code: function compare(a, b, n) {
  	var n2 = n,
  		then = Date.now()
  	while (n2--) {
  		a === b
  	}
  	return (Date.now() - then) * 1e6 / n
  }
docs: Compute a==b n times
  @param {string} a
  @param {string} b
  @param {number} n
  @returns {number} The time per comparison (in ns)