code: def _format_episode_name(names):
      
      if len(names) == 1:
          return names[0]
  
      found_name = ''
      epname = None
      epno = None
      numbers = []
      for cname in names:
          match = re.match(r'(.*) \(([0-9]+)\)$', cname)
          if found_name != '' and (not match or epname != found_name):
              # An episode didn't match
              return cfg.CONF.multiep_join_name_with.join(names)
  
          if match:
              epname, epno = match.group(1), match.group(2)
          else:  # assume that this is the first episode, without number
              epname = cname
              epno = 1
          found_name = epname
          numbers.append(int(epno))
  
      return cfg.CONF.multiep_format % {'epname': found_name,
                                        'episodemin': min(numbers),
                                        'episodemax': max(numbers)}
docs: Takes a list of episode names, formats them into a string.
  
      If two names are supplied, such as "Pilot (1)" and "Pilot (2)", the
      returned string will be "Pilot (1-2)". Note that the first number
      is not required, for example passing "Pilot" and "Pilot (2)" will
      also result in returning "Pilot (1-2)".
  
      If two different episode names are found, such as "The first", and
      "Something else" it will return "The first, Something else"