code: def resource_filename(package_or_requirement, resource_name):
      
      if pkg_resources.resource_exists(package_or_requirement, resource_name):
          return pkg_resources.resource_filename(package_or_requirement, resource_name)
  
      path = _search_in_share_folders(package_or_requirement, resource_name)
  
      if path:
          return path
  
      raise RuntimeError("Resource {} not found in {}".format(package_or_requirement, resource_name))
docs: Similar to pkg_resources.resource_filename but if the resource it not found via pkg_resources
      it also looks in a predefined list of paths in order to find the resource
  
      :param package_or_requirement: the module in which the resource resides
      :param resource_name: the name of the resource
      :return: the path to the resource
      :rtype: str