code: def _columnNameDBToPublic(self, dbName):
      
  
      words = dbName.split('_')
      if dbName.startswith('_'):
        words = words[1:]
      pubWords = [words[0]]
      for word in words[1:]:
        pubWords.append(word[0].upper() + word[1:])
  
      return ''.join(pubWords)
docs: Convert a database internal column name to a public name. This
      takes something of the form word1_word2_word3 and converts it to:
      word1Word2Word3. If the db field name starts with '_', it is stripped out
      so that the name is compatible with collections.namedtuple.
      for example: _word1_word2_word3 => word1Word2Word3
  
      Parameters:
      --------------------------------------------------------------
      dbName:      database internal field name
      retval:      public name