Question: MATh Geek plz!!? A wire 360 inches long is cut into 2 pieces. 1 piece is formed into a square adn the other into a circle. if the 2 figures have the same area, what are the lengths of the two pieces of wire.? to the nearest tenth of inch.

Answer: Let the respective pieces of wire be x inches and y inches\n=>x+y=360\nNow if a sqare is made by the x inch long wire,each of its side would be x/4 and the area would be x^2/16\nif a circle is made of the second piece its circumference would be y inches or y=2XPiXr,where r is the radius of the circle  or r=y/2Pi and its area would be PiXr^2=PiX(y/2Pi)(y/2PI)\n=y^2/4Pi=y^2/12.57\nTherefore by the problem x^2/16=y^2/12.57  =.x^2/y^2=16/12.57 \n=>x/y=4/3.545=1.128    =>x=1.128y\nputting the value of x in the equation x+y=360,we get y=162.30 inches \ntherefore x=360-162.30=197.70\nThe pieces were 197.70 in and162.30 in
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