code: def notify(self, method, *args, **kwargs):
          
          self.protocol.send_notification(method, args, kwargs)
docs: Perform a synchronous remote call where value no return value is desired.
  
          While faster than call it still blocks until the remote callback has been sent.
  
          This may block for sometime in certain situations. If it takes more than the Proxies
          set timeout then a TimeoutError is raised.