text: Hot Linked Questions - Page 2 - Cryptography Stack Exchange
  24 questions linked to/from Why is CBC with predictable IV considered insecure against chosen-plaintext attack?
  Background: I'm putting together a personal project to store multiple short message protected by a master password. This is more to learn and demonstrate that I understand how to use some standard ...
  1,03188 silver badges1818 bronze badges
  I'm using the class BouncyCastleAesCbcBytesEncryptor from Spring Security. One of the constructor has the following signature: ...
  aes initialization-vector salt
  asked May 7 '19 at 7:29
  at rest encrypton question from someone who knows nothing
  this forum is way above me and the members here are far, far smarter than I am, so this probaby isn't the place to ask such a simple question, but whatever. All I wanted to ask is for at rest ...
  encryption aes implementation serpent
  asked Feb 13 '18 at 1:22
  Is it required to use a random IV for AES-CBC with random key per message? [duplicate]
  I'm developing a program to encrypt and decrypt a file with AES-256/CBC in Java. And I want it to be safe enough. In my case, I generated random AES key for each file to encrypt and decrypt them. My ...
  aes cbc initialization-vector key-size
  asked Feb 13 '19 at 15:58
  We need to exchange some data encrypted between a device and our software where the device does not have access to a source of randomness. Both the software and the device know the key (although they ...
  asked Sep 14 '16 at 12:43
  Martin Kolinek
  Best practices for IV generation
  What are the best practices for IV generation for AES and other algorithms? Is RNG enough? What if I cannot use RNG and need to use a variable that is related to some characteristic of the ...
  asked Sep 27 '19 at 19:59
  Crypto_dxb
  Randomly initialised global counter used to encrypt the kth message with IV = IV + k mod 2^n
  The use of an increasing IV is not secure for a block cipher. That is, using a random IV for the first message then IV + 1 for the second , IV + 2 for the 3rd etc. How can I construct an attack to ...