code: def nltk_tree_to_logical_form(tree: Tree) -> str:
      
      # nltk.Tree actually inherits from `list`, so you use `len()` to get the number of children.
      # We're going to be explicit about checking length, instead of using `if tree:`, just to avoid
      # any funny business nltk might have done (e.g., it's really odd if `if tree:` evaluates to
      # `False` if there's a single leaf node with no children).
      if len(tree) == 0:  # pylint: disable=len-as-condition
          return tree.label()
      if len(tree) == 1:
          return tree[0].label()
      return '(' + ' '.join(nltk_tree_to_logical_form(child) for child in tree) + ')'
docs: Given an ``nltk.Tree`` representing the syntax tree that generates a logical form, this method
      produces the actual (lisp-like) logical form, with all of the non-terminal symbols converted
      into the correct number of parentheses.
  
      This is used in the logic that converts action sequences back into logical forms.  It's very
      unlikely that you will need this anywhere else.