Question: find (3cis(7pi/4))^3 and give answer in trigonometric form (CALC)? can anybody lay out the steps in this problem towards solving it? thanks.

Answer: Using de Moivre's theorem:\n(3cis(7pi/4))^3 = 3^3[cis 3(7pi/4)]\n\n= 27(cis(21pi/4))
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