code: public URL getResource(String name) {
          URL url;
          if (parent != null) {
              url = parent.getResource(name);
          } else {
              url = getBootstrapResource(name);
          }
          if (url == null) {
              url = findResource(name);
          }
          return url;
      }
docs: Finds the resource with the given name.  A resource is some data
  (images, audio, text, etc) that can be accessed by class code in a way
  that is independent of the location of the code.
  
  <p> The name of a resource is a '<tt>/</tt>'-separated path name that
  identifies the resource.
  
  <p> This method will first search the parent class loader for the
  resource; if the parent is <tt>null</tt> the path of the class loader
  built-in to the virtual machine is searched.  That failing, this method
  will invoke {@link #findResource(String)} to find the resource.  </p>
  
  @apiNote When overriding this method it is recommended that an
  implementation ensures that any delegation is consistent with the {@link
  #getResources(java.lang.String) getResources(String)} method.
  
  @param  name
  The resource name
  
  @return  A <tt>URL</tt> object for reading the resource, or
  <tt>null</tt> if the resource could not be found or the invoker
  doesn't have adequate  privileges to get the resource.
  
  @since  1.1