code: def nodeByName(self, name):
          
          # note: really long names are encoded differently:
          #  'N'+'\x00'+pack('Q', nameid)  => ofs
          #  and  (ofs, 'N') -> nameid
  
          # at nodebase ( 0xFF000000, 'S', 0x100*nameid )  there is a series of blobs for max 0x80000 sized names.
          cur = self.btree.find('eq', self.namekey(name))
          if cur:
              return struct.unpack('<' + self.fmt, cur.getval())[0]
docs: Return a nodeid by name