n6\\n\\nOutput\\n1\\n\\nInput\\n20\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nThere is only one way to divide the stick in the first sample {1, 1, 2, 2}.\\n\\nFour ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work.\",\"targets\":\"n = int(input())\\nif n % 2 == 1 or n == 2 or n == 4:\\n    print(0)\\nelif n % 4 == 2:\\n    print(n \\/\\/ 4)\\nelse:\\n    print(n \\/\\/ 4 - 1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef has  $N$ boxes arranged in a line.Each box has some candies in it,say $C[i]$. Chef wants to distribute all the candies between of his friends: $A$ and $B$, in the following way:\\n$A$ starts eating candies kept in the leftmost box(box at $1$st place) and $B$ starts eating candies kept in the rightmost box(box at $N$th place). $A$ eats  candies $X$ times faster than $B$ i.e. $A$ eats $X$ candies when $B$ eats only $1$. Candies in each box can be eaten by only the person who reaches that box first. If both reach a box at the same time, then the one who has eaten from more number of BOXES till now will eat the candies in that box. If both have eaten from the same number of boxes till now ,then $A$ will eat the candies in that box.\\nFind the number of boxes finished by both $A$ and $B$.\\nNOTE:- We assume that it does not take any time to switch from one box to another.\\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase contains three lines of input.\\nThe first line of each test case contains $N$, the number of boxes.\\n- The second line of each test case contains a sequence,$C_1$ ,$C_2$ ,$C_3$ . . . $C_N$ where $C_i$ denotes the number of candies in the i-th box.  \\n- The third line of each test case contains an integer $X$ .\\n\\n-----Output:-----\\nFor each testcase, print two space separated integers in a new line - the number of boxes eaten by $A$  and  $B$ respectively. \\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $1 \\\\leq N \\\\leq 200000$\\n- $1 \\\\leq C_i \\\\leq 1000000$\\n- $1 \\\\leq X \\\\leq 10$\\n- Sum of $N$ over all test cases does not exceed $300000$\\n\\n-----Subtasks-----\\nSubtask 1(24 points):\\n- $1 \\\\leq T \\\\leq 10$\\n- $1 \\\\leq N \\\\leq 1000$\\n- $1 \\\\leq C_i \\\\leq 1000$\\n- $1 \\\\leq X \\\\leq 10$\\nSubtask 2(51 points): original constraints\\n\\n-----Sample Input:-----\\n1\\n5\\n2 8 8 2 9\\n2\\n\\n-----Sample Output:-----\\n4 1\\n\\n-----EXPLANATION:-----\\n$A$ will start eating candies in the 1st box(leftmost box having 2 candies) . $B$ will start eating candies in the  5th box(rightmost box having 9...\",\"targets\":\"t=int(input())\\nfor _ in range(t):\\n n=int(input())\\n l=list(map(int,input().split()))\\n x=int(input())\\n j=n-1\\n i=0\\n a=0\\n b=0\\n remain = 0\\n while True:\\n  if i>j:\\n   break\\n  if i==j:\\n   if remain:\\n    a+=1\\n   else:\\n    if b>a:\\n     b+=1\\n    else:\\n     a+=1\\n   break\\n   \\n  b+=1\\n  d = x*l[j]+remain\\n  while i<j:\\n   d-=l[i]\\n   if d==0:\\n    remain = 0\\n    a+=1\\n    i+=1\\n    break\\n   if d<0:\\n    remain = d+l[i]\\n    break\\n   a+=1\\n   i+=1\\n  j-=1\\n print(a,b)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/COMPILER:\\nLira is now very keen on compiler development. :) \\nShe knows that one of the most important components of a compiler, is its parser.\\nA parser is, in simple terms, a software component that processes text, and checks it's semantic correctness, or, if you prefer, if the text is properly built.\\nAs an example, in declaring and initializing an integer, in C\\/C++, you can't do something like:\\nint = x ;4\\nas the semantics of such statement is incorrect, as we all know that the datatype must precede an identifier and only afterwards should come the equal sign and the initialization value, so, the corrected statement should be:\\nint x = 4;\\nToday, Lira is concerned with an abstract instruction which is composed of the characters \\\"<\\\" and \\\">\\\" , which she will use on the design of her language, L++ :D.\\nShe is using it as an abstraction for generating XML code Tags in an easier fashion and she understood that, for an expression to be valid, a \\\"<\\\" symbol must always have a corresponding \\\">\\\" character somewhere (not necessary immediately) after it. Moreover, each \\\">\\\" symbol should correspond to exactly one \\\"<\\\" symbol.\\nSo, for instance, the instructions:\\n<<>> \\n<> \\n<><> \\nare all valid. While:\\n>> \\n><>< \\nare not.\\nGiven some expressions which represent some instructions to be analyzed by Lira's compiler, you should tell the length of the longest prefix of each of these expressions that is valid, or 0 if there's no such a prefix.\\n\\n-----Input-----\\nInput will consist of an integer T denoting the number of test cases to follow.\\nThen, T strings follow, each on a single line, representing a possible expression in L++.\\n\\n-----Output-----\\nFor each expression you should output the length of the longest prefix that is valid or 0 if there's no such a prefix. \\n\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 500\\n- 1 ≤ The length of a single expression ≤ 106\\n- The total size all the input expressions is no more than 5*106\\n\\n-----Example-----\\nInput:\\n3\\n<<>>\\n><\\n<>>>\\nOutput:\\n4\\n0\\n2\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nt=int(input())\\nfor _ in range(t):\\n    s=input()\\n    l=[]\\n    c=0\\n    flag=0\\n    for i in range(len(s)):\\n        if s[i]=='<':\\n            c+=1\\n        else:\\n            c-=1\\n        if c==0:\\n            flag=i+1\\n        if c<0:\\n            break\\n    print(flag)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/630\\/B:\\nThe city administration of IT City decided to fix up a symbol of scientific and technical progress in the city's main square, namely an indicator board that shows the effect of Moore's law in real time.\\n\\nMoore's law is the observation that the number of transistors in a dense integrated circuit doubles approximately every 24 months. The implication of Moore's law is that computer performance as function of time increases exponentially as well.\\n\\nYou are to prepare information that will change every second to display on the indicator board. Let's assume that every second the number of transistors increases exactly 1.000000011 times.\\n\\n\\n-----Input-----\\n\\nThe only line of the input contains a pair of integers n (1000 ≤ n ≤ 10 000) and t (0 ≤ t ≤ 2 000 000 000) — the number of transistors in the initial time and the number of seconds passed since the initial time.\\n\\n\\n-----Output-----\\n\\nOutput one number — the estimate of the number of transistors in a dence integrated circuit in t seconds since the initial time. The relative error of your answer should not be greater than 10^{ - 6}.\\n\\n\\n-----Examples-----\\nInput\\n1000 1000000\\n\\nOutput\\n1011.060722383550382782399454922040\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n\\na, b = [int(x) for x in input().split()]\\nprint(a * 1.000000011 ** b)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/OCT12\\/problems\\/DRGNBOOL:\\nIn the world of DragonBool there are fierce warriors called Soints. Also there are even fiercer warriors called Sofloats – the mortal enemies of Soints.\\n\\nThe power of each warrior is determined by the amount of chakra he possesses which is some positive integer. Warriors with zero level of chakra are dead warriors :) When the fight between Soint with power CI and Sofloat with power CF occurs the warrior with lower power will die and the winner will lose the amount of chakra that his enemy have possessed before the fight. So three cases are possible:\\n\\n- CI > CF. Then Sofloat will die while the new power of Soint will be CI – CF.\\n- CI < CF. Then Soint will die while the new power of Sofloat will be CF – CI.\\n- CI = CF. In this special case both warriors die.\\n\\nEach warrior (Soint or Sofloat) has his level of skills which is denoted by some positive integer. The fight between two warriors can occur only when these warriors are Soint and Sofloat of the same level. In particual, friendly fights are not allowed, i.e., a Soint cannot fight with another Soint and the same holds for Sofloats.\\n\\nLets follow the following convention to denote the warriors. A Soint of level L and power C will be denoted as (I, C, L), while Sofloat of level L and power C will be denoted as (F, C, L). Consider some examples. If A = (I, 50, 1) fights with B = (F, 20, 1), B dies and A becomes (I, 30, 1). On the other hand, (I, 50, 1) cannot fight with (F, 20, 2) as they have different levels.\\n\\nThere is a battle between Soints and Sofloats. There are N Soints and M Sofloats in all. The battle will consist of series of fights. As was mentioned above in each fight one Soint and one Sofloat of the same level take part and after the fight the warrior with lower power will die (or both will die if they have the same power). The battle proceeds as long as there exists at least one pair of warriors who can fight. The distribution of warriors by levels satisfies the following condition: for every Soint of level L there exists at least one Sofloat of the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n  t=int(input())\\n  while t :\\n    t=t-1\\n    n,m=input().split()\\n    x=100*[0]\\n    for i in range(int(n)):\\n      y=input().split()\\n      c=int(y[0])\\n      l=int(y[1])\\n      x[l-1]=x[l-1]+c\\n    z=100*[0]\\n    for i in range(int(m)):\\n      y=input().split()\\n      c=int(y[0])\\n      l=int(y[1])\\n      z[l-1]=z[l-1]+c\\n    s=0\\n    for i in range(100):\\n      if z[i]>x[i] :\\n        s=s+(z[i]-x[i])\\n    print(s)\\n    \\n\\ndef __starting_point():\\n  main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have a tree with N vertices. The i-th edge connects Vertex A_i and B_i bidirectionally.\\nTakahashi is standing at Vertex u, and Aoki is standing at Vertex v.\\nNow, they will play a game of tag as follows:\\n - 1. If Takahashi and Aoki are standing at the same vertex, the game ends. Otherwise, Takahashi moves to a vertex of his choice that is adjacent to his current vertex.\\n - 2. If Takahashi and Aoki are standing at the same vertex, the game ends. Otherwise, Aoki moves to a vertex of his choice that is adjacent to his current vertex.\\n - 3. Go back to step 1.\\nTakahashi performs his moves so that the game ends as late as possible, while Aoki performs his moves so that the game ends as early as possible.\\nFind the number of moves Aoki will perform before the end of the game if both Takahashi and Aoki know each other's position and strategy.\\nIt can be proved that the game is bound to end.\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq u,v \\\\leq N\\n - u \\\\neq v\\n - 1 \\\\leq A_i,B_i \\\\leq N\\n - The given graph is a tree.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN u v\\nA_1 B_1\\n:\\nA_{N-1} B_{N-1}\\n\\n-----Output-----\\nPrint the number of moves Aoki will perform before the end of the game.\\n\\n-----Sample Input-----\\n5 4 1\\n1 2\\n2 3\\n3 4\\n3 5\\n\\n-----Sample Output-----\\n2\\n\\nIf both players play optimally, the game will progress as follows:\\n - Takahashi moves to Vertex 3.\\n - Aoki moves to Vertex 2.\\n - Takahashi moves to Vertex 5.\\n - Aoki moves to Vertex 3.\\n - Takahashi moves to Vertex 3.\\nHere, Aoki performs two moves.\\nNote that, in each move, it is prohibited to stay at the current vertex.\",\"targets\":\"N, S, T = list(map(int, input().split()))\\nS -= 1\\nT -= 1\\n\\nedges = [[] for _ in range(N)]\\nfor _ in range(N - 1):\\n    fr, to = [int(a) - 1 for a in input().split()]\\n    edges[fr].append(to)\\n    edges[to].append(fr)\\n\\ndef calc(s):\\n    minDist = [10**18] * N\\n    minDist[s] = 0\\n    st = [s]\\n    while st:\\n        now = st.pop()\\n        d = minDist[now] + 1\\n        for to in edges[now]:\\n            if minDist[to] > d:\\n                minDist[to] = d\\n                st.append(to)\\n\\n    return minDist\\n\\nminDistS = calc(S)\\nminDistT = calc(T)\\n\\nans = 0\\nfor s, t in zip(minDistS, minDistT):\\n    if s <= t:\\n        ans = max(ans, t - 1)\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nStrings A and B are K-similar (for some non-negative integer K) if we can swap the positions of two letters in A exactly K times so that the resulting string equals B.\\nGiven two anagrams A and B, return the smallest K for which A and B are K-similar.\\nExample 1:\\nInput: A = \\\"ab\\\", B = \\\"ba\\\"\\nOutput: 1\\n\\n\\nExample 2:\\nInput: A = \\\"abc\\\", B = \\\"bca\\\"\\nOutput: 2\\n\\n\\nExample 3:\\nInput: A = \\\"abac\\\", B = \\\"baca\\\"\\nOutput: 2\\n\\n\\nExample 4:\\nInput: A = \\\"aabc\\\", B = \\\"abca\\\"\\nOutput: 2\\n\\n\\n\\nNote:\\n\\n1 <= A.length == B.length <= 20\\nA and B contain only lowercase letters from the set {'a', 'b', 'c', 'd', 'e', 'f'}\",\"targets\":\"class Solution:\\n    def kSimilarity(self, A: str, B: str) -> int:\\n        if A == B:\\n            return 0\\n        visited = set([A])\\n        q = collections.deque([A])\\n        res, n = 0, len(A)\\n        while q:\\n            res += 1\\n            qn = len(q)\\n            for _ in range(qn):\\n                s = q.popleft()\\n                i = 0\\n                while i < n and s[i] == B[i]:\\n                    i += 1\\n                for j in range(i+1, n):\\n                    if s[j] == B[j] or s[j] != B[i]:\\n                        continue\\n                    tmp = self.swap(s, i, j)\\n                    if tmp == B:\\n                        return res\\n                    if tmp not in visited:\\n                        visited.add(tmp)\\n                        q.append(tmp)\\n        return res\\n\\n    def swap(self, s: str, i: int, j: int) -> str:\\n        l = list(s)\\n        l[i], l[j] = l[j], l[i]\\n        return ''.join(l)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1056\\/E:\\nOne of Arkady's friends works at a huge radio telescope. A few decades ago the telescope has sent a signal $s$ towards a faraway galaxy. Recently they've received a response $t$ which they believe to be a response from aliens! The scientists now want to check if the signal $t$ is similar to $s$.\\n\\nThe original signal $s$ was a sequence of zeros and ones (everyone knows that binary code is the universe-wide language). The returned signal $t$, however, does not look as easy as $s$, but the scientists don't give up! They represented $t$ as a sequence of English letters and say that $t$ is similar to $s$ if you can replace all zeros in $s$ with some string $r_0$ and all ones in $s$ with some other string $r_1$ and obtain $t$. The strings $r_0$ and $r_1$ must be different and non-empty.\\n\\nPlease help Arkady's friend and find the number of possible replacements for zeros and ones (the number of pairs of strings $r_0$ and $r_1$) that transform $s$ to $t$.\\n\\n\\n-----Input-----\\n\\nThe first line contains a string $s$ ($2 \\\\le |s| \\\\le 10^5$) consisting of zeros and ones — the original signal.\\n\\nThe second line contains a string $t$ ($1 \\\\le |t| \\\\le 10^6$) consisting of lowercase English letters only — the received signal.\\n\\nIt is guaranteed, that the string $s$ contains at least one '0' and at least one '1'.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the number of pairs of strings $r_0$ and $r_1$ that transform $s$ to $t$.\\n\\nIn case there are no such pairs, print $0$.\\n\\n\\n-----Examples-----\\nInput\\n01\\naaaaaa\\n\\nOutput\\n4\\n\\nInput\\n001\\nkokokokotlin\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, the possible pairs $(r_0, r_1)$ are as follows:  \\\"a\\\", \\\"aaaaa\\\"  \\\"aa\\\", \\\"aaaa\\\"  \\\"aaaa\\\", \\\"aa\\\"  \\\"aaaaa\\\", \\\"a\\\"  \\n\\nThe pair \\\"aaa\\\", \\\"aaa\\\" is not allowed, since $r_0$ and $r_1$ must be different.\\n\\nIn the second example, the following pairs are possible:   \\\"ko\\\", \\\"kokotlin\\\"  \\\"koko\\\", \\\"tlin\\\"\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nfrom math import *\\n\\ndef minp():\\n\\treturn sys.stdin.readline().strip()\\n\\ndef mint():\\n\\treturn int(minp())\\n\\ndef mints():\\n\\treturn map(int, minp().split())\\n\\ndef add(a,b):\\n\\treturn (a+b)%1000000007\\n\\ndef sub(a,b):\\n\\treturn (a+1000000007-b)%1000000007\\n\\ndef mul(a,b):\\n\\treturn (a*b)%1000000007\\n\\np = 102367\\ns = list(map(int,minp()))\\nt = list(map(ord,minp()))\\nh = [0]*(len(t)+1)\\npp = [1]*(len(t)+1)\\nfor i in range(len(t)):\\n\\th[i+1] = add(mul(h[i], p), t[i])\\n\\tpp[i+1] = mul(pp[i], p)\\n\\ndef cmp(a, b, l):\\n\\tif a > b:\\n\\t\\ta, b = b, a\\n\\th1 = sub(h[a+l], mul(h[a], pp[l]))\\n\\th2 = sub(h[b+l], mul(h[b], pp[l]))\\n\\treturn h2 == h1\\n\\nc = [0,0]\\nidx = [-1,-1]\\nfor i in range(len(s)):\\n\\tc[s[i]] += 1\\n\\tif idx[s[i]] < 0:\\n\\t\\tidx[s[i]] = i\\nMv = max(c)\\nmv = min(c)\\nMi = c.index(Mv)\\nmi = (Mi^1)\\nlt = len(t)\\nsp = [0,0]\\nres = 0\\nfor k in range(1,lt\\/\\/Mv+1):\\n\\tl = [0,0]\\n\\tx = (lt-k*Mv)\\/\\/mv\\n\\tif x > 0 and x*mv + k*Mv == lt:\\n\\t\\tl[Mi] = k\\n\\t\\tl[mi] = x\\n\\t\\tif idx[0] < idx[1]:\\n\\t\\t\\tsp[0] = 0\\n\\t\\t\\tsp[1] = idx[1]*l[0]\\n\\t\\telse:\\n\\t\\t\\tsp[1] = 0\\n\\t\\t\\tsp[0] = idx[0]*l[1]\\n\\t\\tok = True\\n\\t\\tj = 0\\n\\t\\tfor i in range(len(s)):\\n\\t\\t\\tif not cmp(sp[s[i]], j, l[s[i]]):\\n\\t\\t\\t\\tok = False\\n\\t\\t\\t\\tbreak\\n\\t\\t\\tj += l[s[i]]\\n\\t\\tif l[0] == l[1] and cmp(sp[0], sp[1], l[0]):\\n\\t\\t\\tok = False\\n\\t\\tif ok:\\n\\t\\t\\tres += 1\\nprint(res)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1300\\/B:\\nReminder: the median of the array $[a_1, a_2, \\\\dots, a_{2k+1}]$ of odd number of elements is defined as follows: let $[b_1, b_2, \\\\dots, b_{2k+1}]$ be the elements of the array in the sorted order. Then median of this array is equal to $b_{k+1}$.\\n\\nThere are $2n$ students, the $i$-th student has skill level $a_i$. It's not guaranteed that all skill levels are distinct.\\n\\nLet's define skill level of a class as the median of skill levels of students of the class.\\n\\nAs a principal of the school, you would like to assign each student to one of the $2$ classes such that each class has odd number of students (not divisible by $2$). The number of students in the classes may be equal or different, by your choice. Every student has to be assigned to exactly one class. Among such partitions, you want to choose one in which the absolute difference between skill levels of the classes is minimized.\\n\\nWhat is the minimum possible absolute difference you can achieve?\\n\\n\\n-----Input-----\\n\\nEach test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \\\\le t \\\\le 10^4$). The description of the test cases follows.\\n\\nThe first line of each test case contains a single integer $n$ ($1 \\\\le n \\\\le 10^5$) — the number of students halved.\\n\\nThe second line of each test case contains $2n$ integers $a_1, a_2, \\\\dots, a_{2 n}$ ($1 \\\\le a_i \\\\le 10^9$) — skill levels of students.\\n\\nIt is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, output a single integer, the minimum possible absolute difference between skill levels of two classes of odd sizes.\\n\\n\\n-----Example-----\\nInput\\n3\\n1\\n1 1\\n3\\n6 5 4 1 2 3\\n5\\n13 4 20 13 2 5 8 3 17 16\\n\\nOutput\\n0\\n1\\n5\\n\\n\\n\\n-----Note-----\\n\\nIn the first test, there is only one way to partition students — one in each class. The absolute difference of the skill levels will be $|1 - 1| = 0$.\\n\\nIn the second test, one of the possible partitions is to make the first class of students with skill levels $[6, 4, 2]$, so that the skill level of the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\nfor _ in range(int(input())):\\n    n=int(input())\\n    li=list(map(int,input().split()))\\n    li.sort()\\n    print(li[n]-li[n-1])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/433\\/C:\\nRyouko is an extremely forgetful girl, she could even forget something that has just happened. So in order to remember, she takes a notebook with her, called Ryouko's Memory Note. She writes what she sees and what she hears on the notebook, and the notebook became her memory.\\n\\nThough Ryouko is forgetful, she is also born with superb analyzing abilities. However, analyzing depends greatly on gathered information, in other words, memory. So she has to shuffle through her notebook whenever she needs to analyze, which is tough work.\\n\\nRyouko's notebook consists of n pages, numbered from 1 to n. To make life (and this problem) easier, we consider that to turn from page x to page y, |x - y| pages should be turned. During analyzing, Ryouko needs m pieces of information, the i-th piece of information is on page a_{i}. Information must be read from the notebook in order, so the total number of pages that Ryouko needs to turn is $\\\\sum_{i = 1}^{m - 1}|a_{i + 1} - a_{i}|$.\\n\\nRyouko wants to decrease the number of pages that need to be turned. In order to achieve this, she can merge two pages of her notebook. If Ryouko merges page x to page y, she would copy all the information on page x to y (1 ≤ x, y ≤ n), and consequently, all elements in sequence a that was x would become y. Note that x can be equal to y, in which case no changes take place.\\n\\nPlease tell Ryouko the minimum number of pages that she needs to turn. Note she can apply the described operation at most once before the reading. Note that the answer can exceed 32-bit integers.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains two integers n and m (1 ≤ n, m ≤ 10^5).\\n\\nThe next line contains m integers separated by spaces: a_1, a_2, ..., a_{m} (1 ≤ a_{i} ≤ n).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum number of pages Ryouko needs to turn.\\n\\n\\n-----Examples-----\\nInput\\n4 6\\n1 2 3 4 3 2\\n\\nOutput\\n3\\n\\nInput\\n10 5\\n9 4 3 8 8\\n\\nOutput\\n6\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, the optimal solution is to merge page 4 to 3, after merging sequence a becomes {1, 2, 3,...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def median(a):\\n    if len(a) == 0:\\n        return 0\\n    if len(a) % 2 == 1:\\n        return a[len(a) \\/\\/ 2]\\n    else:\\n        return (a[len(a) \\/\\/ 2] + a[(len(a) \\/\\/ 2) - 1]) \\/\\/ 2\\n\\n\\ndef profit(a, old_val):\\n    a.sort()\\n    med = median(a)\\n    sum_old = 0\\n    sum_new = 0\\n    for i in a:\\n        sum_old += abs(i - old_val)\\n        sum_new += abs(i - med)\\n    return sum_old - sum_new\\n\\nn, m = [int(c) for c in input().split()]\\npages = [int(c) for c in input().split()]\\n\\ncount = {pages[0]: []}\\ncurrent_page_switches = 0\\n\\nfor i in range(1, len(pages)):\\n    cur_i = pages[i]\\n    prev_i = pages[i - 1]\\n    if not(cur_i in count):\\n        count[cur_i] = []\\n\\n    if cur_i != prev_i:\\n        count[cur_i].append(prev_i)\\n        count[prev_i].append(cur_i)\\n        current_page_switches += abs(cur_i - prev_i)\\n\\nmax_profit = 0\\n\\nfor i in count:\\n    if len(count[i]) > 0:\\n        tmp = profit(count[i], i)\\n        if tmp > max_profit:\\n            max_profit = tmp\\n\\n\\nprint(current_page_switches - max_profit)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/IPC15P3A\\/problems\\/DMSG:\\nDilku and Bhopu live in Artland. Dilku loves Bhopu and he writes a message : “iloveyou”\\non paper and wishes to send it to Bhopu. As Dilku is busy making an artwork, he asks his friend Raj to send the message to Bhopu. However Raj has a condition that he may add\\/remove some  characters and jumble the letters of the message.\\nAs Bhopu understands Dilku, she can read “iloveyou” from the message if all the characters of the string “iloveyou” are in the message received by her. Bhopu is happy if she can read “iloveyou” from the message. Otherwise, she is sad. Tell whether Bhopu is happy or sad.\\n\\n-----Input-----\\nInput contains a string S, where S is the message received by Bhopu. String S consists of only lowercase letters.\\n\\n-----Output-----\\nOutput “happy” if Bhopu is happy and “sad” if Bhopu is sad.\\n\\n-----Constraints-----\\n1 ≤ |S| ≤ 100\\nWhere |S| denotes length of message string S\\n\\n-----Example-----\\nInput 1:\\niloveyou\\n\\nOutput 1:\\nhappy\\n\\nInput 2:\\nulrvysioqjifo\\n\\nOutput 2:\\nsad\\n\\nInput 3:\\nabcvleouioydef\\n\\nOutput 3:\\nhappy\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t=\\\"iloveyou\\\"\\np=1\\ns=input()\\nfor i in t:\\n if i not in s:\\n  p=0\\n  break\\n\\n\\n\\nif p is 1 :\\n print(\\\"happy\\\")\\nelse:\\n print('sad')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1154\\/A:\\nPolycarp has guessed three positive integers $a$, $b$ and $c$. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: $a+b$, $a+c$, $b+c$ and $a+b+c$.\\n\\nYou have to guess three numbers $a$, $b$ and $c$ using given numbers. Print three guessed integers in any order.\\n\\nPay attention that some given numbers $a$, $b$ and $c$ can be equal (it is also possible that $a=b=c$).\\n\\n\\n-----Input-----\\n\\nThe only line of the input contains four positive integers $x_1, x_2, x_3, x_4$ ($2 \\\\le x_i \\\\le 10^9$) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number $x_1, x_2, x_3, x_4$.\\n\\n\\n-----Output-----\\n\\nPrint such positive integers $a$, $b$ and $c$ that four numbers written on a board are values $a+b$, $a+c$, $b+c$ and $a+b+c$ written in some order. Print $a$, $b$ and $c$ in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.\\n\\n\\n-----Examples-----\\nInput\\n3 6 5 4\\n\\nOutput\\n2 1 3\\n\\nInput\\n40 40 40 60\\n\\nOutput\\n20 20 20\\n\\nInput\\n201 101 101 200\\n\\nOutput\\n1 100 100\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"x = sorted(map(int, input().split()))\\nprint(\\\"%d %d %d\\\"%(x[-1]-x[0], x[-1]-x[1], x[-1]-x[2]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/401\\/B:\\nSereja is a coder and he likes to take part in Codesorfes rounds. However, Uzhland doesn't have good internet connection, so Sereja sometimes skips rounds.\\n\\nCodesorfes has rounds of two types: Div1 (for advanced coders) and Div2 (for beginner coders). Two rounds, Div1 and Div2, can go simultaneously, (Div1 round cannot be held without Div2) in all other cases the rounds don't overlap in time. Each round has a unique identifier — a positive integer. The rounds are sequentially (without gaps) numbered with identifiers by the starting time of the round. The identifiers of rounds that are run simultaneously are different by one, also the identifier of the Div1 round is always greater.\\n\\nSereja is a beginner coder, so he can take part only in rounds of Div2 type. At the moment he is taking part in a Div2 round, its identifier equals to x. Sereja remembers very well that he has taken part in exactly k rounds before this round. Also, he remembers all identifiers of the rounds he has taken part in and all identifiers of the rounds that went simultaneously with them. Sereja doesn't remember anything about the rounds he missed.\\n\\nSereja is wondering: what minimum and what maximum number of Div2 rounds could he have missed? Help him find these two numbers.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers: x (1 ≤ x ≤ 4000) — the round Sereja is taking part in today, and k (0 ≤ k < 4000) — the number of rounds he took part in.\\n\\nNext k lines contain the descriptions of the rounds that Sereja took part in before. If Sereja took part in one of two simultaneous rounds, the corresponding line looks like: \\\"1 num_2 num_1\\\" (where num_2 is the identifier of this Div2 round, num_1 is the identifier of the Div1 round). It is guaranteed that num_1 - num_2 = 1. If Sereja took part in a usual Div2 round, then the corresponding line looks like: \\\"2 num\\\" (where num is the identifier of this Div2 round). It is guaranteed that the identifiers of all given rounds are less than x.\\n\\n\\n-----Output-----\\n\\nPrint in a single line two integers —...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#! \\/usr\\/bin\\/env python3.3\\n\\nx, k=list(map(int, input().split()))\\na=[False]*x\\nfor i in range(k):\\n\\to=list(map(int, input().split()))\\n\\ta[o[1]]=True\\n\\tif o[0]==1: a[o[2]]=True\\ncnt1=cnt2=d=0\\nfor i in range(1,x):\\n\\tif a[i]:\\n\\t\\td=0\\n\\telse:\\n\\t\\td^=1\\n\\t\\tcnt1+=d\\n\\t\\tcnt2+=1\\nprint(cnt1, cnt2)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'.\\n\\n\\n'.' Matches any single character.\\n'*' Matches zero or more of the preceding element.\\n\\n\\nThe matching should cover the entire input string (not partial).\\n\\nNote:\\n\\n\\n       s could be empty and contains only lowercase letters a-z.\\n       p could be empty and contains only lowercase letters a-z, and characters like . or *.\\n\\n\\nExample 1:\\n\\n\\nInput:\\ns = \\\"aa\\\"\\np = \\\"a\\\"\\nOutput: false\\nExplanation: \\\"a\\\" does not match the entire string \\\"aa\\\".\\n\\n\\nExample 2:\\n\\n\\nInput:\\ns = \\\"aa\\\"\\np = \\\"a*\\\"\\nOutput: true\\nExplanation: '*' means zero or more of the precedeng element, 'a'. Therefore, by repeating 'a' once, it becomes \\\"aa\\\".\\n\\n\\nExample 3:\\n\\n\\nInput:\\ns = \\\"ab\\\"\\np = \\\".*\\\"\\nOutput: true\\nExplanation: \\\".*\\\" means \\\"zero or more (*) of any character (.)\\\".\\n\\n\\nExample 4:\\n\\n\\nInput:\\ns = \\\"aab\\\"\\np = \\\"c*a*b\\\"\\nOutput: true\\nExplanation: c can be repeated 0 times, a can be repeated 1 time. Therefore it matches \\\"aab\\\".\\n\\n\\nExample 5:\\n\\n\\nInput:\\ns = \\\"mississippi\\\"\\np = \\\"mis*is*p*.\\\"\\nOutput: false\",\"targets\":\"class Solution:\\n     def isMatch(self, s, p):\\n         \\\"\\\"\\\"\\n         :type s: str\\n         :type p: str\\n         :rtype: bool\\n         \\\"\\\"\\\"\\n         if not p and len(s) != 0:\\n             return False\\n         memo = {}\\n         def dp(i, j):\\n             if (i,j) not in memo:\\n                 if j == len(p):\\n                     res = i == len(s)\\n                 else:\\n                     # head must in s and p[j] should be s[i] or '.' \\n                     head_match = i < len(s) and p[j] in {s[i] ,'.'}\\n                     # check\\n                     if j+1 < len(p) and p[j+1] == '*':\\n                         res = dp(i, j+2) or head_match and dp(i+1, j) \\n                     else:\\n                         res = head_match and dp(i+1,j+1)\\n                 memo[(i,j)] = res\\n             return memo[(i,j)]\\n         \\n         return dp(0,0)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe problem describes the properties of a command line. The description somehow resembles the one you usually see in real operating systems. However, there are differences in the behavior. Please make sure you've read the statement attentively and use it as a formal document.\\n\\nIn the Pindows operating system a strings are the lexemes of the command line — the first of them is understood as the name of the program to run and the following lexemes are its arguments. For example, as we execute the command \\\" run.exe one, two . \\\", we give four lexemes to the Pindows command line: \\\"run.exe\\\", \\\"one,\\\", \\\"two\\\", \\\".\\\". More formally, if we run a command that can be represented as string s (that has no quotes), then the command line lexemes are maximal by inclusion substrings of string s that contain no spaces.\\n\\nTo send a string with spaces or an empty string as a command line lexeme, we can use double quotes. The block of characters that should be considered as one lexeme goes inside the quotes. Embedded quotes are prohibited — that is, for each occurrence of character \\\"\\\"\\\" we should be able to say clearly that the quotes are opening or closing. For example, as we run the command \\\"\\\"run.exe o\\\" \\\"\\\" \\\" ne, \\\" two . \\\" \\\" \\\", we give six lexemes to the Pindows command line: \\\"run.exe o\\\", \\\"\\\" (an empty string), \\\" ne, \\\", \\\"two\\\", \\\".\\\", \\\" \\\" (a single space).\\n\\nIt is guaranteed that each lexeme of the command line is either surrounded by spaces on both sides or touches the corresponding command border. One of its consequences is: the opening brackets are either the first character of the string or there is a space to the left of them.\\n\\nYou have a string that consists of uppercase and lowercase English letters, digits, characters \\\".,?!\\\"\\\" and spaces. It is guaranteed that this string is a correct OS Pindows command line string. Print all lexemes of this command line string. Consider the character \\\"\\\"\\\" to be used only in order to denote a single block of characters into one command line lexeme. In particular, the consequence is that the given...\",\"targets\":\"import re, sys, math, string, operator, functools, fractions, collections\\nimport os\\nsys.setrecursionlimit(10**7)\\ndX= [-1, 1, 0, 0,-1, 1,-1, 1]\\ndY= [ 0, 0,-1, 1, 1,-1,-1, 1]\\nRI=lambda: list(map(int,input().split()))\\nRS=lambda: input().rstrip().split()\\nmod=1e9+7\\n#################################################\\ns=input()+' '\\nans=[]\\ni,j=0,-1\\nwhile i<len(s):\\n    if s[i]==' ':\\n        if j!=-1:\\n            ans.append(s[j:i])\\n        j=-1\\n    elif s[i]==\\\"\\\\\\\"\\\":\\n        j=i+1\\n        i+=1\\n        while s[i]!=\\\"\\\\\\\"\\\":\\n            i+=1\\n        ans.append(s[j:i])\\n        j=-1\\n    else:\\n        if j==-1:\\n            j=i\\n    i+=1\\nfor i in ans:\\n    print('<'+i+'>')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nEverybody in Russia uses Gregorian calendar. In this calendar there are 31 days in January, 28 or 29 days in February (depending on whether the year is leap or not), 31 days in March, 30 days in April, 31 days in May, 30 in June, 31 in July, 31 in August, 30 in September, 31 in October, 30 in November, 31 in December.\\n\\nA year is leap in one of two cases: either its number is divisible by 4, but not divisible by 100, or is divisible by 400. For example, the following years are leap: 2000, 2004, but years 1900 and 2018 are not leap.\\n\\nIn this problem you are given n (1 ≤ n ≤ 24) integers a_1, a_2, ..., a_{n}, and you have to check if these integers could be durations in days of n consecutive months, according to Gregorian calendar. Note that these months could belong to several consecutive years. In other words, check if there is a month in some year, such that its duration is a_1 days, duration of the next month is a_2 days, and so on.\\n\\n\\n-----Input-----\\n\\nThe first line contains single integer n (1 ≤ n ≤ 24) — the number of integers.\\n\\nThe second line contains n integers a_1, a_2, ..., a_{n} (28 ≤ a_{i} ≤ 31) — the numbers you are to check.\\n\\n\\n-----Output-----\\n\\nIf there are several consecutive months that fit the sequence, print \\\"YES\\\" (without quotes). Otherwise, print \\\"NO\\\" (without quotes).\\n\\nYou can print each letter in arbitrary case (small or large).\\n\\n\\n-----Examples-----\\nInput\\n4\\n31 31 30 31\\n\\nOutput\\nYes\\n\\n\\nInput\\n2\\n30 30\\n\\nOutput\\nNo\\n\\n\\nInput\\n5\\n29 31 30 31 30\\n\\nOutput\\nYes\\n\\n\\nInput\\n3\\n31 28 30\\n\\nOutput\\nNo\\n\\n\\nInput\\n3\\n31 31 28\\n\\nOutput\\nYes\\n\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the integers can denote months July, August, September and October.\\n\\nIn the second example the answer is no, because there are no two consecutive months each having 30 days.\\n\\nIn the third example the months are: February (leap year) — March — April – May — June.\\n\\nIn the fourth example the number of days in the second month is 28, so this is February. March follows February and has 31 days, but not 30, so the answer is NO.\\n\\nIn the fifth example the...\",\"targets\":\"n = int(input())\\ns = input().split()\\na = [0] * n\\nm = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]\\nfor i in range(n):\\n  a[i] = int(s[i])\\nans = \\\"No\\\"\\nfor i in range(len(m) - n):\\n  if a == m[i:i+n]:\\n    ans = \\\"Yes\\\"\\n    break\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/PBK02020\\/problems\\/ITGUY10:\\nChef gives an integer $K$ in the input.  If the given number is beautiful binary number, print it, Else find its previous beautiful binary number. A beautiful binary number is a number whose binary representation does not contain any consecutive 1s.\\nNote: 1 is also a beautiful binary number.\\n\\n-----Input:-----\\n- First-line will contain $T$, the number of test cases. Then the test cases follow. \\n- Each test case contains a single line of input, one integer $K$. \\n\\n-----Output:-----\\nFor each test case, print a beautiful number.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 10^5$\\n- $1 \\\\leq K \\\\leq 10^5$\\n\\n-----Sample Input:-----\\n3\\n3\\n6\\n8\\n\\n-----Sample Output:-----\\n2\\n5\\n8\\n\\n-----EXPLANATION:-----\\nFor 1) 3 is not a beautiful binary number because the binary representation of 3 is \\\"11\\\" which has consecutive 1s.  hence 2 which is less than 3 is printed.\\nFor 3) 8 is already a beautiful binary number with no consecutive 1s in its binary representation. so, print 8 as it is.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"pref = []\\r\\n\\r\\nfor i in range(10 ** 5 + 10):\\r\\n    b = bin(i)[2:]\\r\\n    if not any(b[j] == b[j+1] == '1' for j in range(len(b) - 1)):\\r\\n        pref.append(i)\\r\\n    else:\\r\\n        pref.append(pref[-1])\\r\\n\\r\\nfor i in range(int(input())):\\r\\n    print(pref[int(input())])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/411\\/B:\\nThe research center Q has developed a new multi-core processor. The processor consists of n cores and has k cells of cache memory. Consider the work of this processor.\\n\\nAt each cycle each core of the processor gets one instruction: either do nothing, or the number of the memory cell (the core will write an information to the cell). After receiving the command, the core executes it immediately. Sometimes it happens that at one cycle, multiple cores try to write the information into a single cell. Unfortunately, the developers did not foresee the possibility of resolving conflicts between cores, so in this case there is a deadlock: all these cores and the corresponding memory cell are locked forever. Each of the locked cores ignores all further commands, and no core in the future will be able to record an information into the locked cell. If any of the cores tries to write an information into some locked cell, it is immediately locked.\\n\\nThe development team wants to explore the deadlock situation. Therefore, they need a program that will simulate the processor for a given set of instructions for each core within m cycles . You're lucky, this interesting work is entrusted to you. According to the instructions, during the m cycles define for each core the number of the cycle, during which it will become locked. It is believed that initially all cores and all memory cells are not locked.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers n, m, k (1 ≤ n, m, k ≤ 100). Then follow n lines describing instructions. The i-th line contains m integers: x_{i}1, x_{i}2, ..., x_{im} (0 ≤ x_{ij} ≤ k), where x_{ij} is the instruction that must be executed by the i-th core at the j-th cycle. If x_{ij} equals 0, then the corresponding instruction is «do nothing». But if x_{ij} is a number from 1 to k, then the corresponding instruction is «write information to the memory cell number x_{ij}».\\n\\nWe assume that the cores are numbered from 1 to n, the work cycles are numbered from 1 to m and the memory cells are numbered from...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m, k = map(int, input().split())\\na = [[0 for i in range(m)] for j in range(n)]\\ninf = [0 for i in range(k + 1)]\\nstat = [True for i in range(n + 1)]\\ntime = [0 for i in range(n + 1)]\\nfor i in range(n):\\n    a[i] = list(map(int, input().split()))\\nfor i in range(m):\\n    for j in range(1, n + 1):\\n        if stat[j]:\\n            current_core = inf[a[j - 1][i]]\\n            if current_core == 0 and a[j - 1][i]  != 0:\\n                inf[a[j - 1][i]] = j\\n            elif current_core == -1:\\n                stat[j], time[j] = False, i + 1\\n            elif a[j - 1][i] != 0:\\n                stat[current_core], time[current_core] = False, i + 1\\n                stat[j], time[j] = False, i + 1\\n                inf[a[j - 1][i]] = -1\\n    for p in range(len(inf)):\\n        if inf[p] != -1:\\n            inf[p] = 0\\nfor i in range(1, n + 1):\\n    print(time[i])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1419\\/D2:\\nThis is the hard version of the problem. The difference between the versions is that in the easy version all prices $a_i$ are different. You can make hacks if and only if you solved both versions of the problem.\\n\\nToday is Sage's birthday, and she will go shopping to buy ice spheres. All $n$ ice spheres are placed in a row and they are numbered from $1$ to $n$ from left to right. Each ice sphere has a positive integer price. In this version, some prices can be equal.\\n\\nAn ice sphere is cheap if it costs strictly less than two neighboring ice spheres: the nearest to the left and the nearest to the right. The leftmost and the rightmost ice spheres are not cheap. Sage will choose all cheap ice spheres and then buy only them.\\n\\nYou can visit the shop before Sage and reorder the ice spheres as you wish. Find out the maximum number of ice spheres that Sage can buy, and show how the ice spheres should be reordered.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ $(1 \\\\le n \\\\le 10^5)$ — the number of ice spheres in the shop.\\n\\nThe second line contains $n$ integers $a_1, a_2, \\\\dots, a_n$ $(1 \\\\le a_i \\\\le 10^9)$ — the prices of ice spheres.\\n\\n\\n-----Output-----\\n\\nIn the first line print the maximum number of ice spheres that Sage can buy.\\n\\nIn the second line print the prices of ice spheres in the optimal order. If there are several correct answers, you can print any of them.\\n\\n\\n-----Example-----\\nInput\\n7\\n1 3 2 2 4 5 4\\n\\nOutput\\n3\\n3 1 4 2 4 2 5 \\n\\n\\n-----Note-----\\n\\nIn the sample it's not possible to place the ice spheres in any order so that Sage would buy $4$ of them. If the spheres are placed in the order $(3, 1, 4, 2, 4, 2, 5)$, then Sage will buy one sphere for $1$ and two spheres for $2$ each.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n=int(input())\\na=list(map(int,input().split()))\\na.sort()\\nans=[0]*n\\nfor i in range(n\\/\\/2):\\n  ans[1+i*2]=a[i]\\nfor i in range(n\\/\\/2,n):\\n  ans[(i-n\\/\\/2)*2]=a[i]\\nco=0\\nfor i in range(1,n-1):\\n  if ans[i-1]>ans[i] and ans[i]<ans[i+1]:co+=1\\nprint(co)\\nprint(*ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a directed acyclic graph with n vertices and m edges. There are no self-loops or multiple edges between any pair of vertices. Graph can be disconnected.\\n\\nYou should assign labels to all vertices in such a way that:\\n\\n  Labels form a valid permutation of length n — an integer sequence such that each integer from 1 to n appears exactly once in it.  If there exists an edge from vertex v to vertex u then label_{v} should be smaller than label_{u}.  Permutation should be lexicographically smallest among all suitable. \\n\\nFind such sequence of labels to satisfy all the conditions.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integer numbers n, m (2 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^5).\\n\\nNext m lines contain two integer numbers v and u (1 ≤ v, u ≤ n, v ≠ u) — edges of the graph. Edges are directed, graph doesn't contain loops or multiple edges.\\n\\n\\n-----Output-----\\n\\nPrint n numbers — lexicographically smallest correct permutation of labels of vertices.\\n\\n\\n-----Examples-----\\nInput\\n3 3\\n1 2\\n1 3\\n3 2\\n\\nOutput\\n1 3 2 \\n\\nInput\\n4 5\\n3 1\\n4 1\\n2 3\\n3 4\\n2 4\\n\\nOutput\\n4 1 2 3 \\n\\nInput\\n5 4\\n3 1\\n2 1\\n2 3\\n4 5\\n\\nOutput\\n3 1 2 4 5\",\"targets\":\"from queue import Queue\\nimport heapq\\n\\nn, m = input().split()\\nn = int(n)\\nm = int(m)\\n\\nf = [0] * (n + 1)\\nsol = [0] * (n + 1)\\nadya = [[] for _ in range(n + 1)]\\n\\nfor i in range(m):\\n    n1, n2 = input().split()\\n    n1 = int(n1)\\n    n2 = int(n2)\\n    adya[n2].append(n1)\\n    f[n1] += 1\\n\\ncola = []\\ncnt = 0\\n\\nfor i in range(1, n + 1):\\n    if(f[i] == 0):\\n        heapq.heappush(cola, -1 * i)\\n        cnt += 1\\nnum = int(n)\\nwhile(cnt > 0):\\n    v = heapq.heappop(cola)\\n    v *= -1\\n    sol[v] = num\\n    cnt -= 1\\n    num -= 1\\n    for to in adya[v]:\\n        f[to] -= 1\\n        if(f[to] == 0):\\n            heapq.heappush(cola, -1 * to)\\n            cnt += 1\\n\\nstringOut = \\\"\\\"\\nfor i in range(1, n + 1):\\n    stringOut += str(sol[i])\\n    if(i != n):\\n        stringOut += ' '\\n        \\nprint(stringOut)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1089\\/L:\\nThe kingdom of Lazyland is the home to $n$ idlers. These idlers are incredibly lazy and create many problems to their ruler, the mighty King of Lazyland. \\n\\nToday $k$ important jobs for the kingdom ($k \\\\le n$) should be performed. Every job should be done by one person and every person can do at most one job. The King allowed every idler to choose one job they wanted to do and the $i$-th idler has chosen the job $a_i$. \\n\\nUnfortunately, some jobs may not be chosen by anyone, so the King has to persuade some idlers to choose another job. The King knows that it takes $b_i$ minutes to persuade the $i$-th idler. He asked his minister of labour to calculate the minimum total time he needs to spend persuading the idlers to get all the jobs done. Can you help him? \\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $k$ ($1 \\\\le k \\\\le n \\\\le 10^5$) — the number of idlers and the number of jobs.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\ldots, a_n$ ($1 \\\\le a_i \\\\le k$) — the jobs chosen by each idler.\\n\\nThe third line of the input contains $n$ integers $b_1, b_2, \\\\ldots, b_n$ ($1 \\\\le b_i \\\\le 10^9$) — the time the King needs to spend to persuade the $i$-th idler.\\n\\n\\n-----Output-----\\n\\nThe only line of the output should contain one number — the minimum total time the King needs to spend persuading the idlers to get all the jobs done.\\n\\n\\n-----Examples-----\\nInput\\n8 7\\n1 1 3 1 5 3 7 1\\n5 7 4 8 1 3 5 2\\n\\nOutput\\n10\\n\\nInput\\n3 3\\n3 1 2\\n5 3 4\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the optimal plan is to persuade idlers 1, 6, and 8 to do jobs 2, 4, and 6.\\n\\nIn the second example each job was chosen by some idler, so there is no need to persuade anyone.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"3\\n# -*- coding: utf-8 -*-\\n\\nimport sys\\n\\ndef rl(proc=None):\\n    if proc is not None:\\n        return proc(sys.stdin.readline())\\n    else:\\n        return sys.stdin.readline().rstrip()\\n\\ndef srl(proc=None):\\n    if proc is not None:\\n        return list(map(proc, rl().split()))\\n    else:\\n        return rl().split()\\n\\ndef main():\\n    n, k = srl(int)\\n    A = srl(int)\\n    B = srl(int)\\n    spare = []\\n    done = [-1] * k\\n    for i in range(n):\\n        task = A[i] - 1\\n        if done[task] == -1:\\n            done[task] = B[i]\\n            continue\\n        spare.append(min(done[task], B[i]))\\n        done[task] = max(done[task], B[i])\\n    spare.sort()\\n    i = 0\\n    r = 0\\n    for d in done:\\n        if d == -1:\\n            r += spare[i]\\n            i += 1\\n    print(r)\\n\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1152\\/B:\\nCat Furrier Transform is a popular algorithm among cat programmers to create longcats. As one of the greatest cat programmers ever exist, Neko wants to utilize this algorithm to create the perfect longcat.\\n\\nAssume that we have a cat with a number $x$. A perfect longcat is a cat with a number equal $2^m - 1$ for some non-negative integer $m$. For example, the numbers $0$, $1$, $3$, $7$, $15$ and so on are suitable for the perfect longcats.\\n\\nIn the Cat Furrier Transform, the following operations can be performed on $x$:  (Operation A): you select any non-negative integer $n$ and replace $x$ with $x \\\\oplus (2^n - 1)$, with $\\\\oplus$ being a bitwise XOR operator. (Operation B): replace $x$ with $x + 1$. \\n\\nThe first applied operation must be of type A, the second of type B, the third of type A again, and so on. Formally, if we number operations from one in the order they are executed, then odd-numbered operations must be of type A and the even-numbered operations must be of type B.\\n\\nNeko wants to produce perfect longcats at industrial scale, thus for each cat Neko only wants to perform at most $40$ operations. Can you help Neko writing a transformation plan?\\n\\nNote that it is not required to minimize the number of operations. You just need to use no more than $40$ operations.\\n\\n\\n-----Input-----\\n\\nThe only line contains a single integer $x$ ($1 \\\\le x \\\\le 10^6$).\\n\\n\\n-----Output-----\\n\\nThe first line should contain a single integer $t$ ($0 \\\\le t \\\\le 40$) — the number of operations to apply.\\n\\nThen for each odd-numbered operation print the corresponding number $n_i$ in it. That is, print $\\\\lceil \\\\frac{t}{2} \\\\rceil$ integers $n_i$ ($0 \\\\le n_i \\\\le 30$), denoting the replacement $x$ with $x \\\\oplus (2^{n_i} - 1)$ in the corresponding step.\\n\\nIf there are multiple possible answers, you can print any of them. It is possible to show, that there is at least one answer in the constraints of this problem.\\n\\n\\n-----Examples-----\\nInput\\n39\\n\\nOutput\\n4\\n5 3 \\nInput\\n1\\n\\nOutput\\n0\\n\\nInput\\n7\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first test, one of the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"x = int(input())\\n\\nans = []\\n\\ncnt = 0\\n\\nwhile x & (x + 1) != 0:\\n    bn = str(bin(x)[2:])\\n    cnt += 1\\n\\n    ret = -1\\n    for i in range(len(bn)):\\n        if bn[i] == '0':\\n            ret = i\\n            break\\n\\n    if ret == -1:\\n        break\\n\\n    x ^= 2 ** (len(bn) - ret) - 1\\n    ans.append(len(bn) - ret)\\n\\n    if x & (x + 1) == 0:\\n        break\\n\\n    x += 1\\n    cnt += 1\\n\\nprint(cnt)\\nif len(ans) > 0:\\n    print(' '.join(str(el) for el in ans))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/571\\/A:\\nYou are given three sticks with positive integer lengths of a, b, and c centimeters. You can increase length of some of them by some positive integer number of centimeters (different sticks can be increased by a different length), but in total by at most l centimeters. In particular, it is allowed not to increase the length of any stick.\\n\\nDetermine the number of ways to increase the lengths of some sticks so that you can form from them a non-degenerate (that is, having a positive area) triangle. Two ways are considered different, if the length of some stick is increased by different number of centimeters in them.\\n\\n\\n-----Input-----\\n\\nThe single line contains 4 integers a, b, c, l (1 ≤ a, b, c ≤ 3·10^5, 0 ≤ l ≤ 3·10^5).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the number of ways to increase the sizes of the sticks by the total of at most l centimeters, so that you can make a non-degenerate triangle from it.\\n\\n\\n-----Examples-----\\nInput\\n1 1 1 2\\n\\nOutput\\n4\\n\\nInput\\n1 2 3 1\\n\\nOutput\\n2\\n\\nInput\\n10 2 1 7\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample test you can either not increase any stick or increase any two sticks by 1 centimeter.\\n\\nIn the second sample test you can increase either the first or the second stick by one centimeter. Note that the triangle made from the initial sticks is degenerate and thus, doesn't meet the conditions.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a, b, c, l = map(int, input().split())\\nans = (l + 3) * (l + 2) \\/\\/ 2 * (l + 1) \\/\\/ 3\\nfor z in (a, b, c):\\n    s = 2 * z - a - b - c\\n    for x in range(l + 1):\\n        m = min(s + x, l - x)\\n        if m >= 0:\\n            ans -= (m + 1) * (m + 2) >> 1\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a linked list, swap every two adjacent nodes and return its head.\\n\\nExample:\\n\\n\\nGiven 1->2->3->4, you should return the list as 2->1->4->3.\\n\\nNote:\\n\\n\\n       Your algorithm should use only constant extra space.\\n       You may not modify the values in the list's nodes, only nodes itself may be changed.\",\"targets\":\"# Definition for singly-linked list.\\n class ListNode:\\n     def __init__(self, x):\\n         self.val = x\\n         self.next = None\\n \\n class Solution:\\n     def swapPairs(self, head):\\n         \\\"\\\"\\\"\\n         :type head: ListNode\\n         :rtype: ListNode\\n         \\\"\\\"\\\"\\n \\n         if head is None or head.next is None:\\n             return head\\n         else:\\n             first = head\\n             second = first.next\\n             third = second.next\\n \\n             second.next = first\\n             first.next = self.swapPairs(third)\\n             return second\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/56d46b8fda159582e100001b:\\nYou have recently discovered that horses travel in a unique pattern - they're either running (at top speed) or resting (standing still).\\n\\nHere's an example of how one particular horse might travel:\\n\\n```\\nThe horse Blaze can run at 14 metres\\/second for 60 seconds, but must then rest for 45 seconds.\\n\\nAfter 500 seconds Blaze will have traveled 4200 metres.\\n```\\n\\nYour job is to write a function that returns how long a horse will have traveled after a given time.\\n\\n####Input: \\n\\n* totalTime - How long the horse will be traveling (in seconds)\\n\\n* runTime - How long the horse can run for before having to rest (in seconds)\\n\\n* restTime - How long the horse have to rest for after running (in seconds)\\n\\n* speed - The max speed of the horse (in metres\\/second)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def travel(total_time, run_time, rest_time, speed):\\n    return speed*(run_time*((total_time)\\/\\/(run_time+rest_time))+min(run_time,total_time%(run_time+rest_time)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1041\\/B:\\nMonocarp has decided to buy a new TV set and hang it on the wall in his flat. The wall has enough free space so Monocarp can buy a TV set with screen width not greater than $a$ and screen height not greater than $b$. Monocarp is also used to TV sets with a certain aspect ratio: formally, if the width of the screen is $w$, and the height of the screen is $h$, then the following condition should be met: $\\\\frac{w}{h} = \\\\frac{x}{y}$.\\n\\nThere are many different TV sets in the shop. Monocarp is sure that for any pair of positive integers $w$ and $h$ there is a TV set with screen width $w$ and height $h$ in the shop.\\n\\nMonocarp isn't ready to choose the exact TV set he is going to buy. Firstly he wants to determine the optimal screen resolution. He has decided to try all possible variants of screen size. But he must count the number of pairs of positive integers $w$ and $h$, beforehand, such that $(w \\\\le a)$, $(h \\\\le b)$ and $(\\\\frac{w}{h} = \\\\frac{x}{y})$.\\n\\nIn other words, Monocarp wants to determine the number of TV sets having aspect ratio $\\\\frac{x}{y}$, screen width not exceeding $a$, and screen height not exceeding $b$. Two TV sets are considered different if they have different screen width or different screen height.\\n\\n\\n-----Input-----\\n\\nThe first line contains four integers $a$, $b$, $x$, $y$ ($1 \\\\le a, b, x, y \\\\le 10^{18}$) — the constraints on the screen width and height, and on the aspect ratio.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the number of different variants to choose TV screen width and screen height so that they meet the aforementioned constraints.\\n\\n\\n-----Examples-----\\nInput\\n17 15 5 3\\n\\nOutput\\n3\\n\\nInput\\n14 16 7 22\\n\\nOutput\\n0\\n\\nInput\\n4 2 6 4\\n\\nOutput\\n1\\n\\nInput\\n1000000000000000000 1000000000000000000 999999866000004473 999999822000007597\\n\\nOutput\\n1000000063\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, there are $3$ possible variants: $(5, 3)$, $(10, 6)$, $(15, 9)$.\\n\\nIn the second example, there is no TV set meeting the constraints.\\n\\nIn the third example, there is only one variant: $(3, 2)$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from fractions import gcd\\na,b,x,y = list(map(int,input().split()))\\n\\ngcd_val = gcd(x, y)\\nx \\/\\/= gcd_val\\ny \\/\\/= gcd_val\\n\\nprint(min(a\\/\\/x,b\\/\\/y))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn an infinite binary tree where every node has two children, the nodes are labelled in row order.\\nIn the odd numbered rows (ie., the first, third, fifth,...), the labelling is left to right, while in the even numbered rows (second, fourth, sixth,...), the labelling is right to left.\\n\\nGiven the label of a node in this tree, return the labels in the path from the root of the tree to the node with that label.\\n \\nExample 1:\\nInput: label = 14\\nOutput: [1,3,4,14]\\n\\nExample 2:\\nInput: label = 26\\nOutput: [1,2,6,10,26]\\n\\n \\nConstraints:\\n\\n1 <= label <= 10^6\",\"targets\":\"class Solution:\\n    def pathInZigZagTree(self, label: int) -> List[int]:\\n        i=label\\n        lst=[]\\n        while(i>=1):\\n            lst.append(i)\\n            i=i\\/\\/2\\n        n=len(lst)\\n        lst=lst[::-1]\\n        print(lst)\\n        for i in range(n):\\n            if n%2==1:\\n                if i%2==1:\\n                    lst[i]=(2**i)+(2**(i+1))-1-lst[i]\\n            else:\\n                if i%2==0:\\n                    lst[i]=(2**i)+(2**(i+1))-1-lst[i]\\n        return lst\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1324\\/B:\\nYou are given an array $a$ consisting of $n$ integers.\\n\\nYour task is to determine if $a$ has some subsequence of length at least $3$ that is a palindrome.\\n\\nRecall that an array $b$ is called a subsequence of the array $a$ if $b$ can be obtained by removing some (possibly, zero) elements from $a$ (not necessarily consecutive) without changing the order of remaining elements. For example, $[2]$, $[1, 2, 1, 3]$ and $[2, 3]$ are subsequences of $[1, 2, 1, 3]$, but $[1, 1, 2]$ and $[4]$ are not.\\n\\nAlso, recall that a palindrome is an array that reads the same backward as forward. In other words, the array $a$ of length $n$ is the palindrome if $a_i = a_{n - i - 1}$ for all $i$ from $1$ to $n$. For example, arrays $[1234]$, $[1, 2, 1]$, $[1, 3, 2, 2, 3, 1]$ and $[10, 100, 10]$ are palindromes, but arrays $[1, 2]$ and $[1, 2, 3, 1]$ are not.\\n\\nYou have to answer $t$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 100$) — the number of test cases.\\n\\nNext $2t$ lines describe test cases. The first line of the test case contains one integer $n$ ($3 \\\\le n \\\\le 5000$) — the length of $a$. The second line of the test case contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le n$), where $a_i$ is the $i$-th element of $a$.\\n\\nIt is guaranteed that the sum of $n$ over all test cases does not exceed $5000$ ($\\\\sum n \\\\le 5000$).\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer — \\\"YES\\\" (without quotes) if $a$ has some subsequence of length at least $3$ that is a palindrome and \\\"NO\\\" otherwise.\\n\\n\\n-----Example-----\\nInput\\n5\\n3\\n1 2 1\\n5\\n1 2 2 3 2\\n3\\n1 1 2\\n4\\n1 2 2 1\\n10\\n1 1 2 2 3 3 4 4 5 5\\n\\nOutput\\nYES\\nYES\\nNO\\nYES\\nNO\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case of the example, the array $a$ has a subsequence $[1, 2, 1]$ which is a palindrome.\\n\\nIn the second test case of the example, the array $a$ has two subsequences of length $3$ which are palindromes: $[2, 3, 2]$ and $[2, 2, 2]$.\\n\\nIn the third test case of the example, the array $a$ has no subsequences of length at least...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"q = int(input())\\nfor rwe in range(q):\\n\\tn = int(input())\\n\\tl = list(map(int,input().split()))\\n\\tdasie = False\\n\\td = {}\\n\\tfor i in range(n):\\n\\t\\td[l[i]] = []\\n\\tfor i in range(n):\\n\\t\\td[l[i]].append(i)\\n\\tfor elt in d:\\n\\t\\tif len(d[elt]) > 2:\\n\\t\\t\\tdasie = True\\n\\t\\t\\tbreak\\n\\t\\tif len(d[elt]) < 2:\\n\\t\\t\\tcontinue\\n\\t\\tif len(d[elt]) == 2:\\n\\t\\t\\tif d[elt][0] != d[elt][1] - 1:\\n\\t\\t\\t\\tdasie = True\\n\\tif dasie:\\n\\t\\tprint(\\\"YES\\\")\\n\\telse:\\n\\t\\tprint(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nRecently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.\\n\\nSuppose the graph G is given. Subset A of its vertices is called a vertex cover of this graph, if for each edge uv there is at least one endpoint of it in this set, i.e. $u \\\\in A$ or $v \\\\in A$ (or both).\\n\\nPari and Arya have won a great undirected graph as an award in a team contest. Now they have to split it in two parts, but both of them want their parts of the graph to be a vertex cover.\\n\\nThey have agreed to give you their graph and you need to find two disjoint subsets of its vertices A and B, such that both A and B are vertex cover or claim it's impossible. Each vertex should be given to no more than one of the friends (or you can even keep it for yourself).\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers n and m (2 ≤ n ≤ 100 000, 1 ≤ m ≤ 100 000) — the number of vertices and the number of edges in the prize graph, respectively.\\n\\nEach of the next m lines contains a pair of integers u_{i} and v_{i} (1  ≤  u_{i},  v_{i}  ≤  n), denoting an undirected edge between u_{i} and v_{i}. It's guaranteed the graph won't contain any self-loops or multiple edges.\\n\\n\\n-----Output-----\\n\\nIf it's impossible to split the graph between Pari and Arya as they expect, print \\\"-1\\\" (without quotes).\\n\\nIf there are two disjoint sets of vertices, such that both sets are vertex cover, print their descriptions. Each description must contain two lines. The first line contains a single integer k denoting the number of vertices in that vertex cover, and the second line contains k integers — the indices of vertices. Note that because of m ≥ 1, vertex cover cannot be empty.\\n\\n\\n-----Examples-----\\nInput\\n4 2\\n1 2\\n2 3\\n\\nOutput\\n1\\n2 \\n2\\n1 3 \\n\\nInput\\n3 3\\n1 2\\n2 3\\n1 3\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, you can give the vertex number 2 to Arya and vertices numbered 1 and 3 to Pari and keep vertex number 4 for yourself (or give it someone, if you wish).\\n\\nIn the second sample, there is no way...\",\"targets\":\"s = list(map(int, input().split()))\\nn, m = s[0], s[1]\\nif m == 0:\\n    print(-1)\\n    return\\ng = [[] for i in range(n)]\\n\\nfor i in range(m):\\n    s = list(map(int, input().split()))\\n    g[s[0] - 1].append(s[1] - 1)\\n    g[s[1] - 1].append(s[0] - 1)\\n\\nvc1 = []\\nvc2 = []\\ncolors = [-1 for i in range(n)]\\n\\nfor i in range(n):\\n    if colors[i] != -1:\\n        continue\\n    stack = [(i, 1)]\\n    colors[i] = 1\\n    while len(stack) > 0:\\n        s = stack.pop()\\n        if s[1] == 1:\\n            vc1.append(s[0] + 1)\\n        else:\\n            vc2.append(s[0] + 1)\\n        for j in g[s[0]]:\\n            if colors[j] == -1:\\n                stack.append((j, s[1] ^ 1))\\n                colors[j] = s[1] ^ 1\\n            elif colors[j] == s[1]:\\n                print(-1)\\n                return\\nprint(len(vc2))\\nfor i in vc2:\\n    print(i, end=' ')\\nprint(\\\"\\\\n\\\", len(vc1), sep='')\\nfor i in vc1:\\n    print(i, end=' ')\\nprint()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/773\\/A:\\nYou are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made y submissions, out of which x have been successful. Thus, your current success rate on Codeforces is equal to x \\/ y.\\n\\nYour favorite rational number in the [0;1] range is p \\/ q. Now you wonder: what is the smallest number of submissions you have to make if you want your success rate to be p \\/ q?\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases.\\n\\nEach of the next t lines contains four integers x, y, p and q (0 ≤ x ≤ y ≤ 10^9; 0 ≤ p ≤ q ≤ 10^9; y > 0; q > 0).\\n\\nIt is guaranteed that p \\/ q is an irreducible fraction.\\n\\nHacks. For hacks, an additional constraint of t ≤ 5 must be met.\\n\\n\\n-----Output-----\\n\\nFor each test case, output a single integer equal to the smallest number of submissions you have to make if you want your success rate to be equal to your favorite rational number, or -1 if this is impossible to achieve.\\n\\n\\n-----Example-----\\nInput\\n4\\n3 10 1 2\\n7 14 3 8\\n20 70 2 7\\n5 6 1 1\\n\\nOutput\\n4\\n10\\n0\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, you have to make 4 successful submissions. Your success rate will be equal to 7 \\/ 14, or 1 \\/ 2.\\n\\nIn the second example, you have to make 2 successful and 8 unsuccessful submissions. Your success rate will be equal to 9 \\/ 24, or 3 \\/ 8.\\n\\nIn the third example, there is no need to make any new submissions. Your success rate is already equal to 20 \\/ 70, or 2 \\/ 7.\\n\\nIn the fourth example, the only unsuccessful submission breaks your hopes of having the success rate equal to 1.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def gcd(a, b):\\n    if b == 0:\\n        return a\\n    else:\\n        return gcd(b, a % b)\\n\\nclass solution:\\n    def __init__(self, a=0, b=0):\\n        self.x = a\\n        self.y = b\\n\\ndef eu (a, b, sol):\\n    if a == 0:\\n        sol.x = 0\\n        sol.y = 1\\n        return b\\n    sol2 = solution()\\n    d = eu (b%a, a, sol2)\\n    sol.x = sol2.y - (b \\/\\/ a) * sol2.x\\n    sol.y = sol2.x\\n    return d\\n\\n\\ndef find_any_solution (a, b, c, sol):\\n    g = eu(abs(a), abs(b), sol)\\n    if c % g != 0:\\n        return -1\\n    sol.x *= c \\/\\/ g\\n    sol.y *= c \\/\\/ g\\n    if (a < 0):\\n        sol.x *= -1\\n    if (b < 0):\\n        sol.y *= -1\\n    return g\\n\\n\\ndef shift_solution (sol, a, b, cnt):\\n    sol.x += cnt * b\\n    sol.y -= cnt * a\\n\\n\\ndef find_all_solution(a, b, c, minx, maxx, miny, maxy):\\n    sol = solution()\\n    g = find_any_solution(a, b, c, sol)\\n    if g == -1:\\n        return (-1, -1)\\n\\n    a \\/\\/= g\\n    b \\/\\/= g\\n\\n    sign_a = 1\\n    if a < 0:\\n        sign_a = -1\\n    sign_b = 1\\n    if b < 0:\\n        sign_b = -1\\n\\n    shift_solution(sol, a, b, (minx - sol.x) \\/\\/ b)\\n    if sol.x < minx:\\n        shift_solution (sol, a, b, sign_b)\\n    if sol.x > maxx:\\n        return (-1, -1)\\n    lx1 = sol.x\\n\\n    shift_solution (sol, a, b, (maxx - sol.x) \\/\\/ b)\\n    if sol.x > maxx:\\n        shift_solution (sol, a, b, -sign_b)\\n    rx1 = sol.x\\n\\n    shift_solution (sol, a, b, - (miny - sol.y) \\/\\/ a)\\n    if sol.y < miny:\\n        shift_solution (sol, a, b, -sign_a)\\n    if sol.y > maxy:\\n        return (-1, -1)\\n    lx2 = sol.x\\n\\n    shift_solution (sol, a, b, - (maxy - sol.y) \\/\\/ a)\\n    if sol.y > maxy:\\n        shift_solution (sol, a, b, sign_a)\\n    rx2 = sol.x\\n\\n    if lx2 > rx2:\\n        lx2, rx2 = rx2, lx2\\n    lx = max (lx1, lx2)\\n    rx = min (rx1, rx2)\\n\\n    if lx > rx:\\n        return (-1, -1)\\n    return (lx, rx)\\n\\ndef solve():\\n    s = input().split()\\n    x = int(s[0])\\n    y = int(s[1])\\n    p = int(s[2])\\n    q = int(s[3])\\n\\n    # x, y, p, q = 3, 10, 1, 2\\n \\n    if p == 0:\\n        if x == 0:\\n            return 0\\n        else:\\n            return -1\\n    if q == p:\\n        if x == y:\\n           ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/BIGPIZA:\\nDid you know that the people of America eat around 100 acres of pizza per day ? Having read this fact on internet, two chefs from the Elephant city, Arjuna and Bhima are set to make pizza popular in India. They organized a social awareness camp, where N people ( other than these two ) sit around a large pizza. To make it more interesting, they make some pairs among these N people and the two persons in a pair, feed each other.\\n\\nEach person should be a part of at most one pair and most importantly, to make feeding easy, any two pairs should not cross each other ( see figure for more clarity ). Arjuna and Bhima decided to play a game on making the pairs. In his turn, a player makes a pair ( selects two persons, as long as its valid ) and this pair start feeding each other. Arjuna and Bhima take turns alternately, by making a pair in each turn, and they  play optimally ( see Notes for more clarity ). The one who can not make a pair in his turn, loses. Given N, find who wins the game, if Arjuna starts first. \\n\\n-----Notes-----\\n- 'Optimally' means, if there is a possible move a person can take in his turn that can make him win finally, he will always take that. You can assume both are very intelligent. \\n\\n-----Input-----\\nFirst line contains an integer T ( number of test cases, around 1000 ). Each of the next T lines contains an integer N ( 2 <= N <= 10000 )\\n\\n-----Output-----\\nFor each test case, output the name of the winner ( either \\\"Arjuna\\\" or \\\"Bhima\\\" ( without quotes ) ) in a new line.\\n\\n-----Example-----\\nInput:\\n4\\n2\\n4\\n5\\n6\\n\\nOutput:\\nArjuna\\nArjuna\\nBhima\\nArjuna\\n\\nExplanation:\\n\\nLet the people around the table are numbered 1, 2, ... , N in clock-wise order as shown in the image \\n\\nCase 1 : N = 2. Only two persons and Arjuna makes the only possible pair (1,2)\\n\\nCase 2 : N = 4. Arjuna can make the pair (1,3). Bhima can not make any more pairs ( without crossing the pair (1,3) )\\n\\nCase 3 : N = 5. No matter which pair Arjuna makes first, Bhima can always make one more pair, and Arjuna can not make any further\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a= [0, 0, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 0, 5, 2, 2, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 2, 7, 4, 0, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 2, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7, 4, 8, 1, 1, 2, 0, 3, 1, 1, 0, 3, 3, 2, 2, 4, 4, 5, 5, 9, 3, 3, 0, 1, 1, 3, 0, 2, 1, 1, 0, 4, 5, 3, 7,...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven two integers dividend and divisor, divide two integers without using multiplication, division and mod operator.\\n\\nReturn the quotient after dividing dividend by divisor.\\n\\nThe integer division should truncate toward zero.\\n\\nExample 1:\\n\\n\\nInput: dividend = 10, divisor = 3\\nOutput: 3\\n\\nExample 2:\\n\\n\\nInput: dividend = 7, divisor = -3\\nOutput: -2\\n\\nNote:\\n\\n\\n       Both dividend and divisor will be 32-bit signed integers.\\n       The divisor will never be 0.\\n       Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. For the purpose of this problem, assume that your function returns 231 − 1 when the division result overflows.\",\"targets\":\"class Solution:\\n     def divide(self, dividend, divisor):\\n         \\\"\\\"\\\"\\n         :type dividend: int\\n         :type divisor: int\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         positive = (dividend < 0) is (divisor < 0)\\n         dividend, divisor, div = abs(dividend), abs(divisor), abs(divisor)\\n         res = 0\\n         q = 1\\n         while dividend >= divisor:\\n                 dividend -= div\\n                 res += q\\n                 q += q\\n                 div += div\\n                 if dividend < div:\\n                     div = divisor\\n                     q = 1\\n         if not positive:\\n             res = -res\\n         return min(max(-2147483648, res), 2147483647)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/JLUG2020\\/problems\\/BRKTBRK:\\nFor her next karate demonstration, Ada will break some bricks.\\nAda stacked three bricks on top of each other. Initially, their widths (from top to bottom) are W1,W2,W3.\\nAda's strength is S. Whenever she hits a stack of bricks, consider the largest k≥0 such that the sum of widths of the topmost k bricks does not exceed S; the topmost k bricks break and are removed from the stack. Before each hit, Ada may also decide to reverse the current stack of bricks, with no cost.\\nFind the minimum number of hits Ada needs in order to break all bricks if she performs the reversals optimally. You are not required to minimise the number of reversals.\\nInput\\nThe first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.\\nThe first and only line of each test case contains four space-separated integers S, W1, W2 and W3.Output\\nFor each test case, print a single line containing one integer ― the minimum required number of hits.Constraints\\n- 1≤T≤64\\n- 1≤S≤8\\n- 1≤Wi≤2 for each valid i\\nit is guaranteed that Ada can break all bricksExample Input\\n\\n3\\n\\n3 1 2 2\\n\\n2 1 1 1\\n\\n3 2 2 1\\nExample Output\\n\\n2\\n\\n2\\n\\n2\\nExplanation\\n\\nExample case 1:\\n\\nAda can reverse the stack and then hit it two times. Before the first hit, the widths of bricks in the stack (from top to bottom) are (2,2,1). After the first hit, the topmost brick breaks and the stack becomes (2,1). The second hit breaks both remaining bricks.\\n\\nIn this particular case, it is also possible to hit the stack two times without reversing. Before the first hit, it is (1,2,2). The first hit breaks the two bricks at the top (so the stack becomes (2)) and the second hit breaks the last brick.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nt=int(input())\\nfor _ in range(t):\\n a=[int(x) for x in input().split()]\\n q=0\\n c=0\\n for i in range(1,4):\\n  if(q+a[i]<=a[0]):\\n   q=q+a[i]\\n   c+=1\\n  else:\\n   q=0\\n if(c==0):\\n  print(1)\\n else:\\n  print(c)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/975\\/C:\\nIvar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.\\n\\nIvar has $n$ warriors, he places them on a straight line in front of the main gate, in a way that the $i$-th warrior stands right after $(i-1)$-th warrior. The first warrior leads the attack.\\n\\nEach attacker can take up to $a_i$ arrows before he falls to the ground, where $a_i$ is the $i$-th warrior's strength.\\n\\nLagertha orders her warriors to shoot $k_i$ arrows during the $i$-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute $t$, they will all be standing to fight at the end of minute $t$.\\n\\nThe battle will last for $q$ minutes, after each minute you should tell Ivar what is the number of his standing warriors.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $q$ ($1 \\\\le n, q \\\\leq 200\\\\,000$) — the number of warriors and the number of minutes in the battle.\\n\\nThe second line contains $n$ integers $a_1, a_2, \\\\ldots, a_n$ ($1 \\\\leq a_i \\\\leq 10^9$) that represent the warriors' strengths.\\n\\nThe third line contains $q$ integers $k_1, k_2, \\\\ldots, k_q$ ($1 \\\\leq k_i \\\\leq 10^{14}$), the $i$-th of them represents Lagertha's order at the $i$-th minute: $k_i$ arrows will attack the warriors.\\n\\n\\n-----Output-----\\n\\nOutput $q$ lines, the $i$-th of them is the number of standing warriors after the $i$-th minute.\\n\\n\\n-----Examples-----\\nInput\\n5 5\\n1 2 1 2 1\\n3 10 1 1 1\\n\\nOutput\\n3\\n5\\n4\\n4\\n3\\n\\nInput\\n4 4\\n1 2 3 4\\n9 1 10 6\\n\\nOutput\\n1\\n4\\n4\\n1\\n\\n\\n\\n-----Note-----\\n\\nIn the first example:   after the 1-st minute, the 1-st and 2-nd warriors die.  after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 — all warriors are alive.  after the 3-rd minute, the 1-st warrior...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#!\\/usr\\/bin\\/env python3\\n\\nimport bisect\\n\\n[n, q] = list(map(int, input().strip().split()))\\nais = list(map(int, input().strip().split()))\\nkis = list(map(int, input().strip().split()))\\n\\niais = [0 for _ in range(n + 1)]\\nfor i in range(n):\\n\\tiais[i + 1] = iais[i] + ais[i]\\n\\n\\ns = 0\\ntot = iais[-1]\\nr = 0\\nfor k in kis:\\n\\ts += k\\n\\tif s >= tot:\\n\\t\\tprint (n)\\n\\t\\ts = 0\\n\\t\\tr = 0\\n\\telse:\\n\\t\\tr = bisect.bisect_right(iais, s, r) - 1\\n\\t\\tprint(n - r)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/400\\/B:\\nInna likes sweets and a game called the \\\"Candy Matrix\\\". Today, she came up with the new game \\\"Candy Matrix 2: Reload\\\".\\n\\nThe field for the new game is a rectangle table of size n × m. Each line of the table contains one cell with a dwarf figurine, one cell with a candy, the other cells of the line are empty. The game lasts for several moves. During each move the player should choose all lines of the matrix where dwarf is not on the cell with candy and shout \\\"Let's go!\\\". After that, all the dwarves from the chosen lines start to simultaneously move to the right. During each second, each dwarf goes to the adjacent cell that is located to the right of its current cell. The movement continues until one of the following events occurs:\\n\\n  some dwarf in one of the chosen lines is located in the rightmost cell of his row;  some dwarf in the chosen lines is located in the cell with the candy. \\n\\nThe point of the game is to transport all the dwarves to the candy cells.\\n\\nInna is fabulous, as she came up with such an interesting game. But what about you? Your task is to play this game optimally well. Specifically, you should say by the given game field what minimum number of moves the player needs to reach the goal of the game.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers n and m (1 ≤ n ≤ 1000; 2 ≤ m ≤ 1000). \\n\\nNext n lines each contain m characters — the game field for the \\\"Candy Martix 2: Reload\\\". Character \\\"*\\\" represents an empty cell of the field, character \\\"G\\\" represents a dwarf and character \\\"S\\\" represents a candy. The matrix doesn't contain other characters. It is guaranteed that each line contains exactly one character \\\"G\\\" and one character \\\"S\\\".\\n\\n\\n-----Output-----\\n\\nIn a single line print a single integer — either the minimum number of moves needed to achieve the aim of the game, or -1, if the aim cannot be achieved on the given game field.\\n\\n\\n-----Examples-----\\nInput\\n3 4\\n*G*S\\nG**S\\n*G*S\\n\\nOutput\\n2\\n\\nInput\\n1 3\\nS*G\\n\\nOutput\\n-1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"h, w = list(map(int, input().split()))\\n\\nans = set()\\ngood = True\\nfor i in range(h):\\n    s = input()\\n    pg = -1\\n    ps = -1\\n    for j in range(w):\\n        if s[j] == 'G':\\n            pg = j\\n        elif s[j] == 'S':\\n            ps = j\\n    if ps < pg:\\n        good = False\\n    ans.add(ps - pg)\\n    \\nif not good:\\n    print(-1)\\nelse:\\n    print(len(ans))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1249\\/B1:\\nThe only difference between easy and hard versions is constraints.\\n\\nThere are $n$ kids, each of them is reading a unique book. At the end of any day, the $i$-th kid will give his book to the $p_i$-th kid (in case of $i = p_i$ the kid will give his book to himself). It is guaranteed that all values of $p_i$ are distinct integers from $1$ to $n$ (i.e. $p$ is a permutation). The sequence $p$ doesn't change from day to day, it is fixed.\\n\\nFor example, if $n=6$ and $p=[4, 6, 1, 3, 5, 2]$ then at the end of the first day the book of the $1$-st kid will belong to the $4$-th kid, the $2$-nd kid will belong to the $6$-th kid and so on. At the end of the second day the book of the $1$-st kid will belong to the $3$-th kid, the $2$-nd kid will belong to the $2$-th kid and so on.\\n\\nYour task is to determine the number of the day the book of the $i$-th child is returned back to him for the first time for every $i$ from $1$ to $n$.\\n\\nConsider the following example: $p = [5, 1, 2, 4, 3]$. The book of the $1$-st kid will be passed to the following kids:  after the $1$-st day it will belong to the $5$-th kid,  after the $2$-nd day it will belong to the $3$-rd kid,  after the $3$-rd day it will belong to the $2$-nd kid,  after the $4$-th day it will belong to the $1$-st kid. \\n\\nSo after the fourth day, the book of the first kid will return to its owner. The book of the fourth kid will return to him for the first time after exactly one day.\\n\\nYou have to answer $q$ independent queries.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $q$ ($1 \\\\le q \\\\le 200$) — the number of queries. Then $q$ queries follow.\\n\\nThe first line of the query contains one integer $n$ ($1 \\\\le n \\\\le 200$) — the number of kids in the query. The second line of the query contains $n$ integers $p_1, p_2, \\\\dots, p_n$ ($1 \\\\le p_i \\\\le n$, all $p_i$ are distinct, i.e. $p$ is a permutation), where $p_i$ is the kid which will get the book of the $i$-th kid.\\n\\n\\n-----Output-----\\n\\nFor each query, print the answer on it: $n$ integers $a_1, a_2, \\\\dots,...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"tc = int(input())\\n\\nwhile tc > 0:\\n\\ttc -= 1\\n\\tn = int(input())\\n\\tp = [0] + list(map(int, input().split()))\\n\\n\\tans = [0] * (n + 1)\\n\\tmk = [False] * (n + 1)\\n\\n\\tfor i in range(1 , n + 1):\\n\\t\\tif not mk[i]:\\n\\t\\t\\tsz = 1\\n\\t\\t\\tcurr = p[i]\\n\\t\\t\\tmk[i] = True\\n\\t\\t\\twhile curr != i:\\n\\t\\t\\t\\tsz += 1\\n\\t\\t\\t\\tmk[curr] = True\\n\\t\\t\\t\\tcurr = p[curr]\\n\\n\\t\\t\\tans[i] = sz\\n\\t\\t\\tcurr = p[i]\\n\\t\\t\\twhile curr != i:\\n\\t\\t\\t\\tans[curr] = sz\\n\\t\\t\\t\\tcurr = p[curr]\\n\\n\\tprint(\\\" \\\".join([str(x) for x in ans[1:]]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/294\\/B:\\nShaass has n books. He wants to make a bookshelf for all his books. He wants the bookshelf's dimensions to be as small as possible. The thickness of the i-th book is t_{i} and its pages' width is equal to w_{i}. The thickness of each book is either 1 or 2. All books have the same page heights. $1$ \\n\\nShaass puts the books on the bookshelf in the following way. First he selects some of the books and put them vertically. Then he puts the rest of the books horizontally above the vertical books. The sum of the widths of the horizontal books must be no more than the total thickness of the vertical books. A sample arrangement of the books is depicted in the figure. [Image] \\n\\nHelp Shaass to find the minimum total thickness of the vertical books that we can achieve.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains an integer n, (1 ≤ n ≤ 100). Each of the next n lines contains two integers t_{i} and w_{i} denoting the thickness and width of the i-th book correspondingly, (1 ≤ t_{i} ≤ 2, 1 ≤ w_{i} ≤ 100).\\n\\n\\n-----Output-----\\n\\nOn the only line of the output print the minimum total thickness of the vertical books that we can achieve.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 12\\n1 3\\n2 15\\n2 5\\n2 1\\n\\nOutput\\n5\\n\\nInput\\n3\\n1 10\\n2 1\\n2 4\\n\\nOutput\\n3\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\na = list(tuple(map(int, input().split())) for i in range(n))\\ns = sum(t for t, w in a)\\na = [(t \\/ w, t, t + w) for t, w in a]\\na.sort(reverse = True)\\nd, i = s, 0\\nwhile d >= 0:\\n    s -= a[i][1]\\n    d -= a[i][2]\\n    i += 1\\ni -= 1\\ns += a[i][1]\\nd += a[i][2]\\nif a[i][1] == 2:\\n    j = i + 1\\n    while j < n and a[j][1] == 2: j += 1\\n    if j < n and d >= a[j][2]:\\n        i = 0\\n        s -= 1\\nif i > 0: \\n    i -= 1\\n    if a[i][1] == 1:\\n        d += a[i][2]\\n        j = i + 1\\n        while j < n and a[j][1] == 1: j += 1\\n        if j < n and d >= a[j][2]: s -= 1\\nprint(s)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou have been appointed as the designer for your school's computer network.\\nIn total, there are N computers in the class, and M computer-to-computer connections need to be made. Also, there are three mandatory conditions the design should fulfill.\\nThe first requirement is that any computer in the network should be able to communicate with any other computer through the connections, possibly, through some other computers.\\nNetwork attacks are possible, so the second requirement is that even if any one computer from the network gets disabled so that the rest of the computers are unable to communicate with it, the rest of the computers can still communicate with each other. In other words, the first requirement still holds for any subset of (N-1) computers.\\nThe third requirement is that there shouldn't be any irrelevant connections in the network. We will call a connection irrelevant if and only if after its' removal, the above two requirements are still held.\\nGiven N, M, please build a network with N computers and M connections, or state that it is impossible.\\n\\n-----Input-----\\nThe first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows.\\nThe first and only line of each test case contains a pair of space-separated integers N and M denoting the number of computers and the number of connections.\\n\\n-----Output-----\\nOutput T blocks.\\nIf it is impossible to construct a network with the given parameters for the corresponding test case, output just -1 -1. Otherwise, output M lines, each of which contains a space-separated pairs of integers denoting the IDs of the computers that should be connected. Note that multiple connections between any pair of computers and connections connecting a computer to itself are implicitly not allowed due to the third requirement.\\n\\n-----Constraints-----\\n\\n- 1 ≤ T ≤ 1000\\n- 1 ≤ M ≤ N * (N - 1) \\/ 2\\n- 1 ≤ Sum of all N ≤ 1000\\n- Subtask 1 (21 point): 1 ≤ N ≤ 4\\n- Subtask 2 (79 points): 1 ≤ N ≤ 100\\n\\n-----Example-----\\nInput:2\\n10 1\\n5...\",\"targets\":\"t = int(input())\\nfor _ in range(0,t):\\n n,m = input().split()\\n n,m = int(n),int(m)\\n if m!=n:\\n  print(\\\"-1 -1\\\")\\n else:\\n  for i in range(0,n):\\n   if i+2<=n : print(i+1,i+2)\\n   else : print(i+1,\\\"1\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nКак известно, в теплую погоду многие жители крупных городов пользуются сервисами городского велопроката. Вот и Аркадий сегодня будет добираться от школы до дома, используя городские велосипеды.\\n\\nШкола и дом находятся на одной прямой улице, кроме того, на той же улице есть n точек, где можно взять велосипед в прокат или сдать его. Первый велопрокат находится в точке x_1 километров вдоль улицы, второй — в точке x_2 и так далее, n-й велопрокат находится в точке x_{n}. Школа Аркадия находится в точке x_1 (то есть там же, где и первый велопрокат), а дом — в точке x_{n} (то есть там же, где и n-й велопрокат). Известно, что x_{i} < x_{i} + 1 для всех 1 ≤ i < n.\\n\\nСогласно правилам пользования велопроката, Аркадий может брать велосипед в прокат только на ограниченное время, после этого он должен обязательно вернуть его в одной из точек велопроката, однако, он тут же может взять новый велосипед, и отсчет времени пойдет заново. Аркадий может брать не более одного велосипеда в прокат одновременно. Если Аркадий решает взять велосипед в какой-то точке проката, то он сдаёт тот велосипед, на котором он до него доехал, берёт ровно один новый велосипед и продолжает на нём своё движение.\\n\\nЗа отведенное время, независимо от выбранного велосипеда, Аркадий успевает проехать не больше k километров вдоль улицы. \\n\\nОпределите, сможет ли Аркадий доехать на велосипедах от школы до дома, и если да, то какое минимальное число раз ему необходимо будет взять велосипед в прокат, включая первый велосипед? Учтите, что Аркадий не намерен сегодня ходить пешком.\\n\\n\\n-----Входные данные-----\\n\\nВ первой строке следуют два целых числа n и k (2 ≤ n ≤ 1 000, 1 ≤ k ≤ 100 000) — количество велопрокатов и максимальное расстояние, которое Аркадий может проехать на одном велосипеде.\\n\\nВ следующей строке следует последовательность целых чисел x_1, x_2, ..., x_{n} (0 ≤ x_1 < x_2 < ... < x_{n} ≤ 100 000) — координаты точек, в которых находятся велопрокаты. Гарантируется, что координаты велопрокатов заданы в порядке возрастания.\\n\\n\\n-----Выходные данные-----\\n\\nЕсли...\",\"targets\":\"a = input().split()\\nn, k = int(a[0]), int(a[1])\\nsharings = []\\ns = 0\\ncoords = input().split()\\nfor i in range(n):\\n    coord = int(coords[i])\\n    sharings.append(coord)\\n    if i != 0 and sharings[i - 1] + k < coord:\\n        s = 1\\nif s != 1:\\n    c = 1\\n    j = 1\\n    i = 0\\n    while j < n - 1:\\n        if sharings[i] + k < sharings[j + 1]:\\n            c += 1\\n            i = j\\n        j += 1\\n    print(c)\\nelse:\\n    print(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOleg's favorite subjects are History and Math, and his favorite branch of mathematics is division.\\n\\nTo improve his division skills, Oleg came up with $t$ pairs of integers $p_i$ and $q_i$ and for each pair decided to find the greatest integer $x_i$, such that:   $p_i$ is divisible by $x_i$;  $x_i$ is not divisible by $q_i$.  Oleg is really good at division and managed to find all the answers quickly, how about you?\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $t$ ($1 \\\\le t \\\\le 50$) — the number of pairs.\\n\\nEach of the following $t$ lines contains two integers $p_i$ and $q_i$ ($1 \\\\le p_i \\\\le 10^{18}$; $2 \\\\le q_i \\\\le 10^{9}$) — the $i$-th pair of integers.\\n\\n\\n-----Output-----\\n\\nPrint $t$ integers: the $i$-th integer is the largest $x_i$ such that $p_i$ is divisible by $x_i$, but $x_i$ is not divisible by $q_i$.\\n\\nOne can show that there is always at least one value of $x_i$ satisfying the divisibility conditions for the given constraints.\\n\\n\\n-----Example-----\\nInput\\n3\\n10 4\\n12 6\\n179 822\\n\\nOutput\\n10\\n4\\n179\\n\\n\\n\\n-----Note-----\\n\\nFor the first pair, where $p_1 = 10$ and $q_1 = 4$, the answer is $x_1 = 10$, since it is the greatest divisor of $10$ and $10$ is not divisible by $4$.\\n\\nFor the second pair, where $p_2 = 12$ and $q_2 = 6$, note that   $12$ is not a valid $x_2$, since $12$ is divisible by $q_2 = 6$;  $6$ is not valid $x_2$ as well: $6$ is also divisible by $q_2 = 6$.  The next available divisor of $p_2 = 12$ is $4$, which is the answer, since $4$ is not divisible by $6$.\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nfor f in range(int(input())):\\n    p,q=list(map(int,input().split()))\\n    d=2\\n    facs=[]\\n    facsm=[]\\n    while q>=d*d:\\n        if q%d==0:\\n            facs.append(d)\\n            x=0\\n            while q%d==0:\\n                x+=1\\n                q\\/\\/=d\\n            facsm.append(x-1)\\n        d+=1\\n    if q>1:\\n        facs.append(q)\\n        facsm.append(0)\\n    mc=p\\n    pc=p\\n    for i in range(len(facs)):\\n        x=0\\n        while pc%facs[i]==0:\\n            x+=1\\n            pc\\/\\/=facs[i]\\n        mc=min(mc,facs[i]**(x-min(x,facsm[i])))\\n    p\\/\\/=mc\\n    print(p)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc125\\/tasks\\/abc125_c:\\nThere are N integers, A_1, A_2, ..., A_N, written on the blackboard.\\nYou will choose one of them and replace it with an integer of your choice between 1 and 10^9 (inclusive), possibly the same as the integer originally written.\\nFind the maximum possible greatest common divisor of the N integers on the blackboard after your move.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 2 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq A_i \\\\leq 10^9\\n\\n-----Output-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 A_2 ... A_N\\n\\n-----Output-----\\nPrint the maximum possible greatest common divisor of the N integers on the blackboard after your move.\\n\\n-----Sample Input-----\\n3\\n7 6 8\\n\\n-----Sample Output-----\\n2\\n\\nIf we replace 7 with 4, the greatest common divisor of the three integers on the blackboard will be 2, which is the maximum possible value.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\nN = int(input())\\nList = list(map(int,input().split()))\\nL=[0]*N\\nR=[0]*N\\nfor i in range(1,N):\\n  L[i] = math.gcd(L[i-1],List[i-1])\\n  R[-i-1] = math.gcd(R[-i],List[-i])\\nans = 0\\nfor i in range(N):\\n  ans = max(ans,math.gcd(L[i],R[i]))\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/59ca8246d751df55cc00014c:\\nA hero is on his way to the castle to complete his mission. However, he's been told that the castle is surrounded with a couple of powerful dragons! each dragon takes 2 bullets to be defeated, our hero has no idea how many bullets he should carry.. Assuming he's gonna grab a specific given number of bullets and move forward to fight another specific given number of dragons, will he survive?\\n\\nReturn True if yes, False otherwise :)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def hero(bullets, dragons):\\n\\n    def teki(dragons):\\n        return 2*dragons\\n\\n    if bullets > teki(dragons):\\n        return True\\n    else:\\n        if bullets == teki(dragons):\\n            return True\\n        else:\\n            return False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLittle Petya likes arrays that consist of non-negative integers a lot. Recently his mom has presented him one such array consisting of n elements. Petya immediately decided to find there a segment of consecutive elements, such that the xor of all numbers from this segment was maximal possible. Help him with that.\\n\\nThe xor operation is the bitwise exclusive \\\"OR\\\", that is denoted as \\\"xor\\\" in Pascal and \\\"^\\\" in C\\/C++\\/Java.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 ≤ n ≤ 100) — the number of elements in the array. The second line contains the space-separated integers from the array. All numbers are non-negative integers strictly less than 2^30.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the required maximal xor of a segment of consecutive elements.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 2 1 1 2\\n\\nOutput\\n3\\n\\nInput\\n3\\n1 2 7\\n\\nOutput\\n7\\n\\nInput\\n4\\n4 2 4 8\\n\\nOutput\\n14\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample one of the optimal segments is the segment that consists of the first and the second array elements, if we consider the array elements indexed starting from one.\\n\\nThe second sample contains only one optimal segment, which contains exactly one array element (element with index three).\",\"targets\":\"n = int(input()) + 1\\nt = [0] + list(map(int, input().split()))\\nfor i in range(1, n):\\n    t[i] = t[i] ^ t[i - 1]\\nprint(max(t[j] ^ t[i] for i in range(0, n) for j in range(i + 1, n)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1183\\/D:\\nThis problem is actually a subproblem of problem G from the same contest.\\n\\nThere are $n$ candies in a candy box. The type of the $i$-th candy is $a_i$ ($1 \\\\le a_i \\\\le n$).\\n\\nYou have to prepare a gift using some of these candies with the following restriction: the numbers of candies of each type presented in a gift should be all distinct (i. e. for example, a gift having two candies of type $1$ and two candies of type $2$ is bad). \\n\\nIt is possible that multiple types of candies are completely absent from the gift. It is also possible that not all candies of some types will be taken to a gift.\\n\\nYour task is to find out the maximum possible size of the single gift you can prepare using the candies you have.\\n\\nYou have to answer $q$ independent queries.\\n\\nIf you are Python programmer, consider using PyPy instead of Python when you submit your code.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $q$ ($1 \\\\le q \\\\le 2 \\\\cdot 10^5$) — the number of queries. Each query is represented by two lines.\\n\\nThe first line of each query contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of candies.\\n\\nThe second line of each query contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le n$), where $a_i$ is the type of the $i$-th candy in the box.\\n\\nIt is guaranteed that the sum of $n$ over all queries does not exceed $2 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each query print one integer — the maximum possible size of the single gift you can compose using candies you got in this query with the restriction described in the problem statement.\\n\\n\\n-----Example-----\\nInput\\n3\\n8\\n1 4 8 4 5 6 3 8\\n16\\n2 1 3 3 4 3 4 4 1 3 2 2 2 4 1 1\\n9\\n2 2 4 4 4 7 7 7 7\\n\\nOutput\\n3\\n10\\n9\\n\\n\\n\\n-----Note-----\\n\\nIn the first query, you can prepare a gift with two candies of type $8$ and one candy of type $5$, totalling to $3$ candies.\\n\\nNote that this is not the only possible solution — taking two candies of type $4$ and one candy of type $6$ is also valid.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#   In this template you are not required to write code in main\\n\\nimport sys\\ninf = float(\\\"inf\\\")\\n\\n#from collections import deque, Counter, OrderedDict,defaultdict\\n#from heapq import nsmallest, nlargest, heapify,heappop ,heappush, heapreplace\\n#from math import ceil,floor,log,sqrt,factorial,pow,pi,gcd\\n#from bisect import bisect_left,bisect_right\\n\\nabc='abcdefghijklmnopqrstuvwxyz'\\nabd={'a': 0, 'b': 1, 'c': 2, 'd': 3, 'e': 4, 'f': 5, 'g': 6, 'h': 7, 'i': 8, 'j': 9, 'k': 10, 'l': 11, 'm': 12, 'n': 13, 'o': 14, 'p': 15, 'q': 16, 'r': 17, 's': 18, 't': 19, 'u': 20, 'v': 21, 'w': 22, 'x': 23, 'y': 24, 'z': 25}\\nmod,MOD=1000000007,998244353\\nvow=['a','e','i','o','u']\\ndx,dy=[-1,1,0,0],[0,0,1,-1]\\n\\ndef get_array(): return list(map(int, sys.stdin.readline().strip().split()))\\ndef get_ints(): return map(int, sys.stdin.readline().strip().split())\\ndef input(): return sys.stdin.readline().strip()\\n\\nq=int(input())\\nwhile q>0:\\n    n=int(input())\\n    Arr=get_array()\\n    mydict=dict()\\n    for i in Arr:\\n        mydict[i]=mydict.get(i,0)+1\\n    myset=set()\\n    count=0\\n    for i in mydict:\\n        if mydict[i] not in myset:\\n            count+=mydict[i]\\n            myset.add(mydict[i])\\n        else:\\n            z=mydict[i]\\n            for i in range(z,0,-1):\\n                if i not in myset:\\n                    count+=i\\n                    myset.add(i)\\n                    break\\n    print(count)\\n    q-=1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/RECTLIT:\\nYou are given an axis-aligned rectangle in a 2D Cartesian plane. The bottom left corner of this rectangle has coordinates (0,0)$(0, 0)$ and the top right corner has coordinates (N−1,N−1)$(N-1, N-1)$. You are also given K$K$ light sources; each light source is a point inside or on the perimeter of the rectangle.\\nFor each light source, let's divide the plane into four quadrants by a horizontal and a vertical line passing through this light source. The light source can only illuminate one of these quadrants (including its border, i.e. the point containing the light source and two half-lines), but the quadrants illuminated by different light sources may be different.\\nYou want to assign a quadrant to each light source in such a way that when they illuminate their respective quadrants, the entire rectangle (including its perimeter) is illuminated. Find out whether it is possible to assign quadrants to light sources in such a way.\\n\\n-----Input-----\\n- The first line of the input contains an integer T$T$ denoting the number of test cases. The description of the test cases follows.\\n- The first line of each test case contains two space-separated integers K$K$ and N$N$.\\n- Each of the next K$K$ lines contains two space-separated integers x$x$ and y$y$ denoting a light source with coordinates (x,y)$(x, y)$.\\n\\n-----Output-----\\nFor each test case, print a single line containing the string \\\"yes\\\" if it is possible to illuminate the whole rectangle or \\\"no\\\" if it is impossible.\\n\\n-----Constraints-----\\n- 1≤T≤5,000$1 \\\\le T \\\\le 5,000$\\n- 1≤K≤100$1 \\\\le K \\\\le 100$\\n- 1≤N≤109$1 \\\\le N \\\\le 10^9$\\n- 0≤x,y≤N−1$0 \\\\le x, y \\\\le N-1$\\n- no two light sources coincide\\n\\n-----Example Input-----\\n2\\n2 10\\n0 0\\n1 0\\n2 10\\n1 2\\n1 1\\n\\n-----Example Output-----\\nyes\\nno\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t=int(input())\\r\\nwhile t:\\r\\n    k,n=map(int,input().split())\\r\\n    l=[]\\r\\n    j=0\\r\\n    h=k\\r\\n    while h:\\r\\n        p=list(map(int,input().split()))\\r\\n        l.append(p)\\r\\n        h-=1\\r\\n    if k>3:\\r\\n        j=1\\r\\n    elif k==1:\\r\\n        if (l[0][0]==0 and l[0][1]==n-1) or (l[0][0]==0 and l[0][1]==0) or (l[0][0]==n-1 and l[0][1]==0) or (l[0][0]==n-1 and l[0][1]==n-1):\\r\\n            j=1\\r\\n    elif k==2:\\r\\n        for q in range(2):\\r\\n            if (l[q][0]==0 and l[q][1]==n-1) or (l[q][0]==0 and l[q][1]==0) or (l[q][0]==n-1 and l[q][1]==0) or (l[q][0]==n-1 and l[q][1]==n-1):\\r\\n                j=1\\r\\n        if l[0][0]==0 or l[0][0]==n-1:\\r\\n            if l[1][0]==0 or l[1][0]==n-1: \\r\\n                j=1\\r\\n        if l[0][1]==0 or l[0][1]==n-1:\\r\\n            if l[1][1]==0 or l[1][1]==n-1: \\r\\n                j=1\\r\\n    elif k==3:\\r\\n        for q in range(3):\\r\\n            if (l[q][0]==0 and l[q][1]==n-1) or (l[q][0]==0 and l[q][1]==0) or (l[q][0]==n-1 and l[q][1]==0) or (l[q][0]==n-1 and l[q][1]==n-1):\\r\\n                j=1\\r\\n        for q in range(2):\\r\\n            for w in range(q+1,3):\\r\\n                if l[q][0]==0 or l[q][0]==n-1:\\r\\n                    if l[w][0]==0 or l[w][0]==n-1: \\r\\n                        j=1\\r\\n                if l[q][1]==0 or l[q][1]==n-1:\\r\\n                    if l[w][1]==0 or l[w][1]==n-1:\\r\\n                        j=1\\r\\n                if l[q][0]==0 or l[q][0]==n-1:\\r\\n                    if l[w][1]==0 or l[w][1]==n-1:\\r\\n                        j=1\\r\\n                if l[q][1]==0 or l[q][1]==n-1:\\r\\n                    if l[w][0]==0 or l[w][0]==n-1:\\r\\n                        j=1\\r\\n        for q in range(3):\\r\\n            w=(q+1)%3\\r\\n            r=(q+2)%3\\r\\n            if l[q][0]==0 or l[q][0]==n-1:\\r\\n                if (l[q][1]-l[w][1])*(l[q][1]-l[r][1])>=0:\\r\\n                    j=1\\r\\n            if l[q][1]==0 or l[q][1]==n-1:\\r\\n                if (l[q][0]-l[w][0])*(l[q][0]-l[r][0])>=0:\\r\\n                    j=1\\r\\n    if j:\\r\\n        print(\\\"yes\\\")\\r\\n    else:\\r\\n        print(\\\"no\\\")\\r\\n    t-=1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe only king stands on the standard chess board. You are given his position in format \\\"cd\\\", where c is the column from 'a' to 'h' and d is the row from '1' to '8'. Find the number of moves permitted for the king.\\n\\nCheck the king's moves here https:\\/\\/en.wikipedia.org\\/wiki\\/King_(chess). [Image] King moves from the position e4 \\n\\n\\n-----Input-----\\n\\nThe only line contains the king's position in the format \\\"cd\\\", where 'c' is the column from 'a' to 'h' and 'd' is the row from '1' to '8'.\\n\\n\\n-----Output-----\\n\\nPrint the only integer x — the number of moves permitted for the king.\\n\\n\\n-----Example-----\\nInput\\ne4\\n\\nOutput\\n8\",\"targets\":\"s = input()\\nx = s[0]\\ny = int(s[1])\\nl = 0\\nif x == 'a' or x == 'h':\\n    l += 1\\nif y == 1 or y == 8:\\n    l += 1\\nif l == 0:\\n    print(8)\\nelif l == 1:\\n    print(5)\\nelse:\\n    print(3)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/AGTK2012\\/problems\\/ALGFACT:\\nThe chef was chatting with his friend who was a mathematician.\\nChef said \\\"Hi !\\\".\\n\\nHis friend replied that '!' is the symbol of factorial.\\n\\nChef had never heard about it and he asked more about it. Then his friend taught him how to calculate the factorial of a number.\\n\\nChef loved that But as always he got tired after calculating a few values and asked you to do it for him.\\n\\n-----Input-----\\nN : Number of inputs\\nthen N lines with input T\\n\\nN<10\\n\\nT<=200\\n\\n-----Output-----\\nThe result for the corresponding value of T\\n\\n-----Example-----\\nInput:\\n3\\n5\\n4\\n6\\n\\nOutput:\\n120\\n24\\n720\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n\\nN=201\\nans=[1]\\ni=1\\nwhile i < N:\\n ans.append(ans[i-1] * i)\\n i = i+1\\n\\nT=int(sys.stdin.readline().strip())\\nwhile T > 0:\\n n=int(sys.stdin.readline().strip())\\n print(ans[n])\\n T=T-1;\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a sequence of integers $A_1, A_2, \\\\ldots, A_N$. This sequence is circular ― for each valid $i$, the element $A_{i+1}$ follows after $A_i$, and the element $A_1$ follows after $A_N$.\\nYou may insert any positive integers at any positions you choose in this sequence; let's denote the resulting sequence by $B$. This sequence is also circular. For each pair of its elements $B_s$ and $B_f$, let's denote the (non-circular) sequence created by starting at $B_s$ and moving from each element to the one that follows after it, until we reach $B_f$, by $B(s, f)$. This sequence includes the elements $B_s$ and $B_f$.\\nFor each $K$ from $2$ to $N$ inclusive, find the smallest possible number of elements that need to be inserted into $A$ to form a sequence $B$ for which there is no subsequence $B(p, q)$ such that:\\n- The size of $B(p, q)$ is at least $K$.\\n- There is no pair of consecutive elements in $B(p, q)$ such that their GCD is equal to $1$.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $N$.\\n- The second line contains $N$ space-separated integers $A_1, A_2, \\\\ldots, A_N$.\\n\\n-----Output-----\\nFor each test case, print a single line containing $N-1$ space-separated integers. For each $i$ ($1 \\\\le i \\\\le N-1$), the $i$-th of these integers should be the smallest number of inserted elements in a valid sequence $B$ for $K = i+1$.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 2,000$\\n- $2 \\\\le N \\\\le 10^5$\\n- $1 \\\\le A_i \\\\le 10^9$ for each valid $i$\\n- the sum of $N$ over all test cases does not exceed $2 \\\\cdot 10^6$\\n\\n-----Example Input-----\\n1\\n5\\n3 6 4 5 9\\n\\n-----Example Output-----\\n3 1 1 0\",\"targets\":\"# cook your dish here\\ndef gcd(m,n):\\n if m > n :\\n  (a,b) = (n,m)\\n else:\\n  (a,b) = (m,n)\\n r = b\\n while r > 1:\\n  r = b%a \\n  (a,b) = (r,a)\\n if r == 0:\\n  return b\\n else:\\n  return 1\\n\\ndef rlmaker(rl,pc,n):\\n d = 1 \\n for i in range(0,pc+1):\\n  if i <n-1 :\\n   rl[i] += pc\\/\\/d\\n   d+=1\\n return rl\\ndef rlmakers(rl,pc,n):\\n d = 1 \\n for i in range(0,pc+1):\\n  if i <n-1 :\\n   if pc%d == 0:\\n    rl[i] += pc\\/\\/d\\n   else:\\n    rl[i] += ((pc\\/\\/d)+1)\\n   d+=1\\n return rl\\n  \\n  \\ndef insFinder(n,l):\\n lstone = 0\\n rl = []\\n for i in range(0,n-1):\\n  rl.append(0)\\n pathli = []\\n pc = 0\\n start = -1\\n end = -1\\n c = 0\\n for i in range (0,n-1):\\n  if gcd(l[i],l[i+1]) != 1 :\\n   if i == 0:\\n    start = 0\\n   if i == n-2:\\n    end = n-1\\n   if lstone == 1:\\n    pc += 1 \\n   else:\\n    lstone = 1 \\n    pc += 1\\n  else:\\n   if lstone == 1:\\n    pathli.append(pc)\\n    pc = 0\\n    lstone = 0\\n    \\n if start == 0:\\n  if end == n-1:\\n   if gcd(l[n-1],l[0]) != 1:\\n    pathli.append(pc)\\n    if len(pathli) > 1:\\n     pathli[0]+= (pathli[len(pathli)-1]+1)\\n     pathli.remove(pathli[len(pathli)-1])\\n    else:\\n     c = 1\\n     pathli[0]+=1\\n   else:\\n    pathli.append(pc)\\n  else:\\n   if gcd(l[n-1],l[0]) != 1:\\n    pathli[0] += 1\\n else:\\n  if end == n-1:\\n   if gcd(l[n-1],l[0]) != 1:\\n    pc += 1\\n    pathli.append(pc)\\n   else:\\n    pathli.append(pc)\\n  else:\\n   if gcd(l[n-1],l[0]) != 1:\\n    pathli.append(1) \\n if c == 1:\\n  rl = rlmakers(rl,pathli[0],n)\\n else:\\n  for i in range(0,len(pathli)):\\n   rl = rlmaker(rl,pathli[i],n)\\n \\n for i in range(0,n-1):\\n  print(rl[i],end = ' ')\\n  \\n print(\\\"\\\") \\n \\nnt = int(input())\\nfor i in range(0,nt):\\n n = int(input())\\n l = list(map(int,input().strip().split(' ')))\\n insFinder(n,l)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Introduction \\n\\nA grille cipher was a technique for encrypting a plaintext by writing it onto a sheet of paper through a pierced sheet (of paper or cardboard or similar). The earliest known description is due to the polymath Girolamo Cardano in 1550. His proposal was for a rectangular stencil allowing single letters, syllables, or words to be written, then later read, through its various apertures. The written fragments of the plaintext could be further disguised by filling the gaps between the fragments with anodyne words or letters. This variant is also an example of steganography, as are many of the grille ciphers. \\nWikipedia Link \\n\\n![Tangiers1](https:\\/\\/upload.wikimedia.org\\/wikipedia\\/commons\\/8\\/8a\\/Tangiers1.png)\\n![Tangiers2](https:\\/\\/upload.wikimedia.org\\/wikipedia\\/commons\\/b\\/b9\\/Tangiers2.png)\\n\\n# Task\\n\\nWrite a function that accepts two inputs: `message` and `code` and returns hidden message decrypted from `message` using the `code`.   \\nThe `code` is a nonnegative integer and it decrypts in binary the `message`.\",\"targets\":\"def grille(s, code):\\n    return ''.join(c for c, k in zip(s[::-1], bin(code)[2:][::-1]) if k == '1')[::-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn this simple exercise, you will build a program that takes a value, `integer `, and returns a list of its multiples up to another value, `limit `. If `limit` is a multiple of ```integer```, it should be included as well. There will only ever be positive integers passed into the function, not consisting of 0. The limit will always be higher than the base.\\n\\nFor example, if the parameters passed are `(2, 6)`, the function should return `[2, 4, 6]` as 2, 4, and 6 are the multiples of 2 up to 6.\\n\\nIf you can, try writing it in only one line of code.\",\"targets\":\"find_multiples = lambda a, b: list(range(a, b + 1, a))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPermutation $p$ is a sequence of integers $p=[p_1, p_2, \\\\dots, p_n]$, consisting of $n$ distinct (unique) positive integers between $1$ and $n$, inclusive. For example, the following sequences are permutations: $[3, 4, 1, 2]$, $[1]$, $[1, 2]$. The following sequences are not permutations: $[0]$, $[1, 2, 1]$, $[2, 3]$, $[0, 1, 2]$.\\n\\nThe important key is in the locked box that you need to open. To open the box you need to enter secret code. Secret code is a permutation $p$ of length $n$. \\n\\nYou don't know this permutation, you only know the array $q$ of prefix maximums of this permutation. Formally:  $q_1=p_1$,  $q_2=\\\\max(p_1, p_2)$,  $q_3=\\\\max(p_1, p_2,p_3)$,  ...  $q_n=\\\\max(p_1, p_2,\\\\dots,p_n)$. \\n\\nYou want to construct any possible suitable permutation (i.e. any such permutation, that calculated $q$ for this permutation is equal to the given array).\\n\\n\\n-----Input-----\\n\\nThe first line contains integer number $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases in the input. Then $t$ test cases follow.\\n\\nThe first line of a test case contains one integer $n$ $(1 \\\\le n \\\\le 10^{5})$ — the number of elements in the secret code permutation $p$.\\n\\nThe second line of a test case contains $n$ integers $q_1, q_2, \\\\dots, q_n$ $(1 \\\\le q_i \\\\le n)$ — elements of the array $q$ for secret permutation. It is guaranteed that $q_i \\\\le q_{i+1}$ for all $i$ ($1 \\\\le i < n$).\\n\\nThe sum of all values $n$ over all the test cases in the input doesn't exceed $10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print:  If it's impossible to find such a permutation $p$, print \\\"-1\\\" (without quotes).  Otherwise, print $n$ distinct integers $p_1, p_2, \\\\dots, p_n$ ($1 \\\\le p_i \\\\le n$). If there are multiple possible answers, you can print any of them. \\n\\n\\n-----Example-----\\nInput\\n4\\n5\\n1 3 4 5 5\\n4\\n1 1 3 4\\n2\\n2 2\\n1\\n1\\n\\nOutput\\n1 3 4 5 2 \\n-1\\n2 1 \\n1 \\n\\n\\n\\n-----Note-----\\n\\nIn the first test case of the example answer $[1,3,4,5,2]$ is the only possible answer:  $q_{1} = p_{1} = 1$;  $q_{2} = \\\\max(p_{1}, p_{2}) = 3$;  $q_{3} = \\\\max(p_{1}, p_{2}, p_{3}) = 4$;  $q_{4} =...\",\"targets\":\"t = int(input())\\nfor request in range(t):\\n    n = int(input())\\n    result, initial = list(map(int, input().split())), []\\n    box, flag = [], True\\n    initial.append(result[0])\\n    for d in range(1, result[0]):\\n                box.append(d)\\n    for i in range(1, n):\\n        if result[i - 1] < result[i]:\\n            initial.append(result[i])\\n            for d in range(result[i - 1] + 1, result[i]):\\n                box.append(d)\\n        else:\\n            try:\\n                initial.append(box.pop())\\n            except:\\n                flag = False\\n                break\\n    if flag:\\n        print(*initial)\\n    else:\\n        print(-1)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\\nAlso, there is a bus going from Station B to Station C that costs Y yen.\\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\\n\\n-----Constraints-----\\n - 1 \\\\leq X,Y \\\\leq 100\\n - Y is an even number.\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nX Y\\n\\n-----Output-----\\nIf it costs x yen to travel from Station A to Station C, print x.\\n\\n-----Sample Input-----\\n81 58\\n\\n-----Sample Output-----\\n110\\n\\n - The train fare is 81 yen.\\n - The train fare is 58 ⁄ 2=29 yen with the 50% discount.\\nThus, it costs 110 yen to travel from Station A to Station C.\",\"targets\":\"a = [int(s) for s in input().split()]\\nprint(int(a[0] + a[1] \\/\\/ 2))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/PROBLEMS:\\nMandarin chinese\\n, Russian and Vietnamese as well.\\nChef is organising a contest with $P$ problems (numbered $1$ through $P$). Each problem has $S$ subtasks (numbered $1$ through $S$).\\nThe difficulty of a problem can be calculated as follows:\\n- Let's denote the score of the $k$-th subtask of this problem by $SC_k$ and the number of contestants who solved it by $NS_k$.\\n- Consider the subtasks sorted in the order of increasing score.\\n- Calculate the number $n$ of valid indices $k$ such that $NS_k > NS_{k + 1}$.\\n- For problem $i$, the difficulty is a pair of integers $(n, i)$.\\nYou should sort the problems in the increasing order of difficulty levels. Since difficulty level is a pair, problem $a$ is more difficult than problem $b$ if the number $n$ is greater for problem $a$ than for problem $b$, or if $a > b$ and $n$ is the same for problems $a$ and $b$.\\n\\n-----Input-----\\n- The first line of the input contains two space-separated integers $P$ and $S$ denoting the number of problems and the number of subtasks in each problem.\\n- $2P$ lines follow. For each valid $i$, the $2i-1$-th of these lines contains $S$ space-separated integers $SC_1, SC_2, \\\\dots, SC_S$ denoting the scores of the $i$-th problem's subtasks, and the $2i$-th of these lines contains $S$ space-separated integers $NS_1, NS_2, \\\\dots, NS_S$ denoting the number of contestants who solved the $i$-th problem's subtasks.\\n\\n-----Output-----\\nPrint $P$ lines containing one integer each — the indices of the problems in the increasing order of difficulty.\\n\\n-----Constraints-----\\n- $1 \\\\le P \\\\le 100,000$\\n- $2 \\\\le S \\\\le 30$\\n- $1 \\\\le SC_i \\\\le 100$ for each valid $i$\\n- $1 \\\\le NS_i \\\\le 1,000$ for each valid $i$\\n- in each problem, the scores of all subtasks are unique\\n\\n-----Subtasks-----\\nSubtask #1 (25 points): $S = 2$\\nSubtask #2 (75 points): original constraints\\n\\n-----Example Input-----\\n3 3\\n16 24 60\\n498 861 589\\n14 24 62\\n72 557 819\\n16 15 69\\n435 779 232\\n\\n-----Example Output-----\\n2\\n1\\n3\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import defaultdict\\nfrom operator import itemgetter\\n\\np, s = list(map(int, input().split()))\\n\\ndiff = []\\nfor _ in range(p):\\n sc = list(map(int, input().split()))\\n nk = list(map(int, input().split()))\\n\\n arr = list(zip(sc, nk))\\n\\n arr_sort = sorted(arr, key = itemgetter(0))\\n # print(arr)\\n temp = 0\\n for i in range(s-1):\\n  if arr_sort[i][1] > arr_sort[i+1][1]:\\n   temp += 1\\n a = (temp, _+1)\\n diff.append(a)\\n\\ntemp = diff[:]\\ntemp.sort(key=lambda x: x[0])\\n\\n\\nfor i in temp:\\n print(i[1])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1009\\/A:\\nMaxim wants to buy some games at the local game shop. There are $n$ games in the shop, the $i$-th game costs $c_i$.\\n\\nMaxim has a wallet which can be represented as an array of integers. His wallet contains $m$ bills, the $j$-th bill has value $a_j$.\\n\\nGames in the shop are ordered from left to right, Maxim tries to buy every game in that order.\\n\\nWhen Maxim stands at the position $i$ in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the $i$-th game using this bill. After Maxim tried to buy the $n$-th game, he leaves the shop.\\n\\nMaxim buys the $i$-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the $i$-th game. If he successfully buys the $i$-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.\\n\\nFor example, for array $c = [2, 4, 5, 2, 4]$ and array $a = [5, 3, 4, 6]$ the following process takes place: Maxim buys the first game using the first bill (its value is $5$), the bill disappears, after that the second bill (with value $3$) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because $c_2 > a_2$, the same with the third game, then he buys the fourth game using the bill of value $a_2$ (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value $a_3$.\\n\\nYour task is to get the number of games Maxim will buy.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $m$ ($1 \\\\le n, m \\\\le 1000$) — the number of games and the number of bills in Maxim's wallet.\\n\\nThe second line of the input contains $n$ integers $c_1, c_2, \\\\dots, c_n$ ($1 \\\\le c_i \\\\le 1000$), where $c_i$ is the cost of the $i$-th game.\\n\\nThe third line of the input contains $m$ integers $a_1, a_2, \\\\dots, a_m$ ($1 \\\\le a_j \\\\le 1000$), where $a_j$...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"input()\\nc = [int(a) for a in input().split()]\\na = [int(a) for a in input().split()]\\ncount = 0\\nfor i in c:\\n    if len(a) > 0 and i <= a[0]:\\n        count += 1\\n        a.pop(0)\\n\\nprint(count)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nEugeny has array a = a_1, a_2, ..., a_{n}, consisting of n integers. Each integer a_{i} equals to -1, or to 1. Also, he has m queries:  Query number i is given as a pair of integers l_{i}, r_{i} (1 ≤ l_{i} ≤ r_{i} ≤ n).  The response to the query will be integer 1, if the elements of array a can be rearranged so as the sum a_{l}_{i} + a_{l}_{i} + 1 + ... + a_{r}_{i} = 0, otherwise the response to the query will be integer 0. \\n\\nHelp Eugeny, answer all his queries.\\n\\n\\n-----Input-----\\n\\nThe first line contains integers n and m (1 ≤ n, m ≤ 2·10^5). The second line contains n integers a_1, a_2, ..., a_{n} (a_{i} = -1, 1). Next m lines contain Eugene's queries. The i-th line contains integers l_{i}, r_{i} (1 ≤ l_{i} ≤ r_{i} ≤ n).\\n\\n\\n-----Output-----\\n\\nPrint m integers — the responses to Eugene's queries in the order they occur in the input.\\n\\n\\n-----Examples-----\\nInput\\n2 3\\n1 -1\\n1 1\\n1 2\\n2 2\\n\\nOutput\\n0\\n1\\n0\\n\\nInput\\n5 5\\n-1 1 1 1 -1\\n1 1\\n2 3\\n3 5\\n2 5\\n1 5\\n\\nOutput\\n0\\n1\\n0\\n1\\n0\",\"targets\":\"n,m = list(map(int,input().split()))\\na = list(map(int, input().split()))\\nb = a.count(1)\\nc = min(b,n-b)\\ns = ''\\nfor i in range(m):\\n    left,right = list(map(int, input().split()))\\n    length = right - left + 1\\n    if length % 2 or length \\/\\/2 > c:\\n        s += \\\"0\\\\n\\\"\\n    else:\\n        s += \\\"1\\\\n\\\"\\nprint(s)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/599\\/C:\\nOne day Squidward, Spongebob and Patrick decided to go to the beach. Unfortunately, the weather was bad, so the friends were unable to ride waves. However, they decided to spent their time building sand castles.\\n\\nAt the end of the day there were n castles built by friends. Castles are numbered from 1 to n, and the height of the i-th castle is equal to h_{i}. When friends were about to leave, Squidward noticed, that castles are not ordered by their height, and this looks ugly. Now friends are going to reorder the castles in a way to obtain that condition h_{i} ≤ h_{i} + 1 holds for all i from 1 to n - 1.\\n\\nSquidward suggested the following process of sorting castles:   Castles are split into blocks — groups of consecutive castles. Therefore the block from i to j will include castles i, i + 1, ..., j. A block may consist of a single castle.  The partitioning is chosen in such a way that every castle is a part of exactly one block.  Each block is sorted independently from other blocks, that is the sequence h_{i}, h_{i} + 1, ..., h_{j} becomes sorted.  The partitioning should satisfy the condition that after each block is sorted, the sequence h_{i} becomes sorted too. This may always be achieved by saying that the whole sequence is a single block. \\n\\nEven Patrick understands that increasing the number of blocks in partitioning will ease the sorting process. Now friends ask you to count the maximum possible number of blocks in a partitioning that satisfies all the above requirements.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a single integer n (1 ≤ n ≤ 100 000) — the number of castles Spongebob, Patrick and Squidward made from sand during the day.\\n\\nThe next line contains n integers h_{i} (1 ≤ h_{i} ≤ 10^9). The i-th of these integers corresponds to the height of the i-th castle.\\n\\n\\n-----Output-----\\n\\nPrint the maximum possible number of blocks in a valid partitioning.\\n\\n\\n-----Examples-----\\nInput\\n3\\n1 2 3\\n\\nOutput\\n3\\n\\nInput\\n4\\n2 1 3 2\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample the partitioning looks like...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def binsearch(a, x, k):\\n    l = 0\\n    r = k\\n    while l < r - 1:\\n        m = (l + r) \\/\\/ 2\\n        if a[m] <= x:\\n            l = m\\n        else:\\n            r = m\\n    return l\\nn = int(input())\\nk = -1\\na = [0] * n\\nfor i in input().split():\\n    x = int(i)\\n    if k == -1:\\n        k += 1\\n        a[k] = x\\n    else:\\n        if x >= a[k]:\\n            k += 1\\n            a[k] = x\\n        else:\\n            k1 = k\\n            k = binsearch(a, x, k + 1)\\n            if a[k] <= x:\\n                k += 1\\n            a[k] = a[k1]\\nprint(k + 1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/448\\/A:\\nBizon the Champion is called the Champion for a reason. \\n\\nBizon the Champion has recently got a present — a new glass cupboard with n shelves and he decided to put all his presents there. All the presents can be divided into two types: medals and cups. Bizon the Champion has a_1 first prize cups, a_2 second prize cups and a_3 third prize cups. Besides, he has b_1 first prize medals, b_2 second prize medals and b_3 third prize medals. \\n\\nNaturally, the rewards in the cupboard must look good, that's why Bizon the Champion decided to follow the rules:  any shelf cannot contain both cups and medals at the same time;  no shelf can contain more than five cups;  no shelf can have more than ten medals. \\n\\nHelp Bizon the Champion find out if we can put all the rewards so that all the conditions are fulfilled.\\n\\n\\n-----Input-----\\n\\nThe first line contains integers a_1, a_2 and a_3 (0 ≤ a_1, a_2, a_3 ≤ 100). The second line contains integers b_1, b_2 and b_3 (0 ≤ b_1, b_2, b_3 ≤ 100). The third line contains integer n (1 ≤ n ≤ 100).\\n\\nThe numbers in the lines are separated by single spaces.\\n\\n\\n-----Output-----\\n\\nPrint \\\"YES\\\" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print \\\"NO\\\" (without the quotes).\\n\\n\\n-----Examples-----\\nInput\\n1 1 1\\n1 1 1\\n4\\n\\nOutput\\nYES\\n\\nInput\\n1 1 3\\n2 3 4\\n2\\n\\nOutput\\nYES\\n\\nInput\\n1 0 0\\n1 0 0\\n1\\n\\nOutput\\nNO\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a1, a2, a3 = [int(x) for x in input().split(' ')]\\nb1, b2, b3 = [int(x) for x in input().split(' ')]\\nn = int(input())\\nat = (a1+a2+a3)\\/\\/5; ar = (a1+a2+a3)%5\\nbt = (b1+b2+b3)\\/\\/10; br = (b1+b2+b3)%10\\nif(ar > 0) : at = at+1\\nif(br > 0) : bt = bt+1\\nif(at+bt <= n) : print(\\\"YES\\\")\\nelse : print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are N cards placed face down in a row. On each card, an integer 1 or 2 is written.\\nLet A_i be the integer written on the i-th card.\\nYour objective is to guess A_1, A_2, ..., A_N correctly.\\nYou know the following facts:\\n - For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.\\nYou are a magician and can use the following magic any number of times:\\nMagic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.\\nWhat is the minimum cost required to determine all of A_1, A_2, ..., A_N?\\nIt is guaranteed that there is no contradiction in given input.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 2 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq M \\\\leq 10^5\\n - 1 \\\\leq X_i < Y_i \\\\leq N\\n - 1 \\\\leq Z_i \\\\leq 100\\n - The pairs (X_i, Y_i) are distinct.\\n - There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M\\nX_1 Y_1 Z_1\\nX_2 Y_2 Z_2\\n\\\\vdots\\nX_M Y_M Z_M\\n\\n-----Output-----\\nPrint the minimum total cost required to determine all of A_1, A_2, ..., A_N.\\n\\n-----Sample Input-----\\n3 1\\n1 2 1\\n\\n-----Sample Output-----\\n2\\n\\nYou can determine all of A_1, A_2, A_3 by using the magic for the first and third cards.\",\"targets\":\"N,M=list(map(int,input().split()))\\nroot=[i for i in range(N)]\\nheight=[0]*N\\ndef find(a):\\n   f=a\\n   if a==root[a]:\\n      return a\\n   while a!=root[a]:\\n      a=root[a]\\n   root[f]=a\\n   return a\\ndef union(a,b):\\n   A=find(a)\\n   B=find(b)\\n   if A==B:\\n      return\\n   if height[A]>height[B]:\\n      root[B]=root[A]\\n   else:\\n      root[A]=root[B]\\n      if height[A]==height[B]:\\n         height[B]+=1\\n\\nfor i in range(M):\\n   a,b,c=map(int,input().split())\\n   a-=1;b-=1\\n   union(a,b)\\nl=[0]*N\\nfor j in range(N):\\n   l[find(j)]+=1\\nprint(N-l.count(0))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n## Fixed xor\\n\\nWrite a function that takes two hex strings as input and XORs them against each other. If the strings are different lengths the output should be the length of the shortest string.\\n\\nHint: The strings would first need to be converted to binary to be XOR'd. \\n\\n## Note:\\nIf the two strings are of different lengths, the output string should be the same length as the smallest string. This means that the longer string will be cut down to the same size as the smaller string, then xor'd\\n\\n### Further help\\n\\nMore information on the XOR operation can be found here https:\\/\\/www.khanacademy.org\\/computing\\/computer-science\\/cryptography\\/ciphers\\/a\\/xor-bitwise-operation\\n\\nMore information of the binary and hex bases can be found here https:\\/\\/www.khanacademy.org\\/math\\/algebra-home\\/alg-intro-to-algebra\\/algebra-alternate-number-bases\\/v\\/number-systems-introduction\\n\\nExamples:\\n\\n```python\\nfixed_xor(\\\"ab3f\\\", \\\"ac\\\") == \\\"07\\\"\\nfixed_xor(\\\"aadf\\\", \\\"bce2\\\") == \\\"163d\\\"\\nfixed_xor(\\\"1c0111001f010100061a024b53535009181c\\\", \\\"686974207468652062756c6c277320657965\\\") == \\\"746865206b696420646f6e277420706c6179\\\"\\n```\",\"targets\":\"def fixed_xor(a, b):\\n    return ''.join('%x' % (int(x, 16) ^ int(y, 16)) for (x, y) in zip(a, b))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/MAKETRI:\\nChef has come to a 2 dimensional garden in which there are N points. Each point has coordinates (x, y), where x can either be 1 or 2 or 3. Chef will now choose every triplet of these N points and make a triangle from it. You need to tell the sum of areas of all the triangles the Chef makes.\\nNote that some of the triplets might not form proper triangles, and would end up as a line or a point (ie. degenerate), but that is fine because their area will be zero.\\n\\n-----Input-----\\n- The first line contains a single integer T, the number of test cases. The description of each testcase follows.\\n- The first line of each test case contains an integer N denoting the number of points on the plane.\\n- The next N lines contain 2 space separated integers x and y denoting the coordinates of the points. \\n\\n-----Output-----\\nFor each test case, output a single line containing the answer. Your answer will be considered correct if the absolute error is less than or equal to 10-2.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 20\\n- 1 ≤ N ≤ 2000\\n- 1 ≤ x ≤ 3\\n- 1 ≤ y ≤106\\n- All (x, y) pairs are distinct\\n\\n-----Example-----\\nInput:\\n2\\n3\\n1 1\\n2 1\\n3 3\\n4\\n1 1\\n2 2\\n2 1\\n3 3\\n\\nOutput:\\n1.0\\n2.0\\n\\n-----Explanation:-----\\nTest Case 1: There is only one triangle which has non-zero area, and it's area is 1, hence the output.\\nTest Case 2: Let the points be A(1,1), B(2,2), C(2,1), D(3,3). There are 3 non degenerate triangles possible. \\n\\n-  area ABC = 0.5\\n-  area BCD = 0.5\\n-  area ACD = 1\\nTotal area = 2\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# Author: Dancing Monkey | Created: 09.DEC.2018\\n\\n\\nimport bisect\\nfor _ in range(int(input())):\\n n = int(input())\\n x1 , x2, x3 = [], [], []\\n for i in range(n):\\n  x, y = list(map(int, input().split()))\\n\\n  if x == 1: x1.append(y)\\n  if x == 2: x2.append(y)\\n  if x == 3: x3.append(y)\\n\\n x1.sort()\\n x2.sort()\\n x3.sort()\\n\\n y1, y2, y3 = len(x1), len(x2), len(x3)\\n area = 0\\n for i in range(y1):\\n  for j in range(i+1, y1):\\n   area += abs(x1[i] - x1[j])*(y2 + (2*y3))\\n\\n for i in range(y3):\\n  for j in range(i+1, y3):\\n   area += abs(x3[i] - x3[j])*(y2 + (2*y1))\\n\\n for i in range(y2):\\n  for j in range(i+1, y2):\\n   area += abs(x2[i] - x2[j])*(y1 + y3)\\n\\n area \\/= 2\\n\\n s1 = [0]\\n for i in range(y2): s1.append(s1[-1] + x2[i])\\n # print(s1)\\n s2 = [0]\\n for i in range(y2):s2.append(s2[-1] + x2[y2 - 1 - i])\\n # print(s2)\\n\\n for i in x1:\\n  for j in x3:\\n   p1 = (i + j) \\/ 2\\n   p = bisect.bisect_left(x2, p1)\\n   # print('p', p)\\n   l = p\\n   h = y2 - l\\n   # print(l, h)\\n\\n   area += p1*(l) - s1[l]\\n   # print('dfg', area)\\n   area += s2[h] - p1*(h)\\n\\n print(format(area, 'f'))\\n # print()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVova's family is building the Great Vova Wall (named by Vova himself). Vova's parents, grandparents, grand-grandparents contributed to it. Now it's totally up to Vova to put the finishing touches.\\n\\nThe current state of the wall can be respresented by a sequence $a$ of $n$ integers, with $a_i$ being the height of the $i$-th part of the wall.\\n\\nVova can only use $2 \\\\times 1$ bricks to put in the wall (he has infinite supply of them, however).\\n\\nVova can put bricks horizontally on the neighboring parts of the wall of equal height. It means that if for some $i$ the current height of part $i$ is the same as for part $i + 1$, then Vova can put a brick there and thus increase both heights by 1. Obviously, Vova can't put bricks in such a way that its parts turn out to be off the borders (to the left of part $1$ of the wall or to the right of part $n$ of it).\\n\\nThe next paragraph is specific to the version 1 of the problem.\\n\\nVova can also put bricks vertically. That means increasing height of any part of the wall by 2.\\n\\nVova is a perfectionist, so he considers the wall completed when:\\n\\n  all parts of the wall has the same height;  the wall has no empty spaces inside it. \\n\\nCan Vova complete the wall using any amount of bricks (possibly zero)?\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of parts in the wall.\\n\\nThe second line contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 10^9$) — the initial heights of the parts of the wall.\\n\\n\\n-----Output-----\\n\\nPrint \\\"YES\\\" if Vova can complete the wall using any amount of bricks (possibly zero).\\n\\nPrint \\\"NO\\\" otherwise.\\n\\n\\n-----Examples-----\\nInput\\n5\\n2 1 1 2 5\\n\\nOutput\\nYES\\n\\nInput\\n3\\n4 5 3\\n\\nOutput\\nYES\\n\\nInput\\n2\\n10 10\\n\\nOutput\\nYES\\n\\nInput\\n3\\n1 2 3\\n\\nOutput\\nNO\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Vova can put a brick on parts 2 and 3 to make the wall $[2, 2, 2, 2, 5]$ and then put 3 bricks on parts 1 and 2 and 3 bricks on parts 3 and 4 to make it $[5, 5, 5, 5, 5]$.\\n\\nIn the second example Vova can put a brick vertically on...\",\"targets\":\"n = int(input())\\na = list(map(int, input().split()))\\nb = []\\nfor i in range(n):\\n    a[i] %= 2\\n    if len(b) != 0:\\n        if b[-1] == a[i]:\\n            b.pop()\\n        else:\\n            b.append(a[i])\\n    else:\\n        b.append(a[i])\\nif len(b) > 1:\\n    print(\\\"NO\\\")\\nelse:\\n    print(\\\"YES\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nCrazy Town is a plane on which there are n infinite line roads. Each road is defined by the equation a_{i}x + b_{i}y + c_{i} = 0, where a_{i} and b_{i} are not both equal to the zero. The roads divide the plane into connected regions, possibly of infinite space. Let's call each such region a block. We define an intersection as the point where at least two different roads intersect.\\n\\nYour home is located in one of the blocks. Today you need to get to the University, also located in some block. In one step you can move from one block to another, if the length of their common border is nonzero (in particular, this means that if the blocks are adjacent to one intersection, but have no shared nonzero boundary segment, then it are not allowed to move from one to another one in one step).\\n\\nDetermine what is the minimum number of steps you have to perform to get to the block containing the university. It is guaranteed that neither your home nor the university is located on the road.\\n\\n\\n-----Input-----\\n\\nThe first line contains two space-separated integers x_1, y_1 ( - 10^6 ≤ x_1, y_1 ≤ 10^6) — the coordinates of your home.\\n\\nThe second line contains two integers separated by a space x_2, y_2 ( - 10^6 ≤ x_2, y_2 ≤ 10^6) — the coordinates of the university you are studying at.\\n\\nThe third line contains an integer n (1 ≤ n ≤ 300) — the number of roads in the city. The following n lines contain 3 space-separated integers ( - 10^6 ≤ a_{i}, b_{i}, c_{i} ≤ 10^6; |a_{i}| + |b_{i}| > 0) — the coefficients of the line a_{i}x + b_{i}y + c_{i} = 0, defining the i-th road. It is guaranteed that no two roads are the same. In addition, neither your home nor the university lie on the road (i.e. they do not belong to any one of the lines).\\n\\n\\n-----Output-----\\n\\nOutput the answer to the problem.\\n\\n\\n-----Examples-----\\nInput\\n1 1\\n-1 -1\\n2\\n0 1 0\\n1 0 0\\n\\nOutput\\n2\\n\\nInput\\n1 1\\n-1 -1\\n3\\n1 0 0\\n0 1 0\\n1 1 -3\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nPictures to the samples are presented below (A is the point representing the house; B is the point representing the...\",\"targets\":\"def input_split(f): return list(map(f, input().split()))\\n\\n\\ndef main():\\n    x1, y1 = input_split(int)\\n    x2, y2 = input_split(int)\\n    n = int(input())\\n    count = 0\\n    for i in range(n):\\n        a, b, c = input_split(int)\\n        if (a*x1+b*y1+c) * (a*x2+b*y2+c) < 0:\\n            count+=1\\n    print(count)\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1251\\/D:\\nYou are the head of a large enterprise. $n$ people work at you, and $n$ is odd (i. e. $n$ is not divisible by $2$).\\n\\nYou have to distribute salaries to your employees. Initially, you have $s$ dollars for it, and the $i$-th employee should get a salary from $l_i$ to $r_i$ dollars. You have to distribute salaries in such a way that the median salary is maximum possible.\\n\\nTo find the median of a sequence of odd length, you have to sort it and take the element in the middle position after sorting. For example:  the median of the sequence $[5, 1, 10, 17, 6]$ is $6$,  the median of the sequence $[1, 2, 1]$ is $1$. \\n\\nIt is guaranteed that you have enough money to pay the minimum salary, i.e $l_1 + l_2 + \\\\dots + l_n \\\\le s$.\\n\\nNote that you don't have to spend all your $s$ dollars on salaries.\\n\\nYou have to answer $t$ test cases.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 2 \\\\cdot 10^5$) — the number of test cases.\\n\\nThe first line of each query contains two integers $n$ and $s$ ($1 \\\\le n < 2 \\\\cdot 10^5$, $1 \\\\le s \\\\le 2 \\\\cdot 10^{14}$) — the number of employees and the amount of money you have. The value $n$ is not divisible by $2$.\\n\\nThe following $n$ lines of each query contain the information about employees. The $i$-th line contains two integers $l_i$ and $r_i$ ($1 \\\\le l_i \\\\le r_i \\\\le 10^9$).\\n\\nIt is guaranteed that the sum of all $n$ over all queries does not exceed $2 \\\\cdot 10^5$.\\n\\nIt is also guaranteed that you have enough money to pay the minimum salary to each employee, i. e. $\\\\sum\\\\limits_{i=1}^{n} l_i \\\\le s$.\\n\\n\\n-----Output-----\\n\\nFor each test case print one integer — the maximum median salary that you can obtain.\\n\\n\\n-----Example-----\\nInput\\n3\\n3 26\\n10 12\\n1 4\\n10 11\\n1 1337\\n1 1000000000\\n5 26\\n4 4\\n2 4\\n6 8\\n5 6\\n2 7\\n\\nOutput\\n11\\n1337\\n6\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, you can distribute salaries as follows: $sal_1 = 12, sal_2 = 2, sal_3 = 11$ ($sal_i$ is the salary of the $i$-th employee). Then the median salary is $11$.\\n\\nIn the second test case, you have to pay $1337$ dollars to the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n \\n  \\ndef solve(mid):\\n    ans = 0\\n    cnt = 0\\n    tmp = []\\n    for i in range(n):\\n        l, r = info[i]\\n        if r < mid:\\n            ans += l\\n        elif mid < l:\\n            ans += l\\n            cnt += 1\\n        else:\\n            tmp.append(l)\\n    tmp.sort(reverse = True)\\n    nokori = (n+1) \\/\\/ 2 - cnt\\n    for i in tmp:\\n        if nokori > 0:\\n            ans += mid\\n            nokori -= 1\\n        else:\\n            ans += i\\n    if ans <= s and nokori <= 0:\\n        return True\\n    else:\\n        return False\\n\\nq = int(input())\\nans = [0]*q\\nfor qi in range(q):\\n    n, s = map(int, input().split())\\n    info = [list(map(int, input().split())) for i in range(n)]\\n    ok = 0\\n    ng = s + 1\\n    while abs(ok - ng) > 1:\\n        mid = (ok + ng) \\/\\/ 2\\n        if solve(mid):\\n            ok = mid\\n        else:\\n            ng = mid\\n    ans[qi] = ok\\nprint('\\\\n'.join(map(str, ans)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/maximum-length-of-repeated-subarray\\/:\\nGiven two integer arrays A and B, return the maximum length of an subarray that appears in both arrays.\\n\\nExample 1:\\n\\nInput:\\nA: [1,2,3,2,1]\\nB: [3,2,1,4,7]\\nOutput: 3\\nExplanation: \\nThe repeated subarray with maximum length is [3, 2, 1].\\n\\n\\n\\nNote:\\n\\n1 \\n0\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def findLength(self, A, B):\\n         def check(length):\\n             seen = {A[i:i+length]\\n                     for i in range(len(A) - length + 1)}\\n             return any(B[j:j+length] in seen\\n                        for j in range(len(B) - length + 1))\\n \\n         A = ''.join(map(chr, A))\\n         B = ''.join(map(chr, B))\\n         lo, hi = 0, min(len(A), len(B)) + 1\\n         while lo < hi:\\n             mi = int((lo + hi) \\/ 2)\\n             if check(mi):\\n                 lo = mi + 1\\n             else:\\n                 hi = mi\\n         return lo - 1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a sequence $b_1, b_2, \\\\ldots, b_n$. Find the lexicographically minimal permutation $a_1, a_2, \\\\ldots, a_{2n}$ such that $b_i = \\\\min(a_{2i-1}, a_{2i})$, or determine that it is impossible.\\n\\n\\n-----Input-----\\n\\nEach test contains one or more test cases. The first line contains the number of test cases $t$ ($1 \\\\le t \\\\le 100$).\\n\\nThe first line of each test case consists of one integer $n$ — the number of elements in the sequence $b$ ($1 \\\\le n \\\\le 100$).\\n\\nThe second line of each test case consists of $n$ different integers $b_1, \\\\ldots, b_n$ — elements of the sequence $b$ ($1 \\\\le b_i \\\\le 2n$).\\n\\nIt is guaranteed that the sum of $n$ by all test cases doesn't exceed $100$.\\n\\n\\n-----Output-----\\n\\nFor each test case, if there is no appropriate permutation, print one number $-1$.\\n\\nOtherwise, print $2n$ integers $a_1, \\\\ldots, a_{2n}$ — required lexicographically minimal permutation of numbers from $1$ to $2n$.\\n\\n\\n-----Example-----\\nInput\\n5\\n1\\n1\\n2\\n4 1\\n3\\n4 1 3\\n4\\n2 3 4 5\\n5\\n1 5 7 2 8\\n\\nOutput\\n1 2 \\n-1\\n4 5 1 2 3 6 \\n-1\\n1 3 5 6 7 9 2 4 8 10\",\"targets\":\"t = int(input())\\nfor _ in range(t):\\n  n = int(input())\\n  a = list(map(int,input().split()))\\n  b = sorted(a)\\n  used = [0 for i in range(2*n+1)]\\n  flg = 1\\n  for i in range(n):\\n    if b[i] > i*2+1:\\n      print(-1)\\n      flg = 0\\n      break\\n    used[b[i]] = 1\\n  if flg == 0:\\n    continue\\n  ans = []\\n  for i in range(n):\\n    ans.append(a[i])\\n    for j in range(a[i],2*n+1):\\n      if used[j] == 0:\\n        ans.append(j)\\n        used[j] = 1\\n        break\\n  print(*ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc071\\/tasks\\/abc071_a:\\nSnuke lives at position x on a number line.\\nOn this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.\\nSnuke decided to get food delivery from the closer of stores A and B.\\nFind out which store is closer to Snuke's residence.\\nHere, the distance between two points s and t on a number line is represented by |s-t|.\\n\\n-----Constraints-----\\n - 1 \\\\leq x \\\\leq 1000\\n - 1 \\\\leq a \\\\leq 1000\\n - 1 \\\\leq b \\\\leq 1000\\n - x, a and b are pairwise distinct.\\n - The distances between Snuke's residence and stores A and B are different.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nx a b\\n\\n-----Output-----\\nIf store A is closer, print A; if store B is closer, print B.\\n\\n-----Sample Input-----\\n5 2 7\\n\\n-----Sample Output-----\\nB\\n\\nThe distances between Snuke's residence and stores A and B are 3 and 2, respectively.\\nSince store B is closer, print B.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"x, a, b= map(int, input().split())\\n\\nprint('A' if abs(x - a) < abs(x - b) else 'B')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef has a sequence $A_1, A_2, \\\\ldots, A_N$; each element of this sequence is either $0$ or $1$. Appy gave him a string $S$ with length $Q$ describing a sequence of queries. There are two types of queries:\\n- '!': right-shift the sequence $A$, i.e. replace $A$ by another sequence $B_1, B_2, \\\\ldots, B_N$ satisfying $B_{i+1} = A_i$ for each valid $i$ and $B_1 = A_N$\\n- '?': find the length of the longest contiguous subsequence of $A$ with length $\\\\le K$ such that each element of this subsequence is equal to $1$\\nAnswer all queries of the second type.\\n\\n-----Input-----\\n- The first line of the input contains three space-separated integers $N$, $Q$ and $K$.\\n- The second line contains $N$ space-separated integers $A_1, A_2, \\\\ldots, A_N$.\\n- The third line contains a string with length $Q$ describing queries. Each character of this string is either '?', denoting a query of the second type, or '!', denoting a query of the first type.\\n\\n-----Output-----\\nFor each query of the second type, print a single line containing one integer — the length of the longest required subsequence.\\n\\n-----Constraints-----\\n- $1 \\\\le K \\\\le N \\\\le 10^5$\\n- $1 \\\\le Q \\\\le 3 \\\\cdot 10^5$\\n- $0 \\\\le A_i \\\\le 1$ for each valid $i$\\n- $S$ contains only characters '?' and '!'\\n\\n-----Subtasks-----\\nSubtask #1 (30 points):\\n- $1 \\\\le N \\\\le 10^3$\\n- $1 \\\\le Q \\\\le 3 \\\\cdot 10^3$\\nSubtask #2 (70 points): original constraints \\n\\n-----Example Input-----\\n5 5 3\\n1 1 0 1 1\\n?!?!?    \\n\\n-----Example Output-----\\n2\\n3\\n3\\n\\n-----Explanation-----\\n- In the first query, there are two longest contiguous subsequences containing only $1$-s: $A_1, A_2$ and $A_4, A_5$. Each has length $2$.\\n- After the second query, the sequence $A$ is $[1, 1, 1, 0, 1]$.\\n- In the third query, the longest contiguous subsequence containing only $1$-s is $A_1, A_2, A_3$.\\n- After the fourth query, $A = [1, 1, 1, 1, 0]$.\\n- In the fifth query, the longest contiguous subsequence containing only $1$-s is $A_1, A_2, A_3, A_4$ with length $4$. However, we only want subsequences with lengths $\\\\le K$. One of the longest such...\",\"targets\":\"n,q,k = map(int,input().split())\\nl = list(map(str,input().split()))\\ns = input()\\nfor x in s:\\n if x==\\\"!\\\":\\n  temp = l[-1]\\n  l[1:] = l[:-1]\\n  l[0] = temp\\n  continue\\n elif x==\\\"?\\\":\\n  s_new = \\\"\\\".join(l[:])\\n  l_new = s_new.split(\\\"0\\\")\\n  l_new.sort()\\n  if len(l_new[-1])>=k:\\n   print(k)\\n  else:\\n   print(len(l_new[-1]))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWitua is a little student from the University of Lviv. He enjoys studying math. Witua knows a lot of famous mathematicians like Eratosthenes, Pythagoras, Fermat, Diophantus, Furko, Gauss and so on. However, his favorite one is Euler. The only thing Witua likes more than Euler is Euler’s totient function φ. He is exploring the nature of this function. One of the steps of his work is finding φ(i)\\/i for all 2≤i≤N. He doesn’t need to know every such value, but Witua wonders for what value i, is φ(i)\\/i the maximum he can get? Help little student to find such i that φ(i)\\/i is maximum among all the  2≤i≤N.\\n\\n-----Input-----\\nThe first line contains single integer T - the number of test cases. Each of the next T lines contains a single integer N. \\n\\n-----Output-----\\nFor every test case output i such that φ(i)\\/i is maximum among all i (2≤i≤N) in a separate line.\\n\\n-----Constrains-----\\nT (1≤T≤500 )\\n\\nN(2≤N≤10^18)\\n\\n\\n-----Example-----\\nInput:\\n3\\n2\\n3\\n4\\n\\nOutput:\\n2\\n3\\n3\\n\\nExplanationφ(2)\\/2=1\\/2\\nφ(3)\\/3=2\\/3\\nφ(4)\\/4=2\\/4\",\"targets\":\"# cook your dish here\\ndef modular_pow(base, exponent, modulus):\\n result = 1\\n while exponent > 0:\\n  if(exponent %2 == 1):\\n   result = (result * base) % modulus\\n  exponent = exponent\\/\\/2\\n  base = (base * base)%modulus\\n return result\\ndef passesMillerRabinTest(n, a):\\n s = 0\\n d = n-1\\n while(d%2 == 0):\\n  s += 1\\n  d >>= 1\\n x = modular_pow(a, d, n)\\n if(x == 1 or x == n-1):\\n  return True\\n for ss in range(s - 1):\\n  x = (x*x)%n\\n  if(x == 1):\\n   return False\\n  if(x == n-1):\\n   return True\\n return False\\nprimeList = (2, 3,5,7,11,13,17,19, 23,29, 31,37)\\ndef isPrime(n):\\n for p in primeList:\\n  if n%p == 0:\\n   return n == p\\n for p in primeList:\\n  if passesMillerRabinTest(n, p) == False:\\n   return False\\n return True\\n \\nt = int(input())\\nfor tt in range(t):\\n n = int(input())\\n if(n == 2):\\n  print(2)\\n  continue\\n if n%2 == 0:\\n  n -= 1\\n while True:\\n  if(isPrime(n)):\\n   print(n)\\n   break\\n  n -= 2\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/495\\/A:\\nMalek lives in an apartment block with 100 floors numbered from 0 to 99. The apartment has an elevator with a digital counter showing the floor that the elevator is currently on. The elevator shows each digit of a number with 7 light sticks by turning them on or off. The picture below shows how the elevator shows each digit.[Image]\\n\\nOne day when Malek wanted to go from floor 88 to floor 0 using the elevator he noticed that the counter shows number 89 instead of 88. Then when the elevator started moving the number on the counter changed to 87. After a little thinking Malek came to the conclusion that there is only one explanation for this: One of the sticks of the counter was broken. Later that day Malek was thinking about the broken stick and suddenly he came up with the following problem.\\n\\nSuppose the digital counter is showing number n. Malek calls an integer x (0 ≤ x ≤ 99) good if it's possible that the digital counter was supposed to show x but because of some(possibly none) broken sticks it's showing n instead. Malek wants to know number of good integers for a specific n. So you must write a program that calculates this number. Please note that the counter always shows two digits.\\n\\n\\n-----Input-----\\n\\nThe only line of input contains exactly two digits representing number n (0 ≤ n ≤ 99). Note that n may have a leading zero.\\n\\n\\n-----Output-----\\n\\nIn the only line of the output print the number of good integers.\\n\\n\\n-----Examples-----\\nInput\\n89\\n\\nOutput\\n2\\n\\nInput\\n00\\n\\nOutput\\n4\\n\\nInput\\n73\\n\\nOutput\\n15\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample the counter may be supposed to show 88 or 89.\\n\\nIn the second sample the good integers are 00, 08, 80 and 88.\\n\\nIn the third sample the good integers are 03, 08, 09, 33, 38, 39, 73, 78, 79, 83, 88, 89, 93, 98, 99.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"d = dict()\\nd['0'] = [0, 8]\\nd['1'] = [0, 1, 3, 4, 7, 8, 9]\\nd['2'] = [2, 8]\\nd['3'] = [3, 8, 9]\\nd['4'] = [4, 8, 9]\\nd['5'] = [5, 6, 8, 9]\\nd['6'] = [6, 8]\\nd['7'] = [0, 3, 7, 8, 9]\\nd['8'] = [8]\\nd['9'] = [8, 9]\\n\\ns = input()\\n\\nret = 1\\nfor j in [len(d[i]) for i in s]:\\n    ret *= j\\n\\nprint(ret)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nSereja has an array A of N positive integers : A[1], A[2], A[3], ... , A[N]. \\n\\nIn a single operation on the array, he performs the following two steps :  \\n\\n- Pick two indices i, j s.t. A[i] > A[j]\\n- A[i] -= A[j]\\n\\nSereja can apply these operations any number of times (possibly zero), such that the sum of resulting elements of the array is as small as possible.\\n\\nHelp Sereja find this minimum sum.\\n\\n-----Input-----\\n\\nFirst line of input contains an integer T - the number of test cases. T test cases follow.\\n\\nFirst line of each test case contains the integer N. The next line contains N integers — A[1], A[2], A[3], ... , A[N].\\n\\n-----Output-----\\nFor each test case, output a single line with the answer.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 10\\n- 1 ≤ N ≤ 105\\n- 1 ≤ A[i] ≤ 109\\n\\n-----Example-----\\nInput:\\n2\\n1\\n1\\n3\\n2 4 6\\n\\nOutput:\\n1\\n6\\n\\n-----Explanation-----\\nExample case 2. In this case, one possible way in which Sereja can perform the operations could be as follows. \\n\\n-  Pick i = 2, j = 1. A[2] -= A[1]. Now the resulting array would be [2, 2, 6].\\n-  Pick i = 3, j = 2. A[3] -= A[2]. Now the resulting array would be [2, 2, 4].\\n-  Pick i = 3, j = 2. A[3] -= A[2]. Now the resulting array would be [2, 2, 2]. \\n\\nAs the resulting array is [2 2 2], so the sum is 6.\",\"targets\":\"from fractions import gcd\\nfrom functools import reduce\\n\\nt = int(input())\\nfor tt in range(t):\\n n = int(input())\\n arr = list(map(int, input().split()))\\n g = reduce(lambda x,y: gcd(x,y), arr)\\n print(g * n)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a chessboard of size 1 × n. It is guaranteed that n is even. The chessboard is painted like this: \\\"BWBW...BW\\\".\\n\\nSome cells of the board are occupied by the chess pieces. Each cell contains no more than one chess piece. It is known that the total number of pieces equals to $\\\\frac{n}{2}$.\\n\\nIn one step you can move one of the pieces one cell to the left or to the right. You cannot move pieces beyond the borders of the board. You also cannot move pieces to the cells that are already occupied.\\n\\nYour task is to place all the pieces in the cells of the same color using the minimum number of moves (all the pieces must occupy only the black cells or only the white cells after all the moves are made).\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer n (2 ≤ n ≤ 100, n is even) — the size of the chessboard. \\n\\nThe second line of the input contains $\\\\frac{n}{2}$ integer numbers $p_{1}, p_{2}, \\\\ldots, p_{\\\\frac{n}{2}}$ (1 ≤ p_{i} ≤ n) — initial positions of the pieces. It is guaranteed that all the positions are distinct.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the minimum number of moves you have to make to place all the pieces in the cells of the same color.\\n\\n\\n-----Examples-----\\nInput\\n6\\n1 2 6\\n\\nOutput\\n2\\n\\nInput\\n10\\n1 2 3 4 5\\n\\nOutput\\n10\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the only possible strategy is to move the piece at the position 6 to the position 5 and move the piece at the position 2 to the position 3. Notice that if you decide to place the pieces in the white cells the minimum number of moves will be 3.\\n\\nIn the second example the possible strategy is to move $5 \\\\rightarrow 9$ in 4 moves, then $4 \\\\rightarrow 7$ in 3 moves, $3 \\\\rightarrow 5$ in 2 moves and $2 \\\\rightarrow 3$ in 1 move.\",\"targets\":\"n = int(input())\\na = sorted(map(int, input().split()))\\nr1 = sum(abs(a[i] - 2 * i - 1) for i in range(n \\/\\/ 2))\\nr2 = sum(abs(a[i] - 2 * i - 2) for i in range(n \\/\\/ 2))\\nprint(min(r1, r2))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a043724ffe75fbab000009f:\\nWrite a function that takes a list of at least four elements as an argument and returns a list of the middle two or three elements in reverse order.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def reverse_middle(lst):\\n    l = len(lst)\\n    return lst[(l+1)\\/\\/2:(l\\/\\/2)-2:-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn this kata, your task is to create a function that takes a single list as an argument and returns a flattened list. The input list will have a maximum of one level of nesting (list(s) inside of a list).\\n\\n```python\\n# no nesting\\n[1, 2, 3]\\n\\n# one level of nesting\\n[1, [2, 3]]\\n```\\n---\\n\\n# Examples\\n\\n```python\\n>>> flatten_me(['!', '?'])\\n['!', '?']\\n\\n>>> flatten_me([1, [2, 3], 4])\\n[1, 2, 3, 4]\\n\\n>>> flatten_me([['a', 'b'], 'c', ['d']])\\n['a', 'b', 'c', 'd']\\n\\n>>> flatten_me([[True, False], ['!'], ['?'], [71, '@']]) \\n[True, False, '!', '?', 71, '@']\\n```\\n\\nGood luck!\",\"targets\":\"def flatten_me(lst):\\n    res = []\\n    for l in lst:\\n        if isinstance(l, list):\\n            res.extend(l)\\n        else:\\n            res.append(l)\\n    return res\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nConsider the following series:\\n\\n`1, 2, 4, 8, 16, 22, 26, 38, 62, 74, 102, 104, 108, 116, 122`\\n\\nIt is generated as follows:\\n\\n* For single digit integers, add the number to itself to get the next element.\\n* For other integers, multiply all the non-zero digits and add the result to the original number to get the next element.\\n\\nFor example: `16 + (6 * 1) = 22` and `104 + (4 * 1) = 108`. \\n\\nLet's begin the same series with a seed value of `3` instead of `1`:\\n\\n`3, 6, 12, 14, 18, 26, 38, 62, 74, 102, 104, 108, 116, 122`\\n\\nNotice that the two sequences converge at `26` and are identical therefter. We will call the series seeded by a value of `1` the \\\"base series\\\" and the other series the \\\"test series\\\". \\n\\nYou will be given a seed value for the test series and your task will be to return the number of integers that have to be generated in the test series before it converges to the base series. In the case above:\\n```Python\\nconvergence(3) = 5, the length of [3, 6, 12, 14, 18]. \\n```  \\n\\nGood luck!\\n\\nIf you like this Kata, please try:\\n\\n[Simple Prime Streaming](https:\\/\\/www.codewars.com\\/kata\\/5a908da30025e995880000e3)\\n\\n[Unique digit sequence](https:\\/\\/www.codewars.com\\/kata\\/599688d0e2800dda4e0001b0)\\n\\n[Divisor harmony](https:\\/\\/www.codewars.com\\/kata\\/59bf97cd4f98a8b1cd00007e)\",\"targets\":\"from functools import reduce\\n\\ndef calculate_next_el(prev_el):\\n    if prev_el < 10:\\n        return 2 * prev_el\\n    else:\\n        multiplication = reduce((lambda x, y: x * y), [x for x in map(int, str(prev_el)) if x > 0], 1)\\n        return prev_el + multiplication\\n\\ndef generate_series(start):\\n    last = start\\n    while True:\\n        last = calculate_next_el(last)\\n        yield last\\n\\ndef convergence(n):\\n    current_base = 1\\n    current_test = n\\n    base_series = generate_series(current_base)\\n    test_series = generate_series(current_test)\\n    result = 0\\n    while current_base != current_test:\\n        if current_base < current_test:\\n            current_base = base_series.__next__()\\n        else:\\n            current_test = test_series.__next__()\\n            result += 1\\n    return result\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTwo pirates Polycarpus and Vasily play a very interesting game. They have n chests with coins, the chests are numbered with integers from 1 to n. Chest number i has a_{i} coins. \\n\\nPolycarpus and Vasily move in turns. Polycarpus moves first. During a move a player is allowed to choose a positive integer x (2·x + 1 ≤ n) and take a coin from each chest with numbers x, 2·x, 2·x + 1. It may turn out that some chest has no coins, in this case the player doesn't take a coin from this chest. The game finishes when all chests get emptied.\\n\\nPolycarpus isn't a greedy scrooge. Polycarpys is a lazy slob. So he wonders in what minimum number of moves the game can finish. Help Polycarpus, determine the minimum number of moves in which the game can finish. Note that Polycarpus counts not only his moves, he also counts Vasily's moves.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 100) — the number of chests with coins. The second line contains a sequence of space-separated integers: a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 1000), where a_{i} is the number of coins in the chest number i at the beginning of the game.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum number of moves needed to finish the game. If no sequence of turns leads to finishing the game, print -1.\\n\\n\\n-----Examples-----\\nInput\\n1\\n1\\n\\nOutput\\n-1\\n\\nInput\\n3\\n1 2 3\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case there isn't a single move that can be made. That's why the players won't be able to empty the chests.\\n\\nIn the second sample there is only one possible move x = 1. This move should be repeated at least 3 times to empty the third chest.\",\"targets\":\"n, s = int(input()), 0\\na = [0] + list(map(int, input().split()))\\nif n % 2 == 0 or n == 1:\\n  print(-1)\\nelse:\\n  for i in range(n, 1, -2):\\n    mx = max(a[i], a[i - 1])\\n    s += mx\\n    a[i \\/\\/ 2] = max(0, a[i \\/\\/ 2] - mx)\\n  print(s + a[1])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc164\\/tasks\\/abc164_f:\\nGiven are an integer N and arrays S, T, U, and V, each of length N.\\nConstruct an N×N matrix a that satisfy the following conditions:\\n - a_{i,j} is an integer.\\n - 0 \\\\leq a_{i,j}  \\\\lt 2^{64}.\\n - If S_{i} = 0, the bitwise AND of the elements in the i-th row is U_{i}.\\n - If S_{i} = 1, the bitwise OR of the elements in the i-th row is U_{i}.\\n - If T_{i} = 0, the bitwise AND of the elements in the i-th column is V_{i}.\\n - If T_{i} = 1, the bitwise OR of the elements in the i-th column is V_{i}.\\nHowever, there may be cases where no matrix satisfies the conditions.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n -  1 \\\\leq N \\\\leq 500 \\n -  0 \\\\leq S_{i} \\\\leq 1 \\n -  0 \\\\leq T_{i} \\\\leq 1  \\n -  0 \\\\leq U_{i} \\\\lt 2^{64}  \\n -  0 \\\\leq V_{i} \\\\lt 2^{64}  \\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nS_{1} S_{2} ...  S_{N}\\nT_{1} T_{2} ...  T_{N}\\nU_{1} U_{2} ...  U_{N}\\nV_{1} V_{2} ...  V_{N}\\n\\n-----Output-----\\nIf there exists a matrix that satisfies the conditions, print one such matrix in the following format:\\na_{1,1} ...  a_{1,N}\\n:\\na_{N,1} ...  a_{N,N}\\n\\nNote that any matrix satisfying the conditions is accepted.\\nIf no matrix satisfies the conditions, print -1.\\n\\n-----Sample Input-----\\n2\\n0 1\\n1 0\\n1 1\\n1 0\\n\\n-----Sample Output-----\\n1 1\\n1 0\\n\\nIn Sample Input 1, we need to find a matrix such that:\\n - the bitwise AND of the elements in the 1-st row is 1;\\n - the bitwise OR of the elements in the 2-nd row is 1;\\n - the bitwise OR of the elements in the 1-st column is 1;\\n - the bitwise AND of the elements in the 2-nd column is 0.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n    import sys\\n    sys.setrecursionlimit(10**9)\\n    input = sys.stdin.readline\\n\\n    N = int(input())\\n    S = list(map(int, input().split()))\\n    T = list(map(int, input().split()))\\n    U = list(map(int, input().split()))\\n    V = list(map(int, input().split()))\\n\\n    range_N = list(range(N))\\n    ans = [[0]*N for _ in range_N]\\n    # 論理積\\n    for i in range_N:\\n        if S[i] == 0:\\n            for j in range_N:\\n                ans[i][j] = ans[i][j] | U[i]\\n        if T[i] == 0:   \\n            for j in range_N:\\n                ans[j][i] = ans[j][i] | V[i]\\n    for i in range_N:\\n        for j in range_N:\\n            if (U[i] & V[j]):\\n                ans[i][j] = ans[i][j] | (U[i] & V[j])\\n\\n    # 論理和\\n    for x in range_N:\\n        if S[x] == 0:\\n            continue\\n        x_sum = ans[x][0]\\n        for y in range_N:\\n            x_sum = x_sum | ans[x][y]\\n        if x_sum == U[x]:\\n            continue\\n        up = U[x] - x_sum\\n        for y in range_N:\\n            if T[y]:\\n                continue\\n            y_mul = ans[0][y]\\n            for i in range_N:\\n                if i == x:\\n                    continue\\n                y_mul = y_mul & ans[i][y]\\n            up_y = (~y_mul) & up\\n            ans[x][y] += up_y\\n            up -= up_y\\n            if up == 0:\\n                break\\n\\n    for y in range_N:\\n        if T[y] == 0:\\n            continue\\n        y_sum = ans[0][y]\\n        for x in range_N:\\n            y_sum = y_sum | ans[x][y]\\n        if y_sum == V[y]: \\n            continue\\n        up = V[y] - y_sum\\n        for x in range_N:\\n            if S[x]:\\n                continue\\n            x_mul = ans[x][0]\\n            for j in range_N:\\n                if y == j:\\n                    continue\\n                x_mul = x_mul & ans[x][j]\\n            up_x = (~x_mul) & up\\n            ans[x][y] += up_x\\n            up -= up_x\\n            if up == 0:\\n                break\\n\\n    # チェック\\n    for i in range_N:\\n        check_xs = ans[i][0]\\n        check_ys = ans[0][i]\\n        check_xm = ans[i][0]\\n        check_ym = ans[0][i]\\n  ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc135\\/tasks\\/abc135_d:\\nGiven is a string S. Each character in S is either a digit (0, ..., 9) or ?.\\nAmong the integers obtained by replacing each occurrence of ? with a digit, how many have a remainder of 5 when divided by 13? An integer may begin with 0.\\nSince the answer can be enormous, print the count modulo 10^9+7.\\n\\n-----Constraints-----\\n - S is a string consisting of digits (0, ..., 9) and ?.\\n - 1 \\\\leq |S| \\\\leq 10^5\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nS\\n\\n-----Output-----\\nPrint the number of integers satisfying the condition, modulo 10^9+7.\\n\\n-----Sample Input-----\\n??2??5\\n\\n-----Sample Output-----\\n768\\n\\nFor example, 482305, 002865, and 972665 satisfy the condition.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n    MOD = 10 ** 9 + 7\\n\\n    s = input()\\n    r = [0] * 13\\n    r[0] = 1\\n    p = 1\\n    for c in reversed(s):\\n        if c == '?':\\n            tank = []\\n            for x in range(10):\\n                x = x * p % 13\\n                tank.append(r[13 - x:] + r[:13 - x])\\n            r = list(map(sum, list(zip(*tank))))\\n            *r, = [x % MOD for x in r]\\n\\n\\n        else:\\n            x = int(c)\\n            x = x * p % 13\\n            r = r[13 - x:] + r[:13 - x]\\n        p = p * 10 % 13\\n\\n    print((r[5]))\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA [binary search tree](https:\\/\\/en.wikipedia.org\\/wiki\\/Binary_search_tree) is a binary tree that is ordered. This means that if you were to convert the tree to an array using an in-order traversal, the array would be in sorted order. The benefit gained by this ordering is that when the tree is balanced, searching is a logarithmic time operation, since each node you look at that isn't the one you're searching for lets you discard half of the tree.\\n\\nIf you haven't worked with binary trees before or don't understand what a traversal is, you can learn more about that here: https:\\/\\/www.codewars.com\\/kata\\/binary-tree-traversal.\\n\\nIn this kata, you will write a function that will validate that a given binary tree is a binary search tree. The sort order is not predefined so it should work with either.\\n\\nThese are valid binary search trees:\\n\\n        5\\n       \\/ \\\\\\n      2   7\\n     \\/ \\\\   \\\\\\n    1   3   9\\n\\n\\n      7\\n     \\/ \\\\\\n    9   2\\n\\n\\nwhile these are not:\\n\\n      1\\n     \\/ \\\\\\n    2   3\\n\\n\\n      5\\n     \\/ \\\\\\n    2   9\\n     \\\\\\n      7\\n\\nThere are several different approaches you can take to solve this kata. If you're not as comfortable with recursion I'd recommend practicing that.\\n\\nNote: no test case tree will contain duplicate numbers.\",\"targets\":\"class T:\\n    def __init__(self,value,left=None,right=None):\\n        self.value=value\\n        self.left=left\\n        self.right=right\\n\\n\\ndef is_bst(node):\\n\\n    def extract(node):\\n        if node is not None:\\n            yield from extract(node.left)\\n            yield node.value\\n            yield from extract(node.right)\\n    \\n    gen = extract(node)\\n    try:\\n        u, v = next(gen), next(gen)\\n    except StopIteration:\\n        return True\\n    \\n    cmp = u<v\\n    for w in gen:\\n        if cmp != (v<w): return False\\n        v = w\\n    return True\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nSalve, mi amice.\\n\\nEt tu quidem de lapis philosophorum. Barba non facit philosophum. Labor omnia vincit. Non potest creatio ex nihilo. Necesse est partibus.\\n\\nRp:\\n\\n    I Aqua Fortis\\n\\n    I Aqua Regia\\n\\n    II Amalgama\\n\\n    VII Minium\\n\\n    IV Vitriol\\n\\nMisce in vitro et æstus, et nil admirari. Festina lente, et nulla tenaci invia est via.\\n\\nFac et spera,\\n\\nVale,\\n\\nNicolas Flamel\\n\\n\\n-----Input-----\\n\\nThe first line of input contains several space-separated integers a_{i} (0 ≤ a_{i} ≤ 100).\\n\\n\\n-----Output-----\\n\\nPrint a single integer.\\n\\n\\n-----Examples-----\\nInput\\n2 4 6 8 10\\n\\nOutput\\n1\",\"targets\":\"from math import floor\\nnums = list(map(int, input().split()))\\nseq = [1, 1, 2, 7, 4]\\n\\nmin_c = 10000000000\\nfor i in range(len(nums)):\\n    if floor(nums[i] \\/ seq[i]) < min_c:\\n        min_c = floor(nums[i] \\/ seq[i])\\nprint(min_c)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPrint the circumference of a circle of radius R.\\n\\n-----Constraints-----\\n - 1 \\\\leq R \\\\leq 100\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nR\\n\\n-----Output-----\\nPrint the circumference of the circle.\\nYour output is considered correct if and only if its absolute or relative error from our answer is at most 10^{-2}.\\n\\n-----Sample Input-----\\n1\\n\\n-----Sample Output-----\\n6.28318530717958623200\\n\\nSince we accept an absolute or relative error of at most 10^{-2}, 6.28 is also an acceptable output, but 6 is not.\",\"targets\":\"import math\\nr = int(input())\\nx = float(2*r*math.pi)\\nprint(x)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nDima loves Inna very much. He decided to write a song for her. Dima has a magic guitar with n strings and m frets. Dima makes the guitar produce sounds like that: to play a note, he needs to hold one of the strings on one of the frets and then pull the string. When Dima pulls the i-th string holding it on the j-th fret the guitar produces a note, let's denote it as a_{ij}. We know that Dima's guitar can produce k distinct notes. It is possible that some notes can be produced in multiple ways. In other words, it is possible that a_{ij} = a_{pq} at (i, j) ≠ (p, q).\\n\\nDima has already written a song — a sequence of s notes. In order to play the song, you need to consecutively produce the notes from the song on the guitar. You can produce each note in any available way. Dima understood that there are many ways to play a song and he wants to play it so as to make the song look as complicated as possible (try to act like Cobein).\\n\\nWe'll represent a way to play a song as a sequence of pairs (x_{i}, y_{i}) (1 ≤ i ≤ s), such that the x_{i}-th string on the y_{i}-th fret produces the i-th note from the song. The complexity of moving between pairs (x_1, y_1) and (x_2, y_2) equals $|x_{1} - x_{2}|$ + $|y_{1} - y_{2}|$. The complexity of a way to play a song is the maximum of complexities of moving between adjacent pairs.\\n\\nHelp Dima determine the maximum complexity of the way to play his song! The guy's gotta look cool!\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains four integers n, m, k and s (1 ≤ n, m ≤ 2000, 1 ≤ k ≤ 9, 2 ≤ s ≤ 10^5). \\n\\nThen follow n lines, each containing m integers a_{ij} (1 ≤ a_{ij} ≤ k). The number in the i-th row and the j-th column (a_{ij}) means a note that the guitar produces on the i-th string and the j-th fret.\\n\\nThe last line of the input contains s integers q_{i} (1 ≤ q_{i} ≤ k) — the sequence of notes of the song.\\n\\n\\n-----Output-----\\n\\nIn a single line print a single number — the maximum possible complexity of the song.\\n\\n\\n-----Examples-----\\nInput\\n4 6 5 7\\n3 1 2 2 3 1\\n3 2 2 2 5 5\\n4 2 2 2...\",\"targets\":\"def solution() : # 最大的距离来自于角落附近的点\\n\\tn,m,k,s = map(int, input().split())\\n\\tdis = lambda a,b : abs(a[0] - b[0]) + abs(a[1] - b[1])\\n\\tcorner = [(0,0), (0,m-1), (n-1,0), (n-1,m-1)]\\n\\tvertex = [[(n,m), (n,-1), (-1,m), (-1,-1)] for _ in range(k+1)]\\n\\tfor i in range(n) :\\n\\t\\tfor j,note in enumerate(map(int, input().split())) :\\n\\t\\t\\tvertex[note] = [\\n\\t\\t\\t\\t(i,j) if dis((i,j), c) < dis(v, c) else v\\n\\t\\t\\t\\tfor v,c in zip(vertex[note], corner)]\\n\\tmaxdis = [[-1] * (k+1) for _ in range(k+1)]\\n\\tpairs = [(0,3),(3,0),(1,2),(2,1)]\\n\\tfor i in range(1, k+1) :\\n\\t\\tfor j in range(i, k+1) :\\n\\t\\t\\tvi,vj = vertex[i],vertex[j]\\n\\t\\t\\tmaxdis[i][j] = max(dis(vi[a], vj[b]) for a,b in pairs)\\n\\t\\t\\tmaxdis[j][i] = maxdis[i][j]\\n\\ts = list(map(int, input().split()))\\n\\tprint(max(maxdis[s[i]][s[i+1]] for i in range(len(s) - 1)))\\nsolution()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFizza is a cute girl and she wants to be more beautiful.\\nSo she approached a magician to increase her beauty magically. But the magician's \\nglasses accidently got locked inside the locker and he forgot the password. Without\\nglasses he can't help her. The password is hidden in N integers i.e. $a[1], a[2], ..... a[N]$ \\nwritten on his magical stick.The password is the maximum number of moves Fizza can perform, for any position $i$ such that 1 < = $i$ < = $N$ and integer $X$ is present at $i$-th\\nposition. In one move she can perform one of the following operations ->\\n$(1)$  If ( $i$ + 1 < = $N$ ) she can go to position ($i$ + 1 ) if integer at ( $i$ + 1 )-th \\nposition is equal to $X$.\\n$(2)$ if ( $i$ + 2 < = $N$ ) she can go to position ($i$ + 2 ) if integer at ($i$ + 2)-th \\nposition is equal to $X$.\\nFizza is a bit worried about her beauty so she can't focus on the problem but she asked for \\nyour help to find the password.\\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase consists of  two lines of input.\\n- Input $N$.\\n- Input $N$ integers . \\n\\n-----Output:-----\\nFor each testcase, output in a single line Maximum number of moves.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $1 \\\\leq N \\\\leq 10^5$\\n- $1 \\\\leq a[i] \\\\leq 2*10^5$\\n\\n-----Sample Input:-----\\n3\\n8\\n6 3 6 4 5 4 3 6\\n9\\n5 5 4 5 2 1 3 4 2\\n6\\n1 2 3 4 5 6\\n\\n-----Sample Output:-----\\n1\\n2\\n0\\n\\n-----EXPLANATION:-----\\nIn the first case, integers at position 1 and 3 are the same and at alternate positions.\\nIn the second case, integers at position 1, 2, 4 follow the conditions.\",\"targets\":\"def check(l,n):\\n    m = 0\\n    for i in range(n-1):\\n        x = l[i]\\n        c = 0\\n        j = i\\n        while (j+2<n and l[j+2]==x) or (j+1<n and l[j+1] == x):\\n            if l[j+1] == x:\\n                j = j+1\\n            else:\\n                j+=2\\n            c+=1\\n        if m<c:\\n            m = c\\n    return m\\n\\nt = int(input())\\nfor _ in range(t):\\n    no = int(input())\\n    a = list(map(int,input().split()))\\n    print(check(a,no))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1360\\/G:\\nYou are given four positive integers $n$, $m$, $a$, $b$ ($1 \\\\le b \\\\le n \\\\le 50$; $1 \\\\le a \\\\le m \\\\le 50$). Find any such rectangular matrix of size $n \\\\times m$ that satisfies all of the following conditions:\\n\\n  each row of the matrix contains exactly $a$ ones;  each column of the matrix contains exactly $b$ ones;  all other elements are zeros. \\n\\nIf the desired matrix does not exist, indicate this.\\n\\nFor example, for $n=3$, $m=6$, $a=2$, $b=1$, there exists a matrix satisfying the conditions above:\\n\\n$$ \\\\begin{vmatrix} 0 & 1 & 0 & 0 & 0 & 1 \\\\\\\\ 1 & 0 & 0 & 1 & 0 & 0 \\\\\\\\ 0 & 0 & 1 & 0 & 1 & 0 \\\\end{vmatrix} $$\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases. Then $t$ test cases follow.\\n\\nEach test case is described by four positive integers $n$, $m$, $a$, $b$ ($1 \\\\le b \\\\le n \\\\le 50$; $1 \\\\le a \\\\le m \\\\le 50$), where $n$ and $m$ are the sizes of the matrix, and $a$ and $b$ are the number of ones for rows and columns, respectively.\\n\\n\\n-----Output-----\\n\\nFor each test case print:\\n\\n  \\\"YES\\\" (without quotes) and the required matrix (if there are several answers, print any) if it exists, or  \\\"NO\\\" (without quotes) if it does not exist. \\n\\nTo print the matrix $n \\\\times m$, print $n$ rows, each of which consists of $m$ numbers $0$ or $1$ describing a row of the matrix. Numbers must be printed without spaces.\\n\\n\\n-----Example-----\\nInput\\n5\\n3 6 2 1\\n2 2 2 1\\n2 2 2 2\\n4 4 2 2\\n2 1 1 2\\n\\nOutput\\nYES\\n010001\\n100100\\n001010\\nNO\\nYES\\n11\\n11\\nYES\\n1100\\n1100\\n0011\\n0011\\nYES\\n1\\n1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# -*- coding: utf-8 -*-\\nimport sys\\n# sys.setrecursionlimit(10**6)\\n# buff_readline = sys.stdin.buffer.readline\\nbuff_readline = sys.stdin.readline\\nreadline = sys.stdin.readline\\n\\nINF = 2**62-1\\n\\n\\ndef read_int():\\n    return int(buff_readline())\\n\\n\\ndef read_int_n():\\n    return list(map(int, buff_readline().split()))\\n\\n\\n# @mt\\ndef slv(N, M, A, B):\\n    if N * A != M*B:\\n        print('NO')\\n        return\\n\\n    print('YES')\\n    mat = [[0] * M for _ in range(N)]\\n    for i in range(N):\\n        for j in range(A):\\n            mat[i][(i*A+j)%M] = 1\\n\\n    for r in mat:\\n        print(''.join(map(str, r)))\\n\\n\\n\\ndef main():\\n    T = read_int()\\n    for _ in range(T):\\n        N, M, A, B = read_int_n()\\n        slv(N, M, A, B)\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are some perfect squares with a particular property.\\nFor example the number ```n = 256``` is a perfect square, its square root is ```16```. If we change the position of the digits of n, we may obtain another perfect square``` 625``` (square root = 25).\\nWith these three digits ```2```,```5``` and ```6``` we can get two perfect squares: ```[256,625]```\\n\\nThe number ```1354896``` may generate another ```4``` perfect squares, having with the number itself, a total of five perfect squares: ```[1354896, 3594816, 3481956, 5391684, 6395841]```, being the last one in the list, ```6395841```, the highest value of the set.\\n\\nYour task is to find the first perfect square above the given lower_limit, that can generate the given k number of perfect squares, and it doesn't contain the digit 0. Then return the maximum perfect square that can be obtained from its digits.\\n\\nExample with the cases seen above:\\n```\\nlower_limit = 200\\nk = 2 (amount of perfect squares)\\nresult = 625\\n\\nlower_limit = 3550000\\nk = 5 (amount of perfect squares)\\nresult  = 6395841\\n```\\nFeatures of the random tests:\\n```\\n100 <= lower_limit <= 1e6\\n2 <= k <= 5\\nnumber of tests = 45\\n```\\nHave a good time!\",\"targets\":\"candidates = ((sq, str(sq)) for sq in (i*i for i in range(12, 3000)))\\ncandidates = ((sq, s) for sq, s in candidates if '0' not in s)\\n\\nd = {}  # 144: [144, 441], 256: [256, 625], ...\\nsqs = {}  # 144: [144, 441], 256: [256, 625], 441: [144, 441], 625: [256, 625], ...\\nfor sq, s in candidates:\\n    sqs[sq] = d.setdefault(int(''.join(sorted(s))), [])\\n    sqs[sq].append(sq)\\n\\ndef next_perfectsq_perm(lower_limit, k): \\n    return sqs[min(x for x in sqs if x > lower_limit and len(sqs[x]) == k)][-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/612\\/B:\\nHDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.\\n\\nOne of the problems of HDD hard drives is the following: the magnetic head should move from one sector to another to read some file.\\n\\nFind the time need to read file split to n fragments. The i-th sector contains the f_{i}-th fragment of the file (1 ≤ f_{i} ≤ n). Note different sectors contains the different fragments. At the start the magnetic head is in the position that contains the first fragment. The file are reading in the following manner: at first the first fragment is read, then the magnetic head moves to the sector that contains the second fragment, then the second fragment is read and so on until the n-th fragment is read. The fragments are read in the order from the first to the n-th.\\n\\nIt takes |a - b| time units to move the magnetic head from the sector a to the sector b. Reading a fragment takes no time.\\n\\n\\n-----Input-----\\n\\nThe first line contains a positive integer n (1 ≤ n ≤ 2·10^5) — the number of fragments.\\n\\nThe second line contains n different integers f_{i} (1 ≤ f_{i} ≤ n) — the number of the fragment written in the i-th sector.\\n\\n\\n-----Output-----\\n\\nPrint the only integer — the number of time units needed to read the file.\\n\\n\\n-----Examples-----\\nInput\\n3\\n3 1 2\\n\\nOutput\\n3\\n\\nInput\\n5\\n1 3 5 4 2\\n\\nOutput\\n10\\n\\n\\n\\n-----Note-----\\n\\nIn the second example the head moves in the following way:  1->2 means movement from the sector 1 to the sector 5, i.e. it takes 4 time units  2->3 means movement from the sector 5 to the sector 2, i.e. it takes 3 time units  3->4 means movement from the sector 2 to the sector 4, i.e. it takes 2 time units  4->5 means movement from the sector 4 to the sector 3, i.e. it takes 1 time units \\n\\nSo the answer to the second example is 4 + 3 + 2 + 1 = 10.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"##n,p,q=map(int,input().split())\\n##\\n##s=input()\\n##\\n##l=list()\\n##\\n##while len(s):\\n##    if len(s)%p!=0 and len(s)>=q:\\n##        l.append(s[0:q])\\n##        s=s[q:]\\n##    elif len(s)%p==0 and len(s)>=p:\\n##        l.append(s[0:p])\\n##        s=s[p:]\\n##    else:\\n##        break\\n##if len(s):\\n##    print(-1)\\n##else:\\n##    print(len(l))\\n##    for x in l:\\n##        print(x)\\n\\nn=input()\\ns=list(input().split())\\n\\ni=1\\nl=list()\\nfor x in s:\\n    l.append((int(x),i))\\n    i+=1\\nl.sort()\\nans=0\\nfor i in range(1,len(l)):\\n    ans+=abs(l[i][1]-l[i-1][1])\\n    \\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1236\\/A:\\nAlice is playing with some stones.\\n\\nNow there are three numbered heaps of stones. The first of them contains $a$ stones, the second of them contains $b$ stones and the third of them contains $c$ stones.\\n\\nEach time she can do one of two operations:  take one stone from the first heap and two stones from the second heap (this operation can be done only if the first heap contains at least one stone and the second heap contains at least two stones);  take one stone from the second heap and two stones from the third heap (this operation can be done only if the second heap contains at least one stone and the third heap contains at least two stones). \\n\\nShe wants to get the maximum number of stones, but she doesn't know what to do. Initially, she has $0$ stones. Can you help her?\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\leq t \\\\leq 100$)  — the number of test cases. Next $t$ lines describe test cases in the following format:\\n\\nLine contains three non-negative integers $a$, $b$ and $c$, separated by spaces ($0 \\\\leq a,b,c \\\\leq 100$) — the number of stones in the first, the second and the third heap, respectively.\\n\\nIn hacks it is allowed to use only one test case in the input, so $t = 1$ should be satisfied.\\n\\n\\n-----Output-----\\n\\nPrint $t$ lines, the answers to the test cases in the same order as in the input. The answer to the test case is the integer  — the maximum possible number of stones that Alice can take after making some operations. \\n\\n\\n-----Example-----\\nInput\\n3\\n3 4 5\\n1 0 5\\n5 3 2\\n\\nOutput\\n9\\n0\\n6\\n\\n\\n\\n-----Note-----\\n\\nFor the first test case in the first test, Alice can take two stones from the second heap and four stones from the third heap, making the second operation two times. Then she can take one stone from the first heap and two stones from the second heap, making the first operation one time. The summary number of stones, that Alice will take is $9$. It is impossible to make some operations to take more than $9$ stones, so the answer is $9$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nreadline = sys.stdin.readline\\n\\nN = int(readline())\\n\\nAns = [None]*N\\nfor qu in range(N):\\n    A, B, C = map(int, readline().split())\\n    res = 0\\n    for a in range(A+1):\\n        if 2*a > B:\\n            break\\n        cnt = 3*a\\n        t = B - 2*a\\n        t = min(t, C\\/\\/2)\\n        cnt += 3*t\\n        res = max(res, cnt)\\n    Ans[qu] = res\\n\\nprint('\\\\n'.join(map(str, Ans)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an array of $n$ integers $a_1, a_2, \\\\ldots, a_n$.\\n\\nYou will perform $q$ operations. In the $i$-th operation, you have a symbol $s_i$ which is either \\\"<\\\" or \\\">\\\" and a number $x_i$.\\n\\nYou make a new array $b$ such that $b_j = -a_j$ if $a_j s_i x_i$ and $b_j = a_j$ otherwise (i.e. if $s_i$ is '>', then all $a_j > x_i$ will be flipped). After doing all these replacements, $a$ is set to be $b$.\\n\\nYou want to know what your final array looks like after all operations.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n,q$ ($1 \\\\leq n,q \\\\leq 10^5$) — the number of integers and the number of queries.\\n\\nThe next line contains $n$ integers $a_1, a_2, \\\\ldots, a_n$ ($-10^5 \\\\leq a_i \\\\leq 10^5$) — the numbers.\\n\\nEach of the next $q$ lines contains a character and an integer $s_i, x_i$. ($s_i \\\\in \\\\{<, >\\\\}, -10^5 \\\\leq x_i \\\\leq 10^5$) – the queries.\\n\\n\\n-----Output-----\\n\\nPrint $n$ integers $c_1, c_2, \\\\ldots, c_n$ representing the array after all operations.\\n\\n\\n-----Examples-----\\nInput\\n11 3\\n-5 -4 -3 -2 -1 0 1 2 3 4 5\\n> 2\\n> -4\\n< 5\\n\\nOutput\\n5 4 -3 -2 -1 0 1 2 -3 4 5\\n\\nInput\\n5 5\\n0 1 -2 -1 2\\n< -2\\n< -1\\n< 0\\n< 1\\n< 2\\n\\nOutput\\n0 -1 2 -1 2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, the array goes through the following changes:   Initial: $[-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5]$  $> 2$: $[-5, -4, -3, -2, -1, 0, 1, 2, -3, -4, -5]$  $> -4$: $[-5, -4, 3, 2, 1, 0, -1, -2, 3, -4, -5]$  $< 5$: $[5, 4, -3, -2, -1, 0, 1, 2, -3, 4, 5]$\",\"targets\":\"n,q=map(int,input().split())\\na=list(map(int,input().split()))\\nswaps=[0]*q\\nfor i in range(q):\\n    b=input().split()\\n    b[1]=int(b[1])\\n    out=1 if (b[0]==\\\"<\\\" and b[1]<=0) or (b[0]==\\\">\\\" and b[1]>=0) else 0\\n    split=b[1]+0.5 if b[0]==\\\">\\\" else b[1]-0.5\\n    sign=1 if split>0 else -1\\n    split=abs(split)\\n    swaps[i]=(split,sign,out)\\nsml=10**5+0.5\\nzeros=0\\nfor i in range(q):\\n    sml=min(swaps[i][0],sml)\\n    zeros+=1-swaps[i][2]\\nzeros%=2\\narr=[0]*100001\\nbig=100000.5\\nflips=1\\nfor i in range(q):\\n    if swaps[-1-i][0]<big:\\n        if swaps[-1-i][2]==1:\\n            for j in range(int(swaps[-1-i][0]+0.5),int(big+0.5)):\\n                arr[j]=-swaps[-i-1][1]*flips\\n        else:\\n            for j in range(int(swaps[-1-i][0]+0.5),int(big+0.5)):\\n                arr[j]=swaps[-i-1][1]*flips\\n        big=swaps[-1-i][0]\\n    if swaps[-1-i][2]==0:\\n        flips=-flips\\ndef func(k):\\n    if abs(k)<sml:\\n        return k if zeros==0 else -k\\n    else:\\n        return arr[abs(k)]*abs(k)\\nprint(\\\" \\\".join([str(func(guy)) for guy in a]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nSitting in a station waiting room, Joisino is gazing at her train ticket.\\nThe ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).\\nIn the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.\\nThe given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.\\n\\n-----Constraints-----\\n - 0≤A,B,C,D≤9\\n - All input values are integers.\\n - It is guaranteed that there is a solution.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nABCD\\n\\n-----Output-----\\nPrint the formula you made, including the part =7.\\nUse the signs + and -.\\nDo not print a space between a digit and a sign.\\n\\n-----Sample Input-----\\n1222\\n\\n-----Sample Output-----\\n1+2+2+2=7\\n\\nThis is the only valid solution.\",\"targets\":\"import itertools\\nx = input()\\nfor v in itertools.product([\\\"+\\\", \\\"-\\\"], repeat=3):\\n    t = x[0]+v[0]+x[1]+v[1]+x[2]+v[2]+x[3]\\n    if eval(t) == 7: break\\nprint(t+\\\"=7\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/arc097\\/tasks\\/arc097_c:\\nThere are 2N balls, N white and N black, arranged in a row. The integers from 1 through N are written on the white balls, one on each ball, and they are also written on the black balls, one on each ball.\\nThe integer written on the i-th ball from the left (1 ≤ i ≤ 2N) is a_i, and the color of this ball is represented by a letter c_i.\\nc_i = W represents the ball is white; c_i = B represents the ball is black.\\nTakahashi the human wants to achieve the following objective:\\n - For every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the white ball with i written on it is to the left of the white ball with j written on it.\\n - For every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the black ball with i written on it is to the left of the black ball with j written on it.\\nIn order to achieve this, he can perform the following operation:\\n - Swap two adjacent balls.\\nFind the minimum number of operations required to achieve the objective.\\n\\n-----Constraints-----\\n - 1 ≤ N ≤ 2000\\n - 1 ≤ a_i ≤ N\\n - c_i = W or c_i = B.\\n - If i ≠ j, (a_i,c_i) ≠ (a_j,c_j).\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nc_1 a_1\\nc_2 a_2\\n:\\nc_{2N} a_{2N}\\n\\n-----Output-----\\nPrint the minimum number of operations required to achieve the objective.\\n\\n-----Sample Input-----\\n3\\nB 1\\nW 2\\nB 3\\nW 1\\nW 3\\nB 2\\n\\n-----Sample Output-----\\n4\\n\\nThe objective can be achieved in four operations, for example, as follows:\\n - Swap the black 3 and white 1.\\n - Swap the white 1 and white 2.\\n - Swap the black 3 and white 3.\\n - Swap the black 3 and black 2.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N = int(input())\\nX = [i for i in range(N+1)]\\nY = [[] for _ in range(N)]\\nB, W = [], []\\nans = 0\\nfor i in range(2 * N):\\n    c, a = input().split()\\n    a = int(a) - 1\\n    if c == \\\"B\\\":\\n        X = [X[i] + 1 if i <= a else X[i] - 1 for i in range(N+1)]\\n        B.append(a)\\n        ans += len([b for b in B if b > a])\\n    else:\\n        Y[a] = X[:]\\n        W.append(a)\\n        ans += len([b for b in W if b > a])\\n\\nZ = [0] * (N+1)\\nfor y in Y:\\n    for i in range(N+1):\\n        Z[i] += y[i]\\n    for i in range(1, N+1):\\n        Z[i] = min(Z[i], Z[i-1])\\n\\nans += Z[-1]\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven an Array and an Example-Array to sort to, write a function that sorts the Array following the Example-Array.\\n\\nAssume Example Array catalogs all elements possibly seen in the input Array. However, the input Array does not necessarily have to have all elements seen in the Example.\\n\\nExample:\\n\\nArr:\\n[1,3,4,4,4,4,5]\\n\\nExample Arr:\\n[4,1,2,3,5]\\n\\nResult:\\n[4,4,4,4,1,3,5]\",\"targets\":\"def example_sort(arr, example_arr):\\n    return [x for x in example_arr for y in arr if x == y]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring).\\nThe score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring.\\n \\nExample 1:\\nInput: s = \\\"011101\\\"\\nOutput: 5 \\nExplanation: \\nAll possible ways of splitting s into two non-empty substrings are:\\nleft = \\\"0\\\" and right = \\\"11101\\\", score = 1 + 4 = 5 \\nleft = \\\"01\\\" and right = \\\"1101\\\", score = 1 + 3 = 4 \\nleft = \\\"011\\\" and right = \\\"101\\\", score = 1 + 2 = 3 \\nleft = \\\"0111\\\" and right = \\\"01\\\", score = 1 + 1 = 2 \\nleft = \\\"01110\\\" and right = \\\"1\\\", score = 2 + 1 = 3\\n\\nExample 2:\\nInput: s = \\\"00111\\\"\\nOutput: 5\\nExplanation: When left = \\\"00\\\" and right = \\\"111\\\", we get the maximum score = 2 + 3 = 5\\n\\nExample 3:\\nInput: s = \\\"1111\\\"\\nOutput: 3\\n\\n \\nConstraints:\\n\\n2 <= s.length <= 500\\nThe string s consists of characters '0' and '1' only.\",\"targets\":\"class Solution:\\n    def maxScore(self, s: str) -> int:\\n        res = 0\\n        for i in range(len(s)):\\n            if(i != len(s)-1):\\n                t = self.calcScore(s[:i+1],s[i+1:])\\n                res = max(res,t)\\n        return res\\n    def calcScore(self,s1:str,s2:str) -> int:\\n        return s1.count('0') + s2.count('1')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nComplete the solution. It should try to retrieve the value of the array at the index provided. If the index is out of the array's max bounds then it should return the default value instead. \\n\\nExample:\\n```Haskell\\nsolution [1..3] 1 1000 `shouldBe` 2\\nsolution [1..5] (10) 1000 `shouldBe` 1000\\n-- negative values work as long as they are not out of the length bounds\\nsolution [1..3] (-1) 1000 `shouldBe` 3\\nsolution [1..3] (-5) 1000 `shouldBe` 1000\\nsolution [1..3] (-3) 1000 `shouldBe` 1\\nsolution [1..5] (-3) 1000 `shouldBe` 3\\n-- for Haskell default value will always be a (random) number, not a character.\\n```\\n\\n```python\\ndata = ['a', 'b', 'c']\\nsolution(data, 1, 'd') # should == 'b'\\nsolution(data, 5, 'd') # should == 'd'\\n\\n# negative values work as long as they aren't out of the length bounds\\nsolution(data, -1, 'd') # should == 'c'\\nsolution(data, -5, 'd') # should == 'd'\\n```\",\"targets\":\"def solution(items, index, default_value):\\n    try:\\n        return items[index]\\n    except LookupError:\\n        return default_value\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA Madhav array has the following property:\\n\\n```a[0] = a[1] + a[2] = a[3] + a[4] + a[5] = a[6] + a[7] + a[8] + a[9] = ...```\\n\\nComplete the function\\/method that returns `true` if the given array is a Madhav array, otherwise it returns `false`.\\n\\n*Edge cases: An array of length* `0` *or* `1` *should not be considered a Madhav array as there is nothing to compare.*\",\"targets\":\"def is_madhav_array(arr):\\n    def check(a, n=1):\\n        return True if len(a) == n else sum(a[:n]) == sum(a[n:2*n+1]) and check(a[n:], n + 1)\\n    return False if len(arr) <= 1 else check(arr)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nRyouko is an extremely forgetful girl, she could even forget something that has just happened. So in order to remember, she takes a notebook with her, called Ryouko's Memory Note. She writes what she sees and what she hears on the notebook, and the notebook became her memory.\\n\\nThough Ryouko is forgetful, she is also born with superb analyzing abilities. However, analyzing depends greatly on gathered information, in other words, memory. So she has to shuffle through her notebook whenever she needs to analyze, which is tough work.\\n\\nRyouko's notebook consists of n pages, numbered from 1 to n. To make life (and this problem) easier, we consider that to turn from page x to page y, |x - y| pages should be turned. During analyzing, Ryouko needs m pieces of information, the i-th piece of information is on page a_{i}. Information must be read from the notebook in order, so the total number of pages that Ryouko needs to turn is $\\\\sum_{i = 1}^{m - 1}|a_{i + 1} - a_{i}|$.\\n\\nRyouko wants to decrease the number of pages that need to be turned. In order to achieve this, she can merge two pages of her notebook. If Ryouko merges page x to page y, she would copy all the information on page x to y (1 ≤ x, y ≤ n), and consequently, all elements in sequence a that was x would become y. Note that x can be equal to y, in which case no changes take place.\\n\\nPlease tell Ryouko the minimum number of pages that she needs to turn. Note she can apply the described operation at most once before the reading. Note that the answer can exceed 32-bit integers.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains two integers n and m (1 ≤ n, m ≤ 10^5).\\n\\nThe next line contains m integers separated by spaces: a_1, a_2, ..., a_{m} (1 ≤ a_{i} ≤ n).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum number of pages Ryouko needs to turn.\\n\\n\\n-----Examples-----\\nInput\\n4 6\\n1 2 3 4 3 2\\n\\nOutput\\n3\\n\\nInput\\n10 5\\n9 4 3 8 8\\n\\nOutput\\n6\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, the optimal solution is to merge page 4 to 3, after merging sequence a becomes {1, 2, 3,...\",\"targets\":\"def median(a):\\n    if len(a) == 0:\\n        return 0\\n    if len(a) % 2 == 1:\\n        return a[len(a) \\/\\/ 2]\\n    else:\\n        return (a[len(a) \\/\\/ 2] + a[(len(a) \\/\\/ 2) - 1]) \\/\\/ 2\\n\\n\\ndef profit(a, old_val):\\n    a.sort()\\n    med = median(a)\\n    sum_old = 0\\n    sum_new = 0\\n    for i in a:\\n        sum_old += abs(i - old_val)\\n        sum_new += abs(i - med)\\n    return sum_old - sum_new\\n\\nn, m = [int(c) for c in input().split()]\\npages = [int(c) for c in input().split()]\\n\\ncount = {pages[0]: []}\\ncurrent_page_switches = 0\\n\\nfor i in range(1, len(pages)):\\n    cur_i = pages[i]\\n    prev_i = pages[i - 1]\\n    if not(cur_i in count):\\n        count[cur_i] = []\\n\\n    if cur_i != prev_i:\\n        count[cur_i].append(prev_i)\\n        count[prev_i].append(cur_i)\\n        current_page_switches += abs(cur_i - prev_i)\\n\\nmax_profit = 0\\n\\nfor i in count:\\n    if len(count[i]) > 0:\\n        tmp = profit(count[i], i)\\n        if tmp > max_profit:\\n            max_profit = tmp\\n\\n\\nprint(current_page_switches - max_profit)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nKarl likes Codeforces and subsequences. He wants to find a string of lowercase English letters that contains at least $k$ subsequences codeforces. Out of all possible strings, Karl wants to find a shortest one.\\n\\nFormally, a codeforces subsequence of a string $s$ is a subset of ten characters of $s$ that read codeforces from left to right. For example, codeforces contains codeforces a single time, while codeforcesisawesome contains codeforces four times: codeforcesisawesome, codeforcesisawesome, codeforcesisawesome, codeforcesisawesome.\\n\\nHelp Karl find any shortest string that contains at least $k$ codeforces subsequences.\\n\\n\\n-----Input-----\\n\\nThe only line contains a single integer $k$ ($1 \\\\leq k \\\\leq 10^{16})$.\\n\\n\\n-----Output-----\\n\\nPrint a shortest string of lowercase English letters that contains at least $k$ codeforces subsequences. If there are several such strings, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n1\\n\\nOutput\\ncodeforces\\n\\nInput\\n3\\n\\nOutput\\ncodeforcesss\",\"targets\":\"k = int(input())\\ncodeforces = \\\"codeforces\\\"\\nans = [1 for _ in range(len(codeforces))]\\ni = 0\\ntot = 1\\nwhile tot < k:\\n    tot \\/\\/= ans[i]\\n    ans[i] += 1\\n    tot *= ans[i]\\n    i += 1\\n    i %= len(codeforces)\\nfor i in range(len(codeforces)):\\n    print(codeforces[i] * ans[i], end = \\\"\\\")\\nprint()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1256\\/A:\\nYou have $a$ coins of value $n$ and $b$ coins of value $1$. You always pay in exact change, so you want to know if there exist such $x$ and $y$ that if you take $x$ ($0 \\\\le x \\\\le a$) coins of value $n$ and $y$ ($0 \\\\le y \\\\le b$) coins of value $1$, then the total value of taken coins will be $S$.\\n\\nYou have to answer $q$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $q$ ($1 \\\\le q \\\\le 10^4$) — the number of test cases. Then $q$ test cases follow.\\n\\nThe only line of the test case contains four integers $a$, $b$, $n$ and $S$ ($1 \\\\le a, b, n, S \\\\le 10^9$) — the number of coins of value $n$, the number of coins of value $1$, the value $n$ and the required total value.\\n\\n\\n-----Output-----\\n\\nFor the $i$-th test case print the answer on it — YES (without quotes) if there exist such $x$ and $y$ that if you take $x$ coins of value $n$ and $y$ coins of value $1$, then the total value of taken coins will be $S$, and NO otherwise.\\n\\nYou may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).\\n\\n\\n-----Example-----\\nInput\\n4\\n1 2 3 4\\n1 2 3 6\\n5 2 6 27\\n3 3 5 18\\n\\nOutput\\nYES\\nNO\\nNO\\nYES\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for _ in range(int(input())):\\n    a, b, n, s = map(int, input().split())\\n    s -= min(a, s \\/\\/ n) * n\\n    if b >= s:\\n        print(\\\"YES\\\")\\n    else:\\n        print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1430\\/E:\\nYou are given a string $s$. You have to reverse it — that is, the first letter should become equal to the last letter before the reversal, the second letter should become equal to the second-to-last letter before the reversal — and so on. For example, if your goal is to reverse the string \\\"abddea\\\", you should get the string \\\"aeddba\\\". To accomplish your goal, you can swap the neighboring elements of the string. \\n\\nYour task is to calculate the minimum number of swaps you have to perform to reverse the given string.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $n$ ($2 \\\\le n \\\\le 200\\\\,000$) — the length of $s$.\\n\\nThe second line contains $s$ — a string consisting of $n$ lowercase Latin letters.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the minimum number of swaps of neighboring elements you have to perform to reverse the string.\\n\\n\\n-----Examples-----\\nInput\\n5\\naaaza\\n\\nOutput\\n2\\n\\nInput\\n6\\ncbaabc\\n\\nOutput\\n0\\n\\nInput\\n9\\nicpcsguru\\n\\nOutput\\n30\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, you have to swap the third and the fourth elements, so the string becomes \\\"aazaa\\\". Then you have to swap the second and the third elements, so the string becomes \\\"azaaa\\\". So, it is possible to reverse the string in two swaps.\\n\\nSince the string in the second example is a palindrome, you don't have to do anything to reverse it.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N = int(input())\\nS = input()\\nT = S[::-1]\\n\\nfrom collections import defaultdict\\ndic = defaultdict(lambda: [])\\nfor i,t in enumerate(T):\\n    dic[t].append(i)\\nfor k in list(dic.keys()):\\n    dic[k].reverse()\\n\\narr = []\\nfor c in S:\\n    arr.append(dic[c].pop())\\n\\ndef inversion(inds):\\n    bit = [0] * (N+1)\\n    def bit_add(x,w):\\n        while x <= N:\\n            bit[x] += w\\n            x += (x & -x)\\n    def bit_sum(x):\\n        ret = 0\\n        while x > 0:\\n            ret += bit[x]\\n            x -= (x & -x)\\n        return ret\\n    inv = 0\\n    for ind in reversed(inds):\\n        inv += bit_sum(ind + 1)\\n        bit_add(ind + 1, 1)\\n    return inv\\n\\nprint(inversion(arr))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/835\\/B:\\nSome natural number was written on the board. Its sum of digits was not less than k. But you were distracted a bit, and someone changed this number to n, replacing some digits with others. It's known that the length of the number didn't change.\\n\\nYou have to find the minimum number of digits in which these two numbers can differ.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer k (1 ≤ k ≤ 10^9).\\n\\nThe second line contains integer n (1 ≤ n < 10^100000).\\n\\nThere are no leading zeros in n. It's guaranteed that this situation is possible.\\n\\n\\n-----Output-----\\n\\nPrint the minimum number of digits in which the initial number and n can differ.\\n\\n\\n-----Examples-----\\nInput\\n3\\n11\\n\\nOutput\\n1\\n\\nInput\\n3\\n99\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, the initial number could be 12.\\n\\nIn the second example the sum of the digits of n is not less than k. The initial number could be equal to n.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"k = int(input())\\nd = list(map(int, list(input())))\\nd.sort()\\nl = sum(d)\\ni = 0\\nwhile l < k:\\n    l += 9 - d[i]\\n    i += 1\\nprint(i)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1368\\/B:\\nKarl likes Codeforces and subsequences. He wants to find a string of lowercase English letters that contains at least $k$ subsequences codeforces. Out of all possible strings, Karl wants to find a shortest one.\\n\\nFormally, a codeforces subsequence of a string $s$ is a subset of ten characters of $s$ that read codeforces from left to right. For example, codeforces contains codeforces a single time, while codeforcesisawesome contains codeforces four times: codeforcesisawesome, codeforcesisawesome, codeforcesisawesome, codeforcesisawesome.\\n\\nHelp Karl find any shortest string that contains at least $k$ codeforces subsequences.\\n\\n\\n-----Input-----\\n\\nThe only line contains a single integer $k$ ($1 \\\\leq k \\\\leq 10^{16})$.\\n\\n\\n-----Output-----\\n\\nPrint a shortest string of lowercase English letters that contains at least $k$ codeforces subsequences. If there are several such strings, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n1\\n\\nOutput\\ncodeforces\\n\\nInput\\n3\\n\\nOutput\\ncodeforcesss\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"k = int(input())\\ncodeforces = \\\"codeforces\\\"\\nans = [1 for _ in range(len(codeforces))]\\ni = 0\\ntot = 1\\nwhile tot < k:\\n    tot \\/\\/= ans[i]\\n    ans[i] += 1\\n    tot *= ans[i]\\n    i += 1\\n    i %= len(codeforces)\\nfor i in range(len(codeforces)):\\n    print(codeforces[i] * ans[i], end = \\\"\\\")\\nprint()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/926\\/H:\\nArkady decided to buy roses for his girlfriend.\\n\\nA flower shop has white, orange and red roses, and the total amount of them is n. Arkady thinks that red roses are not good together with white roses, so he won't buy a bouquet containing both red and white roses. Also, Arkady won't buy a bouquet where all roses have the same color. \\n\\nArkady wants to buy exactly k roses. For each rose in the shop he knows its beauty and color: the beauty of the i-th rose is b_{i}, and its color is c_{i} ('W' for a white rose, 'O' for an orange rose and 'R' for a red rose). \\n\\nCompute the maximum possible total beauty of a bouquet of k roses satisfying the constraints above or determine that it is not possible to make such a bouquet.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and k (1 ≤ k ≤ n ≤ 200 000) — the number of roses in the show and the number of roses Arkady wants to buy.\\n\\nThe second line contains a sequence of integers b_1, b_2, ..., b_{n} (1 ≤ b_{i} ≤ 10 000), where b_{i} equals the beauty of the i-th rose.\\n\\nThe third line contains a string c of length n, consisting of uppercase English letters 'W', 'O' and 'R', where c_{i} denotes the color of the i-th rose: 'W' denotes white, 'O'  — orange, 'R' — red.\\n\\n\\n-----Output-----\\n\\nPrint the maximum possible total beauty of a bouquet of k roses that satisfies the constraints above. If it is not possible to make a single such bouquet, print -1.\\n\\n\\n-----Examples-----\\nInput\\n5 3\\n4 3 4 1 6\\nRROWW\\n\\nOutput\\n11\\n\\nInput\\n5 2\\n10 20 14 20 11\\nRRRRR\\n\\nOutput\\n-1\\n\\nInput\\n11 5\\n5 6 3 2 3 4 7 5 4 5 6\\nRWOORWORROW\\n\\nOutput\\n28\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Arkady wants to buy 3 roses. He can, for example, buy both red roses (their indices are 1 and 2, and their total beauty is 7) and the only orange rose (its index is 3, its beauty is 4). This way the total beauty of the bouquet is 11. \\n\\nIn the second example Arkady can not buy a bouquet because all roses have the same color.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, k = map(int, input().split())\\na = list(map(int, input().split()))\\ns = input()\\nif k == 1:\\n    print(-1)\\n    return\\nhave = [[] for i in range(3)]\\nfor i in range(n):\\n    if s[i] == 'R':\\n        have[0].append(a[i])\\n    elif s[i] == 'O':\\n        have[1].append(a[i])\\n    else:\\n        have[2].append(a[i])\\nfor i in range(3):\\n    have[i].sort(reverse=True)\\n\\n\\nans1 = 0\\np = 0\\nq = 0\\nwas = [0, 0]\\nfor i in range(k - 1):\\n    if p == len(have[0]) and q == len(have[1]):\\n        ans1 = -1\\n        break\\n    if p == len(have[0]):\\n        ans1 += have[1][q]\\n        q += 1\\n        was[1] = 1\\n    elif q == len(have[1]):\\n        ans1 += have[0][p]\\n        p += 1\\n        was[0] = 1\\n    elif(have[0][p] > have[1][q]):\\n        ans1 += have[0][p]\\n        p += 1\\n        was[0] = 1\\n    else:\\n        ans1 += have[1][q]\\n        q += 1\\n        was[1] = 1\\n\\nif ans1 != -1 and sum(was) == 2:\\n    if p == len(have[0]) and q == len(have[1]):\\n        ans = -1\\n    elif p == len(have[0]):\\n        ans1 += have[1][q]\\n    elif q == len(have[1]):\\n        ans1 += have[0][p]\\n    else:\\n        ans1 += max(have[0][p], have[1][q])\\nif ans1 != -1 and was[0] == 0:\\n    if p != len(have[0]):\\n        ans1 += have[0][p]\\n    else:\\n        ans1 = -1\\nif ans1 != -1 and was[1] == 0:\\n    if q != len(have[1]):\\n        ans1 += have[1][q]\\n    else:\\n        ans1 = -1\\n\\n\\nans2 = 0\\np = 0\\nq = 0\\nwas = [0, 0]\\nfor i in range(k - 1):\\n    if p == len(have[2]) and q == len(have[1]):\\n        ans2 = -1\\n        break\\n    if p == len(have[2]):\\n        ans2 += have[1][q]\\n        q += 1\\n        was[1] = 1\\n    elif q == len(have[1]):\\n        ans2 += have[2][p]\\n        p += 1\\n        was[0] = 1\\n    elif have[2][p] > have[1][q]:\\n        ans2 += have[2][p]\\n        p += 1\\n        was[0] = 1\\n    else:\\n        ans2 += have[1][q]\\n        q += 1\\n        was[1] = 1\\n\\nif ans2 != -1 and sum(was) == 2:\\n    if p == len(have[2]) and q == len(have[1]):\\n        ans = -1\\n    elif p == len(have[2]):\\n        ans2 += have[1][q]\\n    elif q == len(have[1]):\\n        ans2 += have[2][p]\\n    else:\\n        ans2 +=...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/583\\/B:\\nRobot Doc is located in the hall, with n computers stand in a line, numbered from left to right from 1 to n. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the i-th of them, the robot needs to collect at least a_{i} any pieces of information from the other computers. Doc can hack the computer only if he is right next to it.\\n\\nThe robot is assembled using modern technologies and can move along the line of computers in either of the two possible directions, but the change of direction requires a large amount of resources from Doc. Tell the minimum number of changes of direction, which the robot will have to make to collect all n parts of information if initially it is next to computer with number 1.\\n\\nIt is guaranteed that there exists at least one sequence of the robot's actions, which leads to the collection of all information. Initially Doc doesn't have any pieces of information.\\n\\n\\n-----Input-----\\n\\nThe first line contains number n (1 ≤ n ≤ 1000). The second line contains n non-negative integers a_1, a_2, ..., a_{n} (0 ≤ a_{i} < n), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information.\\n\\n\\n-----Output-----\\n\\nPrint a single number — the minimum number of changes in direction that the robot will have to make in order to collect all n parts of information.\\n\\n\\n-----Examples-----\\nInput\\n3\\n0 2 0\\n\\nOutput\\n1\\n\\nInput\\n5\\n4 2 3 0 1\\n\\nOutput\\n3\\n\\nInput\\n7\\n0 3 1 0 5 2 6\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece.\\n\\nIn the second sample to collect all the pieces of information in the optimal manner, Doc can go to the fourth computer and get the piece of information, then go to the fifth...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\nlst = [int(x) for x in input().split()]\\n\\npower = 0\\nanswer = 0\\nwhile power != len(lst):\\n\\tfor i in range(len(lst)):\\n\\t\\tif lst[i] <= power:\\n\\t\\t\\tpower += 1\\n\\t\\t\\tlst[i] = float('inf')\\n\\t\\n\\tif power == len(lst):\\n\\t\\tbreak\\n\\tanswer += 1\\n\\t\\n\\tfor i in range(len(lst)-1, -1, -1):\\n\\t\\tif lst[i] <= power:\\n\\t\\t\\tpower += 1\\n\\t\\t\\tlst[i] = float('inf')\\n\\t\\n\\tif power == len(lst):\\n\\t\\tbreak\\n\\tanswer += 1\\n\\nprint(answer)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThis kata is part one of precise fractions series (see pt. 2: http:\\/\\/www.codewars.com\\/kata\\/precise-fractions-pt-2-conversion).\\n\\nWhen dealing with fractional values, there's always a problem with the precision of arithmetical operations. So lets fix it!\\n\\nYour task is to implement class ```Fraction``` that takes care of simple fraction arithmetics. Requirements:\\n\\n* class must have two-parameter constructor `Fraction(numerator, denominator)`; passed values will be non-zero integers, and may be positive or negative.\\n* two conversion methods must be supported:\\n * `toDecimal()` returns decimal representation of fraction\\n * `toString()` returns string with fractional representation of stored value in format:\\n\\n    [ SIGN ] [ WHOLES ] [ NUMERATOR \\/ DENOMINATOR ]\\n   * **Note**: each part is returned only if it is available and non-zero, with the only possible space character going between WHOLES and fraction. Examples: '-1\\/2', '3', '-5 3\\/4'\\n    \\n* The fractional part must always be normalized (ie. the numerator and denominators must not have any common divisors).\\n* Four operations need to be implemented: `add`, `subtract`, `multiply` and `divide`. Each of them may take integers as well as another `Fraction` instance as an argument, and must return a new `Fraction` instance.\\n* Instances must be immutable, hence none of the operations may modify either of the objects it is called upon, nor the passed argument.\\n \\n #### Python Notes\\n* If one integer is passed into the initialiser, then the fraction should be assumed to represent an integer not a fraction.\\n* You must implement the standard operator overrides `__add__`, `__sub__`, `__mul__`, `__div__`, in each case you should support `other` being an `int` or another instance of `Fraction`.\\n* Implement `__str__` and `to_decimal` in place of `toString` and `toDecimal` as described above.\",\"targets\":\"from fractions import Fraction\\n\\ndef to_string(self):\\n    n, d = self.numerator, self.denominator\\n    s, w, n = \\\"-\\\" if n < 0 else \\\"\\\", *divmod(abs(n), d)\\n    r = \\\" \\\".join((str(w) if w else \\\"\\\", f\\\"{n}\\/{d}\\\" if n else \\\"\\\")).strip()\\n    return f\\\"{s}{r}\\\"\\n\\nFraction.__str__ = to_string\\nFraction.to_decimal = lambda self: float(self.numerator) \\/ self.denominator\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1179\\/B:\\nThis morning Tolik has understood that while he was sleeping he had invented an incredible problem which will be a perfect fit for Codeforces! But, as a \\\"Discuss tasks\\\" project hasn't been born yet (in English, well), he decides to test a problem and asks his uncle.\\n\\nAfter a long time thinking, Tolik's uncle hasn't any ideas on how to solve it. But, he doesn't want to tell Tolik about his inability to solve it, so he hasn't found anything better than asking you how to solve this task.\\n\\nIn this task you are given a cell field $n \\\\cdot m$, consisting of $n$ rows and $m$ columns, where point's coordinates $(x, y)$ mean it is situated in the $x$-th row and $y$-th column, considering numeration from one ($1 \\\\leq x \\\\leq n, 1 \\\\leq y \\\\leq m$). Initially, you stand in the cell $(1, 1)$. Every move you can jump from cell $(x, y)$, which you stand in, by any non-zero vector $(dx, dy)$, thus you will stand in the $(x+dx, y+dy)$ cell. Obviously, you can't leave the field, but also there is one more important condition — you're not allowed to use one vector twice. Your task is to visit each cell of the field exactly once (the initial cell is considered as already visited).\\n\\nTolik's uncle is a very respectful person. Help him to solve this task!\\n\\n\\n-----Input-----\\n\\nThe first and only line contains two positive integers $n, m$ ($1 \\\\leq n \\\\cdot m \\\\leq 10^{6}$) — the number of rows and columns of the field respectively.\\n\\n\\n-----Output-----\\n\\nPrint \\\"-1\\\" (without quotes) if it is impossible to visit every cell exactly once.\\n\\nElse print $n \\\\cdot m$ pairs of integers, $i$-th from them should contain two integers $x_i, y_i$ ($1 \\\\leq x_i \\\\leq n, 1 \\\\leq y_i \\\\leq m$) — cells of the field in order of visiting, so that all of them are distinct and vectors of jumps between them are distinct too.\\n\\nNotice that the first cell should have $(1, 1)$ coordinates, according to the statement.\\n\\n\\n-----Examples-----\\nInput\\n2 3\\n\\nOutput\\n1 1\\n1 3\\n1 2\\n2 2\\n2 3\\n2 1\\nInput\\n1 1\\n\\nOutput\\n1 1\\n\\n\\n\\n-----Note-----\\n\\nThe vectors from the first example in the order of...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\nn,m=list(map(int,input().split()))\\nANS=[]\\n\\nfor i in range(1,n\\/\\/2+1):\\n    for j in range(1,m+1):\\n        sys.stdout.write(\\\"\\\".join((str(i),\\\" \\\",str(j),\\\"\\\\n\\\")))\\n        sys.stdout.write(\\\"\\\".join((str(n-i+1),\\\" \\\",str(m-j+1),\\\"\\\\n\\\")))\\n\\n\\n\\nif n%2==1:\\n    for j in range(1,m\\/\\/2+1):\\n        sys.stdout.write(\\\"\\\".join((str(n\\/\\/2+1),\\\" \\\",str(j),\\\"\\\\n\\\")))\\n        sys.stdout.write(\\\"\\\".join((str(n\\/\\/2+1),\\\" \\\",str(m-j+1),\\\"\\\\n\\\")))\\n\\n    if m%2==1:\\n        sys.stdout.write(\\\"\\\".join((str(n\\/\\/2+1),\\\" \\\",str(m\\/\\/2+1),\\\"\\\\n\\\")))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere is a sequence of length N: A_1, A_2, ..., A_N. Initially, this sequence is a permutation of 1, 2, ..., N.\\nOn this sequence, Snuke can perform the following operation:\\n - Choose K consecutive elements in the sequence. Then, replace the value of each chosen element with the minimum value among the chosen elements.\\nSnuke would like to make all the elements in this sequence equal by repeating the operation above some number of times.\\nFind the minimum number of operations required.\\nIt can be proved that, Under the constraints of this problem, this objective is always achievable.\\n\\n-----Constraints-----\\n - 2 \\\\leq K \\\\leq N \\\\leq 100000\\n - A_1, A_2, ..., A_N is a permutation of 1, 2, ..., N.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN K\\nA_1 A_2 ... A_N\\n\\n-----Output-----\\nPrint the minimum number of operations required.\\n\\n-----Sample Input-----\\n4 3\\n2 3 1 4\\n\\n-----Sample Output-----\\n2\\n\\nOne optimal strategy is as follows:\\n - In the first operation, choose the first, second and third elements. The sequence A becomes 1, 1, 1, 4.\\n - In the second operation, choose the second, third and fourth elements. The sequence A becomes 1, 1, 1, 1.\",\"targets\":\"#!\\/usr\\/bin\\/env python\\n# -*- coding: utf-8 -*-\\n#\\n# FileName: \\tC\\n# CreatedDate:  2020-10-03 20:30:05 +0900\\n# LastModified: 2020-10-24 19:05:05 +0900\\n#\\n\\n\\nimport os\\nimport sys\\nimport numpy as np\\n# import pandas as pd\\n\\n\\ndef main():\\n    N, K = list(map(int, input().split()))\\n    A = np.array(list(map(int, input().split())))\\n    cnt = 0\\n    i = 0\\n    while i != N-1:\\n        if i == 0:\\n            A[i: i+K] = np.min(A[i: i+K])\\n            cnt += 1\\n            i = i+K-1\\n\\n        elif i+K < N:\\n            A[i: i+K] = A[i]\\n            cnt += 1\\n            i = i+K-1\\n\\n        else:\\n            A[i: -1] = A[i]\\n            cnt += 1\\n            break\\n#        print(A)\\n\\n    print(cnt)\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/320\\/A:\\nA magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.\\n\\nYou're given a number. Determine if it is a magic number or not.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains an integer n, (1 ≤ n ≤ 10^9). This number doesn't contain leading zeros.\\n\\n\\n-----Output-----\\n\\nPrint \\\"YES\\\" if n is a magic number or print \\\"NO\\\" if it's not.\\n\\n\\n-----Examples-----\\nInput\\n114114\\n\\nOutput\\nYES\\n\\nInput\\n1111\\n\\nOutput\\nYES\\n\\nInput\\n441231\\n\\nOutput\\nNO\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"s = input().rstrip()\\ngood  = '14'\\nfor j in s:\\n    if j not in good:\\n        print('NO')\\n        return\\ncur = ''\\nfor  i in range(len(s)):\\n    if s[i]=='1':\\n        cur='1'\\n    else:\\n        cur+='4'\\n        if cur=='14' and i!=len(s)-1 and s[i+1]=='4':\\n            continue\\n        if cur!='14' and cur !='144':\\n            print('NO')\\n            return\\n        else:\\n            cur=''\\nprint('YES')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/all-oone-data-structure\\/:\\nImplement a data structure supporting the following operations:\\n\\n\\n\\nInc(Key) - Inserts a new key  with value 1. Or increments an existing key by 1. Key is guaranteed to be a non-empty string.\\nDec(Key) - If Key's value is 1, remove it from the data structure. Otherwise decrements an existing key by 1. If the key does not exist, this function does nothing. Key is guaranteed to be a non-empty string.\\nGetMaxKey() - Returns one of the keys with maximal value. If no element exists, return an empty string \\\"\\\".\\nGetMinKey() - Returns one of the keys with minimal value. If no element exists, return an empty string \\\"\\\".\\n\\n\\n\\n\\nChallenge: Perform all these in O(1) time complexity.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Node:\\n     def __init__(self, cnt):\\n         self.count = cnt\\n         self.prev = None\\n         self.next = None\\n \\n \\n class AllOne(object):\\n \\n     def __init__(self):\\n         \\\"\\\"\\\"\\n         Initialize your data structure here.\\n         \\\"\\\"\\\"\\n         self.count_key_map={}\\n         self.key_count_map={}\\n         self.count_node_map={}\\n         \\n         self.head=Node(0)\\n         self.tail=Node(float('inf'))\\n         \\n         self.head.next=self.tail\\n         self.tail.prev=self.head\\n         \\n         self.count_node_map[0]=self.head\\n         self.count_node_map[float('inf')]=self.tail\\n \\n     def inc(self, key):\\n         \\\"\\\"\\\"\\n         Inserts a new key <Key> with value 1. Or increments an existing key by 1.\\n         :type key: str\\n         :rtype: void\\n         \\\"\\\"\\\"\\n         if key not in self.key_count_map:\\n             self.key_count_map[key]=0\\n         \\n         \\n         prev_count=self.key_count_map[key]\\n         prev_node=self.count_node_map[prev_count]\\n         \\n         self.key_count_map[key]+=1\\n         \\n         if prev_node.next.count!=self.key_count_map[key]:\\n             new_node=Node(self.key_count_map[key])\\n             self.insert(prev_node,new_node)\\n             self.count_key_map[self.key_count_map[key]]=set()\\n             self.count_node_map[self.key_count_map[key]]=new_node\\n         \\n         self.count_key_map[self.key_count_map[key]].add(key)\\n         \\n         if prev_count!=0:\\n            \\n            self.count_key_map[prev_count].remove(key)\\n            if len(self.count_key_map[prev_count])==0:\\n                self.count_node_map.pop(prev_count)\\n                self.count_key_map.pop(prev_count)\\n                self.delete(prev_node)\\n                \\n     \\n         \\n \\n     def dec(self, key):\\n         \\\"\\\"\\\"\\n         Decrements an existing key by 1. If Key's value is 1, remove it from the data structure.\\n         :type key: str\\n         :rtype: void\\n         \\\"\\\"\\\"\\n         if key not in self.key_count_map:\\n             return \\n         prev_count=self.key_count_map[key]\\n        ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc142\\/tasks\\/abc142_d:\\nGiven are positive integers A and B.\\nLet us choose some number of positive common divisors of A and B.\\nHere, any two of the chosen divisors must be coprime.\\nAt most, how many divisors can we choose?Definition of common divisor\\nAn integer d is said to be a common divisor of integers x and y when d divides both x and y.Definition of being coprime\\nIntegers x and y are said to be coprime when x and y have no positive common divisors other than 1.Definition of dividing\\nAn integer x is said to divide another integer y when there exists an integer \\\\alpha such that y = \\\\alpha x.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq A, B \\\\leq 10^{12}\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B\\n\\n-----Output-----\\nPrint the maximum number of divisors that can be chosen to satisfy the condition.\\n\\n-----Sample Input-----\\n12 18\\n\\n-----Sample Output-----\\n3\\n\\n12 and 18 have the following positive common divisors: 1, 2, 3, and 6.\\n1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a,b=map(int,input().split())\\ndef gcd(a,b):\\n  if b==0:\\n    return a\\n  else:\\n    return gcd(b,a%b)\\ndef factorize(x):\\n  i=2\\n  res=[]\\n  while i*i<=x:\\n    while x%i==0:\\n      x\\/\\/=i\\n      res.append(i)\\n    i+=1\\n  if x>1:\\n    res.append(x)\\n  return res\\ng=gcd(a,b)\\nf=factorize(g)\\nprint(len(set(f))+1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc171\\/tasks\\/abc171_b:\\nA shop sells N kinds of fruits, Fruit 1, \\\\ldots, N, at prices of p_1, \\\\ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)\\nHere, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.\\n\\n-----Constraints-----\\n - 1 \\\\leq K \\\\leq N \\\\leq 1000\\n - 1 \\\\leq p_i \\\\leq 1000\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN K\\np_1 p_2 \\\\ldots p_N\\n\\n-----Output-----\\nPrint an integer representing the minimum possible total price of fruits.\\n\\n-----Sample Input-----\\n5 3\\n50 100 80 120 80\\n\\n-----Sample Output-----\\n210\\n\\nThis shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.\\nThe minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N,K = list(map(int,input().split()))\\nP = sorted((list(map(int,input().split()))))\\nprint((sum(P[:K])))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPashmak decided to give Parmida a pair of flowers from the garden. There are n flowers in the garden and the i-th of them has a beauty number b_{i}. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty difference is maximal possible!\\n\\nYour task is to write a program which calculates two things:  The maximum beauty difference of flowers that Pashmak can give to Parmida.  The number of ways that Pashmak can pick the flowers. Two ways are considered different if and only if there is at least one flower that is chosen in the first way and not chosen in the second way. \\n\\n\\n-----Input-----\\n\\nThe first line of the input contains n (2 ≤ n ≤ 2·10^5). In the next line there are n space-separated integers b_1, b_2, ..., b_{n} (1 ≤ b_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nThe only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively.\\n\\n\\n-----Examples-----\\nInput\\n2\\n1 2\\n\\nOutput\\n1 1\\nInput\\n3\\n1 4 5\\n\\nOutput\\n4 1\\nInput\\n5\\n3 1 2 3 1\\n\\nOutput\\n2 4\\n\\n\\n-----Note-----\\n\\nIn the third sample the maximum beauty difference is 2 and there are 4 ways to do this:  choosing the first and the second flowers;  choosing the first and the fifth flowers;  choosing the fourth and the second flowers;  choosing the fourth and the fifth flowers.\",\"targets\":\"import fileinput\\nimport math\\n\\nfor line in fileinput.input():   \\n    inp = [ int(i) for i in line.split()]\\n\\nN = len(inp)\\n\\n\\n#case 1, all inputs are the same\\n\\nif len(set(inp)) == 1:\\n    print(0,(N*(N-1))\\/\\/2)\\nelse:\\n    minN = inp[0]\\n    maxN = inp[0]\\n    for i in inp:\\n        if i < minN:\\n            minN = i\\n        if i > maxN:\\n            maxN = i\\n    nMin=0\\n    nMax=0\\n    for i in inp:\\n        if i == minN:\\n            nMin = nMin + 1\\n        if i == maxN:\\n            nMax = nMax + 1\\n\\n    print(maxN-minN, nMin*nMax)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5b358a1e228d316283001892:\\nYou receive the name of a city as a string, and you need to return a string that shows how many times each letter shows up in the string by using an asterisk (`*`).\\n\\nFor example:\\n\\n```\\n\\\"Chicago\\\"  -->  \\\"c:**,h:*,i:*,a:*,g:*,o:*\\\"\\n```\\n\\nAs you can see, the letter `c` is shown only once, but with 2 asterisks.\\n\\nThe return string should include **only the letters** (not the dashes, spaces, apostrophes, etc). There should be no spaces in the output, and the different letters are separated by a comma (`,`) as seen in the example above.\\n\\nNote that the return string must list the letters in order of their first appearence in the original string.\\n\\nMore examples:\\n```\\n\\\"Bangkok\\\"    -->  \\\"b:*,a:*,n:*,g:*,k:**,o:*\\\"\\n\\\"Las Vegas\\\"  -->  \\\"l:*,a:**,s:**,v:*,e:*,g:*\\\"\\n```\\n\\nHave fun! ;)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def get_strings(city):\\n    \\n    # convert to lower case alphabet\\n    city_alpha = \\\"\\\".join(x.lower() for x in city if x.isalpha())\\n    \\n    # order of appearance and count\\n    seen_cnt, order = {}, \\\"\\\"\\n    for x in city_alpha :\\n        if x not in seen_cnt :\\n            seen_cnt[x]=1 \\n            order += x\\n        else :\\n            seen_cnt[x] += 1\\n    \\n    # generate output\\n    output = \\\"\\\"\\n    for x in order :\\n        output += \\\",\\\"+x+\\\":\\\"+\\\"*\\\"*seen_cnt[x]\\n        \\n    return output[1:]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe often have to copy large volumes of information. Such operation can take up many computer resources. Therefore, in this problem you are advised to come up with a way to copy some part of a number array into another one, quickly.\\n\\nMore formally, you've got two arrays of integers a_1, a_2, ..., a_{n} and b_1, b_2, ..., b_{n} of length n. Also, you've got m queries of two types:  Copy the subsegment of array a of length k, starting from position x, into array b, starting from position y, that is, execute b_{y} + q = a_{x} + q for all integer q (0 ≤ q < k). The given operation is correct — both subsegments do not touch unexistent elements.  Determine the value in position x of array b, that is, find value b_{x}. \\n\\nFor each query of the second type print the result — the value of the corresponding element of array b.\\n\\n\\n-----Input-----\\n\\nThe first line contains two space-separated integers n and m (1 ≤ n, m ≤ 10^5) — the number of elements in the arrays and the number of queries, correspondingly. The second line contains an array of integers a_1, a_2, ..., a_{n} (|a_{i}| ≤ 10^9). The third line contains an array of integers b_1, b_2, ..., b_{n} (|b_{i}| ≤ 10^9).\\n\\nNext m lines contain the descriptions of the queries. The i-th line first contains integer t_{i} — the type of the i-th query (1 ≤ t_{i} ≤ 2). If t_{i} = 1, then the i-th query means the copying operation. If t_{i} = 2, then the i-th query means taking the value in array b. If t_{i} = 1, then the query type is followed by three integers x_{i}, y_{i}, k_{i} (1 ≤ x_{i}, y_{i}, k_{i} ≤ n) — the parameters of the copying query. If t_{i} = 2, then the query type is followed by integer x_{i} (1 ≤ x_{i} ≤ n) — the position in array b.\\n\\nAll numbers in the lines are separated with single spaces. It is guaranteed that all the queries are correct, that is, the copying borders fit into the borders of arrays a and b.\\n\\n\\n-----Output-----\\n\\nFor each second type query print the result on a single line.\\n\\n\\n-----Examples-----\\nInput\\n5 10\\n1 2 0 -1 3\\n3 1 5 -2 0\\n2 5\\n1 3 3 3\\n2...\",\"targets\":\"import sys\\n'''\\nSEGMENT TREE\\nAssign\\n'''\\nclass SegmTree():\\n    '''\\n    - modify elements on interval\\n    - get single element\\n    '''\\n    def __init__(self, size):\\n        N = 1\\n        while N < size:\\n            N <<= 1\\n        self.N = N\\n        self.tree = [0] * (2*N)\\n\\n    def modify_range(self, l, r, value):\\n        l += self.N\\n        r += self.N\\n        while l < r:\\n            if l & 1:\\n                self.tree[l] = value\\n                l += 1\\n            if r & 1:\\n                r -= 1\\n                self.tree[r] = value\\n            l >>= 1\\n            r >>= 1\\n    \\n    def query(self, i):\\n        i += self.N\\n        latest_change = self.tree[i]\\n        p = i\\n        while p > 1:\\n            p >>= 1\\n            latest_change = max(latest_change, self.tree[p])\\n        return latest_change\\n\\n# inf = open('input.txt', 'r')\\n# reader = (map(int, line.split()) for line in inf)\\nreader = (list(map(int, line.split())) for line in sys.stdin)\\ninput = reader.__next__\\n\\nn, m = input()\\na = list(input())\\nb = list(input())\\nst = SegmTree(n)\\nrequest = [None] * (m + 1)\\nfor i in range(1, m+1):\\n    t, *arg = input()\\n    if t == 1:\\n        x, y, k = request[i] = arg\\n        st.modify_range(y-1, y-1+k, i)\\n    else:\\n        pos = arg[0] - 1\\n        req_id = st.query(pos)\\n        if req_id > 0:\\n            x, y, k = request[req_id]\\n            ans = a[x+(pos-y)]\\n        else:\\n            ans = b[pos]\\n        sys.stdout.write(f'{ans}\\\\n')\\n\\n# inf.close()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOne of the first algorithm used for approximating the integer square root of a positive integer `n` is known as \\\"Hero's method\\\", \\nnamed after the first-century Greek mathematician Hero of Alexandria who gave the first description\\nof the method. Hero's method can be obtained from Newton's method which came 16 centuries after. \\n\\nWe approximate the square root of a number `n` by taking an initial guess `x`, an error `e` and repeatedly calculating a new approximate *integer* value `x` using: `(x + n \\/ x) \\/ 2`; we are finished when the previous `x` and the `new x` have an absolute difference less than `e`.\\n\\nWe supply to a function (int_rac) a number `n` (positive integer) and a parameter `guess` (positive integer) which will be our initial `x`. For this kata the parameter 'e' is set to `1`.\\n\\nHero's algorithm is not always going to come to an exactly correct result! For instance: if n = 25 we get 5 but for n = 26 we also get 5. Nevertheless `5` is the *integer* square root of `26`.\\n\\nThe kata is to return the count of the progression of integer approximations that the algorithm makes.\\n\\nReference:\\n\\n\\n\\nSome examples:\\n```\\nint_rac(25,1): follows a progression of [1,13,7,5] so our function should return 4.\\n\\nint_rac(125348,300): has a progression of [300,358,354] so our function should return 3.\\n\\nint_rac(125348981764,356243): has a progression of [356243,354053,354046] so our function should return 3.\\n```\\n\\n#\\n\\nYou can use Math.floor (or similar) for each integer approximation.\\n \\n#\\n\\nNote for JavaScript, Coffescript, Typescript:\\n\\nDon't use the double bitwise NOT ~~ at each iteration if you want to have the same results as in the tests and the other languages.\",\"targets\":\"int_rac=lambda n, x, c=1: int_rac(n, (x+n\\/x)\\/2 ,c+1) if abs(int(n**0.5)-x)>=1 else c\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPatrick likes to play baseball, but sometimes he will spend so many hours hitting home runs that his mind starts to get foggy! Patrick is sure that his scores across $n$ sessions follow the identity permutation (ie. in the first game he scores $1$ point, in the second game he scores $2$ points and so on). However, when he checks back to his record, he sees that all the numbers are mixed up! \\n\\nDefine a special exchange as the following: choose any subarray of the scores and permute elements such that no element of subarray gets to the same position as it was before the exchange. For example, performing a special exchange on $[1,2,3]$ can yield $[3,1,2]$ but it cannot yield $[3,2,1]$ since the $2$ is in the same position. \\n\\nGiven a permutation of $n$ integers, please help Patrick find the minimum number of special exchanges needed to make the permutation sorted! It can be proved that under given constraints this number doesn't exceed $10^{18}$.\\n\\nAn array $a$ is a subarray of an array $b$ if $a$ can be obtained from $b$ by deletion of several (possibly, zero or all) elements from the beginning and several (possibly, zero or all) elements from the end.\\n\\n\\n-----Input-----\\n\\nEach test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \\\\le t \\\\le 100$). Description of the test cases follows.\\n\\nThe first line of each test case contains integer $n$ ($1 \\\\leq n \\\\leq 2 \\\\cdot 10^5$)  — the length of the given permutation.\\n\\nThe second line of each test case contains $n$ integers $a_{1},a_{2},...,a_{n}$ ($1 \\\\leq a_{i} \\\\leq n$)  — the initial permutation.\\n\\nIt is guaranteed that the sum of $n$ over all test cases does not exceed $2 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, output one integer: the minimum number of special exchanges needed to sort the permutation.\\n\\n\\n-----Example-----\\nInput\\n2\\n5\\n1 2 3 4 5\\n7\\n3 2 4 5 1 6 7\\n\\nOutput\\n0\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first permutation, it is already sorted so no exchanges are needed.\\n\\nIt can be shown that you need at least $2$ exchanges to sort...\",\"targets\":\"from collections import defaultdict as dd\\nfrom collections import deque\\nimport bisect\\nimport heapq\\n\\ndef ri():\\n    return int(input())\\n\\ndef rl():\\n    return list(map(int, input().split()))\\n\\n\\ndef solve():\\n    n = ri()\\n    A = rl()\\n\\n    first_wrong = -1\\n    first_break = -1\\n    skip = False\\n\\n    for i, a in enumerate(A):\\n        if i + 1 == a:\\n            if first_wrong != -1 and first_break == -1:\\n                first_break = i\\n        else:\\n            if first_wrong == -1:\\n                first_wrong = i\\n            elif first_break != -1:\\n                skip = True\\n\\n    if first_wrong == -1:\\n        print(0)\\n    elif not skip:\\n        print(1)\\n    else:\\n        print(2)\\n\\n\\n\\n\\n\\n\\nmode = 'T'\\n\\nif mode == 'T':\\n    t = ri()\\n    for i in range(t):\\n        solve()\\nelse:\\n    solve()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAlyona decided to go on a diet and went to the forest to get some apples. There she unexpectedly found a magic rooted tree with root in the vertex 1, every vertex and every edge of which has a number written on.\\n\\nThe girl noticed that some of the tree's vertices are sad, so she decided to play with them. Let's call vertex v sad if there is a vertex u in subtree of vertex v such that dist(v, u) > a_{u}, where a_{u} is the number written on vertex u, dist(v, u) is the sum of the numbers written on the edges on the path from v to u.\\n\\nLeaves of a tree are vertices connected to a single vertex by a single edge, but the root of a tree is a leaf if and only if the tree consists of a single vertex — root.\\n\\nThus Alyona decided to remove some of tree leaves until there will be no any sad vertex left in the tree. What is the minimum number of leaves Alyona needs to remove?\\n\\n\\n-----Input-----\\n\\nIn the first line of the input integer n (1 ≤ n ≤ 10^5) is given — the number of vertices in the tree.\\n\\nIn the second line the sequence of n integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9) is given, where a_{i} is the number written on vertex i.\\n\\nThe next n - 1 lines describe tree edges: i^{th} of them consists of two integers p_{i} and c_{i} (1 ≤ p_{i} ≤ n,  - 10^9 ≤ c_{i} ≤ 10^9), meaning that there is an edge connecting vertices i + 1 and p_{i} with number c_{i} written on it.\\n\\n\\n-----Output-----\\n\\nPrint the only integer — the minimum number of leaves Alyona needs to remove such that there will be no any sad vertex left in the tree.\\n\\n\\n-----Example-----\\nInput\\n9\\n88 22 83 14 95 91 98 53 11\\n3 24\\n7 -8\\n1 67\\n1 64\\n9 65\\n5 12\\n6 -80\\n3 8\\n\\nOutput\\n5\\n\\n\\n\\n-----Note-----\\n\\nThe following image represents possible process of removing leaves from the tree:  [Image]\",\"targets\":\"def subtree_count():\\n    stack = [0]\\n    while len(stack):\\n        v = stack[-1]\\n\\n        size = 1\\n        for u, _ in edge[v]:\\n            if u in subtree:\\n                size += subtree[u]\\n            else:\\n                stack.append(u)\\n\\n        if stack[-1] is v:\\n            stack.pop()\\n            subtree[v] = size\\n\\n\\ndef remove_bfs():\\n    queue = [(0, 0)]\\n    removed = 0\\n\\n    while len(queue):\\n        v, s = queue.pop()\\n\\n        if s > vertex[v]:\\n            removed += subtree[v]\\n        else:\\n            for u, c in edge[v]:\\n                queue.append((u, max(s + c, 0)))\\n\\n    return removed\\n\\nn = int(input())\\n\\nvertex = list(map(int, input().split()))\\nedge = {}\\nsubtree = {}\\n\\nfor i in range(n):\\n    edge[i] = []\\n\\nfor i in range(n - 1):\\n    p, c = list(map(int, input().split()))\\n    edge[p - 1].append((i + 1, c))\\n\\nsubtree_count()\\nprint(remove_bfs())\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/825\\/A:\\nPolycarp has just invented a new binary protocol for data transmission. He is encoding positive integer decimal number to binary string using following algorithm:\\n\\n  Each digit is represented with number of '1' characters equal to the value of that digit (for 0 it is zero ones).  Digits are written one by one in order corresponding to number and separated by single '0' character. \\n\\nThough Polycarp learnt how to encode the numbers, he has no idea how to decode them back. Help him calculate the decoded number.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer number n (1 ≤ n ≤ 89) — length of the string s.\\n\\nThe second line contains string s — sequence of '0' and '1' characters, number in its encoded format. It is guaranteed that the number corresponding to the string is positive and doesn't exceed 10^9. The string always starts with '1'.\\n\\n\\n-----Output-----\\n\\nPrint the decoded number.\\n\\n\\n-----Examples-----\\nInput\\n3\\n111\\n\\nOutput\\n3\\n\\nInput\\n9\\n110011101\\n\\nOutput\\n2031\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n=int(input())\\na=input().split('0')\\nans=0\\nfor i in a:\\n\\tans=ans*10+len(i)\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/380\\/C:\\nSereja has a bracket sequence s_1, s_2, ..., s_{n}, or, in other words, a string s of length n, consisting of characters \\\"(\\\" and \\\")\\\".\\n\\nSereja needs to answer m queries, each of them is described by two integers l_{i}, r_{i} (1 ≤ l_{i} ≤ r_{i} ≤ n). The answer to the i-th query is the length of the maximum correct bracket subsequence of sequence s_{l}_{i}, s_{l}_{i} + 1, ..., s_{r}_{i}. Help Sereja answer all queries.\\n\\nYou can find the definitions for a subsequence and a correct bracket sequence in the notes.\\n\\n\\n-----Input-----\\n\\nThe first line contains a sequence of characters s_1, s_2, ..., s_{n} (1 ≤ n ≤ 10^6) without any spaces. Each character is either a \\\"(\\\" or a \\\")\\\". The second line contains integer m (1 ≤ m ≤ 10^5) — the number of queries. Each of the next m lines contains a pair of integers. The i-th line contains integers l_{i}, r_{i} (1 ≤ l_{i} ≤ r_{i} ≤ n) — the description of the i-th query.\\n\\n\\n-----Output-----\\n\\nPrint the answer to each question on a single line. Print the answers in the order they go in the input.\\n\\n\\n-----Examples-----\\nInput\\n())(())(())(\\n7\\n1 1\\n2 3\\n1 2\\n1 12\\n8 12\\n5 11\\n2 10\\n\\nOutput\\n0\\n0\\n2\\n10\\n4\\n6\\n6\\n\\n\\n\\n-----Note-----\\n\\nA subsequence of length |x| of string s = s_1s_2... s_{|}s| (where |s| is the length of string s) is string x = s_{k}_1s_{k}_2... s_{k}_{|}x| (1 ≤ k_1 < k_2 < ... < k_{|}x| ≤ |s|).\\n\\nA correct bracket sequence is a bracket sequence that can be transformed into a correct aryphmetic expression by inserting characters \\\"1\\\" and \\\"+\\\" between the characters of the string. For example, bracket sequences \\\"()()\\\", \\\"(())\\\" are correct (the resulting expressions \\\"(1)+(1)\\\", \\\"((1+1)+1)\\\"), and \\\")(\\\" and \\\"(\\\" are not.\\n\\nFor the third query required sequence will be «()».\\n\\nFor the fourth query required sequence will be «()(())(())».\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\ns = input()\\n\\nM = int(input())\\n\\n\\ndef next_pow_2(n):\\n    p = 1\\n    while p < n:\\n        p <<= 1\\n    return p\\n\\n\\ndef represented_range(node, size):\\n    l = node\\n    r = node\\n    while l < size:\\n        l = 2*l\\n        r = 2*r + 1\\n    return l-size, r-size\\n\\n\\nclass SegTree:\\n    def __init__(self, size):\\n        self.size = next_pow_2(size)\\n        self.answer = [0] * (2*self.size)\\n        self.opened = [0] * (2*self.size)\\n        self.closed = [0] * (2*self.size)\\n\\n    # O(size * (O(func) + O(init))\\n    def build(self, s):\\n        for i in range(self.size):\\n            self.answer[self.size + i] = 0\\n            self.opened[self.size + i] = 1 if i < len(s) and s[i] == '(' else 0\\n            self.closed[self.size + i] = 1 if i < len(s) and s[i] == ')' else 0\\n\\n        for i in range(self.size - 1, 0, -1):\\n            matched = min(self.opened[2*i], self.closed[2*i+1])\\n            self.answer[i] = self.answer[2*i] + self.answer[2*i+1] + matched\\n            self.opened[i] = self.opened[2*i] + self.opened[2*i+1] - matched\\n            self.closed[i] = self.closed[2*i] + self.closed[2*i+1] - matched\\n\\n    # O(log(size)), [l,r]\\n    def query(self, l, r):\\n        l += self.size\\n        r += self.size\\n\\n        eventsR = []\\n        answer = 0\\n        opened = 0\\n        while l <= r:\\n            if l & 1:\\n                matched = min(self.closed[l], opened)\\n                answer += self.answer[l] + matched\\n                opened += self.opened[l] - matched\\n                l += 1\\n            if not (r & 1):\\n                eventsR.append((self.answer[r], self.opened[r], self.closed[r]))\\n                r -= 1\\n            l >>= 1\\n            r >>= 1\\n\\n        for i in range(len(eventsR)-1, -1, -1):\\n            a, o, c = eventsR[i]\\n            matched = min(c, opened)\\n            answer += a + matched\\n            opened += o - matched\\n\\n        return answer\\n\\n\\nseg = SegTree(len(s))\\nseg.build(s)\\n\\nfor i in range(M):\\n    l, r = [int(_) for _ in input().split()]\\n    print(2*seg.query(l-1, r-1))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGottfried learned about binary number representation. He then came up with this task and presented it to you.\\n\\nYou are given a collection of $n$ non-negative integers $a_1, \\\\ldots, a_n$. You are allowed to perform the following operation: choose two distinct indices $1 \\\\leq i, j \\\\leq n$. If before the operation $a_i = x$, $a_j = y$, then after the operation $a_i = x~\\\\mathsf{AND}~y$, $a_j = x~\\\\mathsf{OR}~y$, where $\\\\mathsf{AND}$ and $\\\\mathsf{OR}$ are bitwise AND and OR respectively (refer to the Notes section for formal description). The operation may be performed any number of times (possibly zero).\\n\\nAfter all operations are done, compute $\\\\sum_{i=1}^n a_i^2$ — the sum of squares of all $a_i$. What is the largest sum of squares you can achieve?\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\leq n \\\\leq 2 \\\\cdot 10^5$).\\n\\nThe second line contains $n$ integers $a_1, \\\\ldots, a_n$ ($0 \\\\leq a_i < 2^{20}$).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the largest possible sum of squares that can be achieved after several (possibly zero) operations.\\n\\n\\n-----Examples-----\\nInput\\n1\\n123\\n\\nOutput\\n15129\\n\\nInput\\n3\\n1 3 5\\n\\nOutput\\n51\\n\\nInput\\n2\\n349525 699050\\n\\nOutput\\n1099509530625\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample no operation can be made, thus the answer is $123^2$.\\n\\nIn the second sample we can obtain the collection $1, 1, 7$, and $1^2 + 1^2 + 7^2 = 51$.\\n\\nIf $x$ and $y$ are represented in binary with equal number of bits (possibly with leading zeros), then each bit of $x~\\\\mathsf{AND}~y$ is set to $1$ if and only if both corresponding bits of $x$ and $y$ are set to $1$. Similarly, each bit of $x~\\\\mathsf{OR}~y$ is set to $1$ if and only if at least one of the corresponding bits of $x$ and $y$ are set to $1$. For example, $x = 3$ and $y = 5$ are represented as $011_2$ and $101_2$ (highest bit first). Then, $x~\\\\mathsf{AND}~y = 001_2 = 1$, and $x~\\\\mathsf{OR}~y = 111_2 = 7$.\",\"targets\":\"n=int(input())\\na=list(map(int,input().split()))\\nx=[0]*20\\nfor i in range(n):\\n  s=\\\"{0:b}\\\".format(a[i])\\n  b=[]\\n  for j in range(len(s)):\\n    b.append(s[j])\\n  b.reverse()\\n  for j in range(20-len(s)):\\n    b.append('0')\\n  b.reverse()\\n  for j in range(20):\\n    if b[j]=='1':\\n      x[j]+=1\\nans=0\\nfor i in range(n):\\n  s=[]\\n  for j in range(20):\\n    if x[j]>0:\\n      s.append('1')\\n      x[j]-=1\\n    else:\\n      s.append('0')\\n  ans+=int(''.join(s), 2)**2\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a huge decimal number consisting of $n$ digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.\\n\\nYou may perform several (possibly zero) operations with this number. During each operation you are allowed to change any digit of your number; you may change 0 to 1 or 1 to 0. It is possible that after some operation you can obtain a number with leading zeroes, but it does not matter for this problem.\\n\\nYou are also given two integers $0 \\\\le y < x < n$. Your task is to calculate the minimum number of operations you should perform to obtain the number that has remainder $10^y$ modulo $10^x$. In other words, the obtained number should have remainder $10^y$ when divided by $10^x$.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers $n, x, y$ ($0 \\\\le y < x < n \\\\le 2 \\\\cdot 10^5$) — the length of the number and the integers $x$ and $y$, respectively.\\n\\nThe second line of the input contains one decimal number consisting of $n$ digits, each digit of this number is either 0 or 1. It is guaranteed that the first digit of the number is 1.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the minimum number of operations you should perform to obtain the number having remainder $10^y$ modulo $10^x$. In other words, the obtained number should have remainder $10^y$ when divided by $10^x$.\\n\\n\\n-----Examples-----\\nInput\\n11 5 2\\n11010100101\\n\\nOutput\\n1\\n\\nInput\\n11 5 1\\n11010100101\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the number will be $11010100100$ after performing one operation. It has remainder $100$ modulo $100000$.\\n\\nIn the second example the number will be $11010100010$ after performing three operations. It has remainder $10$ modulo $100000$.\",\"targets\":\"n,x,y=[int(x) for x in input().split()]\\na=[int(x) for x in list(input())]\\ncounter=0\\nfor i in range(n-x,n):\\n    if i==n-y-1:\\n        if a[i]==0:\\n            counter+=1\\n    else:\\n        if a[i]==1:\\n            counter+=1\\nprint(counter)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/952\\/A:\\n-----Input-----\\n\\nThe input contains a single integer a (10 ≤ a ≤ 999).\\n\\n\\n-----Output-----\\n\\nOutput 0 or 1.\\n\\n\\n-----Examples-----\\nInput\\n13\\n\\nOutput\\n1\\n\\nInput\\n927\\n\\nOutput\\n1\\n\\nInput\\n48\\n\\nOutput\\n0\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a = int(input())\\nprint(a % 2)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc151\\/tasks\\/abc151_d:\\nTakahashi has a maze, which is a grid of H \\\\times W squares with H horizontal rows and W vertical columns.\\nThe square at the i-th row from the top and the j-th column is a \\\"wall\\\" square if S_{ij} is #, and a \\\"road\\\" square if S_{ij} is ..\\nFrom a road square, you can move to a horizontally or vertically adjacent road square.\\nYou cannot move out of the maze, move to a wall square, or move diagonally.\\nTakahashi will choose a starting square and a goal square, which can be any road squares, and give the maze to Aoki.\\nAoki will then travel from the starting square to the goal square, in the minimum number of moves required.\\nIn this situation, find the maximum possible number of moves Aoki has to make.\\n\\n-----Constraints-----\\n - 1 \\\\leq H,W \\\\leq 20\\n - S_{ij} is . or #.\\n - S contains at least two occurrences of ..\\n - Any road square can be reached from any road square in zero or more moves.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nH W\\nS_{11}...S_{1W}\\n:\\nS_{H1}...S_{HW}\\n\\n-----Output-----\\nPrint the maximum possible number of moves Aoki has to make.\\n\\n-----Sample Input-----\\n3 3\\n...\\n...\\n...\\n\\n-----Sample Output-----\\n4\\n\\nIf Takahashi chooses the top-left square as the starting square and the bottom-right square as the goal square, Aoki has to make four moves.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"h,w = map(int,input().split())\\nC = [list(input()) for i in range(h)]\\nstartls = []\\n\\nfor i in range(h):\\n    for j in range(w):\\n        if C[i][j] == '.':\\n            startls.append([i,j])\\n            \\ndy_dx = [[1,0],[0,1],[-1,0],[0,-1]]\\nans = 0\\nfor start in startls:\\n    visited = [[-1 for i in range(w)] for i in range(h)]\\n    visited[start[0]][start[1]] = 0\\n    cost = 0\\n    queue = [start]\\n    while len(queue) > 0:\\n        now = queue.pop(0)\\n        cost = visited[now[0]][now[1]]+1\\n        for i in range(4):\\n            y = now[0]+dy_dx[i][0]\\n            x = now[1]+dy_dx[i][1]\\n            if 0 <= y < h and 0 <= x < w:\\n                if C[y][x] != '#' and visited[y][x] == -1:\\n                    visited[y][x] = cost\\n                    queue.append([y,x])\\n                    ans = max(ans,cost)\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1153\\/D:\\nNow Serval is a junior high school student in Japari Middle School, and he is still thrilled on math as before. \\n\\nAs a talented boy in mathematics, he likes to play with numbers. This time, he wants to play with numbers on a rooted tree.\\n\\nA tree is a connected graph without cycles. A rooted tree has a special vertex called the root. A parent of a node $v$ is the last different from $v$ vertex on the path from the root to the vertex $v$. Children of vertex $v$ are all nodes for which $v$ is the parent. A vertex is a leaf if it has no children.\\n\\nThe rooted tree Serval owns has $n$ nodes, node $1$ is the root. Serval will write some numbers into all nodes of the tree. However, there are some restrictions. Each of the nodes except leaves has an operation $\\\\max$ or $\\\\min$ written in it, indicating that the number in this node should be equal to the maximum or minimum of all the numbers in its sons, respectively. \\n\\nAssume that there are $k$ leaves in the tree. Serval wants to put integers $1, 2, \\\\ldots, k$ to the $k$ leaves (each number should be used exactly once). He loves large numbers, so he wants to maximize the number in the root. As his best friend, can you help him?\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $n$ ($2 \\\\leq n \\\\leq 3\\\\cdot 10^5$), the size of the tree.\\n\\nThe second line contains $n$ integers, the $i$-th of them represents the operation in the node $i$. $0$ represents $\\\\min$ and $1$ represents $\\\\max$. If the node is a leaf, there is still a number of $0$ or $1$, but you can ignore it.\\n\\nThe third line contains $n-1$ integers $f_2, f_3, \\\\ldots, f_n$ ($1 \\\\leq f_i \\\\leq i-1$), where $f_i$ represents the parent of the node $i$.\\n\\n\\n-----Output-----\\n\\nOutput one integer — the maximum possible number in the root of the tree.\\n\\n\\n-----Examples-----\\nInput\\n6\\n1 0 1 1 0 1\\n1 2 2 2 2\\n\\nOutput\\n1\\n\\nInput\\n5\\n1 0 1 0 1\\n1 1 1 1\\n\\nOutput\\n4\\n\\nInput\\n8\\n1 0 0 1 0 1 1 0\\n1 1 2 2 3 3 3\\n\\nOutput\\n4\\n\\nInput\\n9\\n1 1 0 0 1 0 1 0 1\\n1 1 2 2 3 3 4 4\\n\\nOutput\\n5\\n\\n\\n\\n-----Note-----\\n\\nPictures below explain the examples. The numbers written...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\na = [None] + list(map(int, input().split()))\\np = [None, None] + list(map(int, input().split()))\\n\\nf = [[0, 0, 10 ** 9] for i in range(n + 1)]\\nfor i in range(n, 1, -1):\\n    if f[i][0] == 0:\\n        c = x = y = 1\\n    else:\\n        c, x, y = f[i]\\n    w = y if a[i] else x\\n    f[p[i]][0] += c\\n    f[p[i]][1] += w\\n    f[p[i]][2] = min(f[p[i]][2], w)\\nw = f[1][2] if a[1] else f[1][1]\\nprint(f[1][0] - w + 1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc097\\/tasks\\/abc097_b:\\nYou are given a positive integer X.\\nFind the largest perfect power that is at most X.\\nHere, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.\\n\\n-----Constraints-----\\n - 1 ≤ X ≤ 1000\\n - X is an integer.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nX\\n\\n-----Output-----\\nPrint the largest perfect power that is at most X.\\n\\n-----Sample Input-----\\n10\\n\\n-----Sample Output-----\\n9\\n\\nThere are four perfect powers that are at most 10: 1, 4, 8 and 9.\\nWe should print the largest among them, 9.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"x = int(input())\\nprint((max([pow(i, j) for i in range(1, 32)\\n           for j in range(2, 10) if pow(i, j) <= x])))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1221\\/B:\\nYou are given a chess board with $n$ rows and $n$ columns. Initially all cells of the board are empty, and you have to put a white or a black knight into each cell of the board.\\n\\nA knight is a chess piece that can attack a piece in cell ($x_2$, $y_2$) from the cell ($x_1$, $y_1$) if one of the following conditions is met:\\n\\n  $|x_1 - x_2| = 2$ and $|y_1 - y_2| = 1$, or  $|x_1 - x_2| = 1$ and $|y_1 - y_2| = 2$. \\n\\nHere are some examples of which cells knight can attack. In each of the following pictures, if the knight is currently in the blue cell, it can attack all red cells (and only them).\\n\\n [Image] \\n\\nA duel of knights is a pair of knights of different colors such that these knights attack each other. You have to put a knight (a white one or a black one) into each cell in such a way that the number of duels is maximum possible.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $n$ ($3 \\\\le n \\\\le 100$) — the number of rows (and columns) in the board.\\n\\n\\n-----Output-----\\n\\nPrint $n$ lines with $n$ characters in each line. The $j$-th character in the $i$-th line should be W, if the cell ($i$, $j$) contains a white knight, or B, if it contains a black knight. The number of duels should be maximum possible. If there are multiple optimal answers, print any of them.\\n\\n\\n-----Example-----\\nInput\\n3\\n\\nOutput\\nWBW\\nBBB\\nWBW\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, there are $8$ duels:\\n\\n  the white knight in ($1$, $1$) attacks the black knight in ($3$, $2$);  the white knight in ($1$, $1$) attacks the black knight in ($2$, $3$);  the white knight in ($1$, $3$) attacks the black knight in ($3$, $2$);  the white knight in ($1$, $3$) attacks the black knight in ($2$, $1$);  the white knight in ($3$, $1$) attacks the black knight in ($1$, $2$);  the white knight in ($3$, $1$) attacks the black knight in ($2$, $3$);  the white knight in ($3$, $3$) attacks the black knight in ($1$, $2$);  the white knight in ($3$, $3$) attacks the black knight in ($2$, $1$).\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\nmat = [[0 for i in range(n)] for j in range(n)]\\nfor i in range(n):\\n\\tfor j in range(n):\\n\\t\\tif (i + j) % 2 == 1:\\n\\t\\t\\tmat[i][j] = 'W'\\n\\t\\telse:\\n\\t\\t\\tmat[i][j] = 'B'\\nfor i in range(n):\\n\\tfor j in range(n):\\n\\t\\tif j < n-1:\\n\\t\\t\\tprint(mat[i][j], end = \\\"\\\")\\n\\t\\telse:\\n\\t\\t\\tprint(mat[i][j])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1249\\/B2:\\nThe only difference between easy and hard versions is constraints.\\n\\nThere are $n$ kids, each of them is reading a unique book. At the end of any day, the $i$-th kid will give his book to the $p_i$-th kid (in case of $i = p_i$ the kid will give his book to himself). It is guaranteed that all values of $p_i$ are distinct integers from $1$ to $n$ (i.e. $p$ is a permutation). The sequence $p$ doesn't change from day to day, it is fixed.\\n\\nFor example, if $n=6$ and $p=[4, 6, 1, 3, 5, 2]$ then at the end of the first day the book of the $1$-st kid will belong to the $4$-th kid, the $2$-nd kid will belong to the $6$-th kid and so on. At the end of the second day the book of the $1$-st kid will belong to the $3$-th kid, the $2$-nd kid will belong to the $2$-th kid and so on.\\n\\nYour task is to determine the number of the day the book of the $i$-th child is returned back to him for the first time for every $i$ from $1$ to $n$.\\n\\nConsider the following example: $p = [5, 1, 2, 4, 3]$. The book of the $1$-st kid will be passed to the following kids:  after the $1$-st day it will belong to the $5$-th kid,  after the $2$-nd day it will belong to the $3$-rd kid,  after the $3$-rd day it will belong to the $2$-nd kid,  after the $4$-th day it will belong to the $1$-st kid. \\n\\nSo after the fourth day, the book of the first kid will return to its owner. The book of the fourth kid will return to him for the first time after exactly one day.\\n\\nYou have to answer $q$ independent queries.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $q$ ($1 \\\\le q \\\\le 1000$) — the number of queries. Then $q$ queries follow.\\n\\nThe first line of the query contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of kids in the query. The second line of the query contains $n$ integers $p_1, p_2, \\\\dots, p_n$ ($1 \\\\le p_i \\\\le n$, all $p_i$ are distinct, i.e. $p$ is a permutation), where $p_i$ is the kid which will get the book of the $i$-th kid.\\n\\nIt is guaranteed that $\\\\sum n \\\\le 2 \\\\cdot 10^5$ (sum of $n$ over all queries does...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"q = int(input())\\nfor i in range(q):\\n    n = int(input())\\n    a = list(map(int, input().split()))\\n    b = [-1 for i in range(n)]\\n    c = [0 for i in range(n + 2)]\\n    used = [True for i in range(n)]\\n    for i in range(n):\\n        if used[i]:\\n            d = a[i] - 1\\n            cell = a[i] - 1\\n            b[cell] = d\\n            c[d] += 1\\n            used[cell] = False\\n            while cell != i:\\n                cell = a[cell] - 1\\n                c[d] += 1\\n                b[cell] = d\\n                used[cell] = False\\n    for i in range(n):\\n        print(c[b[i]], end=\\\" \\\")\\n    print()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/459\\/C:\\nRecently Pashmak has been employed in a transportation company. The company has k buses and has a contract with a school which has n students. The school planned to take the students to d different places for d days (each day in one place). Each day the company provides all the buses for the trip. Pashmak has to arrange the students in the buses. He wants to arrange the students in a way that no two students become close friends. In his ridiculous idea, two students will become close friends if and only if they are in the same buses for all d days.\\n\\nPlease help Pashmak with his weird idea. Assume that each bus has an unlimited capacity.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains three space-separated integers n, k, d (1 ≤ n, d ≤ 1000; 1 ≤ k ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nIf there is no valid arrangement just print -1. Otherwise print d lines, in each of them print n integers. The j-th integer of the i-th line shows which bus the j-th student has to take on the i-th day. You can assume that the buses are numbered from 1 to k.\\n\\n\\n-----Examples-----\\nInput\\n3 2 2\\n\\nOutput\\n1 1 2 \\n1 2 1 \\n\\nInput\\n3 2 1\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nNote that two students become close friends only if they share a bus each day. But the bus they share can differ from day to day.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,k,d=map(int,input().split())\\nif n>k**d:print(-1);return\\nK=1\\nfor j in range(d):\\n    print(\\\" \\\".join([str(i\\/\\/K%k +1) for i in range(n)]))\\n    K*=k\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/projection-area-of-3d-shapes\\/:\\nOn a N * N grid, we place some 1 * 1 * 1 cubes that are axis-aligned with the x, y, and z axes.\\nEach value v = grid[i][j] represents a tower of v cubes placed on top of grid cell (i, j).\\nNow we view the projection of these cubes onto the xy, yz, and zx planes.\\nA projection is like a shadow, that maps our 3 dimensional figure to a 2 dimensional plane. \\nHere, we are viewing the \\\"shadow\\\" when looking at the cubes from the top, the front, and the side.\\nReturn the total area of all three projections.\\n \\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\n\\nExample 1:\\nInput: [[2]]\\nOutput: 5\\n\\n\\nExample 2:\\nInput: [[1,2],[3,4]]\\nOutput: 17\\nExplanation: \\nHere are the three projections (\\\"shadows\\\") of the shape made with each axis-aligned plane.\\n\\n\\n\\nExample 3:\\nInput: [[1,0],[0,2]]\\nOutput: 8\\n\\n\\nExample 4:\\nInput: [[1,1,1],[1,0,1],[1,1,1]]\\nOutput: 14\\n\\n\\nExample 5:\\nInput: [[2,2,2],[2,1,2],[2,2,2]]\\nOutput: 21\\n\\n \\n\\n\\n\\nNote:\\n\\n1 <= grid.length = grid[0].length <= 50\\n0 <= grid[i][j] <= 50\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def projectionArea(self, grid: List[List[int]]) -> int:\\n        ans=0\\n        for i in range(len(grid)):\\n            row=0\\n            col=0\\n            for j in range(len(grid[i])):\\n                if(grid[i][j]):\\n                    ans+=1\\n                row=max(row,grid[i][j])\\n                col=max(col,grid[j][i])\\n            ans+=row+col\\n        return ans\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/592c1dfb912f22055b000099:\\nIntroduction \\n\\nMr. Safety loves numeric locks and his Nokia 3310. He locked almost everything in his house. He is so smart and he doesn't need to remember the combinations. He has an algorithm to generate new passcodes on his Nokia cell phone. \\n\\n\\n Task \\n\\nCan you crack his numeric locks? Mr. Safety's treasures wait for you. Write an algorithm to open his numeric locks. Can you do it without his Nokia 3310? \\n\\nInput \\n\\nThe `str` or `message` (Python) input string consists of lowercase and upercase characters. It's a real object that you want to unlock.\\n\\nOutput \\nReturn a string that only consists of digits.\\n\\nExample\\n```\\nunlock(\\\"Nokia\\\")  \\/\\/ => 66542\\nunlock(\\\"Valut\\\")  \\/\\/ => 82588\\nunlock(\\\"toilet\\\") \\/\\/ => 864538\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"table = str.maketrans(\\\"abcdefghijklmnopqrstuvwxyz\\\", \\\"22233344455566677778889999\\\")\\n\\ndef unlock(message):\\n    return message.lower().translate(table)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc056\\/tasks\\/arc070_a:\\nThere is a kangaroo at coordinate 0 on an infinite number line that runs from left to right, at time 0.\\nDuring the period between time i-1 and time i, the kangaroo can either stay at his position, or perform a jump of length exactly i to the left or to the right.\\nThat is, if his coordinate at time i-1 is x, he can be at coordinate x-i, x or x+i at time i.\\nThe kangaroo's nest is at coordinate X, and he wants to travel to coordinate X as fast as possible.\\nFind the earliest possible time to reach coordinate X.\\n\\n-----Constraints-----\\n - X is an integer.\\n - 1≤X≤10^9\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\nX\\n\\n-----Output-----\\nPrint the earliest possible time for the kangaroo to reach coordinate X.\\n\\n-----Sample Input-----\\n6\\n\\n-----Sample Output-----\\n3\\n\\nThe kangaroo can reach his nest at time 3 by jumping to the right three times, which is the earliest possible time.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nimport re\\nfrom collections import deque, defaultdict, Counter\\nfrom math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians\\nfrom itertools import accumulate, permutations, combinations, product\\nfrom operator import itemgetter, mul\\nfrom copy import deepcopy\\nfrom string import ascii_lowercase, ascii_uppercase, digits\\nfrom bisect import bisect, bisect_left\\nfrom fractions import gcd\\nfrom heapq import heappush, heappop\\nfrom functools import reduce\\ndef input(): return sys.stdin.readline().strip()\\ndef INT(): return int(input())\\ndef MAP(): return list(map(int, input().split()))\\ndef LIST(): return list(map(int, input().split()))\\nsys.setrecursionlimit(10 ** 9)\\nINF = float('inf')\\nmod = 10 ** 9 + 7\\n\\nX = INT()\\n\\nA = []\\ntmp = 0\\nfor i in range(1, X+1):\\n    tmp += i\\n    A.append(tmp)\\n    if tmp >= X:\\n        print(i)\\n        break\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe Cybermen and the Daleks have long been the Doctor's main enemies. Everyone knows that both these species enjoy destroying everything they encounter. However, a little-known fact about them is that they both also love taking Turing tests!\\n\\nHeidi designed a series of increasingly difficult tasks for them to spend their time on, which would allow the Doctor enough time to save innocent lives!\\n\\nThe funny part is that these tasks would be very easy for a human to solve.\\n\\nThe first task is as follows. There are some points on the plane. All but one of them are on the boundary of an axis-aligned square (its sides are parallel to the axes). Identify that point.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $n$ ($2 \\\\le n \\\\le 10$).\\n\\nEach of the following $4n + 1$ lines contains two integers $x_i, y_i$ ($0 \\\\leq x_i, y_i \\\\leq 50$), describing the coordinates of the next point.\\n\\nIt is guaranteed that there are at least $n$ points on each side of the square and all $4n + 1$ points are distinct.\\n\\n\\n-----Output-----\\n\\nPrint two integers — the coordinates of the point that is not on the boundary of the square.\\n\\n\\n-----Examples-----\\nInput\\n2\\n0 0\\n0 1\\n0 2\\n1 0\\n1 1\\n1 2\\n2 0\\n2 1\\n2 2\\n\\nOutput\\n1 1\\n\\nInput\\n2\\n0 0\\n0 1\\n0 2\\n0 3\\n1 0\\n1 2\\n2 0\\n2 1\\n2 2\\n\\nOutput\\n0 3\\n\\n\\n\\n-----Note-----\\n\\nIn both examples, the square has four sides $x=0$, $x=2$, $y=0$, $y=2$.\",\"targets\":\"#!\\/usr\\/bin\\/env python\\nimport sys\\n\\nn = int(input())\\nk = (n << 2) + 1\\n\\nx, y = [], []\\nfor i in range(k):\\n    xi, yi = list(map(int, input().split()))\\n    x.append(xi)\\n    y.append(yi)\\n\\nfor lx in range(0, 50):\\n    for ly in range(0, 50):\\n        for side_len in range(1, 51):\\n            ok, idx = True, -1\\n            for i in range(k):\\n                if not (((x[i] == lx or x[i] == lx + side_len) and ly <= y[i] <= ly + side_len) or\\n                    ((lx <= x[i] <= lx + side_len) and (y[i] == ly or y[i] == ly + side_len))):\\n                    if idx != -1:\\n                        ok = False\\n                    else:\\n                        idx = i\\n            if ok:\\n                print(x[idx], y[idx])\\n                return\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/57a77726bb9944d000000b06:\\nThere's a **\\\"3 for 2\\\"** (or **\\\"2+1\\\"** if you like) offer on mangoes. For a given quantity and price (per mango), calculate the total cost of the mangoes.\\n\\n### Examples\\n```python\\nmango(3, 3) ==> 6    # 2 mangoes for 3 = 6; +1 mango for free\\nmango(9, 5) ==> 30   # 6 mangoes for 5 = 30; +3 mangoes for free\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\ndef mango(quantity, price):\\n    n=math.ceil(quantity*(2\\/3))\\n    return price*n\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1294\\/D:\\nRecall that MEX of an array is a minimum non-negative integer that does not belong to the array. Examples:  for the array $[0, 0, 1, 0, 2]$ MEX equals to $3$ because numbers $0, 1$ and $2$ are presented in the array and $3$ is the minimum non-negative integer not presented in the array;  for the array $[1, 2, 3, 4]$ MEX equals to $0$ because $0$ is the minimum non-negative integer not presented in the array;  for the array $[0, 1, 4, 3]$ MEX equals to $2$ because $2$ is the minimum non-negative integer not presented in the array. \\n\\nYou are given an empty array $a=[]$ (in other words, a zero-length array). You are also given a positive integer $x$.\\n\\nYou are also given $q$ queries. The $j$-th query consists of one integer $y_j$ and means that you have to append one element $y_j$ to the array. The array length increases by $1$ after a query.\\n\\nIn one move, you can choose any index $i$ and set $a_i := a_i + x$ or $a_i := a_i - x$ (i.e. increase or decrease any element of the array by $x$). The only restriction is that $a_i$ cannot become negative. Since initially the array is empty, you can perform moves only after the first query.\\n\\nYou have to maximize the MEX (minimum excluded) of the array if you can perform any number of such operations (you can even perform the operation multiple times with one element).\\n\\nYou have to find the answer after each of $q$ queries (i.e. the $j$-th answer corresponds to the array of length $j$).\\n\\nOperations are discarded before each query. I.e. the array $a$ after the $j$-th query equals to $[y_1, y_2, \\\\dots, y_j]$.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $q, x$ ($1 \\\\le q, x \\\\le 4 \\\\cdot 10^5$) — the number of queries and the value of $x$.\\n\\nThe next $q$ lines describe queries. The $j$-th query consists of one integer $y_j$ ($0 \\\\le y_j \\\\le 10^9$) and means that you have to append one element $y_j$ to the array.\\n\\n\\n-----Output-----\\n\\nPrint the answer to the initial problem after each query — for the query $j$ print the maximum value of MEX after first $j$...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\nq,x=list(map(int,input().split()))\\n\\nseg_el=1<<((x+1).bit_length())\\nSEG=[0]*(2*seg_el)\\n\\ndef add1(n,seg_el):\\n    i=n+seg_el\\n    SEG[i]+=1\\n    i>>=1\\n    \\n    while i!=0:\\n        SEG[i]=min(SEG[i*2],SEG[i*2+1])\\n        i>>=1\\n        \\ndef getvalues(l,r):\\n    L=l+seg_el\\n    R=r+seg_el\\n    ANS=1<<30\\n\\n    while L<R:\\n        if L & 1:\\n            ANS=min(ANS , SEG[L])\\n            L+=1\\n\\n        if R & 1:\\n            R-=1\\n            ANS=min(ANS , SEG[R])\\n        L>>=1\\n        R>>=1\\n\\n    return ANS\\n\\nfor qu in range(q):\\n    t=int(input())\\n    add1(t%x,seg_el)\\n\\n    #print(SEG)\\n\\n    MIN=getvalues(0,x)\\n\\n    OK=0\\n    NG=x\\n\\n    while NG-OK>1:\\n        mid=(OK+NG)\\/\\/2\\n\\n        if getvalues(0,mid)>MIN:\\n            OK=mid\\n        else:\\n            NG=mid\\n\\n    #print(MIN,OK)\\n    print(MIN*x+OK)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn one of the games Arkady is fond of the game process happens on a rectangular field. In the game process Arkady can buy extensions for his field, each extension enlarges one of the field sizes in a particular number of times. Formally, there are n extensions, the i-th of them multiplies the width or the length (by Arkady's choice) by a_{i}. Each extension can't be used more than once, the extensions can be used in any order.\\n\\nNow Arkady's field has size h × w. He wants to enlarge it so that it is possible to place a rectangle of size a × b on it (along the width or along the length, with sides parallel to the field sides). Find the minimum number of extensions needed to reach Arkady's goal.\\n\\n\\n-----Input-----\\n\\nThe first line contains five integers a, b, h, w and n (1 ≤ a, b, h, w, n ≤ 100 000) — the sizes of the rectangle needed to be placed, the initial sizes of the field and the number of available extensions.\\n\\nThe second line contains n integers a_1, a_2, ..., a_{n} (2 ≤ a_{i} ≤ 100 000), where a_{i} equals the integer a side multiplies by when the i-th extension is applied.\\n\\n\\n-----Output-----\\n\\nPrint the minimum number of extensions needed to reach Arkady's goal. If it is not possible to place the rectangle on the field with all extensions, print -1. If the rectangle can be placed on the initial field, print 0.\\n\\n\\n-----Examples-----\\nInput\\n3 3 2 4 4\\n2 5 4 10\\n\\nOutput\\n1\\n\\nInput\\n3 3 3 3 5\\n2 3 5 4 2\\n\\nOutput\\n0\\n\\nInput\\n5 5 1 2 3\\n2 2 3\\n\\nOutput\\n-1\\n\\nInput\\n3 4 1 1 3\\n2 3 2\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first example it is enough to use any of the extensions available. For example, we can enlarge h in 5 times using the second extension. Then h becomes equal 10 and it is now possible to place the rectangle on the field.\",\"targets\":\"def mp():  return list(map(int,input().split()))\\ndef lt():  return list(map(int,input().split()))\\ndef pt(x):  print(x)\\ndef ip():  return input()\\ndef it():  return int(input())\\ndef sl(x):  return [t for t in x]\\ndef spl(x): return x.split()\\ndef aj(liste, item): liste.append(item)\\ndef bin(x):  return \\\"{0:b}\\\".format(x)\\ndef listring(l): return ' '.join([str(x) for x in l])\\ndef ptlist(l): print(' '.join([str(x) for x in l]))\\nfrom copy import deepcopy\\nc,b,h,w,n = mp() \\nd = lt()\\nd.sort(reverse = True)\\nk = min(n,34)\\na = d[:k] \\nif (c <= h and b <= w) or (c <= w and b <= h):\\n    pt(0)\\nelse:\\n    dict = {h:w}\\n    i = 0\\n    bl = True\\n    while bl and i < k:\\n        x = a[i]\\n        dict1 = {}\\n        for r in dict:\\n            if r*x in dict1:\\n                dict1[r*x] = max(dict1[r*x],dict[r])\\n            else:\\n                dict1[r*x] = dict[r]\\n            if r in dict1:\\n                dict1[r] = max(dict1[r],dict[r]*x)\\n            else:\\n                dict1[r] = dict[r]*x\\n        if any((r>=c and dict1[r]>=b) or (r>=b and dict1[r]>=c) for r in dict1):\\n            bl = False\\n        else:\\n            i += 1\\n            dict = deepcopy(dict1)\\n    if i == k:\\n        pt(-1)\\n    else:\\n        pt(i+1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/delete-and-earn\\/:\\nGiven an array nums of integers, you can perform operations on the array.\\n\\nIn each operation, you pick any nums[i] and delete it to earn nums[i] points.  After, you must delete every element equal to nums[i] - 1 or nums[i] + 1.\\n\\nYou start with 0 points.  Return the maximum number of points you can earn by applying such operations.\\n\\n\\nExample 1:\\n\\nInput: nums = [3, 4, 2]\\nOutput: 6\\nExplanation: \\nDelete 4 to earn 4 points, consequently 3 is also deleted.\\nThen, delete 2 to earn 2 points. 6 total points are earned.\\n\\n\\n\\nExample 2:\\n\\nInput: nums = [2, 2, 3, 3, 3, 4]\\nOutput: 9\\nExplanation: \\nDelete 3 to earn 3 points, deleting both 2's and the 4.\\nThen, delete 3 again to earn 3 points, and 3 again to earn 3 points.\\n9 total points are earned.\\n\\n\\n\\nNote:\\nThe length of nums is at most 20000.\\nEach element nums[i] is an integer in the range [1, 10000].\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def deleteAndEarn(self, nums):\\n         \\\"\\\"\\\"\\n         :type nums: List[int]\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         if (nums == []):\\n             return 0\\n         if (len(nums) == 1):\\n             return nums[0]\\n         \\n         nums.sort()\\n         numsp = nums[0]\\n         choose = [0,nums[0]]\\n         for i in range(1,len(nums)):\\n           numsc = nums[i]\\n           if (numsc == numsp):\\n               choose[1] += numsc\\n               continue\\n           elif(numsc == numsp+1):\\n               temp = choose[0]\\n               choose[0] = max(choose)\\n               choose[1] = temp+numsc\\n               numsp = numsc\\n           else:\\n               choose[0] = max(choose)\\n               choose[1] = choose[0]+numsc\\n               numsp = numsc\\n               \\n         return max(choose)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from $1$ to $9$). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, $\\\\ldots$, 9m, 1p, 2p, $\\\\ldots$, 9p, 1s, 2s, $\\\\ldots$, 9s.\\n\\nIn order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.\\n\\nDo you know the minimum number of extra suited tiles she needs to draw so that she can win?\\n\\nHere are some useful definitions in this game:  A mentsu, also known as meld, is formed by a koutsu or a shuntsu;  A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;  A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu. \\n\\nSome examples:   [2m, 3p, 2s, 4m, 1s, 2s, 4s] — it contains no koutsu or shuntsu, so it includes no mentsu;  [4s, 3m, 3p, 4s, 5p, 4s, 5p] — it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;  [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] — it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu. \\n\\nNote that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.\\n\\n\\n-----Input-----\\n\\nThe only line contains three strings — the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from $1$ to $9$ and the second character is m, p or s.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum...\",\"targets\":\"t = input().split()\\n\\nt.sort()\\n\\nif t.count(t[0]) == 3:\\n  print('0')\\nelif t.count(t[0]) == 2 or t.count(t[1]) == 2:\\n  print('1')\\nelse:\\n  num = list(map(int, [t[0][0], t[1][0], t[2][0]]))\\n  suit = [t[0][1], t[1][1], t[2][1]]\\n  if len(set(suit)) == 3:\\n    print('2')\\n  elif len(set(suit)) == 1:\\n    if num[1] == num[0] + 1 or num[2] == num[1] + 1:\\n      if num[2] == num[0] + 2:\\n        print('0')\\n      else:\\n        print('1')\\n    elif num[1] == num[0] + 2 or num[2] == num[1] + 2:\\n        print('1')\\n    else:\\n      print('2')\\n  else:\\n    if suit[0] == suit[1]:\\n      if num[1] - num[0] in [1, 2]:\\n        print('1')\\n      else:\\n        print('2')\\n    elif suit[1] == suit[2]:\\n      if num[2] - num[1] in [1, 2]:\\n        print('1')\\n      else:\\n        print('2')\\n    else:\\n      if num[2] - num[0] in [1, 2]:\\n        print('1')\\n      else:\\n        print('2')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe Tribonacci sequence Tn is defined as follows: \\nT0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2 for n >= 0.\\nGiven n, return the value of Tn.\\n \\nExample 1:\\nInput: n = 4\\nOutput: 4\\nExplanation:\\nT_3 = 0 + 1 + 1 = 2\\nT_4 = 1 + 1 + 2 = 4\\n\\nExample 2:\\nInput: n = 25\\nOutput: 1389537\\n\\n \\nConstraints:\\n\\n0 <= n <= 37\\nThe answer is guaranteed to fit within a 32-bit integer, ie. answer <= 2^31 - 1.\",\"targets\":\"from collections import deque \\nclass Solution:\\n    def tribonacci(self, n: int) -> int:\\n        if n>0 and n<3:\\n            return 1\\n        if n==0:\\n            return 0\\n        queue = deque([0,1,1])\\n        t = 2\\n        while t!=n:\\n            queue.append(sum(queue))\\n            queue.popleft()\\n            t+=1\\n        return queue[2]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou're going on a trip with some students and it's up to you to keep track of how much money each Student has. A student is defined like this:\\n\\n```python\\nclass Student:\\n    def __init__(self, name, fives, tens, twenties):\\n        self.name = name\\n        self.fives = fives\\n        self.tens = tens\\n        self.twenties = twenties\\n```\\n\\nAs you can tell, each Student has some fives, tens, and twenties. Your job is to return the name of the student with the most money. If every student has the same amount, then return `\\\"all\\\"`.\\n\\nNotes:\\n* Each student will have a unique name\\n* There will always be a clear winner: either one person has the most, or everyone has the same amount\\n* If there is only one student, then that student has the most money\",\"targets\":\"def most_money(students):\\n    allsame = True\\n    max = 0\\n    for s in students:\\n        smoney = s.fives*5 + s.tens*10 + s.twenties*20\\n        if max == 0:\\n            richest, max = s.name, smoney\\n        elif smoney != max:\\n            allsame = False\\n            \\n        if smoney > max:\\n            richest, max = s.name, smoney\\n            \\n    return \\\"all\\\" if allsame and len(students)>1 else richest\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a sequence of positive integers of length N, a = (a_1, a_2, ..., a_N).\\nYour objective is to remove some of the elements in a so that a will be a good sequence.\\nHere, an sequence b is a good sequence when the following condition holds true:\\n - For each element x in b, the value x occurs exactly x times in b.\\nFor example, (3, 3, 3), (4, 2, 4, 1, 4, 2, 4) and () (an empty sequence) are good sequences, while (3, 3, 3, 3) and (2, 4, 1, 4, 2) are not.\\nFind the minimum number of elements that needs to be removed so that a will be a good sequence.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 10^5\\n - a_i is an integer.\\n - 1 \\\\leq a_i \\\\leq 10^9\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\na_1 a_2 ... a_N\\n\\n-----Output-----\\nPrint the minimum number of elements that needs to be removed so that a will be a good sequence.\\n\\n-----Sample Input-----\\n4\\n3 3 3 3\\n\\n-----Sample Output-----\\n1\\n\\nWe can, for example, remove one occurrence of 3. Then, (3, 3, 3) is a good sequence.\",\"targets\":\"import collections\\nn = int(input())\\na = list(map(int,input().split()))\\n\\na_cnt = collections.Counter(a)\\n#print(a_cnt)\\ncnt = 0\\nfor item in a_cnt.items():\\n    if item[0]<item[1]:\\n        cnt += item[1]-item[0]\\n    elif item[0]>item[1]:\\n        cnt += item[1]\\nprint(cnt)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/56ee0448588cbb60740013b9:\\nNo Story\\n\\nNo Description\\n\\nOnly by Thinking and Testing\\n\\nLook at the results of the testcases, and guess the code!\\n\\n---\\n\\n## Series:\\n\\n01. [A and B?](http:\\/\\/www.codewars.com\\/kata\\/56d904db9963e9cf5000037d)\\n02. [Incomplete string](http:\\/\\/www.codewars.com\\/kata\\/56d9292cc11bcc3629000533)\\n03. [True or False](http:\\/\\/www.codewars.com\\/kata\\/56d931ecc443d475d5000003)\\n04. [Something capitalized](http:\\/\\/www.codewars.com\\/kata\\/56d93f249c844788bc000002)\\n05. [Uniq or not Uniq](http:\\/\\/www.codewars.com\\/kata\\/56d949281b5fdc7666000004)\\n06. [Spatiotemporal index](http:\\/\\/www.codewars.com\\/kata\\/56d98b555492513acf00077d)\\n07. [Math of Primary School](http:\\/\\/www.codewars.com\\/kata\\/56d9b46113f38864b8000c5a)\\n08. [Math of Middle school](http:\\/\\/www.codewars.com\\/kata\\/56d9c274c550b4a5c2000d92)\\n09. [From nothingness To nothingness](http:\\/\\/www.codewars.com\\/kata\\/56d9cfd3f3928b4edd000021)\\n10. [Not perfect? Throw away!](http:\\/\\/www.codewars.com\\/kata\\/56dae2913cb6f5d428000f77)\\n11. [Welcome to take the bus](http:\\/\\/www.codewars.com\\/kata\\/56db19703cb6f5ec3e001393)\\n12. [A happy day will come](http:\\/\\/www.codewars.com\\/kata\\/56dc41173e5dd65179001167)\\n13. [Sum of 15(Hetu Luosliu)](http:\\/\\/www.codewars.com\\/kata\\/56dc5a773e5dd6dcf7001356)\\n14. [Nebula or Vortex](http:\\/\\/www.codewars.com\\/kata\\/56dd3dd94c9055a413000b22)\\n15. [Sport Star](http:\\/\\/www.codewars.com\\/kata\\/56dd927e4c9055f8470013a5)\\n16. [Falsetto Rap Concert](http:\\/\\/www.codewars.com\\/kata\\/56de38c1c54a9248dd0006e4)\\n17. [Wind whispers](http:\\/\\/www.codewars.com\\/kata\\/56de4d58301c1156170008ff)\\n18. [Mobile phone simulator](http:\\/\\/www.codewars.com\\/kata\\/56de82fb9905a1c3e6000b52)\\n19. [Join but not join](http:\\/\\/www.codewars.com\\/kata\\/56dfce76b832927775000027)\\n20. [I hate big and small](http:\\/\\/www.codewars.com\\/kata\\/56dfd5dfd28ffd52c6000bb7)\\n21. [I want to become diabetic ;-)](http:\\/\\/www.codewars.com\\/kata\\/56e0e065ef93568edb000731)\\n22. [How many blocks?](http:\\/\\/www.codewars.com\\/kata\\/56e0f1dc09eb083b07000028)\\n23. [Operator hidden in a string](http:\\/\\/www.codewars.com\\/kata\\/56e1161fef93568228000aad)\\n24. [Substring...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def mystery(n):\\n    if n < 1:\\n        return []\\n    d = {1, n}\\n    for k in range(2, int(n ** 0.5) + 1):\\n        if not n % k:\\n            d.add(k)\\n            d.add(n \\/\\/ k)\\n    return sorted(i for i in d if i % 2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/280\\/A:\\nYou are given two rectangles on a plane. The centers of both rectangles are located in the origin of coordinates (meaning the center of the rectangle's symmetry). The first rectangle's sides are parallel to the coordinate axes: the length of the side that is parallel to the Ox axis, equals w, the length of the side that is parallel to the Oy axis, equals h. The second rectangle can be obtained by rotating the first rectangle relative to the origin of coordinates by angle α. [Image] \\n\\nYour task is to find the area of the region which belongs to both given rectangles. This region is shaded in the picture.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers w, h, α (1 ≤ w, h ≤ 10^6; 0 ≤ α ≤ 180). Angle α is given in degrees.\\n\\n\\n-----Output-----\\n\\nIn a single line print a real number — the area of the region which belongs to both given rectangles.\\n\\nThe answer will be considered correct if its relative or absolute error doesn't exceed 10^{ - 6}.\\n\\n\\n-----Examples-----\\nInput\\n1 1 45\\n\\nOutput\\n0.828427125\\n\\nInput\\n6 4 30\\n\\nOutput\\n19.668384925\\n\\n\\n\\n-----Note-----\\n\\nThe second sample has been drawn on the picture above.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\n\\nw, h, a = list(map(int, input().strip().split()))\\n\\nif h >   w:\\n    w, h = h, w\\n\\nif a > 90:\\n    a = 90 - (a - 90)\\n\\na = math.radians(a)\\n\\nif a < 2 * math.atan2(h, w):\\n    area = w * h\\n\\n    s = (w \\/ 2) - (h \\/ 2 * math.tan(a \\/ 2))\\n    bigger_area = 0.5 * s * s * math.tan(a)\\n\\n    s = (h \\/ 2) - (w \\/ 2 * math.tan(a \\/ 2))\\n    lower_area = 0.5 * s * s * math.tan(a)\\n\\n    print(area - 2 * bigger_area - 2 * lower_area)\\nelse:\\n    print(h * h \\/ math.sin(a))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed x in the absolute value.\\n\\nNatasha doesn't like when Vanya spends a long time playing, so she hid all of his cards. Vanya became sad and started looking for the cards but he only found n of them. Vanya loves the balance, so he wants the sum of all numbers on found cards equal to zero. On the other hand, he got very tired of looking for cards. Help the boy and say what is the minimum number of cards does he need to find to make the sum equal to zero?\\n\\nYou can assume that initially Vanya had infinitely many cards with each integer number from  - x to x.\\n\\n \\n\\n\\n-----Input-----\\n\\nThe first line contains two integers: n (1 ≤ n ≤ 1000) — the number of found cards and x (1 ≤ x ≤ 1000) — the maximum absolute value of the number on a card. The second line contains n space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed x in their absolute value.\\n\\n\\n-----Output-----\\n\\nPrint a single number — the answer to the problem.\\n\\n\\n-----Examples-----\\nInput\\n3 2\\n-1 1 2\\n\\nOutput\\n1\\n\\nInput\\n2 3\\n-2 -2\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, Vanya needs to find a single card with number -2.\\n\\nIn the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value.\",\"targets\":\"n, x = map(int, input().split())\\nprint(str((abs(sum(map(int, input().split()))) + x - 1) \\/\\/ x))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n$k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.\\n\\nThe people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arkady will choose an integer $x$ and then give the first $x$ candies to himself, the next $x$ candies to the second person, the next $x$ candies to the third person and so on in a cycle. The leftover (the remainder that is not divisible by $x$) will be thrown away.\\n\\nArkady can't choose $x$ greater than $M$ as it is considered greedy. Also, he can't choose such a small $x$ that some person will receive candies more than $D$ times, as it is considered a slow splitting.\\n\\nPlease find what is the maximum number of candies Arkady can receive by choosing some valid $x$.\\n\\n\\n-----Input-----\\n\\nThe only line contains four integers $n$, $k$, $M$ and $D$ ($2 \\\\le n \\\\le 10^{18}$, $2 \\\\le k \\\\le n$, $1 \\\\le M \\\\le n$, $1 \\\\le D \\\\le \\\\min{(n, 1000)}$, $M \\\\cdot D \\\\cdot k \\\\ge n$) — the number of candies, the number of people, the maximum number of candies given to a person at once, the maximum number of times a person can receive candies.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum possible number of candies Arkady can give to himself.\\n\\nNote that it is always possible to choose some valid $x$.\\n\\n\\n-----Examples-----\\nInput\\n20 4 5 2\\n\\nOutput\\n8\\n\\nInput\\n30 9 4 1\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Arkady should choose $x = 4$. He will give $4$ candies to himself, $4$ candies to the second person, $4$ candies to the third person, then $4$ candies to the fourth person and then again $4$ candies to himself. No person is given candies more than $2$ times, and Arkady receives $8$ candies in total.\\n\\nNote that if Arkady chooses $x = 5$, he will receive only $5$ candies, and if he chooses $x = 3$, he will receive only $3 + 3 = 6$ candies as well as the second person, the third and the fourth persons will receive $3$ candies, and $2$ candies will be thrown away. He can't choose $x = 1$ nor $x = 2$ because in...\",\"targets\":\"import math\\n\\n[n,k,M,D]=input().split()\\nn=int(n)\\nk=int(k)\\nM=int(M)\\nD=int(D)\\n\\\"\\\"\\\"\\nll best=0;\\n\\tfor (ll i=0; i<=(D-1); i++){\\n\\t\\tll x=min(up,n\\/(i*k+1));\\n\\t\\tll score=(i+1)*x;\\n\\t\\tbest=max(best,score);\\n\\t}\\n\\t\\n\\tcout<<best<<endl;\\n\\\"\\\"\\\"\\nbest=0\\nfor i in range(D):\\n\\t#print(n, i*k+1)\\n\\tx=min(M,(n\\/\\/(i*k+1)))\\n\\t#print(i, x)\\n\\tscore=(i+1)*x\\n\\tbest=max(best,score)\\nprint(best)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe aim of this kata is to split a given string into different strings of equal size (note size of strings is passed to the method)\\n\\nExample:\\n\\n    Split the below string into other strings of size #3\\n\\n    'supercalifragilisticexpialidocious'\\n\\n    Will return a new string\\n    'sup erc ali fra gil ist ice xpi ali doc iou s'\\n\\n\\nAssumptions:\\n\\n    String length is always greater than 0\\n    String has no spaces\\n    Size is always positive\",\"targets\":\"def split_in_parts(s, part_length):\\n    cnt = 0\\n    answer = \\\"\\\"\\n    for i in s:\\n        if cnt < part_length:\\n            answer += i\\n            cnt += 1\\n        else:\\n            answer = answer + \\\" \\\"  + i\\n            cnt = 1\\n    return answer\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given two positive integers a and b.\\nLet x be the average of a and b.\\nPrint x rounded up to the nearest integer.\\n\\n-----Constraints-----\\n - a and b are integers.\\n - 1 \\\\leq a, b \\\\leq 100\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\na b\\n\\n-----Output-----\\nPrint x rounded up to the nearest integer.\\n\\n-----Sample Input-----\\n1 3\\n\\n-----Sample Output-----\\n2\\n\\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\",\"targets\":\"#ABC082A\\na,b = list(map(int,input().split()))\\na+=b\\nprint(((a+2-1)\\/\\/2))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYour security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly N city blocks, but they let him choose which blocks. That is, your friend must walk the perimeter of a region whose area is exactly N blocks. Your friend is quite lazy and would like your help to find the shortest possible route that meets the requirements. The city is laid out in a square grid pattern, and is large enough that for the sake of the problem it can be considered infinite.\\n\\n\\n-----Input-----\\n\\nInput will consist of a single integer N (1 ≤ N ≤ 10^6), the number of city blocks that must be enclosed by the route.\\n\\n\\n-----Output-----\\n\\nPrint the minimum perimeter that can be achieved.\\n\\n\\n-----Examples-----\\nInput\\n4\\n\\nOutput\\n8\\n\\nInput\\n11\\n\\nOutput\\n14\\n\\nInput\\n22\\n\\nOutput\\n20\\n\\n\\n\\n-----Note-----\\n\\nHere are some possible shapes for the examples:\\n\\n[Image]\",\"targets\":\"import math\\nn=int(input())\\na=int(math.sqrt(n))\\nans=4*a\\nn=n-a*a\\nans+=2*math.ceil(n\\/a)\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/CSTR2020\\/problems\\/SUBTRACT:\\nAyush is learning how to decrease a number by one, but he does it wrong with a number consisting of two or more digits. Ayush subtracts one from a number by the following algorithm:\\nif the last digit of the number is non-zero, he decreases the number by one.\\nif the last digit of the number is zero, he divides the number by 10.\\nYou are given an integer number n\\nAyush will subtract one from it k times. Your task is to print the result after all k subtractions.\\nIt is guaranteed that the result will be a positive integer number.\\nInput\\nThe first line of the input contains two integers n and k (2 ≤ n ≤ 10^9, 1 ≤ k ≤ 50) -- the number from which Ayush will subtract and the number of subtractions respectively.\\nOutput\\nPrint one integer number — the result of the decreasing n by one k times.\\nIt is guaranteed that the result will be a positive integer number.\\nEXAMPLE\\nSample Input 1\\n512 4\\nSample Output 1\\n50\\nSample Input 2\\n1000000000 9\\nSample Output 2\\n1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"(A,B) = list(map(int,input().split(' ')))\\nfor i in range(B):\\n    if str(A)[-1] != '0':\\n        A -= 1\\n    else:\\n        A \\/\\/= 10\\nprint(A)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAre you fond of collecting some kind of stuff? Mike is crazy about collecting stamps. He is an active member of Stamp Collecting Сommunity(SCC). \\n\\nSCC consists of N members which are fond of philately. A few days ago Mike argued with the others from SCC. Mike told them that all stamps of the members could be divided in such a way that i'th member would get i postage stamps. Now Mike wants to know if he was right. The next SCC meeting is tomorrow. Mike still has no answer.\\n\\nSo, help Mike! There are N members in the SCC, i'th member has Ci stamps in his collection. Your task is to determine if it is possible to redistribute C1 + C2 + ... + Cn stamps among the members of SCC thus that i'th member would get i stamps.\\n\\n-----Input-----\\nThe first line contains one integer N, denoting the number of members of SCC.\\nThe second line contains N integers Ci, denoting the numbers of the stamps in the collection of i'th member.\\n\\n-----Output-----\\nThe first line should contain YES, if we can obtain the required division, otherwise NO.\\n\\n-----Constraints-----\\n1 ≤ N ≤ 100 000;\\n1 ≤  Ci ≤ 109.\\n\\n-----Examples-----\\nInput:\\n5\\n7 4 1 1 2\\n\\nOutput:\\nYES\\n\\nInput:\\n5\\n1 1 1 1 1\\n\\nOutput:\\nNO\",\"targets\":\"# cook your dish here\\nl = []\\nn = int(input())\\nx = map(int, input().split())\\nx1 = sum(x)\\nfor i in range(1, n+1):\\n    l.append(i)\\n\\nl1 = sum(l)\\nif x1 == l1:\\n    print(\\\"YES\\\")\\nelse:\\n    print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a set $S$ and $Q$ queries. Initially, $S$ is empty. In each query:\\n- You are given a positive integer $X$.\\n- You should insert $X$ into $S$.\\n- For each $y \\\\in S$ before this query such that $y \\\\neq X$, you should also insert $y \\\\oplus X$ into $S$ ($\\\\oplus$ denotes the XOR operation).\\n- Then, you should find two values $E$ and $O$: the number of elements of $S$ with an even number of $1$-s and with an odd number of $1$-s in the binary representation, respectively.\\nNote that a set cannot have duplicate elements, so if you try to insert into $S$ an element that is already present in $S$, then nothing happens.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $Q$.\\n- Each of the next $Q$ lines contains a single integer $X$ describing a query.\\n\\n-----Output-----\\nFor each query, print a single line containing two space-separated integers $E$ and $O$.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 5$\\n- $1 \\\\le Q, X \\\\le 10^5$\\n\\n-----Subtasks-----\\nSubtask #1 (30 points):\\n- $1 \\\\le Q \\\\le 1,000$\\n- $1 \\\\le X \\\\le 128$\\nSubtask #2 (70 points): original constraints\\n\\n-----Example Input-----\\n1\\n3\\n4\\n2\\n7\\n\\n-----Example Output-----\\n0 1\\n1 2\\n3 4\\n\\n-----Explanation-----\\nExample case 1:\\n- Initially, the set is empty: $S = \\\\{\\\\}$.\\n- After the first query, $S = \\\\{4\\\\}$, so there is only one element with an odd number of $1$-s in the binary representation (\\\"100\\\").\\n- After the second query, $S = \\\\{4,2,6\\\\}$, there is one element with an even number of $1$-s in the binary representation ($6$ is \\\"110\\\") and the other two elements have an odd number of $1$-s.\\n- After the third query, $S = \\\\{4,2,6,7,3,5,1\\\\}$.\",\"targets\":\"import collections\\ndef bits(x):\\n return bin(x).count('1')\\nt=int(input())\\nfor _ in range(t):\\n q=int(input())\\n s=[]\\n d=collections.defaultdict(lambda:-1)\\n e=0\\n o=0\\n p=-1\\n for i in range(q):\\n  x=int(input())\\n  # print(d)\\n  if d[x]!=-1:\\n   print(e,o)\\n   continue\\n  s.append(x)\\n  d[x]=1\\n  #z=len(s)\\n  for j in s:\\n   if j!=x:\\n    l=j^x\\n    if d[l]!=-1:\\n     continue\\n    s.append(l)\\n    d[l]=1\\n   \\n  for j in range(p+1,len(s)):\\n   p=j\\n   if bits(s[j])%2==0:\\n    e=e+1\\n   elif bits(s[j])%2!=0:\\n    o=o+1\\n  print(e,o)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of each value. Such sum is called unfortunate. Gerald wondered: what is the minimum unfortunate sum?\\n\\n\\n-----Input-----\\n\\nThe first line contains number n (1 ≤ n ≤ 1000) — the number of values of the banknotes that used in Geraldion. \\n\\nThe second line contains n distinct space-separated numbers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^6) — the values of the banknotes.\\n\\n\\n-----Output-----\\n\\nPrint a single line — the minimum unfortunate sum. If there are no unfortunate sums, print  - 1.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 2 3 4 5\\n\\nOutput\\n-1\",\"targets\":\"def __starting_point():\\n\\n    n = int(input())\\n    a = [int(x) for x in input().split()]\\n    a.sort()\\n\\n    if a[0] == 1:\\n        print(-1)\\n    else:\\n        print(1)\\n        \\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are $n$ candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from $1$ to $n$. The $i$-th box contains $r_i$ candies, candies have the color $c_i$ (the color can take one of three values ​​— red, green, or blue). All candies inside a single box have the same color (and it is equal to $c_i$).\\n\\nInitially, Tanya is next to the box number $s$. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.\\n\\nIf Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.\\n\\nIt is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.\\n\\nNote that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.\\n\\nTanya wants to eat at least $k$ candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers $n$, $s$ and $k$ ($1 \\\\le n \\\\le 50$, $1 \\\\le s \\\\le n$, $1 \\\\le k \\\\le 2000$) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains $n$ integers $r_i$ ($1 \\\\le r_i \\\\le 50$) — numbers of candies in the boxes. The third line contains sequence of $n$ letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no...\",\"targets\":\"inf = 10000\\nn, s, k = map(int, input().split())\\na = list(map(int, input().split()))\\nb = list(input())\\nfor i in range(n):\\n    if b[i] == 'R':\\n        b[i] = 0\\n    elif b[i] == 'G':\\n        b[i] = 1\\n    else:\\n        b[i] = 2\\nboxes = [[a[i], b[i], i] for i in range(n)]\\nboxes.sort()\\nl = boxes[-1][0] * n + 1\\ns -= 1\\ndp = [[[inf, s, -1] for j in range(l)] for i in range(3)]\\nif l < k:\\n    print(-1)\\n    return\\ndp[0][0][0] = 0\\ndp[1][0][0] = 0\\ndp[2][0][0] = 0\\nfor i in range(n):\\n    pos = boxes[i][2]\\n    clr = boxes[i][1]\\n    cnt = boxes[i][0]\\n    for j in range(l - cnt):\\n        for c in range(3):\\n            if c == clr:\\n                continue\\n            if dp[clr][j + cnt][0] > dp[c][j][0] + abs(dp[c][j][1] - pos) and cnt > dp[c][j][2]:\\n                dp[clr][j + cnt][0] = dp[c][j][0] + abs(dp[c][j][1] - pos)\\n                dp[clr][j + cnt][1] = pos\\n                dp[clr][j + cnt][2] = cnt\\nans = min(dp[0][k][0], min(dp[1][k][0], dp[2][k][0]))\\nfor i in range(k, l):\\n    ans = min(min(ans, dp[0][i][0]), min(dp[1][i][0], dp[2][i][0]))\\nif ans < inf:\\n    print(ans)\\nelse:\\n    print(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given two strings $s$ and $t$ both of length $n$ and both consisting of lowercase Latin letters.\\n\\nIn one move, you can choose any length $len$ from $1$ to $n$ and perform the following operation:   Choose any contiguous substring of the string $s$ of length $len$ and reverse it;  at the same time choose any contiguous substring of the string $t$ of length $len$ and reverse it as well. \\n\\nNote that during one move you reverse exactly one substring of the string $s$ and exactly one substring of the string $t$.\\n\\nAlso note that borders of substrings you reverse in $s$ and in $t$ can be different, the only restriction is that you reverse the substrings of equal length. For example, if $len=3$ and $n=5$, you can reverse $s[1 \\\\dots 3]$ and $t[3 \\\\dots 5]$, $s[2 \\\\dots 4]$ and $t[2 \\\\dots 4]$, but not $s[1 \\\\dots 3]$ and $t[1 \\\\dots 2]$.\\n\\nYour task is to say if it is possible to make strings $s$ and $t$ equal after some (possibly, empty) sequence of moves.\\n\\nYou have to answer $q$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $q$ ($1 \\\\le q \\\\le 10^4$) — the number of test cases. Then $q$ test cases follow.\\n\\nThe first line of the test case contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the length of $s$ and $t$.\\n\\nThe second line of the test case contains one string $s$ consisting of $n$ lowercase Latin letters.\\n\\nThe third line of the test case contains one string $t$ consisting of $n$ lowercase Latin letters.\\n\\nIt is guaranteed that the sum of $n$ over all test cases does not exceed $2 \\\\cdot 10^5$ ($\\\\sum n \\\\le 2 \\\\cdot 10^5$).\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer on it — \\\"YES\\\" (without quotes) if it is possible to make strings $s$ and $t$ equal after some (possibly, empty) sequence of moves and \\\"NO\\\" otherwise.\\n\\n\\n-----Example-----\\nInput\\n4\\n4\\nabcd\\nabdc\\n5\\nababa\\nbaaba\\n4\\nasdf\\nasdg\\n4\\nabcd\\nbadc\\n\\nOutput\\nNO\\nYES\\nNO\\nYES\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\nq=int(input())\\n\\nfrom collections import Counter\\n\\nfor testcases in range(q):\\n    n=int(input())\\n    S=input().strip()\\n    T=input().strip()\\n\\n    CS=Counter(S)\\n    CT=Counter(T)\\n\\n    if CS!=CT:\\n        print(\\\"NO\\\")\\n        continue\\n\\n    if max(CS.values())>=2:\\n        print(\\\"YES\\\")\\n        continue\\n\\n    W=[0]*26\\n    SA=0\\n\\n    for s in S:\\n        SA+=sum(W[ord(s)-97:])\\n        W[ord(s)-97]+=1\\n\\n    #print(SA)\\n\\n    W=[0]*26\\n    TA=0\\n\\n    for s in T:\\n        TA+=sum(W[ord(s)-97:])\\n        W[ord(s)-97]+=1\\n\\n    #print(TA)\\n\\n    if (SA+TA)%2==0:\\n        print(\\\"YES\\\")\\n    else:\\n        print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/CHEFINSQ:\\nChef has a sequence $A_1, A_2, \\\\ldots, A_N$. This sequence has exactly $2^N$ subsequences. Chef considers a subsequence of $A$ interesting if its size is exactly $K$ and the sum of all its elements is minimum possible, i.e. there is no subsequence with size $K$ which has a smaller sum.\\nHelp Chef find the number of interesting subsequences of the sequence $A$.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains two space-separated integers $N$ and $K$.\\n- The second line contains $N$ space-separated integers $A_1, A_2, \\\\ldots, A_N$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer ― the number of interesting subsequences.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 10$\\n- $1 \\\\le K \\\\le N \\\\le 50$\\n- $1 \\\\le A_i \\\\le 100$ for each valid $i$\\n\\n-----Subtasks-----\\nSubtask #1 (30 points): $1 \\\\le N \\\\le 20$\\nSubtask #2 (70 points): original constraints\\n\\n-----Example Input-----\\n1\\n4 2\\n1 2 3 4\\n\\n-----Example Output-----\\n1\\n\\n-----Explanation-----\\nExample case 1: There are six subsequences with length $2$: $(1, 2)$, $(1, 3)$, $(1, 4)$, $(2, 3)$, $(2, 4)$ and $(3, 4)$. The minimum sum is $3$ and the only subsequence with this sum is $(1, 2)$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def fact(n):\\n if n<2:\\n  return 1\\n return n * fact(n-1)\\n \\ndef ncr(n, r):\\n return fact(n)\\/\\/ (fact(r)*fact(n-r))\\n \\nt=int(input())\\n\\nfor _ in range(t):\\n n, k = list(map(int, input().split()))\\n a = list(map(int, input().split()))\\n a.sort()\\n count_z = a.count(a[k-1])\\n count_z_seq = a[:k].count(a[k-1])\\n \\n print(ncr(count_z, count_z_seq))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nCreate a function that will return ```true``` if the input is in the following date time format ```01-09-2016 01:20``` and ```false``` if it is not.\\n\\nThis Kata has been inspired by the Regular Expressions chapter from the book Eloquent JavaScript.\",\"targets\":\"import re\\ndef date_checker(date):\\n    return re.match(r'(\\\\d\\\\d-){2}\\\\d{4} \\\\d{2}:\\\\d{2}', date) != None\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/INTEG:\\nChef has an array of N integers. He wants to play a special game. In this game he needs to make all the integers in the array greater than or equal to 0. \\nChef can use two types of operations. The first type is to  increase all the integers of the given array by 1, but it costs X coins. The operation of the second type is to add 1 to only one integer of the given array and to use this operation you need to pay 1 coin. You need to calculate the minimal cost to win this game (to make all integers greater than or equal to 0)  \\n\\n-----Input-----\\n\\nThe first line of the input contains an integer N denoting the number of elements in the given array. The second line contains N space-separated integers A1, A2, ..., AN denoting the given array. The third line contains number X - cost of the first type operation. \\n\\n\\n-----Output-----\\nFor each test case, output a single line containing minimal cost required to make all the integers greater than or equal to zero.\\n\\n-----Constraints-----\\n\\n- 1 ≤ N ≤ 105\\n- -109 ≤ Ai ≤  109 \\n- 0 ≤ X  ≤ 109\\n\\n-----Example-----\\nInput:\\n3\\n-1 -2 -3\\n2\\n\\nOutput:\\n5\\n\\n-----Explanation-----\\nExample case 1: Use the first type operation twice and the second type once.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n=int(input())\\narr=list(map(int, input().split()))\\nx=int(input())\\nl=[]\\nfor i in arr:\\n if i<0:\\n  l.append(i)\\nl.sort(reverse=True)\\ns=0\\ninc=0\\nz=len(l)\\nfor i in range(len(l)):\\n if x<=z:\\n  l[i]+=inc\\n  s+=abs(l[i])*x\\n  inc+=abs(l[i])\\n  z-=1\\n else:\\n  l[i]+=inc\\n  s+=abs(l[i])\\nprint(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/HILLS:\\nThere are N hills in a row numbered 1 through N from left to right. Each hill has a height; for each valid i, the height of the i-th hill is Hi. Chef is initially on the leftmost hill (hill number 1). He can make an arbitrary number of jumps (including zero) as long as the following conditions are satisfied:\\n\\n- Chef can only jump from each hill to the next hill, i.e. from the i-th hill, he can jump to the i+1-th hill (if it exists).\\n- It's always possible to jump to a hill with the same height as the current hill.\\n- It's possible to jump to a taller hill if it's higher than the current hill by no more than U.\\n- It's possible to jump to a lower hill if it's lower than the current hill by no more than D.\\n- Chef can use a parachute and jump to a lower hill regardless of its height (as long as it's lower than the current hill). This jump can only be performed at most once.\\n\\nChef would like to move as far right as possible. Determine the index of the rightmost hill Chef can reach.\\n\\n-----Input-----\\n- The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.\\n- The first line of each test case contains three space-separated integers N, U and D.\\n- The second line contains N space-separated integers H1, H2, ..., HN.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer — the index of the rightmost reachable hill.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 100\\n- 1 ≤ N ≤ 100\\n- 1 ≤ U, D ≤ 1,000,000\\n- 1 ≤ Hi ≤ 1,000,000 for each valid i\\n\\n-----Subtasks-----\\nSubtask #1 (100 points): original constraints\\n\\n-----Example-----\\nInput:\\n\\n3\\n5 3 2\\n2 5 2 6 3\\n5 2 3\\n4 4 4 4 4\\n5 2 7\\n1 4 3 2 1\\n\\nOutput:\\n\\n3\\n5\\n1\\n\\n-----Explanation-----\\nExample case 1: Chef can jump to second hill because it's higher by no more than U=3 than first hill, to jump to third hill Chef has to use parachute \\nbecause it's lower than second hill by 3 which is more than D=2, Chef can't jump to fourth hill because it's higher than third hill by 4 which is more than U=3\\nExample case...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for _ in range(int(input())):\\n a = input().split()\\n n = int(a[0])\\n u = int(a[1])\\n d = int(a[2])\\n h = list(map(int, input().split()))\\n parachute = True\\n curr = 1\\n for i in range(n-1):\\n  if h[i+1] > h[i]:\\n   if h[i+1] > h[i]+u:\\n    break\\n  elif h[i+1] < h[i]:\\n   if h[i+1] < h[i]-d:\\n    if parachute:\\n     parachute = False\\n    else:\\n     break\\n  curr += 1\\n print(curr)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a6986abe626c5d3e9000063:\\nAs you see in Example test cases, the os running this service is ```posix```.\\n\\nReturn the output by executing the command given as the string on posix os.\\n\\nSee the example test cases for the expected data format.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def get_output(s):\\n    import subprocess\\n    return subprocess.check_output(s.split()).decode('ascii')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1119\\/E:\\nPavel has several sticks with lengths equal to powers of two.\\n\\nHe has $a_0$ sticks of length $2^0 = 1$, $a_1$ sticks of length $2^1 = 2$, ..., $a_{n-1}$ sticks of length $2^{n-1}$. \\n\\nPavel wants to make the maximum possible number of triangles using these sticks. The triangles should have strictly positive area, each stick can be used in at most one triangle.\\n\\nIt is forbidden to break sticks, and each triangle should consist of exactly three sticks.\\n\\nFind the maximum possible number of triangles.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\leq n \\\\leq 300\\\\,000$) — the number of different lengths of sticks.\\n\\nThe second line contains $n$ integers $a_0$, $a_1$, ..., $a_{n-1}$ ($1 \\\\leq a_i \\\\leq 10^9$), where $a_i$ is the number of sticks with the length equal to $2^i$.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum possible number of non-degenerate triangles that Pavel can make.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 2 2 2 2\\n\\nOutput\\n3\\n\\nInput\\n3\\n1 1 1\\n\\nOutput\\n0\\n\\nInput\\n3\\n3 3 3\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, Pavel can, for example, make this set of triangles (the lengths of the sides of the triangles are listed): $(2^0, 2^4, 2^4)$, $(2^1, 2^3, 2^3)$, $(2^1, 2^2, 2^2)$.\\n\\nIn the second example, Pavel cannot make a single triangle.\\n\\nIn the third example, Pavel can, for example, create this set of triangles (the lengths of the sides of the triangles are listed): $(2^0, 2^0, 2^0)$, $(2^1, 2^1, 2^1)$, $(2^2, 2^2, 2^2)$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\nA = list(map(int, input().split()))\\ndp = [A[0] \\/\\/ 3]\\ncnt = A[0]\\nfor i in range(1, n):\\n    ans = 0\\n    x = cnt - 3 * dp[-1]\\n    y = A[i] \\/\\/ 2\\n    if y <= x:\\n        dp.append(dp[-1] + y)\\n    else:\\n        s = A[i] - 2 * x\\n        dp.append(dp[-1] + s \\/\\/ 3 + x)\\n    cnt += A[i]\\nprint(dp[-1])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1051\\/D:\\nYou are given a grid, consisting of $2$ rows and $n$ columns. Each cell of this grid should be colored either black or white.\\n\\nTwo cells are considered neighbours if they have a common border and share the same color. Two cells $A$ and $B$ belong to the same component if they are neighbours, or if there is a neighbour of $A$ that belongs to the same component with $B$.\\n\\nLet's call some bicoloring beautiful if it has exactly $k$ components.\\n\\nCount the number of beautiful bicolorings. The number can be big enough, so print the answer modulo $998244353$.\\n\\n\\n-----Input-----\\n\\nThe only line contains two integers $n$ and $k$ ($1 \\\\le n \\\\le 1000$, $1 \\\\le k \\\\le 2n$) — the number of columns in a grid and the number of components required.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the number of beautiful bicolorings modulo $998244353$.\\n\\n\\n-----Examples-----\\nInput\\n3 4\\n\\nOutput\\n12\\n\\nInput\\n4 1\\n\\nOutput\\n2\\n\\nInput\\n1 2\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nOne of possible bicolorings in sample $1$: [Image]\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, k = list(map(int, input().split()))\\nsame = [0] * (k + 1)\\ndiff = [0] * (k + 1)\\nmod = 998244353\\nsame[1] = 2\\nif k > 1 : diff[2] = 2\\nfor i in range (n - 1) :\\n    newsame = [0] * (k + 1)\\n    newdiff = [0] * (k + 1)\\n    for i in range (1, k + 1) : newsame[i] = (same[i] + same[i - 1] + 2 * diff[i]) % mod\\n    for i in range (2, k + 1) : newdiff[i] = (2 * same[i - 1] + diff[i] + diff[i - 2]) % mod\\n    same = newsame ; diff = newdiff\\nprint((same[-1] + diff[-1]) % mod)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere is a building with 2N floors, numbered 1, 2, \\\\ldots, 2N from bottom to top.\\nThe elevator in this building moved from Floor 1 to Floor 2N just once.\\nOn the way, N persons got on and off the elevator. Each person i (1 \\\\leq i \\\\leq N) got on at Floor A_i and off at Floor B_i. Here, 1 \\\\leq A_i < B_i \\\\leq 2N, and just one person got on or off at each floor.\\nAdditionally, because of their difficult personalities, the following condition was satisfied:\\n - Let C_i (= B_i - A_i - 1) be the number of times, while Person i were on the elevator, other persons got on or off. Then, the following holds:\\n - If there was a moment when both Person i and Person j were on the elevator, C_i = C_j.\\nWe recorded the sequences A and B, but unfortunately, we have lost some of the records. If the record of A_i or B_i is lost, it will be given to you as -1.\\nAdditionally, the remaining records may be incorrect.\\nDetermine whether there is a pair of A and B that is consistent with the remaining records.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 100\\n - A_i = -1 or 1 \\\\leq A_i \\\\leq 2N.\\n - B_i = -1 or 1 \\\\leq B_i \\\\leq 2N.\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 B_1\\nA_2 B_2\\n:\\nA_N B_N\\n\\n-----Output-----\\nIf there is a pair of A and B that is consistent with the remaining records, print Yes; otherwise, print No.\\n\\n-----Sample Input-----\\n3\\n1 -1\\n-1 4\\n-1 6\\n\\n-----Sample Output-----\\nYes\\n\\nFor example, if B_1 = 3, A_2 = 2, and A_3 = 5, all the requirements are met.\\nIn this case, there is a moment when both Person 1 and Person 2 were on the elevator, which is fine since C_1 = C_2 = 1.\",\"targets\":\"def main():\\n    n = int(input())\\n    AB = [list(map(int, input().split())) for _ in range(n)]\\n    YesFlag = True\\n    arr = [True]*(2*n+1)\\n    cnt = 0\\n    for a, b in AB:\\n        if a != -1 and b != -1 and a > b:\\n            YesFlag = False\\n        if a != -1 and not arr[a]:\\n            YesFlag = False\\n        if b != -1 and not arr[b]:\\n            YesFlag = False\\n        if a != -1:\\n            arr[a] = False\\n        if b != -1:\\n            arr[b] = False\\n        if a == -1 and b == -1:\\n            cnt += 1\\n    dp = [-1]*(2*n+1)\\n    dp[0] = cnt\\n    for i in range(0, 2*n+1, 2):\\n        if dp[i] < 0:\\n            continue\\n        for j in range(i+2, 2*n+1, 2):\\n            fs = [True]*(2*n+1)\\n            lngth = (j-i)\\/\\/2\\n            sf = True\\n            for a, b in AB:\\n                if (a == -1 and b == -1) or (a != -1 and (a <= i or j < a)) or (b != -1 and (b <= i or j < b)):\\n                    continue\\n                if a != -1 and b != -1:\\n                    if b-a != lngth or a <= i or j < b:\\n                        sf = False\\n                        break\\n                    else:\\n                        if not fs[a] or not fs[b]:\\n                            sf = False\\n                            break\\n                        else:\\n                            fs[a] = False\\n                            fs[b] = False\\n                elif a == -1:\\n                    p = b - lngth\\n                    if p <= i or j < b:\\n                        sf = False\\n                        break\\n                    if not fs[p] or not fs[b]:\\n                        sf = False\\n                        break\\n                    else:\\n                        fs[p] = False\\n                        fs[b] = False\\n                else:\\n                    q = a + lngth\\n                    if a <= i or j < q:\\n                        sf = False\\n                        break\\n                    if not fs[a] or not fs[q]:\\n                        sf = False\\n                        break\\n                    else:\\n                   ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/928\\/B:\\nThere are times you recall a good old friend and everything you've come through together. Luckily there are social networks — they store all your message history making it easy to know what you argued over 10 years ago.\\n\\nMore formal, your message history is a sequence of messages ordered by time sent numbered from 1 to n where n is the total number of messages in the chat.\\n\\nEach message might contain a link to an earlier message which it is a reply to. When opening a message x or getting a link to it, the dialogue is shown in such a way that k previous messages, message x and k next messages are visible (with respect to message x). In case there are less than k messages somewhere, they are yet all shown.\\n\\nDigging deep into your message history, you always read all visible messages and then go by the link in the current message x (if there is one) and continue reading in the same manner.\\n\\nDetermine the number of messages you'll read if your start from message number t for all t from 1 to n. Calculate these numbers independently. If you start with message x, the initial configuration is x itself, k previous and k next messages. Messages read multiple times are considered as one.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and k (1 ≤ n ≤ 10^5, 0 ≤ k ≤ n) — the total amount of messages and the number of previous and next messages visible.\\n\\nThe second line features a sequence of integers a_1, a_2, ..., a_{n} (0 ≤ a_{i} < i), where a_{i} denotes the i-th message link destination or zero, if there's no link from i. All messages are listed in chronological order. It's guaranteed that the link from message x goes to message with number strictly less than x.\\n\\n\\n-----Output-----\\n\\nPrint n integers with i-th denoting the number of distinct messages you can read starting from message i and traversing the links while possible.\\n\\n\\n-----Examples-----\\nInput\\n6 0\\n0 1 1 2 3 2\\n\\nOutput\\n1 2 2 3 3 3 \\n\\nInput\\n10 1\\n0 1 0 3 4 5 2 3 7 0\\n\\nOutput\\n2 3 3 4 5 6 6 6 8 2 \\n\\nInput\\n2 2\\n0 1\\n\\nOutput\\n2 2 \\n\\n\\n\\n-----Note-----\\n\\nConsider i = 6...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import *\\nfrom random import *\\nfrom copy import *\\nimport os, sys\\n\\nn, k = list(map(int, input().split()))\\nA = list(map(int, input().split()))\\nres = [0] * (n + 1)\\n\\nfor i in range(1, n + 1):\\n  prev = A[i - 1]\\n  res[i] = res[prev]\\n  prev = prev - k if prev == 0 else prev\\n  res[i] += min(max(0, i - prev - k - 1), k) + max(0, min(k + 1, n - i + 1) - max(0, min(n - prev + 1, prev + k - i + 1)))\\nprint(' '.join(list(map(str, res[1 :]))))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou will be given a fruit which a farmer has harvested, your job is to see if you should buy or sell.\\n\\nYou will be given 3 pairs of fruit. Your task is to trade your harvested fruit back into your harvested fruit via the intermediate pair, you should return a string of 3 actions.\\n\\nif you have harvested apples, you would buy this fruit pair: apple_orange, if you have harvested oranges, you would sell that fruit pair.\\n\\n(In other words, to go from left to right (apples to oranges) you buy, and to go from right to left you sell (oranges to apple))\\n\\ne.g. \\napple_orange, orange_pear, apple_pear\\n1. if you have harvested apples, you would buy this fruit pair: apple_orange\\n2. Then you have oranges, so again you would buy this fruit pair: orange_pear\\n3. After you have pear, but now this time you would sell this fruit pair: apple_pear\\n4. Finally you are back with the apples\\n\\nSo your function would return a list: [“buy”,”buy”,”sell”]\\n\\nIf any invalid input is given, \\\"ERROR\\\" should be returned\",\"targets\":\"def buy_or_sell(pairs, want):\\n    r = []\\n    for buy, sell in pairs:\\n        if want not in [buy, sell]: return 'ERROR'\\n        r, want = (r + ['buy'], sell) if buy == want else (r + ['sell'], buy)\\n            \\n    return r\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nI assume most of you are familiar with the ancient legend of the rice (but I see wikipedia suggests [wheat](https:\\/\\/en.wikipedia.org\\/wiki\\/Wheat_and_chessboard_problem), for some reason) problem, but a quick recap for you: a young man asks as a compensation only `1` grain of rice for the first square, `2` grains for the second, `4` for the third, `8` for the fourth and so on, always doubling the previous.\\n\\nYour task is pretty straightforward (but not necessarily easy): given an amount of grains, you need to return up to which square of the chessboard one should count in order to get at least as many.\\n\\nAs usual, a few examples might be way better than thousands of words from me:\\n\\n```python\\nsquares_needed(0) == 0\\nsquares_needed(1) == 1\\nsquares_needed(2) == 2\\nsquares_needed(3) == 2\\nsquares_needed(4) == 3\\n```\\n\\nInput is always going to be valid\\/reasonable: ie: a non negative number; extra cookie for *not* using a loop to compute square-by-square (at least not directly) and instead trying a smarter approach [hint: some peculiar operator]; a trick converting the number might also work: impress me!\",\"targets\":\"def squares_needed(grains):\\n    g = 0\\n    count = 0\\n    for i in range(0,65):\\n        if g<grains:\\n            g = g+2**i\\n            count += 1\\n        else:\\n            return count\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLet {\\\\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.\\nFrom n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\\\\rm comb}(a_i,a_j) is maximized.\\nIf there are multiple pairs that maximize the value, any of them is accepted.\\n\\n-----Constraints-----\\n - 2 \\\\leq n \\\\leq 10^5\\n - 0 \\\\leq a_i \\\\leq 10^9\\n - a_1,a_2,...,a_n are pairwise distinct.\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nn\\na_1 a_2 ... a_n\\n\\n-----Output-----\\nPrint a_i and a_j that you selected, with a space in between.\\n\\n-----Sample Input-----\\n5\\n6 9 4 2 11\\n\\n-----Sample Output-----\\n11 6\\n\\n\\\\rm{comb}(a_i,a_j) for each possible selection is as follows:\\n - \\\\rm{comb}(4,2)=6 \\n - \\\\rm{comb}(6,2)=15 \\n - \\\\rm{comb}(6,4)=15 \\n - \\\\rm{comb}(9,2)=36 \\n - \\\\rm{comb}(9,4)=126 \\n - \\\\rm{comb}(9,6)=84 \\n - \\\\rm{comb}(11,2)=55 \\n - \\\\rm{comb}(11,4)=330 \\n - \\\\rm{comb}(11,6)=462 \\n - \\\\rm{comb}(11,9)=55\\nThus, we should print 11 and 6.\",\"targets\":\"from bisect import bisect_right\\nn=int(input())\\na=sorted(list(map(int,input().split())))\\nx=a[-1]\\nc=bisect_right(a,x\\/\\/2)\\nif x%2==0:\\n    if x\\/\\/2 in a:\\n        print(\\\"{} {}\\\".format(x,x\\/\\/2))\\n    else:\\n        if a[c]-x\\/\\/2>=x\\/\\/2-a[c-1]:\\n            print(\\\"{} {}\\\".format(x,a[c-1]))\\n        else:\\n            print(\\\"{} {}\\\".format(x,a[c]))\\n\\n        \\nelse:\\n    if x\\/\\/2 in a :\\n        print(\\\"{} {}\\\".format(x,x\\/\\/2))\\n    elif x\\/\\/2+1 in a:\\n        print(\\\"{} {}\\\".format(x,x\\/\\/2+1))\\n    else:\\n        if a[c]-(x\\/\\/2+1)>=x\\/\\/2-a[c-1]:\\n            print(\\\"{} {}\\\".format(x,a[c-1]))\\n        else:\\n            print(\\\"{} {}\\\".format(x,a[c]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nHongcow is ruler of the world. As ruler of the world, he wants to make it easier for people to travel by road within their own countries.\\n\\nThe world can be modeled as an undirected graph with n nodes and m edges. k of the nodes are home to the governments of the k countries that make up the world.\\n\\nThere is at most one edge connecting any two nodes and no edge connects a node to itself. Furthermore, for any two nodes corresponding to governments, there is no path between those two nodes. Any graph that satisfies all of these conditions is stable.\\n\\nHongcow wants to add as many edges as possible to the graph while keeping it stable. Determine the maximum number of edges Hongcow can add.\\n\\n\\n-----Input-----\\n\\nThe first line of input will contain three integers n, m and k (1 ≤ n ≤ 1 000, 0 ≤ m ≤ 100 000, 1 ≤ k ≤ n) — the number of vertices and edges in the graph, and the number of vertices that are homes of the government. \\n\\nThe next line of input will contain k integers c_1, c_2, ..., c_{k} (1 ≤ c_{i} ≤ n). These integers will be pairwise distinct and denote the nodes that are home to the governments in this world.\\n\\nThe following m lines of input will contain two integers u_{i} and v_{i} (1 ≤ u_{i}, v_{i} ≤ n). This denotes an undirected edge between nodes u_{i} and v_{i}.\\n\\nIt is guaranteed that the graph described by the input is stable.\\n\\n\\n-----Output-----\\n\\nOutput a single integer, the maximum number of edges Hongcow can add to the graph while keeping it stable.\\n\\n\\n-----Examples-----\\nInput\\n4 1 2\\n1 3\\n1 2\\n\\nOutput\\n2\\n\\nInput\\n3 3 1\\n2\\n1 2\\n1 3\\n2 3\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nFor the first sample test, the graph looks like this:  [Image]  Vertices 1 and 3 are special. The optimal solution is to connect vertex 4 to vertices 1 and 2. This adds a total of 2 edges. We cannot add any more edges, since vertices 1 and 3 cannot have any path between them.\\n\\nFor the second sample test, the graph looks like this:  $\\\\infty$  We cannot add any more edges to this graph. Note that we are not allowed to add self-loops, and the graph must...\",\"targets\":\"n,m,c=list(map(int,input().split()))\\nl=list(map(int,input().split()))\\n\\n\\n\\nqa=n\\nd=[[] for i in range(n+1)]\\nVisited=[False for i in range(n+1)]\\nf=0\\nL=[]\\nfor i in range(m) :\\n    a,b=list(map(int,input().split()))\\n    d[a].append(b)\\n    d[b].append(a)\\n    L.append([a,b])\\nma=0\\n\\nd1={}\\nfor x in l:\\n    q=[x]\\n    r=0\\n    t=0\\n    while q :\\n        v=q[0]\\n        r+=1\\n        Visited[v]=True\\n        t+=len(d[v])\\n        for y in d[v] :\\n            if Visited[y]==False :\\n                q.append(y)\\n                Visited[y]=True\\n        del q[0]\\n    qa-=r\\n    d1[r]=d1.get(r,[])+[t]\\n    \\n    \\n\\nfor x in L :\\n    if Visited[x[0]]==Visited[x[1]]==False :\\n        f+=1\\nrr=True\\ny=sorted(d1,reverse=True)\\nout=-f\\n\\nfor x in y :\\n    for e in d1[x] :\\n        if rr :\\n            u=qa+x\\n            out+=u*(u-1)\\/\\/2-e\\/\\/2\\n            rr=False\\n        else :\\n            out+=x*(x-1)\\/\\/2-e\\/\\/2\\nprint(out)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55d8aa568dec9fb9e200004a:\\nCreate a function ```sel_number()```, that will select numbers that fulfill the following constraints:\\n\\n1) The numbers should have 2 digits at least.\\n\\n2) They should have their respective digits in increasing order from left to right. \\nExamples: 789, 479, 12678, have these feature. But 617, 89927 are not of this type.\\nIn general, if ```d1, d2, d3....``` are the digits of a certain number ```i``` \\nExample:\\n```( i = d1d2d3d4d5) so, d1 < d2 < d3 < d4 < d5```\\n\\n3) They cannot have digits that occurs twice or more. Example: 8991 should be discarded.\\n\\n4) The difference between neighbouring pairs of digits cannot exceed certain value. \\nExample: If the difference between contiguous digits cannot excced 2, so 1345, 23568 and 234578 pass this test. Other numbers like 1456, 389, 157 don't belong to that group because in the first number(1456), the difference between second and first digit 4 - 1 > 2; in the next one(389), we have 8 - 3 > 2; and see by yourself why 157 should be discarded.\\nIn general, taking the example above of ```i = d1d2d3d4d5```:\\n```\\nd2 - d1 <= d;\\n\\nd3 - d2 <= d;\\n\\nd4 - d3 <= d;\\n\\nd5 - d4 <= d;\\n```\\nThe function should accept two arguments n and d; n is the upper limit of the range to work with(all the numbers should be less or equal than n), and d is maximum difference  between every pair of its contiguous digits. It's clear that 1 <= d <= 8.\\n\\nHere we have some cases:\\n```\\nsel_number(0,1) = 0 # n = 0, empty range\\nsel_number(3, 1) = 0 # n = 3, numbers should be higher or equal than 12\\nsel_number(13, 1) = 1 # only 12 fulfill the requirements\\nsel_number(20, 2) = 2 # 12 and 13 are the numbers\\nsel_number(30, 2) = 4 # 12, 13, 23 and 24 are the selected ones\\nsel_number(44, 2) = 6 # 12, 13, 23, 24, 34 and 35 are valid ones\\nsel_number(50, 3) = 12 # 12, 13, 14, 23, 24, 25, 34, 35, 36, 45, 46 and 47 are valid\\n```\\nCompare the last example with this one:\\n```\\nsel_number(47, 3) = 12 # 12, 13, 14, 23, 24, 25, 34, 35, 36, 45, 46 and 47 are valid \\n```\\n(because the instructions says the value of may be included if it...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"sel_number = lambda n, d:len([x for x in range(10,n+1) if sorted(list(set(list(str(x)))))==list(str(x)) and all((int(str(x)[i])-int(str(x)[i-1]))<=d for i in range(1,len(str(x))))])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPolycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for k burles. Assume that there is an unlimited number of such shovels in the shop.\\n\\nIn his pocket Polycarp has an unlimited number of \\\"10-burle coins\\\" and exactly one coin of r burles (1 ≤ r ≤ 9).\\n\\nWhat is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of r burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel.\\n\\n\\n-----Input-----\\n\\nThe single line of input contains two integers k and r (1 ≤ k ≤ 1000, 1 ≤ r ≤ 9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from \\\"10-burle coins\\\". \\n\\nRemember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels.\\n\\n\\n-----Output-----\\n\\nPrint the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. \\n\\n\\n-----Examples-----\\nInput\\n117 3\\n\\nOutput\\n9\\n\\nInput\\n237 7\\n\\nOutput\\n1\\n\\nInput\\n15 2\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.\\n\\nIn the second example it is enough for Polycarp to buy one shovel.\\n\\nIn the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change.\",\"targets\":\"n, k = list(map(int, input().split()))\\nfor i in range(1, 11):\\n    if ((n * i) % 10 == 0 or n * i % 10 == k):\\n        print(i)\\n        break\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/maximum-product-of-two-elements-in-an-array\\/:\\nGiven the array of integers nums, you will choose two different indices i and j of that array. Return the maximum value of (nums[i]-1)*(nums[j]-1).\\n \\nExample 1:\\nInput: nums = [3,4,5,2]\\nOutput: 12 \\nExplanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12. \\n\\nExample 2:\\nInput: nums = [1,5,4,5]\\nOutput: 16\\nExplanation: Choosing the indices i=1 and j=3 (indexed from 0), you will get the maximum value of (5-1)*(5-1) = 16.\\n\\nExample 3:\\nInput: nums = [3,7]\\nOutput: 12\\n\\n \\nConstraints:\\n\\n2 <= nums.length <= 500\\n1 <= nums[i] <= 10^3\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def maxProduct(self, nums: List[int]) -> int:\\n        max_product=0\\n        for i in range(len(nums)):\\n            for j in range(i+1,len(nums)):\\n                if (nums[i]-1)*(nums[j]-1) > max_product:\\n                    max_product = (nums[i]-1)*(nums[j]-1)\\n        return max_product\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThis is the hard version of this problem. The only difference is the constraint on $k$ — the number of gifts in the offer. In this version: $2 \\\\le k \\\\le n$.\\n\\nVasya came to the store to buy goods for his friends for the New Year. It turned out that he was very lucky — today the offer \\\"$k$ of goods for the price of one\\\" is held in store.\\n\\nUsing this offer, Vasya can buy exactly $k$ of any goods, paying only for the most expensive of them. Vasya decided to take this opportunity and buy as many goods as possible for his friends with the money he has.\\n\\nMore formally, for each good, its price is determined by $a_i$ — the number of coins it costs. Initially, Vasya has $p$ coins. He wants to buy the maximum number of goods. Vasya can perform one of the following operations as many times as necessary:\\n\\n  Vasya can buy one good with the index $i$ if he currently has enough coins (i.e $p \\\\ge a_i$). After buying this good, the number of Vasya's coins will decrease by $a_i$, (i.e it becomes $p := p - a_i$).  Vasya can buy a good with the index $i$, and also choose exactly $k-1$ goods, the price of which does not exceed $a_i$, if he currently has enough coins (i.e $p \\\\ge a_i$). Thus, he buys all these $k$ goods, and his number of coins decreases by $a_i$ (i.e it becomes $p := p - a_i$). \\n\\nPlease note that each good can be bought no more than once.\\n\\nFor example, if the store now has $n=5$ goods worth $a_1=2, a_2=4, a_3=3, a_4=5, a_5=7$, respectively, $k=2$, and Vasya has $6$ coins, then he can buy $3$ goods. A good with the index $1$ will be bought by Vasya without using the offer and he will pay $2$ coins. Goods with the indices $2$ and $3$ Vasya will buy using the offer and he will pay $4$ coins. It can be proved that Vasya can not buy more goods with six coins.\\n\\nHelp Vasya to find out the maximum number of goods he can buy.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases in the test.\\n\\nThe next lines contain a description of $t$ test cases. \\n\\nThe first line of...\",\"targets\":\"t = int(input())\\nfor ii in range(t):\\n    n, p, k = list(map(int, input().split()))\\n    a = list(map(int, input().split()))\\n    a = sorted(a)\\n    a = [None] + a\\n    s = [0] * (n+1)\\n    last_ind = 0\\n    for i in range(1,n+1):\\n        if i < k:\\n            s[i] = a[i] + s[i-1]\\n        else:\\n            s[i] = a[i] + s[i-k]\\n        # print('---',s[i], p)\\n        if s[i] <= p:\\n            last_ind = i\\n\\n    print(last_ind)\\n\\n'''\\n8\\n5 6 2\\n2 4 3 5 7\\n5 11 2\\n2 4 3 5 7\\n3 2 3\\n4 2 6\\n5 2 3\\n10 1 3 9 2\\n2 10000 2\\n10000 10000\\n2 9999 2\\n10000 10000\\n4 6 4\\n3 2 3 2\\n5 5 3\\n1 2 2 1 2\\n\\n'''\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a941f4e1a60f6e8a70025fe:\\nYou are given an array with several `\\\"even\\\"` words, one `\\\"odd\\\"` word, and some numbers mixed in.\\n\\nDetermine if any of the numbers in the array is the index of the `\\\"odd\\\"` word. If so, return `true`, otherwise `false`.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def odd_ball(arr):\\n    return int(arr.index('odd')) in arr\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/number-of-ways-to-wear-different-hats-to-each-other\\/:\\nThere are n people and 40 types of hats labeled from 1 to 40.\\nGiven a list of list of integers hats, where hats[i] is a list of all hats preferred by the i-th person.\\nReturn the number of ways that the n people wear different hats to each other.\\nSince the answer may be too large, return it modulo 10^9 + 7.\\n \\nExample 1:\\nInput: hats = [[3,4],[4,5],[5]]\\nOutput: 1\\nExplanation: There is only one way to choose hats given the conditions. \\nFirst person choose hat 3, Second person choose hat 4 and last one hat 5.\\nExample 2:\\nInput: hats = [[3,5,1],[3,5]]\\nOutput: 4\\nExplanation: There are 4 ways to choose hats\\n(3,5), (5,3), (1,3) and (1,5)\\n\\nExample 3:\\nInput: hats = [[1,2,3,4],[1,2,3,4],[1,2,3,4],[1,2,3,4]]\\nOutput: 24\\nExplanation: Each person can choose hats labeled from 1 to 4.\\nNumber of Permutations of (1,2,3,4) = 24.\\n\\nExample 4:\\nInput: hats = [[1,2,3],[2,3,5,6],[1,3,7,9],[1,8,9],[2,5,7]]\\nOutput: 111\\n\\n \\nConstraints:\\n\\nn == hats.length\\n1 <= n <= 10\\n1 <= hats[i].length <= 40\\n1 <= hats[i][j] <= 40\\nhats[i] contains a list of unique integers.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def numberWays(self, hats: List[List[int]]) -> int:\\n        self.visited = 0\\n        hm = {}\\n        for n,i in enumerate(hats):\\n            for j in i:\\n                if j not in hm:\\n                    hm[j] = [n]\\n                else:\\n                    hm[j].append(n)\\n        keys = list(hm.keys())\\n        self.saved = {}\\n        def helper(index):\\n            if (index, self.visited) in self.saved:\\n                return self.saved[(index, self.visited)]\\n            \\n            if self.visited == ((1 << len(hats)) - 1):\\n                return 1\\n            if index == len(keys):\\n                return 0\\n            count = 0\\n\\n            for i in hm[keys[index]]:\\n                if not self.visited & (1 << i):\\n                    self.visited |= 1 << i\\n                    count += helper(index+1)\\n                    self.visited ^= 1 << i\\n            self.saved[(index, self.visited)] = count+ helper(index+1)\\n            return self.saved[(index, self.visited)]\\n        return helper(0) % (10 **9 + 7)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/maximum-profit-of-operating-a-centennial-wheel\\/:\\nYou are the operator of a Centennial Wheel that has four gondolas, and each gondola has room for up to four people. You have the ability to rotate the gondolas counterclockwise, which costs you runningCost dollars.\\nYou are given an array customers of length n where customers[i] is the number of new customers arriving just before the ith rotation (0-indexed). This means you must rotate the wheel i times before the customers[i] customers arrive. You cannot make customers wait if there is room in the gondola. Each customer pays boardingCost dollars when they board on the gondola closest to the ground and will exit once that gondola reaches the ground again.\\nYou can stop the wheel at any time, including before serving all customers. If you decide to stop serving customers, all subsequent rotations are free in order to get all the customers down safely. Note that if there are currently more than four customers waiting at the wheel, only four will board the gondola, and the rest will wait for the next rotation.\\nReturn the minimum number of rotations you need to perform to maximize your profit. If there is no scenario where the profit is positive, return -1.\\n \\nExample 1:\\n\\nInput: customers = [8,3], boardingCost = 5, runningCost = 6\\nOutput: 3\\nExplanation: The numbers written on the gondolas are the number of people currently there.\\n1. 8 customers arrive, 4 board and 4 wait for the next gondola, the wheel rotates. Current profit is 4 * $5 - 1 * $6 = $14.\\n2. 3 customers arrive, the 4 waiting board the wheel and the other 3 wait, the wheel rotates. Current profit is 8 * $5 - 2 * $6 = $28.\\n3. The final 3 customers board the gondola, the wheel rotates. Current profit is 11 * $5 - 3 * $6 = $37.\\nThe highest profit was $37 after rotating the wheel 3 times.\\nExample 2:\\nInput: customers = [10,9,6], boardingCost = 6, runningCost = 4\\nOutput: 7\\nExplanation:\\n1. 10 customers arrive, 4 board and 6 wait for the next gondola, the wheel rotates. Current profit is 4 * $6 - 1 * $4 = $20.\\n2. 9 customers arrive, 4 board and 11 wait (2...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def minOperationsMaxProfit(self, customers: List[int], boardingCost: int, runningCost: int) -> int:\\n        rotations = 0\\n        wheel = [0, 0, 0, 0]\\n        profits = []\\n        cost = 0\\n        waiting = 0\\n        profit = 0\\n        maxProfit = 0\\n        \\n        \\n        for i in range(len(customers)):\\n            waiting += customers[i]\\n            \\n            \\n            '''if rotations < i:\\n                for j in range(rotations - i):\\n                    profit -= runningCost\\n                    wheel[2], wheel[3] = wheel[1], wheel[2]\\n                    wheel[1] = 0'''\\n            \\n                \\n            if waiting > 4:\\n                profit += 4*boardingCost\\n            else:\\n                profit = boardingCost * waiting\\n            profit -= runningCost\\n            rotations += 1\\n            wheel[2], wheel[3] = wheel[1], wheel[2]\\n            wheel[1] = min(waiting, 4)\\n            waiting -= min(waiting, 4)\\n            profits.append((profit, rotations))\\n            \\n        while waiting > 0:\\n            profit += min(4, waiting) * boardingCost\\n            waiting -= min(4, waiting)\\n            profit -= runningCost\\n            rotations += 1\\n            profits.append((profit, rotations))\\n            \\n        #print(profits)\\n        profits = sorted(profits, key = lambda x: (x[0], -x[1]), reverse = True)\\n        if profits[0][0] > 0:\\n            return profits[0][1]\\n        else:\\n            return -1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou like playing chess tournaments online.\\n\\nIn your last tournament you played $n$ games. For the sake of this problem, each chess game is either won or lost (no draws). When you lose a game you get $0$ points. When you win you get $1$ or $2$ points: if you have won also the previous game you get $2$ points, otherwise you get $1$ point. If you win the very first game of the tournament you get $1$ point (since there is not a \\\"previous game\\\").\\n\\nThe outcomes of the $n$ games are represented by a string $s$ of length $n$: the $i$-th character of $s$ is W if you have won the $i$-th game, while it is L if you have lost the $i$-th game.\\n\\nAfter the tournament, you notice a bug on the website that allows you to change the outcome of at most $k$ of your games (meaning that at most $k$ times you can change some symbol L to W, or W to L). Since your only goal is to improve your chess rating, you decide to cheat and use the bug.\\n\\nCompute the maximum score you can get by cheating in the optimal way.\\n\\n\\n-----Input-----\\n\\nEach test contains multiple test cases. The first line contains an integer $t$ ($1\\\\le t \\\\le 20,000$) — the number of test cases. The description of the test cases follows.\\n\\nThe first line of each testcase contains two integers $n, k$ ($1\\\\le n\\\\le 100,000$, $0\\\\le k\\\\le n$) – the number of games played and the number of outcomes that you can change.\\n\\nThe second line contains a string $s$ of length $n$ containing only the characters W and L. If you have won the $i$-th game then $s_i=\\\\,$W, if you have lost the $i$-th game then $s_i=\\\\,$L.\\n\\nIt is guaranteed that the sum of $n$ over all testcases does not exceed $200,000$.\\n\\n\\n-----Output-----\\n\\nFor each testcase, print a single integer – the maximum score you can get by cheating in the optimal way.\\n\\n\\n-----Example-----\\nInput\\n8\\n5 2\\nWLWLL\\n6 5\\nLLLWWL\\n7 1\\nLWLWLWL\\n15 5\\nWWWLLLWWWLLLWWW\\n40 7\\nLLWLWLWWWLWLLWLWWWLWLLWLLWLLLLWLLWWWLWWL\\n1 0\\nL\\n1 1\\nL\\n6 1\\nWLLWLW\\n\\nOutput\\n7\\n11\\n6\\n26\\n46\\n0\\n1\\n6\\n\\n\\n\\n-----Note-----\\n\\nExplanation of the first testcase. Before changing any outcome, the score is...\",\"targets\":\"for _ in range(int(input())):\\n    n, k = list(map(int, input().split()))\\n    s = input()\\n    k = min(k, s.count(\\\"L\\\"))\\n    arr = []\\n    cur = 0\\n    sc = 0\\n    se = False\\n    if s[0] == \\\"W\\\":\\n        sc += 1\\n    for e in s:\\n        if e == \\\"L\\\":\\n            cur += 1\\n        else:\\n            if cur > 0 and se:\\n                arr.append(cur)\\n            se = True\\n            cur = 0\\n    for i in range(1, n):\\n        if s[i] == \\\"W\\\":\\n            if s[i-1] == \\\"W\\\":\\n                sc += 2\\n            else:\\n                sc += 1 \\n    arr.sort() \\n    arr.reverse()\\n    #print(arr, sc)\\n    while len(arr) > 0 and arr[-1] <= k:\\n        k -= arr[-1]\\n        sc += arr[-1]*2+1\\n        arr.pop()\\n    #print(k)\\n    sc += k*2\\n    if k > 0 and s.count(\\\"W\\\") == 0:\\n        sc -= 1\\n    print(sc)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/760\\/B:\\nn hobbits are planning to spend the night at Frodo's house. Frodo has n beds standing in a row and m pillows (n ≤ m). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as many pillows as possible. Of course, it's not always possible to share pillows equally, but any hobbit gets hurt if he has at least two pillows less than some of his neighbors have. \\n\\nFrodo will sleep on the k-th bed in the row. What is the maximum number of pillows he can have so that every hobbit has at least one pillow, every pillow is given to some hobbit and no one is hurt?\\n\\n\\n-----Input-----\\n\\nThe only line contain three integers n, m and k (1 ≤ n ≤ m ≤ 10^9, 1 ≤ k ≤ n) — the number of hobbits, the number of pillows and the number of Frodo's bed.\\n\\n\\n-----Output-----\\n\\nPrint single integer — the maximum number of pillows Frodo can have so that no one is hurt.\\n\\n\\n-----Examples-----\\nInput\\n4 6 2\\n\\nOutput\\n2\\n\\nInput\\n3 10 3\\n\\nOutput\\n4\\n\\nInput\\n3 6 1\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Frodo can have at most two pillows. In this case, he can give two pillows to the hobbit on the first bed, and one pillow to each of the hobbits on the third and the fourth beds.\\n\\nIn the second example Frodo can take at most four pillows, giving three pillows to each of the others.\\n\\nIn the third example Frodo can take three pillows, giving two pillows to the hobbit in the middle and one pillow to the hobbit on the third bed.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m, k = map(int, input().split())\\n\\ndone = 0\\n\\nfor A in range(m \\/\\/ n,m+1):\\n\\n\\tup = A\\n\\n\\tif (k-1) >= (A-1):\\n\\t\\tup = up + A * (A-1) \\/ 2\\n\\t\\tup = up + k - A\\n\\telse:\\n\\t\\ts = A - k + 1\\n\\t\\tup = up + (s + (A - 1)) * (A - s) \\/ 2\\n\\n\\n\\tkk = n - k \\n\\n\\tif (kk) >= (A-1):\\n\\t\\tup = up + A * (A-1) \\/ 2\\n\\t\\tup = up + kk - (A-1)\\n\\telse:\\n\\t\\ts = A - kk\\n\\t\\tup = up + (s + (A - 1)) * (A - s) \\/ 2\\n\\n\\tif up > m:\\n\\t\\tdone = 1\\n\\t\\tprint(A-1)\\n\\t\\tbreak\\n\\n\\nif done == 0:\\n\\n\\tprint(m)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/671\\/A:\\nIt was recycling day in Kekoland. To celebrate it Adil and Bera went to Central Perk where they can take bottles from the ground and put them into a recycling bin.\\n\\nWe can think Central Perk as coordinate plane. There are n bottles on the ground, the i-th bottle is located at position (x_{i}, y_{i}). Both Adil and Bera can carry only one bottle at once each. \\n\\nFor both Adil and Bera the process looks as follows:   Choose to stop or to continue to collect bottles.  If the choice was to continue then choose some bottle and walk towards it.  Pick this bottle and walk to the recycling bin.  Go to step 1. \\n\\nAdil and Bera may move independently. They are allowed to pick bottles simultaneously, all bottles may be picked by any of the two, it's allowed that one of them stays still while the other one continues to pick bottles.\\n\\nThey want to organize the process such that the total distance they walk (the sum of distance walked by Adil and distance walked by Bera) is minimum possible. Of course, at the end all bottles should lie in the recycling bin.\\n\\n\\n-----Input-----\\n\\nFirst line of the input contains six integers a_{x}, a_{y}, b_{x}, b_{y}, t_{x} and t_{y} (0 ≤ a_{x}, a_{y}, b_{x}, b_{y}, t_{x}, t_{y} ≤ 10^9) — initial positions of Adil, Bera and recycling bin respectively.\\n\\nThe second line contains a single integer n (1 ≤ n ≤ 100 000) — the number of bottles on the ground.\\n\\nThen follow n lines, each of them contains two integers x_{i} and y_{i} (0 ≤ x_{i}, y_{i} ≤ 10^9) — position of the i-th bottle.\\n\\nIt's guaranteed that positions of Adil, Bera, recycling bin and all bottles are distinct.\\n\\n\\n-----Output-----\\n\\nPrint one real number — the minimum possible total distance Adil and Bera need to walk in order to put all bottles into recycling bin. Your answer will be considered correct if its absolute or relative error does not exceed 10^{ - 6}.\\n\\nNamely: let's assume that your answer is a, and the answer of the jury is b. The checker program will consider your answer correct if $\\\\frac{|a - b|}{\\\\operatorname{max}(1, b)}...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import sqrt\\n\\nax, ay, bx, by, tx, ty = map(int, input().split())\\n\\nn = int(input())\\n\\nans = 0\\n\\np1, p2, beg, end = [0]*n, [0]*n, [0]*n, [0]*n\\n\\ndef sqr(x):\\n    return x*x\\n\\ndef pref(x):\\n    return beg[x] if x >= 0 else 0\\n\\ndef suff(x):\\n    return end[x] if x < n else 0\\n\\ndef ex(x):\\n    return max(pref(x-1), suff(x+1))\\n\\nfor i in range(n):\\n    x, y = map(int, input().split())\\n    d = sqrt(sqr(x-tx) + sqr(y-ty))\\n    d1 = sqrt(sqr(x-ax) + sqr(y-ay))\\n    d2 = sqrt(sqr(x-bx) + sqr(y-by))\\n    ans += d+d\\n    p1[i], p2[i] = d-d1, d-d2\\n\\nbeg[0] = p1[0]\\nfor i in range(1, n):\\n    beg[i] = max(beg[i-1], p1[i])\\n\\nend[n-1] = p1[n-1]\\nfor i in range(n-2, -1, -1):\\n    end[i] = max(end[i+1], p1[i])\\n\\nres = 1e220\\n\\nfor i in range(0, n):\\n    res = min(res, min(ans-p2[i]-ex(i), ans-max(p1[i], p2[i])))\\n\\nprint(res)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/813\\/A:\\nPasha is participating in a contest on one well-known website. This time he wants to win the contest and will do anything to get to the first place!\\n\\nThis contest consists of n problems, and Pasha solves ith problem in a_{i} time units (his solutions are always correct). At any moment of time he can be thinking about a solution to only one of the problems (that is, he cannot be solving two problems at the same time). The time Pasha spends to send his solutions is negligible. Pasha can send any number of solutions at the same moment.\\n\\nUnfortunately, there are too many participants, and the website is not always working. Pasha received the information that the website will be working only during m time periods, jth period is represented by its starting moment l_{j} and ending moment r_{j}. Of course, Pasha can send his solution only when the website is working. In other words, Pasha can send his solution at some moment T iff there exists a period x such that l_{x} ≤ T ≤ r_{x}.\\n\\nPasha wants to know his best possible result. We need to tell him the minimal moment of time by which he is able to have solutions to all problems submitted, if he acts optimally, or say that it's impossible no matter how Pasha solves the problems.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer n (1 ≤ n ≤ 1000) — the number of problems. The second line contains n integers a_{i} (1 ≤ a_{i} ≤ 10^5) — the time Pasha needs to solve ith problem.\\n\\nThe third line contains one integer m (0 ≤ m ≤ 1000) — the number of periods of time when the website is working. Next m lines represent these periods. jth line contains two numbers l_{j} and r_{j} (1 ≤ l_{j} < r_{j} ≤ 10^5) — the starting and the ending moment of jth period.\\n\\nIt is guaranteed that the periods are not intersecting and are given in chronological order, so for every j > 1 the condition l_{j} > r_{j} - 1 is met.\\n\\n\\n-----Output-----\\n\\nIf Pasha can solve and submit all the problems before the end of the contest, print the minimal moment of time by which he can have all the solutions...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\ns = 0\\nfor i in map(int, input().split()):\\n\\ts += i\\nm = int(input())\\nsol = -1\\nfor i in range(m):\\n\\td = list(map(int, input().split()))\\n\\tif sol == -1:\\n\\t\\tif s >= d[0] and s <= d[1]:\\n\\t\\t\\tsol = s\\n\\t\\telif s <= d[0]:\\n\\t\\t\\tsol = d[0]\\n\\nprint(sol)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn number theory, Euler's totient is an arithmetic function, introduced in 1763 by Euler, that counts the positive integers less than or equal to `n` that are relatively prime to `n`. Thus, if `n` is a positive integer, then `φ(n)`, notation introduced by Gauss in 1801, is the number of positive integers `k ≤ n` for which `gcd(n, k) = 1`.  \\nThe totient function is important in number theory, mainly because it gives the order of the multiplicative group of integers modulo `n`. The totient function also plays a key role in the definition of the RSA encryption system.\\n\\nFor example `let n = 9`.  \\nThen `gcd(9, 3) = gcd(9, 6) = 3` and `gcd(9, 9) = 9`.  \\nThe other six numbers in the range `1 ≤ k ≤ 9` i.e. `1, 2, 4, 5, 7, 8` are relatively prime to `9`.  \\nTherefore, `φ(9) = 6`.  \\nAs another example, `φ(1) = 1` since `gcd(1, 1) = 1`.\\n\\nThere are generally two approaches to this function:\\n\\n* Iteratively counting the numbers `k ≤ n` such that `gcd(n,k) = 1`.\\n\\n* Using the Euler product formula.  \\n  This is an explicit formula for calculating `φ(n)` depending on the prime divisor of `n`:  \\n  `φ(n) = n * Product (1 - 1\\/p)` where the product is taken over the primes `p ≤ n` that divide `n`.  \\n  For example: `φ(36) = 36 * (1 - 1\\/2) * (1 - 1\\/3) = 36 * 1\\/2 * 2\\/3 = 12`.  \\n  This second method seems more complex and not likely to be faster, but in practice we will often look for `φ(n)` with `n` prime. It correctly gives `φ(n) = n - 1` if `n` is prime. \\n\\nYou have to code the Euler totient function, that takes an integer `1 ≤ n` as input and returns `φ(n)`.\\n\\n```if:javascript\\nYou do have to check if `n` is a number, is an integer and that `1 ≤ n`; if that is not the case, the function should return `0`.\\n```\\n\\n```if:python\\nYou do have to check if `n` is a number, is an integer and that `1 ≤ n`; if that is not the case, the function should return `0`.\\n```\\n\\n```if:racket\\n`n` is always a positive integer.\\n```\\n\\nInput range: `1 ≤ n ≤ 1e10`\",\"targets\":\"def totient(n):\\n    if not isinstance(n,int) or n<1: return 0\\n    \\n    phi = n >= 1 and n\\n    for p in range(2, int(n ** .5) + 1):\\n        if not n % p:\\n            phi -= phi \\/\\/ p\\n            while not n % p:\\n                n \\/\\/= p\\n    if n > 1: phi -= phi \\/\\/ n\\n    return phi\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTanya wants to go on a journey across the cities of Berland. There are $n$ cities situated along the main railroad line of Berland, and these cities are numbered from $1$ to $n$. \\n\\nTanya plans her journey as follows. First of all, she will choose some city $c_1$ to start her journey. She will visit it, and after that go to some other city $c_2 > c_1$, then to some other city $c_3 > c_2$, and so on, until she chooses to end her journey in some city $c_k > c_{k - 1}$. So, the sequence of visited cities $[c_1, c_2, \\\\dots, c_k]$ should be strictly increasing.\\n\\nThere are some additional constraints on the sequence of cities Tanya visits. Each city $i$ has a beauty value $b_i$ associated with it. If there is only one city in Tanya's journey, these beauty values imply no additional constraints. But if there are multiple cities in the sequence, then for any pair of adjacent cities $c_i$ and $c_{i + 1}$, the condition $c_{i + 1} - c_i = b_{c_{i + 1}} - b_{c_i}$ must hold.\\n\\nFor example, if $n = 8$ and $b = [3, 4, 4, 6, 6, 7, 8, 9]$, there are several three possible ways to plan a journey:  $c = [1, 2, 4]$;  $c = [3, 5, 6, 8]$;  $c = [7]$ (a journey consisting of one city is also valid). \\n\\nThere are some additional ways to plan a journey that are not listed above.\\n\\nTanya wants her journey to be as beautiful as possible. The beauty value of the whole journey is the sum of beauty values over all visited cities. Can you help her to choose the optimal plan, that is, to maximize the beauty value of the journey?\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of cities in Berland.\\n\\nThe second line contains $n$ integers $b_1$, $b_2$, ..., $b_n$ ($1 \\\\le b_i \\\\le 4 \\\\cdot 10^5$), where $b_i$ is the beauty value of the $i$-th city.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the maximum beauty of a journey Tanya can choose.\\n\\n\\n-----Examples-----\\nInput\\n6\\n10 7 1 9 10 15\\n\\nOutput\\n26\\n\\nInput\\n1\\n400000\\n\\nOutput\\n400000\\n\\nInput\\n7\\n8 9 26 11 12 29 14\\n\\nOutput\\n55\\n\\n\\n\\n-----Note-----\\n\\nThe optimal...\",\"targets\":\"n = int(input())\\na = list(map(int, input().split()))\\nd = dict()\\nfor i in range(n):\\n    d[a[i] - i] = 0\\nmaxi = 0\\nfor i in range(n):\\n    d[a[i] - i] += a[i]\\n    if d[a[i] - i] > maxi:\\n        maxi = d[a[i] - i]\\nprint(maxi)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1401\\/F:\\nYou are given an array $a$ of length $2^n$. You should process $q$ queries on it. Each query has one of the following $4$ types:   $Replace(x, k)$ — change $a_x$ to $k$;  $Reverse(k)$ — reverse each subarray $[(i-1) \\\\cdot 2^k+1, i \\\\cdot 2^k]$ for all $i$ ($i \\\\ge 1$);  $Swap(k)$ — swap subarrays $[(2i-2) \\\\cdot 2^k+1, (2i-1) \\\\cdot 2^k]$ and $[(2i-1) \\\\cdot 2^k+1, 2i \\\\cdot 2^k]$ for all $i$ ($i \\\\ge 1$);  $Sum(l, r)$ — print the sum of the elements of subarray $[l, r]$. \\n\\nWrite a program that can quickly process given queries.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$, $q$ ($0 \\\\le n \\\\le 18$; $1 \\\\le q \\\\le 10^5$) — the length of array $a$ and the number of queries.\\n\\nThe second line contains $2^n$ integers $a_1, a_2, \\\\ldots, a_{2^n}$ ($0 \\\\le a_i \\\\le 10^9$).\\n\\nNext $q$ lines contains queries — one per line. Each query has one of $4$ types:   \\\"$1$ $x$ $k$\\\" ($1 \\\\le x \\\\le 2^n$; $0 \\\\le k \\\\le 10^9$) — $Replace(x, k)$;  \\\"$2$ $k$\\\" ($0 \\\\le k \\\\le n$) — $Reverse(k)$;  \\\"$3$ $k$\\\" ($0 \\\\le k < n$) — $Swap(k)$;  \\\"$4$ $l$ $r$\\\" ($1 \\\\le l \\\\le r \\\\le 2^n$) — $Sum(l, r)$. \\n\\nIt is guaranteed that there is at least one $Sum$ query.\\n\\n\\n-----Output-----\\n\\nPrint the answer for each $Sum$ query.\\n\\n\\n-----Examples-----\\nInput\\n2 3\\n7 4 9 9\\n1 2 8\\n3 1\\n4 2 4\\n\\nOutput\\n24\\n\\nInput\\n3 8\\n7 0 8 8 7 1 5 2\\n4 3 7\\n2 1\\n3 2\\n4 1 6\\n2 3\\n1 5 16\\n4 8 8\\n3 0\\n\\nOutput\\n29\\n22\\n1\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, initially, the array $a$ is equal to $\\\\{7,4,9,9\\\\}$.\\n\\nAfter processing the first query. the array $a$ becomes $\\\\{7,8,9,9\\\\}$.\\n\\nAfter processing the second query, the array $a_i$ becomes $\\\\{9,9,7,8\\\\}$\\n\\nTherefore, the answer to the third query is $9+7+8=24$.\\n\\nIn the second sample, initially, the array $a$ is equal to $\\\\{7,0,8,8,7,1,5,2\\\\}$. What happens next is:   $Sum(3, 7)$ $\\\\to$ $8 + 8 + 7 + 1 + 5 = 29$;  $Reverse(1)$ $\\\\to$ $\\\\{0,7,8,8,1,7,2,5\\\\}$;  $Swap(2)$ $\\\\to$ $\\\\{1,7,2,5,0,7,8,8\\\\}$;  $Sum(1, 6)$ $\\\\to$ $1 + 7 + 2 + 5 + 0 + 7 = 22$;  $Reverse(3)$ $\\\\to$ $\\\\{8,8,7,0,5,2,7,1\\\\}$;  $Replace(5, 16)$ $\\\\to$ $\\\\{8,8,7,0,16,2,7,1\\\\}$;  $Sum(8, 8)$ $\\\\to$ $1$; ...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class BIT():\\n    def __init__(self,n):\\n        self.BIT=[0]*(n+1)\\n        self.num=n\\n\\n    def query(self,idx):\\n        res_sum = 0\\n        while idx > 0:\\n            res_sum += self.BIT[idx]\\n            idx -= idx&(-idx)\\n        return res_sum\\n\\n    #Ai += x O(logN)\\n    def update(self,idx,x):\\n        while idx <= self.num:\\n            self.BIT[idx] += x\\n            idx += idx&(-idx)\\n        return\\n\\nn,q=map(int,input().split())\\na=list(map(int,input().split()))\\nbit=BIT(2**n)\\nfor i in range(2**n):\\n    bit.update(i+1,a[i])\\nb=0\\n\\ndef Sum(r,xor):\\n    id=xor\\n    res=0\\n    if r==-1:\\n        return res\\n    for i in range(n,-1,-1):\\n        if r>>i &1:\\n            L=(id>>i)<<i\\n            R=L+(1<<i)-1\\n            res+=bit.query(R+1)-bit.query(L)\\n            id^=(1<<i)\\n    return res\\n\\n\\nfor _ in range(q):\\n    query=tuple(map(int,input().split()))\\n    if query[0]==1:\\n        g,x,k=query\\n        x-=1\\n        x^=b\\n        bit.update(x+1,k-a[x])\\n        a[x]=k\\n    elif query[0]==2:\\n        k=query[1]\\n        b^=2**k-1\\n    elif query[0]==3:\\n        k=query[1]\\n        if k!=n:\\n            b^=2**k\\n    else:\\n        gl,l,r=query\\n        l-=1\\n        test=Sum(r,b)-Sum(l,b)\\n        print(test)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/713\\/C:\\nSonya was unable to think of a story for this problem, so here comes the formal description.\\n\\nYou are given the array containing n positive integers. At one turn you can pick any element and increase or decrease it by 1. The goal is the make the array strictly increasing by making the minimum possible number of operations. You are allowed to change elements in any way, they can become negative or equal to 0.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a single integer n (1 ≤ n ≤ 3000) — the length of the array.\\n\\nNext line contains n integer a_{i} (1 ≤ a_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nPrint the minimum number of operation required to make the array strictly increasing.\\n\\n\\n-----Examples-----\\nInput\\n7\\n2 1 5 11 5 9 11\\n\\nOutput\\n9\\n\\nInput\\n5\\n5 4 3 2 1\\n\\nOutput\\n12\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, the array is going to look as follows:\\n\\n2 3 5 6 7 9 11\\n\\n|2 - 2| + |1 - 3| + |5 - 5| + |11 - 6| + |5 - 7| + |9 - 9| + |11 - 11| = 9\\n\\nAnd for the second sample:\\n\\n1 2 3 4 5\\n\\n|5 - 1| + |4 - 2| + |3 - 3| + |2 - 4| + |1 - 5| = 12\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from heapq import *\\nclass Maxheap:\\n    def __init__(_): _.h = []\\n    def add(_, v): heappush(_.h, -v)\\n    def top(_): return -_.h[0]\\n    def pop(_): return -heappop(_.h)\\n\\nclass Graph:\\n    def __init__(_):\\n        _.change = Maxheap() # increment slope at ...\\n        _.change.add(-10**18)\\n        _.a = _.y = 0 # last line has slope a, starts from y\\n        _.dx = 0      # the whole graph is shifted right by ...\\n    def __repr__(_): return f\\\"<{[x+_.dx for x in _.change]}; {_.a} {_.y}>\\\"\\n    \\n    def shiftx(_, v): _.dx+= v\\n    def shifty(_, v): _.y+= v\\n    def addleft(_, v):\\n        if _.change.top() < v-_.dx:\\n            dx = v-_.dx - _.change.top()\\n            _.y+= _.a*dx\\n        _.change.add(v-_.dx)\\n    def addright(_, v):\\n        if _.change.top() < v-_.dx:\\n            dx = v-_.dx - _.change.top()\\n            _.y+= _.a*dx; _.a+= 1\\n            _.change.add(v-_.dx)\\n            return\\n        _.change.add(v-_.dx)\\n        _.a+= 1; _.y+= _.change.top()-(v-_.dx)\\n    def cutright(_):\\n        dx = _.change.pop()-_.change.top()\\n        _.a-= 1; _.y-= _.a*dx\\n \\nn = int(input())\\nG = Graph()\\nfor x in map(int,input().split()):\\n    G.shiftx(1)\\n    G.addleft(x)\\n    G.addright(x)\\n    while G.a > 0: G.cutright()\\nprint(G.y)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTo protect people from evil, \\na long and tall wall was constructed a few years ago. \\nBut just a wall is not safe, there should also be soldiers on it, \\nalways keeping vigil. \\nThe wall is very long and connects the left and the right towers. \\nThere are exactly N spots (numbered 1 to N) on the wall for soldiers. \\nThe Kth spot is K miles far from the left tower and (N+1-K) miles from the right tower.\\n\\nGiven a permutation of spots P of {1, 2, ..., N}, soldiers occupy the N spots in that order. \\nThe P[i]th spot is occupied before the P[i+1]th spot. \\nWhen a soldier occupies a spot, he is connected to his nearest soldier already placed to his left. \\nIf there is no soldier to his left, he is connected to the left tower. The same is the case with right side. \\nA connection between two spots requires a wire of length equal to the distance between the two.\\n\\nThe realm has already purchased a wire of M miles long from Nokia, \\npossibly the wire will be cut into smaller length wires. \\nAs we can observe, the total length of the used wire depends on the permutation of the spots P. Help the realm in minimizing the length of the unused wire. If there is not enough wire, output -1.\\n\\n-----Input-----\\nFirst line contains an integer T (number of test cases, 1 ≤ T ≤ 10 ). Each of the next T lines contains two integers N M, as explained in the problem statement (1 ≤ N ≤ 30 , 1 ≤ M ≤ 1000).\\n\\n-----Output-----\\nFor each test case, output the minimum length of the unused wire, or -1 if the the wire is not sufficient.\\n\\n-----Example-----\\nInput:\\n4\\n3 8\\n3 9\\n2 4\\n5 25\\n\\nOutput:\\n0\\n0\\n-1\\n5\\n\\nExplanation:\\n\\nIn the 1st case, for example, the permutation P = {2, 1, 3} will use the exact 8 miles wires in total.\\n\\nIn the 2nd case, for example, the permutation P = {1, 3, 2} will use the exact 9 miles wires in total.\\n\\nTo understand the first two cases, you can see the following figures:\\n\\n\\n\\nIn the 3rd case, the minimum length of wire required is 5, for any of the permutations {1,2} or {2,1}, so length 4 is not sufficient.\\n\\nIn the 4th case, for the permutation...\",\"targets\":\"import sys\\nfirst = True\\nmemmin = {}\\nmemmax = {}\\n\\ndef fmax(n):\\n if n == 1: return 2\\n if n == 0: return 0\\n if n in memmax: return memmax[n]\\n\\n res = 0\\n for i in range(n):\\n  cur = i + 1 + n - i + fmax(i) + fmax(n-i-1)\\n  if cur > res: res = cur\\n\\n memmax[n] = res\\n return res\\n\\ndef fmin(n):\\n if n == 1: return 2\\n if n == 0: return 0\\n if n in memmin: return memmin[n]\\n\\n res = 10 ** 9\\n for i in range(n):\\n  cur = i + 1 + n - i + fmin(i) + fmin(n-i-1)\\n  if cur < res: res = cur\\n\\n memmin[n] = res\\n return res \\n\\nfor line in sys.stdin:\\n if first:\\n  first = False\\n  tc = int(line)\\n  continue\\n\\n tc -= 1\\n if tc < 0: break\\n\\n n, m = list(map(int, line.split()))\\n\\n val1 = fmin(n)\\n val2 = fmax(n)\\n\\n if m < val1: print(-1)\\n else:\\n  if m > val2: print(m - val2)\\n  else: print(0)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVivek initially has an empty array $a$ and some integer constant $m$.\\n\\nHe performs the following algorithm:  Select a random integer $x$ uniformly in range from $1$ to $m$ and append it to the end of $a$.  Compute the greatest common divisor of integers in $a$.  In case it equals to $1$, break  Otherwise, return to step $1$. \\n\\nFind the expected length of $a$. It can be shown that it can be represented as $\\\\frac{P}{Q}$ where $P$ and $Q$ are coprime integers and $Q\\\\neq 0 \\\\pmod{10^9+7}$. Print the value of $P \\\\cdot Q^{-1} \\\\pmod{10^9+7}$.\\n\\n\\n-----Input-----\\n\\nThe first and only line contains a single integer $m$ ($1 \\\\leq m \\\\leq 100000$).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the expected length of the array $a$ written as $P \\\\cdot Q^{-1} \\\\pmod{10^9+7}$.\\n\\n\\n-----Examples-----\\nInput\\n1\\n\\nOutput\\n1\\n\\nInput\\n2\\n\\nOutput\\n2\\n\\nInput\\n4\\n\\nOutput\\n333333338\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, since Vivek can choose only integers from $1$ to $1$, he will have $a=[1]$ after the first append operation, and after that quit the algorithm. Hence the length of $a$ is always $1$, so its expected value is $1$ as well.\\n\\nIn the second example, Vivek each time will append either $1$ or $2$, so after finishing the algorithm he will end up having some number of $2$'s (possibly zero), and a single $1$ in the end. The expected length of the list is $1\\\\cdot \\\\frac{1}{2} + 2\\\\cdot \\\\frac{1}{2^2} + 3\\\\cdot \\\\frac{1}{2^3} + \\\\ldots = 2$.\",\"targets\":\"from sys import *\\nm = int(input())\\nq = [0] * (m + 1)\\nc = 1\\nfor i in range(m, 1, -1):\\n    w = m \\/\\/ i * pow(m, 1000000007 - 2, 1000000007)\\n    q[i] = w * pow(1 - w, 1000000007 - 2, 1000000007) % 1000000007\\n    for j in range(2 * i, m + 1, i):\\n        q[i] = (q[i] - q[j]) % 1000000007\\n    c = c + q[i]\\nprint(c % 1000000007)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5b83c1c44a6acac33400009a:\\nIn this Kata, you will be given a number in form of a string and an integer `k` and your task is to insert `k` commas into the string and determine which of the partitions is the largest. \\n\\n```\\nFor example:\\nsolve('1234',1) = 234 because ('1','234') or ('12','34') or ('123','4').\\nsolve('1234',2) = 34 because ('1','2','34') or ('1','23','4') or ('12','3','4'). \\nsolve('1234',3) = 4\\nsolve('2020',1) = 202\\n```\\n\\nMore examples in test cases. Good luck!\\n\\nPlease also try [Simple remove duplicates](https:\\/\\/www.codewars.com\\/kata\\/5ba38ba180824a86850000f7)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def solve(st, k):\\n    window = len(st) - k\\n    return max(int(st[i:i+window]) for i in range(len(st)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe only difference between easy and hard versions are constraints on $n$ and $k$.\\n\\nYou are messaging in one of the popular social networks via your smartphone. Your smartphone can show at most $k$ most recent conversations with your friends. Initially, the screen is empty (i.e. the number of displayed conversations equals $0$).\\n\\nEach conversation is between you and some of your friends. There is at most one conversation with any of your friends. So each conversation is uniquely defined by your friend.\\n\\nYou (suddenly!) have the ability to see the future. You know that during the day you will receive $n$ messages, the $i$-th message will be received from the friend with ID $id_i$ ($1 \\\\le id_i \\\\le 10^9$).\\n\\nIf you receive a message from $id_i$ in the conversation which is currently displayed on the smartphone then nothing happens: the conversations of the screen do not change and do not change their order, you read the message and continue waiting for new messages.\\n\\nOtherwise (i.e. if there is no conversation with $id_i$ on the screen):  Firstly, if the number of conversations displayed on the screen is $k$, the last conversation (which has the position $k$) is removed from the screen.  Now the number of conversations on the screen is guaranteed to be less than $k$ and the conversation with the friend $id_i$ is not displayed on the screen.  The conversation with the friend $id_i$ appears on the first (the topmost) position on the screen and all the other displayed conversations are shifted one position down. \\n\\nYour task is to find the list of conversations (in the order they are displayed on the screen) after processing all $n$ messages.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $k$ ($1 \\\\le n, k \\\\le 200)$ — the number of messages and the number of conversations your smartphone can show.\\n\\nThe second line of the input contains $n$ integers $id_1, id_2, \\\\dots, id_n$ ($1 \\\\le id_i \\\\le 10^9$), where $id_i$ is the ID of the friend which sends you the $i$-th...\",\"targets\":\"n, m = map(int, input().split())\\ndata = list(map(int, input().split()))\\narray = []\\nc = 0\\nfor i in data:\\n    if i not in array:\\n        c += 1\\n        if c > m:\\n            array = [i] + array[:-1]\\n        else:\\n            array = [i] + array\\nprint(m if c >= m else c)\\nprint(*array)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/819\\/E:\\nIn order to fly to the Moon Mister B just needs to solve the following problem.\\n\\nThere is a complete indirected graph with n vertices. You need to cover it with several simple cycles of length 3 and 4 so that each edge is in exactly 2 cycles.\\n\\nWe are sure that Mister B will solve the problem soon and will fly to the Moon. Will you?\\n\\n\\n-----Input-----\\n\\nThe only line contains single integer n (3 ≤ n ≤ 300).\\n\\n\\n-----Output-----\\n\\nIf there is no answer, print -1.\\n\\nOtherwise, in the first line print k (1 ≤ k ≤ n^2) — the number of cycles in your solution.\\n\\nIn each of the next k lines print description of one cycle in the following format: first print integer m (3 ≤ m ≤ 4) — the length of the cycle, then print m integers v_1, v_2, ..., v_{m} (1 ≤ v_{i} ≤ n) — the vertices in the cycle in the traverse order. Each edge should be in exactly two cycles.\\n\\n\\n-----Examples-----\\nInput\\n3\\n\\nOutput\\n2\\n3 1 2 3\\n3 1 2 3\\n\\nInput\\n5\\n\\nOutput\\n6\\n3 5 4 2\\n3 3 1 5\\n4 4 5 2 3\\n4 4 3 2 1\\n3 4 2 1\\n3 3 1 5\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#!\\/usr\\/bin\\/env python3\\n\\nfrom collections import defaultdict\\n\\nDEBUG = False\\n\\n\\ndef main():\\n    if DEBUG:\\n        test()\\n\\n    n = int(input())\\n\\n    paths = cycles(n)\\n\\n    print(len(paths))\\n    for p in paths:\\n        print('%d %s' % (len(p), ' '.join([str(v) for v in p])))\\n\\n\\ndef cycles(n):\\n    \\\"\\\"\\\"Builds a set of cycles for a fully connected graph with n vertices.\\\"\\\"\\\"\\n    if n % 2 == 0:\\n        return even(n)\\n    else:\\n        return odd(n)\\n\\n\\ndef even(n):\\n    \\\"\\\"\\\"Builds a set of cycles that a graph with even vertices.\\\"\\\"\\\"\\n    assert n % 2 == 0\\n\\n    # Base case for complete graph such that V = {1, 2, 3, 4}.\\n    cycles = [[1, 2, 3], [2, 3, 4], [3, 4, 1], [4, 1, 2]]\\n\\n    for i in range(6, n + 1, 2):\\n        a, b = i, i - 1\\n\\n        # Use edges (a, 1), (a, 0), (b, 1), (b, 0), (a, b) exactly twice each.\\n        cycles += [[a, 1, b], [a, 2, b], [a, 1, b, 2]]\\n\\n        # Similar to odd(...) as we are left with 2n - 2 edges to use\\n        # connected to i - 4 of the vertices V' = {3 ... i - 2}. Notice that\\n        # |V'| is even so we can apply the same strategy as in odd(...).\\n        for k in range(3, i - 1, 2):\\n            c, d = k, k + 1\\n            cycles += [[a, c, b, d]] * 2\\n\\n    return cycles\\n\\n\\ndef odd(n):\\n    \\\"\\\"\\\"Builds a set of cycles that a graph with odd vertices.\\\"\\\"\\\"\\n    assert n % 2 == 1\\n\\n    # Base case for complete graph such that V = {1, 2, 3}.\\n    cycles = [[1, 2, 3]] * 2\\n\\n    for i in range(5, n + 1, 2):\\n        a, b = i, i - 1\\n        # Say the new vertices are {a, b}. Since the graph is fully connected\\n        # adding these 2 vertices results in 2n + 1 more edges. We use a length\\n        # 3 cycle a -> b -> 1 > a twice to use up 3 of these edges.\\n        cycles += [[a, b, 1]] * 2\\n\\n        # At this point we are left with 2n + 1 - 3 = 2n - 2 edges to use\\n        # connected to i - 3 of the vertices V' = {2 ... i - 2}. Notice that\\n        # |V'| is even. To use these edges and cover vertices V' we take pairs\\n        # c, d in V' and create two of each path a -> c -> b -> d -> a.\\n        for k in range(2, i...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given nonnegative integers a and b (a ≤ b), and a positive integer x.\\nAmong the integers between a and b, inclusive, how many are divisible by x?\\n\\n-----Constraints-----\\n - 0 ≤ a ≤ b ≤ 10^{18}\\n - 1 ≤ x ≤ 10^{18}\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\na b x\\n\\n-----Output-----\\nPrint the number of the integers between a and b, inclusive, that are divisible by x.\\n\\n-----Sample Input-----\\n4 8 2\\n\\n-----Sample Output-----\\n3\\n\\nThere are three integers between 4 and 8, inclusive, that are divisible by 2: 4, 6 and 8.\",\"targets\":\"a, b, x = map(int, input().split())\\nans = b\\/\\/x - a\\/\\/x + (a%x==0)\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nEverybody knows the classic [\\\"half your age plus seven\\\"](https:\\/\\/en.wikipedia.org\\/wiki\\/Age_disparity_in_sexual_relationships#The_.22half-your-age-plus-seven.22_rule) dating rule that a lot of people follow (including myself). It's the 'recommended' age range in which to date someone. \\n\\n\\n\\n\\n```minimum age <= your age <= maximum age```\\n#Task\\n\\nGiven an integer (1 <= n <= 100) representing a person's age, return their minimum and maximum age range.\\n\\nThis equation doesn't work when the age <= 14, so use this equation instead:\\n```\\nmin = age - 0.10 * age\\nmax = age + 0.10 * age\\n```\\nYou should floor all your answers so that an integer is given instead of a float (which doesn't represent age). ```Return your answer in the form [min]-[max]```\\n\\n##Examples:\\n\\n```\\nage = 27   =>   20-40\\nage = 5    =>   4-5\\nage = 17   =>   15-20\\n```\",\"targets\":\"def dating_range(age):\\n    if age <= 14:\\n        return f'{int(age - 0.1 * age)}-{int(age + 0.1 * age)}'\\n    return f'{age\\/\\/2 + 7}-{(age-7)*2}'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given sequence a_1, a_2, ..., a_{n} of integer numbers of length n. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains subsequence with odd sum.\\n\\nSubsequence is a sequence that can be derived from another sequence by deleting some elements without changing the order of the remaining elements.\\n\\nYou should write a program which finds sum of the best subsequence.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer number n (1 ≤ n ≤ 10^5).\\n\\nThe second line contains n integer numbers a_1, a_2, ..., a_{n} ( - 10^4 ≤ a_{i} ≤ 10^4). The sequence contains at least one subsequence with odd sum.\\n\\n\\n-----Output-----\\n\\nPrint sum of resulting subseqeuence.\\n\\n\\n-----Examples-----\\nInput\\n4\\n-2 2 -3 1\\n\\nOutput\\n3\\n\\nInput\\n3\\n2 -5 -3\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first example sum of the second and the fourth elements is 3.\",\"targets\":\"n = int(input())\\na = list(map(int, input().split(\\\" \\\")))\\n\\nminus_odd = -10001\\nplus_odd = 10001\\ntotal = 0\\n\\nfor i in a:\\n    if i % 2:\\n        if i < 0:\\n            minus_odd = max(minus_odd, i)\\n        else:\\n            plus_odd = min(plus_odd, i)\\n\\n    if i > 0:\\n        total += i\\n\\nif total % 2 == 0:\\n    if minus_odd == -10001:\\n        print(total - plus_odd)\\n    elif plus_odd == 10001:\\n        print(total + minus_odd)\\n    else:\\n        if -minus_odd > plus_odd:\\n            print(total - plus_odd)\\n        else:\\n            print(total + minus_odd)\\n\\nelse:\\n    print(total)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLaura really hates people using acronyms in her office and wants to force her colleagues to remove all acronyms before emailing her. She wants you to build a system that will edit out all known acronyms or else will notify the sender if unknown acronyms are present.\\n\\nAny combination of three or more letters in upper case will be considered an acronym. Acronyms will not be combined with lowercase letters, such as in the case of 'KPIs'. They will be kept isolated as a word\\/words within a string.\\n\\nFor any string: \\n\\nAll instances of 'KPI' must become \\\"key performance indicators\\\" \\nAll instances of 'EOD' must become \\\"the end of the day\\\" \\nAll instances of 'TBD' must become \\\"to be decided\\\"\\nAll instances of 'WAH' must become \\\"work at home\\\"\\nAll instances of 'IAM' must become \\\"in a meeting\\\"\\nAll instances of 'OOO' must become \\\"out of office\\\"\\nAll instances of 'NRN' must become \\\"no reply necessary\\\"\\nAll instances of 'CTA' must become \\\"call to action\\\"\\nAll instances of 'SWOT' must become \\\"strengths, weaknesses, opportunities and threats\\\"\\nIf there are any unknown acronyms in the string, Laura wants you to return only the message:\\n'[acronym] is an acronym. I do not like acronyms. Please remove them from your email.'\\nSo if the acronym in question was 'BRB', you would return the string:\\n'BRB is an acronym. I do not like acronyms. Please remove them from your email.'\\nIf there is more than one unknown acronym in the string, return only the first in your answer.\\n\\nIf all acronyms can be replaced with full words according to the above, however, return only the altered string.\\n\\nIf this is the case, ensure that sentences still start with capital letters. '!' or '?' will not be used.\",\"targets\":\"def acronym_buster(message):\\n    acronyms = {\\n        'CTA': 'call to action',\\n        'EOD': 'the end of the day',\\n        'IAM': 'in a meeting',\\n        'KPI': 'key performance indicators',\\n        'NRN': 'no reply necessary',\\n        'OOO': 'out of office',\\n        'SWOT': 'strengths, weaknesses, opportunities and threats',\\n        'TBD': 'to be decided',\\n        'WAH': 'work at home'\\n    }\\n    result = []\\n    for sentence in message.split('.'):\\n        tmp = []\\n        for i, word in enumerate(sentence.split()):\\n            if word.isupper() and len(word) > 2:\\n                try:\\n                    word = acronyms[word]\\n                except KeyError:\\n                    return ('{} is an acronym. I do not like acronyms. Please'\\n                            ' remove them from your email.'.format(word))\\n            tmp.append(word[0].upper() + word[1:] if i == 0 else word)\\n        result.append(' '.join(tmp))\\n    return '. '.join(result).rstrip()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/54df2067ecaa226eca000229:\\nDue to another of his misbehaved, \\nthe primary school's teacher of the young Gauß,  Herr J.G. Büttner, to keep the bored and unruly young schoolboy Karl Friedrich Gauss busy for a good long time, while he teaching arithmetic to his mates,\\nassigned him the problem of adding up all the whole numbers from 1 through a given number `n`.\\n\\nYour task is to help the young Carl Friedrich to solve this problem as quickly as you can; so, he can astonish his teacher and rescue his recreation interval.\\n\\nHere's, an example:\\n\\n```\\nf(n=100) \\/\\/ returns 5050 \\n```\\n\\nIt's your duty to verify that n is a valid positive integer number. If not, please, return false (None for Python, null for C#).\\n\\n> **Note:** the goal of this kata is to invite you to think about some 'basic' mathematic formula and how you can do performance optimization on your code. \\n\\n> Advanced - experienced users should try to solve it in one line, without loops, or optimizing the code as much as they can.\\n\\n-----\\n\\n**Credits:** this kata was inspired by the farzher's kata 'Sum of large ints' . In fact, it can be seen as a sort of prep kata for that one.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def f(n):\\n    \\n    if isinstance(n, int) and n >0:\\n\\n        return (1\\/2)*n*(n+1)\\n    \\n    else:\\n        \\n        return None\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/arc081\\/tasks\\/arc081_b:\\nWe have a board with a 2 \\\\times N grid.\\nSnuke covered the board with N dominoes without overlaps.\\nHere, a domino can cover a 1 \\\\times 2 or 2 \\\\times 1 square.\\nThen, Snuke decided to paint these dominoes using three colors: red, cyan and green.\\nTwo dominoes that are adjacent by side should be painted by different colors.\\nHere, it is not always necessary to use all three colors.\\nFind the number of such ways to paint the dominoes, modulo 1000000007.\\nThe arrangement of the dominoes is given to you as two strings S_1 and S_2 in the following manner:\\n - Each domino is represented by a different English letter (lowercase or uppercase).\\n - The j-th character in S_i represents the domino that occupies the square at the i-th row from the top and j-th column from the left.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 52\\n - |S_1| = |S_2| = N\\n - S_1 and S_2 consist of lowercase and uppercase English letters.\\n - S_1 and S_2 represent a valid arrangement of dominoes.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nS_1\\nS_2\\n\\n-----Output-----\\nPrint the number of such ways to paint the dominoes, modulo 1000000007.\\n\\n-----Sample Input-----\\n3\\naab\\nccb\\n\\n-----Sample Output-----\\n6\\n\\nThere are six ways as shown below:\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#template\\ndef inputlist(): return [int(j) for j in input().split()]\\n#template\\n\\nmod = 10**9+7\\n\\nN = int(input())\\n\\nif N == 1:\\n    print((3))\\n    return\\n\\nS1 = list(input())\\nS2 = list(input())\\n\\nblocks = []\\ns = S1[0]\\nfor i in range(1,N):\\n    if S1[i] == S1[i-1]:\\n        s += S1[i]\\n    else:\\n        blocks.append(s)\\n        s = S1[i]\\n    if i == N-1:\\n        blocks.append(s)\\n\\nn = len(blocks)\\n\\nlast_blocks = [0]*n\\n\\nfor i in range(1,n):\\n    last_blocks[i] = len(blocks[i-1])\\n\\nans = 1\\nfor i in range(n):\\n    tmp = blocks[i]\\n    last_block = last_blocks[i]\\n    if last_block == 0:\\n        if len(tmp) == 1:\\n            ans *= 3\\n        else:\\n            ans*=6\\n    if last_block == 1:\\n        ans *= 2\\n    if last_block == 2:\\n        if len(tmp) == 1:\\n            ans*=1\\n        if len(tmp) == 2:\\n            ans*=3\\n    ans %= mod\\n\\nprint((ans%mod))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/python-mutations\\/problem:\\n=====Problem Statement=====\\nWe have seen that lists are mutable (they can be changed), and tuples are immutable (they cannot be changed).\\n\\nLet's try to understand this with an example.\\n\\nYou are given an immutable string, and you want to make changes to it.\\nTask\\nRead a given string, change the character at a given index and then print the modified string. \\n\\n=====Example=====\\nExample\\n>>> string = \\\"abracadabra\\\"\\n\\nYou can access an index by:\\n\\n>>> print string[5]\\na\\n\\nWhat if you would like to assign a value?\\n\\n>>> string[5] = 'k' \\nTraceback (most recent call last):\\n  File \\\"<stdin>\\\", line 1, in <module>\\nTypeError: 'str' object does not support item assignment\\n\\nHow would you approach this?\\n\\n    One solution is to convert the string to a list and then change the value.\\n\\nExample\\n\\n>>> string = \\\"abracadabra\\\"\\n>>> l = list(string)\\n>>> l[5] = 'k'\\n>>> string = ''.join(l)\\n>>> print string\\nabrackdabra\\n\\n    Another approach is to slice the string and join it back.\\n\\nExample\\n\\n>>> string = string[:5] + \\\"k\\\" + string[6:]\\n>>> print string\\nabrackdabra\\n\\n=====Input Format=====\\nThe first line contains a string, S.\\nThe next line contains an integer i, denoting the index location and a character c separated by a space.\\n\\n=====Output Format=====\\nUsing any of the methods explained above, replace the character at index i with character c.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def mutate_string(string, position, character):\\n    out = list(string)\\n    out[position] = character\\n    return \\\"\\\".join(out)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5679aa472b8f57fb8c000047:\\nYou are going to be given an array of integers. Your job is to take that array and find an index N where the sum of the integers to the left of N is equal to the sum of the integers to the right of N. If there is no index that would make this happen, return `-1`.\\n\\n__For example:__\\n\\nLet's say you are given the array `{1,2,3,4,3,2,1}`:  \\nYour function will return the index `3`, because at the 3rd position of the array, the sum of left side of the index (`{1,2,3}`) and the sum of the right side of the index (`{3,2,1}`) both equal `6`.\\n\\n\\nLet's look at another one.  \\nYou are given the array `{1,100,50,-51,1,1}`:  \\nYour function will return the index `1`, because at the 1st position of the array, the sum of left side of the index (`{1}`) and the sum of the right side of the index (`{50,-51,1,1}`) both equal `1`.\\n\\nLast one:  \\nYou are given the array `{20,10,-80,10,10,15,35}`  \\nAt index 0 the left side is `{}`  \\nThe right side is `{10,-80,10,10,15,35}`  \\nThey both are equal to `0` when added. (Empty arrays are equal to 0 in this problem)  \\nIndex 0 is the place where the left side and right side are equal.  \\n\\nNote: Please remember that in most programming\\/scripting languages the index of an array starts at 0.\\n\\n__Input:__  \\nAn integer array of length `0 < arr < 1000`. The numbers in the array can be any integer positive or negative.\\n\\n__Output:__  \\nThe lowest index `N` where the side to the left of `N` is equal to the side to the right of `N`. If you do not find an index that fits these rules, then you will return `-1`.\\n\\n__Note:__  \\nIf you are given an array with multiple answers, return the lowest correct index.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def find_even_index(arr):\\n    left, right = 0, sum(arr)\\n    for i, e in enumerate(arr):\\n        right -= e\\n        if left == right:\\n            return i\\n        left += e\\n    return -1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/57ee2a1b7b45efcf700001bf:\\nYou will be given a string (x) featuring a cat 'C', a dog 'D' and a mouse 'm'. The rest of the string will be made up of '.'. \\n\\nYou need to find out if the cat can catch the mouse from it's current position. The cat can jump (j) characters. \\n\\nAlso, the cat cannot jump over the dog.\\n\\nSo:\\n\\nif j = 5:\\n\\n```..C.....m.``` returns 'Caught!'  <-- not more than j characters between\\n\\n```.....C............m......``` returns 'Escaped!'  <-- as there are more than j characters between the two, the cat can't jump far enough\\n\\nif j = 10:\\n\\n```...m.........C...D``` returns 'Caught!' <--Cat can jump far enough and jump is not over dog\\n\\n```...m....D....C.......``` returns 'Protected!' <-- Cat can jump far enough, but dog is in the way, protecting the mouse\\n\\nFinally, if all three animals are not present, return 'boring without all three'\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def cat_mouse(x, j):\\n    c, d, m = (x.find(animal) for animal in 'CDm')\\n    return ('boring without all three' if c < 0 or d < 0 or m < 0 else\\n            'Escaped!' if abs(c - m) > j else\\n            'Protected!' if c < d < m or c > d > m else\\n            'Caught!')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/QUALPREL:\\nSnackdown 2019 is coming! There are two rounds (round A and round B) after the qualification round. From both of them, teams can qualify to the pre-elimination round. According to the rules, in each of these two rounds, teams are sorted in descending order by their score and each team with a score greater or equal to the score of the team at the $K=1500$-th place advances to the pre-elimination round (this means it is possible to have more than $K$ qualified teams from each round in the case of one or more ties after the $K$-th place).\\nToday, the organizers ask you to count the number of teams which would qualify for the pre-elimination round from round A for a given value of $K$ (possibly different from $1500$). They provided the scores of all teams to you; you should ensure that all teams scoring at least as many points as the $K$-th team qualify.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains two space-separated integers $N$ and $K$.\\n- The second line contains $N$ space-separated integers $S_1, S_2, \\\\dots, S_N$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer — the number of qualified teams.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 1,000$\\n- $1 \\\\le K \\\\le N \\\\le 10^5$\\n- $1 \\\\le S_i \\\\le 10^9$ for each valid $i$\\n- the sum of $N$ for all test cases does not exceed $10^6$\\n\\n-----Example Input-----\\n2\\n5 1\\n3 5 2 4 5\\n6 4\\n6 5 4 3 2 1\\n\\n-----Example Output-----\\n2\\n4\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for _ in range(int(input())):\\n n,k = map(int,input().split())\\n l = list(map(int,input().split()))\\n l.sort(reverse = True)\\n ans = 0\\n x = l[k-1]\\n for i in range(n):\\n  if x>l[i]:\\n   break\\n  ans+=1\\n print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an axis-aligned rectangle in a 2D Cartesian plane. The bottom left corner of this rectangle has coordinates (0,0)$(0, 0)$ and the top right corner has coordinates (N−1,N−1)$(N-1, N-1)$. You are also given K$K$ light sources; each light source is a point inside or on the perimeter of the rectangle.\\nFor each light source, let's divide the plane into four quadrants by a horizontal and a vertical line passing through this light source. The light source can only illuminate one of these quadrants (including its border, i.e. the point containing the light source and two half-lines), but the quadrants illuminated by different light sources may be different.\\nYou want to assign a quadrant to each light source in such a way that when they illuminate their respective quadrants, the entire rectangle (including its perimeter) is illuminated. Find out whether it is possible to assign quadrants to light sources in such a way.\\n\\n-----Input-----\\n- The first line of the input contains an integer T$T$ denoting the number of test cases. The description of the test cases follows.\\n- The first line of each test case contains two space-separated integers K$K$ and N$N$.\\n- Each of the next K$K$ lines contains two space-separated integers x$x$ and y$y$ denoting a light source with coordinates (x,y)$(x, y)$.\\n\\n-----Output-----\\nFor each test case, print a single line containing the string \\\"yes\\\" if it is possible to illuminate the whole rectangle or \\\"no\\\" if it is impossible.\\n\\n-----Constraints-----\\n- 1≤T≤5,000$1 \\\\le T \\\\le 5,000$\\n- 1≤K≤100$1 \\\\le K \\\\le 100$\\n- 1≤N≤109$1 \\\\le N \\\\le 10^9$\\n- 0≤x,y≤N−1$0 \\\\le x, y \\\\le N-1$\\n- no two light sources coincide\\n\\n-----Example Input-----\\n2\\n2 10\\n0 0\\n1 0\\n2 10\\n1 2\\n1 1\\n\\n-----Example Output-----\\nyes\\nno\",\"targets\":\"t=int(input())\\r\\nwhile t:\\r\\n    k,n=map(int,input().split())\\r\\n    l=[]\\r\\n    j=0\\r\\n    h=k\\r\\n    while h:\\r\\n        p=list(map(int,input().split()))\\r\\n        l.append(p)\\r\\n        h-=1\\r\\n    if k>3:\\r\\n        j=1\\r\\n    elif k==1:\\r\\n        if (l[0][0]==0 and l[0][1]==n-1) or (l[0][0]==0 and l[0][1]==0) or (l[0][0]==n-1 and l[0][1]==0) or (l[0][0]==n-1 and l[0][1]==n-1):\\r\\n            j=1\\r\\n    elif k==2:\\r\\n        for q in range(2):\\r\\n            if (l[q][0]==0 and l[q][1]==n-1) or (l[q][0]==0 and l[q][1]==0) or (l[q][0]==n-1 and l[q][1]==0) or (l[q][0]==n-1 and l[q][1]==n-1):\\r\\n                j=1\\r\\n        if l[0][0]==0 or l[0][0]==n-1:\\r\\n            if l[1][0]==0 or l[1][0]==n-1: \\r\\n                j=1\\r\\n        if l[0][1]==0 or l[0][1]==n-1:\\r\\n            if l[1][1]==0 or l[1][1]==n-1: \\r\\n                j=1\\r\\n    elif k==3:\\r\\n        for q in range(3):\\r\\n            if (l[q][0]==0 and l[q][1]==n-1) or (l[q][0]==0 and l[q][1]==0) or (l[q][0]==n-1 and l[q][1]==0) or (l[q][0]==n-1 and l[q][1]==n-1):\\r\\n                j=1\\r\\n        for q in range(2):\\r\\n            for w in range(q+1,3):\\r\\n                if l[q][0]==0 or l[q][0]==n-1:\\r\\n                    if l[w][0]==0 or l[w][0]==n-1: \\r\\n                        j=1\\r\\n                if l[q][1]==0 or l[q][1]==n-1:\\r\\n                    if l[w][1]==0 or l[w][1]==n-1:\\r\\n                        j=1\\r\\n                if l[q][0]==0 or l[q][0]==n-1:\\r\\n                    if l[w][1]==0 or l[w][1]==n-1:\\r\\n                        j=1\\r\\n                if l[q][1]==0 or l[q][1]==n-1:\\r\\n                    if l[w][0]==0 or l[w][0]==n-1:\\r\\n                        j=1\\r\\n        for q in range(3):\\r\\n            w=(q+1)%3\\r\\n            r=(q+2)%3\\r\\n            if l[q][0]==0 or l[q][0]==n-1:\\r\\n                if (l[q][1]-l[w][1])*(l[q][1]-l[r][1])>=0:\\r\\n                    j=1\\r\\n            if l[q][1]==0 or l[q][1]==n-1:\\r\\n                if (l[q][0]-l[w][0])*(l[q][0]-l[r][0])>=0:\\r\\n                    j=1\\r\\n    if j:\\r\\n        print(\\\"yes\\\")\\r\\n    else:\\r\\n        print(\\\"no\\\")\\r\\n    t-=1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/check-if-a-string-contains-all-binary-codes-of-size-k\\/:\\nGiven a binary string s and an integer k.\\nReturn True if every binary code of length k is a substring of s. Otherwise, return False.\\n \\nExample 1:\\nInput: s = \\\"00110110\\\", k = 2\\nOutput: true\\nExplanation: The binary codes of length 2 are \\\"00\\\", \\\"01\\\", \\\"10\\\" and \\\"11\\\". They can be all found as substrings at indicies 0, 1, 3 and 2 respectively.\\n\\nExample 2:\\nInput: s = \\\"00110\\\", k = 2\\nOutput: true\\n\\nExample 3:\\nInput: s = \\\"0110\\\", k = 1\\nOutput: true\\nExplanation: The binary codes of length 1 are \\\"0\\\" and \\\"1\\\", it is clear that both exist as a substring. \\n\\nExample 4:\\nInput: s = \\\"0110\\\", k = 2\\nOutput: false\\nExplanation: The binary code \\\"00\\\" is of length 2 and doesn't exist in the array.\\n\\nExample 5:\\nInput: s = \\\"0000000001011100\\\", k = 4\\nOutput: false\\n\\n \\nConstraints:\\n\\n1 <= s.length <= 5 * 10^5\\ns consists of 0's and 1's only.\\n1 <= k <= 20\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def hasAllCodes(self, s: str, k: int) -> bool:\\n        nums = set()\\n        for i in range(0, len(s) - k + 1):\\n            nums.add(s[i:i+k])\\n            if len(nums) == 2**k:\\n                return True\\n        return False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe only difference between easy and hard versions is constraints.\\n\\nPolycarp loves to listen to music, so he never leaves the player, even on the way home from the university. Polycarp overcomes the distance from the university to the house in exactly $T$ minutes.\\n\\nIn the player, Polycarp stores $n$ songs, each of which is characterized by two parameters: $t_i$ and $g_i$, where $t_i$ is the length of the song in minutes ($1 \\\\le t_i \\\\le 15$), $g_i$ is its genre ($1 \\\\le g_i \\\\le 3$).\\n\\nPolycarp wants to create such a playlist so that he can listen to music all the time on the way from the university to his home, and at the time of his arrival home, the playlist is over. Polycarp never interrupts songs and always listens to them from beginning to end. Thus, if he started listening to the $i$-th song, he would spend exactly $t_i$ minutes on its listening. Polycarp also does not like when two songs of the same genre play in a row (i.e. successively\\/adjacently) or when the songs in his playlist are repeated.\\n\\nHelp Polycarpus count the number of different sequences of songs (their order matters), the total duration is exactly $T$, such that there are no two consecutive songs of the same genre in them and all the songs in the playlist are different.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $T$ ($1 \\\\le n \\\\le 15, 1 \\\\le T \\\\le 225$) — the number of songs in the player and the required total duration, respectively.\\n\\nNext, the $n$ lines contain descriptions of songs: the $i$-th line contains two integers $t_i$ and $g_i$ ($1 \\\\le t_i \\\\le 15, 1 \\\\le g_i \\\\le 3$) — the duration of the $i$-th song and its genre, respectively.\\n\\n\\n-----Output-----\\n\\nOutput one integer — the number of different sequences of songs, the total length of exactly $T$, such that there are no two consecutive songs of the same genre in them and all the songs in the playlist are different. Since the answer may be huge, output it modulo $10^9 + 7$ (that is, the remainder when dividing the quantity by $10^9 +...\",\"targets\":\"from itertools import combinations\\ndef out1(a,b,c):\\n    if a<0 or b<0 or c<0:\\n        return 0\\n    if a==1 and b==0 and c==0:\\n        return 1\\n    return a*(out2(a-1,b,c)+out3(a-1,b,c))\\ndef out2(a,b,c):\\n    if a<0 or b<0 or c<0:\\n        return 0\\n    if a==0 and b==1 and c==0:\\n        return 1\\n    return b*(out1(a,b-1,c)+out3(a,b-1,c))\\ndef out3(a,b,c):\\n    if a<0 or b<0 or c<0:\\n        return 0\\n    if a==0 and b==0 and c==1:\\n        return 1\\n    return c*(out2(a,b,c-1)+out1(a,b,c-1))\\ndef column(matrix, i):\\n    return [row[i] for row in matrix]\\n    \\nN, T = [int(x) for x in input().split()]\\nA = []\\ns = 0\\nfor i in range(N):\\n    A.append([int(x) for x in input().split()])\\nfor i in range(1,N+1):\\n    comb = list(combinations(A, i))\\n    for x in comb:\\n        if sum(column(x,0))==T:\\n            a = column(x,1).count(1)\\n            b = column(x,1).count(2)\\n            c = column(x,1).count(3)\\n            s+=(out1(a,b,c)+out2(a,b,c)+out3(a,b,c))\\nprint(s%1000000007)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/IGNS2012\\/problems\\/IG01:\\nThis is a simple game you must have played around with during your school days, calculating FLAMES of you and your crush! Given the names of two people, cancel out the common letters (repeated occurrence of a letter is treated separately, so 2A's in one name and one A in the other would cancel one A in each name), count the total number of remaining letters (n) and repeatedly cut the letter in the word FLAMES which hits at the nth number when we count from F in cyclic manner.\\n\\nFor example:\\nNAME 1: SHILPA\\nNAME 2: AAMIR\\nAfter cutting the common letters: \\nNAME 1: SHILPA \\nNAME 2: AAMIR\\nTotal number of letters left=7\\nFLAMES, start counting from F : 1=F, 2=L, 3=A, 4=M, 5=E, 6=S,7=F...So cut F\\nFLAMES: repeat this process with remaining letters of FLAMES for number 7 (start count from the letter after \\nthe last letter cut) . In the end, one letter remains. Print the result corresponding to the last letter:\\nF=FRIENDS\\nL=LOVE\\nA=ADORE\\nM=MARRIAGE\\nE=ENEMIES\\nS=SISTER\\n\\n-----Input-----\\nThe no. of test cases (<100)\\ntwo names (may include spaces) for each test case.\\n\\n\\n-----Output-----\\nFLAMES result (Friends\\/Love\\/...etc) for each test case\\n\\n-----Example-----\\nInput:\\n2\\nSHILPA\\nAAMIR\\nMATT\\nDENISE\\n\\nOutput:\\nENEMIES\\nLOVE\\n\\n\\n\\nBy:\\nChintan, Asad, Ashayam, Akanksha\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n\\ndef main():\\n    s = sys.stdin.readline\\n    t = int(s())\\n    for i in range(t):\\n        name = s().strip().lower()\\n        if ' ' in name:\\n            name = name.replace(' ', '')\\n        crush = s().strip().lower()\\n        if ' ' in crush:\\n            crush = crush.replace(' ', '')\\n        namecounter = {}\\n        crushcounter = {}\\n        for letter in name:\\n            if letter in namecounter:\\n                namecounter[letter] += 1\\n            else:\\n                namecounter[letter] = 1\\n    \\n        for letter in crush:\\n            if letter in crushcounter:\\n                crushcounter[letter] += 1\\n            else:\\n                crushcounter[letter] = 1\\n        counter = 0\\n        already = []\\n        for letter in name:\\n            if letter in crush:\\n                if letter not in already:\\n                    if namecounter[letter] == crushcounter[letter]:\\n                        already.append(letter)\\n                        continue\\n                    else:\\n                        counter += abs(namecounter[letter]-crushcounter[letter])\\n            else:\\n                counter += 1\\n            already.append(letter)\\n        for letter in crush:\\n            if letter not in already:\\n                counter += 1\\n        values = {1: 'FRIENDS', 2: 'LOVE', 3: 'ADORE', 4: 'MARRIAGE', 5: 'ENEMIES', 6: 'SISTER'}\\n        result = 0\\n        for i in range(1, 6+1):\\n                result = (result+counter)%i\\n        print(values[result+1])\\n        \\ndef __starting_point():\\n    main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/845\\/D:\\nPolycarp has just attempted to pass the driving test. He ran over the straight road with the signs of four types.\\n\\n  speed limit: this sign comes with a positive integer number — maximal speed of the car after the sign (cancel the action of the previous sign of this type);  overtake is allowed: this sign means that after some car meets it, it can overtake any other car;  no speed limit: this sign cancels speed limit if any (car can move with arbitrary speed after this sign);  no overtake allowed: some car can't overtake any other car after this sign. \\n\\nPolycarp goes past the signs consequentially, each new sign cancels the action of all the previous signs of it's kind (speed limit\\/overtake). It is possible that two or more \\\"no overtake allowed\\\" signs go one after another with zero \\\"overtake is allowed\\\" signs between them. It works with \\\"no speed limit\\\" and \\\"overtake is allowed\\\" signs as well.\\n\\nIn the beginning of the ride overtake is allowed and there is no speed limit.\\n\\nYou are given the sequence of events in chronological order — events which happened to Polycarp during the ride. There are events of following types:\\n\\n  Polycarp changes the speed of his car to specified (this event comes with a positive integer number);  Polycarp's car overtakes the other car;  Polycarp's car goes past the \\\"speed limit\\\" sign (this sign comes with a positive integer);  Polycarp's car goes past the \\\"overtake is allowed\\\" sign;  Polycarp's car goes past the \\\"no speed limit\\\";  Polycarp's car goes past the \\\"no overtake allowed\\\"; \\n\\nIt is guaranteed that the first event in chronological order is the event of type 1 (Polycarp changed the speed of his car to specified).\\n\\nAfter the exam Polycarp can justify his rule violations by telling the driving instructor that he just didn't notice some of the signs. What is the minimal number of signs Polycarp should say he didn't notice, so that he would make no rule violations from his point of view?\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer number n (1 ≤ n ≤ 2·10^5) — number of...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"p = [1e9]\\nd = k = v = 0\\nfor i in range(int(input())):\\n    s = input()\\n    t = int(s[0])\\n    if t == 1:\\n        v = int(s[2:])\\n        while p[-1] < v:\\n            p.pop()\\n            k += 1\\n    if t == 2: k, d = k + d, 0\\n    if t == 3:\\n        u = int(s[2:])\\n        if v > u: k += 1\\n        else: p += [u]\\n    if t == 4: d = 0\\n    if t == 5: p = [1e9]\\n    if t == 6: d += 1\\nprint(k)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThis is a simple game you must have played around with during your school days, calculating FLAMES of you and your crush! Given the names of two people, cancel out the common letters (repeated occurrence of a letter is treated separately, so 2A's in one name and one A in the other would cancel one A in each name), count the total number of remaining letters (n) and repeatedly cut the letter in the word FLAMES which hits at the nth number when we count from F in cyclic manner.\\n\\nFor example:\\nNAME 1: SHILPA\\nNAME 2: AAMIR\\nAfter cutting the common letters: \\nNAME 1: SHILPA \\nNAME 2: AAMIR\\nTotal number of letters left=7\\nFLAMES, start counting from F : 1=F, 2=L, 3=A, 4=M, 5=E, 6=S,7=F...So cut F\\nFLAMES: repeat this process with remaining letters of FLAMES for number 7 (start count from the letter after \\nthe last letter cut) . In the end, one letter remains. Print the result corresponding to the last letter:\\nF=FRIENDS\\nL=LOVE\\nA=ADORE\\nM=MARRIAGE\\nE=ENEMIES\\nS=SISTER\\n\\n-----Input-----\\nThe no. of test cases (<100)\\ntwo names (may include spaces) for each test case.\\n\\n\\n-----Output-----\\nFLAMES result (Friends\\/Love\\/...etc) for each test case\\n\\n-----Example-----\\nInput:\\n2\\nSHILPA\\nAAMIR\\nMATT\\nDENISE\\n\\nOutput:\\nENEMIES\\nLOVE\\n\\n\\n\\nBy:\\nChintan, Asad, Ashayam, Akanksha\",\"targets\":\"import sys\\n\\ndef main():\\n    s = sys.stdin.readline\\n    t = int(s())\\n    for i in range(t):\\n        name = s().strip().lower()\\n        if ' ' in name:\\n            name = name.replace(' ', '')\\n        crush = s().strip().lower()\\n        if ' ' in crush:\\n            crush = crush.replace(' ', '')\\n        namecounter = {}\\n        crushcounter = {}\\n        for letter in name:\\n            if letter in namecounter:\\n                namecounter[letter] += 1\\n            else:\\n                namecounter[letter] = 1\\n    \\n        for letter in crush:\\n            if letter in crushcounter:\\n                crushcounter[letter] += 1\\n            else:\\n                crushcounter[letter] = 1\\n        counter = 0\\n        already = []\\n        for letter in name:\\n            if letter in crush:\\n                if letter not in already:\\n                    if namecounter[letter] == crushcounter[letter]:\\n                        already.append(letter)\\n                        continue\\n                    else:\\n                        counter += abs(namecounter[letter]-crushcounter[letter])\\n            else:\\n                counter += 1\\n            already.append(letter)\\n        for letter in crush:\\n            if letter not in already:\\n                counter += 1\\n        values = {1: 'FRIENDS', 2: 'LOVE', 3: 'ADORE', 4: 'MARRIAGE', 5: 'ENEMIES', 6: 'SISTER'}\\n        result = 0\\n        for i in range(1, 6+1):\\n                result = (result+counter)%i\\n        print(values[result+1])\\n        \\ndef __starting_point():\\n    main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/insert-interval\\/:\\nGiven a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).\\n\\nYou may assume that the intervals were initially sorted according to their start times.\\n\\nExample 1:\\n\\n\\nInput: intervals = [[1,3],[6,9]], newInterval = [2,5]\\nOutput: [[1,5],[6,9]]\\n\\n\\nExample 2:\\n\\n\\nInput: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]\\nOutput: [[1,2],[3,10],[12,16]]\\nExplanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# Definition for an interval.\\n # class Interval:\\n #     def __init__(self, s=0, e=0):\\n #         self.start = s\\n #         self.end = e\\n \\n class Solution:\\n     def insert(self, intervals, newInterval):\\n         \\\"\\\"\\\"\\n         :type intervals: List[Interval]\\n         :type newInterval: Interval\\n         :rtype: List[Interval]\\n         \\\"\\\"\\\"\\n         if intervals == []:\\n             return [newInterval]\\n         \\n         index = 0\\n         while index < len(intervals):\\n             if newInterval.start < intervals[index].start:\\n                 break\\n             index += 1\\n         del_index = 0\\n         insert_index = 0\\n         if index == 0:\\n             s = newInterval.start\\n             e = newInterval.end\\n             insert_index = index \\n         else:\\n             if newInterval.start <= intervals[index - 1].end:\\n                 s = intervals[index - 1].start\\n                 e = max(intervals[index - 1].end, newInterval.end)\\n                 insert_index = index - 1\\n                 del_index += 1\\n             else:\\n                 s = newInterval.start\\n                 e = newInterval.end\\n                 insert_index = index\\n             \\n         while index < len(intervals):\\n             if intervals[index].start <= e:\\n                 e = max(e, intervals[index].end)\\n                 del_index += 1\\n                 index += 1\\n             else:\\n                 break\\n         i = 0\\n         while i < del_index:\\n             intervals.pop(insert_index)\\n             i += 1\\n         intervals.insert(insert_index, Interval(s,e))\\n         return intervals\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/CHEFSEG:\\nChef loves to play games. Now he plays very interesting game called \\\"Segment\\\". At the beginning Chef has segment [0, X] and no points on it. On each step Chef chooses the subsegment of maximal length possible such as it contains no points on it. If there are more than one such subsegment Chef chooses the one with the minimal left coordinate. Once Chef chosed the subsegment he put the point in it's middle and the step is over.\\nHelp Chef to define the coordinate of the point he will put on the K-th step. \\n\\n-----Input-----\\n- The first line contains integer T - number of test cases. \\n- Each of next T lines contains two integers X and K. \\n\\n-----Output-----\\n- For each test case in a single line print single double number - the coordinate of the K-th point Chef will put. Answer will be considered as correct if absolute difference between the answer and correct answer is less or equal 10^(-6). \\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 10^5\\n- 1 ≤ X ≤ 10^9\\n- 1 ≤ K ≤ 10^12\\n\\n-----Subtasks-----\\n- Subtask 1: T ≤ 10; X, K ≤ 20. Points: 15 \\n- Subtask 2: T ≤ 10; X ≤ 10^6, K ≤ 2*10^5. Points: 25\\n- Subtask 3: T ≤ 10^5; X ≤ 10^9, K ≤ 10^12. Points: 60\\n\\n-----Example-----\\nInput:\\n4\\n10 1\\n10 2\\n10 3\\n1000000000 1234567\\nOutput:\\n5.0000\\n2.5000\\n7.5000\\n177375316.6198730500000000\\n\\n-----Explanation-----\\nYou can see the points coordinates for the third sample from first two samples.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"T = int(input())\\nfor _ in range(T):\\n X, K = [int(x) for x in input().split()]\\n \\n k, x, y = 1, 2, 1\\n while x <= K:\\n  k, x, y = k + 1, x * 2, x\\n \\n print((X\\/ x) + (K - y) * X\\/ y)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA function receives a certain numbers of integers ```n1, n2, n3 ..., np```(all positive and different from 0) and a factor ```k, k > 0```\\n\\nThe function rearranges the numbers ```n1, n2, ..., np``` in such order that generates the minimum number concatenating the digits and this number should be divisible by ```k```.\\n\\nThe order that the function receives their arguments is:\\n```python\\nrearranger(k, n1, n2, n3,....,np)\\n```\\n\\n## Examples\\n\\n```python\\nrearranger(4, 32, 3, 34, 7, 12)  == \\\"Rearrangement: 12, 3, 34, 7, 32 generates: 12334732 divisible by 4\\\"\\n\\nrearranger(10, 32, 3, 34, 7, 12) == \\\"There is no possible rearrangement\\\"\\n```\\nIf there are more than one possible arrengement for the same minimum number, your code should be able to handle those cases:\\n```python\\nrearranger(6, 19, 32, 2, 124, 20, 22) == \\\"Rearrangements: 124, 19, 20, 2, 22, 32 and 124, 19, 20, 22, 2, 32 generates: 124192022232 divisible by 6\\\"\\n```\\n\\nThe arrangements should be in sorted order, as you see: `124, 19, 20, 2, 22, 32` comes first than `124, 19, 20, 22, 2, 32`.\\n\\nHave an enjoyable time!\\n\\n(Thanks to `ChristianE.Cooper` for his contribution to this kata)\",\"targets\":\"from itertools import permutations\\n\\ndef rearranger(k, *args):\\n    perms = permutations(map(str, args), len(args))\\n    divisible_by_k = filter(lambda x: int(''.join(x)) % k == 0, perms)\\n    try:\\n        rearranged = min(divisible_by_k, key=lambda x: int(''.join(x)))\\n        return 'Rearrangement: {} generates: {} divisible by {}'.format(', '.join(rearranged), ''.join(rearranged), k)\\n    except ValueError:\\n        return \\\"There is no possible rearrangement\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1379\\/C:\\nVladimir would like to prepare a present for his wife: they have an anniversary! He decided to buy her exactly $n$ flowers.\\n\\nVladimir went to a flower shop, and he was amazed to see that there are $m$ types of flowers being sold there, and there is unlimited supply of flowers of each type. Vladimir wants to choose flowers to maximize the happiness of his wife. He knows that after receiving the first flower of the $i$-th type happiness of his wife increases by $a_i$ and after receiving each consecutive flower of this type her happiness increases by $b_i$. That is, if among the chosen flowers there are $x_i > 0$ flowers of type $i$, his wife gets $a_i + (x_i - 1) \\\\cdot b_i$ additional happiness (and if there are no flowers of type $i$, she gets nothing for this particular type).\\n\\nPlease help Vladimir to choose exactly $n$ flowers to maximize the total happiness of his wife.\\n\\n\\n-----Input-----\\n\\nThe first line contains the only integer $t$ ($1 \\\\leq t \\\\leq 10\\\\,000$), the number of test cases. It is followed by $t$ descriptions of the test cases.\\n\\nEach test case description starts with two integers $n$ and $m$ ($1 \\\\le n \\\\le 10^9$, $1 \\\\le m \\\\le 100\\\\,000$), the number of flowers Vladimir needs to choose and the number of types of available flowers.\\n\\nThe following $m$ lines describe the types of flowers: each line contains integers $a_i$ and $b_i$ ($0 \\\\le a_i, b_i \\\\le 10^9$) for $i$-th available type of flowers.\\n\\nThe test cases are separated by a blank line. It is guaranteed that the sum of values $m$ among all test cases does not exceed $100\\\\,000$.\\n\\n\\n-----Output-----\\n\\nFor each test case output a single integer: the maximum total happiness of Vladimir's wife after choosing exactly $n$ flowers optimally.\\n\\n\\n-----Example-----\\nInput\\n2\\n4 3\\n5 0\\n1 4\\n2 2\\n\\n5 3\\n5 2\\n4 2\\n3 1\\n\\nOutput\\n14\\n16\\n\\n\\n\\n-----Note-----\\n\\nIn the first example case Vladimir can pick 1 flower of the first type and 3 flowers of the second type, in this case the total happiness equals $5 + (1 + 2 \\\\cdot 4) = 14$.\\n\\nIn the second example Vladimir can pick 2 flowers of...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from bisect import bisect_left\\n\\nt = int(input())\\n\\nfor case in range(t):\\n    n, m = list(map(int, input().split()))\\n    ab = [list(map(int, input().split())) for _ in range(m)]\\n\\n    aa = [e for e, _ in ab]\\n    aa.sort()\\n    acc = [0] * (m + 1)\\n    for i in range(m, 0, -1):\\n        acc[i-1] = acc[i] + aa[i-1]\\n\\n    if n > m:\\n        ans = 0\\n    else:\\n        ans = sum(aa[-n:])\\n\\n    for a, b in ab:\\n        i = bisect_left(aa, b)\\n        cnt = min(m - i, n)\\n        sm = acc[m - cnt]\\n        sm += b * (n - cnt)\\n        if a < b:\\n            sm -= b\\n            sm += a\\n\\n        ans = max(ans, sm)\\n\\n    print(ans)\\n\\n    if case != t - 1:\\n        input()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nImplement a basic calculator to evaluate a simple expression string.\\n\\nThe expression string contains only non-negative integers, +, -, *, \\/ operators and empty spaces  . The integer division should truncate toward zero.\\n\\nExample 1:\\n\\n\\nInput: \\\"3+2*2\\\"\\nOutput: 7\\n\\n\\nExample 2:\\n\\n\\nInput: \\\" 3\\/2 \\\"\\nOutput: 1\\n\\nExample 3:\\n\\n\\nInput: \\\" 3+5 \\/ 2 \\\"\\nOutput: 5\\n\\n\\nNote:\\n\\n\\n       You may assume that the given expression is always valid.\\n       Do not use the eval built-in library function.\",\"targets\":\"class Solution:\\n     def calculate(self, s):\\n         if not s: return 0\\n         length = len(s)\\n         stack = []\\n         num = 0\\n         sign = '+'\\n         for idx, c in enumerate(s):\\n             if c.isdigit():\\n                 num = num*10 + ord(c) - ord('0')\\n             if c in ['+','-','*','\\/'] or idx == length - 1:\\n                 if sign == '+':\\n                     stack.append(num)\\n                 elif sign == '-':\\n                     stack.append(-num)\\n                 elif sign == '*':\\n                     stack.append(stack.pop() * num)\\n                 elif sign == '\\/':\\n                     stack.append(int(stack.pop() \\/ num))\\n                 sign = c\\n                 num = 0\\n         \\n         return sum(stack)\\n         \\\"\\\"\\\"\\n         :type s: str\\n         :rtype: int\\n         \\\"\\\"\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1062\\/C:\\nJATC loves Banh-mi (a Vietnamese food). His affection for Banh-mi is so much that he always has it for breakfast. This morning, as usual, he buys a Banh-mi and decides to enjoy it in a special way.\\n\\nFirst, he splits the Banh-mi into $n$ parts, places them on a row and numbers them from $1$ through $n$. For each part $i$, he defines the deliciousness of the part as $x_i \\\\in \\\\{0, 1\\\\}$. JATC's going to eat those parts one by one. At each step, he chooses arbitrary remaining part and eats it. Suppose that part is the $i$-th part then his enjoyment of the Banh-mi will increase by $x_i$ and the deliciousness of all the remaining parts will also increase by $x_i$. The initial enjoyment of JATC is equal to $0$.\\n\\nFor example, suppose the deliciousness of $3$ parts are $[0, 1, 0]$. If JATC eats the second part then his enjoyment will become $1$ and the deliciousness of remaining parts will become $[1, \\\\_, 1]$. Next, if he eats the first part then his enjoyment will become $2$ and the remaining parts will become $[\\\\_, \\\\_, 2]$. After eating the last part, JATC's enjoyment will become $4$.\\n\\nHowever, JATC doesn't want to eat all the parts but to save some for later. He gives you $q$ queries, each of them consisting of two integers $l_i$ and $r_i$. For each query, you have to let him know what is the maximum enjoyment he can get if he eats all the parts with indices in the range $[l_i, r_i]$ in some order.\\n\\nAll the queries are independent of each other. Since the answer to the query could be very large, print it modulo $10^9+7$.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $q$ ($1 \\\\le n, q \\\\le 100\\\\,000$).\\n\\nThe second line contains a string of $n$ characters, each character is either '0' or '1'. The $i$-th character defines the deliciousness of the $i$-th part.\\n\\nEach of the following $q$ lines contains two integers $l_i$ and $r_i$ ($1 \\\\le l_i \\\\le r_i \\\\le n$) — the segment of the corresponding query.\\n\\n\\n-----Output-----\\n\\nPrint $q$ lines, where $i$-th of them contains a single integer — the answer to the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,q = list(map(int, input().split()))\\na = input()\\nQ = []\\nfor _ in range(q):\\n    Q.append(list(map(int, input().split())))\\nd = [0]\\nab = 0\\nfor i in a:\\n    if i == '1':\\n        ab += 1\\n    d.append(ab)\\nmod = int(1e9 + 7)\\np = [1]\\ni = 1\\nfor _ in range(n):\\n    i = (i*2)%mod\\n    p.append(i)\\n    \\nfor l,r in Q:\\n    y = r-l + 1\\n    x = d[r] - d[l-1]\\n    y -= x\\n    print(((p[x]-1)*p[y])%mod)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/610\\/C:\\nThe semester is already ending, so Danil made an effort and decided to visit a lesson on harmony analysis to know how does the professor look like, at least. Danil was very bored on this lesson until the teacher gave the group a simple task: find 4 vectors in 4-dimensional space, such that every coordinate of every vector is 1 or  - 1 and any two vectors are orthogonal. Just as a reminder, two vectors in n-dimensional space are considered to be orthogonal if and only if their scalar product is equal to zero, that is: $\\\\sum_{i = 1}^{n} a_{i} \\\\cdot b_{i} = 0$.\\n\\nDanil quickly managed to come up with the solution for this problem and the teacher noticed that the problem can be solved in a more general case for 2^{k} vectors in 2^{k}-dimensinoal space. When Danil came home, he quickly came up with the solution for this problem. Can you cope with it?\\n\\n\\n-----Input-----\\n\\nThe only line of the input contains a single integer k (0 ≤ k ≤ 9).\\n\\n\\n-----Output-----\\n\\nPrint 2^{k} lines consisting of 2^{k} characters each. The j-th character of the i-th line must be equal to ' * ' if the j-th coordinate of the i-th vector is equal to  - 1, and must be equal to ' + ' if it's equal to  + 1. It's guaranteed that the answer always exists.\\n\\nIf there are many correct answers, print any.\\n\\n\\n-----Examples-----\\nInput\\n2\\n\\nOutput\\n++**\\n+*+*\\n++++\\n+**+\\n\\n\\n-----Note-----\\n\\nConsider all scalar products in example:  Vectors 1 and 2: ( + 1)·( + 1) + ( + 1)·( - 1) + ( - 1)·( + 1) + ( - 1)·( - 1) = 0  Vectors 1 and 3: ( + 1)·( + 1) + ( + 1)·( + 1) + ( - 1)·( + 1) + ( - 1)·( + 1) = 0  Vectors 1 and 4: ( + 1)·( + 1) + ( + 1)·( - 1) + ( - 1)·( - 1) + ( - 1)·( + 1) = 0  Vectors 2 and 3: ( + 1)·( + 1) + ( - 1)·( + 1) + ( + 1)·( + 1) + ( - 1)·( + 1) = 0  Vectors 2 and 4: ( + 1)·( + 1) + ( - 1)·( - 1) + ( + 1)·( - 1) + ( - 1)·( + 1) = 0  Vectors 3 and 4: ( + 1)·( + 1) + ( + 1)·( - 1) + ( + 1)·( - 1) + ( + 1)·( + 1) = 0\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"k = int(input())\\n\\nif (k == 0):\\n    print('+')\\n    return\\n\\nanswer = [['+', '+'], ['+', '*']]\\nlength = 2\\nfor i in range(k - 1):\\n    new = []\\n    for i in answer:\\n        temp = []\\n        for j in range(length):\\n            if i[j] == '+':\\n                temp += ['+', '+']\\n            else:\\n                temp += ['*', '*']\\n        new.append(temp)\\n    for i in answer:\\n        temp = []\\n        for j in range(length):\\n            if i[j] == '+':\\n                temp += ['+', '*']\\n            else:\\n                temp += ['*', '+']\\n        new.append(temp)\\n    answer = new\\n    length *= 2\\n\\nprint('\\\\n'.join([''.join(i) for i in answer]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc048\\/tasks\\/arc064_a:\\nThere are N boxes arranged in a row.\\nInitially, the i-th box from the left contains a_i candies.\\nSnuke can perform the following operation any number of times:\\n - Choose a box containing at least one candy, and eat one of the candies in the chosen box.\\nHis objective is as follows:\\n - Any two neighboring boxes contain at most x candies in total.\\nFind the minimum number of operations required to achieve the objective.\\n\\n-----Constraints-----\\n - 2 ≤ N ≤ 10^5\\n - 0 ≤ a_i ≤ 10^9\\n - 0 ≤ x ≤ 10^9\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\nN x\\na_1 a_2 ... a_N\\n\\n-----Output-----\\nPrint the minimum number of operations required to achieve the objective.\\n\\n-----Sample Input-----\\n3 3\\n2 2 2\\n\\n-----Sample Output-----\\n1\\n\\nEat one candy in the second box.\\nThen, the number of candies in each box becomes (2, 1, 2).\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N, x = map(int, input().split())\\na = list(map(int, input().split()))\\n\\nr1 = sum(a)\\nflow = 0\\n\\nfor i in range(1, N):\\n    t = (a[i] + a[i - 1]) - x\\n    if flow != 0:\\n        a[i-1] -= flow\\n        t -= flow\\n        flow = 0\\n\\n    if t > 0:\\n        if t > a[i]:\\n            t -= a[i]\\n            a[i - 1] -= t\\n            t = a[i]\\n\\n        flow = t\\n\\na[-1] -= flow\\n\\nr2 = sum(a)\\n\\nprint(r1 - r2)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou need count how many valleys you will pass.\\n\\nStart is always from zero level.\\n\\nEvery time you go down below 0 level counts as an entry of a valley, and as you go up to 0 level from valley counts as an exit of a valley.\\n\\nOne passed valley is equal one entry and one exit of a valley.\\n```\\ns='FUFFDDFDUDFUFUF'\\nU=UP\\nF=FORWARD\\nD=DOWN\\n```\\n\\nTo represent string above\\n```\\n(level 1)  __\\n(level 0)_\\/  \\\\         _(exit we are again on level 0)\\n(entry-1)     \\\\_     _\\/\\n(level-2)       \\\\\\/\\\\_\\/\\n```\\nSo here we passed one valley\",\"targets\":\"def counting_valleys(s):\\n    r = l = 0\\n    for x in s:\\n        if x == \\\"U\\\" and l == -1: r += 1\\n        if x != \\\"F\\\": l += 1 if x == \\\"U\\\" else -1\\n    return r\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/SAD:\\nOur Chef is very happy that his son was selected for training in one of the finest culinary schools of the world.\\nSo he and his wife decide to buy a gift for the kid as a token of appreciation.\\nUnfortunately, the Chef hasn't been doing good business lately, and is in no mood on splurging money.\\nOn the other hand, the boy's mother wants to buy something big and expensive.\\nTo settle the matter like reasonable parents, they play a game.\\n\\nThey spend the whole day thinking of various gifts and write them down in a huge matrix.\\nEach cell of the matrix contains the gift's cost.\\nThen they decide that the mother will choose a row number r while the father will choose a column number c,\\nthe item from the corresponding cell will be gifted to the kid in a couple of days. \\n\\nThe boy observes all of this secretly.\\nHe is smart enough to understand that his parents will ultimately choose a gift whose cost is smallest in its row,\\nbut largest in its column.\\nIf no such gift exists, then our little chef has no option but to keep guessing.\\nAs the matrix is huge, he turns to you for help.\\n\\nHe knows that sometimes the gift is not determined uniquely even if a gift exists whose cost is smallest in its row,\\nbut largest in its column.\\nHowever, since the boy is so smart, he realizes that the gift's cost is determined uniquely.\\nYour task is to tell him the gift's cost which is smallest in its row,\\nbut largest in its column, or to tell him no such gift exists.\\n\\n-----Input-----\\nFirst line contains two integers R and C, the number of rows and columns in the matrix respectively. Then follow R lines, each containing C space separated integers - the costs of different gifts.\\n\\n-----Output-----\\nPrint a single integer - a value in the matrix that is smallest in its row but highest in its column. If no such value exists, then print \\\"GUESS\\\" (without quotes of course) \\n\\n-----Constraints-----\\n1 <= R, C <= 100 \\nAll gift costs are positive and less than 100000000 (10^8) \\n\\n-----Example 1-----\\nInput:\\n2 3\\n9 8 8\\n2 6 11\\n\\nOutput:\\n8\\n\\n-----Example...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"r,c=map(int,input().split())\\r\\nmat=[]\\r\\nrmin=[]\\r\\ncmax=[]\\r\\nd={}\\r\\nf=0\\r\\nfor i in range(r):\\r\\n    l=list(map(int,input().split()))\\r\\n    mat.append(l)\\r\\nfor i in range(r):\\r\\n    x=min(mat[i])\\r\\n    rmin.append(x)\\r\\nfor i in range(c):\\r\\n    x=[]\\r\\n    for j in range(r):\\r\\n        x.append(mat[j][i])\\r\\n    cmax.append(max(x))\\r\\nfor i in rmin:\\r\\n    if(i in cmax):\\r\\n        print(i)\\r\\n        f=1\\r\\n        break\\r\\nif(f==0):\\r\\n    print(\\\"GUESS\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/376\\/A:\\nYou have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the Ox axis between points 0 and |s| - 1.\\n\\nThe decoding of the lever description is given below.\\n\\n  If the i-th character of the string equals \\\"^\\\", that means that at coordinate i there is the pivot under the bar.  If the i-th character of the string equals \\\"=\\\", that means that at coordinate i there is nothing lying on the bar.  If the i-th character of the string equals digit c (1-9), that means that at coordinate i there is a weight of mass c on the bar. \\n\\nYour task is, given the lever description, print if it will be in balance or not. Assume that the bar doesn't weight anything. Assume that the bar initially is in balance then all weights are simultaneously put on it. After that the bar either tilts to the left, or tilts to the right, or is in balance.\\n\\n\\n-----Input-----\\n\\nThe first line contains the lever description as a non-empty string s (3 ≤ |s| ≤ 10^6), consisting of digits (1-9) and characters \\\"^\\\" and \\\"=\\\". It is guaranteed that the line contains exactly one character \\\"^\\\". It is guaranteed that the pivot of the lever isn't located in any end of the lever bar.\\n\\nTo solve the problem you may need 64-bit integer numbers. Please, do not forget to use them in your programs.\\n\\n\\n-----Output-----\\n\\nPrint \\\"left\\\" if the given lever tilts to the left, \\\"right\\\" if it tilts to the right and \\\"balance\\\", if it is in balance.\\n\\n\\n-----Examples-----\\nInput\\n=^==\\n\\nOutput\\nbalance\\n\\nInput\\n9===^==1\\n\\nOutput\\nleft\\n\\nInput\\n2==^7==\\n\\nOutput\\nright\\n\\nInput\\n41^52==\\n\\nOutput\\nbalance\\n\\n\\n\\n-----Note-----\\n\\nAs you solve the problem, you may find the following link useful to better understand how a lever functions: http:\\/\\/en.wikipedia.org\\/wiki\\/Lever.\\n\\nThe pictures to the examples:\\n\\n [Image] \\n\\n [Image] \\n\\n [Image] \\n\\n $\\\\Delta \\\\Delta \\\\Delta \\\\Delta$\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"s = input()\\nfor i in range(len(s)):\\n    if s[i] == '^':\\n        o = i\\nl = s[0:o]\\nr = s[o+1:len(s)]\\nl_sum = r_sum = 0\\nfor i in range(len(l)):\\n    if not (l[i] == '='):\\n        l_sum += int(l[i]) * (len(l) - i)\\n        \\nfor i in range(len(r)):\\n    if not (r[i] == '='):\\n        r_sum += int(r[i]) * (i+1)# + 1)\\nif l_sum < r_sum:\\n    print('right')\\nelif l_sum > r_sum:\\n    print('left')\\nelse:\\n    print('balance')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55738b0cffd95756c3000056:\\n### Preface\\nYou are currently working together with a local community to build a school teaching children how to code. First plans have been made and the community wants to decide on the best location for the coding school.\\nIn order to make this decision data about the location of students and potential locations is collected. \\n\\n### Problem\\nIn order to be able to attract and teach as many students as possible we want to minimize the total traveling distance for potential students. The streets system is organized in a traditional grid system and students can only travel horizontally or vertically (not diagonal).\\n\\nThe locations of interested students is given as an array with the first value of each entry presenting the x coordinate and the second value presenting the y coordinate:\\n```python\\nstudents = [[3,7],[2,2],[14,1], ...];\\n```\\nPotential locations are passed as an array of objects with an unique id, a x and y coordinate:\\n```python\\nlocations = [{\\\"id\\\": 1, \\\"x\\\": 3, \\\"y\\\": 4}, {\\\"id\\\": 2, \\\"x\\\": 8, \\\"y\\\": 2}, ...];\\n```\\n\\nYour task is now to evaluate which of the school locations would be best to minimize the distance for all potential students to the school.\\n\\nThe desired output should consist of a string indicating the ID of the best suitable location and the x and y coordinates in the following form:\\n\\n```\\n\\\"The best location is number 1 with the coordinates x = 3 and y = 4\\\"\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def optimum_location(students, locations):\\n  best = min(locations, key = lambda loc: sum(abs(abs(loc['x']-x) + abs(loc['y']-y)) for x, y in students))\\n  return f'The best location is number {best[\\\"id\\\"]} with the coordinates x = {best[\\\"x\\\"]} and y = {best[\\\"y\\\"]}'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5b39e3772ae7545f650000fc:\\nYour task is to remove all duplicate words from a string, leaving only single (first) words entries.\\n\\nExample:\\n\\nInput:\\n\\n'alpha beta beta gamma gamma gamma delta alpha beta beta gamma gamma gamma delta'\\n\\nOutput:\\n\\n'alpha beta gamma delta'\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def remove_duplicate_words(s):\\n    final = []\\n    for w in s.split(' '):\\n        if w not in final:\\n            final.append(w)\\n    return ' '.join(final)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nComplete the function which takes two arguments and returns all numbers which are divisible by the given divisor. First argument is an array of `numbers` and the second is the `divisor`.\\n\\n## Example\\n\\n```python\\ndivisible_by([1, 2, 3, 4, 5, 6], 2) == [2, 4, 6]\\n```\",\"targets\":\"def divisible_by(numbers, divisor):\\n    z =[]\\n    for k in numbers:\\n        if k % divisor == 0:\\n            z.append(k)\\n    return z\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/59f33b86a01431d5ae000032:\\nThe [half-life](https:\\/\\/en.wikipedia.org\\/wiki\\/Half-life) of a radioactive substance is the time it takes (on average) for one-half of its atoms to undergo radioactive decay.\\n\\n# Task Overview\\nGiven the initial quantity of a radioactive substance, the quantity remaining after a given period of time, and the period of time, return the half life of that substance. \\n\\n# Usage Examples\\n\\n```if:csharp\\nDocumentation:\\nKata.HalfLife Method (Double, Double, Int32)\\n\\nReturns the half-life for a substance given the initial quantity, the remaining quantity, and the elasped time.\\n\\nSyntax\\n\\n\\npublic\\nstatic\\ndouble HalfLife(\\ndouble quantityInitial,\\n    double quantityRemaining,\\nint time\\n    )\\n  \\n\\n\\n\\nParameters\\n\\nquantityInitial\\n\\nType: System.Double\\nThe initial amount of the substance.\\n\\nquantityRemaining\\n\\nType: System.Double\\nThe current amount of the substance.\\n\\ntime\\n\\nType: System.Int32\\nThe amount of time elapsed.\\n\\nReturn Value\\n\\nType: System.Double\\n  A floating-point number representing the half-life of the substance.\\n\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\ndef half_life(q0, q1, t):\\n   return 1\\/(math.log(q0\\/q1)\\/(t*math.log(2)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn this problem, your task is to use ASCII graphics to paint a cardiogram. \\n\\nA cardiogram is a polyline with the following corners:$(0 ; 0),(a_{1} ; a_{1}),(a_{1} + a_{2} ; a_{1} - a_{2}),(a_{1} + a_{2} + a_{3} ; a_{1} - a_{2} + a_{3}), \\\\ldots,(\\\\sum_{i = 1}^{n} a_{i} ; \\\\sum_{i = 1}^{n}(- 1)^{i + 1} a_{i})$\\n\\nThat is, a cardiogram is fully defined by a sequence of positive integers a_1, a_2, ..., a_{n}.\\n\\nYour task is to paint a cardiogram by given sequence a_{i}.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (2 ≤ n ≤ 1000). The next line contains the sequence of integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 1000). It is guaranteed that the sum of all a_{i} doesn't exceed 1000.\\n\\n\\n-----Output-----\\n\\nPrint max |y_{i} - y_{j}| lines (where y_{k} is the y coordinate of the k-th point of the polyline), in each line print $\\\\sum_{i = 1}^{n} a_{i}$ characters. Each character must equal either « \\/ » (slash), « \\\\ » (backslash), « » (space). The printed image must be the image of the given polyline. Please study the test samples for better understanding of how to print a cardiogram.\\n\\nNote that in this problem the checker checks your answer taking spaces into consideration. Do not print any extra characters. Remember that the wrong answer to the first pretest doesn't give you a penalty.\\n\\n\\n-----Examples-----\\nInput\\n5\\n3 1 2 5 1\\n\\nOutput\\n      \\/ \\\\     \\n   \\/ \\\\ \\/   \\\\    \\n  \\/       \\\\   \\n \\/         \\\\  \\n          \\\\ \\/ \\n\\nInput\\n3\\n1 5 1\\n\\nOutput\\n \\/ \\\\     \\n  \\\\    \\n   \\\\   \\n    \\\\  \\n     \\\\ \\/\",\"targets\":\"n = int(input())\\na_list = list(map(int, list(str(input()).split(\\\" \\\"))))\\n\\nout = [' '*(sum(a_list))]*2000\\ncur,pref_size = 1000, 0\\ncur_max, cur_min = 1000,1000\\nfor k in range(n):\\n    for i in range(a_list[k]):\\n        ind = pref_size + i\\n        if k % 2 == 0:\\n            out[cur] = out[cur][:ind] + '\\/' + out[cur][ind+1:]\\n            cur += 1\\n        else:\\n            out[cur] = out[cur][:ind] + '\\\\\\\\' + out[cur][ind+1:]\\n            cur -= 1\\n\\n    if k % 2 == 1:\\n        cur += 1\\n        cur_min = min(cur_min, cur)\\n    else:\\n        cur -= 1\\n        cur_max = max(cur_max, cur)\\n        \\n    pref_size += a_list[k]\\n\\nfor i in range(cur_max,cur_min-1,-1):\\n    print(out[i])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYour friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.\\n\\nYou are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.\\n\\nYou would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.\\n\\n\\n-----Input-----\\n\\nThe first line of the input will contain a single integer, n (1 ≤ n ≤ 100 000).\\n\\n\\n-----Output-----\\n\\nOutput a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.\\n\\n\\n-----Examples-----\\nInput\\n1\\n\\nOutput\\n1\\n\\nInput\\n2\\n\\nOutput\\n2\\n\\nInput\\n3\\n\\nOutput\\n2 1\\n\\nInput\\n8\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.\\n\\nIn the second sample, we perform the following steps:\\n\\nInitially we place a single slime in a row by itself. Thus, row is initially 1.\\n\\nThen, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.\\n\\nIn the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.\\n\\nIn the last sample, the steps look as follows:   1  2  2 1  3  3 1  3 2  3 2 1  4\",\"targets\":\"def get(k):\\n    find = False\\n    for i in range(len(k)):\\n        if k[i] == 0:\\n            k[i] = 1\\n            break\\n        else:\\n            k[i] = 0\\n    else:\\n        k.append(1)\\n    return k\\n\\n\\nn = int(input())\\nk = []\\nfor i in range(n):\\n    k = get(k)\\nfor i in range(len(k) - 1, -1, -1):\\n    if k[i]:\\n        print(i + 1, end=' ')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe term of this problem is the same as the previous one, the only exception — increased restrictions.\\n\\n\\n-----Input-----\\n\\nThe first line contains two positive integers n and k (1 ≤ n ≤ 100 000, 1 ≤ k ≤ 10^9) — the number of ingredients and the number of grams of the magic powder.\\n\\nThe second line contains the sequence a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9), where the i-th number is equal to the number of grams of the i-th ingredient, needed to bake one cookie.\\n\\nThe third line contains the sequence b_1, b_2, ..., b_{n} (1 ≤ b_{i} ≤ 10^9), where the i-th number is equal to the number of grams of the i-th ingredient, which Apollinaria has.\\n\\n\\n-----Output-----\\n\\nPrint the maximum number of cookies, which Apollinaria will be able to bake using the ingredients that she has and the magic powder.\\n\\n\\n-----Examples-----\\nInput\\n1 1000000000\\n1\\n1000000000\\n\\nOutput\\n2000000000\\n\\nInput\\n10 1\\n1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000\\n1 1 1 1 1 1 1 1 1 1\\n\\nOutput\\n0\\n\\nInput\\n3 1\\n2 1 4\\n11 3 16\\n\\nOutput\\n4\\n\\nInput\\n4 3\\n4 3 5 6\\n11 12 14 20\\n\\nOutput\\n3\",\"targets\":\"n,k = list(map(int, input().split()))\\na = (list(map(int, input().split())))\\nb = (list(map(int, input().split())))\\nc = list(zip(a,b))\\nc.sort(key=lambda x:(x[1]\\/\\/x[0]))\\ni = 0\\ncount = c[0][1]\\/\\/c[0][0]\\npart = 0\\nfull = 0\\nwhile k>0 and i<n:\\n    if count < c[i][1]\\/\\/c[i][0]:\\n        if k>part:\\n            k-=part\\n            part = 0\\n            count += 1\\n            dco = min(c[i][1]\\/\\/c[i][0]-count, k\\/\\/full)\\n            count += dco\\n            k -= dco*full\\n            part = full+c[i][0] - c[i][1]%c[i][0]\\n            full += c[i][0]\\n        else:\\n            break\\n    else:\\n        part += c[i][0] - c[i][1]%c[i][0]\\n        full += c[i][0]\\n    #~ print(part, full)\\n    i+=1\\nif k>part:\\n    count += 1\\n    k-=part\\ncount += k\\/\\/full\\nprint(count)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/open.kattis.com\\/problems\\/contacttracing:\\nA deadly virus is sweeping across the globe! You are part of an elite group of programmers tasked with tracking the spread of the virus. You have been given the timestamps of people entering and exiting a room. Now your job is to determine how the virus will spread. Hurry up, time is of the essence!\\n\\nThere are $N$ people in this scenario, numbered from $1$ to $N$. Every day, the $i$th person enters and exits the room at time $s_ i$ and $t_ i$ respectively. At the beginning of the $1$st day, there are $C$ people infected with the virus, whose indices will be given in the input.\\n\\nWhen an infected person comes into contact with an uninfected person, the uninfected person will become infected at the start of the next day. Hence, they can only start spreading the infection from the next day onward. An infected person will always remain infected.\\n\\nTwo people are in contact with each other if they are in the room at the same time. This includes cases where one person leaves and another person enters at the exact same time. Also, if a person enters and exits the room at the same time ($s_ i$ = $t_ i$), they are considered to be in contact with everyone in the room at that time. Due to safe-distancing requirements, no more than $50$ people can be in the room at one time.\\n\\nYour job is to print the indices of the people who will be infected after $D$ days. This includes people who came into contact with an infected person on the $D$th day but will only become infected at the start of the $D+1$th day.\\n\\nGiven below are the visualizations for sample inputs $1$ and $2$.\\n\\nNote: In sample $2$, person $2$ and $4$ will get infected after day $1$. They can only spread the infection to person $3$ and $5$ on day $2$. For $D = 1$, the infected people are $1$, $2$, $4$. If $D$ had been $2$, person $3$ and $5$ would have also been infected.\\n\\n-----Input-----\\nThe first line contains two integers, $1 \\\\le N \\\\le 20000$, and $1 \\\\le D \\\\le 50000$, the number of people and number of days respectively.\\n\\nThe second line contains an integer $1...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N = int(input())\\nA = [int(a) for a in input().split()]\\n\\nn1 = A.count(1)\\nn2 = A.count(2)\\n\\nif n1*n2==0:\\n    print(*A)\\nelse:\\n    s1 = (n1-1)\\/\\/2*2\\n    ANS = [2,1]+[1]*s1+[2]*(n2-1)+[1]*(n1-1-s1)\\n    print(*ANS)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nBill is a famous mathematician in BubbleLand. Thanks to his revolutionary math discoveries he was able to make enough money to build a beautiful house. Unfortunately, for not paying property tax on time, court decided to punish Bill by making him lose a part of his property.\\n\\nBill’s property can be observed as a convex regular 2n-sided polygon A_0 A_1... A_2n - 1 A_2n,  A_2n =  A_0, with sides of the exactly 1 meter in length. \\n\\nCourt rules for removing part of his property are as follows:  Split every edge A_{k} A_{k} + 1,  k = 0... 2n - 1 in n equal parts of size 1 \\/ n with points P_0, P_1, ..., P_{n} - 1  On every edge A_2k A_2k + 1,  k = 0... n - 1 court will choose one point B_2k =  P_{i} for some i = 0, ...,  n - 1 such that $\\\\cup_{i = 0}^{n - 1} B_{2i} = \\\\cup_{i = 0}^{n - 1} P_{i}$  On every edge A_2k + 1A_2k + 2,  k = 0...n - 1 Bill will choose one point B_2k + 1 =  P_{i} for some i = 0, ...,  n - 1 such that $\\\\cup_{i = 0}^{n - 1} B_{2 i + 1} = \\\\cup_{i = 0}^{n - 1} P_{i}$  Bill gets to keep property inside of 2n-sided polygon B_0 B_1... B_2n - 1 \\n\\nLuckily, Bill found out which B_2k points the court chose. Even though he is a great mathematician, his house is very big and he has a hard time calculating. Therefore, he is asking you to help him choose points so he maximizes area of property he can keep.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer number n (2 ≤ n ≤ 50000), representing number of edges of 2n-sided polygon.\\n\\nThe second line contains n distinct integer numbers B_2k (0 ≤ B_2k ≤ n - 1,  k = 0... n - 1) separated by a single space, representing points the court chose. If B_2k = i, the court chose point P_{i} on side A_2k A_2k + 1.\\n\\n\\n-----Output-----\\n\\nOutput contains n distinct integers separated by a single space representing points B_1, B_3, ..., B_2n - 1 Bill should choose in order to maximize the property area. If there are multiple solutions that maximize the area, return any of them.\\n\\n\\n-----Example-----\\nInput\\n3\\n0 1 2\\n\\nOutput\\n0 2 1\\n\\n\\n\\n-----Note-----\\n\\nTo maximize area Bill should...\",\"targets\":\"n = int(input())\\na = input().split()\\nfor i in range(n):\\n    a[i] = int(a[i])\\nb = []\\nfor i in range(0, n-1):\\n    b.append((a[i]-(n-a[i+1]), i))\\nb.append((a[n-1]-(n-a[0]), n-1))\\nb = sorted(b)\\nans = n*[0]\\nfor i in range(n):\\n    # the line segment at index b[i][1]\\n    ans[b[i][1]] = i\\nfor i in range(n):\\n    print(ans[i], end = ' ')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef has an array A consisting of N integers. He also has an intger K.\\nChef wants you to find out number of different arrays he can obtain from array A by applying the following operation exactly K times.\\n\\n- Pick some element in the array and multiply it by -1\\n\\nAs answer could be quite large, print it modulo 109 + 7.\\n\\n-----Input-----\\n- The first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows.\\n- The first line of each test case contains two space separated integers N, K as defined above.\\n- The second line contains N space-separated integers A1, A2, ..., AN denoting the elements of the array.\\n\\n-----Output-----\\n- For each test case, output a single line containing an integer corresponding to the number of different arrays Chef can get modulo 109 + 7.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 10\\n- 1 ≤ N, K ≤ 105\\n- -106 ≤ Ai ≤ 106\\n\\n-----Subtasks-----\\n- Subtask #1 (10 points) : N, K ≤ 10\\n- Subtask #2 (30 points) : N, K ≤ 100\\n- Subtask #3 (60 points) : N, K ≤ 105\\n\\n-----Example-----\\nInput:\\n3\\n1 3\\n100\\n3 1\\n1 2 1\\n3 2\\n1 2 1\\n\\nOutput:\\n1\\n3\\n4\\n\\n-----Explanation-----\\nExample case 1.\\nChef has only one element and must apply the operation 3 times to it. After applying the operations, he will end up with -100. That is the only array he will get.\\n\\nExample case 2.\\nChef can apply operation to one of three elements. So, he can obtain three different arrays.\\n\\nExample case 3.\\nNote that other than applying operation to positions (1, 2), (1, 3), (2, 3), Chef can also apply the operation twice on some element and get the original.\\n\\nIn summary, Chef can get following four arrays.\\n\\n[1, 2, 1]\\n[-1, -2, 1]\\n[-1, 2, -1]\\n[1, -2, -1]\",\"targets\":\"mod = 10**9 + 7\\nmod2 = 10**50\\nfor t in range(int(input())):\\n n, k = list(map(int, input().split()))\\n a = list(map(int, input().split()))\\n ans = 0\\n temp = 1\\n limit = min(n,k)+1\\n c = a.count(0)\\n if (c == 0):\\n  x = k%2\\n  for i in range(0, limit):\\n   if (i%2 == x):\\n    ans += temp\\n    ans %= mod\\n   temp = (temp * (n-i)) \\/ (1+i)\\n   temp %= mod2\\n else:\\n  n = n-c\\n  for i in range(0, limit):\\n   ans += temp\\n   ans %= mod\\n   temp = (temp * (n-i)) \\/ (1+i)\\n   temp %= mod2\\n print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc080\\/tasks\\/abc080_c:\\nJoisino is planning to open a shop in a shopping street.\\nEach of the five weekdays is divided into two periods, the morning and the evening. For each of those ten periods, a shop must be either open during the whole period, or closed during the whole period. Naturally, a shop must be open during at least one of those periods.\\nThere are already N stores in the street, numbered 1 through N.\\nYou are given information of the business hours of those shops, F_{i,j,k}. If F_{i,j,k}=1, Shop i is open during Period k on Day j (this notation is explained below); if F_{i,j,k}=0, Shop i is closed during that period. Here, the days of the week are denoted as follows. Monday: Day 1, Tuesday: Day 2, Wednesday: Day 3, Thursday: Day 4, Friday: Day 5. Also, the morning is denoted as Period 1, and the afternoon is denoted as Period 2.\\nLet c_i be the number of periods during which both Shop i and Joisino's shop are open. Then, the profit of Joisino's shop will be P_{1,c_1}+P_{2,c_2}+...+P_{N,c_N}.\\nFind the maximum possible profit of Joisino's shop when she decides whether her shop is open during each period, making sure that it is open during at least one period.\\n\\n-----Constraints-----\\n - 1≤N≤100\\n - 0≤F_{i,j,k}≤1\\n - For every integer i such that 1≤i≤N, there exists at least one pair (j,k) such that F_{i,j,k}=1.\\n - -10^7≤P_{i,j}≤10^7\\n - All input values are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nF_{1,1,1} F_{1,1,2} ... F_{1,5,1} F_{1,5,2}\\n:\\nF_{N,1,1} F_{N,1,2} ... F_{N,5,1} F_{N,5,2}\\nP_{1,0} ... P_{1,10}\\n:\\nP_{N,0} ... P_{N,10}\\n\\n-----Output-----\\nPrint the maximum possible profit of Joisino's shop.\\n\\n-----Sample Input-----\\n1\\n1 1 0 1 0 0 0 1 0 1\\n3 4 5 6 7 8 9 -2 -3 4 -2\\n\\n-----Sample Output-----\\n8\\n\\nIf her shop is open only during the periods when Shop 1 is opened, the profit will be 8, which is the maximum possible profit.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from itertools import combinations\\n\\nn = int(input())\\nf = [list(map(int, input().split())) for _ in range(n)]\\np = [list(map(int, input().split())) for _ in range(n)]\\n\\nans = - 10 ** 18\\nfor i in range(1, 11):\\n    for pat in combinations(list(range(10)), i):\\n        cnt = [0] * n\\n        for e in pat:\\n            for j in range(n):\\n                cnt[j] += f[j][e]\\n\\n        score = 0\\n        for i, e in enumerate(cnt):\\n            score += p[i][e]\\n\\n        ans = max(ans, score)\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are N blocks arranged in a row. Let us paint these blocks.\\nWe will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.\\nFind the number of ways to paint the blocks under the following conditions:\\n - For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.\\n - There may be at most K pairs of adjacent blocks that are painted in the same color.\\nSince the count may be enormous, print it modulo 998244353.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq N, M \\\\leq 2 \\\\times 10^5\\n - 0 \\\\leq K \\\\leq N - 1\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M K\\n\\n-----Output-----\\nPrint the answer.\\n\\n-----Sample Input-----\\n3 2 1\\n\\n-----Sample Output-----\\n6\\n\\nThe following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.\",\"targets\":\"n,m,k=map(int,input().split())\\nmod=998244353\\ncntb=1\\nans=0\\nfor i in range(k+1):\\n    ans=ans+(((m*pow(m-1,n-1-i,mod))%mod)*cntb)%mod\\n    ans=ans%mod\\n    cntb=(cntb*(n-1-i)*pow(i+1,mod-2,mod))%mod\\nprint(ans%mod)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/357\\/A:\\nAt the beginning of the school year Berland State University starts two city school programming groups, for beginners and for intermediate coders. The children were tested in order to sort them into groups. According to the results, each student got some score from 1 to m points. We know that c_1 schoolchildren got 1 point, c_2 children got 2 points, ..., c_{m} children got m points. Now you need to set the passing rate k (integer from 1 to m): all schoolchildren who got less than k points go to the beginner group and those who get at strictly least k points go to the intermediate group. We know that if the size of a group is more than y, then the university won't find a room for them. We also know that if a group has less than x schoolchildren, then it is too small and there's no point in having classes with it. So, you need to split all schoolchildren into two groups so that the size of each group was from x to y, inclusive. \\n\\nHelp the university pick the passing rate in a way that meets these requirements.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer m (2 ≤ m ≤ 100). The second line contains m integers c_1, c_2, ..., c_{m}, separated by single spaces (0 ≤ c_{i} ≤ 100). The third line contains two space-separated integers x and y (1 ≤ x ≤ y ≤ 10000). At least one c_{i} is greater than 0.\\n\\n\\n-----Output-----\\n\\nIf it is impossible to pick a passing rate in a way that makes the size of each resulting groups at least x and at most y, print 0. Otherwise, print an integer from 1 to m — the passing rate you'd like to suggest. If there are multiple possible answers, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n5\\n3 4 3 2 1\\n6 8\\n\\nOutput\\n3\\n\\nInput\\n5\\n0 3 3 4 2\\n3 10\\n\\nOutput\\n4\\n\\nInput\\n2\\n2 5\\n3 6\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample the beginner group has 7 students, the intermediate group has 6 of them. \\n\\nIn the second sample another correct answer is 3.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"maximum = input()\\nm_int = list(map(int,input().split()))\\nsize = list(map(int,input().split()))\\nx = size[0]\\ny = size[1]\\n\\nbeginner = []\\nintermediate = []\\nfor i in range(len(m_int)):\\n    beginner.append(m_int[i])\\n    if sum(beginner) > y or sum(m_int[i+1:]) < x:\\n        del beginner[-1]\\n        break\\n    \\n\\nfor j in range(len(beginner),len(m_int)):\\n    intermediate.append(m_int[j])\\n\\nif (sum(intermediate) < x or sum(intermediate) > y) or (sum(beginner) < x or sum(beginner) > y):\\n    passing_rate = 0\\nelse:\\n    passing_rate = i+1\\nprint(passing_rate)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/ITRA2016\\/problems\\/ITRA06:\\nDivya's watch of worth Rs10 cr is abducted by N thieves(1,2....i...N). The fight over the watch leads to a final decision that it should belong to the thief who wins a simple game. The rules of the game state that every thief  registers a time in the format HH:MM:SS . Accordingly the average A of three clockwise angles  between the hours , minutes and seconds hands is calculated . Thus the ith thief  with the maximum A wins the game and gets to keep the watch.\\n\\nThe thieves are poor in mathematics and will need your help . Given the number of thieves and their registered time resolves the conflict and help them in choosing the winner \\n\\n-----Input-----\\nFirst line of input contains T which denotes the number of test cases.\\n\\nThe first line of each test case consists of an integer which denotes the number of thieves thereby N line follow which give the time choosen by each thieve in the format HH:MM:SS.\\n\\n-----Output:-----\\nOutput single integer i which denotes the ith thief.\\n\\n-----Constraints:-----\\n\\n1<=T<=100\\n\\n1<=N<=50\\n\\n01<=HH<=12\\n\\n00<=MM<=60\\n\\n00<=SS<=60\\n\\n-----Example:-----\\nInput:\\n2\\n3\\n12:28:26\\n07:26:04\\n11:23:17\\n2\\n07:43:25\\n06:23:34\\n\\nOutput:\\n3\\n1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for t in range(int(input())):\\n n = int(input())\\n mx = -1\\n for i in range(n):\\n  h, m, s = list(map(int,input().split(\\\":\\\")))\\n  h %= 12\\n  m %= 60\\n  s %= 60\\n  ha = h*30 + m*0.5 + s*0.5\\/60\\n  ma = m*6 + s*0.1\\n  sa = s*6\\n  \\n  hm1 = abs(ha - ma)\\n  hm2 = 360 - hm1\\n  hm3 = abs(hm1 - hm2)\\n  hm = min(hm1, hm2, hm3)\\n  \\n  ms1 = abs(ma - sa)\\n  ms2 = 360 - ms1\\n  ms3 = abs(ms1 - ms2)\\n  ms = min(ms1, ms2, ms3)\\n  \\n  sh1 = abs(sa - ha)\\n  sh2 = 360 - sh1\\n  sh3 = abs(sh1 - sh2)\\n  sh = min(sh1, sh2, sh3)\\n  \\n  avg = (hm + ms + sh) \\/ 3\\n  if (mx < avg):\\n   ans = i+1\\n   mx = avg\\n print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn this kata you will create a function that takes in a list and returns a list with the reverse order.\\n\\n### Examples\\n\\n```python\\nreverse_list([1,2,3,4]) == [4,3,2,1]\\nreverse_list([3,1,5,4]) == [4,5,1,3]\\n```\",\"targets\":\"reverse_list = lambda l: l[::-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nDo you know Professor Saeed? He is the algorithms professor at Damascus University. Yesterday, he gave his students hard homework (he is known for being so evil) - for a given binary string $S$, they should compute the sum of $F(S, L, R)$ over all pairs of integers $(L, R)$ ($1 \\\\le L \\\\le R \\\\le |S|$), where the function $F(S, L, R)$ is defined as follows:\\n- Create a string $U$: first, set $U = S$, and for each $i$ ($L \\\\le i \\\\le R$), flip the $i$-th character of $U$ (change '1' to '0' or '0' to '1').\\n- Then, $F(S, L, R)$ is the number of valid pairs $(i, i + 1)$ such that $U_i = U_{i+1}$.\\nAs usual, Professor Saeed will give more points to efficient solutions. Please help the students solve this homework.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first and only line of each test case contains a single string $S$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer $\\\\sum_{1 \\\\le L \\\\le R \\\\le |S|} F(S, L, R)$.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 100$\\n- $1 \\\\le |S| \\\\le 3 \\\\cdot 10^6$\\n- the sum of $|S|$ over all test cases does not exceed $6 \\\\cdot 10^6$\\n\\n-----Subtasks-----\\nSubtask #1 (50 points):\\n- $1 \\\\le |S| \\\\le 300$\\n- the sum of $|S|$ over all test cases does not exceed $600$\\nSubtask #2 (50 points): original constraints\\n\\n-----Example Input-----\\n1\\n001\\n\\n-----Example Output-----\\n6\\n\\n-----Explanation-----\\nExample case 1:\\n- $L = 1, R = 1$: $U$ is \\\"101\\\", $F = 0$\\n- $L = 2, R = 2$: $U$ is \\\"011\\\", $F = 1$\\n- $L = 3, R = 3$: $U$ is \\\"000\\\", $F = 2$\\n- $L = 1, R = 2$: $U$ is \\\"111\\\", $F = 2$\\n- $L = 2, R = 3$: $U$ is \\\"010\\\", $F = 0$\\n- $L = 1, R = 3$: $U$ is \\\"110\\\", $F = 1$\",\"targets\":\"# cook your dish here\\ndef solve():\\n t = int(input())\\n for i in range(0, t):\\n  s = input()\\n  \\n  ans = 0\\n  \\n  sums = 0\\n  \\n  for k in range(0,len(s)-1):\\n   if s[k] == s[k+1]:\\n    sums += 1\\n  \\n  ans = len(s)*(len(s)+1)\\/2*sums\\n  \\n  for l in range(0, len(s)):\\n   for r in range(l, len(s)):\\n    if l>0:\\n     if s[l-1] == s[l]:\\n      ans -= 1\\n     else:\\n      ans += 1\\n    if r<len(s)-1:\\n     if s[r] == s[r+1]:\\n      ans -= 1\\n     else:\\n      ans += 1\\n  print(int(ans))\\n  \\nsolve()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/59218bf66034acb9b7000040:\\n# Story\\n\\nOld MacDingle had a farm... \\n\\n...and on that farm he had\\n\\n* horses \\n* chickens \\n* rabbits \\n* some apple trees\\n* a vegetable patch\\n\\nEverything is idylic in the MacDingle farmyard **unless somebody leaves the gates open**\\n\\nDepending which gate was left open then...\\n\\n* horses might run away\\n* horses might eat the apples\\n* horses might eat the vegetables\\n* chickens might run away\\n* rabbits might run away\\n* rabbits might eat the vegetables\\n\\n# Kata Task\\n\\nGiven the state of the farm gates in the evening, your code must return what the farm looks like the next morning when daylight reveals what the animals got up to.\\n\\n# Legend\\n\\n* ```H``` horse\\n* ```C``` chicken\\n* ```R``` rabbit\\n* ```A``` apple tree\\n* ```V``` vegetables\\n* ```|``` gate (closed), \\n* ```\\\\``` or ```\\/``` gate (open)\\n* ```.``` everything else\\n\\n# Example\\n\\n\\nBefore\\n```|..HH....\\\\AAAA\\\\CC..|AAA\\/VVV\\/RRRR|CCC```\\n\\nAfter\\n```|..HH....\\\\....\\\\CC..|AAA\\/...\\/RRRR|...```\\nBecause:\\n\\nThe horses ate whatever apples they could get to\\nThe rabbits ate the vegetables\\nThe chickens ran away\\n\\n\\n\\n\\n# Notes\\n\\n* If the animals can eat things *and* also run away then they do **BOTH** - it is best not to run away when you are hungry!\\n* An animal cannot \\\"go around\\\" a closed gate...\\n* ...but it is possible to run away from the farm and then **RUN BACK** and re-enter though more open gates on the other side!\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"shut_the_gate=lambda s:'|'.join(w.translate(\\n{ord(c):set(w)&set('RH'[i:]or'@')and'.'or c for i,c in enumerate('VARCH')}\\n)for w in '@'.join(3*[s]).split('|')).split('@')[1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFox Ciel is playing a card game with her friend Jiro.\\n\\nJiro has n cards, each one has two attributes: position (Attack or Defense) and strength. Fox Ciel has m cards, each one has these two attributes too. It's known that position of all Ciel's cards is Attack.\\n\\nNow is Ciel's battle phase, Ciel can do the following operation many times:  Choose one of her cards X. This card mustn't be chosen before.  If Jiro has no alive cards at that moment, he gets the damage equal to (X's strength). Otherwise, Ciel needs to choose one Jiro's alive card Y, then:   If Y's position is Attack, then (X's strength)  ≥  (Y's strength) must hold. After this attack, card Y dies, and Jiro gets the damage equal to (X's strength) - (Y's strength).  If Y's position is Defense, then (X's strength)  >  (Y's strength) must hold. After this attack, card Y dies, but Jiro gets no damage.  \\n\\nCiel can end her battle phase at any moment (so, she can use not all her cards). Help the Fox to calculate the maximal sum of damage Jiro can get.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (1 ≤ n, m ≤ 100) — the number of cards Jiro and Ciel have.\\n\\nEach of the next n lines contains a string position and an integer strength (0 ≤ strength ≤ 8000) — the position and strength of Jiro's current card. Position is the string \\\"ATK\\\" for attack, and the string \\\"DEF\\\" for defense.\\n\\nEach of the next m lines contains an integer strength (0 ≤ strength ≤ 8000) — the strength of Ciel's current card.\\n\\n\\n-----Output-----\\n\\nOutput an integer: the maximal damage Jiro can get.\\n\\n\\n-----Examples-----\\nInput\\n2 3\\nATK 2000\\nDEF 1700\\n2500\\n2500\\n2500\\n\\nOutput\\n3000\\n\\nInput\\n3 4\\nATK 10\\nATK 100\\nATK 1000\\n1\\n11\\n101\\n1001\\n\\nOutput\\n992\\n\\nInput\\n2 4\\nDEF 0\\nATK 0\\n0\\n0\\n1\\n1\\n\\nOutput\\n1\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, Ciel has 3 cards with same strength. The best strategy is as follows. First she uses one of these 3 cards to attack \\\"ATK 2000\\\" card first, this attack destroys that card and Jiro gets 2500 - 2000 = 500 damage. Then she uses the second card to destroy the \\\"DEF 1700\\\"...\",\"targets\":\"n, m = map(int, input().split())\\na, d = [1e9], [1e9]\\nfor x in range(n):\\n    p, s = input().split()\\n    [d, a][p < 'B'].append(int(s))\\nv = [int(input()) for y in range(m)]\\nfor q in [a, d, v]: q.sort()\\ns = sum(v)\\ni = j = 0\\nfor t in v:\\n    if t > d[i]: s, i = s - t, i + 1\\n    elif t >= a[j]: s, j = s - a[j], j + 1\\nif i + j - n: s = 0\\nprint(max(s, sum(max(0, y - x) for x, y in zip(a, v[::-1]))))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/675\\/D:\\n(Легенда будет поправлена позже) У нас есть n целых чисел. Первое число становится корнем дерева, для остальных нужно реализовать добавление в дерево поиска и вывести для каждого n - 1 числа его непосредственного предка в дереве.\\n\\n\\n-----Входные данные-----\\n\\nВ первой строке записано одно целое число n (2 ≤ n ≤ 10^5) — количество чиcел. Во второй строке через пробел записаны n различных целых чисел a_{i} (1 ≤ a_{i} ≤ 10^9).\\n\\n\\n-----Выходные данные-----\\n\\nДля всех i > 1 выведите непосредственного предка a_{i}\\n\\n\\n-----Примеры-----\\nВходные данные\\n3\\n1 2 3\\n\\nВыходные данные\\n1 2\\n\\nВходные данные\\n5\\n4 2 3 1 6\\n\\nВыходные данные\\n4 2 2 4\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from bisect import bisect\\n\\nn = int(input())\\narray = [int(x) for x in input().split()]\\n\\ntree = []\\nans = [''] * n\\nfor i in range(n):\\n  item = array[i]\\n  index = bisect(tree, (item, i))\\n  if i != 0:\\n    if index == 0:\\n      ans[i] = str(tree[0][0])\\n    elif index == i:\\n      ans[i] = str(tree[i - 1][0])\\n    else:\\n      ans[i] = str(tree[index - 1][0] if tree[index - 1][1] > tree[index][1] else tree[index][0])\\n  tree[index:index] = [(item, i)]\\nprint(' '.join(ans[1:]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a string which consists of lowercase or uppercase letters, find the length of the longest palindromes that can be built with those letters.\\n\\nThis is case sensitive, for example \\\"Aa\\\" is not considered a palindrome here.\\n\\nNote:\\nAssume the length of given string will not exceed 1,010.\\n\\n\\nExample: \\n\\nInput:\\n\\\"abccccdd\\\"\\n\\nOutput:\\n7\\n\\nExplanation:\\nOne longest palindrome that can be built is \\\"dccaccd\\\", whose length is 7.\",\"targets\":\"class Solution:\\n     def longestPalindrome(self, s):\\n         \\\"\\\"\\\"\\n         :type s: str\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         base, extra, result = {}, 0, 0\\n         for letter in s:\\n             if letter in base:\\n                 base[letter] += 1\\n             else:\\n                 base[letter] = 1\\n         for value in base.values():\\n             if extra == 0 and value % 2 == 1:\\n                     extra += 1\\n             result += value \\/\\/ 2 * 2\\n         return result + extra\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/551186edce486caa61000f5c:\\n# Feynman's squares\\nRichard Phillips Feynman was a well-known American physicist and a recipient of the Nobel Prize in Physics. He worked in theoretical physics and pioneered the field of quantum computing.\\n\\nRecently, an old farmer found some papers and notes that are believed to have belonged to Feynman. Among notes about mesons and electromagnetism, there was a napkin where he wrote a simple puzzle: \\\"how many different squares are there in a grid of NxN squares?\\\".\\n\\nFor example, when N=2, the answer is 5: the 2x2 square itself, plus the four 1x1 squares in its corners:\\n\\n\\n\\n# Task\\n\\nYou have to write a function\\n\\n```python\\ndef count_squares(n):\\n```\\n\\nthat solves Feynman's question in general. The input to your function will always be a positive integer.\\n\\n#Examples\\n\\n```python\\ncount_squares(1) =  1\\ncount_squares(2) =  5\\ncount_squares(3) = 14\\n```\\n\\n(Adapted from the Sphere Online Judge problem SAMER08F by Diego Satoba)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def count_squares(n):     \\n    return n if n<2 else n ** 2 + count_squares(n-1)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/238\\/A:\\nA sequence of non-negative integers a_1, a_2, ..., a_{n} of length n is called a wool sequence if and only if there exists two integers l and r (1 ≤ l ≤ r ≤ n) such that $a_{l} \\\\oplus a_{l + 1} \\\\oplus \\\\cdots \\\\oplus a_{r} = 0$. In other words each wool sequence contains a subsequence of consecutive elements with xor equal to 0.\\n\\nThe expression $x \\\\oplus y$ means applying the operation of a bitwise xor to numbers x and y. The given operation exists in all modern programming languages, for example, in languages C++ and Java it is marked as \\\"^\\\", in Pascal — as \\\"xor\\\".\\n\\nIn this problem you are asked to compute the number of sequences made of n integers from 0 to 2^{m} - 1 that are not a wool sequence. You should print this number modulo 1000000009 (10^9 + 9).\\n\\n\\n-----Input-----\\n\\nThe only line of input contains two space-separated integers n and m (1 ≤ n, m ≤ 10^5).\\n\\n\\n-----Output-----\\n\\nPrint the required number of sequences modulo 1000000009 (10^9 + 9) on the only line of output.\\n\\n\\n-----Examples-----\\nInput\\n3 2\\n\\nOutput\\n6\\n\\n\\n\\n-----Note-----\\n\\nSequences of length 3 made of integers 0, 1, 2 and 3 that are not a wool sequence are (1, 3, 1), (1, 2, 1), (2, 1, 2), (2, 3, 2), (3, 1, 3) and (3, 2, 3).\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = map(int, input().split())\\ns, d = 1, 1000000009\\nk = pow(2, m, d) - 1\\nfor i in range(n): s, k = (s * k) % d, k - 1\\nprint(s)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/FRCPRT:\\nMandarin chinese\\n, Russian and Vietnamese as well.\\nYou are given a grid with $n$ rows and $m$ columns. Each cell of this grid can either be empty or it contains one particle. It can never contain more than one particle. Let's denote the cell in the $i$-th row and $j$-th column by $(i, j)$, with the top left corner being $(0, 0)$. From a cell $(i, j)$, a particle could move in one of the following four directions:\\n- to the left, i.e. to the cell $(i, j - 1)$\\n- to the right, i.e. to the cell $(i, j + 1)$\\n- up, i.e. to the cell $(i - 1, j)$\\n- down, i.e. to the cell $(i + 1, j)$\\nIt is not possible for a particle to move to a cell that already contains a particle or to a cell that does not exist (leave the grid).\\nIt is possible to apply a force in each of these directions. When a force is applied in a given direction, all particles will simultaneously start moving in this direction as long as it is still possible for them to move.\\nYou are given a sequence of forces. Each subsequent force is applied only after all particles have stopped moving. Determine which cells of the grid contain particles after all forces from this sequence are applied in the given order.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains two space-separated integers $n$ and $m$.\\n- $n$ lines describing the initial grid follow. For each $i$ ($1 \\\\le i \\\\le n$), the $i$-th of these lines contains a binary string with length $m$ describing the $i$-th row of the grid. For each $j$ ($1 \\\\le j \\\\le m$), if the $j$-th character of this string is '1', then the cell $(i, j)$ contains a particle, and if it is '0', then the cell $(i, j)$ is empty.\\n- The last line contains a single string $S$ describing the sequence of applied forces. Each character of this string corresponds to applying a force in some direction; forces applied in the directions left, right, up, down correspond to characters 'L', 'R', 'U', 'D'...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n for _ in range(int(input())):\\n  rows,column = map(int,input().split())\\n  arr = []\\n  for i in range(rows):\\n   arr.append(list(input()))\\n  string = input()\\n  last = string[-1]\\n  operation = Find(string,last)\\n  # print(operation)\\n  for i in string:\\n   if i == \\\"L\\\":\\n    arr = Left(arr)\\n   if i == \\\"R\\\":\\n    arr = Right(arr)\\n   if i == \\\"U\\\":\\n    arr = Transpose(arr)\\n    arr = Left(arr)\\n    arr = Transpose(arr)\\n   if i == \\\"D\\\":\\n    arr = Transpose(arr)\\n    arr = Right(arr)\\n    arr = Transpose(arr)\\n  for i in arr:\\n   print(i)\\ndef Left(arr):\\n for i in range(len(arr)):\\n  ans = arr[i].count(\\\"1\\\")\\n  arr[i] = \\\"1\\\"*ans + (len(arr[i]) - ans)*\\\"0\\\"\\n return arr\\ndef Right(arr):\\n for i in range(len(arr)):\\n  ans = arr[i].count(\\\"1\\\")\\n  arr[i] = (len(arr[i]) - ans)*\\\"0\\\"+\\\"1\\\"*ans\\n return arr\\ndef Transpose(arr):\\n ansss = []\\n ans = list(map(list, zip(*arr)))\\n for i in ans:\\n  ass = i\\n  hello = \\\"\\\"\\n  for j in ass:\\n   hello += j\\n  ansss.append(hello)\\n return ansss \\ndef Find(string,last):\\n oper = \\\"\\\"+last\\n for i in string[-2::-1]: \\n  if last == \\\"L\\\":\\n   if i in [\\\"D\\\",\\\"U\\\"]:\\n    oper = i + oper\\n    last = i\\n  if last == \\\"R\\\":\\n   if i in [\\\"D\\\",\\\"U\\\"]:\\n    oper = i + oper\\n    last = i\\n  if last == \\\"D\\\":\\n   if i in [\\\"L\\\",\\\"R\\\"]:\\n    oper = i + oper\\n    last = i\\n  if last == \\\"U\\\":\\n   if i in [\\\"L\\\",\\\"R\\\"]:\\n    oper = i + oper\\n    last = i \\n return oper\\n \\ndef __starting_point():\\n main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/MAXDIFF:\\nChef has gone shopping with his 5-year old son. They have bought N items so far. The items are numbered from 1 to N, and the item i weighs Wi grams.\\n\\nChef's son insists on helping his father in carrying the items. He wants his dad to give him a few items. Chef does not want to burden his son. But he won't stop bothering him unless he is given a few items to carry. So Chef decides to give him some items. Obviously, Chef wants to give the kid less weight to carry.\\n\\nHowever, his son is a smart kid. To avoid being given the bare minimum weight to carry, he suggests that the items are split into two groups, and one group contains exactly K items. Then Chef will carry the heavier group, and his son will carry the other group.\\n\\nHelp the Chef in deciding which items should the son take. Your task will be simple. Tell the Chef the maximum possible difference between the weight carried by him and the weight carried by the kid.\\n\\n-----Input:-----\\nThe first line of input contains an integer T, denoting the number of test cases. Then T test cases follow. The first line of each test contains two space-separated integers N and K. The next line contains N space-separated integers W1, W2, ..., WN.\\n\\n-----Output:-----\\nFor each test case, output the maximum possible difference between the weights carried by both in grams.\\n\\n-----Constraints:-----\\n- 1 ≤ T ≤ 100\\n- 1 ≤ K < N ≤ 100\\n- 1 ≤ Wi ≤ 100000 (105)\\n\\n-----Example:-----\\nInput:\\n2\\n5 2\\n8 4 5 2 10\\n8 3\\n1 1 1 1 1 1 1 1\\n\\nOutput:\\n17\\n2\\n\\n-----Explanation:-----\\nCase #1: The optimal way is that Chef gives his son K=2 items with weights 2 and 4. Chef carries the rest of the items himself. Thus the difference is: (8+5+10) − (4+2) = 23 − 6 = 17.\\n\\nCase #2: Chef gives his son 3 items and he carries 5 items himself.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nfor _ in range(int(input())):\\n n,k = map(int,input().split())\\n w = list(map(int,input().split()))\\n w.sort()\\n if k <= n\\/\\/2:\\n  s1 = sum(w[:k])\\n  s2 = sum(w[k:])\\n  print(abs(s2 - s1))\\n else:\\n  s1 = sum(w[n-k:])\\n  s2 = sum(w[:n-k])\\n  print(abs(s2-s1))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58545549b45c01ccab00058c:\\nCreate a function that returns the total of a meal including tip and tax. You should not tip on the tax.\\n\\nYou will be given the subtotal, the tax as a percentage and the tip as a percentage. Please round your result to two decimal places.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def calculate_total(subtotal, tax, tip):\\n    return round(subtotal * ( 1 + tax \\/ 100.0 + tip \\/100.0), 2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/re-findall-re-finditer\\/problem:\\n=====Function Descriptions=====\\nre.findall()\\n\\nThe expression re.findall() returns all the non-overlapping matches of patterns in a string as a list of strings.\\nCode\\n\\n>>> import re\\n>>> re.findall(r'\\\\w','http:\\/\\/www.hackerrank.com\\/')\\n['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']\\n\\nre.finditer()\\n\\nThe expression re.finditer() returns an iterator yielding MatchObject instances over all non-overlapping matches for the re pattern in the string.\\nCode\\n\\n>>> import re\\n>>> re.finditer(r'\\\\w','http:\\/\\/www.hackerrank.com\\/')\\n<callable-iterator object at 0x0266C790>\\n>>> map(lambda x: x.group(),re.finditer(r'\\\\w','http:\\/\\/www.hackerrank.com\\/'))\\n['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']\\n\\n=====Problem Statement=====\\nYou are given a string S. It consists of alphanumeric characters, spaces and symbols(+,-).\\nYour task is to find all the substrings of S that contains 2 or more vowels.\\nAlso, these substrings must lie in between 2 consonants and should contain vowels only.\\n\\nNote :\\nVowels are defined as: AEIOU and aeiou.\\nConsonants are defined as: QWRTYPSDFGHJKLZXCVBNM and qwrtypsdfghjklzxcvbnm.\\n\\n=====Input Format=====\\nA single line of input containing string S.\\n\\n=====Constraints=====\\n0<len(S)<100\\n\\n=====Output Format=====\\nPrint the matched substrings in their order of occurrence on separate lines.\\nIf no match is found, print -1.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import re\\ns = input()\\nresult = re.findall(r'(?<=[QWRTYPSDFGHJKLZXCVBNMqwrtypsdfghjklzxcvbnm])([AEIOUaeiou]{2,})(?=[QWRTYPSDFGHJKLZXCVBNMqwrtypsdfghjklzxcvbnm])',s)\\nif result:\\n    for i in result:\\n        print(i)\\nelse:\\n    print((-1))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55a29405bc7d2efaff00007c:\\nConsider the following numbers (where `n!` is `factorial(n)`):\\n```\\nu1 = (1 \\/ 1!) * (1!)\\nu2 = (1 \\/ 2!) * (1! + 2!)\\nu3 = (1 \\/ 3!) * (1! + 2! + 3!)\\n...\\nun = (1 \\/ n!) * (1! + 2! + 3! + ... + n!)\\n```\\n\\nWhich will win: `1 \\/ n!` or `(1! + 2! + 3! + ... + n!)`?\\n\\nAre these numbers going to `0` because of `1\\/n!` or to infinity due\\nto the sum of factorials or to another number?\\n\\n## Task\\nCalculate `(1 \\/ n!) * (1! + 2! + 3! + ... + n!)` \\nfor a given `n`, where `n` is an integer greater or equal to `1`.\\n\\nTo avoid discussions about rounding, return the result **truncated** to 6 decimal places, for example:\\n```\\n1.0000989217538616 will be truncated to 1.000098\\n1.2125000000000001 will be truncated to 1.2125\\n```\\n\\n## Remark\\nKeep in mind that factorials grow rather rapidly, and you need to handle large inputs.\\n\\n## Hint\\nYou could try to simplify the expression.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# truncate to 6 decimals\\ndef trunc(n):\\n    return float(str(n)[:8])\\n\\ndef going(n):\\n    sum = 1\\n    fact = 1.0\\n    for i in range(1,n):\\n        fact = fact\\/(n-i+1)\\n        sum += fact\\n    return trunc(sum)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe need a function ```count_sel()``` that receives an array or list of integers (positive and negative) and may give us the following information in the order and  structure presented bellow:\\n\\n```[(1), (2), (3), [[(4)], 5]]```\\n\\n(1) - Total amount of received integers.\\n\\n(2) - Total amount of different values the array has.\\n\\n(3) - Total amount of values that occur only once.\\n\\n(4) and (5) both in a list\\n\\n(4) - It is (or they are) the element(s) that has (or have) the maximum occurrence. If there are more than one, the elements should be sorted (by their value obviously)\\n\\n(5) - Maximum occurrence of the integer(s)\\n\\nLet's see some cases\\n```python\\n____ count_sel([-3, -2, -1, 3, 4, -5, -5, 5, -1, -5]) ----> [10, 7, 5, [[-5], 3]]\\n\\n(1) - The list has ten elements (10 numbers)\\n\\n(2) - We have seven different values: -5, -3, -2, -1, 3, 4, 5 (7 values)\\n\\n(3) - The numbers that occur only once: -3, -2, 3, 4, 5 (5 values)\\n\\n(4) and (5) - The number -5 occurs three times (3 occurrences)\\n\\n____ count_sel([4, 4, 2, -3, 1, 4, 3, 2, 0, -5, 2, -2, -2, -5]) ----> [14, 8, 4, [[2, 4], 3]]\\n```\\nEnjoy it and happy coding!!\",\"targets\":\"from collections import Counter, defaultdict\\n\\ndef count_sel(lst):\\n    c    = Counter(lst)\\n    freq = defaultdict(list)\\n    for n,v in c.items(): freq[v].append(n)\\n    maxF,fLst = max(freq.items(), default=(0,[]))\\n    \\n    return [len(lst),\\n            len(c),\\n            len(freq[1]),\\n            [ sorted(fLst),\\n              maxF] ]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5566b0dd450172dfc4000005:\\nAs part of this Kata, you need to find the length of the sequence in an array, between the first and the second occurrence of a specified number.\\n\\nFor example, for a given array `arr`\\n\\n    [0, -3, 7, 4, 0, 3, 7, 9]\\n    \\nFinding length between two `7`s like\\n    \\n    lengthOfSequence([0, -3, 7, 4, 0, 3, 7, 9], 7)\\n    \\nwould return `5`.\\n\\nFor sake of simplicity, there will only be numbers (positive or negative) in the supplied array.\\n\\nIf there are less or more than two occurrences of the number to search for, return `0`, or in Haskell, `Nothing`.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def length_of_sequence(arr, n):\\n    if arr.count(n) != 2:\\n        return 0\\n    a = arr.index(n)\\n    b = arr.index(n, a + 1)\\n    return b - a + 1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nKontti language is a finnish word play game.\\n\\nYou add `-kontti` to the end of each word and then swap their characters until and including the first vowel (\\\"aeiouy\\\"); \\n\\nFor example the word `tame` becomes `kome-tantti`; `fruity` becomes `koity-fruntti` and so on.\\n\\nIf no vowel is present, the word stays the same.\\n\\nWrite a string method that turns a sentence into kontti language!\",\"targets\":\"kontti=lambda s:' '.join((lambda i:i<len(w)and'ko'+w[i+1:]+'-'+w[:i+1]+'ntti'or w)(min(i for i,c in enumerate(w+'a')if c in'aeiouyAEIOUY'))for w in s.split())\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/690\\/C1:\\nOne particularly well-known fact about zombies is that they move and think terribly slowly. While we still don't know why their movements are so sluggish, the problem of laggy thinking has been recently resolved. It turns out that the reason is not (as previously suspected) any kind of brain defect – it's the opposite! Independent researchers confirmed that the nervous system of a zombie is highly complicated – it consists of n brains (much like a cow has several stomachs). They are interconnected by brain connectors, which are veins capable of transmitting thoughts between brains. There are two important properties such a brain network should have to function properly:   It should be possible to exchange thoughts between any two pairs of brains (perhaps indirectly, through other brains).  There should be no redundant brain connectors, that is, removing any brain connector would make property 1 false. \\n\\nIf both properties are satisfied, we say that the nervous system is valid. Unfortunately (?), if the system is not valid, the zombie stops thinking and becomes (even more) dead. Your task is to analyze a given nervous system of a zombie and find out whether it is valid.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two space-separated integers n and m (1 ≤ n, m ≤ 1000) denoting the number of brains (which are conveniently numbered from 1 to n) and the number of brain connectors in the nervous system, respectively. In the next m lines, descriptions of brain connectors follow. Every connector is given as a pair of brains a b it connects (1 ≤ a, b ≤ n, a ≠ b).\\n\\n\\n-----Output-----\\n\\nThe output consists of one line, containing either yes or no depending on whether the nervous system is valid.\\n\\n\\n-----Examples-----\\nInput\\n4 4\\n1 2\\n2 3\\n3 1\\n4 1\\n\\nOutput\\nno\\n\\nInput\\n6 5\\n1 2\\n2 3\\n3 4\\n4 5\\n3 6\\n\\nOutput\\nyes\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"l = []\\nwere = []\\n\\n\\ndef dfs(v):\\n    nonlocal l, were\\n    if not were:\\n        were = len(l) * [False]\\n    were[v] = True\\n    for i in l[v]:\\n        if not were[i]:\\n            dfs(i)\\n\\n\\nn, m = list(map(int, input().split()))\\nif m != n - 1:\\n    print(\\\"no\\\")\\nelse:\\n    l = [[] for i in range(n)]\\n    for i in range(m):\\n        a, b = list(map(int, input().split()))\\n        l[a - 1].append(b - 1)\\n        l[b - 1].append(a - 1)\\n\\n    dfs(0)\\n    f = True\\n    for i in were:\\n        f = f and i\\n\\n    if f:\\n        print(\\\"yes\\\")\\n    else:\\n        print(\\\"no\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nHongcow likes solving puzzles.\\n\\nOne day, Hongcow finds two identical puzzle pieces, with the instructions \\\"make a rectangle\\\" next to them. The pieces can be described by an n by m grid of characters, where the character 'X' denotes a part of the puzzle and '.' denotes an empty part of the grid. It is guaranteed that the puzzle pieces are one 4-connected piece. See the input format and samples for the exact details on how a jigsaw piece will be specified.\\n\\nThe puzzle pieces are very heavy, so Hongcow cannot rotate or flip the puzzle pieces. However, he is allowed to move them in any directions. The puzzle pieces also cannot overlap.\\n\\nYou are given as input the description of one of the pieces. Determine if it is possible to make a rectangle from two identical copies of the given input. The rectangle should be solid, i.e. there should be no empty holes inside it or on its border. Keep in mind that Hongcow is not allowed to flip or rotate pieces and they cannot overlap, i.e. no two 'X' from different pieces can share the same position.\\n\\n\\n-----Input-----\\n\\nThe first line of input will contain two integers n and m (1 ≤ n, m ≤ 500), the dimensions of the puzzle piece.\\n\\nThe next n lines will describe the jigsaw piece. Each line will have length m and will consist of characters '.' and 'X' only. 'X' corresponds to a part of the puzzle piece, '.' is an empty space.\\n\\nIt is guaranteed there is at least one 'X' character in the input and that the 'X' characters form a 4-connected region.\\n\\n\\n-----Output-----\\n\\nOutput \\\"YES\\\" if it is possible for Hongcow to make a rectangle. Output \\\"NO\\\" otherwise.\\n\\n\\n-----Examples-----\\nInput\\n2 3\\nXXX\\nXXX\\n\\nOutput\\nYES\\n\\nInput\\n2 2\\n.X\\nXX\\n\\nOutput\\nNO\\n\\nInput\\n5 5\\n.....\\n..X..\\n.....\\n.....\\n.....\\n\\nOutput\\nYES\\n\\n\\n\\n-----Note-----\\n\\nFor the first sample, one example of a rectangle we can form is as follows \\n\\n111222\\n\\n111222\\n\\n\\n\\nFor the second sample, it is impossible to put two of those pieces without rotating or flipping to form a rectangle.\\n\\nIn the third sample, we can shift the first tile by one to the right, and...\",\"targets\":\"def f():\\n    s=input().split()\\n    m=int(s[0])\\n    n=int(s[1])\\n    ss=[]\\n    for i in range(m):\\n        ss.append(input())\\n    for i in range(m):\\n        for j in range(n):\\n            if ss[i][j]=='X':\\n                return (ss,m,n,i,j)\\n\\ndef ff(ss,m,n):\\n    for k in range(m-1,-1,-1):\\n        for l in range(n-1,-1,-1):\\n            if ss[k][l]=='X':\\n                return (k,l)\\n\\nss,m,n,i,j=f()\\nk,l=ff(ss,m,n)\\nsss=[]\\nfor x in range(m):\\n    s=\\\"\\\"\\n    for y in range(n):\\n        if (i<=x and x<=k and j<=y and y<=l):\\n            s+=\\\"X\\\"\\n        else:\\n            s+=\\\".\\\"\\n    sss.append(s)\\nif(ss==sss):\\n    print(\\\"YES\\\")\\nelse:\\n    print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/894\\/B:\\nRalph has a magic field which is divided into n × m blocks. That is to say, there are n rows and m columns on the field. Ralph can put an integer in each block. However, the magic field doesn't always work properly. It works only if the product of integers in each row and each column equals to k, where k is either 1 or -1.\\n\\nNow Ralph wants you to figure out the number of ways to put numbers in each block in such a way that the magic field works properly. Two ways are considered different if and only if there exists at least one block where the numbers in the first way and in the second way are different. You are asked to output the answer modulo 1000000007 = 10^9 + 7.\\n\\nNote that there is no range of the numbers to put in the blocks, but we can prove that the answer is not infinity.\\n\\n\\n-----Input-----\\n\\nThe only line contains three integers n, m and k (1 ≤ n, m ≤ 10^18, k is either 1 or -1).\\n\\n\\n-----Output-----\\n\\nPrint a single number denoting the answer modulo 1000000007.\\n\\n\\n-----Examples-----\\nInput\\n1 1 -1\\n\\nOutput\\n1\\n\\nInput\\n1 3 1\\n\\nOutput\\n1\\n\\nInput\\n3 3 -1\\n\\nOutput\\n16\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the only way is to put -1 into the only block.\\n\\nIn the second example the only way is to put 1 into every block.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"\\\"\\\"\\\"\\nATSTNG's ejudge Python3 solution template\\n(actual solution is below)\\n\\\"\\\"\\\"\\n\\nimport sys, queue, string, math, itertools\\n\\ntry:\\n    import dev_act_ffc429465ab634  # empty file in directory\\n    DEV = True\\nexcept:\\n    DEV = False\\n\\ndef log(*s):\\n    if DEV: print('LOG', *s)\\n\\nclass EJudge:\\n    def __init__(self, problem=\\\"default\\\", reclim=1<<30):\\n        self.problem = problem\\n        sys.setrecursionlimit(reclim)\\n\\n    def use_files(self, infile='', outfile=''):\\n        if infile!='':\\n            self.infile = open(infile)\\n            sys.stdin = self.infile\\n        if infile!='':\\n            self.outfile = open(outfile, 'w')\\n            sys.stdout = self.outfile\\n\\n    def use_bacs_files(self):\\n        self.use_files(self.problem+'.in', self.problem+'.out')\\n\\n    def get_tl(self):\\n        while True: pass\\n\\n    def get_ml(self):\\n        tmp = [[[5]*100000 for _ in range(1000)]]\\n        while True: tmp.append([[5]*100000 for _ in range(1000)])\\n\\n    def get_re(self):\\n        s = (0,)[8]\\n\\n    def get_wa(self, wstr='blablalblah'):\\n        for _ in range(3): print(wstr)\\n        return\\n\\nclass IntReader:\\n    def __init__(self):\\n        self.ost = queue.Queue()\\n\\n    def get(self):\\n        return int(self.sget())\\n\\n    def sget(self):\\n        if self.ost.empty():\\n            for el in input().split():\\n                self.ost.put(el)\\n        return self.ost.get()\\n\\n    def release(self):\\n        res = []\\n        while not self.ost.empty():\\n            res.append(self.ost.get())\\n        return res\\n\\n\\n\\n###############################################################################\\nej = EJudge( '' )\\nint_reader = IntReader()\\nfmap = lambda f,*l: list(map(f,*l))\\nparse_int = lambda: fmap(int, input().split())\\nrevrange = lambda x: list(range(x-1, -1, -1))\\n\\ndef aeq(ar, v):\\n    for el in ar:\\n        if el != v: return False\\n    return True\\nk = -1\\n\\n\\nh, w = 5, 1\\n\\ndef calcfast(h, w, k):\\n    if k == -1 and (h+w) & 1: return 0\\n    ans = pow(2, ((h-1)*(w-1)), 1000000007)\\n    return ans\\n\\ndef calc(h,w, k):\\n    a = [ [0]*w for i in range(h) ]\\n   ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAnton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.\\n\\nAnton has n variants when he will attend chess classes, i-th variant is given by a period of time (l_{1, }i, r_{1, }i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l_{2, }i, r_{2, }i).\\n\\nAnton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.\\n\\nThe distance between periods (l_1, r_1) and (l_2, r_2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l_1 ≤ i ≤ r_1 and l_2 ≤ j ≤ r_2. In particular, when the periods intersect, the distance between them is 0.\\n\\nAnton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of time periods when Anton can attend chess classes.\\n\\nEach of the following n lines of the input contains two integers l_{1, }i and r_{1, }i (1 ≤ l_{1, }i ≤ r_{1, }i ≤ 10^9) — the i-th variant of a period of time when Anton can attend chess classes.\\n\\nThe following line of the input contains a single integer m (1 ≤ m ≤ 200 000) — the number of time periods when Anton can attend programming classes.\\n\\nEach of the following m lines of the input contains two integers l_{2, }i and r_{2, }i (1 ≤ l_{2, }i ≤ r_{2, }i ≤ 10^9) — the i-th variant of a period of time when Anton can attend programming classes.\\n\\n\\n-----Output-----\\n\\nOutput one integer — the maximal possible distance between time periods.\\n\\n\\n-----Examples-----\\nInput\\n3\\n1 5\\n2 6\\n2 3\\n2\\n2 4\\n6...\",\"targets\":\"import sys\\nn=int(input())\\nmin=sys.maxsize\\nmax1=0\\nfor _ in range(n):\\n    a,b=map(int,input().split())\\n    if min>b:\\n        min=b\\n    if max1<a:\\n        max1=a\\nm=int(input())\\nmax=0\\nmin1=sys.maxsize\\nfor _ in range(m):\\n    a,b=map(int,input().split())\\n    if max<a:\\n        max=a\\n    if min1>b:\\n        min1=b\\nif max<=min:\\n    ans=0\\nelse:\\n    ans=max-min\\nif max1<=min1:\\n    ans1=0\\nelse:\\n    ans1=max1-min1\\nif ans>ans1:\\n    print(ans)\\nelse:\\n    print(ans1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given array a with n elements and the number m. Consider some subsequence of a and the value of least common multiple (LCM) of its elements. Denote LCM as l. Find any longest subsequence of a with the value l ≤ m.\\n\\nA subsequence of a is an array we can get by erasing some elements of a. It is allowed to erase zero or all elements.\\n\\nThe LCM of an empty array equals 1.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (1 ≤ n, m ≤ 10^6) — the size of the array a and the parameter from the problem statement.\\n\\nThe second line contains n integers a_{i} (1 ≤ a_{i} ≤ 10^9) — the elements of a.\\n\\n\\n-----Output-----\\n\\nIn the first line print two integers l and k_{max} (1 ≤ l ≤ m, 0 ≤ k_{max} ≤ n) — the value of LCM and the number of elements in optimal subsequence.\\n\\nIn the second line print k_{max} integers — the positions of the elements from the optimal subsequence in the ascending order.\\n\\nNote that you can find and print any subsequence with the maximum length.\\n\\n\\n-----Examples-----\\nInput\\n7 8\\n6 2 9 2 7 2 3\\n\\nOutput\\n6 5\\n1 2 4 6 7\\n\\nInput\\n6 4\\n2 2 2 3 3 3\\n\\nOutput\\n2 3\\n1 2 3\",\"targets\":\"import sys\\n\\nn, m = [int(x) for x in input().split()]\\nA = [int(x) for x in input().split()]\\nB, C = [0]*(m+1), [0]*(m+1)\\nfor a in A:\\n    if a <= m: B[a] += 1\\nfor i in range(2, m + 1):\\n    for j in range(i, m+1, i):\\n        C[j] += B[i]\\n\\nk, l = 1, 0\\nfor i in range(2, m+1):\\n    if C[i] > l:\\n        l = C[i]\\n        k = i\\nprint(k, l + B[1])\\nfor i, a in enumerate(A):\\n    if k%a == 0: sys.stdout.write(str(i+1) + ' ')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a40c250c5e284a76400008c:\\nYou drop a ball from a given height. After each bounce, the ball returns to some fixed proportion of its previous height. If the ball bounces to height 1 or less, we consider it to have stopped bouncing. Return the number of bounces it takes for the ball to stop moving.\\n\\n```\\nbouncingBall(initialHeight, bouncingProportion)\\n\\nboucingBall(4, 0.5)\\nAfter first bounce, ball bounces to height 2\\nAfter second bounce, ball bounces to height 1\\nTherefore answer is 2 bounces\\n\\nboucingBall(30, 0.3)\\nAfter first bounce, ball bounces to height 9\\nAfter second bounce, ball bounces to height 2.7\\nAfter third bounce, ball bounces to height 0.81\\nTherefore answer is 3 bounces\\n\\n\\n```\\n\\nInitial height is an integer in range [2,1000]\\n\\nBouncing Proportion is a decimal in range [0, 1)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import ceil, log\\n\\ndef bouncing_ball(initial, proportion):\\n    return ceil(log(1 \\/ initial, proportion))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5b077ebdaf15be5c7f000077:\\nIf you can't sleep, just count sheep!!\\n\\n## Task:\\nGiven a non-negative integer, `3` for example, return a string with a murmur: `\\\"1 sheep...2 sheep...3 sheep...\\\"`.  Input will always be valid, i.e. no negative integers.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def count_sheep(n):\\n    # your code\\n    o = \\\"\\\"\\n    for i in range(1, n+1):\\n        o+=f\\\"{i} sheep...\\\"\\n    return o\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55baa55cf332e67eb000000a:\\nLexicographic permutations are ordered combinations of a set of items ordered in a specific way.\\n\\nFor instance, the first 8 permutations of the digits 0123, in lexicographic order, are:\\n\\n```\\n1st 0123\\n2nd 0132\\n3rd 0213\\n4th 0231\\n5th 0312\\n6th 0321\\n7th 1023\\n8th 1032\\n```\\n\\nYour task is to write a function ```L( n, d )``` that will return a `string` representing the `nth` permutation of the `d` digit, starting with 0 (i.e. d=10 means all digits 0123456789).\\n\\nSo for `d = 4`, `L(7,4)` should return `'1023'`, and `L(4,4)` should return `'0231'`\\n.\\n\\n\\nSome things to bear in mind:\\n\\n• The function should return a `string`, otherwise permutations beginning with a 0 will have it removed. \\n\\n• Test cases will not exceed the highest possible valid values for `n`\\n\\n• The function should work for any `d` between `1` and `10`.\\n\\n• A value of 1 for `n` means the 1st permutation, so `n = 0` is not a valid input.\\n\\n• Oh, and no itertools ;)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\ndef nth_perm(n,d):\\n    digits = [str(i) for i in range(d)]\\n    out = ''\\n    for i in range(1, d):\\n        cycles = math.ceil(n\\/math.factorial(d-i))\\n        out += digits.pop((cycles % (d-i+1)) - 1)\\n    return out + digits.pop()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/CHPTRS01\\/problems\\/FUNRUN:\\nWalter White and Jesse Pinkman (a drug addict) both love to play with chemicals. One day they were playing with some chemicals to make an energy drink. Unknowingly they made a highly powerful drink. To test the drink on others also they called some of their friends and gave a drop of it to everyone. Now they all were feeling highly energetic and thought of an unique game to play with each other.\\nAfter pondering for a while, Jesse came up with an extraordinary idea of competing in a race around a circular globe with N checkpoints each of one unit. Walter and all their other friends agreed with it.They divided themselves in $2$ teams with $N$ teammates in each team.This race has two commencing points $A$ and $B$ strictly facing each other. Walter and his team commences from $A$ point and other team starts from $B$. Both the teams start running at the same time clockwise around the globe. Speed of every player is constant throughout the race. If a player has a speed $X$ then it means that he covers a distance of $X$ units in one second.The race ends when some member of one team overtakes all members of opposite team at any point of time. Now you have to tell if any team will win the race or not.They all are stubborn and can run forever just to win the race. Help them to know if it is possible in anyway that the race will come to an end. \\nFor Clarity, you can visualize the path as a circular paths where $A$ and $B$ are opposite ends of diameter. It can be proven that the actual circumference of circle do not affect the answer.\\nIt is also possible that someone don't run at all.Keep in mind that the fastest one wins the race so does the code.\\n\\n-----Input:------\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows. \\n- The first line of each test case contains a single integer $N$ number of teammates in both team.\\n- The second line contains $N$ space-separated integers $A_1, A_2 \\\\ldots A_N$ denoting speed of A's Team\\n- The third line...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t = int(input())\\nwhile(t>0):\\n    n = int(input())\\n    a  =[int(i) for i in input().split()]\\n    b = [int(i) for i in input().split()]\\n    if max(a)!=max(b):\\n        print('YES')\\n    else:\\n        print('NO')\\n    t-=1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an array points representing integer coordinates of some points on a 2D-plane, where points[i] = [xi, yi].\\nThe cost of connecting two points [xi, yi] and [xj, yj] is the manhattan distance between them: |xi - xj| + |yi - yj|, where |val| denotes the absolute value of val.\\nReturn the minimum cost to make all points connected. All points are connected if there is exactly one simple path between any two points.\\n \\nExample 1:\\n\\nInput: points = [[0,0],[2,2],[3,10],[5,2],[7,0]]\\nOutput: 20\\nExplanation:\\n\\nWe can connect the points as shown above to get the minimum cost of 20.\\nNotice that there is a unique path between every pair of points.\\n\\nExample 2:\\nInput: points = [[3,12],[-2,5],[-4,1]]\\nOutput: 18\\n\\nExample 3:\\nInput: points = [[0,0],[1,1],[1,0],[-1,1]]\\nOutput: 4\\n\\nExample 4:\\nInput: points = [[-1000000,-1000000],[1000000,1000000]]\\nOutput: 4000000\\n\\nExample 5:\\nInput: points = [[0,0]]\\nOutput: 0\\n\\n \\nConstraints:\\n\\n1 <= points.length <= 1000\\n-106 <= xi, yi <= 106\\nAll pairs (xi, yi) are distinct.\",\"targets\":\"class Solution:\\n    def minCostConnectPoints(self, points: List[List[int]]) -> int:\\n        def find_parent(parent,x):\\n            if parent[x] == -1:\\n                return x\\n            return find_parent(parent,parent[x])\\n        \\n        def union(parent,x,y):\\n            x_s = find_parent(parent,x)\\n            y_s = find_parent(parent,y)\\n            parent[x_s] = y_s\\n        \\n        def kruskals(edges):\\n            parent = [-1]*len(points)\\n            min_weight = 0\\n            i = 0\\n            j = 0\\n            while j < len(points) - 1:\\n                start,end,weight = edges[i]\\n                x = find_parent(parent,start)\\n                y = find_parent(parent,end)\\n                i+=1\\n                if x!=y:\\n                    j+=1\\n                    union(parent,x,y)\\n                    min_weight += weight\\n            return min_weight\\n\\n        edges = []\\n        for i in range(len(points)):\\n            for j in range(i+1,len(points)):\\n                dis = abs(points[i][0] - points[j][0]) + abs(points[i][1] - points[j][1])\\n                edges.append([i,j,dis])\\n        edges.sort(key = lambda x: x[2])\\n        return kruskals(edges)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are total N friends went to Chef's Pizza shop. There they bought a pizza. Chef divided the pizza into K equal slices. Now you have to check whether these K pizza slices can be distributed equally among the friends. Also given that every person should get at least one slice. If the above conditions are possible then print \\\"YES\\\" otherwise print \\\"NO\\\".\\n\\n-----Input:-----\\nThe first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.\\nThe first line of each test case contains a integers N.\\nThe second line of each test case contains K.\\n\\n-----Output:-----\\nFor each test case, print a single line containing \\\"YES\\\" if the given conditions are true else \\\"NO\\\" if the given conditions are false.\\n\\n-----Constraints-----\\n1<=T<=10\\n1<=N<=10^6\\n1<=K<=10^6\\n\\n-----Sample Input:-----\\n2\\n10\\n20\\n12\\n5\\n\\n-----Sample Output:-----\\nYES\\nNO\\n\\n-----EXPLANATION:-----\\nExplanation case 1: since there are 10 friends and 20 pizza slice, so each can get 2 slices, so \\\"YES\\\".\\nExplanation case 2: Since there are 12 friends and only 5 pizza slice, so there is no way pizza slices can be distributed equally and each friend gets at least one pizza slice, so \\\"NO\\\".\",\"targets\":\"for _ in range(int(input())):\\n    N = int(input())\\n    K = int(input())\\n    \\n    if K%N == 0:\\n        print(\\\"YES\\\")\\n    else:\\n        print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5efae11e2d12df00331f91a6:\\nGiven is a md5 hash of a five digits long PIN. It is given as string.\\nMd5 is a function to hash your password:\\n\\\"password123\\\" ===> \\\"482c811da5d5b4bc6d497ffa98491e38\\\"\\n\\nWhy is this useful?\\nHash functions like md5 can create a hash from string in a short time and it is impossible to find out the password, if you only got the hash. The only way is cracking it, means try every combination, hash it and compare it with the hash you want to crack. (There are also other ways of attacking md5 but that's another story)\\nEvery Website and OS is storing their passwords as hashes, so if a hacker gets access to the database, he can do nothing, as long the password is safe enough.\\n\\nWhat is a hash:\\nhttps:\\/\\/en.wikipedia.org\\/wiki\\/Hash_function#:~:text=A%20hash%20function%20is%20any,table%20called%20a%20hash%20table.\\n\\nWhat is md5:\\nhttps:\\/\\/en.wikipedia.org\\/wiki\\/MD5\\n\\nNote: Many languages have build in tools to hash md5. If not, you can write your own md5 function or google for an example.\\n\\nHere is another kata on generating md5 hashes:\\nhttps:\\/\\/www.codewars.com\\/kata\\/password-hashes\\n\\nYour task is to return the cracked PIN as string.\\n\\nThis is a little fun kata, to show you, how weak PINs are and how important a bruteforce protection is, if you create your own login.\\n\\nIf you liked this kata, here is an extension with short passwords:\\nhttps:\\/\\/www.codewars.com\\/kata\\/59146f7b4670ba520900000a\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import hashlib \\n\\ndef crack(hash):\\n    for i in range (0,99999):\\n        pin = digit_to_pin(i).encode()\\n        rand_hash = hashlib.md5(pin).hexdigest()\\n        if hash == rand_hash:\\n            return pin.decode()\\n        else:\\n            pass\\n    \\ndef digit_to_pin(digit):\\n    string = str(digit)\\n    if len(string)<5:\\n        nulls = (5 - len(string))*\\\"0\\\"\\n        string  = nulls + string\\n    return string\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/628\\/A:\\nA tennis tournament with n participants is running. The participants are playing by an olympic system, so the winners move on and the losers drop out.\\n\\nThe tournament takes place in the following way (below, m is the number of the participants of the current round):  let k be the maximal power of the number 2 such that k ≤ m,  k participants compete in the current round and a half of them passes to the next round, the other m - k participants pass to the next round directly,  when only one participant remains, the tournament finishes. \\n\\nEach match requires b bottles of water for each participant and one bottle for the judge. Besides p towels are given to each participant for the whole tournament.\\n\\nFind the number of bottles and towels needed for the tournament.\\n\\nNote that it's a tennis tournament so in each match two participants compete (one of them will win and the other will lose).\\n\\n\\n-----Input-----\\n\\nThe only line contains three integers n, b, p (1 ≤ n, b, p ≤ 500) — the number of participants and the parameters described in the problem statement.\\n\\n\\n-----Output-----\\n\\nPrint two integers x and y — the number of bottles and towels need for the tournament.\\n\\n\\n-----Examples-----\\nInput\\n5 2 3\\n\\nOutput\\n20 15\\n\\nInput\\n8 2 4\\n\\nOutput\\n35 32\\n\\n\\n\\n-----Note-----\\n\\nIn the first example will be three rounds:  in the first round will be two matches and for each match 5 bottles of water are needed (two for each of the participants and one for the judge),  in the second round will be only one match, so we need another 5 bottles of water,  in the third round will also be only one match, so we need another 5 bottles of water. \\n\\nSo in total we need 20 bottles of water.\\n\\nIn the second example no participant will move on to some round directly.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, b, p = list(map(int, input().split(\\\" \\\")))\\ndup = n\\nans = 0\\nwhile n>1:\\n\\tans += (n\\/\\/2)*(2*b + 1)\\n\\tn = n\\/\\/2 + n%2\\nprint(ans, p*dup)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/934\\/A:\\nNian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cracking noise, all of which frighten the monster out of coming.\\n\\nLittle Tommy has n lanterns and Big Banban has m lanterns. Tommy's lanterns have brightness a_1, a_2, ..., a_{n}, and Banban's have brightness b_1, b_2, ..., b_{m} respectively.\\n\\nTommy intends to hide one of his lanterns, then Banban picks one of Tommy's non-hidden lanterns and one of his own lanterns to form a pair. The pair's brightness will be the product of the brightness of two lanterns.\\n\\nTommy wants to make the product as small as possible, while Banban tries to make it as large as possible.\\n\\nYou are asked to find the brightness of the chosen pair if both of them choose optimally.\\n\\n\\n-----Input-----\\n\\nThe first line contains two space-separated integers n and m (2 ≤ n, m ≤ 50).\\n\\nThe second line contains n space-separated integers a_1, a_2, ..., a_{n}.\\n\\nThe third line contains m space-separated integers b_1, b_2, ..., b_{m}.\\n\\nAll the integers range from  - 10^9 to 10^9.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the brightness of the chosen pair.\\n\\n\\n-----Examples-----\\nInput\\n2 2\\n20 18\\n2 14\\n\\nOutput\\n252\\n\\nInput\\n5 3\\n-1 0 1 2 3\\n-1 0 1\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, Tommy will hide 20 and Banban will choose 18 from Tommy and 14 from himself.\\n\\nIn the second example, Tommy will hide 3 and Banban will choose 2 from Tommy and 1 from himself.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = map(int, input().split())\\nl1 = list(map(int, input().split()))\\nl2 = list(map(int, input().split()))\\nans1 = []\\nfor i in range(n):\\n    ans = -10 ** 18 - 1\\n    for j in range(n):\\n        if j != i:\\n            for q in range(m):\\n                if ans < l1[j] * l2[q]:\\n                    ans = l1[j] * l2[q]\\n    ans1.append(ans)\\nprint(min(ans1))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc135\\/tasks\\/abc135_c:\\nThere are N+1 towns. The i-th town is being attacked by A_i monsters.\\nWe have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters.\\nWhat is the maximum total number of monsters the heroes can cooperate to defeat?\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq A_i \\\\leq 10^9\\n - 1 \\\\leq B_i \\\\leq 10^9\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 A_2 ... A_{N+1}\\nB_1 B_2 ... B_N\\n\\n-----Output-----\\nPrint the maximum total number of monsters the heroes can defeat.\\n\\n-----Sample Input-----\\n2\\n3 5 2\\n4 5\\n\\n-----Sample Output-----\\n9\\n\\nIf the heroes choose the monsters to defeat as follows, they can defeat nine monsters in total, which is the maximum result.\\n - The first hero defeats two monsters attacking the first town and two monsters attacking the second town.\\n - The second hero defeats three monsters attacking the second town and two monsters attacking the third town.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\na = list(map(int,input().split()))\\nb = list(map(int,input().split()))\\nnum = 0\\nfor i in range(n):\\n    min_ab = min(a[i],b[i])\\n    num += min_ab\\n    a[i] -= min_ab\\n    b[i] -= min_ab\\n    if b[i] != 0:\\n        min_ab = min(a[i + 1],b[i])\\n        num += min_ab\\n        a[i + 1] -= min_ab\\n        b[i] -= min_ab\\nprint(num)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/59e66e48fc3c499ec5000103:\\nIn this Kata, you will be given an array of arrays and your task will be to return the number of unique arrays that can be formed by picking exactly one element from each subarray. \\n\\nFor example: `solve([[1,2],[4],[5,6]]) = 4`, because it results in only `4` possiblites. They are `[1,4,5],[1,4,6],[2,4,5],[2,4,6]`. \\n\\n```if:r\\nIn R, we will use a list data structure.\\nSo the argument for `solve` is a list of numeric vectors.\\n~~~\\nsolve(list(c(1, 2), 4, c(5, 6)))\\n[1] 4\\n~~~\\n```\\n\\nMake sure that you don't count duplicates; for example `solve([[1,2],[4,4],[5,6,6]]) = 4`, since the extra outcomes are just duplicates. \\n\\nSee test cases for more examples.\\n\\nGood luck!\\n\\nIf you like this Kata, please try:\\n\\n[Sum of integer combinations](https:\\/\\/www.codewars.com\\/kata\\/59f3178e3640cef6d90000d5)\\n\\n[Sum of array singles](https:\\/\\/www.codewars.com\\/kata\\/59f11118a5e129e591000134)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def solve(arr):\\n    from functools import reduce\\n    return reduce(lambda a,b: a*b, [len(set(a)) for a in arr])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAs a New Year's gift, Dolphin received a string s of length 19.\\n\\nThe string s has the following format: [five lowercase English letters],[seven lowercase English letters],[five lowercase English letters].\\n\\nDolphin wants to convert the comma-separated string s into a space-separated string.\\n\\nWrite a program to perform the conversion for him.  \\n\\n-----Constraints-----\\n - The length of s is 19.\\n - The sixth and fourteenth characters in s are ,.\\n - The other characters in s are lowercase English letters.\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\ns\\n\\n-----Output-----\\nPrint the string after the conversion.\\n\\n-----Sample Input-----\\nhappy,newyear,enjoy\\n\\n-----Sample Output-----\\nhappy newyear enjoy\\n\\nReplace all the commas in happy,newyear,enjoy with spaces to obtain happy newyear enjoy.\",\"targets\":\"print(input().replace(\\\",\\\",\\\" \\\"))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nBike is interested in permutations. A permutation of length n is an integer sequence such that each integer from 0 to (n - 1) appears exactly once in it. For example, [0, 2, 1] is a permutation of length 3 while both [0, 2, 2] and [1, 2, 3] is not.\\n\\nA permutation triple of permutations of length n (a, b, c) is called a Lucky Permutation Triple if and only if $\\\\forall i(1 \\\\leq i \\\\leq n), a_{i} + b_{i} \\\\equiv c_{i} \\\\operatorname{mod} n$. The sign a_{i} denotes the i-th element of permutation a. The modular equality described above denotes that the remainders after dividing a_{i} + b_{i} by n and dividing c_{i} by n are equal.\\n\\nNow, he has an integer n and wants to find a Lucky Permutation Triple. Could you please help him?\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 10^5).\\n\\n\\n-----Output-----\\n\\nIf no Lucky Permutation Triple of length n exists print -1.\\n\\nOtherwise, you need to print three lines. Each line contains n space-seperated integers. The first line must contain permutation a, the second line — permutation b, the third — permutation c.\\n\\nIf there are multiple solutions, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n5\\n\\nOutput\\n1 4 3 2 0\\n1 0 2 4 3\\n2 4 0 1 3\\n\\nInput\\n2\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn Sample 1, the permutation triple ([1, 4, 3, 2, 0], [1, 0, 2, 4, 3], [2, 4, 0, 1, 3]) is Lucky Permutation Triple, as following holds:  $1 + 1 \\\\equiv 2 \\\\equiv 2 \\\\operatorname{mod} 5$;  $4 + 0 \\\\equiv 4 \\\\equiv 4 \\\\operatorname{mod} 5$;  $3 + 2 \\\\equiv 0 \\\\equiv 0 \\\\operatorname{mod} 5$;  $2 + 4 \\\\equiv 6 \\\\equiv 1 \\\\operatorname{mod} 5$;  $0 + 3 \\\\equiv 3 \\\\equiv 3 \\\\operatorname{mod} 5$. \\n\\nIn Sample 2, you can easily notice that no lucky permutation triple exists.\",\"targets\":\"a = int(input())\\nt=\\\"\\\"\\ntt=\\\"\\\"\\nttt=\\\"\\\"\\nif a%2!=0:\\n    for x in range(0,a):\\n        t=t+(str(x)+\\\" \\\")\\n    for x in range(0,a):\\n        tt=tt+(str(x)+\\\" \\\")\\n    for x in range(0,a):\\n        ttt=ttt+(str(2*x%a)+\\\" \\\")\\nelse:\\n    print(-1)\\n\\n\\nprint(t)\\nprint(tt)\\nprint(ttt)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1279\\/D:\\nSanta Claus has received letters from $n$ different kids throughout this year. Of course, each kid wants to get some presents from Santa: in particular, the $i$-th kid asked Santa to give them one of $k_i$ different items as a present. Some items could have been asked by multiple kids.\\n\\nSanta is really busy, so he wants the New Year Bot to choose the presents for all children. Unfortunately, the Bot's algorithm of choosing presents is bugged. To choose a present for some kid, the Bot does the following:\\n\\n  choose one kid $x$ equiprobably among all $n$ kids;  choose some item $y$ equiprobably among all $k_x$ items kid $x$ wants;  choose a kid $z$ who will receive the present equipropably among all $n$ kids (this choice is independent of choosing $x$ and $y$); the resulting triple $(x, y, z)$ is called the decision of the Bot. \\n\\nIf kid $z$ listed item $y$ as an item they want to receive, then the decision valid. Otherwise, the Bot's choice is invalid.\\n\\nSanta is aware of the bug, but he can't estimate if this bug is really severe. To do so, he wants to know the probability that one decision generated according to the aforementioned algorithm is valid. Can you help him?\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $n$ ($1 \\\\le n \\\\le 10^6$) — the number of kids who wrote their letters to Santa.\\n\\nThen $n$ lines follow, the $i$-th of them contains a list of items wanted by the $i$-th kid in the following format: $k_i$ $a_{i, 1}$ $a_{i, 2}$ ... $a_{i, k_i}$ ($1 \\\\le k_i, a_{i, j} \\\\le 10^6$), where $k_i$ is the number of items wanted by the $i$-th kid, and $a_{i, j}$ are the items themselves. No item is contained in the same list more than once.\\n\\nIt is guaranteed that $\\\\sum \\\\limits_{i = 1}^{n} k_i \\\\le 10^6$.\\n\\n\\n-----Output-----\\n\\nPrint the probatility that the Bot produces a valid decision as follows:\\n\\nLet this probability be represented as an irreducible fraction $\\\\frac{x}{y}$. You have to print $x \\\\cdot y^{-1} \\\\mod 998244353$, where $y^{-1}$ is the inverse element of $y$ modulo $998244353$ (such integer that...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n\\np = 998244353\\nn = int(sys.stdin.readline().strip())\\nA = [0] * (10 ** 6 + 1)\\na = []\\nk = []\\nfor i in range (0, n):\\n    line = list(map(int,sys.stdin.readline().strip().split()))\\n    k.append(line[0])\\n    a.append(line[1:])\\n    for j in range (0, k[i]):\\n        x = a[i][j]\\n        A[x] = A[x] + 1\\nr, s = 0, 1\\nfor i in range (0, n):\\n    x = 0\\n    for j in range (0, k[i]):\\n        x = x + A[a[i][j]]\\n    y = k[i] * n\\n    r, s = (r * y + s * x) % p, (s * y) % p\\nans = r\\ns = s * n\\nq = p - 2\\nwhile q > 0:\\n    if q % 2 == 1:\\n        ans = (ans * s) % p \\n        q = q - 1\\n    else:\\n        q = q \\/\\/ 2\\n        s = (s * s) % p\\n\\n\\nprint(ans % p)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/359\\/A:\\nSimon has a rectangular table consisting of n rows and m columns. Simon numbered the rows of the table from top to bottom starting from one and the columns — from left to right starting from one. We'll represent the cell on the x-th row and the y-th column as a pair of numbers (x, y). The table corners are cells: (1, 1), (n, 1), (1, m), (n, m).\\n\\nSimon thinks that some cells in this table are good. Besides, it's known that no good cell is the corner of the table. \\n\\nInitially, all cells of the table are colorless. Simon wants to color all cells of his table. In one move, he can choose any good cell of table (x_1, y_1), an arbitrary corner of the table (x_2, y_2) and color all cells of the table (p, q), which meet both inequations: min(x_1, x_2) ≤ p ≤ max(x_1, x_2), min(y_1, y_2) ≤ q ≤ max(y_1, y_2).\\n\\nHelp Simon! Find the minimum number of operations needed to color all cells of the table. Note that you can color one cell multiple times.\\n\\n\\n-----Input-----\\n\\nThe first line contains exactly two integers n, m (3 ≤ n, m ≤ 50).\\n\\nNext n lines contain the description of the table cells. Specifically, the i-th line contains m space-separated integers a_{i}1, a_{i}2, ..., a_{im}. If a_{ij} equals zero, then cell (i, j) isn't good. Otherwise a_{ij} equals one. It is guaranteed that at least one cell is good. It is guaranteed that no good cell is a corner.\\n\\n\\n-----Output-----\\n\\nPrint a single number — the minimum number of operations Simon needs to carry out his idea.\\n\\n\\n-----Examples-----\\nInput\\n3 3\\n0 0 0\\n0 1 0\\n0 0 0\\n\\nOutput\\n4\\n\\nInput\\n4 3\\n0 0 0\\n0 0 1\\n1 0 0\\n0 0 0\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, the sequence of operations can be like this: [Image]   For the first time you need to choose cell (2, 2) and corner (1, 1).  For the second time you need to choose cell (2, 2) and corner (3, 3).  For the third time you need to choose cell (2, 2) and corner (3, 1).  For the fourth time you need to choose cell (2, 2) and corner (1, 3). \\n\\nIn the second sample the sequence of operations can be like this: [Image]   For the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"data = input().split()\\n\\nN, M = int(data[0]), int(data[1])\\n\\ntable = []\\nfor i in range(N):\\n    table.append(input().split())\\n\\nanswer = 0\\n\\n## for first row\\nif any(e == '1' for e in table[0]):\\n    answer = 2\\n##  for last row\\nelif any(e == '1' for e in table[-1]):\\n    answer = 2\\n## for first and  last column\\nelse:\\n    for i in range(N):\\n        if table[i][0] == '1':\\n            answer = 2\\n        elif table[i][-1] == '1':\\n            answer = 2\\n\\nif answer == 0:\\n    print('4')\\nelse:\\n    print(answer)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a grid of size M x N, where each square is colored with some random color among K colors with each having equal probability.\\n\\nA Good Rectangle is defined as one where all squares lying on the inner border are of the same color.\\n\\nWhat is the expected number of Good Rectangles in the given grid.\\n\\n-----Input-----\\n\\n- \\nFirst Line contains M, N, K\\n\\n-----Output-----\\nA single value rounded off to the nearest Integer corresponding to the required answer.\\n\\n-----Constraints-----\\n-  1 <= N <= 105 \\n-  1 <= M <= 105 \\n-  1 <= K <= 105 \\n\\n-----Example-----\\nInput:\\n1 3 1\\nOutput:\\n6\",\"targets\":\"n, m, k = list(map(int, input().split()))\\n\\nif k == 1:\\n x, y = 0, 0\\n for p in range(2, n + 1):\\n  x += (n - p + 1)\\n for p in range(2, m + 1):\\n  y += (m - p + 1)\\n ans = x * y\\n x = 0\\n for p in range(1, n + 1):\\n  x += (n - p + 1)\\n y = 0\\n for p in range(1, m + 1):\\n  y += (m - p + 1)\\n ans += m * x\\n ans += n * y\\n ans -= n * m\\n print(ans)\\nelse:\\n x, y = 0.0, 0.0\\n q = 1.0\\n for p in range(2, n + 1):\\n  q \\/= k * k\\n  x += (n - p + 1) * q\\n for p in range(2, m + 1):\\n  q \\/= k * k\\n  y += (m - p + 1) * q\\n ans = k * x * y\\n x = 0.0\\n q = 1.0\\n for p in range(1, n + 1):\\n  x += (n - p + 1) * q\\n  q \\/= k\\n y = 0.0\\n q = 1.0\\n for p in range(1, m + 1):\\n  y += (m - p + 1) * q\\n  q \\/= k\\n ans += m * x\\n ans += n * y\\n ans -= n * m\\n ans += 1e-9\\n # print ans\\n print(\\\"%.0f\\\" % ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given two integers $n$ and $m$. You have to construct the array $a$ of length $n$ consisting of non-negative integers (i.e. integers greater than or equal to zero) such that the sum of elements of this array is exactly $m$ and the value $\\\\sum\\\\limits_{i=1}^{n-1} |a_i - a_{i+1}|$ is the maximum possible. Recall that $|x|$ is the absolute value of $x$.\\n\\nIn other words, you have to maximize the sum of absolute differences between adjacent (consecutive) elements. For example, if the array $a=[1, 3, 2, 5, 5, 0]$ then the value above for this array is $|1-3| + |3-2| + |2-5| + |5-5| + |5-0| = 2 + 1 + 3 + 0 + 5 = 11$. Note that this example doesn't show the optimal answer but it shows how the required value for some array is calculated.\\n\\nYou have to answer $t$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases. Then $t$ test cases follow.\\n\\nThe only line of the test case contains two integers $n$ and $m$ ($1 \\\\le n, m \\\\le 10^9$) — the length of the array and its sum correspondingly.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer — the maximum possible value of $\\\\sum\\\\limits_{i=1}^{n-1} |a_i - a_{i+1}|$ for the array $a$ consisting of $n$ non-negative integers with the sum $m$.\\n\\n\\n-----Example-----\\nInput\\n5\\n1 100\\n2 2\\n5 5\\n2 1000000000\\n1000000000 1000000000\\n\\nOutput\\n0\\n2\\n10\\n1000000000\\n2000000000\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case of the example, the only possible array is $[100]$ and the answer is obviously $0$.\\n\\nIn the second test case of the example, one of the possible arrays is $[2, 0]$ and the answer is $|2-0| = 2$.\\n\\nIn the third test case of the example, one of the possible arrays is $[0, 2, 0, 3, 0]$ and the answer is $|0-2| + |2-0| + |0-3| + |3-0| = 10$.\",\"targets\":\"for _ in range(int(input())):\\n    n,m=map(int,input().split())\\n    if n==1:print(0)\\n    elif n==2:print(m)\\n    else:print(2*m)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nBeaches are filled with sand, water, fish, and sun. Given a string, calculate how many times the words `\\\"Sand\\\"`, `\\\"Water\\\"`, `\\\"Fish\\\"`, and `\\\"Sun\\\"` appear without overlapping (regardless of the case).\\n\\n## Examples\\n\\n```python\\nsum_of_a_beach(\\\"WAtErSlIde\\\")                    ==>  1\\nsum_of_a_beach(\\\"GolDeNSanDyWateRyBeaChSuNN\\\")    ==>  3\\nsum_of_a_beach(\\\"gOfIshsunesunFiSh\\\")             ==>  4\\nsum_of_a_beach(\\\"cItYTowNcARShoW\\\")               ==>  0\\n```\",\"targets\":\"def sum_of_a_beach(beach):\\n    return sum([beach.lower().count(element) for element in ['sand', 'water', 'fish', 'sun']])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1430\\/C:\\nNumbers $1, 2, 3, \\\\dots n$ (each integer from $1$ to $n$ once) are written on a board. In one operation you can erase any two numbers $a$ and $b$ from the board and write one integer $\\\\frac{a + b}{2}$ rounded up instead.\\n\\nYou should perform the given operation $n - 1$ times and make the resulting number that will be left on the board as small as possible. \\n\\nFor example, if $n = 4$, the following course of action is optimal:  choose $a = 4$ and $b = 2$, so the new number is $3$, and the whiteboard contains $[1, 3, 3]$;  choose $a = 3$ and $b = 3$, so the new number is $3$, and the whiteboard contains $[1, 3]$;  choose $a = 1$ and $b = 3$, so the new number is $2$, and the whiteboard contains $[2]$. \\n\\nIt's easy to see that after $n - 1$ operations, there will be left only one number. Your goal is to minimize it.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases.\\n\\nThe only line of each test case contains one integer $n$ ($2 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of integers written on the board initially.\\n\\nIt's guaranteed that the total sum of $n$ over test cases doesn't exceed $2 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, in the first line, print the minimum possible number left on the board after $n - 1$ operations. Each of the next $n - 1$ lines should contain two integers — numbers $a$ and $b$ chosen and erased in each operation.\\n\\n\\n-----Example-----\\nInput\\n1\\n4\\n\\nOutput\\n2\\n2 4\\n3 3\\n3 1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys, math\\nimport io, os\\n#data = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline\\nfrom bisect import bisect_left as bl, bisect_right as br, insort\\nfrom heapq import heapify, heappush, heappop\\nfrom collections import defaultdict as dd, deque, Counter\\n#from itertools import permutations,combinations\\ndef data(): return sys.stdin.readline().strip()\\ndef mdata(): return list(map(int, data().split()))\\ndef outl(var) : sys.stdout.write('\\\\n'.join(map(str, var))+'\\\\n')\\ndef out(var) : sys.stdout.write(str(var)+'\\\\n')\\n#from decimal import Decimal\\n#from fractions import Fraction\\n#sys.setrecursionlimit(100000)\\nINF = float('inf')\\nmod=10**9+7\\n\\n\\nfor t in range(int(data())):\\n    n=int(data())\\n    out(2)\\n    ans=[]\\n    k=n\\n    for i in range(n-1,0,-1):\\n        ans.append(str(k)+' '+str(i))\\n        k=(k+i+1)\\/\\/2\\n    outl(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTwo-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, \\\"AZ\\\", \\\"AA\\\", \\\"ZA\\\" — three distinct two-grams.\\n\\nYou are given a string $s$ consisting of $n$ capital Latin letters. Your task is to find any two-gram contained in the given string as a substring (i.e. two consecutive characters of the string) maximal number of times. For example, for string $s$ = \\\"BBAABBBA\\\" the answer is two-gram \\\"BB\\\", which contained in $s$ three times. In other words, find any most frequent two-gram.\\n\\nNote that occurrences of the two-gram can overlap with each other.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains integer number $n$ ($2 \\\\le n \\\\le 100$) — the length of string $s$. The second line of the input contains the string $s$ consisting of $n$ capital Latin letters.\\n\\n\\n-----Output-----\\n\\nPrint the only line containing exactly two capital Latin letters — any two-gram contained in the given string $s$ as a substring (i.e. two consecutive characters of the string) maximal number of times.\\n\\n\\n-----Examples-----\\nInput\\n7\\nABACABA\\n\\nOutput\\nAB\\n\\nInput\\n5\\nZZZAA\\n\\nOutput\\nZZ\\n\\n\\n\\n-----Note-----\\n\\nIn the first example \\\"BA\\\" is also valid answer.\\n\\nIn the second example the only two-gram \\\"ZZ\\\" can be printed because it contained in the string \\\"ZZZAA\\\" two times.\",\"targets\":\"n = int(input())\\ns = input()\\na = [[0] * 26 for _ in range(26)]\\nfor i in range(n -1):\\n    a[ord(s[i]) - ord('A')][ord(s[i + 1]) - ord('A')] += 1\\n\\nmx = -1\\n\\nfor i in range(26):\\n    for j in range(26):\\n        if a[i][j] > mx:\\n            mx = a[i][j]\\n            ans = chr(i + ord('A')) + chr(j + ord('A'))\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc076\\/tasks\\/abc076_b:\\nSquare1001 has seen an electric bulletin board displaying the integer 1.\\nHe can perform the following operations A and B to change this value:\\n - Operation A: The displayed value is doubled.\\n - Operation B: The displayed value increases by K.\\nSquare1001 needs to perform these operations N times in total.\\nFind the minimum possible value displayed in the board after N operations.\\n\\n-----Constraints-----\\n - 1 \\\\leq N, K \\\\leq 10\\n - All input values are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nK\\n\\n-----Output-----\\nPrint the minimum possible value displayed in the board after N operations.\\n\\n-----Sample Input-----\\n4\\n3\\n\\n-----Sample Output-----\\n10\\n\\nThe value will be minimized when the operations are performed in the following order: A, A, B, B.\\n\\nIn this case, the value will change as follows: 1 → 2 → 4 → 7 → 10.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N = int(input())\\nK = int(input())\\nv = 1\\nfor _ in range(N):\\n    if v <= K:\\n        v *= 2\\n    else:\\n        v += K\\nprint(v)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAbhiram needs to search for an antidote. He comes to know that clue for finding the antidote is carefully hidden by KrishnaMurthy in the form of a puzzle.\\n\\nThe puzzle consists of a string S and a keywordK. Abhiram needs to find the string of position of anagrams R of the keyword in the string which is the clue. \\nThe antidote is found in the box numbered R. Help him find his clue R.\\nAnagram: A word or phrase that is made by arranging the letters of another word or phrase in a different order. Eg: 'elvis' and 'lives' are both anagrams of each other.\\nNote: Consider, Tac and act are not anagrams(case sensitive).\\n\\n-----Input:-----\\nThe first line contains a string S of length land the second line contains a keyword K.\\n\\n-----Output:-----\\n\\nOutput contains a line\\\"The antidote is found in R.\\\" Where R= string of positions of anagrams.(the position of the first word in the string is 1).\\n\\n-----Constraints:-----\\n1<=l<=500\\n\\n1<=k<=50\\n\\n-----Example:-----\\nInput:\\ncat is the act of tac\\ncat\\n\\nOutput:\\nThe antidote is found in 46.\",\"targets\":\"s = input()\\nk = input()\\nwrds = s.split(' ')\\nkl = len(k)\\ncomp = sorted(k)\\n\\ndef ana(an):\\n if an == k:\\n  return False\\n return comp == sorted(an)\\n\\nans = ''\\nfor x in range(0, len(wrds)):\\n word = wrds[x]\\n if len(word) == kl and ana(word):\\n  ans += str(x+1)\\n\\nprint('The antidote is found in %s.' %ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/484\\/B:\\nYou are given a sequence a consisting of n integers. Find the maximum possible value of $a_{i} \\\\operatorname{mod} a_{j}$ (integer remainder of a_{i} divided by a_{j}), where 1 ≤ i, j ≤ n and a_{i} ≥ a_{j}.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n — the length of the sequence (1 ≤ n ≤ 2·10^5). \\n\\nThe second line contains n space-separated integers a_{i} (1 ≤ a_{i} ≤ 10^6).\\n\\n\\n-----Output-----\\n\\nPrint the answer to the problem.\\n\\n\\n-----Examples-----\\nInput\\n3\\n3 4 5\\n\\nOutput\\n2\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n    input()\\n    aa = sorted(map(int, input().split()))\\n    maxa = aa[-1]\\n    m = [False] * (maxa + 1)\\n    x = []\\n    b = res = 0\\n    for a in aa:\\n        if b != a:\\n            m[a] = True\\n            for i in range(b, a):\\n                x.append(b)\\n            b = a\\n    x.append(b)\\n    for a in range(maxa - 1, 1, -1):\\n        if a < res:\\n            break\\n        if m[a]:\\n            for b in range(2 * a - 1, maxa + 2 * a, a):\\n                res = max(res, x[min(b, maxa)] % a)\\n    print(res)\\n\\n\\ndef __starting_point():\\n    main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVladik often travels by trains. He remembered some of his trips especially well and I would like to tell you about one of these trips:\\n\\nVladik is at initial train station, and now n people (including Vladik) want to get on the train. They are already lined up in some order, and for each of them the city code a_{i} is known (the code of the city in which they are going to).\\n\\nTrain chief selects some number of disjoint segments of the original sequence of people (covering entire sequence by segments is not necessary). People who are in the same segment will be in the same train carriage. The segments are selected in such way that if at least one person travels to the city x, then all people who are going to city x should be in the same railway carriage. This means that they can’t belong to different segments. Note, that all people who travel to the city x, either go to it and in the same railway carriage, or do not go anywhere at all.\\n\\nComfort of a train trip with people on segment from position l to position r is equal to XOR of all distinct codes of cities for people on the segment from position l to position r. XOR operation also known as exclusive OR.\\n\\nTotal comfort of a train trip is equal to sum of comfort for each segment.\\n\\nHelp Vladik to know maximal possible total comfort.\\n\\n\\n-----Input-----\\n\\nFirst line contains single integer n (1 ≤ n ≤ 5000) — number of people.\\n\\nSecond line contains n space-separated integers a_1, a_2, ..., a_{n} (0 ≤ a_{i} ≤ 5000), where a_{i} denotes code of the city to which i-th person is going.\\n\\n\\n-----Output-----\\n\\nThe output should contain a single integer — maximal possible total comfort.\\n\\n\\n-----Examples-----\\nInput\\n6\\n4 4 2 5 2 3\\n\\nOutput\\n14\\n\\nInput\\n9\\n5 1 3 1 5 2 4 2 5\\n\\nOutput\\n9\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case best partition into segments is: [4, 4] [2, 5, 2] [3], answer is calculated as follows: 4 + (2 xor 5) + 3 = 4 + 7 + 3 = 14\\n\\nIn the second test case best partition into segments is: 5 1 [3] 1 5 [2, 4, 2] 5, answer calculated as follows: 3 + (2 xor 4) = 3 + 6 = 9.\",\"targets\":\"n = int(input())\\na = list(map(int, input().split()))\\n\\ndp = [0]*(n + 1)\\nf,l = {}, {}\\nfor i in range(len(a)):\\n    x = a[i]\\n    if x not in f:\\n        f[x] = i\\n    l[x] = i\\npr = [a[0]]\\n\\nfor i in range(1, len(a) + 1):\\n    j = i\\n    mx = 0\\n    nums = set()\\n    curxor = 0\\n    b = i\\n    while j > 0:\\n        x = a[j-1]\\n        if l[x] > i - 1:\\n            break\\n        if x not in nums:\\n            nums.add(x)\\n            curxor ^= x\\n        b = min(b, f[x] + 1)\\n        if b == j:\\n            mx = max(mx, dp[j-1] + curxor)\\n        j -= 1\\n    dp[i] = max(dp[i-1], mx)\\nprint(dp[len(a)])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere is an H \\\\times W grid (H vertical, W horizontal), where each square contains a lowercase English letter.\\nSpecifically, the letter in the square at the i-th row and j-th column is equal to the j-th character in the string S_i.\\nSnuke can apply the following operation to this grid any number of times:\\n - Choose two different rows and swap them. Or, choose two different columns and swap them.\\nSnuke wants this grid to be symmetric.\\nThat is, for any 1 \\\\leq i \\\\leq H and 1 \\\\leq j \\\\leq W, the letter in the square at the i-th row and j-th column and the letter in the square at the (H + 1 - i)-th row and (W + 1 - j)-th column should be equal.\\nDetermine if Snuke can achieve this objective.\\n\\n-----Constraints-----\\n - 1 \\\\leq H \\\\leq 12\\n - 1 \\\\leq W \\\\leq 12\\n - |S_i| = W\\n - S_i consists of lowercase English letters.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nH W\\nS_1\\nS_2\\n:\\nS_H\\n\\n-----Output-----\\nIf Snuke can make the grid symmetric, print YES; if he cannot, print NO.\\n\\n-----Sample Input-----\\n2 3\\narc\\nrac\\n\\n-----Sample Output-----\\nYES\\n\\nIf the second and third columns from the left are swapped, the grid becomes symmetric, as shown in the image below:\",\"targets\":\"h,w = map(int,input().split())\\ns = [input() for _ in range(h)]\\na = [-1]*h\\nb = [1]*w\\n\\ndef check(x):\\n    if x==0:\\n        return 1\\n    i = b.index(1)\\n    if x&1:\\n        if all(s[p][i] == s[a[p]][i] for p in range(h)):\\n            b[i] = 0\\n            if check(x-1): return 1\\n            b[i] = 1\\n    for j in range(i+1,w):\\n        if b[j] and all(s[p][i] == s[a[p]][j] for p in range(h)):\\n            b[i] = b[j] = 0\\n            if check(x-2): return 1\\n            b[i] = b[j] = 1\\n    return 0\\n\\ndef dfs(x):\\n    if x==0:\\n        return check(w)\\n    i = a.index(-1)\\n    if x&1:\\n        a[i] = i\\n        if dfs(x-1): return 1\\n        a[i] = -1\\n    for j in range(i+1,h):\\n        if a[j] == -1:\\n            a[i],a[j] = j,i\\n            if dfs(x-2): return 1\\n            a[i] = a[j] = -1\\n    return 0\\n\\nprint(\\\"YES\\\" if dfs(h) else \\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1405\\/B:\\nYou're given an array $a$ of $n$ integers, such that $a_1 + a_2 + \\\\cdots + a_n = 0$.\\n\\nIn one operation, you can choose two different indices $i$ and $j$ ($1 \\\\le i, j \\\\le n$), decrement $a_i$ by one and increment $a_j$ by one. If $i < j$ this operation is free, otherwise it costs one coin.\\n\\nHow many coins do you have to spend in order to make all elements equal to $0$?\\n\\n\\n-----Input-----\\n\\nEach test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \\\\le t \\\\le 5000$). Description of the test cases follows.\\n\\nThe first line of each test case contains an integer $n$ ($1 \\\\le n \\\\le 10^5$)  — the number of elements.\\n\\nThe next line contains $n$ integers $a_1, \\\\ldots, a_n$ ($-10^9 \\\\le a_i \\\\le 10^9$). It is given that $\\\\sum_{i=1}^n a_i = 0$.\\n\\nIt is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the minimum number of coins we have to spend in order to make all elements equal to $0$.\\n\\n\\n-----Example-----\\nInput\\n7\\n4\\n-3 5 -3 1\\n2\\n1 -1\\n4\\n-3 2 -3 4\\n4\\n-1 1 1 -1\\n7\\n-5 7 -6 -4 17 -13 4\\n6\\n-1000000000 -1000000000 -1000000000 1000000000 1000000000 1000000000\\n1\\n0\\n\\nOutput\\n3\\n0\\n4\\n1\\n8\\n3000000000\\n0\\n\\n\\n\\n-----Note-----\\n\\nPossible strategy for the first test case:   Do $(i=2, j=3)$ three times (free), $a = [-3, 2, 0, 1]$.  Do $(i=2, j=1)$ two times (pay two coins), $a = [-1, 0, 0, 1]$.  Do $(i=4, j=1)$ one time (pay one coin), $a = [0, 0, 0, 0]$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nimport math\\ndef II():\\n\\treturn int(sys.stdin.readline())\\n\\ndef LI():\\n\\treturn list(map(int, sys.stdin.readline().split()))\\n\\ndef MI():\\n\\treturn list(map(int, sys.stdin.readline().split()))\\n\\ndef SI():\\n\\treturn sys.stdin.readline().strip()\\nt = II()\\nfor q in range(t):\\n\\tn = II()\\n\\ta = LI()\\n\\td = [0]*n\\n\\ts = 0\\n\\tfor i in range(n):\\n\\t\\ts+=a[i]\\n\\t\\td[i] = s\\n\\tans = min(d)\\n\\tif ans>0:\\n\\t\\tans = 0\\n\\tprint(-ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array.\\n\\n\\nExample:\\nFor num = 5 you should return [0,1,1,2,1,2].\\n\\n\\nFollow up:\\n\\nIt is very easy to come up with a solution with run time O(n*sizeof(integer)). But can you do it in linear time O(n) \\/possibly in a single pass?\\nSpace complexity should be O(n).\\nCan you do it like a boss? Do it without using any builtin function like __builtin_popcount  in c++ or in any other language.\\n\\n\\n\\nCredits:Special thanks to @ syedee  for adding this problem and creating all test cases.\",\"targets\":\"class Solution:\\n     def countBits(self, num):\\n         \\\"\\\"\\\"\\n         :type num: int\\n         :rtype: List[int]\\n         \\\"\\\"\\\"\\n         ans = [0]\\n         while len(ans) < num + 1:\\n             ans += [1 + x for x in ans]\\n         # len(ans) > num\\n         return ans[:num+1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1400\\/C:\\nConsider the following process. You have a binary string (a string where each character is either 0 or 1) $w$ of length $n$ and an integer $x$. You build a new binary string $s$ consisting of $n$ characters. The $i$-th character of $s$ is chosen as follows:\\n\\n  if the character $w_{i-x}$ exists and is equal to 1, then $s_i$ is 1 (formally, if $i > x$ and $w_{i-x} = $ 1, then $s_i = $ 1);  if the character $w_{i+x}$ exists and is equal to 1, then $s_i$ is 1 (formally, if $i + x \\\\le n$ and $w_{i+x} = $ 1, then $s_i = $ 1);  if both of the aforementioned conditions are false, then $s_i$ is 0. \\n\\nYou are given the integer $x$ and the resulting string $s$. Reconstruct the original string $w$.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases.\\n\\nEach test case consists of two lines. The first line contains the resulting string $s$ ($2 \\\\le |s| \\\\le 10^5$, each character of $s$ is either 0 or 1). The second line contains one integer $x$ ($1 \\\\le x \\\\le |s| - 1$).\\n\\nThe total length of all strings $s$ in the input does not exceed $10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer on a separate line as follows:\\n\\n  if no string $w$ can produce the string $s$ at the end of the process, print $-1$;  otherwise, print the binary string $w$ consisting of $|s|$ characters. If there are multiple answers, print any of them. \\n\\n\\n-----Example-----\\nInput\\n3\\n101110\\n2\\n01\\n1\\n110\\n1\\n\\nOutput\\n111011\\n10\\n-1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for t in range(int(input())):\\n    s = [int(c == \\\"1\\\") for c in input()]\\n    x = int(input())\\n    n = len(s)\\n\\n    sat = lambda i: (s[i] if i in range(n) else 1)\\n\\n    w = [(sat(i - x) & sat(i + x)) for i in range(n)]\\n\\n    wat = lambda i: (w[i] if i in range(n) else 0)\\n\\n    s_ref = [(wat(i - x) | wat(i + x)) for i in range(n)]\\n    \\n    if s != s_ref:\\n        print(-1)\\n    else:\\n        print(\\\"\\\".join(map(str, w)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Description:\\n\\n Move all exclamation marks to the end of the sentence\\n\\n# Examples\\n\\n```\\nremove(\\\"Hi!\\\") === \\\"Hi!\\\"\\nremove(\\\"Hi! Hi!\\\") === \\\"Hi Hi!!\\\"\\nremove(\\\"Hi! Hi! Hi!\\\") === \\\"Hi Hi Hi!!!\\\"\\nremove(\\\"Hi! !Hi Hi!\\\") === \\\"Hi Hi Hi!!!\\\"\\nremove(\\\"Hi! Hi!! Hi!\\\") === \\\"Hi Hi Hi!!!!\\\"\\n```\",\"targets\":\"def remove(s):\\n    s = list(s)\\n    exclamations = ''\\n    #look for any exlamations remove and add to exclamations\\n    while '!' in s:\\n        s.remove('!')\\n        exclamations += '!'\\n    #put string back together and add the exclamations\\n    return ''.join(s) + exclamations\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n### Combine strings function\\n```if:coffeescript,haskell,javascript\\nCreate a function named `combineNames` that accepts two parameters (first and last name). The function should return the full name.\\n```\\n```if:python,ruby\\nCreate a function named (`combine_names`) that accepts two parameters (first and last name). The function should return the full name.\\n```\\n```if:csharp\\nCreate a function named (`Combine_names`) that accepts two parameters (first and last name). The function should return the full name.\\n```\\n\\nExample: \\n```python\\ncombine_names('James', 'Stevens')\\n```\\nreturns:\\n```python\\n'James Stevens'\\n```\",\"targets\":\"def combine_names(f1,f2):# Create the combine_names function here\\n    return f1 + ' ' + f2\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/583710ccaa6717322c000105:\\nThis kata is about multiplying a given number by eight if it is an even number and by nine otherwise.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def simple_multiplication(number) :\\n    if number % 2 == 0:\\n       return number *8\\n    else:\\n       return number *9\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/isomorphic-strings\\/:\\nGiven two strings s and t, determine if they are isomorphic.\\n\\nTwo strings are isomorphic if the characters in s can be replaced to get t.\\n\\nAll occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.\\n\\nExample 1:\\n\\n\\nInput: s = \\\"egg\\\", t = \\\"add\\\"\\nOutput: true\\n\\n\\nExample 2:\\n\\n\\nInput: s = \\\"foo\\\", t = \\\"bar\\\"\\nOutput: false\\n\\nExample 3:\\n\\n\\nInput: s = \\\"paper\\\", t = \\\"title\\\"\\nOutput: true\\n\\nNote:\\nYou may assume both s and t have the same length.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def isIsomorphic(self, s, t):\\n         \\\"\\\"\\\"\\n         :type s: str\\n         :type t: str\\n         :rtype: bool\\n         \\\"\\\"\\\"\\n         map1 = {}\\n         map2 = {}\\n         for i in range(len(s)):\\n             if (s[i] in map1 and map1[s[i]] != t[i]) or (t[i] in map2 and map2[t[i]] != s[i]):\\n                 return False\\n             else:\\n                 map1[s[i]] = t[i]\\n                 map2[t[i]] = s[i]\\n         return True\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou would like to get the 'weight' of a name by getting the sum of the ascii values. However you believe that capital letters should be worth more than mere lowercase letters. Spaces, numbers, or any other character are worth 0.\\n\\nNormally in ascii\\n\\n    a has a value of 97\\n    A has a value of 65\\n    ' ' has a value of 32\\n    0 has a value of 48\\n\\nTo find who has the 'weightier' name you will switch all the values so:\\n\\n    A will be 97\\n    a will be 65\\n    ' ' will be 0\\n    0 will be 0\\n    etc...\\n\\nFor example Joe will have a weight of 254, instead of 286 using normal ascii values.\",\"targets\":\"import re\\ndef get_weight(name):\\n    return sum(map(ord, re.sub(r'[^a-zA-Z]', '', name.swapcase())))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/IARCSJUD\\/problems\\/WORDLIST:\\nIn this problem the input will consist of a number of lines of English text consisting of the letters of the English alphabet, the punctuation marks ' (apostrophe), . (full stop), , (comma), ; (semicolon), :(colon) and white space characters (blank, newline).\\nYour task is print the words in the text in lexicographic order (that is, dictionary order). Each word should appear exactly once in your list. You can ignore the case (for instance, \\\"The\\\" and \\\"the\\\" are to be treated as the same word). There should be no uppercase letters in the output.\\nFor example, consider the following candidate for the input text: \\nThis is a sample piece of text to illustrate this \\nproblem.\\n\\nThe corresponding output would read as:\\na\\nillustrate\\nis\\nof\\npiece\\nproblem\\nsample\\ntext\\nthis\\nto\\n\\n-----Input format-----\\n- The first line of input contains a single integer $N$, indicating the number of lines in the input.\\n- This is followed by $N$ lines of input text.\\n\\n-----Output format-----\\n- The first line of output contains a single integer $M$ indicating the number of distinct words in the given text. \\n- The next $M$ lines list out these words in lexicographic order.\\n\\n-----Constraints-----\\n- $1 \\\\leq N \\\\leq 10000$\\n- There are at most 80 characters in each line.\\n- There are at the most 1000 distinct words in the given text.\\n\\n-----Sample Input-----\\n2\\nThis is a sample piece of text to illustrate this \\nproblem. \\n\\n-----Sample Output-----\\n10\\na\\nillustrate\\nis\\nof\\npiece\\nproblem\\nsample\\ntext\\nthis\\nto\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"lst=[]\\r\\nans=[]\\r\\npunctuations = '''!()-[]{};:'\\\"\\\\,<>.\\/?@#$%^&*_~'''\\r\\nt=int(input())\\r\\nfor i in range(t):\\r\\n    str= input()\\r\\n    s=str.lower()\\r\\n    no_punct = \\\"\\\"\\r\\n    for char in s:\\r\\n       if char not in punctuations:\\r\\n           no_punct = no_punct + char\\r\\n    lst.extend(no_punct.split())\\r\\n    \\r\\n    \\r\\nfor i in lst:\\r\\n    if i not in ans:\\r\\n        ans.append(i)\\r\\nans.sort()\\r\\nprint(len(ans))\\r\\nfor j in ans:\\r\\n    print(j)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe  Chef  has bought $N$ boxes of Tiles. The number of tiles present in  $i^{th}$ box is  $i$  ($i   $ varies from $1$ to $N$) . The Chef  has two houses  with  $N$  rooms  each, whose  floors  is a square with area $(i*i)$ ,i varies from $(1....N)$. He want to distribute equal number of tiles from $i^{th}$ box to any two rooms (each room must belong to one house ) such that all tiles  of $i^ { th}$  box is used and floor of  both rooms of different houses are tiled completely.\\nSince chef is busy doing some other works so he wants your help to count the total number of rooms of both houses that will be tiled completely.\\nNote $:$ size of  each tile present in boxes has length and breadth equal to $1$. It is not mandatory to use all the boxes.\\nA room should be tilled completely from a single box.\\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase contains one integer $N$.\\n\\n-----Output:-----\\nFor each testcase print  the total number of rooms of both houses that will be tiled completely.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 5000$\\n- $1 \\\\leq N \\\\leq 10^{12}$\\n\\n-----Sample Input:-----\\n1\\n16\\n\\n-----Sample Output:-----\\n4\\n\\n-----EXPLANATION:-----\\nThe room $1$ and $2$ of both the houses are completely tiled.\",\"targets\":\"# cook your dish here\\nimport math\\nt=int(input())\\nfor i in range(t):\\n\\tn=int(input())\\n\\tp=n\\/\\/2\\n\\tprint(math.floor(math.sqrt(p))*2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc075\\/tasks\\/abc075_d:\\nWe have N points in a two-dimensional plane.\\n\\nThe coordinates of the i-th point (1 \\\\leq i \\\\leq N) are (x_i,y_i).\\n\\nLet us consider a rectangle whose sides are parallel to the coordinate axes that contains K or more of the N points in its interior.\\n\\nHere, points on the sides of the rectangle are considered to be in the interior.\\n\\nFind the minimum possible area of such a rectangle.  \\n\\n-----Constraints-----\\n - 2 \\\\leq K \\\\leq N \\\\leq 50 \\n - -10^9 \\\\leq x_i,y_i \\\\leq 10^9 (1 \\\\leq i \\\\leq N) \\n - x_i≠x_j (1 \\\\leq i<j \\\\leq N) \\n - y_i≠y_j (1 \\\\leq i<j \\\\leq N) \\n - All input values are integers. (Added at 21:50 JST)  \\n\\n-----Input-----\\nInput is given from Standard Input in the following format:  \\nN K  \\nx_1 y_1\\n:  \\nx_{N} y_{N}\\n\\n-----Output-----\\nPrint the minimum possible area of a rectangle that satisfies the condition.  \\n\\n-----Sample Input-----\\n4 4\\n1 4\\n3 3\\n6 2\\n8 1\\n\\n-----Sample Output-----\\n21\\n\\nOne rectangle that satisfies the condition with the minimum possible area has the following vertices: (1,1), (8,1), (1,4) and (8,4).\\n\\nIts area is (8-1) × (4-1) = 21.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,K = map(int,input().split())\\nd = [[int(i) for i in input().split()] for _ in range(n)]\\nx = sorted(d,key=lambda x:x[0])\\ny = sorted(d,key=lambda x:x[1])\\nans = float(\\\"inf\\\")\\n\\nfor i in range(n):\\n    for j in range(i+1,n):\\n        for k in range(n):\\n            cnt = 0\\n            for l in range(k,n):\\n                if x[i][0] <= y[l][0] <= x[j][0]: cnt += 1\\n                if cnt == K:\\n                    dx = x[j][0]-x[i][0]\\n                    dy = y[l][1]-y[k][1]\\n                    ans = min(ans, dx*dy)\\n                    break\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/367\\/C:\\nLet's call an array consisting of n integer numbers a_1, a_2, ..., a_{n}, beautiful if it has the following property:\\n\\n  consider all pairs of numbers x, y (x ≠ y), such that number x occurs in the array a and number y occurs in the array a;  for each pair x, y must exist some position j (1 ≤ j < n), such that at least one of the two conditions are met, either a_{j} = x, a_{j} + 1 = y, or a_{j} = y, a_{j} + 1 = x. \\n\\nSereja wants to build a beautiful array a, consisting of n integers. But not everything is so easy, Sereja's friend Dima has m coupons, each contains two integers q_{i}, w_{i}. Coupon i costs w_{i} and allows you to use as many numbers q_{i} as you want when constructing the array a. Values q_{i} are distinct. Sereja has no coupons, so Dima and Sereja have made the following deal. Dima builds some beautiful array a of n elements. After that he takes w_{i} rubles from Sereja for each q_{i}, which occurs in the array a. Sereja believed his friend and agreed to the contract, and now he is wondering, what is the maximum amount of money he can pay.\\n\\nHelp Sereja, find the maximum amount of money he can pay to Dima.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (1 ≤ n ≤ 2·10^6, 1 ≤ m ≤ 10^5). Next m lines contain pairs of integers. The i-th line contains numbers q_{i}, w_{i} (1 ≤ q_{i}, w_{i} ≤ 10^5).\\n\\nIt is guaranteed that all q_{i} are distinct.\\n\\n\\n-----Output-----\\n\\nIn a single line print maximum amount of money (in rubles) Sereja can pay.\\n\\nPlease, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.\\n\\n\\n-----Examples-----\\nInput\\n5 2\\n1 2\\n2 3\\n\\nOutput\\n5\\n\\nInput\\n100 3\\n1 2\\n2 1\\n3 1\\n\\nOutput\\n4\\n\\nInput\\n1 2\\n1 1\\n2 100\\n\\nOutput\\n100\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample Sereja can pay 5 rubles, for example, if Dima constructs the following array: [1, 2, 1, 2, 2]. There are another optimal arrays for this test.\\n\\nIn the third sample Sereja can pay 100 rubles, if Dima constructs the following array: [2].\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def Fun(n):\\n    if(n%2): return n*(n-1)\\/\\/2+1\\n    return n*n\\/\\/2\\n\\nn,m = list(map(int,input().split()))\\nq = [0] * (m)\\nw = [0] * (m)\\nfor i in range(m):\\n    q[i],w[i] = [int(x) for x in input().split()]\\n    #print(q[i],w[i])\\nw.sort(reverse = True)\\n#print(*w)\\ns = 0\\nv = 0\\n#print(\\\"n=\\\",n)\\nfor i in range(m):\\n    #print(\\\"i=\\\",i,\\\" v=\\\",v,\\\"w[i]=\\\",w[i])\\n    if(Fun(i+1)>n): break\\n    s+=w[i]\\nprint(s)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA permutation of length $n$ is an array $p=[p_1,p_2,\\\\dots,p_n]$, which contains every integer from $1$ to $n$ (inclusive) and, moreover, each number appears exactly once. For example, $p=[3,1,4,2,5]$ is a permutation of length $5$.\\n\\nFor a given number $n$ ($n \\\\ge 2$), find a permutation $p$ in which absolute difference (that is, the absolute value of difference) of any two neighboring (adjacent) elements is between $2$ and $4$, inclusive. Formally, find such permutation $p$ that $2 \\\\le |p_i - p_{i+1}| \\\\le 4$ for each $i$ ($1 \\\\le i < n$).\\n\\nPrint any such permutation for the given integer $n$ or determine that it does not exist.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $t$ ($1 \\\\le t \\\\le 100$) — the number of test cases in the input. Then $t$ test cases follow.\\n\\nEach test case is described by a single line containing an integer $n$ ($2 \\\\le n \\\\le 1000$).\\n\\n\\n-----Output-----\\n\\nPrint $t$ lines. Print a permutation that meets the given requirements. If there are several such permutations, then print any of them. If no such permutation exists, print -1.\\n\\n\\n-----Example-----\\nInput\\n6\\n10\\n2\\n4\\n6\\n7\\n13\\n\\nOutput\\n9 6 10 8 4 7 3 1 5 2 \\n-1\\n3 1 4 2 \\n5 3 6 2 4 1 \\n5 1 3 6 2 4 7 \\n13 9 7 11 8 4 1 3 5 2 6 10 12\",\"targets\":\"from sys import stdin\\n \\nfor _ in range(int(stdin.readline())):\\n    inp = int(stdin.readline())\\n    if inp<4:\\n        print('-1')\\n    else:\\n        odd = list(range(5,inp+1,2))\\n        odd.reverse()\\n        even = list(range(6,inp+1,2))\\n        r = odd+[3,1,4,2]+even\\n        print(' '.join(map(str,r)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc104\\/tasks\\/abc104_d:\\nThe ABC number of a string T is the number of triples of integers (i, j, k) that satisfy all of the following conditions:\\n - 1 ≤ i < j < k ≤ |T| (|T| is the length of T.)\\n - T_i = A (T_i is the i-th character of T from the beginning.)\\n - T_j = B\\n - T_k = C\\nFor example, when T = ABCBC, there are three triples of integers (i, j, k) that satisfy the conditions: (1, 2, 3), (1, 2, 5), (1, 4, 5). Thus, the ABC number of T is 3.\\nYou are given a string S. Each character of S is A, B, C or ?.\\nLet Q be the number of occurrences of ? in S. We can make 3^Q strings by replacing each occurrence of ? in S with A, B or C. Find the sum of the ABC numbers of all these strings.\\nThis sum can be extremely large, so print the sum modulo 10^9 + 7.\\n\\n-----Constraints-----\\n - 3 ≤ |S| ≤ 10^5\\n - Each character of S is A, B, C or ?.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nS\\n\\n-----Output-----\\nPrint the sum of the ABC numbers of all the 3^Q strings, modulo 10^9 + 7.\\n\\n-----Sample Input-----\\nA??C\\n\\n-----Sample Output-----\\n8\\n\\nIn this case, Q = 2, and we can make 3^Q = 9 strings by by replacing each occurrence of ? with A, B or C. The ABC number of each of these strings is as follows:\\n - AAAC: 0\\n - AABC: 2\\n - AACC: 0\\n - ABAC: 1\\n - ABBC: 2\\n - ABCC: 2\\n - ACAC: 0\\n - ACBC: 1\\n - ACCC: 0\\nThe sum of these is 0 + 2 + 0 + 1 + 2 + 2 + 0 + 1 + 0 = 8, so we print 8 modulo 10^9 + 7, that is, 8.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"MOD = 10**9 + 7\\nS = input()\\nres = 0\\ndp0 = 1 # ''\\ndp1 = 0 # 'a'\\ndp2 = 0 # 'ab'\\ndp3 = 0 # 'abc'\\n\\nfor c in S:\\n    if c == 'A':\\n        dp1 += dp0\\n    elif c == 'B':\\n        dp2 += dp1\\n    elif c == 'C':\\n        dp3 += dp2\\n    else:\\n        dp0,dp1,dp2,dp3 = dp0*3,dp1*3+dp0,dp2*3+dp1,dp3*3+dp2\\n    dp0 %= MOD\\n    dp1 %= MOD\\n    dp2 %= MOD\\n    dp3 %= MOD\\nprint(dp3)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAhoy Matey!\\n\\nWelcome to the seven seas.\\n\\nYou are the captain of a pirate ship.\\n\\nYou are in battle against the royal navy.\\n\\nYou have cannons at the ready.... or are they?\\n\\nYour task is to check if the gunners are loaded and ready, if they are: ```Fire!```\\n\\nIf they aren't ready: ```Shiver me timbers!```\\n\\nYour gunners for each test case are 4 or less.\\n\\nWhen you check if they are ready their answers are in a dictionary and will either be: ```aye``` or ```nay```\\n\\nFiring with less than all gunners ready is non-optimum (this is not fire at will, this is fire by the captain's orders or walk the plank, dirty sea-dog!)\\n\\nIf all answers are 'aye' then Fire!\\nif one or more are 'nay' then Shiver me timbers!\\n\\nAlso, check out the new Pirates!! Kata:\\nhttps:\\/\\/www.codewars.com\\/kata\\/57e2d5f473aa6a476b0000fe\",\"targets\":\"def cannons_ready(gunners):\\n    if any([x for x in list(gunners.values()) if x!='aye']):\\n           return 'Shiver me timbers!'\\n    else:\\n           return 'Fire!'\\n  # Fire! or Shiver me timbers!\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThis is the first subtask of problem F. The only differences between this and the second subtask are the constraints on the value of $m$ and the time limit. You need to solve both subtasks in order to hack this one.\\n\\nThere are $n+1$ distinct colours in the universe, numbered $0$ through $n$. There is a strip of paper $m$ centimetres long initially painted with colour $0$. \\n\\nAlice took a brush and painted the strip using the following process. For each $i$ from $1$ to $n$, in this order, she picks two integers $0 \\\\leq a_i < b_i \\\\leq m$, such that the segment $[a_i, b_i]$ is currently painted with a single colour, and repaints it with colour $i$. \\n\\nAlice chose the segments in such a way that each centimetre is now painted in some colour other than $0$. Formally, the segment $[i-1, i]$ is painted with colour $c_i$ ($c_i \\\\neq 0$). Every colour other than $0$ is visible on the strip.\\n\\nCount the number of different pairs of sequences $\\\\{a_i\\\\}_{i=1}^n$, $\\\\{b_i\\\\}_{i=1}^n$ that result in this configuration. \\n\\nSince this number may be large, output it modulo $998244353$.\\n\\n\\n-----Input-----\\n\\nThe first line contains a two integers $n$, $m$ ($1 \\\\leq n \\\\leq 500$, $n = m$) — the number of colours excluding the colour $0$ and the length of the paper, respectively.\\n\\nThe second line contains $m$ space separated integers $c_1, c_2, \\\\ldots, c_m$ ($1 \\\\leq c_i \\\\leq n$) — the colour visible on the segment $[i-1, i]$ after the process ends. It is guaranteed that for all $j$ between $1$ and $n$ there is an index $k$ such that $c_k = j$.\\n\\nNote that since in this subtask $n = m$, this means that $c$ is a permutation of integers $1$ through $n$.\\n\\n\\n-----Output-----\\n\\nOutput a single integer — the number of ways Alice can perform the painting, modulo $998244353$.\\n\\n\\n-----Examples-----\\nInput\\n3 3\\n1 2 3\\n\\nOutput\\n5\\n\\nInput\\n7 7\\n4 5 1 6 2 3 7\\n\\nOutput\\n165\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, there are $5$ ways, all depicted in the figure below. Here, $0$ is white, $1$ is red, $2$ is green and $3$ is blue.\\n\\n[Image]\\n\\nBelow is an example of a...\",\"targets\":\"n, m = map(int, input().split())\\nl = list(map(int, input().split()))\\nindex = [[0 for i in range(n)] for j in range(n)]\\nfor i in range(n):\\n\\tmini = 10000000000000\\n\\tfor j in range(i, n):\\n\\t\\tif l[j] < mini:\\n\\t\\t\\tinde = j\\n\\t\\t\\tmini = l[j]\\n\\t\\tindex[i][j] = inde\\nprime = 998244353\\nd = {}\\nval = [[1 for i in range(n + 1)] for j in range(n + 1)]\\nfor i in range(n):\\n\\tfor j in range(n - i):\\n\\t\\tif i == 0:\\n\\t\\t\\tval[j][j + i] = 1\\n\\t\\telif i == 1:\\n\\t\\t\\tval[j][j + i] = 2\\n\\t\\telse:\\n\\t\\t\\tind = index[j][j + i]\\n\\t\\t\\tsumap = 0\\n\\t\\t\\tsumak = 0\\n\\t\\t\\tfor p in range(j, ind +1):\\n\\t\\t\\t\\tsumap += (val[j][p - 1] * val[p][ind - 1]) % prime\\n\\t\\t\\tfor k in range(ind, j + i + 1):\\n\\t\\t\\t\\tsumak += (val[ind + 1][k] * val[k + 1][j + i]) % prime\\n\\t\\t\\tval[j][j + i] = (sumap * sumak) % prime\\nprint(val[0][n-1])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef likes inequalities. Please help him to solve next one.\\nGiven four integers a, b, c, d. Find number of solutions x < y, where a ≤ x ≤ b and c ≤ y ≤ d and x, y integers.\\n\\n-----Input-----\\nThe first line contains an integer T denoting number of tests.\\nFirst line of each test case contains four positive integer numbers a, b, c and d.\\n\\n-----Output-----\\nFor each test case, output a single number each in separate line denoting number of integer solutions as asked in the problem.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 20 \\n- 1 ≤ a, b, c, d ≤ 106 \\n\\n-----Subtasks-----\\n- Subtask #1: (30 points)  1 ≤ a, b, c, d ≤ 103.\\n- Subtask #2: (70 points)  Original constraints.\\n\\n-----Example-----\\nInput:1\\n2 3 3 4\\n\\nOutput:3\\n\\nInput:1\\n2 999999 1 1000000\\n\\nOutput:499998500001\",\"targets\":\"# Akhilesh Ravi\\n# Codechef - Chef and Inequality\\n\\nT = int(input())\\nl = []\\nfor i in range(T):\\n l += [[int(j) for j in input().split()]]\\n\\nl1 = []\\nfor i in l:\\n a,b,c,d = tuple(i)\\n if a >= d:\\n  l1 += [0]\\n  \\n elif b < c:\\n  l1 += [(b-a+1)*(d-c+1)]\\n  \\n elif c <= a <= d <= b:\\n  n = d-a\\n  l1 += [n*(n+1)\\/2]\\n  \\n elif c <= a <= b <= d:\\n  l1 += [(d-a) * (d-a+1)\\/2\\n    - (d-b-1) * (d-b)\\/2]\\n  \\n elif a < c <= d <= b:\\n  l1 += [ (d-c+1) * (c-a)\\n    + (d-c) * (d-c+1)\\/2 ]\\n  \\n elif a < c <= b <= d:\\n  l1 += [ (d-c+1) * (c-a)\\n    + (d-c) * (d-c+1)\\/2\\n    - (d-b-1) * (d-b)\\/2]\\n  \\n else:\\n  l1 += [0]\\n\\nfor i in l1:\\n print(i)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55e4c52ad58df7509c00007e:\\n# Invalid Login - Bug Fixing #11\\n\\nOh NO! Timmy has moved divisions... but now he's in the field of security. Timmy, being the top coder he is, has allowed some bad code through. You must help Timmy and filter out any injected code!\\n\\n## Task\\n\\nYour task is simple, search the password string for any injected code (Injected code is any thing that would be used to exploit flaws in the current code, so basically anything that contains `||` or `\\/\\/`) if you find any you must return `\\\"Wrong username or password!\\\"` because no one likes someone trying to cheat their way in!\\n\\n## Preloaded\\n\\nYou will be given a preloaded class called `Database` with a method `login` this takes two parameters `username` and `password`. This is a generic login function which will check the database for the user it will return either `'Successfully Logged in!'` if it passes the test or `'Wrong username or password!'` if either the password is wrong or username does not exist.\\n\\n## Usage\\n\\n```python\\ndatabase = Database()\\ndatabase.login('Timmy', 'password')\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def validate(username, password):\\n    print (username, password)\\n    if username == 'Timmy' and password == 'password':\\n        return 'Successfully Logged in!'\\n    elif username == 'Alice' and password == 'alice':\\n        return 'Successfully Logged in!'\\n    elif username == 'Johny' and password == 'Hf7FAbf6':\\n        return 'Successfully Logged in!'  \\n    elif username == 'Roger' and password == 'Cheater':\\n        return 'Successfully Logged in!'\\n    elif username == 'Simon' and password == 'password':\\n        return 'Successfully Logged in!'\\n    elif username == 'Simon' and password == 'says':\\n        return 'Successfully Logged in!'\\n    elif username == 'Roger' and password == 'pass':\\n        return 'Successfully Logged in!'\\n    elif username == 'Admin' and password == 'ads78adsg7dasga':\\n        return 'Successfully Logged in!'\\n    else:\\n        return 'Wrong username or password!'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA string is called bracket sequence if it does not contain any characters other than \\\"(\\\" and \\\")\\\". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters \\\"+\\\" and \\\"1\\\" into this sequence. For example, \\\"\\\", \\\"(())\\\" and \\\"()()\\\" are RBS and \\\")(\\\" and \\\"(()\\\" are not.\\n\\nWe can see that each opening bracket in RBS is paired with some closing bracket, and, using this fact, we can define nesting depth of the RBS as maximum number of bracket pairs, such that the $2$-nd pair lies inside the $1$-st one, the $3$-rd one — inside the $2$-nd one and so on. For example, nesting depth of \\\"\\\" is $0$, \\\"()()()\\\" is $1$ and \\\"()((())())\\\" is $3$.\\n\\nNow, you are given RBS $s$ of even length $n$. You should color each bracket of $s$ into one of two colors: red or blue. Bracket sequence $r$, consisting only of red brackets, should be RBS, and bracket sequence, consisting only of blue brackets $b$, should be RBS. Any of them can be empty. You are not allowed to reorder characters in $s$, $r$ or $b$. No brackets can be left uncolored.\\n\\nAmong all possible variants you should choose one that minimizes maximum of $r$'s and $b$'s nesting depth. If there are multiple solutions you can print any of them.\\n\\n\\n-----Input-----\\n\\nThe first line contains an even integer $n$ ($2 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the length of RBS $s$.\\n\\nThe second line contains regular bracket sequence $s$ ($|s| = n$, $s_i \\\\in \\\\{$\\\"(\\\", \\\")\\\"$\\\\}$).\\n\\n\\n-----Output-----\\n\\nPrint single string $t$ of length $n$ consisting of \\\"0\\\"-s and \\\"1\\\"-s. If $t_i$ is equal to 0 then character $s_i$ belongs to RBS $r$, otherwise $s_i$ belongs to $b$.\\n\\n\\n-----Examples-----\\nInput\\n2\\n()\\n\\nOutput\\n11\\n\\nInput\\n4\\n(())\\n\\nOutput\\n0101\\n\\nInput\\n10\\n((()())())\\n\\nOutput\\n0110001111\\n\\n\\n-----Note-----\\n\\nIn the first example one of optimal solutions is $s = $ \\\"$\\\\color{blue}{()}$\\\". $r$ is empty and $b = $ \\\"$()$\\\". The answer is $\\\\max(0, 1) = 1$.\\n\\nIn the second example it's optimal to make $s = $ \\\"$\\\\color{red}{(}\\\\color{blue}{(}\\\\color{red}{)}\\\\color{blue}{)}$\\\". $r = b...\",\"targets\":\"n = int( input() )\\ns = input()\\nd = 0\\nl = []\\nfor c in s:\\n    if c == '(':\\n        l.append(d)\\n        d ^= 1\\n    else:\\n        d ^= 1\\n        l.append( d )\\n\\nprint( \\\"\\\".join( [ str(i) for i in l ]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1290\\/B:\\nLet's call two strings $s$ and $t$ anagrams of each other if it is possible to rearrange symbols in the string $s$ to get a string, equal to $t$.\\n\\nLet's consider two strings $s$ and $t$ which are anagrams of each other. We say that $t$ is a reducible anagram of $s$ if there exists an integer $k \\\\ge 2$ and $2k$ non-empty strings $s_1, t_1, s_2, t_2, \\\\dots, s_k, t_k$ that satisfy the following conditions:\\n\\n  If we write the strings $s_1, s_2, \\\\dots, s_k$ in order, the resulting string will be equal to $s$;  If we write the strings $t_1, t_2, \\\\dots, t_k$ in order, the resulting string will be equal to $t$;  For all integers $i$ between $1$ and $k$ inclusive, $s_i$ and $t_i$ are anagrams of each other. \\n\\nIf such strings don't exist, then $t$ is said to be an irreducible anagram of $s$. Note that these notions are only defined when $s$ and $t$ are anagrams of each other.\\n\\nFor example, consider the string $s = $ \\\"gamegame\\\". Then the string $t = $ \\\"megamage\\\" is a reducible anagram of $s$, we may choose for example $s_1 = $ \\\"game\\\", $s_2 = $ \\\"gam\\\", $s_3 = $ \\\"e\\\" and $t_1 = $ \\\"mega\\\", $t_2 = $ \\\"mag\\\", $t_3 = $ \\\"e\\\":\\n\\n [Image] \\n\\nOn the other hand, we can prove that $t = $ \\\"memegaga\\\" is an irreducible anagram of $s$.\\n\\nYou will be given a string $s$ and $q$ queries, represented by two integers $1 \\\\le l \\\\le r \\\\le |s|$ (where $|s|$ is equal to the length of the string $s$). For each query, you should find if the substring of $s$ formed by characters from the $l$-th to the $r$-th has at least one irreducible anagram.\\n\\n\\n-----Input-----\\n\\nThe first line contains a string $s$, consisting of lowercase English characters ($1 \\\\le |s| \\\\le 2 \\\\cdot 10^5$).\\n\\nThe second line contains a single integer $q$ ($1 \\\\le q \\\\le 10^5$)  — the number of queries.\\n\\nEach of the following $q$ lines contain two integers $l$ and $r$ ($1 \\\\le l \\\\le r \\\\le |s|$), representing a query for the substring of $s$ formed by characters from the $l$-th to the $r$-th.\\n\\n\\n-----Output-----\\n\\nFor each query, print a single line containing \\\"Yes\\\" (without quotes) if the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nreadline = sys.stdin.readline\\n\\nS = list([ord(x)-97 for x in readline().strip()])\\nN = len(S)\\ntable = [[0]*26 for _ in range(N)]\\nfor i in range(N):\\n    table[i][S[i]] = 1\\nfor i in range(1, N):\\n    for j in range(26):\\n        table[i][j] += table[i-1][j]\\n\\nQ = int(readline())\\nAns = [None]*Q\\nfor qu in range(Q):\\n    l, r = list(map(int, readline().split()))\\n    l -= 1\\n    r -= 1 \\n    if l == r or S[l] != S[r]:\\n        Ans[qu] = True\\n        continue\\n    K = [table[r][j] - table[l][j] for j in range(26)]\\n    if len([k for k in K if k]) <= 2:\\n        Ans[qu] = False\\n    else:\\n        Ans[qu] = True\\nprint('\\\\n'.join(['Yes' if s else 'No' for s in Ans]))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5bbecf840441ca6d6a000126:\\nWe have an integer array with unique elements and we want to do the permutations that have an element fixed, in other words, these permutations should have a certain element at the same position than the original.\\n\\nThese permutations will be called: **permutations with one fixed point**.\\n\\nLet's see an example with an array of four elements and we want the permutations that have a coincidence **only at  index 0**, so these permutations are (the permutations between parenthesis):\\n``` \\narr = [1, 2, 3, 4]\\n      (1, 3, 4, 2)\\n      (1, 4, 2, 3)\\nTwo permutations matching with arr only at index 0\\n``` \\n\\nLet's see the permutations of the same array with only one coincidence at index **1**:\\n``` \\narr = [1, 2, 3, 4]\\n      (3, 2, 4, 1)\\n      (4, 2, 1, 3)\\nTwo permutations matching with arr only at index 1\\n```\\nOnce again, let's see the permutations of the same array with only one coincidence at index **2**:\\n``` \\narr = [1, 2, 3, 4]\\n      (2, 4, 3, 1)\\n      (4, 1, 3, 2)\\nTwo permutations matching with arr only at index 2\\n```\\nFinally, let's see the permutations of the same array with only one coincidence at index **3**:\\n``` \\narr = [1, 2, 3, 4]\\n      (2, 3, 1, 4)\\n      (3, 1, 2, 4)\\nTwo permutations matching with arr only at index 3\\n```\\nFor this array given above (arr) :\\n\\n- We conclude that we have 8 permutations with one fixed point (two at each index of arr).\\n\\n- We may do the same development for our array, `arr`, with two fixed points and we will get `6` permutations.\\n\\n- There are no permutations with coincidences only at three indexes.\\n\\n- It's good to know that the amount of permutations with no coincidences at all are `9`. See the kata Shuffle It Up!!\\n\\nIn general:\\n\\n- When the amount of fixed points is equal to the array length, there is only one permutation, the original array.\\n\\n- When the amount of fixed points surpasses the length of the array, obvously, there are no permutations at all.\\n\\nCreate a function that receives the length of the array and the number of fixed points and may output the total amount of permutations...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from functools import lru_cache\\n\\n@lru_cache(maxsize=None)\\ndef f(n):\\n    return (n-1) * (f(n-1) + f(n-2)) if n > 2 else int(n != 1)\\n\\ndef fixed_points_perms(n,k):\\n    return n * fixed_points_perms(n-1, k-1) \\/\\/ k if k else f(n)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55f0a7d8c44c6f1438000013:\\nWe need a function that may receive a list  of an unknown amount of points in the same plane, having each of them, cartesian coordinates of the form (x, y) and may find the biggest triangle (the one with the largest area) formed by all of the possible combinations of groups of three points of that given list.\\nOf course, we will have some combinations of three points that does not form a triangle, because the three points are aligned.\\nThe function find_biggTriang(listOfPoints), will output a list with the following data in the order presented bellow:\\n```python\\n[(1), (2), (3), (4), 5]\\n\\n(1) - Number of points received (You may assume that you will not receive duplicates)\\n\\n(2) - Maximum possible amount of triangles that can be formed with the amount of received \\n      points (number in data (1) above). It should be expressed as an integer, (no L for long type \\n      variables)\\n\\n(3) - Real Number of triangles that can be formed with the given points. (The function should have a \\n      counter for all the cases of three points aligned). It should be expressedas as an integer.\\n\\n(4) - The triangles that have maximum area in a sorted list. \\n      If there are two triangles with the biggest area, the result will be presented in this way:\\n      [[[xA1, yA1], [xB1, yB1], [xC1, yC1]], [[xA2, yA2], [xB2, yB2], [xC2, yC2]]]\\n      But if we have only one triangle with max. area, there is no need of a spare level of braces, \\n      so it will be as follows: [[xA1, yA1], [xB1, yB1], [xC1, yC1]]\\n\\n(5) - The value of max. area (absolute value) that was found as a float. As we did not define the \\n      units of length for the coordinates, the units for the area will be ignored.\\n\\n```\\n\\nIt would be useful to apply the expression for the area of a triangle with vertices A, B, and C, is equal to the half of the determinant of the matrix, using the respective coordinates as follows:\\n\\n```python\\n\\n                               | xA    yA    1|\\nArea Triangle(A, B, C) = 1\\/2 . | xB    yB    1|\\n                               | xC    yC   ...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from itertools import combinations\\n\\ndef area(t):\\n    (a,b),(c,d),(e,f) = t\\n    return abs(a*d+b*e+c*f-d*e-a*f-b*c)\\/2\\n\\ndef find_biggTriang(lst):\\n    tris  = list(combinations(lst,3))\\n    areas = list(map(area,tris))\\n    m     = max(areas)\\n    mTris = [list(map(list,t)) for t,v in zip(tris,areas) if v==m]\\n    return [ len(lst), len(tris), sum(map(bool,areas)),\\n             mTris if len(mTris)!=1 else mTris.pop(), m]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/596144f0ada6db581200004f:\\nLeonardo Fibonacci in a rare portrait of his younger days\\n\\nI assume you are all familiar with the famous Fibonacci sequence, having to get each number as the sum of the previous two (and typically starting with either `[0,1]` or `[1,1]` as the first numbers).\\n\\nWhile there are plenty of variation on it ([including](https:\\/\\/www.codewars.com\\/kata\\/tribonacci-sequence) [a few](https:\\/\\/www.codewars.com\\/kata\\/fibonacci-tribonacci-and-friends) [I wrote](https:\\/\\/www.codewars.com\\/kata\\/triple-shiftian-numbers\\/)), usually the catch is all the same: get a starting (signature) list of numbers, then proceed creating more with the given rules.\\n\\nWhat if you were to get to get two parameters, one with the signature (starting value) and the other with the number you need to sum at each iteration to obtain the next one?\\n\\nAnd there you have it, getting 3 parameters:\\n\\n* a signature of length `length`\\n* a second parameter is a list\\/array of indexes of the last `length` elements you need to use to obtain the next item in the sequence (consider you can end up not using a few or summing the same number multiple times)' in other words, if you get a signature of length `5` and `[1,4,2]` as indexes, at each iteration you generate the next number by summing the 2nd, 5th and 3rd element (the ones with indexes `[1,4,2]`) of the last 5 numbers\\n* a third and final parameter is of course which sequence element you need to return (starting from zero, I don't want to bother you with adding\\/removing 1s or just coping with the fact that after years on CodeWars we all count as computers do):\\n\\n```python\\ncustom_fib([1,1],[0,1],2) == 2 #classical fibonacci!\\ncustom_fib([1,1],[0,1],3) == 3 #classical fibonacci!\\ncustom_fib([1,1],[0,1],4) == 5 #classical fibonacci!\\ncustom_fib([3,5,2],[0,1,2],4) == 17 #similar to my Tribonacci\\ncustom_fib([7,3,4,1],[1,1],6) == 2 #can you figure out how it worked ;)?\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import deque\\n\\ndef custom_fib(signature,indexes,n):\\n    s = deque(signature, maxlen=len(signature))\\n    for i in range(n):\\n        s.append(sum(s[i] for i in indexes))\\n    return s[0]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/perfect-number\\/:\\nWe define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. \\n\\nNow, given an integer n, write a function that returns true when it is a perfect number and false when it is not.\\n\\n\\nExample:\\n\\nInput: 28\\nOutput: True\\nExplanation: 28 = 1 + 2 + 4 + 7 + 14\\n\\n\\n\\nNote:\\nThe input number n will not exceed 100,000,000. (1e8)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def checkPerfectNumber(self, num):\\n         \\\"\\\"\\\"\\n         :type num: int\\n         :rtype: bool\\n         \\\"\\\"\\\"\\n         if num <= 1:\\n             return False\\n         factors = []\\n         for i in range(1, int(num ** 0.5) + 1):\\n             if num % i == 0:\\n                 factors.append(i)\\n         for factor in factors:\\n             if num \\/ factor not in factors and factor > 1:\\n                 factors.append(num \\/ factor)\\n         print(factors)\\n         if num == sum(i for i in factors):\\n             return True\\n         else:\\n             return False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1389\\/C:\\nLet's call left cyclic shift of some string $t_1 t_2 t_3 \\\\dots t_{n - 1} t_n$ as string $t_2 t_3 \\\\dots t_{n - 1} t_n t_1$.\\n\\nAnalogically, let's call right cyclic shift of string $t$ as string $t_n t_1 t_2 t_3 \\\\dots t_{n - 1}$.\\n\\nLet's say string $t$ is good if its left cyclic shift is equal to its right cyclic shift.\\n\\nYou are given string $s$ which consists of digits 0–9.\\n\\nWhat is the minimum number of characters you need to erase from $s$ to make it good?\\n\\n\\n-----Input-----\\n\\nThe first line contains single integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases.\\n\\nNext $t$ lines contains test cases — one per line. The first and only line of each test case contains string $s$ ($2 \\\\le |s| \\\\le 2 \\\\cdot 10^5$). Each character $s_i$ is digit 0–9.\\n\\nIt's guaranteed that the total length of strings doesn't exceed $2 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the minimum number of characters you need to erase from $s$ to make it good.\\n\\n\\n-----Example-----\\nInput\\n3\\n95831\\n100120013\\n252525252525\\n\\nOutput\\n3\\n5\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, you can erase any $3$ characters, for example, the $1$-st, the $3$-rd, and the $4$-th. You'll get string 51 and it is good.\\n\\nIn the second test case, we can erase all characters except 0: the remaining string is 0000 and it's good.\\n\\nIn the third test case, the given string $s$ is already good.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def det(s, i, j):\\n    ans = 0\\n    curr = i\\n    for a in s:\\n        if a == curr:\\n            ans += 1\\n            if curr == i: curr = j\\n            else: curr = i\\n\\n    if i == j: return ans\\n    return ans \\/\\/ 2 * 2\\n\\nfor t in range(int(input())):\\n    s = list(map(int, list(input())))\\n    ans = 0\\n    \\n    for i in range(10):\\n        for j in range(10):\\n            ans = max(ans, det(s, i, j))\\n\\n    print(len(s)-ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n You are given a string consisting of `\\\"D\\\", \\\"P\\\" and \\\"C\\\"`. A positive integer N is called DPC of this string if it satisfies the following properties: \\n \\n ```\\n For each i = 1, 2, ... , size of the string:\\n\\n If i-th character is \\\"D\\\", then N can be divided by i\\n If i-th character is \\\"P\\\", then N and i should be relatively prime\\n If i-th character is \\\"C\\\", then N should neither be divided by i \\n                           nor be relatively prime with i```\\n\\nYour task is to find the smallest DPC of a given string, or return `-1` if there is no such. The result is guaranteed to be `<= 10^9`.\\n\\n# Example\\n For `s = \\\"DDPDD\\\"`, the result should be `20`.\\n \\n `\\\"DDPDD\\\"` means `N` should `divided by 1,2,4,5`, and `N,3` should be relatively prime. The smallest N should be `20`.\\n\\n# Input\\/Output\\n\\n\\n - `[input]` string `s`\\n\\n  The given string\\n\\n\\n - `[output]` an integer\\n\\n  The smallest DPC of `s` or `-1` if it doesn't exist.\",\"targets\":\"from math import gcd\\n\\ntry:\\n    from math import prod\\nexcept ImportError:\\n    def prod(l, p=1):\\n        for n in l: p *= n\\n        return p\\n\\nmax_n = 1000000000\\n\\ndef DPC_sequence(s):\\n    if s[0] == 'C':\\n        return -1\\n    primes = list(find_primes(len(s)))\\n    pf = []\\n    for p in primes:\\n        if s[p-1] == 'C':\\n            return -1\\n        if s[p-1] == 'D':\\n            pf.append(p)\\n    #print(pf)\\n    for p in pf:\\n        for i in range(2*p-1, len(s), p):\\n            if s[i] == 'P':\\n                return -1\\n    base = prod(pf)\\n    nmax = min(prod(primes), max_n)\\n    #print(base, nmax)\\n    for n in range(base, nmax, base):\\n        if test(s, n):\\n            return n\\n    return -1\\n\\ndef test(s, n):\\n    for k in range(2, len(s)+1):\\n        c = s[k-1]\\n        if c == 'D':\\n            if n % k != 0: return False\\n        else:\\n            if (gcd(n, k) == 1) != (c == 'P'): return False\\n    return True\\n\\ndef find_primes(n):\\n    if n < 2: return\\n    yield 2\\n    s = list(range(1, n+1, 2))\\n    mroot = int(n ** 0.5)\\n    half = (n+1) \\/\\/ 2\\n    i = 1\\n    m = 3\\n    while m <= mroot:\\n        if s[i]:\\n            yield s[i]\\n            j = m*m \\/\\/ 2\\n            while j < half:\\n                s[j] = 0\\n                j += m\\n        i += 1\\n        m += 2\\n    for x in s[i:]:\\n        if x:\\n            yield x\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMaksim has $n$ objects and $m$ boxes, each box has size exactly $k$. Objects are numbered from $1$ to $n$ in order from left to right, the size of the $i$-th object is $a_i$.\\n\\nMaksim wants to pack his objects into the boxes and he will pack objects by the following algorithm: he takes one of the empty boxes he has, goes from left to right through the objects, and if the $i$-th object fits in the current box (the remaining size of the box is greater than or equal to $a_i$), he puts it in the box, and the remaining size of the box decreases by $a_i$. Otherwise he takes the new empty box and continues the process above. If he has no empty boxes and there is at least one object not in some box then Maksim cannot pack the chosen set of objects.\\n\\nMaksim wants to know the maximum number of objects he can pack by the algorithm above. To reach this target, he will throw out the leftmost object from the set until the remaining set of objects can be packed in boxes he has. Your task is to say the maximum number of objects Maksim can pack in boxes he has.\\n\\nEach time when Maksim tries to pack the objects into the boxes, he will make empty all the boxes he has before do it (and the relative order of the remaining set of objects will not change).\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers $n$, $m$, $k$ ($1 \\\\le n, m \\\\le 2 \\\\cdot 10^5$, $1 \\\\le k \\\\le 10^9$) — the number of objects, the number of boxes and the size of each box.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le k$), where $a_i$ is the size of the $i$-th object.\\n\\n\\n-----Output-----\\n\\nPrint the maximum number of objects Maksim can pack using the algorithm described in the problem statement.\\n\\n\\n-----Examples-----\\nInput\\n5 2 6\\n5 2 1 4 2\\n\\nOutput\\n4\\n\\nInput\\n5 1 4\\n4 2 3 4 1\\n\\nOutput\\n1\\n\\nInput\\n5 3 3\\n1 2 3 1 1\\n\\nOutput\\n5\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Maksim can pack only $4$ objects. Firstly, he tries to pack all the $5$ objects. Distribution of objects will be $[5], [2, 1]$. Maxim cannot pack the next...\",\"targets\":\"def main():\\n    nobj, nbox, boxsize = list(map(int, input().split()))\\n    obj = list(map(int, input().split()))\\n    box = boxsize\\n    curr = 0\\n    ans = 0\\n    i = nobj - 1\\n    while i >= 0:\\n        o = obj[i]\\n        #print('box: ' + str(box) + ' i = ' + str(i) + ', o = ' + str(o))\\n        if o <= box:\\n            box -= o\\n            ans += 1\\n        else:\\n            curr += 1\\n            box = boxsize\\n            if curr >= nbox:\\n                break\\n            continue\\n        i -= 1\\n    print(ans)\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nEhab is interested in the bitwise-xor operation and the special graphs. Mahmoud gave him a problem that combines both. He has a complete graph consisting of n vertices numbered from 0 to n - 1. For all 0 ≤ u < v < n, vertex u and vertex v are connected with an undirected edge that has weight $u \\\\oplus v$ (where $\\\\oplus$ is the bitwise-xor operation). Can you find the weight of the minimum spanning tree of that graph?\\n\\nYou can read about complete graphs in https:\\/\\/en.wikipedia.org\\/wiki\\/Complete_graph\\n\\nYou can read about the minimum spanning tree in https:\\/\\/en.wikipedia.org\\/wiki\\/Minimum_spanning_tree\\n\\nThe weight of the minimum spanning tree is the sum of the weights on the edges included in it.\\n\\n\\n-----Input-----\\n\\nThe only line contains an integer n (2 ≤ n ≤ 10^12), the number of vertices in the graph.\\n\\n\\n-----Output-----\\n\\nThe only line contains an integer x, the weight of the graph's minimum spanning tree.\\n\\n\\n-----Example-----\\nInput\\n4\\n\\nOutput\\n4\\n\\n\\n-----Note-----\\n\\nIn the first sample: [Image] The weight of the minimum spanning tree is 1+2+1=4.\",\"targets\":\"a = int(input())\\n\\ndef ans(n, p=1):\\n    return ans( (n+1) \\/\\/ 2, p*2 ) + (n\\/\\/2)*p if n > 1 else 0\\n\\nprint (ans(a))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIf　`a = 1, b = 2, c = 3 ... z = 26`\\n\\nThen `l + o + v + e = 54`\\n\\nand `f + r + i + e + n + d + s + h + i + p = 108`\\n\\nSo `friendship` is twice stronger than `love` :-)\\n\\nThe input will always be in lowercase and never be empty.\",\"targets\":\"import string\\ndef words_to_marks(s):\\n    # Easy one\\n    letters = string.ascii_lowercase\\n    total = 0\\n    \\n    for i in s:\\n        total += letters.index(i) + 1\\n\\n    return total\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef is in need of money, so he decided to play a game with Ramsay. In this game, there are $N$ rows of coins (numbered $1$ through $N$). For each valid $i$, the $i$-th row contains $C_i$ coins with values $A_{i, 1}, A_{i, 2}, \\\\ldots, A_{i, C_i}$.\\nChef and Ramsay alternate turns; Chef plays first. In each turns, the current player can choose one row that still contains coins and take one of the coins remaining in this row. Chef may only take the the first (leftmost) remaining coin in the chosen row, while Ramsay may only take the last (rightmost) remaining coin in the chosen row. The game ends when there are no coins left.\\nEach player wants to maximise the sum of values of the coins he took. Assuming that both Chef and Ramsay play optimally, what is the maximum amount of money (sum of values of coins) Chef can earn through this game?\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $N$.\\n- $N$ lines follow. For each valid $i$, the $i$-th of these lines contains an integer $C_i$, followed by a space and $C_i$ space-separated integers $A_{i, 1}, A_{i, 2}, \\\\ldots, A_{i, C_i}$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer ― the maximum amount of money Chef can earn.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 10$\\n- $1 \\\\le N \\\\le 10^4$\\n- $1 \\\\le C_i \\\\le 10$ for each valid $i$\\n- $1 \\\\le A_{i, j} \\\\le 10^5$ for each valid $i$ and $j$\\n\\n-----Subtasks-----\\nSubtask #1 (20 points): $N = 1$\\nSubtask #2 (80 points): original constraints\\n\\n-----Example Input-----\\n1\\n2\\n4 5 2 3 4\\n2 1 6\\n\\n-----Example Output-----\\n8\\n\\n-----Explanation-----\\nExample case 1: One optimal sequence of moves is: Chef takes the coin with value $5$, Ramsay takes $4$, Chef takes $2$, Ramsay takes $3$, Chef takes $1$ and Ramsay takes $6$. At the end, Chef has $5+2+1 = 8$ units of money.\",\"targets\":\"# cook your dish here\\nimport math\\nfor _ in range(int(input())):\\n n=int(input())\\n x=0\\n for i in range(n):\\n  l=list(map(int,input().split()))\\n  c=l[0]\\n  l1=l[1:]\\n  d=math.ceil(c\\/2)\\n  s=sum(l1[:d])\\n  x=x+s\\n  l1=[]\\n  c=0\\n  d=0\\n print(x)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/BRKBKS:\\nFor her next karate demonstration, Ada will break some bricks.\\nAda stacked three bricks on top of each other. Initially, their widths (from top to bottom) are $W_1, W_2, W_3$.\\nAda's strength is $S$. Whenever she hits a stack of bricks, consider the largest $k \\\\ge 0$ such that the sum of widths of the topmost $k$ bricks does not exceed $S$; the topmost $k$ bricks break and are removed from the stack. Before each hit, Ada may also decide to reverse the current stack of bricks, with no cost.\\nFind the minimum number of hits Ada needs in order to break all bricks if she performs the reversals optimally. You are not required to minimise the number of reversals.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first and only line of each test case contains four space-separated integers $S$, $W_1$, $W_2$ and $W_3$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer ― the minimum required number of hits.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 64$\\n- $1 \\\\le S \\\\le 8$\\n- $1 \\\\le W_i \\\\le 2$ for each valid $i$\\n- it is guaranteed that Ada can break all bricks\\n\\n-----Subtasks-----\\nSubtask #1 (50 points): $W_1 = W_2 = W_3$\\nSubtask #2 (50 points): original constraints\\n\\n-----Example Input-----\\n3\\n3 1 2 2\\n2 1 1 1\\n3 2 2 1\\n\\n-----Example Output-----\\n2\\n2\\n2\\n\\n-----Explanation-----\\nExample case 1: Ada can reverse the stack and then hit it two times. Before the first hit, the widths of bricks in the stack (from top to bottom) are $(2,2,1)$. After the first hit, the topmost brick breaks and the stack becomes $(2,1)$. The second hit breaks both remaining bricks.\\nIn this particular case, it is also possible to hit the stack two times without reversing. Before the first hit, it is $(1, 2, 2)$. The first hit breaks the two bricks at the top (so the stack becomes $(2)$) and the second hit breaks the last brick.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for _ in range(int(input())):\\n s,w1,w2,w3 = list(map(int,input().split()))\\n tot = w1+w2+w3\\n if tot<=s :\\n  print(1)\\n elif s == 1 :\\n  print(3)\\n elif s == 2 :\\n  if tot>=5 :\\n   print(3)\\n  elif w2 == 2 :\\n   print(3)\\n  else :\\n   print(2)\\n elif s == 3 :\\n  if tot<=5 :\\n   print(2)\\n  else :\\n   print(3)\\n else :\\n  print(2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/492\\/C:\\nVanya wants to pass n exams and get the academic scholarship. He will get the scholarship if the average grade mark for all the exams is at least avg. The exam grade cannot exceed r. Vanya has passed the exams and got grade a_{i} for the i-th exam. To increase the grade for the i-th exam by 1 point, Vanya must write b_{i} essays. He can raise the exam grade multiple times.\\n\\nWhat is the minimum number of essays that Vanya needs to write to get scholarship?\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers n, r, avg (1 ≤ n ≤ 10^5, 1 ≤ r ≤ 10^9, 1 ≤ avg ≤ min(r, 10^6)) — the number of exams, the maximum grade and the required grade point average, respectively.\\n\\nEach of the following n lines contains space-separated integers a_{i} and b_{i} (1 ≤ a_{i} ≤ r, 1 ≤ b_{i} ≤ 10^6).\\n\\n\\n-----Output-----\\n\\nIn the first line print the minimum number of essays.\\n\\n\\n-----Examples-----\\nInput\\n5 5 4\\n5 2\\n4 7\\n3 1\\n3 2\\n2 5\\n\\nOutput\\n4\\n\\nInput\\n2 5 4\\n5 2\\n5 2\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample Vanya can write 2 essays for the 3rd exam to raise his grade by 2 points and 2 essays for the 4th exam to raise his grade by 1 point.\\n\\nIn the second sample, Vanya doesn't need to write any essays as his general point average already is above average.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nimport math\\n\\nn, r, avg = [int(x) for x in (sys.stdin.readline()).split()]\\nres = 0\\nk = []\\nvsum = 0\\nfor i in range(n):\\n    a, b = [int(x) for x in (sys.stdin.readline()).split()]\\n    if(a >= r):\\n        vsum += r\\n    else:\\n        vsum += a\\n        k.append((r - a, b))\\n        \\nk.sort(key = lambda x: x[1])\\n\\nval = n * avg - vsum\\nif(val <= 0):\\n    print(0)\\n    return\\n\\nz = 0\\ni = 0\\nwhile(z < val):\\n    z += k[i][0]\\n    res += k[i][1] * k[i][0]\\n    i += 1\\n    \\ni -= 1\\nif(z > val):\\n    res -= (z - val) * k[i][1]\\n    print(res)\\nelse:\\n    print(res)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere is a pond with a rectangular shape.\\nThe pond is divided into a grid with H rows and W columns of squares.\\nWe will denote the square at the i-th row from the top and j-th column from the left by (i,\\\\ j).\\nSome of the squares in the pond contains a lotus leaf floating on the water.\\nOn one of those leaves, S, there is a frog trying to get to another leaf T.\\nThe state of square (i,\\\\ j) is given to you by a character a_{ij}, as follows:\\n - . : A square without a leaf.\\n - o : A square with a leaf floating on the water.\\n - S : A square with the leaf S.\\n - T : A square with the leaf T.\\nThe frog will repeatedly perform the following action to get to the leaf T: \\\"jump to a leaf that is in the same row or the same column as the leaf where the frog is currently located.\\\"\\nSnuke is trying to remove some of the leaves, other than S and T, so that the frog cannot get to the leaf T.\\nDetermine whether this objective is achievable. If it is achievable, find the minimum necessary number of leaves to remove.\\n\\n-----Constraints-----\\n - 2 ≤ H, W ≤ 100\\n - a_{ij} is ., o, S or T.\\n - There is exactly one S among a_{ij}.\\n - There is exactly one T among a_{ij}.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nH W\\na_{11} ... a_{1W}\\n:\\na_{H1} ... a_{HW}\\n\\n-----Output-----\\nIf the objective is achievable, print the minimum necessary number of leaves to remove.\\nOtherwise, print -1 instead.\\n\\n-----Sample Input-----\\n3 3\\nS.o\\n.o.\\no.T\\n\\n-----Sample Output-----\\n2\\n\\nRemove the upper-right and lower-left leaves.\",\"targets\":\"# 最大流\\n# https:\\/\\/tjkendev.github.io\\/procon-library\\/python\\/max_flow\\/dinic.html\\nimport sys\\nsys.setrecursionlimit(10**7)\\nfrom collections import deque\\nclass MaxFlow:\\n  # n:頂点数\\n  def __init__(self,n):\\n    self.n=n\\n    self.g=[[] for i in range(n)]\\n  \\n  # 辺を追加する\\n  # fr:辺の始点\\n  # to:辺の終点\\n  # cap:辺のキャパシティ\\n  def add_edge(self,fr,to,cap):\\n    forward=[to,cap,None]\\n    forward[2]=backward=[fr,0,forward]\\n    # forward[2]=backward,backward[2]=forwardとなるように再帰的にforwardとbackwardを定義\\n    self.g[fr].append(forward)\\n    self.g[to].append(backward)\\n    #print('add_edge',fr,to)\\n\\n  # sから各頂点への距離を返す。フローを流すごとにcapが減り、最終的に通れる辺が減り、tまで辿り着けなくなる。それまでフローを流す\\n  def bfs(self,s,t):\\n    self.level=level=[None]*self.n\\n    deq=deque([s])\\n    level[s]=0\\n    g=self.g\\n    while deq:\\n      v=deq.popleft()\\n      nlv=level[v]+1\\n      for nv,cap, _ in g[v]:\\n        if cap and level[nv] is None:\\n          level[nv]=nlv\\n          deq.append(nv)\\n    return level[t] is not None\\n  # v->tにfを流す。再帰的に呼び出す。v=tとなるまで続ける。\\n  # sから遠ざかるようなパスを見つけ、フローを流す\\n  def dfs(self,v,t,f):\\n    if v==t:\\n      return f\\n    level=self.level\\n    # self.it[v]:頂点vから伸びる辺。一本の辺について着目するとfordwardとbackwardが交互に呼び出される。\\n    for e in self.it[v]:\\n      nv,cap,rev=e\\n      if cap and level[v]<level[nv]:\\n        d=self.dfs(nv,t,min(f,cap))\\n        if d:\\n          e[1]-=d\\n          rev[1]+=d\\n          return d\\n    return 0\\n\\n  # sからtへの最大フローを返す。\\n  # 以下の処理をフローを流しきるまで繰り返す。\\n  # BFSでsourceから各頂点までの距離(level)を計算\\n  # DFSでsourceからの距離が遠くなるようなパスを見つけ、フローを流す\\n  def flow(self,s,t):\\n    flow=0\\n    INF=10**9+7\\n    g=self.g\\n    # sから各頂点への距離を計算。sからtへ辿り着けない場合、終了。距離はself.levelに保存される。\\n    while self.bfs(s,t):\\n      # グラフの各要素をイテレータに変換ものをself.itに入れる。????\\n      *self.it,=list(map(iter,self.g))\\n      f=INF\\n      while f:\\n        # s->tにフローを流す。流せた量をflowに加算。流せる量があるまで続ける。\\n        f=self.dfs(s,t,INF)\\n        flow+=f\\n    return flow\\n\\n\\ndef main2(h,w,mat):\\n  ss=-1,-1\\n  tt=-1,-1\\n  n=h+w+2\\n  g=[[] for _ in range(n)]\\n  ary=[]\\n  inf=10**18\\n  for i in range(h):\\n    for j in range(w):\\n      if  mat[i][j]=='o':\\n        ary.append([i,h+j,1])\\n       ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nRight now she actually isn't. But she will be, if you don't solve this problem.\\n\\nYou are given integers n, k, A and B. There is a number x, which is initially equal to n. You are allowed to perform two types of operations:   Subtract 1 from x. This operation costs you A coins.  Divide x by k. Can be performed only if x is divisible by k. This operation costs you B coins.  What is the minimum amount of coins you have to pay to make x equal to 1?\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 2·10^9).\\n\\nThe second line contains a single integer k (1 ≤ k ≤ 2·10^9).\\n\\nThe third line contains a single integer A (1 ≤ A ≤ 2·10^9).\\n\\nThe fourth line contains a single integer B (1 ≤ B ≤ 2·10^9).\\n\\n\\n-----Output-----\\n\\nOutput a single integer — the minimum amount of coins you have to pay to make x equal to 1.\\n\\n\\n-----Examples-----\\nInput\\n9\\n2\\n3\\n1\\n\\nOutput\\n6\\n\\nInput\\n5\\n5\\n2\\n20\\n\\nOutput\\n8\\n\\nInput\\n19\\n3\\n4\\n2\\n\\nOutput\\n12\\n\\n\\n\\n-----Note-----\\n\\nIn the first testcase, the optimal strategy is as follows:   Subtract 1 from x (9 → 8) paying 3 coins.  Divide x by 2 (8 → 4) paying 1 coin.  Divide x by 2 (4 → 2) paying 1 coin.  Divide x by 2 (2 → 1) paying 1 coin. \\n\\nThe total cost is 6 coins.\\n\\nIn the second test case the optimal strategy is to subtract 1 from x 4 times paying 8 coins in total.\",\"targets\":\"from sys import stdin as cin\\n\\ndef main():\\n    n = int(cin.readline())\\n    k = int(cin.readline())\\n    a = int(cin.readline())\\n    b = int(cin.readline())\\n    o = 0\\n    if k == 1:\\n        print((n - 1) * a)\\n        return\\n    while n > 1:\\n        if n % k:\\n            t = n - n \\/\\/ k * k\\n            if t == n:\\n                t -= 1\\n            o += a * t\\n            n -= t\\n        else:\\n            t = n \\/\\/ k\\n            o += min(a * (n - t), b)\\n            n = t\\n        #print(n, o)\\n    print(o)\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFor a given array $a$ consisting of $n$ integers and a given integer $m$ find if it is possible to reorder elements of the array $a$ in such a way that $\\\\sum_{i=1}^{n}{\\\\sum_{j=i}^{n}{\\\\frac{a_j}{j}}}$ equals $m$? It is forbidden to delete elements as well as insert new elements. Please note that no rounding occurs during division, for example, $\\\\frac{5}{2}=2.5$.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $t$ — the number of test cases ($1 \\\\le t \\\\le 100$). The test cases follow, each in two lines.\\n\\nThe first line of a test case contains two integers $n$ and $m$ ($1 \\\\le n \\\\le 100$, $0 \\\\le m \\\\le 10^6$). The second line contains integers $a_1, a_2, \\\\ldots, a_n$ ($0 \\\\le a_i \\\\le 10^6$) — the elements of the array.\\n\\n\\n-----Output-----\\n\\nFor each test case print \\\"YES\\\", if it is possible to reorder the elements of the array in such a way that the given formula gives the given value, and \\\"NO\\\" otherwise.\\n\\n\\n-----Example-----\\nInput\\n2\\n3 8\\n2 5 1\\n4 4\\n0 1 2 3\\n\\nOutput\\nYES\\nNO\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case one of the reorders could be $[1, 2, 5]$. The sum is equal to $(\\\\frac{1}{1} + \\\\frac{2}{2} + \\\\frac{5}{3}) + (\\\\frac{2}{2} + \\\\frac{5}{3}) + (\\\\frac{5}{3}) = 8$. The brackets denote the inner sum $\\\\sum_{j=i}^{n}{\\\\frac{a_j}{j}}$, while the summation of brackets corresponds to the sum over $i$.\",\"targets\":\"for u in range(int(input())):\\n    n, m = map(int, input().split())\\n    x = [int(w) for w in input().split()]\\n    \\n    if(sum(x) == m):\\n        print(\\\"YES\\\")\\n        \\n    else:\\n        print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given positive integers $L$ and $R$. You have to find the sum\\nS=∑i=LR(L∧(L+1)∧…∧i),S=∑i=LR(L∧(L+1)∧…∧i),S = \\\\sum_{i=L}^R \\\\left(L \\\\wedge (L+1) \\\\wedge \\\\ldots \\\\wedge i\\\\right) \\\\,,\\nwhere $\\\\wedge$ denotes the bitwise AND operation. Since the sum could be large, compute it modulo $10^9+7$.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first and only line of each test case contains two space-separated integers $L$ and $R$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer — the sum $S$ modulo $10^9+7$.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 10^5$\\n- $1 \\\\le L \\\\le R \\\\le 10^{18}$\\n\\n-----Example Input-----\\n2\\n1 4\\n4 10\\n\\n-----Example Output-----\\n1\\n16\\n\\n-----Explanation-----\\nExample case 1: The sum is 1 + 1 AND 2 + 1 AND 2 AND 3 + 1 AND 2 AND 3 AND 4 = 1 + 0 + 0 + 0 = 1.\\nExample case 2: The sum is 4 + 4 AND 5 + 4 AND 5 AND 6 + 4 AND 5 AND 6 AND 7 + … + 4 AND 5 AND … AND 10 = 4 + 4 + … + 0 = 16.\",\"targets\":\"# cook your dish here\\nt=int(input())\\nwhile t>0:\\n a,b=list(map(int,input().split()))\\n k=1\\n m=a\\n n=b\\n sum=0\\n x=0\\n y=1\\n while a>0:\\n  a=a\\/\\/2\\n  l=m\\/\\/k\\n  if l%2!=0:\\n   p=k*l\\n   q=k*(l+1)\\n  else:\\n   p=k*(l+1)\\n   q=k*(l+2)\\n  k*=2\\n  if m>=p and m<q:\\n   if b<q:\\n    o=b-m+1\\n    lum=((o%1000000007)*(y%1000000007))%1000000007\\n    sum=sum+lum\\n    sum=sum%1000000007\\n   else:\\n    o=q-m\\n    lum=((o%1000000007)*(y%1000000007))%1000000007\\n    sum=sum+lum\\n    sum=sum%1000000007\\n  y*=2\\n print(sum)\\n t-=1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1203\\/C:\\nYou are given an array $a$ consisting of $n$ integers.\\n\\nYour task is to say the number of such positive integers $x$ such that $x$ divides each number from the array. In other words, you have to find the number of common divisors of all elements in the array.\\n\\nFor example, if the array $a$ will be $[2, 4, 6, 2, 10]$, then $1$ and $2$ divide each number from the array (so the answer for this test is $2$).\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $n$ ($1 \\\\le n \\\\le 4 \\\\cdot 10^5$) — the number of elements in $a$.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 10^{12}$), where $a_i$ is the $i$-th element of $a$.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the number of such positive integers $x$ such that $x$ divides each number from the given array (in other words, the answer is the number of common divisors of all elements in the array).\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 2 3 4 5\\n\\nOutput\\n1\\n\\nInput\\n6\\n6 90 12 18 30 18\\n\\nOutput\\n4\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def gcd(a, b):\\n    if a == 0:\\n        return b\\n    return gcd(b % a, a)\\n\\nn = int(input())\\na = [int(c) for c in input().split()]\\n\\ng = a[0]\\nfor i in range(1, n):\\n    g = gcd(g, a[i])\\n\\nans = 0\\nfor i in range(1, int(g ** (0.5)) + 1):\\n    if g % i == 0:\\n        if g \\/\\/ i != i:\\n            ans += 2\\n        else:\\n            ans += 1\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMany websites use weighted averages of various polls to make projections for elections. They’re weighted based on a variety of factors, such as historical accuracy of the polling firm, sample size, as well as date(s). The weights, in this kata, are already calculated for you. All you need to do is convert a set of polls with weights, into a fixed projection for the result.\\n\\n#### Task:\\n\\nYour job is to convert an array of candidates (variable name `candidates`) and an array of polls (variable name `polls`), each poll with two parts, a result and a weight, into a guess of the result, with each value rounded to one decimal place, through use of a weighted average. Weights can be zero! Don't worry about the sum not totalling 100. The final result should be a hash in Ruby and Crystal, dictionary in Python, or object in JS in the format shown below:\\n\\n```python\\n{ \\n  \\\"\\\": \\\"\\\",\\n  \\\"\\\": \\\"\\\",\\n  ...\\n}\\n\\nFor your convenience, a function named round1 has been defined for you. You can\\nuse it to round to the nearest tenth correctly (due to the inaccuracy of round\\nand floats in general).\\n```\\n\\n_The input should not be modified._\\n\\n#### Calculation for projections:\\n\\n```\\n[(poll1 * weight1) + (poll2 * weight2) + ...] \\/ (weight1 + weight2 + ...)\\n```\\n\\n#### An example:\\n\\n```python\\ncandidates = ['A', 'B', 'C']\\n\\npoll1res = [20, 30, 50]\\npoll1wt = 1\\npoll1 = [poll1res, poll1wt]\\n\\npoll2res = [40, 40, 20]\\npoll2wt = 0.5\\npoll2 = [poll2res, poll2wt]\\n\\npoll3res = [50, 40, 10]\\npoll3wt = 2\\npoll3 = [poll3res, poll3wt]\\n\\npolls = [poll1, poll2, poll3]\\n\\npredict(candidates, polls)\\n#=> {\\n     'A': 40,\\n     'B': 37.1,\\n     'C': 22.9\\n    }\\n\\n# because...\\n\\ncandidate 'A' weighted average\\n  = ((20 * 1) + (40 * 0.5) + (50 * 2)) \\/ (1 + 0.5 + 2)\\n  = (20 + 20 + 100) \\/ 3.5\\n  = 140 \\/ 3.5\\n  = 40\\n\\ncandidate 'B' weighted average\\n  = ((30 * 1) + (40 * 0.5) + (40 * 2)) \\/ (1 + 0.5 + 2)\\n  = (30 + 20 + 80) \\/ 3.5\\n  = 130 \\/ 3.5\\n  = 37.142857...\\n  ≈ 37.1 (round to nearest tenth)\\n\\ncandidate 'C' weighted average\\n  = ((50 * 1) + (20 * 0.5) + (10 * 2)) \\/ (1 + 0.5 + 2)\\n  = (50 + 10 + 20) \\/...\",\"targets\":\"import math\\ndef predict(candidates, polls):\\n    t ={}\\n    for i,j in enumerate(candidates):\\n        m = 0\\n        n = 0\\n        for z in polls:\\n            n += z[1]\\n            m += z[0][i]*z[1]\\n        t[j]= round1(m\\/n)\\n    return t\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a nested list of integers represented as a string, implement a parser to deserialize it.\\n\\nEach element is either an integer, or a list -- whose elements may also be integers or other lists.\\n\\nNote:\\nYou may assume that the string is well-formed:\\n\\nString is non-empty.\\nString does not contain white spaces.\\nString contains only digits 0-9, [, - ,, ].\\n\\n\\n\\nExample 1:\\n\\nGiven s = \\\"324\\\",\\n\\nYou should return a NestedInteger object which contains a single integer 324.\\n\\n\\n\\nExample 2:\\n\\nGiven s = \\\"[123,[456,[789]]]\\\",\\n\\nReturn a NestedInteger object containing a nested list with 2 elements:\\n\\n1. An integer containing value 123.\\n2. A nested list containing two elements:\\n    i.  An integer containing value 456.\\n    ii. A nested list with one element:\\n         a. An integer containing value 789.\",\"targets\":\"# \\\"\\\"\\\"\\n # This is the interface that allows for creating nested lists.\\n # You should not implement it, or speculate about its implementation\\n # \\\"\\\"\\\"\\n #class NestedInteger:\\n #    def __init__(self, value=None):\\n #        \\\"\\\"\\\"\\n #        If value is not specified, initializes an empty list.\\n #        Otherwise initializes a single integer equal to value.\\n #        \\\"\\\"\\\"\\n #\\n #    def isInteger(self):\\n #        \\\"\\\"\\\"\\n #        @return True if this NestedInteger holds a single integer, rather than a nested list.\\n #        :rtype bool\\n #        \\\"\\\"\\\"\\n #\\n #    def add(self, elem):\\n #        \\\"\\\"\\\"\\n #        Set this NestedInteger to hold a nested list and adds a nested integer elem to it.\\n #        :rtype void\\n #        \\\"\\\"\\\"\\n #\\n #    def setInteger(self, value):\\n #        \\\"\\\"\\\"\\n #        Set this NestedInteger to hold a single integer equal to value.\\n #        :rtype void\\n #        \\\"\\\"\\\"\\n #\\n #    def getInteger(self):\\n #        \\\"\\\"\\\"\\n #        @return the single integer that this NestedInteger holds, if it holds a single integer\\n #        Return None if this NestedInteger holds a nested list\\n #        :rtype int\\n #        \\\"\\\"\\\"\\n #\\n #    def getList(self):\\n #        \\\"\\\"\\\"\\n #        @return the nested list that this NestedInteger holds, if it holds a nested list\\n #        Return None if this NestedInteger holds a single integer\\n #        :rtype List[NestedInteger]\\n #        \\\"\\\"\\\"\\n \\n class Solution:    \\n     def convertListToNestedInteger(self, nestList):\\n         if type(nestList) == type(0):\\n             return NestedInteger(nestList)\\n         rtype = NestedInteger()\\n         for item in nestList:\\n             if type(item) == type(0):\\n                 rtype.add(item)\\n             else:\\n                 nestedList = self.convertListToNestedInteger(item)\\n                 rtype.add(nestedList)\\n         return rtype\\n         \\n     def deserializeHelper(self, st):\\n         if len(st) > 0:\\n             if st[0] != '[':\\n                 return int(st)\\n         assert(len(st) > 1)\\n         assert(st[0] == '[')\\n         assert(st[-1] == ']')\\n        ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/591392af88a4994caa0000e0:\\nWe have a set of consecutive numbers from ```1``` to ```n```.\\nWe want to count all the subsets that do not contain consecutive numbers.\\nE.g.\\n\\nIf our set ```S1``` is equal to ```[1,2,3,4,5]```\\nThe subsets that fulfill these property are:\\n```\\n[1],[2],[3],[4],[5],[1,3],[1,4],[1,5],[2,4],[2,5],[3,5],[1,3,5]\\n```\\nA total of      ```12   ``` subsets.\\n\\nFrom the set ```S2``` equals to```[1,2,3]```, it is obvious that we have only ```4``` subsets and are:\\n```\\n[1],[2],[3],[1,3]\\n```\\nMake a code that may give the amount of all these subsets for any integer       ```n >= 2       ```.\\n\\nFeatures of the random tests:\\n```\\nnumber of tests = 100 \\n10 <= n <= 120\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"FIBS = [1, 1]\\n\\ndef f(n):\\n    # I dedicate this method to oeis.org :)\\n    while len(FIBS) <= n + 1:\\n        FIBS.append(FIBS[-2] + FIBS[-1])\\n    return FIBS[n + 1] - 1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn some other world, today is Christmas.\\nMr. Takaha decides to make a multi-dimensional burger in his party. A level-L burger (L is an integer greater than or equal to 0) is the following thing:\\n - A level-0 burger is a patty.\\n - A level-L burger (L \\\\geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.\\nFor example, a level-1 burger and a level-2 burger look like BPPPB and BBPPPBPBPPPBB (rotated 90 degrees), where B and P stands for a bun and a patty.\\nThe burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 50\\n - 1 \\\\leq X \\\\leq ( the total number of layers in a level-N burger )\\n - N and X are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN X\\n\\n-----Output-----\\nPrint the number of patties in the bottom-most X layers from the bottom of a level-N burger.\\n\\n-----Sample Input-----\\n2 7\\n\\n-----Sample Output-----\\n4\\n\\nThere are 4 patties in the bottom-most 7 layers of a level-2 burger (BBPPPBPBPPPBB).\",\"targets\":\"n,x=map(int,input().split())\\n\\ndef func(m,y):\\n  if y==0:return 0\\n  ret=0\\n  t=4*pow(2,m)-3\\n  if y>=t-1:\\n    ret=pow(2,m+1)-1\\n  elif y==(t-1)\\/\\/2:\\n    ret=pow(2,m)-1\\n  elif y==(t-1)\\/\\/2+1:\\n    ret=pow(2,m)\\n  elif y>(t-1)\\/\\/2+1:\\n    ret=pow(2,m)\\n    ret+=func(m-1,y-(t-1)\\/\\/2-1)\\n  else:\\n    ret=func(m-1,y-1)\\n  return ret\\n\\nprint(func(n,x))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/935\\/E:\\nAncient Egyptians are known to have understood difficult concepts in mathematics. The ancient Egyptian mathematician Ahmes liked to write a kind of arithmetic expressions on papyrus paper which he called as Ahmes arithmetic expression.\\n\\nAn Ahmes arithmetic expression can be defined as:   \\\"d\\\" is an Ahmes arithmetic expression, where d is a one-digit positive integer;  \\\"(E_1 op E_2)\\\" is an Ahmes arithmetic expression, where E_1 and E_2 are valid Ahmes arithmetic expressions (without spaces) and op is either plus ( + ) or minus ( - ).  For example 5, (1-1) and ((1+(2-3))-5) are valid Ahmes arithmetic expressions.\\n\\nOn his trip to Egypt, Fafa found a piece of papyrus paper having one of these Ahmes arithmetic expressions written on it. Being very ancient, the papyrus piece was very worn out. As a result, all the operators were erased, keeping only the numbers and the brackets. Since Fafa loves mathematics, he decided to challenge himself with the following task:\\n\\nGiven the number of plus and minus operators in the original expression, find out the maximum possible value for the expression on the papyrus paper after putting the plus and minus operators in the place of the original erased operators.\\n\\n\\n-----Input-----\\n\\nThe first line contains a string E (1 ≤ |E| ≤ 10^4) — a valid Ahmes arithmetic expression. All operators are erased and replaced with '?'.\\n\\nThe second line contains two space-separated integers P and M (0 ≤ min(P, M) ≤ 100) — the number of plus and minus operators, respectively. \\n\\nIt is guaranteed that P + M =  the number of erased operators.\\n\\n\\n-----Output-----\\n\\nPrint one line containing the answer to the problem.\\n\\n\\n-----Examples-----\\nInput\\n(1?1)\\n1 0\\n\\nOutput\\n2\\n\\nInput\\n(2?(1?2))\\n1 1\\n\\nOutput\\n1\\n\\nInput\\n((1?(5?7))?((6?2)?7))\\n3 2\\n\\nOutput\\n18\\n\\nInput\\n((1?(5?7))?((6?2)?7))\\n2 3\\n\\nOutput\\n16\\n\\n\\n\\n-----Note-----  The first sample will be (1 + 1)  =  2.  The second sample will be (2 + (1 - 2))  =  1.  The third sample will be ((1 - (5 - 7)) + ((6 + 2) + 7))  =  18.  The fourth sample will be ((1 + (5 + 7)) - ((6 - 2) -...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import inf\\n\\nclass Node:\\n    def __init__(self, parent = None, leftExp = None, rightExp = None, signQ = 0):\\n        self.parent, self.leftExp, self.rightExp, self.signQ = parent, leftExp, rightExp, signQ\\n    def __str__(self):\\n        return \\\"Node\\\"\\n\\nmemo = {}\\n\\ndef Memoize(node, p, maxValue, minValue):\\n    if not node in memo:\\n        memo.update({node : {p : [maxValue, minValue]} })\\n    else:\\n        memo[node].update({p : [maxValue, minValue]})\\n\\ndef ExpMaxValue(root: Node, p):\\n\\n    m = root.signQ - p\\n    \\\"\\\"\\\"if root.signQ == 1:\\n        if p == 1:\\n            return [root.leftExp.value + root.rightExp.value, root.leftExp.value + root.rightExp.value]\\n        else:\\n            return [root.leftExp.value - root.rightExp.value, root.leftExp.value - root.rightExp.value]\\\"\\\"\\\"\\n\\n    if root.signQ == 0:\\n        return [root.value, root.value]\\n    \\n    if root in memo:\\n        if p in memo[root]:\\n            return memo[root][p]\\n\\n    if m == 0:\\n        value = ExpMaxValue(root.leftExp, root.leftExp.signQ)[0] + ExpMaxValue(root.rightExp, root.rightExp.signQ)[0]\\n        Memoize(root, p, value, value)\\n        return [value, value]\\n    if p == 0:\\n        value = ExpMaxValue(root.leftExp, 0)[0] - ExpMaxValue(root.rightExp, 0)[0]\\n        Memoize(root, p, value, value)\\n        return [value, value]\\n        \\n    maxValue = -inf\\n    minValue = inf\\n    if m >= p:\\n        for pQMid in range(2):\\n            pQLeftMin = min(p - pQMid, root.leftExp.signQ)\\n            for pQLeft in range(pQLeftMin + 1):\\n                if root.leftExp.signQ - pQLeft + (1 - pQMid) > m:\\n                    continue\\n                \\n                resLeft = ExpMaxValue(root.leftExp, pQLeft)\\n                resRight = ExpMaxValue(root.rightExp, p - pQMid - pQLeft)\\n                \\n                if pQMid == 1:\\n                    maxValue = max(resLeft[0] + resRight[0], maxValue)\\n                    minValue = min(resLeft[1] + resRight[1], minValue)\\n                else:\\n                    maxValue = max(resLeft[0] - resRight[1], maxValue)\\n     ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:\\n\\n  To make a \\\"red bouquet\\\", it needs 3 red flowers.  To make a \\\"green bouquet\\\", it needs 3 green flowers.  To make a \\\"blue bouquet\\\", it needs 3 blue flowers.  To make a \\\"mixing bouquet\\\", it needs 1 red, 1 green and 1 blue flower. \\n\\nHelp Fox Ciel to find the maximal number of bouquets she can make.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers r, g and b (0 ≤ r, g, b ≤ 10^9) — the number of red, green and blue flowers.\\n\\n\\n-----Output-----\\n\\nPrint the maximal number of bouquets Fox Ciel can make.\\n\\n\\n-----Examples-----\\nInput\\n3 6 9\\n\\nOutput\\n6\\n\\nInput\\n4 4 4\\n\\nOutput\\n4\\n\\nInput\\n0 0 0\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.\\n\\nIn test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.\",\"targets\":\"x=input().split()\\nx=[int(p) for p in x]\\nr,g,b=x[0],x[1],x[2]\\n\\ndiff=max(r,g,b)-min(r,g,b)\\n\\ndef f1(r,g,b,i):\\n        no1=0\\n        while(r!=i and g!=i and b!=i):\\n                mini=min(r,g,b)\\n                maxi=max(r,g,b)\\n                \\n                r-=(mini+i)\\n                g-=(mini+i)\\n                b-=(mini+i)\\n                no1+=(mini-i)\\n        return no1,r,g,b        \\n\\n\\n\\n\\nif(r==65 and g==30 and b==74):\\n        print(56)\\nelse:\\n        \\n\\n        if(r!=0 and g!=0 and b!=0 and diff>=2):\\n                if(diff==2):\\n                        no,r1,g1,b1=f1(r,g,b,1)\\n                        if(x.count(max(x))==2):\\n                                print(no + 2)\\n                        else:\\n                                print((no)+1)\\n                elif(diff>2):\\n                        no,r1,g1,b1=f1(r,g,b,0)\\n                        r1=r1\\/\\/3\\n                        g1=g1\\/\\/3\\n                        b1=b1\\/\\/3\\n                        no+=(r1+g1+b1)\\n                        print(no)\\n                \\n                      \\n\\n        elif(r!=0 and g!=0 and b!=0 and diff<2):\\n                print(min(x))\\n         \\n        else:\\n                no=0\\n                r1=r\\/\\/3\\n                g1=g\\/\\/3\\n                b1=b\\/\\/3\\n                no=r1+g1+b1\\n                print(no)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1100\\/B:\\nArkady coordinates rounds on some not really famous competitive programming platform. Each round features $n$ problems of distinct difficulty, the difficulties are numbered from $1$ to $n$.\\n\\nTo hold a round Arkady needs $n$ new (not used previously) problems, one for each difficulty. As for now, Arkady creates all the problems himself, but unfortunately, he can't just create a problem of a desired difficulty. Instead, when he creates a problem, he evaluates its difficulty from $1$ to $n$ and puts it into the problems pool.\\n\\nAt each moment when Arkady can choose a set of $n$ new problems of distinct difficulties from the pool, he holds a round with these problems and removes them from the pool. Arkady always creates one problem at a time, so if he can hold a round after creating a problem, he immediately does it.\\n\\nYou are given a sequence of problems' difficulties in the order Arkady created them. For each problem, determine whether Arkady held the round right after creating this problem, or not. Initially the problems pool is empty.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $m$ ($1 \\\\le n, m \\\\le 10^5$) — the number of difficulty levels and the number of problems Arkady created.\\n\\nThe second line contains $m$ integers $a_1, a_2, \\\\ldots, a_m$ ($1 \\\\le a_i \\\\le n$) — the problems' difficulties in the order Arkady created them.\\n\\n\\n-----Output-----\\n\\nPrint a line containing $m$ digits. The $i$-th digit should be $1$ if Arkady held the round after creation of the $i$-th problem, and $0$ otherwise.\\n\\n\\n-----Examples-----\\nInput\\n3 11\\n2 3 1 2 2 2 3 2 2 3 1\\n\\nOutput\\n00100000001\\n\\nInput\\n4 8\\n4 1 3 3 2 3 3 3\\n\\nOutput\\n00001000\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Arkady held the round after the first three problems, because they are of distinct difficulties, and then only after the last problem.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,m=list(map(int,input().split()))\\na2=set(range(1,n+1))\\na=list(map(int,input().split()))\\na1=set()\\nans=\\\"\\\"\\nns={}\\nfor i in a:\\n    a1.add(i)\\n    if i in ns:\\n        ns[i]=ns[i]+1\\n    else:\\n        ns[i]=1\\n    if a1==a2:\\n        nns={}\\n        for i in ns:\\n            ns[i]=ns[i]-1\\n            if ns[i]!=0:\\n                nns[i]=ns[i]\\n        ns=nns\\n        a1=set(ns)\\n        ans+=\\\"1\\\"\\n    else:\\n        ans+=\\\"0\\\"\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVanja and Miksi have already finished everything for this year at their university, so they decided to spend their free time playing a game with a binary sequence $A_1, A_2, \\\\dots, A_N$ (i.e. a sequence containing only integers $0$ and $1$).\\nAt the beginning of the game, Vanja and Miksi write down the expression $* A_1 * A_2 * A_3 * \\\\ldots * A_N$ (note below that each $*$ is a placeholder and does not denote multiplication).\\nThe players take turns alternately, starting with Vanja. The game lasts $N$ turns. In each turn, the current player must replace the first (leftmost) remaining $*$ by the sign $+$ or $-$ (or, equivalently, by the operation of addition or subtraction).\\nAfter the last turn, the boys calculate the resulting value $V$ of the expression. If $|V| \\\\ge K$, the winner is Vanja; otherwise, the winner is Miksi.\\nPlease predict the winner of the game if both players play optimally. \\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains two space-separated integers $N$ and $K$.\\n- The second line contains $N$ space-separated integers $A_1, A_2, \\\\dots, A_N$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer — $1$ if Vanja (the first player) is the winner or $2$ if Miksi (the second player) is the winner.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 50$\\n- $1 \\\\le N \\\\le 3 \\\\cdot 10^4$\\n- $0 \\\\le K \\\\le 3 \\\\cdot 10^4$\\n- $0 \\\\le A_i \\\\le 1$ for each valid $i$\\n\\n-----Example Input-----\\n2\\n2 1\\n1 0\\n3 5\\n0 1 0\\n\\n-----Example Output-----\\n1\\n2\\n\\n-----Explanation-----\\nExample case 1: $K = 1$, so if Vanja replaces the first $*$ by $+$, the value of the final expression will be $V = 1$; then, $K \\\\le |V|$, so the winner is Vanja.\\nExample case 2: $K = 5$, but the absolute value of the final expression cannot be greater than $1$. The winner is Miksi.\",\"targets\":\"for j in range(int(input())):\\n n,k=map(int,input().split())\\n x=list(map(int,input().split()))\\n c=0\\n for i in range(n):\\n  if(i%2==0):\\n   if(c<0):\\n    c-=x[i]\\n   else:\\n    c+=x[i]\\n  else:\\n   if(c<0):\\n    c+=x[i]\\n   else:\\n    c-=x[i]\\n if(abs(c)>=k):\\n  print(1)\\n else:\\n  print(2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWrite a function that returns a sequence (index begins with 1) of all the even characters from a string. If the string is smaller than two characters or longer than 100 characters, the function should return \\\"invalid string\\\". \\n\\nFor example:\\n`````\\n\\\"abcdefghijklm\\\" --> [\\\"b\\\", \\\"d\\\", \\\"f\\\", \\\"h\\\", \\\"j\\\", \\\"l\\\"]\\n\\\"a\\\"             --> \\\"invalid string\\\"\\n`````\",\"targets\":\"def even_chars(s):\\n    return list(s[1::2]) if 2 <= len(s) <= 100 else 'invalid string'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/DCC2020\\/problems\\/DCC201:\\nChef’s girlfriend is angry with him because he forgot her birthday. Chef decided to please her by gifting her a Love Graph. \\nChef has $N$ vertices: $V_1, V_2, \\\\dots, V_N$. Love Graph is an undirected multigraph with no self-loops and can be constructed by performing the following operations:-\\n- Choose an integer $i$ ($1 \\\\leq i \\\\leq N$)\\n- Choose another integer $j \\\\space \\\\space \\\\{ (i \\\\neq j) \\\\text{ and } (1 \\\\leq j \\\\leq N) \\\\}$\\n- Make an edge between $V_i$ and $V_j$\\n- Set $i = j$\\n- Repeat steps $2, 3$ and $4$ in order $M-1$ more times.\\nFind the number of ways in which Chef can construct a Love Graph. Since the answer can be very large, compute it modulo $10^9+7$.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows. \\n- The first line of each test case contains two space-separated integers $N$ and $M$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer — the number of ways in which Chef can construct a Love Graph modulo $10^9+7$.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 10^5$\\n- $2 \\\\leq N \\\\leq 10^9$\\n- $1 \\\\leq M \\\\leq 10^{18}$\\n\\n-----Subtasks-----\\n- 30 points:\\n- $1 \\\\leq T \\\\leq 100$\\n- $2 \\\\leq N \\\\leq 10$\\n- $1 \\\\leq M \\\\leq 10$ \\n- 70 points: original constraints\\n\\n-----Sample Input-----\\n1\\n\\n2 1   \\n\\n-----Sample Output-----\\n2   \\n\\n-----Explanation-----\\nThere are two ways of constructing Love Graph.\\n\\nIn first way, we pick Vertex 1 and then join with Vertex 2.\\n\\nIn second way, we pick Vertex 2 and then join with Vertex 1.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nt = int(input())\\nfor i in range(t):\\n n,m = list(map(int,input().split()))\\n ans = n * pow(n-1,m, 10**9+7) % (10**9+7)\\n print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe Little Elephant from the Zoo of Lviv currently is on the military mission. There are N enemy buildings placed in a row and numbered from left to right strating from 0. Each building i (except the first and the last) has exactly two adjacent buildings with indices i-1 and i+1. The first and the last buildings have just a single adjacent building.\\n\\nSome of the buildings contain bombs. When bomb explodes in some building it destroys it and all adjacent to it buildings.\\n\\nYou are given the string S of length N, where Si is 1 if the i-th building contains bomb, 0 otherwise. Find for the Little Elephant the number of buildings that will not be destroyed after all bombs explode. Please note that all bombs explode simultaneously.\\n\\n-----Input-----\\nThe first line contains single integer T - the number of test cases. T test cases follow. The first line of each test case contains the single integer N - the number of buildings. The next line contains the string S of length N consisted only of digits 0 and 1.\\n\\n-----Output-----\\nIn T lines print T inetgers - the answers for the corresponding test cases.\\n\\n-----Constraints-----\\n\\n1 <= T <= 100\\n\\n1 <= N <= 1000\\n\\n-----Example-----\\nInput:\\n3\\n3\\n010\\n5\\n10001\\n7\\n0000000\\n\\nOutput:\\n0\\n1\\n7\",\"targets\":\"t = int(input())\\nfor nTest in range(t):\\n n = int(input())\\n s = input().strip()\\n ns = int(s)\\n ns = ns + ns\\/\\/10 + 10*ns\\n \\n ss = str(ns)[-n:]\\n print(ss.count(\\\"0\\\") + n-len(ss))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA country has n cities. Initially, there is no road in the country. One day, the king decides to construct some roads connecting pairs of cities. Roads can be traversed either way. He wants those roads to be constructed in such a way that it is possible to go from each city to any other city by traversing at most two roads. You are also given m pairs of cities — roads cannot be constructed between these pairs of cities.\\n\\nYour task is to construct the minimum number of roads that still satisfy the above conditions. The constraints will guarantee that this is always possible.\\n\\n\\n-----Input-----\\n\\nThe first line consists of two integers n and m $(1 \\\\leq n \\\\leq 10^{3}, 0 \\\\leq m < \\\\frac{n}{2})$.\\n\\nThen m lines follow, each consisting of two integers a_{i} and b_{i} (1 ≤ a_{i}, b_{i} ≤ n, a_{i} ≠ b_{i}), which means that it is not possible to construct a road connecting cities a_{i} and b_{i}. Consider the cities are numbered from 1 to n.\\n\\nIt is guaranteed that every pair of cities will appear at most once in the input.\\n\\n\\n-----Output-----\\n\\nYou should print an integer s: the minimum number of roads that should be constructed, in the first line. Then s lines should follow, each consisting of two integers a_{i} and b_{i} (1 ≤ a_{i}, b_{i} ≤ n, a_{i} ≠ b_{i}), which means that a road should be constructed between cities a_{i} and b_{i}.\\n\\nIf there are several solutions, you may print any of them.\\n\\n\\n-----Examples-----\\nInput\\n4 1\\n1 3\\n\\nOutput\\n3\\n1 2\\n4 2\\n2 3\\n\\n\\n\\n-----Note-----\\n\\nThis is one possible solution of the example:  [Image] \\n\\nThese are examples of wrong solutions: [Image]  The above solution is wrong because it doesn't use the minimum number of edges (4 vs 3). In addition, it also tries to construct a road between cities 1 and 3, while the input specifies that it is not allowed to construct a road between the pair. [Image]  The above solution is wrong because you need to traverse at least 3 roads to go from city 1 to city 3, whereas in your country it must be possible to go from any city to another by traversing at most 2...\",\"targets\":\"n, m = list(map(int, input().split()))\\nc = [list(map(int, input().split())) for _ in range(m)]\\nr = [[True for j in range(n+1)] for i in range(n+1)]\\n\\nfor v in c:\\n    r[v[0]][v[1]] = False\\n    r[v[1]][v[0]] = False\\n\\nnode = -1\\n\\nfor i in range(1, n+1):\\n    cont = True\\n    for j in range(1, n+1):\\n        cont &= r[i][j]\\n        if not cont:\\n            break\\n    if cont:\\n        node = i\\n        break\\n\\nprint(n-1)\\n\\nfor i in range(1, n+1):\\n    if i != node:\\n        print(node, i)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFind the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter.\\n\\n-----Constraints-----\\n - 2\\\\leq K\\\\leq 100\\n - K is an integer.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nK\\n\\n-----Output-----\\nPrint the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive).\\n\\n-----Sample Input-----\\n3\\n\\n-----Sample Output-----\\n2\\n\\nTwo pairs can be chosen: (2,1) and (2,3).\",\"targets\":\"k=int(input())\\nif k % 2 == 0:\\n  kazu = k\\/\\/2\\n  print(kazu**2)\\n  \\nelse:\\n  kazu = k \\/\\/2\\n  print( kazu * (kazu+1))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/51e04f6b544cf3f6550000c1:\\nLet's pretend your company just hired your friend from college and paid you a referral bonus. Awesome! To celebrate, you're taking your team out to the terrible dive bar next door and using the referral bonus to buy, and build, the largest three-dimensional beer can pyramid you can. And then probably drink those beers, because let's pretend it's Friday too. \\n\\nA beer can pyramid will square the number of cans in each level - 1 can in the top level, 4 in the second, 9 in the next, 16, 25... \\n\\nComplete the beeramid function to return the number of **complete** levels of a beer can pyramid you can make, given the parameters of: \\n\\n1) your referral bonus, and\\n\\n2) the price of a beer can\\n\\nFor example:\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from itertools import count\\n\\ndef beeramid(bonus, price):\\n    bonus = max(bonus,0)\\n    n = bonus\\/\\/price\\n    return next(x for x in count(int((n*3)**(1\\/3)+1),-1) if x*(x+1)*(2*x+1)\\/\\/6 <= n)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou just got done with your set at the gym, and you are wondering how much weight you could lift if you did a single repetition. Thankfully, a few scholars have devised formulas for this purpose (from [Wikipedia](https:\\/\\/en.wikipedia.org\\/wiki\\/One-repetition_maximum)) :\\n\\n\\n### Epley\\n\\n\\n### McGlothin\\n\\n\\n### Lombardi\\n\\n\\nYour function will receive a weight `w` and a number of repetitions `r` and must return your projected one repetition maximum. Since you are not sure which formula to use and you are feeling confident, your function will return the largest value from the three formulas shown above, rounded to the nearest integer. However, if the number of repetitions passed in is `1` (i.e., it is already a one rep max), your function must return `w`. Also, if the number of repetitions passed in is `0` (i.e., no repetitions were completed), your function must return `0`.\",\"targets\":\"def calculate_1RM(w, r):\\n    if r in (0, 1):\\n        return (0, w)[r]\\n    epley = w * (1 + r \\/ 30)\\n    mcg = 100 * w \\/ (101.3 - 2.67123 * r)\\n    lomb = w * r ** .1\\n    return round(max((epley, mcg, lomb)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAn agent called Cypher is decrypting a message, that contains a composite number $n$. All divisors of $n$, which are greater than $1$, are placed in a circle. Cypher can choose the initial order of numbers in the circle.\\n\\nIn one move Cypher can choose two adjacent numbers in a circle and insert their least common multiple between them. He can do that move as many times as needed.\\n\\nA message is decrypted, if every two adjacent numbers are not coprime. Note that for such constraints it's always possible to decrypt the message.\\n\\nFind the minimal number of moves that Cypher should do to decrypt the message, and show the initial order of numbers in the circle for that.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $t$ $(1 \\\\le t \\\\le 100)$ — the number of test cases. Next $t$ lines describe each test case.\\n\\nIn a single line of each test case description, there is a single composite number $n$ $(4 \\\\le n \\\\le 10^9)$ — the number from the message.\\n\\nIt's guaranteed that the total number of divisors of $n$ for all test cases does not exceed $2 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case in the first line output the initial order of divisors, which are greater than $1$, in the circle. In the second line output, the minimal number of moves needed to decrypt the message.\\n\\nIf there are different possible orders with a correct answer, print any of them.\\n\\n\\n-----Example-----\\nInput\\n3\\n6\\n4\\n30\\n\\nOutput\\n2 3 6 \\n1\\n2 4 \\n0\\n2 30 6 3 15 5 10 \\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case $6$ has three divisors, which are greater than $1$: $2, 3, 6$. Regardless of the initial order, numbers $2$ and $3$ are adjacent, so it's needed to place their least common multiple between them. After that the circle becomes $2, 6, 3, 6$, and every two adjacent numbers are not coprime.\\n\\nIn the second test case $4$ has two divisors greater than $1$: $2, 4$, and they are not coprime, so any initial order is correct, and it's not needed to place any least common multiples.\\n\\nIn the third test case all divisors of $30$ greater than $1$ can be...\",\"targets\":\"from sys import stdin, stdout\\nimport math\\nimport bisect\\n\\ndef gcd(a,b):\\n    while b > 0:\\n        a, b = b, a % b\\n    return a\\n\\ndef solve(n):\\n    dv = [n]\\n    x = 2\\n    while x*x <= n:\\n        if n%x == 0:\\n            dv.append(x)\\n            if x != n\\/\\/x:\\n                dv.append(n\\/\\/x)\\n        x += 1\\n    dv = sorted(dv)\\n    ans = [0]*len(dv) \\n\\n    ans[0], ans[-1] = dv[0], dv[-1]\\n    seen = {dv[0], dv[-1]}\\n    cur_prime = dv[0]\\n    min_prime = dv[0]\\n    while len(seen) < len(dv):\\n        for x in dv:\\n            if x in seen: continue\\n            if min_prime == -1:\\n                min_prime = x\\n\\n            if cur_prime == -1:\\n                if ans[len(seen)-2]%x == 0:\\n                    cur_prime = x\\n                    ans[len(seen)-1] = x\\n                    seen.add(x)\\n            else:\\n                if x%cur_prime == 0:\\n                    ans[len(seen)-1] = x\\n                    seen.add(x)\\n        if cur_prime == -1:\\n            cur_prime = min_prime\\n        else:\\n            cur_prime = -1\\n        min_prime = -1\\n    cnt = 0\\n    for i in range(1, len(ans)):\\n        if gcd(ans[i], ans[i-1]) == 1:\\n            cnt += 1\\n    print(\\\" \\\".join(map(str, ans)))\\n    print(cnt)\\n\\nt = int(stdin.readline())\\nfor _ in range(t):\\n    n = int(stdin.readline())\\n    solve(n)\\n\\n#for i in range(2, 50):\\n#    solve(i)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1370\\/E:\\nNaman has two binary strings $s$ and $t$ of length $n$ (a binary string is a string which only consists of the characters \\\"0\\\" and \\\"1\\\"). He wants to convert $s$ into $t$ using the following operation as few times as possible.\\n\\nIn one operation, he can choose any subsequence of $s$ and rotate it clockwise once.\\n\\nFor example, if $s = 1\\\\textbf{1}101\\\\textbf{00}$, he can choose a subsequence corresponding to indices ($1$-based) $\\\\{2, 6, 7 \\\\}$ and rotate them clockwise. The resulting string would then be $s = 1\\\\textbf{0}101\\\\textbf{10}$.\\n\\nA string $a$ is said to be a subsequence of string $b$ if $a$ can be obtained from $b$ by deleting some characters without changing the ordering of the remaining characters.\\n\\nTo perform a clockwise rotation on a sequence $c$ of size $k$ is to perform an operation which sets $c_1:=c_k, c_2:=c_1, c_3:=c_2, \\\\ldots, c_k:=c_{k-1}$ simultaneously.\\n\\nDetermine the minimum number of operations Naman has to perform to convert $s$ into $t$ or say that it is impossible. \\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ $(1 \\\\le n \\\\le 10^6)$ — the length of the strings.\\n\\nThe second line contains the binary string $s$ of length $n$.\\n\\nThe third line contains the binary string $t$ of length $n$.\\n\\n\\n-----Output-----\\n\\nIf it is impossible to convert $s$ to $t$ after any number of operations, print $-1$.\\n\\nOtherwise, print the minimum number of operations required.\\n\\n\\n-----Examples-----\\nInput\\n6\\n010000\\n000001\\n\\nOutput\\n1\\nInput\\n10\\n1111100000\\n0000011111\\n\\nOutput\\n5\\nInput\\n8\\n10101010\\n01010101\\n\\nOutput\\n1\\nInput\\n10\\n1111100000\\n1111100001\\n\\nOutput\\n-1\\n\\n\\n-----Note-----\\n\\nIn the first test, Naman can choose the subsequence corresponding to indices $\\\\{2, 6\\\\}$ and rotate it once to convert $s$ into $t$.\\n\\nIn the second test, he can rotate the subsequence corresponding to all indices $5$ times. It can be proved, that it is the minimum required number of operations.\\n\\nIn the last test, it is impossible to convert $s$ into $t$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\na = input()\\nb = input()\\ndiff = 0\\nmaxDiff = 0\\nminDiff = 0\\nfor i in range(n):\\n    if a[i] == '1':\\n        diff += 1\\n    if b[i] == '1':\\n        diff -= 1\\n    if diff > maxDiff:\\n        maxDiff = diff\\n    if diff < minDiff:\\n        minDiff = diff\\nif diff != 0:\\n    print(-1)\\nelse:\\n    print(maxDiff - minDiff)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given two strings $s$ and $t$. Both strings have length $n$ and consist of lowercase Latin letters. The characters in the strings are numbered from $1$ to $n$.\\n\\nYou can successively perform the following move any number of times (possibly, zero):  swap any two adjacent (neighboring) characters of $s$ (i.e. for any $i = \\\\{1, 2, \\\\dots, n - 1\\\\}$ you can swap $s_i$ and $s_{i + 1})$. \\n\\nYou can't apply a move to the string $t$. The moves are applied to the string $s$ one after another.\\n\\nYour task is to obtain the string $t$ from the string $s$. Find any way to do it with at most $10^4$ such moves.\\n\\nYou do not have to minimize the number of moves, just find any sequence of moves of length $10^4$ or less to transform $s$ into $t$.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $n$ ($1 \\\\le n \\\\le 50$) — the length of strings $s$ and $t$.\\n\\nThe second line of the input contains the string $s$ consisting of $n$ lowercase Latin letters.\\n\\nThe third line of the input contains the string $t$ consisting of $n$ lowercase Latin letters.\\n\\n\\n-----Output-----\\n\\nIf it is impossible to obtain the string $t$ using moves, print \\\"-1\\\".\\n\\nOtherwise in the first line print one integer $k$ — the number of moves to transform $s$ to $t$. Note that $k$ must be an integer number between $0$ and $10^4$ inclusive.\\n\\nIn the second line print $k$ integers $c_j$ ($1 \\\\le c_j < n$), where $c_j$ means that on the $j$-th move you swap characters $s_{c_j}$ and $s_{c_j + 1}$.\\n\\nIf you do not need to apply any moves, print a single integer $0$ in the first line and either leave the second line empty or do not print it at all.\\n\\n\\n-----Examples-----\\nInput\\n6\\nabcdef\\nabdfec\\n\\nOutput\\n4\\n3 5 4 5 \\n\\nInput\\n4\\nabcd\\naccd\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the string $s$ changes as follows: \\\"abcdef\\\" $\\\\rightarrow$ \\\"abdcef\\\" $\\\\rightarrow$ \\\"abdcfe\\\" $\\\\rightarrow$ \\\"abdfce\\\" $\\\\rightarrow$ \\\"abdfec\\\".\\n\\nIn the second example there is no way to transform the string $s$ into the string $t$ through any allowed moves.\",\"targets\":\"# from math import ceil\\n#from sys import stdout\\n\\nt = 1#int(input())\\nfor test in range(1,t+1):\\n    n = int(input())\\n    s = list(input())\\n    t = list(input())\\n    s1 = list(s)\\n    t1 = list(t)\\n    s1.sort();t1.sort()\\n    if s1!=t1:\\n        print(-1)\\n        continue\\n    count = 0\\n    moves = []\\n    for i in range(n):\\n        tmp = i+s[i:].index(t[i])\\n        count+=tmp-i\\n        for j in range(tmp-1, i-1, -1):\\n            s[j], s[j+1] = s[j+1], s[j]\\n            moves.append(j+1)\\n    print(count)\\n    print(*moves)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOne day n friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together. \\n\\nSimply speaking, the process of taking photos can be described as follows. On the photo, each photographed friend occupies a rectangle of pixels: the i-th of them occupies the rectangle of width w_{i} pixels and height h_{i} pixels. On the group photo everybody stands in a line, thus the minimum pixel size of the photo including all the photographed friends, is W × H, where W is the total sum of all widths and H is the maximum height of all the photographed friends.\\n\\nAs is usually the case, the friends made n photos — the j-th (1 ≤ j ≤ n) photo had everybody except for the j-th friend as he was the photographer.\\n\\nPrint the minimum size of each made photo in pixels. \\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (2 ≤ n ≤ 200 000) — the number of friends. \\n\\nThen n lines follow: the i-th line contains information about the i-th friend. The line contains a pair of integers w_{i}, h_{i} (1 ≤ w_{i} ≤ 10, 1 ≤ h_{i} ≤ 1000) — the width and height in pixels of the corresponding rectangle.\\n\\n\\n-----Output-----\\n\\nPrint n space-separated numbers b_1, b_2, ..., b_{n}, where b_{i} — the total number of pixels on the minimum photo containing all friends expect for the i-th one.\\n\\n\\n-----Examples-----\\nInput\\n3\\n1 10\\n5 5\\n10 1\\n\\nOutput\\n75 110 60 \\nInput\\n3\\n2 1\\n1 2\\n2 1\\n\\nOutput\\n6 4 6\",\"targets\":\"#!\\/bin\\/env python3\\n\\nfrom sys import stdin\\nfrom collections import namedtuple\\n\\nGuy = namedtuple('Guy', ['w', 'h'])\\n\\nmaxh1 = 0\\nmaxh2 = 0\\n\\nguys = []\\n\\nsumw = 0\\nstdin.readline()\\nfor line in stdin:\\n    try:\\n        w, h = map(lambda s: int(s.strip()), line.lstrip().split(' ', 1))\\n    except:\\n        continue\\n    guys.append(Guy(w, h))\\n    sumw += w\\n    if h >= maxh1:\\n        maxh2 = maxh1\\n        maxh1 = h\\n    elif h > maxh2:\\n        maxh2 = h\\n\\nfor g in guys:\\n    sq = (sumw - g.w)*(maxh1 if g.h != maxh1 else maxh2)\\n    print (sq, end=' ')\\n\\nprint()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/valid-palindrome\\/:\\nGiven a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.\\n\\nNote: For the purpose of this problem, we define empty string as valid palindrome.\\n\\nExample 1:\\n\\n\\nInput: \\\"A man, a plan, a canal: Panama\\\"\\nOutput: true\\n\\n\\nExample 2:\\n\\n\\nInput: \\\"race a car\\\"\\nOutput: false\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def isPalindrome(self, s):\\n         \\\"\\\"\\\"\\n         :type s: str\\n         :rtype: bool\\n         \\\"\\\"\\\"\\n         s = [symbol for symbol in s.lower() if  'a' <= symbol <= 'z' or '0' <= symbol <= '9']\\n         \\n         return s == s[::-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/minimum-number-of-taps-to-open-to-water-a-garden\\/:\\nThere is a one-dimensional garden on the x-axis. The garden starts at the point 0 and ends at the point n. (i.e The length of the garden is n).\\nThere are n + 1 taps located at points [0, 1, ..., n] in the garden.\\nGiven an integer n and an integer array ranges of length n + 1 where ranges[i] (0-indexed) means the i-th tap can water the area [i - ranges[i], i + ranges[i]] if it was open.\\nReturn the minimum number of taps that should be open to water the whole garden, If the garden cannot be watered return -1.\\n \\nExample 1:\\n\\nInput: n = 5, ranges = [3,4,1,1,0,0]\\nOutput: 1\\nExplanation: The tap at point 0 can cover the interval [-3,3]\\nThe tap at point 1 can cover the interval [-3,5]\\nThe tap at point 2 can cover the interval [1,3]\\nThe tap at point 3 can cover the interval [2,4]\\nThe tap at point 4 can cover the interval [4,4]\\nThe tap at point 5 can cover the interval [5,5]\\nOpening Only the second tap will water the whole garden [0,5]\\n\\nExample 2:\\nInput: n = 3, ranges = [0,0,0,0]\\nOutput: -1\\nExplanation: Even if you activate all the four taps you cannot water the whole garden.\\n\\nExample 3:\\nInput: n = 7, ranges = [1,2,1,0,2,1,0,1]\\nOutput: 3\\n\\nExample 4:\\nInput: n = 8, ranges = [4,0,0,0,0,0,0,0,4]\\nOutput: 2\\n\\nExample 5:\\nInput: n = 8, ranges = [4,0,0,0,4,0,0,0,4]\\nOutput: 1\\n\\n \\nConstraints:\\n\\n1 <= n <= 10^4\\nranges.length == n + 1\\n0 <= ranges[i] <= 100\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def minTaps(self, n: int, ranges: List[int]) -> int:\\n        if n < 1 or ranges is None: return -1\\n        dp = [None]*len(ranges)\\n        # for each tap\\n        for i in range(len(dp)):\\n            # calc tap left and right extent\\n            l = max(0, i-ranges[i])\\n            r = min(len(dp)-1, i+ranges[i])\\n            # for each cell in extent, take the min of the cell or the left extent of the tap\\n            for j in range(l, r+1):\\n                if dp[j] is None:\\n                    dp[j] = l\\n                else:\\n                    dp[j] = min(dp[j], l)\\n            # since we can reach to front from last, only one tap is required\\n            if dp[-1] == 0:\\n                return 1\\n        # start from end, jump backwards incrementing tap count each time\\n        # careful to exit if no jump can be made\\n        i = len(dp)-1\\n        c = 0\\n        while i > 0 and dp[i] is not None and dp[i] != i:\\n            i = dp[i]\\n            c += 1\\n        # if we can jump all the way to the front, then return the count else -1\\n        return c if i == 0 else -1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/590\\/B:\\nA team of furry rescue rangers was sitting idle in their hollow tree when suddenly they received a signal of distress. In a few moments they were ready, and the dirigible of the rescue chipmunks hit the road.\\n\\nWe assume that the action takes place on a Cartesian plane. The headquarters of the rescuers is located at point (x_1, y_1), and the distress signal came from the point (x_2, y_2).\\n\\nDue to Gadget's engineering talent, the rescuers' dirigible can instantly change its current velocity and direction of movement at any moment and as many times as needed. The only limitation is: the speed of the aircraft relative to the air can not exceed $v_{\\\\operatorname{max}}$ meters per second.\\n\\nOf course, Gadget is a true rescuer and wants to reach the destination as soon as possible. The matter is complicated by the fact that the wind is blowing in the air and it affects the movement of the dirigible. According to the weather forecast, the wind will be defined by the vector (v_{x}, v_{y}) for the nearest t seconds, and then will change to (w_{x}, w_{y}). These vectors give both the direction and velocity of the wind. Formally, if a dirigible is located at the point (x, y), while its own velocity relative to the air is equal to zero and the wind (u_{x}, u_{y}) is blowing, then after $T$ seconds the new position of the dirigible will be $(x + \\\\tau \\\\cdot u_{x}, y + \\\\tau \\\\cdot u_{y})$.\\n\\nGadget is busy piloting the aircraft, so she asked Chip to calculate how long will it take them to reach the destination if they fly optimally. He coped with the task easily, but Dale is convinced that Chip has given the random value, aiming only not to lose the face in front of Gadget. Dale has asked you to find the right answer.\\n\\nIt is guaranteed that the speed of the wind at any moment of time is strictly less than the maximum possible speed of the airship relative to the air.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains four integers x_1, y_1, x_2, y_2 (|x_1|,  |y_1|,  |x_2|,  |y_2| ≤ 10 000) — the coordinates of the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"f = lambda: map(int, input().split())\\na, b, c, d = f()\\ns, t = f()\\nvx, vy = f()\\nux, uy = f()\\ndef g(m):\\n    vt = min(t, m)\\n    ut = max(0, m - t)\\n    x = c - a - ut * ux - vt * vx\\n    y = d - b - ut * uy - vt * vy\\n    return x * x + y * y > (m * s) ** 2\\nl, r = 0, 1e9\\nwhile r - l > 1e-6:\\n    m = (l + r) \\/ 2\\n    if g(m): l = m\\n    else: r = m\\nprint(r)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLimak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are n players (including Limak himself) and right now all of them have bids on the table. i-th of them has bid with size a_{i} dollars.\\n\\nEach player can double his bid any number of times and triple his bid any number of times. The casino has a great jackpot for making all bids equal. Is it possible that Limak and his friends will win a jackpot?\\n\\n\\n-----Input-----\\n\\nFirst line of input contains an integer n (2 ≤ n ≤ 10^5), the number of players.\\n\\nThe second line contains n integer numbers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9) — the bids of players.\\n\\n\\n-----Output-----\\n\\nPrint \\\"Yes\\\" (without the quotes) if players can make their bids become equal, or \\\"No\\\" otherwise.\\n\\n\\n-----Examples-----\\nInput\\n4\\n75 150 75 50\\n\\nOutput\\nYes\\n\\nInput\\n3\\n100 150 250\\n\\nOutput\\nNo\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample test first and third players should double their bids twice, second player should double his bid once and fourth player should both double and triple his bid.\\n\\nIt can be shown that in the second sample test there is no way to make all bids equal.\",\"targets\":\"def div23(a):\\n\\twhile (a % 2 == 0):\\n\\t\\ta \\/\\/= 2\\n\\twhile (a % 3 == 0):\\n\\t\\ta \\/\\/= 3\\n\\treturn a\\n\\nn = int(input())\\ns = [int(i) for i in input().split(' ')]\\na = div23(s[0])\\ni = 1\\nwhile i < len(s):\\n\\tif (a != div23(s[i])):\\n\\t\\tbreak\\n\\ti += 1\\n\\nif i == len(s):\\n\\tprint(\\\"Yes\\\")\\nelse:\\n\\tprint(\\\"No\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1144\\/A:\\nA string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: \\\"fced\\\", \\\"xyz\\\", \\\"r\\\" and \\\"dabcef\\\". The following string are not diverse: \\\"az\\\", \\\"aa\\\", \\\"bad\\\" and \\\"babc\\\". Note that the letters 'a' and 'z' are not adjacent.\\n\\nFormally, consider positions of all letters in the string in the alphabet. These positions should form contiguous segment, i.e. they should come one by one without any gaps. And all letters in the string should be distinct (duplicates are not allowed).\\n\\nYou are given a sequence of strings. For each string, if it is diverse, print \\\"Yes\\\". Otherwise, print \\\"No\\\".\\n\\n\\n-----Input-----\\n\\nThe first line contains integer $n$ ($1 \\\\le n \\\\le 100$), denoting the number of strings to process. The following $n$ lines contains strings, one string per line. Each string contains only lowercase Latin letters, its length is between $1$ and $100$, inclusive.\\n\\n\\n-----Output-----\\n\\nPrint $n$ lines, one line per a string in the input. The line should contain \\\"Yes\\\" if the corresponding string is diverse and \\\"No\\\" if the corresponding string is not diverse. You can print each letter in any case (upper or lower). For example, \\\"YeS\\\", \\\"no\\\" and \\\"yES\\\" are all acceptable.\\n\\n\\n-----Example-----\\nInput\\n8\\nfced\\nxyz\\nr\\ndabcef\\naz\\naa\\nbad\\nbabc\\n\\nOutput\\nYes\\nYes\\nYes\\nYes\\nNo\\nNo\\nNo\\nNo\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#38728191\\nfrom collections import defaultdict as DD\\nfrom bisect import bisect_left as BL\\nfrom bisect import bisect_right as BR\\nfrom itertools import combinations as IC\\nfrom itertools import permutations as IP\\nfrom random import randint as RI\\nimport sys\\nMOD=pow(10,9)+7\\n\\ndef IN(f=0):\\n    if f==0:\\n        return ( [int(i) for i in sys.stdin.readline().split()] )\\n    else:\\n        return ( int(sys.stdin.readline()) )\\nnn=IN(1)\\nfor _ in range(nn):\\n    s=input()\\n    s=list(s)\\n    s.sort()\\n    n=len(s)\\n    if len(set(s))!=n:\\n        print(\\\"No\\\")\\n    else:\\n        f=0\\n        for i in range(1,n):\\n            if abs(ord(s[i])-ord(s[i-1]))!=1:\\n                f=1\\n        if f==1:\\n            print(\\\"No\\\")\\n        else:\\n            print(\\\"Yes\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58b16300a470d47498000811:\\nIn this Kata we focus on finding a sum S(n) which is the total number of divisors taken for all natural numbers less or equal to n. More formally, we investigate the sum of n components denoted by d(1) + d(2) + ... + d(n) in which for any i starting from 1 up to n the value of d(i) tells us how many distinct numbers divide i without a remainder. \\n\\nYour solution should work for possibly large values of n without a timeout.\\nAssume n to be greater than zero and not greater than 999 999 999 999 999.\\nBrute force approaches will not be feasible options in such cases. It is fairly simple to conclude that for every n>1 there holds a recurrence S(n) = S(n-1) + d(n) with initial case S(1) = 1.\\n\\nFor example:\\nS(1) = 1\\nS(2) = 3\\nS(3) = 5\\nS(4) = 8\\nS(5) = 10\\n\\nBut is the fact useful anyway? If you find it is rather not, maybe this will help: \\n\\nTry to convince yourself that for any natural k, the number S(k) is the same as the number of pairs (m,n) that solve the inequality mn <= k in natural numbers.\\nOnce it becomes clear, we can think of a partition of all the solutions into classes just by saying that a pair (m,n) belongs to the class indexed by n.\\nThe question now arises if it is possible to count solutions of n-th class. If f(n) stands for the number of solutions that belong to n-th class, it means that S(k) = f(1) + f(2) + f(3) + ...\\n\\nThe reasoning presented above leads us to some kind of a formula for S(k), however not necessarily the most efficient one. Can you imagine that all the solutions to inequality mn <= k can be split using sqrt(k) as pivotal item?\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def count_divisors(n):\\n  \\\"\\\"\\\"Counts the integer points under the parabola xy = n.\\n\\n  Because the region is symmetric about x = y, it is only necessary to sum up\\n  to that point (at n^{1\\/2}), and double it. By this method, a square region is\\n  counted twice, and thus subtracted off the total.\\n  \\\"\\\"\\\"\\n  r = int(n**(1\\/2))\\n  return 2*sum(n \\/\\/ i for i in range(1, r+1)) - r*r\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58558673b6b0e5a16b000028:\\nYou are making your very own boardgame. The game is played by two opposing players, featuring a 6 x 6 tile system, with the players taking turns to move their pieces (similar to chess). The design is finished, now it's time to actually write and implement the features. Being the good programmer you are, you carefully plan the procedure and break the program down into smaller managable sections. You decide to start coding the logic for resolving \\\"fights\\\" when two pieces engage in combat on a tile. \\n\\nYour boardgame features four unique pieces: \\n\\nSwordsman, Cavalry, Archer and Pikeman\\n\\nEach piece has unique movement and has advantages and weaknesses in combat against one of the other pieces. \\n\\nTask\\n\\nYou must write a function ```fightResolve``` that takes the attacking and defending piece as input parameters, and returns the winning piece. It may be the case that both the attacking and defending piece belong to the same player, after which you must return an error value to indicate an illegal move. \\n\\nIn C++ and C, the pieces will be represented as ```chars```. Values will be case-sensitive to display ownership. Let the following char values represent each piece from their respective player.\\n\\nPlayer 1:  ```p```= Pikeman, ```k```= Cavalry, ```a```= Archer, ```s```= Swordsman \\n\\nPlayer 2:  ```P```= Pikeman, ```K```= Cavalry, ```A```= Archer, ```S```= Swordsman \\n\\nThe outcome of the fight between two pieces depends on which piece attacks, the type of the attacking piece and the type of the defending piece. Archers always win against swordsmens, swordsmen always win against pikemen, pikemen always win against cavalry and cavalry always win against archers. If a matchup occurs that was not previously mentioned (for example Archers vs Pikemen) the attacker will always win. This table represents the winner of each possible engagement between an attacker and a defender.\\n\\n\\n(Attacker→)\\n   ...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def fight_resolve(d, a):\\n    return -1 if d.islower() == a.islower() else d if d.lower() + a.lower() in \\\"ka sp as pk\\\" else a\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe biggest event of the year – Cota 2 world championship \\\"The Innernational\\\" is right around the corner. $2^n$ teams will compete in a double-elimination format (please, carefully read problem statement even if you know what is it) to identify the champion. \\n\\nTeams are numbered from $1$ to $2^n$ and will play games one-on-one. All teams start in the upper bracket.\\n\\nAll upper bracket matches will be held played between teams that haven't lost any games yet. Teams are split into games by team numbers. Game winner advances in the next round of upper bracket, losers drop into the lower bracket.\\n\\nLower bracket starts with $2^{n-1}$ teams that lost the first upper bracket game. Each lower bracket round consists of two games. In the first game of a round $2^k$ teams play a game with each other (teams are split into games by team numbers). $2^{k-1}$ loosing teams are eliminated from the championship, $2^{k-1}$ winning teams are playing $2^{k-1}$ teams that got eliminated in this round of upper bracket (again, teams are split into games by team numbers). As a result of each round both upper and lower bracket have $2^{k-1}$ teams remaining. See example notes for better understanding.\\n\\nSingle remaining team of upper bracket plays with single remaining team of lower bracket in grand-finals to identify championship winner.\\n\\nYou are a fan of teams with numbers $a_1, a_2, ..., a_k$. You want the championship to have as many games with your favourite teams as possible. Luckily, you can affect results of every championship game the way you want. What's maximal possible number of championship games that include teams you're fan of?\\n\\n\\n-----Input-----\\n\\nFirst input line has two integers $n, k$ — $2^n$ teams are competing in the championship. You are a fan of $k$ teams ($2 \\\\le n \\\\le 17; 0 \\\\le k \\\\le 2^n$).\\n\\nSecond input line has $k$ distinct integers $a_1, \\\\ldots, a_k$ — numbers of teams you're a fan of ($1 \\\\le a_i \\\\le 2^n$).\\n\\n\\n-----Output-----\\n\\nOutput single integer — maximal possible number of championship games that include...\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\nn,k=list(map(int,input().split()))\\nif k==0:\\n    print(0)\\n    return\\n\\nA=sorted(map(int,input().split()))\\n\\n# DP[UL][n][left]\\n# [left*pow(2,n),left*pow(2,n)+pow(2,n))の間のチームで,\\n# ファンのチームが\\n# UL=0: upperでもlowerでも勝ち残っている\\n# UL=1: upperでのみ勝ち残っている\\n# UL=2: lowerでのみ勝ち残っている\\n# ときの、そこまでのファンのチームの試合数の最大値.\\n\\nDP=[[[0]*((1<<n)+2) for i in range(n+1)] for UL in range(3)]\\n\\nfor i in range(k):\\n    if A[i]%2==1:\\n        DP[1][1][A[i]]=1\\n        DP[2][1][A[i]]=1\\n    else:\\n        DP[1][1][A[i]-1]=1\\n        DP[2][1][A[i]-1]=1\\n\\n    if i<k-1 and A[i]%2==1 and A[i+1]==A[i]+1:\\n        DP[0][1][A[i]]=1\\n        \\nfor i in range(2,n+1):\\n    for left in range(1,(1<<n)+1,1<<i):\\n\\n        if DP[0][i-1][left]:\\n            DP[0][i][left]=max(DP[0][i-1][left] + DP[0][i-1][left+(1<<(i-1))] + 3,DP[0][i-1][left] + DP[1][i-1][left+(1<<(i-1))] + 3,\\\\\\n                               DP[0][i-1][left] + DP[2][i-1][left+(1<<(i-1))] + 3)\\n            \\n        if DP[0][i-1][left+(1<<(i-1))]:\\n            DP[0][i][left]=max(DP[0][i][left], DP[0][i-1][left] + DP[0][i-1][left+(1<<(i-1))] + 3,\\\\\\n                               DP[1][i-1][left] + DP[0][i-1][left+(1<<(i-1))] + 3,DP[2][i-1][left] + DP[0][i-1][left+(1<<(i-1))] + 3)\\n\\n        if DP[1][i-1][left]:\\n            DP[1][i][left]=max(DP[1][i][left], DP[1][i-1][left] + 1)\\n            DP[2][i][left]=max(DP[2][i][left], DP[1][i-1][left] + 2)\\n\\n        if DP[2][i-1][left]:\\n            DP[2][i][left]=max(DP[2][i][left], DP[2][i-1][left] + 2)\\n\\n        if DP[1][i-1][left+(1<<(i-1))]:\\n            DP[1][i][left]=max(DP[1][i][left], DP[1][i-1][left+(1<<(i-1))] + 1)\\n            DP[2][i][left]=max(DP[2][i][left], DP[1][i-1][left+(1<<(i-1))] + 2)\\n\\n        if DP[2][i-1][left+(1<<(i-1))]:\\n            DP[2][i][left]=max(DP[2][i][left], DP[2][i-1][left+(1<<(i-1))] + 2)\\n\\n\\n        if DP[1][i-1][left] and DP[1][i-1][left+(1<<(i-1))]:\\n            DP[0][i][left]=max(DP[0][i][left], DP[1][i-1][left] + DP[1][i-1][left+(1<<(i-1))] + 2)\\n\\n        if DP[1][i-1][left] and DP[2][i-1][left+(1<<(i-1))]:\\n         ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an integer $n$.\\n\\nYou can perform any of the following operations with this number an arbitrary (possibly, zero) number of times:   Replace $n$ with $\\\\frac{n}{2}$ if $n$ is divisible by $2$;  Replace $n$ with $\\\\frac{2n}{3}$ if $n$ is divisible by $3$;  Replace $n$ with $\\\\frac{4n}{5}$ if $n$ is divisible by $5$. \\n\\nFor example, you can replace $30$ with $15$ using the first operation, with $20$ using the second operation or with $24$ using the third operation.\\n\\nYour task is to find the minimum number of moves required to obtain $1$ from $n$ or say that it is impossible to do it.\\n\\nYou have to answer $q$ independent queries.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $q$ ($1 \\\\le q \\\\le 1000$) — the number of queries.\\n\\nThe next $q$ lines contain the queries. For each query you are given the integer number $n$ ($1 \\\\le n \\\\le 10^{18}$).\\n\\n\\n-----Output-----\\n\\nPrint the answer for each query on a new line. If it is impossible to obtain $1$ from $n$, print -1. Otherwise, print the minimum number of moves required to do it.\\n\\n\\n-----Example-----\\nInput\\n7\\n1\\n10\\n25\\n30\\n14\\n27\\n1000000000000000000\\n\\nOutput\\n0\\n4\\n6\\n6\\n-1\\n6\\n72\",\"targets\":\"n = int(input())\\nfor i in range(n):\\n    q = int(input())\\n    s = 0\\n    while(q%5==0):\\n        q = q\\/\\/5\\n        s+=3\\n    while(q%3==0):\\n        q = q\\/\\/3\\n        s+=2\\n    while(q%2==0):\\n        q = q\\/\\/2\\n        s+=1\\n    if(q==1):\\n        print(s)\\n    else:\\n        print(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/KM252020\\/problems\\/KM25P5C:\\nGiven the values at the leaf nodes of a complete binary tree. The total number of nodes in the binary tree, is also given. Sum of the values at both the children of a node is equal to the value of the node itself. You can add any value or subtract any value from a node. Print the minimum change(difference made) in the sum of values of all the nodes in the tree, such that all the leaf nodes have the same value.\\n\\nNote: If a value transfers from one node to another, then that is not a change, but if an extra is needed to be added or subtracted to the entire total value of the nodes, then that is a change.\\n\\nInput Description:\\n\\nInput will contain an integer N, the number of nodes in the tree on a newline, followed by N space separated integers representing the values at the leaf nodes of the tree.\\n\\nOutput Description:\\n\\nPrint the required value on a newline.\\n\\nConstraints:\\n\\n1<=N<=20000\\n1<=Value at each node in the leaves<=1000\\n\\nExample 1:\\nInput:\\n\\n1\\n\\n50\\nOutput:\\n\\n0\\n\\nExplanation: Since there is only one node, it is a leaf node itself and no change needs to be made.\\n\\nExample 2:\\nInput:\\n\\n3\\n\\n200 800\\nOutput:\\n\\n0 \\n\\nExplanation: There are two leaf nodes, and they can be made to 500 500, since no change in the total was made so difference made is 0. \\n\\nExample 3:\\nInput:\\n\\n30\\n\\n29 33 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17\\nOutput:\\n\\n6\\n\\nOutput: A total change of 6 needs to be changed to the entire value of the nodes, to get the leaf nodes equal.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"print(0)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5803956ddb07c5c74200144e:\\nEverybody knows the classic [\\\"half your age plus seven\\\"](https:\\/\\/en.wikipedia.org\\/wiki\\/Age_disparity_in_sexual_relationships#The_.22half-your-age-plus-seven.22_rule) dating rule that a lot of people follow (including myself). It's the 'recommended' age range in which to date someone. \\n\\n\\n\\n\\n```minimum age <= your age <= maximum age```\\n#Task\\n\\nGiven an integer (1 <= n <= 100) representing a person's age, return their minimum and maximum age range.\\n\\nThis equation doesn't work when the age <= 14, so use this equation instead:\\n```\\nmin = age - 0.10 * age\\nmax = age + 0.10 * age\\n```\\nYou should floor all your answers so that an integer is given instead of a float (which doesn't represent age). ```Return your answer in the form [min]-[max]```\\n\\n##Examples:\\n\\n```\\nage = 27   =>   20-40\\nage = 5    =>   4-5\\nage = 17   =>   15-20\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def dating_range(age):\\n    if age <= 14:\\n        return f'{int(age - 0.1 * age)}-{int(age + 0.1 * age)}'\\n    return f'{age\\/\\/2 + 7}-{(age-7)*2}'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/721\\/C:\\nRecently Irina arrived to one of the most famous cities of Berland — the Berlatov city. There are n showplaces in the city, numbered from 1 to n, and some of them are connected by one-directional roads. The roads in Berlatov are designed in a way such that there are no cyclic routes between showplaces.\\n\\nInitially Irina stands at the showplace 1, and the endpoint of her journey is the showplace n. Naturally, Irina wants to visit as much showplaces as she can during her journey. However, Irina's stay in Berlatov is limited and she can't be there for more than T time units.\\n\\nHelp Irina determine how many showplaces she may visit during her journey from showplace 1 to showplace n within a time not exceeding T. It is guaranteed that there is at least one route from showplace 1 to showplace n such that Irina will spend no more than T time units passing it.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers n, m and T (2 ≤ n ≤ 5000,  1 ≤ m ≤ 5000,  1 ≤ T ≤ 10^9) — the number of showplaces, the number of roads between them and the time of Irina's stay in Berlatov respectively.\\n\\nThe next m lines describes roads in Berlatov. i-th of them contains 3 integers u_{i}, v_{i}, t_{i} (1 ≤ u_{i}, v_{i} ≤ n, u_{i} ≠ v_{i}, 1 ≤ t_{i} ≤ 10^9), meaning that there is a road starting from showplace u_{i} and leading to showplace v_{i}, and Irina spends t_{i} time units to pass it. It is guaranteed that the roads do not form cyclic routes.\\n\\nIt is guaranteed, that there is at most one road between each pair of showplaces.\\n\\n\\n-----Output-----\\n\\nPrint the single integer k (2 ≤ k ≤ n) — the maximum number of showplaces that Irina can visit during her journey from showplace 1 to showplace n within time not exceeding T, in the first line.\\n\\nPrint k distinct integers in the second line — indices of showplaces that Irina will visit on her route, in the order of encountering them.\\n\\nIf there are multiple answers, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n4 3 13\\n1 2 5\\n2 3 7\\n2 4 8\\n\\nOutput\\n3\\n1 2 4 \\n\\nInput\\n6 6 7\\n1 2 2\\n1 3 3\\n3...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def __starting_point():\\n\\tn, m, t = map(int, input().split())\\n\\tedge = {i:{} for i in range(n)}\\n\\tincome = [0 for i in range(n)]\\n\\tfor i in range(m):\\n\\t\\tu, v, ti = map(int, input().split())\\n\\t\\tedge[v-1][u-1] = ti\\n\\t\\tincome[u-1] += 1\\n\\tstat = [{} for _ in range(n)]\\n\\tstat[n-1] = {1 : (0, -1)}\\n\\tqueue = [n-1]\\n\\tfirst = 0\\n\\tlast = 1\\n\\tfor i in range(n-2, 0, -1):\\n\\t\\tif income[i] == 0:\\n\\t\\t\\tqueue.append(i)\\n\\t\\t\\tlast += 1\\n\\twhile (first < last):\\n\\t\\tv = queue[first]\\n\\t\\tfirst += 1\\n\\t\\tfor u in edge[v].keys():\\n\\t\\t\\tincome[u] -= 1\\n\\t\\t\\tfor vis in stat[v].keys():\\n\\t\\t\\t\\tcost = stat[v][vis][0] + edge[v][u]\\n\\t\\t\\t\\tucost = stat[u].get(vis+1, (t+1,-1))[0]\\n\\t\\t\\t\\tif ucost > cost:\\n\\t\\t\\t\\t\\tstat[u][vis+1] = (cost, v)\\n\\t\\t\\tif income[u] <= 0:\\n\\t\\t\\t\\tqueue.append(u)\\n\\t\\t\\t\\tlast += 1\\n\\t#print(queue, last)\\n\\tres = max(stat[0].keys())\\n\\tprint(res)\\n\\tpath = []\\n\\tcurr = 0\\n\\tpath.append(curr+1)\\n\\twhile(stat[curr][res][1] >= 0):\\n\\t\\tcurr = stat[curr][res][1]\\n\\t\\tpath.append(curr+1)\\n\\t\\tres -= 1\\n\\tprint(' '.join(map(str, path)))\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/858\\/A:\\nFor a given positive integer n denote its k-rounding as the minimum positive integer x, such that x ends with k or more zeros in base 10 and is divisible by n.\\n\\nFor example, 4-rounding of 375 is 375·80 = 30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375.\\n\\nWrite a program that will perform the k-rounding of n.\\n\\n\\n-----Input-----\\n\\nThe only line contains two integers n and k (1 ≤ n ≤ 10^9, 0 ≤ k ≤ 8).\\n\\n\\n-----Output-----\\n\\nPrint the k-rounding of n.\\n\\n\\n-----Examples-----\\nInput\\n375 4\\n\\nOutput\\n30000\\n\\nInput\\n10000 1\\n\\nOutput\\n10000\\n\\nInput\\n38101 0\\n\\nOutput\\n38101\\n\\nInput\\n123456789 8\\n\\nOutput\\n12345678900000000\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def gcd(a,b):\\n    while b!=0:\\n        a,b=b,a%b\\n    return a\\n\\n\\nn, k = map(int, input().split())\\nn1 = n\\nk1 = k\\na = n1 \\/\\/ gcd(n, 10 ** k) * 10 ** k1\\nprint(a)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/919\\/D:\\nYou are given a graph with $n$ nodes and $m$ directed edges. One lowercase letter is assigned to each node. We define a path's value as the number of the most frequently occurring letter. For example, if letters on a path are \\\"abaca\\\", then the value of that path is $3$. Your task is find a path whose value is the largest.\\n\\n\\n-----Input-----\\n\\nThe first line contains two positive integers $n, m$ ($1 \\\\leq n, m \\\\leq 300\\\\,000$), denoting that the graph has $n$ nodes and $m$ directed edges.\\n\\nThe second line contains a string $s$ with only lowercase English letters. The $i$-th character is the letter assigned to the $i$-th node.\\n\\nThen $m$ lines follow. Each line contains two integers $x, y$ ($1 \\\\leq x, y \\\\leq n$), describing a directed edge from $x$ to $y$. Note that $x$ can be equal to $y$ and there can be multiple edges between $x$ and $y$. Also the graph can be not connected.\\n\\n\\n-----Output-----\\n\\nOutput a single line with a single integer denoting the largest value. If the value can be arbitrarily large, output -1 instead.\\n\\n\\n-----Examples-----\\nInput\\n5 4\\nabaca\\n1 2\\n1 3\\n3 4\\n4 5\\n\\nOutput\\n3\\n\\nInput\\n6 6\\nxzyabc\\n1 2\\n3 1\\n2 3\\n5 4\\n4 3\\n6 4\\n\\nOutput\\n-1\\n\\nInput\\n10 14\\nxzyzyzyzqx\\n1 2\\n2 4\\n3 5\\n4 5\\n2 6\\n6 8\\n6 5\\n2 10\\n3 9\\n10 9\\n4 6\\n1 10\\n2 8\\n3 7\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, the path with largest value is $1 \\\\to 3 \\\\to 4 \\\\to 5$. The value is $3$ because the letter 'a' appears $3$ times.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from sys import stdin\\ninput=lambda : stdin.readline().strip()\\nfrom math import ceil,sqrt,factorial,gcd\\nfrom collections import deque\\nfrom bisect import bisect_left\\nn,m=list(map(int,input().split()))\\ns=input()\\nx=[]\\ny=[]\\nfor i in range(m):\\n    a,b=list(map(int,input().split()))\\n    x.append(a)\\n    y.append(b)\\n\\ndef beauty(n,m,s,x,y):\\n    l=list(s)\\n    degree=[0 for i in range(n)]\\n    graph={i:[] for i in range(n)}\\n    for i in range(m):\\n        a,b=x[i],y[i]\\n        a-=1\\n        b-=1\\n        graph[a].append(b)\\n        degree[b]+=1\\n    q=deque()\\n    for i in range(n):\\n        if degree[i]==0:\\n            q.append(i)\\n    \\n    count=0\\n    ans=0\\n    # print(degree)\\n    dp=[[0 for i in range(26)] for i in range(n)]\\n    while count<n and q:\\n            x=q.popleft()\\n            count+=1\\n            # print(ord(l[x])-97)\\n            dp[x][ord(l[x])-97]+=1\\n            for i in graph[x]:\\n                    for j in range(26):\\n                            dp[i][j]=max(dp[i][j],dp[x][j])\\n                    degree[i]-=1\\n                    if degree[i]==0:\\n                            q.append(i)\\n    # print(degree)\\n    if count!=n:\\n            print(-1)\\n    else:\\n            ans=0\\n            for i in range(n):\\n                    ans=max(ans,max(dp[i]))\\n            print(ans)\\n\\nbeauty(n,m,s,x,y)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1361\\/B:\\nJohnny has just found the new, great tutorial: \\\"How to become a grandmaster?\\\". The tutorial tells many strange and unexpected for Johnny things, such as you have to be patient or that very important is solving many harder and harder problems. \\n\\nThe boy has found an online judge with tasks divided by topics they cover. He has picked $p^{k_i}$ problems from $i$-th category ($p$ is his favorite number). He wants to solve them in two weeks (the patience condition is too hard for Johnny, so for simplicity, he looks only at easy tasks, which can be solved in such a period). Now our future grandmaster has to decide which topics to cover first and which the second week. Help him assign topics in such a way, that workload is balanced.\\n\\nFormally, given $n$ numbers $p^{k_i}$, the boy wants to divide them into two disjoint sets, minimizing the absolute difference between sums of numbers in each set. Find the minimal absolute difference. Output the result modulo $10^{9}+7$.\\n\\n\\n-----Input-----\\n\\nInput consists of multiple test cases. The first line contains one integer $t$ $(1 \\\\leq t \\\\leq 10^5)$ — the number of test cases. Each test case is described as follows:\\n\\nThe first line contains two integers $n$ and $p$ $(1 \\\\leq n, p \\\\leq 10^6)$. The second line contains $n$ integers $k_i$ $(0 \\\\leq k_i \\\\leq 10^6)$.\\n\\nThe sum of $n$ over all test cases doesn't exceed $10^6$.\\n\\n\\n-----Output-----\\n\\nOutput one integer — the reminder of division the answer by $1\\\\,000\\\\,000\\\\,007$.\\n\\n\\n-----Example-----\\nInput\\n4\\n5 2\\n2 3 4 4 3\\n3 1\\n2 10 1000\\n4 5\\n0 1 1 100\\n1 8\\n89\\n\\nOutput\\n4\\n1\\n146981438\\n747093407\\n\\n\\n\\n-----Note-----\\n\\nYou have to minimize the difference, not it's remainder. For example, if the minimum difference is equal to $2$, but there is also a distribution where the difference is $10^9 + 8$, then the answer is $2$, not $1$.\\n\\nIn the first test case of the example, there're the following numbers: $4$, $8$, $16$, $16$, and $8$. We can divide them into such two sets: ${4, 8, 16}$ and ${8, 16}$. Then the difference between the sums of numbers in sets would be $4$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nmod=1000000007\\n\\nt=int(input())\\nfor tests in range(t):\\n    n,p=list(map(int,input().split()))\\n    K=sorted(map(int,input().split()),reverse=True)\\n\\n    if p==1:\\n        if n%2==0:\\n            print(0)\\n        else:\\n            print(1)\\n        continue\\n\\n    ANS=[0,0]\\n    flag=0\\n\\n    for i in range(n):\\n        k=K[i]\\n        \\n        if ANS[0]==0:\\n            ANS=[1,k]\\n            \\n        elif ANS[1]==k:\\n            ANS[0]-=1\\n\\n        else:\\n            while ANS[1]>k:\\n                ANS[0]*=p\\n                ANS[1]-=1\\n\\n                if ANS[0]>10**7:\\n                    flag=1\\n                    lastind=i\\n                    break\\n\\n            if flag==1:\\n                A=ANS[0]*pow(p,ANS[1],mod)%mod\\n                #print(A,ANS)\\n\\n                for j in range(lastind,n):\\n                    A=(A-pow(p,K[j],mod))%mod\\n                print(A)\\n                break\\n            else:\\n                ANS[0]-=1\\n\\n    if flag==0:\\n        print(ANS[0]*pow(p,ANS[1],mod)%mod)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1076\\/C:\\nTry guessing the statement from this picture:  $3$ \\n\\nYou are given a non-negative integer $d$. You have to find two non-negative real numbers $a$ and $b$ such that $a + b = d$ and $a \\\\cdot b = d$.\\n\\n\\n-----Input-----\\n\\nThe first line contains $t$ ($1 \\\\le t \\\\le 10^3$) — the number of test cases.\\n\\nEach test case contains one integer $d$ $(0 \\\\le d \\\\le 10^3)$.\\n\\n\\n-----Output-----\\n\\nFor each test print one line.\\n\\nIf there is an answer for the $i$-th test, print \\\"Y\\\", and then the numbers $a$ and $b$.\\n\\nIf there is no answer for the $i$-th test, print \\\"N\\\".\\n\\nYour answer will be considered correct if $|(a + b) - a \\\\cdot b| \\\\le 10^{-6}$ and $|(a + b) - d| \\\\le 10^{-6}$.\\n\\n\\n-----Example-----\\nInput\\n7\\n69\\n0\\n1\\n4\\n5\\n999\\n1000\\n\\nOutput\\nY 67.985071301 1.014928699\\nY 0.000000000 0.000000000\\nN\\nY 2.000000000 2.000000000\\nY 3.618033989 1.381966011\\nY 997.998996990 1.001003010\\nY 998.998997995 1.001002005\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for _ in range(int(input())):\\n    d=int(input())\\n    anws=False\\n    if d**2>=4*d:\\n        root=(d**2-4*d)**0.5\\n        a=(d+root)\\/2\\n        b=(d-root)\\/2\\n        anws=True\\n    if anws:\\n        print(\\\"Y {:.9f} {:.9f}\\\".format(a,b))\\n    else:\\n        print(\\\"N\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nBimokh is Mashmokh's boss. For the following n days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each worker can give some of his tokens back to get a certain amount of money. The worker can save the rest of tokens but he can't use it in any other day to get more money. If a worker gives back w tokens then he'll get $\\\\lfloor \\\\frac{w \\\\cdot a}{b} \\\\rfloor$ dollars. \\n\\nMashmokh likes the tokens however he likes money more. That's why he wants to save as many tokens as possible so that the amount of money he gets is maximal possible each day. He has n numbers x_1, x_2, ..., x_{n}. Number x_{i} is the number of tokens given to each worker on the i-th day. Help him calculate for each of n days the number of tokens he can save.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains three space-separated integers n, a, b (1 ≤ n ≤ 10^5; 1 ≤ a, b ≤ 10^9). The second line of input contains n space-separated integers x_1, x_2, ..., x_{n} (1 ≤ x_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nOutput n space-separated integers. The i-th of them is the number of tokens Mashmokh can save on the i-th day.\\n\\n\\n-----Examples-----\\nInput\\n5 1 4\\n12 6 11 9 1\\n\\nOutput\\n0 2 3 1 1 \\nInput\\n3 1 2\\n1 2 3\\n\\nOutput\\n1 0 1 \\nInput\\n1 1 1\\n1\\n\\nOutput\\n0\",\"targets\":\"import math\\n\\nn,a,b=map(int,input().split())\\nxlist=[int(x) for x in input().split()]\\nsavestring=''\\n\\nfor i in range(n):\\n    maxmoney=math.floor(xlist[i]*a\\/b)\\n    saves=xlist[i]-math.ceil(maxmoney*b\\/a)\\n    savestring+=str(saves)+' '\\n    \\nprint(savestring)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/CLEANUP:\\nAfter a long and successful day of preparing food for the banquet, it is time to clean up. There is a list of n jobs to do before the kitchen can be closed for the night. These jobs are indexed from 1 to n.\\n\\nMost of the cooks have already left and only the Chef and his assistant are left to clean up. Thankfully, some of the cooks took care of some of the jobs before they left so only a subset of the n jobs remain. The Chef and his assistant divide up the remaining jobs in the following manner. The Chef takes the unfinished job with least index, the assistant takes the unfinished job with the second least index, the Chef takes the unfinished job with the third least index, etc. That is, if the unfinished jobs were listed in increasing order of their index then the Chef would take every other one starting with the first job in the list and the assistant would take every other one starting with the second job on in the list.\\n\\nThe cooks logged which jobs they finished before they left. Unfortunately, these jobs were not recorded in any particular order. Given an unsorted list\\nof finished jobs, you are to determine which jobs the Chef must complete and which jobs his assitant must complete before closing the kitchen for the \\nevening.\\n\\n-----Input-----\\n\\nThe first line contains a single integer T ≤ 50 indicating the number of test cases to follow. Each test case consists of two lines. The first line contains two numbers n,m satisfying 0 ≤ m ≤ n ≤ 1000. Here, n is the total number of jobs that must be completed before closing and m is the number of jobs that have already been completed. The second line contains a list of m distinct integers between 1 and n. These are the indices of the jobs that have already been completed. Consecutive integers are separated by a single space.\\n\\n-----Output-----\\n\\nThe output for each test case consists of two lines. The first line is a list of the indices of the jobs assigned to the Chef. The second line is a list of the indices of the jobs assigned to his assistant. Both lists must...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n=int(input())\\nfor _ in range(n):\\n c,a=[],[]\\n tot=list(map(int,input().split()))\\n done=list(map(int,input().split()))\\n for i in range(1,tot[0]+1):\\n  if i in done:\\n   continue\\n  else:\\n   if len(c)<=len(a):\\n    c.append(i)\\n   else:\\n    a.append(i)\\n c.sort()\\n a.sort()\\n for j in c:\\n  print(j,end=\\\" \\\")\\n print()\\n for k in a:\\n  print(k,end=\\\" \\\")\\n print()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOne day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.\\n\\nBut there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest by its name.\\n\\nIt is known, that problem is from this contest if and only if its name contains one of Alex's friends' name exactly once. His friends' names are \\\"Danil\\\", \\\"Olya\\\", \\\"Slava\\\", \\\"Ann\\\" and \\\"Nikita\\\".\\n\\nNames are case sensitive.\\n\\n\\n-----Input-----\\n\\nThe only line contains string from lowercase and uppercase letters and \\\"_\\\" symbols of length, not more than 100 — the name of the problem.\\n\\n\\n-----Output-----\\n\\nPrint \\\"YES\\\", if problem is from this contest, and \\\"NO\\\" otherwise.\\n\\n\\n-----Examples-----\\nInput\\nAlex_and_broken_contest\\n\\nOutput\\nNO\\nInput\\nNikitaAndString\\n\\nOutput\\nYES\\nInput\\nDanil_and_Olya\\n\\nOutput\\nNO\",\"targets\":\"s = input()\\n\\nif s.count('Danil') + s.count('Olya') + s.count('Slava') + \\\\\\n   s.count('Ann') + s.count('Nikita') == 1:\\n    print('YES')\\nelse:\\n    print('NO')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a positive integer $n$, written without leading zeroes (for example, the number 04 is incorrect). \\n\\nIn one operation you can delete any digit of the given integer so that the result remains a positive integer without leading zeros.\\n\\nDetermine the minimum number of operations that you need to consistently apply to the given integer $n$ to make from it the square of some positive integer or report that it is impossible.\\n\\nAn integer $x$ is the square of some positive integer if and only if $x=y^2$ for some positive integer $y$.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^{9}$). The number is given without leading zeroes.\\n\\n\\n-----Output-----\\n\\nIf it is impossible to make the square of some positive integer from $n$, print -1. In the other case, print the minimal number of operations required to do it.\\n\\n\\n-----Examples-----\\nInput\\n8314\\n\\nOutput\\n2\\n\\nInput\\n625\\n\\nOutput\\n0\\n\\nInput\\n333\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first example we should delete from $8314$ the digits $3$ and $4$. After that $8314$ become equals to $81$, which is the square of the integer $9$.\\n\\nIn the second example the given $625$ is the square of the integer $25$, so you should not delete anything. \\n\\nIn the third example it is impossible to make the square from $333$, so the answer is -1.\",\"targets\":\"def is_sqr(x):\\n  y = 1\\n  while y**2 < x:\\n    y += 1\\n  return y**2 == x\\n\\nfrom itertools import combinations\\nn = input()\\nans = 100\\nfor r in range(1, len(n) + 1):\\n  for item in combinations(n, r):\\n    #print(int(''.join(item)))\\n    if is_sqr(int(''.join(item))) and item[0] != '0':\\n      ans = min(ans, len(n) - len(item))\\nprint(ans if ans != 100 else -1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are fighting with Zmei Gorynich — a ferocious monster from Slavic myths, a huge dragon-like reptile with multiple heads! \\n\\n $m$ \\n\\nInitially Zmei Gorynich has $x$ heads. You can deal $n$ types of blows. If you deal a blow of the $i$-th type, you decrease the number of Gorynich's heads by $min(d_i, curX)$, there $curX$ is the current number of heads. But if after this blow Zmei Gorynich has at least one head, he grows $h_i$ new heads. If $curX = 0$ then Gorynich is defeated. \\n\\nYou can deal each blow any number of times, in any order.\\n\\nFor example, if $curX = 10$, $d = 7$, $h = 10$ then the number of heads changes to $13$ (you cut $7$ heads off, but then Zmei grows $10$ new ones), but if $curX = 10$, $d = 11$, $h = 100$ then number of heads changes to $0$ and Zmei Gorynich is considered defeated.\\n\\nCalculate the minimum number of blows to defeat Zmei Gorynich!\\n\\nYou have to answer $t$ independent queries.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 100$) – the number of queries.\\n\\nThe first line of each query contains two integers $n$ and $x$ ($1 \\\\le n \\\\le 100$, $1 \\\\le x \\\\le 10^9$) — the number of possible types of blows and the number of heads Zmei initially has, respectively.\\n\\nThe following $n$ lines of each query contain the descriptions of types of blows you can deal. The $i$-th line contains two integers $d_i$ and $h_i$ ($1 \\\\le d_i, h_i \\\\le 10^9$) — the description of the $i$-th blow.\\n\\n\\n-----Output-----\\n\\nFor each query print the minimum number of blows you have to deal to defeat Zmei Gorynich. \\n\\nIf Zmei Gorynuch cannot be defeated print $-1$.\\n\\n\\n-----Example-----\\nInput\\n3\\n3 10\\n6 3\\n8 2\\n1 4\\n4 10\\n4 1\\n3 2\\n2 6\\n1 100\\n2 15\\n10 11\\n14 100\\n\\nOutput\\n2\\n3\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first query you can deal the first blow (after that the number of heads changes to $10 - 6 + 3 = 7$), and then deal the second blow.\\n\\nIn the second query you just deal the first blow three times, and Zmei is defeated. \\n\\nIn third query you can not defeat Zmei Gorynich. Maybe it's better to convince it to stop fighting?\",\"targets\":\"from bisect import bisect_left as bl\\nfrom collections import defaultdict as dd\\n\\n\\nfor _ in range(int(input())):\\n\\tn, x = [int(i) for i in input().split()]\\n\\tl = []\\n\\tf = dd(int)\\n\\tfor j in range(n):\\n\\t\\td, h = [int(i) for i in input().split()]\\n\\t\\tl.append(d - h)\\n\\t\\tf[d] = 1\\n\\t#print(n, x)\\n\\tl.sort(reverse = 1)\\n\\t#print(l)\\n\\tans = 1\\n\\tx -= max(f.keys())\\n\\tif x <= 0:\\n\\t\\tprint(ans)\\n\\telse:\\n\\t\\tif l[0] <= 0:\\n\\t\\t\\tans = -1\\n\\t\\telse:\\n\\t\\t\\tans = x \\/\\/ l[0]\\n\\t\\t\\tif (x % l[0]) == 0:\\n\\t\\t\\t\\tans += 1\\n\\t\\t\\telse:\\n\\t\\t\\t\\tans += 2\\n\\t\\tprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are three horses living in a horse land: one gray, one white and one gray-and-white. The horses are really amusing animals, which is why they adore special cards. Each of those cards must contain two integers, the first one on top, the second one in the bottom of the card. Let's denote a card with a on the top and b in the bottom as (a, b).\\n\\nEach of the three horses can paint the special cards. If you show an (a, b) card to the gray horse, then the horse can paint a new (a + 1, b + 1) card. If you show an (a, b) card, such that a and b are even integers, to the white horse, then the horse can paint a new $(\\\\frac{a}{2}, \\\\frac{b}{2})$ card. If you show two cards (a, b) and (b, c) to the gray-and-white horse, then he can paint a new (a, c) card.\\n\\nPolycarpus really wants to get n special cards (1, a_1), (1, a_2), ..., (1, a_{n}). For that he is going to the horse land. He can take exactly one (x, y) card to the horse land, such that 1 ≤ x < y ≤ m. How many ways are there to choose the card so that he can perform some actions in the horse land and get the required cards?\\n\\nPolycarpus can get cards from the horses only as a result of the actions that are described above. Polycarpus is allowed to get additional cards besides the cards that he requires.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n, m (1 ≤ n ≤ 10^5, 2 ≤ m ≤ 10^9). The second line contains the sequence of integers a_1, a_2, ..., a_{n} (2 ≤ a_{i} ≤ 10^9). Note, that the numbers in the sequence can coincide.\\n\\nThe numbers in the lines are separated by single spaces.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the answer to the problem. \\n\\nPlease, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.\\n\\n\\n-----Examples-----\\nInput\\n1 6\\n2\\n\\nOutput\\n11\\n\\nInput\\n1 6\\n7\\n\\nOutput\\n14\\n\\nInput\\n2 10\\n13 7\\n\\nOutput\\n36\",\"targets\":\"# written with help of editorial\\nn, m = list(map(int, input().split()))\\na = list(map(int, input().split()))\\n\\ndef gcd(x, y):\\n    while y:\\n        x, y = y, x % y\\n    return x\\n\\ng = 0\\nfor x in a:\\n    g = gcd(g, x - 1)\\n\\nanswer = 0\\n\\ndef process(x):\\n    nonlocal answer\\n    if x % 2 == 0:\\n        return 0\\n    for i in range(30):\\n        v = 2 ** i * x\\n        if v > m:\\n            break\\n        answer += m - v\\n\\nfor i in range(1, g + 1):\\n    if i * i > g:\\n        break\\n    if g % i:\\n        continue\\n    process(i)\\n    if i * i != g:\\n        process(g \\/\\/ i)\\n\\nprint(answer)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1353\\/E:\\nYou are given a garland consisting of $n$ lamps. States of the lamps are represented by the string $s$ of length $n$. The $i$-th character of the string $s_i$ equals '0' if the $i$-th lamp is turned off or '1' if the $i$-th lamp is turned on. You are also given a positive integer $k$.\\n\\nIn one move, you can choose one lamp and change its state (i.e. turn it on if it is turned off and vice versa).\\n\\nThe garland is called $k$-periodic if the distance between each pair of adjacent turned on lamps is exactly $k$. Consider the case $k=3$. Then garlands \\\"00010010\\\", \\\"1001001\\\", \\\"00010\\\" and \\\"0\\\" are good but garlands \\\"00101001\\\", \\\"1000001\\\" and \\\"01001100\\\" are not. Note that the garland is not cyclic, i.e. the first turned on lamp is not going after the last turned on lamp and vice versa.\\n\\nYour task is to find the minimum number of moves you need to make to obtain $k$-periodic garland from the given one.\\n\\nYou have to answer $t$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 25~ 000$) — the number of test cases. Then $t$ test cases follow.\\n\\nThe first line of the test case contains two integers $n$ and $k$ ($1 \\\\le n \\\\le 10^6; 1 \\\\le k \\\\le n$) — the length of $s$ and the required period. The second line of the test case contains the string $s$ consisting of $n$ characters '0' and '1'.\\n\\nIt is guaranteed that the sum of $n$ over all test cases does not exceed $10^6$ ($\\\\sum n \\\\le 10^6$).\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer — the minimum number of moves you need to make to obtain $k$-periodic garland from the given one.\\n\\n\\n-----Example-----\\nInput\\n6\\n9 2\\n010001010\\n9 3\\n111100000\\n7 4\\n1111111\\n10 3\\n1001110101\\n1 1\\n1\\n1 1\\n0\\n\\nOutput\\n1\\n2\\n5\\n4\\n0\\n0\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nstrs = iter(sys.stdin.read().split())\\nints = (int(x) for x in strs)\\nsys.setrecursionlimit(3000)\\n\\ndef main():\\n    ntc = next(ints)\\n    for tc in range(1,ntc+1):\\n        n, k = (next(ints) for i in range(2))\\n        s = next(strs)\\n        R = (n+k-1)\\/\\/k\\n        m = [[int(i*k+j<n and s[i*k+j]=='1') for i in range(R)] for j in range(k)]\\n        s = [sum(m[j]) for j in range(k)]\\n        s_sum = sum(s)\\n        ans = [0]*k\\n        #0  1  1  0  1  0  1  1  0\\n        for j in range(k):\\n            off = [0]*(R+1)\\n            on  = [0]*(R+1)\\n            for i in range(R-1, -1, -1):\\n                off[i] = m[j][i] + off[i+1]\\n                on[i] = 1-m[j][i]+min(on[i+1], off[i+1])\\n            for i in range(R+1):\\n                off[i] = (i and off[i-1]) + (i<R and m[j][i])\\n                on[i] = on[i] + (i and off[i-1])\\n            ans[j] = s_sum-s[j] + min(on)\\n        print(min(ans))\\n    return\\n\\nmain()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/add-digits\\/:\\nGiven a non-negative integer num, repeatedly add all its digits until the result has only one digit.\\n\\nExample:\\n\\n\\nInput: 38\\nOutput: 2 \\nExplanation: The process is like: 3 + 8 = 11, 1 + 1 = 2. \\n             Since 2 has only one digit, return it.\\n\\n\\nFollow up:\\nCould you do it without any loop\\/recursion in O(1) runtime?\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def addDigits(self, num):\\n         \\\"\\\"\\\"\\n         :type num: int\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         return num if num < 10 else num%9 if num%9!=0 else 9\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nBack in 2015, Usain Bolt announced that he'll be retiring after the 2017 World Championship. Though his final season did not end gloriously, we all know that he is a true legend and we witnessed his peak during 2008 - 2013. \\nPost retirement, Usain Bolt is still leading an adventurous life. He's exploring the unexplored parts of the globe. But sometimes he gets bored, and reads questions asked about him on Quora. One such question he read was, \\\"Who would win a race between Usain Bolt and a tiger if the race is on a straight line track and the tiger is $distancetoBolt$ meters behind Bolt? The finishing point is $finish$ meters away from Bolt's starting position. The tiger starts with an initial speed of $0$ $meter\\/second$, and will accelerate itself with $tigerAccelaration$ $m\\/s^2$. Bolt can run with a constant speed of $boltSpeed$ $m\\/s$ from start to finish. Given these values, find out who will win the race - Bolt or the tiger? \\\"\\nNote that Bolt will win the race if and only if he touches the finishing line before the tiger touches it. If both of them finish together, the tiger is announced as the winner since Bolt was given an initial advantage. See the figure below for more clarity.\\n\\nSince Bolt was busy practicing in the tracks during his Physics school classes, he is asking for your help to solve the question. Can you please help him?\\nHe just remembers two formulae from the class, and thinks that they will be useful to you:\\n$Displacement (S) $ = $ut$ +$ (1\\/2)at^2$ where $u$ is the initial velocity , #$ $is the acceleration and $t$ is the time taken.\\n$Velocity$ = $Displacement \\/Time$\\n\\n-----Input:-----\\n- The first line will contain $T$, the number of testcases. Then the description of each test case follow. \\n- Each test case contains 4 integers $finish, distancetoBolt, tigerAccelaration, boltSpeed$. \\n\\n-----Output:-----\\nFor each testcase, output in a single line, the word \\\"Bolt\\\" or \\\"Tiger\\\" without quotes, depending on whether Bolt wins or the tiger wins.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100000$\\n- $1...\",\"targets\":\"for i in range(int(input())):\\n finish,distanetobolt,tigerAcceleration,boltspeed=list(map(int,input().split()))\\n t1=((2*(finish+distanetobolt)\\/(tigerAcceleration))**0.5)\\n t2=(finish\\/boltspeed)\\n if t1>t2:\\n  print(\\\"Bolt\\\")\\n elif t1<t2:\\n  print(\\\"Tiger\\\")\\n else:\\n  print(\\\"Tiger\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nSquirrel Liss is interested in sequences. She also has preferences of integers. She thinks n integers a_1, a_2, ..., a_{n} are good.\\n\\nNow she is interested in good sequences. A sequence x_1, x_2, ..., x_{k} is called good if it satisfies the following three conditions:  The sequence is strictly increasing, i.e. x_{i} < x_{i} + 1 for each i (1 ≤ i ≤ k - 1).  No two adjacent elements are coprime, i.e. gcd(x_{i}, x_{i} + 1) > 1 for each i (1 ≤ i ≤ k - 1) (where gcd(p, q) denotes the greatest common divisor of the integers p and q).  All elements of the sequence are good integers. \\n\\nFind the length of the longest good sequence.\\n\\n\\n-----Input-----\\n\\nThe input consists of two lines. The first line contains a single integer n (1 ≤ n ≤ 10^5) — the number of good integers. The second line contains a single-space separated list of good integers a_1, a_2, ..., a_{n} in strictly increasing order (1 ≤ a_{i} ≤ 10^5; a_{i} < a_{i} + 1).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the length of the longest good sequence.\\n\\n\\n-----Examples-----\\nInput\\n5\\n2 3 4 6 9\\n\\nOutput\\n4\\n\\nInput\\n9\\n1 2 3 5 6 7 8 9 10\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, the following sequences are examples of good sequences: [2; 4; 6; 9], [2; 4; 6], [3; 9], [6]. The length of the longest good sequence is 4.\",\"targets\":\"# import math\\n# N=10010\\n# def solve(ar):\\n# \\tdp=[0 for i in range(N+20)]\\n# \\tfor i in ar:\\n# \\t\\tx=math.sqrt(i)\\n# \\t\\tfor j in range(2,x+1):\\n# \\t\\t\\tif(i%j==0):\\n# \\t\\t\\t\\tdp[i]=max(dp[i],max(dp[j]+1,dp[i\\/\\/j]+1))\\n#         for j in range(2,x+1):\\n#         \\tif(i%j==0):\\n#         \\t\\tdp[j]=dp[i\\/\\/j]=dp[i]\\n#     m=1\\n#     for i in range(1,10010):\\n#     \\tm=max(m,dp[i])\\n#     return m\\nimport math\\nN=100100\\ndef solve(ar):\\n\\tn=len(ar)\\n\\tdp=[0 for i in range(N+20)]\\n\\tfor a in ar:\\n\\t\\tx=math.sqrt(a)\\n\\t\\tdp[a]=1\\n\\t\\tfor j in range(2,a):\\n\\t\\t\\tif(j*j<=a):\\n\\t\\t\\t\\tif(a%j == 0):\\n\\t\\t\\t\\t    dp[a]=max(dp[a],max(dp[a\\/\\/j]+1,dp[j]+1))\\n\\t\\t\\telse:\\n\\t\\t\\t\\tbreak\\n\\t\\tfor j in range(2,a):\\n\\t\\t\\tif(j*j<=a):\\n\\t\\t\\t\\tif(a%j == 0):\\n\\t\\t\\t\\t   dp[j]=dp[a\\/\\/j]=dp[a]\\n\\t\\t\\telse:\\n\\t\\t\\t\\tbreak\\n\\t\\t\\t\\n\\tm=1\\n\\tfor x in range(1,100100):\\n\\t\\tm=max(m,dp[x])\\n\\treturn m\\n\\nn=int(input())\\nar=list(map(int,input().split()))\\nx=solve(ar)\\nprint(x)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAlice and Bob play a game. Initially they have a string $s_1, s_2, \\\\dots, s_n$, consisting of only characters . and X. They take alternating turns, and Alice is moving first. During each turn, the player has to select a contiguous substring consisting only of characters . and replaces each of them with X. Alice must select a substing of length $a$, and Bob must select a substring of length $b$. It is guaranteed that $a > b$.\\n\\nFor example, if $s =$ ...X.. and $a = 3$, $b = 2$, then after Alice's move string can turn only into XXXX... And if it's Bob's turn and the string $s =$ ...X.., then after Bob's move the string can turn into XX.X.., .XXX.. or ...XXX.\\n\\nWhoever is unable to make a move, loses. You have to determine who wins if they both play optimally.\\n\\nYou have to answer $q$ independent queries.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $q$ ($1 \\\\le q \\\\le 3 \\\\cdot 10^5$) — the number of queries.\\n\\nThe first line of each query contains two integers $a$ and $b$ ($1 \\\\le b < a \\\\le 3 \\\\cdot 10^5$).\\n\\nThe second line of each query contains the string $s$ ($1 \\\\le |s| \\\\le 3 \\\\cdot 10^5$), consisting of only characters . and X.\\n\\nIt is guaranteed that sum of all $|s|$ over all queries not exceed $3 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case print YES if Alice can win and NO otherwise.\\n\\nYou may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).\\n\\n\\n-----Example-----\\nInput\\n3\\n3 2\\nXX......XX...X\\n4 2\\nX...X.X..X\\n5 3\\n.......X..X\\n\\nOutput\\nYES\\nNO\\nYES\\n\\n\\n\\n-----Note-----\\n\\nIn the first query Alice can select substring $s_3 \\\\dots s_5$. After that $s$ turns into XXXXX...XX...X. After that, no matter what move Bob makes, Alice can make the move (this will be her second move), but Bob can't make his second move.\\n\\nIn the second query Alice can not win because she cannot even make one move.\\n\\nIn the third query Alice can choose substring $s_2 \\\\dots s_6$. After that $s$ turns into .XXXXX.X..X, and Bob can't make a move after that.\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nt = int(input())\\nfor _ in range(t):\\n  a,b = map(int,input().split())\\n  s = input()\\n  n = len(s)\\n  ls = []\\n  if s[0] == \\\".\\\":\\n    cnt = 1\\n  else:\\n    cnt = 0\\n  for i in range(1,n+1):\\n    if i < n and s[i] == \\\".\\\":\\n      cnt += 1\\n    else:\\n      if cnt >= b:\\n        ls.append(cnt)\\n      cnt = 0\\n  if not ls:\\n    print(\\\"NO\\\")\\n    continue\\n  ls.sort()\\n  if a >= 2*b:\\n    if len(ls) >= 2 or ls[0] > a+(b-1)*2 or ls[0] < a:\\n      print(\\\"NO\\\")\\n    else:\\n      print(\\\"YES\\\")\\n  else:\\n    if ls[0] < a:# or ls[-1] > a+(2*b-1)*2:\\n      print(\\\"NO\\\")\\n    elif len(ls) >= 2 and ls[-2] >= 2*b:\\n      print(\\\"NO\\\")\\n    else:\\n      l = len(ls)-1\\n      t = ls[-1]\\n      for i in range(t):\\n        if i+a <= t:\\n          p,q = i,t-(i+a)\\n          if not (b<=p<a or b<=q<a or p>=2*b or q>=2*b):\\n            x = l+(a<=p<2*b)+(a<=q<2*b)\\n            if x%2 == 0:\\n              print(\\\"YES\\\")\\n              break\\n      else:\\n        print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc150\\/tasks\\/abc150_d:\\nGiven are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.\\nLet a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \\\\leq k \\\\leq N):\\n - There exists a non-negative integer p such that X= a_k \\\\times (p+0.5).\\nFind the number of semi-common multiples of A among the integers between 1 and M (inclusive).\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq M \\\\leq 10^9\\n - 2 \\\\leq a_i \\\\leq 10^9\\n - a_i is an even number.\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M\\na_1 a_2 ... a_N\\n\\n-----Output-----\\nPrint the number of semi-common multiples of A among the integers between 1 and M (inclusive).\\n\\n-----Sample Input-----\\n2 50\\n6 10\\n\\n-----Sample Output-----\\n2\\n\\n - 15 = 6  \\\\times 2.5 \\n - 15 = 10 \\\\times 1.5 \\n - 45 = 6  \\\\times 7.5 \\n - 45 = 10 \\\\times 4.5 \\nThus, 15 and 45 are semi-common multiples of A. There are no other semi-common multiples of A between 1 and 50, so the answer is 2.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import gcd, ceil\\nn, m = list(map(int, input().split()))\\na = list(map(int, input().split()))\\na = [i \\/\\/ 2 for i in a]\\nl = 1\\nfor i in a:\\n    l *= i \\/\\/ gcd(l, i)\\nfor i in a:\\n    if l \\/\\/ i % 2 == 0:\\n        print((0))\\n        return\\n#print(ceil((m \\/\\/ l) \\/ 2))\\nprint(((m\\/\\/l+1)\\/\\/2))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/625\\/C:\\nPeople do many crazy things to stand out in a crowd. Some of them dance, some learn by heart rules of Russian language, some try to become an outstanding competitive programmers, while others collect funny math objects.\\n\\nAlis is among these collectors. Right now she wants to get one of k-special tables. In case you forget, the table n × n is called k-special if the following three conditions are satisfied:  every integer from 1 to n^2 appears in the table exactly once;  in each row numbers are situated in increasing order;  the sum of numbers in the k-th column is maximum possible. \\n\\nYour goal is to help Alice and find at least one k-special table of size n × n. Both rows and columns are numbered from 1 to n, with rows numbered from top to bottom and columns numbered from left to right.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers n and k (1 ≤ n ≤ 500, 1 ≤ k ≤ n) — the size of the table Alice is looking for and the column that should have maximum possible sum.\\n\\n\\n-----Output-----\\n\\nFirst print the sum of the integers in the k-th column of the required table.\\n\\nNext n lines should contain the description of the table itself: first line should contains n elements of the first row, second line should contain n elements of the second row and so on.\\n\\nIf there are multiple suitable table, you are allowed to print any.\\n\\n\\n-----Examples-----\\nInput\\n4 1\\n\\nOutput\\n28\\n1 2 3 4\\n5 6 7 8\\n9 10 11 12\\n13 14 15 16\\n\\nInput\\n5 3\\n\\nOutput\\n85\\n5 6 17 18 19\\n9 10 23 24 25\\n7 8 20 21 22\\n3 4 14 15 16\\n1 2 11 12 13\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"3\\n\\nn,k = [int(i) for i in input().split()]\\n\\ntotal_sum = n*n-(n-k)\\nfor row in range(1,n):\\n\\trow_right = n*n - (row)*(n-k+1)\\n\\tval = row_right - (n-k)\\n\\ttotal_sum += val\\n\\nprint(total_sum)\\n\\nnext_l_num = 1\\n\\nfor row in range(1,n+1):\\n\\trow_right = n*n - (row-1)*(n-k+1)\\n\\tnext_r_num = row_right - (n-k)\\n\\tfor col in range(1,n+1):\\n\\t\\tif col < k:\\n\\t\\t\\tprint(next_l_num, end=' ')\\n\\t\\t\\tnext_l_num += 1\\n\\t\\telse:\\n\\t\\t\\tprint(next_r_num, end=' ')\\n\\t\\t\\tnext_r_num += 1\\n\\n\\tprint()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA sequence of square brackets is regular if by inserting symbols \\\"+\\\" and \\\"1\\\" into it, you can get a regular mathematical expression from it. For example, sequences \\\"[[]][]\\\", \\\"[]\\\" and \\\"[[][[]]]\\\" — are regular, at the same time \\\"][\\\", \\\"[[]\\\" and \\\"[[]]][\\\" — are irregular. \\n\\nDraw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height — use symbols '+', '-' and '|'. For example, the sequence \\\"[[][]][]\\\" should be represented as: \\n\\n+-        -++- -+    \\n\\n|+- -++- -+||   |\\n\\n||   ||   |||   |\\n\\n|+- -++- -+||   |\\n\\n+-        -++- -+\\n\\n\\n\\nEach bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.\\n\\nBrackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height. \\n\\nThe enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.\\n\\nStudy carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique. \\n\\n\\n-----Input-----\\n\\nThe first line contains an even integer n (2 ≤ n ≤ 100) — the length of the sequence of brackets.\\n\\nThe second line contains the sequence of brackets — these are n symbols \\\"[\\\" and \\\"]\\\". It is guaranteed that the given sequence of brackets is regular. \\n\\n\\n-----Output-----\\n\\nPrint the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces. \\n\\n\\n-----Examples-----\\nInput\\n8\\n[[][]][]\\n\\nOutput\\n+-        -++- -+\\n|+- -++- -+||   |\\n||   ||   |||   |\\n|+- -++- -+||   |\\n+-        -++- -+\\n\\nInput\\n6\\n[[[]]]\\n\\nOutput\\n+-     -+\\n|+-   -+|\\n||+-...\",\"targets\":\"def draw(ind, type, size):\\n    nonlocal ans, mid\\n    ans[mid][ind] = '|'\\n    for i in range(size \\/\\/ 2):\\n        ans[mid + i][ind] = '|'\\n        ans[mid - i][ind] = '|'\\n    ans[mid + size \\/\\/ 2][ind] = '+'\\n    ans[mid - size \\/\\/ 2][ind] = '+'\\n    if type == \\\"left\\\":\\n        ans[mid + size \\/\\/ 2][ind - 1] = '-'\\n        ans[mid - size \\/\\/ 2][ind - 1] = '-'\\n    else:\\n        ans[mid + size \\/\\/ 2][ind + 1] = '-'\\n        ans[mid - size \\/\\/ 2][ind + 1] = '-'\\n\\n\\nn = int(input())\\ns = input()\\nmx = 0\\ncs = 0\\nfor i in range(n):\\n    if s[i] == \\\"[\\\":\\n        cs += 1\\n    else:\\n        cs -= 1\\n    mx = max(mx, cs)\\nmx -= 1\\na = [mx]\\nfor i in range(1, n):\\n    if (s[i] == \\\"[\\\" and s[i - 1] == \\\"]\\\") or (s[i - 1] == \\\"[\\\" and s[i] == \\\"]\\\"):\\n        a.append(a[-1])\\n    elif s[i] == \\\"[\\\":\\n        a.append(a[-1] - 1)\\n    else:\\n        a.append(a[-1] + 1)\\nans = [[' ' for i in range(n * 3)] for j in range(3 + mx * 2)]\\nmid = mx + 1\\ndraw(0, \\\"right\\\", mx * 2 + 3)\\nli = 0\\nfor i in range(1, n):\\n    if s[i] == \\\"[\\\" and s[i - 1] == \\\"]\\\":\\n        li += 1\\n        draw(li, \\\"right\\\", a[i] * 2 + 3)\\n    elif s[i - 1] == \\\"[\\\" and s[i] == \\\"]\\\":\\n        li += 4\\n        draw(li, \\\"left\\\", a[i] * 2 + 3)\\n    elif s[i] == \\\"[\\\":\\n        li += 1\\n        draw(li, \\\"right\\\", a[i] * 2 + 3)\\n    else:\\n        li += 1\\n        draw(li, \\\"left\\\", a[i] * 2 + 3)\\nfor i in ans:\\n    for j in range(li + 1):\\n        print(i[j], end=\\\"\\\")\\n    print()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/56530b444e831334c0000020:\\nThe male gametes or sperm cells in humans and other mammals are heterogametic and contain one of two types of sex chromosomes. They are either X or Y. The female gametes or eggs however, contain only the X sex chromosome and are homogametic.\\n\\nThe sperm cell determines the sex of an individual in this case. If a sperm cell containing an X chromosome fertilizes an egg, the resulting zygote will be XX or female. If the sperm cell contains a Y chromosome, then the resulting zygote will be XY or male.\\n\\nDetermine if the sex of the offspring will be male or female based on the X or Y chromosome present in the male's sperm.\\n\\nIf the sperm contains the X chromosome, return \\\"Congratulations! You're going to have a daughter.\\\";\\nIf the sperm contains the Y chromosome, return \\\"Congratulations! You're going to have a son.\\\";\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def chromosome_check(s):\\n    if s==\\\"XX\\\": return \\\"Congratulations! You\\\\'re going to have a daughter.\\\"\\n    if s==\\\"XY\\\":return \\\"Congratulations! You're going to have a son.\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc140\\/tasks\\/abc140_a:\\nTakahashi is going to set a 3-character password.\\nHow many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 9\\n - N is an integer.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\n\\n-----Output-----\\nPrint the number of possible passwords.\\n\\n-----Sample Input-----\\n2\\n\\n-----Sample Output-----\\n8\\n\\nThere are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"print(int(input())**3)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nJack and Jill are playing a game. They have balls numbered from `0` to `n - 1`. Jack looks the other way and asks Jill to reverse the position of the balls, for instance, to change the order from say, `0,1,2,3` to `3,2,1,0`. He further asks Jill to reverse the position of the balls `n` times, each time starting from one position further to the right, till she reaches the last ball. So, Jill has to reverse the positions of the ball starting from position `0`, then from position `1`, then from position `2` and so on. At the end of the game, Jill will ask Jack to guess the final position of any ball numbered `k`. \\n\\nYou will be given `2` integers, the first will be `n`(balls numbered from `0` to `n-1`) and the second will be `k`. You will return the position of the ball numbered `k` after the rearrangement.\\n\\n```Perl\\nsolve(4,1) = 3. The reversals are [0,1,2,3] -> [3,2,1,0] -> [3,0,1,2] -> [3,0,2,1]. => 1 is in position 3.\\n```\\n\\nMore examples in the test cases. Good luck!\",\"targets\":\"def solve(n, k):\\n    second_half = k >= n \\/\\/ 2\\n    return (-1)**second_half * 2 * k + second_half * (n * 2 - 3) + 1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nNastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.\\n\\nTwo matrices $A$ and $B$ are given, each of them has size $n \\\\times m$. Nastya can perform the following operation to matrix $A$ unlimited number of times:   take any square square submatrix of $A$ and transpose it (i.e. the element of the submatrix which was in the $i$-th row and $j$-th column of the submatrix will be in the $j$-th row and $i$-th column after transposing, and the transposed submatrix itself will keep its place in the matrix $A$). \\n\\nNastya's task is to check whether it is possible to transform the matrix $A$ to the matrix $B$.\\n\\n $\\\\left. \\\\begin{array}{|c|c|c|c|c|c|c|c|} \\\\hline 6 & {3} & {2} & {11} \\\\\\\\ \\\\hline 5 & {9} & {4} & {2} \\\\\\\\ \\\\hline 3 & {3} & {3} & {3} \\\\\\\\ \\\\hline 4 & {8} & {2} & {2} \\\\\\\\ \\\\hline 7 & {8} & {6} & {4} \\\\\\\\ \\\\hline \\\\end{array} \\\\right.$ Example of the operation \\n\\nAs it may require a lot of operations, you are asked to answer this question for Nastya.\\n\\nA square submatrix of matrix $M$ is a matrix which consist of all elements which comes from one of the rows with indeces $x, x+1, \\\\dots, x+k-1$ of matrix $M$ and comes from one of the columns with indeces $y, y+1, \\\\dots, y+k-1$ of matrix $M$. $k$ is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $m$ separated by space ($1 \\\\leq n, m \\\\leq 500$) — the numbers of rows and columns in $A$ and $B$ respectively.\\n\\nEach of the next $n$ lines contains $m$ integers, the $j$-th number in the $i$-th of these lines denotes the $j$-th element of the $i$-th row of the matrix $A$ ($1 \\\\leq A_{ij} \\\\leq 10^{9}$).\\n\\nEach of the next $n$ lines contains $m$ integers, the $j$-th number in the $i$-th of these lines denotes the $j$-th element of the $i$-th row of the matrix $B$ ($1 \\\\leq B_{ij} \\\\leq 10^{9}$).\\n\\n\\n-----Output-----\\n\\nPrint \\\"YES\\\" (without quotes) if it is...\",\"targets\":\"n,m=list(map(int,input().split()))\\narr1=[]\\nfor i in range(n):\\n\\ttemp=list(map(int,input().split()))\\n\\tarr1.append(temp)\\narr2=[]\\nfor i in range(n):\\n\\ttemp=list(map(int,input().split()))\\n\\tarr2.append(temp)\\n\\nflag=0\\nfor i in range(n):\\n\\ttemparr1=[]\\n\\ttemparr2=[]\\n\\tindexi=i\\n\\tindexj=0\\n\\twhile(indexi>=0 and indexj<m):\\n\\t\\ttemparr1.append(arr1[indexi][indexj])\\n\\t\\ttemparr2.append(arr2[indexi][indexj])\\n\\t\\tindexi-=1\\n\\t\\tindexj+=1\\n\\ttemparr1.sort()\\n\\ttemparr2.sort()\\n\\t#print(*temparr1)\\n\\t#print(*temparr2)\\n\\tfor j in range(len(temparr1)):\\n\\t\\tif(temparr1[j]!=temparr2[j]):\\n\\t\\t\\tflag=1\\n\\t\\t\\tbreak\\nif(flag==1):\\n\\tprint('NO')\\nelse:\\n\\tfor i in range(1,m):\\n\\t\\ttemparr1=[]\\n\\t\\ttemparr2=[]\\n\\t\\tindexi=n-1\\n\\t\\tindexj=i\\n\\t\\twhile(indexi>=0 and indexj<m):\\n\\t\\t\\ttemparr1.append(arr1[indexi][indexj])\\n\\t\\t\\ttemparr2.append(arr2[indexi][indexj])\\n\\t\\t\\tindexi-=1\\n\\t\\t\\tindexj+=1\\n\\t\\ttemparr1.sort()\\n\\t\\ttemparr2.sort()\\n\\t\\t#print(*temparr1)\\n\\t\\tfor j in range(len(temparr1)):\\n\\t\\t\\tif(temparr1[j]!=temparr2[j]):\\n\\t\\t\\t\\tflag=1\\n\\t\\t\\t\\tbreak\\n\\tif(flag==0):\\n\\t\\tprint('YES')\\n\\telse:\\n\\t\\tprint('NO')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nDZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number x_{i}, DZY will put it into the bucket numbered h(x_{i}), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.\\n\\nHowever, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a \\\"conflict\\\" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer x_{i} (0 ≤ x_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nOutput a single integer — the answer to the problem.\\n\\n\\n-----Examples-----\\nInput\\n10 5\\n0\\n21\\n53\\n41\\n53\\n\\nOutput\\n4\\n\\nInput\\n5 5\\n0\\n1\\n2\\n3\\n4\\n\\nOutput\\n-1\",\"targets\":\"def main():\\n    p, n = [int(i) for i in input().split()]\\n    \\n    d = [0 for i in range(p)]\\n    \\n    for i in range(n):\\n        x = int(input()) % p\\n        if d[x]:\\n            print(i + 1)\\n            return\\n        d[x] = 1\\n    \\n    print(-1)\\n\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/725\\/A:\\nIn a new version of the famous Pinball game, one of the most important parts of the game field is a sequence of n bumpers. The bumpers are numbered with integers from 1 to n from left to right. There are two types of bumpers. They are denoted by the characters '<' and '>'. When the ball hits the bumper at position i it goes one position to the right (to the position i + 1) if the type of this bumper is '>', or one position to the left (to i - 1) if the type of the bumper at position i is '<'. If there is no such position, in other words if i - 1 < 1 or i + 1 > n, the ball falls from the game field.\\n\\nDepending on the ball's starting position, the ball may eventually fall from the game field or it may stay there forever. You are given a string representing the bumpers' types. Calculate the number of positions such that the ball will eventually fall from the game field if it starts at that position.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the length of the sequence of bumpers. The second line contains the string, which consists of the characters '<' and '>'. The character at the i-th position of this string corresponds to the type of the i-th bumper.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the number of positions in the sequence such that the ball will eventually fall from the game field if it starts at that position.\\n\\n\\n-----Examples-----\\nInput\\n4\\n<<><\\n\\nOutput\\n2\\nInput\\n5\\n>>>>>\\n\\nOutput\\n5\\nInput\\n4\\n>><<\\n\\nOutput\\n0\\n\\n\\n-----Note-----\\n\\nIn the first sample, the ball will fall from the field if starts at position 1 or position 2.\\n\\nIn the second sample, any starting position will result in the ball falling from the field.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\nl = input()\\nans = 0\\nfor i in range(n):\\n    if l[i] == '<':\\n        ans += 1\\n    else:\\n        break\\nfor i in range(n - 1, -1, -1):\\n    if l[i] == '>':\\n        ans += 1\\n    else:\\n        break\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIf you like Taco Bell, you will be familiar with their signature doritos locos taco. They're very good.\\n\\n\\nWhy can't everything be a taco? We're going to attempt that here, turning every word we find into the taco bell recipe with each ingredient.\\n\\n\\nWe want to input a word as a string, and return a list representing that word as a taco.\\n\\n***Key***\\n\\nall vowels (except 'y') = beef\\n\\nt = tomato\\n\\nl = lettuce\\n\\nc = cheese\\n\\ng = guacamole\\n\\ns = salsa\\n\\n  \\n***NOTE***    \\nWe do not care about case here. 'S' is therefore equivalent to 's' in our taco.\\n  \\nIgnore all other letters; we don't want our taco uneccesarily clustered or else it will be too difficult to eat.\\n\\nNote that no matter what ingredients are passed, our taco will always have a shell.\",\"targets\":\"def tacofy(word):\\n    ingred = {\\n        'a':'beef', 'u':'beef', 'i':'beef', 'o':'beef', 'e':'beef',\\n        't':'tomato', 'c':'cheese', 'l':'lettuce', 'g':'guacamole', 's':'salsa'\\n    }\\n    return ['shell'] + [ingred[c] for c in word.lower() if c in ingred] + ['shell']\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPetya has n positive integers a_1, a_2, ..., a_{n}. \\n\\nHis friend Vasya decided to joke and replaced all digits in Petya's numbers with a letters. He used the lowercase letters of the Latin alphabet from 'a' to 'j' and replaced all digits 0 with one letter, all digits 1 with another letter and so on. For any two different digits Vasya used distinct letters from 'a' to 'j'.\\n\\nYour task is to restore Petya's numbers. The restored numbers should be positive integers without leading zeros. Since there can be multiple ways to do it, determine the minimum possible sum of all Petya's numbers after the restoration. It is guaranteed that before Vasya's joke all Petya's numbers did not have leading zeros.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 1 000) — the number of Petya's numbers.\\n\\nEach of the following lines contains non-empty string s_{i} consisting of lowercase Latin letters from 'a' to 'j' — the Petya's numbers after Vasya's joke. The length of each string does not exceed six characters.\\n\\n\\n-----Output-----\\n\\nDetermine the minimum sum of all Petya's numbers after the restoration. The restored numbers should be positive integers without leading zeros. It is guaranteed that the correct restore (without leading zeros) exists for all given tests.\\n\\n\\n-----Examples-----\\nInput\\n3\\nab\\nde\\naj\\n\\nOutput\\n47\\n\\nInput\\n5\\nabcdef\\nghij\\nbdef\\naccbd\\ng\\n\\nOutput\\n136542\\n\\nInput\\n3\\naa\\njj\\naa\\n\\nOutput\\n44\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, you need to replace the letter 'a' with the digit 1, the letter 'b' with the digit 0, the letter 'd' with the digit 2, the letter 'e' with the digit 3, and the letter 'j' with the digit 4. So after the restoration numbers will look like [10, 23, 14]. The sum of them is equal to 47, which is the minimum possible sum of the numbers after the correct restoration.\\n\\nIn the second example the numbers after the restoration can look like: [120468, 3579, 2468, 10024, 3]. \\n\\nIn the second example the numbers after the restoration can look like: [11, 22, 11].\",\"targets\":\"import math\\nimport operator\\nnum = int(input())\\ntotal = 0\\nstore = {}\\nnonzero = []\\n_max = 0\\nfor i in range(num):\\n    _in = input()\\n    if _max < len(_in):\\n    \\t_max = len(_in)\\n    if _in[0] not in nonzero:\\n    \\tnonzero.append(_in[0])\\n    for j in range(len(_in)-1,-1,-1):\\n    \\tif _in[j] in store:\\n    \\t\\tstore[_in[j]] += pow(10,len(_in)-j-1)\\n    \\telse:\\n    \\t\\tstore[_in[j]] = pow(10,len(_in)-j-1)\\nx = store\\nsorted_x = sorted(x.items(), key=operator.itemgetter(1))\\n\\nused = False\\ncur = 1\\nfor i in range(len(sorted_x)-1,-1,-1):\\n\\tif sorted_x[i][0] not in nonzero and used == False:\\n\\t\\tused = True\\n\\telse:\\n\\t\\ttotal += sorted_x[i][1] * cur\\n\\t\\tcur += 1\\nprint(total)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1190\\/A:\\nRecently, Tokitsukaze found an interesting game. Tokitsukaze had $n$ items at the beginning of this game. However, she thought there were too many items, so now she wants to discard $m$ ($1 \\\\le m \\\\le n$) special items of them.\\n\\nThese $n$ items are marked with indices from $1$ to $n$. In the beginning, the item with index $i$ is placed on the $i$-th position. Items are divided into several pages orderly, such that each page contains exactly $k$ positions and the last positions on the last page may be left empty.\\n\\nTokitsukaze would do the following operation: focus on the first special page that contains at least one special item, and at one time, Tokitsukaze would discard all special items on this page. After an item is discarded or moved, its old position would be empty, and then the item below it, if exists, would move up to this empty position. The movement may bring many items forward and even into previous pages, so Tokitsukaze would keep waiting until all the items stop moving, and then do the operation (i.e. check the special page and discard the special items) repeatedly until there is no item need to be discarded.\\n\\n [Image] Consider the first example from the statement: $n=10$, $m=4$, $k=5$, $p=[3, 5, 7, 10]$. The are two pages. Initially, the first page is special (since it is the first page containing a special item). So Tokitsukaze discards the special items with indices $3$ and $5$. After, the first page remains to be special. It contains $[1, 2, 4, 6, 7]$, Tokitsukaze discards the special item with index $7$. After, the second page is special (since it is the first page containing a special item). It contains $[9, 10]$, Tokitsukaze discards the special item with index $10$. \\n\\nTokitsukaze wants to know the number of operations she would do in total.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers $n$, $m$ and $k$ ($1 \\\\le n \\\\le 10^{18}$, $1 \\\\le m \\\\le 10^5$, $1 \\\\le m, k \\\\le n$) — the number of items, the number of special items to be discarded and the number of positions in each page.\\n\\nThe...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"R = lambda :list(map(int,input().split()))\\nn,m,k = R()\\nl = R()\\n\\nq = 0\\nt = 1\\nnb = 0\\nfor i in range(m-1) :\\n\\tif ((l[i+1]-1-q)\\/\\/k) == ( ( (l[i]-1-q)\\/\\/k)) :\\n\\t\\tt += 1\\n\\t\\tpass\\n\\telse :\\n\\t\\tnb +=1\\n\\t\\tq += t\\n\\t\\tt = 1\\n\\nprint(nb+1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/596d34df24a04ee1e3000a25:\\nGiven two numbers: 'left' and 'right' (1 <= 'left' <= 'right' <= 200000000000000)\\nreturn sum of all '1' occurencies in binary representations of numbers between 'left' and 'right' (including both)\\n\\n``` \\nExample:\\ncountOnes 4 7 should return 8, because:\\n4(dec) = 100(bin), which adds 1 to the result.\\n5(dec) = 101(bin), which adds 2 to the result.\\n6(dec) = 110(bin), which adds 2 to the result.\\n7(dec) = 111(bin), which adds 3 to the result.\\nSo finally result equals 8.\\n```\\nWARNING: Segment may contain billion elements, to pass this kata, your solution cannot iterate through all numbers in the segment!\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def countOnesFromZero(num):\\n    l = sorted([i for i, v in enumerate(bin(num)[2:][::-1]) if v == '1'], reverse=True)\\n    l.append(0)\\n    return sum(i * 2**v + v * 2**(v-1) for i, v in enumerate(l))\\n\\ndef countOnes(left, right):\\n    # Your code here!\\n    return countOnesFromZero(right) - countOnesFromZero(left) + bin(left).count('1')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n$Riggi$   is a spy of $KBI$ and he is on a secret mission, he is spying an Underworld Don  $Anit$.\\n$Riggi$  is spying him since 5 years and he is not able to find  any evidence against $Anit$. \\n$KBI$ told $Riggi$ they will send him a code string in a special format that will inform him whether he  has continue or return back from mission.\\nAccording to $KBI$  firstly  he  has to find what is the original string and then he has to check string is palindrome or not .\\nIf its a palindrome then he has to leave the mission and return back else continue spying $Anit$. \\nRules to find original string :\\n1:-If in Code string any integer(N) followed by a string of alphabets that starts with '+' and  ends with '-' then he has to repeat that string N times  , like 3+acg- = acgacgacg.\\n2:-If there is no integer present before string then print the string is repeated 1 time.\\nlike bc=bc.\\nExample of conversion from  Code string  to original string  : 2+ac-3+kb-j=acackbkbkbj  \\n\\n-----Input:-----\\n- Code string $S$ is taken as input  .\\n\\n-----Output:-----\\n- Print  string $Continue$ if code string $S$ is not a palindrome else print $Return$ .\\n\\n-----Constraints-----\\n- $1 \\\\leq S \\\\leq 1000$\\n- $1 \\\\leq N \\\\leq 1000$\\n\\n-----Sample Input 1:-----\\n3+xy-bb3+yx-\\n\\n-----Sample Output 1:-----\\nReturn\\n\\n-----Sample Input 2:-----\\n3+xy-bb3+xy-\\n\\n-----Sample Output 2:-----\\nContinue\\n\\n-----EXPLANATION:-----\\nSample 1:- original string will be xyxyxybbyxyxyx which is  a palindrome hence print $Return$.\\nSample 2:- original string will be xyxyxybbxyxyxy which is not a palindrome hence print \\n$Continue$.\",\"targets\":\"# cook your dish here\\ns=input().rstrip()\\ni=0\\nfinal=''\\nwhile i<len(s):\\n    if s[i].isdigit():\\n        val=int(s[i])\\n        s1=''\\n        while s[i]!='-':\\n            if s[i].isalpha():\\n                s1+=s[i]\\n            i+=1\\n        i+=1\\n        final+=s1*val\\n    else:\\n        s1=''\\n        while s[i].isalpha():\\n            s1+=s[i]\\n            i+=1\\n            if i>=len(s):\\n                break\\n        final+=s1\\n#print(final)\\nfinal=list(final)\\ntemp=final[::-1]\\n#print(temp,final)\\nif final==temp:\\n    print('Return')\\nelse:\\n    print('Continue')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nStriver$Striver$ wants to strive hard in order to reach his goals, hence asks his mentor to give him a question for which he has to strive hard. \\nThe mentor gives Striver$Striver$ a N$N$ X N$N$ matrix consisting of lowercase characters (′a′$'a'$ to ′z′$'z'$) and Q$Q$ queries. Every query consists of X$X$ and Y$Y$. From any position in the matrix, one can either move towards the right or towards down. He asks striver to write down all the paths from (1,1)$(1, 1)$ to (X,Y)$(X, Y)$ and find out which string has the maximum number of character ′a′$'a'$ in it and answer him the number of characters which are not 'a' in that string. \\nStriver wants to strive hard but also wants to impress his mentor. He asks for your help to answer Q$Q$ queries given by his mentor as fast as he can so that he can impress his mentor also. Can you help him to answer the Q queries?\\n\\n-----Input:-----\\n- First line will contain T$T$, number of test cases. Then the test cases follow. \\n- First line of every test case contains a number N$N$ and Q$Q$ which denotes the dimensions of the matrix and number of queries respectively.  \\n- N lines follow, which contains N numbers each denoting the elements of the matrix. \\n- Q line follow, every line contains X and Y. \\n\\n-----Output:-----\\nFor every test case, print a single integer which prints the answer to mentor's every query. \\n\\n-----Constraints-----\\n- 1≤T≤10$1 \\\\leq T \\\\leq 10$\\n- 1≤N≤103$1 \\\\leq N \\\\leq 10^3$\\n- 1≤Q≤105$1 \\\\leq Q \\\\leq 10^5$\\n- 1≤X,Y≤N$1 \\\\leq X, Y \\\\leq N$\\n\\n-----Sample Input:-----\\n1\\n3 2 \\na b a \\na c d \\nb a b\\n1 3\\n3 3 \\n\\n-----Sample Output:-----\\n1 \\n2\\n\\n-----EXPLANATION:-----\\nQuery-1: There is only one path from (1,1) to (1,3) i.e.,\\\"aba\\\" and the number of characters which are not 'a' is 1. \\nQuery-2:  The path which has the maximum number of 'a' in it is \\\"aabab\\\", hence non 'a' characters are 2.\",\"targets\":\"t=int(input())\\r\\nfor _ in range(t):\\r\\n    n,q=list(map(int,input().split()))\\r\\n    main=[[0]*(n+1)]\\r\\n    final=[[0]*(n+1)]\\r\\n    const=[[0]*(n+1)]\\r\\n    for i in range(n):\\r\\n        l=[0]*(n+1)\\r\\n        z=[0]*(n+1)\\r\\n        w=list(input().split())\\r\\n        w.insert(0,0)\\r\\n        final.append(w)\\r\\n        main.append(l)\\r\\n        const.append(z)\\r\\n\\r\\n    for i in range(1,n+1):\\r\\n        for j in range(1,n+1):\\r\\n            \\r\\n            main[i][j]=max(main[i-1][j],main[i][j-1])\\r\\n            if final[i][j]=='a':\\r\\n                main[i][j]+=1\\r\\n            if main[i-1][j]>main[i][j-1]:\\r\\n                const[i][j]+=const[i-1][j]\\r\\n            else:\\r\\n                const[i][j]+=const[i][j-1]\\r\\n            if final[i][j]!='a':\\r\\n                const[i][j]+=1\\r\\n                \\r\\n                \\r\\n            \\r\\n    for i in range(q):\\r\\n        s,d=list(map(int,input().split()))\\r\\n        print(s+d-1-main[s][d])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/291\\/A:\\nPolycarpus is the director of a large corporation. There are n secretaries working for the corporation, each of them corresponds via the famous Spyke VoIP system during the day. We know that when two people call each other via Spyke, the Spyke network assigns a unique ID to this call, a positive integer session number.\\n\\nOne day Polycarpus wondered which secretaries are talking via the Spyke and which are not. For each secretary, he wrote out either the session number of his call or a 0 if this secretary wasn't talking via Spyke at that moment.\\n\\nHelp Polycarpus analyze these data and find out the number of pairs of secretaries that are talking. If Polycarpus has made a mistake in the data and the described situation could not have taken place, say so.\\n\\nNote that the secretaries can correspond via Spyke not only with each other, but also with the people from other places. Also, Spyke conferences aren't permitted — that is, one call connects exactly two people.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 ≤ n ≤ 10^3) — the number of secretaries in Polycarpus's corporation. The next line contains n space-separated integers: id_1, id_2, ..., id_{n} (0 ≤ id_{i} ≤ 10^9). Number id_{i} equals the number of the call session of the i-th secretary, if the secretary is talking via Spyke, or zero otherwise.\\n\\nConsider the secretaries indexed from 1 to n in some way.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the number of pairs of chatting secretaries, or -1 if Polycarpus's got a mistake in his records and the described situation could not have taken place.\\n\\n\\n-----Examples-----\\nInput\\n6\\n0 1 7 1 7 10\\n\\nOutput\\n2\\n\\nInput\\n3\\n1 1 1\\n\\nOutput\\n-1\\n\\nInput\\n1\\n0\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first test sample there are two Spyke calls between secretaries: secretary 2 and secretary 4, secretary 3 and secretary 5.\\n\\nIn the second test sample the described situation is impossible as conferences aren't allowed.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\nd = list(map(int, input().split()))\\ncalls = dict()\\ninvalid = False\\nc = 0\\nfor i in range(n):\\n    if d[i] > 0:\\n        if d[i] in calls.keys() : calls[d[i]] += 1\\n        else : calls[d[i]] = 1\\n        if calls[d[i]] == 2:\\n           c += 1\\n        elif calls[d[i]] == 3:\\n            invalid = True\\n            break\\n        \\nif invalid: print(-1)\\nelse: print(c)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nRecently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows you to set a program of switching its state (states are \\\"lights on\\\" and \\\"lights off\\\"). Unfortunately, some program is already installed into the lamp.\\n\\nThe lamp allows only good programs. Good program can be represented as a non-empty array $a$, where $0 < a_1 < a_2 < \\\\dots < a_{|a|} < M$. All $a_i$ must be integers. Of course, preinstalled program is a good program.\\n\\nThe lamp follows program $a$ in next manner: at moment $0$ turns power and light on. Then at moment $a_i$ the lamp flips its state to opposite (if it was lit, it turns off, and vice versa). The state of the lamp flips instantly: for example, if you turn the light off at moment $1$ and then do nothing, the total time when the lamp is lit will be $1$. Finally, at moment $M$ the lamp is turning its power off regardless of its state.\\n\\nSince you are not among those people who read instructions, and you don't understand the language it's written in, you realize (after some testing) the only possible way to alter the preinstalled program. You can insert at most one element into the program $a$, so it still should be a good program after alteration. Insertion can be done between any pair of consecutive elements of $a$, or even at the begining or at the end of $a$.\\n\\nFind such a way to alter the program that the total time when the lamp is lit is maximum possible. Maybe you should leave program untouched. If the lamp is lit from $x$ till moment $y$, then its lit for $y - x$ units of time. Segments of time when the lamp is lit are summed up.\\n\\n\\n-----Input-----\\n\\nFirst line contains two space separated integers $n$ and $M$ ($1 \\\\le n \\\\le 10^5$, $2 \\\\le M \\\\le 10^9$) — the length of program $a$ and the moment when power turns off.\\n\\nSecond line contains $n$ space separated integers $a_1, a_2, \\\\dots, a_n$ ($0 < a_1 < a_2 < \\\\dots < a_n < M$) —...\",\"targets\":\"def main():\\n    n, M = [int(i) for i in input().split(' ')]\\n    a = [0] + [int(i) for i in input().split(' ')] + [M]\\n\\n    n = n + 2\\n    incr_sum =  []\\n    s = 0\\n    for i in range(n):\\n        if i % 2 == 1:\\n            s += a[i] - a[i-1]\\n        incr_sum.append(s)\\n\\n    max_sum = s\\n    for i in range(n-1):\\n        if a[i+1] - a[i] != 1:\\n            to_add = a[i+1] - 1 # added in pos between i and i+1\\n\\n            s_ = incr_sum[i]\\n            s_ += to_add - a[i]\\n            s_ += (a[-1] - a[i+1]) - (incr_sum[-1] - incr_sum[i+1])\\n\\n            if s_ > max_sum:\\n                max_sum = s_\\n\\n    print(max_sum)\\n    \\ndef __starting_point():\\n    main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLimak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be n problems, sorted by difficulty, i.e. problem 1 is the easiest and problem n is the hardest. Limak knows it will take him 5·i minutes to solve the i-th problem.\\n\\nLimak's friends organize a New Year's Eve party and Limak wants to be there at midnight or earlier. He needs k minutes to get there from his house, where he will participate in the contest first.\\n\\nHow many problems can Limak solve if he wants to make it to the party?\\n\\n\\n-----Input-----\\n\\nThe only line of the input contains two integers n and k (1 ≤ n ≤ 10, 1 ≤ k ≤ 240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house.\\n\\n\\n-----Output-----\\n\\nPrint one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier.\\n\\n\\n-----Examples-----\\nInput\\n3 222\\n\\nOutput\\n2\\n\\nInput\\n4 190\\n\\nOutput\\n4\\n\\nInput\\n7 1\\n\\nOutput\\n7\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenario Limak would solve 2 problems. He doesn't have enough time to solve 3 problems so the answer is 2.\\n\\nIn the second sample, Limak can solve all 4 problems in 5 + 10 + 15 + 20 = 50 minutes. At 20:50 he will leave the house and go to the party. He will get there exactly at midnight.\\n\\nIn the third sample, Limak needs only 1 minute to get to the party. He has enough time to solve all 7 problems.\",\"targets\":\"n, m = map(int, input().split())\\nl = 240 - m\\nss = []\\nx = [i * 5 + 5 for i in range(n)]\\nfor i in range(n + 1):\\n    if (sum(x[:i]) <= l):\\n        ss.append(i)\\nprint(max(ss))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/558\\/D:\\nAmr bought a new video game \\\"Guess Your Way Out! II\\\". The goal of the game is to find an exit from the maze that looks like a perfect binary tree of height h. The player is initially standing at the root of the tree and the exit from the tree is located at some leaf node.\\n\\nLet's index all the nodes of the tree such that   The root is number 1  Each internal node i (i ≤ 2^{h} - 1 - 1) will have a left child with index = 2i and a right child with index = 2i + 1 \\n\\nThe level of a node is defined as 1 for a root, or 1 + level of parent of the node otherwise. The vertices of the level h are called leaves. The exit to the maze is located at some leaf node n, the player doesn't know where the exit is so he has to guess his way out! \\n\\nIn the new version of the game the player is allowed to ask questions on the format \\\"Does the ancestor(exit, i) node number belong to the range [L, R]?\\\". Here ancestor(v, i) is the ancestor of a node v that located in the level i. The game will answer with \\\"Yes\\\" or \\\"No\\\" only. The game is designed such that it doesn't always answer correctly, and sometimes it cheats to confuse the player!.\\n\\nAmr asked a lot of questions and got confused by all these answers, so he asked you to help him. Given the questions and its answers, can you identify whether the game is telling contradictory information or not? If the information is not contradictory and the exit node can be determined uniquely, output its number. If the information is not contradictory, but the exit node isn't defined uniquely, output that the number of questions is not sufficient. Otherwise output that the information is contradictory.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers h, q (1 ≤ h ≤ 50, 0 ≤ q ≤ 10^5), the height of the tree and the number of questions respectively.\\n\\nThe next q lines will contain four integers each i, L, R, ans (1 ≤ i ≤ h, 2^{i} - 1 ≤ L ≤ R ≤ 2^{i} - 1, $\\\\text{ans} \\\\in \\\\{0,1 \\\\}$), representing a question as described in the statement with its answer (ans = 1 if the answer is \\\"Yes\\\" and ans = 0...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"h,q=list(map(int,input().split()))\\nd=[(2**h,0),(2**(h-1),0)]\\nfor _ in range(q):\\n\\ti,l,r,a=list(map(int,input().split()))\\n\\tl,r=l*2**(h-i),(r+1)*2**(h-i)\\n\\td.extend([[(l,1),(r,-1)],[(0,1),(l,-1),(r,1)]][a])\\ns=0\\nl=0\\nd=sorted(d)\\nfor (a,x),(b,_) in zip(d,d[1:]):\\n\\ts+=x\\n\\tif a!=b and s==0:q=a;l+=b-a\\nprint((\\\"Game cheated!\\\",q,\\\"Data not sufficient!\\\")[min(l,2)])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAn elementary school student Takahashi has come to a variety store.\\nHe has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?\\nNote that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.\\n\\n-----Constraints-----\\n - All input values are integers.\\n - 1 \\\\leq A, B \\\\leq 500\\n - 1 \\\\leq C \\\\leq 1000\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B C\\n\\n-----Output-----\\nIf Takahashi can buy the toy, print Yes; if he cannot, print No.\\n\\n-----Sample Input-----\\n50 100 120\\n\\n-----Sample Output-----\\nYes\\n\\nHe has 50 + 100 = 150 yen, so he can buy the 120-yen toy.\",\"targets\":\"a, b, c = map(int, input().split())\\nprint('Yes' if a + b >= c else 'No')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLet's denote a m-free matrix as a binary (that is, consisting of only 1's and 0's) matrix such that every square submatrix of size m × m of this matrix contains at least one zero. \\n\\nConsider the following problem:\\n\\nYou are given two integers n and m. You have to construct an m-free square matrix of size n × n such that the number of 1's in this matrix is maximum possible. Print the maximum possible number of 1's in such matrix.\\n\\nYou don't have to solve this problem. Instead, you have to construct a few tests for it.\\n\\nYou will be given t numbers x_1, x_2, ..., x_{t}. For every $i \\\\in [ 1, t ]$, find two integers n_{i} and m_{i} (n_{i} ≥ m_{i}) such that the answer for the aforementioned problem is exactly x_{i} if we set n = n_{i} and m = m_{i}.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer t (1 ≤ t ≤ 100) — the number of tests you have to construct.\\n\\nThen t lines follow, i-th line containing one integer x_{i} (0 ≤ x_{i} ≤ 10^9).\\n\\nNote that in hacks you have to set t = 1.\\n\\n\\n-----Output-----\\n\\nFor each test you have to construct, output two positive numbers n_{i} and m_{i} (1 ≤ m_{i} ≤ n_{i} ≤ 10^9) such that the maximum number of 1's in a m_{i}-free n_{i} × n_{i} matrix is exactly x_{i}. If there are multiple solutions, you may output any of them; and if this is impossible to construct a test, output a single integer  - 1. \\n\\n\\n-----Example-----\\nInput\\n3\\n21\\n0\\n1\\n\\nOutput\\n5 2\\n1 1\\n-1\",\"targets\":\"n = int(input())\\nfor x in range(n):\\n    x = int(input())\\n    if x == 0:\\n        print(1, 1)\\n    else:\\n        flag = True\\n        for d in range(1, int(x**0.5)+2):\\n            if x % d == 0:\\n                s = x \\/\\/ d\\n                n = (s + d)\\/\\/2\\n                if int(n) != n:\\n                    continue\\n                nm = s - n\\n                if nm <= 0:\\n                    continue\\n                m = n\\/\\/nm\\n                if (m>0) and (n**2 - (n\\/\\/m)**2 == x):\\n                    print(n, m)\\n                    flag = False\\n                    break\\n        if flag:\\n            print(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/escape-a-large-maze\\/:\\nIn a 1 million by 1 million grid, the coordinates of each grid square are (x, y) with 0 <= x, y < 10^6.\\nWe start at the source square and want to reach the target square.  Each move, we can walk to a 4-directionally adjacent square in the grid that isn't in the given list of blocked squares.\\nReturn true if and only if it is possible to reach the target square through a sequence of moves.\\n \\nExample 1:\\nInput: blocked = [[0,1],[1,0]], source = [0,0], target = [0,2]\\nOutput: false\\nExplanation: \\nThe target square is inaccessible starting from the source square, because we can't walk outside the grid.\\n\\nExample 2:\\nInput: blocked = [], source = [0,0], target = [999999,999999]\\nOutput: true\\nExplanation: \\nBecause there are no blocked cells, it's possible to reach the target square.\\n\\n \\nNote:\\n\\n0 <= blocked.length <= 200\\nblocked[i].length == 2\\n0 <= blocked[i][j] < 10^6\\nsource.length == target.length == 2\\n0 <= source[i][j], target[i][j] < 10^6\\nsource != target\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def isEscapePossible(self, blocked: List[List[int]], source: List[int], target: List[int]) -> bool:\\n        blocked = {tuple(i) for i in blocked}\\n        def bfs(source,target):\\n            que = [source]\\n            seen = {tuple(source)}\\n            for x,y in que:\\n                for i,j in [(0,1),(1,0),(-1,0),(0,-1)]:\\n                    m,n = x+i,y+j\\n                    if 0<=m<10**6 and 0<=n<10**6 and (m,n) not in seen and (m,n) not in blocked:\\n                        if m == target[0] and n==target[1]:\\n                            return True\\n                        que.append((m,n))\\n                        seen.add((m,n))\\n                    if len(que)>=20000:\\n                        return True\\n            return False\\n        return bfs(source,target) and bfs(target,source)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAs you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are n planes on Earth, numbered from 1 to n, and the plane with number i likes the plane with number f_{i}, where 1 ≤ f_{i} ≤ n and f_{i} ≠ i.\\n\\nWe call a love triangle a situation in which plane A likes plane B, plane B likes plane C and plane C likes plane A. Find out if there is any love triangle on Earth.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (2 ≤ n ≤ 5000) — the number of planes.\\n\\nThe second line contains n integers f_1, f_2, ..., f_{n} (1 ≤ f_{i} ≤ n, f_{i} ≠ i), meaning that the i-th plane likes the f_{i}-th.\\n\\n\\n-----Output-----\\n\\nOutput «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».\\n\\nYou can output any letter in lower case or in upper case.\\n\\n\\n-----Examples-----\\nInput\\n5\\n2 4 5 1 3\\n\\nOutput\\nYES\\n\\nInput\\n5\\n5 5 5 5 1\\n\\nOutput\\nNO\\n\\n\\n\\n-----Note-----\\n\\nIn first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.\\n\\nIn second example there are no love triangles.\",\"targets\":\"n = int(input())\\na = [int(z) for z in input().split()]\\na = [0] + a\\nfor i in range(1, n):\\n    if (a[a[a[i]]] == i):\\n        print(\\\"YES\\\")\\n        return\\nprint(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/757\\/C:\\nIt's that time of the year, Felicity is around the corner and you can see people celebrating all around the Himalayan region. The Himalayan region has n gyms. The i-th gym has g_{i} Pokemon in it. There are m distinct Pokemon types in the Himalayan region numbered from 1 to m. There is a special evolution camp set up in the fest which claims to evolve any Pokemon. The type of a Pokemon could change after evolving, subject to the constraint that if two Pokemon have the same type before evolving, they will have the same type after evolving. Also, if two Pokemon have different types before evolving, they will have different types after evolving. It is also possible that a Pokemon has the same type before and after evolving. \\n\\nFormally, an evolution plan is a permutation f of {1, 2, ..., m}, such that f(x) = y means that a Pokemon of type x evolves into a Pokemon of type y.\\n\\nThe gym leaders are intrigued by the special evolution camp and all of them plan to evolve their Pokemons. The protocol of the mountain states that in each gym, for every type of Pokemon, the number of Pokemon of that type before evolving any Pokemon should be equal the number of Pokemon of that type after evolving all the Pokemons according to the evolution plan. They now want to find out how many distinct evolution plans exist which satisfy the protocol.\\n\\nTwo evolution plans f_1 and f_2 are distinct, if they have at least one Pokemon type evolving into a different Pokemon type in the two plans, i. e. there exists an i such that f_1(i) ≠ f_2(i).\\n\\nYour task is to find how many distinct evolution plans are possible such that if all Pokemon in all the gyms are evolved, the number of Pokemon of each type in each of the gyms remains the same. As the answer can be large, output it modulo 10^9 + 7.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^6) — the number of gyms and the number of Pokemon types.\\n\\nThe next n lines contain the description of Pokemons in the gyms. The i-th of these lines begins with the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import Counter\\nn, m = list(map(int, input().split()))\\nx = [[] for i in range(m)]\\nfor i in range(n):\\n    a = list(map(int, input().split()))\\n    k = a[0]\\n    for j in a[1:]:\\n        x[j - 1].append(i)\\n\\n\\nans = 1\\nMOD = 10 ** 9 + 7\\nfor e in list(Counter(list(map(str, x))).values()):\\n    for i in range(2, e + 1):\\n        ans = ans * i % MOD\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/540\\/B:\\nLittle Vova studies programming in an elite school. Vova and his classmates are supposed to write n progress tests, for each test they will get a mark from 1 to p. Vova is very smart and he can write every test for any mark, but he doesn't want to stand out from the crowd too much. If the sum of his marks for all tests exceeds value x, then his classmates notice how smart he is and start distracting him asking to let them copy his homework. And if the median of his marks will be lower than y points (the definition of a median is given in the notes), then his mom will decide that he gets too many bad marks and forbid him to play computer games.\\n\\nVova has already wrote k tests and got marks a_1, ..., a_{k}. He doesn't want to get into the first or the second situation described above and now he needs to determine which marks he needs to get for the remaining tests. Help him do that.\\n\\n\\n-----Input-----\\n\\nThe first line contains 5 space-separated integers: n, k, p, x and y (1 ≤ n ≤ 999, n is odd, 0 ≤ k < n, 1 ≤ p ≤ 1000, n ≤ x ≤ n·p, 1 ≤ y ≤ p). Here n is the number of tests that Vova is planned to write, k is the number of tests he has already written, p is the maximum possible mark for a test, x is the maximum total number of points so that the classmates don't yet disturb Vova, y is the minimum median point so that mom still lets him play computer games.\\n\\nThe second line contains k space-separated integers: a_1, ..., a_{k} (1 ≤ a_{i} ≤ p) — the marks that Vova got for the tests he has already written.\\n\\n\\n-----Output-----\\n\\nIf Vova cannot achieve the desired result, print \\\"-1\\\".\\n\\nOtherwise, print n - k space-separated integers — the marks that Vova should get for the remaining tests. If there are multiple possible solutions, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n5 3 5 18 4\\n3 5 4\\n\\nOutput\\n4 1\\n\\nInput\\n5 3 5 16 4\\n5 5 5\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nThe median of sequence a_1, ..., a_{n} where n is odd (in this problem n is always odd) is the element staying on (n + 1) \\/ 2 position in the sorted list of a_{i}.\\n\\nIn...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,k,p,x,y = map(int, input().split())\\nA = list(map(int, input().split()))\\ncnt = n\\/\\/2+1\\nfor i in A :\\n    if i >= y :\\n        cnt -= 1\\ncnt = max(cnt, 0)\\nif n-k < cnt :\\n    print(-1)\\nelse :\\n    B = [y]*cnt + [1]*(n-k-cnt)\\n    if sum(A) + sum(B) > x :\\n        print(-1)\\n    else :\\n        for i in B :\\n            print(i, end = ' ')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n**This Kata is intended as a small challenge for my students**\\n\\nAll Star Code Challenge #19\\n\\nYou work for an ad agency and your boss, Bob, loves a catchy slogan. He's always jumbling together \\\"buzz\\\" words until he gets one he likes. You're looking to impress Boss Bob with a function that can do his job for him.\\n\\nCreate a function called sloganMaker() that accepts an array of string \\\"buzz\\\" words. The function returns an array of all possible UNIQUE string permutations of the buzz words (concatonated and separated by spaces).\\n\\nYour boss is not very bright, so anticipate him using the same \\\"buzz\\\" word more than once, by accident. The function should ignore these duplicate string inputs.\\n\\n```\\nsloganMaker([\\\"super\\\", \\\"hot\\\", \\\"guacamole\\\"]);\\n\\/\\/[ 'super hot guacamole',\\n\\/\\/  'super guacamole hot',\\n\\/\\/  'hot super guacamole',\\n\\/\\/  'hot guacamole super',\\n\\/\\/  'guacamole super hot',\\n\\/\\/  'guacamole hot super' ]\\n\\nsloganMaker([\\\"cool\\\", \\\"pizza\\\", \\\"cool\\\"]); \\/\\/ => [ 'cool pizza', 'pizza cool' ]\\n```\\n\\nNote:  \\nThere should be NO duplicate strings in the output array\\n\\nThe input array MAY contain duplicate strings, which should STILL result in an output array with all unique strings\\n\\nAn empty string is valid input\\n\\n```if-not:python,crystal\\nThe order of the permutations in the output array does not matter\\n```\\n```if:python,crystal\\nThe order of the output array must match those rules:\\n1. Generate the permutations in lexicographic order of the original array.\\n2. keep only the first occurence of a permutation, when duplicates are found.\\n```\",\"targets\":\"import itertools\\ndef slogan_maker(tab):\\n    tab_set = set()\\n    unique = [x for x in tab if x not in tab_set and (tab_set.add(x) or True)]\\n    generator = [] * len(unique)\\n    x = list(itertools.permutations(unique))\\n    for i in x:\\n        generator.append(\\\" \\\".join(i))\\n    return generator\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/317\\/D:\\nVasya and Petya wrote down all integers from 1 to n to play the \\\"powers\\\" game (n can be quite large; however, Vasya and Petya are not confused by this fact).\\n\\nPlayers choose numbers in turn (Vasya chooses first). If some number x is chosen at the current turn, it is forbidden to choose x or all of its other positive integer powers (that is, x^2, x^3, ...) at the next turns. For instance, if the number 9 is chosen at the first turn, one cannot choose 9 or 81 later, while it is still allowed to choose 3 or 27. The one who cannot make a move loses.\\n\\nWho wins if both Vasya and Petya play optimally?\\n\\n\\n-----Input-----\\n\\nInput contains single integer n (1 ≤ n ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nPrint the name of the winner — \\\"Vasya\\\" or \\\"Petya\\\" (without quotes).\\n\\n\\n-----Examples-----\\nInput\\n1\\n\\nOutput\\nVasya\\n\\nInput\\n2\\n\\nOutput\\nPetya\\n\\nInput\\n8\\n\\nOutput\\nPetya\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample Vasya will choose 1 and win immediately.\\n\\nIn the second sample no matter which number Vasya chooses during his first turn, Petya can choose the remaining number and win.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from sys import stdin, stdout\\nimport math, collections\\nmod = 10**9+7\\n\\ndef isPower(n):\\n    if (n <= 1):\\n        return True\\n    for x in range(2, (int)(math.sqrt(n)) + 1):\\n        p = x\\n        while (p <= n):\\n            p = p * x\\n            if (p == n):\\n                return True\\n\\n    return False\\nn = int(input())\\narr = [0,1,2,1,4,3,2,1,5,6,2,1,8,7,5,9,8,7,3,4,7,4,2,1,10,9,3,6,11,12]\\nans = arr[int(math.log(n, 2))]\\ns = int(math.log(n, 2))\\nfor i in range(3, int(n**0.5)+1):\\n    if not isPower(i):\\n        ans^=arr[int(math.log(n, i))]\\n        s+=int(math.log(n, i))\\nans^=((n-s)%2)\\nprint(\\\"Vasya\\\" if ans else \\\"Petya\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\nA cake is sliced with `n` straight lines. Your task is to calculate the maximum number of pieces the cake can have.\\n\\n# Example\\n\\n For `n = 0`, the output should be `1`.\\n \\n For `n = 1`, the output should be `2`.\\n \\n For `n = 2`, the output should be `4`.\\n \\n For `n = 3`, the output should be `7`.\\n \\n See the following image to understand it:\\n \\n ![](https:\\/\\/cdn2.scratch.mit.edu\\/get_image\\/project\\/92275349_500x400.png?v=1450672809.79)\\n\\n# Input\\/Output\\n\\n\\n - `[input]` integer `n`\\n\\n  `0 ≤ n ≤ 10000`\\n\\n\\n - `[output]` an integer\\n\\n  The maximum number of pieces the sliced cake can have.\",\"targets\":\"def cake_slice(n):\\n  return 0.5*n**2+0.5*n+1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/536e7c7fd38523be14000ca2:\\nOne of the services provided by an operating system is memory management. The OS typically provides an API for allocating and releasing memory in a process's address space. A process should only read and write memory at addresses which have been allocated by the operating system. In this kata you will implement a simulation of a simple memory manager.\\n\\nThe language you will be using has no low level memory API, so for our simulation we will simply use an array as the process address space. The memory manager constructor will accept an array (further referred to as `memory`) where blocks of indices will be allocated later.\\n\\n___\\n\\n# Memory Manager Contract\\n\\n## allocate(size)\\n\\n`allocate` reserves a sequential block (sub-array) of `size` received as an argument in `memory`. It should return the index of the first element in the allocated block, or throw an exception if there is no block big enough to satisfy the requirements.\\n\\n## release(pointer)\\n\\n`release` accepts an integer representing the start of the block allocated ealier, and frees that block. If the released block is adjacent to a free block, they should be merged into a larger free block. Releasing an unallocated block should cause an exception.\\n\\n## write(pointer, value)\\n\\nTo support testing this simulation our memory manager needs to support read\\/write functionality. Only elements within allocated blocks may be written to. The `write` method accepts an index in `memory` and a `value`. The `value` should be stored in `memory` at that index if it lies within an allocated block, or throw an exception otherwise.\\n\\n## read(pointer)\\n\\nThis method is the counterpart to `write`. Only indices within allocated blocks may be read. The `read` method accepts an index. If the `index` is within an allocated block, the value stored in `memory` at that index should be returned, or an exception should be thrown otherwise.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import copy\\nclass MemoryManager:\\n    def __init__(self, memory:list):\\n        \\\"\\\"\\\"\\n        @constructor Creates a new memory manager for the provided array.\\n        @param {memory} An array to use as the backing memory.\\n        \\\"\\\"\\\"\\n        self.memory = memory\\n        self.Firstindex = copy.copy(memory)\\n        self.lens = len(self.Firstindex)\\n    def allocate(self, size):\\n        \\\"\\\"\\\"\\n        Allocates a block of memory of requested size.\\n        @param {number} size - The size of the block to allocate.\\n        @returns {number} A pointer which is the index of the first location in the allocated block.\\n        @raises If it is not possible to allocate a block of the requested size.\\n        \\\"\\\"\\\"\\n        if(size > self.lens):\\n            raise Exception(\\\"allocate size ERROR\\\")\\n        else:\\n            # index = 0\\n            tempindex = self.Firstindex\\n            while(tempindex):\\n                if(tempindex.count(None) == 0):\\n                    # print(tempindex)\\n                    break\\n                else:\\n                    index = self.Firstindex.index(None)\\n                if(index+size > self.lens):\\n                    break\\n                else:\\n                    last = index+size\\n                if(self.Firstindex[index:last] == [None]*size):\\n                    self.Firstindex[index:last] = [index]*size\\n                    return index\\n                else:\\n                    needlist = self.Firstindex[index:last]\\n                    s2 = list(filter(None, needlist))\\n                    tempindex = (tempindex[tempindex.index(s2[-1]) + 1:])\\n\\n            raise Exception(\\\"allocate END ERROR\\\")\\n    def release(self, pointer:int):\\n        \\\"\\\"\\\"\\n        Releases a previously allocated block of memory.\\n        @param {number} pointer - The pointer to the block to release.\\n        @raises If the pointer does not point to an allocated block.\\n        \\\"\\\"\\\"\\n        if(pointer not in self.Firstindex):\\n            raise Exception(\\\"pointer release ERROR\\\")\\n        counts = self.Firstindex.count(pointer)\\n       ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1229\\/C:\\nKonrad is a Human Relations consultant working for VoltModder, a large electrical equipment producer. Today, he has been tasked with evaluating the level of happiness in the company.\\n\\nThere are $n$ people working for VoltModder, numbered from $1$ to $n$. Each employee earns a different amount of money in the company — initially, the $i$-th person earns $i$ rubles per day.\\n\\nOn each of $q$ following days, the salaries will be revised. At the end of the $i$-th day, employee $v_i$ will start earning $n+i$ rubles per day and will become the best-paid person in the company. The employee will keep his new salary until it gets revised again.\\n\\nSome pairs of people don't like each other. This creates a great psychological danger in the company. Formally, if two people $a$ and $b$ dislike each other and $a$ earns more money than $b$, employee $a$ will brag about this to $b$. A dangerous triple is a triple of three employees $a$, $b$ and $c$, such that $a$ brags to $b$, who in turn brags to $c$. If $a$ dislikes $b$, then $b$ dislikes $a$.\\n\\nAt the beginning of each day, Konrad needs to evaluate the number of dangerous triples in the company. Can you help him do it?\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $m$ ($1 \\\\le n \\\\le 100\\\\,000$, $0 \\\\le m \\\\le 100\\\\,000$) — the number of employees in the company and the number of pairs of people who don't like each other. Each of the following $m$ lines contains two integers $a_i$, $b_i$ ($1 \\\\le a_i, b_i \\\\le n$, $a_i \\\\neq b_i$) denoting that employees $a_i$ and $b_i$ hate each other (that is, $a_i$ dislikes $b_i$ and $b_i$ dislikes $a_i$). Each such relationship will be mentioned exactly once.\\n\\nThe next line contains an integer $q$ ($0 \\\\le q \\\\le 100\\\\,000$) — the number of salary revisions. The $i$-th of the following $q$ lines contains a single integer $v_i$ ($1 \\\\le v_i \\\\le n$) denoting that at the end of the $i$-th day, employee $v_i$ will earn the most.\\n\\n\\n-----Output-----\\n\\nOutput $q + 1$ integers. The $i$-th of them should contain the number of dangerous triples...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n\\nn, m = list(map(int, sys.stdin.readline().strip().split()))\\nL = [0 for i in range (0, n)]\\nH = [[] for i in range (0, n)]\\nfor i in range (0, m):\\n    x, y = list(map(int, sys.stdin.readline().strip().split()))\\n    x = x - 1\\n    y = y - 1\\n    if x > y:\\n        x, y = y, x\\n    L[y] = L[y] + 1\\n    H[x].append(y)\\nans = 0\\nfor i in range (0, n):\\n    ans = ans + L[i] * len(H[i])\\nprint(ans)\\nq = int(sys.stdin.readline().strip())\\nfor i in range (0, q):\\n    v = int(sys.stdin.readline().strip()) - 1\\n    ans = ans - L[v] * len(H[v])\\n    L[v] = L[v] + len(H[v])\\n    while len(H[v]) > 0:\\n        w = H[v].pop()\\n        H[w].append(v)\\n        L[w] = L[w] - 1\\n        ans = ans + L[w] - len(H[w]) + 1\\n    print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFox Ciel has a robot on a 2D plane. Initially it is located in (0, 0). Fox Ciel code a command to it. The command was represented by string s. Each character of s is one move operation. There are four move operations at all:  'U': go up, (x, y)  →  (x, y+1);  'D': go down, (x, y)  →  (x, y-1);  'L': go left, (x, y)  →  (x-1, y);  'R': go right, (x, y)  →  (x+1, y). \\n\\nThe robot will do the operations in s from left to right, and repeat it infinite times. Help Fox Ciel to determine if after some steps the robot will located in (a, b).\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers a and b, ( - 10^9 ≤ a, b ≤ 10^9). The second line contains a string s (1 ≤ |s| ≤ 100, s only contains characters 'U', 'D', 'L', 'R') — the command.\\n\\n\\n-----Output-----\\n\\nPrint \\\"Yes\\\" if the robot will be located at (a, b), and \\\"No\\\" otherwise.\\n\\n\\n-----Examples-----\\nInput\\n2 2\\nRU\\n\\nOutput\\nYes\\n\\nInput\\n1 2\\nRU\\n\\nOutput\\nNo\\n\\nInput\\n-1 1000000000\\nLRRLU\\n\\nOutput\\nYes\\n\\nInput\\n0 0\\nD\\n\\nOutput\\nYes\\n\\n\\n\\n-----Note-----\\n\\nIn the first and second test case, command string is \\\"RU\\\", so the robot will go right, then go up, then right, and then up and so on.\\n\\nThe locations of its moves are (0, 0)  →  (1, 0)  →  (1, 1)  →  (2, 1)  →  (2, 2)  →  ...\\n\\nSo it can reach (2, 2) but not (1, 2).\",\"targets\":\"dx = {'U': 0, 'D': 0, 'L': -1, 'R': 1}\\ndy = {'U': 1, 'D': -1, 'L': 0, 'R': 0}\\nx, y, xl, yl = 0, 0, [], []\\na, b = list(map(int, input().split()))\\nfor ch in input():\\n    xl.append(x)\\n    yl.append(y)\\n    x += dx[ch]\\n    y += dy[ch]\\nfor xi, yi in zip(xl, yl):\\n    mx, my = a - xi, b - yi\\n    if x == 0 and mx != 0 or x != 0 and (mx % x != 0 or mx \\/\\/ x < 0):\\n        continue\\n    if y == 0 and my != 0 or y != 0 and (my % y != 0 or my \\/\\/ y < 0):\\n        continue\\n    if x != 0 and y != 0 and mx \\/\\/ x != my \\/\\/ y:\\n        continue\\n    print('Yes')\\n    return\\nprint('No')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/DIFFSUM:\\nWrite a program to take two numbers as input and print their difference if the first number is greater than the second number otherwise$otherwise$ print their sum.\\n\\n-----Input:-----\\n- First line will contain the first number (N1$N1$)\\n- Second line will contain the second number (N2$N2$)\\n\\n-----Output:-----\\nOutput a single line containing the difference of 2 numbers (N1−N2)$(N1 - N2)$ if the first number is greater than the second number otherwise output their sum (N1+N2)$(N1 + N2)$.\\n\\n-----Constraints-----\\n- −1000≤N1≤1000$-1000 \\\\leq N1 \\\\leq 1000$\\n- −1000≤N2≤1000$-1000 \\\\leq N2 \\\\leq 1000$\\n\\n-----Sample Input:-----\\n82\\n28\\n\\n-----Sample Output:-----\\n54\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a=int(input())\\nb=int(input())\\nif a>b:\\n    print(a-b)\\nelse:\\n    print(a+b)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/768\\/C:\\nJon Snow now has to fight with White Walkers. He has n rangers, each of which has his own strength. Also Jon Snow has his favourite number x. Each ranger can fight with a white walker only if the strength of the white walker equals his strength. He however thinks that his rangers are weak and need to improve. Jon now thinks that if he takes the bitwise XOR of strengths of some of rangers with his favourite number x, he might get soldiers of high strength. So, he decided to do the following operation k times: \\n\\n Arrange all the rangers in a straight line in the order of increasing strengths.\\n\\n Take the bitwise XOR (is written as $\\\\oplus$) of the strength of each alternate ranger with x and update it's strength.\\n\\n Suppose, Jon has 5 rangers with strengths [9, 7, 11, 15, 5] and he performs the operation 1 time with x = 2. He first arranges them in the order of their strengths, [5, 7, 9, 11, 15]. Then he does the following: \\n\\n The strength of first ranger is updated to $5 \\\\oplus 2$, i.e. 7.\\n\\n The strength of second ranger remains the same, i.e. 7.\\n\\n The strength of third ranger is updated to $9 \\\\oplus 2$, i.e. 11.\\n\\n The strength of fourth ranger remains the same, i.e. 11.\\n\\n The strength of fifth ranger is updated to $15 \\\\oplus 2$, i.e. 13.\\n\\n The new strengths of the 5 rangers are [7, 7, 11, 11, 13]\\n\\nNow, Jon wants to know the maximum and minimum strength of the rangers after performing the above operations k times. He wants your help for this task. Can you help him?\\n\\n\\n-----Input-----\\n\\nFirst line consists of three integers n, k, x (1 ≤ n ≤ 10^5, 0 ≤ k ≤ 10^5, 0 ≤ x ≤ 10^3) — number of rangers Jon has, the number of times Jon will carry out the operation and Jon's favourite number respectively.\\n\\nSecond line consists of n integers representing the strengths of the rangers a_1, a_2, ..., a_{n} (0 ≤ a_{i} ≤ 10^3).\\n\\n\\n-----Output-----\\n\\nOutput two integers, the maximum and the minimum strength of the rangers after performing the operation k times.\\n\\n\\n-----Examples-----\\nInput\\n5 1 2\\n9 7 11 15 5\\n\\nOutput\\n13 7\\nInput\\n2 100000...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, k, x = map(int, input().split())\\nrangers = list(map(int, input().split()))\\nfor i in range(min(k, 8 + (k & 3))):\\n\\trangers.sort()\\n\\trangers = [rangers[i] if (i & 1) else rangers[i] ^ x for i in range(n)]\\nrangers.sort()\\nprint(rangers[-1], rangers[0])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1418\\/D:\\nVova decided to clean his room. The room can be represented as the coordinate axis $OX$. There are $n$ piles of trash in the room, coordinate of the $i$-th pile is the integer $p_i$. All piles have different coordinates.\\n\\nLet's define a total cleanup as the following process. The goal of this process is to collect all the piles in no more than two different $x$ coordinates. To achieve this goal, Vova can do several (possibly, zero) moves. During one move, he can choose some $x$ and move all piles from $x$ to $x+1$ or $x-1$ using his broom. Note that he can't choose how many piles he will move.\\n\\nAlso, there are two types of queries:\\n\\n  $0$ $x$ — remove a pile of trash from the coordinate $x$. It is guaranteed that there is a pile in the coordinate $x$ at this moment.  $1$ $x$ — add a pile of trash to the coordinate $x$. It is guaranteed that there is no pile in the coordinate $x$ at this moment. \\n\\nNote that it is possible that there are zero piles of trash in the room at some moment.\\n\\nVova wants to know the minimum number of moves he can spend if he wants to do a total cleanup before any queries. He also wants to know this number of moves after applying each query. Queries are applied in the given order. Note that the total cleanup doesn't actually happen and doesn't change the state of piles. It is only used to calculate the number of moves.\\n\\nFor better understanding, please read the Notes section below to see an explanation for the first example.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $q$ ($1 \\\\le n, q \\\\le 10^5$) — the number of piles in the room before all queries and the number of queries, respectively.\\n\\nThe second line of the input contains $n$ distinct integers $p_1, p_2, \\\\dots, p_n$ ($1 \\\\le p_i \\\\le 10^9$), where $p_i$ is the coordinate of the $i$-th pile.\\n\\nThe next $q$ lines describe queries. The $i$-th query is described with two integers $t_i$ and $x_i$ ($0 \\\\le t_i \\\\le 1; 1 \\\\le x_i \\\\le 10^9$), where $t_i$ is $0$ if you need to remove a pile from the coordinate...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class SortedList:\\n    def __init__(self, iterable=[], _load=200):\\n        \\\"\\\"\\\"Initialize sorted list instance.\\\"\\\"\\\"\\n        values = sorted(iterable)\\n        self._len = _len = len(values)\\n        self._load = _load\\n        self._lists = _lists = [values[i:i + _load] for i in range(0, _len, _load)]\\n        self._list_lens = [len(_list) for _list in _lists]\\n        self._mins = [_list[0] for _list in _lists]\\n        self._fen_tree = []\\n        self._rebuild = True\\n\\n    def _fen_build(self):\\n        \\\"\\\"\\\"Build a fenwick tree instance.\\\"\\\"\\\"\\n        self._fen_tree[:] = self._list_lens\\n        _fen_tree = self._fen_tree\\n        for i in range(len(_fen_tree)):\\n            if i | i + 1 < len(_fen_tree):\\n                _fen_tree[i | i + 1] += _fen_tree[i]\\n        self._rebuild = False\\n\\n    def _fen_update(self, index, value):\\n        \\\"\\\"\\\"Update `fen_tree[index] += value`.\\\"\\\"\\\"\\n        if not self._rebuild:\\n            _fen_tree = self._fen_tree\\n            while index < len(_fen_tree):\\n                _fen_tree[index] += value\\n                index |= index + 1\\n\\n    def _fen_query(self, end):\\n        \\\"\\\"\\\"Return `sum(_fen_tree[:end])`.\\\"\\\"\\\"\\n        if self._rebuild:\\n            self._fen_build()\\n\\n        _fen_tree = self._fen_tree\\n        x = 0\\n        while end:\\n            x += _fen_tree[end - 1]\\n            end &= end - 1\\n        return x\\n\\n    def _fen_findkth(self, k):\\n        \\\"\\\"\\\"Return a pair of (the largest `idx` such that `sum(_fen_tree[:idx]) <= k`, `k - sum(_fen_tree[:idx])`).\\\"\\\"\\\"\\n        _list_lens = self._list_lens\\n        if k < _list_lens[0]:\\n            return 0, k\\n        if k >= self._len - _list_lens[-1]:\\n            return len(_list_lens) - 1, k + _list_lens[-1] - self._len\\n        if self._rebuild:\\n            self._fen_build()\\n\\n        _fen_tree = self._fen_tree\\n        idx = -1\\n        for d in reversed(list(range(len(_fen_tree).bit_length()))):\\n            right_idx = idx + (1 << d)\\n            if right_idx < len(_fen_tree) and k >= _fen_tree[right_idx]:\\n                idx = right_idx\\n                k -=...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are n cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers a_1, a_2, ..., a_{n}. All coordinates are pairwise distinct.\\n\\nIt is possible to get from one city to another only by bus. But all buses and roads are very old, so the Minister of Transport decided to build a new bus route. The Minister doesn't want to spend large amounts of money — he wants to choose two cities in such a way that the distance between them is minimal possible. The distance between two cities is equal to the absolute value of the difference between their coordinates.\\n\\nIt is possible that there are multiple pairs of cities with minimal possible distance, so the Minister wants to know the quantity of such pairs. \\n\\nYour task is to write a program that will calculate the minimal possible distance between two pairs of cities and the quantity of pairs which have this distance.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer number n (2 ≤ n ≤ 2·10^5).\\n\\nThe second line contains n integer numbers a_1, a_2, ..., a_{n} ( - 10^9 ≤ a_{i} ≤ 10^9). All numbers a_{i} are pairwise distinct.\\n\\n\\n-----Output-----\\n\\nPrint two integer numbers — the minimal distance and the quantity of pairs with this distance.\\n\\n\\n-----Examples-----\\nInput\\n4\\n6 -3 0 4\\n\\nOutput\\n2 1\\n\\nInput\\n3\\n-2 0 2\\n\\nOutput\\n2 2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the distance between the first city and the fourth city is |4 - 6| = 2, and it is the only pair with this distance.\",\"targets\":\"n = int(input())\\na = sorted([int(i) for i in input().split()])\\nm = abs(a[1] - a[0])\\ncount = 0\\nfor i in range(1, len(a)):\\n\\tt = abs(a[i] - a[i -1])\\n\\tif t < m:\\n\\t\\tm = t\\n\\t\\tcount = 1\\n\\telif t == m:\\n\\t\\tcount += 1\\nprint(m, count)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe chef is trying to solve some pattern problems, Chef wants your help to code it. Chef has one number K to form a new pattern. Help the chef to code this pattern problem.\\n\\n-----Input:-----\\n- First-line will contain $T$, the number of test cases. Then the test cases follow. \\n- Each test case contains a single line of input, one integer $K$. \\n\\n-----Output:-----\\nFor each test case, output as the pattern.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $1 \\\\leq K \\\\leq 100$\\n\\n-----Sample Input:-----\\n4\\n1\\n2\\n3\\n4\\n\\n-----Sample Output:-----\\n1\\n13\\n57\\n135\\n7911\\n131517\\n1357\\n9111315\\n17192123\\n25272931\\n\\n-----EXPLANATION:-----\\nNo need, else pattern can be decode easily.\",\"targets\":\"# cook your dish here\\nfor _ in range(int(input())):\\n    k = int(input())\\n    x = 1\\n    for i in range(k):\\n        for j in range(k):\\n            print(x,end = '')\\n            x = x + 2\\n        print()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nN friends of Takahashi has come to a theme park.\\nTo ride the most popular roller coaster in the park, you must be at least K centimeters tall.\\nThe i-th friend is h_i centimeters tall.\\nHow many of the Takahashi's friends can ride the roller coaster?\\n\\n-----Constraints-----\\n -  1 \\\\le N \\\\le 10^5 \\n -  1 \\\\le K \\\\le 500 \\n -  1 \\\\le h_i \\\\le 500\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN K\\nh_1 h_2 \\\\ldots h_N\\n\\n-----Output-----\\nPrint the number of people among the Takahashi's friends who can ride the roller coaster.\\n\\n-----Sample Input-----\\n4 150\\n150 140 100 200\\n\\n-----Sample Output-----\\n2\\n\\nTwo of them can ride the roller coaster: the first and fourth friends.\",\"targets\":\"num_persons, need_height = list(map(int, input().split()))\\na = list(map(int, input().split()))\\nheight_list = list(a)\\n\\ncount_height_ok = 0\\n\\nfor i in height_list:\\n    if i >= need_height:\\n        count_height_ok += 1\\n\\nprint(count_height_ok)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/count-odd-numbers-in-an-interval-range\\/:\\nGiven two non-negative integers low and high. Return the count of odd numbers between low and high (inclusive).\\n \\nExample 1:\\nInput: low = 3, high = 7\\nOutput: 3\\nExplanation: The odd numbers between 3 and 7 are [3,5,7].\\nExample 2:\\nInput: low = 8, high = 10\\nOutput: 1\\nExplanation: The odd numbers between 8 and 10 are [9].\\n \\nConstraints:\\n\\n0 <= low <= high <= 10^9\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def countOdds(self, low: int, high: int) -> int:\\n        return (high - low + 1) \\/\\/ 2 + (high % 2 and low % 2);\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nHarry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they are not under its influence.\\n\\nHe has names of n people who possessed the diary in order. You need to tell, for each person, if he\\/she possessed the diary at some point before or not.\\n\\nFormally, for a name s_{i} in the i-th line, output \\\"YES\\\" (without quotes) if there exists an index j such that s_{i} = s_{j} and j < i, otherwise, output \\\"NO\\\" (without quotes).\\n\\n\\n-----Input-----\\n\\nFirst line of input contains an integer n (1 ≤ n ≤ 100) — the number of names in the list.\\n\\nNext n lines each contain a string s_{i}, consisting of lowercase English letters. The length of each string is between 1 and 100.\\n\\n\\n-----Output-----\\n\\nOutput n lines each containing either \\\"YES\\\" or \\\"NO\\\" (without quotes), depending on whether this string was already present in the stream or not.\\n\\nYou can print each letter in any case (upper or lower).\\n\\n\\n-----Examples-----\\nInput\\n6\\ntom\\nlucius\\nginny\\nharry\\nginny\\nharry\\n\\nOutput\\nNO\\nNO\\nNO\\nNO\\nYES\\nYES\\n\\nInput\\n3\\na\\na\\na\\n\\nOutput\\nNO\\nYES\\nYES\\n\\n\\n\\n-----Note-----\\n\\nIn test case 1, for i = 5 there exists j = 3 such that s_{i} = s_{j} and j < i, which means that answer for i = 5 is \\\"YES\\\".\",\"targets\":\"n = int(input())\\n\\na = []\\nfor x in range(n):\\n    x = input()\\n    a.append(x)\\n\\nlst = []\\nfor x in a:\\n    if not x in lst:\\n        print('NO')\\n        lst.append(x)\\n    else:\\n        print('YES')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an integer $n$ and an integer $k$.\\n\\nIn one step you can do one of the following moves:   decrease $n$ by $1$;  divide $n$ by $k$ if $n$ is divisible by $k$. \\n\\nFor example, if $n = 27$ and $k = 3$ you can do the following steps: $27 \\\\rightarrow 26 \\\\rightarrow 25 \\\\rightarrow 24 \\\\rightarrow 8 \\\\rightarrow 7 \\\\rightarrow 6 \\\\rightarrow 2 \\\\rightarrow 1 \\\\rightarrow 0$.\\n\\nYou are asked to calculate the minimum number of steps to reach $0$ from $n$. \\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 100$) — the number of queries.\\n\\nThe only line of each query contains two integers $n$ and $k$ ($1 \\\\le n \\\\le 10^{18}$, $2 \\\\le k \\\\le 10^{18}$).\\n\\n\\n-----Output-----\\n\\nFor each query print the minimum number of steps to reach $0$ from $n$ in single line. \\n\\n\\n-----Example-----\\nInput\\n2\\n59 3\\n1000000000000000000 10\\n\\nOutput\\n8\\n19\\n\\n\\n\\n-----Note-----\\n\\nSteps for the first test case are: $59 \\\\rightarrow 58 \\\\rightarrow 57 \\\\rightarrow 19 \\\\rightarrow 18 \\\\rightarrow 6 \\\\rightarrow 2 \\\\rightarrow 1 \\\\rightarrow 0$.\\n\\nIn the second test case you have to divide $n$ by $k$ $18$ times and then decrease $n$ by $1$.\",\"targets\":\"def main():\\n    t = int(input())\\n    for i in range(t):\\n        steps = 0\\n        n,k = list(map(int,input().split()))\\n        while n != 0:\\n            if n%k == 0:\\n                n = n\\/\\/k\\n                steps += 1\\n            else:\\n                steps += n%k\\n                n -= n%k\\n\\n        print(steps)\\n\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/612\\/A:\\nYou are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.\\n\\nFor example, the string \\\"Hello\\\" for p = 2, q = 3 can be split to the two strings \\\"Hel\\\" and \\\"lo\\\" or to the two strings \\\"He\\\" and \\\"llo\\\".\\n\\nNote it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).\\n\\n\\n-----Input-----\\n\\nThe first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).\\n\\nThe second line contains the string s consists of lowercase and uppercase latin letters and digits.\\n\\n\\n-----Output-----\\n\\nIf it's impossible to split the string s to the strings of length p and q print the only number \\\"-1\\\".\\n\\nOtherwise in the first line print integer k — the number of strings in partition of s.\\n\\nEach of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.\\n\\nIf there are several solutions print any of them.\\n\\n\\n-----Examples-----\\nInput\\n5 2 3\\nHello\\n\\nOutput\\n2\\nHe\\nllo\\n\\nInput\\n10 9 5\\nCodeforces\\n\\nOutput\\n2\\nCodef\\norces\\n\\nInput\\n6 4 5\\nPrivet\\n\\nOutput\\n-1\\n\\nInput\\n8 1 1\\nabacabac\\n\\nOutput\\n8\\na\\nb\\na\\nc\\na\\nb\\na\\nc\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a, b, c = map(int, input().split(' '))\\nx = input()\\nfor i in range(105):\\n    for j in range(105):\\n        if i*b+j*c == a:\\n            print(i+j)\\n            for k in range(i):\\n                print(x[:b])\\n                x = x[b:]\\n            for l in range(j):\\n                print(x[:c])\\n                x = x[c:]\\n            quit()\\nprint(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef has recently been playing a lot of chess in preparation for the ICCT (International Chef Chess Tournament).\\nSince putting in long hours is not an easy task, Chef's mind wanders elsewhere. He starts counting the number of squares with odd side length on his chessboard..\\nHowever, Chef is not satisfied. He wants to know the number of squares of odd side length on a generic $N*N$ chessboard.\\n\\n-----Input:-----\\n- The first line will contain a single integer $T$, the number of test cases.\\n- The next $T$ lines will have a single integer $N$, the size of the chess board.\\n\\n-----Output:-----\\nFor each test case, print a integer denoting the number of squares with odd length.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $1 \\\\leq N \\\\leq 1000$\\n\\n-----Sample Input:-----\\n2\\n3\\n8\\n\\n-----Sample Output:-----\\n10\\n120\",\"targets\":\"# cook your dish here\\nt=int(input())\\nfor _ in range(t):\\n s=0\\n n=int(input())\\n while(n>0):\\n  s+=(n*n)\\n  n-=2\\n print(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n**The Rub**\\n\\nYou need to make a function that takes an object as an argument, and returns a very similar object but with a special property. The returned object should allow a user to access values by providing only the beginning of the key for the value they want. For example if the given object has a key `idNumber`, you should be able to access its value on the returned object by using a key `idNum` or even simply `id`. `Num` and `Number` shouldn't work because we are only looking for matches at the beginning of a key.\\n\\nBe aware that you _could_ simply add all these partial keys one by one to the object. However, for the sake of avoiding clutter, we don't want to have a JSON with a bunch of nonsensical keys. Thus, in the random tests there will be a test to check that you did not add or remove any keys from the object passed in or the object returned.\\n\\nAlso, if a key is tested that appears as the beginning of more than one key in the original object (e.g. if the original object had a key `idNumber` and `idString` and we wanted to test the key `id`) then return the value corresponding with whichever key comes first **alphabetically**. (In this case it would be `idNumber`s value because it comes first alphabetically.)\\n\\n**Example**\\n\\n```python\\no = partial_keys({\\\"abcd\\\": 1})\\n\\no['abcd'] == 1 # true\\no['abc'] == 1 # true\\no['ab'] == 1 # true\\no['a'] == 1 # true\\n\\no['b'] == 1 # false!\\no['b'] == None # true\\n\\nlist(o.keys()) # ['abcd']\\n```\",\"targets\":\"class partial_keys(dict):\\n    def __getitem__(self, key):\\n        keys = sorted(k for k in self.keys() if k.startswith(key))\\n        if keys: return super().__getitem__(keys[0])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPrint all the integers that satisfies the following in ascending order:\\n - Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.\\n\\n-----Constraints-----\\n - 1 \\\\leq A \\\\leq B \\\\leq 10^9\\n - 1 \\\\leq K \\\\leq 100\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B K\\n\\n-----Output-----\\nPrint all the integers that satisfies the condition above in ascending order.\\n\\n-----Sample Input-----\\n3 8 2\\n\\n-----Sample Output-----\\n3\\n4\\n7\\n8\\n\\n - 3 is the first smallest integer among the integers between 3 and 8.\\n - 4 is the second smallest integer among the integers between 3 and 8.\\n - 7 is the second largest integer among the integers between 3 and 8.\\n - 8 is the first largest integer among the integers between 3 and 8.\",\"targets\":\"a, b, k = map(int, input().split())\\n\\nif b - a < 2 * k:\\n    for i in range(a, b + 1):\\n        print(i)\\nelse:\\n    for i in range(a, a + k):\\n        print(i)\\n    for i in range(b - k + 1, b + 1):\\n        print(i)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFor an integer ```k``` rearrange all the elements of the given array in such way, that:\\n\\nall elements that are less than ```k``` are placed before elements that are not less than ```k```;\\nall elements that are less than ```k``` remain in the same order with respect to each other;\\nall elements that are not less than ```k``` remain in the same order with respect to each other.\\n\\nFor ```k = 6``` and ```elements = [6, 4, 10, 10, 6]```, the output should be\\n```splitByValue(k, elements) = [4, 6, 10, 10, 6]```.\\n\\nFor ```k``` = 5 and ```elements = [1, 3, 5, 7, 6, 4, 2]```, the output should be\\n```splitByValue(k, elements) = [1, 3, 4, 2, 5, 7, 6]```.\\n\\nS: codefights.com\",\"targets\":\"from itertools import chain\\n\\ndef split_by_value(k, arr):\\n    lst = [[],[]]\\n    for v in arr: lst[v>=k].append(v)\\n    return list(chain(*lst))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/811\\/A:\\nAt regular competition Vladik and Valera won a and b candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vladik for same reason gave 3 candies to Valera in next turn.\\n\\nMore formally, the guys take turns giving each other one candy more than they received in the previous turn.\\n\\nThis continued until the moment when one of them couldn’t give the right amount of candy. Candies, which guys got from each other, they don’t consider as their own. You need to know, who is the first who can’t give the right amount of candy.\\n\\n\\n-----Input-----\\n\\nSingle line of input data contains two space-separated integers a, b (1 ≤ a, b ≤ 10^9) — number of Vladik and Valera candies respectively.\\n\\n\\n-----Output-----\\n\\nPring a single line \\\"Vladik’’ in case, if Vladik first who can’t give right amount of candy, or \\\"Valera’’ otherwise.\\n\\n\\n-----Examples-----\\nInput\\n1 1\\n\\nOutput\\nValera\\n\\nInput\\n7 6\\n\\nOutput\\nVladik\\n\\n\\n\\n-----Note-----\\n\\nIllustration for first test case:\\n\\n[Image]\\n\\nIllustration for second test case:\\n\\n[Image]\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a, b = list(map(int, input().split()))\\ncnt = 0\\nwhile True:\\n    cnt += 1\\n    a -= cnt\\n    if a < 0:\\n        print('Vladik')\\n        break\\n    cnt += 1\\n    b -= cnt\\n    if b < 0:\\n        print('Valera')\\n        break\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/592538b3071ba54511000219:\\n# Task\\nWe know that some numbers can be split into two primes. ie. `5 = 2 + 3, 10 = 3 + 7`. But some numbers are not. ie. `17, 27, 35`, etc.. \\n\\nGiven a positive integer `n`. Determine whether it can be split into two primes. If yes, return the maximum product of two primes. If not, return `0` instead.\\n\\n# Input\\/Output\\n\\n`[input]` integer `n`\\n\\nA positive integer. \\n\\n`0 ≤ n ≤ 100000`\\n\\n`[output]` an integer\\n\\nThe possible maximum product of two primes. or return `0` if it's impossible split into two primes.\\n\\n# Example\\n\\nFor `n = 1`, the output should be `0`.\\n\\n`1` can not split into two primes\\n\\nFor `n = 4`, the output should be `4`.\\n\\n`4` can split into two primes `2 and 2`. `2 x 2 = 4`\\n\\nFor `n = 20`, the output should be `91`.\\n\\n`20` can split into two primes `7 and 13` or `3 and 17`. The maximum product is `7 x 13 = 91`\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def primes_set():\\n    primes, sieve = {2}, [True] * 50000\\n    for i in range(3, 317, 2):\\n        if sieve[i \\/\\/ 2]:\\n            sieve[i * i \\/\\/ 2 :: i] = [False] * ((100000 - i * i - 1) \\/\\/ (2 * i) + 1)\\n    primes.update((2 * i + 1) for i in range(1, 50000) if sieve[i])\\n    return primes\\n\\nprimes = primes_set()\\n\\ndef prime_product(n):\\n    if n % 2 or n == 4:\\n        return (2 * (n - 2)) if (n - 2) in primes else 0\\n    m, s = n \\/\\/ 2, n % 4 == 0\\n    return next(((m + i) * (m - i) for i in range(s, m, 2) if {m + i, m - i} < primes), 0)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1251\\/C:\\nYou are given a huge integer $a$ consisting of $n$ digits ($n$ is between $1$ and $3 \\\\cdot 10^5$, inclusive). It may contain leading zeros.\\n\\nYou can swap two digits on adjacent (neighboring) positions if the swapping digits are of different parity (that is, they have different remainders when divided by $2$). \\n\\nFor example, if $a = 032867235$ you can get the following integers in a single operation:   $302867235$ if you swap the first and the second digits;  $023867235$ if you swap the second and the third digits;  $032876235$ if you swap the fifth and the sixth digits;  $032862735$ if you swap the sixth and the seventh digits;  $032867325$ if you swap the seventh and the eighth digits. \\n\\nNote, that you can't swap digits on positions $2$ and $4$ because the positions are not adjacent. Also, you can't swap digits on positions $3$ and $4$ because the digits have the same parity.\\n\\nYou can perform any number (possibly, zero) of such operations.\\n\\nFind the minimum integer you can obtain.\\n\\nNote that the resulting integer also may contain leading zeros.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases in the input.\\n\\nThe only line of each test case contains the integer $a$, its length $n$ is between $1$ and $3 \\\\cdot 10^5$, inclusive.\\n\\nIt is guaranteed that the sum of all values $n$ does not exceed $3 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case print line — the minimum integer you can obtain.\\n\\n\\n-----Example-----\\nInput\\n3\\n0709\\n1337\\n246432\\n\\nOutput\\n0079\\n1337\\n234642\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, you can perform the following sequence of operations (the pair of swapped digits is highlighted): $0 \\\\underline{\\\\textbf{70}} 9 \\\\rightarrow 0079$.\\n\\nIn the second test case, the initial integer is optimal. \\n\\nIn the third test case you can perform the following sequence of operations: $246 \\\\underline{\\\\textbf{43}} 2 \\\\rightarrow 24 \\\\underline{\\\\textbf{63}}42 \\\\rightarrow 2 \\\\underline{\\\\textbf{43}} 642 \\\\rightarrow 234642$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# PARITY'S RELATIVE POSITION DOESN'T CHANGE! (PROBLEM C)\\ndef solve1(s):\\n    # return list\\n    evens = [u for u in s if u % 2 == 0]\\n    odds  = [u for u in s if u % 2 == 1]\\n    if len(odds) == 0:\\n        return evens\\n    ans = []\\n    inserted_odd = 0\\n    current_odd = odds[inserted_odd]\\n    for i in range(len(evens)):\\n        while current_odd < evens[i] and inserted_odd < len(odds):\\n            ans.append(current_odd)\\n            inserted_odd += 1\\n            if inserted_odd < len(odds):\\n                current_odd = odds[inserted_odd]\\n        ans.append(evens[i])\\n    while inserted_odd < len(odds):\\n        ans.append(current_odd)\\n        inserted_odd += 1\\n        if inserted_odd < len(odds):\\n            current_odd = odds[inserted_odd]\\n    return ans\\n\\ndef solve2(s):\\n    # return list\\n    # lazy code lmao\\n    odds = [u for u in s if u % 2 == 0]\\n    evens  = [u for u in s if u % 2 == 1]\\n    if len(odds) == 0:\\n        return evens\\n    ans = []\\n    inserted_odd = 0\\n    current_odd = odds[inserted_odd]\\n    for i in range(len(evens)):\\n        while current_odd < evens[i] and inserted_odd < len(odds):\\n            ans.append(current_odd)\\n            inserted_odd += 1\\n            if inserted_odd < len(odds):\\n                current_odd = odds[inserted_odd]\\n        ans.append(evens[i])\\n    while inserted_odd < len(odds):\\n        ans.append(current_odd)\\n        inserted_odd += 1\\n        if inserted_odd < len(odds):\\n            current_odd = odds[inserted_odd]\\n    return ans\\n\\nfor _ in range(int(input())):\\n    s = list(map(int, list(input())))\\n    ans = min(solve1(s), solve2(s))\\n    print (''.join(map(str, ans)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are N mountains ranging from east to west, and an ocean to the west.\\nAt the top of each mountain, there is an inn. You have decided to choose where to stay from these inns.\\nThe height of the i-th mountain from the west is H_i.\\nYou can certainly see the ocean from the inn at the top of the westmost mountain.\\nFor the inn at the top of the i-th mountain from the west (i = 2, 3, ..., N), you can see the ocean if and only if H_1 \\\\leq H_i, H_2 \\\\leq H_i, ..., and H_{i-1} \\\\leq H_i.\\nFrom how many of these N inns can you see the ocean?\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq N \\\\leq 20\\n - 1 \\\\leq H_i \\\\leq 100\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nH_1 H_2 ... H_N\\n\\n-----Output-----\\nPrint the number of inns from which you can see the ocean.\\n\\n-----Sample Input-----\\n4\\n6 5 6 8\\n\\n-----Sample Output-----\\n3\\n\\nYou can see the ocean from the first, third and fourth inns from the west.\",\"targets\":\"n = int(input())\\nL = list(map(int,input().split()))\\nm = 0\\ncnt = 0\\nfor l in L:\\n  if m <= l:\\n    m = l\\n    cnt += 1\\nprint(cnt)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a sequence $A_1, A_2, \\\\ldots, A_N$. You want all the elements of the sequence to be equal. In order to achieve that, you may perform zero or more moves. In each move, you must choose an index $i$ ($1 \\\\le i \\\\le N$), then choose $j = i-1$ or $j = i+1$ (it is not allowed to choose $j = 0$ or $j = N+1$) and change the value of $A_i$ to $A_j$ — in other words, you should replace the value of one element of the sequence by one of its adjacent elements.\\nWhat is the minimum number of moves you need to make in order to make all the elements of the sequence equal?\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $N$.\\n- The second line contains $N$ space-separated integers $A_1, A_2, \\\\ldots, A_N$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer — the minimum required number of moves.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 100$\\n- $1 \\\\le N \\\\le 100$\\n- $1 \\\\le A_i \\\\le 100$ for each valid $i$\\n\\n-----Example Input-----\\n3\\n5\\n1 1 1 1 1\\n4\\n9 8 1 8\\n2\\n1 9\\n\\n-----Example Output-----\\n0\\n2\\n1\\n\\n-----Explanation-----\\nExample case 1: No moves are needed since all the elements are already equal.\\nExample case 3: We can perform one move on either $A_1$ or $A_2$.\",\"targets\":\"t=int(input())\\nfor i in range(t):\\n n=int(input())\\n a=input().split()\\n b=set(a)\\n ma=0\\n for j in b:\\n  p=a.count(j)\\n  if(ma<p):\\n   ma=p\\n print(n-ma)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nArkady needs your help again! This time he decided to build his own high-speed Internet exchange point. It should consist of n nodes connected with minimum possible number of wires into one network (a wire directly connects two nodes). Exactly k of the nodes should be exit-nodes, that means that each of them should be connected to exactly one other node of the network, while all other nodes should be connected to at least two nodes in order to increase the system stability.\\n\\nArkady wants to make the system as fast as possible, so he wants to minimize the maximum distance between two exit-nodes. The distance between two nodes is the number of wires a package needs to go through between those two nodes.\\n\\nHelp Arkady to find such a way to build the network that the distance between the two most distant exit-nodes is as small as possible.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and k (3 ≤ n ≤ 2·10^5, 2 ≤ k ≤ n - 1) — the total number of nodes and the number of exit-nodes.\\n\\nNote that it is always possible to build at least one network with n nodes and k exit-nodes within the given constraints.\\n\\n\\n-----Output-----\\n\\nIn the first line print the minimum possible distance between the two most distant exit-nodes. In each of the next n - 1 lines print two integers: the ids of the nodes connected by a wire. The description of each wire should be printed exactly once. You can print wires and wires' ends in arbitrary order. The nodes should be numbered from 1 to n. Exit-nodes can have any ids.\\n\\nIf there are multiple answers, print any of them.\\n\\n\\n-----Examples-----\\nInput\\n3 2\\n\\nOutput\\n2\\n1 2\\n2 3\\n\\nInput\\n5 3\\n\\nOutput\\n3\\n1 2\\n2 3\\n3 4\\n3 5\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the only network is shown on the left picture.\\n\\nIn the second example one of optimal networks is shown on the right picture.\\n\\nExit-nodes are highlighted. [Image]\",\"targets\":\"n, k = map(int, input().split())\\nmid = n-k-1\\nr = [0] * k\\nfor i in range(n-1):\\n  r[i%k] += 1\\nprint(r[0]+r[1])\\nv1 = 2\\nans = []\\nfor i in range(k):\\n  v0 = 1\\n  for _ in range(r[i]):\\n    ans.append(\\\"%d %d\\\"%(v0, v1))\\n    v0 = v1\\n    v1 += 1\\nprint(\\\"\\\\n\\\".join(ans))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a binary tree, return the vertical order traversal of its nodes values.\\nFor each node at position (X, Y), its left and right children respectively will be at positions (X-1, Y-1) and (X+1, Y-1).\\nRunning a vertical line from X = -infinity to X = +infinity, whenever the vertical line touches some nodes, we report the values of the nodes in order from top to bottom (decreasing Y coordinates).\\nIf two nodes have the same position, then the value of the node that is reported first is the value that is smaller.\\nReturn an list of non-empty reports in order of X coordinate.  Every report will have a list of values of nodes.\\n \\nExample 1:\\n\\n\\nInput: [3,9,20,null,null,15,7]\\nOutput: [[9],[3,15],[20],[7]]\\nExplanation: \\nWithout loss of generality, we can assume the root node is at position (0, 0):\\nThen, the node with value 9 occurs at position (-1, -1);\\nThe nodes with values 3 and 15 occur at positions (0, 0) and (0, -2);\\nThe node with value 20 occurs at position (1, -1);\\nThe node with value 7 occurs at position (2, -2).\\n\\n\\nExample 2:\\n\\nInput: [1,2,3,4,5,6,7]\\nOutput: [[4],[2],[1,5,6],[3],[7]]\\nExplanation: \\nThe node with value 5 and the node with value 6 have the same position according to the given scheme.\\nHowever, in the report \\\"[1,5,6]\\\", the node value of 5 comes first since 5 is smaller than 6.\\n\\n \\n\\nNote:\\n\\nThe tree will have between 1 and 1000 nodes.\\nEach node's value will be between 0 and 1000.\",\"targets\":\"# Definition for a binary tree node.\\n# class TreeNode:\\n#     def __init__(self, val=0, left=None, right=None):\\n#         self.val = val\\n#         self.left = left\\n#         self.right = right\\nclass Solution:\\n    def verticalTraversal(self, root: TreeNode) -> List[List[int]]:\\n        res = []\\n        frontier = [(root, 0)]\\n        h = defaultdict(list)\\n        while frontier:\\n            next = []\\n            for u, x in frontier:\\n                h[x].append(u.val)\\n                if u.left: next.append((u.left, x-1)) \\n                if u.right: next.append((u.right, x+1))\\n                next.sort(key = lambda x: (x[1], x[0].val))\\n            frontier = next\\n        for k in sorted(h):\\n            res.append(h[k])\\n        return res\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1280\\/A:\\nWe start with a string $s$ consisting only of the digits $1$, $2$, or $3$. The length of $s$ is denoted by $|s|$. For each $i$ from $1$ to $|s|$, the $i$-th character of $s$ is denoted by $s_i$. \\n\\nThere is one cursor. The cursor's location $\\\\ell$ is denoted by an integer in $\\\\{0, \\\\ldots, |s|\\\\}$, with the following meaning:   If $\\\\ell = 0$, then the cursor is located before the first character of $s$.  If $\\\\ell = |s|$, then the cursor is located right after the last character of $s$.  If $0 < \\\\ell < |s|$, then the cursor is located between $s_\\\\ell$ and $s_{\\\\ell+1}$. \\n\\nWe denote by $s_\\\\text{left}$ the string to the left of the cursor and $s_\\\\text{right}$ the string to the right of the cursor. \\n\\nWe also have a string $c$, which we call our clipboard, which starts out as empty. There are three types of actions:  The Move action. Move the cursor one step to the right. This increments $\\\\ell$ once.  The Cut action. Set $c \\\\leftarrow s_\\\\text{right}$, then set $s \\\\leftarrow s_\\\\text{left}$.  The Paste action. Append the value of $c$ to the end of the string $s$. Note that this doesn't modify $c$. \\n\\nThe cursor initially starts at $\\\\ell = 0$. Then, we perform the following procedure:  Perform the Move action once.  Perform the Cut action once.  Perform the Paste action $s_\\\\ell$ times.  If $\\\\ell = x$, stop. Otherwise, return to step 1. \\n\\nYou're given the initial string $s$ and the integer $x$. What is the length of $s$ when the procedure stops? Since this value may be very large, only find it modulo $10^9 + 7$. \\n\\nIt is guaranteed that $\\\\ell \\\\le |s|$ at any time.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains a single integer $t$ ($1 \\\\le t \\\\le 1000$) denoting the number of test cases. The next lines contain descriptions of the test cases.\\n\\nThe first line of each test case contains a single integer $x$ ($1 \\\\le x \\\\le 10^6$). The second line of each test case consists of the initial string $s$ ($1 \\\\le |s| \\\\le 500$). It is guaranteed, that $s$ consists of the characters \\\"1\\\", \\\"2\\\", \\\"3\\\".\\n\\nIt is guaranteed that the sum of $x$...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import defaultdict as dc\\n'''from collections import deque as dq\\nfrom bisect import bisect_left,bisect_right,insort_left'''\\nimport sys\\nimport math\\n#define of c++ as inl=input()\\nmod=10**9 +7\\ndef bs(a,x):\\n    i=bisect_left(a,x)\\n    if i!=len(a):\\n        return i\\n    else:\\n        return len(a)\\ndef bs(a,b):\\n    l=a\\n    r=b+1\\n    x=b\\n    ans=0\\n    while(l<r):\\n        mid=(l+r)\\/\\/2\\n        if x|mid>ans:\\n            ans=x|mid\\n            l=mid+1\\n        else:\\n            r=mid\\n    return ans\\ndef digit(n):\\n    a=[]\\n    while(n>0):\\n        a.append(n%10)\\n        n=n\\/\\/10\\n    return a\\ndef inp():\\n    p=int(input())\\n    return p\\ndef line():\\n    p=list(map(int,input().split()))\\n    return p\\ndef ans(a,p,z,t):\\n    q=[]\\n    for i in range(len(a)):\\n        if p[a[i]]==t and z>0 and p[a[i][::-1]]==0:\\n            q.append(i+1)\\n            z=z-1\\n    return q\\n            \\nfor i in range(inp()):\\n    x=inp()\\n    s=str(input())\\n    n=len(s)\\n    p=n\\n    for i in range(1,x+1):\\n        if s[i-1]!='1':\\n            p=(p%mod+((p-i)%mod * (int(s[i-1])-1)%mod)%mod)%mod\\n            if len(s)<x:\\n                z=s[i:]\\n                s=s+z*(int(s[i-1])-1)\\n    print(p)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58e0bd6a79716b7fcf0013b1:\\nCreate a function that takes in the sum and age difference of two people, calculates their individual ages, and returns a pair of values (oldest age first) if those exist or `null\\/None` if:\\n\\n* `sum < 0`\\n* `difference < 0`\\n* Either of the calculated ages come out to be negative\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"get_ages=lambda s,d:(lambda*a:None if any(x<0for x in(*a,s,d))else a)((s+d)\\/2,(s-d)\\/2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an array of distinct positive integers locations where locations[i] represents the position of city i. You are also given integers start, finish and fuel representing the starting city, ending city, and the initial amount of fuel you have, respectively.\\nAt each step, if you are at city i, you can pick any city j such that j != i and 0 <= j < locations.length and move to city j. Moving from city i to city j reduces the amount of fuel you have by |locations[i] - locations[j]|. Please notice that |x| denotes the absolute value of x.\\nNotice that fuel cannot become negative at any point in time, and that you are allowed to visit any city more than once (including start and finish).\\nReturn the count of all possible routes from start to finish.\\nSince the answer may be too large, return it modulo 10^9 + 7.\\n \\nExample 1:\\nInput: locations = [2,3,6,8,4], start = 1, finish = 3, fuel = 5\\nOutput: 4\\nExplanation: The following are all possible routes, each uses 5 units of fuel:\\n1 -> 3\\n1 -> 2 -> 3\\n1 -> 4 -> 3\\n1 -> 4 -> 2 -> 3\\n\\nExample 2:\\nInput: locations = [4,3,1], start = 1, finish = 0, fuel = 6\\nOutput: 5\\nExplanation: The following are all possible routes:\\n1 -> 0, used fuel = 1\\n1 -> 2 -> 0, used fuel = 5\\n1 -> 2 -> 1 -> 0, used fuel = 5\\n1 -> 0 -> 1 -> 0, used fuel = 3\\n1 -> 0 -> 1 -> 0 -> 1 -> 0, used fuel = 5\\n\\nExample 3:\\nInput: locations = [5,2,1], start = 0, finish = 2, fuel = 3\\nOutput: 0\\nExplanation: It's impossible to get from 0 to 2 using only 3 units of fuel since the shortest route needs 4 units of fuel.\\nExample 4:\\nInput: locations = [2,1,5], start = 0, finish = 0, fuel = 3\\nOutput: 2\\nExplanation: There are two possible routes, 0 and 0 -> 1 -> 0.\\nExample 5:\\nInput: locations = [1,2,3], start = 0, finish = 2, fuel = 40\\nOutput: 615088286\\nExplanation: The total number of possible routes is 2615088300. Taking this number modulo 10^9 + 7 gives us 615088286.\\n\\n \\nConstraints:\\n\\n2 <= locations.length <= 100\\n1 <= locations[i] <= 10^9\\nAll integers in locations are distinct.\\n0 <= start, finish < locations.length\\n1 <= fuel <= 200\",\"targets\":\"class Solution:\\n    def countRoutes(self, locations: List[int], start: int, finish: int, fuel: int) -> int:\\n        dp = {}\\n        self.mode = (int)(1e9) + 7\\n        return self.dfs(fuel, start, finish, locations, dp)\\n    \\n    def dfs(self, fuel, u, target, locations, dp):\\n        if fuel < 0:\\n            return 0\\n        \\n        if (fuel, u, target) in dp:\\n            return dp[(fuel, u, target)]\\n        ans =  1 if u == target else 0\\n        for v in range(len(locations)):\\n            if u == v:\\n                continue\\n            ans += self.dfs(fuel - abs(locations[u] - locations[v]), v, target, locations, dp)\\n            ans %= self.mode\\n        dp[(fuel, u, target)] = ans\\n        return ans\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.\\n - Let s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\\\\ldots{s'}_i (the first i characters in s').\\n\\n-----Notes-----\\n - A subsequence of a string a is a string obtained by deleting zero or more characters from a and concatenating the remaining characters without changing the relative order. For example, the subsequences of contest include net, c, and contest.\\n\\n-----Constraints-----\\n - 1 \\\\leq |s| \\\\leq 10^5\\n - 1 \\\\leq |t| \\\\leq 10^5\\n - s and t consists of lowercase English letters.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\ns\\nt\\n\\n-----Output-----\\nIf there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print -1.\\n\\n-----Sample Input-----\\ncontest\\nson\\n\\n-----Sample Output-----\\n10\\n\\nt = son is a subsequence of the string contestcon (the first 10 characters in s' = contestcontestcontest...), so i = 10 satisfies the condition.\\nOn the other hand, t is not a subsequence of the string contestco (the first 9 characters in s'), so i = 9 does not satisfy the condition.\\nSimilarly, any integer less than 9 does not satisfy the condition, either. Thus, the minimum integer i satisfying the condition is 10.\",\"targets\":\"import bisect\\nS = input()\\nT = input()\\nD = dict()\\nfor i in range(len(T)):\\n    if T[i] in D:\\n        continue\\n    else:\\n        D[T[i]] = []\\nfor i in range(len(S)):\\n    if S[i] in D:\\n        D[S[i]].append(i)\\n\\nif len(set(T)-set(S))>0:\\n    print(-1)\\nelse:\\n    r = -1\\n    cnt = 0\\n    for i in range(len(T)):\\n        m = bisect.bisect_right(D[T[i]], r)\\n        if m < len(D[T[i]]):\\n            r = D[T[i]][m]\\n        else:\\n            r = D[T[i]][0]\\n            cnt += 1\\n    print(len(S)*cnt+r+1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nBeing tired of participating in too many Codeforces rounds, Gildong decided to take some rest in a park. He sat down on a bench, and soon he found two rabbits hopping around. One of the rabbits was taller than the other.\\n\\nHe noticed that the two rabbits were hopping towards each other. The positions of the two rabbits can be represented as integer coordinates on a horizontal line. The taller rabbit is currently on position $x$, and the shorter rabbit is currently on position $y$ ($x \\\\lt y$). Every second, each rabbit hops to another position. The taller rabbit hops to the positive direction by $a$, and the shorter rabbit hops to the negative direction by $b$.\\n\\n [Image] \\n\\nFor example, let's say $x=0$, $y=10$, $a=2$, and $b=3$. At the $1$-st second, each rabbit will be at position $2$ and $7$. At the $2$-nd second, both rabbits will be at position $4$.\\n\\nGildong is now wondering: Will the two rabbits be at the same position at the same moment? If so, how long will it take? Let's find a moment in time (in seconds) after which the rabbits will be at the same point.\\n\\n\\n-----Input-----\\n\\nEach test contains one or more test cases. The first line contains the number of test cases $t$ ($1 \\\\le t \\\\le 1000$).\\n\\nEach test case contains exactly one line. The line consists of four integers $x$, $y$, $a$, $b$ ($0 \\\\le x \\\\lt y \\\\le 10^9$, $1 \\\\le a,b \\\\le 10^9$) — the current position of the taller rabbit, the current position of the shorter rabbit, the hopping distance of the taller rabbit, and the hopping distance of the shorter rabbit, respectively.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the single integer: number of seconds the two rabbits will take to be at the same position.\\n\\nIf the two rabbits will never be at the same position simultaneously, print $-1$.\\n\\n\\n-----Example-----\\nInput\\n5\\n0 10 2 3\\n0 10 3 3\\n900000000 1000000000 1 9999999\\n1 2 1 1\\n1 3 1 1\\n\\nOutput\\n2\\n-1\\n10\\n-1\\n1\\n\\n\\n\\n-----Note-----\\n\\nThe first case is explained in the description.\\n\\nIn the second case, each rabbit will be at position $3$ and $7$ respectively at the...\",\"targets\":\"for _ in range(int(input())):\\n\\tx, y, a, b = list(map(int, input().split()))\\n\\t\\n\\tt = (y - x) \\/ (a + b)\\n\\ttz = (y - x) \\/\\/ (a + b)\\n\\n\\tif t != tz:\\n\\t\\tprint(-1)\\n\\telse:\\n\\t\\tprint(tz)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYour task is to find the number couple with the greatest difference from a given array of number-couples. \\n\\nAll number couples will be given as strings and all numbers in them will be positive integers.  \\n\\nFor instance: ['56-23','1-100']; in this case, you should identify '1-100' as the number couple with the greatest difference and return it.\\n\\nIn case there are more than one option, for instance ['1-3','5-7','2-3'], you should identify whichever is first, so in this case '1-3'. \\n\\nIf there is no difference, like so ['11-11', '344-344'], return false.\",\"targets\":\"def diff(arr):\\n    r = [abs(eval(s)) for s in arr]\\n    return arr[r.index(max(r))] if r and max(r) else False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have N balls. The i-th ball has an integer A_i written on it.\\n\\nFor each k=1, 2, ..., N, solve the following problem and print the answer.  \\n - Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.\\n\\n-----Constraints-----\\n - 3 \\\\leq N \\\\leq 2 \\\\times 10^5\\n - 1 \\\\leq A_i \\\\leq N\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 A_2 ... A_N\\n\\n-----Output-----\\nFor each k=1,2,...,N, print a line containing the answer.\\n\\n-----Sample Input-----\\n5\\n1 1 2 1 2\\n\\n-----Sample Output-----\\n2\\n2\\n3\\n2\\n3\\n\\nConsider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.\\n\\nFrom these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.\\n\\nThus, the answer for k=1 is 2.\",\"targets\":\"n = int(input())\\na = [int(i) for i in input().split()]\\ndic = {}\\nfor i in range(n):\\n  dic[i+1] = 0\\nfor ai in a:\\n  dic[ai] += 1\\ncnt = 0\\nfor di in dic:\\n  cnt += dic[di] * (dic[di] - 1) \\/\\/ 2\\nfor i in range(n):\\n  print(cnt - dic[a[i]] * (dic[a[i]] - 1) \\/\\/ 2 + (dic[a[i]] - 2) * (dic[a[i]] - 1) \\/\\/ 2)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYour friend has been out shopping for puppies (what a time to be alive!)... He arrives back with multiple dogs, and you simply do not know how to respond!\\n\\nBy repairing the function provided, you will find out exactly how you should respond, depending on the number of dogs he has.\\n\\nThe number of dogs will always be a number and there will always be at least 1 dog.\\n\\n```r\\nThe expected behaviour is as follows:\\n- Your friend has fewer than 10 dogs:                    \\\"Hardly any\\\"\\n- Your friend has at least 10 but fewer than 51 dogs:    \\\"More than a handful!\\\"\\n- Your friend has at least 51 but not exactly 101 dogs:  \\\"Woah that's a lot of dogs!\\\"\\n- Your friend has 101 dogs:                              \\\"101 DALMATIANS!!!\\\"\\n\\nYour friend will always have between 1 and 101 dogs, inclusive.\\n```\",\"targets\":\"def how_many_dalmatians(n):\\n  dogs = [\\\"Hardly any\\\", \\\"More than a handful!\\\", \\\"Woah that's a lot of dogs!\\\", \\\"101 DALMATIONS!!!\\\"];\\n  return dogs[(n>10)+(n>50)+(n==101)]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan).\\nIn how many ways can we select some of these coins so that they are X yen in total?\\nCoins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.\\n\\n-----Constraints-----\\n - 0 \\\\leq A, B, C \\\\leq 50\\n - A + B + C \\\\geq 1\\n - 50 \\\\leq X \\\\leq 20 000\\n - A, B and C are integers.\\n - X is a multiple of 50.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA\\nB\\nC\\nX\\n\\n-----Output-----\\nPrint the number of ways to select coins.\\n\\n-----Sample Input-----\\n2\\n2\\n2\\n100\\n\\n-----Sample Output-----\\n2\\n\\nThere are two ways to satisfy the condition:\\n - Select zero 500-yen coins, one 100-yen coin and zero 50-yen coins.\\n - Select zero 500-yen coins, zero 100-yen coins and two 50-yen coins.\",\"targets\":\"a = int(input())\\nb = int(input())\\nc = int(input())\\nx = int(input())\\n\\ncnt = 0\\n\\nfor i in range(a+1):\\n    for j in range(b+1):\\n        for k in range(c+1):\\n            if 500*i + 100*j + 50*k == x:\\n                cnt += 1\\n\\nprint(cnt)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/585cec2471677ee42c000296:\\nEver heard about Dijkstra's shallowest path algorithm? Me neither. But I can imagine what it would be.\\n\\nYou're hiking in the wilderness of Northern Canada and you must cross a large river. You have a map of one of the safer places to cross the river showing the depths of the water on a rectangular grid. When crossing the river you can only move from a cell to one of the (up to 8) neighboring cells. You can start anywhere along the left river bank, but you have to stay on the map.\\n\\nAn example of the depths provided on the map is \\n\\n```\\n[[2, 3, 2],\\n [1, 1, 4],\\n [9, 5, 2],\\n [1, 4, 4],\\n [1, 5, 4],\\n [2, 1, 4],\\n [5, 1, 2],\\n [5, 5, 5],\\n [8, 1, 9]]\\n```\\nIf you study these numbers, you'll see that there is a path accross the river (from left to right) where the depth never exceeds 2. This path can be described by the list of pairs `[(1, 0), (1, 1), (2, 2)]`. There are also other paths of equal maximum depth, e.g., `[(1, 0), (1, 1), (0, 2)]`. The pairs denote the cells on the path where the first element in each pair is the row and the second element is the column of a cell on the path.\\n\\nYour job is to write a function `shallowest_path(river)` that takes a list of lists of positive ints (or array of arrays, depending on language) showing the depths of the river as shown in the example above and returns a shallowest path (i.e., the maximum depth is minimal) as a list of coordinate pairs (represented as tuples, Pairs, or arrays, depending on language) as described above. If there are several paths that are equally shallow, the function shall return a shortest such path. All depths are given as positive integers.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from heapq import *\\n\\nMOVES = tuple( (dx,dy) for dx in range(-1,2) for dy in range(-1,2) if dx or dy)\\n\\n\\ndef shallowest_path(river):\\n\\n    lX,lY   = len(river), len(river[0])\\n    pathDct = {}\\n    cost    = [ [(float('inf'),float('inf'))]*lY for _ in range(lX) ]\\n    for x in range(lX): cost[x][0] = (river[x][0],1)\\n    \\n    q = [ (river[x][0], lY==1, 1, (x,0)) for x in range(lX)]\\n    heapify(q)\\n    \\n    while not q[0][1]:\\n        c,_,steps,pos = heappop(q)\\n        x,y = pos\\n        for dx,dy in MOVES:\\n            a,b = new = x+dx,y+dy\\n            if 0<=a<lX and 0<=b<lY: \\n                check = nC,nS = max(c, river[a][b]), steps+1\\n                if cost[a][b] > check:\\n                    cost[a][b] = check\\n                    pathDct[new] = pos\\n                    heappush(q, (nC, b==lY-1, nS, new))\\n    \\n    path, pos = [], q[0][-1]\\n    while pos:\\n        path.append(pos)\\n        pos = pathDct.get(pos)\\n    return path[::-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/filling-bookcase-shelves\\/:\\nWe have a sequence of books: the i-th book has thickness books[i][0] and height books[i][1].\\nWe want to place these books in order onto bookcase shelves that have total width shelf_width.\\nWe choose some of the books to place on this shelf (such that the sum of their thickness is <= shelf_width), then build another level of shelf of the bookcase so that the total height of the bookcase has increased by the maximum height of the books we just put down.  We repeat this process until there are no more books to place.\\nNote again that at each step of the above process, the order of the books we place is the same order as the given sequence of books.  For example, if we have an ordered list of 5 books, we might place the first and second book onto the first shelf, the third book on the second shelf, and the fourth and fifth book on the last shelf.\\nReturn the minimum possible height that the total bookshelf can be after placing shelves in this manner.\\n \\nExample 1:\\n\\nInput: books = [[1,1],[2,3],[2,3],[1,1],[1,1],[1,1],[1,2]], shelf_width = 4\\nOutput: 6\\nExplanation:\\nThe sum of the heights of the 3 shelves are 1 + 3 + 2 = 6.\\nNotice that book number 2 does not have to be on the first shelf.\\n\\n \\nConstraints:\\n\\n1 <= books.length <= 1000\\n1 <= books[i][0] <= shelf_width <= 1000\\n1 <= books[i][1] <= 1000\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def minHeightShelves(self, books: List[List[int]], shelf_width: int) -> int:\\n        # n = len(books)\\n        # @lru_cache(None)\\n        # def dfs(i, w, h):\\n        #     if i >= n:\\n        #         return h\\n        #     return min(h + dfs(i + 1, books[i][0], books[i][1]), float('inf') if w + books[i][0] > shelf_width else dfs(i + 1, w + books[i][0], max(h, books[i][1])))\\n        # return dfs(0, 0, 0)\\n        \\n        n = len(books)\\n        dp = [0] + [float('inf')] * n\\n        for p in range(1, n + 1):\\n            i = p\\n            w = h = 0\\n            while i > 0 and w + books[i-1][0] <= shelf_width:\\n                w += books[i-1][0]\\n                h = max(h, books[i-1][1])\\n                dp[p] = min(dp[p], dp[i-1] + h)\\n                i -= 1\\n        return dp[-1]\\n        \\n        \\n        # n = len(books)\\n        # dp = [0] + [float('inf')] * n\\n        # for p in range(1, n + 1):\\n        #     i = p\\n        #     w = h = 0\\n        #     while i > 0 and w + books[i-1][0] <= shelf_width:\\n        #         w += books[i-1][0]\\n        #         h = max(h, books[i-1][1])\\n        #         dp[p] = min(dp[p], dp[i-1]+h)\\n        #         i -= 1\\n        # return dp[-1]\\n        \\n        # n = len(books)\\n        # @lru_cache(None)\\n        # def dfs(i, w, h):\\n        #     if i >= n:\\n        #         return h\\n        #     return min(h + dfs(i + 1, books[i][0], books[i][1]), float('inf') if w + books[i][0] > shelf_width else dfs(i + 1, w + books[i][0], max(h, books[i][1])))\\n        # return dfs(0, 0, 0)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/269\\/B:\\nEmuskald is an avid horticulturist and owns the world's longest greenhouse — it is effectively infinite in length.\\n\\nOver the years Emuskald has cultivated n plants in his greenhouse, of m different plant species numbered from 1 to m. His greenhouse is very narrow and can be viewed as an infinite line, with each plant occupying a single point on that line.\\n\\nEmuskald has discovered that each species thrives at a different temperature, so he wants to arrange m - 1 borders that would divide the greenhouse into m sections numbered from 1 to m from left to right with each section housing a single species. He is free to place the borders, but in the end all of the i-th species plants must reside in i-th section from the left.\\n\\nOf course, it is not always possible to place the borders in such way, so Emuskald needs to replant some of his plants. He can remove each plant from its position and place it anywhere in the greenhouse (at any real coordinate) with no plant already in it. Since replanting is a lot of stress for the plants, help Emuskald find the minimum number of plants he has to replant to be able to place the borders.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains two space-separated integers n and m (1 ≤ n, m ≤ 5000, n ≥ m), the number of plants and the number of different species. Each of the following n lines contain two space-separated numbers: one integer number s_{i} (1 ≤ s_{i} ≤ m), and one real number x_{i} (0 ≤ x_{i} ≤ 10^9), the species and position of the i-th plant. Each x_{i} will contain no more than 6 digits after the decimal point.\\n\\nIt is guaranteed that all x_{i} are different; there is at least one plant of each species; the plants are given in order \\\"from left to the right\\\", that is in the ascending order of their x_{i} coordinates (x_{i} < x_{i} + 1, 1 ≤ i < n).\\n\\n\\n-----Output-----\\n\\nOutput a single integer — the minimum number of plants to be replanted.\\n\\n\\n-----Examples-----\\nInput\\n3 2\\n2 1\\n1 2.0\\n1 3.100\\n\\nOutput\\n1\\n\\nInput\\n3 3\\n1 5.0\\n2 5.5\\n3 6.0\\n\\nOutput\\n0\\n\\nInput\\n6 3\\n1 14.284235\\n2...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"numbers, types = list(map(int, input().split()))\\n\\nposition = [0] * (numbers)\\nbinary_search_array = [1] * (numbers)\\n\\nfor i in range(numbers):\\n    position[i] = int(input().split()[0])\\n\\nmax_length = int(0)\\n\\nfor i in range(numbers):\\n    low = int(0)\\n    high = int(max_length)\\n\\n    while (low < high):\\n        mid = int((low + high) \\/ 2)\\n        if (binary_search_array[mid] <= position[i]):\\n            low = mid + 1\\n        else:\\n            high = mid\\n\\n    binary_search_array[low] = position[i]\\n    if (low == max_length):\\n        max_length += 1\\n\\n\\nprint(numbers - max_length)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/598\\/F:\\nGiven simple (without self-intersections) n-gon. It is not necessary convex. Also you are given m lines. For each line find the length of common part of the line and the n-gon.\\n\\nThe boundary of n-gon belongs to polygon. It is possible that n-gon contains 180-degree angles.\\n\\n\\n-----Input-----\\n\\nThe first line contains integers n and m (3 ≤ n ≤ 1000;1 ≤ m ≤ 100). The following n lines contain coordinates of polygon vertices (in clockwise or counterclockwise direction). All vertices are distinct.\\n\\nThe following m lines contain line descriptions. Each of them contains two distict points of a line by their coordinates.\\n\\nAll given in the input coordinates are real numbers, given with at most two digits after decimal point. They do not exceed 10^5 by absolute values.\\n\\n\\n-----Output-----\\n\\nPrint m lines, the i-th line should contain the length of common part of the given n-gon and the i-th line. The answer will be considered correct if the absolute or relative error doesn't exceed 10^{ - 6}.\\n\\n\\n-----Examples-----\\nInput\\n4 3\\n0 0\\n1 0\\n1 1\\n0 1\\n0 0 1 1\\n0 0 0 1\\n0 0 1 -1\\n\\nOutput\\n1.41421356237309514547\\n1.00000000000000000000\\n0.00000000000000000000\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\n \\neps = 1e-9\\n \\ndef sign(n):\\n    if n > eps: return 1\\n    if n < -eps: return -1\\n    return 0\\n \\ndef cross(a, b):\\n    return a.x * b.y - a.y * b.x\\n \\nclass Vector:\\n    def __init__(self, x, y):\\n        self.x = x\\n        self.y = y\\n \\n    def __add__(self, v):\\n        return Vector(self.x + v.x, self.y + v.y)\\n    \\n    def __sub__(self, v):\\n        return Vector(self.x - v.x, self.y - v.y)\\n    \\n    def length(self):\\n        return math.hypot(self.x, self.y)\\n \\ndef solve(polygon, p, q):\\n    intersections = []\\n    for (a, b) in zip(polygon, polygon[1:] + polygon[:1]):\\n        ss = sign(cross(a - p, q - p))\\n        es = sign(cross(b - p, q - p))\\n \\n        if ss == es: continue\\n \\n        t = cross(a - p, a - b) \\/ cross(q - p, a - b)\\n        intersections.append((t, es - ss))\\n    intersections = sorted(intersections)\\n    total_t, previous_t, count = [0] * 3\\n    \\n    for t, order in intersections:\\n        if (count > 0): total_t += t - previous_t\\n        previous_t = t\\n        count += order\\n    # print(total_t) \\n \\n    print(total_t * (q - p).length())\\n    \\nn, m = map(int, input().split())\\n \\npolygon = []\\nfor i in range(n):\\n    x, y = map(float, input().split())\\n    polygon.append(Vector(x, y))\\narea = sum(map(lambda x: cross(x[0], x[1]), zip(polygon, polygon[1:] + polygon[:1])))\\nif (area < 0): polygon.reverse()\\n \\nfor i in range(m):\\n    x1, y1, x2, y2 = map(float, input().split())\\n    solve(polygon, Vector(x1, y1), Vector(x2, y2))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWrite a program to determine if two numbers are coprime. A pair of numbers are coprime if their greatest shared factor is 1. For example:\\n```\\n20 and 27\\nFactors of 20: 1, 2, 4, 5, 10, 20\\nFactors of 27: 1, 3, 9, 27\\nGreatest shared factor: 1\\n20 and 27 are coprime```\\nAn example of two numbers that are not coprime:\\n```\\n12 and 39\\nFactors of 12: 1, 2, 3, 4, 6, 12\\nFactors of 39: 1, 3, 13, 39\\nGreatest shared factor: 3\\n12 and 39 are not coprime```\\nIf the two inputs are coprime, your program should return true. If they are not coprime, your program should return false.\\n\\nThe inputs will always be two positive integers between 2 and 99.\",\"targets\":\"are_coprime=lambda*a:__import__('fractions').gcd(*a)<2\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\\nYou can take and complete at most one of these jobs in a day.\\nHowever, you cannot retake a job that you have already done.\\nFind the maximum total reward that you can earn no later than M days from today.\\nYou can already start working today.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq M \\\\leq 10^5\\n - 1 \\\\leq A_i \\\\leq 10^5\\n - 1 \\\\leq B_i \\\\leq 10^4\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M\\nA_1 B_1\\nA_2 B_2\\n\\\\vdots\\nA_N B_N\\n\\n-----Output-----\\nPrint the maximum total reward that you can earn no later than M days from today.\\n\\n-----Sample Input-----\\n3 4\\n4 3\\n4 1\\n2 2\\n\\n-----Sample Output-----\\n5\\n\\nYou can earn the total reward of 5 by taking the jobs as follows:\\n - Take and complete the first job today. You will earn the reward of 3 after four days from today.\\n - Take and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\",\"targets\":\"import sys, math\\nfrom functools import lru_cache\\nimport numpy as np\\nimport heapq\\nfrom collections import defaultdict\\nsys.setrecursionlimit(10**9)\\nMOD = 10**9+7\\n\\ndef input():\\n    return sys.stdin.readline()[:-1]\\n\\ndef mi():\\n    return list(map(int, input().split()))\\n\\ndef ii():\\n    return int(input())\\n\\ndef i2(n):\\n    tmp = [list(mi()) for i in range(n)]\\n    return [list(i) for i in zip(*tmp)]\\n\\n\\ndef lcm(a, b):\\n    return a*b\\/\\/math.gcd(a, b)\\n\\n\\ndef main():\\n    N, M = mi()\\n    A, B = i2(N)\\n    ans = 0\\n\\n    d = defaultdict(list)\\n    for i in range(N):\\n        d[A[i]].append(B[i])\\n\\n    h = []\\n    heapq.heapify(h)\\n\\n    for i in range(1, M+1):\\n        for v in d[i]:\\n            heapq.heappush(h, -v)\\n        if h:\\n            ans -= heapq.heappop(h)\\n        else:\\n            continue\\n\\n    print(ans)\\n\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nRecently Vladik discovered a new entertainment — coding bots for social networks. He would like to use machine learning in his bots so now he want to prepare some learning data for them.\\n\\nAt first, he need to download t chats. Vladik coded a script which should have downloaded the chats, however, something went wrong. In particular, some of the messages have no information of their sender. It is known that if a person sends several messages in a row, they all are merged into a single message. It means that there could not be two or more messages in a row with the same sender. Moreover, a sender never mention himself in his messages.\\n\\nVladik wants to recover senders of all the messages so that each two neighboring messages will have different senders and no sender will mention himself in his messages.\\n\\nHe has no idea of how to do this, and asks you for help. Help Vladik to recover senders in each of the chats!\\n\\n\\n-----Input-----\\n\\nThe first line contains single integer t (1 ≤ t ≤ 10) — the number of chats. The t chats follow. Each chat is given in the following format.\\n\\nThe first line of each chat description contains single integer n (1 ≤ n ≤ 100) — the number of users in the chat.\\n\\nThe next line contains n space-separated distinct usernames. Each username consists of lowercase and uppercase English letters and digits. The usernames can't start with a digit. Two usernames are different even if they differ only with letters' case. The length of username is positive and doesn't exceed 10 characters.\\n\\nThe next line contains single integer m (1 ≤ m ≤ 100) — the number of messages in the chat. The next m line contain the messages in the following formats, one per line:   <username>:<text> — the format of a message with known sender. The username should appear in the list of usernames of the chat.  <?>:<text> — the format of a message with unknown sender. \\n\\nThe text of a message can consist of lowercase and uppercase English letter, digits, characters '.' (dot), ',' (comma), '!' (exclamation mark), '?' (question...\",\"targets\":\"import re\\nt = int(input())\\nfor _ in range(t):\\n    n = int(input())\\n    names = set(input().split())\\n    m = int(input())\\n    dp = []\\n    a = []\\n    for i in range(m): a.append(input())\\n    for i in range(m):\\n        sender, msg = a[i].split(':')\\n        ls = set([_f for _f in re.split('\\\\W+',msg) if _f])\\n        dp.append((names if sender == '?' else set([sender])) - ls)\\n        if i and len(dp[i-1]) == 1: dp[i] -= dp[i-1]\\n        # print(dp[i]);\\n    if any([len(p) == 0 for p in dp]): print(\\\"Impossible\\\")\\n    else:\\n        res = []\\n        for i in reversed(list(range(m))):\\n            res.append(dp[i].pop())\\n            if i > 0: dp[i-1].discard(res[-1])\\n        for i in range(m): \\n            sender, msg = a[i].split(':')\\n            sender = res[m-i-1]\\n            print(sender+':'+msg)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nEach test case will generate a variable whose value is 777. Find the name of the variable.\",\"targets\":\"def find_variable():\\n    for i in globals():\\n        if eval(i) == 777:\\n            return i\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1409\\/B:\\nYou are given four integers $a$, $b$, $x$ and $y$. Initially, $a \\\\ge x$ and $b \\\\ge y$. You can do the following operation no more than $n$ times:\\n\\n  Choose either $a$ or $b$ and decrease it by one. However, as a result of this operation, value of $a$ cannot become less than $x$, and value of $b$ cannot become less than $y$. \\n\\nYour task is to find the minimum possible product of $a$ and $b$ ($a \\\\cdot b$) you can achieve by applying the given operation no more than $n$ times.\\n\\nYou have to answer $t$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 2 \\\\cdot 10^4$) — the number of test cases. Then $t$ test cases follow.\\n\\nThe only line of the test case contains five integers $a$, $b$, $x$, $y$ and $n$ ($1 \\\\le a, b, x, y, n \\\\le 10^9$). Additional constraint on the input: $a \\\\ge x$ and $b \\\\ge y$ always holds.\\n\\n\\n-----Output-----\\n\\nFor each test case, print one integer: the minimum possible product of $a$ and $b$ ($a \\\\cdot b$) you can achieve by applying the given operation no more than $n$ times.\\n\\n\\n-----Example-----\\nInput\\n7\\n10 10 8 5 3\\n12 8 8 7 2\\n12343 43 4543 39 123212\\n1000000000 1000000000 1 1 1\\n1000000000 1000000000 1 1 1000000000\\n10 11 2 1 5\\n10 11 9 1 10\\n\\nOutput\\n70\\n77\\n177177\\n999999999000000000\\n999999999\\n55\\n10\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case of the example, you need to decrease $b$ three times and obtain $10 \\\\cdot 7 = 70$.\\n\\nIn the second test case of the example, you need to decrease $a$ one time, $b$ one time and obtain $11 \\\\cdot 7 = 77$.\\n\\nIn the sixth test case of the example, you need to decrease $a$ five times and obtain $5 \\\\cdot 11 = 55$.\\n\\nIn the seventh test case of the example, you need to decrease $b$ ten times and obtain $10 \\\\cdot 1 = 10$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def find(a,b,x,y,n):\\n    req = a-x\\n    min_val = min(req,n)\\n    a -= min_val\\n    n -= min_val\\n    b -= n\\n\\n    return a*b\\n\\ndef solve(a,b,x,y,n,ans):\\n    req1 = a-x\\n    req2 = b-y\\n    if req1+req2 <= n:\\n        a = x\\n        b = y\\n        ans.append(str(a*b))\\n    else:\\n        min_val = find(a,b,x,y,n)\\n        min_val = min(min_val,find(b,a,y,x,n))\\n        ans.append(str(min_val))\\n\\ndef main():\\n    t = int(input())\\n    ans = []\\n    for i in range(t):\\n        a,b,x,y,n = list(map(int,input().split()))\\n        solve(a,b,x,y,n,ans)\\n\\n    print('\\\\n'.join(ans))\\n    \\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIs the MRP of my new shoes exclusive or inclusive of taxes?\\n\\n-----Input:-----\\n- First line will contain an integer $P$\\n\\n-----Output:-----\\nFor each testcase, print either 'Inclusive' or 'Exclusive' without quotes.\\n\\n-----Constraints-----\\n- $100 \\\\leq P \\\\leq 999$\\n\\n-----Sample Input 1:-----\\n123\\n\\n-----Sample Output 1:-----\\nExclusive\\n\\n-----Sample Input 2:-----\\n111\\n\\n-----Sample Output 2:-----\\nInclusive\",\"targets\":\"n = input()\\nans = 0\\nfor i in n:\\n    ans = ans ^int(i)\\nif ans:\\n    print(\\\"Inclusive\\\")\\nelse:\\n    print(\\\"Exclusive\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/preimage-size-of-factorial-zeroes-function\\/:\\nLet f(x) be the number of zeroes at the end of x!. (Recall that x! = 1 * 2 * 3 * ... * x, and by convention, 0! = 1.)\\n\\nFor example, f(3) = 0 because 3! = 6 has no zeroes at the end, while f(11) = 2 because 11! = 39916800 has 2 zeroes at the end. Given K, find how many non-negative integers x have the property that f(x) = K.\\n\\n\\nExample 1:\\nInput: K = 0\\nOutput: 5\\nExplanation: 0!, 1!, 2!, 3!, and 4! end with K = 0 zeroes.\\n\\nExample 2:\\nInput: K = 5\\nOutput: 0\\nExplanation: There is no x such that x! ends in K = 5 zeroes.\\n\\n\\nNote:\\n\\n\\n       K will be an integer in the range [0, 10^9].\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def canTransform(self, start, end):\\n         \\\"\\\"\\\"\\n         :type start: str\\n         :type end: str\\n         :rtype: bool\\n         \\\"\\\"\\\"\\n         start_pair = [(i, c) for i, c in enumerate(start) if c != 'X']\\n         end_pair = [(i, c) for i, c in enumerate(end) if c != 'X']\\n         if len(start_pair) != len(end_pair):\\n             return False\\n         for (i_start, c_start), (i_end, c_end) in zip(start_pair, end_pair):\\n             if c_start != c_end or (c_start == 'L' and i_start < i_end) or (c_start == 'R' and i_start > i_end):\\n                 return False\\n         return True\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/COG2020\\/problems\\/COG2004:\\nChef has a strip of length $N$ units and he wants to tile it using $4$ kind of tiles\\n\\n-A Red tile of $2$ unit length\\n\\n-A Red tile of $1$ unit length\\n\\n-A Blue tile of $2$ unit length\\n\\n-A Blue tile of $1$ unit length   \\nChef is having an infinite supply of each of these tiles. He wants to find out the number of ways in which he can tile the strip. Help him find this number.\\nSince this number can be large, output your answer modulo 1000000007 ($10^9 + 7$).\\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase contains of a single line of input, an integer $N$. \\n\\n-----Output:-----\\nFor each testcase, output in a single line your answer modulo 1000000007.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 1000$\\n- $2 \\\\leq N \\\\leq 10^{18}$\\n\\n-----Sample Input:-----\\n1\\n2\\n\\n-----Sample Output:-----\\n6\\n\\n-----EXPLANATION:-----\\n\\nIt can be seen that for a strip of length $2$, there are $6$ possible configurations.     \\n$NOTE : $ 2 tiles of 1 unit length are different from 1 tile of 2 unit length.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from typing import List\\r\\nMatrix = List[List[int]]\\r\\n\\r\\nMOD = 10 ** 9 + 7\\r\\n\\r\\n\\r\\ndef identity(n: int) -> Matrix:\\r\\n    matrix = [[0] * n for _ in range(n)]\\r\\n\\r\\n    for i in range(n):\\r\\n        matrix[i][i] = 1\\r\\n\\r\\n    return matrix\\r\\n\\r\\n\\r\\ndef multiply(mat1: Matrix, mat2: Matrix, copy: Matrix) -> None:\\r\\n    r1, r2 = len(mat1), len(mat2)\\r\\n    c1, c2 = len(mat1[0]), len(mat2[0])\\r\\n\\r\\n    result = [[0] * c2 for _ in range(r1)]\\r\\n\\r\\n    for i in range(r1):\\r\\n        for j in range(c2):\\r\\n            for k in range(r2):\\r\\n                result[i][j] = (result[i][j] + mat1[i][k] * mat2[k][j]) % MOD\\r\\n\\r\\n    for i in range(r1):\\r\\n        for j in range(c2):\\r\\n            copy[i][j] = result[i][j]\\r\\n\\r\\n\\r\\ndef power(mat: Matrix, n: int) -> Matrix:\\r\\n    res = identity(len(mat))\\r\\n\\r\\n    while n:\\r\\n        if n & 1:\\r\\n            multiply(res, mat, res)\\r\\n\\r\\n        multiply(mat, mat, mat)\\r\\n\\r\\n        n >>= 1\\r\\n\\r\\n    return res\\r\\n\\r\\n\\r\\ndef fib(n: int) -> int:\\r\\n    if n == 0:\\r\\n        return 0\\r\\n\\r\\n    magic = [[2, 1],\\r\\n             [2, 0]]\\r\\n\\r\\n    mat = power(magic, n)\\r\\n\\r\\n    return mat[0][0]\\r\\n\\r\\nfor _ in range(int(input())):\\r\\n    n = int(input())\\r\\n\\r\\n    print(fib(n) % MOD)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAnmol gained a lot of weight last semester. So this semester, he decided to run everyday. There is a very long straight road starting at his hostel. There are N poles on the road - P1, P2, P3,..., PN on the road. All the poles lie on the same side of his hostel. The distance between Pi and his hostel is Di.\\nFor 1 ≤ i, j ≤ N, i < j implies Di < Dj\\nEveryday, Anmol chooses a pole Pi to start running from. He keeps on running until he reaches Pi+K. Whenever he reaches a pole (other than the starting pole), he records the distance traveled since the last pole.\\n\\nYou are given the distances recorded by him today. Your task is to find the number of distinct values of i such that i + K ≤ N and if he starts at Pi and end at Pi+K, he would end up having exactly the same record of distances (in the same order).\\n\\n-----Input-----\\n- The first line of the input contains an integer T denoting the number of test cases.\\n- The first line of each test case contains two space separated integers N and K.\\n- The next line contains N space separated integers D1, D2,..., DN.\\n- The next line contains K space separated integers representing the distances recorded by Anmol in the same order.\\n.\\n\\n-----Output-----\\n- For each test case, output a single line containing the answer for that test case.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 10\\n- 2 ≤ N ≤ 5 x 104\\n- 1 ≤ K < N\\n- 1 ≤ Di ≤ 106\\n\\n-----Subtasks-----\\n\\n-----Subtask #1 (20 points)-----\\n- 1 ≤ N ≤ 1000\\n\\n-----Subtask #2 (80 points)-----\\n- Original constraints\\n\\n-----Example-----\\nInput:\\n3\\n5 1\\n1 5 10 12 14\\n5\\n5 2\\n5 8 13 16 21\\n3 5\\n5 3\\n2 6 8 11 16\\n2 3 5\\n\\nOutput:\\n1\\n2\\n1\\n\\n-----Explanation-----\\nExample case 1. If he runs from P2 to P3, he will record (5)\\nExample case 2. He can start at P1 or P3\\nExample case 3. He can start at P2\",\"targets\":\"for t in range(int(input())):\\n n, k = list(map(int, input().split()))\\n poles = list(map(int, input().split()))\\n dist = list(map(int, input().split()))\\n pd = []\\n for i in range(1,n):\\n  pd.append(poles[i]-poles[i-1])\\n c = 0\\n for i in range(n-k):\\n  flag = 1\\n  for j in range(k):\\n   if (pd[i+j] != dist[j]):\\n    flag = 0\\n    break\\n  if (flag ==1):\\n   c += 1\\n print(c)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOnce N boys and M girls attended a party. You are given a matrix A of N rows and M columns where Aij is 1 if the i-th boy likes the j-th girl, otherwise it will be 0. Note that it is not necessary that if a boy x likes girl y, then girl y should like boy x.\\nYou know that if there are two different boys x and y, who both like girl z, then there will be a collision.\\nCan you calculate the number of different collisions at this party? Note that order of boys in the collision doesn't matter.\\n\\n-----Input-----\\nThe first line contains a single integer T denoting the number of test cases. Then T test cases follow.\\nThe first line of each test case contains two space separated integers N, M denoting the number of boys and girls, respectively.\\nEach of the following N lines contain M characters, each of them is either '0' or '1'.\\n\\n-----Output-----\\nFor each test case output a single line containing an integer corresponding to the number of collisions at the party.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 100\\n- 1 ≤ N, M ≤ 10\\n\\n-----Example-----\\nInput:\\n2\\n4 3\\n111\\n100\\n110\\n000\\n2 2\\n10\\n01\\n\\nOutput:\\n4\\n0\\n\\n-----Explanation-----\\nExample Case 1. All three boys like the first girl, so there are (1, 2, 1), (1, 3, 1), (2, 3, 1) collisions with her. Boys 1 and 3 both like the second girl so this is one more collision. Only one boy likes the third girl, so there are no collisions with her and thus we have 4 collisions total.\\nExample Case 2. For each girl there is only one boy who likes her, so there are no collisions at all.\",\"targets\":\"def fact(i):\\n a = i\\n while a > 1:\\n  i += (a-1)\\n  a = a - 1\\n return i\\n\\nfor _ in range(int(input())):\\n n, m = list(map(int, input().split()))\\n matrix = [0] * m\\n for _ in range(n):\\n  s = input()\\n  for i in range(len(s)):\\n   if s[i] == '1':\\n    matrix[i] += 1\\n coll = [fact(matrix[i]-1) for i in range(m) if matrix[i] > 1]\\n print((sum(coll) if coll else 0))# cook your dish here\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven is an integer N.\\nDetermine whether there is a pair of positive integers (A, B) such that 3^A + 5^B = N, and find one such pair if it exists.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 10^{18}\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\n\\n-----Output-----\\nIf there is no pair (A, B) that satisfies the condition, print -1.\\nIf there is such a pair, print A and B of one such pair with space in between. If there are multiple such pairs, any of them will be accepted.\\n\\n-----Sample Input-----\\n106\\n\\n-----Sample Output-----\\n4 2\\n\\nWe have 3^4 + 5^2 = 81 + 25 = 106, so (A, B) = (4, 2) satisfies the condition.\",\"targets\":\"N = int(input())\\n\\nfor i in range(1,100):\\n  for j in range(1,100):\\n    if 3**i+5**j==N:\\n      print(i,j)\\n      return\\n\\nprint(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/886\\/B:\\nVlad likes to eat in cafes very much. During his life, he has visited cafes n times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.\\n\\nFirst of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes he visited in a row, in order of visiting them. Now, Vlad wants to find such a cafe that his last visit to that cafe was before his last visits to every other cafe. In other words, he wants to find such a cafe that he hasn't been there for as long as possible. Help Vlad to find that cafe.\\n\\n\\n-----Input-----\\n\\nIn first line there is one integer n (1 ≤ n ≤ 2·10^5) — number of cafes indices written by Vlad.\\n\\nIn second line, n numbers a_1, a_2, ..., a_{n} (0 ≤ a_{i} ≤ 2·10^5) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, some indices could be omitted.\\n\\n\\n-----Output-----\\n\\nPrint one integer — index of the cafe that Vlad hasn't visited for as long as possible.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 3 2 1 2\\n\\nOutput\\n3\\n\\nInput\\n6\\n2 1 2 2 4 1\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer. \\n\\nIn second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with index 2, so the answer is 2. Note that Vlad could omit some numbers while numerating the cafes.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def ma():\\n    n=int(input())\\n    b=list(map(int,input().split()))\\n    k={b[-1]};last=b[-1]\\n    for i in range(n-1,-1,-1):\\n        if not (b[i] in k):\\n            last=b[i];\\n            k.add(b[i])\\n    print(last)\\nma()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/52ea928a1ef5cfec800003ee:\\nTake the following IPv4 address:  128.32.10.1\\nThis address has 4 octets where each octet is a single byte (or 8 bits).\\n\\n* 1st octet 128 has the binary representation: 10000000\\n* 2nd octet 32 has the binary representation: 00100000\\n* 3rd octet 10 has the binary representation: 00001010\\n* 4th octet 1 has the binary representation: 00000001\\n\\nSo 128.32.10.1 == 10000000.00100000.00001010.00000001\\n\\nBecause the above IP address has 32 bits, we can represent it as the 32\\nbit number: 2149583361.\\n\\nWrite a function ip_to_int32(ip) ( **JS**: `ipToInt32(ip)` ) that takes an IPv4 address and returns\\na 32 bit number.\\n\\n```python\\n  ip_to_int32(\\\"128.32.10.1\\\") => 2149583361\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def ip_to_int32(ip):\\n    result = 0\\n    for s in ip.split('.'):\\n        result *= 256\\n        result += int(s)\\n    return result\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a string s and should process m queries. Each query is described by two 1-based indices l_{i}, r_{i} and integer k_{i}. It means that you should cyclically shift the substring s[l_{i}... r_{i}] k_{i} times. The queries should be processed one after another in the order they are given.\\n\\nOne operation of a cyclic shift (rotation) is equivalent to moving the last character to the position of the first character and shifting all other characters one position to the right.\\n\\nFor example, if the string s is abacaba and the query is l_1 = 3, r_1 = 6, k_1 = 1 then the answer is abbacaa. If after that we would process the query l_2 = 1, r_2 = 4, k_2 = 2 then we would get the string baabcaa.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains the string s (1 ≤ |s| ≤ 10 000) in its initial state, where |s| stands for the length of s. It contains only lowercase English letters.\\n\\nSecond line contains a single integer m (1 ≤ m ≤ 300) — the number of queries.\\n\\nThe i-th of the next m lines contains three integers l_{i}, r_{i} and k_{i} (1 ≤ l_{i} ≤ r_{i} ≤ |s|, 1 ≤ k_{i} ≤ 1 000 000) — the description of the i-th query.\\n\\n\\n-----Output-----\\n\\nPrint the resulting string s after processing all m queries.\\n\\n\\n-----Examples-----\\nInput\\nabacaba\\n2\\n3 6 1\\n1 4 2\\n\\nOutput\\nbaabcaa\\n\\n\\n\\n-----Note-----\\n\\nThe sample is described in problem statement.\",\"targets\":\"my_string = input().strip()\\nmy_string = list(my_string)\\nsl = len(my_string)\\nm = int(input())\\n\\nfor i in range(m):\\n    l, r, k = list(map(int, input().split()))\\n    range_length = r - l + 1\\n    k = k % range_length\\n    l = l - 1\\n    k = range_length - k\\n\\n    my_string[l:r] = my_string[l+k:r] + my_string[l:l+k] \\n\\nans = ''.join(my_string)\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n![](http:\\/\\/www.grindtv.com\\/wp-content\\/uploads\\/2015\\/08\\/drone.jpg)\\n\\nThe other day I saw an amazing video where a guy hacked some wifi controlled lightbulbs by flying a drone past them. Brilliant.\\n\\nIn this kata we will recreate that stunt... sort of.\\n\\nYou will be given two strings: `lamps` and `drone`. `lamps` represents a row of lamps, currently off, each represented by `x`. When these lamps are on, they should be represented by `o`.\\n\\nThe `drone` string represents the position of the drone `T` (any better suggestion for character??) and its flight path up until this point `=`. The drone always flies left to right, and always begins at the start of the row of lamps. Anywhere the drone has flown, including its current position, will result in the lamp at that position switching on.\\n\\nReturn the resulting `lamps` string. See example tests for more clarity.\",\"targets\":\"def fly_by(lamps, drone):\\n    os = min(len(drone), len(lamps))\\n    xs = len(lamps) - len(drone)\\n    return os * \\\"o\\\" + xs * \\\"x\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have a string S of lowercase letters, and an integer array shifts.\\nCall the shift of a letter, the next letter in the alphabet, (wrapping around so that 'z' becomes 'a'). \\nFor example, shift('a') = 'b', shift('t') = 'u', and shift('z') = 'a'.\\nNow for each shifts[i] = x, we want to shift the first i+1 letters of S, x times.\\nReturn the final string after all such shifts to S are applied.\\nExample 1:\\nInput: S = \\\"abc\\\", shifts = [3,5,9]\\nOutput: \\\"rpl\\\"\\nExplanation: \\nWe start with \\\"abc\\\".\\nAfter shifting the first 1 letters of S by 3, we have \\\"dbc\\\".\\nAfter shifting the first 2 letters of S by 5, we have \\\"igc\\\".\\nAfter shifting the first 3 letters of S by 9, we have \\\"rpl\\\", the answer.\\n\\nNote:\\n\\n1 <= S.length = shifts.length <= 20000\\n0 <= shifts[i] <= 10 ^ 9\",\"targets\":\"class Solution:\\n    def shiftingLetters(self, S: str, shifts: List[int]) -> str:\\n        # cumulative sum from back\\n        shifts[-1] = shifts[-1] % 26\\n        \\n        if len(shifts) >= 2:\\n            for i in range(len(shifts) - 2, -1, -1):\\n                shifts[i] += shifts[i + 1]\\n                shifts[i] = shifts[i] % 26\\n                \\n        # shift characters\\n        shifted_chars = []\\n        \\n        for i in range(len(S)):\\n            shifted_ascii = (ord(S[i]) - 97 + shifts[i]) % 26 + 97\\n            shifted_chars.append(chr(shifted_ascii))\\n            \\n        return \\\\\\\"\\\\\\\".join(shifted_chars)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nConsider the following process. You have a binary string (a string where each character is either 0 or 1) $w$ of length $n$ and an integer $x$. You build a new binary string $s$ consisting of $n$ characters. The $i$-th character of $s$ is chosen as follows:\\n\\n  if the character $w_{i-x}$ exists and is equal to 1, then $s_i$ is 1 (formally, if $i > x$ and $w_{i-x} = $ 1, then $s_i = $ 1);  if the character $w_{i+x}$ exists and is equal to 1, then $s_i$ is 1 (formally, if $i + x \\\\le n$ and $w_{i+x} = $ 1, then $s_i = $ 1);  if both of the aforementioned conditions are false, then $s_i$ is 0. \\n\\nYou are given the integer $x$ and the resulting string $s$. Reconstruct the original string $w$.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases.\\n\\nEach test case consists of two lines. The first line contains the resulting string $s$ ($2 \\\\le |s| \\\\le 10^5$, each character of $s$ is either 0 or 1). The second line contains one integer $x$ ($1 \\\\le x \\\\le |s| - 1$).\\n\\nThe total length of all strings $s$ in the input does not exceed $10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer on a separate line as follows:\\n\\n  if no string $w$ can produce the string $s$ at the end of the process, print $-1$;  otherwise, print the binary string $w$ consisting of $|s|$ characters. If there are multiple answers, print any of them. \\n\\n\\n-----Example-----\\nInput\\n3\\n101110\\n2\\n01\\n1\\n110\\n1\\n\\nOutput\\n111011\\n10\\n-1\",\"targets\":\"for t in range(int(input())):\\n    s = [int(c == \\\"1\\\") for c in input()]\\n    x = int(input())\\n    n = len(s)\\n\\n    sat = lambda i: (s[i] if i in range(n) else 1)\\n\\n    w = [(sat(i - x) & sat(i + x)) for i in range(n)]\\n\\n    wat = lambda i: (w[i] if i in range(n) else 0)\\n\\n    s_ref = [(wat(i - x) | wat(i + x)) for i in range(n)]\\n    \\n    if s != s_ref:\\n        print(-1)\\n    else:\\n        print(\\\"\\\".join(map(str, w)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/find-two-non-overlapping-sub-arrays-each-with-target-sum\\/:\\nGiven an array of integers arr and an integer target.\\nYou have to find two non-overlapping sub-arrays of arr each with sum equal target. There can be multiple answers so you have to find an answer where the sum of the lengths of the two sub-arrays is minimum.\\nReturn the minimum sum of the lengths of the two required sub-arrays, or return -1 if you cannot find such two sub-arrays.\\n \\nExample 1:\\nInput: arr = [3,2,2,4,3], target = 3\\nOutput: 2\\nExplanation: Only two sub-arrays have sum = 3 ([3] and [3]). The sum of their lengths is 2.\\n\\nExample 2:\\nInput: arr = [7,3,4,7], target = 7\\nOutput: 2\\nExplanation: Although we have three non-overlapping sub-arrays of sum = 7 ([7], [3,4] and [7]), but we will choose the first and third sub-arrays as the sum of their lengths is 2.\\n\\nExample 3:\\nInput: arr = [4,3,2,6,2,3,4], target = 6\\nOutput: -1\\nExplanation: We have only one sub-array of sum = 6.\\n\\nExample 4:\\nInput: arr = [5,5,4,4,5], target = 3\\nOutput: -1\\nExplanation: We cannot find a sub-array of sum = 3.\\n\\nExample 5:\\nInput: arr = [3,1,1,1,5,1,2,1], target = 3\\nOutput: 3\\nExplanation: Note that sub-arrays [1,2] and [2,1] cannot be an answer because they overlap.\\n\\n \\nConstraints:\\n\\n1 <= arr.length <= 10^5\\n1 <= arr[i] <= 1000\\n1 <= target <= 10^8\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def minSumOfLengths(self, arr: List[int], target: int) -> int:\\n        n = len(arr)\\n        left = [float('inf')]*n\\n        memo = {0:-1}\\n        current = 0\\n        for k in range(n):\\n            if k > 0:\\n                left[k] = left[k-1]\\n            current += arr[k]\\n            if current - target in memo:\\n                left[k] = min(left[k], k - memo[current - target])\\n            memo[current] = k\\n        print(left)\\n        \\n        right = [float('inf')]*n\\n        memo = {0:n}\\n        current = 0\\n        for k in range(n-1, -1, -1):\\n            if k < n-1:\\n                right[k] = right[k+1]\\n            current += arr[k]\\n            if current - target in memo:\\n                right[k] = min(right[k], memo[current-target] - k)\\n            memo[current] = k\\n        \\n        ans = float('inf')\\n        for k in range(n-1):\\n            ans = min(ans, left[k] + right[k+1])\\n        return ans if ans != float('inf') else -1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string.\\n\\nExample 1:\\n\\n\\nInput: num1 = \\\"2\\\", num2 = \\\"3\\\"\\nOutput: \\\"6\\\"\\n\\nExample 2:\\n\\n\\nInput: num1 = \\\"123\\\", num2 = \\\"456\\\"\\nOutput: \\\"56088\\\"\\n\\n\\nNote:\\n\\n\\n       The length of both num1 and num2 is < 110.\\n       Both num1 and num2 contain only digits 0-9.\\n       Both num1 and num2 do not contain any leading zero, except the number 0 itself.\\n       You must not use any built-in BigInteger library or convert the inputs to integer directly.\",\"targets\":\"class Solution:\\n     def multiply(self,num1, num2):\\n         \\\"\\\"\\\"\\n         :type num1: str\\n         :type num2: str\\n         :rtype: str\\n         \\\"\\\"\\\"\\n         a=['0','1','2','3','4','5','6','7','8','9']\\n         z=0\\n         x=0\\n         \\n      \\n         for i,element in enumerate(num1):\\n             for j in range(10):\\n                 if element==a[j]:\\n                     z+=j*(10**(len(num1)-i-1))\\n                         \\n                     \\n         for c,b in enumerate(num2):\\n             for k in range(10):\\n                 if b==a[k]:\\n                     x+=k*(10**(len(num2)-c-1))\\n                     \\n                     \\n         \\n         mul=z*x\\n         \\n         return(''.join('%d'%mul))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMagic The Gathering is a collectible card game that features wizards battling against each other with spells and creature summons. The game itself can be quite complicated to learn. In this series of katas, we'll be solving some of the situations that arise during gameplay. You won't need any prior knowledge of the game to solve these contrived problems, as I will provide you with enough information.\\n\\n## Creatures\\n\\nEach creature has a power and toughness. We will represent this in an array. [2, 3] means this creature has a power of 2 and a toughness of 3.\\n\\nWhen two creatures square off, they each deal damage equal to their power to each other at the same time. If a creature takes on damage greater than or equal to their toughness, they die.\\n\\nExamples:\\n\\n- Creature 1 - [2, 3]\\n- Creature 2 - [3, 3]\\n- Creature 3 - [1, 4]\\n- Creature 4 - [4, 1]\\n\\nIf creature 1 battles creature 2, creature 1 dies, while 2 survives. If creature 3 battles creature 4, they both die, as 3 deals 1 damage to 4, but creature 4 only has a toughness of 1.\\n\\nWrite a function `battle(player1, player2)` that takes in 2 arrays of creatures. Each players' creatures battle each other in order (player1[0] battles the creature in player2[0]) and so on. If one list of creatures is longer than the other, those creatures are considered unblocked, and do not battle.\\n\\nYour function should return an object (a hash in Ruby) with the keys player1 and player2 that contain the power and toughness of the surviving creatures.\\n\\nExample:\\n```\\nGood luck with your battles!\\n\\n\\nCheck out my other Magic The Gathering katas:\\n\\n\\nMagic The Gathering #1: Creatures\\nMagic The Gathering #2: Mana\",\"targets\":\"from itertools import zip_longest\\n\\ndef battle(player1, player2):\\n    rem = {'player1': [], 'player2': []}\\n    for c1,c2 in zip_longest(player1, player2, fillvalue=[0,0]):\\n        if c1[1] > c2[0]: rem['player1'].append(c1)\\n        if c2[1] > c1[0]: rem['player2'].append(c2)\\n    return rem\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou got a job as a marketer in a pet shop, and your current task is to boost sales of cat food. One of the strategies is to sell cans of food in packs with discounts. \\n\\nSuppose you decided to sell packs with $a$ cans in a pack with a discount and some customer wants to buy $x$ cans of cat food. Then he follows a greedy strategy:   he buys $\\\\left\\\\lfloor \\\\frac{x}{a} \\\\right\\\\rfloor$ packs with a discount;  then he wants to buy the remaining $(x \\\\bmod a)$ cans one by one. \\n\\n$\\\\left\\\\lfloor \\\\frac{x}{a} \\\\right\\\\rfloor$ is $x$ divided by $a$ rounded down, $x \\\\bmod a$ is the remainer of $x$ divided by $a$.\\n\\nBut customers are greedy in general, so if the customer wants to buy $(x \\\\bmod a)$ cans one by one and it happens that $(x \\\\bmod a) \\\\ge \\\\frac{a}{2}$ he decides to buy the whole pack of $a$ cans (instead of buying $(x \\\\bmod a)$ cans). It makes you, as a marketer, happy since the customer bought more than he wanted initially.\\n\\nYou know that each of the customers that come to your shop can buy any number of cans from $l$ to $r$ inclusive. Can you choose such size of pack $a$ that each customer buys more cans than they wanted initially?\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases.\\n\\nThe first and only line of each test case contains two integers $l$ and $r$ ($1 \\\\le l \\\\le r \\\\le 10^9$) — the range of the number of cans customers can buy.\\n\\n\\n-----Output-----\\n\\nFor each test case, print YES if you can choose such size of pack $a$ that each customer buys more cans than they wanted initially. Otherwise, print NO.\\n\\nYou can print each character in any case.\\n\\n\\n-----Example-----\\nInput\\n3\\n3 4\\n1 2\\n120 150\\n\\nOutput\\nYES\\nNO\\nYES\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, you can take, for example, $a = 5$ as the size of the pack. Then if a customer wants to buy $3$ cans, he'll buy $5$ instead ($3 \\\\bmod 5 = 3$, $\\\\frac{5}{2} = 2.5$). The one who wants $4$ cans will also buy $5$ cans.\\n\\nIn the second test case, there is no way to choose $a$.\\n\\nIn the third test case, you can take,...\",\"targets\":\"for _ in range(int(input())):\\n    a,b = map(int,input().split())\\n    if(b<2*a):\\n        print(\\\"YES\\\")\\n    else:\\n        print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/57ee4a67108d3fd9eb0000e7:\\nWrite a function, `gooseFilter` \\/ `goose-filter` \\/ `goose_filter` \\/` GooseFilter`, that takes an array of strings as an argument and returns a filtered array containing the same elements but with the 'geese' removed.\\n\\nThe geese are any strings in the following array, which is pre-populated in your solution:\\n\\n```python\\ngeese = [\\\"African\\\", \\\"Roman Tufted\\\", \\\"Toulouse\\\", \\\"Pilgrim\\\", \\\"Steinbacher\\\"]\\n```\\n\\nFor example, if this array were passed as an argument:\\n\\n```python\\n[\\\"Mallard\\\", \\\"Hook Bill\\\", \\\"African\\\", \\\"Crested\\\", \\\"Pilgrim\\\", \\\"Toulouse\\\", \\\"Blue Swedish\\\"]\\n```\\n\\nYour function would return the following array:\\n\\n```python\\n[\\\"Mallard\\\", \\\"Hook Bill\\\", \\\"Crested\\\", \\\"Blue Swedish\\\"]\\n```\\n\\nThe elements in the returned array should be in the same order as in the initial array passed to your function, albeit with the 'geese' removed. Note that all of the strings will be in the same case as those provided, and some elements may be repeated.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"geese = [\\\"African\\\", \\\"Roman Tufted\\\", \\\"Toulouse\\\", \\\"Pilgrim\\\", \\\"Steinbacher\\\"]\\n\\ndef goose_filter(birds):\\n    return [brd for brd in birds if brd not in geese]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/932\\/C:\\nFor a permutation P[1... N] of integers from 1 to N, function f is defined as follows:\\n\\n $f(i, j) = \\\\left\\\\{\\\\begin{array}{ll}{P [ i ]} & {\\\\text{if} j = 1} \\\\\\\\{f(P [ i ], j - 1)} & {\\\\text{otherwise}} \\\\end{array} \\\\right.$ \\n\\nLet g(i) be the minimum positive integer j such that f(i, j) = i. We can show such j always exists.\\n\\nFor given N, A, B, find a permutation P of integers from 1 to N such that for 1 ≤ i ≤ N, g(i) equals either A or B.\\n\\n\\n-----Input-----\\n\\nThe only line contains three integers N, A, B (1 ≤ N ≤ 10^6, 1 ≤ A, B ≤ N).\\n\\n\\n-----Output-----\\n\\nIf no such permutation exists, output -1. Otherwise, output a permutation of integers from 1 to N.\\n\\n\\n-----Examples-----\\nInput\\n9 2 5\\n\\nOutput\\n6 5 8 3 4 1 9 2 7\\nInput\\n3 2 1\\n\\nOutput\\n1 2 3 \\n\\n\\n-----Note-----\\n\\nIn the first example, g(1) = g(6) = g(7) = g(9) = 2 and g(2) = g(3) = g(4) = g(5) = g(8) = 5 \\n\\nIn the second example, g(1) = g(2) = g(3) = 1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#This code sucks, you know it and I know it.  \\n#Move on and call me an idiot later.\\n\\ndef solve(a, b, n):\\n \\n    i = 0\\n    while i * a <= n:\\n         \\n        if (n - (i * a)) % b == 0:\\n            x = i\\n            y = (n - (i * a)) \\/\\/ b\\n            return (x, y)\\n        i = i + 1\\n     \\n    return (-1, -1)\\n\\nn, a, b = map(int, input().split())\\naa, bb = solve(a, b, n)\\nl = []\\nif (aa, bb) == (-1, -1):\\n    print(-1)\\nelse:\\n\\n    for i in range(1,aa+1):\\n        x = a*(i-1) + 1\\n        y = a*i\\n        l += [y]\\n        l += [j for j in range(x, y)]\\n\\n    for i in range(1,bb+1):\\n        x = a*aa + b*(i-1) + 1\\n        y = a*aa + b*i\\n        l += [y]\\n        l += [j for j in range(x, y)]\\n    \\n    print(\\\" \\\".join(map(str, l)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/630\\/C:\\nThe numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.\\n\\nLucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.\\n\\n\\n-----Input-----\\n\\nThe only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.\\n\\n\\n-----Output-----\\n\\nOutput one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.\\n\\n\\n-----Examples-----\\nInput\\n2\\n\\nOutput\\n6\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"print(2**(int(input())+1)-2)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target.\\n\\nEach number in candidates may only be used once in the combination.\\n\\nNote:\\n\\n\\n       All numbers (including target) will be positive integers.\\n       The solution set must not contain duplicate combinations.\\n\\n\\nExample 1:\\n\\n\\nInput: candidates = [10,1,2,7,6,1,5], target = 8,\\nA solution set is:\\n[\\n  [1, 7],\\n  [1, 2, 5],\\n  [2, 6],\\n  [1, 1, 6]\\n]\\n\\n\\nExample 2:\\n\\n\\nInput: candidates = [2,5,2,1,2], target = 5,\\nA solution set is:\\n[\\n  [1,2,2],\\n  [5]\\n]\",\"targets\":\"class Solution(object):\\n     def combinationSum2(self, candidates, target):\\n         \\\"\\\"\\\"\\n         :type candidates: List[int]\\n         :type target: int\\n         :rtype: List[List[int]]\\n         \\\"\\\"\\\"\\n         result = []\\n         temp = []\\n         candidates.sort(reverse=True)\\n \\n         self.util(candidates, target, result, temp)\\n         return result       \\n \\n     def util(self, nums, target, result, temp):\\n \\n         for i in range(len(nums)): \\n             if nums[i] == target and (temp + [nums[i]] not in result):\\n                 result.append(temp + [nums[i]])\\n             elif nums[i] < target:\\n                 self.util(nums[i + 1:], target - nums[i], result, temp + [nums[i]])\\n \\n         return\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA printer – who still uses moveable type – is preparing to print a set of pages for a book. These pages are to be numbered, as usual. The printer needs to know how many instances of each decimal digit will be required to set up the page numbers in the section of the book to be printed.\\n\\nFor example, if pages 10, 11, 12, 13, 14 and 15 are to be printed, computing the number of digits is relatively simple: just look at the page numbers that will appear, and count the number of times each digit appears. The digit 0 appears only once, the digit 1 appears 7 times, the digits 2, 3, 4 and 5 each appear once, and 6, 7, 8 and 9 don’t appear at all.\\n\\nYour task in this problem is to provide the printer with the appropriate counts of the digits. You will be given the numbers of the two pages that identify the section of the book to be printed. You may safely assume that all pages in that section are to be numbered, that no leading zeroes will be printed, that page numbers are positive, and that no page will have more than three digits in its page number.\\n\\n-----Input-----\\n\\nThere will be multiple cases to consider. The input for each case has two integers, A and B, each of which is guaranteed to be positive. These identify the pages to be printed. That is, each integer P between A and B, including A and B, is to be printed. A single zero will follow the input for the last case.\\n\\n-----Output-----\\n\\nFor each input case, display the case number (1, 2, …) and the number of occurrences of each decimal digit 0 through 9 in the specified range of page numbers. Display your results in the format shown in the examples below.\\n\\n-----Example-----\\nInput:\\n\\n10 15\\n912 912\\n900 999\\n0\\n\\nOutput:\\n\\nCase 1: 0:1 1:7 2:1 3:1 4:1 5:1 6:0 7:0 8:0 9:0\\nCase 2: 0:0 1:1 2:1 3:0 4:0 5:0 6:0 7:0 8:0 9:1\\nCase 3: 0:20 1:20 2:20 3:20 4:20 5:20 6:20 7:20 8:20 9:120\",\"targets\":\"entry = input()\\nt=0\\n \\nwhile entry != \\\"0\\\":\\n\\t\\n    t+=1\\n    \\n    mymap= {\\n\\t\\t'0':0,\\n\\t\\t'1':0,\\n\\t\\t'2':0,\\n\\t\\t'3':0,\\n\\t\\t'4':0,\\n\\t\\t'5':0,\\n\\t\\t'6':0,\\n\\t\\t'7':0,\\n\\t\\t'8':0,\\n\\t\\t'9':0\\n\\t\\t\\t}\\n    \\n    \\n    n = list(map(int,entry.split()))\\n    for i in range(min(n),max(n)+1):\\n        for j in str(i):\\n            mymap[j] += 1\\n    store1 = list(mymap.items())\\n    store1.sort()        \\n    print(\\\"Case %s: %s\\\" % (t, \\\" \\\".join([\\\"%s:%s\\\" % (k,v) for k,v in store1])))\\n    entry = input()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n Let's consider a table consisting of `n` rows and `n` columns. The cell located at the intersection of the i-th row and the j-th column contains number i × j. The rows and columns are numbered starting from 1.\\n\\n You are given a positive integer `x`. Your task is to count the number of cells in a table that contain number `x`.\\n\\n# Example\\n\\n For `n = 5 and x = 5`, the result should be `2`.\\n \\n The table looks like:\\n ```\\n   1  2  3  4  (5)\\n   2  4  6  8  10\\n   3  6  9  12 15\\n   4  8  12 16 20\\n (5) 10 15 20 25```\\n There are two number `5` in it.\\n  \\n For `n = 10 and x = 5`, the result should be 2.\\n \\n For `n = 6 and x = 12`, the result should be 4.\\n ```\\n   1  2   3   4   5   6\\n   2  4   6   8   10 (12)\\n   3  6   9  (12) 15  18\\n   4  8  (12) 16  20  24\\n   5  10  15  20  25  30\\n   6 (12) 18  24  30  36\\n ```\\n \\n# Input\\/Output\\n\\n\\n - `[input]` integer `n`\\n\\n  `1 ≤ n ≤ 10^5.`\\n\\n\\n - `[input]` integer `x`\\n\\n  `1 ≤ x ≤ 10^9.`\\n\\n\\n - `[output]` an integer\\n\\n  The number of times `x` occurs in the table.\",\"targets\":\"def count_number(n, x):\\n    k = [1, x \\/\\/ n][x > n]\\n    return sum(1 for i in range(k, n + 1) if x\\/i == x\\/\\/i and x\\/i in range(1, n + 1))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/576400f2f716ca816d001614:\\nWrite a function which reduces fractions to their simplest form! Fractions will be presented as an array\\/tuple (depending on the language), and the reduced fraction must be returned as an array\\/tuple:\\n\\n```\\ninput:   [numerator, denominator]\\noutput:  [newNumerator, newDenominator]\\nexample: [45, 120] --> [3, 8]\\n```\\n\\nAll numerators and denominators will be positive integers.\\n\\nNote: This is an introductory Kata for a series... coming soon!\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def reduce_fraction(fraction):\\n    n1, n2 = fraction[0], fraction[1]\\n    for i in range(2, 999):\\n        if n1 % i == 0 and n2 % i == 0:\\n            n1, n2 = n1 \\/\\/ i, n2 \\/\\/ i\\n            fraction = reduce_fraction([n1, n2])     \\n    return tuple(fraction)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven an integer array nums and an integer k, return the maximum sum of a non-empty subsequence of that array such that for every two consecutive integers in the subsequence, nums[i] and nums[j], where i < j, the condition j - i <= k is satisfied.\\nA subsequence of an array is obtained by deleting some number of elements (can be zero) from the array, leaving the remaining elements in their original order.\\n \\nExample 1:\\nInput: nums = [10,2,-10,5,20], k = 2\\nOutput: 37\\nExplanation: The subsequence is [10, 2, 5, 20].\\n\\nExample 2:\\nInput: nums = [-1,-2,-3], k = 1\\nOutput: -1\\nExplanation: The subsequence must be non-empty, so we choose the largest number.\\n\\nExample 3:\\nInput: nums = [10,-2,-10,-5,20], k = 2\\nOutput: 23\\nExplanation: The subsequence is [10, -2, -5, 20].\\n\\n \\nConstraints:\\n\\n1 <= k <= nums.length <= 10^5\\n-10^4 <= nums[i] <= 10^4\",\"targets\":\"class Solution:\\n    def constrainedSubsetSum(self, nums: List[int], k: int) -> int:\\n        rec = -nums[0]\\n        heap = [(-nums[0], 0)]\\n        for j, n in enumerate(nums[1:]):\\n            while j+1-heap[0][1] > k:\\n                heapq.heappop(heap)\\n            cand = -n + heap[0][0] if heap[0][0] <= 0 else -n\\n            rec = min(rec, cand)\\n            heapq.heappush(heap, (cand, j+1))\\n        return -rec\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5995ceb5d4280d07f6000822:\\nIn this Kata, you will create a function that converts a string with letters and numbers to the inverse of that string (with regards to Alpha and Numeric characters). So, e.g. the letter `a` will become `1` and number `1` will become `a`; `z` will become `26` and `26` will become `z`.\\n\\nExample: `\\\"a25bz\\\"` would become `\\\"1y226\\\"`\\n\\n\\nNumbers representing letters (`n <= 26`) will always be separated by letters, for all test cases: \\n\\n* `\\\"a26b\\\"` may be tested, but not `\\\"a262b\\\"`\\n* `\\\"cjw9k\\\"` may be tested, but not `\\\"cjw99k\\\"`\\n\\nA list named `alphabet` is preloaded for you: `['a', 'b', 'c', ...]`\\n\\nA dictionary of letters and their number equivalent is also preloaded for you called `alphabetnums = {'a': '1', 'b': '2', 'c': '3', ...}`\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import re\\n\\ndef AlphaNum_NumAlpha(string):\\n    return ''.join(chr(int(e)+96) if e.isdigit() else str(ord(e)-96) for e in re.split('([a-z])', string) if e)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nEvery email consists of a local name and a domain name, separated by the @ sign.\\nFor example, in alice@leetcode.com, alice is the local name, and leetcode.com is the domain name.\\nBesides lowercase letters, these emails may contain '.'s or '+'s.\\nIf you add periods ('.') between some characters in the local name part of an email address, mail sent there will be forwarded to the same address without dots in the local name.  For example, \\\"alice.z@leetcode.com\\\" and \\\"alicez@leetcode.com\\\" forward to the same email address.  (Note that this rule does not apply for domain names.)\\nIf you add a plus ('+') in the local name, everything after the first plus sign will be ignored. This allows certain emails to be filtered, for example m.y+name@email.com will be forwarded to my@email.com.  (Again, this rule does not apply for domain names.)\\nIt is possible to use both of these rules at the same time.\\nGiven a list of emails, we send one email to each address in the list.  How many different addresses actually receive mails? \\n \\n\\nExample 1:\\nInput: [\\\"test.email+alex@leetcode.com\\\",\\\"test.e.mail+bob.cathy@leetcode.com\\\",\\\"testemail+david@lee.tcode.com\\\"]\\nOutput: 2\\nExplanation: \\\"testemail@leetcode.com\\\" and \\\"testemail@lee.tcode.com\\\" actually receive mails\\n\\n \\nNote:\\n\\n1 <= emails[i].length <= 100\\n1 <= emails.length <= 100\\nEach emails[i] contains exactly one '@' character.\\nAll local and domain names are non-empty.\\nLocal names do not start with a '+' character.\",\"targets\":\"class Solution:\\n    def numUniqueEmails(self, emails: List[str]) -> int:\\n        l=[]\\n        for i in emails:\\n            end=i[i.index('@'):]\\n            s=''\\n            string=''\\n            for j in i:\\n                if j=='.':\\n                    continue\\n                if j=='+':\\n                    break \\n                if j=='@':\\n                    break\\n                else:\\n                    s=s+j\\n            l.append(s+end)    \\n        \\n        return (len(set(l)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIf you can't sleep, just count sheep!!\\n\\n## Task:\\nGiven a non-negative integer, `3` for example, return a string with a murmur: `\\\"1 sheep...2 sheep...3 sheep...\\\"`.  Input will always be valid, i.e. no negative integers.\",\"targets\":\"def count_sheep(n):\\n    # your code\\n    o = \\\"\\\"\\n    for i in range(1, n+1):\\n        o+=f\\\"{i} sheep...\\\"\\n    return o\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/746\\/B:\\nPolycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, info. If the word consists of single letter, then according to above definition this letter is the median letter. \\n\\nPolycarp encodes each word in the following way: he writes down the median letter of the word, then deletes it and repeats the process until there are no letters left. For example, he encodes the word volga as logva.\\n\\nYou are given an encoding s of some word, your task is to decode it. \\n\\n\\n-----Input-----\\n\\nThe first line contains a positive integer n (1 ≤ n ≤ 2000) — the length of the encoded word.\\n\\nThe second line contains the string s of length n consisting of lowercase English letters — the encoding.\\n\\n\\n-----Output-----\\n\\nPrint the word that Polycarp encoded.\\n\\n\\n-----Examples-----\\nInput\\n5\\nlogva\\n\\nOutput\\nvolga\\n\\nInput\\n2\\nno\\n\\nOutput\\nno\\n\\nInput\\n4\\nabba\\n\\nOutput\\nbaba\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word became va. Then he wrote down the letter v, then the letter a. Thus, the encoding looked like logva.\\n\\nIn the second example Polycarp encoded the word no. He wrote down the letter n, the word became o, and he wrote down the letter o. Thus, in this example, the word and its encoding are the same.\\n\\nIn the third example Polycarp encoded the word baba. At first, he wrote down the letter a, which was at the position 2, after that the word looked like bba. Then he wrote down the letter b, which was at the position 2, his word looked like ba. After that he wrote down the letter b, which was at the position 1,...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\nword = input()\\nnew_w = [0] * n\\n\\nif n % 2 == 1:\\n    middle = n \\/\\/ 2\\n    new_w[middle] = word[0]\\n    for i in range(1, middle + 1):\\n        new_w[middle - i] = word[2 * i - 1]\\n        new_w[middle + i] = word[2 * i]\\n    print(\\\"\\\".join(new_w))\\nelse:\\n    new_w.append(\\\"\\\")\\n    middle = (n + 1) \\/\\/ 2\\n    new_w[middle] = ''\\n    for i in range(1, middle + 1):\\n        new_w[middle - i] = word[2 * i - 2]\\n        new_w[middle + i] = word[2 * i - 1]\\n    print(\\\"\\\".join(new_w))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n## Task\\nGiven an array of strings, reverse them and their order in such way that their length stays the same as the length of the original inputs.\\n\\n### Example:\\n\\n```\\nInput:  {\\\"I\\\", \\\"like\\\", \\\"big\\\", \\\"butts\\\", \\\"and\\\", \\\"I\\\", \\\"cannot\\\", \\\"lie!\\\"}\\nOutput: {\\\"!\\\", \\\"eilt\\\", \\\"onn\\\", \\\"acIdn\\\", \\\"ast\\\", \\\"t\\\", \\\"ubgibe\\\", \\\"kilI\\\"}\\n```\\n\\nGood luck!\",\"targets\":\"def reverse(a):\\n    letters = ''.join(a)[::-1]\\n    result, chunk_size = [], 0\\n    for word in a:\\n        result.append(letters[chunk_size:chunk_size + len(word)])\\n        chunk_size += len(word)\\n    return result\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPankaj likes to eat Ice cream when he is working late into the night. Today has been yet another long day for Pankaj. So, he wants to eat ice cream now. He opens the fridge and sees that he has 2 types of containers holding the ice cream.\\nThe first container is a cone with radius r1 and height h1. There is also a hemisphere on the top of the cone which has the same radius. The other container is a cylindrical with radius r2 and height h2. Pankaj wants to know the amount (volume) of ice cream in both the containers. Since Pankaj is tired after coding all day, you have to help him with this task.\\n\\n-----Input-----\\n- The first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows.\\n- Each test case consists of a single line having the r1, h1, r2 and h2. Each value is given upto 2 decimal places. See example for more information.\\n\\n-----Output-----\\n- For each test case, output a single line containing the volumes of the two containers separated by space. The answer is considered correct if it is correct upto 6 decimal places.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 100\\n- 0 <  r1, h1, r2, h2 ≤ 100\\n\\n-----Example-----\\nInput:\\n2\\n1.00 1.00 1.00 1.00\\n3.02 7.23 5.20 6.00\\n\\nOutput:\\n3.141592654 3.141592654\\n126.739919445 509.691992118\",\"targets\":\"from math import pi\\nfor _ in range(int(input())):\\n  r1, h1, r2, h2 = list(map(float, input().split()))\\n  print(\\\"%0.6f %0.6f\\\"%(r1 ** 2 * pi * h1 \\/ 3 + r1 ** 3 * pi * 2 \\/ 3, r2 ** 2 * pi * h2))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5b02ae6aa2afd8f1b4001ba4:\\n## Description\\n\\nPeter enjoys taking risks, and this time he has decided to take it up a notch!\\n\\nPeter asks his local barman to pour him **n** shots, after which Peter then puts laxatives in **x** of them. He then turns around and lets the barman shuffle the shots. Peter approaches the shots and drinks **a** of them one at a time. Just one shot is enough to give Peter a runny tummy. What is the probability that Peter doesn't need to run to the loo?\\n\\n## Task\\n\\nYou are given:\\n\\n**n** - The total number of shots.\\n\\n**x** - The number of laxative laden shots.\\n\\n**a** - The number of shots that peter drinks.\\n\\n\\nreturn the probability that Peter won't have the trots after drinking. **n** will always be greater than **x**, and **a** will always be less than **n**.\\n\\n**You must return the probability rounded to two decimal places i.e. 0.05 or 0.81**\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def get_chance(n, x, a):\\n    c=0\\n    r=n-x\\n    p=1\\n    while c<a:\\n        b=r\\/n\\n        p=p*b\\n        r=r-1\\n        n=n-1\\n        c=c+1\\n    return round(p,2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGru wants to distribute $N$ bananas to $K$ minions on his birthday.\\nGru does not like to just give everyone the same number of bananas, so instead, he wants to distribute bananas in such a way that each minion gets a $distinct$ amount of bananas. That is, no two minions should get the same number of bananas.\\nGru also loves $gcd$. The higher the $gcd$, the happier Gru and the minions get. So help Gru in distributing the bananas in such a way that each Minion gets a distinct amount of bananas and gcd of this distribution is highest possible. Output this maximum gcd. If such a distribution is not possible output $-1$.\\nNote: You have to distribute $all$ $N$ bananas. \\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase consists of a single line of input, which has two integers: $N, K$. \\n\\n-----Output:-----\\nFor each testcase, output in a single line the maximum gcd or -1.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $1 \\\\leq N, K \\\\leq 10^9$\\n\\n-----Sample Input:-----\\n1\\n6 3\\n\\n-----Sample Output:-----\\n1\\n\\n-----EXPLANATION:-----\\nThe only possible distribution is $[1, 2, 3]$. So the answer is 1.\",\"targets\":\"def factors(x):\\n result = []\\n i = 1\\n while i*i <= x:\\n  if x % i == 0:\\n   result.append(i)\\n   if x\\/\\/i != i:\\n    result.append(x\\/\\/i)\\n  i += 1\\n return result\\n\\nt = int(input())\\nfor _ in range(t):\\n n, k = map(int, input().split())\\n a = factors(n)\\n an = -1\\n for i in a:\\n  c = ((i*k*(k+1))\\/\\/2)\\n  if (c%i==0 and c<=n):\\n   an=max(an,i)\\n print(an)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are parking at a parking lot. You can choose from the following two fee plans:\\n - Plan 1: The fee will be A×T yen (the currency of Japan) when you park for T hours.\\n - Plan 2: The fee will be B yen, regardless of the duration.\\nFind the minimum fee when you park for N hours.\\n\\n-----Constraints-----\\n - 1≤N≤20\\n - 1≤A≤100\\n - 1≤B≤2000\\n - All input values are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN A B\\n\\n-----Output-----\\nWhen the minimum fee is x yen, print the value of x.\\n\\n-----Sample Input-----\\n7 17 120\\n\\n-----Sample Output-----\\n119\\n\\n - If you choose Plan 1, the fee will be 7×17=119 yen.\\n - If you choose Plan 2, the fee will be 120 yen.\\nThus, the minimum fee is 119 yen.\",\"targets\":\"n, a, b = map(int, input().split())\\nprint(min(n * a, b))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n You are given n rectangular boxes, the ith box has the length lengthi, the width widthi and the height heighti. \\n \\n Your task is to check if it is possible to pack all boxes into one so that inside each box there is no more than one another box (which, in turn, can contain at most one another box, and so on). \\n \\n More formally, your task is to check whether there is such sequence of n different numbers pi (1 ≤ pi ≤ n) that for each 1 ≤ i < n the box number pi can be put into the box number pi+1.\\n\\n A box can be put into another box if all sides of the first one are less than the respective ones of the second one. You can rotate each box as you wish, i.e. you can `swap` its length, width and height if necessary.\\n\\n# Example\\n\\n For `length = [1, 3, 2], width = [1, 3, 2] and height = [1, 3, 2]`, the output should be `true`;\\n \\n For `length = [1, 1], width = [1, 1] and height = [1, 1],` the output should be `false`;\\n \\n For `length = [3, 1, 2], width = [3, 1, 2] and height = [3, 2, 1]`, the output should be `false`.\\n \\n# Input\\/Output\\n\\n\\n - `[input]` integer array `length`\\n\\n    Array of positive integers.\\n\\n    Constraints:\\n\\n    `1 ≤ length.length ≤ 100,`\\n\\n    `1 ≤ length[i] ≤ 2000.`\\n\\n\\n - `[input]` integer array `width`\\n\\n    Array of positive integers.\\n\\n    Constraints:\\n\\n    `width.length = length.length,`\\n\\n    `1 ≤ width[i] ≤ 2000.`\\n\\n\\n - `[input]` integer array `height`\\n\\n    Array of positive integers.\\n\\n    Constraints:\\n\\n    `height.length = length.length,`\\n\\n    `1 ≤ height[i] ≤ 2000.`\\n\\n\\n - `[output]` a boolean value\\n\\n    `true` if it is possible to put all boxes into one, `false` otherwise.\",\"targets\":\"def boxes_packing(length, width, height):\\n    boxes = sorted(map(sorted, zip(length, width, height)))\\n    return all(all(d1 < d2 for d1, d2 in zip(smaller, larger)) for smaller, larger in zip(boxes, boxes[1:]))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5aa859ad4a6b3408920002be:\\n# The Kata\\nYour task is to transform an input nested list into an hypercube list, which is a special kind of nested list where each level must have the very same size,\\nThis Kata is an exercise on recursion and algorithms. You will need to visualize many aspects of this question to be able to solve it efficiently, as such there is a section on definitions of the terms that will be used in the Kata, make sure to fully understand them before attempting. A naive brute-force-ish answer will most likely fail the tests. There will be tests on  nested lists of dimension and size up to 10. Good luck.\\n\\n\\n# Definitions\\n### Nested List\\nA nested list is a list that may contain either non-list items or more nested lists as items in the list. Here are a few examples of nested lists.\\n\\n    [[2, 3], 4, 5, 6, [2, [2, 3, 4, 5], 2, 1, 2], [[[[1]]]], []]\\n    [[[]]]\\n    [1, 2]\\n    [[], []]\\n    [4, 5, 6, 7, [], 2]\\n    []\\n\\n\\n- A *basic element* refers to any non-list element of a nested list.\\n\\n\\n- A nested list's *dimension* is defined as the deepest the list goes.  \\n\\n\\n- A nested list's *size* is defined as the longest the list or any of its sublists go.  \\n\\nFor example, the *dimension* and *size* of the above nested lists is as follows.\\n\\n    [[2, 3], 4, 5, 6, [2, [2, 3, 4, 5], 2, 1, 2], [[[[1]]]], []]  # dimension: 5, size: 7\\n    [[[]]]                                                        # dimension: 3, size: 1\\n    [1, 2]                                                        # dimension: 1, size: 2\\n    [[], []]                                                      # dimension: 2, size: 2\\n    [4, 5, 6, 7, [], 2]                                           # dimension: 2, size: 6\\n    []                                                            # dimension: 1, size: 0\\n\\n\\n### Hypercube List\\n- A `1`-dimensional **hypercube list** of size `n` is a nested list of dimension `1` and size `n`.  \\n\\n\\n- A `d`-dimensional hypercube list of size `n` is a nested list of dimension `d` and size `n` such that the nested list has `n` elements each of which...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from itertools import zip_longest\\n\\ndef normalize(lst: List, growing: int = 0) -> List:\\n    \\\"\\\"\\\"Convert the given nested list to hypercube format with the given <growing_value> and return it.\\n    \\\"\\\"\\\"\\n    \\n    def seeker(lst, d = 1):\\n        yield len(lst), d\\n        for elt in lst:\\n            if isinstance(elt, list):\\n                yield from seeker(elt, d + 1)\\n                \\n    def grower(lst, d = 1):\\n        return [ grower(o if isinstance(o, list) else [o] * size, d + 1)\\n                   if d != depth else o\\n                 for o, _ in zip_longest(lst, list(range(size)), fillvalue=growing) ]\\n    \\n    size, depth = list(map(max, list(zip(*seeker(lst)))))\\n    return grower(lst)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1369\\/D:\\nLee tried so hard to make a good div.2 D problem to balance his recent contest, but it still doesn't feel good at all. Lee invented it so tediously slow that he managed to develop a phobia about div.2 D problem setting instead. And now he is hiding behind the bushes...\\n\\nLet's define a Rooted Dead Bush (RDB) of level $n$ as a rooted tree constructed as described below.\\n\\nA rooted dead bush of level $1$ is a single vertex. To construct an RDB of level $i$ we, at first, construct an RDB of level $i-1$, then for each vertex $u$:   if $u$ has no children then we will add a single child to it;  if $u$ has one child then we will add two children to it;  if $u$ has more than one child, then we will skip it. \\n\\n [Image] Rooted Dead Bushes of level $1$, $2$ and $3$. \\n\\nLet's define a claw as a rooted tree with four vertices: one root vertex (called also as center) with three children. It looks like a claw:\\n\\n [Image] The center of the claw is the vertex with label $1$. \\n\\nLee has a Rooted Dead Bush of level $n$. Initially, all vertices of his RDB are green.\\n\\nIn one move, he can choose a claw in his RDB, if all vertices in the claw are green and all vertices of the claw are children of its center, then he colors the claw's vertices in yellow.\\n\\nHe'd like to know the maximum number of yellow vertices he can achieve. Since the answer might be very large, print it modulo $10^9+7$.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases.\\n\\nNext $t$ lines contain test cases — one per line.\\n\\nThe first line of each test case contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^6$) — the level of Lee's RDB.\\n\\n\\n-----Output-----\\n\\nFor each test case, print a single integer — the maximum number of yellow vertices Lee can make modulo $10^9 + 7$.\\n\\n\\n-----Example-----\\nInput\\n7\\n1\\n2\\n3\\n4\\n5\\n100\\n2000000\\n\\nOutput\\n0\\n0\\n4\\n4\\n12\\n990998587\\n804665184\\n\\n\\n\\n-----Note-----\\n\\nIt's easy to see that the answer for RDB of level $1$ or $2$ is $0$.\\n\\nThe answer for RDB of level $3$ is $4$ since there is only one claw we can...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def gns():\\n    return list(map(int,input().split()))\\nt=int(input())\\nns=[]\\nans=[0,0,0,4,4,12]\\nfor _ in range(t):\\n    n=int(input())\\n    ns.append(n)\\nmx=max(ns)\\nmd=10**9+7\\nfor i in range(6,mx+6):\\n    ans.append((ans[-2]*2+ans[-1]+(4 if i%3==0 else 0))%md)\\nfor ni in ns:\\n    print(ans[ni])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/581a52d305fe7756720002eb:\\nCongratulations! That Special Someone has given you their phone number.\\n\\nBut WAIT, is it a valid number? \\n\\nYour task is to write a function that verifies whether a given string contains a valid British mobile (cell) phone number or not. \\n\\nIf valid, return 'In with a chance'.\\n\\nIf invalid, or if you're given an empty string, return 'Plenty more fish in the sea'.\\n\\nA number can be valid in the following ways: \\n\\nHere in the UK mobile numbers begin with '07' followed by 9 other digits, e.g. '07454876120'.\\n\\nSometimes the number is preceded by the country code, the prefix '+44', which replaces the '0' in ‘07’, e.g. '+447454876120'.\\n\\nAnd sometimes you will find numbers with dashes in-between digits or on either side, e.g. '+44--745---487-6120' or '-074-54-87-61-20-'. As you can see, dashes may be consecutive. \\n\\nGood Luck Romeo\\/Juliette!\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import re\\n\\nVALID_NUM = re.compile(r'(\\\\+44|0)7\\\\d{9}$')\\n\\ndef validate_number(s):\\n    return \\\"In with a chance\\\" if VALID_NUM.match(s.replace(\\\"-\\\",\\\"\\\")) else  \\\"Plenty more fish in the sea\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1215\\/C:\\nMonocarp has got two strings $s$ and $t$ having equal length. Both strings consist of lowercase Latin letters \\\"a\\\" and \\\"b\\\". \\n\\nMonocarp wants to make these two strings $s$ and $t$ equal to each other. He can do the following operation any number of times: choose an index $pos_1$ in the string $s$, choose an index $pos_2$ in the string $t$, and swap $s_{pos_1}$ with $t_{pos_2}$.\\n\\nYou have to determine the minimum number of operations Monocarp has to perform to make $s$ and $t$ equal, and print any optimal sequence of operations — or say that it is impossible to make these strings equal.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $n$ $(1 \\\\le n \\\\le 2 \\\\cdot 10^{5})$ — the length of $s$ and $t$.\\n\\nThe second line contains one string $s$ consisting of $n$ characters \\\"a\\\" and \\\"b\\\". \\n\\nThe third line contains one string $t$ consisting of $n$ characters \\\"a\\\" and \\\"b\\\". \\n\\n\\n-----Output-----\\n\\nIf it is impossible to make these strings equal, print $-1$.\\n\\nOtherwise, in the first line print $k$ — the minimum number of operations required to make the strings equal. In each of the next $k$ lines print two integers — the index in the string $s$ and the index in the string $t$ that should be used in the corresponding swap operation. \\n\\n\\n-----Examples-----\\nInput\\n4\\nabab\\naabb\\n\\nOutput\\n2\\n3 3\\n3 2\\n\\nInput\\n1\\na\\nb\\n\\nOutput\\n-1\\n\\nInput\\n8\\nbabbaabb\\nabababaa\\n\\nOutput\\n3\\n2 6\\n1 3\\n7 8\\n\\n\\n\\n-----Note-----\\n\\nIn the first example two operations are enough. For example, you can swap the third letter in $s$ with the third letter in $t$. Then $s = $ \\\"abbb\\\", $t = $ \\\"aaab\\\". Then swap the third letter in $s$ and the second letter in $t$. Then both $s$ and $t$ are equal to \\\"abab\\\".\\n\\nIn the second example it's impossible to make two strings equal.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\ns1 = input()\\ns2 = input()\\nab = []\\nba = []\\nfor i in range(n):\\n    if s1[i] == 'a' and s2[i] == 'b':\\n        ab.append(i)\\n    elif s1[i] == 'b' and s2[i] == 'a':\\n        ba.append(i)\\nif (len(ab) + len(ba)) % 2:\\n    print(-1)\\nelse:\\n    print(len(ab) \\/\\/ 2 + len(ba) \\/\\/ 2 + (len(ab) % 2) * 2)\\n    for i in range(1, len(ab), 2):\\n        print(ab[i - 1] + 1, ab[i] + 1)\\n    for i in range(1, len(ba), 2):\\n        print(ba[i - 1] + 1, ba[i] + 1)\\n    if len(ab) % 2:\\n        print(ab[-1] + 1, ab[-1] + 1)\\n        print(ab[-1] + 1, ba[-1] + 1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA positive integer is called a 2-3-integer, if it is equal to 2^{x}·3^{y} for some non-negative integers x and y. In other words, these integers are such integers that only have 2 and 3 among their prime divisors. For example, integers 1, 6, 9, 16 and 108 — are 2-3 integers, while 5, 10, 21 and 120 are not.\\n\\nPrint the number of 2-3-integers on the given segment [l, r], i. e. the number of sich 2-3-integers t that l ≤ t ≤ r.\\n\\n\\n-----Input-----\\n\\nThe only line contains two integers l and r (1 ≤ l ≤ r ≤ 2·10^9).\\n\\n\\n-----Output-----\\n\\nPrint a single integer the number of 2-3-integers on the segment [l, r].\\n\\n\\n-----Examples-----\\nInput\\n1 10\\n\\nOutput\\n7\\n\\nInput\\n100 200\\n\\nOutput\\n5\\n\\nInput\\n1 2000000000\\n\\nOutput\\n326\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the 2-3-integers are 1, 2, 3, 4, 6, 8 and 9.\\n\\nIn the second example the 2-3-integers are 108, 128, 144, 162 and 192.\",\"targets\":\"a = [1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768, 65536, 131072, 262144, 524288, 1048576, 2097152, 4194304, 8388608, 16777216, 33554432, 67108864, 134217728, 268435456, 536870912, 1073741824]\\nb = [1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049, 177147, 531441, 1594323, 4782969, 14348907, 43046721, 129140163, 387420489, 1162261467]\\n\\nl = list(map(int, input().split()))\\n#print(l[0])\\n#print(l[1])\\n\\nsc = 0\\n\\n\\nfor i in a:\\n    for j in b:\\n        x = i*j\\n        #print(i)\\n        #print(j)\\n        #print(x)\\n        #print(sc)\\n        if (x >= l[0] and x <= l[1]):\\n            sc += 1\\n\\n\\nprint(sc)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMr Keks is a typical white-collar in Byteland.\\n\\nHe has a bookshelf in his office with some books on it, each book has an integer positive price.\\n\\nMr Keks defines the value of a shelf as the sum of books prices on it. \\n\\nMiraculously, Mr Keks was promoted and now he is moving into a new office.\\n\\nHe learned that in the new office he will have not a single bookshelf, but exactly $k$ bookshelves. He decided that the beauty of the $k$ shelves is the bitwise AND of the values of all the shelves.\\n\\nHe also decided that he won't spend time on reordering the books, so he will place several first books on the first shelf, several next books on the next shelf and so on. Of course, he will place at least one book on each shelf. This way he will put all his books on $k$ shelves in such a way that the beauty of the shelves is as large as possible. Compute this maximum possible beauty.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $k$ ($1 \\\\leq k \\\\leq n \\\\leq 50$) — the number of books and the number of shelves in the new office.\\n\\nThe second line contains $n$ integers $a_1, a_2, \\\\ldots a_n$, ($0 < a_i < 2^{50}$) — the prices of the books in the order they stand on the old shelf.\\n\\n\\n-----Output-----\\n\\nPrint the maximum possible beauty of $k$ shelves in the new office.\\n\\n\\n-----Examples-----\\nInput\\n10 4\\n9 14 28 1 7 13 15 29 2 31\\n\\nOutput\\n24\\n\\nInput\\n7 3\\n3 14 15 92 65 35 89\\n\\nOutput\\n64\\n\\n\\n\\n-----Note-----\\n\\nIn the first example you can split the books as follows:\\n\\n$$(9 + 14 + 28 + 1 + 7) \\\\& (13 + 15) \\\\& (29 + 2) \\\\& (31) = 24.$$\\n\\nIn the second example you can split the books as follows:\\n\\n$$(3 + 14 + 15 + 92) \\\\& (65) \\\\& (35 + 89) = 64.$$\",\"targets\":\"#!\\/usr\\/bin\\/env python3\\n\\n[n, k] = list(map(int, input().strip().split()))\\nais = list(map(int, input().strip().split()))\\niais = [0 for _ in range(n + 1)]\\nfor i in range(n):\\n\\tiais[i + 1] = iais[i] + ais[i]\\n\\ndef calc(k, split):\\n\\tres = 0\\n\\tfor i in range(k):\\n\\t\\tres &= iais[split[i + 1]] - iais[split[i]]\\n\\treturn res\\n\\ndef check_mask(mask):\\n\\tdp = [[False for j in range(n + 1)] for i in range(k + 1)]\\n\\n\\tfor j in range(1, n - k + 1 + 1):\\n\\t\\tdp[1][j] = (iais[j] & mask == mask)\\n\\tif not any(dp[1]):\\n\\t\\treturn False\\n\\n\\tfor i in range(2, k + 1):\\n\\t\\tfor j in range(i, n - (k - i) + 1):\\n\\t\\t\\tdp[i][j] = any(dp[i - 1][r] and ((iais[j] - iais[r]) & mask == mask) for r in range(i - 1, j - 1 + 1))\\n\\t\\tif not any(dp[i]):\\n\\t\\t\\treturn False\\n\\n\\treturn dp[k][n]\\n\\n\\nmask = 0\\nfor i in range(55, -1, -1):\\n\\tif check_mask(mask | (1 << i)):\\n\\t\\tmask |= 1 << i\\n\\nprint (mask)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nРодители Васи хотят, чтобы он как можно лучше учился. Поэтому если он получает подряд три положительные оценки («четвёрки» или «пятёрки»), они дарят ему подарок. Соответственно, оценки «единица», «двойка» и «тройка» родители Васи считают плохими. Когда Вася получает подряд три хорошие оценки, ему сразу вручают подарок, но для того, чтобы получить ещё один подарок, ему вновь надо получить подряд ещё три хорошие оценки.\\n\\nНапример, если Вася получит подряд пять «четвёрок» оценок, а потом «двойку», то ему дадут только один подарок, а вот если бы «четвёрок» было уже шесть, то подарков было бы два. \\n\\nЗа месяц Вася получил n оценок. Вам предстоит посчитать количество подарков, которые получил Вася. Оценки будут даны именно в том порядке, в котором Вася их получал. \\n\\n\\n-----Входные данные-----\\n\\nВ первой строке входных данных следует целое положительное число n (3 ≤ n ≤ 1000) — количество оценок, полученных Васей.\\n\\nВо второй строке входных данных следует последовательность из n чисел a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 5) — оценки, полученные Васей. Оценки заданы в том порядке, в котором Вася их получил. \\n\\n\\n-----Выходные данные-----\\n\\nВыведите одно целое число — количество подарков, полученных Васей.\\n\\n\\n-----Примеры-----\\nВходные данные\\n6\\n4 5 4 5 4 4\\n\\nВыходные данные\\n2\\n\\nВходные данные\\n14\\n1 5 4 5 2 4 4 5 5 4 3 4 5 5\\n\\nВыходные данные\\n3\\n\\n\\n\\n-----Примечание-----\\n\\nВ первом примере Вася получит два подарка — за первые три положительные оценки и за следующую тройку положительных оценок соответственно.\",\"targets\":\"n = int(input())\\na = list(map(int, input().split()))\\ncount = 0\\ni = 1\\nwhile i < len(a) - 1:\\n    if a[i - 1] > 3 and a[i] > 3 and a[i + 1] > 3:\\n        count += 1\\n        i += 3\\n    else:\\n        i += 1\\nprint(count)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/PERPALIN:\\nChef recently learned about concept of periodicity of strings. A string is said to have a period P, if P divides N and for each i, the i-th of character of the string is same as i-Pth character (provided it exists), e.g. \\\"abab\\\" has a period P = 2, It also has a period of P = 4, but it doesn't have a period of 1 or 3.\\nChef wants to construct a string of length N that is a palindrome and has a period P. It's guaranteed that N is divisible by P. This string can only contain character 'a' or 'b'. Chef doesn't like the strings that contain all a's or all b's.\\nGiven the values of N, P, can you construct one such palindromic string that Chef likes? If it's impossible to do so, output \\\"impossible\\\" (without quotes)\\n\\n-----Input-----\\nThe first line of the input contains an integer T denoting the number of test cases.\\nThe only line of each test case contains two space separated integers N, P.\\n\\n-----Output-----\\nFor each test case, output a single line containing the answer of the problem, i.e. the valid string if it exists otherwise \\\"impossible\\\"  (without quotes). If there are more than possible answers, you can output any.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 20\\n- 1 ≤ P, N ≤ 105\\n\\n-----Subtasks-----\\n- Subtask #1 (25 points) : P = N\\n- Subtask #2 (75 points) : No additional constraints\\n\\n-----Example-----\\nInput\\n5\\n3 1\\n2 2\\n3 3\\n4 4\\n6 3\\n\\nOutput\\nimpossible\\nimpossible\\naba\\nabba\\nabaaba\\n\\n-----Explanation-----\\nExample 1: The only strings possible are either aaa or bbb, which Chef doesn't like. So, the answer is impossible.\\nExample 2: There are four possible strings, aa, ab, ba, bb. Only aa and bb are palindromic, but Chef doesn't like these strings. Hence, the answer is impossible.\\nExample 4: The string abba is a palindrome and has a period of 4.\\nExample 5: The string abaaba is a palindrome and has a period of length 3.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t = int(input())\\nwhile(t>0):\\n t-=1\\n n,p = [int(x) for x in input().split()]\\n if(p <= 2):\\n  print('impossible')\\n  continue\\n else:\\n  s = 'a' + ('b'*(p-2)) + 'a'\\n  s = s*int(n\\/p)\\n  print(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nBasic regex tasks. Write a function that takes in a numeric code of any length. The function should check if the code begins with 1, 2, or 3 and return `true` if so. Return `false` otherwise. \\n\\nYou can assume the input will always be a number.\",\"targets\":\"from re import match\\nfrom math import log10\\n\\ndef validate_code(code):\\n    # Without bothering with string conversion\\n    return 0 < code \\/\\/ 10**int(log10(code)) < 4\\n    \\n    # Title says regex so let's write one\\n    return bool(match(\\\"\\\\A[1-3]\\\", str(code)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc077\\/tasks\\/arc084_a:\\nThe season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.\\nHe has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.\\nTo build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.\\nHow many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq A_i \\\\leq 10^9(1\\\\leq i\\\\leq N)\\n - 1 \\\\leq B_i \\\\leq 10^9(1\\\\leq i\\\\leq N)\\n - 1 \\\\leq C_i \\\\leq 10^9(1\\\\leq i\\\\leq N)\\n - All input values are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 ... A_N\\nB_1 ... B_N\\nC_1 ... C_N\\n\\n-----Output-----\\nPrint the number of different altars that Ringo can build.\\n\\n-----Sample Input-----\\n2\\n1 5\\n2 4\\n3 6\\n\\n-----Sample Output-----\\n3\\n\\nThe following three altars can be built:\\n - Upper: 1-st part, Middle: 1-st part, Lower: 1-st part\\n - Upper: 1-st part, Middle: 1-st part, Lower: 2-nd part\\n - Upper: 1-st part, Middle: 2-nd part, Lower: 2-nd part\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import bisect\\n\\nN = int(input())\\nA = list(map(int, input().split()))\\nB = list(map(int, input().split()))\\nC = list(map(int, input().split()))\\n\\nA.sort()\\nB.sort()\\nC.sort()\\n\\nans = 0\\n\\nfor b in B:\\n    a_count = bisect.bisect_left(A, b)\\n    c_count = N - bisect.bisect_right(C, b)\\n    ans += a_count * c_count\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/56a13035eb55c8436a000041:\\nYour job is to return the volume of a cup when given the diameter of the top, the diameter of the bottom and the height.\\n\\nYou know that there is a steady gradient from the top to the bottom.\\n\\nYou want to return the volume rounded to 2 decimal places.\\n\\nExmples:\\n```python\\ncup_volume(1, 1, 1)==0.79\\n\\ncup_volume(10, 8, 10)==638.79\\n\\ncup_volume(1000, 1000, 1000)==785398163.4\\n\\ncup_volume(13.123, 123.12, 1)==4436.57\\n\\ncup_volume(5, 12, 31)==1858.51\\n```\\n\\nYou will only be passed positive numbers.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"cup_volume=lambda d,D,h:round(__import__('math').pi*h\\/12*(d*d+d*D+D*D),2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1420\\/C2:\\nThis is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.\\n\\nPikachu is a cute and friendly pokémon living in the wild pikachu herd.\\n\\nBut it has become known recently that infamous team R wanted to steal all these pokémon! Pokémon trainer Andrew decided to help Pikachu to build a pokémon army to resist.\\n\\nFirst, Andrew counted all the pokémon — there were exactly $n$ pikachu. The strength of the $i$-th pokémon is equal to $a_i$, and all these numbers are distinct.\\n\\nAs an army, Andrew can choose any non-empty subsequence of pokemons. In other words, Andrew chooses some array $b$ from $k$ indices such that $1 \\\\le b_1 < b_2 < \\\\dots < b_k \\\\le n$, and his army will consist of pokémons with forces $a_{b_1}, a_{b_2}, \\\\dots, a_{b_k}$.\\n\\nThe strength of the army is equal to the alternating sum of elements of the subsequence; that is, $a_{b_1} - a_{b_2} + a_{b_3} - a_{b_4} + \\\\dots$.\\n\\nAndrew is experimenting with pokémon order. He performs $q$ operations. In $i$-th operation Andrew swaps $l_i$-th and $r_i$-th pokémon.\\n\\nAndrew wants to know the maximal stregth of the army he can achieve with the initial pokémon placement. He also needs to know the maximal strength after each operation.\\n\\nHelp Andrew and the pokémon, or team R will realize their tricky plan!\\n\\n\\n-----Input-----\\n\\nEach test contains multiple test cases.\\n\\nThe first line contains one positive integer $t$ ($1 \\\\le t \\\\le 10^3$) denoting the number of test cases. Description of the test cases follows.\\n\\nThe first line of each test case contains two integers $n$ and $q$ ($1 \\\\le n \\\\le 3 \\\\cdot 10^5, 0 \\\\le q \\\\le 3 \\\\cdot 10^5$) denoting the number of pokémon and number of operations respectively.\\n\\nThe second line contains $n$ distinct positive integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le n$) denoting the strengths of the pokémon.\\n\\n$i$-th of the last $q$ lines contains two positive integers $l_i$ and $r_i$ ($1 \\\\le l_i \\\\le r_i \\\\le n$)...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = lambda: sys.stdin.readline().rstrip()\\n\\nANS = []\\nT = int(input())\\nfor _ in range(T):\\n    N, Q = list(map(int, input().split()))\\n    A = [int(a) for a in input().split()]\\n    ans = sum(max(b - a, 0) for a, b in zip([0] + A, A))\\n    ANS.append(ans)\\n    for _ in range(Q):\\n        l, r = list(map(int, input().split()))\\n        l, r = l-1, r-1\\n        if l == r:\\n            ANS.append(ans)\\n            continue\\n        \\n        ans -= max(A[l] - A[l-1], 0) if l else A[l]\\n        if l < N - 1: ans -= max(A[l+1] - A[l], 0)\\n        if r > l + 1: ans -= max(A[r] - A[r-1], 0)\\n        if r < N - 1: ans -= max(A[r+1] - A[r], 0)\\n        \\n        A[l], A[r] = A[r], A[l]\\n        \\n        ans += max(A[l] - A[l-1], 0) if l else A[l]\\n        if l < N - 1: ans += max(A[l+1] - A[l], 0)\\n        if r > l + 1: ans += max(A[r] - A[r-1], 0)\\n        if r < N - 1: ans += max(A[r+1] - A[r], 0)\\n        \\n        ANS.append(ans)\\n\\nprint(\\\"\\\\n\\\".join(map(str, ANS)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are $X$ people participating in a quiz competition and their IDs have been numbered from $1$ to $X$ (both inclusive). Beth needs to form a team among these $X$ participants. She has been given an integer $Y$. She can choose participants whose ID numbers are divisible by $Y$. \\nNow that the team is formed, Beth wants to know the strength of her team. The strength of a team is the sum of all the last digits of the team members’ ID numbers.\\nCan you help Beth in finding the strength of her team?\\n\\n-----Input:-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. $T$ lines follow \\n- The first line of each test case contains $X$ and $Y$. \\n\\n-----Output:-----\\n- For each test case print the strength of Beth's team\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 1000$\\n- $1 \\\\leq X,Y \\\\leq 10^{20}$\\n\\n-----Sample Input:-----\\n2\\n10 3\\n\\n15 5\\n\\n-----Sample Output:-----\\n18 \\n\\n10\\n\\n-----EXPLANATION:-----\\n- Example case 1: ID numbers divisible by 3 are 3,6,9 and the sum of the last digits are 3+6+9=18\",\"targets\":\"for _ in range(int(input())):\\r\\n    a,b=map(int,input().split())\\r\\n    ans=0\\r\\n    y=a\\/\\/b\\r\\n    x=b\\r\\n    for i in range(y):\\r\\n        x=x%10\\r\\n        ans+=x\\r\\n        x+=b\\r\\n    print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTakahashi, who is a novice in competitive programming, wants to learn M algorithms.\\nInitially, his understanding level of each of the M algorithms is 0.\\nTakahashi is visiting a bookstore, where he finds N books on algorithms.\\nThe i-th book (1\\\\leq i\\\\leq N) is sold for C_i yen (the currency of Japan). If he buys and reads it, his understanding level of the j-th algorithm will increase by A_{i,j} for each j (1\\\\leq j\\\\leq M).\\nThere is no other way to increase the understanding levels of the algorithms.\\nTakahashi's objective is to make his understanding levels of all the M algorithms X or higher. Determine whether this objective is achievable. If it is achievable, find the minimum amount of money needed to achieve it.\",\"targets\":\"def main():\\n    n, m, x = list(map(int, input().split()))\\n    sofar = 10 ** 5 + 1\\n    cl = list(list(map(int, input().split())) for _ in range(n))\\n    # print(cl)\\n    ans = float('inf')\\n    for i in range(2 ** n):\\n        tmp = [0] * m\\n        cost = 0\\n        for j in range(n):\\n            # print(bin(j), i, bin(i >> j))\\n            if (i >> j) & 1:\\n                for k in range(m):\\n                    tmp[k] += cl[j][k + 1]\\n                cost += cl[j][0]\\n                # print(tmp)\\n        for t in tmp:\\n            if t < x:\\n                break\\n        else:\\n            ans = min(ans, cost)\\n    if ans == float('inf'):\\n        return -1\\n    else:\\n        return ans\\n\\n\\ndef __starting_point():\\n    print((main()))\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/787\\/A:\\nA monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times b, b + a, b + 2a, b + 3a, ... and Morty screams at times d, d + c, d + 2c, d + 3c, ....  [Image] \\n\\nThe Monster will catch them if at any point they scream at the same time, so it wants to know when it will catch them (the first time they scream at the same time) or that they will never scream at the same time.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains two integers a and b (1 ≤ a, b ≤ 100). \\n\\nThe second line contains two integers c and d (1 ≤ c, d ≤ 100).\\n\\n\\n-----Output-----\\n\\nPrint the first time Rick and Morty will scream at the same time, or  - 1 if they will never scream at the same time.\\n\\n\\n-----Examples-----\\nInput\\n20 2\\n9 19\\n\\nOutput\\n82\\n\\nInput\\n2 1\\n16 12\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample testcase, Rick's 5th scream and Morty's 8th time are at time 82. \\n\\nIn the second sample testcase, all Rick's screams will be at odd times and Morty's will be at even times, so they will never scream at the same time.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from fractions import gcd\\n\\na,b = list(map(int,input().split()))\\nc,d = list(map(int,input().split()))\\n\\n#ax+b=cy+d\\n\\nval = gcd(a,c)\\n\\nif (d-b)%val != 0:\\n    print(-1)\\nelse:\\n    i=b\\n    while True:\\n        if ((i-d)%c==0) and (i-d)\\/c>=0:\\n            break\\n        i=i+a\\n    print(i)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nI need to save some money to buy a gift. I think I can do something like that:\\n\\nFirst week (W0) I save nothing on Sunday, 1 on Monday, 2 on Tuesday... 6 on Saturday,\\nsecond week (W1) 2 on Monday... 7 on Saturday and so on according to the table below where the days are numbered from 0 to 6.\\n\\nCan you tell me how much I will have for my gift on Saturday evening after I have saved 12? (Your function finance(6) should return 168 which is the sum of the savings in the table). \\n\\nImagine now that we live on planet XY140Z-n where the days of the week are numbered from 0 to n (integer n > 0) and where\\nI save from week number 0 to week number n included (in the table below n = 6).\\n\\nHow much money would I have at the end of my financing plan on planet XY140Z-n?\\n\\n\\n\\n  -- |Su|Mo|Tu|We|Th|Fr|Sa|\\n   --|--|--|--|--|--|--|--|\\n  W6 |  |  |  |  |  |  |12|\\n  W5 |  |  |  |  |  |10|11|\\n  W4 |  |  |  |  |8 |9 |10|\\n  W3 |  |  |  |6 |7 |8 |9 |\\n  W2 |  |  |4 |5 |6 |7 |8 |\\n  W1 |  |2 |3 |4 |5 |6 |7 |\\n  W0 |0 |1 |2 |3 |4 |5 |6 |\\n  \\n#Example:\\n```\\nfinance(5) --> 105\\nfinance(6) --> 168\\nfinance(7) --> 252\\nfinance(5000) --> 62537505000\\n```\\n#Hint: \\ntry to avoid nested loops\",\"targets\":\"def finance(n):\\n    return sum([sum(range(2*i,i+n+1)) for i in range(n+1)])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1011\\/A:\\nNatasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.\\n\\nThere are $n$ stages available. The rocket must contain exactly $k$ of them. Stages in the rocket should be ordered by their weight. So, after the stage with some letter can go only stage with a letter, which is at least two positions after in the alphabet (skipping one letter in between, or even more). For example, after letter 'c' can't go letters 'a', 'b', 'c' and 'd', but can go letters 'e', 'f', ..., 'z'.\\n\\nFor the rocket to fly as far as possible, its weight should be minimal. The weight of the rocket is equal to the sum of the weights of its stages. The weight of the stage is the number of its letter in the alphabet. For example, the stage 'a 'weighs one ton,' b 'weighs two tons, and' z' — $26$ tons.\\n\\nBuild the rocket with the minimal weight or determine, that it is impossible to build a rocket at all. Each stage can be used at most once.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains two integers — $n$ and $k$ ($1 \\\\le k \\\\le n \\\\le 50$) – the number of available stages and the number of stages to use in the rocket.\\n\\nThe second line contains string $s$, which consists of exactly $n$ lowercase Latin letters. Each letter defines a new stage, which can be used to build the rocket. Each stage can be used at most once.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all.\\n\\n\\n-----Examples-----\\nInput\\n5 3\\nxyabd\\n\\nOutput\\n29\\nInput\\n7 4\\nproblem\\n\\nOutput\\n34\\nInput\\n2 2\\nab\\n\\nOutput\\n-1\\nInput\\n12 1\\nabaabbaaabbb\\n\\nOutput\\n1\\n\\n\\n-----Note-----\\n\\nIn the first example, the following rockets satisfy the condition:\\n\\n\\n\\n \\\"adx\\\" (weight is $1+4+24=29$);\\n\\n \\\"ady\\\" (weight is $1+4+25=30$);\\n\\n \\\"bdx\\\" (weight is $2+4+24=30$);\\n\\n \\\"bdy\\\" (weight is $2+4+25=31$).\\n\\nRocket \\\"adx\\\" has the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, k = map(int, input().split())\\ns = sorted(list(input()))\\nprev = 0\\nw = 0\\nfor el in s:\\n\\tif k == 0:\\n\\t\\tbreak\\n\\tif ord(el) >= prev + 2:\\n\\t\\tk -= 1\\n\\t\\tw += ord(el) - ord('a') + 1\\n\\t\\tprev = ord(el)\\nif k == 0:\\n\\tprint(w)\\nelse:\\n\\tprint(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe Government of Siruseri is no different from any other when it comes to being \\\"capital-centric\\\" in its policies. Recently the government decided to set up a nationwide fiber-optic network to take Siruseri into the digital age. And as usual, this decision was implemented in a capital centric manner --- from each city in the country, a fiber optic cable was laid to the capital! Thus, traffic between any two cities had to go through the capital.\\nSoon, it became apparent that this was not quite a clever idea, since any breakdown at the capital resulted in the disconnection of services between other cities. So, in the second phase, the government plans to connect a few more pairs of cities directly by fiber-optic cables. The government has specified that this is to be done in such a way that the disruption of services at any one city will still leave the rest of the country connected.\\nThe government has data on the cost of laying fiber optic cables between every pair of cities. You task is to compute the minimum cost of additional cabling required to ensure the requirement described above is met.\\nFor example, if Siruseri has $4$ cities numbered $1,2,3$ and $4$ where $1$ is the capital and further suppose that the cost of laying cables between these cities are as given in the table below:\\n\\nNote that the government has already connected the capital with every other city. So, if we connect the cities $2$ and $3$ as well as $3$ and $4$, you can check that disruption of service at any one city will still leave the other cities connected. The cost of connecting these two pairs is $4 + 6 = 10$. The same effect could have been achieved by connecting $2$ and $3$ as well as $2$ and $4$, which would have cost $4 + 5 = 9$. You can check that this is the best you can do.\\nYour task is to write a program that allows the government to determine the minimum cost it has to incur in laying additional cables to fulfil the requirement.\\n\\n-----Input:-----\\n- The first line of the input contains a single integer $N$ indicating the...\",\"targets\":\"n=int(input())\\r\\nl=[]\\r\\nfor i in range(n):\\r\\n\\tl.append([int(x) for x in input().split()])\\r\\nd=[10**9]*(n)\\r\\nq=set([int(x) for x in range(1,n)])\\r\\nd[1]=0\\r\\n#print(q)\\r\\ndef extract():\\r\\n\\tmini=10**9\\r\\n\\to=0\\r\\n\\tfor i in range(1,len(d)):\\r\\n\\t\\tif d[i]<mini and i in q:\\r\\n\\t\\t\\tmini=d[i]\\r\\n\\t\\t\\to=i\\r\\n\\tq.remove(o)\\r\\n\\treturn o\\r\\nwhile len(q)!=0:\\r\\n\\tx=extract()\\r\\n\\tfor i in range(1,n):\\r\\n\\t\\tif i in q and l[x][i]<d[i]:\\r\\n\\t\\t\\td[i]=l[x][i]\\r\\nprint(sum(d[1:]))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1063\\/B:\\nYou are playing some computer game. One of its levels puts you in a maze consisting of n lines, each of which contains m cells. Each cell either is free or is occupied by an obstacle. The starting cell is in the row r and column c. In one step you can move one square up, left, down or right, if the target cell is not occupied by an obstacle. You can't move beyond the boundaries of the labyrinth.\\n\\nUnfortunately, your keyboard is about to break, so you can move left no more than x times and move right no more than y times. There are no restrictions on the number of moves up and down since the keys used to move up and down are in perfect condition.\\n\\nNow you would like to determine for each cell whether there exists a sequence of moves that will put you from the starting cell to this particular one. How many cells of the board have this property?\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n, m (1 ≤ n, m ≤ 2000) — the number of rows and the number columns in the labyrinth respectively.\\n\\nThe second line contains two integers r, c (1 ≤ r ≤ n, 1 ≤ c ≤ m) — index of the row and index of the column that define the starting cell.\\n\\nThe third line contains two integers x, y (0 ≤ x, y ≤ 10^9) — the maximum allowed number of movements to the left and to the right respectively.\\n\\nThe next n lines describe the labyrinth. Each of them has length of m and consists only of symbols '.' and '*'. The j-th character of the i-th line corresponds to the cell of labyrinth at row i and column j. Symbol '.' denotes the free cell, while symbol '*' denotes the cell with an obstacle.\\n\\nIt is guaranteed, that the starting cell contains no obstacles.\\n\\n\\n-----Output-----\\n\\nPrint exactly one integer — the number of cells in the labyrinth, which are reachable from starting cell, including the starting cell itself.\\n\\n\\n-----Examples-----\\nInput\\n4 5\\n3 2\\n1 2\\n.....\\n.***.\\n...**\\n*....\\n\\nOutput\\n10\\n\\nInput\\n4 4\\n2 2\\n0 1\\n....\\n..*.\\n....\\n....\\n\\nOutput\\n7\\n\\n\\n\\n-----Note-----\\n\\nCells, reachable in the corresponding example, are marked with '+'.\\n\\nFirst example: ...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import deque\\nn,m = [int(x) for x in input().split()]\\nx,y = [int(x) for x in input().split()]\\nleft,right = [int(x) for x in input().split()]\\ns=[]\\nans=0\\nd=[None]*2007\\nfor i in range(0,2007):\\n    d[i]=[0 for j in range(0,2007)]\\n\\nfor i in range(0,n):\\n    s.append(input())\\n\\nq = deque()\\n\\nq.append([x-1,y-1,left,right])\\n\\nwhile(len(q)):\\n    v = q[0]\\n    q.popleft()\\n    \\n    if(v[0]<0 or v[0]>=n or v[1]<0 or v[1]>=m or d[v[0]][v[1]]==1 or v[2]<0 or v[3]<0 or s[v[0]][v[1]]=='*'): continue\\n    \\n    d[v[0]][v[1]]=1\\n    \\n    q.appendleft([v[0]+1,v[1],v[2],v[3]])\\n    q.appendleft([v[0]-1,v[1],v[2],v[3]])\\n    q.append([v[0],v[1]+1,v[2],v[3]-1])\\n    q.append([v[0],v[1]-1,v[2]-1,v[3]])\\n       \\n   \\n    \\n    \\nfor i in range(0,n):\\n    for j in range(0,m):\\n        ans+=d[i][j]\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTic-Tac-Toe used to be Chef's favourite game during his childhood. Reminiscing in his childhood memories, he decided to create his own \\\"Tic-Tac-Toe\\\", with rules being similar to the original Tic-Tac-Toe, other than the fact that it is played on an NxN board.\\n\\nThe game is played between two players taking turns. First player puts an 'X' in an empty cell of the board, then the second player puts an 'O' in some other free cell. If the first player has K continuous X's or the second player has K continuous O's in row, column or diagonal, then he wins.\\n\\nChef started playing this new \\\"Tic-Tac-Toe\\\" with his assistant, beginning as the first player himself (that is, Chef plays 'X's). Currently, the game is ongoign, and it's Chef's turn. However, he needs to leave soon to begin tonight's dinner preparations, and has time to play only one more move. If he can win in one move, output \\\"YES\\\", otherwise output \\\"NO\\\" (without quotes). It is guaranteed that no player has already completed the winning criterion before this turn, and that it's a valid \\\"Tic-Tac-Toe\\\" game.\\n\\n-----Input-----\\nThe first line of input contains one integer T denoting the number of testcases. First line of each testcase contains two integers N and K, next N lines contains N characters each. Each character is either an 'X' denoting that the first player used this cell, an 'O' meaning that the second player used this cell, or a '.' (a period) representing a free cell.\\n\\n-----Output-----\\nFor each testcase, output, in a single line, \\\"YES\\\" if Chef can win in one move, or \\\"NO\\\" otherwise.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 100\\n- 3 ≤ N ≤ 20\\n- 1 ≤ K ≤ N\\n\\n-----Example-----\\nInput:\\n3\\n3 3\\nXOX\\nO.O\\nXOX\\n3 1\\n...\\n...\\n...\\n3 2\\n...\\n...\\n...\\n\\nOutput:\\nYES\\nYES\\nNO\\n\\nInput:\\n1\\n4 4\\nXOXO\\nOX..\\nXO..\\nOXOX\\n\\nOutput:\\nYES\\n\\n-----Subtasks-----\\n- Subtask 1:  K  = 1. Points - 10\\n- Subtask 2:  N  =  K  = 3. Points - 30\\n- Subtask 3: Original constraints. Points - 60\\n\\n-----Explanation-----\\nTest #1:\\n\\nIn first testcase, put 'X' in (2, 2), in second we can put 'X' in any cell and win. \\nTest #2:\\n\\nIf you...\",\"targets\":\"# cook your code here\\n\\n\\ndef checkRow(A,row,N,K):\\n    count = 0\\n    move  = 0\\n    for i in range(N):\\n        if(A[row][i]=='.'):\\n            move = move+1\\n        if(not(A[row][i]=='O') and move<2):\\n            count = count+1\\n        else:\\n            count = 0\\n        if(count==K):\\n            return 1\\n    return 0\\n    \\ndef checkCol(A,col,N,K):\\n    count = 0\\n    move  = 0\\n    for i in range(N):\\n        if(A[i][col]=='.'):\\n            move = move+1\\n        if(not(A[i][col]=='O') and move<2):\\n            count = count+1\\n        else:\\n            count = 0\\n        if(count==K):\\n            return 1\\n    return 0  \\n    \\ndef checkDiag(A,row,col,N,K):\\n    count = 0\\n    move  = 0\\n    \\n    for i in range(K):\\n        if(A[row+i][col+i]=='.'):\\n            move = move+1\\n        if(A[row+i][col+i]=='0' and move<=1):\\n            return 0\\n    \\n    if(move<2):\\n        return 1\\n    return 0\\n    \\ndef chck(A,N,K):\\n    flag = 0\\n    \\n    if(flag==0):\\n        #row\\n        for i in range(N):\\n            flag = checkRow(A,i,N,K)\\n            if(flag==1):\\n                break\\n    \\n    if(flag==0):\\n        #col\\n        for j in range(N):\\n            flag = checkCol(A,j,N,K)\\n            if(flag==1):\\n                break\\n    \\n    if(flag==0):\\n        #diag\\n        for i in range(N-K+1):\\n            for j in range(N-K+1):\\n                flag = checkDiag(A,i,j,N,K)\\n                if(flag==1):\\n                    break\\n            if(flag==1):\\n                    break\\n            \\n    return flag\\n\\nfor tests in range(eval(input())):\\n    [N,K] = list(map(int,input().split()))\\n    A = [\\\"\\\"]*N\\n    \\n    for i in range(N):\\n        A[i] = input()\\n    \\n    if(chck(A,N,K)==1):\\n        print(\\\"YES\\\")\\n    else:\\n        print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/52fba2a9adcd10b34300094c:\\nWrite a function that outputs the transpose of a matrix - a new matrix\\nwhere the columns and rows of the original are swapped.\\n\\nFor example, the transpose of:\\n  \\n    | 1 2 3 |\\n    | 4 5 6 |\\n\\nis\\n\\n    | 1 4 |\\n    | 2 5 |\\n    | 3 6 |\\n\\nThe input to your function will be an array of matrix rows. You can\\nassume that each row has the same length, and that the height and\\nwidth of the matrix are both positive.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def transpose(matrix):\\n    return list(map(list, zip(*matrix)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nImagine that there is a group of three friends: A, B and С. A owes B 20 rubles and B owes C 20 rubles. The total sum of the debts is 40 rubles. You can see that the debts are not organized in a very optimal manner. Let's rearrange them like that: assume that A owes C 20 rubles and B doesn't owe anything to anybody. The debts still mean the same but the total sum of the debts now equals 20 rubles.\\n\\nThis task is a generalisation of a described example. Imagine that your group of friends has n people and you know the debts between the people. Optimize the given debts without changing their meaning. In other words, finally for each friend the difference between the total money he should give and the total money he should take must be the same. Print the minimum sum of all debts in the optimal rearrangement of the debts. See the notes to the test samples to better understand the problem.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and m (1 ≤ n ≤ 100; 0 ≤ m ≤ 10^4). The next m lines contain the debts. The i-th line contains three integers a_{i}, b_{i}, c_{i} (1 ≤ a_{i}, b_{i} ≤ n; a_{i} ≠ b_{i}; 1 ≤ c_{i} ≤ 100), which mean that person a_{i} owes person b_{i} c_{i} rubles.\\n\\nAssume that the people are numbered by integers from 1 to n.\\n\\nIt is guaranteed that the same pair of people occurs at most once in the input. The input doesn't simultaneously contain pair of people (x, y) and pair of people (y, x).\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum sum of debts in the optimal rearrangement.\\n\\n\\n-----Examples-----\\nInput\\n5 3\\n1 2 10\\n2 3 1\\n2 4 1\\n\\nOutput\\n10\\n\\nInput\\n3 0\\n\\nOutput\\n0\\n\\nInput\\n4 3\\n1 2 1\\n2 3 1\\n3 1 1\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, you can assume that person number 1 owes 8 rubles to person number 2, 1 ruble to person number 3 and 1 ruble to person number 4. He doesn't owe anybody else anything. In the end, the total debt equals 10.\\n\\nIn the second sample, there are no debts.\\n\\nIn the third sample, you can annul all the debts.\",\"targets\":\"n, m = list(map(int, input().split()))\\n\\nms = [[0, 0] for i in range(n)]\\nfor i in range(m):\\n    a, b, c = list(map(int, input().split()))\\n    ms[a-1][0] += c\\n    ms[b-1][1] += c\\n\\nsol = 0\\nfor i in range(n):\\n    sol += max(ms[i][0] - ms[i][1], 0)\\n\\nprint(sol)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1395\\/B:\\nBoboniu likes playing chess with his employees. As we know, no employee can beat the boss in the chess game, so Boboniu has never lost in any round.\\n\\nYou are a new applicant for his company. Boboniu will test you with the following chess question:\\n\\nConsider a $n\\\\times m$ grid (rows are numbered from $1$ to $n$, and columns are numbered from $1$ to $m$). You have a chess piece, and it stands at some cell $(S_x,S_y)$ which is not on the border (i.e. $2 \\\\le S_x \\\\le n-1$ and $2 \\\\le S_y \\\\le m-1$).\\n\\nFrom the cell $(x,y)$, you can move your chess piece to $(x,y')$ ($1\\\\le y'\\\\le m, y' \\\\neq y$) or $(x',y)$ ($1\\\\le x'\\\\le n, x'\\\\neq x$). In other words, the chess piece moves as a rook. From the cell, you can move to any cell on the same row or column.\\n\\nYour goal is to visit each cell exactly once. Can you find a solution?\\n\\nNote that cells on the path between two adjacent cells in your route are not counted as visited, and it is not required to return to the starting point.\\n\\n\\n-----Input-----\\n\\nThe only line of the input contains four integers $n$, $m$, $S_x$ and $S_y$ ($3\\\\le n,m\\\\le 100$, $2 \\\\le S_x \\\\le n-1$, $2 \\\\le S_y \\\\le m-1$) — the number of rows, the number of columns, and the initial position of your chess piece, respectively.\\n\\n\\n-----Output-----\\n\\nYou should print $n\\\\cdot m$ lines.\\n\\nThe $i$-th line should contain two integers $x_i$ and $y_i$ ($1 \\\\leq x_i \\\\leq n$, $1 \\\\leq y_i \\\\leq m$), denoting the $i$-th cell that you visited. You should print exactly $nm$ pairs $(x_i, y_i)$, they should cover all possible pairs $(x_i, y_i)$, such that $1 \\\\leq x_i \\\\leq n$, $1 \\\\leq y_i \\\\leq m$.\\n\\nWe can show that under these constraints there always exists a solution. If there are multiple answers, print any.\\n\\n\\n-----Examples-----\\nInput\\n3 3 2 2\\n\\nOutput\\n2 2\\n1 2\\n1 3\\n2 3\\n3 3\\n3 2\\n3 1\\n2 1\\n1 1\\n\\nInput\\n3 4 2 2\\n\\nOutput\\n2 2\\n2 1\\n2 3\\n2 4\\n1 4\\n3 4\\n3 3\\n3 2\\n3 1\\n1 1\\n1 2\\n1 3\\n\\n\\n\\n-----Note-----\\n\\nPossible routes for two examples: [Image]\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,m,sx,sy = list(map(int, input().split()))\\n\\ndef do_row(sx, vis):\\n    last = -1\\n    for j in range(1, m+1):\\n        if (sx, j) not in vis:\\n            print(sx, j)\\n            vis.add((sx, j))\\n            last = j\\n    return last\\n\\nvis = set()\\nvis.add((sx,sy))\\nprint(sx,sy)\\nl = sy\\nl2 = do_row(sx, vis)\\nif l2 != -1:\\n    l = l2\\nfor i in range(1,n+1):\\n    if (i, l) in vis:\\n        continue\\n    print(i, l)\\n    vis.add((i, l))\\n    l2 = do_row(i, vis)\\n    if l2 != -1:\\n        l = l2\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA family of kookaburras are in my backyard.\\n\\nI can't see them all, but I can hear them!\\n\\n# How many kookaburras are there?\\n\\n\\n\\n\\n## Hint \\n\\nThe trick to counting kookaburras is to listen carefully\\n\\n* The males go ```HaHaHa```...\\n\\n* The females go ```hahaha```...\\n\\n* And they always alternate male\\/female\\n\\n\\n\\n^ Kata Note : No validation is necessary; only valid input will be passed :-)\",\"targets\":\"def kooka_counter(laughing):\\n    return 0 if laughing == '' else laughing.count('Hah') + laughing.count('haH') + 1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given K eggs, and you have access to a building with N floors from 1 to N. \\nEach egg is identical in function, and if an egg breaks, you cannot drop it again.\\nYou know that there exists a floor F with 0 <= F <= N such that any egg dropped at a floor higher than F will break, and any egg dropped at or below floor F will not break.\\nEach move, you may take an egg (if you have an unbroken one) and drop it from any floor X (with 1 <= X <= N). \\nYour goal is to know with certainty what the value of F is.\\nWhat is the minimum number of moves that you need to know with certainty what F is, regardless of the initial value of F?\\n \\n\\n\\n\\nExample 1:\\nInput: K = 1, N = 2\\nOutput: 2\\nExplanation: \\nDrop the egg from floor 1.  If it breaks, we know with certainty that F = 0.\\nOtherwise, drop the egg from floor 2.  If it breaks, we know with certainty that F = 1.\\nIf it didn't break, then we know with certainty F = 2.\\nHence, we needed 2 moves in the worst case to know what F is with certainty.\\n\\n\\nExample 2:\\nInput: K = 2, N = 6\\nOutput: 3\\n\\n\\nExample 3:\\nInput: K = 3, N = 14\\nOutput: 4\\n\\n \\nNote:\\n\\n1 <= K <= 100\\n1 <= N <= 10000\",\"targets\":\"class Solution:\\n    def superEggDrop(self, K: int, N: int) -> int:\\n        def f(t):\\n            a=0\\n            r=1\\n            for i in range(1, K+1):\\n                r *= (t-i+1)\\n                r\\/\\/=i\\n                a+=r\\n                if a>=N: \\n                    break\\n            return a\\n        \\n        l, h= 1, N\\n        while l<h:\\n            m=(l+h)\\/\\/2\\n            if f(m)<N:\\n                l=m+1\\n            else:\\n                h=m\\n        return l\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n The string is called `prime` if it cannot be constructed by concatenating some (more than one) equal strings together.\\n\\n For example, \\\"abac\\\" is prime, but \\\"xyxy\\\" is not(\\\"xyxy\\\"=\\\"xy\\\"+\\\"xy\\\").\\n \\n Given a string determine if it is prime or not.\\n\\n# Input\\/Output\\n\\n\\n - `[input]` string `s`\\n\\n  string containing only lowercase English letters\\n\\n - `[output]` a boolean value\\n\\n  `true` if the string is prime, `false` otherwise\",\"targets\":\"def prime_string(s):\\n    return (s + s).find(s, 1) == len(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n In ChessLand there is a small but proud chess bishop with a recurring dream. \\n \\n In the dream the bishop finds itself on an `n × m` chessboard with mirrors along each edge, and it is not a bishop but a ray of light. This ray of light moves only along diagonals (the bishop can't imagine any other types of moves even in its dreams), it never stops, and once it reaches an edge or a corner of the chessboard it reflects from it and moves on.\\n\\n Given the initial position and the direction of the ray, find its position after `k` steps where a step means either moving from one cell to the neighboring one or reflecting from a corner of the board.\\n\\n# Example\\n\\n For `boardSize = [3, 7], initPosition = [1, 2], initDirection = [-1, 1] and k = 13,` the output should be `[0, 1]`.\\n\\n Here is the bishop's path:\\n```\\n[1, 2] -> [0, 3] -(reflection from the top edge)\\n         -> [0, 4] -> [1, 5] -> [2, 6] -(reflection from the bottom right corner)\\n         -> [2, 6] ->[1, 5] -> [0, 4] -(reflection from the top edge)\\n         -> [0, 3] ->[1, 2] -> [2, 1] -(reflection from the bottom edge)\\n         -> [2, 0] -(reflection from the left edge)\\n         -> [1, 0] -> [0, 1]```\\n\\n ![](https:\\/\\/codefightsuserpics.s3.amazonaws.com\\/tasks\\/chessBishopDream\\/img\\/example.png?_tm=1472324389202)\\n\\n# Input\\/Output\\n\\n\\n - `[input]` integer array `boardSize`\\n\\n    An array of two integers, the number of `rows` and `columns`, respectively. Rows are numbered by integers from `0 to boardSize[0] - 1`, columns are numbered by integers from `0 to boardSize[1] - 1` (both inclusive).\\n\\n    Constraints: `1 ≤ boardSize[i] ≤ 20.`\\n\\n\\n - `[input]` integer array `initPosition`\\n\\n    An array of two integers, indices of the `row` and the `column` where the bishop initially stands, respectively.\\n\\n    Constraints:  `0 ≤ initPosition[i] < boardSize[i]`.\\n\\n\\n - `[input]` integer array `initDirection`\\n\\n    An array of two integers representing the initial direction of the bishop. \\n    \\n    If it stands in `(a, b)`, the next cell he'll move to is `(a + initDirection[0], b +...\",\"targets\":\"def chess_bishop_dream(board_size, init_position, init_direction, k):\\n    m,n=board_size\\n    x,y=init_position\\n    dx,dy=init_direction\\n    r=[[x,y]]\\n    while(True):\\n        x,y=x+dx,y+dy\\n        if not (0<=x<m):\\n            x+=-dx\\n            dx=-dx\\n        if not (0<=y<n):\\n            y+=-dy\\n            dy=-dy\\n        r.append([x,y])\\n        if len(r)>2 and r[:2]==r[-2:]:\\n            break\\n    r=r[:-2]\\n    return r[k%len(r)]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA carpet shop sells carpets in different varieties. Each carpet can come in a different roll width and can have a different price per square meter. \\n\\nWrite a function `cost_of_carpet` which calculates the cost (rounded to 2 decimal places) of carpeting a room, following these constraints:\\n\\n* The carpeting has to be done in one unique piece. If not possible, retrun `\\\"error\\\"`.\\n* The shop sells any length of a roll of carpets, but always with a full width.\\n* The cost has to be minimal.\\n* The length of the room passed as argument can sometimes be shorter than its width (because we define these relatively to the position of the door in the room).\\n* A length or width equal to zero is considered invalid, return `\\\"error\\\"` if it occurs.\\n\\n\\nINPUTS:\\n\\n`room_width`, `room_length`, `roll_width`, `roll_cost` as floats.\\n\\nOUTPUT:\\n\\n`\\\"error\\\"` or the minimal cost of the room carpeting, rounded to two decimal places.\",\"targets\":\"def cost_of_carpet(room_length, room_width, roll_width, roll_cost):\\n    if roll_width < min(room_length, room_width):\\n        return 'error'\\n    elif  room_length == 0 or room_width ==0:\\n         return \\\"error\\\"\\n    cost_1 = roll_width*room_length*roll_cost if roll_width >= room_width else float('inf')\\n    cost_2 = roll_width*room_width*roll_cost if roll_width >= room_length else float('inf')\\n    return round(min(cost_1, cost_2), 2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an integer sequence $1, 2, \\\\dots, n$. You have to divide it into two sets $A$ and $B$ in such a way that each element belongs to exactly one set and $|sum(A) - sum(B)|$ is minimum possible.\\n\\nThe value $|x|$ is the absolute value of $x$ and $sum(S)$ is the sum of elements of the set $S$.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^9$).\\n\\n\\n-----Output-----\\n\\nPrint one integer — the minimum possible value of $|sum(A) - sum(B)|$ if you divide the initial sequence $1, 2, \\\\dots, n$ into two sets $A$ and $B$.\\n\\n\\n-----Examples-----\\nInput\\n3\\n\\nOutput\\n0\\n\\nInput\\n5\\n\\nOutput\\n1\\n\\nInput\\n6\\n\\nOutput\\n1\\n\\n\\n\\n-----Note-----\\n\\nSome (not all) possible answers to examples:\\n\\nIn the first example you can divide the initial sequence into sets $A = \\\\{1, 2\\\\}$ and $B = \\\\{3\\\\}$ so the answer is $0$.\\n\\nIn the second example you can divide the initial sequence into sets $A = \\\\{1, 3, 4\\\\}$ and $B = \\\\{2, 5\\\\}$ so the answer is $1$.\\n\\nIn the third example you can divide the initial sequence into sets $A = \\\\{1, 4, 5\\\\}$ and $B = \\\\{2, 3, 6\\\\}$ so the answer is $1$.\",\"targets\":\"n=int(input())\\n\\nif n%4==1 or n%4==2:\\n\\tprint(1)\\nelse:\\n\\tprint(0)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/270\\/A:\\nEmuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.\\n\\nHe wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle a.\\n\\nWill the robot be able to build the fence Emuskald wants? In other words, is there a regular polygon which angles are equal to a?\\n\\n\\n-----Input-----\\n\\nThe first line of input contains an integer t (0 < t < 180) — the number of tests. Each of the following t lines contains a single integer a (0 < a < 180) — the angle the robot can make corners at measured in degrees.\\n\\n\\n-----Output-----\\n\\nFor each test, output on a single line \\\"YES\\\" (without quotes), if the robot can build a fence Emuskald wants, and \\\"NO\\\" (without quotes), if it is impossible.\\n\\n\\n-----Examples-----\\nInput\\n3\\n30\\n60\\n90\\n\\nOutput\\nNO\\nYES\\nYES\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, it is impossible to build the fence, since there is no regular polygon with angle $30^{\\\\circ}$.\\n\\nIn the second test case, the fence is a regular triangle, and in the last test case — a square.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for i in range(int(input())):print('NO' if 360%(180-int(input())) else 'YES')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/392\\/B:\\nThe Tower of Hanoi is a well-known mathematical puzzle. It consists of three rods, and a number of disks of different sizes which can slide onto any rod. The puzzle starts with the disks in a neat stack in ascending order of size on one rod, the smallest at the top, thus making a conical shape.\\n\\nThe objective of the puzzle is to move the entire stack to another rod, obeying the following simple rules:   Only one disk can be moved at a time.  Each move consists of taking the upper disk from one of the stacks and placing it on top of another stack i.e. a disk can only be moved if it is the uppermost disk on a stack.  No disk may be placed on top of a smaller disk. \\n\\nWith three disks, the puzzle can be solved in seven moves. The minimum number of moves required to solve a Tower of Hanoi puzzle is 2^{n} - 1, where n is the number of disks. (c) Wikipedia.\\n\\nSmallY's puzzle is very similar to the famous Tower of Hanoi. In the Tower of Hanoi puzzle you need to solve a puzzle in minimum number of moves, in SmallY's puzzle each move costs some money and you need to solve the same puzzle but for minimal cost. At the beginning of SmallY's puzzle all n disks are on the first rod. Moving a disk from rod i to rod j (1 ≤ i, j ≤ 3) costs t_{ij} units of money. The goal of the puzzle is to move all the disks to the third rod.\\n\\nIn the problem you are given matrix t and an integer n. You need to count the minimal cost of solving SmallY's puzzle, consisting of n disks.\\n\\n\\n-----Input-----\\n\\nEach of the first three lines contains three integers — matrix t. The j-th integer in the i-th line is t_{ij} (1 ≤ t_{ij} ≤ 10000; i ≠ j). The following line contains a single integer n (1 ≤ n ≤ 40) — the number of disks.\\n\\nIt is guaranteed that for all i (1 ≤ i ≤ 3), t_{ii} = 0.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimum cost of solving SmallY's puzzle.\\n\\n\\n-----Examples-----\\nInput\\n0 1 1\\n1 0 1\\n1 1 0\\n3\\n\\nOutput\\n7\\n\\nInput\\n0 2 2\\n1 0 100\\n1 2 0\\n3\\n\\nOutput\\n19\\n\\nInput\\n0 2 1\\n1 0 100\\n1 2 0\\n5\\n\\nOutput\\n87\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#\\t!\\/bin\\/env python3\\n#\\tcoding: UTF-8\\n\\n\\n#\\t✪ H4WK3yE乡\\n#\\tMohd. Farhan Tahir\\n#\\tIndian Institute Of Information Technology and Management,Gwalior\\n\\n#\\tQuestion Link\\n#\\thttps:\\/\\/codeforces.com\\/problemset\\/problem\\/392\\/B\\n#\\n\\n# \\/\\/\\/==========Libraries, Constants and Functions=============\\/\\/\\/\\n\\n\\nimport sys\\n\\ninf = float(\\\"inf\\\")\\nmod = 1000000007\\n\\n\\ndef get_array(): return list(map(int, sys.stdin.readline().split()))\\n\\n\\ndef get_ints(): return list(map(int, sys.stdin.readline().split()))\\n\\n\\ndef input(): return sys.stdin.readline()\\n\\n# \\/\\/\\/==========MAIN=============\\/\\/\\/\\n\\n\\ndef main():\\n    dp = [[[0 for _ in range(3)] for _ in range(3)] for _ in range(43)]\\n    matrix = [[0 for _ in range(3)] for _ in range(3)]\\n    for i in range(3):\\n        matrix[i] = get_array()\\n    n = int(input())\\n    for i in range(1, n+1):\\n        for frm in range(3):\\n            for to in range(3):\\n                other = 3-frm-to\\n                if frm == to:\\n                    continue\\n                dp[i][frm][to] = dp[i-1][frm][other]+matrix[frm][to]+dp[i-1][other][to]\\n                c = dp[i-1][frm][to]+matrix[frm][other] + \\\\\\n                    dp[i-1][to][frm]+matrix[other][to]+dp[i-1][frm][to]\\n                dp[i][frm][to] = min(c, dp[i][frm][to])\\n    print(dp[n][0][2])\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1027\\/D:\\nMedicine faculty of Berland State University has just finished their admission campaign. As usual, about $80\\\\%$ of applicants are girls and majority of them are going to live in the university dormitory for the next $4$ (hopefully) years.\\n\\nThe dormitory consists of $n$ rooms and a single mouse! Girls decided to set mouse traps in some rooms to get rid of the horrible monster. Setting a trap in room number $i$ costs $c_i$ burles. Rooms are numbered from $1$ to $n$.\\n\\nMouse doesn't sit in place all the time, it constantly runs. If it is in room $i$ in second $t$ then it will run to room $a_i$ in second $t + 1$ without visiting any other rooms inbetween ($i = a_i$ means that mouse won't leave room $i$). It's second $0$ in the start. If the mouse is in some room with a mouse trap in it, then the mouse get caught into this trap.\\n\\nThat would have been so easy if the girls actually knew where the mouse at. Unfortunately, that's not the case, mouse can be in any room from $1$ to $n$ at second $0$.\\n\\nWhat it the minimal total amount of burles girls can spend to set the traps in order to guarantee that the mouse will eventually be caught no matter the room it started from?\\n\\n\\n-----Input-----\\n\\nThe first line contains as single integers $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of rooms in the dormitory.\\n\\nThe second line contains $n$ integers $c_1, c_2, \\\\dots, c_n$ ($1 \\\\le c_i \\\\le 10^4$) — $c_i$ is the cost of setting the trap in room number $i$.\\n\\nThe third line contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le n$) — $a_i$ is the room the mouse will run to the next second after being in room $i$.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the minimal total amount of burles girls can spend to set the traps in order to guarantee that the mouse will eventually be caught no matter the room it started from.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 2 3 2 10\\n1 3 4 3 3\\n\\nOutput\\n3\\n\\nInput\\n4\\n1 10 2 10\\n2 4 2 2\\n\\nOutput\\n10\\n\\nInput\\n7\\n1 1 1 1 1 1 1\\n2 2 2 3 6 7 6\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first example it is enough to set...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\nc  = [0] + [int(j) for j in input().split()]\\na  = [0] + [int(j) for j in input().split()]\\n \\nvis = [0] * (n+1)\\nans = 0\\nfor i in range(1,n+1):\\n    x = i\\n    while vis[x] == 0:\\n        vis[x] = i\\n        x = a[x]\\n    if vis[x] != i:\\n        continue\\n    v = x\\n    mn = c[x]\\n    while a[x] != v:\\n        x = a[x]\\n        mn = min(mn,c[x])\\n    ans+=mn\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/600\\/A:\\nYou are given string s. Let's call word any largest sequence of consecutive symbols without symbols ',' (comma) and ';' (semicolon). For example, there are four words in string \\\"aba,123;1a;0\\\": \\\"aba\\\", \\\"123\\\", \\\"1a\\\", \\\"0\\\". A word can be empty: for example, the string s=\\\";;\\\" contains three empty words separated by ';'.\\n\\nYou should find all words in the given string that are nonnegative INTEGER numbers without leading zeroes and build by them new string a. String a should contain all words that are numbers separating them by ',' (the order of numbers should remain the same as in the string s). By all other words you should build string b in the same way (the order of numbers should remain the same as in the string s).\\n\\nHere strings \\\"101\\\", \\\"0\\\" are INTEGER numbers, but \\\"01\\\" and \\\"1.0\\\" are not.\\n\\nFor example, for the string aba,123;1a;0 the string a would be equal to \\\"123,0\\\" and string b would be equal to \\\"aba,1a\\\".\\n\\n\\n-----Input-----\\n\\nThe only line of input contains the string s (1 ≤ |s| ≤ 10^5). The string contains only symbols '.' (ASCII 46), ',' (ASCII 44), ';' (ASCII 59), digits, lowercase and uppercase latin letters.\\n\\n\\n-----Output-----\\n\\nPrint the string a to the first line and string b to the second line. Each string should be surrounded by quotes (ASCII 34).\\n\\nIf there are no words that are numbers print dash (ASCII 45) on the first line. If all words are numbers print dash on the second line.\\n\\n\\n-----Examples-----\\nInput\\naba,123;1a;0\\n\\nOutput\\n\\\"123,0\\\"\\n\\\"aba,1a\\\"\\n\\nInput\\n1;;01,a0,\\n\\nOutput\\n\\\"1\\\"\\n\\\",01,a0,\\\"\\n\\nInput\\n1\\n\\nOutput\\n\\\"1\\\"\\n-\\n\\nInput\\na\\n\\nOutput\\n-\\n\\\"a\\\"\\n\\n\\n\\n-----Note-----\\n\\nIn the second example the string s contains five words: \\\"1\\\", \\\"\\\", \\\"01\\\", \\\"a0\\\", \\\"\\\".\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import ceil, modf\\ns = input().replace(\\\",\\\", \\\";\\\")\\ns = s.split(\\\";\\\")\\na = []\\nb = []\\nfor i in s:\\n    try:\\n        d = str(int(i))\\n        if len(i)>1 and i[0] == \\\"0\\\" or i[0] == \\\"-\\\":\\n            b.append(i)\\n        else:\\n            a.append(d)\\n    except ValueError:\\n        b.append(i)\\nif a:\\n    print('\\\"'+\\\",\\\".join(a)+'\\\"')\\nelse:\\n    print(\\\"-\\\")\\nif b:\\n    print('\\\"'+\\\",\\\".join(b)+'\\\"')\\nelse:\\n    print(\\\"-\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAsh like soup very much! So, on the Raksha Bandhan day, his sister gave him a soup maker as a gift. Soup maker in the ith hour will make volume  Vi liters of soup and pours it in a bowl.\\nEach hour, the Volume of soup in every bowl is reduced due to evaporation. More precisely, when the temperature on a given hour is Ti, the Volume of soup in every bowl will reduce its volume by Ti. If this would reduce the volume of soup to or below zero, Bowl gets empty. All bowls are independent of each other.\\nNote that the Volume of soup in every bowl made in an hour i already lose part of its volume at the same hour. In an extreme case, this may mean that there is no soup left in the bowl at the end of a particular hour.\\nYou are given the initial volumes of soup in bowls and the temperature on each hour. Determine the total volume of soup evaporated in each hour.\\nInput\\nThe first line contains a single integer N (1 ≤ N ≤ 10^5) — the number of hours.\\nThe second line contains N integers V 1, V 2, …, V N (0 ≤ V i ≤ 10^9), where V i is the initial volume of soup made in an hour i.\\nThe third line contains N integers T 1, T 2, …, T N (0 ≤ T i ≤ 10^9), where T i is the temperature in an hour i.\\nOutput\\nOutput a single line with N integers, where the i-th integer represents the total volume of soup melted in an hour i.\\nExamples\\nInput\\n3\\n10 10 5\\n5 7 2\\nOutput\\n5 12 4\\nInput\\n5\\n30 25 20 15 10\\n9 10 12 4 13\\nOutput\\n9 20 35 11 25\\nNote\\nIn the first sample, In the first hour, 10 liters of soup is prepared, which evaporates to the size of 5 at the same hour. In the second hour, another 10 liters of soup is made. Since it is a bit warmer than the hour before, the first bowl gets empty while the second bowl shrinks to 3. At the end of the second hour, only one bowl with 3 liters soup is left. In the third hour, another bowl with less volume of soup is made, but as the temperature dropped too, both bowls survive till the end of the hour.\",\"targets\":\"# cook your dish here\\nx=int(input())\\n\\nsop=[int(i) for i in input().split()]\\ntem=[int(j) for j in input().split()]\\nfor i in range(x):\\n    sm=0\\n    for j in range(i+1):\\n        if (sop[j] >= tem[i]):\\n            sm+=tem[i]\\n            sop[j]-=tem[i]\\n        else:\\n            sm+=sop[j]\\n            sop[j]=0\\n    print(sm,end=\\\" \\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1430\\/B:\\nYou have $n$ barrels lined up in a row, numbered from left to right from one. Initially, the $i$-th barrel contains $a_i$ liters of water.\\n\\nYou can pour water from one barrel to another. In one act of pouring, you can choose two different barrels $x$ and $y$ (the $x$-th barrel shouldn't be empty) and pour any possible amount of water from barrel $x$ to barrel $y$ (possibly, all water). You may assume that barrels have infinite capacity, so you can pour any amount of water in each of them. \\n\\nCalculate the maximum possible difference between the maximum and the minimum amount of water in the barrels, if you can pour water at most $k$ times.\\n\\nSome examples:   if you have four barrels, each containing $5$ liters of water, and $k = 1$, you may pour $5$ liters from the second barrel into the fourth, so the amounts of water in the barrels are $[5, 0, 5, 10]$, and the difference between the maximum and the minimum is $10$;  if all barrels are empty, you can't make any operation, so the difference between the maximum and the minimum amount is still $0$. \\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases.\\n\\nThe first line of each test case contains two integers $n$ and $k$ ($1 \\\\le k < n \\\\le 2 \\\\cdot 10^5$) — the number of barrels and the number of pourings you can make.\\n\\nThe second line contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($0 \\\\le a_i \\\\le 10^{9}$), where $a_i$ is the initial amount of water the $i$-th barrel has.\\n\\nIt's guaranteed that the total sum of $n$ over test cases doesn't exceed $2 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print the maximum possible difference between the maximum and the minimum amount of water in the barrels, if you can pour water at most $k$ times.\\n\\n\\n-----Example-----\\nInput\\n2\\n4 1\\n5 5 5 5\\n3 2\\n0 0 0\\n\\nOutput\\n10\\n0\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t=int(input())\\nfor i in range(t):\\n    n,k=[int(i) for i in input().split()]\\n    a=[int(i) for i in input().split()]\\n    a.sort(reverse=True)\\n    print(sum(a[:k+1]))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a connected undirected weighted graph consisting of $n$ vertices and $m$ edges.\\n\\nYou need to print the $k$-th smallest shortest path in this graph (paths from the vertex to itself are not counted, paths from $i$ to $j$ and from $j$ to $i$ are counted as one).\\n\\nMore formally, if $d$ is the matrix of shortest paths, where $d_{i, j}$ is the length of the shortest path between vertices $i$ and $j$ ($1 \\\\le i < j \\\\le n$), then you need to print the $k$-th element in the sorted array consisting of all $d_{i, j}$, where $1 \\\\le i < j \\\\le n$.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers $n, m$ and $k$ ($2 \\\\le n \\\\le 2 \\\\cdot 10^5$, $n - 1 \\\\le m \\\\le \\\\min\\\\Big(\\\\frac{n(n-1)}{2}, 2 \\\\cdot 10^5\\\\Big)$, $1 \\\\le k \\\\le \\\\min\\\\Big(\\\\frac{n(n-1)}{2}, 400\\\\Big)$ — the number of vertices in the graph, the number of edges in the graph and the value of $k$, correspondingly.\\n\\nThen $m$ lines follow, each containing three integers $x$, $y$ and $w$ ($1 \\\\le x, y \\\\le n$, $1 \\\\le w \\\\le 10^9$, $x \\\\ne y$) denoting an edge between vertices $x$ and $y$ of weight $w$.\\n\\nIt is guaranteed that the given graph is connected (there is a path between any pair of vertices), there are no self-loops (edges connecting the vertex with itself) and multiple edges (for each pair of vertices $x$ and $y$, there is at most one edge between this pair of vertices in the graph).\\n\\n\\n-----Output-----\\n\\nPrint one integer — the length of the $k$-th smallest shortest path in the given graph (paths from the vertex to itself are not counted, paths from $i$ to $j$ and from $j$ to $i$ are counted as one).\\n\\n\\n-----Examples-----\\nInput\\n6 10 5\\n2 5 1\\n5 3 9\\n6 2 2\\n1 3 1\\n5 1 8\\n6 5 10\\n1 6 5\\n6 4 6\\n3 6 2\\n3 4 5\\n\\nOutput\\n3\\n\\nInput\\n7 15 18\\n2 6 3\\n5 7 4\\n6 5 4\\n3 6 9\\n6 7 7\\n1 6 4\\n7 1 6\\n7 2 1\\n4 3 2\\n3 2 8\\n5 3 6\\n2 5 5\\n3 7 9\\n4 1 8\\n2 1 1\\n\\nOutput\\n9\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\nN, M, K = list(map(int, input().split()))\\nX = []\\nfor _ in range(M):\\n    x, y, w = list(map(int, input().split()))\\n    X.append([min(x,y), max(x,y), w])\\nX = (sorted(X, key = lambda x: x[2])+[[0, 0, 10**20] for _ in range(K)])[:K]\\nD = {}\\nfor x, y, w in X:\\n    if x: D[x*10**6+y] = w\\n\\nflg = 1\\nwhile flg:\\n    flg = 0\\n    for i in range(len(X)):\\n        x1, y1, w1 = X[i]\\n        for j in range(i+1, len(X)):\\n            x2, y2, w2 = X[j]\\n            if x1==x2: a, b = min(y1,y2), max(y1,y2)\\n            elif y1==y2: a, b = min(x1,x2), max(x1,x2)\\n            elif x1==y2: a, b = x2, y1\\n            elif x2==y1: a, b = x1, y2\\n            else: a, b = 0, 0\\n            if a:\\n                if (a*10**6+b in D and w1+w2 < D[a*10**6+b]) or (a*10**6+b not in D and w1+w2 < X[-1][2]):\\n                    if a*10**6+b in D:\\n                        for k in range(len(X)):\\n                            if X[k][0] == a and X[k][1] == b:\\n                                X[k][2] = w1+w2\\n                    else:\\n                        x, y, w = X.pop()\\n                        if x: D.pop(x*10**6+y)\\n                        X.append([a,b,w1+w2])\\n                    D[a*10**6+b] = w1+w2\\n                    X = sorted(X, key = lambda x: x[2])\\n                    flg = 1\\nprint(X[-1][2])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn this task you have to code process planner.\\n\\nYou will be given initial thing, target thing and a set of processes to turn one thing into another (in the form of _[process\\\\_name, start\\\\_thing, end\\\\_thing]_). You must return  names of shortest sequence of processes to turn initial thing into target thing, or empty sequence if it's impossible.\\n\\nIf start already equals end, return [], since no path is required.\\n\\nExample: \\n\\n```python\\ntest_processes = [\\n        ['gather', 'field', 'wheat'],\\n        ['bake', 'flour', 'bread'],\\n        ['mill', 'wheat', 'flour']\\n];\\n\\nprocesses('field', 'bread', test_processes) # should return ['gather', 'mill', 'bake']\\nprocesses('field', 'ferrari', test_processes) # should return []\\nprocesses('field', 'field', test_processes) # should return [], since no processes are needed\\n```\\n\\nGood luck!\",\"targets\":\"from collections import defaultdict, namedtuple\\n\\nEdge = namedtuple('Edge', ['process_name', 'to'])\\nState = namedtuple('State', ['stack', 'visited', 'min_stack'])\\n\\ndef dfs(graph, cur_node, end_node, state):\\n    if cur_node in state.visited:\\n        return\\n    if len(state.min_stack) and len(state.stack) >= len(state.min_stack):\\n        return\\n    if cur_node == end_node:\\n        state.min_stack.clear()\\n        state.min_stack.extend(state.stack)\\n        return\\n\\n    state.visited.add(cur_node)\\n    for process, node in graph[cur_node]:\\n        state.stack.append(process)\\n        dfs(graph, node, end_node, state)\\n        state.stack.pop()\\n    state.visited.remove(cur_node)\\n\\ndef processes(start, end, processes):\\n  if start == end:\\n      return []\\n  graph = defaultdict(list)\\n  \\n  for process_name, start_node, end_node in processes:\\n      graph[start_node].append(Edge(process_name, end_node))\\n  \\n  state = State([], set(), [])\\n  dfs(graph, start, end, state)\\n  \\n  return state.min_stack\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have the numbers with different colours with the sequence: ['red', 'yellow', 'blue'].\\n\\nThat sequence colours the numbers in the following way:\\n\\n 1   2   3    4    5   6  7   8   9   10   11  12   13 .....\\n\\nWe have got the following recursive function:\\n\\n  ```\\nf(1) = 1\\nf(n) = f(n - 1) + n\\n```\\n\\nSome terms of this sequence with their corresponding colour are:\\n\\n```\\nterm   value   colour\\n1        1     \\\"red\\\"\\n2        3     \\\"blue\\\"\\n3        6     \\\"blue\\\"\\n4       10     \\\"red\\\"\\n5       15     \\\"blue\\\"\\n6       21     \\\"blue\\\"\\n7       28     \\\"red\\\"\\n```\\n\\nThe three terms of the same colour \\\"blue\\\", higher than 3, are: `[6, 15, 21]`\\n\\nWe need a function `same_col_seq(), that may receive three arguments:\\n\\n- `val`, an integer number\\n- `k`, an integer number\\n- `colour`, the name of one of the three colours(red, yellow or blue), as a string.\\n\\nThe function will output a sorted array with the smallest `k` terms, having the same marked colour, but higher than `val`.\\n\\nLet's see some examples:\\n\\n```python\\nsame_col_seq(3, 3, 'blue') == [6, 15, 21]\\nsame_col_seq(100, 4, 'red') == [136, 190, 253, 325]\\n```\\n\\nThe function may output an empty list if it does not find terms of the sequence with the wanted colour in the range [val, 2* k * val]\\n\\n```python\\nsame_col_seq(250, 6, 'yellow') == []\\n```\\n\\nThat means that the function did not find any \\\"yellow\\\" term in the range `[250, 3000]`\\n \\nTests will be with the following features:\\n\\n* Nmber of tests: `100`\\n* `100 < val < 1000000`\\n* `3 < k < 20`\",\"targets\":\"def same_col_seq(val, k, col):\\n    colDct = {'red': 1, 'blue': 0}\\n\\n    def gen():\\n        n = ((1 + 24*val\\/3)**.5 - 1)\\/\\/2\\n        while True:\\n            n += 1\\n            s = n*(n+1)\\/2\\n            if s%3 == colDct[col]: yield s\\n            \\n    g = gen()\\n    return [next(g) for _ in range(k)] if col != 'yellow' else []\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc135\\/tasks\\/abc135_b:\\nWe have a sequence p = {p_1,\\\\ p_2,\\\\ ...,\\\\ p_N} which is a permutation of {1,\\\\ 2,\\\\ ...,\\\\ N}.\\nYou can perform the following operation at most once: choose integers i and j (1 \\\\leq i < j \\\\leq N), and swap p_i and p_j. Note that you can also choose not to perform it.\\nPrint YES if you can sort p in ascending order in this way, and NO otherwise.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 2 \\\\leq N \\\\leq 50\\n - p is a permutation of {1,\\\\ 2,\\\\ ...,\\\\ N}.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\np_1 p_2 ... p_N\\n\\n-----Output-----\\nPrint YES if you can sort p in ascending order in the way stated in the problem statement, and NO otherwise.\\n\\n-----Sample Input-----\\n5\\n5 2 3 4 1\\n\\n-----Sample Output-----\\nYES\\n\\nYou can sort p in ascending order by swapping p_1 and p_5.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N = int(input())\\np = [int(i) for i in input().split()]\\nr = sorted(p)\\nfor i in range(N):\\n    for j in range(i+1,N):\\n        q = []\\n        for k in range(N):\\n            if(k == i):\\n                q.append(p[j])\\n            elif(k == j):\\n                q.append(p[i])\\n            else:\\n                q.append(p[k])\\n        if(p == r or q == r):\\n            print(\\\"YES\\\")\\n            return\\nprint(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a binary string s (a string consisting only of '0's and '1's), we can split s into 3 non-empty strings s1, s2, s3 (s1+ s2+ s3 = s).\\nReturn the number of ways s can be split such that the number of characters '1' is the same in s1, s2, and s3.\\nSince the answer may be too large, return it modulo 10^9 + 7.\\n \\nExample 1:\\nInput: s = \\\"10101\\\"\\nOutput: 4\\nExplanation: There are four ways to split s in 3 parts where each part contain the same number of letters '1'.\\n\\\"1|010|1\\\"\\n\\\"1|01|01\\\"\\n\\\"10|10|1\\\"\\n\\\"10|1|01\\\"\\n\\nExample 2:\\nInput: s = \\\"1001\\\"\\nOutput: 0\\n\\nExample 3:\\nInput: s = \\\"0000\\\"\\nOutput: 3\\nExplanation: There are three ways to split s in 3 parts.\\n\\\"0|0|00\\\"\\n\\\"0|00|0\\\"\\n\\\"00|0|0\\\"\\n\\nExample 4:\\nInput: s = \\\"100100010100110\\\"\\nOutput: 12\\n\\n \\nConstraints:\\n\\n3 <= s.length <= 10^5\\ns[i] is '0' or '1'.\",\"targets\":\"class Solution:\\n    def numWays(self, s: str) -> int:\\n        c = s.count('1')\\n        if c%3: return 0\\n        M = 10**9 +7\\n        if not c:\\n            return (len(s)-1)*(len(s)-2)\\/\\/2%M\\n    \\n        cur = 0\\n        first = 0\\n        second = 0\\n        for l in s:\\n            if cur == c\\/\\/3:\\n                first += 1\\n            elif cur == c\\/\\/3*2:\\n                second += 1\\n            cur += l == '1'\\n            \\n        return first*second%M\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/57dd8c78eb0537722f0006bd:\\nA group of friends (n >= 2) have reunited for a get-together after \\na very long time. \\n\\nThey agree that they will make presentations on holiday destinations \\nor expeditions they have been to only if it satisfies **one simple rule**: \\n> the holiday\\/journey being presented must have been visited _only_ by the presenter and no one else from the audience.\\n\\nWrite a program to output the presentation agenda, including the\\npresenter and their respective presentation titles. \\n\\n---\\n### EXAMPLES\\n\\n```python\\npresentation_agenda([\\n    {'person': 'Abe', 'dest': ['London', 'Dubai']},\\n    {'person': 'Bond', 'dest': ['Melbourne', 'Dubai']}\\n]) == [{'person': 'Abe', 'dest': ['London']},\\n       {'person': 'Bond', 'dest': ['Melbourne']}]\\n\\npresentation_agenda([\\n    {'person': 'Abe', 'dest': ['Dubai']},\\n    {'person': 'Brad', 'dest': ['Dubai']}\\n]) == []\\n\\npresentation_agenda([\\n    {'person': 'Abe', 'dest': ['London', 'Dubai']},\\n    {'person': 'Bond', 'dest': ['Melbourne', 'Dubai']},\\n    {'person': 'Carrie', 'dest': ['Melbourne']},\\n    {'person': 'Damu', 'dest': ['Melbourne', 'Dubai', 'Paris']}\\n]) == [{'person': 'Abe',  'dest': ['London']},\\n       {'person': 'Damu', 'dest': ['Paris']}]\\n\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def presentation_agenda(friend_list):\\n    out = []\\n    for friend in friend_list:\\n        p_list = friend['dest'] \\n        for f in friend_list:\\n            p_list = [loc for loc in p_list if f == friend or loc not in f['dest']]\\n        if len(p_list):\\n            out.append({'person': friend['person'], 'dest': p_list})\\n    return out\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn Berland a bus travels along the main street of the capital. The street begins from the main square and looks like a very long segment. There are n bus stops located along the street, the i-th of them is located at the distance a_{i} from the central square, all distances are distinct, the stops are numbered in the order of increasing distance from the square, that is, a_{i} < a_{i} + 1 for all i from 1 to n - 1. The bus starts its journey from the first stop, it passes stops 2, 3 and so on. It reaches the stop number n, turns around and goes in the opposite direction to stop 1, passing all the intermediate stops in the reverse order. After that, it again starts to move towards stop n. During the day, the bus runs non-stop on this route.\\n\\nThe bus is equipped with the Berland local positioning system. When the bus passes a stop, the system notes down its number.\\n\\nOne of the key features of the system is that it can respond to the queries about the distance covered by the bus for the parts of its path between some pair of stops. A special module of the system takes the input with the information about a set of stops on a segment of the path, a stop number occurs in the set as many times as the bus drove past it. This module returns the length of the traveled segment of the path (or -1 if it is impossible to determine the length uniquely). The operation of the module is complicated by the fact that stop numbers occur in the request not in the order they were visited but in the non-decreasing order.\\n\\nFor example, if the number of stops is 6, and the part of the bus path starts at the bus stop number 5, ends at the stop number 3 and passes the stops as follows: $5 \\\\rightarrow 6 \\\\rightarrow 5 \\\\rightarrow 4 \\\\rightarrow 3$, then the request about this segment of the path will have form: 3, 4, 5, 5, 6. If the bus on the segment of the path from stop 5 to stop 3 has time to drive past the 1-th stop (i.e., if we consider a segment that ends with the second visit to stop 3 on the way from 5), then the request will have...\",\"targets\":\"n=int(input())\\nc=[0]*n\\na=[int(x) for x in input().split()]\\nm=int(input())\\nb=[int(x)-1 for x in input().split()]\\nfor e in b:\\n    c[e]+=1\\nc[0]*=2\\nc[-1]*=2\\nd=0\\ndf=0\\nr=max([e\\/\\/2 for e in c])\\nc=[e-r*2 for e in c]\\nif not any(c):\\n    de=a[1]-a[0]\\n    for i in range(1,n-1):\\n        if a[i+1]-a[i]!=de:\\n            print(-1)\\n            break\\n    else:\\n        print(r*de*2*(n-1)-de)\\nelse:\\n    for i in range(n-1):\\n        de=a[i+1]-a[i]\\n        d+=min(c[i],c[i+1])*de\\n        df+=de    \\n    print(d+r*2*df)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAs the name of the task implies, you are asked to do some work with segments and trees.\\n\\nRecall that a tree is a connected undirected graph such that there is exactly one simple path between every pair of its vertices.\\n\\nYou are given $n$ segments $[l_1, r_1], [l_2, r_2], \\\\dots, [l_n, r_n]$, $l_i < r_i$ for every $i$. It is guaranteed that all segments' endpoints are integers, and all endpoints are unique — there is no pair of segments such that they start in the same point, end in the same point or one starts in the same point the other one ends.\\n\\nLet's generate a graph with $n$ vertices from these segments. Vertices $v$ and $u$ are connected by an edge if and only if segments $[l_v, r_v]$ and $[l_u, r_u]$ intersect and neither of it lies fully inside the other one.\\n\\nFor example, pairs $([1, 3], [2, 4])$ and $([5, 10], [3, 7])$ will induce the edges but pairs $([1, 2], [3, 4])$ and $([5, 7], [3, 10])$ will not.\\n\\nDetermine if the resulting graph is a tree or not.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\le n \\\\le 5 \\\\cdot 10^5$) — the number of segments.\\n\\nThe $i$-th of the next $n$ lines contain the description of the $i$-th segment — two integers $l_i$ and $r_i$ ($1 \\\\le l_i < r_i \\\\le 2n$).\\n\\nIt is guaranteed that all segments borders are pairwise distinct. \\n\\n\\n-----Output-----\\n\\nPrint \\\"YES\\\" if the resulting graph is a tree and \\\"NO\\\" otherwise.\\n\\n\\n-----Examples-----\\nInput\\n6\\n9 12\\n2 11\\n1 3\\n6 10\\n5 7\\n4 8\\n\\nOutput\\nYES\\n\\nInput\\n5\\n1 3\\n2 4\\n5 9\\n6 8\\n7 10\\n\\nOutput\\nNO\\n\\nInput\\n5\\n5 8\\n3 6\\n2 9\\n7 10\\n1 4\\n\\nOutput\\nNO\\n\\n\\n\\n-----Note-----\\n\\nThe graph corresponding to the first example:\\n\\n[Image]\\n\\nThe graph corresponding to the second example:\\n\\n[Image]\\n\\nThe graph corresponding to the third example:\\n\\n[Image]\",\"targets\":\"import sys\\nreader = (s.rstrip() for s in sys.stdin)\\ninput = reader.__next__\\n\\nclass BIT_RSQ():\\n    def __init__(self, n):\\n        self.n = n\\n        self.data = [0]*(n+2)\\n\\n    def add(self, i, v):\\n        while i <= self.n:\\n            self.data[i] += v\\n            i += i & -i\\n\\n    def sum(self, i):\\n        ret = 0\\n        while(i > 0):\\n            ret += self.data[i]\\n            i -= i & -i\\n        return ret\\n\\n    def query(self, l, r):\\n        return self.sum(r) - self.sum(l-1)\\n\\n    def lowerBound(self, w):\\n        if w <= 0: return 0\\n        x, k = 0, 2**self.n.bit_length()\\n        while k:\\n            if x+k <= self.n and self.data[x+k] < w:\\n                w -= self.data[x+k]\\n                x += k\\n            k >>= 1\\n        return x + 1\\n\\nn = int(input())\\nedges = [0]*(2*n)\\nc = [0]*(2*n)\\nBIT = BIT_RSQ(2*n)\\n\\nuf = [-1]*n\\ndef root(x):\\n    if uf[x] < 0:\\n        return x\\n    uf[x] = root(uf[x])\\n    return uf[x]\\ndef unite(x,y):\\n    rx, ry = root(x), root(y)\\n    if rx == ry:\\n        return False\\n    if uf[rx] > uf[ry]:\\n        rx, ry = ry, rx\\n    uf[rx] += uf[ry]\\n    uf[ry] = rx\\n    return True\\n\\nfor i in range(n):\\n    a,b = list(map(int, input().split()))\\n    a,b = a-1,b-1\\n    c[a] = c[b] = i\\n    edges[a] = b\\n    edges[b] = b\\n\\nfor i in reversed(list(range(2*n))):\\n    j = edges[i]\\n    if j == i:\\n        BIT.add(j+1, 1)\\n    else:\\n        BIT.add(j+1, -1)\\n        cnt = BIT.sum(j+1)\\n        while cnt:\\n            k = BIT.lowerBound(cnt)\\n            if not unite(c[j], c[k-1]):\\n                print(\\\"NO\\\")\\n                return\\n            cnt -= 1\\nif sum(i<0 for i in uf) == 1:\\n    print(\\\"YES\\\")\\nelse:\\n    print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc156\\/tasks\\/abc156_e:\\nThere is a building with n rooms, numbered 1 to n.\\nWe can move from any room to any other room in the building.\\nLet us call the following event a move: a person in some room i goes to another room j~ (i \\\\neq j).\\nInitially, there was one person in each room in the building.\\nAfter that, we know that there were exactly k moves happened up to now.\\nWe are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?\\nFind the count modulo (10^9 + 7).\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 3 \\\\leq n \\\\leq 2 \\\\times 10^5\\n - 2 \\\\leq k \\\\leq 10^9\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nn k\\n\\n-----Output-----\\nPrint the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).\\n\\n-----Sample Input-----\\n3 2\\n\\n-----Sample Output-----\\n10\\n\\nLet c_1, c_2, and c_3 be the number of people in Room 1, 2, and 3 now, respectively. There are 10 possible combination of (c_1, c_2, c_3):\\n - (0, 0, 3)\\n - (0, 1, 2)\\n - (0, 2, 1)\\n - (0, 3, 0)\\n - (1, 0, 2)\\n - (1, 1, 1)\\n - (1, 2, 0)\\n - (2, 0, 1)\\n - (2, 1, 0)\\n - (3, 0, 0)\\nFor example, (c_1, c_2, c_3) will be (0, 1, 2) if the person in Room 1 goes to Room 2 and then one of the persons in Room 2 goes to Room 3.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\n\\nsys.setrecursionlimit(10 ** 6)\\nINF = float(\\\"inf\\\")\\nMOD = 10 ** 9 + 7\\n\\n\\ndef input():\\n    return sys.stdin.readline().strip()\\n\\n\\nclass Combination:\\n    \\\"\\\"\\\"\\n    O(n)の前計算を1回行うことで，O(1)でnCr mod mを求められる\\n    n_max = 10**6のとき前処理は約950ms (PyPyなら約340ms, 10**7で約1800ms)\\n    使用例：\\n    comb = Combination(1000000)\\n    print(comb(5, 3))  # 10\\n    \\\"\\\"\\\"\\n\\n    def __init__(self, n_max, mod=10 ** 9 + 7):\\n        self.mod = mod\\n        self.modinv = self.make_modinv_list(n_max)\\n        self.fac, self.facinv = self.make_factorial_list(n_max)\\n\\n    def __call__(self, n, r):\\n        if n < r:\\n            return 0\\n        return self.fac[n] * self.facinv[r] % self.mod * self.facinv[n - r] % self.mod\\n\\n    def make_factorial_list(self, n):\\n        # 階乗のリストと階乗のmod逆元のリストを返す O(n)\\n        # self.make_modinv_list()が先に実行されている必要がある\\n        fac = [1]\\n        facinv = [1]\\n        for i in range(1, n + 1):\\n            fac.append(fac[i - 1] * i % self.mod)\\n            facinv.append(facinv[i - 1] * self.modinv[i] % self.mod)\\n        return fac, facinv\\n\\n    def make_modinv_list(self, n):\\n        # 0からnまでのmod逆元のリストを返す O(n)\\n        modinv = [0] * (n + 1)\\n        modinv[1] = 1\\n        for i in range(2, n + 1):\\n            modinv[i] = self.mod - self.mod \\/\\/ i * modinv[self.mod % i] % self.mod\\n        return modinv\\n\\n\\ndef main():\\n    N, K = list(map(int, input().split()))\\n    comb = Combination(n_max=10 ** 5 * 4 + 10)\\n\\n    if N <= K:\\n        ans = comb(2 * N - 1, N)\\n    else:\\n        if K == 1:\\n            ans = comb(N, 1) * comb(N - 1, 1)\\n        else:\\n            ans = 0\\n            # mはゼロとなる数\\n            for m in range(K + 1):\\n                ans += comb(N, m) * comb(N - 1, m)\\n                ans %= MOD\\n\\n    print(ans)\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/518\\/B:\\nLittle Tanya decided to present her dad a postcard on his Birthday. She has already created a message — string s of length n, consisting of uppercase and lowercase English letters. Tanya can't write yet, so she found a newspaper and decided to cut out the letters and glue them into the postcard to achieve string s. The newspaper contains string t, consisting of uppercase and lowercase English letters. We know that the length of string t greater or equal to the length of the string s.\\n\\nThe newspaper may possibly have too few of some letters needed to make the text and too many of some other letters. That's why Tanya wants to cut some n letters out of the newspaper and make a message of length exactly n, so that it looked as much as possible like s. If the letter in some position has correct value and correct letter case (in the string s and in the string that Tanya will make), then she shouts joyfully \\\"YAY!\\\", and if the letter in the given position has only the correct value but it is in the wrong case, then the girl says \\\"WHOOPS\\\".\\n\\nTanya wants to make such message that lets her shout \\\"YAY!\\\" as much as possible. If there are multiple ways to do this, then her second priority is to maximize the number of times she says \\\"WHOOPS\\\". Your task is to help Tanya make the message.\\n\\n\\n-----Input-----\\n\\nThe first line contains line s (1 ≤ |s| ≤ 2·10^5), consisting of uppercase and lowercase English letters — the text of Tanya's message.\\n\\nThe second line contains line t (|s| ≤ |t| ≤ 2·10^5), consisting of uppercase and lowercase English letters — the text written in the newspaper.\\n\\nHere |a| means the length of the string a.\\n\\n\\n-----Output-----\\n\\nPrint two integers separated by a space:  the first number is the number of times Tanya shouts \\\"YAY!\\\" while making the message,  the second number is the number of times Tanya says \\\"WHOOPS\\\" while making the message. \\n\\n\\n-----Examples-----\\nInput\\nAbC\\nDCbA\\n\\nOutput\\n3 0\\n\\nInput\\nABC\\nabc\\n\\nOutput\\n0 3\\n\\nInput\\nabacaba\\nAbaCaBA\\n\\nOutput\\n3 4\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"s = input()\\nt = input()\\ns_letters = dict()\\nt_letters = dict()\\n\\nCAPS =   'QWERTYUIOPASDFGHJKLZXCVBNM'\\nSMALLS = 'qwertyuiopasdfghjklzxcvbnm'\\n\\nfor letter in CAPS:\\n    s_letters[letter] = 0\\n    t_letters[letter] = 0\\nfor letter in SMALLS:\\n    s_letters[letter] = 0\\n    t_letters[letter] = 0\\n\\nfor letter in s:\\n    s_letters[letter] += 1\\nfor letter in t:\\n    t_letters[letter] += 1\\n\\nhurray = 0\\nhopa = 0\\nfor i in range(26):\\n    Letter = CAPS[i]\\n    letter = SMALLS[i]\\n    tmp = min(s_letters[Letter], t_letters[Letter])\\n    hurray += tmp\\n    s_letters[Letter] -= tmp\\n    t_letters[Letter] -= tmp\\n    tmp = min(s_letters[letter], t_letters[letter])\\n    hurray += tmp\\n    s_letters[letter] -= tmp\\n    t_letters[letter] -= tmp\\n    hopa += min(s_letters[Letter] + s_letters[letter], t_letters[Letter] + t_letters[letter])\\n\\nprint(hurray, hopa)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1335\\/E2:\\nThe only difference between easy and hard versions is constraints.\\n\\nYou are given a sequence $a$ consisting of $n$ positive integers.\\n\\nLet's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these elements are $a$ and $b$, $a$ can be equal $b$) and is as follows: $[\\\\underbrace{a, a, \\\\dots, a}_{x}, \\\\underbrace{b, b, \\\\dots, b}_{y}, \\\\underbrace{a, a, \\\\dots, a}_{x}]$. There $x, y$ are integers greater than or equal to $0$. For example, sequences $[]$, $[2]$, $[1, 1]$, $[1, 2, 1]$, $[1, 2, 2, 1]$ and $[1, 1, 2, 1, 1]$ are three block palindromes but $[1, 2, 3, 2, 1]$, $[1, 2, 1, 2, 1]$ and $[1, 2]$ are not.\\n\\nYour task is to choose the maximum by length subsequence of $a$ that is a three blocks palindrome.\\n\\nYou have to answer $t$ independent test cases.\\n\\nRecall that the sequence $t$ is a a subsequence of the sequence $s$ if $t$ can be derived from $s$ by removing zero or more elements without changing the order of the remaining elements. For example, if $s=[1, 2, 1, 3, 1, 2, 1]$, then possible subsequences are: $[1, 1, 1, 1]$, $[3]$ and $[1, 2, 1, 3, 1, 2, 1]$, but not $[3, 2, 3]$ and $[1, 1, 1, 1, 2]$.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 10^4$) — the number of test cases. Then $t$ test cases follow.\\n\\nThe first line of the test case contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the length of $a$. The second line of the test case contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 200$), where $a_i$ is the $i$-th element of $a$. Note that the maximum value of $a_i$ can be up to $200$.\\n\\nIt is guaranteed that the sum of $n$ over all test cases does not exceed $2 \\\\cdot 10^5$ ($\\\\sum n \\\\le 2 \\\\cdot 10^5$).\\n\\n\\n-----Output-----\\n\\nFor each test case, print the answer — the maximum possible length of some subsequence of $a$ that is a three blocks palindrome.\\n\\n\\n-----Example-----\\nInput\\n6\\n8\\n1 1 2 2 3 2 1 1\\n3\\n1 3 3\\n4\\n1 10 10 1\\n1\\n26\\n2\\n2 1\\n3\\n1 1 1\\n\\nOutput\\n7\\n2\\n4\\n1\\n1\\n3\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from operator import itemgetter\\nimport sys\\ninput = sys.stdin.readline\\n\\nMAX_A = 200\\nt = int(input())\\n\\nfor _ in range(t):\\n    n = int(input())\\n    a = list(map(int, input().split()))\\n    \\n    ruiseki = [[0] * MAX_A for i in range(n + 1)]\\n    for i in range(n):\\n        for j in range(MAX_A):\\n            ruiseki[i + 1][j] = ruiseki[i][j]\\n            if a[i] - 1 == j:\\n                ruiseki[i + 1][j] += 1\\n\\n    ans = 0\\n    for num in set(a):\\n        l = 0\\n        r = n - 1\\n        cnt = 0\\n        while True:\\n            while True:\\n                if a[l] != num:\\n                    l += 1\\n                else:\\n                    break\\n            while True:\\n                if a[r] != num:\\n                    r -= 1\\n                else:\\n                    break\\n            if l == r:\\n                ans = max(ans, cnt + 1)\\n                break\\n            elif l > r:\\n                break\\n            cnt += 1\\n            tmp_max = 0\\n            for j in range(MAX_A):\\n                tmp_max = max(tmp_max, ruiseki[r][j] - ruiseki[l + 1][j])\\n            ans = max(ans, cnt * 2 + tmp_max)\\n            l += 1\\n            r -= 1\\n    print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n### Lyrics...\\n\\nPyramids are amazing! Both in architectural and mathematical sense. If you have a computer, you can mess with pyramids even if you are not in Egypt at the time. For example, let's consider the following problem. Imagine that you have a pyramid built of numbers, like this one here:\\n\\n```\\n   \\/3\\/\\n  \\\\7\\\\ 4 \\n 2 \\\\4\\\\ 6 \\n8 5 \\\\9\\\\ 3\\n```\\n\\n### Here comes the task...\\n\\nLet's say that the *'slide down'* is the maximum sum of consecutive numbers from the top to the bottom of the pyramid. As you can see, the longest *'slide down'* is `3 + 7 + 4 + 9 = 23`\\n\\nYour task is to write a function `longestSlideDown` (in ruby: `longest_slide_down`) that takes a pyramid representation as argument and returns its' __largest__ *'slide down'*. For example,\\n\\n```python\\nlongestSlideDown([[3], [7, 4], [2, 4, 6], [8, 5, 9, 3]]) => 23\\n```\\n\\n### By the way...\\n\\nMy tests include some extraordinarily high pyramids so as you can guess, brute-force method is a bad idea unless you have a few centuries to waste. You must come up with something more clever than that.\\n\\n(c) This task is a lyrical version of the __Problem 18__ and\\/or __Problem 67__ on [ProjectEuler](https:\\/\\/projecteuler.net).\",\"targets\":\"def longest_slide_down(pyr):\\n    for row in range(len(pyr)-1, 0, -1):\\n        for col in range(0, row):\\n            pyr[row-1][col] += max(pyr[row][col], pyr[row][col+1])\\n    return pyr[0][0]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/489\\/D:\\nTomash keeps wandering off and getting lost while he is walking along the streets of Berland. It's no surprise! In his home town, for any pair of intersections there is exactly one way to walk from one intersection to the other one. The capital of Berland is very different!\\n\\nTomash has noticed that even simple cases of ambiguity confuse him. So, when he sees a group of four distinct intersections a, b, c and d, such that there are two paths from a to c — one through b and the other one through d, he calls the group a \\\"damn rhombus\\\". Note that pairs (a, b), (b, c), (a, d), (d, c) should be directly connected by the roads. Schematically, a damn rhombus is shown on the figure below: [Image] \\n\\nOther roads between any of the intersections don't make the rhombus any more appealing to Tomash, so the four intersections remain a \\\"damn rhombus\\\" for him.\\n\\nGiven that the capital of Berland has n intersections and m roads and all roads are unidirectional and are known in advance, find the number of \\\"damn rhombi\\\" in the city.\\n\\nWhen rhombi are compared, the order of intersections b and d doesn't matter.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a pair of integers n, m (1 ≤ n ≤ 3000, 0 ≤ m ≤ 30000) — the number of intersections and roads, respectively. Next m lines list the roads, one per line. Each of the roads is given by a pair of integers a_{i}, b_{i} (1 ≤ a_{i}, b_{i} ≤ n;a_{i} ≠ b_{i}) — the number of the intersection it goes out from and the number of the intersection it leads to. Between a pair of intersections there is at most one road in each of the two directions.\\n\\nIt is not guaranteed that you can get from any intersection to any other one.\\n\\n\\n-----Output-----\\n\\nPrint the required number of \\\"damn rhombi\\\".\\n\\n\\n-----Examples-----\\nInput\\n5 4\\n1 2\\n2 3\\n1 4\\n4 3\\n\\nOutput\\n1\\n\\nInput\\n4 12\\n1 2\\n1 3\\n1 4\\n2 1\\n2 3\\n2 4\\n3 1\\n3 2\\n3 4\\n4 1\\n4 2\\n4 3\\n\\nOutput\\n12\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from sys import stdin\\ninp = stdin.readline\\nn, m = map(int, inp().split())\\ng = {x: [] for x in range(1, n + 1)}\\nfor _ in range(m):\\n    a, b = map(int, inp().split())\\n    g[a].append(b)\\nans = 0\\nfor i in range(1, n + 1):\\n    d = {}\\n    for j in g[i]:\\n        for k in g[j]:\\n            if k != i:\\n                d[k] = d.get(k, 0) + 1\\n    for k in d.values():\\n        ans += k * (k - 1) \\/\\/ 2\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are times you recall a good old friend and everything you've come through together. Luckily there are social networks — they store all your message history making it easy to know what you argued over 10 years ago.\\n\\nMore formal, your message history is a sequence of messages ordered by time sent numbered from 1 to n where n is the total number of messages in the chat.\\n\\nEach message might contain a link to an earlier message which it is a reply to. When opening a message x or getting a link to it, the dialogue is shown in such a way that k previous messages, message x and k next messages are visible (with respect to message x). In case there are less than k messages somewhere, they are yet all shown.\\n\\nDigging deep into your message history, you always read all visible messages and then go by the link in the current message x (if there is one) and continue reading in the same manner.\\n\\nDetermine the number of messages you'll read if your start from message number t for all t from 1 to n. Calculate these numbers independently. If you start with message x, the initial configuration is x itself, k previous and k next messages. Messages read multiple times are considered as one.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and k (1 ≤ n ≤ 10^5, 0 ≤ k ≤ n) — the total amount of messages and the number of previous and next messages visible.\\n\\nThe second line features a sequence of integers a_1, a_2, ..., a_{n} (0 ≤ a_{i} < i), where a_{i} denotes the i-th message link destination or zero, if there's no link from i. All messages are listed in chronological order. It's guaranteed that the link from message x goes to message with number strictly less than x.\\n\\n\\n-----Output-----\\n\\nPrint n integers with i-th denoting the number of distinct messages you can read starting from message i and traversing the links while possible.\\n\\n\\n-----Examples-----\\nInput\\n6 0\\n0 1 1 2 3 2\\n\\nOutput\\n1 2 2 3 3 3 \\n\\nInput\\n10 1\\n0 1 0 3 4 5 2 3 7 0\\n\\nOutput\\n2 3 3 4 5 6 6 6 8 2 \\n\\nInput\\n2 2\\n0 1\\n\\nOutput\\n2 2 \\n\\n\\n\\n-----Note-----\\n\\nConsider i = 6...\",\"targets\":\"from math import *\\nfrom random import *\\nfrom copy import *\\nimport os, sys\\n\\nn, k = list(map(int, input().split()))\\nA = list(map(int, input().split()))\\nres = [0] * (n + 1)\\n\\nfor i in range(1, n + 1):\\n  prev = A[i - 1]\\n  res[i] = res[prev]\\n  prev = prev - k if prev == 0 else prev\\n  res[i] += min(max(0, i - prev - k - 1), k) + max(0, min(k + 1, n - i + 1) - max(0, min(n - prev + 1, prev + k - i + 1)))\\nprint(' '.join(list(map(str, res[1 :]))))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou have n dices each one having s sides numbered from 1 to s.\\nHow many outcomes add up to a specified number k?\\n\\nFor example if we roll four normal six-sided dices we\\nhave four outcomes that add up to 5. \\n\\n(1, 1, 1, 2)\\n(1, 1, 2, 1)\\n(1, 2, 1, 1)\\n(2, 1, 1, 1)\",\"targets\":\"def outcome(n, s, k):\\n\\n    if n * s * k == 0: \\n        return 0\\n    \\n    dp = [[0] * (k + 1) for i in range(n + 1)]\\n    \\n    for i in range(1, min(s + 1, k + 1)): \\n        dp[1][i] = 1\\n    \\n    for i in range(2, n + 1): \\n        for j in range(1, k + 1): \\n            for l in range(1, min(s + 1, j)): \\n                dp[i][j] += dp[i - 1][j - l]\\n      \\n    return dp.pop().pop()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/696\\/C:\\nAs we all know Barney's job is \\\"PLEASE\\\" and he has not much to do at work. That's why he started playing \\\"cups and key\\\". In this game there are three identical cups arranged in a line from left to right. Initially key to Barney's heart is under the middle cup. [Image] \\n\\nThen at one turn Barney swaps the cup in the middle with any of other two cups randomly (he choses each with equal probability), so the chosen cup becomes the middle one. Game lasts n turns and Barney independently choses a cup to swap with the middle one within each turn, and the key always remains in the cup it was at the start.\\n\\nAfter n-th turn Barney asks a girl to guess which cup contains the key. The girl points to the middle one but Barney was distracted while making turns and doesn't know if the key is under the middle cup. That's why he asked you to tell him the probability that girl guessed right.\\n\\nNumber n of game turns can be extremely large, that's why Barney did not give it to you. Instead he gave you an array a_1, a_2, ..., a_{k} such that  $n = \\\\prod_{i = 1}^{k} a_{i}$ \\n\\nin other words, n is multiplication of all elements of the given array.\\n\\nBecause of precision difficulties, Barney asked you to tell him the answer as an irreducible fraction. In other words you need to find it as a fraction p \\/ q such that $\\\\operatorname{gcd}(p, q) = 1$, where $gcd$ is the greatest common divisor. Since p and q can be extremely large, you only need to find the remainders of dividing each of them by 10^9 + 7.\\n\\nPlease note that we want $gcd$ of p and q to be 1, not $gcd$ of their remainders after dividing by 10^9 + 7.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains a single integer k (1 ≤ k ≤ 10^5) — the number of elements in array Barney gave you.\\n\\nThe second line contains k integers a_1, a_2, ..., a_{k} (1 ≤ a_{i} ≤ 10^18) — the elements of the array.\\n\\n\\n-----Output-----\\n\\nIn the only line of output print a single string x \\/ y where x is the remainder of dividing p by 10^9 + 7 and y is the remainder of dividing q by 10^9 +...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"m = 1000000007\\ninput()\\nn, d = 2, 1\\nfor q in map(int, input().split()): d, n = q & d, pow(n, q, m)\\nn = n * pow(2, m - 2, m) % m\\nk = (n + 1 - 2 * d) * pow(3, m - 2, m) % m\\nprint(str(k) + '\\/' + str(n))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/716\\/B:\\nZS the Coder loves to read the dictionary. He thinks that a word is nice if there exists a substring (contiguous segment of letters) of it of length 26 where each letter of English alphabet appears exactly once. In particular, if the string has length strictly less than 26, no such substring exists and thus it is not nice.\\n\\nNow, ZS the Coder tells you a word, where some of its letters are missing as he forgot them. He wants to determine if it is possible to fill in the missing letters so that the resulting word is nice. If it is possible, he needs you to find an example of such a word as well. Can you help him?\\n\\n\\n-----Input-----\\n\\nThe first and only line of the input contains a single string s (1 ≤ |s| ≤ 50 000), the word that ZS the Coder remembers. Each character of the string is the uppercase letter of English alphabet ('A'-'Z') or is a question mark ('?'), where the question marks denotes the letters that ZS the Coder can't remember.\\n\\n\\n-----Output-----\\n\\nIf there is no way to replace all the question marks with uppercase letters such that the resulting word is nice, then print  - 1 in the only line.\\n\\nOtherwise, print a string which denotes a possible nice word that ZS the Coder learned. This string should match the string from the input, except for the question marks replaced with uppercase English letters.\\n\\nIf there are multiple solutions, you may print any of them.\\n\\n\\n-----Examples-----\\nInput\\nABC??FGHIJK???OPQR?TUVWXY?\\n\\nOutput\\nABCDEFGHIJKLMNOPQRZTUVWXYS\\nInput\\nWELCOMETOCODEFORCESROUNDTHREEHUNDREDANDSEVENTYTWO\\n\\nOutput\\n-1\\nInput\\n??????????????????????????\\n\\nOutput\\nMNBVCXZLKJHGFDSAQPWOEIRUYT\\nInput\\nAABCDEFGHIJKLMNOPQRSTUVW??M\\n\\nOutput\\n-1\\n\\n\\n-----Note-----\\n\\nIn the first sample case, ABCDEFGHIJKLMNOPQRZTUVWXYS is a valid answer beacuse it contains a substring of length 26 (the whole string in this case) which contains all the letters of the English alphabet exactly once. Note that there are many possible solutions, such as ABCDEFGHIJKLMNOPQRSTUVWXYZ or ABCEDFGHIJKLMNOPQRZTUVWXYS.\\n\\nIn the second sample case, there are...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from collections import Counter\\n\\ns = input()\\nif len(s) < 26:\\n    print(-1)\\nelse:\\n    a = Counter(s[:26])\\n    score = len(a)\\n    if '?' in a:\\n        score += a['?'] - 1\\n    ans = []\\n    if score == 26:\\n        for c in s[:26]:\\n            if c == '?':\\n                for z in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ':\\n                    if not a[z]:\\n                        a[z] = 1\\n                        ans += z\\n                        break\\n            else:\\n                ans += c\\n        for c in s[26:]:\\n            ans += 'A' if c == '?' else c\\n        print(''.join(ans))\\n    else:\\n        for i, c in enumerate(s[26:]):\\n            p = s[i]\\n            ans += 'A' if p == '?' else p\\n            a[p] -= 1\\n            if p == '?' or a[p] == 0:\\n                score -= 1\\n            a[c] += 1\\n            if c == '?' or a[c] == 1:\\n                score += 1\\n            if score == 26:\\n                for c in s[i+1:i+27]:\\n                    if c == '?':\\n                        for z in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ':\\n                            if not a[z]:\\n                                a[z] = 1\\n                                ans += z\\n                                break\\n                    else:\\n                        ans += c\\n                for c in s[i+27:]:\\n                    ans += 'A' if c == '?' else c\\n                print(''.join(ans))\\n                break\\n        else:\\n            print(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc092\\/tasks\\/arc093_a:\\nThere are N sightseeing spots on the x-axis, numbered 1, 2, ..., N.\\nSpot i is at the point with coordinate A_i.\\nIt costs |a - b| yen (the currency of Japan) to travel from a point with coordinate a to another point with coordinate b along the axis.\\nYou planned a trip along the axis.\\nIn this plan, you first depart from the point with coordinate 0, then visit the N spots in the order they are numbered, and finally return to the point with coordinate 0.\\nHowever, something came up just before the trip, and you no longer have enough time to visit all the N spots, so you decided to choose some i and cancel the visit to Spot i.\\nYou will visit the remaining spots as planned in the order they are numbered.\\nYou will also depart from and return to the point with coordinate 0 at the beginning and the end, as planned.\\nFor each i = 1, 2, ..., N, find the total cost of travel during the trip when the visit to Spot i is canceled.\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 10^5\\n - -5000 \\\\leq A_i \\\\leq 5000 (1 \\\\leq i \\\\leq N)\\n - All input values are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 A_2 ... A_N\\n\\n-----Output-----\\nPrint N lines.\\nIn the i-th line, print the total cost of travel during the trip when the visit to Spot i is canceled.\\n\\n-----Sample Input-----\\n3\\n3 5 -1\\n\\n-----Sample Output-----\\n12\\n8\\n10\\n\\nSpot 1, 2 and 3 are at the points with coordinates 3, 5 and -1, respectively.\\nFor each i, the course of the trip and the total cost of travel when the visit to Spot i is canceled, are as follows:\\n - For i = 1, the course of the trip is 0 \\\\rightarrow 5 \\\\rightarrow -1 \\\\rightarrow 0 and the total cost of travel is 5 + 6 + 1 = 12 yen.\\n - For i = 2, the course of the trip is 0 \\\\rightarrow 3 \\\\rightarrow -1 \\\\rightarrow 0 and the total cost of travel is 3 + 4 + 1 = 8 yen.\\n - For i = 3, the course of the trip is 0 \\\\rightarrow 3 \\\\rightarrow 5 \\\\rightarrow 0 and the total cost of travel is 3 + 2 + 5 = 10 yen.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n    n = int(input())\\n    a = list(map(int, input().split()))\\n    a.append(0)\\n\\n    base = abs(a[0])\\n    for i in range(n):\\n        base += abs(a[i+1] - a[i])\\n    \\n    ans = []\\n    for i in range(n):\\n        if (a[i] - a[i-1]) * (a[i+1] - a[i]) >= 0:\\n            ans.append(base)\\n        else:\\n            ans.append(base - 2 * min(abs(a[i] - a[i-1]), abs(a[i+1] - a[i])))\\n    \\n    for i in ans:\\n        print(i)\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nImplement a function, so it will produce a sentence out of the given parts.\\n\\nArray of parts could contain:\\n- words;\\n- commas in the middle;\\n- multiple periods at the end.\\n\\nSentence making rules:\\n- there must always be a space between words;\\n- there must not be a space between a comma and word on the left;\\n- there must always be one and only one period at the end of a sentence.\\n\\n**Example:**\",\"targets\":\"import re\\n\\ndef make_sentences(parts):\\n    return re.sub(' ([,.])', r'\\\\1', ' '.join(parts).replace(' ,', ',')).rstrip('.') + '.'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1056\\/F:\\nPolycarp, Arkady's friend, prepares to the programming competition and decides to write a contest. The contest consists of $n$ problems and lasts for $T$ minutes. Each of the problems is defined by two positive integers $a_i$ and $p_i$ — its difficulty and the score awarded by its solution.\\n\\nPolycarp's experience suggests that his skill level is defined with positive real value $s$, and initially $s=1.0$. To solve the $i$-th problem Polycarp needs $a_i\\/s$ minutes.\\n\\nPolycarp loves to watch series, and before solving each of the problems he will definitely watch one episode. After Polycarp watches an episode, his skill decreases by $10\\\\%$, that is skill level $s$ decreases to $0.9s$. Each episode takes exactly $10$ minutes to watch. When Polycarp decides to solve some problem, he firstly has to watch one episode, and only then he starts solving the problem without breaks for $a_i\\/s$ minutes, where $s$ is his current skill level. In calculation of $a_i\\/s$ no rounding is performed, only division of integer value $a_i$ by real value $s$ happens.\\n\\nAlso, Polycarp can train for some time. If he trains for $t$ minutes, he increases his skill by $C \\\\cdot t$, where $C$ is some given positive real constant. Polycarp can train only before solving any problem (and before watching series). Duration of the training can be arbitrary real value.\\n\\nPolycarp is interested: what is the largest score he can get in the contest? It is allowed to solve problems in any order, while training is only allowed before solving the first problem.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $tc$ ($1 \\\\le tc \\\\le 20$) — the number of test cases. Then $tc$ test cases follow.\\n\\nThe first line of each test contains one integer $n$ ($1 \\\\le n \\\\le 100$) — the number of problems in the contest.\\n\\nThe second line of the test contains two real values $C, T$ ($0 < C < 10$, $0 \\\\le T \\\\le 2 \\\\cdot 10^5$), where $C$ defines the efficiency of the training and $T$ is the duration of the contest in minutes. Value $C, T$ are given exactly with three digits...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import sqrt\\nclass pro(object):\\n    def __init__(self,dif,sc):\\n        self.dif=dif\\n        self.sc=sc\\n\\n    def __lt__(self,other):\\n        return self.dif>other.dif\\n\\nT=int(input())\\nmul=[1]\\nfor i in range(100):\\n    mul.append(mul[i]*10\\/9)\\ninf=1000000007\\nfor t in range(T):\\n    n=int(input())\\n    effi,tim=list(map(float,input().split()))\\n    prob=[]\\n    for i in range(n):\\n        x,y=list(map(int,input().split()))\\n        prob.append(pro(x,y))\\n    prob.sort()\\n    f=[[inf for i in range(n+1)] for j in range(1001)]\\n    f[0][0]=0\\n    totsc=0\\n    for i in range(n):\\n        totsc+=prob[i].sc\\n        for j in range(totsc,prob[i].sc-1,-1):\\n            for k in range(1,i+2):\\n                f[j][k]=min(f[j][k],f[j-prob[i].sc][k-1]+prob[i].dif*mul[k])\\n    for i in range(totsc,-1,-1):\\n        flag=False\\n        for j in range(n+1):\\n            if sqrt(effi*f[i][j])>=1:\\n                res=2*sqrt(f[i][j]\\/effi)-1\\/effi+10*j\\n            else:\\n                res=f[i][j]+10*j\\n            if res<=tim:\\n                print(i)\\n                flag=True\\n                break\\n        if flag==True:\\n            break\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/602\\/A:\\nAfter seeing the \\\"ALL YOUR BASE ARE BELONG TO US\\\" meme for the first time, numbers X and Y realised that they have different bases, which complicated their relations.\\n\\nYou're given a number X represented in base b_{x} and a number Y represented in base b_{y}. Compare those two numbers.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two space-separated integers n and b_{x} (1 ≤ n ≤ 10, 2 ≤ b_{x} ≤ 40), where n is the number of digits in the b_{x}-based representation of X. \\n\\nThe second line contains n space-separated integers x_1, x_2, ..., x_{n} (0 ≤ x_{i} < b_{x}) — the digits of X. They are given in the order from the most significant digit to the least significant one.\\n\\nThe following two lines describe Y in the same way: the third line contains two space-separated integers m and b_{y} (1 ≤ m ≤ 10, 2 ≤ b_{y} ≤ 40, b_{x} ≠ b_{y}), where m is the number of digits in the b_{y}-based representation of Y, and the fourth line contains m space-separated integers y_1, y_2, ..., y_{m} (0 ≤ y_{i} < b_{y}) — the digits of Y.\\n\\nThere will be no leading zeroes. Both X and Y will be positive. All digits of both numbers are given in the standard decimal numeral system.\\n\\n\\n-----Output-----\\n\\nOutput a single character (quotes for clarity):   '<' if X < Y  '>' if X > Y  '=' if X = Y \\n\\n\\n-----Examples-----\\nInput\\n6 2\\n1 0 1 1 1 1\\n2 10\\n4 7\\n\\nOutput\\n=\\n\\nInput\\n3 3\\n1 0 2\\n2 5\\n2 4\\n\\nOutput\\n<\\n\\nInput\\n7 16\\n15 15 4 0 0 7 10\\n7 9\\n4 8 0 3 1 5 0\\n\\nOutput\\n>\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, X = 101111_2 = 47_10 = Y.\\n\\nIn the second sample, X = 102_3 = 21_5 and Y = 24_5 = 112_3, thus X < Y.\\n\\nIn the third sample, $X = FF 4007 A_{16}$ and Y = 4803150_9. We may notice that X starts with much larger digits and b_{x} is much larger than b_{y}, so X is clearly larger than Y.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"z1 = list(map(int,input().split()))\\nx = list(map(int,input().split()))\\nz2 = list(map(int,input().split()))\\ny= list(map(int,input().split()))\\n\\nn1, b1 = z1[0],z1[1]\\nn2, b2 = z2[0],z2[1]\\n\\nansx = ansy = 0\\n\\nfor i in range(n1):\\n    ansx+= x[n1-i-1]*(b1**i)\\nfor i in range(n2):\\n    ansy+= y[n2-i-1]*(b2**i)\\n    \\nif ansx == ansy:\\n    print('=')\\nelif ansx > ansy:\\n    print('>')\\nelse:\\n    print('<')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc114\\/tasks\\/abc114_c:\\nYou are given an integer N. Among the integers between 1 and N (inclusive), how many Shichi-Go-San numbers (literally \\\"Seven-Five-Three numbers\\\") are there?\\nHere, a Shichi-Go-San number is a positive integer that satisfies the following condition:\\n - When the number is written in base ten, each of the digits 7, 5 and 3 appears at least once, and the other digits never appear.\\n\\n-----Constraints-----\\n - 1 \\\\leq N < 10^9\\n - N is an integer.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\n\\n-----Output-----\\nPrint the number of the Shichi-Go-San numbers between 1 and N (inclusive).\\n\\n-----Sample Input-----\\n575\\n\\n-----Sample Output-----\\n4\\n\\nThere are four Shichi-Go-San numbers not greater than 575: 357, 375, 537 and 573.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\n\\nans = 0\\n\\n\\ndef gen_pat(cur):\\n    nonlocal ans\\n\\n    if int(cur) > n:\\n        return\\n\\n    if len(set(cur)) == 4:  # 0 7 5 3 が含まれる。\\n        ans += 1\\n\\n    gen_pat(cur + \\\"3\\\")\\n    gen_pat(cur + \\\"5\\\")\\n    gen_pat(cur + \\\"7\\\")\\n\\n\\ngen_pat(\\\"0\\\")\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/577a98a6ae28071780000989:\\nYour task is to make two functions, ```max``` and ```min``` (`maximum` and `minimum` in PHP and Python) that take a(n) array\\/vector of integers ```list``` as input and outputs, respectively, the largest and lowest number in that array\\/vector.\\n\\n#Examples\\n```python\\nmaximun([4,6,2,1,9,63,-134,566]) returns 566\\nminimun([-52, 56, 30, 29, -54, 0, -110]) returns -110\\nmaximun([5]) returns 5\\nminimun([42, 54, 65, 87, 0]) returns 0\\n```\\n\\n#Notes\\n- You may consider that there will not be any empty arrays\\/vectors.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def minimum(arr):\\n    minimum = arr[0]\\n    for i in range(0, len(arr)):\\n        if arr[i] < minimum:\\n            minimum = arr[i]\\n    return minimum\\n\\ndef maximum(arr):\\n    maximum = arr[0]\\n    for i in range(0, len(arr)):\\n        if arr[i] > maximum:\\n            maximum = arr[i]\\n    return maximum\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/PLAYSTR:\\nChef usually likes to play cricket, but now, he is bored of playing it too much, so he is trying new games with strings. Chef's friend Dustin gave him binary strings $S$ and $R$, each with length $N$, and told him to make them identical. However, unlike Dustin, Chef does not have any superpower and Dustin lets Chef perform only operations of one type: choose any pair of integers $(i, j)$ such that $1 \\\\le i, j \\\\le N$ and swap the $i$-th and $j$-th character of $S$. He may perform any number of operations (including zero).\\nFor Chef, this is much harder than cricket and he is asking for your help. Tell him whether it is possible to change the string $S$ to the target string $R$ only using operations of the given type.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $N$.\\n- The second line contains a binary string $S$.\\n- The third line contains a binary string $R$.\\n\\n-----Output-----\\nFor each test case, print a single line containing the string \\\"YES\\\" if it is possible to change $S$ to $R$ or \\\"NO\\\" if it is impossible (without quotes).\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 400$\\n- $1 \\\\le N \\\\le 100$\\n- $|S| = |R| = N$\\n- $S$ and $R$ will consist of only '1' and '0'\\n\\n-----Example Input-----\\n2\\n5\\n11000\\n01001\\n3\\n110\\n001\\n\\n-----Example Output-----\\nYES\\nNO\\n\\n-----Explanation-----\\nExample case 1: Chef can perform one operation with $(i, j) = (1, 5)$. Then, $S$ will be \\\"01001\\\", which is equal to $R$.\\nExample case 2: There is no sequence of operations which would make $S$ equal to $R$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nfor i in range(int(input())):\\n a=int(input())\\n b=input()\\n c=input()\\n if(b.count(\\\"1\\\")==c.count(\\\"1\\\")):\\n  print(\\\"YES\\\")\\n else:\\n  print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58efb6ef0849132bf000008f:\\n## Task\\n\\nGiven a string, add the fewest number of characters possible from the front or back to make it a palindrome.\\n\\n## Example\\n\\nFor the input `cdcab`, the output should be `bacdcab`\\n\\n## Input\\/Output\\n\\nInput is a string consisting of lowercase latin letters with length 3 <= str.length <= 10\\n\\nThe output is a palindrome string satisfying the task.\\n\\nFor s = `ab` either solution (`aba` or `bab`) will be accepted.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def is_palindrome(s):\\n    \\\"\\\"\\\"Check if s is a palindrome\\\"\\\"\\\"\\n    return s == s[::-1]\\n\\n\\ndef left_strip_palindrome(s):\\n    \\\"\\\"\\\"Keeps stripping from left to find a palindrome. If not found return None. \\n    If found return the stripped characters in stripping order\\\"\\\"\\\"\\n    for i in range(len(s)-1):\\n        if is_palindrome(s[i:]):\\n            return s[:i]\\n    return None\\n\\ndef right_strip_palindrome(s):\\n    \\\"\\\"\\\"Keeps stripping from right to find a palindrome. If not found return None. \\n    If found return the stripped characters in stripping order\\\"\\\"\\\"\\n    for i in range(-1,1-len(s),-1):\\n        if is_palindrome(s[:i]):\\n            return s[i:]\\n            \\ndef build_palindrome(s):\\n    \\\"\\\"\\\"Build a palindrome by adding the min number of characters possible.\\\"\\\"\\\"\\n    lsp = left_strip_palindrome(s)\\n    rsp = right_strip_palindrome(s)\\n    # Answer is obtained by getting the stripped characters and add them in reverse order \\n    # to the opps direction they were stripped from in reverse direction.\\n    if lsp is not None:\\n        lsp_ans = s+lsp[::-1]\\n        if rsp is not None:\\n            rsp_ans = rsp[::-1]+s\\n            # In the case both left stripping and right stripping works, return the shortest answer.\\n            return min((lsp_ans,rsp_ans), key=len)\\n        return lsp_ans\\n            \\n    if rsp is not None:\\n        rsp_ans = rsp[::-1]+s\\n        return rsp_ans\\n    \\n    # If stripping does not work return the string with the copy of all characters \\n    # but the first concatenated at the starting in reverse order.\\n    return s[1:][::-1]+s\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAuthor has gone out of the stories about Vasiliy, so here is just a formal task description.\\n\\nYou are given q queries and a multiset A, initially containing only integer 0. There are three types of queries:  \\\"+ x\\\" — add integer x to multiset A. \\\"- x\\\" — erase one occurrence of integer x from multiset A. It's guaranteed that at least one x is present in the multiset A before this query. \\\"? x\\\" — you are given integer x and need to compute the value $\\\\operatorname{max}_{y \\\\in A}(x \\\\oplus y)$, i.e. the maximum value of bitwise exclusive OR (also know as XOR) of integer x and some integer y from the multiset A.\\n\\nMultiset is a set, where equal elements are allowed.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a single integer q (1 ≤ q ≤ 200 000) — the number of queries Vasiliy has to perform.\\n\\nEach of the following q lines of the input contains one of three characters '+', '-' or '?' and an integer x_{i} (1 ≤ x_{i} ≤ 10^9). It's guaranteed that there is at least one query of the third type.\\n\\nNote, that the integer 0 will always be present in the set A.\\n\\n\\n-----Output-----\\n\\nFor each query of the type '?' print one integer — the maximum value of bitwise exclusive OR (XOR) of integer x_{i} and some integer from the multiset A.\\n\\n\\n-----Example-----\\nInput\\n10\\n+ 8\\n+ 9\\n+ 11\\n+ 6\\n+ 1\\n? 3\\n- 8\\n? 3\\n? 8\\n? 11\\n\\nOutput\\n11\\n10\\n14\\n13\\n\\n\\n\\n-----Note-----\\n\\nAfter first five operations multiset A contains integers 0, 8, 9, 11, 6 and 1.\\n\\nThe answer for the sixth query is integer $11 = 3 \\\\oplus 8$ — maximum among integers $3 \\\\oplus 0 = 3$, $3 \\\\oplus 9 = 10$, $3 \\\\oplus 11 = 8$, $3 \\\\oplus 6 = 5$ and $3 \\\\oplus 1 = 2$.\",\"targets\":\"# 10\\n# + 8\\n# + 9\\n# + 11\\n# + 6\\n# + 1\\n# ? 3\\n# - 8\\n# ? 3\\n# ? 8\\n# ? 11\\n\\nMAX_BIT = 30\\n\\nclass Node:\\n    def __init__(self):\\n        self.left = None\\n        self.right = None\\n        self.leftCnt = 0\\n        self.rightCnt = 0\\n    \\n    def AddRight(self):\\n        if self.right == None:\\n            self.right = Node()\\n            self.rightCnt = 1\\n        else:\\n            self.rightCnt += 1\\n    \\n    def AddLeft(self):\\n        if self.left == None:\\n            self.left = Node()\\n            self.leftCnt = 1\\n        else:\\n            self.leftCnt += 1\\n\\n    def RemRight(self):\\n        self.rightCnt -= 1\\n    \\n    def RemLeft(self):\\n        self.leftCnt -= 1\\n\\n    def Left(self):\\n        return self.left != None and self.leftCnt > 0\\n\\n    def Right(self):\\n        return self.right != None and self.rightCnt > 0\\n\\ndef insert(u, num, dig=MAX_BIT):\\n    if dig < 0:\\n        return\\n    \\n    bit = (num>>dig)&1\\n    if bit > 0: #insert to right\\n        u.AddRight()\\n        insert(u.right, num, dig-1)\\n    else:\\n        u.AddLeft()\\n        insert(u.left, num, dig-1)\\n\\ndef remove(u, num, dig=MAX_BIT):\\n    if dig < 0:\\n        return\\n    \\n    bit = (num>>dig)&1\\n    if bit > 0: #remove right\\n        u.RemRight()\\n        remove(u.right, num, dig-1)\\n    else:\\n        u.RemLeft()\\n        remove(u.left, num, dig-1)\\n\\ndef cal(u, num, dig=MAX_BIT):\\n    if dig < 0 or u == None:\\n        return 0\\n    \\n    bit = (num>>dig)&1\\n    if bit > 0: #try to go to left first\\n        if u.Left(): #if valid\\n            return (1<<dig) + cal(u.left, num, dig-1)\\n        elif u.Right():\\n            return cal(u.right, num, dig-1)\\n    else: #try to go to right first\\n        if u.Right():\\n            return (1<<dig) + cal(u.right, num, dig-1)\\n        elif u.Left():\\n            return cal(u.left, num, dig-1)\\n    return 0\\n\\ndef main():\\n    root = Node()\\n    insert(root, 0)\\n\\n    n = int(input())\\n    for i in range(n):\\n        tmp = input().split()\\n        num = int(tmp[1])\\n        if tmp[0] == \\\"+\\\":\\n            insert(root, num)\\n        elif tmp[0] == \\\"-\\\":\\n           ...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given two lists of segments $[al_1, ar_1], [al_2, ar_2], \\\\dots, [al_n, ar_n]$ and $[bl_1, br_1], [bl_2, br_2], \\\\dots, [bl_n, br_n]$.\\n\\nInitially, all segments $[al_i, ar_i]$ are equal to $[l_1, r_1]$ and all segments $[bl_i, br_i]$ are equal to $[l_2, r_2]$.\\n\\nIn one step, you can choose one segment (either from the first or from the second list) and extend it by $1$. In other words, suppose you've chosen segment $[x, y]$ then you can transform it either into $[x - 1, y]$ or into $[x, y + 1]$.\\n\\nLet's define a total intersection $I$ as the sum of lengths of intersections of the corresponding pairs of segments, i.e. $\\\\sum\\\\limits_{i=1}^{n}{\\\\text{intersection_length}([al_i, ar_i], [bl_i, br_i])}$. Empty intersection has length $0$ and length of a segment $[x, y]$ is equal to $y - x$.\\n\\nWhat is the minimum number of steps you need to make $I$ greater or equal to $k$?\\n\\n\\n-----Input-----\\n\\nThe first line contains the single integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases.\\n\\nThe first line of each test case contains two integers $n$ and $k$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$; $1 \\\\le k \\\\le 10^9$) — the length of lists and the minimum required total intersection.\\n\\nThe second line of each test case contains two integers $l_1$ and $r_1$ ($1 \\\\le l_1 \\\\le r_1 \\\\le 10^9$) — the segment all $[al_i, ar_i]$ are equal to initially.\\n\\nThe third line of each test case contains two integers $l_2$ and $r_2$ ($1 \\\\le l_2 \\\\le r_2 \\\\le 10^9$) — the segment all $[bl_i, br_i]$ are equal to initially.\\n\\nIt's guaranteed that the sum of $n$ doesn't exceed $2 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nPrint $t$ integers — one per test case. For each test case, print the minimum number of step you need to make $I$ greater or equal to $k$.\\n\\n\\n-----Example-----\\nInput\\n3\\n3 5\\n1 2\\n3 4\\n2 1000000000\\n1 1\\n999999999 999999999\\n10 3\\n5 10\\n7 8\\n\\nOutput\\n7\\n2000000000\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, we can achieve total intersection $5$, for example, using next strategy:   make $[al_1, ar_1]$ from $[1, 2]$ to $[1, 4]$ in $2$ steps;  make $[al_2, ar_2]$ from...\",\"targets\":\"def inter(l1, r1, l2, r2):\\n    l = max(l1,l2)\\n    r = min(r1,r2)\\n    return max(r - l, 0)\\ndef solve():\\n    n, k = map(int,input().split())\\n    al, ar = map(int,input().split())\\n    bl, br = map(int,input().split())\\n    res = inter(al,ar,bl,br) * n\\n    goodt = max(ar, br) - min(al,bl) - inter(al,ar,bl,br)\\n    minhodi = 1000000000000\\n    hodi = 0\\n    to_soed = max(0, max(al,bl) - min(ar, br))\\n    if res >= k:\\n        print(0)\\n        return 0\\n    for i in range(n):\\n        hodi += to_soed\\n        ineed = k - res\\n        if goodt >= ineed:\\n            hodi += ineed\\n            minhodi = min(minhodi, hodi)\\n            break\\n        hodi += goodt\\n        res += goodt\\n        minhodi = min(hodi + (k - res) * 2, minhodi)\\n    print(minhodi)\\nfor i in range(int(input())):\\n    solve()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/518\\/F:\\nOn a certain meeting of a ruling party \\\"A\\\" minister Pavel suggested to improve the sewer system and to create a new pipe in the city.\\n\\nThe city is an n × m rectangular squared field. Each square of the field is either empty (then the pipe can go in it), or occupied (the pipe cannot go in such square). Empty squares are denoted by character '.', occupied squares are denoted by character '#'.\\n\\nThe pipe must meet the following criteria:  the pipe is a polyline of width 1,  the pipe goes in empty squares,  the pipe starts from the edge of the field, but not from a corner square,  the pipe ends at the edge of the field but not in a corner square,  the pipe has at most 2 turns (90 degrees),  the border squares of the field must share exactly two squares with the pipe,  if the pipe looks like a single segment, then the end points of the pipe must lie on distinct edges of the field,  for each non-border square of the pipe there are exacly two side-adjacent squares that also belong to the pipe,  for each border square of the pipe there is exactly one side-adjacent cell that also belongs to the pipe. \\n\\nHere are some samples of allowed piping routes: \\n\\n           ....#            ....#            .*..#\\n\\n           *****            ****.            .***.\\n\\n           ..#..            ..#*.            ..#*.\\n\\n           #...#            #..*#            #..*#\\n\\n           .....            ...*.            ...*.\\n\\n\\n\\nHere are some samples of forbidden piping routes: \\n\\n           .**.#            *...#            .*.*#\\n\\n           .....            ****.            .*.*.\\n\\n           ..#..            ..#*.            .*#*.\\n\\n           #...#            #..*#            #*.*#\\n\\n           .....            ...*.            .***.\\n\\n\\n\\nIn these samples the pipes are represented by characters ' * '.\\n\\nYou were asked to write a program that calculates the number of distinct ways to make exactly one pipe in the city. \\n\\nThe two ways to make a pipe are considered distinct if they are distinct in at least one square.\\n\\n\\n-----Input-----\\n\\nThe first...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = [int(x) for x in input().split()]\\na = [[int(c == '.') for c in input()] for i in range(n)]\\n\\ndef rotate(a):\\n    n = len(a)\\n    m = len(a[0])\\n    b = [[0] * n for i in range(m)]\\n    for i in range(n):\\n        for j in range(m):\\n            b[j][n - 1 - i] = a[i][j]\\n    return b\\n\\ndef calc(a):\\n    n = len(a)\\n    m = len(a[0])\\n    alive = a[0][:]\\n    alive[0], alive[m - 1] = 0, 0\\n    ans_l, ans_r, ans_u = 0, 0, 0\\n    ans_bs = [0] * m\\n    for i in range(1, n - 1):\\n        s = 0\\n        for j in range(1, m - 1):\\n            if a[i][j]:\\n                if alive[j]:\\n                    ans_u += s - alive[j - 1]\\n                ans_bs[j] += s\\n                s += alive[j]\\n            else:\\n                s = 0\\n                ans_bs[j] = 0\\n                alive[j] = 0\\n        if a[i][m - 1]:\\n            ans_r += s\\n        s = 0\\n        for j in range(m - 2, 0, -1):\\n            if a[i][j]:\\n                if alive[j]:\\n                    ans_u += s - alive[j + 1]\\n                ans_bs[j] += s\\n                s += alive[j]\\n            else:\\n                s = 0\\n                ans_bs[j] = 0\\n                alive[j] = 0\\n        if a[i][0]:\\n            ans_l += s\\n    ans_u \\/\\/= 2\\n    ans_b = sum(a[n - 1][i] * (ans_bs[i] + alive[i]) for i in range(1, m - 1))\\n    return ans_l, ans_r, ans_u, ans_b\\nans = 0\\nans_l, ans_r, ans_u, ans_b = calc(a)\\nans += ans_l + ans_r + ans_u + ans_b\\na = rotate(a)\\nans_l, _, ans_u, ans_b = calc(a)\\nans += ans_l + ans_u + ans_b\\na = rotate(a)\\nans_l, _, ans_u, _= calc(a)\\nans += ans_l + ans_u\\na = rotate(a)\\n_, _, ans_u, _= calc(a)\\nans += ans_u\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/57507369b0b6d1b5a60001b3:\\nIn genetics a reading frame is a way to divide a sequence of nucleotides (DNA bases) into a set of consecutive non-overlapping triplets (also called codon). Each of this triplets is translated into an amino-acid during a translation process to create proteins.\\n\\nInput\\n---\\nIn a single strand of DNA you find 3 Reading frames, take for example the following input sequence:\\n\\n    AGGTGACACCGCAAGCCTTATATTAGC\\n    \\nOutput\\n---\\nFor the output we are going to take the combinations and show them in the following manner:\\n\\n````\\nFrame 1: AGG TGA CAC CGC AAG CCT TAT ATT AGC\\nFrame 2: A GGT GAC ACC GCA AGC CTT ATA TTA GC\\nFrame 3: AG GTG ACA CCG CAA GCC TTA TAT TAG C\\n````\\n\\nFor frame 1 split all of them in groups of three starting by the first base (letter).\\n\\nFor frame 2 split all of them in groups of three starting by the second base (letter) but having the first base (letter) at the beggining.\\n\\nFor frame 3 split all of them in groups of three starting by the third letter, but having the first and second bases (letters) at the beginning in the same order.\\n\\nSeries\\n---\\n\\n1. [Decompose single strand DNA into 3 reading frames](http:\\/\\/www.codewars.com\\/kata\\/57507369b0b6d1b5a60001b3)\\n\\n2. [Decompose double strand DNA into 6 reading frames](http:\\/\\/www.codewars.com\\/kata\\/57519060f2dac7ec95000c8e\\/)\\n\\n3.  [Translate DNA to protein in 6 frames](http:\\/\\/www.codewars.com\\/kata\\/5708ef48fe2d018413000776)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def decompose_single_strand(s):\\n    F1 = []\\n    F2 = [s[0]]\\n    F3 = [s[:2]]\\n    for i in range(0,len(s), 3):\\n       F1.append(s[i:i + 3])\\n    F1 = ' '.join(F1)\\n    for i in range(1,len(s), 3):\\n       F2.append(s[i:i + 3])\\n    F2 = ' '.join(F2)\\n    for i in range(2,len(s), 3):\\n       F3.append(s[i:i + 3])\\n    F3 = ' '.join(F3)\\n    return 'Frame 1: ' + F1 + '\\\\n' + 'Frame 2: ' + F2 + '\\\\n' + 'Frame 3: ' + F3\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\nWe know that some numbers can be split into two primes. ie. `5 = 2 + 3, 10 = 3 + 7`. But some numbers are not. ie. `17, 27, 35`, etc.. \\n\\nGiven a positive integer `n`. Determine whether it can be split into two primes. If yes, return the maximum product of two primes. If not, return `0` instead.\\n\\n# Input\\/Output\\n\\n`[input]` integer `n`\\n\\nA positive integer. \\n\\n`0 ≤ n ≤ 100000`\\n\\n`[output]` an integer\\n\\nThe possible maximum product of two primes. or return `0` if it's impossible split into two primes.\\n\\n# Example\\n\\nFor `n = 1`, the output should be `0`.\\n\\n`1` can not split into two primes\\n\\nFor `n = 4`, the output should be `4`.\\n\\n`4` can split into two primes `2 and 2`. `2 x 2 = 4`\\n\\nFor `n = 20`, the output should be `91`.\\n\\n`20` can split into two primes `7 and 13` or `3 and 17`. The maximum product is `7 x 13 = 91`\",\"targets\":\"def primes_set():\\n    primes, sieve = {2}, [True] * 50000\\n    for i in range(3, 317, 2):\\n        if sieve[i \\/\\/ 2]:\\n            sieve[i * i \\/\\/ 2 :: i] = [False] * ((100000 - i * i - 1) \\/\\/ (2 * i) + 1)\\n    primes.update((2 * i + 1) for i in range(1, 50000) if sieve[i])\\n    return primes\\n\\nprimes = primes_set()\\n\\ndef prime_product(n):\\n    if n % 2 or n == 4:\\n        return (2 * (n - 2)) if (n - 2) in primes else 0\\n    m, s = n \\/\\/ 2, n % 4 == 0\\n    return next(((m + i) * (m - i) for i in range(s, m, 2) if {m + i, m - i} < primes), 0)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLittle Artem found a grasshopper. He brought it to his house and constructed a jumping area for him.\\n\\nThe area looks like a strip of cells 1 × n. Each cell contains the direction for the next jump and the length of that jump. Grasshopper starts in the first cell and follows the instructions written on the cells. Grasshopper stops immediately if it jumps out of the strip. Now Artem wants to find out if this will ever happen.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a single integer n (1 ≤ n ≤ 100 000) — length of the strip. \\n\\nNext line contains a string of length n which consists of characters \\\"<\\\" and \\\">\\\" only, that provide the direction of the jump from the corresponding cell. Next line contains n integers d_{i} (1 ≤ d_{i} ≤ 10^9) — the length of the jump from the i-th cell.\\n\\n\\n-----Output-----\\n\\nPrint \\\"INFINITE\\\" (without quotes) if grasshopper will continue his jumps forever. Otherwise print \\\"FINITE\\\" (without quotes).\\n\\n\\n-----Examples-----\\nInput\\n2\\n><\\n1 2\\n\\nOutput\\nFINITE\\n\\nInput\\n3\\n>><\\n2 1 1\\n\\nOutput\\nINFINITE\\n\\n\\n-----Note-----\\n\\nIn the first sample grasshopper starts from the first cell and jumps to the right on the next cell. When he is in the second cell he needs to jump two cells left so he will jump out of the strip.\\n\\nSecond sample grasshopper path is 1 - 3 - 2 - 3 - 2 - 3 and so on. The path is infinite.\",\"targets\":\"n = int(input())\\ns = input()\\nl = list(map(int, input().split()))\\ncount = 0\\nmas = [False for i in range(n)]\\npos = 0\\nans = 'INFINITE'\\nfor i in range(n):\\n    if mas[pos]:\\n        break\\n    else:\\n        mas[pos] = True\\n    if s[pos] == '<':\\n        if pos - l[pos] < 0:\\n            ans =  'FINITE'\\n        else:\\n            pos -= l[pos]\\n    else:\\n        if pos + l[pos] >= n:\\n            ans = 'FINITE'\\n        else:\\n            pos += l[pos]\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/strong-password-checker\\/:\\nA password is considered strong if below conditions are all met:\\n\\n\\n It has at least 6 characters and at most 20 characters. \\n It must contain at least one lowercase letter, at least one uppercase letter, and at least one digit. \\n It must NOT contain three repeating characters in a row (\\\"...aaa...\\\" is weak, but \\\"...aa...a...\\\" is strong, assuming other conditions are met). \\n\\n\\nWrite a function strongPasswordChecker(s), that takes a string s as input, and return the MINIMUM change required to make s a strong password. If s is already strong, return 0.\\n\\nInsertion, deletion or replace of any one character are all considered as one change.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def strongPasswordChecker(self, s):\\n         \\\"\\\"\\\"\\n         :type s: str\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         def length_requirement(password):\\n             length = len(password)\\n             # positive means addition, negative means deletion\\n             if length < 6:\\n                 return 6 - length\\n             elif length > 20:\\n                 return 20 - length\\n             else:\\n                 return 0\\n \\n \\n         def category_requirement(password):\\n             # input\\n             string = set(password)\\n             lowercase = set('qwertyuiopasdfghjklzxcvbnm')\\n             uppercase = set('QWERTYUIOPASDFGHJKLZXCVBNM')\\n             digit = set('1234567890')\\n             condition = [lowercase, uppercase, digit]\\n             # output positive for addition\\n             missing = 0\\n             for s in condition:\\n                 if not s & string:\\n                     missing += 1\\n             return missing\\n \\n \\n         def repeat_requirement(password):\\n             # store the repeated character and counts its occurrence\\n             count = 1\\n             repeat = None\\n             weak_pair = []\\n             for c in password:\\n                 if c == repeat:\\n                     # the same character\\n                     count += 1\\n                 else:\\n                     # new character\\n                     if count >= 3:\\n                         weak_pair.append([repeat, count])\\n                     count = 1\\n                     repeat = c\\n             # add last pair\\n             if count >= 3:\\n                 weak_pair.append([repeat, count])\\n             # length of 'aaaaaa' divide by 3 returns the time of change\\n             change = 0\\n             one = 0\\n             two = 0\\n             for _, length in weak_pair:\\n                 change += length \\/\\/ 3\\n                 if length % 3 == 0:\\n                     one += 1\\n                 elif length % 3 == 1:\\n                     two += 1\\n             return change, one, two\\n \\n \\n         def...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWrite a function that takes a string as input and reverse only the vowels of a string.\\n\\n\\nExample 1:\\nGiven s = \\\"hello\\\", return \\\"holle\\\".\\n\\n\\n\\nExample 2:\\nGiven s = \\\"leetcode\\\", return \\\"leotcede\\\".\\n\\n\\n\\nNote:\\nThe vowels does not include the letter \\\"y\\\".\",\"targets\":\"class Solution:\\n     def reverseVowels(self, s):\\n         \\\"\\\"\\\"\\n         :type s: str\\n         :rtype: str\\n         \\\"\\\"\\\"\\n         vowels = 'aeiouAEIOU'\\n         s = list(s)\\n         l = len(s)\\n         p1,p2 = 0,l-1\\n         while p1<p2:\\n             if s[p1] in vowels and s[p2] in vowels:\\n                 s[p1],s[p2] = s[p2],s[p1]\\n                 p1+=1\\n                 p2-=1\\n             elif s[p1] not in vowels:\\n                 p1+=1\\n             elif s[p2]  not in vowels:\\n                 p2-=1\\n         return ''.join(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/855\\/B:\\nProfessor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he wants to give Dumbledore exactly x drops of the potion he made. \\n\\nValue of x is calculated as maximum of p·a_{i} + q·a_{j} + r·a_{k} for given p, q, r and array a_1, a_2, ... a_{n} such that 1 ≤ i ≤ j ≤ k ≤ n. Help Snape find the value of x. Do note that the value of x may be negative.\\n\\n\\n-----Input-----\\n\\nFirst line of input contains 4 integers n, p, q, r ( - 10^9 ≤ p, q, r ≤ 10^9, 1 ≤ n ≤ 10^5).\\n\\nNext line of input contains n space separated integers a_1, a_2, ... a_{n} ( - 10^9 ≤ a_{i} ≤ 10^9).\\n\\n\\n-----Output-----\\n\\nOutput a single integer the maximum value of p·a_{i} + q·a_{j} + r·a_{k} that can be obtained provided 1 ≤ i ≤ j ≤ k ≤ n.\\n\\n\\n-----Examples-----\\nInput\\n5 1 2 3\\n1 2 3 4 5\\n\\nOutput\\n30\\n\\nInput\\n5 1 2 -3\\n-1 -2 -3 -4 -5\\n\\nOutput\\n12\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample case, we can take i = j = k = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.\\n\\nIn second sample case, selecting i = j = 1 and k = 5 gives the answer 12.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def get_ans(n, p, q, r, a):\\n    maxpre = [-100000000] * n\\n    minpre = [100000000] * n\\n    maxsuf = [-100000000] * n\\n    minsuf = [100000000] * n\\n\\n    curmax = a[0]\\n    curmin = a[0]\\n\\n    for i in range(n):\\n        if a[i] > curmax:\\n            curmax = a[i]\\n        maxpre[i] = curmax\\n\\n        if a[i] < curmin:\\n            curmin = a[i]\\n        minpre[i] = curmin\\n\\n    curmax = a[n - 1]\\n    curmin = a[n - 1]\\n\\n    for i in range(n - 1, -1, -1):\\n        if a[i] > curmax:\\n            curmax = a[i]\\n        maxsuf[i] = curmax\\n\\n        if a[i] < curmin:\\n            curmin = a[i]\\n        minsuf[i] = curmin\\n\\n    ans = []\\n    for i in range(n):\\n        pmas = maxpre if p > 0 else minpre\\n        rmas = maxsuf if r > 0 else minsuf\\n\\n        ans.append(pmas[i] * p + a[i] * q + rmas[i] * r)\\n\\n    return max(ans)\\n\\nn, p, q, r = tuple(map(int, input().split()))\\na = list(map(int, input().split()))\\nprint(get_ans(n, p, q, r, a))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given $n$ strings $a_1, a_2, \\\\ldots, a_n$: all of them have the same length $m$. The strings consist of lowercase English letters.\\n\\nFind any string $s$ of length $m$ such that each of the given $n$ strings differs from $s$ in at most one position. Formally, for each given string $a_i$, there is no more than one position $j$ such that $a_i[j] \\\\ne s[j]$.\\n\\nNote that the desired string $s$ may be equal to one of the given strings $a_i$, or it may differ from all the given strings.\\n\\nFor example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer $t$ ($1 \\\\le t \\\\le 100$) — the number of test cases. Then $t$ test cases follow.\\n\\nEach test case starts with a line containing two positive integers $n$ ($1 \\\\le n \\\\le 10$) and $m$ ($1 \\\\le m \\\\le 10$) — the number of strings and their length.\\n\\nThen follow $n$ strings $a_i$, one per line. Each of them has length $m$ and consists of lowercase English letters.\\n\\n\\n-----Output-----\\n\\nPrint $t$ answers to the test cases. Each answer (if it exists) is a string of length $m$ consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print \\\"-1\\\" (\\\"minus one\\\", without quotes).\\n\\n\\n-----Example-----\\nInput\\n5\\n2 4\\nabac\\nzbab\\n2 4\\naaaa\\nbbbb\\n3 3\\nbaa\\naaa\\naab\\n2 2\\nab\\nbb\\n3 1\\na\\nb\\nc\\n\\nOutput\\nabab\\n-1\\naaa\\nab\\nz\\n\\n\\n-----Note-----\\n\\nThe first test case was explained in the statement.\\n\\nIn the second test case, the answer does not exist.\",\"targets\":\"t = int(input())\\nfor _ in range(t):\\n\\tn, m = map(int, input().split())\\n\\ta = [input() for _ in range(n)]\\n\\tfound = False\\n\\tfor i in range(m):\\n\\t\\tfor c in range(26):\\n\\t\\t\\tsol = list(a[0])\\n\\t\\t\\tsol[i] = chr(c + ord('a'))\\n\\t\\t\\tsol = \\\"\\\".join(sol)\\n\\t\\t\\tfound = True\\n\\t\\t\\tfor j in range(n):\\n\\t\\t\\t\\td = 0\\n\\t\\t\\t\\tfor k in range(m):\\n\\t\\t\\t\\t\\tif sol[k] != a[j][k]: d += 1\\n\\t\\t\\t\\tif d > 1:\\n\\t\\t\\t\\t\\tfound = False\\n\\t\\t\\t\\t\\tbreak\\n\\t\\t\\tif found: break\\n\\t\\tif found: break\\n\\tif found: print(sol)\\n\\telse: print(-1)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/797\\/C:\\nPetya recieved a gift of a string s with length up to 10^5 characters for his birthday. He took two more empty strings t and u and decided to play a game. This game has two possible moves:  Extract the first character of s and append t with this character.  Extract the last character of t and append u with this character. \\n\\nPetya wants to get strings s and t empty and string u lexicographically minimal.\\n\\nYou should write a program that will help Petya win the game.\\n\\n\\n-----Input-----\\n\\nFirst line contains non-empty string s (1 ≤ |s| ≤ 10^5), consisting of lowercase English letters.\\n\\n\\n-----Output-----\\n\\nPrint resulting string u.\\n\\n\\n-----Examples-----\\nInput\\ncab\\n\\nOutput\\nabc\\n\\nInput\\nacdb\\n\\nOutput\\nabdc\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n    s = list(input())\\n\\n    suffix = []\\n    for x in reversed(s):\\n        if suffix:\\n            suffix.append(min(suffix[-1], x))\\n        else:\\n            suffix.append(x)\\n\\n    suffix = suffix[::-1]\\n\\n    u = []\\n    t = []\\n    i = 0\\n\\n    while True:\\n        m = suffix[i]\\n\\n        while t and t[-1] <= m:\\n            u.append(t[-1])\\n            t.pop()\\n\\n        while s[i] != m:\\n            t.append(s[i])\\n            i += 1\\n\\n        u.append(s[i])\\n\\n        i += 1\\n        if i == len(s):\\n            break\\n\\n    u += t[::-1]\\n\\n    print(''.join(u))\\n\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou've had a baby.\\n\\nWell done. Nice isn't it? Life destroying... but in a good way.\\n\\nPart of your new routine is lying awake at night worrying that you've either lost the baby... or that you have more than 1!\\n\\nGiven a string of words (x), you need to calculate how many babies are in it. To count as a baby you must have all of the letters in baby ('b', 'a', 'b', 'y'). That counts as 1. They do not need to be in order in the string. Upper and lower case letters count.\\n\\nExamples:\\n\\nIf there are no babies in the string - you lost the baby!! Return a different value, as shown below:\\n\\n```if-not:kotlin\\n'none here' = \\\"Where's the baby?!\\\"\\n'' = \\\"Where's the baby?!\\\"\\n```\\n\\n```if:kotlin \\n\\\"none here\\\" = null\\n\\\"\\\" = null\\n```\",\"targets\":\"from collections import Counter\\n\\ndef baby_count(s):\\n    c = Counter(s.lower())\\n    return min(c['a'],c['b']\\/\\/2,c['y']) or \\\"Where's the baby?!\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThis is a harder version of the problem. In this version, $n \\\\le 50\\\\,000$.\\n\\nThere are $n$ distinct points in three-dimensional space numbered from $1$ to $n$. The $i$-th point has coordinates $(x_i, y_i, z_i)$. The number of points $n$ is even.\\n\\nYou'd like to remove all $n$ points using a sequence of $\\\\frac{n}{2}$ snaps. In one snap, you can remove any two points $a$ and $b$ that have not been removed yet and form a perfectly balanced pair. A pair of points $a$ and $b$ is perfectly balanced if no other point $c$ (that has not been removed yet) lies within the axis-aligned minimum bounding box of points $a$ and $b$.\\n\\nFormally, point $c$ lies within the axis-aligned minimum bounding box of points $a$ and $b$ if and only if $\\\\min(x_a, x_b) \\\\le x_c \\\\le \\\\max(x_a, x_b)$, $\\\\min(y_a, y_b) \\\\le y_c \\\\le \\\\max(y_a, y_b)$, and $\\\\min(z_a, z_b) \\\\le z_c \\\\le \\\\max(z_a, z_b)$. Note that the bounding box might be degenerate. \\n\\nFind a way to remove all points in $\\\\frac{n}{2}$ snaps.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($2 \\\\le n \\\\le 50\\\\,000$; $n$ is even), denoting the number of points.\\n\\nEach of the next $n$ lines contains three integers $x_i$, $y_i$, $z_i$ ($-10^8 \\\\le x_i, y_i, z_i \\\\le 10^8$), denoting the coordinates of the $i$-th point.\\n\\nNo two points coincide.\\n\\n\\n-----Output-----\\n\\nOutput $\\\\frac{n}{2}$ pairs of integers $a_i, b_i$ ($1 \\\\le a_i, b_i \\\\le n$), denoting the indices of points removed on snap $i$. Every integer between $1$ and $n$, inclusive, must appear in your output exactly once.\\n\\nWe can show that it is always possible to remove all points. If there are many solutions, output any of them.\\n\\n\\n-----Examples-----\\nInput\\n6\\n3 1 0\\n0 3 0\\n2 2 0\\n1 0 0\\n1 3 0\\n0 1 0\\n\\nOutput\\n3 6\\n5 1\\n2 4\\n\\nInput\\n8\\n0 1 1\\n1 0 1\\n1 1 0\\n1 1 1\\n2 2 2\\n3 2 2\\n2 3 2\\n2 2 3\\n\\nOutput\\n4 5\\n1 6\\n2 7\\n3 8\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, here is what points and their corresponding bounding boxes look like (drawn in two dimensions for simplicity, as all points lie on $z = 0$ plane). Note that order of removing matters: for example,...\",\"targets\":\"n = int(input())\\npoints = []\\n\\nfor i in range(n):\\n    points.append(list(map(int, input().split())))\\n    points[i].append(i+1)\\npoints.sort()\\n\\nrem = []\\n\\ni = 0\\nwhile i < len(points):\\n    if i < len(points)-1 and points[i][:2] == points[i+1][:2]:\\n        print(points[i][3],points[i+1][3])\\n        i+=2\\n    else:\\n        rem.append(points[i])\\n        i+=1\\npoints = list(rem)\\nrem = []\\ni = 0\\nwhile i < len(points):\\n    if i < len(points)-1 and points[i][0] == points[i+1][0]:\\n        print(points[i][3],points[i+1][3])\\n        i+=2\\n    else:\\n        rem.append(points[i])\\n        i+=1\\n#print(rem)\\npoints = list(rem)\\nrem = []\\ni = 0\\nwhile i < len(points)-1:\\n    print(points[i][3], points[i+1][3])\\n    i+=2\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/FLYMODE:\\nYou like tracking airplane flights a lot. Specifically, you maintain history of an airplane’s flight at several instants and record them in your notebook. Today, you have recorded N such records h1, h2, ..., hN, denoting the heights of some airplane at several instants. These records mean that airplane was first flying on height h1, then started changing its height to h2, then from h2 to h3 and so on. The airplanes are usually on cruise control while descending or ascending, so \\nyou can assume that plane will smoothly increase\\/decrease its height from hi to hi + 1 with a constant speed. You can see that during this period, the airplane will cover all possible heights in the range [min(hi, hi+1), max(hi, hi+1)] (both inclusive). It is easy to see that the plane will be at all possible heights in the range exactly a single instant of time during this ascend\\/descend.\\n\\nYou are interested in finding the maximum integer K such that the plane was at some height exactly K times during the flight.\\n\\n-----Input-----\\nThere is a single test case.\\nFirst line of the input contains an integer N denoting the number of records of heights of the plane.\\nSecond line contains N space separated integers denoting h1, h2, ..., hN.\\n\\n-----Output-----\\nOutput a single maximum integer K in one line, such that the plane was at some height exactly K times during the flight.\\n\\n-----Constraints-----\\n- hi ≠ hi+1\\n\\n-----Subtasks-----\\nSubtask #1: (30 points)\\n- 1 ≤ N ≤ 1000\\n- 1 ≤ hi ≤ 1000\\n\\nSubtask #2: (70 points)\\n- 1 ≤ N ≤ 105\\n- 1 ≤ hi ≤ 109\\n\\n-----Example-----\\nInput:\\n5\\n1 2 3 2 3\\n\\nOutput:\\n3\\n\\n-----Explanation-----\\n\\nThe flight can be draw as:\\n\\n3  \\/\\\\\\/\\n2 \\/\\n1\\n\\nThere are infinitely many heights at which the plane was 3 times during the flight, for example 2.5, 2.1. Notice that the plane was only 2 times at height 2. Moreover, there are no height at which the plane was more than 3 times, so the answer is 3.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def f(n):\\n\\n s = list(map(int, input().split()))\\n low = []\\n high = []\\n\\n for i in range(n - 1):\\n  low.append(min(s[i], s[i+1]))\\n  high.append(max(s[i], s[i+1]))\\n low.sort()\\n high.sort()\\n curr = mx = 0\\n i = j = 0\\n n -= 1\\n while i < n and j < n:\\n  if low[i] < high[j]:\\n   i += 1\\n   curr += 1\\n  else:\\n   j += 1\\n   curr -= 1\\n  mx = max(mx, curr)\\n\\n return mx \\n \\nn = int(input())\\nprint(f(n))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/input\\/problem:\\n=====Function Descriptions=====\\ninput()\\nIn Python 2, the expression input() is equivalent to eval(raw _input(prompt)).\\n\\nCode\\n>>> input()  \\n1+2\\n3\\n>>> company = 'HackerRank'\\n>>> website = 'www.hackerrank.com'\\n>>> input()\\n'The company name: '+company+' and website: '+website\\n'The company name: HackerRank and website: www.hackerrank.com'\\n\\n=====Problem Statement=====\\nYou are given a polynomial P of a single indeterminate (or variable), x. You are also given the values of x and k. Your task is to verify if P(x) = k.\\n\\n=====Output Format=====\\nPrint True if P(x) = k. Otherwise, print False.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#!\\/usr\\/bin\\/env python3\\n\\ndef __starting_point():\\n    x, k = map(int, input().strip().split())\\n    string = input().strip()\\n    \\n    if eval(string) == k:\\n        print(True)\\n    else:\\n        print(False)\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAlice and Bob are playing a game. The game involves splitting up game pieces into two teams. There are n pieces, and the i-th piece has a strength p_{i}.\\n\\nThe way to split up game pieces is split into several steps:\\n\\n  First, Alice will split the pieces into two different groups A and B. This can be seen as writing the assignment of teams of a piece in an n character string, where each character is A or B.  Bob will then choose an arbitrary prefix or suffix of the string, and flip each character in that suffix (i.e. change A to B and B to A). He can do this step at most once.  Alice will get all the pieces marked A and Bob will get all the pieces marked B. \\n\\nThe strength of a player is then the sum of strengths of the pieces in the group.\\n\\nGiven Alice's initial split into two teams, help Bob determine an optimal strategy. Return the maximum strength he can achieve.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 ≤ n ≤ 5·10^5) — the number of game pieces.\\n\\nThe second line contains n integers p_{i} (1 ≤ p_{i} ≤ 10^9) — the strength of the i-th piece.\\n\\nThe third line contains n characters A or B — the assignment of teams after the first step (after Alice's step).\\n\\n\\n-----Output-----\\n\\nPrint the only integer a — the maximum strength Bob can achieve.\\n\\n\\n-----Examples-----\\nInput\\n5\\n1 2 3 4 5\\nABABA\\n\\nOutput\\n11\\n\\nInput\\n5\\n1 2 3 4 5\\nAAAAA\\n\\nOutput\\n15\\n\\nInput\\n1\\n1\\nB\\n\\nOutput\\n1\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample Bob should flip the suffix of length one.\\n\\nIn the second sample Bob should flip the prefix or the suffix (here it is the same) of length 5.\\n\\nIn the third sample Bob should do nothing.\",\"targets\":\"n = int(input())\\nP = list(map(int, input().split()))\\ns = input()\\nres = sum(P[i] for i in range(n) if s[i] == 'B')\\nmaxdiff = 0\\nsuma = 0\\nsumb = 0\\nfor i in range(n):\\n    if(s[i] == 'A'):\\n        suma += P[i]\\n    else:sumb += P[i]\\n    if(suma - sumb > maxdiff):\\n        maxdiff = suma - sumb\\n\\nsuma = 0\\nsumb = 0\\nfor i in range(n)[::-1]:\\n    if(s[i] == 'A'):\\n        suma += P[i]\\n    else:sumb += P[i]\\n    if(suma - sumb > maxdiff):\\n        maxdiff = suma - sumb\\n\\nprint(res + maxdiff)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc074\\/tasks\\/arc083_a:\\nSnuke is making sugar water in a beaker.\\nInitially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.\\n - Operation 1: Pour 100A grams of water into the beaker.\\n - Operation 2: Pour 100B grams of water into the beaker.\\n - Operation 3: Put C grams of sugar into the beaker.\\n - Operation 4: Put D grams of sugar into the beaker.\\nIn our experimental environment, E grams of sugar can dissolve into 100 grams of water.\\nSnuke will make sugar water with the highest possible density.\\nThe beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker.\\nFind the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it.\\nIf there is more than one candidate, any of them will be accepted.\\nWe remind you that the sugar water that contains a grams of water and b grams of sugar is \\\\frac{100b}{a + b} percent.\\nAlso, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.\\n\\n-----Constraints-----\\n - 1 \\\\leq A < B \\\\leq 30\\n - 1 \\\\leq C < D \\\\leq 30\\n - 1 \\\\leq E \\\\leq 100\\n - 100A \\\\leq F \\\\leq 3 000\\n - A, B, C, D, E and F are all integers.\\n\\n-----Inputs-----\\nInput is given from Standard Input in the following format:\\nA B C D E F\\n\\n-----Outputs-----\\nPrint two integers separated by a space.\\nThe first integer should be the mass of the desired sugar water, and the second should be the mass of the sugar dissolved in it.\\n\\n-----Sample Input-----\\n1 2 10 20 15 200\\n\\n-----Sample Output-----\\n110 10\\n\\nIn this environment, 15 grams of sugar can dissolve into 100 grams of water, and the beaker can contain at most 200 grams of substances.\\nWe can make 110 grams of sugar water by performing Operation 1 once and Operation 3 once.\\nIt is not possible to make sugar water with higher density.\\nFor example, the following sequences of operations are infeasible:\\n - If we perform Operation 1 once and Operation 4 once, there will be...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"a,b,c,d,e,f=map(int,input().split())\\ng=[-1]*9999\\ng[a*100]=0\\ng[b*100]=0\\nh=[a*100,0]\\np=0\\nfor i in range(1,f+1):\\n    if g[i]==-1:\\n        continue\\n    if (g[i]+c)\\/(i-g[i])<=e*0.01:\\n        g[i+c]=max(g[i]+c,g[i+c])\\n    if (g[i]+d)\\/(i-g[i])<=e*0.01:\\n        g[i+d]=max(g[i]+d,g[i+d])\\n    g[i+a*100]=max(g[i+a*100],g[i])\\n    g[i+b*100]=max(g[i+b*100],g[i])\\n    if g[i]\\/i>p:\\n        p=g[i]\\/i\\n        h=[i,g[i]]\\nprint(*h)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/text-alignment\\/problem:\\n=====Function Descriptions=====\\nIn Python, a string of text can be aligned left, right and center.\\n\\n.ljust(width)\\n\\nThis method returns a left aligned string of length width.\\n\\n>>> width = 20\\n>>> print 'HackerRank'.ljust(width,'-')\\nHackerRank----------  \\n\\n.center(width)\\n\\nThis method returns a centered string of length width.\\n\\n>>> width = 20\\n>>> print 'HackerRank'.center(width,'-')\\n-----HackerRank-----\\n\\n.rjust(width)\\n\\nThis method returns a right aligned string of length width.\\n\\n>>> width = 20\\n>>> print 'HackerRank'.rjust(width,'-')\\n----------HackerRank\\n\\n=====Problem Statement=====\\nYou are given a partial code that is used for generating the HackerRank Logo of variable thickness.\\nYour task is to replace the blank (______) with rjust, ljust or center.\\n\\n=====Input Format=====\\nA single line containing the thickness value for the logo.\\n\\n=====Constraints=====\\nThe thickness must be an odd number.\\n0 < thickness < 50\\n\\n=====Output Format=====\\nOutput the desired logo.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"#Replace all ______ with rjust, ljust or center. \\n\\nthickness = int(input()) #This must be an odd number\\nc = 'H'\\n\\n#Top Cone\\nfor i in range(thickness):\\n    print(((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1)))\\n\\n#Top Pillars\\nfor i in range(thickness+1):\\n    print(((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)))\\n\\n#Middle Belt\\nfor i in range((thickness+1)\\/\\/2):\\n    print(((c*thickness*5).center(thickness*6)))    \\n\\n#Bottom Pillars\\nfor i in range(thickness+1):\\n    print(((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)))    \\n\\n#Bottom Cone\\nfor i in range(thickness):\\n    print((((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef likes all arrays equally. But he likes some arrays more equally than others. In particular, he loves Rainbow Arrays. \\nAn array is Rainbow if it has the following structure:\\n- First a1 elements equal 1. \\n- Next a2 elements equal 2. \\n- Next a3 elements equal 3. \\n- Next a4 elements equal 4. \\n- Next a5 elements equal 5. \\n- Next a6 elements equal 6. \\n- Next a7 elements equal 7. \\n- Next a6 elements equal 6. \\n- Next a5 elements equal 5. \\n- Next a4 elements equal 4. \\n- Next a3 elements equal 3. \\n- Next a2 elements equal 2. \\n- Next a1 elements equal 1. \\n- ai can be any non-zero positive integer.\\n- There are no other elements in array. \\n\\nHelp Chef in finding out if the given array is a Rainbow Array or not. \\n\\n-----Input-----\\n- The first line of the input contains an integer T denoting the number of test cases.\\n- The first line of each test case contains an integer N, denoting the number of elements in the given array. \\n- The second line contains N space-separated integers A1, A2, ..., AN denoting the elements of array. \\n\\n-----Output-----\\n- For each test case, output a line containing \\\"yes\\\" or \\\"no\\\" (without quotes) corresponding to the case if the array is rainbow array or not. \\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 100\\n- 7 ≤ N ≤ 100\\n- 1 ≤ Ai ≤ 10\\n\\n-----Subtasks-----\\n- Subtask 1 (100 points) : Original constraints\\n\\n-----Example-----\\nInput\\n3\\n19\\n1 2 3 4 4 5 6 6 6 7 6 6 6 5 4 4 3 2 1\\n14\\n1 2 3 4 5 6 7 6 5 4 3 2 1 1\\n13\\n1 2 3 4 5 6 8 6 5 4 3 2 1\\n\\nOutput\\nyes\\nno\\nno\\n\\n-----Explanation-----\\nThe first example satisfies all the conditions. \\nThe second example has 1 element of value 1 at the beginning and 2 elements of value 1 at the end. \\nThe third one has no elements with value 7 after elements with value 6.\",\"targets\":\"# cook your dish here\\nt=int(input())\\nfor ts in range (t):\\n n=int(input())\\n l=list(map(int,input().split()))\\n li=[]\\n for i in l:\\n  if i not in li:\\n   li.append(i)\\n li.sort()\\n print('yes' if (li==[1,2,3,4,5,6,7] and l==l[::-1]) else 'no')\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMr Leicester's cheese factory is the pride of the East Midlands, but he's feeling a little blue. It's the time of the year when **the taxman is coming round to take a slice of his cheddar** - and the final thing he has to work out is how much money he's spending on his staff. Poor Mr Leicester can barely sleep he's so stressed. Can you help? \\n\\n- Mr Leicester **employs 4 staff**, who together make **10 wheels of cheese every 6 minutes**.\\n- Worker pay is calculated on **how many wheels of cheese they produce in a day**. \\n- Mr Leicester pays his staff according to the UK living wage, which is currently **£8.75p an hour**. There are **100 pence (p) to the UK pound (£)**. \\n\\nThe input for function payCheese will be provided as an array of five integers, one for each amount of cheese wheels produced each day.\\n\\nWhen the workforce don't work a nice integer number of minutes - much to the chagrin of the company accountant - Mr Leicester very generously **rounds up to the nearest hour** at the end of the week (*not the end of each day*). Which means if the workers make 574 wheels on each day of the week, they're each paid 29 hours for the week (28.699 hours rounded up) and not 30 (6 hours a day rounded up * 5).\\n\\nThe return value should be a string (with the £ included) of the **total £ of staff wages for that week.**\",\"targets\":\"import math\\n\\ndef pay_cheese(arr):\\n    return f'L{round(math.ceil(sum(map(lambda x: x \\/ 100, arr))) * 4 * 8.75)}'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).\\n\\nYou may assume that the intervals were initially sorted according to their start times.\\n\\nExample 1:\\n\\n\\nInput: intervals = [[1,3],[6,9]], newInterval = [2,5]\\nOutput: [[1,5],[6,9]]\\n\\n\\nExample 2:\\n\\n\\nInput: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]\\nOutput: [[1,2],[3,10],[12,16]]\\nExplanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].\",\"targets\":\"# Definition for an interval.\\n # class Interval:\\n #     def __init__(self, s=0, e=0):\\n #         self.start = s\\n #         self.end = e\\n \\n class Solution:\\n     def insert(self, intervals, newInterval):\\n         \\\"\\\"\\\"\\n         :type intervals: List[Interval]\\n         :type newInterval: Interval\\n         :rtype: List[Interval]\\n         \\\"\\\"\\\"\\n         if intervals == []:\\n             return [newInterval]\\n         \\n         index = 0\\n         while index < len(intervals):\\n             if newInterval.start < intervals[index].start:\\n                 break\\n             index += 1\\n         del_index = 0\\n         insert_index = 0\\n         if index == 0:\\n             s = newInterval.start\\n             e = newInterval.end\\n             insert_index = index \\n         else:\\n             if newInterval.start <= intervals[index - 1].end:\\n                 s = intervals[index - 1].start\\n                 e = max(intervals[index - 1].end, newInterval.end)\\n                 insert_index = index - 1\\n                 del_index += 1\\n             else:\\n                 s = newInterval.start\\n                 e = newInterval.end\\n                 insert_index = index\\n             \\n         while index < len(intervals):\\n             if intervals[index].start <= e:\\n                 e = max(e, intervals[index].end)\\n                 del_index += 1\\n                 index += 1\\n             else:\\n                 break\\n         i = 0\\n         while i < del_index:\\n             intervals.pop(insert_index)\\n             i += 1\\n         intervals.insert(insert_index, Interval(s,e))\\n         return intervals\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are three squares, each with side length a placed on the x-axis. The coordinates of centers of these squares are (x1, a\\/2), (x2, a\\/2) and (x3, a\\/2) respectively. All of them are placed with one of their sides resting on the x-axis.\\nYou are allowed to move the centers of each of these squares along the x-axis (either to the left or to the right)  by a distance of at most K. Find the maximum possible area of intersections of all these three squares that you can achieve. That is, the maximum area of the region which is part of all the three squares in the final configuration.\\n\\n-----Input-----\\n- The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.\\n- The first line of each test case contains two space-separated integers a, K denoting side length of the squares, and the maximum distance that you can move the center of any square.\\n- The second line contains three space separated integers x1, x2, x3\\n\\n-----Output-----\\nFor each test case, output a real number corresponding to the maximum area of the intersection of the three squares that you can obtain. Your answer will be considered correct if it has an absolute error of less than or equal to \\t10-2.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 105\\n- 1 ≤ a ≤ 105\\n- 0 ≤ K ≤ 106\\n- -106 ≤ x1, x2, x3 ≤ 106\\n\\n-----Example-----\\nInput\\n3\\n1 0\\n1 2 3\\n1 1\\n1 2 3\\n1 1\\n1 4 6\\n\\nOutput\\n0.000000\\n1.0000\\n0.0\\n\\n-----Explanation-----\\nTestcase 1: The figure below shows the three squares:\\n\\nSince K = 0, they cannot be moved, and since there is no region which belongs to all three squares, the answer is 0.\\nTestcase 2: The starting configuration is the same as above, but now each of the squares can move 1 unit. So we can move the first square 1 unit to the right and the third square one unit to the left, and have all the three squares at x-coordinate = 2. Thus the entire square is part of all three squares, and the answer is 1.\",\"targets\":\"T=int(input())\\nfor j in range(T):\\n  \\n  ak=input()\\n  \\n  ip1=ak.split(\\\" \\\")\\n\\n  #print(ip1)\\n  a=float(ip1[0])\\n  k=float(ip1[1])\\n  x=input()\\n  \\n  ip2=list(map(int,x.split()))\\n  ip2.sort()\\n  x1=float(ip2[0])\\n  x2=float(ip2[1])\\n  x3=float(ip2[2])\\n\\n  X1=x1+a\\/2+k\\n  X3=x3-a\\/2-k\\n  #print(X1,X3)\\n  if(X1>=X3):\\n   \\n   if(x3-2*k-x1<=0):\\n     area=a*a\\n   else:\\n     a1=X1-X3\\n     area=a1*a\\n   \\n  else:\\n   area=0\\n  print(\\\"{0:.2f}\\\".format(float(area)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nSuppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k), where h is the height of the person and k is the number of people in front of this person who have a height greater than or equal to h. Write an algorithm to reconstruct the queue.\\n\\n\\nNote:\\nThe number of people is less than 1,100.\\n\\n\\n\\n\\nExample\\n\\nInput:\\n[[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]]\\n\\nOutput:\\n[[5,0], [7,0], [5,2], [6,1], [4,4], [7,1]]\",\"targets\":\"class Solution:\\n     def reconstructQueue(self, people):\\n         \\\"\\\"\\\"\\n         :type people: List[List[int]]\\n         :rtype: List[List[int]]\\n         \\\"\\\"\\\"\\n         people.sort(key=lambda x: (-x[0], x[1]))\\n         \\n         res = []\\n         for person in people:\\n             res.insert(person[1], person)\\n             \\n         return res\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have N sticks with negligible thickness.\\nThe length of the i-th stick is A_i.\\nSnuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides.\\nFind the maximum possible area of the rectangle.\\n\\n-----Constraints-----\\n - 4 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq A_i \\\\leq 10^9\\n - A_i is an integer.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 A_2 ... A_N\\n\\n-----Output-----\\nPrint the maximum possible area of the rectangle.\\nIf no rectangle can be formed, print 0.\\n\\n-----Sample Input-----\\n6\\n3 1 2 4 2 1\\n\\n-----Sample Output-----\\n2\\n\\n1 \\\\times 2 rectangle can be formed.\",\"targets\":\"from collections import Counter\\nn=int(input())\\na=list(map(int,input().split()))\\n\\nc=Counter(a)\\ncan_make=[i[0] for i in c.items() if i[1]>=2]\\ncan_make_square=[i[0] for i in c.items() if i[1]>=4]\\ncan_make+=can_make_square\\ncan_make.sort()\\n\\nif len(can_make)<2:\\n    print(0)\\nelse:\\n    print(can_make[-1]*can_make[-2])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn these quarantine days, Chef and Chefina are getting bored. So, Chef came up with a game for her. He gets a pack of cards with numbers written on them. Chef then asks her to remove cards from the pack in the following manner: Chefina can choose any 3 cards at a time, having unique values, and remove the smallest and largest of them, and put back the middle one. For example, say Chefina chooses 3 cards that have numbers $x$, $y$, $z$ on them, such that $x <= y <= z$. Then she can throw away cards with number $x$ and $z$, but has to put the card with number $y$ on it back into the pack. Chefina can repeat this process any number of times. As soon as the pack contains cards with unique numbers, the game ends. If Chefina can determine the count of cards that will remain in the end, and tell it to Chef beforehand, she wins the game. Chefina asks for your help to win this game. Given the number written on the cards, help her find the count of cards in the pack when she wins.\\n$Note:$ You need to maximize the array length or the number of unique elements\\n\\n-----Input:-----\\n- The first line of the input consists of a single integer $T$, denoting the number of test cases. Description of $T$ test cases follow.\\n- The first line of each test case consists of a single integer $N$, denoting the number of cards in the pack\\n- The next line consists of $N$ space separated numbers $A1$, $A2$ … $An$. For each valid $i (1 <= i <= N)$, the $i$-th card has the number $Ai$ written on it.\\n\\n-----Output:-----\\n- For each test case, print the count of the cards that remain in the end.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 500$\\n- $1 \\\\leq N \\\\leq 10^6$\\n- $1 \\\\leq Ai \\\\leq N$\\n\\n-----Subtasks-----\\n- 30 points : $1 \\\\leq T \\\\leq 20$; $ 1 \\\\leq N \\\\leq 5*10^5$\\n- 70 points : Original constraints\\n\\n-----Sample Input:-----\\n2\\n5\\n1 2 2 3 5\\n9\\n1 2 2 3 3 5 8 8 9\\n\\n-----Sample Output:-----\\n3\\n5\\n\\n-----EXPLANATION:-----\\nTest case 1:\\nChefina chooses the cards with number: 2, 3, 5, throws away 2 & 5, and puts back 3. So, the pack now contains cards with numbers: 1,...\",\"targets\":\"# cook your dish here\\nimport sys\\ninput=sys.stdin.readline\\nT=int(input())\\nfor i in range (T):\\n N=int(input())\\n A=list(map(int,input().split()))\\n B=[0 for i in range(N+1)]\\n fc=0\\n flag=0\\n for i in A:\\n  if (B[i]!=1):\\n   fc=fc+1\\n   B[i]=B[i]+1\\n  else:\\n   flag=flag+1\\n if (flag%2==0):\\n  print(fc)\\n else:\\n  print(max(fc-1,1))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nManao is trying to open a rather challenging lock. The lock has n buttons on it and to open it, you should press the buttons in a certain order to open the lock. When you push some button, it either stays pressed into the lock (that means that you've guessed correctly and pushed the button that goes next in the sequence), or all pressed buttons return to the initial position. When all buttons are pressed into the lock at once, the lock opens.\\n\\nConsider an example with three buttons. Let's say that the opening sequence is: {2, 3, 1}. If you first press buttons 1 or 3, the buttons unpress immediately. If you first press button 2, it stays pressed. If you press 1 after 2, all buttons unpress. If you press 3 after 2, buttons 3 and 2 stay pressed. As soon as you've got two pressed buttons, you only need to press button 1 to open the lock.\\n\\nManao doesn't know the opening sequence. But he is really smart and he is going to act in the optimal way. Calculate the number of times he's got to push a button in order to open the lock in the worst-case scenario.\\n\\n\\n-----Input-----\\n\\nA single line contains integer n (1 ≤ n ≤ 2000) — the number of buttons the lock has.\\n\\n\\n-----Output-----\\n\\nIn a single line print the number of times Manao has to push a button in the worst-case scenario.\\n\\n\\n-----Examples-----\\nInput\\n2\\n\\nOutput\\n3\\n\\nInput\\n3\\n\\nOutput\\n7\\n\\n\\n\\n-----Note-----\\n\\nConsider the first test sample. Manao can fail his first push and push the wrong button. In this case he will already be able to guess the right one with his second push. And his third push will push the second right button. Thus, in the worst-case scenario he will only need 3 pushes.\",\"targets\":\"n = int(input())\\nprint((n**3+5*n)\\/\\/6)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n\\nWrite a function that accepts `msg` string and returns local tops of string from the highest to the lowest.  \\nThe string's tops are from displaying the string in the below way:\\n\\n```      \\n                                                      3 \\n                              p                     2   4\\n            g               o   q                 1\\n  b       f   h           n       r             z \\na   c   e       i       m          s          y\\n      d           j   l             t       x\\n                    k                 u   w \\n                                        v\\n\\n\\n```\\nThe next top is always 1 character higher than the previous one. \\nFor the above example, the solution for the `abcdefghijklmnopqrstuvwxyz1234` input string is `3pgb`.\\n\\n- When the `msg` string is empty, return an empty string.\\n- The input strings may be very long. Make sure your solution has good performance.\\n\\nCheck the test cases for more samples.\\n\\n# **Note** for C++\\n\\nDo not post an issue in my solution without checking if your returned string doesn't have some invisible characters. You read most probably outside of `msg` string.\",\"targets\":\"def tops(msg):\\n    if not msg: return ''\\n    n, length = 2, len(msg)\\n    counter = 0\\n    s = ''\\n    while counter+n <= length:\\n        counter += n\\n        s += msg[counter-1]\\n        counter += n-1\\n        n += 2\\n    return s[::-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPolycarp plays \\\"Game 23\\\". Initially he has a number $n$ and his goal is to transform it to $m$. In one move, he can multiply $n$ by $2$ or multiply $n$ by $3$. He can perform any number of moves.\\n\\nPrint the number of moves needed to transform $n$ to $m$. Print -1 if it is impossible to do so.\\n\\nIt is easy to prove that any way to transform $n$ to $m$ contains the same number of moves (i.e. number of moves doesn't depend on the way of transformation).\\n\\n\\n-----Input-----\\n\\nThe only line of the input contains two integers $n$ and $m$ ($1 \\\\le n \\\\le m \\\\le 5\\\\cdot10^8$).\\n\\n\\n-----Output-----\\n\\nPrint the number of moves to transform $n$ to $m$, or -1 if there is no solution.\\n\\n\\n-----Examples-----\\nInput\\n120 51840\\n\\nOutput\\n7\\n\\nInput\\n42 42\\n\\nOutput\\n0\\n\\nInput\\n48 72\\n\\nOutput\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, the possible sequence of moves is: $120 \\\\rightarrow 240 \\\\rightarrow 720 \\\\rightarrow 1440 \\\\rightarrow 4320 \\\\rightarrow 12960 \\\\rightarrow 25920 \\\\rightarrow 51840.$ The are $7$ steps in total.\\n\\nIn the second example, no moves are needed. Thus, the answer is $0$.\\n\\nIn the third example, it is impossible to transform $48$ to $72$.\",\"targets\":\"N,M=list(map(int,input().split()))\\nd = M\\/N\\nif not d.is_integer():\\n    print(-1)\\nelse:\\n    d = int(d)\\n    n = 0\\n    while d and d%2==0:\\n        n += 1\\n        d >>= 1\\n    while d and d%3==0:\\n        n += 1\\n        d \\/\\/= 3\\n    if d == 1:\\n        print(n)\\n    else:\\n        print(-1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5cb05eee03c3ff002153d4ef:\\nYour website is divided vertically in sections, and each can be of different size (height).  \\nYou need to establish the section index (starting at `0`) you are at, given the `scrollY` and `sizes` of all sections.  \\nSections start with `0`, so if first section is `200` high, it takes `0-199` \\\"pixels\\\" and second starts at `200`.\\n\\n### Example:\\n\\n`getSectionIdFromScroll( 300, [300,200,400,600,100] )`\\n\\nwill output number `1` as it's the second section.\\n\\n`getSectionIdFromScroll( 1600, [300,200,400,600,100] )`\\n\\nwill output number `-1` as it's past last section.\\n\\nGiven the `scrollY` integer (always non-negative) and an array of non-negative integers (with at least one element), calculate the index (starting at `0`) or `-1` if `scrollY` falls beyond last section (indication of an error).\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from itertools import accumulate\\n\\ndef get_section_id(scroll, sizes):\\n    return next((i for i,s in enumerate(accumulate(sizes)) if s > scroll), -1)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIntegral numbers can be even or odd.\\n\\nEven numbers satisfy `n = 2m` ( with `m` also integral ) and we will ( completely arbitrarily ) think of odd numbers as `n = 2m + 1`.  \\nNow, some odd numbers can be more odd than others: when for some `n`, `m` is more odd than for another's. Recursively. :]  \\nEven numbers are just not odd.\\n\\n# Task\\n\\nGiven a finite list of integral ( not necessarily non-negative ) numbers, determine the number that is _odder than the rest_.  \\nIf there is no single such number, no number is odder than the rest; return `Nothing`, `null` or a similar empty value.\\n\\n# Examples\\n\\n```python\\noddest([1,2]) => 1\\noddest([1,3]) => 3\\noddest([1,5]) => None\\n```\\n\\n# Hint\\n\\nDo you _really_ want one? Point or tap here.\",\"targets\":\"def oddest(xs):\\n    os = list(map(oddness, xs))\\n    max_o = max(os, default=None)\\n    return xs[os.index(max_o)] if os.count(max_o) == 1 else None\\n\\ndef oddness(x):\\n    return float('inf') if x == -1 else ~x & -~x\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/57cebe1dc6fdc20c57000ac9:\\nSimple, given a string of words, return the length of the shortest word(s).\\n\\nString will never be empty and you do not need to account for different data types.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def find_short(s):\\n    return min( [len(i) for i in s.split()] )\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1096\\/F:\\nA permutation of size $n$ is an array of size $n$ such that each integer from $1$ to $n$ occurs exactly once in this array. An inversion in a permutation $p$ is a pair of indices $(i, j)$ such that $i > j$ and $a_i < a_j$. For example, a permutation $[4, 1, 3, 2]$ contains $4$ inversions: $(2, 1)$, $(3, 1)$, $(4, 1)$, $(4, 3)$.\\n\\nYou are given a permutation $p$ of size $n$. However, the numbers on some positions are replaced by $-1$. Let the valid permutation be such a replacement of $-1$ in this sequence back to numbers from $1$ to $n$ in such a way that the resulting sequence is a permutation of size $n$.\\n\\nThe given sequence was turned into a valid permutation randomly with the equal probability of getting each valid permutation.\\n\\nCalculate the expected total number of inversions in the resulting valid permutation.\\n\\nIt can be shown that it is in the form of $\\\\frac{P}{Q}$ where $P$ and $Q$ are non-negative integers and $Q \\\\ne 0$. Report the value of $P \\\\cdot Q^{-1} \\\\pmod {998244353}$.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the length of the sequence.\\n\\nThe second line contains $n$ integers $p_1, p_2, \\\\dots, p_n$ ($-1 \\\\le p_i \\\\le n$, $p_i \\\\ne 0$) — the initial sequence.\\n\\nIt is guaranteed that all elements not equal to $-1$ are pairwise distinct.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the expected total number of inversions in the resulting valid permutation.\\n\\nIt can be shown that it is in the form of $\\\\frac{P}{Q}$ where $P$ and $Q$ are non-negative integers and $Q \\\\ne 0$. Report the value of $P \\\\cdot Q^{-1} \\\\pmod {998244353}$.\\n\\n\\n-----Examples-----\\nInput\\n3\\n3 -1 -1\\n\\nOutput\\n499122179\\n\\nInput\\n2\\n1 2\\n\\nOutput\\n0\\n\\nInput\\n2\\n-1 -1\\n\\nOutput\\n499122177\\n\\n\\n\\n-----Note-----\\n\\nIn the first example two resulting valid permutations are possible:\\n\\n  $[3, 1, 2]$ — $2$ inversions;  $[3, 2, 1]$ — $3$ inversions. \\n\\nThe expected value is $\\\\frac{2 \\\\cdot 1 + 3 \\\\cdot 1}{2} = 2.5$.\\n\\nIn the second example no $-1$ are present, thus the only valid permutation is possible — the given one....\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\n\\nL = [int(x) for x in input().split()]\\nD = {}\\nJ = []\\nS = []\\nT = [0]*(n+1)\\nfor i in range(n):\\n    if L[i] > 0:\\n        D[L[i]] = i\\n        J.append(L[i])\\n        T[i+1] = T[i]\\n    else:\\n        T[i+1] = T[i]+1\\n        \\ndef I(J):\\n    if len(J) <= 1:\\n        return J, 0\\n    else:\\n        a = J[:len(J)\\/\\/2]\\n        b = J[len(J)\\/\\/2:]\\n        a, ai = I(a)\\n        b, bi = I(b)\\n        c = []\\n        i = 0\\n        j = 0\\n        inversions = ai + bi\\n    while i < len(a) and j < len(b):\\n        if a[i] <= b[j]:\\n            c.append(a[i])\\n            i += 1\\n        else:\\n            c.append(b[j])\\n            j += 1\\n            inversions += (len(a)-i)\\n    c += a[i:]\\n    c += b[j:]\\n    return c, inversions\\n\\nfor i in range(1,n+1):\\n    if not i in D:\\n        S.append(i)\\n\\ntotal = len(S)\\nnum = 1\\ndenom = 1\\nif total > 0:\\n    themostimportantsum = 0\\n    for i in J:\\n        low = 0\\n        high = total-1\\n        while high-low > 1:\\n            guess = (high+low)\\/\\/2\\n            if S[guess] > i:\\n                high = guess\\n            else:\\n                low = guess\\n        if S[low] > i:\\n            smaller = low\\n        elif S[high] > i:\\n            smaller = high\\n        else:\\n            smaller = high+1\\n        #D[i] is the position of i in the list\\n        #T[D[i]] is how many -1s there are to the left of it\\n        themostimportantsum += T[D[i]]*(total-smaller)+(total-T[D[i]])*(smaller)\\n        num = themostimportantsum+total\\n        denom = total\\n\\nnum =(denom*(((total)*(total-1))\\/\\/2)+2*num)%998244353\\ndenom *= 2\\nif num == denom:\\n    if I(J)[1] == 0:\\n        print(0)\\n    else:\\n        print(I(J)[1]%998244353)\\nelse:       \\n    num += denom*I(J)[1]\\n    print(((num-denom)*pow(denom%998244353,998244351,998244353))%998244353)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have N integers A_1, A_2, ..., A_N.\\nThere are \\\\frac{N(N-1)}{2} ways to choose two of them and form a pair. If we compute the product of each of those pairs and sort the results in ascending order, what will be the K-th number in that list?\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 2 \\\\leq N \\\\leq 2 \\\\times 10^5\\n - 1 \\\\leq K \\\\leq \\\\frac{N(N-1)}{2}\\n - -10^9 \\\\leq A_i \\\\leq 10^9\\\\ (1 \\\\leq i \\\\leq N)\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN K\\nA_1 A_2 \\\\dots A_N\\n\\n-----Output-----\\nPrint the answer.\\n\\n-----Sample Input-----\\n4 3\\n3 3 -4 -2\\n\\n-----Sample Output-----\\n-6\\n\\nThere are six ways to form a pair. The products of those pairs are 9, -12, -6, -12, -6, 8.\\nSorting those numbers in ascending order, we have -12, -12, -6, -6, 8, 9. The third number in this list is -6.\",\"targets\":\"import sys\\nreadline=sys.stdin.readline\\n\\nimport numpy as np\\n\\nN,K=list(map(int,readline().split()))\\nA=np.array(readline().split(),dtype=int)\\n\\nnega_list=A[A<0]\\nposi_list=A[A>0]\\nzero_num=A[A==0].size\\n\\n# print(nega_list)\\n# print(posi_list)\\n# print(zero_num)\\n\\nnega_list=np.sort(nega_list)\\nposi_list=np.sort(posi_list)\\n\\nnega_cnt=nega_list.size * posi_list.size\\nposi_cnt=((posi_list.size * posi_list.size-1) \\/\\/ 2) + ((nega_list.size * nega_list.size-1) \\/\\/ 2)\\n\\nzero_cnt=(zero_num * (zero_num-1)) \\/\\/ 2 + zero_num * (nega_list.size + posi_list.size)\\n\\n# print(nega_cnt)\\n# print(posi_cnt)\\n# print(zero_cnt)\\n\\n\\n# Kがどこに属するかを判断\\nif K <= nega_cnt:\\n  # 負の数が答え\\n  # かけてX以下になる組み合わせをK個以上作れればOK\\n  \\n  def isOkNega(x):\\n    return np.searchsorted(nega_list,x\\/\\/posi_list,side=\\\"right\\\").sum() >= K\\n    \\n  ok=0\\n  ng=-10**18-1\\n  while (ok-ng)>1:\\n    mid=(ok+ng)\\/\\/2\\n    if isOkNega(mid):\\n      ok=mid\\n    else:\\n      ng=mid\\n  print(ok)\\n  \\nelif K <= nega_cnt+zero_cnt:\\n  # 0が答え\\n  print((0))\\n  \\nelse:  \\n  # 正の数が答え\\n  K-=(nega_cnt+zero_cnt)\\n  # 正のグループ内の積、負のグループ内の積、それぞれを合わせてX以下の数をK個以上作れる\\n  \\n  # 負の数リストは、掛け合わせた絶対値が小さいものを求める必要があるため、正のリストに変更\\n  nega_list = np.flipud(nega_list * (-1))\\n  \\n  # 自分自身との積は除外する必要があるため、自分同士の積リストを作成\\n  self_nega=nega_list * nega_list\\n  self_posi=posi_list * posi_list\\n  \\n  def isOkPosi(x):\\n    # print(\\\"x\\\",x)\\n    # 重複を考えずに、負の数同士の積で条件を満たすものをカウント\\n    nega_all = np.searchsorted(nega_list, x \\/\\/ nega_list, side = \\\"right\\\")\\n    # print(nega_all)\\n    # print(\\\"self_nega[self_nega <= x]\\\",self_nega[self_nega <= x])\\n    # 自分自身を掛け合わせたもので、条件を満たすものの個数はカウントから除外する必要がある\\n    nega_cnt = nega_all.sum() - self_nega[self_nega <= x].size\\n    # print(nega_cnt)\\n    \\n    # 同じペアを二回数えているため1\\/2する\\n    nega_cnt \\/\\/= 2\\n    \\n    # 正の数リストで同じことをする\\n    posi_all = np.searchsorted(posi_list, x \\/\\/ posi_list, side = \\\"right\\\")\\n    # print(posi_all)\\n    # print(\\\"self_posi[self_posi <= x]\\\",self_posi[self_posi <= x])\\n    posi_cnt = posi_all.sum() - self_posi[self_posi <= x].size\\n    # print(posi_cnt)\\n    posi_cnt \\/\\/= 2\\n        \\n    return nega_cnt + posi_cnt >= K\\n  \\n  ok=10**18+1\\n  ng=0\\n  while...\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nPolycarp decided to relax on his weekend and visited to the performance of famous ropewalkers: Agafon, Boniface and Konrad.\\n\\nThe rope is straight and infinite in both directions. At the beginning of the performance, Agafon, Boniface and Konrad are located in positions $a$, $b$ and $c$ respectively. At the end of the performance, the distance between each pair of ropewalkers was at least $d$.\\n\\nRopewalkers can walk on the rope. In one second, only one ropewalker can change his position. Every ropewalker can change his position exactly by $1$ (i. e. shift by $1$ to the left or right direction on the rope). Agafon, Boniface and Konrad can not move at the same time (Only one of them can move at each moment). Ropewalkers can be at the same positions at the same time and can \\\"walk past each other\\\".\\n\\nYou should find the minimum duration (in seconds) of the performance. In other words, find the minimum number of seconds needed so that the distance between each pair of ropewalkers can be greater or equal to $d$.\\n\\nRopewalkers can walk to negative coordinates, due to the rope is infinite to both sides.\\n\\n\\n-----Input-----\\n\\nThe only line of the input contains four integers $a$, $b$, $c$, $d$ ($1 \\\\le a, b, c, d \\\\le 10^9$). It is possible that any two (or all three) ropewalkers are in the same position at the beginning of the performance.\\n\\n\\n-----Output-----\\n\\nOutput one integer — the minimum duration (in seconds) of the performance.\\n\\n\\n-----Examples-----\\nInput\\n5 2 6 3\\n\\nOutput\\n2\\n\\nInput\\n3 1 5 6\\n\\nOutput\\n8\\n\\nInput\\n8 3 3 2\\n\\nOutput\\n2\\n\\nInput\\n2 3 10 4\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first example: in the first two seconds Konrad moves for 2 positions to the right (to the position $8$), while Agafon and Boniface stay at their positions. Thus, the distance between Agafon and Boniface will be $|5 - 2| = 3$, the distance between Boniface and Konrad will be $|2 - 8| = 6$ and the distance between Agafon and Konrad will be $|5 - 8| = 3$. Therefore, all three pairwise distances will be at least $d=3$, so the performance could be finished...\",\"targets\":\"a, b, c, d = list(map(int, input().split()))\\ns = [a, b, c]\\ns.sort()\\na, b, c = s\\nprint(max(0, a - b + d) + max(0, b - c + d))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nReverse bits of a given 32 bits unsigned integer.\\n\\nNote:\\n\\nNote that in some languages such as Java, there is no unsigned integer type. In this case, both input and output will be given as a signed integer type. They should not affect your implementation, as the integer's internal binary representation is the same, whether it is signed or unsigned.\\nIn Java, the compiler represents the signed integers using 2's complement notation. Therefore, in Example 2 above, the input represents the signed integer -3 and the output represents the signed integer -1073741825.\\nFollow up:\\n\\nIf this function is called many times, how would you optimize it?\\n\\nExample 1:\\n\\nInput: n = 00000010100101000001111010011100\\nOutput:    964176192 (00111001011110000010100101000000)\\nExplanation: The input binary string 00000010100101000001111010011100 represents the unsigned integer 43261596, so return 964176192 which its binary representation is 00111001011110000010100101000000.\\n\\nExample 2:\\n\\nInput: n = 11111111111111111111111111111101\\nOutput:   3221225471 (10111111111111111111111111111111)\\nExplanation: The input binary string 11111111111111111111111111111101 represents the unsigned integer 4294967293, so return 3221225471 which its binary representation is 10111111111111111111111111111111. \\n\\nConstraints:\\n\\nThe input must be a binary string of length 32\",\"targets\":\"class Solution:\\n     def reverseBits(self, n: int) -> int:\\n        result = 0\\n        power = 31\\n        while n:\\n            result += (n & 1) << power\\n            n = n >> 1\\n            power -= 1\\n            \\n        return result\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a1ee4dfffe75f0fcb000145:\\nFor this game of `BINGO`, you will receive a single array of 10 numbers from 1 to 26 as an input. Duplicate numbers within the array are possible.\\n\\nEach number corresponds to their alphabetical order letter (e.g. 1 = A. 2 = B, etc). Write a function where you will win the game if your numbers can spell `\\\"BINGO\\\"`. They do not need to be in the right order in the input array). Otherwise you will lose. Your outputs should be `\\\"WIN\\\"` or `\\\"LOSE\\\"` respectively.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def bingo(a): \\n    return \\\"WIN\\\" if all([x in a for x in [2, 7, 9, 14, 15]]) else \\\"LOSE\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given four integers $a$, $b$, $x$ and $y$. Initially, $a \\\\ge x$ and $b \\\\ge y$. You can do the following operation no more than $n$ times:\\n\\n  Choose either $a$ or $b$ and decrease it by one. However, as a result of this operation, value of $a$ cannot become less than $x$, and value of $b$ cannot become less than $y$. \\n\\nYour task is to find the minimum possible product of $a$ and $b$ ($a \\\\cdot b$) you can achieve by applying the given operation no more than $n$ times.\\n\\nYou have to answer $t$ independent test cases.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 2 \\\\cdot 10^4$) — the number of test cases. Then $t$ test cases follow.\\n\\nThe only line of the test case contains five integers $a$, $b$, $x$, $y$ and $n$ ($1 \\\\le a, b, x, y, n \\\\le 10^9$). Additional constraint on the input: $a \\\\ge x$ and $b \\\\ge y$ always holds.\\n\\n\\n-----Output-----\\n\\nFor each test case, print one integer: the minimum possible product of $a$ and $b$ ($a \\\\cdot b$) you can achieve by applying the given operation no more than $n$ times.\\n\\n\\n-----Example-----\\nInput\\n7\\n10 10 8 5 3\\n12 8 8 7 2\\n12343 43 4543 39 123212\\n1000000000 1000000000 1 1 1\\n1000000000 1000000000 1 1 1000000000\\n10 11 2 1 5\\n10 11 9 1 10\\n\\nOutput\\n70\\n77\\n177177\\n999999999000000000\\n999999999\\n55\\n10\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case of the example, you need to decrease $b$ three times and obtain $10 \\\\cdot 7 = 70$.\\n\\nIn the second test case of the example, you need to decrease $a$ one time, $b$ one time and obtain $11 \\\\cdot 7 = 77$.\\n\\nIn the sixth test case of the example, you need to decrease $a$ five times and obtain $5 \\\\cdot 11 = 55$.\\n\\nIn the seventh test case of the example, you need to decrease $b$ ten times and obtain $10 \\\\cdot 1 = 10$.\",\"targets\":\"def find(a,b,x,y,n):\\n    req = a-x\\n    min_val = min(req,n)\\n    a -= min_val\\n    n -= min_val\\n    b -= n\\n\\n    return a*b\\n\\ndef solve(a,b,x,y,n,ans):\\n    req1 = a-x\\n    req2 = b-y\\n    if req1+req2 <= n:\\n        a = x\\n        b = y\\n        ans.append(str(a*b))\\n    else:\\n        min_val = find(a,b,x,y,n)\\n        min_val = min(min_val,find(b,a,y,x,n))\\n        ans.append(str(min_val))\\n\\ndef main():\\n    t = int(input())\\n    ans = []\\n    for i in range(t):\\n        a,b,x,y,n = list(map(int,input().split()))\\n        solve(a,b,x,y,n,ans)\\n\\n    print('\\\\n'.join(ans))\\n    \\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOkabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an n by n square grid of integers. A good lab is defined as a lab in which every number not equal to 1 can be expressed as the sum of a number in the same row and a number in the same column. In other words, for every x, y such that 1 ≤ x, y ≤ n and a_{x}, y ≠ 1, there should exist two indices s and t so that a_{x}, y = a_{x}, s + a_{t}, y, where a_{i}, j denotes the integer in i-th row and j-th column.\\n\\nHelp Okabe determine whether a given lab is good!\\n\\n\\n-----Input-----\\n\\nThe first line of input contains the integer n (1 ≤ n ≤ 50) — the size of the lab. \\n\\nThe next n lines contain n space-separated integers denoting a row of the grid. The j-th integer in the i-th row is a_{i}, j (1 ≤ a_{i}, j ≤ 10^5).\\n\\n\\n-----Output-----\\n\\nPrint \\\"Yes\\\" if the given lab is good and \\\"No\\\" otherwise.\\n\\nYou can output each letter in upper or lower case.\\n\\n\\n-----Examples-----\\nInput\\n3\\n1 1 2\\n2 3 1\\n6 4 1\\n\\nOutput\\nYes\\n\\nInput\\n3\\n1 5 2\\n1 1 1\\n1 2 3\\n\\nOutput\\nNo\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample test, the 6 in the bottom left corner is valid because it is the sum of the 2 above it and the 4 on the right. The same holds for every number not equal to 1 in this table, so the answer is \\\"Yes\\\".\\n\\nIn the second sample test, the 5 cannot be formed as the sum of an integer in the same row and an integer in the same column. Thus the answer is \\\"No\\\".\",\"targets\":\"a = [list(map(int, input().split())) for i in range(int(input()))]\\nn = len(a)\\nfor i in range(n):\\n    for j in range(n):\\n        if a[i][j] != 1:\\n            found = False\\n            for i2 in range(n):\\n                for j2 in range(n):\\n                    if a[i][j] == a[i][j2] + a[i2][j]:\\n                        found = True\\n            if not found:\\n                print('No\\\\n')\\n                return\\nprint('Yes')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/462\\/A:\\nToastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?\\n\\nGiven a n × n checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells of the board are adjacent if they share a side.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer n (1 ≤ n ≤ 100). Then n lines follow containing the description of the checkerboard. Each of them contains n characters (either 'x' or 'o') without spaces.\\n\\n\\n-----Output-----\\n\\nPrint \\\"YES\\\" or \\\"NO\\\" (without the quotes) depending on the answer to the problem.\\n\\n\\n-----Examples-----\\nInput\\n3\\nxxo\\nxox\\noxx\\n\\nOutput\\nYES\\n\\nInput\\n4\\nxxxo\\nxoxo\\noxox\\nxxxx\\n\\nOutput\\nNO\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import collections\\nimport itertools\\n\\n\\nn = int(input())\\nm = collections.defaultdict(lambda: \\\"x\\\")\\nfor y in range(n):\\n\\n    for x, ch in enumerate(input()):\\n\\n        m[x, y] = ch\\n\\ndeltas = ((-1, 0), (0, -1), (1, 0), (0, 1))\\nfor p in itertools.product(list(range(n)), repeat=2):\\n\\n    cps = [tuple(map(sum, list(zip(p, dp)))) for dp in deltas]\\n    if len(tuple([cp for cp in cps if m[cp] == \\\"o\\\"])) % 2:\\n\\n        print(\\\"NO\\\")\\n        return\\n\\nprint(\\\"YES\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n3R2 - Standby for Action\\n\\nOur dear Cafe's owner, JOE Miller, will soon take part in a new game TV-show \\\"1 vs. $n$\\\"!\\n\\nThe game goes in rounds, where in each round the host asks JOE and his opponents a common question. All participants failing to answer are eliminated. The show ends when only JOE remains (we assume that JOE never answers a question wrong!).\\n\\nFor each question JOE answers, if there are $s$ ($s > 0$) opponents remaining and $t$ ($0 \\\\le t \\\\le s$) of them make a mistake on it, JOE receives $\\\\displaystyle\\\\frac{t}{s}$ dollars, and consequently there will be $s - t$ opponents left for the next question.\\n\\nJOE wonders what is the maximum possible reward he can receive in the best possible scenario. Yet he has little time before show starts, so can you help him answering it instead?\\n\\n\\n-----Input-----\\n\\nThe first and single line contains a single integer $n$ ($1 \\\\le n \\\\le 10^5$), denoting the number of JOE's opponents in the show.\\n\\n\\n-----Output-----\\n\\nPrint a number denoting the maximum prize (in dollars) JOE could have.\\n\\nYour answer will be considered correct if it's absolute or relative error won't exceed $10^{-4}$. In other words, if your answer is $a$ and the jury answer is $b$, then it must hold that $\\\\frac{|a - b|}{max(1, b)} \\\\le 10^{-4}$.\\n\\n\\n-----Examples-----\\nInput\\n1\\n\\nOutput\\n1.000000000000\\n\\nInput\\n2\\n\\nOutput\\n1.500000000000\\n\\n\\n\\n-----Note-----\\n\\nIn the second example, the best scenario would be: one contestant fails at the first question, the other fails at the next one. The total reward will be $\\\\displaystyle \\\\frac{1}{2} + \\\\frac{1}{1} = 1.5$ dollars.\",\"targets\":\"n = int(input())\\n\\ns = 0\\n\\nfor i in range(1, n + 1):\\n\\ts += 1\\/i\\n\\nprint(s)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc163\\/tasks\\/abc163_c:\\nA company has N members, who are assigned ID numbers 1, ..., N.\\nEvery member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.\\nWhen a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.\\nYou are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 2 \\\\times 10^5\\n - 1 \\\\leq A_i < i\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_2 ... A_N\\n\\n-----Output-----\\nFor each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.\\n\\n-----Sample Input-----\\n5\\n1 1 2 2\\n\\n-----Sample Output-----\\n2\\n2\\n0\\n0\\n0\\n\\nThe member numbered 1 has two immediate subordinates: the members numbered 2 and 3.\\nThe member numbered 2 has two immediate subordinates: the members numbered 4 and 5.\\nThe members numbered 3, 4, and 5 do not have immediate subordinates.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nfrom collections import deque, defaultdict, Counter\\nfrom itertools import accumulate, product, permutations, combinations\\nfrom operator import itemgetter\\nfrom bisect import bisect_left, bisect_right\\nfrom heapq import heappop, heappush\\nfrom math import ceil, floor, sqrt, gcd, inf\\nfrom copy import deepcopy\\nimport numpy as np\\nimport scipy as sp\\n\\nINF = inf\\nMOD = 1000000007\\n\\nn = int(input())\\nA = [int(i) for i in input().split()]\\n\\ntmp = [[] for i in range(n + 1)]\\nres = 0\\n\\nfor i in range(1, n):\\n    tmp[A[i - 1]].append(i + 1)\\nres = \\\"\\\\n\\\".join([str(len(r)) for r in tmp[1:]])\\n\\nprint(res)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nEverybody knows that the $m$-coder Tournament will happen soon. $m$ schools participate in the tournament, and only one student from each school participates.\\n\\nThere are a total of $n$ students in those schools. Before the tournament, all students put their names and the names of their schools into the Technogoblet of Fire. After that, Technogoblet selects the strongest student from each school to participate. \\n\\nArkady is a hacker who wants to have $k$ Chosen Ones selected by the Technogoblet. Unfortunately, not all of them are the strongest in their schools, but Arkady can make up some new school names and replace some names from Technogoblet with those. You can't use each made-up name more than once. In that case, Technogoblet would select the strongest student in those made-up schools too.\\n\\nYou know the power of each student and schools they study in. Calculate the minimal number of schools Arkady has to make up so that $k$ Chosen Ones would be selected by the Technogoblet.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers $n$, $m$ and $k$ ($1 \\\\le n \\\\le 100$, $1 \\\\le m, k \\\\le n$) — the total number of students, the number of schools and the number of the Chosen Ones.\\n\\nThe second line contains $n$ different integers $p_1, p_2, \\\\ldots, p_n$ ($1 \\\\le p_i \\\\le n$), where $p_i$ denotes the power of $i$-th student. The bigger the power, the stronger the student.\\n\\nThe third line contains $n$ integers $s_1, s_2, \\\\ldots, s_n$ ($1 \\\\le s_i \\\\le m$), where $s_i$ denotes the school the $i$-th student goes to. At least one student studies in each of the schools. \\n\\nThe fourth line contains $k$ different integers $c_1, c_2, \\\\ldots, c_k$ ($1 \\\\le c_i \\\\le n$)  — the id's of the Chosen Ones.\\n\\n\\n-----Output-----\\n\\nOutput a single integer  — the minimal number of schools to be made up by Arkady so that $k$ Chosen Ones would be selected by the Technogoblet.\\n\\n\\n-----Examples-----\\nInput\\n7 3 1\\n1 5 3 4 6 7 2\\n1 3 1 2 1 2 3\\n3\\n\\nOutput\\n1\\n\\nInput\\n8 4 4\\n1 2 3 4 5 6 7 8\\n4 3 2 1 4 3 2 1\\n3 4 5 6\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nIn the first...\",\"targets\":\"n, m, k = list(map(int, input().split()))\\npower = list(map(int, input().split()))\\nsch = list(map(int, input().split()))\\nchosen = list(map(int, input().split()))\\nans = 0\\nd = dict()\\nfor i in range(n + 1):\\n    d[i] = []\\n    \\nfor i in range(n):\\n    d[sch[i]].append((power[i], i + 1))\\n\\nfor i in range(n + 1):\\n    d[i] = sorted(d[i])\\n\\nfor i in range(k):\\n    if (d[sch[chosen[i] - 1]][-1][1] != chosen[i]):\\n        ans += 1\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58162692c2a518f03a000189:\\nChingel is practicing for a rowing competition to be held on this saturday. He is trying his best to win this tournament for which he needs to figure out how much time it takes to cover a certain distance. \\n\\n**Input**\\n\\nYou will be provided with the total distance of the journey, speed of the boat and whether he is going downstream or upstream. The speed of the stream and direction of rowing will be given as a string. Check example test cases!\\n\\n**Output**\\n\\nThe output returned should be the time taken to cover the distance. If the result has decimal places, round them to 2 fixed positions.\\n\\n`Show some love ;) Rank and Upvote!`\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"time=lambda d,s,S:round(d\\/(s+(-1)**(S[0]>'D')*int(S.split()[1])),2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nCheck if given numbers are prime numbers. \\nIf number N is prime ```return \\\"Probable Prime\\\"``` else ``` return \\\"Composite\\\"```. \\nHINT: Upper bount is really big so you should use an efficient algorithm.\\n\\nInput\\n  1 < N ≤ 10^(100)\\n\\nExample\\n  prime_or_composite(2)  # should return Probable Prime\\n  prime_or_composite(200)  # should return Composite\",\"targets\":\"def prime_or_composite(n):\\n    if n < 4: return 'Probable Prime'\\n    if n % 2 == 0: return 'Composite'\\n    d, r = n - 1, 0\\n    while d % 2 == 0:\\n        d, r = d \\/\\/ 2, r + 1\\n    for a in [2, 31]:\\n        x = pow(a, d, n)\\n        if x in (1, n - 1):\\n            continue\\n        for _ in range(r-1):\\n            x = pow(x, 2, n)\\n            if x == 1: return 'Composite'\\n            if x == n-1: break\\n        else: return 'Composite'\\n    return 'Probable Prime'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/898\\/A:\\nVasya has a non-negative integer n. He wants to round it to nearest integer, which ends up with 0. If n already ends up with 0, Vasya considers it already rounded.\\n\\nFor example, if n = 4722 answer is 4720. If n = 5 Vasya can round it to 0 or to 10. Both ways are correct.\\n\\nFor given n find out to which integer will Vasya round it.\\n\\n\\n-----Input-----\\n\\nThe first line contains single integer n (0 ≤ n ≤ 10^9) — number that Vasya has.\\n\\n\\n-----Output-----\\n\\nPrint result of rounding n. Pay attention that in some cases answer isn't unique. In that case print any correct answer.\\n\\n\\n-----Examples-----\\nInput\\n5\\n\\nOutput\\n0\\n\\nInput\\n113\\n\\nOutput\\n110\\n\\nInput\\n1000000000\\n\\nOutput\\n1000000000\\n\\nInput\\n5432359\\n\\nOutput\\n5432360\\n\\n\\n\\n-----Note-----\\n\\nIn the first example n = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\nimport sys\\nimport getpass\\nimport bisect\\n\\n\\ndef ria():\\n    return [int(i) for i in input().split()]\\n\\n\\nfiles = False\\n\\nif getpass.getuser().lower() == 'frohe' and files:\\n    sys.stdin = open('test.in')\\n    # sys.stdout = open('test.out', 'w')\\n\\nn=ria()[0]\\nprint(int(round(n\\/10)*10))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/binary-tree-zigzag-level-order-traversal\\/:\\nGiven a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).\\n\\n\\nFor example:\\nGiven binary tree [3,9,20,null,null,15,7],\\n\\n    3\\n   \\/ \\\\\\n  9  20\\n    \\/  \\\\\\n   15   7\\n\\n\\n\\nreturn its zigzag level order traversal as:\\n\\n[\\n  [3],\\n  [20,9],\\n  [15,7]\\n]\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# Definition for a binary tree node.\\n # class TreeNode:\\n #     def __init__(self, x):\\n #         self.val = x\\n #         self.left = None\\n #         self.right = None\\n \\n class Solution:\\n     def zigzagLevelOrder(self, root):\\n         \\\"\\\"\\\"\\n         :type root: TreeNode\\n         :rtype: List[List[int]]\\n         \\\"\\\"\\\"\\n         if not root:\\n             return []\\n         \\n         cur_level,levelOrder,level=[root],[],1\\n         while cur_level:\\n             next_level,vals=[],[]\\n             for node in cur_level:\\n                 vals.append(node.val)\\n                 if node.left:\\n                     next_level.append(node.left)\\n                 if node.right:\\n                     next_level.append(node.right)\\n             if level%2==1:\\n                 levelOrder.append(vals)\\n             else:\\n                 levelOrder.append(vals[::-1])\\n             level+=1\\n             cur_level=next_level\\n         return levelOrder\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nConsider the array `[3,6,9,12]`. If we generate all the combinations with repetition that sum to `12`, we get `5` combinations: `[12], [6,6], [3,9], [3,3,6], [3,3,3,3]`. The length of the sub-arrays (such as `[3,3,3,3]` should be less than or equal to the length of the initial array (`[3,6,9,12]`).  \\n\\nGiven an array of positive integers and a number `n`, count all combinations with repetition of integers that sum to `n`. For example: \\n```Haskell\\nfind([3,6,9,12],12) = 5.\\n```\\n\\nMore examples in the test cases. \\n\\nGood luck!\\n\\nIf you like this Kata, please try:\\n\\n[Array combinations](https:\\/\\/www.codewars.com\\/kata\\/59e66e48fc3c499ec5000103)\\n\\n[Sum of prime-indexed elements](https:\\/\\/www.codewars.com\\/kata\\/59f38b033640ce9fc700015b)\",\"targets\":\"from itertools import combinations_with_replacement as c\\nfind=lambda a,k:sum(1for i in range(1,len(a)+1)for j in c(a,i)if sum(j)==k)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nInnokentiy decides to change the password in the social net \\\"Contact!\\\", but he is too lazy to invent a new password by himself. That is why he needs your help. \\n\\nInnokentiy decides that new password should satisfy the following conditions:  the length of the password must be equal to n,  the password should consist only of lowercase Latin letters,  the number of distinct symbols in the password must be equal to k,  any two consecutive symbols in the password must be distinct. \\n\\nYour task is to help Innokentiy and to invent a new password which will satisfy all given conditions. \\n\\n\\n-----Input-----\\n\\nThe first line contains two positive integers n and k (2 ≤ n ≤ 100, 2 ≤ k ≤ min(n, 26)) — the length of the password and the number of distinct symbols in it. \\n\\nPay attention that a desired new password always exists.\\n\\n\\n-----Output-----\\n\\nPrint any password which satisfies all conditions given by Innokentiy.\\n\\n\\n-----Examples-----\\nInput\\n4 3\\n\\nOutput\\njava\\n\\nInput\\n6 6\\n\\nOutput\\npython\\n\\nInput\\n5 2\\n\\nOutput\\nphphp\\n\\n\\n\\n-----Note-----\\n\\nIn the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.\\n\\nIn the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letters.\\n\\nIn the third test there is one of the appropriate new passwords — phphp, because its length is equal to 5 and 2 distinct lowercase letters p and h are used in it.\\n\\nPay attention the condition that no two identical symbols are consecutive is correct for all appropriate passwords in tests.\",\"targets\":\"#This code is dedicated to Olya S.\\n\\npassword=''\\nn,k=list(map(int,input().split()))\\nalph=[chr(i) for i in range(97,97+k)]\\n\\nfor i in range(n):\\n    password+=alph[i%k]\\n\\nprint(password)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/582933a3c983ca0cef0003de:\\n>When no more interesting kata can be resolved, I just choose to create the new kata, to solve their own, to enjoy the process  --myjinxin2015 said\\n\\n# Description:\\n In kindergarten, the teacher gave the children some candies. The number of candies each child gets is not always the same. Here is an array `candies`(all elements are positive integer). It's the number of candy for each child:\\n ```\\n candies = [10,2,8,22,16,4,10,6,14,20]\\n ```\\n The teacher asked the children to form a circle and play a game: Each child gives half of his candies to the child on his right(at the same time). If the number of children's candy is an odd number, the teacher will give him an extra candy, so that he can evenly distribute his candy. \\n \\n Repeat such distribute process, until all the children's candies are equal in number.\\n \\n You should return two numbers: 1.How many times of distribution; 2. After the game, the number of each child's candy. Returns the result using an array that contains two elements.\\n \\n  \\n# Some examples:\\n\\n```\\n      candies = [ 1,2,3,4,5 ]\\nDistribution 1: [ 4,2,3,4,5 ]\\nDistribution 2: [ 5,3,3,4,5 ]\\nDistribution 3: [ 6,5,4,4,5 ]\\nDistribution 4: [ 6,6,5,4,5 ]\\nDistribution 5: [ 6,6,6,5,5 ]\\nDistribution 6: [ 6,6,6,6,6 ]\\nSo, we need return: [6,6]\\n\\ndistributionOfCandy([1,2,3,4,5]) === [6,6]\\n\\n       candies = [ 10,  2,  8, 22, 16,  4, 10,  6, 14, 20 ]\\ndistribution  1: [ 15,  6,  5, 15, 19, 10,  7,  8, 10, 17 ]\\ndistribution  2: [ 17, 11,  6, 11, 18, 15,  9,  8,  9, 14 ]\\ndistribution  3: [ 16, 15,  9,  9, 15, 17, 13,  9,  9, 12 ]\\ndistribution  4: [ 14, 16, 13, 10, 13, 17, 16, 12, 10, 11 ]\\ndistribution  5: [ 13, 15, 15, 12, 12, 16, 17, 14, 11, 11 ]\\ndistribution  6: [ 13, 15, 16, 14, 12, 14, 17, 16, 13, 12 ]\\ndistribution  7: [ 13, 15, 16, 15, 13, 13, 16, 17, 15, 13 ]\\ndistribution  8: [ 14, 15, 16, 16, 15, 14, 15, 17, 17, 15 ]\\ndistribution  9: [ 15, 15, 16, 16, 16, 15, 15, 17, 18, 17 ]\\ndistribution 10: [ 17, 16, 16, 16, 16, 16, 16, 17, 18, 18 ]\\ndistribution 11: [ 18, 17, 16, 16, 16, 16, 16, 17, 18, 18 ]\\ndistribution 12:...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def distribution_of_candy(candies):\\n    steps = 0\\n    while len(set(candies)) > 1:\\n        candies = [(a + 1) \\/\\/ 2 + (b + 1) \\/\\/ 2\\n                   for a, b in zip(candies, candies[-1:] + candies)]\\n        steps += 1\\n    return [steps, candies.pop()]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/56c2acc8c44a3ad6e400050a:\\nGigi is a clever monkey, living in the zoo, his teacher (animal keeper) recently taught him some knowledge of \\\"0\\\".\\n\\nIn Gigi's eyes, \\\"0\\\" is a character contains some circle(maybe one, maybe two).\\n\\nSo, a is a \\\"0\\\",b is a \\\"0\\\",6 is also a \\\"0\\\"，and 8 have two \\\"0\\\" ,etc...\\n\\nNow, write some code to count how many \\\"0\\\"s in the text.\\n\\nLet us see who is smarter? You ? or monkey?\\n\\nInput always be a string(including words numbers and symbols)，You don't need to verify it, but pay attention to the difference between uppercase and lowercase letters.\\n\\nHere is a table of characters：\\n\\none zeroabdegopq069DOPQR         () <-- A pair of braces as a zerotwo zero%&B8\\n\\nOutput will be a number of \\\"0\\\".\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"ONE_ZERO = 'abdegopq069DOPQR'\\nTWO_ZERO = '%&B8'\\ndef countzero(string):\\n    string = string.replace('()', '0')\\n    return sum(1 if c in ONE_ZERO else 2 if c in TWO_ZERO else 0 for c in string)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given an undirected unweighted graph with N vertices and M edges that contains neither self-loops nor double edges.\\n\\nHere, a self-loop is an edge where a_i = b_i (1≤i≤M), and double edges are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).\\n\\nHow many different paths start from vertex 1 and visit all the vertices exactly once?\\n\\nHere, the endpoints of a path are considered visited.  \\nFor example, let us assume that the following undirected graph shown in Figure 1 is given.\\nFigure 1: an example of an undirected graph\\nThe following path shown in Figure 2 satisfies the condition.\\nFigure 2: an example of a path that satisfies the condition\\nHowever, the following path shown in Figure 3 does not satisfy the condition, because it does not visit all the vertices.\\nFigure 3: an example of a path that does not satisfy the condition\\nNeither the following path shown in Figure 4, because it does not start from vertex 1.\\nFigure 4: another example of a path that does not satisfy the condition\\n\\n-----Constraints-----\\n - 2≦N≦8 \\n - 0≦M≦N(N-1)\\/2 \\n - 1≦a_i<b_i≦N \\n - The given graph contains neither self-loops nor double edges.\\n\\n-----Input-----\\nThe input is given from Standard Input in the following format:\\nN M  \\na_1 b_1  \\na_2 b_2\\n:  \\na_M b_M  \\n\\n-----Output-----\\nPrint the number of the different paths that start from vertex 1 and visit all the vertices exactly once.\\n\\n-----Sample Input-----\\n3 3\\n1 2\\n1 3\\n2 3\\n\\n-----Sample Output-----\\n2\\n\\nThe given graph is shown in the following figure:\\nThe following two paths satisfy the condition:\",\"targets\":\"#\\n# abc054 c\\n#\\n\\nimport sys\\nfrom io import StringIO\\nimport unittest\\nimport itertools\\n\\n\\nclass TestClass(unittest.TestCase):\\n    def assertIO(self, input, output):\\n        stdout, stdin = sys.stdout, sys.stdin\\n        sys.stdout, sys.stdin = StringIO(), StringIO(input)\\n        resolve()\\n        sys.stdout.seek(0)\\n        out = sys.stdout.read()[:-1]\\n        sys.stdout, sys.stdin = stdout, stdin\\n        self.assertEqual(out, output)\\n\\n    def test_入力例_1(self):\\n        input = \\\"\\\"\\\"3 3\\n1 2\\n1 3\\n2 3\\\"\\\"\\\"\\n        output = \\\"\\\"\\\"2\\\"\\\"\\\"\\n        self.assertIO(input, output)\\n\\n    def test_入力例_2(self):\\n        input = \\\"\\\"\\\"7 7\\n1 3\\n2 7\\n3 4\\n4 5\\n4 6\\n5 6\\n6 7\\\"\\\"\\\"\\n        output = \\\"\\\"\\\"1\\\"\\\"\\\"\\n        self.assertIO(input, output)\\n\\n\\ndef resolve():\\n    N, M = list(map(int, input().split()))\\n    P = [list(map(int, input().split())) for _ in range(M)]\\n\\n    R = itertools.permutations(list(range(1, N+1)))\\n\\n    ans = 0\\n    for r in R:\\n        flag = True\\n        r = list(r)\\n        if r[0] != 1:\\n            break\\n        for i in range(1, N):\\n            for p in P:\\n                if (r[i-1] == p[0] and r[i] == p[1]) or (r[i-1] == p[1] and r[i] == p[0]):\\n                    break\\n            else:\\n                flag = False\\n        if flag == True:\\n            ans += 1\\n\\n    print(ans)\\n\\n\\ndef __starting_point():\\n    # unittest.main()\\n    resolve()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nStudents in a class are making towers of blocks. Each student makes a (non-zero) tower by stacking pieces lengthwise on top of each other. n of the students use pieces made of two blocks and m of the students use pieces made of three blocks.\\n\\nThe students don’t want to use too many blocks, but they also want to be unique, so no two students’ towers may contain the same number of blocks. Find the minimum height necessary for the tallest of the students' towers.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two space-separated integers n and m (0 ≤ n, m ≤ 1 000 000, n + m > 0) — the number of students using two-block pieces and the number of students using three-block pieces, respectively.\\n\\n\\n-----Output-----\\n\\nPrint a single integer, denoting the minimum possible height of the tallest tower.\\n\\n\\n-----Examples-----\\nInput\\n1 3\\n\\nOutput\\n9\\n\\nInput\\n3 2\\n\\nOutput\\n8\\n\\nInput\\n5 0\\n\\nOutput\\n10\\n\\n\\n\\n-----Note-----\\n\\nIn the first case, the student using two-block pieces can make a tower of height 4, and the students using three-block pieces can make towers of height 3, 6, and 9 blocks. The tallest tower has a height of 9 blocks.\\n\\nIn the second case, the students can make towers of heights 2, 4, and 8 with two-block pieces and towers of heights 3 and 6 with three-block pieces, for a maximum height of 8 blocks.\",\"targets\":\"def check(x):\\n    return max(n - (x - 2) \\/\\/ 6 - (x - 4) \\/\\/ 6 - 2, 0) + \\\\\\n           max(m - (x - 3) \\/\\/ 6 - 1, 0) <= x \\/\\/ 6\\n\\n\\nn, m = list(map(int, input().split()))\\nleft, right = 0, 10 ** 10\\nwhile left + 1 < right:\\n    middle = (left + right) >> 1\\n    if check(middle):\\n        right = middle\\n    else:\\n        left = middle\\nprint(right)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/290\\/A:\\n-----Input-----\\n\\nThe input contains a single integer a (1 ≤ a ≤ 40).\\n\\n\\n-----Output-----\\n\\nOutput a single string.\\n\\n\\n-----Examples-----\\nInput\\n2\\n\\nOutput\\nAdams\\n\\nInput\\n8\\n\\nOutput\\nVan Buren\\n\\nInput\\n29\\n\\nOutput\\nHarding\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"print([\\\"Washington\\\",\\\"Adams\\\",\\\"Jefferson\\\",\\\"Madison\\\",\\\"Monroe\\\",\\\"Adams\\\",\\\"Jackson\\\",\\\"Van Buren\\\",\\\"Harrison\\\",\\\"Tyler\\\",\\\"Polk\\\",\\\"Taylor\\\",\\\"Fillmore\\\",\\\"Pierce\\\",\\\"Buchanan\\\",\\\"Lincoln\\\",\\\"Johnson\\\",\\\"Grant\\\",\\\"Hayes\\\",\\\"Garfield\\\",\\\"Arthur\\\",\\\"Cleveland\\\",\\\"Harrison\\\",\\\"Cleveland\\\",\\\"McKinley\\\",\\\"Roosevelt\\\",\\\"Taft\\\",\\\"Wilson\\\",\\\"Harding\\\",\\\"Coolidge\\\",\\\"Hoover\\\",\\\"Roosevelt\\\",\\\"Truman\\\",\\\"Eisenhower\\\",\\\"Kennedy\\\",\\\"Johnson\\\",\\\"Nixon\\\",\\\"Ford\\\",\\\"Carter\\\",\\\"Reagan\\\",\\\"Bush\\\"][int(input())-1])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven are a sequence of N positive integers A_1, A_2, \\\\ldots, A_N and another positive integer S.\\n\\nFor a non-empty subset T of the set \\\\{1, 2, \\\\ldots , N \\\\}, let us define f(T) as follows:\\n\\n - f(T) is the number of different non-empty subsets \\\\{x_1, x_2, \\\\ldots , x_k \\\\} of T such that A_{x_1}+A_{x_2}+\\\\cdots +A_{x_k} = S.\\nFind the sum of f(T) over all 2^N-1 subsets T of \\\\{1, 2, \\\\ldots , N \\\\}. Since the sum can be enormous, print it modulo 998244353.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq N \\\\leq 3000\\n - 1 \\\\leq S \\\\leq 3000\\n - 1 \\\\leq A_i \\\\leq 3000\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN S\\nA_1 A_2 ... A_N\\n\\n-----Output-----\\nPrint the sum of f(T) modulo 998244353.\\n\\n-----Sample Input-----\\n3 4\\n2 2 4\\n\\n-----Sample Output-----\\n6\\n\\nFor each T, the value of f(T) is shown below. The sum of these values is 6.\\n - f(\\\\{1\\\\}) = 0\\n - f(\\\\{2\\\\}) = 0\\n - f(\\\\{3\\\\}) = 1 (One subset \\\\{3\\\\} satisfies the condition.)\\n - f(\\\\{1, 2\\\\}) = 1 (\\\\{1, 2\\\\})\\n - f(\\\\{2, 3\\\\}) = 1 (\\\\{3\\\\})\\n - f(\\\\{1, 3\\\\}) = 1 (\\\\{3\\\\})\\n - f(\\\\{1, 2, 3\\\\}) = 2 (\\\\{1, 2\\\\}, \\\\{3\\\\})\",\"targets\":\"#!python3\\n\\niim = lambda: list(map(int, input().rstrip().split()))\\n\\ndef resolve():\\n    N, S = iim()\\n    A = list(iim())\\n    mod = 998244353\\n    S1 = S + 1\\n\\n    dp = [0] * (S+1)\\n\\n    dp[0] = pow(2, N, mod)\\n    inv = pow(2, mod-2, mod)\\n\\n    for ai in A:\\n        for i in range(S, ai-1, -1):\\n            dp[i] = (dp[i] + dp[i-ai]*inv) % mod\\n\\n    print((dp[-1]))\\n\\n\\ndef __starting_point():\\n    resolve()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1385\\/D:\\nYou are given a string $s[1 \\\\dots n]$ consisting of lowercase Latin letters. It is guaranteed that $n = 2^k$ for some integer $k \\\\ge 0$.\\n\\nThe string $s[1 \\\\dots n]$ is called $c$-good if at least one of the following three conditions is satisfied:  The length of $s$ is $1$, and it consists of the character $c$ (i.e. $s_1=c$); The length of $s$ is greater than $1$, the first half of the string consists of only the character $c$ (i.e. $s_1=s_2=\\\\dots=s_{\\\\frac{n}{2}}=c$) and the second half of the string (i.e. the string $s_{\\\\frac{n}{2} + 1}s_{\\\\frac{n}{2} + 2} \\\\dots s_n$) is a $(c+1)$-good string;  The length of $s$ is greater than $1$, the second half of the string consists of only the character $c$ (i.e. $s_{\\\\frac{n}{2} + 1}=s_{\\\\frac{n}{2} + 2}=\\\\dots=s_n=c$) and the first half of the string (i.e. the string $s_1s_2 \\\\dots s_{\\\\frac{n}{2}}$) is a $(c+1)$-good string. \\n\\nFor example: \\\"aabc\\\" is 'a'-good, \\\"ffgheeee\\\" is 'e'-good.\\n\\nIn one move, you can choose one index $i$ from $1$ to $n$ and replace $s_i$ with any lowercase Latin letter (any character from 'a' to 'z').\\n\\nYour task is to find the minimum number of moves required to obtain an 'a'-good string from $s$ (i.e. $c$-good string for $c=$ 'a'). It is guaranteed that the answer always exists.\\n\\nYou have to answer $t$ independent test cases.\\n\\nAnother example of an 'a'-good string is as follows. Consider the string $s = $\\\"cdbbaaaa\\\". It is an 'a'-good string, because:  the second half of the string (\\\"aaaa\\\") consists of only the character 'a';  the first half of the string (\\\"cdbb\\\") is 'b'-good string, because:   the second half of the string (\\\"bb\\\") consists of only the character 'b';  the first half of the string (\\\"cd\\\") is 'c'-good string, because:   the first half of the string (\\\"c\\\") consists of only the character 'c';  the second half of the string (\\\"d\\\") is 'd'-good string.   \\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $t$ ($1 \\\\le t \\\\le 2 \\\\cdot 10^4$) — the number of test cases. Then $t$ test cases follow.\\n\\nThe first line of the test case...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"alph=\\\"abcdefghijklmnopqrstuvwqyz\\\"\\ndef solve(s,i,n):\\n    if n==1:\\n        if s[0]==alph[i]:\\n            return 0\\n        else:\\n            return 1\\n    else:\\n        c1=0\\n        c2=0\\n        s1=s[0:n\\/\\/2]\\n        s2=s[n\\/\\/2:n]\\n        for x in s1:\\n            if x!=alph[i]:\\n                c1+=1\\n        for x in s2:\\n            if x!=alph[i]:\\n                c2+=1\\n        return min(c1+solve(s2,i+1,n\\/\\/2),c2+solve(s1,i+1,n\\/\\/2))\\nimport sys\\ninput = sys.stdin.readline\\nfor f in range(int(input())):\\n    n=int(input())\\n    s=input()\\n    s=s[0:n]\\n    print(solve(s,0,n))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/749\\/C:\\nThere are n employees in Alternative Cake Manufacturing (ACM). They are now voting on some very important question and the leading world media are trying to predict the outcome of the vote.\\n\\nEach of the employees belongs to one of two fractions: depublicans or remocrats, and these two fractions have opposite opinions on what should be the outcome of the vote. The voting procedure is rather complicated:   Each of n employees makes a statement. They make statements one by one starting from employees 1 and finishing with employee n. If at the moment when it's time for the i-th employee to make a statement he no longer has the right to vote, he just skips his turn (and no longer takes part in this voting).  When employee makes a statement, he can do nothing or declare that one of the other employees no longer has a right to vote. It's allowed to deny from voting people who already made the statement or people who are only waiting to do so. If someone is denied from voting he no longer participates in the voting till the very end.  When all employees are done with their statements, the procedure repeats: again, each employees starting from 1 and finishing with n who are still eligible to vote make their statements.  The process repeats until there is only one employee eligible to vote remaining and he determines the outcome of the whole voting. Of course, he votes for the decision suitable for his fraction. \\n\\nYou know the order employees are going to vote and that they behave optimal (and they also know the order and who belongs to which fraction). Predict the outcome of the vote.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of employees. \\n\\nThe next line contains n characters. The i-th character is 'D' if the i-th employee is from depublicans fraction or 'R' if he is from remocrats.\\n\\n\\n-----Output-----\\n\\nPrint 'D' if the outcome of the vote will be suitable for depublicans and 'R' if remocrats will...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\ns = input()\\n\\ndd = 0\\ndr = 0\\nwhile len(s) > 1:\\n    t = ''\\n    cd = 0\\n    cr = 0\\n    for c in s:\\n        if c == 'D':\\n            if dd > 0:\\n                dd -= 1\\n            else:\\n                dr += 1\\n                t += c\\n                cd += 1\\n        else:\\n            if dr > 0:\\n                dr -= 1\\n            else:\\n                dd += 1\\n                t += c\\n                cr += 1\\n    s = t\\n    if cd == 0:\\n        s = 'R'\\n        break\\n    if cr == 0:\\n        s = 'D'\\n        break\\n    if dd >= cd:\\n        s = 'R'\\n        break\\n    if dr >= cr:\\n        s = 'D'\\n        break\\n    \\nprint(s[0])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/802\\/D:\\nHeidi is a statistician to the core, and she likes to study the evolution of marmot populations in each of V (1 ≤ V ≤ 100) villages! So it comes that every spring, when Heidi sees the first snowdrops sprout in the meadows around her barn, she impatiently dons her snowshoes and sets out to the Alps, to welcome her friends the marmots to a new season of thrilling adventures.\\n\\nArriving in a village, Heidi asks each and every marmot she comes across for the number of inhabitants of that village. This year, the marmots decide to play an April Fools' joke on Heidi. Instead of consistently providing the exact number of inhabitants P (10 ≤ P ≤ 1000) of the village, they respond with a random non-negative integer k, drawn from one of two types of probability distributions:\\n\\n  Poisson (d'avril) distribution: the probability of getting an answer k is $\\\\frac{p^{k} e^{-P}}{k !}$ for k = 0, 1, 2, 3, ...,  Uniform distribution: the probability of getting an answer k is $\\\\frac{1}{2 P + 1}$ for k = 0, 1, 2, ..., 2P. \\n\\nHeidi collects exactly 250 answers per village. Every village follows either the Poisson or the uniform distribution. Heidi cannot tell marmots apart, so she may query some marmots several times, and each time the marmot will answer with a new number drawn from the village's distribution.\\n\\nCan you help Heidi to find out whether a village follows a Poisson or a uniform distribution?\\n\\n\\n-----Input-----\\n\\nThe first line of input will contain the number of villages V (1 ≤ V ≤ 100). The following V lines each describe one village. The description of each village consists of 250 space-separated integers k, drawn from one of the above distributions.\\n\\n\\n-----Output-----\\n\\nOutput one line per village, in the same order as provided in the input. The village's line shall state poisson if the village's distribution is of the Poisson type, and uniform if the answer came from a uniform distribution.\\n\\n\\n-----Example-----\\nInput\\n2\\n92 100 99 109 93 105 103 106 101 99 ... (input is truncated)\\n28 180 147 53 84 80 180 85 8 16 ... (input...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import *\\n\\nn = int(input())\\nfor _ in range(n):\\n    a = [int(i) for i in input().split()]\\n    c = len(a)\\n    avg = sum(a)\\/c\\n    ulik = log(2*avg + 1)*(-c)\\n    plik = 0\\n    for k in a:\\n        plik += log(avg)*k\\n        plik += -avg\\n        for i in range(1, k+1):\\n            plik -= log(i)\\n    isu = ulik > plik\\n    ans = [\\\"poisson\\\", \\\"uniform\\\"][isu]\\n    print(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe window of Takahashi's room has a width of A. There are two curtains hung over the window, each of which has a horizontal length of B. (Vertically, the curtains are long enough to cover the whole window.)\\nWe will close the window so as to minimize the total horizontal length of the uncovered part of the window.\\nFind the total horizontal length of the uncovered parts of the window then.\\n\\n-----Constraints-----\\n - 1 \\\\leq A \\\\leq 100\\n - 1 \\\\leq B \\\\leq 100\\n - A and B are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B\\n\\n-----Output-----\\nPrint the total horizontal length of the uncovered parts of the window.\\n\\n-----Sample Input-----\\n12 4\\n\\n-----Sample Output-----\\n4\\n\\nWe have a window with a horizontal length of 12, and two curtains, each of length 4, that cover both ends of the window, for example. The uncovered part has a horizontal length of 4.\",\"targets\":\"a,b=list(map(int,input().split()))\\nif a <= 2*b:\\n    print((0))\\nelse:\\n    print((a-2*b))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nReturn the Nth Even Number\\n\\nThe input will not be 0.\",\"targets\":\"def nth_even(n):\\n    return [i for i in range(n * 2 - 50, n * 2, 2)][-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/257\\/C:\\nFlatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex at the origin of coordinates and with all mannequins standing inside or on the boarder of this angle. \\n\\nAs you spend lots of time \\\"glued to the screen\\\", your vision is impaired. So you have to write a program that will pass the check for you.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer n (1 ≤ n ≤ 10^5) — the number of mannequins.\\n\\nNext n lines contain two space-separated integers each: x_{i}, y_{i} (|x_{i}|, |y_{i}| ≤ 1000) — the coordinates of the i-th mannequin. It is guaranteed that the origin of the coordinates has no mannequin. It is guaranteed that no two mannequins are located in the same point on the plane.\\n\\n\\n-----Output-----\\n\\nPrint a single real number — the value of the sought angle in degrees. The answer will be considered valid if the relative or absolute error doesn't exceed 10^{ - 6}. \\n\\n\\n-----Examples-----\\nInput\\n2\\n2 0\\n0 2\\n\\nOutput\\n90.0000000000\\n\\nInput\\n3\\n2 0\\n0 2\\n-2 2\\n\\nOutput\\n135.0000000000\\n\\nInput\\n4\\n2 0\\n0 2\\n-2 0\\n0 -2\\n\\nOutput\\n270.0000000000\\n\\nInput\\n2\\n2 1\\n1 2\\n\\nOutput\\n36.8698976458\\n\\n\\n\\n-----Note-----\\n\\nSolution for the first sample test is shown below:  [Image] \\n\\nSolution for the second sample test is shown below:  [Image] \\n\\nSolution for the third sample test is shown below:  [Image] \\n\\nSolution for the fourth sample test is shown below:  $\\\\#$\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys, math\\n\\nn = int(sys.stdin.readline())\\npoints = []\\nfor i in range(n):\\n    [a, b] = list(map(int, sys.stdin.readline().split()))\\n    points.append(math.atan2(a,b))\\npoints = sorted(points)\\ndiffs = []\\nfor i in range(n):\\n    if (i == n-1):\\n        diffs.append(points[0]-points[n-1] + 2 * math.pi)\\n    else:\\n        diffs.append(points[i+1]-points[i])\\nprint(360-180*max(diffs)\\/math.pi)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nJohnny has recently found an ancient, broken computer. The machine has only one register, which allows one to put in there one variable. Then in one operation, you can shift its bits left or right by at most three positions. The right shift is forbidden if it cuts off some ones. So, in fact, in one operation, you can multiply or divide your number by $2$, $4$ or $8$, and division is only allowed if the number is divisible by the chosen divisor. \\n\\nFormally, if the register contains a positive integer $x$, in one operation it can be replaced by one of the following:   $x \\\\cdot 2$  $x \\\\cdot 4$  $x \\\\cdot 8$  $x \\/ 2$, if $x$ is divisible by $2$  $x \\/ 4$, if $x$ is divisible by $4$  $x \\/ 8$, if $x$ is divisible by $8$ \\n\\nFor example, if $x = 6$, in one operation it can be replaced by $12$, $24$, $48$ or $3$. Value $6$ isn't divisible by $4$ or $8$, so there're only four variants of replacement.\\n\\nNow Johnny wonders how many operations he needs to perform if he puts $a$ in the register and wants to get $b$ at the end.\\n\\n\\n-----Input-----\\n\\nThe input consists of multiple test cases. The first line contains an integer $t$ ($1 \\\\leq t \\\\leq 1000$) — the number of test cases. The following $t$ lines contain a description of test cases.\\n\\nThe first and only line in each test case contains integers $a$ and $b$ ($1 \\\\leq a, b \\\\leq 10^{18}$) — the initial and target value of the variable, respectively.\\n\\n\\n-----Output-----\\n\\nOutput $t$ lines, each line should contain one integer denoting the minimum number of operations Johnny needs to perform. If Johnny cannot get $b$ at the end, then write $-1$.\\n\\n\\n-----Example-----\\nInput\\n10\\n10 5\\n11 44\\n17 21\\n1 1\\n96 3\\n2 128\\n1001 1100611139403776\\n1000000000000000000 1000000000000000000\\n7 1\\n10 8\\n\\nOutput\\n1\\n1\\n-1\\n0\\n2\\n2\\n14\\n0\\n-1\\n-1\\n\\n\\n\\n-----Note-----\\n\\nIn the first test case, Johnny can reach $5$ from $10$ by using the shift to the right by one (i.e. divide by $2$).\\n\\nIn the second test case, Johnny can reach $44$ from $11$ by using the shift to the left by two (i.e. multiply by $4$).\\n\\nIn the third test case, it...\",\"targets\":\"for i in range(int(input())):\\n    a,b=map(int,input().split())\\n    m=0\\n    l=0\\n    while a%2==0:\\n        a\\/\\/=2\\n        m+=1\\n    while b%2==0:\\n        b\\/\\/=2\\n        l+=1\\n    if b!=a:\\n        print(-1)\\n    else:\\n        u=abs(l-m)\\n        if u%3!=0:\\n            print(u\\/\\/3+1)\\n        else:\\n            print(u\\/\\/3)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nOhana Matsumae is trying to clean a room, which is divided up into an n by n grid of squares. Each square is initially either clean or dirty. Ohana can sweep her broom over columns of the grid. Her broom is very strange: if she sweeps over a clean square, it will become dirty, and if she sweeps over a dirty square, it will become clean. She wants to sweep some columns of the room to maximize the number of rows that are completely clean. It is not allowed to sweep over the part of the column, Ohana can only sweep the whole column.\\n\\nReturn the maximum number of rows that she can make completely clean.\\n\\n\\n-----Input-----\\n\\nThe first line of input will be a single integer n (1 ≤ n ≤ 100).\\n\\nThe next n lines will describe the state of the room. The i-th line will contain a binary string with n characters denoting the state of the i-th row of the room. The j-th character on this line is '1' if the j-th square in the i-th row is clean, and '0' if it is dirty.\\n\\n\\n-----Output-----\\n\\nThe output should be a single line containing an integer equal to a maximum possible number of rows that are completely clean.\\n\\n\\n-----Examples-----\\nInput\\n4\\n0101\\n1000\\n1111\\n0101\\n\\nOutput\\n2\\n\\nInput\\n3\\n111\\n111\\n111\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, Ohana can sweep the 1st and 3rd columns. This will make the 1st and 4th row be completely clean.\\n\\nIn the second sample, everything is already clean, so Ohana doesn't need to do anything.\",\"targets\":\"n = int(input())\\n\\nd = {}\\n\\nfor i in range(n):\\n\\ts = input()\\n\\tif s in d:\\n\\t\\td[s] += 1\\n\\telse:\\n\\t\\td[s] = 1\\n\\nprint(d[max(d,key=d.get)])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1111\\/B:\\nEvery superhero has been given a power value by the Felicity Committee. The avengers crew wants to maximize the average power of the superheroes in their team by performing certain operations.\\n\\nInitially, there are $n$ superheroes in avengers team having powers $a_1, a_2, \\\\ldots, a_n$, respectively. In one operation, they can remove one superhero from their team (if there are at least two) or they can increase the power of a superhero by $1$. They can do at most $m$ operations. Also, on a particular superhero at most $k$ operations can be done.\\n\\nCan you help the avengers team to maximize the average power of their crew?\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers $n$, $k$ and $m$ ($1 \\\\le n \\\\le 10^{5}$, $1 \\\\le k \\\\le 10^{5}$, $1 \\\\le m \\\\le 10^{7}$) — the number of superheroes, the maximum number of times you can increase power of a particular superhero, and the total maximum number of operations.\\n\\nThe second line contains $n$ integers $a_1, a_2, \\\\ldots, a_n$ ($1 \\\\le a_i \\\\le 10^{6}$) — the initial powers of the superheroes in the cast of avengers.\\n\\n\\n-----Output-----\\n\\nOutput a single number — the maximum final average power.\\n\\nYour answer is considered correct if its absolute or relative error does not exceed $10^{-6}$.\\n\\nFormally, let your answer be $a$, and the jury's answer be $b$. Your answer is accepted if and only if $\\\\frac{|a - b|}{\\\\max{(1, |b|)}} \\\\le 10^{-6}$.\\n\\n\\n-----Examples-----\\nInput\\n2 4 6\\n4 7\\n\\nOutput\\n11.00000000000000000000\\n\\nInput\\n4 2 6\\n1 3 2 3\\n\\nOutput\\n5.00000000000000000000\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, the maximum average is obtained by deleting the first element and increasing the second element four times.\\n\\nIn the second sample, one of the ways to achieve maximum average is to delete the first and the third element and increase the second and the fourth elements by $2$ each.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n,k,m = map(int,input().split())\\na = list(map(int,input().split()))\\na.sort(reverse = True)\\ns = sum(a)\\nans = 0\\nwhile n > 0 and m > -1:\\n    s2 = (s + min(m,n * k)) \\/ n\\n    ans = max(ans,s2)\\n    s -= a.pop()\\n    n -= 1\\n    m -= 1\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are $n$ students standing in a row. Two coaches are forming two teams — the first coach chooses the first team and the second coach chooses the second team.\\n\\nThe $i$-th student has integer programming skill $a_i$. All programming skills are distinct and between $1$ and $n$, inclusive.\\n\\nFirstly, the first coach will choose the student with maximum programming skill among all students not taken into any team, and $k$ closest students to the left of him and $k$ closest students to the right of him (if there are less than $k$ students to the left or to the right, all of them will be chosen). All students that are chosen leave the row and join the first team. Secondly, the second coach will make the same move (but all students chosen by him join the second team). Then again the first coach will make such move, and so on. This repeats until the row becomes empty (i. e. the process ends when each student becomes to some team).\\n\\nYour problem is to determine which students will be taken into the first team and which students will be taken into the second team.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $k$ ($1 \\\\le k \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of students and the value determining the range of chosen students during each move, respectively.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le n$), where $a_i$ is the programming skill of the $i$-th student. It is guaranteed that all programming skills are distinct.\\n\\n\\n-----Output-----\\n\\nPrint a string of $n$ characters; $i$-th character should be 1 if $i$-th student joins the first team, or 2 otherwise.\\n\\n\\n-----Examples-----\\nInput\\n5 2\\n2 4 5 3 1\\n\\nOutput\\n11111\\n\\nInput\\n5 1\\n2 1 3 5 4\\n\\nOutput\\n22111\\n\\nInput\\n7 1\\n7 2 1 3 5 4 6\\n\\nOutput\\n1121122\\n\\nInput\\n5 1\\n2 4 5 3 1\\n\\nOutput\\n21112\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the first coach chooses the student on a position $3$, and the row becomes empty (all students join the first team).\\n\\nIn the second example the first coach chooses the student on...\",\"targets\":\"n, k = map(int, input().split())\\n\\nlst = map(int, input().split())\\n\\ndef debug():\\n\\n\\tprint('-')\\n\\tlst = [0 for _ in range(n)]\\n\\tfor i in range(n):\\n\\t\\tnode = table[i]\\n\\t\\tlst[node.index] = node.team\\n\\n\\tprint (''.join(str(x) for x in lst))\\n\\tprint('-')\\n\\nclass Node:\\n\\n\\tdef __init__(self, index):\\n\\t\\tself.index = index\\n\\t\\tself.team = 0 \\n\\t\\tself.prev = None\\n\\t\\tself.next = None\\n\\ntable = [None for _ in range(n)]\\n\\nprev_node = None\\nfor index, element in enumerate(lst):\\n\\n\\tnode = Node(index)\\n\\n\\tif prev_node:\\n\\t\\tprev_node.next = node\\n\\n\\tnode.prev = prev_node\\n\\n\\ttable[element - 1] = node\\n\\tprev_node = node\\n\\nteam = 1\\nfor i in reversed(range(n)):\\n\\n\\t# taken\\n\\tif table[i].team != 0:\\n\\t\\tcontinue\\n\\n\\tnode = table[i]\\n\\tnode.team = team\\n\\n\\tnext_node = node.next\\n\\tfor j in range(k):\\n\\n\\t\\tif next_node is None:\\n\\t\\t\\tbreak\\n\\n\\t\\tnext_node.team = team\\n\\t\\tnext_node = next_node.next\\n\\n\\tprev_node = node.prev\\n\\tfor j in range(k):\\n\\n\\t\\tif prev_node is None:\\n\\t\\t\\tbreak\\n\\n\\t\\tprev_node.team = team\\n\\t\\tprev_node = prev_node.prev\\n\\n\\tif prev_node is not None:\\n\\t\\tprev_node.next = next_node\\n\\n\\tif next_node is not None:\\n\\t\\tnext_node.prev = prev_node\\n\\n\\tteam = 1 if team == 2 else 2\\n\\nlst = [0 for _ in range(n)]\\nfor i in range(n):\\n\\tnode = table[i]\\n\\tlst[node.index] = node.team\\n\\nprint (''.join(str(x) for x in lst))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nQuickly after finishing the tutorial of the online game ATChat, you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the friendliness of Player i is A_i.\\nThe N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.\\nWhen each player, except the first one to arrive, arrives at the place, the player gets comfort equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.\\nWhat is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 2 \\\\leq N \\\\leq 2 \\\\times 10^5\\n - 1 \\\\leq A_i \\\\leq 10^9\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nA_1 A_2 \\\\dots A_N\\n\\n-----Output-----\\nPrint the maximum total comfort the N players can get.\\n\\n-----Sample Input-----\\n4\\n2 2 1 3\\n\\n-----Sample Output-----\\n7\\n\\nBy arriving at the place in the order Player 4, 2, 1, 3, and cutting into the circle as shown in the figure, they can get the total comfort of 7.\\n\\nThey cannot get the total comfort greater than 7, so the answer is 7.\",\"targets\":\"n=int(input())\\nA=list(map(int, input().split()))\\nA=sorted(A, reverse=True)\\nans=0\\nfor i in range(1,n):\\n    ans+=A[i\\/\\/2]\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a certain integer  ```n, n > 0```and a number of partitions,  ```k, k > 0```; we want to know the partition which has the maximum or minimum product of its terms.\\n\\nThe function ```find_spec_partition() ```, will receive three arguments,  ```n```,  ```k```, and a command:  ```'max' or 'min'```\\n\\nThe function should output the partition that has maximum or minimum value product (it depends on the given command) as an array with its terms in decreasing order.\\n\\nLet's see some cases (Python and Ruby)\\n```\\nfind_spec_partition(10, 4, 'max') == [3, 3, 2, 2]\\nfind_spec_partition(10, 4, 'min') == [7, 1, 1, 1]\\n```\\nand Javascript:\\n```\\nfindSpecPartition(10, 4, 'max') == [3, 3, 2, 2]\\nfindSpecPartition(10, 4, 'min') == [7, 1, 1, 1]\\n```\\nThe partitions of 10 with 4 terms with their products are:\\n```\\n(4, 3, 2, 1): 24\\n(4, 2, 2, 2): 32\\n(6, 2, 1, 1): 12\\n(3, 3, 3, 1): 27\\n(4, 4, 1, 1): 16\\n(5, 2, 2, 1): 20 \\n(7, 1, 1, 1): 7   <------- min. productvalue\\n(3, 3, 2, 2): 36  <------- max.product value\\n(5, 3, 1, 1): 15\\n```\\nEnjoy it!\",\"targets\":\"def find_spec_partition(n, k, com):\\n    x,r = divmod(n,k)\\n    return {'max': [x+1]*r + [x]*(k-r),\\n            'min': [n+1-k] + [1]*(k-1)}[com]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58f0ba42e89aa6158400000e:\\nHave you heard about the myth that [if you fold a paper enough times, you can reach the moon with it](http:\\/\\/scienceblogs.com\\/startswithabang\\/2009\\/08\\/31\\/paper-folding-to-the-moon\\/)? Sure you have, but exactly how many? Maybe it's time to write a program to figure it out.\\n\\nYou know that a piece of paper has a thickness of `0.0001m`. Given `distance` in units of meters, calculate how many times you have to fold the paper to make the paper reach this distance.  \\n(If you're not familiar with the concept of folding a paper: Each fold doubles its total thickness.)\\n\\nNote: Of course you can't do half a fold. You should know what this means ;P\\n\\nAlso, if somebody is giving you a negative distance, it's clearly bogus and you should yell at them by returning `null` (or whatever equivalent in your language. In Shell please return `None`).\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\ndef fold_to(distance):\\n    return math.ceil(math.log((distance\\/0.0001),2)) if distance>0.0001 else None if distance<0 else 0\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/GERALD05:\\n-----Problem Statement-----\\nChef studies combinatorics. He tries to group objects by their rang (a positive integer associated with each object). He also gives the formula for calculating the number of different objects with rang N as following:\\n\\nthe number of different objects with rang N = F(N) = A0 + A1 * N + A2 * N2 + A3 * N3.\\n\\nNow Chef wants to know how many different multisets of these objects exist such that sum of rangs of the objects in the multiset equals to S. You are given the coefficients in F(N) and the target sum S. Please, find the number of different multisets modulo 1,000,000,007.\\n\\nYou should consider a multiset as an unordered sequence of integers. Two multisets are different if and only if there at least exists one element which occurs X times in the first multiset but Y times in the second one, where (X ≠ Y).\\n\\n-----Input-----\\nThe first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows. \\n\\nThe first line of each test case contains four integers A0, A1, A2, A3. The second line contains an integer S.\\n\\n-----Output-----\\nFor each test case, output a single line containing a single integer - the answer to the test case modulo 1,000,000,007.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 500\\n- 1 ≤ S ≤ 100\\n- 0 ≤ Ai ≤ 1000\\n- Sum of all S for all test cases is not greater than 500. It's guaranteed that at least one Ai is non-zero.\\n\\n-----Example-----\\nInput:\\n4\\n1 0 0 0\\n1\\n1 0 0 0\\n3\\n0 1 0 0\\n2\\n2 3 1 4\\n10\\n\\nOutput:\\n1\\n3\\n3\\n213986343\\n\\n-----Explanation-----\\nExample case 2. \\n\\nIn the second example function looks as follows F(N) = 1. So for each rang there is a single object of the rang. To get multiset with sum of rangs equal to 3, you can pick: three objects of rang 1, or one object of rang 1 and one of rang 2, or only one object of rang 3. \\nExample case 3. \\n\\nIn the third example function looks as follows F(N) = N. So, you have one distinct object of rang 1, two distinct objects of rang 2, three distinct objects of rang 3 and so on. To get\\nmultiset with sum of...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nimport sys\\n\\nmod_val = 1000000007\\nrang = [0]*101\\npow_cache = [0]*102\\nmultisets = {}\\n\\n\\ndef mod_pow(base, pow):\\n result = 1\\n while pow:\\n  if pow&1:\\n   result = (result*base) % mod_val\\n  base = (base*base) % mod_val\\n  pow = pow>>1\\n return result\\n\\n\\ndef precalculate():\\n\\n for i in range(1, 102):\\n  pow_cache[i] = mod_pow(i, mod_val-2)\\n\\n\\ndef cal_recurse(i, target_sum):\\n if target_sum == 0:\\n  return 1\\n if i>=target_sum:\\n  return 0\\n if (i, target_sum) in multisets:\\n  return multisets[(i, target_sum)]\\n ans = cal_recurse(i+1, target_sum)\\n max_pos = target_sum\\/\\/(i+1)\\n choose = rang[i+1]%mod_val\\n for j in range(1, max_pos+1):\\n  temp = choose*cal_recurse(i+1, target_sum-j*(i+1))\\n  # temp%=mod_val\\n  ans += temp\\n  ans %= mod_val\\n  choose *= rang[i+1]+j\\n  # choose %= mod_val\\n  choose *= pow_cache[j+1]\\n  choose %= mod_val\\n multisets[i, target_sum] = ans\\n return ans\\n\\n\\ndef calculate(target_sum, rang_index):\\n populate(target_sum, rang_index)\\n return cal_recurse(0, target_sum)\\n\\n\\ndef populate(target_sum, rang_i):\\n for i in range(1, target_sum+1):\\n  rang[i] = rang_i[0] + (rang_i[1] + (rang_i[2] + rang_i[3]*i)*i)*i\\n\\n\\n_test_cases = int(input())\\nprecalculate()\\nfor _a_case in range(_test_cases):\\n rang = [0]*101\\n multisets = {}\\n _rang_index = [int(i) for i in input().split(' ')]\\n _target_sum = int(input())\\n print(calculate(_target_sum, _rang_index))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/DIVIDING:\\nAre you fond of collecting some kind of stuff? Mike is crazy about collecting stamps. He is an active member of Stamp Collecting Сommunity(SCC). \\n\\nSCC consists of N members which are fond of philately. A few days ago Mike argued with the others from SCC. Mike told them that all stamps of the members could be divided in such a way that i'th member would get i postage stamps. Now Mike wants to know if he was right. The next SCC meeting is tomorrow. Mike still has no answer.\\n\\nSo, help Mike! There are N members in the SCC, i'th member has Ci stamps in his collection. Your task is to determine if it is possible to redistribute C1 + C2 + ... + Cn stamps among the members of SCC thus that i'th member would get i stamps.\\n\\n-----Input-----\\nThe first line contains one integer N, denoting the number of members of SCC.\\nThe second line contains N integers Ci, denoting the numbers of the stamps in the collection of i'th member.\\n\\n-----Output-----\\nThe first line should contain YES, if we can obtain the required division, otherwise NO.\\n\\n-----Constraints-----\\n1 ≤ N ≤ 100 000;\\n1 ≤  Ci ≤ 109.\\n\\n-----Examples-----\\nInput:\\n5\\n7 4 1 1 2\\n\\nOutput:\\nYES\\n\\nInput:\\n5\\n1 1 1 1 1\\n\\nOutput:\\nNO\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nl = []\\nn = int(input())\\nx = map(int, input().split())\\nx1 = sum(x)\\nfor i in range(1, n+1):\\n    l.append(i)\\n\\nl1 = sum(l)\\nif x1 == l1:\\n    print(\\\"YES\\\")\\nelse:\\n    print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe want to know the index of the vowels in a given word, for example, there are two vowels in the word super (the second and fourth letters). \\n\\nSo given a string \\\"super\\\", we should return a list of [2, 4].\\n\\n        Some examples:\\n        Mmmm  => []\\n        Super => [2,4]\\n        Apple => [1,5]\\n        YoMama -> [1,2,4,6]\\n\\n**NOTES:**\\n\\n* Vowels in this context refers to: a e i o u y (including upper case)\\n* This is indexed from `[1..n]` (not zero indexed!)\",\"targets\":\"vowel_indices=lambda w: [i+1 for i,k in enumerate(w) if k.lower() in \\\"aeiouy\\\"]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChef likes to play with big numbers. Today, he has a big positive integer N. He can select any two digits from this number (the digits can be same but their positions should be different) and orders them in any one of the two possible ways. For each of these ways, he creates a two digit number from it (might contain leading zeros). Then, he will pick a character corresponding to the ASCII value equal to this number, i.e. the number 65 corresponds to 'A', 66 to 'B' and so on till 90 for 'Z'. Chef is only interested in finding which of the characters in the range 'A' to 'Z' can possibly be picked this way. \\n\\n-----Input-----\\nThe first line of the input contains an integer T denoting the number of test cases.\\nThe first line of the input contains an integer N. \\n\\n-----Output-----\\nFor each test case, output a string containing characters Chef can pick in sorted order If the resulting size of string is zero, you should output a new line.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 10\\n- 1 ≤ N ≤ 10100000\\n\\n-----Subtasks-----\\n- Subtask #1 (40 points) N ≤ 1010\\n- Subtask #2 (60 points) Original Constraints\\n\\n-----Example-----\\nInput:\\n4\\n65\\n566\\n11\\n1623455078\\n\\nOutput:\\nA\\nAB\\n\\nACDFGHIJKLNPQRSTUVW\\n\\n-----Explanation-----\\nExample case 1. Chef can pick digits 6 and 5 and create integers 56 and 65. The integer 65 corresponds to 'A'.\\nExample case 2. Chef can pick digits 6 and 5 and create 'A' as it equals 65. He can pick 6 and 6 (they are picked from position 2 and position 3, respectively) to create 'B' too. Hence answer is \\\"AB\\\".\\nExample case 3. It's not possible to create any character from 'A' to 'Z'. Hence, we just print a new line.\",\"targets\":\"for t in range(int(input())):\\n word=input()\\n lis=list(word)\\n d={}\\n for l in range(10):\\n  d[l]=None\\n s=''\\n for w in lis:\\n  if d[int(w)]!=None:\\n   d[int(w)]+=1\\n  else:\\n   d[int(w)]=1\\n \\n for i in range(5,10):\\n  if d[i]!=None and i!=6 and d[6]!=None:\\n   s=s+chr(60+i)\\n  if d[i]!=None and d[i]>=2 and i==6:\\n   s=s+chr(60+i)\\n for i in range(10):\\n  if d[i]!=None and i!=7 and d[7]!=None:\\n   s=s+chr(70+i)\\n  if d[i]!=None and d[i]>=2 and i==7:\\n   s=s+chr(70+i)\\n for i in range(10):\\n  if d[i]!=None and i!=8 and d[8]!=None:\\n   s=s+chr(80+i)\\n  if d[i]!=None and d[i]>=2 and i==8:\\n   s=s+chr(80+i)\\n if d[9]!=None and d[0]!=None:\\n  s=s+chr(90)\\n if len(s)==0:\\n  print()\\n else:\\n  print(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nMobile Display Keystrokes\\n\\nDo you remember the old mobile display keyboards? Do you also remember how inconvenient it was to write on it?\\nWell, here you have to calculate how much keystrokes you have to do for a specific word.\\n\\nThis is the layout:\\n\\n\\n\\nReturn the amount of keystrokes of input str (! only letters, digits and special characters in lowercase included in layout without whitespaces !)\\n\\ne.g:\\n\\n\\nmobileKeyboard(\\\"123\\\") => 3 (1+1+1)\\nmobileKeyboard(\\\"abc\\\") => 9 (2+3+4)\\nmobileKeyboard(\\\"codewars\\\") => 26 (4+4+2+3+2+2+4+5)\",\"targets\":\"def mobile_keyboard(s):\\n    a = \\\"12abc3def4ghi5jkl6mno7pqrs8tuv9wxyz*0#\\\"\\n    b = \\\"11234123412341234123412345123412345111\\\"\\n    d = {x: int(y) for x, y in zip(a, b)}\\n    return sum(d[x] for x in s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nFurther research on zombie thought processes yielded interesting results. As we know from the previous problem, the nervous system of a zombie consists of n brains and m brain connectors joining some pairs of brains together. It was observed that the intellectual abilities of a zombie depend mainly on the topology of its nervous system. More precisely, we define the distance between two brains u and v (1 ≤ u, v ≤ n) as the minimum number of brain connectors used when transmitting a thought between these two brains. The brain latency of a zombie is defined to be the maximum distance between any two of its brains. Researchers conjecture that the brain latency is the crucial parameter which determines how smart a given zombie is. Help them test this conjecture by writing a program to compute brain latencies of nervous systems.\\n\\nIn this problem you may assume that any nervous system given in the input is valid, i.e., it satisfies conditions (1) and (2) from the easy version.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two space-separated integers n and m (1 ≤ n, m ≤ 100000) denoting the number of brains (which are conveniently numbered from 1 to n) and the number of brain connectors in the nervous system, respectively. In the next m lines, descriptions of brain connectors follow. Every connector is given as a pair of brains a b it connects (1 ≤ a, b ≤ n and a ≠ b).\\n\\n\\n-----Output-----\\n\\nPrint one number – the brain latency.\\n\\n\\n-----Examples-----\\nInput\\n4 3\\n1 2\\n1 3\\n1 4\\n\\nOutput\\n2\\nInput\\n5 4\\n1 2\\n2 3\\n3 4\\n3 5\\n\\nOutput\\n3\",\"targets\":\"n,m=map(int,input().split())\\n\\ngr=[[] for i in range(n)]\\n\\nfor i in range(m):\\n\\tu,v=map(int,input().split())\\n\\tgr[v-1].append(u-1)\\n\\tgr[u-1].append(v-1)\\n\\nv=[False for i in range(n)]\\ns=[0]\\ntr={}\\ntr[0]=0\\nwhile s:\\n\\tx=s.pop()\\n\\tv[x]=True\\n\\tfor j in gr[x]:\\n\\t\\tif v[j]:continue\\n\\t\\ts.append(j)\\n\\t\\ttr[j]=tr[x]+1\\nva=0\\nma=0\\nfor j in tr.keys():\\n\\tif ma<tr[j]:\\n\\t\\tma=tr[j]\\n\\t\\tva=j\\nv=[False for i in range(n)]\\ns=[va]\\ntr={}\\ntr[va]=0\\nwhile s:\\n\\tx=s.pop()\\n\\tv[x]=True\\n\\tfor i in gr[x]:\\n\\t\\tif v[i]:continue\\n\\t\\ts.append(i)\\n\\t\\ttr[i]=tr[x]+1\\nprint(max(tr.values()))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/903\\/B:\\nVova is again playing some computer game, now an RPG. In the game Vova's character received a quest: to slay the fearsome monster called Modcrab.\\n\\nAfter two hours of playing the game Vova has tracked the monster and analyzed its tactics. The Modcrab has h_2 health points and an attack power of a_2. Knowing that, Vova has decided to buy a lot of strong healing potions and to prepare for battle.\\n\\nVova's character has h_1 health points and an attack power of a_1. Also he has a large supply of healing potions, each of which increases his current amount of health points by c_1 when Vova drinks a potion. All potions are identical to each other. It is guaranteed that c_1 > a_2.\\n\\nThe battle consists of multiple phases. In the beginning of each phase, Vova can either attack the monster (thus reducing its health by a_1) or drink a healing potion (it increases Vova's health by c_1; Vova's health can exceed h_1). Then, if the battle is not over yet, the Modcrab attacks Vova, reducing his health by a_2. The battle ends when Vova's (or Modcrab's) health drops to 0 or lower. It is possible that the battle ends in a middle of a phase after Vova's attack.\\n\\nOf course, Vova wants to win the fight. But also he wants to do it as fast as possible. So he wants to make up a strategy that will allow him to win the fight after the minimum possible number of phases.\\n\\nHelp Vova to make up a strategy! You may assume that Vova never runs out of healing potions, and that he can always win.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers h_1, a_1, c_1 (1 ≤ h_1, a_1 ≤ 100, 2 ≤ c_1 ≤ 100) — Vova's health, Vova's attack power and the healing power of a potion.\\n\\nThe second line contains two integers h_2, a_2 (1 ≤ h_2 ≤ 100, 1 ≤ a_2 < c_1) — the Modcrab's health and his attack power.\\n\\n\\n-----Output-----\\n\\nIn the first line print one integer n denoting the minimum number of phases required to win the battle.\\n\\nThen print n lines. i-th line must be equal to HEAL if Vova drinks a potion in i-th phase, or STRIKE if he attacks the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"h1,a1,c1 = list(map(int,input().split()))\\nh2,a2 = list(map(int,input().split()))\\nactions = [0]*10000\\nj = 0\\n\\nwhile h2 >= 0:\\n    if h2 <= a1:\\n        actions[j] = 1\\n        j += 1\\n        break\\n    if h1 <= a2:\\n        actions[j] = 2\\n        j += 1\\n        h1 += c1 - a2\\n        continue\\n    actions[j] = 1\\n    j += 1\\n    h1 -= a2\\n    h2 -= a1\\n\\nprint(j)\\nfor i in range(j):\\n    if actions[i] == 1:\\n        print(\\\"STRIKE\\\")\\n    elif actions[i] == 2:\\n        print(\\\"HEAL\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a string s consisting only of characters 0 and 1. A substring [l, r] of s is a string s_{l}s_{l} + 1s_{l} + 2... s_{r}, and its length equals to r - l + 1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.\\n\\nYou have to determine the length of the longest balanced substring of s.\\n\\n\\n-----Input-----\\n\\nThe first line contains n (1 ≤ n ≤ 100000) — the number of characters in s.\\n\\nThe second line contains a string s consisting of exactly n characters. Only characters 0 and 1 can appear in s.\\n\\n\\n-----Output-----\\n\\nIf there is no non-empty balanced substring in s, print 0. Otherwise, print the length of the longest balanced substring.\\n\\n\\n-----Examples-----\\nInput\\n8\\n11010111\\n\\nOutput\\n4\\n\\nInput\\n3\\n111\\n\\nOutput\\n0\\n\\n\\n\\n-----Note-----\\n\\nIn the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.\\n\\nIn the second example it's impossible to find a non-empty balanced substring.\",\"targets\":\"n=int(input())\\nstrs=input()\\ncounta=[]\\ncountb=[]\\nno1=0\\nno0=0\\ni=0\\nwhile(i<len(strs)):\\n    if(strs[i]=='1'):\\n        no1+=1\\n    else:\\n        no0+=1\\n    counta.append(no1)\\n    countb.append(no0)\\n    i+=1\\nhashd=dict()\\nhashd[0]=[-1]\\ni=0\\nmaxm=0\\nwhile(i<len(strs)):\\n    if((counta[i]-countb[i]) in hashd):\\n        hashd[(counta[i]-countb[i])].append(i)\\n        if(i-hashd[(counta[i]-countb[i])][0]>maxm):\\n            maxm=i-hashd[(counta[i]-countb[i])][0]\\n    else:\\n        hashd[counta[i]-countb[i]]=[i]\\n    i+=1\\nprint(maxm)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1314\\/B:\\nThe biggest event of the year – Cota 2 world championship \\\"The Innernational\\\" is right around the corner. $2^n$ teams will compete in a double-elimination format (please, carefully read problem statement even if you know what is it) to identify the champion. \\n\\nTeams are numbered from $1$ to $2^n$ and will play games one-on-one. All teams start in the upper bracket.\\n\\nAll upper bracket matches will be held played between teams that haven't lost any games yet. Teams are split into games by team numbers. Game winner advances in the next round of upper bracket, losers drop into the lower bracket.\\n\\nLower bracket starts with $2^{n-1}$ teams that lost the first upper bracket game. Each lower bracket round consists of two games. In the first game of a round $2^k$ teams play a game with each other (teams are split into games by team numbers). $2^{k-1}$ loosing teams are eliminated from the championship, $2^{k-1}$ winning teams are playing $2^{k-1}$ teams that got eliminated in this round of upper bracket (again, teams are split into games by team numbers). As a result of each round both upper and lower bracket have $2^{k-1}$ teams remaining. See example notes for better understanding.\\n\\nSingle remaining team of upper bracket plays with single remaining team of lower bracket in grand-finals to identify championship winner.\\n\\nYou are a fan of teams with numbers $a_1, a_2, ..., a_k$. You want the championship to have as many games with your favourite teams as possible. Luckily, you can affect results of every championship game the way you want. What's maximal possible number of championship games that include teams you're fan of?\\n\\n\\n-----Input-----\\n\\nFirst input line has two integers $n, k$ — $2^n$ teams are competing in the championship. You are a fan of $k$ teams ($2 \\\\le n \\\\le 17; 0 \\\\le k \\\\le 2^n$).\\n\\nSecond input line has $k$ distinct integers $a_1, \\\\ldots, a_k$ — numbers of teams you're a fan of ($1 \\\\le a_i \\\\le 2^n$).\\n\\n\\n-----Output-----\\n\\nOutput single integer — maximal possible number of championship games that include...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\nn,k=list(map(int,input().split()))\\nif k==0:\\n    print(0)\\n    return\\n\\nA=sorted(map(int,input().split()))\\n\\n# DP[UL][n][left]\\n# [left*pow(2,n),left*pow(2,n)+pow(2,n))の間のチームで,\\n# ファンのチームが\\n# UL=0: upperでもlowerでも勝ち残っている\\n# UL=1: upperでのみ勝ち残っている\\n# UL=2: lowerでのみ勝ち残っている\\n# ときの、そこまでのファンのチームの試合数の最大値.\\n\\nDP=[[[0]*((1<<n)+2) for i in range(n+1)] for UL in range(3)]\\n\\nfor i in range(k):\\n    if A[i]%2==1:\\n        DP[1][1][A[i]]=1\\n        DP[2][1][A[i]]=1\\n    else:\\n        DP[1][1][A[i]-1]=1\\n        DP[2][1][A[i]-1]=1\\n\\n    if i<k-1 and A[i]%2==1 and A[i+1]==A[i]+1:\\n        DP[0][1][A[i]]=1\\n        \\nfor i in range(2,n+1):\\n    for left in range(1,(1<<n)+1,1<<i):\\n\\n        if DP[0][i-1][left]:\\n            DP[0][i][left]=max(DP[0][i-1][left] + DP[0][i-1][left+(1<<(i-1))] + 3,DP[0][i-1][left] + DP[1][i-1][left+(1<<(i-1))] + 3,\\\\\\n                               DP[0][i-1][left] + DP[2][i-1][left+(1<<(i-1))] + 3)\\n            \\n        if DP[0][i-1][left+(1<<(i-1))]:\\n            DP[0][i][left]=max(DP[0][i][left], DP[0][i-1][left] + DP[0][i-1][left+(1<<(i-1))] + 3,\\\\\\n                               DP[1][i-1][left] + DP[0][i-1][left+(1<<(i-1))] + 3,DP[2][i-1][left] + DP[0][i-1][left+(1<<(i-1))] + 3)\\n\\n        if DP[1][i-1][left]:\\n            DP[1][i][left]=max(DP[1][i][left], DP[1][i-1][left] + 1)\\n            DP[2][i][left]=max(DP[2][i][left], DP[1][i-1][left] + 2)\\n\\n        if DP[2][i-1][left]:\\n            DP[2][i][left]=max(DP[2][i][left], DP[2][i-1][left] + 2)\\n\\n        if DP[1][i-1][left+(1<<(i-1))]:\\n            DP[1][i][left]=max(DP[1][i][left], DP[1][i-1][left+(1<<(i-1))] + 1)\\n            DP[2][i][left]=max(DP[2][i][left], DP[1][i-1][left+(1<<(i-1))] + 2)\\n\\n        if DP[2][i-1][left+(1<<(i-1))]:\\n            DP[2][i][left]=max(DP[2][i][left], DP[2][i-1][left+(1<<(i-1))] + 2)\\n\\n\\n        if DP[1][i-1][left] and DP[1][i-1][left+(1<<(i-1))]:\\n            DP[0][i][left]=max(DP[0][i][left], DP[1][i-1][left] + DP[1][i-1][left+(1<<(i-1))] + 2)\\n\\n        if DP[1][i-1][left] and DP[2][i-1][left+(1<<(i-1))]:\\n         ...\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a7893ef0025e9eb50000013:\\n# Introduction and Warm-up (Highly recommended)\\n\\n# [Playing With Lists\\/Arrays Series](https:\\/\\/www.codewars.com\\/collections\\/playing-with-lists-slash-arrays)\\n___\\n\\n# Task\\n\\n**_Given_** an *array\\/list [] of integers* , **_Find_** **_The maximum difference_** *between the successive elements in its sorted form*. \\n___\\n\\n# Notes \\n\\n* **_Array\\/list_** size is *at least 3*  .\\n\\n* **_Array\\/list's numbers_**  Will be **mixture of positives and negatives also zeros_**  \\n\\n* **_Repetition_** of numbers in *the array\\/list could occur*.\\n\\n* **_The Maximum Gap_** is *computed Regardless the sign*.\\n\\n___\\n\\n# Input >> Output Examples \\n\\n```\\nmaxGap ({13,10,5,2,9}) ==> return (4)\\n```\\n\\n## **_Explanation_**: \\n\\n* **_The Maximum Gap_** *after sorting the array is* `4` , *The difference between*   ``` 9 - 5 = 4 ``` .\\n___\\n\\n```\\nmaxGap ({-3,-27,-4,-2}) ==> return (23)\\n```\\n## **_Explanation_**: \\n\\n* **_The Maximum Gap_** *after sorting the array is* `23` , *The difference between*   ` |-4- (-27) | = 23` .\\n\\n*  **_Note_** : *Regardless the sign of negativity* .\\n___\\n\\n```\\nmaxGap ({-7,-42,-809,-14,-12}) ==> return (767)  \\n```\\n## **_Explanation_**: \\n\\n* **_The Maximum Gap_** *after sorting the array is* `767` , *The difference between*   ` | -809- (-42) | = 767` .\\n\\n*  **_Note_** : *Regardless the sign of negativity* .\\n___\\n\\n```\\nmaxGap ({-54,37,0,64,640,0,-15}) \\/\\/return (576)\\n```\\n## **_Explanation_**: \\n\\n* **_The Maximum Gap_** *after sorting the array is* `576` , *The difference between*   ` | 64 - 640 | = 576` .\\n\\n*  **_Note_** : *Regardless the sign of negativity* .\\n___\\n___\\n___\\n\\n# [Playing with Numbers Series](https:\\/\\/www.codewars.com\\/collections\\/playing-with-numbers)\\n\\n# [Playing With Lists\\/Arrays Series](https:\\/\\/www.codewars.com\\/collections\\/playing-with-lists-slash-arrays)\\n\\n# [For More Enjoyable Katas](http:\\/\\/www.codewars.com\\/users\\/MrZizoScream\\/authored)\\n___\\n\\n## ALL translations are welcomed\\n\\n## Enjoy Learning !!\\n# Zizou\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def max_gap(n):\\n    n.sort()\\n    return max(a-b for a, b in zip(n[1:], n))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWrite a function, that doubles every second integer in a list starting from the left.\",\"targets\":\"def double_every_other(lst):\\n    for ind, item in enumerate(lst):\\n        if ind % 2 != 0:\\n            lst[ind] = item*2\\n    return lst\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/589aca25fef1a81a10000057:\\n# Task\\n You are given an array of integers `a` and a non-negative number of operations `k`, applied to the array. Each operation consists of two parts:\\n```\\nfind the maximum element value of the array;\\nreplace each element a[i] with (maximum element value - a[i]).```\\nHow will the array look like after `k` such operations?\\n\\n# Example\\n\\n For `a = [-4, 0, -1, 0]` and `k = 2`, the output should be `[0, 4, 3, 4]`.\\n ```\\n initial array: [-4, 0, -1, 0]\\n 1st operation: \\n find the maximum value --> 0\\n replace each element:  --> [(0 - -4), (0 - 0), (0 - -1), (0 - 0)]\\n                        --> [4, 0, 1, 0]\\n 2nd operation: \\n find the maximum value --> 4\\n replace each element:  --> [(4 - 4), (4 - 0), (4 - 1), (4 - 0)]\\n                        --> [0, 4, 3, 4]\\n \\n ```\\n For `a = [0, -1, 0, 0, -1, -1, -1, -1, 1, -1]` and `k = 1`, \\n \\n the output should be `[1, 2, 1, 1, 2, 2, 2, 2, 0, 2]`.\\n ```\\n initial array: [0, -1, 0, 0, -1, -1, -1, -1, 1, -1]\\n 1st operation: \\n find the maximum value --> 1\\n replace each element:  -->\\n [(1-0),(1- -1),(1-0),(1-0),(1- -1),(1- -1),(1- -1),(1- -1),(1-1),(1- -1)]\\n--> [1, 2, 1, 1, 2, 2, 2, 2, 0, 2]\\n ```\\n\\n# Input\\/Output\\n\\n\\n - `[input]` integer array a\\n\\n    The initial array.\\n\\n    Constraints: \\n\\n    `1 <= a.length <= 100`\\n    \\n    `-100 <= a[i] <= 100`\\n\\n\\n - `[input]` integer `k`\\n\\n    non-negative number of operations.\\n\\n    Constraints: `0 <= k <= 100000`\\n\\n\\n - [output] an integer array\\n\\n    The array after `k` operations.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def array_operations(a, n):\\n  li = []\\n  for i in range(n):\\n        m = max(a)\\n        a = [m-i for i in a] \\n        if a in li:\\n            if not n & 1 : return li[-1]\\n            return a\\n        li.append(a)\\n  return a\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc161\\/tasks\\/abc161_b:\\nWe have held a popularity poll for N items on sale. Item i received A_i votes.\\nFrom these N items, we will select M as popular items. However, we cannot select an item with less than \\\\dfrac{1}{4M} of the total number of votes.\\nIf M popular items can be selected, print Yes; otherwise, print No.\\n\\n-----Constraints-----\\n - 1 \\\\leq M \\\\leq N \\\\leq 100\\n - 1 \\\\leq A_i \\\\leq 1000\\n - A_i are distinct.\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M\\nA_1 ... A_N\\n\\n-----Output-----\\nIf M popular items can be selected, print Yes; otherwise, print No.\\n\\n-----Sample Input-----\\n4 1\\n5 4 2 1\\n\\n-----Sample Output-----\\nYes\\n\\nThere were 12 votes in total. The most popular item received 5 votes, and we can select it.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N, M = map(int, input().split())\\n\\nA = list(map(int, input().split()))\\n\\nsums = sum(A)\\n\\nA.sort(reverse=True)\\n\\n\\nif 4*M*A[M-1] >= sums:\\n    print('Yes')\\nelse:\\n    print('No')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/723\\/B:\\nModern text editors usually show some information regarding the document being edited. For example, the number of words, the number of pages, or the number of characters.\\n\\nIn this problem you should implement the similar functionality.\\n\\nYou are given a string which only consists of:  uppercase and lowercase English letters,  underscore symbols (they are used as separators),  parentheses (both opening and closing). \\n\\nIt is guaranteed that each opening parenthesis has a succeeding closing parenthesis. Similarly, each closing parentheses has a preceding opening parentheses matching it. For each pair of matching parentheses there are no other parenthesis between them. In other words, each parenthesis in the string belongs to a matching \\\"opening-closing\\\" pair, and such pairs can't be nested.\\n\\nFor example, the following string is valid: \\\"_Hello_Vasya(and_Petya)__bye_(and_OK)\\\".\\n\\nWord is a maximal sequence of consecutive letters, i.e. such sequence that the first character to the left and the first character to the right of it is an underscore, a parenthesis, or it just does not exist. For example, the string above consists of seven words: \\\"Hello\\\", \\\"Vasya\\\", \\\"and\\\", \\\"Petya\\\", \\\"bye\\\", \\\"and\\\" and \\\"OK\\\". Write a program that finds:  the length of the longest word outside the parentheses (print 0, if there is no word outside the parentheses),  the number of words inside the parentheses (print 0, if there is no word inside the parentheses). \\n\\n\\n-----Input-----\\n\\nThe first line of the input contains a single integer n (1 ≤ n ≤ 255) — the length of the given string. The second line contains the string consisting of only lowercase and uppercase English letters, parentheses and underscore symbols. \\n\\n\\n-----Output-----\\n\\nPrint two space-separated integers:  the length of the longest word outside the parentheses (print 0, if there is no word outside the parentheses),  the number of words inside the parentheses (print 0, if there is no word inside the parentheses)....\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"input()\\ns = input()\\n\\nw, maxp = 0, 0\\ncur = 0\\ninp = False\\nfor c in s:\\n    if c.isalpha():\\n        cur += 1\\n    elif cur > 0:\\n        if inp:\\n            w += 1\\n        cur = 0\\n    if c == \\\"(\\\":\\n        inp = True\\n    if c == \\\")\\\":\\n        inp = False\\n    if not inp and cur > maxp:\\n        maxp = cur\\nprint(maxp, w)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven is a string S representing the day of the week today.\\nS is SUN, MON, TUE, WED, THU, FRI, or SAT, for Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday, respectively.\\nAfter how many days is the next Sunday (tomorrow or later)?\\n\\n-----Constraints-----\\n - S is SUN, MON, TUE, WED, THU, FRI, or SAT.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nS\\n\\n-----Output-----\\nPrint the number of days before the next Sunday.\\n\\n-----Sample Input-----\\nSAT\\n\\n-----Sample Output-----\\n1\\n\\nIt is Saturday today, and tomorrow will be Sunday.\",\"targets\":\"s = input()\\n\\nweek = ['SUN','MON','TUE','WED','THU','FRI','SAT']\\nn = week.index(s)\\n\\nprint(7-n)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/359\\/B:\\nA permutation p is an ordered group of numbers p_1,   p_2,   ...,   p_{n}, consisting of n distinct positive integers, each is no more than n. We'll define number n as the length of permutation p_1,   p_2,   ...,   p_{n}.\\n\\nSimon has a positive integer n and a non-negative integer k, such that 2k ≤ n. Help him find permutation a of length 2n, such that it meets this equation: $\\\\sum_{i = 1}^{n}|a_{2 i - 1} - a_{2i}|-|\\\\sum_{i = 1}^{n} a_{2 i - 1} - a_{2i}|= 2 k$.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers n and k (1 ≤ n ≤ 50000, 0 ≤ 2k ≤ n).\\n\\n\\n-----Output-----\\n\\nPrint 2n integers a_1, a_2, ..., a_2n — the required permutation a. It is guaranteed that the solution exists. If there are multiple solutions, you can print any of them.\\n\\n\\n-----Examples-----\\nInput\\n1 0\\n\\nOutput\\n1 2\\nInput\\n2 1\\n\\nOutput\\n3 2 1 4\\n\\nInput\\n4 0\\n\\nOutput\\n2 7 4 6 1 3 5 8\\n\\n\\n\\n-----Note-----\\n\\nRecord |x| represents the absolute value of number x. \\n\\nIn the first sample |1 - 2| - |1 - 2| = 0.\\n\\nIn the second sample |3 - 2| + |1 - 4| - |3 - 2 + 1 - 4| = 1 + 3 - 2 = 2.\\n\\nIn the third sample |2 - 7| + |4 - 6| + |1 - 3| + |5 - 8| - |2 - 7 + 4 - 6 + 1 - 3 + 5 - 8| = 12 - 12 = 0.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def main():\\n    n, k = [int(x) for x in input().split()]\\n    for i in range(n):\\n        if k > 0:\\n            print(2*i + 1, 2*i + 2, end=' ')\\n            k -= 1\\n        else:\\n            print(2*i + 2, 2*i + 1, end=' ')\\n\\n\\n\\ndef __starting_point():\\n    main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1372\\/E:\\nOmkar is building a house. He wants to decide how to make the floor plan for the last floor.\\n\\nOmkar's floor starts out as $n$ rows of $m$ zeros ($1 \\\\le n,m \\\\le 100$). Every row is divided into intervals such that every $0$ in the row is in exactly $1$ interval. For every interval for every row, Omkar can change exactly one of the $0$s contained in that interval to a $1$. Omkar defines the quality of a floor as the sum of the squares of the sums of the values in each column, i. e. if the sum of the values in the $i$-th column is $q_i$, then the quality of the floor is $\\\\sum_{i = 1}^m q_i^2$.\\n\\nHelp Omkar find the maximum quality that the floor can have.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers, $n$ and $m$ ($1 \\\\le n,m \\\\le 100$), which are the number of rows and number of columns, respectively.\\n\\nYou will then receive a description of the intervals in each row. For every row $i$ from $1$ to $n$: The first row contains a single integer $k_i$ ($1 \\\\le k_i \\\\le m$), which is the number of intervals on row $i$. The $j$-th of the next $k_i$ lines contains two integers $l_{i,j}$ and $r_{i,j}$, which are the left and right bound (both inclusive), respectively, of the $j$-th interval of the $i$-th row. It is guaranteed that all intervals other than the first interval will be directly after the interval before it. Formally, $l_{i,1} = 1$, $l_{i,j} \\\\leq r_{i,j}$ for all $1 \\\\le j \\\\le k_i$, $r_{i,j-1} + 1 = l_{i,j}$ for all $2 \\\\le j \\\\le k_i$, and $r_{i,k_i} = m$.\\n\\n\\n-----Output-----\\n\\nOutput one integer, which is the maximum possible quality of an eligible floor plan.\\n\\n\\n-----Example-----\\nInput\\n4 5\\n2\\n1 2\\n3 5\\n2\\n1 3\\n4 5\\n3\\n1 1\\n2 4\\n5 5\\n3\\n1 1\\n2 2\\n3 5\\n\\nOutput\\n36\\n\\n\\n\\n-----Note-----\\n\\nThe given test case corresponds to the following diagram. Cells in the same row and have the same number are a part of the same interval.\\n\\n [Image] \\n\\nThe most optimal assignment is:\\n\\n [Image] \\n\\nThe sum of the $1$st column is $4$, the sum of the $2$nd column is $2$, the sum of the $3$rd and $4$th columns are $0$, and the sum of the $5$th column...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ndef rs(): return sys.stdin.readline().rstrip()\\ndef ri(): return int(sys.stdin.readline())\\ndef ria(): return list(map(int, sys.stdin.readline().split()))\\ndef ws(s): sys.stdout.write(s); sys.stdout.write('\\\\n')\\ndef wi(n): sys.stdout.write(str(n)); sys.stdout.write('\\\\n')\\ndef wia(a, sep=' '): sys.stdout.write(sep.join([str(x) for x in a])); sys.stdout.write('\\\\n')\\n\\n\\nfrom functools import lru_cache\\n\\n\\ndef solve(n, m, a):\\n\\n    b = [[] for _ in range(m)]\\n    for j in range(m):\\n        for l, r, i in a:\\n            if l <= j <= r:\\n                b[j].append((l, r, i))\\n\\n    @lru_cache(maxsize=None)\\n    def go(left, right):\\n        if left > right:\\n            return 0\\n\\n        best = 0\\n        for mid in range(left, right + 1):\\n            cnt = 0\\n            for l, r, i in b[mid]:\\n                if l <= mid <= r and l >= left and r <= right:\\n                    cnt += 1\\n\\n            best = max(best, cnt * cnt + go(left, mid - 1) + go(mid + 1, right))\\n\\n        return best\\n\\n    return go(0, m-1)\\n\\n\\ndef main():\\n    n, m = ria()\\n    a = set()\\n    for i in range(n):\\n        k = ri()\\n        for j in range(k):\\n            l, r = ria()\\n            l -= 1\\n            r -= 1\\n            a.add((l, r, i))\\n\\n    wi(solve(n, m, a))\\n\\n\\ndef __starting_point():\\n    main()\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5264f5685fda8ed370000265:\\nScientists working internationally use metric units almost exclusively. Unless that is, they wish to crash multimillion dollars worth of equipment on Mars.\\n\\nYour task is to write a simple function that takes a number of meters, and outputs it using metric prefixes.\\n\\nIn practice, meters are only measured in \\\"mm\\\" (thousandths of a meter), \\\"cm\\\" (hundredths of a meter), \\\"m\\\" (meters) and \\\"km\\\" (kilometers, or clicks for the US military).\\n\\nFor this exercise we just want units bigger than a meter, from meters up to yottameters, excluding decameters and hectometers.\\n\\nAll values passed in will be positive integers.\\ne.g.\\n\\n```python\\nmeters(5);\\n\\/\\/ returns \\\"5m\\\"\\n\\nmeters(51500);\\n\\/\\/ returns \\\"51.5km\\\"\\n\\nmeters(5000000);\\n\\/\\/ returns \\\"5Mm\\\"\\n```\\n\\nSee http:\\/\\/en.wikipedia.org\\/wiki\\/SI_prefix for a full list of prefixes\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import log\\ndef meters(x):\\n    prefixes = ['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y']\\n    order = int(log(x, 1000))\\n    return \\\"{:g}{}m\\\".format(x \\/ (1000**order or 1), prefixes[order])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/arc104\\/tasks\\/arc104_b:\\nWe have a string S of length N consisting of A, T, C, and G.\\nStrings T_1 and T_2 of the same length are said to be complementary when, for every i (1 \\\\leq i \\\\leq l), the i-th character of T_1 and the i-th character of T_2 are complementary. Here, A and T are complementary to each other, and so are C and G.\\nFind the number of non-empty contiguous substrings T of S that satisfies the following condition:\\n - There exists a string that is a permutation of T and is complementary to T.\\nHere, we distinguish strings that originate from different positions in S, even if the contents are the same.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 5000\\n - S consists of A, T, C, and G.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN S\\n\\n-----Output-----\\nPrint the number of non-empty contiguous substrings T of S that satisfies the condition.\\n\\n-----Sample Input-----\\n4 AGCT\\n\\n-----Sample Output-----\\n2\\n\\nThe following two substrings satisfy the condition:\\n - GC (the 2-nd through 3-rd characters) is complementary to CG, which is a permutation of GC.\\n - AGCT (the 1-st through 4-th characters) is complementary to TCGA, which is a permutation of AGCT.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n# sys.setrecursionlimit(10**6)\\n\\ndef inp():\\n    return int(input())\\ndef inps():\\n    return input().rstrip()\\ndef inpl():\\n    return list(map(int, input().split()))\\ndef inpls():\\n    return list(map(str, input().split()))\\n\\n# import decimal\\n# from decimal import Decimal\\n# decimal.getcontext().prec = 10\\n\\n# from heapq import heappush, heappop, heapify\\n# import math\\nfrom math import gcd, floor, ceil, factorial\\nimport itertools as it\\nfrom collections import deque, defaultdict\\nfrom collections import Counter\\n\\ndef lcd(a, b):\\n    return a * b \\/\\/ gcd(a, b)\\n\\ndef chmin(dp, i, x):\\n    if x < dp[i]: dp[i] = x; return True\\n    return False\\n\\ndef chmax(dp, i, x): \\n    if x > dp[i]: dp[i] = x; return True\\n    return False\\n\\n# ---------------------------------------\\n\\nN, S = input().split()\\nN = int(N)\\nS = S.rstrip()\\n\\nA = [0] * (N + 1)\\nT = [0] * (N + 1)\\nC = [0] * (N + 1)\\nG = [0] * (N + 1)\\nfor i in range(N):\\n    s = S[i]\\n    A[i+1] = A[i] + (1 if s == \\\"A\\\" else 0)  \\n    T[i+1] = T[i] + (1 if s == \\\"T\\\" else 0)\\n    C[i+1] = C[i] + (1 if s == \\\"C\\\" else 0)\\n    G[i+1] = G[i] + (1 if s == \\\"G\\\" else 0)\\n\\nans = 0\\nfor i in range(N):\\n    j = i + 2\\n    while j <= N:\\n        if A[j] - A[i] == T[j] - T[i] and C[j] - C[i] == G[j] - G[i]:\\n            ans += 1\\n        j += 2\\n            \\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc062\\/tasks\\/abc062_a:\\nBased on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below.\\nGiven two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.\\n\\n-----Constraints-----\\n - x and y are integers.\\n - 1 ≤ x < y ≤ 12\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nx y\\n\\n-----Output-----\\nIf x and y belong to the same group, print Yes; otherwise, print No.\\n\\n-----Sample Input-----\\n1 3\\n\\n-----Sample Output-----\\nYes\\n\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"x,y=map(int,input().split())\\n\\nn=[0,1,3,1,2,1,2,1,1,2,1,2,1]\\n\\nif n[x]==n[y]:\\n    ans=\\\"Yes\\\"\\nelse:\\n    ans=\\\"No\\\"\\n            \\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nToday, Yasser and Adel are at the shop buying cupcakes. There are $n$ cupcake types, arranged from $1$ to $n$ on the shelf, and there are infinitely many of each type. The tastiness of a cupcake of type $i$ is an integer $a_i$. There are both tasty and nasty cupcakes, so the tastiness can be positive, zero or negative.\\n\\nYasser, of course, wants to try them all, so he will buy exactly one cupcake of each type.\\n\\nOn the other hand, Adel will choose some segment $[l, r]$ $(1 \\\\le l \\\\le r \\\\le n)$ that does not include all of cupcakes (he can't choose $[l, r] = [1, n]$) and buy exactly one cupcake of each of types $l, l + 1, \\\\dots, r$.\\n\\nAfter that they will compare the total tastiness of the cupcakes each of them have bought. Yasser will be happy if the total tastiness of cupcakes he buys is strictly greater than the total tastiness of cupcakes Adel buys regardless of Adel's choice.\\n\\nFor example, let the tastinesses of the cupcakes be $[7, 4, -1]$. Yasser will buy all of them, the total tastiness will be $7 + 4 - 1 = 10$. Adel can choose segments $[7], [4], [-1], [7, 4]$ or $[4, -1]$, their total tastinesses are $7, 4, -1, 11$ and $3$, respectively. Adel can choose segment with tastiness $11$, and as $10$ is not strictly greater than $11$, Yasser won't be happy :(\\n\\nFind out if Yasser will be happy after visiting the shop.\\n\\n\\n-----Input-----\\n\\nEach test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \\\\le t \\\\le 10^4$). The description of the test cases follows.\\n\\nThe first line of each test case contains $n$ ($2 \\\\le n \\\\le 10^5$).\\n\\nThe second line of each test case contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($-10^9 \\\\le a_i \\\\le 10^9$), where $a_i$ represents the tastiness of the $i$-th type of cupcake.\\n\\nIt is guaranteed that the sum of $n$ over all test cases doesn't exceed $10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case, print \\\"YES\\\", if the total tastiness of cupcakes Yasser buys will always be strictly greater than the total tastiness of cupcakes Adel buys regardless of Adel's...\",\"targets\":\"# = map(int, input().split())\\n# = list(map(int, input().split()))\\nt = int(input())\\nfor _ in range(t):\\n    n = int(input())\\n    z = list(map(int, input().split()))\\n    sm = sum(z)\\n    maxsum = 0\\n    minpref = 0\\n    curpref = 0\\n    for a in z[:-1]:\\n        curpref += a\\n        if curpref - minpref > maxsum:\\n            maxsum = curpref - minpref\\n        minpref = min(minpref, curpref)\\n    minpref = 0\\n    curpref = 0\\n    for a in z[1:]:\\n        curpref += a\\n        if curpref - minpref > maxsum:\\n            maxsum = curpref - minpref\\n        minpref = min(minpref, curpref)\\n    if maxsum < sm:\\n        print('YES')\\n    else:\\n        print('NO')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven two arrays `a` and `b` write a function `comp(a, b)` (`compSame(a, b)` in Clojure) that checks whether the two arrays have the \\\"same\\\" elements, with the same multiplicities. \\\"Same\\\" means, here, that the elements in `b` are the elements in `a` squared, regardless of the order.\\n\\n## Examples\\n## Valid arrays\\n```\\na = [121, 144, 19, 161, 19, 144, 19, 11]  \\nb = [121, 14641, 20736, 361, 25921, 361, 20736, 361]\\n```\\n`comp(a, b)` returns true because in `b` 121 is the square of 11, 14641 is the square of 121, 20736 the square of 144, 361 the square of 19, 25921 the square of 161, and so on. It gets obvious if we write `b`'s elements in terms of squares:\\n```\\na = [121, 144, 19, 161, 19, 144, 19, 11] \\nb = [11*11, 121*121, 144*144, 19*19, 161*161, 19*19, 144*144, 19*19]\\n```\\n### Invalid arrays\\nIf we change the first number to something else, `comp` may not return true anymore:\\n```\\na = [121, 144, 19, 161, 19, 144, 19, 11]  \\nb = [132, 14641, 20736, 361, 25921, 361, 20736, 361]\\n```\\n`comp(a,b)` returns false because in `b` 132 is not the square of any number of `a`.\\n```\\na = [121, 144, 19, 161, 19, 144, 19, 11]  \\nb = [121, 14641, 20736, 36100, 25921, 361, 20736, 361]\\n```\\n`comp(a,b)` returns false because in `b` 36100 is not the square of any number of `a`.\\n\\n## Remarks\\n- `a` or `b` might be `[]` (all languages except R, Shell).\\n- `a` or `b` might be `nil` or `null` or `None` or `nothing` (except in Haskell, Elixir, C++, Rust, R, Shell, PureScript). \\n\\nIf `a` or `b` are `nil` (or `null` or `None`), the problem doesn't make sense so return false.\\n\\n#### Note for C\\nThe two arrays have the same size `(> 0)` given as parameter in function `comp`.\",\"targets\":\"def comp(array1, array2):\\n    return None not in (array1, array2) and sum([i*i for i in array1]) == sum(array2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are N empty boxes arranged in a row from left to right.\\nThe integer i is written on the i-th box from the left (1 \\\\leq i \\\\leq N).\\nFor each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.\\nWe say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:\\n - For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.\\nDoes there exist a good set of choices? If the answer is yes, find one good set of choices.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq N \\\\leq 2 \\\\times 10^5\\n - a_i is 0 or 1.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\na_1 a_2 ... a_N\\n\\n-----Output-----\\nIf a good set of choices does not exist, print -1.\\nIf a good set of choices exists, print one such set of choices in the following format:\\nM\\nb_1 b_2 ... b_M\\n\\nwhere M denotes the number of boxes that will contain a ball, and b_1,\\\\ b_2,\\\\ ...,\\\\ b_M are the integers written on these boxes, in any order.\\n\\n-----Sample Input-----\\n3\\n1 0 0\\n\\n-----Sample Output-----\\n1\\n1\\n\\nConsider putting a ball only in the box with 1 written on it.\\n - There are three boxes with multiples of 1 written on them: the boxes with 1, 2, and 3. The total number of balls contained in these boxes is 1.\\n - There is only one box with a multiple of 2 written on it: the box with 2. The total number of balls contained in these boxes is 0.\\n - There is only one box with a multiple of 3 written on it: the box with 3. The total number of balls contained in these boxes is 0.\\nThus, the condition is satisfied, so this set of choices is good.\",\"targets\":\"icase=0\\nif icase==0:\\n    n=int(input())\\n    a=[0]+list(map(int,input().split()))\\nelif icase==3:\\n    f=open(r\\\"C:\\\\Users\\\\nishi\\\\999atcoder\\\\ABCD040-151\\\\ABC134D\\\\testcase_12.in\\\")\\n    ll=f.readline()\\n    n=int(ll)\\n    ll=f.readline()\\n    a=[0]+list(map(int,ll.split()))\\n    f.close()\\nb=[0]*(n+1)\\nfor i in range(n\\/\\/2+1,n+1):\\n    b[i]=a[i]\\n#    print(i,a[i])\\n    \\nfor i in range(n\\/\\/2,0,-1):\\n    i2=i*2\\n    asum=0\\n    while i2<=n:\\n        asum+=b[i2]\\n        i2+=i\\n    b[i]=(asum+a[i])%2\\n#    print(i,b[i],a[i],asum)\\n    \\nprint(sum(b))\\nfor i in range(1,len(b)):\\n    if b[i]==1:\\n        print(i,end=\\\" \\\")\\nprint(\\\" \\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/CFW32020\\/problems\\/OMGO:\\nYou came across this story while reading a book. Long a ago when the modern entertainment systems did not exist people used to go to watch plays in theaters, where people would perform live in front of an audience. There was a beautiful actress who had a disability she could not pronounce the character $'r'$. To win her favours which many have been denied in past, you decide to write a whole play without the character $'r'$. Now you have to get the script reviewed by the editor before presenting it to her.\\nThe editor was flattered by the script and agreed to you to proceed. The editor will edit the script in this way to suit her style. For each word replace it with a sub-sequence of itself such that it contains the character 'a'. \\nA subsequence is a sequence that can be derived from another sequence by deleting some or no elements without changing the order of the remaining elements Wikipedia \\nNow given a script with $N$ words, for each word in the script you wish to know the number of subsequences with which it can be replaced. \\n\\n-----Input:-----\\n- First-line will contain $N$, the number of words in the script. Then next $N$ line with one test case each. \\n- Each test case contains a single word $W_i$\\n\\n-----Output:-----\\nFor each test case, output in a single line number of subsequences with which it can be replaced. \\n\\n-----Constraints-----\\n- $1 \\\\leq N \\\\leq 1000$\\n- $1 \\\\leq$ length of $W_i$  $\\\\leq 20$\\n- $W_i$  on contains lowercase english alphabets and does not have the character 'r'\\n\\n-----Sample Input 1:-----\\n2\\nabc\\naba\\n\\n-----Sample Output 1:-----\\n4\\n6\\n\\n-----EXPLANATION:-----\\nThis subsequences with which $abc$ can be replaed : ${a,ab,ac,abc}$. \\nThis subsequences with which $aba$ can be replaed : ${a,ab,aba,a,ba,a}$. \\n\\n-----Sample Input 2:-----\\n3\\nabcde\\nabcdea\\nxyz\\n\\n-----Sample Output 2:-----\\n16\\n48\\n0\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nn = int(input())\\nfor i in range(n):\\n    w = input()\\n    l = len(w)\\n    s = 0\\n    a = 0\\n    for i in w:\\n        if i == 'a':\\n            a += 1\\n            s += 2**(l-a)\\n    print(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/437\\/A:\\nOnce upon a time a child got a test consisting of multiple-choice questions as homework. A multiple-choice question consists of four choices: A, B, C and D. Each choice has a description, and the child should find out the only one that is correct.\\n\\nFortunately the child knows how to solve such complicated test. The child will follow the algorithm:\\n\\n  If there is some choice whose description at least twice shorter than all other descriptions, or at least twice longer than all other descriptions, then the child thinks the choice is great.  If there is exactly one great choice then the child chooses it. Otherwise the child chooses C (the child think it is the luckiest choice). \\n\\nYou are given a multiple-choice questions, can you predict child's choose?\\n\\n\\n-----Input-----\\n\\nThe first line starts with \\\"A.\\\" (without quotes), then followed the description of choice A. The next three lines contains the descriptions of the other choices in the same format. They are given in order: B, C, D. Please note, that the description goes after prefix \\\"X.\\\", so the prefix mustn't be counted in description's length.\\n\\nEach description is non-empty and consists of at most 100 characters. Each character can be either uppercase English letter or lowercase English letter, or \\\"_\\\". \\n\\n\\n-----Output-----\\n\\nPrint a single line with the child's choice: \\\"A\\\", \\\"B\\\", \\\"C\\\" or \\\"D\\\" (without quotes).\\n\\n\\n-----Examples-----\\nInput\\nA.VFleaKing_is_the_author_of_this_problem\\nB.Picks_is_the_author_of_this_problem\\nC.Picking_is_the_author_of_this_problem\\nD.Ftiasch_is_cute\\n\\nOutput\\nD\\n\\nInput\\nA.ab\\nB.abcde\\nC.ab\\nD.abc\\n\\nOutput\\nC\\n\\nInput\\nA.c\\nB.cc\\nC.c\\nD.c\\n\\nOutput\\nB\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, the first choice has length 39, the second one has length 35, the third one has length 37, and the last one has length 15. The choice D (length 15) is twice shorter than all other choices', so it is great choice. There is no other great choices so the child will choose D.\\n\\nIn the second sample, no choice is great, so the child will choose the luckiest choice C.\\n\\nIn the...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"v = [input()[2:] for i in range(4)]\\nl = [(len(s),s) for s in v]\\n\\nmin_l, min_s = min(l)[0], min(l)[1]\\nmax_l, max_s = max(l)[0], max(l)[1]\\n\\nmin_ind = 0\\nmax_ind = 0\\n\\nfor i in range(4):\\n    if i != v.index(min_s) and len(v[i]) \\/ min_l >= 2:\\n        min_ind += 1\\n    if i != v.index(max_s) and max_l \\/ len(v[i]) >= 2:\\n        max_ind += 1\\n\\nif min_ind == 3 and max_ind != 3:\\n    print(chr(65 + v.index(min_s)))\\nelif max_ind == 3 and min_ind != 3:\\n    print(chr(65 + v.index(max_s)))\\nelse:print('C')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1365\\/B:\\nAshish has $n$ elements arranged in a line. \\n\\nThese elements are represented by two integers $a_i$ — the value of the element and $b_i$ — the type of the element (there are only two possible types: $0$ and $1$). He wants to sort the elements in non-decreasing values of $a_i$.\\n\\nHe can perform the following operation any number of times:  Select any two elements $i$ and $j$ such that $b_i \\\\ne b_j$ and swap them. That is, he can only swap two elements of different types in one move. \\n\\nTell him if he can sort the elements in non-decreasing values of $a_i$ after performing any number of operations.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ $(1 \\\\le t \\\\le 100)$ — the number of test cases. The description of the test cases follows.\\n\\nThe first line of each test case contains one integer $n$ $(1 \\\\le n \\\\le 500)$ — the size of the arrays.\\n\\nThe second line contains $n$ integers $a_i$ $(1 \\\\le a_i \\\\le 10^5)$  — the value of the $i$-th element.\\n\\nThe third line containts $n$ integers $b_i$ $(b_i \\\\in \\\\{0, 1\\\\})$  — the type of the $i$-th element.\\n\\n\\n-----Output-----\\n\\nFor each test case, print \\\"Yes\\\" or \\\"No\\\" (without quotes) depending on whether it is possible to sort elements in non-decreasing order of their value.\\n\\nYou may print each letter in any case (upper or lower).\\n\\n\\n-----Example-----\\nInput\\n5\\n4\\n10 20 20 30\\n0 1 0 1\\n3\\n3 1 2\\n0 1 1\\n4\\n2 2 4 8\\n1 1 1 1\\n3\\n5 15 4\\n0 0 0\\n4\\n20 10 100 50\\n1 0 0 1\\n\\nOutput\\nYes\\nYes\\nYes\\nNo\\nYes\\n\\n\\n\\n-----Note-----\\n\\nFor the first case: The elements are already in sorted order.\\n\\nFor the second case: Ashish may first swap elements at positions $1$ and $2$, then swap elements at positions $2$ and $3$.\\n\\nFor the third case: The elements are already in sorted order.\\n\\nFor the fourth case: No swap operations may be performed as there is no pair of elements $i$ and $j$ such that $b_i \\\\ne b_j$. The elements cannot be sorted.\\n\\nFor the fifth case: Ashish may swap elements at positions $3$ and $4$, then elements at positions $1$ and $2$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t = int(input())\\nfor qwe in range(t):\\n\\tn = int(input())\\n\\ta = list(map(int, input().split()))\\n\\tb = list(map(int, input().split()))\\n\\tif (min(b) != max(b)):\\n\\t\\tprint(\\\"Yes\\\")\\n\\telse:\\n\\t\\tif list(sorted(a)) == a:\\n\\t\\t\\tprint(\\\"Yes\\\")\\n\\t\\telse:\\n\\t\\t\\tprint(\\\"No\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/535\\/C:\\nKarafs is some kind of vegetable in shape of an 1 × h rectangle. Tavaspolis people love Karafs and they use Karafs in almost any kind of food. Tavas, himself, is crazy about Karafs. [Image] \\n\\nEach Karafs has a positive integer height. Tavas has an infinite 1-based sequence of Karafses. The height of the i-th Karafs is s_{i} = A + (i - 1) × B.\\n\\nFor a given m, let's define an m-bite operation as decreasing the height of at most m distinct not eaten Karafses by 1. Karafs is considered as eaten when its height becomes zero.\\n\\nNow SaDDas asks you n queries. In each query he gives you numbers l, t and m and you should find the largest number r such that l ≤ r and sequence s_{l}, s_{l} + 1, ..., s_{r} can be eaten by performing m-bite no more than t times or print -1 if there is no such number r.\\n\\n\\n-----Input-----\\n\\nThe first line of input contains three integers A, B and n (1 ≤ A, B ≤ 10^6, 1 ≤ n ≤ 10^5).\\n\\nNext n lines contain information about queries. i-th line contains integers l, t, m (1 ≤ l, t, m ≤ 10^6) for i-th query.\\n\\n\\n-----Output-----\\n\\nFor each query, print its answer in a single line.\\n\\n\\n-----Examples-----\\nInput\\n2 1 4\\n1 5 3\\n3 3 10\\n7 10 2\\n6 4 8\\n\\nOutput\\n4\\n-1\\n8\\n-1\\n\\nInput\\n1 5 2\\n1 5 10\\n2 7 4\\n\\nOutput\\n1\\n2\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\na, b, n = [int(x) for x in input().split()]\\n\\nfor i in range(n):\\n    l, t, m = [int(x) for x in input().split()]\\n    x = a + (l - 1) * b\\n    if x > t:\\n        print(\\\"-1\\\")\\n        continue\\n\\n    r = (t - a) \\/\\/ b + 1\\n    D = (2 * x - b) ** 2 + 8 * m * t * b\\n    d = int(math.floor((-2 * x + b + math.sqrt(D)) \\/ (2 * b)))\\n    r = min(r, l + d - 1)\\n    # total = t * m\\n    # last = a + (r - 1) * b\\n    # total_need = (x + last) * (r - l + 1) \\/\\/ 2\\n    # while total_need > total:\\n    #     total_need -= last\\n    #     last -= b\\n    #     r -= 1\\n    print(r)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere always is something to choose from! And now, instead of \\\"Noughts and Crosses\\\", Inna choose a very unusual upgrade of this game. The rules of the game are given below:\\n\\nThere is one person playing the game. Before the beginning of the game he puts 12 cards in a row on the table. Each card contains a character: \\\"X\\\" or \\\"O\\\". Then the player chooses two positive integers a and b (a·b = 12), after that he makes a table of size a × b from the cards he put on the table as follows: the first b cards form the first row of the table, the second b cards form the second row of the table and so on, the last b cards form the last (number a) row of the table. The player wins if some column of the table contain characters \\\"X\\\" on all cards. Otherwise, the player loses.\\n\\nInna has already put 12 cards on the table in a row. But unfortunately, she doesn't know what numbers a and b to choose. Help her win the game: print to her all the possible ways of numbers a, b that she can choose and win.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains integer t (1 ≤ t ≤ 100). This value shows the number of sets of test data in the input. Next follows the description of each of the t tests on a separate line.\\n\\nThe description of each test is a string consisting of 12 characters, each character is either \\\"X\\\", or \\\"O\\\". The i-th character of the string shows the character that is written on the i-th card from the start.\\n\\n\\n-----Output-----\\n\\nFor each test, print the answer to the test on a single line. The first number in the line must represent the number of distinct ways to choose the pair a, b. Next, print on this line the pairs in the format axb. Print the pairs in the order of increasing first parameter (a). Separate the pairs in the line by whitespaces.\\n\\n\\n-----Examples-----\\nInput\\n4\\nOXXXOXOOXOOX\\nOXOXOXOXOXOX\\nXXXXXXXXXXXX\\nOOOOOOOOOOOO\\n\\nOutput\\n3 1x12 2x6 4x3\\n4 1x12 2x6 3x4 6x2\\n6 1x12 2x6 3x4 4x3 6x2 12x1\\n0\",\"targets\":\"t = int(input())\\nfor _ in range(t):\\n  s = input()\\n  b = []\\n  for n in [1, 2, 3, 4, 6, 12]:\\n    m = 12 \\/\\/ n\\n    for j in range(m):\\n      if s[j::m] == \\\"X\\\" * n:\\n        b += [(n, m)]\\n        break\\n  print(len(b), ' '.join(str(x) + \\\"x\\\" + str(y) for x, y in b))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a2b7edcb6486a856e00005b:\\nCheck if it is a vowel(a, e, i, o, u,) on the ```n``` position in a string (the first argument). Don't forget about uppercase.\\n\\nA few cases:\\n\\n```\\n{\\ncheckVowel('cat', 1)  ->   true \\/\\/ 'a' is a vowel\\ncheckVowel('cat', 0)  ->   false \\/\\/ 'c' is not a vowel\\ncheckVowel('cat', 4)  ->   false \\/\\/ this position doesn't exist\\n}\\n```\\nP.S. If n < 0, return false\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def check_vowel(s, i):\\n    return s[i].lower() in 'aeiou' if len(s) > i > -1 else False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/TSORT:\\nGiven the list of numbers, you are to sort them in non decreasing order.\\n\\n-----Input-----\\nt – the number of numbers in list, then t lines follow [t <= 10^6]. \\n\\nEach line contains one integer: N [0 <= N <= 10^6]\\n\\n-----Output-----\\nOutput given numbers in non decreasing order.\\n\\n-----Example-----\\nInput:\\n5\\n5\\n3\\n6\\n7\\n1\\n\\nOutput:\\n1\\n3\\n5\\n6\\n7\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nt = int(input())\\nls = []\\nfor _ in range(t):\\n    ls.append(int(input()))\\nls.sort()\\nfor item in ls:\\n    print(item)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/ENFE2020\\/problems\\/ECFEB205:\\nChef is playing a game which contains a binary string. \\nHe can perform one operation only:\\n- Toggle the i_th bit of the string (0 to 1 or 1 to 0)\\nBy performing operations on the string (can be zero times), you have to convert the string with no adjacent bit being the same.\\nCan you help chef ?\\n\\n-----Input:-----\\n- First line will contain $T$, number of test cases. Then the test cases follow. \\n- First line of each test case, contains the size of the  string $N$\\n- Seond line contains a single line of input, the binary string. \\n\\n-----Output:-----\\nFor each testcase, output in a single line answer - the minimum operations.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $2 \\\\leq |S| \\\\leq 10^3$\\n\\n-----Sample Input:-----\\n1\\n4\\n1011\\n\\n-----Sample Output:-----\\n1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for i in range(int(input())):\\n n=int(input())\\n l=input()\\n k=n\\/\\/2\\n p='10'*k\\n q='01'*k\\n x=y=0\\n if n%2==0:\\n  for i in range(n):\\n   if l[i]!=p[i]:\\n    x=x+1\\n   if l[i]!=q[i]:\\n    y=y+1\\n  print(min(x,y))\\n else:\\n  p=p+'1'\\n  q=q+'0'\\n  for i in range(n):\\n   if l[i]!=p[i]:\\n    x=x+1\\n   if l[i]!=q[i]:\\n    y=y+1\\n  print(min(x,y))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/DIVTHREE:\\nChef wants to host some Division-3 contests. Chef has $N$ setters who are busy creating new problems for him. The $i^{th}$ setter has made $A_i$ problems where $1 \\\\leq i \\\\leq N$.    \\nA Division-3 contest should have exactly $K$ problems. Chef wants to plan for the next $D$ days using the problems that they have currently. But Chef cannot host more than one Division-3 contest in a day.\\nGiven these constraints, can you help Chef find the maximum number of Division-3 contests that can be hosted in these $D$ days?\\n\\n-----Input:-----\\n- The first line of input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains three space-separated integers - $N$, $K$ and $D$ respectively.\\n- The second line of each test case contains $N$ space-separated integers $A_1, A_2, \\\\ldots, A_N$ respectively. \\n\\n-----Output:-----\\nFor each test case, print a single line containing one integer ― the maximum number of Division-3 contests Chef can host in these $D$ days.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 10^3$\\n- $1 \\\\leq N \\\\leq 10^2$\\n- $1 \\\\le K \\\\le 10^9$ \\n- $1 \\\\le D \\\\le 10^9$\\n- $1 \\\\le A_i \\\\le 10^7$ for each valid $i$\\n\\n-----Subtasks-----\\nSubtask #1 (40 points):\\n- $N = 1$\\n- $1 \\\\le A_1 \\\\le 10^5$\\nSubtask #2 (60 points): Original constraints\\n\\n-----Sample Input:-----\\n5\\n1 5 31\\n4\\n1 10 3\\n23\\n2 5 7\\n20 36\\n2 5 10\\n19 2\\n3 3 300\\n1 1 1\\n\\n-----Sample Output:-----\\n0\\n2\\n7\\n4\\n1\\n\\n-----Explanation:-----\\n- \\nExample case 1: Chef only has $A_1 = 4$ problems and he needs $K = 5$ problems for a Division-3 contest. So Chef won't be able to host any Division-3 contest in these 31 days. Hence the first output is $0$.\\n- \\nExample case 2: Chef has $A_1 = 23$ problems and he needs $K = 10$ problems for a Division-3 contest. Chef can choose any $10+10 = 20$ problems and host $2$ Division-3 contests in these 3 days. Hence the second output is $2$.\\n- \\nExample case 3: Chef has $A_1 = 20$ problems from setter-1 and $A_2 = 36$ problems from setter-2, and so has a total of $56$ problems....\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t=int(input())\\nfor x in range(0,t):\\n n,k,d=list(map(int,input().split()))\\n noofq=list(map(int,input().split()))\\n sum1=0\\n poss=0\\n for j in range(n):\\n  sum1=sum1+noofq[j]\\n if(sum1>=k):\\n  poss=sum1\\/\\/k\\n else:\\n  poss=0\\n if(poss>d):\\n  poss=d\\n print(poss)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1068\\/D:\\nIvan unexpectedly saw a present from one of his previous birthdays. It is array of $n$ numbers from $1$ to $200$. Array is old and some numbers are hard to read. Ivan remembers that for all elements at least one of its neighbours ls not less than it, more formally:\\n\\n$a_{1} \\\\le a_{2}$,\\n\\n$a_{n} \\\\le a_{n-1}$ and\\n\\n$a_{i} \\\\le max(a_{i-1}, \\\\,\\\\, a_{i+1})$ for all $i$ from $2$ to $n-1$.\\n\\nIvan does not remember the array and asks to find the number of ways to restore it. Restored elements also should be integers from $1$ to $200$. Since the number of ways can be big, print it modulo $998244353$.\\n\\n\\n-----Input-----\\n\\nFirst line of input contains one integer $n$ ($2 \\\\le n \\\\le 10^{5}$) — size of the array.\\n\\nSecond line of input contains $n$ integers $a_{i}$ — elements of array. Either $a_{i} = -1$ or $1 \\\\le a_{i} \\\\le 200$. $a_{i} = -1$ means that $i$-th element can't be read.\\n\\n\\n-----Output-----\\n\\nPrint number of ways to restore the array modulo $998244353$.\\n\\n\\n-----Examples-----\\nInput\\n3\\n1 -1 2\\n\\nOutput\\n1\\n\\nInput\\n2\\n-1 -1\\n\\nOutput\\n200\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, only possible value of $a_{2}$ is $2$.\\n\\nIn the second example, $a_{1} = a_{2}$ so there are $200$ different values because all restored elements should be integers between $1$ and $200$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"MOD = 998244353.0\\nfloat_prec = 1801439850948198.4\\nfloat_mod = lambda x: x if -float_prec < x < float_prec else x % MOD\\n\\nn = int(input())\\na = [int(i) for i in input().split()]\\n\\nf0, f1 = [1.0] * 201, [0.0] * 201\\nfor i in range(n):\\n    nf0, nf1 = [0.0] * 201, [0.0] * 201\\n    if a[i] == -1:\\n        for j in range(200):\\n            nf0[j + 1] = float_mod(nf0[j] + f0[j] + f1[j])\\n            nf1[j + 1] = float_mod(nf1[j] - f0[j] + f0[j + 1] - f1[j] + f1[200])\\n    else:\\n        for j in range(200):\\n            nf0[j + 1], nf1[j + 1] = nf0[j], nf1[j]\\n            if j + 1 == a[i]:\\n                nf0[j + 1] = float_mod(nf0[j] + f0[j] + f1[j])\\n                nf1[j + 1] = float_mod(nf1[j] - f0[j] + f0[j + 1] - f1[j] + f1[200])\\n    f0, f1 = nf0, nf1\\n\\nprint(int(f1[200] % MOD))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA [sequence or a series](http:\\/\\/world.mathigon.org\\/Sequences), in mathematics, is a string of objects, like numbers, that follow a particular pattern. The individual elements in a sequence are called terms. A simple example is `3, 6, 9, 12, 15, 18, 21, ...`, where the pattern is: _\\\"add 3 to the previous term\\\"_.\\n\\nIn this kata, we will be using a more complicated sequence:   `0, 1, 3, 6, 10, 15, 21, 28, ...`\\nThis sequence is generated with the pattern: _\\\"the nth term is the sum of numbers from 0 to n, inclusive\\\"_.\\n\\n```\\n[ 0,  1,    3,      6,   ...]\\n  0  0+1  0+1+2  0+1+2+3\\n```\\n\\n## Your Task\\n\\nComplete the function that takes an integer `n` and returns a list\\/array of length `abs(n) + 1` of the arithmetic series explained above. When`n < 0` return the sequence with negative terms.\\n\\n## Examples \\n\\n```\\n 5  -->  [0,  1,  3,  6,  10,  15]\\n-5  -->  [0, -1, -3, -6, -10, -15]\\n 7  -->  [0,  1,  3,  6,  10,  15,  21,  28]\\n```\",\"targets\":\"def sum_of_n(n):\\n    sign, n = (1, -1)[n < 0], abs(n) \\n    return [sign * (i * i + i) \\/ 2 for i in range (n + 1)]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/two-sum\\/:\\nGiven an array of integers, return indices of the two numbers such that they add up to a specific target.\\n\\nYou may assume that each input would have exactly one solution, and you may not use the same element twice.\\n\\nExample:\\n\\n\\nGiven nums = [2, 7, 11, 15], target = 9,\\n\\nBecause nums[0] + nums[1] = 2 + 7 = 9,\\nreturn [0, 1].\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def twoSum(self, nums, target):\\n         \\\"\\\"\\\"\\n         :type nums: List[int]\\n         :type target: int\\n         :rtype: List[int]\\n         \\\"\\\"\\\"\\n         dict = {}\\n         for i in range(0,len(nums)):\\n             if nums[i] in dict:\\n                 return [dict[nums[i]],i]\\n             else:\\n                 dict[target-nums[i]] = i\\n         return []\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAfter a hard quarter in the office you decide to get some rest on a vacation. So you will book a flight for you and your girlfriend and try to leave all the mess behind you.\\n\\nYou will need a rental car in order for you to get around in your vacation. The manager of the car rental makes you some good offers.\\n\\nEvery day you rent the car costs $40. If you rent the car for 7 or more days, you get $50 off your total. Alternatively, if you rent the car for 3 or more days, you get $20 off your total.\\n\\nWrite a code that gives out the total amount for different days(d).\",\"targets\":\"def rental_car_cost(d):\\n\\n    sum = 40*d\\n    \\n    if d >= 7:\\n        sum = sum - 50\\n        \\n    elif d >= 3:\\n        sum = sum - 20\\n        \\n    return sum\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/56576f82ab83ee8268000059:\\nKevin is noticing his space run out! Write a function that removes the spaces from the values and returns an array showing the space decreasing.\\nFor example, running this function on the array ['i', 'have','no','space'] would produce ['i','ihave','ihaveno','ihavenospace'].\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def spacey(array):\\n    return [''.join(array[:i+1]) for i in range(len(array))]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5a91a7c5fd8c061367000002:\\n# Task\\n\\n**_Given_** *an array of N integers, you have to find* **_how many times_** *you have to* **_add up the smallest numbers_** *in the array until* **_their Sum_**  *becomes greater or equal to* **_K_**.\\n___\\n \\n# Notes: \\n\\n* **_List size_**  is *at least 3*.\\n\\n* **_All numbers_**  *will be*  **_positive_**.\\n\\n* **_Numbers_**  could  *occur more than once* ,   **_(Duplications may exist)_**.\\n\\n* Threshold  **_K_**  will *always be reachable*.\\n___\\n# Input >> Output Examples\\n\\n```\\nminimumSteps({1, 10, 12, 9, 2, 3}, 6)  ==>  return (2)\\n```\\n## **_Explanation_**:\\n\\n* We  *add two smallest elements*  **_(1 + 2)_**,  *their sum is 3* .\\n\\n* **_Then_**  we  **_add the next smallest number to it (3 + 3)_** , so  *the sum becomes 6* .\\n\\n* **_Now_**  the result is greater or equal to **_6_** ,  *Hence the output is (2) i.e (2) operations are required to do this* .\\n___\\n```\\nminimumSteps({8 , 9, 4, 2}, 23)  ==> return (3)\\n```\\n## **_Explanation_**:\\n\\n* We  *add two smallest elements*  **_(4 + 2)_**,  *their sum is 6* .\\n\\n* **_Then_**  we  **_add the next smallest number to it (6 + 8)_** , so *the sum becomes 14* .\\n\\n* **_Now_**  we  **_add the next smallest number (14 + 9)_** , so *the sum becomes 23*  .\\n\\n* **_Now_**  the result is greater or equal to **_23_** ,  *Hence the output is (3) i.e (3) operations are required to do this* .\\n___\\n```\\nminimumSteps({19,98,69,28,75,45,17,98,67}, 464)  ==>  return (8)\\n```\\n## **_Explanation_**:\\n\\n* We  *add two smallest elements*  **_(19 + 17)_**,  *their sum is 36* .\\n\\n* **_Then_**  we  **_add the next smallest number to it (36 + 28)_** , so *the sum becomes 64* .\\n\\n* We need to **_keep doing this_** *until **_the sum_** becomes greater or equal to **_K_** (464 in this case)*, which will require **_8_** Steps .\\n___\\n ## Expected Time Complexity `O(n Log n)`\\n___\\n___\\n___\\n\\n# [Playing with Numbers Series](https:\\/\\/www.codewars.com\\/collections\\/playing-with-numbers)\\n\\n# [Playing With Lists\\/Arrays Series](https:\\/\\/www.codewars.com\\/collections\\/playing-with-lists-slash-arrays)\\n\\n# [For More Enjoyable...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from itertools import accumulate\\n\\ndef minimum_steps(numbers, value):\\n    return next(i for i, x in enumerate(accumulate(sorted(numbers))) if x >= value)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a long decimal number $a$ consisting of $n$ digits from $1$ to $9$. You also have a function $f$ that maps every digit from $1$ to $9$ to some (possibly the same) digit from $1$ to $9$.\\n\\nYou can perform the following operation no more than once: choose a non-empty contiguous subsegment of digits in $a$, and replace each digit $x$ from this segment with $f(x)$. For example, if $a = 1337$, $f(1) = 1$, $f(3) = 5$, $f(7) = 3$, and you choose the segment consisting of three rightmost digits, you get $1553$ as the result.\\n\\nWhat is the maximum possible number you can obtain applying this operation no more than once?\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $n$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$) — the number of digits in $a$.\\n\\nThe second line contains a string of $n$ characters, denoting the number $a$. Each character is a decimal digit from $1$ to $9$.\\n\\nThe third line contains exactly $9$ integers $f(1)$, $f(2)$, ..., $f(9)$ ($1 \\\\le f(i) \\\\le 9$).\\n\\n\\n-----Output-----\\n\\nPrint the maximum number you can get after applying the operation described in the statement no more than once.\\n\\n\\n-----Examples-----\\nInput\\n4\\n1337\\n1 2 5 4 6 6 3 1 9\\n\\nOutput\\n1557\\n\\nInput\\n5\\n11111\\n9 8 7 6 5 4 3 2 1\\n\\nOutput\\n99999\\n\\nInput\\n2\\n33\\n1 1 1 1 1 1 1 1 1\\n\\nOutput\\n33\",\"targets\":\"n = int(input())\\na1 = list(map(int, list(input())))\\nu = list(map(int, input().split()))\\na2 = []\\nfor i in range(n):\\n    a2.append(u[a1[i] - 1])\\nok = False\\ni1 = -1\\nfor i in range(n):\\n    if a2[i] > a1[i]:\\n        i1 = i\\n        ok = True\\n        break\\nif ok:\\n    i2 = n\\n    for i in range(i1 + 1, n):\\n        if a2[i] < a1[i]:\\n            i2 = i\\n            break\\n    for i in range(i1, i2):\\n        a1[i] = a2[i]\\nprint(''.join(map(str, a1)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n< PREVIOUS KATA\\nNEXT KATA >\\n \\n###Task:\\n\\nYou have to write a function `pattern` which returns the following Pattern(See Examples) upto (3n-2) rows, where n is parameter.\\n\\n* Note:`Returning` the pattern is not the same as `Printing` the pattern.\\n\\n####Rules\\/Note:\\n* The pattern should be created using only unit digits.\\n* If `n < 1` then it should return \\\"\\\" i.e. empty string.\\n* `The length of each line is same`, and is equal to the length of longest line in the pattern i.e. `length = (3n-2)`.\\n* Range of Parameters (for the sake of CW Compiler) :\\n  + `n ∈ (-∞,50]`\\n\\n###Examples:\\n\\n  + pattern(5) :\\n\\n            11111    \\n            22222    \\n            33333    \\n            44444    \\n        1234555554321\\n        1234555554321\\n        1234555554321\\n        1234555554321\\n        1234555554321\\n            44444    \\n            33333    \\n            22222    \\n            11111    \\n        \\n  + pattern(11):\\n\\n                  11111111111          \\n                  22222222222          \\n                  33333333333          \\n                  44444444444          \\n                  55555555555          \\n                  66666666666          \\n                  77777777777          \\n                  88888888888          \\n                  99999999999          \\n                  00000000000          \\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n        1234567890111111111110987654321\\n                  00000000000          \\n                  99999999999          \\n                  88888888888          \\n                  77777777777          \\n                  66666666666          \\n                  55555555555          \\n                  44444444444          \\n             ...\",\"targets\":\"def pattern(n):\\n    return ''.join((str((k+1)%10)*n).center(3*n-2)+'\\\\n' for k in range(n-1))+(''.join(str((i+1)%10) for i in range(n-1))+n*str(n%10)+''.join(str(j%10) for j in range(n-1,0,-1))+'\\\\n')*n+'\\\\n'.join((str(g%10)*n).center(3*n-2) for g in range(n-1,0,-1))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/unique-email-addresses\\/:\\nEvery email consists of a local name and a domain name, separated by the @ sign.\\nFor example, in alice@leetcode.com, alice is the local name, and leetcode.com is the domain name.\\nBesides lowercase letters, these emails may contain '.'s or '+'s.\\nIf you add periods ('.') between some characters in the local name part of an email address, mail sent there will be forwarded to the same address without dots in the local name.  For example, \\\"alice.z@leetcode.com\\\" and \\\"alicez@leetcode.com\\\" forward to the same email address.  (Note that this rule does not apply for domain names.)\\nIf you add a plus ('+') in the local name, everything after the first plus sign will be ignored. This allows certain emails to be filtered, for example m.y+name@email.com will be forwarded to my@email.com.  (Again, this rule does not apply for domain names.)\\nIt is possible to use both of these rules at the same time.\\nGiven a list of emails, we send one email to each address in the list.  How many different addresses actually receive mails? \\n \\n\\nExample 1:\\nInput: [\\\"test.email+alex@leetcode.com\\\",\\\"test.e.mail+bob.cathy@leetcode.com\\\",\\\"testemail+david@lee.tcode.com\\\"]\\nOutput: 2\\nExplanation: \\\"testemail@leetcode.com\\\" and \\\"testemail@lee.tcode.com\\\" actually receive mails\\n\\n \\nNote:\\n\\n1 <= emails[i].length <= 100\\n1 <= emails.length <= 100\\nEach emails[i] contains exactly one '@' character.\\nAll local and domain names are non-empty.\\nLocal names do not start with a '+' character.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    def numUniqueEmails(self, emails: List[str]) -> int:\\n        l=[]\\n        for i in emails:\\n            end=i[i.index('@'):]\\n            s=''\\n            string=''\\n            for j in i:\\n                if j=='.':\\n                    continue\\n                if j=='+':\\n                    break \\n                if j=='@':\\n                    break\\n                else:\\n                    s=s+j\\n            l.append(s+end)    \\n        \\n        return (len(set(l)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/955\\/B:\\nLet's call a string adorable if its letters can be realigned in such a way that they form two consequent groups of equal symbols (note that different groups must contain different symbols). For example, ababa is adorable (you can transform it to aaabb, where the first three letters form a group of a-s and others — a group of b-s), but cccc is not since in each possible consequent partition letters in these two groups coincide.\\n\\nYou're given a string s. Check whether it can be split into two non-empty subsequences such that the strings formed by these subsequences are adorable. Here a subsequence is an arbitrary set of indexes of the string.\\n\\n\\n-----Input-----\\n\\nThe only line contains s (1 ≤ |s| ≤ 10^5) consisting of lowercase latin letters.\\n\\n\\n-----Output-----\\n\\nPrint «Yes» if the string can be split according to the criteria above or «No» otherwise.\\n\\nEach letter can be printed in arbitrary case.\\n\\n\\n-----Examples-----\\nInput\\nababa\\n\\nOutput\\nYes\\n\\nInput\\nzzcxx\\n\\nOutput\\nYes\\n\\nInput\\nyeee\\n\\nOutput\\nNo\\n\\n\\n\\n-----Note-----\\n\\nIn sample case two zzcxx can be split into subsequences zc and zxx each of which is adorable.\\n\\nThere's no suitable partition in sample case three.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"s = input()\\na = set()\\nfor i in s:\\n    a.add(i)\\na = list(a)\\nif len(a) == 4:\\n    print(\\\"Yes\\\")\\nelif len(a) == 2:\\n    if s.count(a[0]) > 1 and s.count(a[1]) > 1:\\n        print(\\\"Yes\\\")\\n    else:\\n        print(\\\"No\\\")\\nelif len(a) == 3:\\n    if s.count(a[0]) > 1 or s.count(a[1]) > 1 or s.count(a[2]) > 1:\\n        print(\\\"Yes\\\")\\n    else:\\n        print(\\\"No\\\")\\nelse:\\n    print(\\\"No\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven an array, return the reversed version of the array (a different kind of reverse though), you reverse portions of the array, you'll be given a length argument which represents the length of each portion you are to reverse.\\n\\nE.g\\n  \\n  if after reversing some portions of the array and the length of the remaining portion in the array is not up to the length argument, just reverse them.\\n  \\n\\n`selReverse(array, length)`\\n\\n- array - array to reverse\\n- length - length of each portion to reverse\\n\\nNote : if the length argument exceeds the array length, reverse all of them, if the length argument is zero do not reverse at all.\",\"targets\":\"def sel_reverse(arr,l):\\n    #your code here\\n    res = []\\n    \\n    if l == 0:\\n      return arr\\n      \\n    i = 0\\n    while i < len(arr):\\n      res.append(arr[i:i+l][::-1])\\n      i += l\\n    \\n    return sum(res, [])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc158\\/tasks\\/abc158_a:\\nIn AtCoder City, there are three stations numbered 1, 2, and 3.\\nEach of these stations is operated by one of the two railway companies, A and B. A string S of length 3 represents which company operates each station. If S_i is A, Company A operates Station i; if S_i is B, Company B operates Station i.\\nTo improve the transportation condition, for each pair of a station operated by Company A and one operated by Company B, there will be a bus service connecting them.\\nDetermine if there is a pair of stations that will be connected by a bus service.\\n\\n-----Constraints-----\\n - Each character of S is A or B.\\n - |S| = 3\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nS\\n\\n-----Output-----\\nIf there is a pair of stations that will be connected by a bus service, print Yes; otherwise, print No.\\n\\n-----Sample Input-----\\nABA\\n\\n-----Sample Output-----\\nYes\\n\\nCompany A operates Station 1 and 3, while Company B operates Station 2.\\nThere will be a bus service between Station 1 and 2, and between Station 2 and 3, so print Yes.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"S = input()\\nif len(set(list(S))) == 1:\\n    print('No')\\nelse:\\n    print('Yes')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou have to rebuild a string from an enumerated list.\\nFor this task, you have to check if input is correct beforehand.\\n\\n* Input must be a list of tuples\\n* Each tuple has two elements.\\n* Second element is an alphanumeric character.\\n* First element is the index of this character into the reconstructed string.\\n* Indexes start at 0 and have to match with output indexing: no gap is allowed.\\n* Finally tuples aren't necessarily ordered by index.\\n\\nIf any condition is invalid, the function should return `False`.\\n\\nInput example: \\n```python \\n[(4,'y'),(1,'o'),(3,'t'),(0,'m'),(2,'n')]\\n```\\nReturns\\n\\n```python\\n'monty'\\n```\",\"targets\":\"def denumerate(e):\\n    if type(e)!=list or any(type(i)!=tuple for i in e) or sorted([i[0] for i in e])!=list(range(0,len(e))) : return False\\n    li = \\\"\\\".join([i[1] for i in sorted(e) if len(i[1])==1 and i[1].isalnum() and len(i)==2])\\n    return li if len(li)==len(e) else False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1371\\/B:\\nA competitive eater, Alice is scheduling some practices for an eating contest on a magical calendar. The calendar is unusual because a week contains not necessarily $7$ days!\\n\\nIn detail, she can choose any integer $k$ which satisfies $1 \\\\leq k \\\\leq r$, and set $k$ days as the number of days in a week.\\n\\nAlice is going to paint some $n$ consecutive days on this calendar. On this calendar, dates are written from the left cell to the right cell in a week. If a date reaches the last day of a week, the next day's cell is the leftmost cell in the next (under) row.\\n\\nShe wants to make all of the painted cells to be connected by side. It means, that for any two painted cells there should exist at least one sequence of painted cells, started in one of these cells, and ended in another, such that any two consecutive cells in this sequence are connected by side.\\n\\nAlice is considering the shape of the painted cells. Two shapes are the same if there exists a way to make them exactly overlapped using only parallel moves, parallel to the calendar's sides.\\n\\nFor example, in the picture, a week has $4$ days and Alice paints $5$ consecutive days. [1] and [2] are different shapes, but [1] and [3] are equal shapes. [Image] \\n\\nAlice wants to know how many possible shapes exists if she set how many days a week has and choose consecutive $n$ days and paints them in calendar started in one of the days of the week. As was said before, she considers only shapes, there all cells are connected by side.\\n\\n\\n-----Input-----\\n\\nThe input consists of multiple test cases. The first line contains a single integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of test cases. Next $t$ lines contain descriptions of test cases.\\n\\nFor each test case, the only line contains two integers $n$, $r$ ($1 \\\\le n \\\\le 10^9, 1 \\\\le r \\\\le 10^9$).\\n\\n\\n-----Output-----\\n\\nFor each test case, print a single integer  — the answer to the problem.\\n\\nPlease note, that the answer for some test cases won't fit into $32$-bit integer type, so you should use at least $64$-bit integer type in...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def solve():\\n    n, r = list(map(int, input().split()))\\n    k = min(r, n - 1)\\n    print(k * (k + 1) \\/\\/ 2 + (r >= n))\\n\\n\\nfor i in range(int(input())):\\n    solve()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n Mirko has been moving up in the world of basketball. He started as a mere spectator, but has already reached the coveted position of the national team coach!\\n\\n Mirco is now facing a difficult task: selecting five primary players for the upcoming match against Tajikistan. Since Mirko is incredibly lazy, he doesn't bother remembering players' names, let alone their actual skills. That's why he has settled on selecting five players who share the same first letter of their surnames, so that he can remember them easier. If there are no five players sharing the first letter of their surnames, Mirko will simply forfeit the game!\\n\\n Your task is to find the first letters Mirko's players' surnames can begin with(In alphabetical order), or return `\\\"forfeit\\\"` if Mirko can't gather a team.\\n\\n# Input\\/Output\\n\\n\\n - `[input]` string array `players`\\n\\n  Array of players' surnames, consisting only of lowercase English letters.\\n\\n \\n - `[output]` a string\\n\\n  A **sorted** string of possible first letters, or \\\"forfeit\\\" if it's impossible to gather a team.\\n\\n\\n# Example\\n\\nFor `players = [\\\"michael\\\",\\\"jordan\\\",\\\"lebron\\\",\\\"james\\\",\\\"kobe\\\",\\\"bryant\\\"]`, the output should be `\\\"forfeit\\\"`.\\n\\n For\\n ```\\n players = [\\\"babic\\\",\\\"keksic\\\",\\\"boric\\\",\\\"bukic\\\",\\n              \\\"sarmic\\\",\\\"balic\\\",\\\"kruzic\\\",\\\"hrenovkic\\\",\\n              \\\"beslic\\\",\\\"boksic\\\",\\\"krafnic\\\",\\\"pecivic\\\",\\n              \\\"klavirkovic\\\",\\\"kukumaric\\\",\\\"sunkic\\\",\\\"kolacic\\\",\\n              \\\"kovacic\\\",\\\"prijestolonasljednikovic\\\"]\\n```\\nthe output should be \\\"bk\\\".\",\"targets\":\"def strange_coach(players):\\n    letters = [p[0] for p in players]\\n    res = set(l for l in letters if letters.count(l) > 4)\\n    return ''.join(sorted(res)) if res else 'forfeit'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/432\\/D:\\nYou have a string s = s_1s_2...s_{|}s|, where |s| is the length of string s, and s_{i} its i-th character. \\n\\nLet's introduce several definitions:  A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string s_{i}s_{i} + 1...s_{j}.  The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].  The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|]. \\n\\nYour task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.\\n\\n\\n-----Input-----\\n\\nThe single line contains a sequence of characters s_1s_2...s_{|}s| (1 ≤ |s| ≤ 10^5) — string s. The string only consists of uppercase English letters.\\n\\n\\n-----Output-----\\n\\nIn the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers l_{i} c_{i}. Numbers l_{i} c_{i} mean that the prefix of the length l_{i} matches the suffix of length l_{i} and occurs in string s as a substring c_{i} times. Print pairs l_{i} c_{i} in the order of increasing l_{i}.\\n\\n\\n-----Examples-----\\nInput\\nABACABA\\n\\nOutput\\n3\\n1 4\\n3 2\\n7 1\\n\\nInput\\nAAA\\n\\nOutput\\n3\\n1 3\\n2 2\\n3 1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"s = str(input())\\n\\nlps = [0]*100005\\ndp = [0]*100005\\nada = [0]*100005\\ntunda = [0]*100005\\n\\nn = len(s)\\n\\ni = 1\\nj = 0\\nlps[0] = 0\\n\\nwhile(i < n):\\n    if (s[i] == s[j]):\\n        j += 1\\n        lps[i] = j\\n        i += 1\\n    elif (j == 0):\\n        lps[i] = 0\\n        i += 1\\n    else:\\n        j = lps[j-1]\\n\\n\\nfor i in range(n-1,-1,-1):\\n    tunda[i] += 1\\n    dp[lps[i]] += tunda[i]\\n    if (lps[i]):tunda[lps[i]-1] += tunda[i]\\n\\nj = n\\n\\n\\\"\\\"\\\"\\nfor i in range(n):\\n    print(\\\"SAD\\\", i, lps[i])\\n\\\"\\\"\\\"\\n\\nvector = []\\n\\nwhile(1):\\n    vector.append((j,1+dp[j]))\\n    j = lps[j-1]\\n    if (j == 0): break\\n\\n\\nvector.reverse()\\n\\nprint(len(vector))\\nfor i in vector:\\n    print(i[0], i[1])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/57ef016a7b45ef647a00002d:\\nChallenge:\\n\\nGiven a two-dimensional array, return a new array which carries over only those arrays from the original, which were not empty and whose items are all of the same type (i.e. homogenous). For simplicity, the arrays inside the array will only contain characters and integers.\\n\\nExample:\\n\\nGiven [[1, 5, 4], ['a', 3, 5], ['b'], [], ['1', 2, 3]], your function should return [[1, 5, 4], ['b']].\\n\\nAddendum:\\n\\nPlease keep in mind that for this kata, we assume that empty arrays are not homogenous.\\n\\nThe resultant arrays should be in the order they were originally in and should not have its values changed.\\n\\nNo implicit type casting is allowed. A subarray [1, '2'] would be considered illegal and should be filtered out.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def filter_homogenous(arrays):\\n    return[a for a in arrays if len(set(map(type,a)))==1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc060\\/tasks\\/arc073_a:\\nIn a public bath, there is a shower which emits water for T seconds when the switch is pushed.\\nIf the switch is pushed when the shower is already emitting water, from that moment it will be emitting water for T seconds.\\nNote that it does not mean that the shower emits water for T additional seconds.\\nN people will push the switch while passing by the shower.\\nThe i-th person will push the switch t_i seconds after the first person pushes it.\\nHow long will the shower emit water in total?\\n\\n-----Constraints-----\\n - 1 ≤ N ≤ 200,000\\n - 1 ≤ T ≤ 10^9\\n - 0 = t_1 < t_2 < t_3 < , ..., < t_{N-1} < t_N ≤ 10^9\\n - T and each t_i are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN T\\nt_1 t_2 ... t_N\\n\\n-----Output-----\\nAssume that the shower will emit water for a total of X seconds. Print X.\\n\\n-----Sample Input-----\\n2 4\\n0 3\\n\\n-----Sample Output-----\\n7\\n\\nThree seconds after the first person pushes the water, the switch is pushed again and the shower emits water for four more seconds, for a total of seven seconds.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, T = map(int, input().split())\\nt = list(map(int, input().split()))\\n\\nans = 0\\nfor i in range(n-1):\\n    ans += min(T, t[i+1]-t[i])\\nans += T\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nVasya started working in a machine vision company of IT City. Vasya's team creates software and hardware for identification of people by their face.\\n\\nOne of the project's know-how is a camera rotating around its optical axis on shooting. People see an eye-catching gadget — a rotating camera — come up to it to see it better, look into it. And the camera takes their photo at that time. What could be better for high quality identification?\\n\\nBut not everything is so simple. The pictures from camera appear rotated too (on clockwise camera rotation frame the content becomes rotated counter-clockwise). But the identification algorithm can work only with faces that are just slightly deviated from vertical.\\n\\nVasya was entrusted to correct the situation — to rotate a captured image so that image would be minimally deviated from vertical. Requirements were severe. Firstly, the picture should be rotated only on angle divisible by 90 degrees to not lose a bit of information about the image. Secondly, the frames from the camera are so huge and FPS is so big that adequate rotation speed is provided by hardware FPGA solution only. And this solution can rotate only by 90 degrees clockwise. Of course, one can apply 90 degrees turn several times but for the sake of performance the number of turns should be minimized.\\n\\nHelp Vasya implement the program that by the given rotation angle of the camera can determine the minimum number of 90 degrees clockwise turns necessary to get a picture in which up direction deviation from vertical is minimum.\\n\\nThe next figure contains frames taken from an unrotated camera, then from rotated 90 degrees clockwise, then from rotated 90 degrees counter-clockwise. Arrows show direction to \\\"true up\\\". [Image] \\n\\nThe next figure shows 90 degrees clockwise turn by FPGA hardware. [Image] \\n\\n\\n-----Input-----\\n\\nThe only line of the input contains one integer x ( - 10^18 ≤ x ≤ 10^18) — camera angle in degrees. Positive value denotes clockwise camera rotation, negative —...\",\"targets\":\"n = int(input())\\nans = 0\\nn %= 360\\n\\nif n <= 45 or n >= 270:\\n    ans = 0\\nif n > 45 and n <= 135:\\n    ans = 1\\nif n > 135 and n <= 225:\\n    ans = 2\\nif n > 225 and n < 315:\\n    ans = 3\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nShichi-Go-San (literally \\\"Seven-Five-Three\\\") is a traditional event in a certain country to celebrate the growth of seven-, five- and three-year-old children.\\nTakahashi is now X years old. Will his growth be celebrated in Shichi-Go-San this time?\\n\\n-----Constraints-----\\n - 1 ≤ X ≤ 9\\n - X is an integer.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nX\\n\\n-----Output-----\\nIf Takahashi's growth will be celebrated, print YES; if it will not, print NO.\\n\\n-----Sample Input-----\\n5\\n\\n-----Sample Output-----\\nYES\\n\\nThe growth of a five-year-old child will be celebrated.\",\"targets\":\"A = int(input())\\n\\nif A in [3, 5, 7]:\\n  print('YES')\\nelse:\\n  print('NO')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/POTATOES:\\nFarmer Feb has three fields with potatoes planted in them. He harvested x potatoes from the first field, y potatoes from the second field and is yet to harvest potatoes from the third field. Feb is very superstitious and believes that if the sum of potatoes he harvests from the three fields is a prime number (http:\\/\\/en.wikipedia.org\\/wiki\\/Prime_number), he'll make a huge profit. Please help him by calculating for him the minimum number of potatoes that if harvested from the third field will make the sum of potatoes prime. At least one potato should be harvested from the third field.\\n\\n-----Input-----\\nThe first line of the input contains an integer T denoting the number of test cases. Each of the next T lines contain 2 integers separated by single space: x and y.\\n\\n-----Output-----\\nFor each test case, output a single line containing the answer.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 1000\\n- 1 ≤ x ≤ 1000\\n- 1 ≤ y ≤ 1000\\n\\n-----Example-----\\nInput:\\n2\\n1 3\\n4 3\\n\\nOutput:\\n1\\n4\\n\\n-----Explanation-----\\n\\nIn example case 1: the farmer harvested a potato from the first field and 3 potatoes from the second field. The sum is 4. If he is able to harvest a potato from the third field, that will make the sum 5, which is prime. Hence the answer is 1(he needs one more potato to make the sum of harvested potatoes prime.)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def factors(n):\\n c=0\\n for i in range(1,n+1):\\n  if n%i==0:\\n   c+=1\\n return c\\n \\nt=int(input())\\nfor _ in range(t):\\n z=1\\n x,y=map(int,input().split(\\\" \\\"))\\n k=x+y\\n while(True):\\n  t=k+z \\n  if factors(t)==2:\\n   break\\n  else:\\n   z+=1\\n print(z)\\n t-=1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/51dda84f91f5b5608b0004cc:\\nWrite a function that takes an integer and returns an array `[A, B, C]`, where `A` is the number of multiples of 3 (but not 5) below the given integer, `B` is the number of multiples of 5 (but not 3) below the given integer and `C` is the number of multiples of 3 and 5 below the given integer. \\n\\nFor example, `solution(20)` should return `[5, 2, 1]`\\n\\n~~~if:r\\n```r\\n# in R, returns a numeric vector\\nsolution(20)\\n[1] 5 2 1\\n\\nclass(solution(20))\\n[1] \\\"numeric\\\"\\n```\\n~~~\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def solution(number):\\n    A = (number - 1) \\/\\/ 3\\n    B = (number - 1) \\/\\/ 5\\n    C = (number - 1) \\/\\/ 15    \\n    return [A - C, B - C, C]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nValera has got a rectangle table consisting of n rows and m columns. Valera numbered the table rows starting from one, from top to bottom and the columns – starting from one, from left to right. We will represent cell that is on the intersection of row x and column y by a pair of integers (x, y).\\n\\nValera wants to place exactly k tubes on his rectangle table. A tube is such sequence of table cells (x_1, y_1), (x_2, y_2), ..., (x_{r}, y_{r}), that:   r ≥ 2;  for any integer i (1 ≤ i ≤ r - 1) the following equation |x_{i} - x_{i} + 1| + |y_{i} - y_{i} + 1| = 1 holds;  each table cell, which belongs to the tube, must occur exactly once in the sequence. \\n\\nValera thinks that the tubes are arranged in a fancy manner if the following conditions are fulfilled:   no pair of tubes has common cells;  each cell of the table belongs to some tube. \\n\\nHelp Valera to arrange k tubes on his rectangle table in a fancy manner.\\n\\n\\n-----Input-----\\n\\nThe first line contains three space-separated integers n, m, k (2 ≤ n, m ≤ 300; 2 ≤ 2k ≤ n·m) — the number of rows, the number of columns and the number of tubes, correspondingly. \\n\\n\\n-----Output-----\\n\\nPrint k lines. In the i-th line print the description of the i-th tube: first print integer r_{i} (the number of tube cells), then print 2r_{i} integers x_{i}1, y_{i}1, x_{i}2, y_{i}2, ..., x_{ir}_{i}, y_{ir}_{i} (the sequence of table cells).\\n\\nIf there are multiple solutions, you can print any of them. It is guaranteed that at least one solution exists. \\n\\n\\n-----Examples-----\\nInput\\n3 3 3\\n\\nOutput\\n3 1 1 1 2 1 3\\n3 2 1 2 2 2 3\\n3 3 1 3 2 3 3\\n\\nInput\\n2 3 1\\n\\nOutput\\n6 1 1 1 2 1 3 2 3 2 2 2 1\\n\\n\\n\\n-----Note-----\\n\\nPicture for the first sample:  [Image] \\n\\nPicture for the second sample:  [Image]\",\"targets\":\"n,m,k = [int(i) for i in input().split()]\\nimport sys\\nseq = []\\nrev = False\\nfor i in range(n):\\n    l = list(zip([i+1]*m,range(1,m+1)))\\n    if rev:\\n        l.reverse()\\n    seq += l\\n    rev = not rev\\n\\nfor i in range(k-1):\\n    sys.stdout.write('2 ' + str(seq[i*2][0]) + ' ' + str(seq[i*2][1]) + ' ' + str(seq[i*2+1][0]) + ' ' + str(seq[i*2+1][1]) + '\\\\n')\\n\\nprint(len(seq) - k*2 + 2,end=' ')\\nfor a,b in seq[k*2-2:]:\\n    sys.stdout.write(str(a) + ' ' + str(b) + ' ')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have an undirected graph G with N vertices numbered 1 to N and N edges as follows:\\n - For each i=1,2,...,N-1, there is an edge between Vertex i and Vertex i+1.\\n - There is an edge between Vertex X and Vertex Y.\\nFor each k=1,2,...,N-1, solve the problem below:\\n - Find the number of pairs of integers (i,j) (1 \\\\leq i < j \\\\leq N) such that the shortest distance between Vertex i and Vertex j in G is k.\\n\\n-----Constraints-----\\n - 3 \\\\leq N \\\\leq 2 \\\\times 10^3\\n - 1 \\\\leq X,Y \\\\leq N\\n - X+1 < Y\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN X Y\\n\\n-----Output-----\\nFor each k=1, 2, ..., N-1 in this order, print a line containing the answer to the problem.\\n\\n-----Sample Input-----\\n5 2 4\\n\\n-----Sample Output-----\\n5\\n4\\n1\\n0\\n\\nThe graph in this input is as follows:\\n\\n\\n\\n\\n\\nThere are five pairs (i,j) (1 \\\\leq i < j \\\\leq N) such that the shortest distance between Vertex i and Vertex j is 1: (1,2)\\\\,,(2,3)\\\\,,(2,4)\\\\,,(3,4)\\\\,,(4,5).\\n\\n\\nThere are four pairs (i,j) (1 \\\\leq i < j \\\\leq N) such that the shortest distance between Vertex i and Vertex j is 2: (1,3)\\\\,,(1,4)\\\\,,(2,5)\\\\,,(3,5).\\n\\n\\nThere is one pair (i,j) (1 \\\\leq i < j \\\\leq N) such that the shortest distance between Vertex i and Vertex j is 3: (1,5).\\n\\n\\nThere are no pairs (i,j) (1 \\\\leq i < j \\\\leq N) such that the shortest distance between Vertex i and Vertex j is 4.\",\"targets\":\"from collections import deque\\n\\nn, x, y = map(int, input().split())\\n\\ng = [[] for _ in range(n)]\\n\\nfor i in range(n - 1):\\n    g[i].append(i + 1)\\n    g[i + 1].append(i)\\ng[x - 1].append(y - 1)\\ng[y - 1].append(x - 1)\\n\\n\\ndef bfs(g, n_node, start_node):\\n    dist = [-1] * n_node\\n    dist[start_node] = 0\\n    que = deque([start_node])\\n\\n    while que:\\n        node = que.popleft()\\n        for j in g[node]:\\n            if dist[j] != -1:\\n                continue\\n            dist[j] = dist[node] + 1\\n            que.append(j)\\n    return dist\\n\\n\\nans = [0] * n\\n\\nfor i in range(n):\\n    dist = bfs(g, n, i)\\n    for d in dist:\\n        ans[d] += 1\\n\\nfor a in ans[1:]:\\n    print(a\\/\\/2)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n(Легенда будет поправлена позже) У нас есть n целых чисел. Первое число становится корнем дерева, для остальных нужно реализовать добавление в дерево поиска и вывести для каждого n - 1 числа его непосредственного предка в дереве.\\n\\n\\n-----Входные данные-----\\n\\nВ первой строке записано одно целое число n (2 ≤ n ≤ 10^5) — количество чиcел. Во второй строке через пробел записаны n различных целых чисел a_{i} (1 ≤ a_{i} ≤ 10^9).\\n\\n\\n-----Выходные данные-----\\n\\nДля всех i > 1 выведите непосредственного предка a_{i}\\n\\n\\n-----Примеры-----\\nВходные данные\\n3\\n1 2 3\\n\\nВыходные данные\\n1 2\\n\\nВходные данные\\n5\\n4 2 3 1 6\\n\\nВыходные данные\\n4 2 2 4\",\"targets\":\"from bisect import bisect\\n\\nn = int(input())\\narray = [int(x) for x in input().split()]\\n\\ntree = []\\nans = [''] * n\\nfor i in range(n):\\n  item = array[i]\\n  index = bisect(tree, (item, i))\\n  if i != 0:\\n    if index == 0:\\n      ans[i] = str(tree[0][0])\\n    elif index == i:\\n      ans[i] = str(tree[i - 1][0])\\n    else:\\n      ans[i] = str(tree[index - 1][0] if tree[index - 1][1] > tree[index][1] else tree[index][0])\\n  tree[index:index] = [(item, i)]\\nprint(' '.join(ans[1:]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nA sequence a=\\\\{a_1,a_2,a_3,......\\\\} is determined as follows:\\n - The first term s is given as input.\\n - Let f(n) be the following function: f(n) = n\\/2 if n is even, and f(n) = 3n+1 if n is odd.\\n - a_i = s when i = 1, and a_i = f(a_{i-1}) when i > 1.\\nFind the minimum integer m that satisfies the following condition:\\n - There exists an integer n such that a_m = a_n (m > n).\\n\\n-----Constraints-----\\n - 1 \\\\leq s \\\\leq 100\\n - All values in input are integers.\\n - It is guaranteed that all elements in a and the minimum m that satisfies the condition are at most 1000000.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\ns\\n\\n-----Output-----\\nPrint the minimum integer m that satisfies the condition.\\n\\n-----Sample Input-----\\n8\\n\\n-----Sample Output-----\\n5\\n\\na=\\\\{8,4,2,1,4,2,1,4,2,1,......\\\\}. As a_5=a_2, the answer is 5.\",\"targets\":\"s = int(input())\\n\\nans_list = [s]\\ncurr_value = s\\nindex = 1\\nwhile(True):\\n    if curr_value%2==0:\\n        curr_value = int(curr_value\\/2)\\n    else:\\n        curr_value = 3*curr_value + 1\\n    index += 1\\n    if curr_value in ans_list:\\n        break\\n    else:\\n        ans_list.append(curr_value)\\nprint(index)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/529872bdd0f550a06b00026e:\\nComplete the `greatestProduct` method so that it'll find the greatest product of five consecutive digits in the given string of digits.\\n\\nFor example:\\n\\nThe input string always has more than five digits.\\n\\nAdapted from Project Euler.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from itertools import islice\\nfrom functools import reduce\\n\\ndef greatest_product(n):\\n    numbers=[int(value) for value in n]\\n    result=[reduce(lambda x,y: x*y, islice(numbers, i, i+5), 1) for i in range(len(numbers)-4)]\\n    return max(result)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nn participants of the competition were split into m teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.\\n\\nYour task is to write a program that will find the minimum and the maximum number of pairs of friends that could have formed by the end of the competition.\\n\\n\\n-----Input-----\\n\\nThe only line of input contains two integers n and m, separated by a single space (1 ≤ m ≤ n ≤ 10^9) — the number of participants and the number of teams respectively. \\n\\n\\n-----Output-----\\n\\nThe only line of the output should contain two integers k_{min} and k_{max} — the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively.\\n\\n\\n-----Examples-----\\nInput\\n5 1\\n\\nOutput\\n10 10\\n\\nInput\\n3 2\\n\\nOutput\\n1 1\\n\\nInput\\n6 3\\n\\nOutput\\n3 6\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample all the participants get into one team, so there will be exactly ten pairs of friends.\\n\\nIn the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.\\n\\nIn the third sample minimum number of newly formed friendships can be achieved if participants were split on teams consisting of 2 people, maximum number can be achieved if participants were split on teams of 1, 1 and 4 people.\",\"targets\":\"n,m=list(map(int,input().split()))\\n\\nmaxx=((n-m+1)*(n-m))\\/\\/2\\n\\nx=n\\/\\/m\\nminn=(x*(x-1))\\/\\/2\\nminn*=m\\nminn+=x*(n%m)\\n\\nprint(minn,maxx)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/429\\/A:\\nIahub is very proud of his recent discovery, propagating trees. Right now, he invented a new tree, called xor-tree. After this new revolutionary discovery, he invented a game for kids which uses xor-trees.\\n\\nThe game is played on a tree having n nodes, numbered from 1 to n. Each node i has an initial value init_{i}, which is either 0 or 1. The root of the tree is node 1.\\n\\nOne can perform several (possibly, zero) operations on the tree during the game. The only available type of operation is to pick a node x. Right after someone has picked node x, the value of node x flips, the values of sons of x remain the same, the values of sons of sons of x flips, the values of sons of sons of sons of x remain the same and so on.\\n\\nThe goal of the game is to get each node i to have value goal_{i}, which can also be only 0 or 1. You need to reach the goal of the game by using minimum number of operations.\\n\\n\\n-----Input-----\\n\\nThe first line contains an integer n (1 ≤ n ≤ 10^5). Each of the next n - 1 lines contains two integers u_{i} and v_{i} (1 ≤ u_{i}, v_{i} ≤ n; u_{i} ≠ v_{i}) meaning there is an edge between nodes u_{i} and v_{i}. \\n\\nThe next line contains n integer numbers, the i-th of them corresponds to init_{i} (init_{i} is either 0 or 1). The following line also contains n integer numbers, the i-th number corresponds to goal_{i} (goal_{i} is either 0 or 1).\\n\\n\\n-----Output-----\\n\\nIn the first line output an integer number cnt, representing the minimal number of operations you perform. Each of the next cnt lines should contain an integer x_{i}, representing that you pick a node x_{i}.\\n\\n\\n-----Examples-----\\nInput\\n10\\n2 1\\n3 1\\n4 2\\n5 1\\n6 2\\n7 5\\n8 6\\n9 8\\n10 5\\n1 0 1 1 0 1 0 1 0 1\\n1 0 1 0 0 1 1 1 0 1\\n\\nOutput\\n2\\n4\\n7\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input())\\np = [[] for i in range(n + 1)]\\nfor i in range(n - 1):\\n    a, b = map(int, input().split())\\n    p[a].append(b)\\n    p[b].append(a)\\nu, v = ' ' + input()[:: 2], ' ' + input()[:: 2]\\ns, q = [(1, 0, 0, 0)], []\\nwhile s:\\n    a, k, i, j = s.pop()\\n    if k:\\n        if i != (u[a] != v[a]):\\n            q.append(a)\\n            i = 1 - i\\n    else:\\n        if j != (u[a] != v[a]):\\n            q.append(a)\\n            j = 1 - j\\n    k = 1 - k\\n    for b in p[a]:\\n        p[b].remove(a)\\n        s.append((b, k, i, j))\\nprint(len(q))\\nprint('\\\\n'.join(map(str, q)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou throw a ball vertically upwards with an initial speed `v (in km per hour)`. The height `h` of the ball at each time `t`\\nis given by `h = v*t - 0.5*g*t*t` where `g` is Earth's gravity `(g ~ 9.81 m\\/s**2)`. A device is recording at every **tenth\\nof second** the height of the ball.\\nFor example with `v = 15 km\\/h` the device gets something of the following form:\\n`(0, 0.0), (1, 0.367...), (2, 0.637...), (3, 0.808...), (4, 0.881..) ...`\\nwhere the first number is the time in tenth of second and the second number the height in meter.\\n# Task\\nWrite a function `max_ball` with parameter `v (in km per hour)` that returns the `time in tenth of second`\\nof the maximum height recorded by the device.\\n# Examples:\\n`max_ball(15) should return 4`\\n\\n`max_ball(25) should return 7`\\n# Notes\\n- Remember to convert the velocity from km\\/h to m\\/s or from m\\/s in km\\/h when necessary.\\n- The maximum height recorded by the device is not necessarily the maximum height reached by the ball.\",\"targets\":\"def max_ball(v0):\\n    return round(10*v0\\/9.81\\/3.6)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc145\\/tasks\\/abc145_e:\\nTakahashi is at an all-you-can-eat restaurant.\\nThe restaurant offers N kinds of dishes. It takes A_i minutes to eat the i-th dish, whose deliciousness is B_i.\\nThe restaurant has the following rules:\\n - You can only order one dish at a time. The dish ordered will be immediately served and ready to eat.\\n - You cannot order the same kind of dish more than once.\\n - Until you finish eating the dish already served, you cannot order a new dish.\\n - After T-0.5 minutes from the first order, you can no longer place a new order, but you can continue eating the dish already served.\\nLet Takahashi's happiness be the sum of the deliciousness of the dishes he eats in this restaurant.\\nWhat is the maximum possible happiness achieved by making optimal choices?\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 3000\\n - 1 \\\\leq T \\\\leq 3000\\n - 1 \\\\leq A_i \\\\leq 3000\\n - 1 \\\\leq B_i \\\\leq 3000\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN T\\nA_1 B_1\\n:\\nA_N B_N\\n\\n-----Output-----\\nPrint the maximum possible happiness Takahashi can achieve.\\n\\n-----Sample Input-----\\n2 60\\n10 10\\n100 100\\n\\n-----Sample Output-----\\n110\\n\\nBy ordering the first and second dishes in this order, Takahashi's happiness will be 110.\\nNote that, if we manage to order a dish in time, we can spend any amount of time to eat it.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import numpy as np\\n\\nN, T = map(int, input().split())\\nAB = []\\nfor i in range(N):\\n  A, B = map(int, input().split())\\n  AB.append([A, B])\\n\\nAB.sort()\\n\\ndp = np.zeros(T, dtype=int)\\n\\nans = 0\\nfor a, b in AB:\\n  ans = max(ans, dp[-1] + b)\\n  dp[a:] = np.maximum(dp[a:], dp[:-a] + b)\\n\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nToday, the bookstore owner has a store open for customers.length minutes.  Every minute, some number of customers (customers[i]) enter the store, and all those customers leave after the end of that minute.\\nOn some minutes, the bookstore owner is grumpy.  If the bookstore owner is grumpy on the i-th minute, grumpy[i] = 1, otherwise grumpy[i] = 0.  When the bookstore owner is grumpy, the customers of that minute are not satisfied, otherwise they are satisfied.\\nThe bookstore owner knows a secret technique to keep themselves not grumpy for X minutes straight, but can only use it once.\\nReturn the maximum number of customers that can be satisfied throughout the day.\\n \\nExample 1:\\nInput: customers = [1,0,1,2,1,1,7,5], grumpy = [0,1,0,1,0,1,0,1], X = 3\\nOutput: 16\\nExplanation: The bookstore owner keeps themselves not grumpy for the last 3 minutes. \\nThe maximum number of customers that can be satisfied = 1 + 1 + 1 + 1 + 7 + 5 = 16.\\n\\n \\nNote:\\n\\n1 <= X <= customers.length == grumpy.length <= 20000\\n0 <= customers[i] <= 1000\\n0 <= grumpy[i] <= 1\",\"targets\":\"class Solution:\\n    def maxSatisfied(self, customers: List[int], grumpy: List[int], X: int) -> int:\\n        total = 0\\n        \\n        for i in range(len(customers)):\\n            total += (1-grumpy[i]) * customers[i]\\n            grumpy[i] *= customers[i]\\n        \\n        maxsum = 0\\n        for i in range(X):\\n            maxsum += grumpy[i]\\n        cur = maxsum\\n        for j in range(X, len(grumpy)):\\n            i = j-X\\n            cur += grumpy[j]\\n            cur -= grumpy[i]\\n            maxsum = max(maxsum, cur)\\n        #print(maxsum)\\n        return total + maxsum\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nDanny, the local Math Maniac, is fascinated by circles, Omkar's most recent creation. Help him solve this circle problem!\\n\\nYou are given $n$ nonnegative integers $a_1, a_2, \\\\dots, a_n$ arranged in a circle, where $n$ must be odd (ie. $n-1$ is divisible by $2$). Formally, for all $i$ such that $2 \\\\leq i \\\\leq n$, the elements $a_{i - 1}$ and $a_i$ are considered to be adjacent, and $a_n$ and $a_1$ are also considered to be adjacent. In one operation, you pick a number on the circle, replace it with the sum of the two elements adjacent to it, and then delete the two adjacent elements from the circle. This is repeated until only one number remains in the circle, which we call the circular value.\\n\\nHelp Danny find the maximum possible circular value after some sequences of operations. \\n\\n\\n-----Input-----\\n\\nThe first line contains one odd integer $n$ ($1 \\\\leq n < 2 \\\\cdot 10^5$, $n$ is odd)  — the initial size of the circle.\\n\\nThe second line contains $n$ integers $a_{1},a_{2},\\\\dots,a_{n}$ ($0 \\\\leq a_{i} \\\\leq 10^9$)  — the initial numbers in the circle.\\n\\n\\n-----Output-----\\n\\nOutput the maximum possible circular value after applying some sequence of operations to the given circle.\\n\\n\\n-----Examples-----\\nInput\\n3\\n7 10 2\\n\\nOutput\\n17\\n\\nInput\\n1\\n4\\n\\nOutput\\n4\\n\\n\\n\\n-----Note-----\\n\\nFor the first test case, here's how a circular value of $17$ is obtained:\\n\\nPick the number at index $3$. The sum of adjacent elements equals $17$. Delete $7$ and $10$ from the circle and replace $2$ with $17$.\\n\\nNote that the answer may not fit in a $32$-bit integer.\",\"targets\":\"y=lambda x:print(x)or quit()\\nn=int(input())\\np=list(map(int,input().split()))\\nif n<2:y(p[0])\\nif n<4:y(sum(p)-min(p))\\ns=[p[-1],p[-2]]\\nr=[p[0],p[1]]\\nfor i in range(2,n):\\n    r.append(r[-2]+p[i])\\n    s.append(s[-2]+p[-i-1])\\ns=s[::-1]\\nm=r[-1]+r[-2]\\nfor i in range(n-3):m=min(m,r[i]+s[i+3])\\nm=min([m,r[n-3],s[1],s[2]])\\ny(r[-1]+r[-2]-m)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/55830eec3e6b6c44ff000040:\\nGiven an integer `n` return `\\\"odd\\\"` if the number of its divisors is odd. Otherwise return `\\\"even\\\"`.\\n\\n**Note**: big inputs will be tested.\\n\\n## Examples:\\n\\nAll prime numbers have exactly two divisors (hence `\\\"even\\\"`).\\n\\nFor `n = 12` the divisors are `[1, 2, 3, 4, 6, 12]` – `\\\"even\\\"`.\\n\\nFor `n = 4` the divisors are `[1, 2, 4]` – `\\\"odd\\\"`.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\ndef oddity(n):\\n    return math.sqrt(n) % 1 == 0 and 'odd' or 'even'\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIn Japan, people make offerings called hina arare, colorful crackers, on March 3.\\nWe have a bag that contains N hina arare. (From here, we call them arare.)\\nIt is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.\\nWe have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: P, white: W, green: G, yellow: Y.\\nIf the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 100\\n - S_i is P, W, G or Y.\\n - There always exist i, j and k such that S_i=P, S_j=W and S_k=G.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nS_1 S_2 ... S_N\\n\\n-----Output-----\\nIf the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.\\n\\n-----Sample Input-----\\n6\\nG W Y P Y W\\n\\n-----Sample Output-----\\nFour\\n\\nThe bag contained arare in four colors, so you should print Four.\",\"targets\":\"N = int(input())\\nS = input().split()\\nprint('Four' if 'Y' in S else 'Three')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/ICOD2016\\/problems\\/ICODE16G:\\nAbhishek is fond of playing cricket very much. One morning, he is playing cricket with his friends. Abhishek  is a right-hand batsman\\n\\n.He has to face  all types of balls either good or  bad. There are total 26 balls in the game and each ball is represented\\n\\nby one of the following two ways:-\\n1. \\\"g\\\" denotes a good ball.\\n2. \\\"b\\\" denotes a bad  ball.\\nAll 26 balls are represented by lower case letters (a,b,.....z).\\nBalls faced by Abhishek are represented as a string s, all the characters of which are lower case  i.e, within  26 above mentioned balls.\\nA substring s[l...r] (1≤l≤r≤|s|) of string s=s1s2...s|s| (where |s| is the length of string s) is string slsl+1...sr.\\nThe substring s[l...r] is good, if among the letters slsl+1...sr, there are at most k bad ones (refer sample explanation ).\\nYour task is to find out the number of distinct good substrings for the given string s. Two substrings s[x...y] and s[p...q] are considered distinct if their contents are different, i.e. s[x...y]≠s[p...q].\\n\\n-----Input Format-----\\nFirst Line contains an integer T, number of test cases. For each test case, first line contains a string - a sequence of balls faced by Abhishek.\\n\\nAnd, next line contains a string of characters \\\"g\\\" and \\\"b\\\" of length 26 characters. If the ith character of this string equals \\\"1\\\", then the i-th English letter is good, otherwise it's bad. That is, the first character of this string corresponds to letter \\\"a\\\", the second one corresponds to letter \\\"b\\\" and so on.\\n\\nAnd, the third line of the test case consists of a single integer k (0≤k≤|s|) — the maximum acceptable number of bad characters in a good substring.\\n\\n-----Output Format -----\\nFor each test case, print a single integer — the number of distinct good substrings of string s.\\n\\n-----Constraints-----\\n- 1<=T<=1000\\n- 1<=|s|<=2000\\n- 0<=k<=|s|\\n\\n-----Subtasks-----\\nSubtask 1 : 20 Points\\n- 1<=T<=10\\n- 1<=|s|<=20\\n- 0<=k<=|s|\\nSubtask 2 : 80 Points \\nOriginal Constraints\\nSample Input\\n2\\nababab\\nbgbbbbbbbbbbbbbbbbbbbbbbbb\\n1\\nacbacbacaa\\nbbbbbbbbbbbbbbbbbbbbbbbbbb\\n2\\nSample...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nfor _ in range(0,eval(input())):   \\n    d,c,inp,mp,n,q=[],0,list(map(ord,list(sys.stdin.readline().strip()))),sys.stdin.readline().strip(),eval(input()),ord('a')\\n    for i in range(0,len(inp)):\\n        nn,h=n,0\\n        for j in range(i,len(inp)):\\n                if ( (mp[inp[j]-q]=='g') or  nn>0 ):\\n                    if((mp[inp[j]-q]=='g') == False ):                \\n                        nn=nn-1\\n                    h=(h*256)^inp[j]\\n                    d+=[h]\\n                else:\\n                    break  \\n    print(len(set(d)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYura is tasked to build a closed fence in shape of an arbitrary non-degenerate simple quadrilateral. He's already got three straight fence segments with known lengths $a$, $b$, and $c$. Now he needs to find out some possible integer length $d$ of the fourth straight fence segment so that he can build the fence using these four segments. In other words, the fence should have a quadrilateral shape with side lengths equal to $a$, $b$, $c$, and $d$. Help Yura, find any possible length of the fourth side.\\n\\nA non-degenerate simple quadrilateral is such a quadrilateral that no three of its corners lie on the same line, and it does not cross itself.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $t$ — the number of test cases ($1 \\\\le t \\\\le 1000$). The next $t$ lines describe the test cases.\\n\\nEach line contains three integers $a$, $b$, and $c$ — the lengths of the three fence segments ($1 \\\\le a, b, c \\\\le 10^9$).\\n\\n\\n-----Output-----\\n\\nFor each test case print a single integer $d$ — the length of the fourth fence segment that is suitable for building the fence. If there are multiple answers, print any. We can show that an answer always exists.\\n\\n\\n-----Example-----\\nInput\\n2\\n1 2 3\\n12 34 56\\n\\nOutput\\n4\\n42\\n\\n\\n\\n-----Note-----\\n\\nWe can build a quadrilateral with sides $1$, $2$, $3$, $4$.\\n\\nWe can build a quadrilateral with sides $12$, $34$, $56$, $42$.\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\ndef getInts():\\n    return [int(s) for s in input().split()]\\n\\ndef getInt():\\n    return int(input())\\n\\ndef getStrs():\\n    return [s for s in input().split()]\\n\\ndef getStr():\\n    return input().strip()\\n\\ndef listStr():\\n    return list(input().strip())\\n\\nimport collections as col\\nimport math\\n\\n\\\"\\\"\\\"\\n\\\"\\\"\\\"\\n\\ndef solve():\\n    A, B, C = getInts()\\n    return A+B+C-1\\n\\nfor _ in range(getInt()):\\n    print(solve())\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLet's look at the following process: initially you have an empty stack and an array $s$ of the length $l$. You are trying to push array elements to the stack in the order $s_1, s_2, s_3, \\\\dots s_{l}$. Moreover, if the stack is empty or the element at the top of this stack is not equal to the current element, then you just push the current element to the top of the stack. Otherwise, you don't push the current element to the stack and, moreover, pop the top element of the stack. \\n\\nIf after this process the stack remains empty, the array $s$ is considered stack exterminable.\\n\\nThere are samples of stack exterminable arrays:   $[1, 1]$;  $[2, 1, 1, 2]$;  $[1, 1, 2, 2]$;  $[1, 3, 3, 1, 2, 2]$;  $[3, 1, 3, 3, 1, 3]$;  $[3, 3, 3, 3, 3, 3]$;  $[5, 1, 2, 2, 1, 4, 4, 5]$; \\n\\nLet's consider the changing of stack more details if $s = [5, 1, 2, 2, 1, 4, 4, 5]$ (the top of stack is highlighted).   after pushing $s_1 = 5$ the stack turn into $[\\\\textbf{5}]$;  after pushing $s_2 = 1$ the stack turn into $[5, \\\\textbf{1}]$;  after pushing $s_3 = 2$ the stack turn into $[5, 1, \\\\textbf{2}]$;  after pushing $s_4 = 2$ the stack turn into $[5, \\\\textbf{1}]$;  after pushing $s_5 = 1$ the stack turn into $[\\\\textbf{5}]$;  after pushing $s_6 = 4$ the stack turn into $[5, \\\\textbf{4}]$;  after pushing $s_7 = 4$ the stack turn into $[\\\\textbf{5}]$;  after pushing $s_8 = 5$ the stack is empty. \\n\\nYou are given an array $a_1, a_2, \\\\ldots, a_n$. You have to calculate the number of its subarrays which are stack exterminable.\\n\\nNote, that you have to answer $q$ independent queries.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $q$ ($1 \\\\le q \\\\le 3 \\\\cdot 10^5$) — the number of queries.\\n\\nThe first line of each query contains one integer $n$ ($1 \\\\le n \\\\le 3 \\\\cdot 10^5$) — the length of array $a$.\\n\\nThe second line of each query contains $n$ integers $a_1, a_2, \\\\ldots, a_n$ ($1 \\\\le a_i \\\\le n$) — the elements.\\n\\nIt is guaranteed that the sum of all $n$ over all queries does not exceed $3 \\\\cdot 10^5$.\\n\\n\\n-----Output-----\\n\\nFor each test case print one...\",\"targets\":\"# encoding: utf-8\\nfrom sys import stdin\\n\\n\\ndef solve(a):\\n    # root node of tries denotes empty stack\\n    stack = [None]\\n    node_stack = [[1, {}]]\\n\\n    counter = 0\\n    for i in range(len(a)):\\n        el = a[i]\\n\\n        if len(stack) == 0 or stack[-1] != el:\\n\\n            current_node = node_stack[-1]\\n            stack.append(el)\\n            if el not in current_node[1]:\\n                current_node[1][el] = [0, {}]\\n\\n            next_node = current_node[1][el]\\n            next_node[0] += 1\\n            node_stack.append(next_node)\\n\\n        else:\\n            # just go up in trie\\n            stack.pop()\\n            node_stack.pop()\\n            node_stack[-1][0] += 1\\n\\n        value = node_stack[-1][0]\\n        counter += (value - 1)\\n\\n    return counter\\n\\n\\nq = int(stdin.readline().strip())\\nfor _ in range(q):\\n    n = int(stdin.readline().strip())\\n    a = [int(i) for i in stdin.readline().strip().split()]\\n    print(solve(a))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThis is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.\\n\\nYou are given a string $s$ consisting of $n$ lowercase Latin letters.\\n\\nYou have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in $s$).\\n\\nAfter coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.\\n\\nThe goal is to make the string sorted, i.e. all characters should be in alphabetical order.\\n\\nYour task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains one integer $n$ ($1 \\\\le n \\\\le 200$) — the length of $s$.\\n\\nThe second line of the input contains the string $s$ consisting of exactly $n$ lowercase Latin letters.\\n\\n\\n-----Output-----\\n\\nIf it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print \\\"NO\\\" (without quotes) in the first line.\\n\\nOtherwise, print \\\"YES\\\" in the first line and any correct coloring in the second line (the coloring is the string consisting of $n$ characters, the $i$-th character should be '0' if the $i$-th character is colored the first color and '1' otherwise).\\n\\n\\n-----Examples-----\\nInput\\n9\\nabacbecfd\\n\\nOutput\\nYES\\n001010101\\n\\nInput\\n8\\naaabbcbb\\n\\nOutput\\nYES\\n01011011\\n\\nInput\\n7\\nabcdedc\\n\\nOutput\\nNO\\n\\nInput\\n5\\nabcde\\n\\nOutput\\nYES\\n00000\",\"targets\":\"alp = \\\"abcdefghijklmnopqrstuvwxyz\\\"\\n\\ndic = {}\\nfor i,s in enumerate(alp):\\n    dic[s] = i\\n\\nlis = [-1] * 27\\n\\nn = int(input())\\nS = input()\\nans = []\\n\\nfor i,s in enumerate(S):\\n\\n    ind = dic[s]\\n\\n    ans.append(max(lis[ind+1:]) + 1)\\n\\n    lis[ind] = ans[-1]\\n\\nif max(ans) <= 1:\\n\\n    print (\\\"YES\\\")\\n    print(\\\"\\\".join(map(str,ans)))\\n\\nelse:\\n    print (\\\"NO\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou have an infinite number of stacks arranged in a row and numbered (left to right) from 0, each of the stacks has the same maximum capacity.\\nImplement the DinnerPlates class:\\n\\nDinnerPlates(int capacity) Initializes the object with the maximum capacity of the stacks.\\nvoid push(int val) Pushes the given positive integer val into the leftmost stack with size less than capacity.\\nint pop() Returns the value at the top of the rightmost non-empty stack and removes it from that stack, and returns -1 if all stacks are empty.\\nint popAtStack(int index) Returns the value at the top of the stack with the given index and removes it from that stack, and returns -1 if the stack with that given index is empty.\\n\\nExample:\\nInput: \\n[\\\"DinnerPlates\\\",\\\"push\\\",\\\"push\\\",\\\"push\\\",\\\"push\\\",\\\"push\\\",\\\"popAtStack\\\",\\\"push\\\",\\\"push\\\",\\\"popAtStack\\\",\\\"popAtStack\\\",\\\"pop\\\",\\\"pop\\\",\\\"pop\\\",\\\"pop\\\",\\\"pop\\\"]\\n[[2],[1],[2],[3],[4],[5],[0],[20],[21],[0],[2],[],[],[],[],[]]\\nOutput: \\n[null,null,null,null,null,null,2,null,null,20,21,5,4,3,1,-1]\\n\\nExplanation: \\nDinnerPlates D = DinnerPlates(2);  \\/\\/ Initialize with capacity = 2\\nD.push(1);\\nD.push(2);\\nD.push(3);\\nD.push(4);\\nD.push(5);         \\/\\/ The stacks are now:  2  4\\n                                           1  3  5\\n                                           ﹈ ﹈ ﹈\\nD.popAtStack(0);   \\/\\/ Returns 2.  The stacks are now:     4\\n                                                       1  3  5\\n                                                       ﹈ ﹈ ﹈\\nD.push(20);        \\/\\/ The stacks are now: 20  4\\n                                           1  3  5\\n                                           ﹈ ﹈ ﹈\\nD.push(21);        \\/\\/ The stacks are now: 20  4 21\\n                                           1  3  5\\n                                           ﹈ ﹈ ﹈\\nD.popAtStack(0);   \\/\\/ Returns 20.  The stacks are now:     4 21\\n                                                        1  3  5\\n                                                        ﹈ ﹈ ﹈\\nD.popAtStack(2);   \\/\\/ Returns 21.  The stacks are now:     4\\n                                             ...\",\"targets\":\"class DinnerPlates:\\n\\n    def __init__(self, capacity: int):\\n        self.capacity = capacity\\n        self.stacks = []\\n        self.available = []\\n        \\n    def push(self, val: int) -> None:\\n        if not self.available:\\n            self.stacks.append([])\\n            self.available.append(len(self.stacks) - 1)\\n        slot = self.available[0]\\n        self.stacks[slot].append(val)\\n        if len(self.stacks[slot]) == self.capacity:\\n            heapq.heappop(self.available)\\n            self.remove_empty_stacks()\\n    \\n    def remove_empty_stacks(self):\\n        while self.stacks and not self.stacks[-1]:\\n            self.stacks.pop()\\n        while self.available and self.available[0] >= len(self.stacks):\\n            heapq.heappop(self.available)\\n        \\n    def pop(self) -> int:\\n        return self.popAtStack(len(self.stacks) - 1)\\n\\n    def popAtStack(self, index: int) -> int:\\n        if index < 0 or index >= len(self.stacks) or not self.stacks[index]:\\n            return -1\\n        result = self.stacks[index].pop()\\n        if len(self.stacks[index]) == self.capacity - 1:\\n            heapq.heappush(self.available, index)\\n        self.remove_empty_stacks()\\n        return result\\n\\n\\n# Your DinnerPlates object will be instantiated and called as such:\\n# obj = DinnerPlates(capacity)\\n# obj.push(val)\\n# param_2 = obj.pop()\\n# param_3 = obj.popAtStack(index)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a string of numbers between 0-9. Find the average of these numbers and return it as a floored whole number (ie: no decimal places) written out as a string. Eg:\\n\\n\\\"zero nine five two\\\" -> \\\"four\\\"\\n\\nIf the string is empty or includes a number greater than 9, return \\\"n\\/a\\\"\",\"targets\":\"def average_string(s):\\n    sn={\\\"zero\\\":0,\\\"one\\\":1,\\\"two\\\":2,\\\"three\\\":3,\\\"four\\\":4,\\\"five\\\":5,\\\"six\\\":6,\\\"seven\\\":7,\\\"eight\\\":8,\\\"nine\\\":9}\\n    a=0\\n    try:\\n        for i in s.split():\\n            a+=sn[i]\\n        a\\/=len(s.split())\\n    except:\\n        return \\\"n\\/a\\\"\\n    return list(sn.keys())[list(sn.values()).index(int(a))]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/integer-replacement\\/:\\nGiven a positive integer n and you can do operations as follow:\\n\\n\\n\\n\\nIf n is even, replace n with n\\/2.\\nIf n is odd, you can replace n with either n + 1 or n - 1.\\n\\n\\n\\n\\nWhat is the minimum number of replacements needed for n to become 1?\\n\\n\\n\\n\\nExample 1:\\n\\nInput:\\n8\\n\\nOutput:\\n3\\n\\nExplanation:\\n8 -> 4 -> 2 -> 1\\n\\n\\n\\nExample 2:\\n\\nInput:\\n7\\n\\nOutput:\\n4\\n\\nExplanation:\\n7 -> 8 -> 4 -> 2 -> 1\\nor\\n7 -> 6 -> 3 -> 2 -> 1\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n     def Is2(self, n):\\n         root = int(math.log(n, 2))\\n         return (2**root) == n\\n     def GetNear2(self, n):\\n         if n == 0:\\n             return -1\\n         if n == 1:\\n             return 0\\n         if n == 2:\\n             return 1\\n         if self.Is2(n):\\n             return n\\n         for ind in range(n - 1, n + 2):\\n             if self.Is2(ind):\\n                 return ind\\n         return -1\\n     def integerReplacement(self, n):\\n         \\\"\\\"\\\"\\n         :type n: int\\n         :rtype: int\\n         \\\"\\\"\\\"\\n \\n         m = n\\n         cnt = 0\\n         while m != 1:\\n             if m == 1:\\n                 return cnt\\n             if m == 2:\\n                 return 1 + cnt\\n             if m <= 4:\\n                 return 2 + cnt\\n             if m <= 6:\\n                 return 3 + cnt\\n             if m % 2 == 0:\\n                 cnt += 1\\n                 m = int(m \\/ 2)\\n                 continue\\n             k = m % 4\\n             if k == 1:\\n                 cnt += 1\\n                 m = int(m - 1)\\n             elif k == 3:\\n                 cnt += 1\\n                 m = int(m + 1)\\n             \\n         return cnt\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n=====Problem Statement=====\\nHere is a sample line of code that can be executed in Python:\\nprint(\\\"Hello, World!\\\")\\n\\nYou can just as easily store a string as a variable and then print it to stdout:\\nmy_string = \\\"Hello, World!\\\"\\nprint(my_string)\\n\\nThe above code will print Hello, World! on your screen. Try it yourself in the editor below!\\n\\n=====Input Format=====\\nYou do not need to read any input in this challenge.\\n\\n=====Output Format=====\\nPrint Hello, World! to stdout.\",\"targets\":\"def __starting_point():\\n    print(\\\"Hello, World!\\\")\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/441\\/B:\\nValera loves his garden, where n fruit trees grow.\\n\\nThis year he will enjoy a great harvest! On the i-th tree b_{i} fruit grow, they will ripen on a day number a_{i}. Unfortunately, the fruit on the tree get withered, so they can only be collected on day a_{i} and day a_{i} + 1 (all fruits that are not collected in these two days, become unfit to eat).\\n\\nValera is not very fast, but there are some positive points. Valera is ready to work every day. In one day, Valera can collect no more than v fruits. The fruits may be either from the same tree, or from different ones. What is the maximum amount of fruit Valera can collect for all time, if he operates optimally well?\\n\\n\\n-----Input-----\\n\\nThe first line contains two space-separated integers n and v (1 ≤ n, v ≤ 3000) — the number of fruit trees in the garden and the number of fruits that Valera can collect in a day. \\n\\nNext n lines contain the description of trees in the garden. The i-th line contains two space-separated integers a_{i} and b_{i} (1 ≤ a_{i}, b_{i} ≤ 3000) — the day the fruits ripen on the i-th tree and the number of fruits on the i-th tree.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum number of fruit that Valera can collect. \\n\\n\\n-----Examples-----\\nInput\\n2 3\\n1 5\\n2 3\\n\\nOutput\\n8\\n\\nInput\\n5 10\\n3 20\\n2 20\\n1 20\\n4 20\\n5 20\\n\\nOutput\\n60\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample, in order to obtain the optimal answer, you should act as follows.   On the first day collect 3 fruits from the 1-st tree.  On the second day collect 1 fruit from the 2-nd tree and 2 fruits from the 1-st tree.  On the third day collect the remaining fruits from the 2-nd tree.  \\n\\nIn the second sample, you can only collect 60 fruits, the remaining fruit will simply wither.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, v = list(map(int, input().split()))\\ntrees = {}\\ndays = set()\\nfor i in range(n):\\n        a, b = list(map(int, input().split()))\\n        if a not in trees:\\n            trees[a] = b\\n        else:\\n            trees[a] += b\\n        days.add(a)\\n\\nmax_days = max(days)\\ntotal = 0\\nfor a in range(1, max_days+1):\\n#    print(a)\\n#    print(trees)\\n    prev_collected = 0\\n    if a-1 in trees:\\n        prev_collected = min(trees[a-1], v)\\n        trees[a-1] -= prev_collected\\n        total += prev_collected\\n#        print('prev_collected', prev_collected)\\n    if a in trees:\\n        collected = min(trees[a], v-prev_collected)\\n        trees[a] -= collected\\n        total += collected\\n#        print('collected', collected)\\n    elif a-1 in trees and prev_collected == 0:\\n        add_collected = min(trees[a-1], v)\\n        trees[a-1] -= add_collected\\n        total += add_collected\\n#        print('add_collected', add_collected)\\n\\nif max_days in trees:\\n    total += min(trees[max_days], v)\\nprint(total)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThis is the first step to understanding FizzBuzz.  \\n\\nYour inputs:\\na positive integer, n, greater than or equal to one.\\nn is provided, you have NO CONTROL over its value.\\n\\nYour expected output is an array of positive integers from 1 to n (inclusive).\\n\\nYour job is to write an algorithm that gets you from the input to the output.\",\"targets\":\"def pre_fizz(n):\\n    return [1] if n == 1 else list(range(1, (n+1)))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Description:\\n\\n Find the longest successive exclamation marks and question marks combination in the string. A successive exclamation marks and question marks combination must contains two part: a substring of \\\"!\\\" and a substring \\\"?\\\", they are adjacent. \\n \\n If more than one result are found, return the one which at left side; If no such a combination found, return `\\\"\\\"`.\\n\\n# Examples\\n\\n```\\nfind(\\\"!!\\\") === \\\"\\\"\\nfind(\\\"!??\\\") === \\\"!??\\\"\\nfind(\\\"!?!!\\\") === \\\"?!!\\\"\\nfind(\\\"!!???!????\\\") === \\\"!!???\\\"\\nfind(\\\"!!???!?????\\\") === \\\"!?????\\\"\\nfind(\\\"!????!!!?\\\") === \\\"????!!!\\\" \\nfind(\\\"!?!!??!!!?\\\") === \\\"??!!!\\\"\\n```\\n\\n# Note\\nPlease don't post issue about difficulty or duplicate. Because:\\n>[That's unfair on the kata creator. This is a valid kata and introduces new people to javascript some regex or loops, depending on how they tackle this problem.  --matt c](https:\\/\\/www.codewars.com\\/kata\\/remove-exclamation-marks\\/discuss#57fabb625c9910c73000024e)\",\"targets\":\"from itertools import groupby\\n\\ndef find(s):\\n    L = [k*len(list(v)) for k,v in groupby(s)]\\n    return max((x + y for x,y in zip(L, L[1:])), key=len, default=\\\"\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/58397ee871df657929000209:\\nLaura really hates people using acronyms in her office and wants to force her colleagues to remove all acronyms before emailing her. She wants you to build a system that will edit out all known acronyms or else will notify the sender if unknown acronyms are present.\\n\\nAny combination of three or more letters in upper case will be considered an acronym. Acronyms will not be combined with lowercase letters, such as in the case of 'KPIs'. They will be kept isolated as a word\\/words within a string.\\n\\nFor any string: \\n\\nAll instances of 'KPI' must become \\\"key performance indicators\\\" \\nAll instances of 'EOD' must become \\\"the end of the day\\\" \\nAll instances of 'TBD' must become \\\"to be decided\\\"\\nAll instances of 'WAH' must become \\\"work at home\\\"\\nAll instances of 'IAM' must become \\\"in a meeting\\\"\\nAll instances of 'OOO' must become \\\"out of office\\\"\\nAll instances of 'NRN' must become \\\"no reply necessary\\\"\\nAll instances of 'CTA' must become \\\"call to action\\\"\\nAll instances of 'SWOT' must become \\\"strengths, weaknesses, opportunities and threats\\\"\\nIf there are any unknown acronyms in the string, Laura wants you to return only the message:\\n'[acronym] is an acronym. I do not like acronyms. Please remove them from your email.'\\nSo if the acronym in question was 'BRB', you would return the string:\\n'BRB is an acronym. I do not like acronyms. Please remove them from your email.'\\nIf there is more than one unknown acronym in the string, return only the first in your answer.\\n\\nIf all acronyms can be replaced with full words according to the above, however, return only the altered string.\\n\\nIf this is the case, ensure that sentences still start with capital letters. '!' or '?' will not be used.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def acronym_buster(message):\\n    acronyms = {\\n        'CTA': 'call to action',\\n        'EOD': 'the end of the day',\\n        'IAM': 'in a meeting',\\n        'KPI': 'key performance indicators',\\n        'NRN': 'no reply necessary',\\n        'OOO': 'out of office',\\n        'SWOT': 'strengths, weaknesses, opportunities and threats',\\n        'TBD': 'to be decided',\\n        'WAH': 'work at home'\\n    }\\n    result = []\\n    for sentence in message.split('.'):\\n        tmp = []\\n        for i, word in enumerate(sentence.split()):\\n            if word.isupper() and len(word) > 2:\\n                try:\\n                    word = acronyms[word]\\n                except KeyError:\\n                    return ('{} is an acronym. I do not like acronyms. Please'\\n                            ' remove them from your email.'.format(word))\\n            tmp.append(word[0].upper() + word[1:] if i == 0 else word)\\n        result.append(' '.join(tmp))\\n    return '. '.join(result).rstrip()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAssume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.\\n\\n\\nNote:\\nYou may assume the greed factor is always positive. \\nYou cannot assign more than one cookie to one child.\\n\\n\\nExample 1:\\n\\nInput: [1,2,3], [1,1]\\n\\nOutput: 1\\n\\nExplanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. \\nAnd even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.\\nYou need to output 1.\\n\\n\\n\\nExample 2:\\n\\nInput: [1,2], [1,2,3]\\n\\nOutput: 2\\n\\nExplanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. \\nYou have 3 cookies and their sizes are big enough to gratify all of the children, \\nYou need to output 2.\",\"targets\":\"class Solution:\\n     def findContentChildren(self, g, s):\\n         \\\"\\\"\\\"\\n         :type g: List[int]\\n         :type s: List[int]\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         g.sort()\\n         s.sort()\\n         \\n         index, result = 0, 0\\n         while index < len(s) and len(g) > 0:\\n             if s[index] >= g[0]:\\n                 result += 1\\n                 index += 1\\n                 g.remove(g[0])\\n             else:\\n                 index += 1\\n         return result\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven any integer x, Aoki can do the operation below.\\nOperation: Replace x with the absolute difference of x and K.\\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\\n\\n-----Constraints-----\\n - 0 ≤ N ≤ 10^{18}\\n - 1 ≤ K ≤ 10^{18}\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN K\\n\\n-----Output-----\\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\\n\\n-----Sample Input-----\\n7 4\\n\\n-----Sample Output-----\\n1\\n\\nInitially, N=7.\\nAfter one operation, N becomes |7-4| = 3.\\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\",\"targets\":\"N,K=map(int,input().split());print(min(N%K,K-N%K))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n# Task\\n\\nYou got a `scratch lottery`, you want to know how much money you win.\\n\\nThere are `6` sets of characters on the lottery. Each set of characters represents a chance to win. The text has a coating on it. When you buy the lottery ticket and then blow it off, you can see the text information below the coating.\\n\\nEach set of characters contains three animal names and a number, like this: `\\\"tiger tiger tiger 100\\\"`. If the three animal names are the same, Congratulations, you won the prize. You will win the same bonus as the last number.\\n\\nGiven the `lottery`, returns the total amount of the bonus.\\n\\n# Input\\/Output\\n\\n\\n`[input]` string array `lottery`\\n\\nA string array that contains six sets of characters.\\n\\n`[output]` an integer\\n\\nthe total amount of the bonus.\\n\\n# Example\\n\\nFor \\n```\\nlottery = [\\n\\\"tiger tiger tiger 100\\\",\\n\\\"rabbit dragon snake 100\\\",\\n\\\"rat ox pig 1000\\\",\\n\\\"dog cock sheep 10\\\",\\n\\\"horse monkey rat 5\\\",\\n\\\"dog dog dog 1000\\\"\\n]```\\n\\nthe output should be `1100`.\\n\\n`\\\"tiger tiger tiger 100\\\"` win $100, and `\\\"dog dog dog 1000\\\"` win $1000. \\n\\n`100 + 1000 = 1100`\",\"targets\":\"def scratch(lottery):\\n    return sum(win(*line.split()) for line in lottery)\\n\\ndef win(a, b, c, d):\\n    return int(d) if a == b == c else 0\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nInitially on a notepad only one character 'A' is present. You can perform two operations on this notepad for each step: \\n\\nCopy All: You can copy all the characters present on the notepad (partial copy is not allowed).\\nPaste: You can paste the characters which are copied last time.\\n\\n\\n\\n\\nGiven a number n. You have to get exactly n 'A' on the notepad by performing the minimum number of steps permitted. Output the minimum number of steps to get n 'A'. \\n\\n\\nExample 1:\\n\\nInput: 3\\nOutput: 3\\nExplanation:\\nIntitally, we have one character 'A'.\\nIn step 1, we use Copy All operation.\\nIn step 2, we use Paste operation to get 'AA'.\\nIn step 3, we use Paste operation to get 'AAA'.\\n\\n\\n\\n\\nNote:\\n\\nThe n will be in the range [1, 1000].\",\"targets\":\"class Solution:\\n     def minSteps(self, n):\\n         m = n\\n         sum = 0\\n         tmp=2\\n         if m == 1:\\n             return 0\\n         if m == 2:\\n             return 2\\n         else:\\n             while(m>tmp):\\n                 k=m%tmp\\n                 if k==0:\\n                     m=m\\/tmp\\n                     sum += tmp\\n                 else:\\n                     tmp=tmp+1\\n             sum = sum+tmp\\n                 \\n             return sum\\n         \\n         \\\"\\\"\\\"\\n         :type n: int\\n         :rtype: int\\n         \\\"\\\"\\\"\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have an integer array with unique elements and we want to do the permutations that have an element fixed, in other words, these permutations should have a certain element at the same position than the original.\\n\\nThese permutations will be called: **permutations with one fixed point**.\\n\\nLet's see an example with an array of four elements and we want the permutations that have a coincidence **only at  index 0**, so these permutations are (the permutations between parenthesis):\\n``` \\narr = [1, 2, 3, 4]\\n      (1, 3, 4, 2)\\n      (1, 4, 2, 3)\\nTwo permutations matching with arr only at index 0\\n``` \\n\\nLet's see the permutations of the same array with only one coincidence at index **1**:\\n``` \\narr = [1, 2, 3, 4]\\n      (3, 2, 4, 1)\\n      (4, 2, 1, 3)\\nTwo permutations matching with arr only at index 1\\n```\\nOnce again, let's see the permutations of the same array with only one coincidence at index **2**:\\n``` \\narr = [1, 2, 3, 4]\\n      (2, 4, 3, 1)\\n      (4, 1, 3, 2)\\nTwo permutations matching with arr only at index 2\\n```\\nFinally, let's see the permutations of the same array with only one coincidence at index **3**:\\n``` \\narr = [1, 2, 3, 4]\\n      (2, 3, 1, 4)\\n      (3, 1, 2, 4)\\nTwo permutations matching with arr only at index 3\\n```\\nFor this array given above (arr) :\\n\\n- We conclude that we have 8 permutations with one fixed point (two at each index of arr).\\n\\n- We may do the same development for our array, `arr`, with two fixed points and we will get `6` permutations.\\n\\n- There are no permutations with coincidences only at three indexes.\\n\\n- It's good to know that the amount of permutations with no coincidences at all are `9`. See the kata Shuffle It Up!!\\n\\nIn general:\\n\\n- When the amount of fixed points is equal to the array length, there is only one permutation, the original array.\\n\\n- When the amount of fixed points surpasses the length of the array, obvously, there are no permutations at all.\\n\\nCreate a function that receives the length of the array and the number of fixed points and may output the total amount of permutations...\",\"targets\":\"from functools import lru_cache\\n\\n@lru_cache(maxsize=None)\\ndef f(n):\\n    return (n-1) * (f(n-1) + f(n-2)) if n > 2 else int(n != 1)\\n\\ndef fixed_points_perms(n,k):\\n    return n * fixed_points_perms(n-1, k-1) \\/\\/ k if k else f(n)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a string s, return the maximum number of unique substrings that the given string can be split into.\\nYou can split string s into any list of non-empty substrings, where the concatenation of the substrings forms the original string. However, you must split the substrings such that all of them are unique.\\nA substring is a contiguous sequence of characters within a string.\\n \\nExample 1:\\nInput: s = \\\"ababccc\\\"\\nOutput: 5\\nExplanation: One way to split maximally is ['a', 'b', 'ab', 'c', 'cc']. Splitting like ['a', 'b', 'a', 'b', 'c', 'cc'] is not valid as you have 'a' and 'b' multiple times.\\n\\nExample 2:\\nInput: s = \\\"aba\\\"\\nOutput: 2\\nExplanation: One way to split maximally is ['a', 'ba'].\\n\\nExample 3:\\nInput: s = \\\"aa\\\"\\nOutput: 1\\nExplanation: It is impossible to split the string any further.\\n\\n \\nConstraints:\\n\\n\\n1 <= s.length <= 16\\n\\n\\ns contains only lower case English letters.\",\"targets\":\"class Solution:\\n    def maxUniqueSplit(self, s: str) -> int:\\n        # dfs O(2^n) \\/ O(n)\\n        def dfs(index, visited):\\n            nonlocal ans\\n            \\n            # if we have not seen the rest, then our answer is at least 1 larger\\n            if s[index:n] and s[index:n] not in visited:\\n                ans = max(ans, len(visited) + 1)\\n            \\n            #try each section of the remaining\\n            for i in range(index, n):\\n                # only if it doesn't exist yet, and it is not impossible to beat current max\\n                if s[index:i] and s[index:i] not in visited and len(visited) + 1 + n - i > ans: # prune\\n                    visited.add(s[index:i])\\n                    dfs(i, visited)\\n                    visited.remove(s[index:i])\\n\\n        n, ans = len(s), 0\\n        dfs(0, set())\\n        return ans\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1392\\/F:\\nOmkar is standing at the foot of Celeste mountain. The summit is $n$ meters away from him, and he can see all of the mountains up to the summit, so for all $1 \\\\leq j \\\\leq n$ he knows that the height of the mountain at the point $j$ meters away from himself is $h_j$ meters. It turns out that for all $j$ satisfying $1 \\\\leq j \\\\leq n - 1$, $h_j < h_{j + 1}$ (meaning that heights are strictly increasing).\\n\\nSuddenly, a landslide occurs! While the landslide is occurring, the following occurs: every minute, if $h_j + 2 \\\\leq h_{j + 1}$, then one square meter of dirt will slide from position $j + 1$ to position $j$, so that $h_{j + 1}$ is decreased by $1$ and $h_j$ is increased by $1$. These changes occur simultaneously, so for example, if $h_j + 2 \\\\leq h_{j + 1}$ and $h_{j + 1} + 2 \\\\leq h_{j + 2}$ for some $j$, then $h_j$ will be increased by $1$, $h_{j + 2}$ will be decreased by $1$, and $h_{j + 1}$ will be both increased and decreased by $1$, meaning that in effect $h_{j + 1}$ is unchanged during that minute.\\n\\nThe landslide ends when there is no $j$ such that $h_j + 2 \\\\leq h_{j + 1}$. Help Omkar figure out what the values of $h_1, \\\\dots, h_n$ will be after the landslide ends. It can be proven that under the given constraints, the landslide will always end in finitely many minutes.\\n\\nNote that because of the large amount of input, it is recommended that your code uses fast IO.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($1 \\\\leq n \\\\leq 10^6$). \\n\\nThe second line contains $n$ integers $h_1, h_2, \\\\dots, h_n$ satisfying $0 \\\\leq h_1 < h_2 < \\\\dots < h_n \\\\leq 10^{12}$ — the heights.\\n\\n\\n-----Output-----\\n\\nOutput $n$ integers, where the $j$-th integer is the value of $h_j$ after the landslide has stopped.\\n\\n\\n-----Example-----\\nInput\\n4\\n2 6 7 8\\n\\nOutput\\n5 5 6 7\\n\\n\\n\\n-----Note-----\\n\\nInitially, the mountain has heights $2, 6, 7, 8$.\\n\\nIn the first minute, we have $2 + 2 \\\\leq 6$, so $2$ increases to $3$ and $6$ decreases to $5$, leaving $3, 5, 7, 8$.\\n\\nIn the second minute, we have $3 + 2 \\\\leq 5$ and $5 + 2 \\\\leq 7$, so...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n = int(input());tot = sum(map(int, input().split()));extra = (n * (n - 1))\\/\\/2;smol = (tot - extra) \\/\\/ n;out = [smol + i for i in range(n)]\\nfor i in range(tot - sum(out)):out[i] += 1\\nprint(' '.join(map(str,out)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/888\\/B:\\nIvan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0, 0). The robot can process commands. There are four types of commands it can perform:  U — move from the cell (x, y) to (x, y + 1);  D — move from (x, y) to (x, y - 1);  L — move from (x, y) to (x - 1, y);  R — move from (x, y) to (x + 1, y). \\n\\nIvan entered a sequence of n commands, and the robot processed it. After this sequence the robot ended up in the starting cell (0, 0), but Ivan doubts that the sequence is such that after performing it correctly the robot ends up in the same cell. He thinks that some commands were ignored by robot. To acknowledge whether the robot is severely bugged, he needs to calculate the maximum possible number of commands that were performed correctly. Help Ivan to do the calculations!\\n\\n\\n-----Input-----\\n\\nThe first line contains one number n — the length of sequence of commands entered by Ivan (1 ≤ n ≤ 100).\\n\\nThe second line contains the sequence itself — a string consisting of n characters. Each character can be U, D, L or R.\\n\\n\\n-----Output-----\\n\\nPrint the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell.\\n\\n\\n-----Examples-----\\nInput\\n4\\nLDUR\\n\\nOutput\\n4\\n\\nInput\\n5\\nRRRUU\\n\\nOutput\\n0\\n\\nInput\\n6\\nLLRRRR\\n\\nOutput\\n4\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# -*- coding: utf-8 -*-\\n\\nimport math\\nimport collections\\nimport bisect\\nimport heapq\\nimport time\\nimport random\\nimport itertools\\nimport sys\\n\\n\\\"\\\"\\\"\\ncreated by shhuan at 2017\\/11\\/9 23:05\\n\\n\\\"\\\"\\\"\\n\\nN = int(input())\\nS = input()\\n\\n\\nu, d, l, r = S.count('U'), S.count('D'), S.count('L'), S.count('R')\\n\\nprint(N - abs(u-d) - abs(l-r))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAt a break Vanya came to the class and saw an array of $n$ $k$-bit integers $a_1, a_2, \\\\ldots, a_n$ on the board. An integer $x$ is called a $k$-bit integer if $0 \\\\leq x \\\\leq 2^k - 1$. \\n\\nOf course, Vanya was not able to resist and started changing the numbers written on the board. To ensure that no one will note anything, Vanya allowed himself to make only one type of changes: choose an index of the array $i$ ($1 \\\\leq i \\\\leq n$) and replace the number $a_i$ with the number $\\\\overline{a_i}$. We define $\\\\overline{x}$ for a $k$-bit integer $x$ as the $k$-bit integer such that all its $k$ bits differ from the corresponding bits of $x$. \\n\\nVanya does not like the number $0$. Therefore, he likes such segments $[l, r]$ ($1 \\\\leq l \\\\leq r \\\\leq n$) such that $a_l \\\\oplus a_{l+1} \\\\oplus \\\\ldots \\\\oplus a_r \\\\neq 0$, where $\\\\oplus$ denotes the bitwise XOR operation. Determine the maximum number of segments he likes Vanya can get applying zero or more operations described above.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $k$ ($1 \\\\leq n \\\\leq 200\\\\,000$, $1 \\\\leq k \\\\leq 30$).\\n\\nThe next line contains $n$ integers $a_1, a_2, \\\\ldots, a_n$ ($0 \\\\leq a_i \\\\leq 2^k - 1$), separated by spaces — the array of $k$-bit integers.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the maximum possible number of segments with XOR not equal to $0$ that can be obtained by making several (possibly $0$) operations described in the statement.\\n\\n\\n-----Examples-----\\nInput\\n3 2\\n1 3 0\\n\\nOutput\\n5\\nInput\\n6 3\\n1 4 4 7 3 4\\n\\nOutput\\n19\\n\\n\\n-----Note-----\\n\\nIn the first example if Vasya does not perform any operations, he gets an array that has $5$ segments that Vanya likes. If he performs the operation with $i = 2$, he gets an array $[1, 0, 0]$, because $\\\\overline{3} = 0$ when $k = 2$. This array has $3$ segments that Vanya likes. Also, to get an array with $5$ segments that Vanya likes, he can perform two operations with $i = 3$ and with $i = 2$. He then gets an array $[1, 0, 3]$. It can be proven that he can't obtain $6$ or more segments that...\",\"targets\":\"'''input\\n3 2\\n1 3 0\\n'''\\ndef solve():\\n\\tn,k = list(map(int,input().split()))\\n\\tflipVal = (1<<k)-1\\n\\tl = list(map(int,input().split()))\\n\\tD = {}\\n\\tD[0]=1\\n\\tfor i in range(1,n):\\n\\t\\tl[i]^=l[i-1]\\n\\tfor i in range(0,n):\\n\\t\\tl[i]=min(l[i],l[i]^flipVal)\\n\\t\\tif l[i] in D:\\n\\t\\t\\tD[l[i]]+=1\\n\\t\\telse:\\n\\t\\t\\tD[l[i]]=1\\n\\t#print(l)\\n\\ttotal = n*(n+1)\\/\\/2\\n\\tbad = 0\\n\\tfor i in D:\\n\\t\\ttemp = D[i]\\n\\t\\ttot = temp\\/\\/2\\n\\t\\tbad+= tot*(tot-1)\\/\\/2\\n\\t\\ttot = temp - tot\\n\\t\\tbad+= tot*(tot-1)\\/\\/2\\n\\tprint(total-bad)\\n\\treturn\\nt = 1\\n#t = int(input())\\nwhile t>0:\\n\\tt-=1\\n\\tsolve()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n## Story\\n\\n> \\\"You have serious coding skillz? You wannabe a [scener](https:\\/\\/en.wikipedia.org\\/wiki\\/Demoscene)? Complete this mission and u can get in teh crew!\\\"\\n\\nYou have read a similar message on your favourite [diskmag](https:\\/\\/en.wikipedia.org\\/wiki\\/Disk_magazine) back in the early 90s, and got really excited. You contacted the demo crew immediately and they gave you the following job: write a vertical sinus scroller... **for the printer!**\\n\\n## Your task\\n\\nWrite a function that takes three parameters: `text`, `amp` (for [peak amplitude](https:\\/\\/en.wikipedia.org\\/wiki\\/Amplitude)) and `period` (or [wavelength](https:\\/\\/en.wikipedia.org\\/wiki\\/Wavelength)). Return a string (split into multiple lines) that will display the text as a vertical sine wave.\\n\\nNote: `amp` and `period` are measured in characters and are always positive integers; `text` is never empty.\\n\\n## Example\\n\\n```python\\n>>> scroller('Hello World!', 3, 10)\\n'   H\\\\n     e\\\\n      l\\\\n      l\\\\n     o\\\\n    \\\\n W\\\\no\\\\nr\\\\n l\\\\n   d\\\\n     !'\\n```\\n\\nDoesn't make much sense? Well, let's print it!\\n\\n```python\\n   H        1\\n     e      2\\n      l     3\\n      l     4\\n     o      5\\n            6\\n W          7\\no           8\\nr           9\\n l         10\\n   d        1\\n     !      2\\n\\n3210123\\n```\\n\\n(Obviously, the numbers are only shown above to demonstrate `amp` and `period`)\\n\\nHappy coding!\\n\\n*Note:* due to the inevitable use of floats, solutions with slight rounding errors (1 space difference in less than 10% of the output lines) will be accepted.\\n\\n---\\n\\n## My other katas\\n\\nIf you enjoyed this kata then please try [my other katas](https:\\/\\/www.codewars.com\\/collections\\/katas-created-by-anter69)! :-)\\n\\n#### *Translations are welcome!*\",\"targets\":\"import math\\ndef scroller(text, amp, period):\\n    phi = 2*math.pi\\/period \\n    ans = []\\n    for i, e in enumerate(text):\\n        x = math.sin(phi*i)+1 \\n        t = round(x*amp)\\n        temp = ' '*int(t) + e\\n        ans.append(temp)\\n    return '\\\\n'.join(ans)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5e4217e476126b000170489b:\\nMost of this problem is by the original author of [the harder kata](https:\\/\\/www.codewars.com\\/kata\\/556206664efbe6376700005c), I just made it simpler.\\n\\nI read a book recently, titled \\\"Things to Make and Do in the Fourth Dimension\\\" by comedian and mathematician Matt Parker ( [Youtube](https:\\/\\/www.youtube.com\\/user\\/standupmaths) ), and in the first chapter of the book Matt talks about problems he likes to solve in his head to take his mind off the fact that he is in his dentist's chair, we've all been there!\\n\\nThe problem he talks about relates to polydivisible numbers, and I thought a kata should be written on the subject as it's quite interesting. (Well it's interesting to me, so there!)\\n\\n### Polydivisib... huh what?\\n\\nSo what are they?\\n\\nA polydivisible number is divisible in an unusual way. The first digit is cleanly divisible by `1`, the first two digits are cleanly divisible by `2`, the first three by `3`, and so on.\\n\\n### Examples\\n\\nLet's take the number `1232` as an example.\\n```\\n1     \\/ 1 = 1     \\/\\/ Works\\n12    \\/ 2 = 6     \\/\\/ Works\\n123   \\/ 3 = 41    \\/\\/ Works\\n1232  \\/ 4 = 308   \\/\\/ Works\\n```\\n`1232` is a polydivisible number.\\n\\n\\nHowever, let's take the number `123220` and see what happens.\\n```\\n 1      \\/1 = 1    \\/\\/ Works\\n 12     \\/2 = 6    \\/\\/ Works\\n 123    \\/3 = 41   \\/\\/ Works\\n 1232   \\/4 = 308  \\/\\/ Works\\n 12322  \\/5 = 2464.4         \\/\\/ Doesn't work\\n 123220 \\/6 = 220536.333...  \\/\\/ Doesn't work\\n```\\n`123220` is not polydivisible.\\n\\n### Your job: check if a number is polydivisible or not.\\n\\nReturn `true` if it is, and `false` if it isn't.\\n\\nNote: All inputs will be valid numbers between `0` and `2^53-1 (9,007,199,254,740,991)` (inclusive).   \\nNote: All single digit numbers (including `0`) are trivially polydivisible.\\nNote: Except for `0`, no numbers will start with `0`.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def polydivisible(x):\\n    li = list(str(x))\\n    for i, digit in enumerate(li):\\n        if int(\\\"\\\".join(li[:i+1])) % (i + 1) != 0:\\n            return False\\n    return True\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/5d472159d4f8c3001d81b1f8:\\n# Task\\n\\nGiven the birthdates of two people, find the date when the younger one is exactly half the age of the other.\\n\\n# Notes\\n\\n* The dates are given in the format YYYY-MM-DD and are not sorted in any particular order\\n* Round **down** to the nearest day\\n* Return the result as a string, like the input dates\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from datetime import date\\ndef half_life(person1, person2):\\n    p1 = list(map(int,person1.split(\\\"-\\\")))\\n    p1_date = date(p1[0],p1[1],p1[2])\\n    p2 = list(map(int,person2.split(\\\"-\\\")))\\n    p2_date = date(p2[0],p2[1],p2[2])\\n    if p1[0]>p2[0]:\\n        diff = p1_date-p2_date\\n        b = p1_date+diff\\n        return str(b)\\n    else:\\n        diff = p2_date-p1_date\\n        a = p2_date+diff\\n        return str(a)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nArkady invited Anna for a dinner to a sushi restaurant. The restaurant is a bit unusual: it offers $n$ pieces of sushi aligned in a row, and a customer has to choose a continuous subsegment of these sushi to buy.\\n\\nThe pieces of sushi are of two types: either with tuna or with eel. Let's denote the type of the $i$-th from the left sushi as $t_i$, where $t_i = 1$ means it is with tuna, and $t_i = 2$ means it is with eel.\\n\\nArkady does not like tuna, Anna does not like eel. Arkady wants to choose such a continuous subsegment of sushi that it has equal number of sushi of each type and each half of the subsegment has only sushi of one type. For example, subsegment $[2, 2, 2, 1, 1, 1]$ is valid, but subsegment $[1, 2, 1, 2, 1, 2]$ is not, because both halves contain both types of sushi.\\n\\nFind the length of the longest continuous subsegment of sushi Arkady can buy.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($2 \\\\le n \\\\le 100\\\\,000$) — the number of pieces of sushi.\\n\\nThe second line contains $n$ integers $t_1$, $t_2$, ..., $t_n$ ($t_i = 1$, denoting a sushi with tuna or $t_i = 2$, denoting a sushi with eel), representing the types of sushi from left to right.\\n\\nIt is guaranteed that there is at least one piece of sushi of each type. Note that it means that there is at least one valid continuous segment.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the maximum length of a valid continuous segment.\\n\\n\\n-----Examples-----\\nInput\\n7\\n2 2 2 1 1 2 2\\n\\nOutput\\n4\\n\\nInput\\n6\\n1 2 1 2 1 2\\n\\nOutput\\n2\\n\\nInput\\n9\\n2 2 1 1 1 2 2 2 2\\n\\nOutput\\n6\\n\\n\\n\\n-----Note-----\\n\\nIn the first example Arkady can choose the subsegment $[2, 2, 1, 1]$ or the subsegment $[1, 1, 2, 2]$ with length $4$.\\n\\nIn the second example there is no way but to choose one of the subsegments $[2, 1]$ or $[1, 2]$ with length $2$.\\n\\nIn the third example Arkady's best choice is the subsegment $[1, 1, 1, 2, 2, 2]$.\",\"targets\":\"n = int(input())\\nsushi = [int(x) for x in input().strip().split(\\\" \\\")]\\n\\nnewList = []\\nprev = sushi[0]\\nnewList.append(1)\\n\\nfor type in sushi[1:]:\\n    if prev != type:\\n        newList.append(1)\\n    else:\\n        newList[len(newList) - 1] += 1\\n    prev = type\\n\\nmaxSushi = 0\\nfor i, j in zip(newList, newList[1:]):\\n    maxSushi = max(maxSushi, min(i, j))\\n\\nprint(maxSushi * 2)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe are given a certain number ```n``` and we do the product partitions of it.\\n```[59, 3, 2, 2, 2]``` is a product partition of ```1416``` because:\\n```\\n59 * 3 * 2 * 2 * 2 = 1416\\n```\\nWe form a score, ```sc``` for each partition in the following way:\\n- if ```d1, d2, ...., dk``` are the prime factors of ```n```, and ```f1, f2, ...., fk```, the corresponding frequencies for each factor, we calculate:\\n\\n\\n\\nSuposse that we have that ```n = 1416``` \\nThe product partitions of this number with a corresponding special score are as follows:\\n```\\nProduct Partition           Score(sc)\\n[59, 3, 2, 2, 2]             350    # equals to: (59^1 + 3^1 + 2^3) * 5\\n[177, 2, 2, 2]               740    # equals to: (177^1 + 2^3) * 4\\n[118, 3, 2, 2]               500\\n[59, 6, 2, 2]                276\\n[354, 2, 2]                 1074\\n[59, 4, 3, 2]                272\\n[236, 3, 2]                  723\\n[177, 4, 2]                  549\\n[118, 6, 2]                  378\\n[59, 12, 2]                  219\\n[708, 2]                    1420  <---- maximum value\\n[118, 4, 3]                  375\\n[59, 8, 3]                   210\\n[472, 3]                     950\\n[59, 6, 4]                   207\\n[354, 4]                     716\\n[236, 6]                     484\\n[177, 8]                     370\\n[118, 12]                    260\\n[59, 24]                     166  <---- minimum value\\n```\\nSo we need a function that may give us the product partition with maximum or minimum score.\\n\\nThe function ```find_spec_prod_part()``` will receive two arguments:\\n\\n- an integer ```n, n > 0```\\n- a command as a string, one of the following ones: ```'max' or 'min'```\\n\\nThe function should output a list with two elements: the found product partition (as a list sorted in descendin order) with its corresponding score.\\n```\\nfind_spec_prod_part(n, com) ---> [prod_partition, score]\\n```\\nLet'see some cases:\\n```python\\nfind_spec_prod_part(1416, 'max') == [[708, 2], 1420]\\n\\nfind_spec_prod_part(1416, 'min') == [[59, 24], 166]\\n```\\n\\nThe function should reject prime...\",\"targets\":\"from collections import Counter\\nfrom itertools import permutations\\nfrom itertools import chain\\nimport numpy as np\\n\\n\\ndef prime_factors(n):\\n    factors = []\\n    while n % 2 == 0:\\n        n = n \\/\\/ 2\\n        factors.append(2)\\n        \\n    for k in range(3, n+1, 2):\\n        while n % k == 0:\\n            n = n \\/\\/ k\\n            factors.append(k)\\n        if n == 1:\\n            break\\n    return factors\\n\\n   \\ndef get_score(factors):\\n    factor_counts = Counter(factors)\\n    return sum(f**factor_counts[f] for f in factor_counts)*sum(c for c in factor_counts.values())\\n\\n\\ndef int_partitions(m, memo = {}):\\n    if m in memo:\\n        return memo[m]\\n    all_partitions = [[m]]\\n    \\n    for i in range(1, m):\\n        for p in int_partitions(m-i, memo):\\n            all_partitions.append([i] + p)\\n    \\n    memo[m] = all_partitions\\n    return all_partitions\\n\\n\\ndef make_partitions(factors):\\n    partitions = int_partitions(len(factors))\\n    part_perm = []\\n    \\n    for p in partitions:\\n        part_perm.append(set(list(permutations(p, len(p)))))\\n\\n    part_perm = set(list(chain.from_iterable(part_perm)))\\n    all_new_factors = []\\n\\n    for inds in part_perm:        \\n        new_factors = []\\n        j_start = 0\\n\\n        for i in inds:\\n            j_end = j_start + i\\n            new_factors.append(np.product(factors[j_start:j_end]))\\n            j_start = j_end\\n        \\n        if len(new_factors) > 1:\\n            all_new_factors.append(new_factors) \\n    \\n    return all_new_factors\\n\\n\\ndef find_spec_prod_part(n, com):\\n    factors = prime_factors(n)   \\n    \\n    if len(factors) == 1:\\n        return \\\"It is a prime number\\\"\\n    \\n    all_factors = make_partitions(factors)\\n    scores = [get_score(x) for x in all_factors]\\n    \\n    if com == \\\"max\\\":\\n        opt_id = np.argmax(scores)\\n    else:\\n        opt_id = np.argmin(scores)\\n    \\n    return [sorted(all_factors[opt_id], reverse=True), scores[opt_id]]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc067\\/tasks\\/arc078_a:\\nSnuke and Raccoon have a heap of N cards. The i-th card from the top has the integer a_i written on it.\\nThey will share these cards.\\nFirst, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining cards.\\nHere, both Snuke and Raccoon have to take at least one card.\\nLet the sum of the integers on Snuke's cards and Raccoon's cards be x and y, respectively.\\nThey would like to minimize |x-y|.\\nFind the minimum possible value of |x-y|.\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 2 \\\\times 10^5\\n - -10^{9} \\\\leq a_i \\\\leq 10^{9}\\n - a_i is an integer.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\na_1 a_2 ... a_{N}\\n\\n-----Output-----\\nPrint the answer.\\n\\n-----Sample Input-----\\n6\\n1 2 3 4 5 6\\n\\n-----Sample Output-----\\n1\\n\\nIf Snuke takes four cards from the top, and Raccoon takes the remaining two cards, x=10, y=11, and thus |x-y|=1. This is the minimum possible value.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n=int(input())\\na=list(map(int,input().split()))\\nans=2*(10**14)+1\\ns=sum(a)\\nx=0\\ny=s\\nfor i in range(n-1):\\n    x+=a[i]\\n    y-=a[i]\\n    ans=min(ans,abs(x-y))\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/validate-a-roman-number\\/problem:\\n=====Problem Statement=====\\nYou are given a string, and you have to validate whether it's a valid Roman numeral. If it is valid, print True. Otherwise, print False. Try to create a regular expression for a valid Roman numeral.\\n\\n=====Input Format=====\\nA single line of input containing a string of Roman characters.\\n\\n=====Output Format=====\\nOutput a single line containing True or False according to the instructions above.\\n\\n=====Constraints=====\\nThe number will be between 1 and 3999 (both included).\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# Enter your code here. Read input from STDIN. Print output to STDOUT\\nimport re\\ndef my_func(s):\\n    s = s.upper()\\n    ##res=re.match(r'^(?=[MDCLXVI])M*(C[MD]|D?C{0,3})(X[CL]|L?X{0,3})(I[XV]|V?I{0,3})$',s)\\n    res=re.search(r'^M{0,4}(CM|CD|D?C{0,3})(XC|XL|L?X{0,3})(IX|IV|V?I{0,3})$',s)\\n    if(s==\\\"MMMM\\\"):\\n        print(\\\"False\\\")\\n    else:\\n        if res:\\n            print(\\\"True\\\")\\n        else:\\n            print(\\\"False\\\")\\nmy_func(input())\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1174\\/E:\\nLet's define a function $f(p)$ on a permutation $p$ as follows. Let $g_i$ be the greatest common divisor (GCD) of elements $p_1$, $p_2$, ..., $p_i$ (in other words, it is the GCD of the prefix of length $i$). Then $f(p)$ is the number of distinct elements among $g_1$, $g_2$, ..., $g_n$.\\n\\nLet $f_{max}(n)$ be the maximum value of $f(p)$ among all permutations $p$ of integers $1$, $2$, ..., $n$.\\n\\nGiven an integers $n$, count the number of permutations $p$ of integers $1$, $2$, ..., $n$, such that $f(p)$ is equal to $f_{max}(n)$. Since the answer may be large, print the remainder of its division by $1000\\\\,000\\\\,007 = 10^9 + 7$.\\n\\n\\n-----Input-----\\n\\nThe only line contains the integer $n$ ($2 \\\\le n \\\\le 10^6$) — the length of the permutations.\\n\\n\\n-----Output-----\\n\\nThe only line should contain your answer modulo $10^9+7$.\\n\\n\\n-----Examples-----\\nInput\\n2\\n\\nOutput\\n1\\nInput\\n3\\n\\nOutput\\n4\\nInput\\n6\\n\\nOutput\\n120\\n\\n\\n-----Note-----\\n\\nConsider the second example: these are the permutations of length $3$:  $[1,2,3]$, $f(p)=1$.  $[1,3,2]$, $f(p)=1$.  $[2,1,3]$, $f(p)=2$.  $[2,3,1]$, $f(p)=2$.  $[3,1,2]$, $f(p)=2$.  $[3,2,1]$, $f(p)=2$. \\n\\nThe maximum value $f_{max}(3) = 2$, and there are $4$ permutations $p$ such that $f(p)=2$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"p=10**9+7\\nimport math\\ndef prod(l):\\n    x=1\\n    for m in l:\\n        x=x*m%p\\n    return x\\nn=int(input())\\na,k,x,t=[],int(math.log2(n)),n,0\\nwhile x>0:\\n    a.append(x-x\\/\\/2)\\n    x\\/\\/=2\\nc=[sum(a[i:]) for i in range(k+1)]\\nb=[n\\/\\/(3*2**i)-n\\/\\/(6*2**i) for i in range(k+1)]\\nd=[n\\/\\/2**i-n\\/\\/(3*2**i) for i in range(k+1)]\\ny=prod([i for i in range(2,n+1)])\\ns=k if n<3*(2**(k-1)) else 0\\nfor j in range(s,k+1):\\n    e=[a[i] for i in range(j)]+[d[j]]+[b[i] for i in range(j,k)]\\n    x=(y*prod(e))%p\\n    f=prod([sum(e[:i+1]) for i in range(k+1)])\\n    while f>1:\\n        x*=p\\/\\/f+1\\n        f=(f*(p\\/\\/f+1))%p\\n    t+=x%p\\nprint(t%p)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are policeman and you are playing a game with Slavik. The game is turn-based and each turn consists of two phases. During the first phase you make your move and during the second phase Slavik makes his move.\\n\\nThere are $n$ doors, the $i$-th door initially has durability equal to $a_i$.\\n\\nDuring your move you can try to break one of the doors. If you choose door $i$ and its current durability is $b_i$ then you reduce its durability to $max(0, b_i - x)$ (the value $x$ is given).\\n\\nDuring Slavik's move he tries to repair one of the doors. If he chooses door $i$ and its current durability is $b_i$ then he increases its durability to $b_i + y$ (the value $y$ is given). Slavik cannot repair doors with current durability equal to $0$.\\n\\nThe game lasts $10^{100}$ turns. If some player cannot make his move then he has to skip it.\\n\\nYour goal is to maximize the number of doors with durability equal to $0$ at the end of the game. You can assume that Slavik wants to minimize the number of such doors. What is the number of such doors in the end if you both play optimally?\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains three integers $n$, $x$ and $y$ ($1 \\\\le n \\\\le 100$, $1 \\\\le x, y \\\\le 10^5$) — the number of doors, value $x$ and value $y$, respectively.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 10^5$), where $a_i$ is the initial durability of the $i$-th door.\\n\\n\\n-----Output-----\\n\\nPrint one integer — the number of doors with durability equal to $0$ at the end of the game, if you and Slavik both play optimally.\\n\\n\\n-----Examples-----\\nInput\\n6 3 2\\n2 3 1 3 4 2\\n\\nOutput\\n6\\n\\nInput\\n5 3 3\\n1 2 4 2 3\\n\\nOutput\\n2\\n\\nInput\\n5 5 6\\n1 2 6 10 3\\n\\nOutput\\n2\\n\\n\\n\\n-----Note-----\\n\\nClarifications about the optimal strategy will be ignored.\",\"targets\":\"n,x,y=map(int,input().split())\\narr=list(map(int,input().split()))\\nif x<=y:\\n\\tc=0\\n\\tarr=sorted(arr)\\n\\tfor i in range(0,len(arr),2):\\n\\t\\tif arr[i]<=x:\\n\\t\\t\\tc+=1\\n\\tprint(c)\\n\\treturn\\n# if x==y:\\n# \\tc=0\\n# \\tfor i in range(0,len(arr)):\\n# \\t\\tif arr[i]<=x:\\n# \\t\\t\\tc+=1\\n# \\tprint(c\\/\\/2)\\n# \\treturn\\nif x>y:\\n\\tc=0\\n\\tprint(n)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe only difference between easy and hard versions is the constraints.\\n\\nPolycarp has to write a coursework. The coursework consists of $m$ pages.\\n\\nPolycarp also has $n$ cups of coffee. The coffee in the $i$-th cup Polycarp has $a_i$ caffeine in it. Polycarp can drink some cups of coffee (each one no more than once). He can drink cups in any order. Polycarp drinks each cup instantly and completely (i.e. he cannot split any cup into several days).\\n\\nSurely, courseworks are not being written in a single day (in a perfect world of Berland, at least).\\n\\nLet's consider some day of Polycarp's work. Consider Polycarp drinks $k$ cups of coffee during this day and caffeine dosages of cups Polycarp drink during this day are $a_{i_1}, a_{i_2}, \\\\dots, a_{i_k}$. Then the first cup he drinks gives him energy to write $a_{i_1}$ pages of coursework, the second cup gives him energy to write $max(0, a_{i_2} - 1)$ pages, the third cup gives him energy to write $max(0, a_{i_3} - 2)$ pages, ..., the $k$-th cup gives him energy to write $max(0, a_{i_k} - k + 1)$ pages.\\n\\nIf Polycarp doesn't drink coffee during some day, he cannot write coursework at all that day.\\n\\nPolycarp has to finish his coursework as soon as possible (spend the minimum number of days to do it). Your task is to find out this number of days or say that it is impossible.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $m$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$, $1 \\\\le m \\\\le 10^9$) — the number of cups of coffee and the number of pages in the coursework.\\n\\nThe second line of the input contains $n$ integers $a_1, a_2, \\\\dots, a_n$ ($1 \\\\le a_i \\\\le 10^9$), where $a_i$ is the caffeine dosage of coffee in the $i$-th cup.\\n\\n\\n-----Output-----\\n\\nIf it is impossible to write the coursework, print -1. Otherwise print the minimum number of days Polycarp needs to do it.\\n\\n\\n-----Examples-----\\nInput\\n5 8\\n2 3 1 1 2\\n\\nOutput\\n4\\n\\nInput\\n7 10\\n1 3 4 2 1 4 2\\n\\nOutput\\n2\\n\\nInput\\n5 15\\n5 5 5 5 5\\n\\nOutput\\n1\\n\\nInput\\n5 16\\n5 5 5 5 5\\n\\nOutput\\n2\\n\\nInput\\n5 26\\n5 5 5 5...\",\"targets\":\"def check_possibility(days, m, coffee):\\n    sum_coffee = 0\\n    for i, cup in enumerate(coffee):\\n        tax = i \\/\\/ days\\n        if sum_coffee >= m or tax >= cup:\\n            break\\n        sum_coffee += cup - tax\\n    return sum_coffee >= m\\n\\n\\nn, m = list(map(int, input().split()))\\ncoffee = sorted(map(int, input().split()), reverse=True)\\n\\nbad = 0\\ngood = len(coffee)\\n\\nwhile good - bad > 1:\\n    days = (bad + good) \\/\\/ 2\\n    if check_possibility(days, m, coffee):\\n        good = days\\n    else:\\n        bad = days\\n\\npossible = check_possibility(good, m, coffee)\\nprint(good if possible else -1)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have a string S of length N consisting of A, T, C, and G.\\nStrings T_1 and T_2 of the same length are said to be complementary when, for every i (1 \\\\leq i \\\\leq l), the i-th character of T_1 and the i-th character of T_2 are complementary. Here, A and T are complementary to each other, and so are C and G.\\nFind the number of non-empty contiguous substrings T of S that satisfies the following condition:\\n - There exists a string that is a permutation of T and is complementary to T.\\nHere, we distinguish strings that originate from different positions in S, even if the contents are the same.\\n\\n-----Constraints-----\\n - 1 \\\\leq N \\\\leq 5000\\n - S consists of A, T, C, and G.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN S\\n\\n-----Output-----\\nPrint the number of non-empty contiguous substrings T of S that satisfies the condition.\\n\\n-----Sample Input-----\\n4 AGCT\\n\\n-----Sample Output-----\\n2\\n\\nThe following two substrings satisfy the condition:\\n - GC (the 2-nd through 3-rd characters) is complementary to CG, which is a permutation of GC.\\n - AGCT (the 1-st through 4-th characters) is complementary to TCGA, which is a permutation of AGCT.\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n# sys.setrecursionlimit(10**6)\\n\\ndef inp():\\n    return int(input())\\ndef inps():\\n    return input().rstrip()\\ndef inpl():\\n    return list(map(int, input().split()))\\ndef inpls():\\n    return list(map(str, input().split()))\\n\\n# import decimal\\n# from decimal import Decimal\\n# decimal.getcontext().prec = 10\\n\\n# from heapq import heappush, heappop, heapify\\n# import math\\nfrom math import gcd, floor, ceil, factorial\\nimport itertools as it\\nfrom collections import deque, defaultdict\\nfrom collections import Counter\\n\\ndef lcd(a, b):\\n    return a * b \\/\\/ gcd(a, b)\\n\\ndef chmin(dp, i, x):\\n    if x < dp[i]: dp[i] = x; return True\\n    return False\\n\\ndef chmax(dp, i, x): \\n    if x > dp[i]: dp[i] = x; return True\\n    return False\\n\\n# ---------------------------------------\\n\\nN, S = input().split()\\nN = int(N)\\nS = S.rstrip()\\n\\nA = [0] * (N + 1)\\nT = [0] * (N + 1)\\nC = [0] * (N + 1)\\nG = [0] * (N + 1)\\nfor i in range(N):\\n    s = S[i]\\n    A[i+1] = A[i] + (1 if s == \\\"A\\\" else 0)  \\n    T[i+1] = T[i] + (1 if s == \\\"T\\\" else 0)\\n    C[i+1] = C[i] + (1 if s == \\\"C\\\" else 0)\\n    G[i+1] = G[i] + (1 if s == \\\"G\\\" else 0)\\n\\nans = 0\\nfor i in range(N):\\n    j = i + 2\\n    while j <= N:\\n        if A[j] - A[i] == T[j] - T[i] and C[j] - C[i] == G[j] - G[i]:\\n            ans += 1\\n        j += 2\\n            \\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTakahashi has a strong stomach. He never gets a stomachache from eating something whose \\\"best-by\\\" date is at most X days earlier.\\nHe gets a stomachache if the \\\"best-by\\\" date of the food is X+1 or more days earlier, though.\\nOther than that, he finds the food delicious if he eats it not later than the \\\"best-by\\\" date. Otherwise, he does not find it delicious.\\nTakahashi bought some food A days before the \\\"best-by\\\" date, and ate it B days after he bought it.\\nWrite a program that outputs delicious if he found it delicious, safe if he did not found it delicious but did not get a stomachache either, and dangerous if he got a stomachache.\\n\\n-----Constraints-----\\n - 1 ≤ X,A,B ≤ 10^9\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nX A B\\n\\n-----Output-----\\nPrint delicious if Takahashi found the food delicious; print safe if he neither found it delicious nor got a stomachache; print dangerous if he got a stomachache.\\n\\n-----Sample Input-----\\n4 3 6\\n\\n-----Sample Output-----\\nsafe\\n\\nHe ate the food three days after the \\\"best-by\\\" date. It was not delicious or harmful for him.\",\"targets\":\"days_of_fine, day_befoe_exparitation, eating_day = map(int, input().split())\\n\\nif eating_day <= days_of_fine:\\n    print('delicious')\\nelif day_befoe_exparitation < eating_day <= days_of_fine + day_befoe_exparitation:\\n    print('safe')\\nelse:\\n    print('dangerous')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/abc159\\/tasks\\/abc159_a:\\nWe have N+M balls, each of which has an integer written on it.\\n\\nIt is known that:  \\n - The numbers written on N of the balls are even.\\n - The numbers written on M of the balls are odd.\\nFind the number of ways to choose two of the N+M balls (disregarding order) so that the sum of the numbers written on them is even.\\n\\nIt can be shown that this count does not depend on the actual values written on the balls.\\n\\n-----Constraints-----\\n - 0 \\\\leq N,M \\\\leq 100\\n - 2 \\\\leq N+M\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M\\n\\n-----Output-----\\nPrint the answer.\\n\\n-----Sample Input-----\\n2 1\\n\\n-----Sample Output-----\\n1\\n\\nFor example, let us assume that the numbers written on the three balls are 1,2,4.\\n - If we choose the two balls with 1 and 2, the sum is odd;\\n - If we choose the two balls with 1 and 4, the sum is odd;\\n - If we choose the two balls with 2 and 4, the sum is even.\\nThus, the answer is 1.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import math\\n\\nn, m = list(map(int, input().split()))\\n\\ndef c(a, b):\\n    if a >= 2:\\n        return math.factorial(a) \\/\\/ (math.factorial(b) * math.factorial(a - b))\\n    else:\\n        return 0\\n        \\n\\nprint((c(n, 2) + c(m, 2)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/UCOD2020\\/problems\\/DSEXAM:\\nYou are provided with the marks of entire class in Data structures exam out of 100. You need to calculate the number of students having backlog (passing marks is >=31) and the average of the class. But this average is not a normal average, for this average marks of students having backlog are not considered but they will be considered in number of students. Also print the index of topper’s marks and print the difference of everyone’s marks with respect to the topper. \\nIn first line print the number of students having backlog and average of the class. In second line print indices of all the toppers(in case of more than 1 topper print index of all toppers in reverse order). Next N lines print the difference of everyone’s marks with respect to topper(s).\\nNote- if all students have backlog than average will be 0.\\nINPUT\\nThe first line of the input contains an integer T denoting the number of test cases.\\nNext line contains N denoting the no of students in the class.\\nThe line contains N space seprated integers A1,A2,A3….AN denoting the marks of each student in exam.\\nOUTPUT\\nFirst line contains the number of students having backlog and the special average of marks as described above. Average must have 2 decimal places.\\nNext line contains the indices of all the toppers in given array in reverse order.\\nNext N lines contain the difference of every student’s marks with respect to toppers.\\nConstraints\\n1<= T <= 100\\n1<= N <= 30\\n0<= Ai<= 100\\nExample\\nInput\\n1\\n9\\n56 42 94 25 74 99 27 52 83\\nOutput\\n2 55.55\\n5 \\n43\\n57\\n5\\n74\\n25\\n0\\n72\\n47\\n16\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"for j in range(int(input())):\\n input()\\n a = list(map(int,input().split()))\\n marks = 0\\n backlok = 0\\n top_marks = max(a)\\n topper = []\\n for i in range(len(a)):\\n  if(a[i] >= 31):\\n   marks+=a[i]\\n  if(a[i]<31):\\n   backlok+=1\\n  if(a[i] == top_marks):\\n   topper.append(i)\\n print(backlok, \\\"{:0.2f}\\\".format(marks\\/len(a),2))\\n topper.sort(reverse=True)\\n for i in topper:\\n  print(i,\\\" \\\")\\n for i in a:\\n  print(top_marks-i)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nEasy and hard versions are actually different problems, so read statements of both problems completely and carefully.\\n\\nSummer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will read each book together to end this exercise faster.\\n\\nThere are $n$ books in the family library. The $i$-th book is described by three integers: $t_i$ — the amount of time Alice and Bob need to spend to read it, $a_i$ (equals $1$ if Alice likes the $i$-th book and $0$ if not), and $b_i$ (equals $1$ if Bob likes the $i$-th book and $0$ if not).\\n\\nSo they need to choose some books from the given $n$ books in such a way that:\\n\\n  Alice likes at least $k$ books from the chosen set and Bob likes at least $k$ books from the chosen set;  the total reading time of these books is minimized (they are children and want to play and joy as soon a possible). \\n\\nThe set they choose is the same for both Alice an Bob (it's shared between them) and they read all books together, so the total reading time is the sum of $t_i$ over all books that are in the chosen set.\\n\\nYour task is to help them and find any suitable set of books or determine that it is impossible to find such a set.\\n\\n\\n-----Input-----\\n\\nThe first line of the input contains two integers $n$ and $k$ ($1 \\\\le k \\\\le n \\\\le 2 \\\\cdot 10^5$).\\n\\nThe next $n$ lines contain descriptions of books, one description per line: the $i$-th line contains three integers $t_i$, $a_i$ and $b_i$ ($1 \\\\le t_i \\\\le 10^4$, $0 \\\\le a_i, b_i \\\\le 1$), where:\\n\\n  $t_i$ — the amount of time required for reading the $i$-th book;  $a_i$ equals $1$ if Alice likes the $i$-th book and $0$ otherwise;  $b_i$ equals $1$ if Bob likes the $i$-th book and $0$ otherwise. \\n\\n\\n-----Output-----\\n\\nIf there is no solution, print only one integer -1. Otherwise print one integer $T$ — the minimum total reading time of the suitable set of books.\\n\\n\\n-----Examples-----\\nInput\\n8 4\\n7 1 1\\n2 1 1\\n4 0 1\\n8 1 1\\n1 0 1\\n1 1 1\\n1...\",\"targets\":\"#!\\/usr\\/bin\\/env pypy3\\n\\nfrom sys import stdin, stdout\\n \\ndef input():\\n    return stdin.readline().strip()\\n\\nN, K = input().split(' ')\\nN = int(N)\\nK = int(K)\\n\\nalice_only = []\\nbob_only = []\\nboth = []\\n\\nfor _ in range(N):\\n    t, a, b = input().split(' ')\\n    t = int(t)\\n    a = int(a)\\n    b = int(b)\\n\\n    if a == 0 and b == 0: continue\\n    if a == 1 and b == 1: both += [t]\\n    if a == 1 and b == 0: alice_only += [t]\\n    if a == 0 and b == 1: bob_only += [t]\\n\\nhybrid = []\\n\\nalice_only = sorted(alice_only)\\nbob_only = sorted(bob_only)\\n\\nfor a, b in zip(alice_only, bob_only):\\n    hybrid += [a + b]\\n\\ncandidates = sorted(both + hybrid)\\n\\nif len(candidates) < K:\\n    print(-1)\\nelse:\\n    print(sum(candidates[0:K]))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/RTCG2020\\/problems\\/RTCG004:\\nEmily and Mia are friends. Emily got Mia’s essay paper, but since she is a prankster, she decided to meddle with the words present in the paper. She changes all the words in the paper into palindromes. To do this, she follows two rules: \\n- In one operation she can only reduce the value of an alphabet by 1, i.e.  she can change ‘d’ to ‘c’, but she cannot change ‘c’ to ‘d’ or ‘d’ to ‘b’. \\n- The alphabet ‘a’ will not be reduced any further. \\nEach reduction in the value of any alphabet is counted as a single operation. Find the minimum number of operations required to convert a given string into a palindrome.\\n\\n-----Input:-----\\n- The first line contains an integer $T$, denoting the number of test cases. \\n- Each test case consists of a string $S$ containing only lowercase characters with no spaces.\\n\\n-----Output:-----\\nFor each test case on a new line, print the minimum number of operations for the corresponding test case.\\n\\n-----Constraints-----\\n- $1<=T<=10$\\n- $1<=|S|<=10^7$, where $|S|$ denotes length of string S.\\n\\n-----Sample Input:-----\\n4 \\nabc \\nabcba \\nabcd \\ncba\\n\\n-----Sample Output:-----\\n2 \\n0\\n4\\n2\\n\\n-----EXPLANATION:-----\\nFor the first test case string = “abc” \\nc->b->a so the string become “aba” which is a palindrome. For this we perform 2 operations\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"# cook your dish here\\nnumbers = int(input())\\nfor x in range(numbers):\\n    st = input().strip()\\n    l = len(st)\\n    res = 0\\n    j = l - 1\\n    i = 0\\n    while(i < j):\\n        if (st[i] != st[j]):\\n            res += abs(ord(st[i])-ord(st[j]))\\n        i = i + 1\\n        j = j - 1\\n    if res==0:\\n        print(0)\\n    else:\\n        print(res)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nLet's define the niceness of a sequence of positive integers X1,X2,…,XN$X_1, X_2, \\\\dots, X_N$ as the sum of greatest common divisors of all pairs of its elements, i.e.\\nN∑i=1N∑j=i+1gcd(Xi,Xj).∑i=1N∑j=i+1Ngcd(Xi,Xj).\\\\sum_{i=1}^N \\\\sum_{j=i+1}^N \\\\mathrm{gcd}(X_i, X_j)\\\\;.\\nFor example, the niceness of the sequence [1,2,2]$[1, 2, 2]$ is gcd(1,2)+gcd(1,2)+gcd(2,2)=4$gcd(1, 2) + gcd(1, 2) + gcd(2, 2) = 4$.\\nYou are given a sequence A1,A2,…,AN$A_1, A_2, \\\\dots, A_N$; each of its elements is either a positive integer or missing.\\nConsider all possible ways to replace each missing element of A$A$ by a positive integer (not necessarily the same for each element) such that the sum of all elements is equal to S$S$. Your task is to find the total niceness of all resulting sequences, i.e. compute the niceness of each possible resulting sequence and sum up all these values. Since the answer may be very large, compute it modulo 109+7$10^9 + 7$.\\n\\n-----Input-----\\n- The first line of the input contains a single integer T$T$ denoting the number of test cases. The description of T$T$ test cases follows.\\n- The first line of each test case contains two space-separated integers N$N$ and S$S$. \\n- The second line contains N$N$ space-separated integers A1,A2,…,AN$A_1, A_2, \\\\dots, A_N$. Missing elements in this sequence are denoted by −1$-1$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer — the total niceness modulo 109+7$10^9 + 7$.\\n\\n-----Constraints-----\\n- 1≤T≤20$1 \\\\le T \\\\le 20$\\n- 1≤N,S≤50$1 \\\\le N, S \\\\le 50$\\n- 1≤Ai≤50$1 \\\\le A_i \\\\le 50$ or Ai=−1$A_i = -1$ for each valid i$i$\\n\\n-----Subtasks-----\\nSubtask #1 (30 points):\\n- 1≤N,S≤18$1 \\\\le N, S \\\\le 18$\\n- 1≤Ai≤18$1 \\\\le A_i \\\\le 18$ or Ai=−1$A_i = -1$ for each valid i$i$\\nSubtask #2 (70 points): original constraints\\n\\n-----Example Input-----\\n3\\n3 3\\n1 1 -1\\n4 8\\n1 -1 -1 3\\n3 10\\n-1 -1 -1\\n\\n-----Example Output-----\\n3\\n23\\n150\\n\\n-----Explanation-----\\nExample case 1: There is only one possible way to fill in the missing element; the resulting sequence is [1,1,1]$[1, 1, 1]$. Its...\",\"targets\":\"# cook your dish here\\nmod = 10**9 + 7\\nfrom math import gcd\\ndef fac50():\\n    f = [0]*51\\n    f[0] ,f[1] = 1,1\\n    for i in range(1,51):f[i] = (f[i-1]*i)%mod\\n    return f\\ndef gcd110():\\n    gc = [[0]*111 for i in range(111)]\\n    for i in range(111):\\n        for j in range(111):gc[i][j] = gcd(i,j)\\n    return gc\\nfactorials,gcds = fac50(),gcd110()\\ndef rule_asc(n,l):\\n    a,k = [0 for i in range(n + 1)],1\\n    a[1] = n\\n    while k != 0:\\n        x,y = a[k - 1] + 1,a[k] - 1 \\n        k -= 1\\n        while x <= y and k < l - 1:\\n            a[k],y = x,y-x\\n            k += 1\\n        a[k] = x + y\\n        yield a[:k + 1]\\ndef niceness(s):\\n    t = 0\\n    for i in range(len(s)):\\n        for j in range(i+1,len(s)):t = (t + gcds[s[i]][s[j]])%mod\\n    return t\\ndef permcount(s,c):\\n    f,p = [s.count(x) for x in set(s)],factorials[c] \\n    for e in f:p = (p*pow(factorials[e],mod-2,mod))%mod\\n    return p\\ndef main():\\n    for i in range(int(input())):\\n        n,s = [int(item) for item in input().split()]\\n        a = [int(item) for item in input().split()]\\n        b = [i for i in a if i != -1]\\n        s , ones = s - sum(b),a.count(-1)         \\n        if s < 0:print(0)\\n        elif (s == 0 and ones == 0):print(niceness(a)%mod)\\n        elif (s > 0 and ones == 0):print(0)\\n        else:\\n            t = 0\\n            for seq in rule_asc(s,ones):\\n                if len(seq) == ones: t = (t + (((permcount(seq,ones))%mod)*(niceness(b+seq)%mod))%mod)%mod\\n            print(t)         \\ndef __starting_point():main()\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1322\\/D:\\nA popular reality show is recruiting a new cast for the third season! $n$ candidates numbered from $1$ to $n$ have been interviewed. The candidate $i$ has aggressiveness level $l_i$, and recruiting this candidate will cost the show $s_i$ roubles.\\n\\nThe show host reviewes applications of all candidates from $i=1$ to $i=n$ by increasing of their indices, and for each of them she decides whether to recruit this candidate or not. If aggressiveness level of the candidate $i$ is strictly higher than that of any already accepted candidates, then the candidate $i$ will definitely be rejected. Otherwise the host may accept or reject this candidate at her own discretion. The host wants to choose the cast so that to maximize the total profit.\\n\\nThe show makes revenue as follows. For each aggressiveness level $v$ a corresponding profitability value $c_v$ is specified, which can be positive as well as negative. All recruited participants enter the stage one by one by increasing of their indices. When the participant $i$ enters the stage, events proceed as follows:\\n\\n  The show makes $c_{l_i}$ roubles, where $l_i$ is initial aggressiveness level of the participant $i$.  If there are two participants with the same aggressiveness level on stage, they immediately start a fight. The outcome of this is:\\n\\n  the defeated participant is hospitalized and leaves the show.  aggressiveness level of the victorious participant is increased by one, and the show makes $c_t$ roubles, where $t$ is the new aggressiveness level. \\n\\n The fights continue until all participants on stage have distinct aggressiveness levels. \\n\\nIt is allowed to select an empty set of participants (to choose neither of the candidates).\\n\\nThe host wants to recruit the cast so that the total profit is maximized. The profit is calculated as the total revenue from the events on stage, less the total expenses to recruit all accepted participants (that is, their total $s_i$). Help the host to make the show as profitable as possible.\\n\\n\\n-----Input-----\\n\\nThe first line contains...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\nn,m=list(map(int,input().split()))\\nA=list(map(int,input().split()))\\nC=list(map(int,input().split()))\\nP=list(map(int,input().split()))\\n\\nDP=[[-1<<30]*(n+1) for i in range(5001)]\\n# DP[k][cnt] = Aのmaxがkで, そういう人間がcnt人いるときのprofitの最大値\\n\\nfor i in range(5001):\\n    DP[i][0]=0\\n\\nfor i in range(n-1,-1,-1):\\n    a,c = A[i]-1,C[i]\\n\\n    for j in range(n,-1,-1):\\n        if DP[a][j]==-1<<30:\\n            continue\\n        \\n        if DP[a][j] - c + P[a] > DP[a][j+1]:\\n            DP[a][j+1] = DP[a][j] - c + P[a]\\n\\n            x, w=a, j+1\\n            while x+1<n+m:\\n                if DP[x+1][w\\/\\/2] < DP[x][w] + w\\/\\/2 * P[x+1]:\\n                    DP[x+1][w\\/\\/2] = DP[x][w] + w\\/\\/2 * P[x+1]\\n\\n                    x,w=x+1,w\\/\\/2\\n                else:\\n                    break\\n\\nANS=0\\nfor i in range(5001):\\n    ANS=max(ANS,DP[i][0],DP[i][1])\\n\\nprint(ANS)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1090\\/A:\\nA conglomerate consists of $n$ companies. To make managing easier, their owners have decided to merge all companies into one. By law, it is only possible to merge two companies, so the owners plan to select two companies, merge them into one, and continue doing so until there is only one company left.\\n\\nBut anti-monopoly service forbids to merge companies if they suspect unfriendly absorption. The criterion they use is the difference in maximum salaries between two companies. Merging is allowed only if the maximum salaries are equal.\\n\\nTo fulfill the anti-monopoly requirements, the owners can change salaries in their companies before merging. But the labor union insists on two conditions: it is only allowed to increase salaries, moreover all the employees in one company must get the same increase.\\n\\nSure enough, the owners want to minimize the total increase of all salaries in all companies. Help them find the minimal possible increase that will allow them to merge companies into one.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ — the number of companies in the conglomerate ($1 \\\\le n \\\\le 2 \\\\cdot 10^5$). Each of the next $n$ lines describes a company. \\n\\nA company description start with an integer $m_i$ — the number of its employees ($1 \\\\le m_i \\\\le 2 \\\\cdot 10^5$). Then $m_i$ integers follow: the salaries of the employees. All salaries are positive and do not exceed $10^9$. \\n\\nThe total number of employees in all companies does not exceed $2 \\\\cdot 10^5$. \\n\\n\\n-----Output-----\\n\\nOutput a single integer — the minimal total increase of all employees that allows to merge all companies.\\n\\n\\n-----Example-----\\nInput\\n3\\n2 4 3\\n2 2 1\\n3 1 1 1\\n\\nOutput\\n13\\n\\n\\n\\n-----Note-----\\n\\nOne of the optimal merging strategies is the following. First increase all salaries in the second company by $2$, and merge the first and the second companies. Now the conglomerate consists of two companies with salaries $[4, 3, 4, 3]$ and $[1, 1, 1]$. To merge them, increase the salaries in the second of those by $3$. The total increase is $2 +...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"z=[]\\nm=0\\ns=0\\nfor _ in range(int(input())):\\n\\ta=list(map(int,input().split()))\\n\\tz+=[[max(a[1:]),a[0]]]\\n\\tif z[-1][0]>m:\\n\\t\\tm=z[-1][0]\\nfor i in z:\\n\\ts+=(m-i[0])*i[1]\\nprint(s)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/487\\/C:\\nConsider a sequence [a_1, a_2, ... , a_{n}]. Define its prefix product sequence $[ a_{1} \\\\operatorname{mod} n,(a_{1} a_{2}) \\\\operatorname{mod} n, \\\\cdots,(a_{1} a_{2} \\\\cdots a_{n}) \\\\operatorname{mod} n ]$.\\n\\nNow given n, find a permutation of [1, 2, ..., n], such that its prefix product sequence is a permutation of [0, 1, ..., n - 1].\\n\\n\\n-----Input-----\\n\\nThe only input line contains an integer n (1 ≤ n ≤ 10^5).\\n\\n\\n-----Output-----\\n\\nIn the first output line, print \\\"YES\\\" if such sequence exists, or print \\\"NO\\\" if no such sequence exists.\\n\\nIf any solution exists, you should output n more lines. i-th line contains only an integer a_{i}. The elements of the sequence should be different positive integers no larger than n.\\n\\nIf there are multiple solutions, you are allowed to print any of them.\\n\\n\\n-----Examples-----\\nInput\\n7\\n\\nOutput\\nYES\\n1\\n4\\n3\\n6\\n5\\n2\\n7\\n\\nInput\\n6\\n\\nOutput\\nNO\\n\\n\\n\\n-----Note-----\\n\\nFor the second sample, there are no valid sequences.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def comp(x):\\n    for i in range(2, x):\\n        if x % i == 0:\\n            return True\\n    return False\\n\\nN = int(input())\\n\\nif N == 4:\\n    print('YES', '1', '3', '2', '4', sep = '\\\\n')\\nelif comp(N):\\n    print('NO')\\nelse:\\n    print('YES', '1', sep = '\\\\n')\\n    if N > 1:\\n        for i in range(2, N):\\n            print((i - 1) * pow(i, N - 2, N) % N)\\n        print(N)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1105\\/C:\\nAyoub had an array $a$ of integers of size $n$ and this array had two interesting properties:   All the integers in the array were between $l$ and $r$ (inclusive).  The sum of all the elements was divisible by $3$. \\n\\nUnfortunately, Ayoub has lost his array, but he remembers the size of the array $n$ and the numbers $l$ and $r$, so he asked you to find the number of ways to restore the array. \\n\\nSince the answer could be very large, print it modulo $10^9 + 7$ (i.e. the remainder when dividing by $10^9 + 7$). In case there are no satisfying arrays (Ayoub has a wrong memory), print $0$.\\n\\n\\n-----Input-----\\n\\nThe first and only line contains three integers $n$, $l$ and $r$ ($1 \\\\le n \\\\le 2 \\\\cdot 10^5 , 1 \\\\le l \\\\le r \\\\le 10^9$) — the size of the lost array and the range of numbers in the array.\\n\\n\\n-----Output-----\\n\\nPrint the remainder when dividing by $10^9 + 7$ the number of ways to restore the array.\\n\\n\\n-----Examples-----\\nInput\\n2 1 3\\n\\nOutput\\n3\\n\\nInput\\n3 2 2\\n\\nOutput\\n1\\n\\nInput\\n9 9 99\\n\\nOutput\\n711426616\\n\\n\\n\\n-----Note-----\\n\\nIn the first example, the possible arrays are : $[1,2], [2,1], [3, 3]$.\\n\\nIn the second example, the only possible array is $[2, 2, 2]$.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from sys import stdin, stdout\\nprime = 10**9 + 7\\n\\ndef unitMatrix(size):\\n    out = [[0]*size for i in range(size)]\\n    for i in range(size):\\n        out[i][i] = 1\\n    return out\\n\\ndef matrixMult(pre, post):\\n    rows = len(pre)\\n    mid = len(post)\\n    columns = len(post[0])\\n    out = [[0]*columns for i in range(rows)]\\n    for i in range(rows):\\n        for j in range(columns):\\n            for k in range(mid):\\n                out[i][j] += pre[i][k]*post[k][j]\\n                out[i][j] = out[i][j]%prime\\n    return out\\n\\ndef matrixExp(base, power):\\n    if power == 0:\\n        return unitMatrix(len(base))\\n    else:\\n        if power%2 == 0:\\n            half = matrixExp(base, power\\/2)\\n            return matrixMult(half, half)\\n        else:\\n            half = matrixExp(base, (power-1)\\/2)\\n            return matrixMult(matrixMult(half, half), base)\\n\\ndef main():\\n    n, l, r = [int(i) for i in stdin.readline().split()]\\n\\n    vals = [[1], [0], [0]]\\n    mods = [(r-l+1)\\/\\/3 ,(r-l+1)\\/\\/3 ,(r-l+1)\\/\\/3]\\n    remainder = (r-l+1)%3\\n    if remainder >= 1:\\n        mods[l%3] += 1\\n    if remainder == 2:\\n        mods[(l+1)%3] += 1\\n        \\n    transforms = [[mods[0], mods[2], mods[1]], [mods[1], mods[0], mods[2]], [mods[2], mods[1], mods[0]]]\\n    power = matrixExp(transforms, n)\\n    out = matrixMult(power, vals)\\n    print(out[0][0])\\n\\nmain()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a sequence $A_1, A_2, \\\\ldots, A_N$. You have to split the array into maximum number of non-empty subarrays such that the gcd of elements of each subarray is equal to 1.\\n\\n-----Input:-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $N$.\\n- The second line contains $N$ space-separated integers $A_1, A_2, \\\\ldots, A_N$.\\n\\n-----Output:-----\\nFor each test case, print a single line containing one integer ― the maximum number of subarrays formed, or $-1$ if the array cannot be split while satisfying the above condition.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 3$\\n- $1 \\\\le N \\\\le 5 \\\\cdot 10^5$\\n- $1 \\\\le A_i \\\\le 10^6$ for each valid $i$\\n\\n-----Sample Input:-----\\n2\\n3\\n2 2 3\\n4\\n2 3 3 2\\n\\n-----Sample Output:-----\\n1\\n2\",\"targets\":\"MOD = 1000000007\\nMOD2 = 998244353\\nii = lambda: int(input())\\nsi = lambda: input()\\ndgl = lambda: list(map(int, input()))\\nf = lambda: map(int, input().split())\\nil = lambda: list(map(int, input().split()))\\nls = lambda: list(input())\\nfrom math import gcd\\nfor _ in range(ii()):\\n n=ii()\\n l=il()\\n c=0\\n g=0\\n for i in range(n):\\n  g = gcd(g,l[i])\\n  if g==1:\\n   c+=1\\n   g=0\\n print(c)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/atcoder.jp\\/contests\\/arc104\\/tasks\\/arc104_d:\\nGiven positive integers N, K and M, solve the following problem for every integer x between 1 and N (inclusive):\\n - Find the number, modulo M, of non-empty multisets containing between 0 and K (inclusive) instances of each of the integers 1, 2, 3 \\\\cdots, N such that the average of the elements is x.\\n\\n-----Constraints-----\\n - 1 \\\\leq N, K \\\\leq 100\\n - 10^8 \\\\leq M \\\\leq 10^9 + 9\\n - M is prime.\\n - All values in input are integers.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN K M\\n\\n-----Output-----\\nUse the following format:\\nc_1\\nc_2\\n:\\nc_N\\n\\nHere, c_x should be the number, modulo M, of multisets such that the average of the elements is x.\\n\\n-----Sample Input-----\\n3 1 998244353\\n\\n-----Sample Output-----\\n1\\n3\\n1\\n\\nConsider non-empty multisets containing between 0 and 1 instance(s) of each of the integers between 1 and 3. Among them, there are:\\n - one multiset such that the average of the elements is k = 1: \\\\{1\\\\};\\n - three multisets such that the average of the elements is k = 2: \\\\{2\\\\}, \\\\{1, 3\\\\}, \\\\{1, 2, 3\\\\};\\n - one multiset such that the average of the elements is k = 3: \\\\{3\\\\}.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\nreadline = sys.stdin.readline\\n\\nN, K, MOD = list(map(int, readline().split()))\\n\\nMAX = K*(N\\/\\/2)*(N\\/\\/2+1)\\/\\/2+1\\n\\n\\ntable = [[1]]\\n\\nfor idx in range(1, N+1):\\n    dp = table[-1]\\n    dp2 = dp + [0]*(idx*(K+1))\\n    s = idx*(K+1)\\n    for i in range(min(len(dp), len(dp2)-s)):\\n        dp2[i+s] = (dp2[i+s] + -dp[i])%MOD\\n    for i in range(len(dp2)-idx):\\n        dp2[i+idx] = (dp2[i+idx]+dp2[i])%MOD\\n    \\n    if len(dp2) > MAX:\\n        dp2 = dp2[:MAX]\\n    table.append(dp2)\\n\\nAns = [None]*(N+1)\\nfor x in range(1, N+1):\\n    if N-x < x:\\n        Ans[x] = Ans[N+1-x]\\n    ans = 0\\n    for i in range(min(len(table[x-1]), len(table[N-x]))):\\n        ans = (ans + table[x-1][i]*table[N-x][i])%MOD\\n    ans = (ans*(K+1)-1)%MOD\\n    Ans[x] = ans\\nprint(('\\\\n'.join(map(str, Ans[1:]))))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given two positive integers A and B. Compare the magnitudes of these numbers.\\n\\n-----Constraints-----\\n - 1 ≤ A, B ≤ 10^{100}\\n - Neither A nor B begins with a 0.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA\\nB\\n\\n-----Output-----\\nPrint GREATER if A>B, LESS if A<B and EQUAL if A=B.\\n\\n-----Sample Input-----\\n36\\n24\\n\\n-----Sample Output-----\\nGREATER\\n\\nSince 36>24, print GREATER.\",\"targets\":\"a=int(input())\\nb=int(input())\\n\\nif a<b:\\n    print(\\\"LESS\\\")\\nelif a>b:\\n    print(\\\"GREATER\\\")\\nelse:\\n    print(\\\"EQUAL\\\")\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe have two bottles for holding water.\\nBottle 1 can hold up to A milliliters of water, and now it contains B milliliters of water.\\nBottle 2 contains C milliliters of water.\\nWe will transfer water from Bottle 2 to Bottle 1 as much as possible.\\nHow much amount of water will remain in Bottle 2?\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 1 \\\\leq B \\\\leq A \\\\leq 20\\n - 1 \\\\leq C \\\\leq 20\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nA B C\\n\\n-----Output-----\\nPrint the integer representing the amount of water, in milliliters, that will remain in Bottle 2.\\n\\n-----Sample Input-----\\n6 4 3\\n\\n-----Sample Output-----\\n1\\n\\nWe will transfer two milliliters of water from Bottle 2 to Bottle 1, and one milliliter of water will remain in Bottle 2.\",\"targets\":\"a,b,c = map(int, input().split())\\n\\nif c>= a-b:\\n    print(c-(a-b))\\nelse:\\n    print(0)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven an array of integers your solution should find the smallest integer. \\n\\nFor example:\\n\\n- Given `[34, 15, 88, 2]` your solution will return `2`\\n- Given `[34, -345, -1, 100]` your solution will return `-345`\\n\\nYou can assume, for the purpose of this kata, that the supplied array will not be empty.\",\"targets\":\"def find_smallest_int(arr):\\n    return min(arr)\\n#Hellllllyes second kata finished\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nChefina has two sequences $A_1, A_2, \\\\ldots, A_N$ and $B_1, B_2, \\\\ldots, B_N$. She views two sequences with length $N$ as identical if, after they are sorted in non-decreasing order, the $i$-th element of one sequence is equal to the $i$-th element of the other sequence for each $i$ ($1 \\\\le i \\\\le N$).\\nTo impress Chefina, Chef wants to make the sequences identical. He may perform the following operation zero or more times: choose two integers $i$ and $j$ $(1 \\\\le i,j \\\\le N)$ and swap $A_i$ with $B_j$. The cost of each such operation is $\\\\mathrm{min}(A_i, B_j)$.\\nYou have to find the minimum total cost with which Chef can make the two sequences identical.\\n\\n-----Input-----\\n- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.\\n- The first line of each test case contains a single integer $N$.\\n- The second line contains $N$ space-separated integers $A_1, A_2, \\\\ldots, A_N$.\\n- The third line contains $N$ space-separated integers $B_1, B_2, \\\\ldots, B_N$.\\n\\n-----Output-----\\nFor each test case, print a single line containing one integer ― the minimum cost, or $-1$ if no valid sequence of operations exists.\\n\\n-----Constraints-----\\n- $1 \\\\le T \\\\le 2,000$\\n- $1 \\\\le N \\\\le 2 \\\\cdot 10^5$\\n- $1 \\\\le A_i, B_i \\\\le 10^9$ for each valid $i$\\n- the sum of $N$ over all test cases does not exceed $2 \\\\cdot 10^6$\\n\\n-----Subtasks-----\\nSubtask #1 (15 points):\\n- $T \\\\le 20$\\n- $N \\\\le 20$\\nSubtask #2 (85 points): original constraints\\n\\n-----Example Input-----\\n3\\n1\\n1\\n2\\n2\\n1 2\\n2 1\\n2\\n1 1\\n2 2\\n\\n-----Example Output-----\\n-1\\n0\\n1\\n\\n-----Explanation-----\\nExample case 1: There is no way to make the sequences identical, so the answer is $-1$.\\nExample case 2: The sequence are identical initially, so the answer is $0$.\\nExample case 3: We can swap $A_1$ with $B_2$, which makes the two sequences identical, so the answer is $1$.\",\"targets\":\"for _ in range(int(input())):\\n n = int(input())\\n a = list(map(int, input().split()))\\n b = list(map(int, input().split()))\\n minimum = min(min(a), min(b))\\n s = set()\\n ad = {}\\n bd = {}\\n for i in a:\\n  if i in s:\\n   s.remove(i)\\n  else:\\n   s.add(i)\\n  ad[i] = ad.setdefault(i, 0) + 1\\n  bd[i] = bd.setdefault(i, 0) - 1\\n for i in b:\\n  if i in s:\\n   s.remove(i)\\n  else:\\n   s.add(i)\\n  bd[i] = bd.setdefault(i, 0) + 1\\n  ad[i] = ad.setdefault(i, 0) - 1\\n if len(s) > 0:\\n  print(\\\"-1\\\")\\n  continue\\n a = []\\n b = []\\n for i in ad.keys():\\n  if ad[i] > 0:\\n   a.extend([i] * (ad[i] \\/\\/ 2))\\n for i in bd.keys():\\n  if bd[i] > 0:\\n   b.extend([i] * (bd[i] \\/\\/ 2))\\n cost = 0\\n a.sort()\\n b.sort()\\n for i in range(len(a)):\\n  cost += min(min(a[i], b[len(a) - 1 - i]), 2 * minimum)\\n print(cost)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nWe are given a list schedule of employees, which represents the working time for each employee.\\n\\nEach employee has a list of non-overlapping Intervals, and these intervals are in sorted order.\\n\\nReturn the list of finite intervals representing common, positive-length free time for all employees, also in sorted order.\\n\\n\\nExample 1:\\n\\nInput: schedule = [[[1,2],[5,6]],[[1,3]],[[4,10]]]\\nOutput: [[3,4]]\\nExplanation:\\nThere are a total of three employees, and all common\\nfree time intervals would be [-inf, 1], [3, 4], [10, inf].\\nWe discard any intervals that contain inf as they aren't finite.\\n\\n\\nExample 2:\\n\\nInput: schedule = [[[1,3],[6,7]],[[2,4]],[[2,5],[9,12]]]\\nOutput: [[5,6],[7,9]]\\n\\n\\n\\n\\n(Even though we are representing Intervals in the form [x, y], the objects inside are Intervals, not lists or arrays.  For example, schedule[0][0].start = 1, schedule[0][0].end = 2, and schedule[0][0][0] is not defined.)\\n\\nAlso, we wouldn't include intervals like [5, 5] in our answer, as they have zero length.\\n\\n\\nNote:\\nschedule and schedule[i] are lists with lengths in range [1, 50].\\n0 .\",\"targets\":\"class Solution:\\n     def intersectionSizeTwo(self, intervals):\\n         \\\"\\\"\\\"\\n         :type intervals: List[List[int]]\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         r1=[x[0] for x in intervals]\\n         r2=[x[1] for x in intervals]\\n         intervals=sorted(intervals,key=lambda x: x[1])\\n         s=[intervals[0][1]-1,intervals[0][1]]\\n         for interval in intervals:\\n             if interval[0]>s[-1]:\\n                     s+=[interval[1]-1,interval[1]]\\n             elif interval[0]>s[-2]:\\n                 s+=[interval[1]]\\n         return len(s)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/validating-credit-card-number\\/problem:\\n=====Problem Statement=====\\nYou and Fredrick are good friends. Yesterday, Fredrick received\\n\\ncredit cards from ABCD Bank. He wants to verify whether his credit card numbers are valid or not. You happen to be great at regex so he is asking for your help!\\n\\nA valid credit card from ABCD Bank has the following characteristics:\\n\\n► It must start with a 4, 5 or 6.\\n► It must contain exactly 16 digits.\\n► It must only consist of digits (0-9).\\n► It may have digits in groups of 4, separated by one hyphen \\\"-\\\".\\n► It must NOT use any other separator like ' ' , '_', etc.\\n► It must NOT have 4 or more consecutive repeated digits.\\n\\n=====Example=====\\n\\nValid Credit Card Numbers\\n\\n4253625879615786\\n4424424424442444\\n5122-2368-7954-3214\\n\\nInvalid Credit Card Numbers\\n\\n42536258796157867       #17 digits in card number → Invalid \\n4424444424442444        #Consecutive digits are repeating 4 or more times → Invalid\\n5122-2368-7954 - 3214   #Separators other than '-' are used → Invalid\\n44244x4424442444        #Contains non digit characters → Invalid\\n0525362587961578        #Doesn't start with 4, 5 or 6 → Invalid\\n\\n\\n=====Input Format=====\\nThe first line of input contains an integer N.\\nThe next N lines contain credit card numbers. \\n\\n\\n=====Constraints=====\\n0<N<100\\n\\n=====Output Format=====\\nPrint 'Valid' if the credit card number is valid. Otherwise, print 'Invalid'. Do not print the quotes.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import re\\n\\ndef __starting_point():\\n    t = int(input().strip())\\n    \\n    for _ in range(t):\\n        num = \\\"\\\".join(input())\\n        if (re.match(r'^[456]', num) and\\n            (re.match(r'([\\\\d]{4}-){3}[\\\\d]{4}$', num) or\\n             re.match(r'[\\\\d]{16}', num)) and\\n            not re.search(r'(\\\\d)\\\\1{3,}', num.replace(\\\"-\\\", \\\"\\\"))):\\n            print(\\\"Valid\\\")\\n        else:\\n            print(\\\"Invalid\\\")\\n\\n__starting_point()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nTeacher brought a fruit basket for three students. The basket contains only Apples, Mangoes and Oranges. Student A knows a value $a$, the total number of Apples and Mangoes in the Basket, B knows a value $b$, the total number of Mangoes and Oranges in the basket and Student C knows a value $c$, the total number of Oranges and Apples in the Basket. Since the teacher brought it he knows a value $d$ , the total number of fruits in the basket. You have to determine the exact number of Apples , Mangoes and Oranges in the basket separately.\\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each testcase contains of a single line of input, four integers $a,b,c,d$. \\n\\n-----Output:-----\\nFor each testcase, output in a single line the number of Apples , Mangoes and Oranges in this order.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $0 \\\\leq a \\\\leq 1000$\\n- $0 \\\\leq b \\\\leq 1000$\\n- $0 \\\\leq c \\\\leq 1000$\\n- $0 \\\\leq d \\\\leq 1000$ \\n-The Solution always exisits\\n\\n-----Sample Input:-----\\n2\\n\\n7 9 8 12\\n\\n3 8 7 9\\n\\n-----Sample Output:-----\\n3 4 5\\n\\n1 2 6\",\"targets\":\"tc=int(input())\\nwhile(tc>0):\\n a=list(map(int,input().split()))\\n a1=a[3]-a[1]\\n a2=a[3]-a[2]\\n a3=a[3]-a[0]\\n print(a1,a2,a3)\\n tc=tc-1\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1186\\/D:\\nVus the Cossack has $n$ real numbers $a_i$. It is known that the sum of all numbers is equal to $0$. He wants to choose a sequence $b$ the size of which is $n$ such that the sum of all numbers is $0$ and each $b_i$ is either $\\\\lfloor a_i \\\\rfloor$ or $\\\\lceil a_i \\\\rceil$. In other words, $b_i$ equals $a_i$ rounded up or down. It is not necessary to round to the nearest integer.\\n\\nFor example, if $a = [4.58413, 1.22491, -2.10517, -3.70387]$, then $b$ can be equal, for example, to $[4, 2, -2, -4]$. \\n\\nNote that if $a_i$ is an integer, then there is no difference between $\\\\lfloor a_i \\\\rfloor$ and $\\\\lceil a_i \\\\rceil$, $b_i$ will always be equal to $a_i$.\\n\\nHelp Vus the Cossack find such sequence!\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $n$ ($1 \\\\leq n \\\\leq 10^5$) — the number of numbers.\\n\\nEach of the next $n$ lines contains one real number $a_i$ ($|a_i| < 10^5$). It is guaranteed that each $a_i$ has exactly $5$ digits after the decimal point. It is guaranteed that the sum of all the numbers is equal to $0$.\\n\\n\\n-----Output-----\\n\\nIn each of the next $n$ lines, print one integer $b_i$. For each $i$, $|a_i-b_i|<1$ must be met.\\n\\nIf there are multiple answers, print any.\\n\\n\\n-----Examples-----\\nInput\\n4\\n4.58413\\n1.22491\\n-2.10517\\n-3.70387\\n\\nOutput\\n4\\n2\\n-2\\n-4\\n\\nInput\\n5\\n-6.32509\\n3.30066\\n-0.93878\\n2.00000\\n1.96321\\n\\nOutput\\n-6\\n3\\n-1\\n2\\n2\\n\\n\\n\\n-----Note-----\\n\\nThe first example is explained in the legend.\\n\\nIn the second example, we can round the first and fifth numbers up, and the second and third numbers down. We can round the fourth number neither up, nor down.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from math import*\\nn=int(input())\\nsom=0\\nch=[]\\nch2=[]\\nfor i in range(n):\\n    f=float(input())\\n    ch.append(floor(f))\\n    ch2.append(f)\\n    som+=floor(f)\\ni=0\\nwhile som!=0:\\n    if ceil(ch2[i])!=ch2[i]:\\n        som+=1\\n        ch[i]+=1\\n    i+=1\\nfor i in range(n):\\n    print(ch[i])\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\n>When no more interesting kata can be resolved, I just choose to create the new kata, to solve their own, to enjoy the process  --myjinxin2015 said\\n\\n# Description:\\n In kindergarten, the teacher gave the children some candies. The number of candies each child gets is not always the same. Here is an array `candies`(all elements are positive integer). It's the number of candy for each child:\\n ```\\n candies = [10,2,8,22,16,4,10,6,14,20]\\n ```\\n The teacher asked the children to form a circle and play a game: Each child gives half of his candies to the child on his right(at the same time). If the number of children's candy is an odd number, the teacher will give him an extra candy, so that he can evenly distribute his candy. \\n \\n Repeat such distribute process, until all the children's candies are equal in number.\\n \\n You should return two numbers: 1.How many times of distribution; 2. After the game, the number of each child's candy. Returns the result using an array that contains two elements.\\n \\n  \\n# Some examples:\\n\\n```\\n      candies = [ 1,2,3,4,5 ]\\nDistribution 1: [ 4,2,3,4,5 ]\\nDistribution 2: [ 5,3,3,4,5 ]\\nDistribution 3: [ 6,5,4,4,5 ]\\nDistribution 4: [ 6,6,5,4,5 ]\\nDistribution 5: [ 6,6,6,5,5 ]\\nDistribution 6: [ 6,6,6,6,6 ]\\nSo, we need return: [6,6]\\n\\ndistributionOfCandy([1,2,3,4,5]) === [6,6]\\n\\n       candies = [ 10,  2,  8, 22, 16,  4, 10,  6, 14, 20 ]\\ndistribution  1: [ 15,  6,  5, 15, 19, 10,  7,  8, 10, 17 ]\\ndistribution  2: [ 17, 11,  6, 11, 18, 15,  9,  8,  9, 14 ]\\ndistribution  3: [ 16, 15,  9,  9, 15, 17, 13,  9,  9, 12 ]\\ndistribution  4: [ 14, 16, 13, 10, 13, 17, 16, 12, 10, 11 ]\\ndistribution  5: [ 13, 15, 15, 12, 12, 16, 17, 14, 11, 11 ]\\ndistribution  6: [ 13, 15, 16, 14, 12, 14, 17, 16, 13, 12 ]\\ndistribution  7: [ 13, 15, 16, 15, 13, 13, 16, 17, 15, 13 ]\\ndistribution  8: [ 14, 15, 16, 16, 15, 14, 15, 17, 17, 15 ]\\ndistribution  9: [ 15, 15, 16, 16, 16, 15, 15, 17, 18, 17 ]\\ndistribution 10: [ 17, 16, 16, 16, 16, 16, 16, 17, 18, 18 ]\\ndistribution 11: [ 18, 17, 16, 16, 16, 16, 16, 17, 18, 18 ]\\ndistribution 12:...\",\"targets\":\"def distribution_of_candy(candies):\\n    steps = 0\\n    while len(set(candies)) > 1:\\n        candies = [(a + 1) \\/\\/ 2 + (b + 1) \\/\\/ 2\\n                   for a, b in zip(candies, candies[-1:] + candies)]\\n        steps += 1\\n    return [steps, candies.pop()]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codechef.com\\/problems\\/EMITL:\\nYou are given a string S constisting of uppercase Latin letters. Is it possible to reorder the characters in this string to get a string with prefix \\\"LTIME\\\" and suffix \\\"EMITL\\\"?\\nWe remind you that a prefix of a string is any substring which contains its first character, while a suffix of a string is substring containing its last character.\\n\\n-----Input-----\\nThe first line contains a single integer T, denoting the number of testcases. The descriptions of T test cases follow.\\nThe first and only line of the test case description has one non-empty string S consisting of uppercase Latin letters only.\\n\\n-----Output-----\\nFor each testcase output a single line containing the string \\\"YES\\\" (without quotes) if it's possible to reorder the characters to get the required prefix and suffix, or \\\"NO\\\" (without quotes) otherwise.\\n\\n-----Constraints-----\\n- Subtask 1 (23 points) : 1 ≤ T ≤ 100, 1 ≤ |S| ≤ 9\\n- Subtask 2 (77 points) : 1 ≤ T ≤ 1000, 1 ≤ |S| ≤ 100\\n\\n-----Example-----\\nInput:3\\nLTIMEAZAZAITLME\\nLLLTTTIIIMMMEEEAHA\\nLTIMEM\\n\\nOutput:YES\\nYES\\nNO\\n\\n-----Explanation-----\\nTest case 1: we can permute the last 5 letters and get LTIMEAZAZAEMITL\\nTest case 2: we have 3 copies of each of the letters 'L', 'T', 'I', 'M', 'E' so we can leave 5 of them in the beginning and move 5 of them to the end.\\nTest case 3: we have only one letter 'L' so we can't make necessary prefix and suffix at the same time.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"t = int(input())\\nfor T in range(t):\\n s = input()\\n l = s.count(\\\"L\\\")\\n t = s.count(\\\"T\\\")\\n i = s.count(\\\"I\\\")\\n m = s.count(\\\"M\\\")\\n e = s.count(\\\"E\\\")\\n\\n if min(l, t, i, m, e) >= 2 and len(s) > 9:\\n  print(\\\"YES\\\")\\n elif min(l, t, i, m) >= 2 and e >= 1 and len(s) == 9:\\n  print(\\\"YES\\\")\\n else:\\n  print(\\\"NO\\\")\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nDima took up the biology of bacteria, as a result of his experiments, he invented k types of bacteria. Overall, there are n bacteria at his laboratory right now, and the number of bacteria of type i equals c_{i}. For convenience, we will assume that all the bacteria are numbered from 1 to n. The bacteria of type c_{i} are numbered from $(\\\\sum_{k = 1}^{i - 1} c_{k}) + 1$ to $\\\\sum_{k = 1}^{i} c_{k}$.\\n\\nWith the help of special equipment Dima can move energy from some bacteria into some other one. Of course, the use of such equipment is not free. Dima knows m ways to move energy from some bacteria to another one. The way with number i can be described with integers u_{i}, v_{i} and x_{i} mean that this way allows moving energy from bacteria with number u_{i} to bacteria with number v_{i} or vice versa for x_{i} dollars.\\n\\nDima's Chef (Inna) calls the type-distribution correct if there is a way (may be non-direct) to move energy from any bacteria of the particular type to any other bacteria of the same type (between any two bacteria of the same type) for zero cost.\\n\\nAs for correct type-distribution the cost of moving the energy depends only on the types of bacteria help Inna to determine is the type-distribution correct? If it is, print the matrix d with size k × k. Cell d[i][j] of this matrix must be equal to the minimal possible cost of energy-moving from bacteria with type i to bacteria with type j.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers n, m, k (1 ≤ n ≤ 10^5; 0 ≤ m ≤ 10^5; 1 ≤ k ≤ 500). The next line contains k integers c_1, c_2, ..., c_{k} (1 ≤ c_{i} ≤ n). Each of the next m lines contains three integers u_{i}, v_{i}, x_{i} (1 ≤ u_{i}, v_{i} ≤ 10^5; 0 ≤ x_{i} ≤ 10^4). It is guaranteed that $\\\\sum_{i = 1}^{k} c_{i} = n$.\\n\\n\\n-----Output-----\\n\\nIf Dima's type-distribution is correct, print string «Yes», and then k lines: in the i-th line print integers d[i][1], d[i][2], ..., d[i][k] (d[i][i] = 0). If there is no way to move energy from bacteria i to bacteria j appropriate d[i][j] must equal to -1....\",\"targets\":\"#!\\/usr\\/bin\\/env python3\\nfrom sys import stdin\\nfrom bisect import bisect_left, bisect_right\\n    \\nINF = int(1e9)\\n\\ndef find(par, a):\\n    if par[a] == a:\\n        return a\\n    par[a] = find(par, par[a])\\n    return par[a]\\n\\ndef union(par, rnk, a, b):\\n    a = find(par,a)\\n    b = find(par,b)\\n    if a==b:\\n        return\\n    \\n    if rnk[a]<rnk[b]:\\n        par[a] = b\\n    else:\\n        par[b] = a\\n        if rnk[a]==rnk[b]:\\n            rnk[a] += 1\\n    \\ndef solve():\\n    n, m, k = map(int, stdin.readline().split())\\n    cnts = list(map(int, stdin.readline().split()))\\n    for i in range(1,k):\\n        cnts[i] += cnts[i-1]\\n    \\n    group = list(range(n))\\n    rnk = [0 for i in range(n)]\\n    adj = [[INF for j in range(k)] for i in range(k)]\\n    for i in range(m):\\n        u, v, x = map(int, stdin.readline().split())\\n        if x==0:\\n            union(group, rnk, u-1, v-1)\\n        tu = bisect_left(cnts, u)\\n        tv = bisect_left(cnts, v)\\n        adj[tu][tv] = min(adj[tu][tv], x)\\n        adj[tv][tu] = min(adj[tv][tu], x)\\n    \\n    p = 0\\n    for i in range(k):\\n        cur = group[p]\\n        while p<cnts[i]:\\n            if group[p]!=cur:\\n                print(\\\"No\\\")\\n                return\\n            p += 1\\n    print(\\\"Yes\\\")\\n    \\n    for p in range(k):\\n        for i in range(k):\\n            for j in range(k):\\n                adj[i][j] = min(adj[i][j], adj[i][p]+adj[p][j])\\n    \\n    for i in range(k):\\n        adj[i][i] = 0\\n        for j in range(k):\\n            if adj[i][j] == INF:\\n                adj[i][j] = -1\\n    \\n    for i in range(k):\\n        print(' '.join(map(lambda x: str(x), adj[i])))\\n    \\n    \\nsolve()\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThe chef is trying to solve some pattern problems, Chef wants your help to code it. Chef has one number K to form a new pattern. Help the chef to code this pattern problem.\\n\\n-----Input:-----\\n- First-line will contain $T$, the number of test cases. Then the test cases follow. \\n- Each test case contains a single line of input, one integer $K$. \\n\\n-----Output:-----\\nFor each test case, output as the pattern.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 100$\\n- $1 \\\\leq K \\\\leq 100$\\n\\n-----Sample Input:-----\\n3\\n2\\n3\\n4\\n\\n-----Sample Output:-----\\n21\\n1\\n123\\n21\\n1\\n4321\\n123\\n21\\n1\\n\\n-----EXPLANATION:-----\\nNo need, else pattern can be decode easily.\",\"targets\":\"for _ in range(int(input())):\\n n = int(input())\\n l = list(range(1, n+1))\\n\\n while l:\\n  if len(l) % 2 == 0:\\n   print(*l[::-1], sep='')\\n  else:\\n   print(*l, sep='')\\n\\n  l.pop()\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1354\\/A:\\nPolycarp has spent the entire day preparing problems for you. Now he has to sleep for at least $a$ minutes to feel refreshed.\\n\\nPolycarp can only wake up by hearing the sound of his alarm. So he has just fallen asleep and his first alarm goes off in $b$ minutes.\\n\\nEvery time Polycarp wakes up, he decides if he wants to sleep for some more time or not. If he's slept for less than $a$ minutes in total, then he sets his alarm to go off in $c$ minutes after it is reset and spends $d$ minutes to fall asleep again. Otherwise, he gets out of his bed and proceeds with the day.\\n\\nIf the alarm goes off while Polycarp is falling asleep, then he resets his alarm to go off in another $c$ minutes and tries to fall asleep for $d$ minutes again.\\n\\nYou just want to find out when will Polycarp get out of his bed or report that it will never happen.\\n\\nPlease check out the notes for some explanations of the example.\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer $t$ ($1 \\\\le t \\\\le 1000$) — the number of testcases.\\n\\nThe only line of each testcase contains four integers $a, b, c, d$ ($1 \\\\le a, b, c, d \\\\le 10^9$) — the time Polycarp has to sleep for to feel refreshed, the time before the first alarm goes off, the time before every succeeding alarm goes off and the time Polycarp spends to fall asleep.\\n\\n\\n-----Output-----\\n\\nFor each test case print one integer. If Polycarp never gets out of his bed then print -1. Otherwise, print the time it takes for Polycarp to get out of his bed.\\n\\n\\n-----Example-----\\nInput\\n7\\n10 3 6 4\\n11 3 6 4\\n5 9 4 10\\n6 5 2 3\\n1 1 1 1\\n3947465 47342 338129 123123\\n234123843 13 361451236 361451000\\n\\nOutput\\n27\\n27\\n9\\n-1\\n1\\n6471793\\n358578060125049\\n\\n\\n\\n-----Note-----\\n\\nIn the first testcase Polycarp wakes up after $3$ minutes. He only rested for $3$ minutes out of $10$ minutes he needed. So after that he sets his alarm to go off in $6$ minutes and spends $4$ minutes falling asleep. Thus, he rests for $2$ more minutes, totaling in $3+2=5$ minutes of sleep. Then he repeats the procedure three more times and ends up with $11$...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def read_int():\\n    return int(input())\\n\\n\\ndef read_ints():\\n    return list(map(int, input().split(' ')))\\n\\n\\nt = read_int()\\nfor case_num in range(t):\\n    a, b, c, d = read_ints()\\n    if a > b and d >= c:\\n        print(-1)\\n    elif a <= b:\\n        print(b)\\n    else:\\n        remain = a - b\\n        extra = ((remain - 1) \\/\\/ (c - d) + 1) * c\\n        print(b + extra)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nJeff has become friends with Furik. Now these two are going to play one quite amusing game.\\n\\nAt the beginning of the game Jeff takes a piece of paper and writes down a permutation consisting of n numbers: p_1, p_2, ..., p_{n}. Then the guys take turns to make moves, Jeff moves first. During his move, Jeff chooses two adjacent permutation elements and then the boy swaps them. During his move, Furic tosses a coin and if the coin shows \\\"heads\\\" he chooses a random pair of adjacent elements with indexes i and i + 1, for which an inequality p_{i} > p_{i} + 1 holds, and swaps them. But if the coin shows \\\"tails\\\", Furik chooses a random pair of adjacent elements with indexes i and i + 1, for which the inequality p_{i} < p_{i} + 1 holds, and swaps them. If the coin shows \\\"heads\\\" or \\\"tails\\\" and Furik has multiple ways of adjacent pairs to take, then he uniformly takes one of the pairs. If Furik doesn't have any pair to take, he tosses a coin one more time. The game ends when the permutation is sorted in the increasing order.\\n\\nJeff wants the game to finish as quickly as possible (that is, he wants both players to make as few moves as possible). Help Jeff find the minimum mathematical expectation of the number of moves in the game if he moves optimally well.\\n\\nYou can consider that the coin shows the heads (or tails) with the probability of 50 percent.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 ≤ n ≤ 3000). The next line contains n distinct integers p_1, p_2, ..., p_{n} (1 ≤ p_{i} ≤ n) — the permutation p. The numbers are separated by spaces.\\n\\n\\n-----Output-----\\n\\nIn a single line print a single real value — the answer to the problem. The answer will be considered correct if the absolute or relative error doesn't exceed 10^{ - 6}.\\n\\n\\n-----Examples-----\\nInput\\n2\\n1 2\\n\\nOutput\\n0.000000\\n\\nInput\\n5\\n3 5 2 4 1\\n\\nOutput\\n13.000000\\n\\n\\n\\n-----Note-----\\n\\nIn the first test the sequence is already sorted, so the answer is 0.\",\"targets\":\"def count(a):\\n    n   = len(a)\\n    cnt = 0\\n    for i in range(n):\\n        for j in range(i+1, n):\\n            if a[i] > a[j]:\\n                cnt+=1\\n    return cnt          \\n\\nn = int(input())\\np = list(map(int, input().split()))\\nnum = count(p)\\n\\nprint(num*2 - num%2)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nKamil likes streaming the competitive programming videos. His MeTube channel has recently reached $100$ million subscribers. In order to celebrate this, he posted a video with an interesting problem he couldn't solve yet. Can you help him?\\n\\nYou're given a tree — a connected undirected graph consisting of $n$ vertices connected by $n - 1$ edges. The tree is rooted at vertex $1$. A vertex $u$ is called an ancestor of $v$ if it lies on the shortest path between the root and $v$. In particular, a vertex is an ancestor of itself.\\n\\nEach vertex $v$ is assigned its beauty $x_v$ — a non-negative integer not larger than $10^{12}$. This allows us to define the beauty of a path. Let $u$ be an ancestor of $v$. Then we define the beauty $f(u, v)$ as the greatest common divisor of the beauties of all vertices on the shortest path between $u$ and $v$. Formally, if $u=t_1, t_2, t_3, \\\\dots, t_k=v$ are the vertices on the shortest path between $u$ and $v$, then $f(u, v) = \\\\gcd(x_{t_1}, x_{t_2}, \\\\dots, x_{t_k})$. Here, $\\\\gcd$ denotes the greatest common divisor of a set of numbers. In particular, $f(u, u) = \\\\gcd(x_u) = x_u$.\\n\\nYour task is to find the sum\\n\\n$$ \\\\sum_{u\\\\text{ is an ancestor of }v} f(u, v). $$\\n\\nAs the result might be too large, please output it modulo $10^9 + 7$.\\n\\nNote that for each $y$, $\\\\gcd(0, y) = \\\\gcd(y, 0) = y$. In particular, $\\\\gcd(0, 0) = 0$.\\n\\n\\n-----Input-----\\n\\nThe first line contains a single integer $n$ ($2 \\\\le n \\\\le 100\\\\,000$) — the number of vertices in the tree.\\n\\nThe following line contains $n$ integers $x_1, x_2, \\\\dots, x_n$ ($0 \\\\le x_i \\\\le 10^{12}$). The value $x_v$ denotes the beauty of vertex $v$.\\n\\nThe following $n - 1$ lines describe the edges of the tree. Each of them contains two integers $a, b$ ($1 \\\\le a, b \\\\le n$, $a \\\\neq b$) — the vertices connected by a single edge.\\n\\n\\n-----Output-----\\n\\nOutput the sum of the beauties on all paths $(u, v)$ such that $u$ is ancestor of $v$. This sum should be printed modulo $10^9 + 7$.\\n\\n\\n-----Examples-----\\nInput\\n5\\n4 5 6 0 8\\n1 2\\n1 3\\n1 4\\n4 5\\n\\nOutput\\n42\\n\\nInput\\n7\\n0 2...\",\"targets\":\"n = int(input())\\nbeauty = list(map(int, input().strip().split()))\\ntree = [[] for i in range(n)]\\nmod = 1000000007\\nused = [False for i in range(n)]\\ndef gcd(a,b):\\n    mn = min(a,b)\\n    mx = max(a,b)\\n    if mn == 0:\\n        return mx\\n    md = mx%mn\\n    if md == 0:\\n        return mn\\n    else:\\n        return gcd(mn, md)\\nfor i in range(n-1):\\n    a,b = map(int, input().strip().split())\\n    tree[a-1].append(b-1)\\n    tree[b-1].append(a-1)\\nsegment_vals = [{} for i in range(n)]\\nans = beauty[0]\\nsegment_vals[0][beauty[0]] = 1\\ncur_nodes = [0]\\nused[0] = True\\nwhile 1:\\n    new_nodes = []\\n    for node in cur_nodes:\\n        for potential_new in tree[node]:\\n            if used[potential_new] == False:\\n                used[potential_new] = True\\n                new_nodes.append(potential_new)\\n                new_beauty = beauty[potential_new]\\n                segment_vals[potential_new][new_beauty] = 1\\n                for g in segment_vals[node].keys():\\n                    segment_gcd = gcd(new_beauty,g)\\n                    segment_vals[potential_new][segment_gcd] = segment_vals[potential_new].get(segment_gcd,0) + segment_vals[node][g]\\n                for k in segment_vals[potential_new].keys():\\n                    ans += k*segment_vals[potential_new][k]\\n                    ans = ans % mod\\n    if len(new_nodes) == 0:\\n        break\\n    else:\\n        cur_nodes = new_nodes\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1162\\/B:\\nYou are given two $n \\\\times m$ matrices containing integers. A sequence of integers is strictly increasing if each next number is greater than the previous one. A row is strictly increasing if all numbers from left to right are strictly increasing. A column is strictly increasing if all numbers from top to bottom are strictly increasing. A matrix is increasing if all rows are strictly increasing and all columns are strictly increasing. \\n\\nFor example, the matrix $\\\\begin{bmatrix} 9&10&11\\\\\\\\ 11&12&14\\\\\\\\ \\\\end{bmatrix}$ is increasing because each individual row and column is strictly increasing. On the other hand, the matrix $\\\\begin{bmatrix} 1&1\\\\\\\\ 2&3\\\\\\\\ \\\\end{bmatrix}$ is not increasing because the first row is not strictly increasing.\\n\\nLet a position in the $i$-th row (from top) and $j$-th column (from left) in a matrix be denoted as $(i, j)$. \\n\\nIn one operation, you can choose any two numbers $i$ and $j$ and swap the number located in $(i, j)$ in the first matrix with the number in $(i, j)$ in the second matrix. In other words, you can swap two numbers in different matrices if they are located in the corresponding positions.\\n\\nYou would like to make both matrices increasing by performing some number of operations (possibly none). Determine if it is possible to do this. If it is, print \\\"Possible\\\", otherwise, print \\\"Impossible\\\".\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $n$ and $m$ ($1 \\\\leq n,m \\\\leq 50$) — the dimensions of each matrix.\\n\\nEach of the next $n$ lines contains $m$ integers $a_{i1}, a_{i2}, \\\\ldots, a_{im}$ ($1 \\\\leq a_{ij} \\\\leq 10^9$) — the number located in position $(i, j)$ in the first matrix.\\n\\nEach of the next $n$ lines contains $m$ integers $b_{i1}, b_{i2}, \\\\ldots, b_{im}$ ($1 \\\\leq b_{ij} \\\\leq 10^9$) — the number located in position $(i, j)$ in the second matrix.\\n\\n\\n-----Output-----\\n\\nPrint a string \\\"Impossible\\\" or \\\"Possible\\\".\\n\\n\\n-----Examples-----\\nInput\\n2 2\\n2 10\\n11 5\\n9 4\\n3 12\\n\\nOutput\\nPossible\\n\\nInput\\n2 3\\n2 4 5\\n4 5 6\\n3 6 7\\n8 10 11\\n\\nOutput\\nPossible\\n\\nInput\\n3 2\\n1 3\\n2 4\\n5 10\\n3 1\\n3 6\\n4...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"n, m = map(int, input().split())\\nl1 = [list(map(int, input().split())) for i in range(n)]\\nl2 = [list(map(int, input().split())) for i in range(n)]\\nfor i in range(n):\\n    for j in range(m):\\n        l1[i][j], l2[i][j] = min(l1[i][j], l2[i][j]), max(l1[i][j], l2[i][j])\\nans = True\\nfor i in range(1, n):\\n    for j in range(m):\\n        if l1[i][j] <= l1[i - 1][j] or l2[i][j] <= l2[i - 1][j]:\\n            ans = False\\nfor i in range(n):\\n    for j in range(1, m):\\n        if l1[i][j] <= l1[i][j - 1] or l2[i][j] <= l2[i][j - 1]:\\n            ans = False\\nif ans:\\n    print('Possible')\\nelse:\\n    print('Impossible')\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/563e320cee5dddcf77000158:\\nIt's the academic year's end, fateful moment of your school report.\\nThe averages must be calculated. All the students come to you and entreat you to calculate their average for them.\\nEasy ! You just need to write a script.\\n\\nReturn the average of the given array rounded **down** to its nearest integer.\\n\\nThe array will never be empty.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def get_average(marks):\\n    average = sum(marks) \\/ len(marks)    \\n    return int(average)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven a 2D binary matrix filled with 0's and 1's, find the largest square containing only 1's and return its area.\\n\\nExample:\\n\\n\\nInput: \\n\\n1 0 1 0 0\\n1 0 1 1 1\\n1 1 1 1 1\\n1 0 0 1 0\\n\\nOutput: 4\",\"targets\":\"class Solution:\\n     def maximalSquare(self, matrix):\\n         \\\"\\\"\\\"\\n         :type matrix: List[List[str]]\\n         :rtype: int\\n         \\\"\\\"\\\"\\n         if len(matrix) == 0 or len(matrix[0]) == 0:\\n             return 0\\n         \\n         dp = [[0 for i in range(len(matrix[0]))] for i in range(len(matrix))]\\n         \\n         largest = 0;\\n         for i in range(len(matrix)):\\n             dp[i][0] = int(matrix[i][0])\\n             largest = max(largest, dp[i][0])\\n             \\n         for j in range(len(matrix[0])):\\n             dp[0][j] = int(matrix[0][j])\\n             largest = max(largest , dp[0][j])\\n             \\n         \\n         \\n         for i in range(1, len(matrix)):\\n             for j in range(1, len(matrix[0])):\\n                 if matrix[i][j] == '1':\\n                     if dp[i - 1][j] >= dp[i - 1][j - 1] and dp[i][j - 1] >= dp[i - 1][j - 1]:\\n                         dp[i][j] = dp[i - 1][j - 1] + 1\\n \\n                     else:\\n                         dp[i][j] = min(int(dp[i - 1][j]), int(dp[i][j - 1])) + 1\\n                 else:\\n                     dp[i][j] = 0\\n                 \\n                 largest = max(largest, dp[i][j])\\n         \\n         \\n         return largest * largest\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/546ba103f0cf8f7982000df4:\\nIn this kata you need to write a function that will receive two strings (```n1``` and ```n2```), each representing an integer as a binary number. A third parameter will be provided (```o```) as a string representing one of the following operators: add, subtract, multiply.\\n\\nYour task is to write the calculate function so that it will perform the arithmetic and the result returned should be a string representing the binary result.\\n\\nExamples:\\n```\\n1 + 1 === 10\\n10 + 10 === 100\\n```\\n\\nNegative binary numbers are usually preceded by several 1's. For this kata, negative numbers can be represented with the negative symbol at the beginning of the string.\\n\\nExamples of negatives:\\n```\\n1 - 10 === -1\\n10 - 100 === -10\\n```\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def calculate(n1, n2, o):\\n    if o == 'add': return bin(int(n1,2) + int(n2,2))[2:]\\n    if o == 'subtract': \\n        result = bin(int(n1,2) - int(n2,2))\\n        if result[0] == '-':\\n            return result[0] + result[3:]\\n        return result[2:]\\n    if o == 'multiply': return bin(int(n1,2) * int(n2,2))[2:]\\n    if o == 'divide': return bin(int(n1,2) \\/ int(n2,2))[2:]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYour search for Heidi is over – you finally found her at a library, dressed up as a human. In fact, she has spent so much time there that she now runs the place! Her job is to buy books and keep them at the library so that people can borrow and read them. There are n different books, numbered 1 through n.\\n\\nWe will look at the library's operation during n consecutive days. Heidi knows in advance that on the i-th day (1 ≤ i ≤ n) precisely one person will come to the library, request to borrow the book a_{i}, read it in a few hours, and return the book later on the same day.\\n\\nHeidi desperately wants to please all her guests, so she will make sure to always have the book a_{i} available in the library on the i-th day. During the night before the i-th day, she has the option of going to the bookstore (which operates at nights to avoid competition with the library) and buying any book for the price of 1 CHF. Of course, if she already has a book at the library, she does not need to buy it again. Initially, the library contains no books.\\n\\nThere is a problem, though. The capacity of the library is k – this means that at any time, there can be at most k books at the library. If buying a new book would cause Heidi to have more than k books, she must first get rid of some book that she already has, in order to make room for the new book. If she later needs a book that she got rid of, she will need to buy that book again.\\n\\nYou are given k and the sequence of requests for books a_1, a_2, ..., a_{n}. What is the minimum cost (in CHF) of buying new books to satisfy all the requests?\\n\\n\\n-----Input-----\\n\\nThe first line of input will contain two integers n and k (1 ≤ n, k ≤ 80). The second line will contain n integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ n) – the sequence of book requests.\\n\\n\\n-----Output-----\\n\\nOn a single line print the minimum cost of buying books at the store so as to satisfy all requests.\\n\\n\\n-----Examples-----\\nInput\\n4 80\\n1 2 2 1\\n\\nOutput\\n2\\n\\nInput\\n4 1\\n1 2 2 1\\n\\nOutput\\n3\\n\\nInput\\n4 2\\n1 2 3...\",\"targets\":\"n, k = [int(x) for x in input().split()]\\nrequests = [int(x) for x in input().split()]\\n\\nreq_list = {}\\n\\ndef find_last(bucket):\\n    last_book = None\\n    last_date = None\\n    nonlocal req_list\\n    i = 0\\n    for item in bucket:\\n        #print(item, req_list)\\n        if last_book is None:\\n            last_book = item\\n            if len(req_list[item]) < 1:\\n                last_date = float('inf')\\n                return item, i\\n            else:\\n                last_date = req_list[item][0]\\n            index = i\\n        elif len(req_list[item]) >= 1 and req_list[item][0] > last_date:\\n            last_book = item\\n            last_date = req_list[item][0]\\n            index = i\\n        elif len(req_list[item]) < 1 and last_date < float('inf'):\\n            return item, i\\n        i += 1\\n    return last_book, index\\n\\ndef update_reqlist(book):\\n    nonlocal req_list\\n    req_list[book] = req_list[book][1:]\\n\\n\\nfor i in range(n):\\n    if requests[i] in req_list:\\n        req_list[requests[i]].append(i)\\n    else:\\n        req_list[requests[i]] = [i]\\n\\nbucket = []\\nbucket_size = 0\\ncost = 0\\nfor book in requests:\\n    if book in bucket:\\n        update_reqlist(book)\\n        continue\\n    if bucket_size < k:\\n        bucket.append(book)\\n        bucket_size += 1\\n        cost += 1\\n        update_reqlist(book)\\n    else:\\n        last_book, index = find_last(bucket)\\n        if len(bucket) > 1:\\n            bucket.pop(index)\\n        else:\\n            bucket = []\\n        bucket.append(book)\\n        update_reqlist(book)\\n        cost += 1\\n    #print(bucket, req_list)\\n\\n#print(req_list)\\nprint(cost)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nThere are N islands lining up from west to east, connected by N-1 bridges.\\nThe i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.\\nOne day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:\\nRequest i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.\\nYou decided to remove some bridges to meet all these M requests.\\nFind the minimum number of bridges that must be removed.\\n\\n-----Constraints-----\\n - All values in input are integers.\\n - 2 \\\\leq N \\\\leq 10^5\\n - 1 \\\\leq M \\\\leq 10^5\\n - 1 \\\\leq a_i < b_i \\\\leq N\\n - All pairs (a_i, b_i) are distinct.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN M\\na_1 b_1\\na_2 b_2\\n:\\na_M b_M\\n\\n-----Output-----\\nPrint the minimum number of bridges that must be removed.\\n\\n-----Sample Input-----\\n5 2\\n1 4\\n2 5\\n\\n-----Sample Output-----\\n1\\n\\nThe requests can be met by removing the bridge connecting the second and third islands from the west.\",\"targets\":\"N, M = map(int, input().split())\\nreq = []\\nfor i in range(M):\\n    a, b = map(int, input().split())\\n    req.append([a, b])\\n\\nreq = sorted(req, key=lambda x: x[1])\\n\\nans = 1\\ncurrent = req[0][1]\\nfor i in range(1, len(req)):\\n    if req[i][0] < current:\\n        continue\\n    current = req[i][1]\\n    ans += 1\\nprint(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nGiven the coordinates of four points in 2D space, return whether the four points could construct a square.\\n\\nThe coordinate (x,y) of a point is represented by an integer array with two integers.\\n\\nExample:\\n\\nInput: p1 = [0,0], p2 = [1,1], p3 = [1,0], p4 = [0,1]\\nOutput: True\\n\\n\\n\\n Note: \\n\\nAll the input integers are in the range [-10000, 10000].\\nA valid square has four equal sides with positive length and four equal angles (90-degree angles).\\nInput points have no order.\",\"targets\":\"class Solution:\\n     def validSquare(self, p1, p2, p3, p4):\\n         \\\"\\\"\\\"\\n         :type p1: List[int]\\n         :type p2: List[int]\\n         :type p3: List[int]\\n         :type p4: List[int]\\n         :rtype: bool\\n         \\\"\\\"\\\"\\n         \\n         p1 = [p1[0]*4, p1[1]*4]\\n         p2 = [p2[0]*4, p2[1]*4]\\n         p3 = [p3[0]*4, p3[1]*4]\\n \\n         p4 = [p4[0]*4, p4[1]*4]\\n \\n         \\n         center_x = (p1[0] + p2[0] + p3[0] + p4[0]) \\/ 4\\n         center_y = (p1[1] + p2[1] + p3[1] + p4[1]) \\/ 4\\n         #print(center_x, \\\" \\\", center_y)\\n \\n         #if center_x != center_y:\\n             #return False\\n         #print(center_x, \\\" \\\", center_y)\\n \\n         if p1 == [center_x, center_y]:\\n             return False\\n         \\n         #print(center_x, \\\" \\\", center_y)\\n         \\n         center_to_p1 = [center_x - p1[0], center_y - p1[1]]\\n         e_p2 = [(int)(center_x - (center_y - p1[1])), (int)(center_y + (center_x - p1[0]))]\\n         e_p3 = [(int)(center_x + center_x - p1[0]), (int)(center_y + center_y - p1[1])]\\n         e_p4 = [(int)(center_x + (center_y - p1[1])), (int)(center_y - (center_x - p1[0]))]\\n         \\n         #print (\\\"e_p2 \\\", e_p2, \\\" e_p3 \\\", e_p3, \\\" e_p4 \\\", e_p4)\\n         \\n         #print (\\\"p2 \\\", p2, \\\" p3 \\\", p3, \\\" p4 \\\", p4)\\n         \\n         if (e_p2 == p2 or e_p2 == p3 or e_p2 == p4) and (e_p3 == p2 or e_p3 == p3 or e_p3 == p4) and (e_p4 == p2 or e_p4 == p3 or e_p4 == p4):\\n             return True\\n         else:\\n             return False\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou have initially a string of N characters, denoted by A1,A2...AN. You have to print the size of the largest subsequence of string A such that all the characters in that subsequence are distinct ie. no two characters in that subsequence should be same.\\n\\nA subsequence of string A is a sequence that can be derived from A by deleting some elements  and without changing the order of the remaining elements.\\n\\n-----Input-----\\nFirst line contains T, number of testcases. Each testcase consists of a single string in one line. Each character of the string will be a small alphabet(ie. 'a' to 'z').\\n\\n-----Output-----\\nFor each testcase, print the required answer in one line.\\n\\n-----Constraints-----\\n- 1 ≤ T ≤ 10\\n- Subtask 1 (20 points):1 ≤ N ≤ 10\\n- Subtask 2 (80 points):1 ≤ N ≤ 105\\n\\n-----Example-----\\nInput:\\n2\\nabc\\naba\\n\\nOutput:\\n3\\n2\\n\\n-----Explanation-----\\nFor first testcase, the whole string is a subsequence which has all distinct characters.\\n\\nIn second testcase, the we can delete last or first 'a' to get the required subsequence.\",\"targets\":\"for _ in range(int(input())):\\n s = input()\\n arr =[]\\n for i in range(len(s)):\\n  if s[i] in arr:\\n   pass\\n  else:\\n   arr.append(s[i])\\n print(len(arr))\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAn altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \\\\leq i \\\\leq N) is given to you as a character c_i; R stands for red and W stands for white.\\nYou can do the following two kinds of operations any number of times in any order:\\n - Choose two stones (not necessarily adjacent) and swap them.\\n - Choose one stone and change its color (from red to white and vice versa).\\nAccording to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?\\n\\n-----Constraints-----\\n - 2 \\\\leq N \\\\leq 200000\\n - c_i is R or W.\\n\\n-----Input-----\\nInput is given from Standard Input in the following format:\\nN\\nc_{1}c_{2}...c_{N}\\n\\n-----Output-----\\nPrint an integer representing the minimum number of operations needed.\\n\\n-----Sample Input-----\\n4\\nWWRR\\n\\n-----Sample Output-----\\n2\\n\\nFor example, the two operations below will achieve the objective.\\n - Swap the 1-st and 3-rd stones from the left, resulting in RWWR.\\n - Change the color of the 4-th stone from the left, resulting in RWWW.\",\"targets\":\"n = int(input())\\nc = input()\\n\\na = c.count(\\\"R\\\")\\nb = c[:a].count(\\\"W\\\")\\nprint(b)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/593b1909e68ff627c9000186:\\nNickname Generator\\n\\nWrite a function, `nicknameGenerator` that takes a string name as an argument and returns the first 3 or 4 letters as a nickname.\\n\\nIf the 3rd letter is a consonant, return the first 3 letters.\\n\\nIf the 3rd letter is a vowel, return the first 4 letters. \\n\\nIf the string is less than 4 characters, return \\\"Error: Name too short\\\".\\n\\n**Notes:**\\n\\n- Vowels are \\\"aeiou\\\", so discount the letter \\\"y\\\".\\n- Input will always be a string.\\n- Input will always have the first letter capitalised and the rest lowercase (e.g. Sam).\\n- The input can be modified\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"is_vowel = set(\\\"aeiou\\\").__contains__\\n\\ndef nickname_generator(name):\\n    if len(name) < 4: return \\\"Error: Name too short\\\" # Take that Yu, Lee, Bob, and others!\\n    if is_vowel(name[2]): return name[:4]\\n    return name[:3]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nAs a part of this Kata, you need to create a function that when provided with a triplet, returns the index of the numerical element that lies between the other two elements.\\n\\nThe input to the function will be an array of three distinct numbers (Haskell: a tuple).\\n\\nFor example:\\n\\n    gimme([2, 3, 1]) => 0\\n\\n*2* is the number that fits between *1* and *3* and the index of *2* in the input array is *0*.\\n\\nAnother example (just to make sure it is clear):\\n\\n    gimme([5, 10, 14]) => 1\\n    \\n*10* is the number that fits between *5* and *14* and the index of *10* in the input array is *1*.\",\"targets\":\"def gimme(arr):\\n    sort = sorted(arr)\\n    arr.index(sort[1])\\n    return arr.index(sort[1])\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/883\\/G:\\nVasya has a graph containing both directed (oriented) and undirected (non-oriented) edges. There can be multiple edges between a pair of vertices.\\n\\nVasya has picked a vertex s from the graph. Now Vasya wants to create two separate plans:\\n\\n  to orient each undirected edge in one of two possible directions to maximize number of vertices reachable from vertex s;  to orient each undirected edge in one of two possible directions to minimize number of vertices reachable from vertex s. \\n\\nIn each of two plans each undirected edge must become directed. For an edge chosen directions can differ in two plans.\\n\\nHelp Vasya find the plans.\\n\\n\\n-----Input-----\\n\\nThe first line contains three integers n, m and s (2 ≤ n ≤ 3·10^5, 1 ≤ m ≤ 3·10^5, 1 ≤ s ≤ n) — number of vertices and edges in the graph, and the vertex Vasya has picked.\\n\\nThe following m lines contain information about the graph edges. Each line contains three integers t_{i}, u_{i} and v_{i} (1 ≤ t_{i} ≤ 2, 1 ≤ u_{i}, v_{i} ≤ n, u_{i} ≠ v_{i}) — edge type and vertices connected by the edge. If t_{i} = 1 then the edge is directed and goes from the vertex u_{i} to the vertex v_{i}. If t_{i} = 2 then the edge is undirected and it connects the vertices u_{i} and v_{i}.\\n\\nIt is guaranteed that there is at least one undirected edge in the graph.\\n\\n\\n-----Output-----\\n\\nThe first two lines should describe the plan which maximizes the number of reachable vertices. The lines three and four should describe the plan which minimizes the number of reachable vertices.\\n\\nA description of each plan should start with a line containing the number of reachable vertices. The second line of a plan should consist of f symbols '+' and '-', where f is the number of undirected edges in the initial graph. Print '+' as the j-th symbol of the string if the j-th undirected edge (u, v) from the input should be oriented from u to v. Print '-' to signify the opposite direction (from v to u). Consider undirected edges to be numbered in the same order they are given in the input.\\n\\nIf there are multiple...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import sys\\ninput = sys.stdin.readline\\n\\ndef put():\\n  return list(map(int, input().split()))\\n\\n\\n\\n\\ndef dfs0(x):\\n  s = [x]\\n  vis = [0] * n\\n  ans = ['+'] * m\\n  vis[x] = 1\\n  while s:\\n    i = s.pop()\\n    for j, k in graph[i]:\\n      if (vis[j] == 0):\\n        if (k < 0):\\n          ans[-k - 1] = '-'\\n        elif (k > 0):\\n          ans[k - 1] = '+'\\n        \\n          \\n        s.append(j)\\n        vis[j] = 1\\n\\n  return ''.join(ans), sum(vis)\\n\\ndef dfs1(x):\\n  s = [x]\\n  vis = [0] * n\\n  ans = ['+'] * m\\n  vis[x] = 1\\n  while s:\\n    i = s.pop()\\n    for j, k in graph[i]:\\n      if (vis[j] == 0):\\n        if (k < 0):\\n          ans[-k - 1] = '+'\\n        elif (k > 0):\\n          ans[k - 1] = '-'\\n        if (k == 0):\\n          s.append(j)\\n          vis[j] = 1\\n\\n  return ''.join(ans), sum(vis)\\n\\n        \\n\\n  \\n\\n\\n\\n\\nn,m,s = put()\\ngraph = [[] for i in range(n)]\\n\\nk = 1\\n\\nfor _ in range(m):\\n  z,x,y = put()\\n  x,y = x - 1, y - 1\\n  if (z == 1):\\n    graph[x].append((y, 0))\\n  else:\\n    graph[x].append((y, k))\\n    graph[y].append((x, -k))\\n    k += 1\\n\\nm = k - 1\\nx, y = dfs0(s - 1)\\nprint(y)\\nprint(x)\\nx, y = dfs1(s - 1)\\nprint(y)\\nprint(x)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nIvan has n different boxes. The first of them contains some balls of n different colors.\\n\\nIvan wants to play a strange game. He wants to distribute the balls into boxes in such a way that for every i (1 ≤ i ≤ n) i-th box will contain all balls with color i.\\n\\nIn order to do this, Ivan will make some turns. Each turn he does the following:  Ivan chooses any non-empty box and takes all balls from this box;  Then Ivan chooses any k empty boxes (the box from the first step becomes empty, and Ivan is allowed to choose it), separates the balls he took on the previous step into k non-empty groups and puts each group into one of the boxes. He should put each group into a separate box. He can choose either k = 2 or k = 3. \\n\\nThe penalty of the turn is the number of balls Ivan takes from the box during the first step of the turn. And penalty of the game is the total penalty of turns made by Ivan until he distributes all balls to corresponding boxes.\\n\\nHelp Ivan to determine the minimum possible penalty of the game!\\n\\n\\n-----Input-----\\n\\nThe first line contains one integer number n (1 ≤ n ≤ 200000) — the number of boxes and colors.\\n\\nThe second line contains n integer numbers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9), where a_{i} is the number of balls with color i.\\n\\n\\n-----Output-----\\n\\nPrint one number — the minimum possible penalty of the game.\\n\\n\\n-----Examples-----\\nInput\\n3\\n1 2 3\\n\\nOutput\\n6\\n\\nInput\\n4\\n2 3 4 5\\n\\nOutput\\n19\\n\\n\\n\\n-----Note-----\\n\\nIn the first example you take all the balls from the first box, choose k = 3 and sort all colors to corresponding boxes. Penalty is 6.\\n\\nIn the second example you make two turns:   Take all the balls from the first box, choose k = 3, put balls of color 3 to the third box, of color 4 — to the fourth box and the rest put back into the first box. Penalty is 14;  Take all the balls from the first box, choose k = 2, put balls of color 1 to the first box, of color 2 — to the second box. Penalty is 5. \\n\\nTotal penalty is 19.\",\"targets\":\"import heapq as h\\nn = int(input())\\nai = [int(i) for i in input().split()]\\nif n % 2 == 0:\\n    ai = [0] + ai\\nresult = 0\\nh.heapify(ai)\\nwhile len(ai) > 1:\\n\\ta1 = h.heappop(ai)\\n\\ta2 = h.heappop(ai)\\n\\ta3 = h.heappop(ai)\\n\\tresult += a1 + a2 + a3\\n\\th.heappush(ai, a1 + a2 + a3)\\nprint(result)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.codewars.com\\/kata\\/59590976838112bfea0000fa:\\nBorn a misinterpretation of [this kata](https:\\/\\/www.codewars.com\\/kata\\/simple-fun-number-334-two-beggars-and-gold\\/), your task here is pretty simple: given an array of values and an amount of beggars, you are supposed to return an array with the sum of what each beggar brings home, assuming they all take regular turns, from the first to the last.\\n\\nFor example: `[1,2,3,4,5]` for `2` beggars will return a result of `[9,6]`, as the first one takes `[1,3,5]`, the second collects `[2,4]`.\\n\\nThe same array with `3` beggars would have in turn have produced a better out come for the second beggar: `[5,7,3]`, as they will respectively take `[1,4]`, `[2,5]` and `[3]`.\\n\\nAlso note that not all beggars have to take the same amount of \\\"offers\\\", meaning that the length of the array is not necessarily a multiple of `n`; length can be even shorter, in which case the last beggars will of course take nothing (`0`).\\n\\n***Note:*** in case you don't get why this kata is about *English* beggars, then you are not familiar on how religiously queues are taken in the kingdom ;)\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"def beggars(values, n):\\n    return [sum(values[k::n]) for k in range(n)]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nYou are given a permutation p of length n. Remove one element from permutation to make the number of records the maximum possible.\\n\\nWe remind that in a sequence of numbers a_1, a_2, ..., a_{k} the element a_{i} is a record if for every integer j (1 ≤ j < i) the following holds: a_{j} < a_{i}. \\n\\n\\n-----Input-----\\n\\nThe first line contains the only integer n (1 ≤ n ≤ 10^5) — the length of the permutation.\\n\\nThe second line contains n integers p_1, p_2, ..., p_{n} (1 ≤ p_{i} ≤ n) — the permutation. All the integers are distinct.\\n\\n\\n-----Output-----\\n\\nPrint the only integer — the element that should be removed to make the number of records the maximum possible. If there are multiple such elements, print the smallest one.\\n\\n\\n-----Examples-----\\nInput\\n1\\n1\\n\\nOutput\\n1\\n\\nInput\\n5\\n5 1 2 3 4\\n\\nOutput\\n5\\n\\n\\n\\n-----Note-----\\n\\nIn the first example the only element can be removed.\",\"targets\":\"n=int(input())\\nm1=0\\nm2=0\\na=[0]*(n+1)\\na[0]=-n-5\\nmini=n+5\\nk=list(map(int,input().split()))\\nm=0\\n\\nfor i in k:\\n    if i>m:\\n        a[i]=-1\\n    else:\\n        a[i]=0\\n    m=max(m,i)\\n\\nif n==1:\\n    print(k[0])\\n    return\\n\\nfor i in k:\\n    mini=min(mini,i)\\n    if m1>i>m2:\\n        a[m1]+=1\\n        m2=int(i)\\n    if i>m1:\\n        m2=int(m1)\\n        m1=int(i)\\n\\nm=max(a)\\nif m==0:\\n    print(min(k[1:]))\\nelse:\\n    print(a.index(m))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"Solve in Python:\\nRahul is a serial killer. Rahul has been betrayed by his lover in the past and now he want to eliminate entire Universe.He has already Eliminated majority of the population and now only a handful number of people are left. Like other Serial killers, he has an interesting pattern of killing people. \\nHe either kill one individual at a time or if he find two individuals of different heights,he eliminates both of them simultaneously. Now Rahul wants to eliminate them as quickly as he can.\\nSo given $N$ as the number of people left and an array containing height of those $N$ people,tell the minimum number of kills Rahul require to eliminate the entire universe.\\n\\n-----Input:-----\\n- First line will contain $T$, number of testcases. Then the testcases follow. \\n- Each test case constitutes of Two lines. \\n- First line contains $N$, representing the number of people left in the universe\\n- The second line contains an array $a[i]$ of size $N$ containing heights of those $N$ people.\\n\\n-----Output:-----\\nFor each testcase, you have to output a Single line Containing the minimum number of kills required by Rahul to eliminate the Universe.\\n\\n-----Constraints-----\\n- $1 \\\\leq T \\\\leq 50000$\\n- $1 \\\\leq N \\\\leq 50000$\\n- $100 \\\\leq a[i] \\\\leq 10^5$\\n\\n-----Sample Input:-----\\n1\\n10\\n178 184 178 177 171 173 171 183 171 175\\n\\n-----Sample Output:-----\\n5\",\"targets\":\"from math import ceil\\r\\nt=int(input())\\r\\nfor i in range(t):\\r\\n       p=int(input())\\r\\n       l=list(map(int,input().split()))\\r\\n       maxx=1\\r\\n       for i in range(len(l)):\\r\\n           maxx=max(maxx,l.count(l[i]))\\r\\n       if(maxx*2>p):\\r\\n           print(maxx)\\r\\n       else:\\r\\n           q=p-maxx*2\\r\\n           maxx+=ceil(q\\/2)\\r\\n           print(maxx)\",\"language\":\"python\",\"split\":\"train\",\"template\":\"qsol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/www.hackerrank.com\\/challenges\\/class-1-dealing-with-complex-numbers\\/problem:\\n=====Problem Statement=====\\nFor this challenge, you are given two complex numbers, and you have to print the result of their addition, subtraction, multiplication, division and modulus operations. The real and imaginary precision part should be correct up to two decimal places.\\n\\n=====Input Format=====\\nOne line of input: The real and imaginary part of a number separated by a space.\\n\\n=====Output Format=====\\nFor two complex numbers C and D, the output should be in the following sequence on separate lines:\\nC+D\\nC-D\\nC*D\\nC\\/D\\nmod(C)\\nmod(D)\\n\\nFor complex numbers with non-zero real (A) and complex part (B), the output should be in the following format:\\nReplace the plus symbol (+) with a minus symbol (-) when B<0.\\nFor complex numbers with a zero complex part i.e. real numbers, the output should be:\\nA+0.00i\\nFor complex numbers where the real part is zero and the complex part is non-zero, the output should be:\\n0.00+Bi\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"import numbers\\n\\nr1, i1 = map(float, input().split())\\nr2, i2 = map(float, input().split())\\nc1 = complex(r1, i1)\\nc2 = complex(r2, i2)\\n\\ndef printer(c):\\n    real = c.real\\n    imag = c.imag\\n\\n    sign = '+' if imag >= 0 else '-'\\n    print('{:.2f}{}{:.2f}i'.format(real, sign, abs(imag)))\\n\\ndef mod(c):\\n    return (c.real * c.real + c.imag * c.imag) ** 0.5\\n\\nprinter(c1 + c2)\\nprinter(c1 - c2)\\nprinter(c1 * c2)\\nprinter(c1 \\/ c2)\\nprint('{:.2f}+0.00i'.format(mod(c1)))\\nprint('{:.2f}+0.00i'.format(mod(c2)))\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/305\\/C:\\nIvan has got an array of n non-negative integers a_1, a_2, ..., a_{n}. Ivan knows that the array is sorted in the non-decreasing order. \\n\\nIvan wrote out integers 2^{a}_1, 2^{a}_2, ..., 2^{a}_{n} on a piece of paper. Now he wonders, what minimum number of integers of form 2^{b} (b ≥ 0) need to be added to the piece of paper so that the sum of all integers written on the paper equalled 2^{v} - 1 for some integer v (v ≥ 0). \\n\\nHelp Ivan, find the required quantity of numbers.\\n\\n\\n-----Input-----\\n\\nThe first line contains integer n (1 ≤ n ≤ 10^5). The second input line contains n space-separated integers a_1, a_2, ..., a_{n} (0 ≤ a_{i} ≤ 2·10^9). It is guaranteed that a_1 ≤ a_2 ≤ ... ≤ a_{n}.\\n\\n\\n-----Output-----\\n\\nPrint a single integer — the answer to the problem.\\n\\n\\n-----Examples-----\\nInput\\n4\\n0 1 1 1\\n\\nOutput\\n0\\n\\nInput\\n1\\n3\\n\\nOutput\\n3\\n\\n\\n\\n-----Note-----\\n\\nIn the first sample you do not need to add anything, the sum of numbers already equals 2^3 - 1 = 7.\\n\\nIn the second sample you need to add numbers 2^0, 2^1, 2^2.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"from sys import stdin, stdout\\n\\nn = int(stdin.readline())\\nt = list(map(int, stdin.readline().split()))\\n\\ny = s = t[0]\\nx = i = 1\\nwhile True:\\n    while i < n and t[i] == y:\\n        i += 1\\n        x += 1\\n\\n    s += (x + 1) & 1\\n    x \\/\\/= 2\\n    y += 1\\n\\n    if x: continue\\n    if i == n: break\\n    \\n    s += t[i] - y\\n    x, y = 1, t[i]\\n    i += 1        \\n\\nprint(s)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/codeforces.com\\/problemset\\/problem\\/1425\\/E:\\nMr. Chanek is currently participating in a science fair that is popular in town. He finds an exciting puzzle in the fair and wants to solve it.\\n\\nThere are $N$ atoms numbered from $1$ to $N$. These atoms are especially quirky. Initially, each atom is in normal state. Each atom can be in an excited. Exciting atom $i$ requires $D_i$ energy. When atom $i$ is excited, it will give $A_i$ energy. You can excite any number of atoms (including zero).\\n\\nThese atoms also form a peculiar one-way bond. For each $i$, $(1 \\\\le i < N)$, if atom $i$ is excited, atom $E_i$ will also be excited at no cost. Initially, $E_i$ = $i+1$. Note that atom $N$ cannot form a bond to any atom.\\n\\nMr. Chanek must change exactly $K$ bonds. Exactly $K$ times, Mr. Chanek chooses an atom $i$, $(1 \\\\le i < N)$ and changes $E_i$ to a different value other than $i$ and the current $E_i$. Note that an atom's bond can remain unchanged or changed more than once. Help Mr. Chanek determine the maximum energy that he can achieve!\\n\\nnote: You must first change exactly $K$ bonds before you can start exciting atoms.\\n\\n\\n-----Input-----\\n\\nThe first line contains two integers $N$ $K$ $(4 \\\\le N \\\\le 10^5, 0 \\\\le K < N)$, the number of atoms, and the number of bonds that must be changed.\\n\\nThe second line contains $N$ integers $A_i$ $(1 \\\\le A_i \\\\le 10^6)$, which denotes the energy given by atom $i$ when on excited state.\\n\\nThe third line contains $N$ integers $D_i$ $(1 \\\\le D_i \\\\le 10^6)$, which denotes the energy needed to excite atom $i$.\\n\\n\\n-----Output-----\\n\\nA line with an integer that denotes the maximum number of energy that Mr. Chanek can get.\\n\\n\\n-----Example-----\\nInput\\n6 1\\n5 6 7 8 10 2\\n3 5 6 7 1 10\\n\\nOutput\\n35\\n\\n\\n\\n-----Note-----\\n\\nAn optimal solution to change $E_5$ to 1 and then excite atom 5 with energy 1. It will cause atoms 1, 2, 3, 4, 5 be excited. The total energy gained by Mr. Chanek is (5 + 6 + 7 + 8 + 10) - 1 = 35.\\n\\nAnother possible way is to change $E_3$ to 1 and then exciting atom 3 (which will excite atom 1, 2, 3) and exciting atom 4 (which will excite atom 4,...\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"N,K = map(int,input().split())\\nA = list(map(int,input().split()))\\nD = list(map(int,input().split()))\\nif K >= 2:\\n    print(max(0,sum(A)-min(D[:N-1]),A[N-1]-D[N-1]))\\nif K == 0:\\n    S = 0\\n    ans = 0\\n    for i in range(N)[::-1]:\\n        S += A[i]\\n        ans = max(ans,S-D[i])\\n    print(ans)\\nif K == 1:\\n    minD = [D[0]]\\n    csA = [A[0]]\\n    for i in range(1,N):\\n        minD.append(min(minD[-1],D[i]))\\n        csA.append(csA[-1]+A[i])\\n    csinvA = [A[N-1]]\\n    for i in range(N-1)[::-1]:\\n        csinvA.append(csinvA[-1]+A[i])\\n    csinvA = csinvA[::-1]\\n    right = []\\n    S = 0\\n    for i in range(N)[::-1]:\\n        S += A[i]\\n        right.append(S-D[i])\\n    right = right[::-1]\\n    rightM = [right[N-1]]\\n    for i in range(N-1)[::-1]:\\n        rightM.append(max(rightM[-1],right[i]))\\n    rightM = rightM[::-1]\\n    ans = 0\\n    z = 0\\n    for i in range(N)[::-1]:\\n        x = 0\\n        y = csA[i]-minD[i]\\n        if y >= 0:\\n            x += y\\n        x += z\\n        if i != N-1 and i != 0:\\n            ans = max(ans,x)\\n        z = max(z,right[i])\\n    for i in range(N-2):\\n        ans = max(ans,right[i+1])\\n        ans = max(ans,rightM[0]-D[i+1])\\n        ans = max(ans,rightM[i+2])\\n        ans = max(ans,rightM[0]-A[i+1])\\n    print(ans)\",\"language\":\"python\",\"split\":\"test\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"
"{\"inputs\":\"I found an interesting problem on https:\\/\\/leetcode.com\\/problems\\/longest-common-subsequence\\/:\\nGiven two strings text1 and text2, return the length of their longest common subsequence.\\nA subsequence of a string is a new string generated from the original string with some characters(can be none) deleted without changing the relative order of the remaining characters. (eg, \\\"ace\\\" is a subsequence of \\\"abcde\\\" while \\\"aec\\\" is not). A common subsequence of two strings is a subsequence that is common to both strings.\\n \\nIf there is no common subsequence, return 0.\\n \\nExample 1:\\nInput: text1 = \\\"abcde\\\", text2 = \\\"ace\\\" \\nOutput: 3  \\nExplanation: The longest common subsequence is \\\"ace\\\" and its length is 3.\\n\\nExample 2:\\nInput: text1 = \\\"abc\\\", text2 = \\\"abc\\\"\\nOutput: 3\\nExplanation: The longest common subsequence is \\\"abc\\\" and its length is 3.\\n\\nExample 3:\\nInput: text1 = \\\"abc\\\", text2 = \\\"def\\\"\\nOutput: 0\\nExplanation: There is no such common subsequence, so the result is 0.\\n\\n \\nConstraints:\\n\\n1 <= text1.length <= 1000\\n1 <= text2.length <= 1000\\nThe input strings consist of lowercase English characters only.\\n\\nI tried it in Python, but could not do it. Can you solve it?\",\"targets\":\"class Solution:\\n    \\n    def longestCommonSubsequence(self, text1: str, text2: str) -> int:\\n        ## recurrsion => lead to time exceeded\\n        # if not text1 or not text2:\\n        #     return 0            \\n        # if text1[-1]==text2[-1]:\\n        #     return 1+self.longestCommonSubsequence(text1[0:-1],text2[0:-1])\\n        # elif text1[-1] != text2[-1]:\\n        #     t1 = self.longestCommonSubsequence(text1,text2[0:-1])\\n        #     t2 = self.longestCommonSubsequence(text1[0:-1],text2)\\n        #     return max(t1,t2)\\n        ## memorized method \\n#         n = len(text1)\\n#         m = len(text2)\\n#         arr = [[0] * (m+1) for _ in range(n+1)]\\n#         return self.LCS(text1,text2,n,m,arr)\\n        \\n#     def LCS(self,text1,text2,n,m,arr):\\n#         if arr[n][m]:\\n#             return arr[n][m]\\n#         if n==0 or m==0:\\n#             res = 0\\n#         elif text1[n-1]==text2[m-1]:\\n#             res = 1+self.LCS(text1,text2,n-1,m-1,arr)\\n#         else:\\n#             t1 = self.LCS(text1,text2,n,m-1,arr)\\n#             t2 = self.LCS(text1,text2,n-1,m,arr)\\n#             res = max(t1,t2)\\n#         arr[n][m] = res\\n#         return res\\n        # bottom-up method\\n        n,m = len(text1), len(text2)\\n        arr = [[0]*(m+1) for _ in range(n+1)]\\n        for i in range(n+1):\\n            for j in range(m+1):\\n                if i==0 or j==0:\\n                    arr[i][j] = 0\\n                elif text1[i-1]==text2[j-1]:\\n                    arr[i][j] = 1 + arr[i-1][j-1]\\n                else:\\n                    arr[i][j] = max(arr[i-1][j],arr[i][j-1])\\n        return arr[-1][-1] # arr[-1][-1]\",\"language\":\"python\",\"split\":\"train\",\"template\":\"abovesol\",\"dataset\":\"codeparrot\\/apps\",\"config\":\"all\"}\n"