code: def find_in_subgraph_by_name(subgraph, target_name, target_package, nodetype):
      
      for name, model in subgraph.items():
          if id_matches(name, target_name, target_package, nodetype, model):
              return model
  
      return None
docs: Find an entry in a subgraph by name. Any mapping that implements
      .items() and maps unique id -> something can be used as the subgraph.
  
      Names are like:
          '{nodetype}.{target_package}.{target_name}'
  
      You can use `None` for the package name as a wildcard.