code: @Pure
  	public IntegerProperty minXProperty() {
  		if (this.minX == null) {
  			this.minX = new SimpleIntegerProperty(this, MathFXAttributeNames.MINIMUM_X) {
  				@Override
  				protected void invalidated() {
  					final int currentMin = get();
  					final int currentMax = getMaxX();
  					if (currentMax < currentMin) {
  						// min-max constrain is broken
  						maxXProperty().set(currentMin);
  					}
  				}
  			};
  		}
  		return this.minX;
  	}
docs: Replies the property that is the minimum x coordinate of the box.
  
  @return the minX property.