docs: def V_multiple_hole_cylinder(Do, L, holes):
      r'''Returns the solid volume of a cylinder with multiple cylindrical holes.
      Calculation will naively return a negative value or other impossible
      result if the number of cylinders added is physically impossible.
  
      .. math::
          V = \frac{\pi D_o^2}{4}L - L\frac{\pi D_i^2}{4}
  
      Parameters
      ----------
      Do : float
          Diameter of the exterior of the cylinder, [m]
      L : float
          Length of the cylinder, [m]
      holes : list
          List of tuples containing (diameter, count) pairs of descriptions for
          each of the holes sizes.
  
      Returns
      -------
      V : float
          Volume [m^3]
  
      Examples
      --------
      >>> V_multiple_hole_cylinder(0.01, 0.1, [(0.005, 1)])
      5.890486225480862e-06
      '''
      V = pi*Do**2/4*L
      for Di, n in holes:
          V -= pi*Di**2/4*L*n
      return V