code: def get_next_work_day(self, division=None, date=None):
          
          date = date or datetime.date.today()
          one_day = datetime.timedelta(days=1)
          holidays = set(holiday['date'] for holiday in self.get_holidays(division=division))
          while True:
              date += one_day
              if date.weekday() not in self.weekend and date not in holidays:
                  return date
docs: Returns the next work day, skipping weekends and bank holidays
          :param division: see division constants; defaults to common holidays
          :param date: search starting from this date; defaults to today
          :return: datetime.date; NB: get_next_holiday returns a dict