code: def find(self, relpath, rsc=None, useFilepath=None):
          
          self.init()
          
          # load the default resource information
          if rsc is None:
              try:
                  key = relpath.replace('\\', '/').split('/')[0]
                  rsc = self.default(key)
              except IndexError:
                  return ''
          
          # determine the filepath location
          relpath = os.path.normpath(nativestring(relpath))
          rscpath = self.resourcePath()
          
          if useFilepath is None:
              useFilepath = self.useFilepath()
          
          # return from the filesystem
          if useFilepath and rscpath:
              if rsc and isinstance(rsc, XResourceManager):
                  return rsc.find(relpath, useFilepath=useFilepath)
              elif rsc:
                  filepath = os.path.join(rscpath, rsc, relpath)
              else:
                  filepath = os.path.join(rscpath, relpath)
              
              if os.path.exists(filepath):
                  return filepath
          
          # return resource
          if isinstance(rsc, XResourceManager):
              return rsc.find(relpath, useFilepath=useFilepath)
          elif rsc:
              return ':{0}/{1}'.format(rsc, relpath.replace(os.path.sep, '/'))
          else:
              return ':{0}'.format(relpath.replace(os.path.sep, '/'))
docs: Looks up the path for the resource based on the inputed relative path.
          
          :param      relpath | <str>
          
          :return     <str>