code: private int bytesNetworkOrder2Number(byte[] bytesInNetworkOrder) {
      int sourceNumber = 0;
      for (int i = 0; i < 4; i++) {
        sourceNumber <<= 8;
        sourceNumber |= bytesInNetworkOrder[i] & 0xff;
      }
      return sourceNumber;
    }
docs: 4个字节的网络字节序bytes数组还原成一个数字
  
  @param bytesInNetworkOrder