code: def or_(cls, *queries):
          
          if len(queries) < 2:
              raise ValueError('or_ need two queries at least')
          if not all(x._query_class._class_name == queries[0]._query_class._class_name for x in queries):
              raise TypeError('All queries must be for the same class')
          query = Query(queries[0]._query_class._class_name)
          query._or_query(queries)
          return query
docs: 根据传入的 Query 对象，构造一个新的 OR 查询。
  
          :param queries: 需要构造的子查询列表
          :rtype: Query