code: def max_len(iterable, minimum=0):
      
      try:
          result = max(map(len, iterable))
      except ValueError:
          result = minimum
      return minimum if result < minimum else result
docs: Return the len() of the longest item in ``iterable`` or ``minimum``.
  
      >>> max_len(['spam', 'ham'])
      4
  
      >>> max_len([])
      0
  
      >>> max_len(['ham'], 4)
      4