code: def get_dep_names_of_package(
          package,
          keep_version_pins=False,
          recursive=False,
          verbose=False,
          include_build_requirements=False
          ):
      
  
      # First, obtain the dependencies:
      dependencies = get_package_dependencies(
          package, recursive=recursive, verbose=verbose,
          include_build_requirements=include_build_requirements,
      )
      if verbose:
          print("get_dep_names_of_package_folder: " +
                "processing dependency list to names: " +
                str(dependencies))
  
      # Transform dependencies to their stripped down names:
      # (they can still have version pins/restrictions, conditionals, ...)
      dependency_names = set()
      for dep in dependencies:
          # If we are supposed to keep exact version pins, extract first:
          pin_to_append = ""
          if keep_version_pins and "(==" in dep and dep.endswith(")"):
              # This is a dependency of the format: 'pkg (==1.0)'
              pin_to_append = "==" + dep.rpartition("==")[2][:-1]
          elif keep_version_pins and "==" in dep and not dep.endswith(")"):
              # This is a dependency of the format: 'pkg==1.0'
              pin_to_append = "==" + dep.rpartition("==")[2]
          # Now get true (and e.g. case-corrected) dependency name:
          dep_name = get_package_name(dep) + pin_to_append
          dependency_names.add(dep_name)
      return dependency_names
docs: Gets the dependencies from the package in the given folder,
          then attempts to deduce the actual package name resulting
          from each dependency line, stripping away everything else.