code: def niceString2uri(aUriString, namespaces=None):
      
  
      if not namespaces:
          namespaces = []
  
      for aNamespaceTuple in namespaces:
          if aNamespaceTuple[0] and aUriString.find(
                  aNamespaceTuple[0].__str__() + ":") == 0:
              aUriString_name = aUriString.split(":")[1]
              return rdflib.term.URIRef(aNamespaceTuple[1] + aUriString_name)
  
      # we dont handle the 'base' URI case
      return rdflib.term.URIRef(aUriString)
docs: From a string representing a URI possibly with the namespace qname, returns a URI instance.
  
      gold:Citation  ==> rdflib.term.URIRef(u'http://purl.org/linguistics/gold/Citation')
  
      Namespaces are a list
  
      [('xml', rdflib.URIRef('http://www.w3.org/XML/1998/namespace'))
      ('', rdflib.URIRef('http://cohereweb.net/ontology/cohere.owl#'))
      (u'owl', rdflib.URIRef('http://www.w3.org/2002/07/owl#'))
      ('rdfs', rdflib.URIRef('http://www.w3.org/2000/01/rdf-schema#'))
      ('rdf', rdflib.URIRef('http://www.w3.org/1999/02/22-rdf-syntax-ns#'))
      (u'xsd', rdflib.URIRef('http://www.w3.org/2001/XMLSchema#'))]