code: def channel_L(self):
          
          channel_L = ((self.vol / (self.channel_W * self.downstream_H) + self.ent_tank_L) / self.channel_n).to(u.m)
          return channel_L
docs: The channel length of the flocculator. If ha.HUMAN_W_MIN or W_min_HS_ratio
          is the defining constraint for the flocculator width, then the flocculator
          volume will be greater than necessary. Bring the volume back to the design
          volume by shortening the flocculator in this case. This design approach
          will produce flocculators that are the same length as the max_L that was
          specified in many cases. The flocculator will be less than the specified
          length especially for cases with only one or two sed tanks.
          channel_L = (vol/(channel_W * downstream_H) + entrancetank_L)/channel_n
          :returns: Channel length
          :rtype: float * meter