code: def urlunsplit(data):
      
      scheme, netloc, url, query, fragment = data
      if netloc or (scheme and scheme in uses_netloc and url[:2] != '//'):
          if url and url[:1] != '/': url = '/' + url
          url = '//' + (netloc or '') + url
      if scheme:
          url = scheme + ':' + url
      if query:
          url = url + '?' + query
      if fragment:
          url = url + '#' + fragment
      return url
docs: Combine the elements of a tuple as returned by urlsplit() into a
      complete URL as a string. The data argument can be any five-item iterable.
      This may result in a slightly different, but equivalent URL, if the URL that
      was parsed originally had unnecessary delimiters (for example, a ? with an
      empty query; the RFC states that these are equivalent).