code: def no(self, text, count=None):
          
          if count is None and self.persistent_count is not None:
              count = self.persistent_count
  
          if count is None:
              count = 0
          mo = re.search(r"\A(\s*)(.+?)(\s*)\Z", text)
          pre = mo.group(1)
          word = mo.group(2)
          post = mo.group(3)
  
          if str(count).lower() in pl_count_zero:
              return "{}no {}{}".format(pre, self.plural(word, 0), post)
          else:
              return "{}{} {}{}".format(pre, count, self.plural(word, count), post)
docs: If count is 0, no, zero or nil, return 'no' followed by the plural
          of text.
  
          If count is one of:
              1, a, an, one, each, every, this, that
          return count followed by text.
  
          Otherwise return count follow by the plural of text.
  
          In the return value count is always followed by a space.
  
          Whitespace at the start and end is preserved.