code: function() {
              var intersection = [],
                  arrays = slice.call(arguments),
                  arraysLength,
                  array,
                  arrayLength,
                  minArray,
                  minArrayIndex,
                  minArrayCandidate,
                  minArrayLength,
                  element,
                  elementCandidate,
                  elementCount,
                  i, j, k;
  
              if (!arrays.length) {
                  return intersection;
              }
  
              // Find the smallest array
              arraysLength = arrays.length;
              for (i = minArrayIndex = 0; i < arraysLength; i++) {
                  minArrayCandidate = arrays[i];
                  if (!minArray || minArrayCandidate.length < minArray.length) {
                      minArray = minArrayCandidate;
                      minArrayIndex = i;
                  }
              }
  
              minArray = ExtArray.unique(minArray);
              erase(arrays, minArrayIndex, 1);
  
              // Use the smallest unique'd array as the anchor loop. If the other array(s) do contain
              // an item in the small array, we're likely to find it before reaching the end
              // of the inner loop and can terminate the search early.
              minArrayLength = minArray.length;
              arraysLength = arrays.length;
              for (i = 0; i < minArrayLength; i++) {
                  element = minArray[i];
                  elementCount = 0;
  
                  for (j = 0; j < arraysLength; j++) {
                      array = arrays[j];
                      arrayLength = array.length;
                      for (k = 0; k < arrayLength; k++) {
                          elementCandidate = array[k];
                          if (element === elementCandidate) {
                              elementCount++;
                              break;
                          }
                      }
                  }
  
                  if (elementCount === arraysLength) {
                      intersection.push(element);
                  }
              }
  
              return intersection;
          }
docs: Merge multiple arrays into one with unique items that exist in all of the arrays.
  
  @param {Array} array1
  @param {Array} array2
  @param {Array} etc
  @return {Array} intersect