code: def Nor(*xs, simplify=True):
      
      xs = [Expression.box(x).node for x in xs]
      y = exprnode.not_(exprnode.or_(*xs))
      if simplify:
          y = y.simplify()
      return _expr(y)
docs: Expression NOR (not OR) operator
  
      If *simplify* is ``True``, return a simplified expression.