code: function findAllAfter(parent, index, test) {
    var results = []
    var children
    var child
    var length
  
    if (!parent || !parent.type || !parent.children) {
      throw new Error('Expected parent node')
    }
  
    children = parent.children
    length = children.length
  
    if (index && index.type) {
      index = children.indexOf(index)
    }
  
    if (isNaN(index) || index < 0 || index === Infinity) {
      throw new Error('Expected positive finite index or child node')
    }
  
    while (++index < length) {
      child = children[index]
  
      if (is(test, child, index, parent)) {
        results.push(child)
      }
    }
  
    return results
  }
docs: /* Find nodes after `index` in `parent` which pass `test`.