code: public T find(String id) {
          SharedPreferences prefs = loadSharedPreferences("object");
  
          JSONObject object = null;
  
          try {
              String json = prefs.getString(String.valueOf(id), null);
  
              if (json == null) return null;
  
              object = new JSONObject(json);
  
          } catch (JSONException e) {
              e.printStackTrace();
          }
  
          return fromJson(object);
      }
docs: Find a specific object from its id.
  
  TODO: Figure out how to make this accesible without...
  creating a dummy instance.
  
  @param id Object's id.
  @return The object if found, null otherwise.
  @throws com.mauriciogiordano.easydb.exception.NoContextFoundException in case of null context.