code: public XMLResource xml(JSONPathQuery path) throws Exception {
  		Object jsonValue = path.eval(this);
  		return xml(jsonValue.toString());
  	}
docs: Execute the given path query on the json and GET the returned URI expecting text/*
  
  @param path path to the URI to follow
  @return a new resource, as a result of getting it from the server in JSON format
  @throws Exception