docs: def SensorsPost(self, parameters):
          """
              Create a sensor in CommonSense.
              If SensorsPost is successful, the sensor details, including its sensor_id, can be obtained by a call to getResponse(), and should be a json string.
              
              @param parameters (dictonary) - Dictionary containing the details of the sensor to be created. 
                      @note - http://www.sense-os.nl/46?nodeId=46&selectedId=11887            
                                      
              @return (bool) - Boolean indicating whether SensorsPost was successful.
          """
          if self.__SenseApiCall__('/sensors.json', 'POST', parameters = parameters):
              return True
          else:
              self.__error__ = "api call unsuccessful"
              return False