code: def ServicesPost (self, sensor_id, parameters):
          
          if self.__SenseApiCall__('/sensors/{0}/services.json'.format(sensor_id), 'POST', parameters = parameters):
              return True
          else:
              self.__error__ = "api call unsuccessful"
              return False
docs: Create a new service in CommonSense, attached to a specific sensor. 
              If ServicesPost was successful, the service details, including its service_id, can be obtained from getResponse(), and should be a json string.
              
              @param sensor_id (int) - The sensor id of the sensor to connect the service to.
              @param parameters (dictionary) - The specifics of the service to create.
                      @note: http://www.sense-os.nl/81?nodeId=81&selectedId=11887
              
              @return (bool) - Boolean indicating whether ServicesPost was successful.