code: def structurally_match(self, o):
          
  
          # TODO: Convert a and b into canonical forms
  
          if self.op != o.op:
              return False
  
          if len(self.args) != len(o.args):
              return False
  
          for arg_a, arg_b in zip(self.args, o.args):
              if not isinstance(arg_a, Base):
                  if type(arg_a) != type(arg_b):
                      return False
                  # They are not ASTs
                  if arg_a != arg_b:
                      return False
                  else:
                      continue
  
              if arg_a.op in operations.leaf_operations:
                  if arg_a is not arg_b:
                      return False
  
              else:
                  if not arg_a.structurally_match(arg_b):
                      return False
  
          return True
docs: Structurally compares two A objects, and check if their corresponding leaves are definitely the same A object
          (name-wise or hash-identity wise).
  
          :param o: the other claripy A object
          :return: True/False