code: def _feature_most_alternative(self, results, full_results=False):
          
          try:
              alt_names = [len(i['alternativenames']) for i in results['hits']['hits']]
              most_alt = results['hits']['hits'][np.array(alt_names).argmax()]
              if full_results:
                  return most_alt
              else:
                  return most_alt['country_code3']
          except (IndexError, ValueError, TypeError):
              return ""
docs: Find the placename with the most alternative names and return its country.
          More alternative names are a rough measure of importance.
  
          Paramaters
          ----------
          results: dict
              output of `query_geonames`
  
          Returns
          -------
          most_alt: str
              ISO code of country of place with most alternative names,
              or empty string if none