code: def subdict_by_keys(dict_obj, keys):
      
      return {k: dict_obj[k] for k in set(keys).intersection(dict_obj.keys())}
docs: Returns a sub-dict composed solely of the given keys.
  
      Parameters
      ----------
      dict_obj : dict
          The dict to create a sub-dict from.
      keys : list of str
          The keys to keep in the sub-dict. Keys not present in the given dict
          will be ignored.
  
      Returns
      -------
      dict
          A sub-dict of the given dict composed solely of the given keys.
  
      Example:
      --------
      >>> dict_obj = {'a': 1, 'b': 2, 'c': 3, 'd': 4}
      >>> subdict = subdict_by_keys(dict_obj, ['b', 'd', 'e'])
      >>> print(sorted(subdict.items()))
      [('b', 2), ('d', 4)]