code: def element_conforms(element, etype) -> bool:
      
      from pyjsg.jsglib import Empty
  
      if isinstance(element, etype):
          return True
      # This catches the Optional[] idiom
      if (element is None or element is Empty) and issubclass(etype, type(None)):
          return True
      elif element is Empty:
          return False
      elif isinstance(etype, type(type)) and (issubclass(etype, type(None))):
          return element is None
      elif element is None:
          return False
      else:
          return isinstance(element, etype)
docs: Determine whether element conforms to etype