code: def _send(self, message):
          
          message['command'] = 'zappa.asynchronous.route_lambda_task'
          payload = json.dumps(message).encode('utf-8')
          if len(payload) > LAMBDA_ASYNC_PAYLOAD_LIMIT: # pragma: no cover
              raise AsyncException("Payload too large for async Lambda call")
          self.response = self.client.invoke(
                                      FunctionName=self.lambda_function_name,
                                      InvocationType='Event', #makes the call async
                                      Payload=payload
                                  )
          self.sent = (self.response.get('StatusCode', 0) == 202)
docs: Given a message, directly invoke the lamdba function for this task.