code: def OpenFile(self, filepath):
      
      archive = False
      if '.zip/' in filepath:
        archive = True
        archive_type = '.zip'
      if '.par/' in filepath:
        archive = True
        archive_type = '.par'
      if archive:
        path, archived_file = filepath.split(archive_type)
        path += archive_type
        zip_file = zipfile.ZipFile(path)
        return zip_file.open(archived_file.strip('/'))
      return open(filepath)
docs: open()-replacement that automatically handles zip files.
  
      This assumes there is at most one .zip in the file path.
      Args:
        filepath: the path to the file to open.
      Returns:
        An open file-like object.