code: def _restore_path(table):
      
      name = None
      splited = table.split('___')
      path = splited[0]
      if len(splited) == 2:
          name = splited[1]
      path = path.replace('__', os.path.sep)
      path += '.csv'
      return path, name
docs: Restore resource's path and name from storage's table.
  
      Args:
          table (str): table name
  
      Returns:
          (str, str): resource path and name