code: def max_lemma_count(ambiguous_word: str) -> "wn.Synset":
      
      sense2lemmacounts = {}
      for i in wn.synsets(ambiguous_word, pos=None):
          sense2lemmacounts[i] = sum(j.count() for j in i.lemmas())
      return max(sense2lemmacounts, key=sense2lemmacounts.get)
docs: Returns the sense with the highest lemma_name count.
      The max_lemma_count() can be treated as a rough gauge for the
      Most Frequent Sense (MFS), if no other sense annotated corpus is available.
      NOTE: The lemma counts are from the Brown Corpus
  
      :param ambiguous_word: String, a single word.
      :return: The estimated most common Synset.