code: def group_by_count(iterable: List[Any], count: int, default_value: Any) -> List[List[Any]]:
      
      return [list(l) for l in zip_longest(*[iter(iterable)] * count, fillvalue=default_value)]
docs: Takes a list and groups it into sublists of size ``count``, using ``default_value`` to pad the
      list at the end if the list is not divisable by ``count``.
  
      For example:
      >>> group_by_count([1, 2, 3, 4, 5, 6, 7], 3, 0)
      [[1, 2, 3], [4, 5, 6], [7, 0, 0]]
  
      This is a short method, but it's complicated and hard to remember as a one-liner, so we just
      make a function out of it.