code: public ResourceFactory findResourceFactory(String name, Type clazz) {
          Map<String, ResourceEntry> map = this.store.get(clazz);
          if (map != null && map.containsKey(name)) return this;
          if (parent != null) return parent.findResourceFactory(name, clazz);
          return null;
      }
docs: 查找指定资源名和资源类型的资源对象所在的ResourceFactory， 没有则返回null
  
  @param name  资源名
  @param clazz 资源类型
  
  @return ResourceFactory