code: def convert_sent_to_conll(sent_ls: List[Extraction]):
      
      # Sanity check - make sure all extractions are on the same sentence
      assert(len(set([ex.sent for ex in sent_ls])) == 1)
      toks = sent_ls[0].sent.split(' ')
  
      return safe_zip(*[range(len(toks)),
                        toks] + \
                      [extraction_to_conll(ex)
                       for ex in sent_ls])
docs: Given a list of extractions for a single sentence -
      convert it to conll representation.