docs: def remove_text_inside_brackets(s, brackets="()[]"):
      """
      From http://stackoverflow.com/a/14603508/610569
      """
      count = [0] * (len(brackets) // 2) # count open/close brackets
      saved_chars = []
      for character in s:
          for i, b in enumerate(brackets):
              if character == b: # found bracket
                  kind, is_close = divmod(i, 2)
                  count[kind] += (-1)**is_close # `+1`: open, `-1`: close
                  if count[kind] < 0: # unbalanced bracket
                      count[kind] = 0
                  break
          else: # character is not a bracket
              if not any(count): # outside brackets
                  saved_chars.append(character)
      return ''.join(saved_chars)