Question: what mass of K3 [subscript] PO4 [subscript] is required to prepare 4 L of 1.5 M solution? 

Answer: formula mass of potassium phosphate= 212.27g/mol\n\nnumber of moles = concentration x volume\nn = 1.5 x 4\nn=6\n\nmass required 6 x 212.27\n=1273.62g
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