code: def find_backwards(self, sub, in_current_line=False, ignore_case=False, count=1):
          
          if in_current_line:
              before_cursor = self.current_line_before_cursor[::-1]
          else:
              before_cursor = self.text_before_cursor[::-1]
  
          flags = re.IGNORECASE if ignore_case else 0
          iterator = re.finditer(re.escape(sub[::-1]), before_cursor, flags)
  
          try:
              for i, match in enumerate(iterator):
                  if i + 1 == count:
                      return - match.start(0) - len(sub)
          except StopIteration:
              pass
docs: Find `text` before the cursor, return position relative to the cursor
          position. Return `None` if nothing was found.
  
          :param count: Find the n-th occurance.