code: def find_first_in_list(txt: str, str_list: [str]) -> int:  # type: ignore
      
      start = len(txt) + 1
      for item in str_list:
          if start > txt.find(item) > -1:
              start = txt.find(item)
      return start if len(txt) + 1 > start > -1 else -1
docs: Returns the index of the earliest occurence of an item from a list in a string
  
      Ex: find_first_in_list('foobar', ['bar', 'fin']) -> 3