code: def ServicesGet (self, sensor_id):
          
          if self.__SenseApiCall__('/sensors/{0}/services.json'.format(sensor_id), 'GET'):
              return True
          else:
              self.__error__ = "api call unsuccessful"
              return False
docs: Retrieve services connected to a sensor in CommonSense.
              If ServicesGet is successful, the result can be obtained by a call to getResponse() and should be a json string.
              
              @sensor_id (int) - Sensor id of sensor to retrieve services from.
              
              @return (bool) - Boolean indicating whether ServicesGet was successful.