code: def hcl2lab(h__, c__, l__):
      
      h_rad = np.deg2rad(h__)
      l2_ = l__ * 61 + 9
      angle = np.pi / 3.0 - h_rad
      r__ = (l__ * 311 + 125) * c__
      a__ = np.sin(angle) * r__
      b__ = np.cos(angle) * r__
      return l2_, a__, b__
docs: HCL to L*ab