code: def _authority(scheme=DEFAULT_SCHEME, host=DEFAULT_HOST, port=DEFAULT_PORT):
      
      if ':' in host:
          # IPv6 addresses must be enclosed in [ ] in order to be well
          # formed.
          host = '[' + host + ']'
      return UrlEncoded("%s://%s:%s" % (scheme, host, port), skip_encode=True)
docs: Construct a URL authority from the given *scheme*, *host*, and *port*.
  
      Named in accordance with RFC2396_, which defines URLs as::
  
          <scheme>://<authority><path>?<query>
  
      .. _RFC2396: http://www.ietf.org/rfc/rfc2396.txt
  
      So ``https://localhost:8000/a/b/b?boris=hilda`` would be parsed as::
  
          scheme := https
          authority := localhost:8000
          path := /a/b/c
          query := boris=hilda
  
      :param scheme: URL scheme (the default is "https")
      :type scheme: "http" or "https"
      :param host: The host name (the default is "localhost")
      :type host: string
      :param port: The port number (the default is 8089)
      :type port: integer
      :return: The URL authority.
      :rtype: UrlEncoded (subclass of ``str``)
  
      **Example**::
  
          _authority() == "https://localhost:8089"
  
          _authority(host="splunk.utopia.net") == "https://splunk.utopia.net:8089"
  
          _authority(host="2001:0db8:85a3:0000:0000:8a2e:0370:7334") == \
              "https://[2001:0db8:85a3:0000:0000:8a2e:0370:7334]:8089"
  
          _authority(scheme="http", host="splunk.utopia.net", port="471") == \
              "http://splunk.utopia.net:471"