code: def _has_valid_abs_ref(self, i, construction_table):
          
          c_table = construction_table
          abs_refs = constants.absolute_refs
          A = np.empty((3, 3))
          row = c_table.index.get_loc(i)
          if row > 2:
              message = 'The index {i} is not from the first three, rows'.format
              raise ValueError(message(i=i))
          for k in range(3):
              if k < row:
                  A[k] = self.loc[c_table.iloc[row, k], ['x', 'y', 'z']]
              else:
                  A[k] = abs_refs[c_table.iloc[row, k]]
          v1, v2 = A[2] - A[1], A[1] - A[0]
          K = np.cross(v1, v2)
          zero = np.full(3, 0.)
          return not (np.allclose(K, zero) or np.allclose(v1, zero)
                      or np.allclose(v2, zero))
docs: Checks, if ``i`` uses valid absolute references.
  
          Checks for each index from first to third row of the
          ``construction_table``, if the references are colinear.
          This case has to be specially treated, because the references
          are not only atoms (to fix internal degrees of freedom) but also points
          in cartesian space called absolute references.
          (to fix translational and rotational degrees of freedom)
  
          Args:
              i (label): The label has to be in the first three rows.
              construction_table (pd.DataFrame):
  
          Returns:
              bool: