code: def get_anlz_factor(freq):
      
  
      # 'Q-NOV' would give us (2001, 1); we just want (2000, 1).
      try:
          base, mult = get_freq_code(freq)
      except ValueError:
          # The above will fail for a bunch of irregular frequencies, such
          # as 'Q-NOV' or 'BQS-APR'
          freq = freq.upper()
          if freq.startswith(("A-", "BA-", "AS-", "BAS-")):
              freq = "A"
          elif freq.startswith(("Q-", "BQ-", "QS-", "BQS-")):
              freq = "Q"
          elif freq in {"MS", "BMS"}:
              freq = "M"
          else:
              raise ValueError("Invalid frequency: %s" % freq)
          base, mult = get_freq_code(freq)
      return PERIODS_PER_YEAR[(base // 1000) * 1000] / mult
docs: Find the number of periods per year given a frequency.
  
      Parameters
      ----------
      freq : str
          Any frequency str or anchored offset str recognized by Pandas.
  
      Returns
      -------
      float
  
      Example
      -------
      >>> get_anlz_factor('D')
      252.0
      >>> get_anlz_factor('5D')  # 5-business-day periods per year
      50.4
  
      >>> get_anlz_factor('Q')
      4.0
      >>> get_anlz_factor('Q-DEC')
      4.0
      >>> get_anlz_factor('BQS-APR')
      4.0