code: def col_scrubf(df,col_name,which,count = 1,dest = False):
      
      if dest:
          df.loc[which,col_name] = df.loc[which,col_name].str[count:]
      else:
          new_col = df[col_name].copy()
          new_col[which] = df.loc[which,col_name].str[count:]
          return new_col
docs: Removes characters from the front of the entries in DataFrame for a column
      Parameters:
      df - DataFrame
          DataFrame to operate on
      col_name - string
          Name of column to scrub
      which - boolean array
          Boolean array that determines which elements to scrub, where True means scrub
      count - integer, default 1
          amount of characters to scrub
      dest - bool, default False
          Whether to apply the result to the DataFrame or return it.
          True is apply, False is return.