code: def get_dict_hashid(dict_):
      r
      import utool as ut
      raw_text = ut.repr4(dict_, sorted_=True, strvals=True, nl=2)
      #print('raw_text = %r' % (raw_text,))
      hashid = ut.hashstr27(raw_text)
      #from utool import util_hash
      #hashid = hash(frozenset(dict_.items()))
      #hashid = util_hash.make_hash(dict_)
      return hashid
docs: r"""
      Args:
          dict_ (dict):
  
      Returns:
          int: id hash
  
      References:
          http://stackoverflow.com/questions/5884066/hashing-a-python-dictionary
  
      CommandLine:
          python -m utool.util_dict --test-get_dict_hashid
          python3 -m utool.util_dict --test-get_dict_hashid
  
      Example:
          >>> # ENABLE_DOCTEST
          >>> from utool.util_dict import *  # NOQA
          >>> dict_ = {}
          >>> dict_ = {'a': 'b'}
          >>> dict_ = {'a': {'c': 'd'}}
          >>> #dict_ = {'a': {'c': 'd'}, 1: 143, dict: set}
          >>> #dict_ = {'a': {'c': 'd'}, 1: 143 } non-determenism
          >>> hashid = get_dict_hashid(dict_)
          >>> result = str(hashid)
          >>> print(result)
          mxgkepoboqjerkhb
  
          oegknoalkrkojumi