code: def last_location_of_maximum(x):
      
      x = np.asarray(x)
      return 1.0 - np.argmax(x[::-1]) / len(x) if len(x) > 0 else np.NaN
docs: Returns the relative last location of the maximum value of x.
      The position is calculated relatively to the length of x.
  
      :param x: the time series to calculate the feature of
      :type x: numpy.ndarray
      :return: the value of this feature
      :return type: float