code: def _linux_os_release():
      
      pretty_name = ''
      ashtray = {}
      keys = ['NAME', 'VERSION_ID']
      try:
          with open(os.path.join('/etc', 'os-release')) as f:
              for line in f:
                  for key in keys:
                      if line.startswith(key):
                          ashtray[key] = re.sub(r'^"|"$', '', line.strip().split('=')[1])
      except (OSError, IOError):
          return pretty_name
  
      if ashtray:
          if 'NAME' in ashtray:
              pretty_name = ashtray['NAME']
          if 'VERSION_ID' in ashtray:
              pretty_name += ' {}'.format(ashtray['VERSION_ID'])
  
      return pretty_name
docs: Try to determine the name of a Linux distribution.
  
      This function checks for the /etc/os-release file.
      It takes the name from the 'NAME' field and the version from 'VERSION_ID'.
      An empty string is returned if the above values cannot be determined.