code: public JSONResource json(XPathQuery path) throws Exception {
  		String uri = path.eval(this, String.class);
  		return json(uri);
  	}
docs: Execute the given path query on the XML, GET the returned URI expecting JSON as content
  
  @param path path to the URI to follow, must be a String QName result
  @return a new resource, as a result of getting it from the server in JSON format
  @throws Exception
  @throws JSONException