code: public static String getPath(String uriStr) {
  		URI uri = null;
  		try {
  			uri = new URI(uriStr);
  		} catch (URISyntaxException e) {
  			throw new UtilException(e);
  		}
  		return uri.getPath();
  	}
docs: 获得path部分<br>
  
  @param uriStr URI路径
  @return path
  @exception UtilException 包装URISyntaxException