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## Idea/theory to re-balance the recon class. Also first post paragraph . . . somewhere in the wall of text.

Posts: 973

Date of registration
: Nov 15th 2012

Platform: PC

Location: Chile

Battlelog:

Reputation modifier: 5

Wednesday, March 13th 2013, 10:41am

### Quoted from "Rizn-Nuke"

I think the best class system would lie somewhere between BF2 and BF3 (sry never palyed BC1 or BC2 but I don't like the Idea of Medic having LMGs)

-Assault: AR - M320/M26 - ???
-Engineer: Carb - SMAW/STINGER - REP/MINE
-Medic: Carb - Medkit - Defib
-Support: LMG - AMMO - Mortar
-Scout: PDW/Shotgun - Motionballs/TUGS/MAV - Spawn
-Sniper: SR - Claymore - SOFLAM/Binocs

Who do you think should get C4 in this setup? What should the assault get to complete his set? What equipmnet should be added?
Scouts. I think Medics should get LMGs, BF2 style? Scouts should probably get carbines.
Avatar is from here!

### Quoted from "Riesig"

Finesse

You do not have it.

### Sleeper case...

[email protected]
Noctua NH-U14s

Asus Z97-I plus
2x8GB DDR3-1866

eVGA GTX 670 blower, can't remember what edition
Assortment of HDDs and SSDs
Silverstone SFX 600w

first!!! denied...

Posts: 603

Date of registration
: Dec 8th 2011

Platform: PC

Location: Undisclosed but alive

Battlelog:

Reputation modifier: 7

Wednesday, March 13th 2013, 10:46am

### Quoted from "Rizn-Nuke"

I think the best class system would lie somewhere between BF2 and BF3 (sry never palyed BC1 or BC2 but I don't like the Idea of Medic having LMGs)

-Assault: AR - M320/M26 - ???
-Engineer: Carb - SMAW/STINGER - REP/MINE
-Medic: Carb - Medkit - Defib
-Support: LMG - AMMO - Mortar
-Scout: PDW/Shotgun - Motionballs/TUGS/MAV - Spawn
-Sniper: SR - Claymore - SOFLAM/Binocs

Who do you think should get C4 in this setup? What should the assault get to complete his set? What equipmnet should be added?
Scouts. I think Medics should get LMGs, BF2 style? Scouts should probably get carbines.
In BF2 Style, the medic was just like now... with the best AR in the game (G36E) ... everyone played medic back then

Bullets may have your name on them, but shrapnel is addressed "to whom it may concern"

### Quoted from "ViperFTW"

"Pff, c'mon. You know I'm like the crazy homeless man who lives in the postbox, everyone ignores me but I'M GONNA KEEP TALKING ABOUT SHIT ANYWAYS DD"

### Spoiler

"I don't think I've ever moved THAT fast xD. Next time a bear's chasing me say he'll hack my acount if he catches me xDD" -Vip3rFTW

### Quoted from "ViperFTW"

I've sat and came up with 3 theories about your PC, Rizn.
1) Its constructed by Satan and every so often it'll crash to a Red Screen that just says "Another must fall", which is your queue to go out, find a virgin, kill her and pour the blood over the beating-heart-like processor within
3) (My sister's idea) Its powered by the core of the Earth and is, as a direct result, responsible for climate change. Your PC being able to run the BF4 beta without crashing/lagging will destroy humanity

Posts: 973

Date of registration
: Nov 15th 2012

Platform: PC

Location: Chile

Battlelog:

Reputation modifier: 5

Wednesday, March 13th 2013, 10:47am

### Quoted from "Rizn-Nuke"

I think the best class system would lie somewhere between BF2 and BF3 (sry never palyed BC1 or BC2 but I don't like the Idea of Medic having LMGs)

-Assault: AR - M320/M26 - ???
-Engineer: Carb - SMAW/STINGER - REP/MINE
-Medic: Carb - Medkit - Defib
-Support: LMG - AMMO - Mortar
-Scout: PDW/Shotgun - Motionballs/TUGS/MAV - Spawn
-Sniper: SR - Claymore - SOFLAM/Binocs

Who do you think should get C4 in this setup? What should the assault get to complete his set? What equipmnet should be added?
Scouts. I think Medics should get LMGs, BF2 style? Scouts should probably get carbines.
In BF2 Style, the medic was just like now... with the best AR in the game (G36E) ... everyone played medic back then
I liked medic MGs, I think that would work nice.

My main problem with the assault being separate from the medic is that it encourages the use of the 320. At least in BF3 you have to give up your medkits for it, but if you just give them out for free (with the amount of kids playing the game) every smallish map will end up a 320 spam fest.
Avatar is from here!

### Quoted from "Riesig"

Finesse

You do not have it.

### Sleeper case...

[email protected]
Noctua NH-U14s

Asus Z97-I plus
2x8GB DDR3-1866

eVGA GTX 670 blower, can't remember what edition
Assortment of HDDs and SSDs
Silverstone SFX 600w

first!!! denied...

Posts: 603

Date of registration
: Dec 8th 2011

Platform: PC

Location: Undisclosed but alive

Battlelog:

Reputation modifier: 7

Wednesday, March 13th 2013, 10:55am

### Quoted from "Gorbaz The Dragon"

My main problem with the assault being separate from the medic is that it encourages the use of the 320. At least in BF3 you have to give up your medkits for it, but if you just give them out for free (with the amount of kids playing the game) every smallish map will end up a 320 spam fest.
You have a point there. However when I played BF2 (back in the days ) This didn't seem like much of a problem. But if you take away the AR from medics you might be right about that...

Bullets may have your name on them, but shrapnel is addressed "to whom it may concern"

### Quoted from "ViperFTW"

"Pff, c'mon. You know I'm like the crazy homeless man who lives in the postbox, everyone ignores me but I'M GONNA KEEP TALKING ABOUT SHIT ANYWAYS DD"

### Spoiler

"I don't think I've ever moved THAT fast xD. Next time a bear's chasing me say he'll hack my acount if he catches me xDD" -Vip3rFTW

### Quoted from "ViperFTW"

I've sat and came up with 3 theories about your PC, Rizn.
1) Its constructed by Satan and every so often it'll crash to a Red Screen that just says "Another must fall", which is your queue to go out, find a virgin, kill her and pour the blood over the beating-heart-like processor within
3) (My sister's idea) Its powered by the core of the Earth and is, as a direct result, responsible for climate change. Your PC being able to run the BF4 beta without crashing/lagging will destroy humanity

Posts: 7

Date of registration
: Mar 12th 2013

Platform: PC

Battlelog:

Reputation modifier: 4

Thursday, March 14th 2013, 12:40am

Hey I just wanted to add my 2 cents as a heavy recon class user (currently 10SS and over 7k kills with sniper rifles) and BF2 veteran.
Imho, class balance was way better back then. Yes, the medic was still generally the most powerful, but not as broken as it is in BF3
• First of all, I can understand why many people are afraid of the the recon class being buffed because of the camper issues.
But why are there these many hill/crane campers on BF3? The reason is 3D-spotting. People will camp as long as they have targets to shoot at. If you dont have any targets, it will become utterly boring (you may argue it is anyway, but some people find high reward in hitting long range targets, I recommend you to check out this channel:
The way they solved this issue in BF2 was to add a little fog effect which didn't allow you to see enemies past 300-400m or so. Nowadays, you have red triangles to shoot at all over the place!
So my suggestion is to range-limit the spotting effect (Possibly making it variable, maybe assault 100-200m and recon up to 400m). This would prevent long range camping and also give the recon an additional edge.
• The weapon balance of sniper rifles
In BF3 the sniper rifles are a little UP compared to the rest. The bolt-actions suffer a great time from the suppression mechanic - even the slightest bit of suppression may cause you to miss the headshot which these weapon depend on.
As far as for the SEMI-AUTOS: the SKS is good, the rest is IMHO utterly useless! A headshot wont kill the target and the spread increase for these rifles is just too damn high! For what do I need an M39 with 300 RPM when due to the huge spread increase basically makes your follow up shots all miss? (This is also the main reason I believe why many beginners can't hit a stone with these. You have to restrict your fire to around 150 RPM to use them effectively...)
• The recon class and its roles compared to the other classes. There are mainly 2 roles for the recon:
1st: CQC with TUGS/MAV and PDWs
Now as already pointed out the assault completly outclasses the recon in CQC - while the TUGS is fine and good, healing and reviving are just wayyyyyy better.
Though you can still use the recon as a sort of stealth/spec ops class using suppressed PDWs. The problem is though, that the tugs and spawn beacon need time to deploy and also alert enemies with their constant beeping.
I really wished dice would have made them noiseless and I would also like to see a revival of the motion sensor ball from BC or BFP4F which would help the class a lot!

2nd: longer range combat with SOLFAM/MAV and sniper-rifles
Like I said before the suppression mechanic and high accuracy assault rifles really hurt the sniper a lot. I would really like to see DICE removing the spread increase from suppression, but keeping the blur effects...
As far as for the SOLFAM: its a dumb gadget which requires no skill. And as already said smoke recharges way too fast to make it acutally useful. I think here you could bring in a neat idea from BFP4F: the tracer dart. Once shot at a vehicle it would make RPGs lock on to it. They could implement this by making the recon able to load the tracer darts into the sniper rifle. Than he would have to shoot and hit the vehicle (skill based) and remain there until removed by an explosion or being manually removed by the enemy.
• Removing bolt-action from the game entirely
NO WAY !!!

Posts: 7

Date of registration
: Mar 11th 2013

Platform: PC

Battlelog:

Reputation modifier: 4

Thursday, March 14th 2013, 7:36am

### Quoted from "Rizn-Nuke"

I think the best class system would lie somewhere between BF2 and BF3 (sry never palyed BC1 or BC2 but I don't like the Idea of Medic having LMGs)

-Assault: AR - M320/M26 - ???
-Engineer: Carb - SMAW/STINGER - REP/MINE
-Medic: Carb - Medkit - Defib
-Support: LMG - AMMO - Mortar
-Scout: PDW/Shotgun - Motionballs/TUGS/MAV - Spawn
-Sniper: SR - Claymore - SOFLAM/Binocs

Who do you think should get C4 in this setup? What should the assault get to complete his set? What equipmnet should be added?
Scouts. I think Medics should get LMGs, BF2 style? Scouts should probably get carbines.
In BF2 Style, the medic was just like now... with the best AR in the game (G36E) ... everyone played medic back then
I liked medic MGs, I think that would work nice.

My main problem with the assault being separate from the medic is that it encourages the use of the 320. At least in BF3 you have to give up your medkits for it, but if you just give them out for free (with the amount of kids playing the game) every smallish map will end up a 320 spam fest.
Aren't the smallish maps the maps we want out of battlefield? I have some modifications to consider.

-Assault: AR *AND BATTLE RIFLES/FULL BATTLE CARTRIDGE/7.62 WEAPONS* - M320/M26 - maybe an immediate area intelligence device such as nighvision/IR vision while other classes are stuck with flashligh/IR scope (total shot in the dark) , OR MAYBE . . . SUNGLASSES

-Engineer: Carb and *PDW/Shotguns* - SMAW/STINGER - REP/MINE (IMO if you want to OPERATE/NOT IN PASSENGER SEAT of a tank/LAV/Jet/heli you should have to give up everything but, a PDW and maybe I would allow shotguns. The reason behind this is you should give up something to use a powerful vehicle and to rationalize it you are cramped in all this vehicles and would have a difficult time bring in a full sized weapon into a vehicle. BUT, this discussion is for another thread.)

-Medic: Carb - Medkit - Defib

-Support: LMG/AR - AMMO - Mortar/C4 - *ONLY PICK ONE: AR OR C4*

-Scout: Carb/AR - Motionballs - Claymore/c4 - *ONLY PICK ONE: AR OR C4*

-Sniper: SR In addition to the anti material ammo - SOFLAM/Binocs - TUGS

I want to give another class access to the ARs as long as the Assault class has exclusive access over the battle rifles (hopefully they will be more than just one of them and they will actually be more relevant.) I do not want the Medics or Engineers to have them since I am confident that they will not be under powered but, I am not sure if the scout or the support class should have access to them. I am leaning more towards the support class as they do not have C4 so they have no way of combating vehicles right now but, I could easily be convinced to go another way.

P.S. In my natural way I figured as I was typing this that the best way to sort this would be to give access to the ARs if you give up the C4 for each class. but, what I said above is still relevant as this is extremely theoretical in nature. Also, if you are wondering where the MAV went . . . FUCK THE FLYING BARBECUE!

Posts: 973

Date of registration
: Nov 15th 2012

Platform: PC

Location: Chile

Battlelog:

Reputation modifier: 5

Thursday, March 14th 2013, 11:52am

I think keeping the ARs to the assault class is very important for keeping balance, the difference between ARs and BRs is that battle rifles sacrifice ease of use and controllability for damage and accuracy, if they were 'better' than ARs we would end up with pretty bad balance.
Avatar is from here!

### Quoted from "Riesig"

Finesse

You do not have it.

### Sleeper case...

[email protected]
Noctua NH-U14s

Asus Z97-I plus
2x8GB DDR3-1866

eVGA GTX 670 blower, can't remember what edition
Assortment of HDDs and SSDs
Silverstone SFX 600w

Posts: 7

Date of registration
: Mar 12th 2013

Platform: PC

Battlelog:

Reputation modifier: 4

Thursday, March 14th 2013, 2:20pm

Hey I just wanted to add my 2 cents as a heavy recon class user (currently 10SS and over 7k kills with sniper rifles) and BF2 veteran.
Imho, class balance was way better back then. Yes, the medic was still generally the most powerful, but not as broken as it is in BF3

=> First of all, I can understand why many people are afraid of the the recon class being buffed because of the camper issues.

But why are there these many hill/crane campers on BF3? The reason is 3D-spotting. People will camp as long as they have targets to shoot at. If you dont have any targets, it will become utterly boring (you may argue it is anyway, but some people find high reward in hitting long range targets, I recommend you to check out this channel: RYANDPAHL PRODUCTIONS - YouTube
The way they solved this issue in BF2 was to add a little fog effect which didn't allow you to see enemies past 300-400m or so. Nowadays, you have red triangles to shoot at all over the place!
So my suggestion is to range-limit the spotting effect (Possibly making it variable, maybe assault 100-200m and recon up to 400m). This would prevent long range camping and also give the recon an additional edge.

=> The weapon balance of sniper rifles

In BF3 the sniper rifles are a little UP compared to the rest. The bolt-actions suffer a great time from the suppression mechanic - even the slightest bit of suppression may cause you to miss the headshot which these weapon depend on.
As far as for the SEMI-AUTOS: the SKS is good, the rest is IMHO utterly useless! A headshot wont kill the target and the spread increase for these rifles is just too damn high! For what do I need an M39 with 300 RPM when due to the huge spread increase basically makes your follow up shots all miss? (This is also the main reason I believe why many beginners can't hit a stone with these. You have to restrict your fire to around 150 RPM to use them effectively...)

=> The recon class and its roles compared to the other classes. There are mainly 2 roles for the recon:

1st: CQC with TUGS/MAV and PDWs
Now as already pointed out the assault completly outclasses the recon in CQC - while the TUGS is fine and good, healing and reviving are just wayyyyyy better.
Though you can still use the recon as a sort of stealth/spec ops class using suppressed PDWs. The problem is though, that the tugs and spawn beacon need time to deploy and also alert enemies with their constant beeping.
I really wished dice would have made them noiseless and I would also like to see a revival of the motion sensor ball from BC or BFP4F which would help the class a lot!

2nd: longer range combat with SOLFAM/MAV and sniper-rifles
Like I said before the suppression mechanic and high accuracy assault rifles really hurt the sniper a lot. I would really like to see DICE removing the spread increase from suppression, but keeping the blur effects...
As far as for the SOLFAM: its a dumb gadget which requires no skill. And as already said smoke recharges way too fast to make it acutally useful. I think here you could bring in a neat idea from BFP4F: the tracer dart. Once shot at a vehicle it would make RPGs lock on to it. They could implement this by making the recon able to load the tracer darts into the sniper rifle. Than he would have to shoot and hit the vehicle (skill based) and remain there until removed by an explosion or being manually removed by the enemy.

=> Removing bolt-action from the game entirely

NO WAY !!!

Posts: 7

Date of registration
: Mar 11th 2013

Platform: PC

Battlelog:

Reputation modifier: 4

Thursday, March 14th 2013, 8:13pm

### Quoted from "Gorbaz The Dragon"

I think keeping the ARs to the assault class is very important for keeping balance, the difference between ARs and BRs is that battle rifles sacrifice ease of use and controllability for damage and accuracy, if they were 'better' than ARs we would end up with pretty bad balance.
I would agree with that entirely if the BR's stay as they are right now. Hopefully, we will see the BR's fill a role that extends the engagement potential of the assault class beyond what I feel the true effective engagement distance of the G3A3 is now (about <100m) IMO the BR's should be weapon of the Assault class that allows them to reach out and touch the semi-auto snipers but, I digress if the BR's stay the same I completely agree with the model that gives exclusivity of AR's to the Assault class.

-Assault: AR - M320/M26/*Another rail attachment - IR/nightvison/sunglasses
-Engineer: Carb - SMAW/STINGER - REP/MINE
-Medic: Carb - Medkit - Defib
-Support: LMG - AMMO - Mortar/**Spawn
-Scout: Carb - Motionballs - Claymore/C4
-Sniper: SR - Anti Material ammo/TUGS - SOFLAM/Binocs
***- Vehicle Operator: PDW/Shotgun - whatever their class offers - whatever their class offers

*I am terrified that the M320 will dominant the M26 if they stay balanced as they are right now so, I figure that they should try to add more rail accessories into the game (MAGPUL angled foregrip, Grippod, ect.) So maybe it is an easy way to over complicate a system that works but, I don't think that having a flashlight and laser sight on a gun is game breaking. Remember I am talking exclusively about the attachments that go on the rails or in other words having both a heavy barrel and a flash supp. on a gun would be game breaking.

**Totally forgot Spawn beacon from last model. IMO the support shouldn't be too far from the front lines as they will provide ammo to everyone. The support class can also provide suppression to get newly spawned players back to the front lines.

*** simplification of:

### Quoted from "slidingbandit"

(IMO if you want to OPERATE/NOT IN PASSENGER SEAT of a tank/LAV/Jet/heli you should have to give up everything but, a PDW and maybe I would allow shotguns. The reason behind this is you should give up something to use a powerful vehicle and to rationalize it you are cramped in all this vehicles and would have a difficult time bring in a full sized weapon into a vehicle. BUT, this discussion is for another thread.)


text:
# Dynamic volume formula

Printable View

• Oct 13th 2011, 05:57 PM
markshr
Dynamic volume formula
I need a formula to size a rainwater tank based on:

a. 18.7 litres per second entering the tank over a 11.6 minute duration

b. 1.3 litres per second discharging from the tank.
• Oct 13th 2011, 06:02 PM
pickslides
Re: Dynamic volume formula
Can't you just say the maximum volume of the tank required is $(18.7-1.3) \times 11.6\times 60$ ?

format: plain


text:
# Image segmentation with test time augmentation with keras

In the last post, I introduced the U-Net model for segmenting salt depots in seismic images. This time, we will see how to improve the model by data augmentation and especially test time augmentation (TTA). You will learn how to use data augmentation with segmentation masks and what test time augmentation is and how to use it in keras.

# U-Net for segmenting seismic images with keras

Today I’m going to write about a kaggle competition I started working on recently. In the TGS Salt Identification Challenge, you are asked to segment salt deposits beneath the Earth’s surface. So we are given a set of seismic images that are $101 \times 101$ pixels each and each pixel is classified as either salt or sediment.

# State-of-the-art named entity recognition with residual LSTM and ELMo

This is the sixth post in my series about named entity recognition. This time I’m going to show you some cutting edge stuff. We will use a residual LSTM network together with ELMo embeddings, developed at Allen NLP. You will learn how to wrap a tensorflow hub pre-trained model to work with keras. The resulting model with give you state-of-the-art performance on the named entity recognition task.

# Debugging black-box text classifiers with LIME

Often in text classification, we use so called black-box classifiers. By black-box classifiers I mean a classification system where the internal workings are completely hidden from you. A famous example are deep neural nets, in text classification often recurrent or convolutional neural nets.

# Explain neural networks with keras and eli5

In this post, I’m going to show you how you can use a neural network from keras with the LIME algorithm implemented in the eli5 TextExplainer class. For this we will write a scikit-learn compatible wrapper for a keras bidirectional LSTM model. The wrapper will also handle the tokenization and the storage of the vocabulary.

# PyData Amsterdam 2018

Last weekend I participated at the PyData Amsterdam 2018 Conference in, you guess it, in Amsterdam. It has been a great conference and I meet a lot of great people and had a very good time in Amsterdam.

# Enhancing LSTMs with character embeddings for Named entity recognition

This is the fifth post in my series about named entity recognition. If you haven’t seen the last four, have a look now. The last time we used a CRF-LSTM to model the sequence structure of our sentences.

# Guide to word vectors with gensim and keras

Word vectors Today, I tell you what word vectors are, how you create them in python and finally how you can use them with neural networks in keras. For a long time, NLP methods use a vectorspace model to represent words.

# How to build a smart product: Transfer Learning for Dog Breed Identification with keras

This time I will show you how to build a simple “AI” product with transfer learning. We will build a “dog breed identification chat bot”. In this first post, I will show how to build a good model using keras, augmentation, pre-trained models for transfer learning and fine-tuning.

# Detecting Network Attacks with Isolation Forests

In this post, I will show you how to use the isolation forest algorithm to detect attacks to computer networks in python. The term isolation means separating an instance from the rest of the instances. Since anomalies are ‘few and different’ and therefore they are more susceptible to isolation.

# A strong and simple baseline to classify toxic comments on wikipedia with keras

This time we’re going to discuss a current machine learning completion on kaggle. In this competition, you’re challenged to build a multi-headed model that’s capable of detecting different types of of toxicity like threats, obscenity, insults, and identity-based hate.


text:
Zer0
Citizen
Posts: 59
Joined: Sat Oct 06, 2012 9:55 am
Location: Sweden
Contact:

Sorry for double posting.

Here is three more examples of mazes.

One with octagons, one with several layers and one with 10 different maze generation algorithms.
Attachments
OctagonMaze.love
Welcome to the OCTAGON.
mutliLayer.love
Several layers
JustMazes.love
10 maze algorithms
If you can't fix it, Kill it with fire. ( Preferably before it lays eggs. )

Germanunkol
Party member
Posts: 711
Joined: Fri Jun 22, 2012 4:54 pm
Contact:

Yay for the multilayer one! That looks pretty awesome
trAInsported - Write AI to control your trains
Bandana (Dev blog) - Platformer featuring an awesome little ninja by Micha and me
GridCars - Our jam entry for LD31
Germanunkol.de

Ref
Party member
Posts: 690
Joined: Wed May 02, 2012 11:05 pm

You guys are creating some very nice wall paper but I was wondering if you had any scripts that would permit specifying a starting position (like lower left corner) and an objective position (like upper right corner or center screen) and maze grid size - something used for game scripts?

Ranguna259
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Posts: 911
Joined: Tue Jun 18, 2013 10:58 pm
Location: I'm right next to you

Yeah I was thinking the same thing
LoveDebug- A library that will help you debug your game with an on-screen fully interactive lua console, you can even do code hotswapping

Zer0
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Posts: 59
Joined: Sat Oct 06, 2012 9:55 am
Location: Sweden
Contact:

Ref wrote:You guys are creating some very nice wall paper but I was wondering if you had any scripts that would permit specifying a starting position (like lower left corner) and an objective position (like upper right corner or center screen) and maze grid size - something used for game scripts?
You could just slightly modify the recursive backtracker to have a higher chance of moving towards the finish point and have it start at the start point.
Or you could make your own recursive backtracker, it really isn't that hard.

Code: Select all

--Backtracker
path={math.random(1,width),math.random(1,height)}
map = newMap()
end

function love.update(dt)
if #path > 0 then
local x,y = path[#path][1],path[#path][2]
local t = {}
-- Add all the positions it CAN walk to from x and y
if #t > 0 then -- It can walk somewhere
local c = t[math.random(1,#t)]
merge(x,y,c.x,c.y) -- Merge the points
path[#path+1] = {c.x,c.y} -- Add the new point to the path
else
path[#path] = nil -- Remove the part in the path that could no walk anywhere
end
else
print('DONE')
end
end

function love.draw()
love.graphics.draw( -- draw the map
end
thats what the actual algorithm looks like ( if not optimised ) but should not be too hard to make.

and as I have not seen anyone store maps the way I do here is a quick explanation:

using a texture atlas / tile sheet a table storing the different quads from 1 to 15. ( using 0 most of the time )
left,up,right,down = 1,2,4,8 -- power of two's
is just quad[left] and therefore only goes left
and likewise quad[left+up+down] goes left, up and down
they can therefore be quickly added to a map where 0 is empty by doing
map[y][x] = map[y][x] + (left, up, right or down)
which is used instead of map[y][x].(left, up, right or down) = true

I use this method because:
1) its just the quad index stored in the map.
2) it take up less ram since less tables are needed.

the drawbacks are:
1) may be harder to get a hang on at first.

thats a quick summary of it, if you want a more complete explanation please tell me so.
If you can't fix it, Kill it with fire. ( Preferably before it lays eggs. )

davisdude
Party member
Posts: 1154
Joined: Sun Apr 28, 2013 3:29 am
Location: North Carolina

davisdude used Max Revive!
I figured I would try out making a maze to test my programming abilities.
You can check out my progress here.
It generates a 80*60 tile maze currently, but you can play around with the configurations if you want to.

It takes around 3 minutes to fully complete.
Take a peek at the source code if you want. I tried to make it pretty readable, but I have a nasty habit of not commenting my code enough.
Attachments
Maze.love
GitHub | MLib - Math and shape intersections library | Walt - Animation library | Brady - Camera library with parallax scrolling | Vim-love-docs - Help files and syntax coloring for Vim

Ranguna259
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Posts: 911
Joined: Tue Jun 18, 2013 10:58 pm
Location: I'm right next to you

Finally, a maze with a start and a finish
LoveDebug- A library that will help you debug your game with an on-screen fully interactive lua console, you can even do code hotswapping

davisdude
Party member
Posts: 1154
Joined: Sun Apr 28, 2013 3:29 am
Location: North Carolina

Confession: I actually added the end with MS Paint.
I tried a 200 * 150 grid. Here are the results:

Green is the start, yellow is the end. Working on making it automatically choose an end.
GitHub | MLib - Math and shape intersections library | Walt - Animation library | Brady - Camera library with parallax scrolling | Vim-love-docs - Help files and syntax coloring for Vim

Germanunkol
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# UK General Elections - part1

Published: 20/01/2015

The political machines of the UK are currently in the process of ramping up in preparation for the general election on May 7th. This marks the election of the 56th parliament of the united kingdom, and seems like a good opportunity to take a look at some of the data from previous elections.

## Getting the Data

What I first set out to look at past election results in the UK I had assumed that the data would be easy to obtain. Wikipedia contains the overall results of the elections stretching back over nearly 200 years. What it does not contain is the break down of the results on a constituency level, which seems like a more interesting dataset.

My next stop was the electoral commission. They have an excellent break down of elections since 2000, however after a few emails to them it became apparent that they don't hold any results before that.

The only place I could find the results online was Political Science Resources. Here the results were available down to the constituency level, but not in an easy to access format. I had to do some web scrapping, but the consistent format meant that a short python script, available here, allowed me to grab the data and save it in JSON format. The resulting data can be found here, and covers the general elections since 1950.

• The data covers 17 general elections, spanning the last 60 years.
• In these elections almost 5 billion votes were cast, with over ten thousand MPs being elected.
• almost 668 Political parties took part (this is an over-count obscured by the fact that the same party might be have it's name recorded slightly differently, e.g. 'LibDem' and 'Liberal Democrat'). This includes a number of uncommon names such as 'Death Dungeons & Taxes' Party.

How did it go for the parties involved? The total number of seats in parliament won by each party can be found below

As you can see, the British system is dominated by two parties: Labour and Conservatives. In far third place are the Liberals (Here I follow wikipedia's lead use the label "Liberal" to cover the Liberals, the SDP–Liberal Alliance and the Liberal Democrats). Behind that are a series of small parties and independent candidates labelled "other". I will use this convention in the following. Some of the time my numbers show and off-by-one error with respect reports elsewhere. As far as I can tell this is due to the inclusions of the Speaker - who in my data is not considered to have a party and so gets lumped in "other".

## Looking at the Data

We've just seen a total summary of the vote - how does this share of seat won by each party changes over time?

The vertical black lines show when an election took place, and the white line shows half the total number of available seats.

Notice that the total number of seat available changes over time. This happens whenever there are boundary changes for constituencies. The process is designed to take into account population shifts over time and to keep it so that each MP represents roughly the same number of people.

Over the same range we can look at the total share of each vote the parties won

Where the style is the same as the previous graph.

Ignoring the full results themselves and focusing only on the total number of votes cast we see a steady rise over time until 1992, then a drop. This means that despite the total population of the country increasing by 5 million between 1992 and 2010, the total number of people voting in these elections fell by almost 5 million. Let's take a look at this in more detail.

How does the percentage turnout vary over time?

Here the black line represents the mean turnout for each constituency for a given year, and the black shaded area around this line shows the a fifty percent range - that means that the turnout for half the constituencies of that year lie in that range. I was curious to see if the winner party had any effect on the turn out, so I plotted the lines representing the mean turnout each year for each of the parties separately. These are the coloured lines on the graph.

However you look at it the turnout rate is dropping - this is true for every party. It seems to be true for most countries as well.

Looking at the graph it might be possible to say that the turnout for constituencies where Conservatives and Liberals win is slightly higher than for constituencies where the Labour win. To investigate this further, let's look at just the constituencies where Labour and Conservatives win seats. Because of the large variation on turnout due to time, I am going to subtract off the mean turnout for each year from the results. A histogram of the remaining turnout is shown below.

That looks fairly conclusive: on average the areas that return Conservative MPs have a higher turn out than those that vote Labour.

I have a feeling that this difference could be due to how closely fought an election was. I can imaging a situation where the turnout of an area is lower than average if it is expected beforehand that one party or candidate is going to win the election by a long way. While the data does not allow me to directly measure this feeling, I can try and get a proxy for it by looking at the number of votes the winning candidate won by, as a percentage of the total number of voters.

To do this, I am going to look at every election and collect both the fraction of the votes the winner received, and the percentage turnout for the election. Again I am going to subtract off the mean turnout for that year from each of the elections.

Here every data point represents the result of a single election in a single constituency in a single year.

Fitting a straight line to the data results in the black line over the top of the data points, with the form of the fit and R squared value quoted on the graph. There is some sort of general pattern there - when the winning candidate gets more votes the turnout is on average lower, but the low $R^{2}$ value suggests that only 16% of the variance in the turnout can be explained this way.

The above graph hints that there may be a difference between the parties, but does not make it clear. Let's look at each party in turn and see how they fit into the overall pattern.

Where each square shows has the results for a different party highlighted - the results for the other parties have had their transparency reduced.

This is interesting: different parties show different shapes. Qualitatively we can note the following

• Roughly each party shows some trend of the form: the higher the winning fraction, the lower the turnout.
• Compared to the Conservatives, Labour has more scatter in their points. It has more areas where the turn out is lower and more areas where they win by a long way - but these are not necessarily the same areas.
• Compared to Labour and Conservatives, the areas where Liberals win tend to have a higher turnout, and the election is closer.
• The parties in "Other" show the strongest correlation between how close the election was and what the turnout was. This could be due to the parties lumped in "Other" often related to local issues - potentially making it more obvious when an election is going to be close - although that is pure speculation.

All of this suggests that the difference in turnout rate between areas that return Conservatives and Labour MPs cannot be explained by just differences in how close the elections are alone (at least when assuming a naive linear model relating the two). These ideas can be made more quantitative by comparing the mean of each distribution before and after adjustment for percentage win - and the result is the same conclusion as above.

In the future I'd like to look at how other factors come into play. It would be interesting to see how results change in regions over time. To do this I'd need to include factors like by elections and how constituency boundaries have changed . Another would be to try and look at how demographics correlate with political party. Hopefully these will be topics for future posts.


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# Show that a finite generated subgroup $H$ of $G$ with index 3 exists which is not normal in $G$.

> Suppose that $$a$$ & $$b$$ are the generators of a free group $$G$$.Show that a finite generated subgroup $$H$$ of $$G$$ with index 3 exists which is not normal in $$G$$.

The way i try to solve the problem was that trying to find a covering space for $$S^1\vee S^1$$ which is not regular and reach the graph i attached but i do'nt know it works or not and still i didn't learn how to write the covering space from the following graph and the other similar graphs.Thanks in advance

Let $$\widetilde X$$ be the graph you drew, let $$X = S^1 \vee S^1$$ be the original space, and let $$\pi : \widetilde X \to X$$ be the covering map. Also define $$p \in X$$ to be the point $$p=\pi(p_1) = \pi(p_2) = \pi(p_3)$$.
We want to show that the covering $$\pi : \widetilde X \to X$$ is not regular. Consider the fibre above the $$p \in X$$, which is $$\pi^{-1}(p) = \{ p_1, p_2, p_3 \}$$. To show that the covering is not regular, it suffices to show that there does not exist a deck transformation $$\tau : \widetilde X \to \widetilde X$$ such that $$\tau(p_1) = p_2$$. [A deck transformation is a homeomorphism $$\tau : \widetilde X \to \widetilde X$$ such that $$\pi \circ \tau = \pi$$.]
Since $$\tau$$ obeys $$\pi \circ \tau = \pi$$, it must permute the points in $$\pi^{-1}(p)$$. So if $$\tau(p_1) = p_2$$, then there are two options: either $$\tau$$ sends $$p_1 \mapsto p_2$$, $$p_2 \mapsto p_3$$ and $$p_3 \mapsto p_1$$, or $$\tau$$ sends $$p_1 \mapsto p_2$$, $$p_2 \mapsto p_1$$ and $$p_3 \mapsto p_3$$.
Both options are impossible. In $$\widetilde X$$, every path from $$p_1$$ to $$p_3$$ passes through $$p_2$$. But there is a path from $$p_2$$ to $$p_1$$ that doesn't pass through $$p_3$$, and there is a path from $$p_2$$ to $$p_3$$ hat doesn't pass through $$p_1$$. Therefore, there cannot exist a homeomorphism $$\tau : \widetilde X \to \widetilde X$$ sending $$p_1 \mapsto p_2$$, $$p_2 \mapsto p_3$$ and $$p_3 \mapsto p_1$$, or sending $$p_1 \mapsto p_2$$, $$p_2 \mapsto p_1$$ and $$p_3 \mapsto p_3$$.
The intuition is that the points $$p_1, p_2, p_3$$ are in different "environments". In my proof, I exploited the fact that $$p_1$$ is an "end-point", whereas $$p_2$$ is a "middle-point" (excuse the poor terminology).
• @pershinaolad So the general recipe is: (i) pick your favourite point in the base space (it doesn't matter which one you pick), (ii) find the fibre above this point, (iii) decide whether the deck transformations act transitively on this fibre. In your example, I picked $p$ purely for convenience. – Kenny Wong Jan 18 at 14:57


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# For safety of a concrete dam against overturning, what must be width of the dam of rectangular cross section of height 10 m, if the height of water storage on one side of it is 9 m? Take unit weight of water as 10 kN/m3 and unit weight of concrete as 25 kN/m3.(Ignore effect of uplift, friction and any other force)

Free Practice With Testbook Mock Tests

## Options:

1. $$\dfrac{4\sqrt{3}}{5} \ m$$

2. $$\dfrac{3\sqrt{3}}{5} \ m$$

3. $$9\dfrac{\sqrt{3}}{5} \ m$$

4. 0.6 m

### Correct Answer: Option 3 (Solution Below)

This question was previously asked in

SSC JE CE Previous Year Paper 8 (Held on 29 Oct 2020 Morning)

SSC JE CE Previous Year Paper (Held On: 29 Oct 2020 Morning)

## Solution:

Explanation:

rc = 25 kN/m3

γw = 10 kW/m3

let length of Dam is pm

B is width of Dam

Hydrostatic force on dam, $${P_w} = \frac{1}{2}{\gamma_w}H \times H = \frac{1}{2} \times 10 \times 9 \times 9 = 405\;kN$$

Force due to weight of Dam, W = γc × A × L = 25 × B × 10 × 1 = 250 B kN

‘Pw’ force try to overturn the dam about the and ‘w’ force try to script it.

To safety against overturning,

NOT ≤ NR

Pw × ≤ W × B/2

$$405 \times 3 \le 250\;B \times \frac{B}{2}$$

⇒ $$B \ge \sqrt {\frac{{405\; \times\; 2\; \times\; 3}}{{250}}}$$

⇒ $$B \ge \frac{9}{5}\sqrt 3 \;m$$


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# cubic feet to feet

Using measurements in feet: Area of the Circle (ft 2) = Pi x (Diameter/2)^2. Pi = 3.14. The cubic foot is a US customary and imperial unit of volume. cubic feet = oil barrel * 5.6145833334. Volume in Cubic Meters (m 3) = Volume in Cubic Feet (ft 3) x 0.0283. Instant free online tool for cubic foot to ton register conversion or vice versa. Next, let's look at an example showing the work and calculations that are involved in converting from cubic meters to cubic feet (m 3 to ft 3). A cubic foot is a unit of volume. An estimated 60% of users will prefer ovens ranging from 1.1-1.9 cubic ft to other microwave ovens. Energy units equivalents With this energy units pair converter , a difference between two energy units are calculated to work out their corresponding equivalent values. Also, explore tools to convert cubic foot or ton register to other volume units or learn more about volume conversions. A cubic foot (pl cubic feet) is a unit of measuring volume used by those countries who recognize the Imperial system and the US customary system (the US, the UK, a series of countries in African and the Pacific regions, etc. Total stocks now stand at 3.726 trillion cubic feet, up 284 billion cubic feet from a year ago, and 243 billion cubic feet above the five-year average, the government said. After converting the measurements into feet from another unit, multiply the values to get volume in cubic feet. Therefore, the top area in square feet of the cuboid can be calculated by using the formulae: $$Area = Length \times Width = 10\,ft \times 6\,ft = 60\,ft^2$$ 3 Responses to âEscambia Collects 4 Million Cubic Feet Of Hurricane Sally Debrisâ joe on December 17th, 2020 8:20 pm The people marking the piles needs to be run out of â¦ There are only three measurements you need to take to work out the volume or capacity in cubic feet: length, width and height.Once you've obtained those measurements, it's only a case of multiplying them together. 1 cubic meter is equal to 852.11336848478 kilo gram, or 35.314666572222 cubic foot. 2. 29 inch =. length(feet) × width(feet) × height(feet) = cubic feet(cf³) length(inches) × width(inches) × height(inches) ÷ 1728 = cubic feet(cf³) length(yards) × width(yards) × height(yards) × 27 â¦ Type the number of Cubic feet per second (ft³/s) you want to convert in the text box, to see the results in the table. Note that rounding errors may occur, so always check the results. In the first field, labeled âDiameter (ft),â enter the diameter, in feet, of the cylinder. To convet between fluid barrels and cubic feet, please visit fluid barrels to cubic feet converter. 12.7037 cubic feet. Use this formula to find the volume of a cylinder: Cubic Feet = Ï × radius 2 × height \pi \times \text{radius}^2 \times \text{height} Ï × radius 2 × height Cubic feet per second (ft³/s - Per second), volumetric flow rate. If you don't want to convert the unit to feet first, that's ok, below are formulas for other units. There are 12 inches in a foot, so divide the number of inches by 12 to get the decimal equivalent. For example, 1 cubic foot can be written as 1 ft³, 1 cu foot, 1 cu ft, or 1 CF. Use this page to learn how to convert between ounces and trillion cubic feet. Most microwave oven users prefer the full-size microwave oven. The cubic foot is an imperial and US customary (non-metric) unit of volume, used in the United States and the United Kingdom. Examples: If the diameter is five feet, enter â5â. The result is the pounds per cubic foot, i.e., density. 54.9 cubic inches / 1728 cubic feet per cubic inch = 0.0318 cubic feet Worked Example You measure a box and find it is 12 inches long, 5 inches high, and 3 inches deep. If you measured your â¦ )A cubic foot is equal to the volume of a cube with each side of 0.3048 meter, or 1 foot. units in reverse from cubic feet of natural gas into British thermal units. You then divide by 1,728 to find out the cubic feet of your microwave oven. 1 cubic meter is equal to 33814.022558919 ounce [US, liquid], or 3.5314666572222E-11 trillion cubic feet. The cuboid has dimensions 10 feet in length and 6 feet in width. A cubic foot is sometimes also referred to as a cubic ft. Cubic feet can be abbreviated as ft³, and are also sometimes abbreviated as cu foot, cu ft, or CF. 1 Oil Barrel = 5.6145833334 Cubic Feet. ounce [US, liquid] or trillion cubic feet The SI derived unit for volume is the cubic meter. Divide the weight (in pounds) of the shipment by the total cubic feet. 37.2868 inch. The cubic foot [ft^3] to ton register [ton reg] conversion table and conversion steps are also listed. If the diameter is seven feet, four inches, enter â7.33â. CUBIC METER TO BOARD FOOT (m3 TO board foot) FORMULA To convert between Cubic Meter and Board Foot you have to do the following: First divide 1 / ((0.003785411784/231)*1728)/12 = 423.77600066 Then multiply the amount of Cubic Meter you want to convert to Board Foot, use the chart below to guide you. Note that rounding errors may occur, so always check the results. Cubic feet formula for different units. It is the size of a cube that is 1 foot on a side. So, how many cubic feet in a cubic â¦ Calculate concrete volume of a round slab. If the diameter is six feet, nine inches, enter â6.75â. Converting to Cubic Feet Divide by 1,728 to convert cubic inches to cubic feet. And, cubic yard (yd3) is referred to as the measurement of volume along with a length, width, and height of 1 yard. Use this page to learn how to convert between kilograms and cubic feet. The volume formula for a rectangular (or square) box in cubic feet is height(ft) x width(ft) x length(ft), as seen in the figure below: For example, to fill a box with a width of 3ft and a length of 6ft, to a depth of 1ft, you need to multiply 1ft x 3ft x 6ft = 24ft 3 (cubic feet) of gravel, then multiply that by the density. 14.114 cubic feet. A cubic meter, or cubic metre, is a unit of volume. This page features online conversion from centum cubic feet to mil cubic feet.These units belong to the same measurement system: British And U.S. Derivatives Of Length Units. In the example the container is 20 feet x 5.67 feet x 7.5 feet. It is defined as the volume of a cube with sides of one foot (0.3048 m) in length. Or, if you prefer, you can let the cubic feet calculator do the hard work for you.Length (feet) x Width (feet) x Height (feet) = Volume in cubic feet (written as Xft3)If the shape is irregular, mentally divide it into regular shapes and calculâ¦ It is about 7.5 gallons or about 28.3 liters. Volume in Cubic Feet (ft 3) = Depth x Area. 30 cubic feet =. A cubic foot (ft3) is said to be as a measurement of volume that contains a length, width, and height of 1 foot. Convert energy of British thermal unit (BTU) and cubic feet of natural gas (cu ft N.G.) For example, to convert 5 oil barrels to cubic feet, multiply 5 by 5.6145833334, that makes 28.0729 cubic feet is 5 oil bbl. oil barrels to cubic feet formula. Cubic feet to Square feet Calculator: Cubic feet (ft 3) :: Square feet (ft 2) :: Home A decimal can be used if the measurement is not a whole number. 29 cubic feet =. The conversions from cubic yards to cubic feet are generally used to figure out the gravel, sand, and several other materials that fill in a large area. 30 inch =. Read more: Best 1000 Watt Microwave Ovens. â¦ The cubic foot per minute (symbol: CFM) is a the unit of volumetric flow rate equal to that of a cubic foot moving each minute.It is equal 0.000471947 m 3 /s. 36.8678 inch. 15.625 cubic feet. How to Find Cubic Feet of a Cylinder? If you need to convert centum cubic feet to another compatible unit, please pick the one you need on the page below. You will be able to view your total estimated weight and total volume by clicking on "View Total" button Volume in Cubic Yards (yd 3) = Volume in Cubic Feet (ft 3) / 27. 9 Cubic feet = 0.000207 Acre feet: 1000 Cubic feet = 0.023 Acre feet: 1000000 Cubic feet = 22.9568 Acre feet: Embed this unit converter in your page or blog, by copying the following HTML code: convertlive Its volume is 28.3168 litres or about 1/35 of a cubic metre. Round fractions to the nearest full cubic foot number. cubic meter to cubic feet Conversion Table:: m 3 to cu ft 1.0 = 35.31467 2.0 = 70.62933 3.0 = 105.9440 4.0 = 141.25867 5.0 = 176.5733: cubic meter to cubic feet Step â¦ Most Common Cubic Feet for Microwave Ovens. For multiple pieces, add the weight of each piece together before dividing by the total cubic feet of the shipment. 'S ok, below are formulas for other units feet ( ft 3 ) x 0.0283 users prefer. 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text:
Example QF.2.3 : $A =\frac 1 2; q(x) = \frac 1 2 x^2$
This is best understood as the composition of the core quadratic function $g(x)= x^2$ followed by the linear function $f(x) = \frac 1 2 x$, so $q(x) = f(g(x))$.
Draw a mapping diagram showing this composition  or have SAGE create this by evaluating.
Compare the mapping diagram with the graphs of $g(x)$ and $q(x)$
 Graphs of $g(x)$ and $q(x)$ Mapping Diagram Showing Composition. Given a point / number, $x$, on the source line, there is a blue arrow meeting the target line at the point / number, $\frac 1 2 x^2$. This point corresponds to the quadratic function's value for $x$. he values for the core mapping diagram for $x^2$ in green are magnified by a factor of $\frac 1 2$  shown by the red arrows.

As $x$ increases, $q(x)$ decreases to value $q(0)=0$ and then increases.


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# Kerodon

$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$

Remark 4.3.5.15. Let $f_{-}: K_{-} \rightarrow X$ and $f_{+}: K_{+} \rightarrow X$ be morphisms of simplicial sets. Then Proposition 4.3.5.13 supplies bijections between the following:

$(1)$

The collection of morphisms $\overline{f}_{-}: K_{-} \rightarrow X_{/ f_{+}}$ for which the composition $K_{-} \xrightarrow { \overline{f}_{-} } X_{/f_{+}} \rightarrow X$ is equal to $f_{-}$.

$(2)$

The collection of morphisms $\overline{f}_{+}: K_{+} \rightarrow X_{f_{-} /}$ for which the composition $K_{-} \xrightarrow { \overline{f}_{+}} X_{f_{-}/} \rightarrow X$ is equal to $f_{+}$.

$(3)$

The collection of morphisms $f_{\pm }: K_{-} \star K_{+} \rightarrow X$ for which $f_{\pm }|_{K_{-}} = f_{-}$ and $f_{\pm }|_{ K_{+}} = f_{+}$.

Suppose we are given a morphism of simplicial sets $f_{\pm }: K_{-} \star K_{+} \rightarrow X$ as in $(3)$, corresponding to morphisms $\overline{f}_{-}: K_{-} \rightarrow X_{ / f_{+} }$ and $\overline{f}_{+}: K_{+} \rightarrow X_{f_{-} /}$ as in $(1)$ and $(2)$, respectively. For every simplicial set $Y$, Proposition 4.3.5.13 supplies canonical bijections between the following:

$(1')$

The collection of morphisms $Y \rightarrow ( X_{ / f_{+} } )_{ \overline{f}_{-} / }$.

$(2')$

The collection of morphisms $Y \rightarrow ( X_{ f_{-} /} )_{ / \overline{f}_{+} }$.

$(3')$

The collection of morphisms $f: K_{-} \star Y \star K_{+} \rightarrow X$ satisfying $f|_{ K_{-} \star K_{+} } = f_{\pm }$.

These bijections determine a canonical isomorphism of simplicial sets

$(X_{f/} )_{ / \overline{f}' } \simeq ( X_{/ f'} )_{ \overline{f} / }.$

We will henceforth abuse notation by denoting either of these simplicial sets by $X_{ f_{-} / \, / f_{+} }$. Beware that the simplicial set $X_{ f_{-} / \, / f_{+} }$ depends not only on $f_{-}$ and $f_{+}$, but also on their common extension $f_{\pm }: K_{-} \star K_{+} \rightarrow X$.


text:
# Lecture 9 – Hypothesis Testing¶

## DSC 80, Winter 2023¶

### Announcements¶

• Lab 3 is due today at 11:59PM.
• Project 2's checkpoint is due Thursday, February 2nd at 11:59PM, and the full project is due on Thursday, February 9th at 11:59PM.
• Read this note on Ed about indexing into Series' that result from calling .value_counts().
• Soon, we'll release a "Grade Report" that summarizes your scores and slip days on all graded assignments so far (including Project 1).
• I'll be in the CSES "CS Jeopardy" event on Wednesday 2/1 from 5-7PM in CSE 1202.
• I know discussion is from 5-6PM 😢 – if you're interested, you can come after.

### Agenda¶

We'll look at many examples, and cover the necessary theory along the way.

• Coin flipping
• Total variation distance.
• Penguin bill lengths 🐧.

### "Standard" hypothesis testing¶

"Standard" hypothesis testing helps us answer questions of the form:

I have a population distribution, and I have one sample. Does this sample look like it was drawn from the population?

• Sample: 59 heads and 41 tails. Population: A fair coin.
• Sample: Ethnic distribution of UCSD. Population: Ethnic distribution of California. (Comparing categorical distributions with the TVD.)
• Sample: Sample of Torgersen Island penguins. Population: All 333 penguins.

## Example: Coin flipping¶

### Recap: Coin flipping¶

Let's recap the example we saw last time.

• Observation: We flipped a coin 100 times, and saw 59 heads and 41 tails.
• Null Hypothesis: The coin is fair.
• Alternative Hypothesis: The coin is biased in favor of heads.
• Test Statistic: Number of heads, $N_H$.

### Generating the null distribution¶

• Now that we've chosen a test statistic, we need to generate the distribution of the test statistic under the assumption the null hypothesis is true, i.e. the null distribution.
• This distribution will give us, for instance:
• The probability of seeing 4 heads in 100 flips of a fair coin.
• The probability of seeing at most 46 heads in 100 flips of a fair coin.
• The probability of seeing at least 59 heads in 100 flips of a fair coin.

### Generating the null distribution, using math¶

The number of heads in 100 flips of a fair coin follows the $\text{Binomial(100, 0.5)}$ distribution, in which

$$P(\text{# heads} = k) = {100 \choose k} (0.5)^k{(1-0.5)^{100-k}} = {100 \choose k} 0.5^{100}$$

The probability that we see at least 59 heads is then:

Let's look at this distribution visually.


text:
# Q T-Resummation for Polarized Semi-Inclusive Deep Inelastic Scattering

We study the transverse-momentum distribution of hadrons produced in semi-inclusive deep-inelastic scattering. We consider cross sections for various combinations of the polarizations of the initial lepton and nucleon or the produced hadron, for which we perform the resummation of large double-logarithmic perturbative corrections arising at small transverse momentum. We present phenomenological results for the process $ep\to e\pi X$ for the typical kinematics in the COMPASS experiment. We discuss the impact of the perturbative resummation and of estimated non-perturbative contributions on the corresponding cross sections and their spin asymmetry.

Author: Yuji Koike; Junji Nagashima; Werner Vogelsang

Source: https://archive.org/


text:
# How to get the list of opened applications in windows with PowerShell?

PowerShellMicrosoft TechnologiesSoftware & Coding

#### Powershell for beginners

15 Lectures 3.5 hours

#### Learning Task Automation using Windows PowerShell

35 Lectures 2.5 hours

#### The Complete PowerShell 7 course: Beginner To Advanced

Most Popular

145 Lectures 12.5 hours

We can get the list of opened applications in Windows using PowerShell using Get-Process command. Get-Process command shows the currently running processes in the foreground and the background as well.

If we simply run the Get-Process command then it will give the process names and their associated process IDs and CPU, memory usage.

PS C:\> Get-Process

If we check the members of the Get-Process, there is a MainWindowsTitle Property. This property indicates the Title of the opened application.

In the below example, we will find the Application Name, associated process, and the ID of the application. For example,

Get-Process | Select MainWindowTitle,ProcessName,Id | where{\$_.MainWindowTitle -ne ""}

We need to filter out the blank titles because they may be used by the background processes.

Updated on 20-Nov-2020 08:49:49


text:
# Exactly how compatible is LibreOffice with Microsoft Office? [closed]

I'm thinking specifically of calc/excel.

I want to make two spreadsheets, one for working out my timesheets and figuring out how much time I've spent on a job compared to others etc.

Another which deals with my finances. In order to automate these as much as possible I would like to integrate my spreadsheets with Python and build several Macro's.

Samples of what I would build is a prompting system which reads through a fie of my finances containing each item for the month. If it recognises the item it would automatically place it into a specific row/column/sheet. If not the programme will prompt me about the item if it doesn't to tell iin order to figure out where to put it (in this case the response would then be stored in the hopes that future items will be remembered). Another would be for my timesheet system. There I'd set up a programme which would ask me for a job number, time spent and the day in which I'm talking about. That would then find the appropriate palce and automatically input the item.

After that the sheets would be set to automatically incorporate the new data into their analysis, updating any statistical tables and graphs I've set up.

My home computers are all running Ubuntu and therefore I'm using LibreOffice, however my work computer runs windows and Microsoft Office.

So what I want to know is that, if I build all my spreadhseets in LibreOffice, will I be able to transfer them over into Microsoft Office for work successfully. Or should I build a Microsoft and Libre Office version?

edit retag reopen merge delete

### Closed for the following reason the question is answered, right answer was accepted by Alex Kemp close date 2016-02-29 21:37:41.594335

Sort by » oldest newest most voted

A simple very practical approach - Why don't you build 1 spreadsheet and try how it works in the other application. You don't need to develop the very big sheet only test sample with a smaller macro, and maybe a chart.

Between Calc and Excel I always use XLS format not XLSX. because I remember having seen some problems.

In an older version of LIbO (v3 family) I remember some bugs with charts. But now I am running LIbO 4.1.4.2 and have not seen a problem recently.

I never had a macro in my spreadsheet thus don't know how macros will behave.

more

I would like to integrate my spreadsheets with Python and build several Macro's. [...] My home computers are all running Ubuntu and therefore I'm using LibreOffice, however my work computer runs windows and Microsoft Office.

As @ROSt52 indicates, for compatibility with LO you are going to have to either:

• Use the old binary XLS format or the newer OOXML XLSX format on older versions on MS Office.
• Use ODF v1.2 (rather than the v1.2 Extended used by default) in conjunction with MS Office 2013 as indicated here.

In either case though, macros are likely to be an issue as XLSX will only save VBA macros, while ODS can save LO Basic and VBA[1]. There are evidently tools to allow limited Python[2] manipulation in XLS/X, but you do not indicate what you are considering in this area.

By way of general answer to your title, I have recently written this outline of MS binary vs OOXML support in LO.

[1] Tools > Options... > Load/Save > VBA Properties > indicates whether a copy of the existing VBA macro is preserved or not. Also note this answer about the option required at the head of a VBA macro to allow it to run.

[2] There is no native IDE for Python in LO and no native method of saving Python macros in ODS (the scripts are saved to the user profile under Scripts/python/). There are however some workarounds and extensions available to try and simplify this somewhat (refer this Apache OO forum thread).

more


text:
Two scales on a voltmeter, which is constructed from a galvanometer, measure voltages up to 24 V and 34 V respectively. The resistance connected in series with the galvanometer is 1680 for the 24 scale and 2941 for the 34 scale.
Determine the internal resistance of the galvanometer.
Answer to 2 s.f.

### Get this answer with Chegg Study

Practice with similar questions
Q:
Two scales on a voltmeter, which is constructed from a galvanometer, measure voltages up to 24 V and 33 V respectively. The resistance connected in series with the galvanometer is 1679 for the 24 scale and 2937 for the 33 scale.Determine the internal resistance of the galvanometer.Answer to 2 s.f.


text:
183_notes:torque

Section 5.4 and 11.4 in Matter and Interactions (4th edition)

Until now, you have worked with forces and work to explain and predict the motion of objects. You've even used work and energy to begin to explain that objects can rotate, but you haven't yet unpacked how that occurs – only that a system can share energy between translation and rotation. In these notes, you will read about torque, which is a force applied at a distance from a specific point that causes a twisting or rotating about that point.

Torque is a vector quantity that describes how you can change the rotation of an object.. Specifically, the torque about a point A is the vector (cross) product of the vector that points from A to the point where the force is applied and the force itself. That's a mouthful, but you can think about it in terms of the figure to the right.

Consider a bolt that is located at A in the figure to the right. You attach a wrench to location A and push on the end of the wrench with the force indicated. The vector that points from A to the end of the wrench where the force is applied is $\vec{r}_A$. This distance is often called the “lever arm.” It indicates the point of application of the force relative to the rotation axis.

In this situation, the force that you apply to the end of the wrench is not “100% effective” because only the component of the force applied perpendicular to the lever arm contributes to the rotation of the bolt. In any event, the bolt will rotate in a counter-clockwise manner as the end of the wrench moves around the dotted circle. The torque that is applied is related to the lever arm and the applied force by the cross product.

$$\vec{\tau}_{A} = \vec{r}_A \times \vec{F}$$

The torque is a vector; it has both a magnitude and direction. The units of torque are Newton-meters ($\mathrm{Nm}$). This is the first physical quantity that you have seen that depends on the cross (vector) product between two vectors. It's worth taking some time to understand how this mathematics works.

The magnitude of the torque depends on the component of the force that is perpendicular to the lever arm. In the figure above, the perpendicular component of the force is given by,

$$F_{\perp} = F\sin\theta$$

So that the magnitude of the torque around location A is given by,

$$\left|\vec{\tau}_{A}\right| = \left|\vec{r}_A \times \vec{F}\right| = r_{A} F\sin\theta$$

This mathematical relationship holds for any cross product. The magnitude of a general cross product is the product of the magnitudes of the vectors multiplied by the sine of the angle between them.

$$\left|\vec{B} \times \vec{C}\right| = \left|\vec{B}\right|\left|\vec{C}\right|\sin \theta_{BC}$$

So, as shown in the figure to the right, the torque is only due to the component of the force that is perpendicular to the lever arm ($F_{\perp}$).

Torque is a vector quantity; it has a direction. How can you determine that direction?

In general, this is done mathematically by taking the determinant of a special matrix, which you might have seen in other mathematics courses. For most purposes, you will consider motion in the plane (e.g., $x-y$ plane). This is a bit easier to think about than cross products in general 1). If the lever arm ($\vec{r}_A$) and the applied force ($\vec{F}$) live in the $x-y$ plane, the torque points in the $z$-direction (either + or -).

Here's the proof of that. Consider a lever arm in the $x-y$ plane that locates a force with respect to some rotation axis: $\vec{r}_A = \langle r_x, r_y, 0\rangle$ and a force that similar lives in the $x-y$ plane: $\vec{F} = \langle F_x, F_y, 0\rangle$. You want to take the cross product to find the torque:

$$\vec{\tau}_{A} = \vec{r}_A \times \vec{F} = det\begin{vmatrix} \hat{x} & \hat{y} & \hat{z} \\ r_x & r_y & 0 \\ F_x & F_y & 0 \\ \end{vmatrix}$$

Taking the cross product as described in these notes:

$$\vec{\tau}_A = \left(r_y(0)-0(F_y)\right)\hat{x} - \left(r_x(0)-0(F_x)\right)\hat{y} + \left(r_xF_y-r_yF_x\right)\hat{z} = \left(r_xF_y-r_yF_x\right)\hat{z}$$

$$\vec{\tau}_A = \langle 0,0,r_xF_y-r_yF_x\rangle$$

Notice that if the applied force and the lever arm point in the same (or precisely opposite directions) the torque is zero. The cross product of two parallel or anti-parallel vectors is zero.

When working with forces and lever arms that exist is a plane (e.g., $x-y$ plane), the torque always points in the $z$-direction. So, it becomes useful to think about the torque as having a sign, either + or - depending on whether in points in the $+z$ or $-z$ direction. The “right-hand rule” is helpful to think about this.

To use this rule, point your fingers in the direction of the the lever arm (from the rotation point to the point of application of the of the force). Then, curl your fingers in the direction of the force. Your thumb will point in the direction of the torque. This works for any situation, but you might be confused about the sign. A simpler way of remembering it is using the picture on the right. This is somewhat analogous to having forces in different directions.

The language often used to describe the torque direction is into the page and out of the page. It is the nature of cross products that the resultant is perpendicular to the plane defined by the vectors in the cross product. So, if the lever arm and the force vector appear on page (or screen), the torque will point into or out of the page (or screen). In the cases shown to the right, it means the vector associated with the torque points into the screen (negative, clockwise rotation) or out of the screen (positive, counter-clockwise rotation).

Just like you read for forces, there can be multiple torques applied to an object. That is, there might be forces applied at different locations and in different directions, which could (on their own) give rise to different rotations. The concept of a net torque is an important one because it helps you decide what the rotation will be (or even if there will be any rotation). The net torque is the vector sum of all the torques acting on an object. These torques must be computed around the same rotation axis (i.e., the lever arm for each force can be different, but this lever arm must be measured from the same rotation location).

$$\vec{\tau}_{net} = \sum_i \vec{\tau}_i$$

The sign of each torque is incredibly important for determining the net torque. It is the net torque that causes changes in rotation, just like it is the net force that causes changes in translation.

1)
For most problems, you can transform the situation into a planar problem where the plane is defined by the lever arm and the force. So we will only consider problems where that has been done.
• 183_notes/torque.txt
• Last modified: 2021/05/08 18:56
• by stumptyl


text:
# Bug Tracker

ID 39🔗 2013-09-11 17:28:28 Closed (Not a Bug) glossaries 3.02 if hyperref is loaded before glossaries then the subscript size is wrong Linux Debian Wheezy

## Description

How to reproduce:

1. Create a file q.tex with the following contents:

\documentclass{article}
\usepackage{hyperref}
\newglossaryentry{N}{name={N}, description={N}}
\begin{document}
$\gls{N}_{\gls{N}}$
\end{document}

2. Run
latex q.tex && dvips -o q.ps q.dvi

3. Run
xdvi q.dvi &
gv q.ps &

4. Observe that both occurencies of N are generated same size, which is incorrect.

When \usepackage{hyperref} is commented out, the second occurence of N is generated smaller, the way it should be for the lower index.

Loading hyperref after glossaries produces right font size at the cost of functionaility. Namely, the hyperlinks from the text items to the glossary are gone then.

I would be grateful if you, perhaps together with the maintainer of hyperref, could correct the issue.

Thanks!
Jaakov.

## MWE

\documentclass{article}
\usepackage{hyperref}
\newglossaryentry{N}{name={N}, description={N}}
\begin{document}
$\gls{N}_{\gls{N}}$
\end{document}

## Evaluation

This is not a bug in glossaries as the same issue occurs without the glossaries package, but it only occurs when you use latex instead of pdflatex. Minimal example:

\documentclass{article}

\usepackage{hyperref}

\begin{document}
Target: \hypertarget{N}{N}.

$N_N$
$\hyperlink{N}{N}_{\hyperlink{N}{N}}$
\end{document}

This is either an issue with the DVI format of LaTeX or with hyperref. I recommend you use pdflatex rather than latex if you want hyperlinks in your document, as it has much better support for hyperlinks. If you really must create a DVI file, then try $\gls{N}[_{\glsentrytext{N}}]$  instead. This will bring the subscript inside the hyperlink but note that you need to use \glsentrytext not \gls.

Name (optional):

Are you human? Please confirm the bug report ID (which can be found at the top of this page) or login if you have an account.

Comment:

You can use the following markup:

Block:

[pre]Displayed verbatim[/pre]
[quote]block quote[/quote]

In line:

[tt]code[/tt]
[file]file/package/class name[/file]
[em]emphasized text[/em]
[b]bold text[/b]
[url]web address[/url] [sup]superscript[/sup]
[sub]subscript[/sub]

Ordered list:
[ol]
[li]first item[/li]
[li]second item[/li]
[/ol]

Unordered list:
[ul]
[li]first item[/li]
[li]second item[/li]
[/ul]

You can use the Preview button to review your message formatting before submitting.


text:
## 6.3 CIs for one proportion

Endotracheal intubation (ETI) is a method for maintaining an open airway or as a method for administering certain drugs for ill patients.

ETI is widely used for airway management of children in the out-of-hospital setting, but for many years little evidence was available on the effect of using ETI.

A study examined the use of ETI for airway management of children in the out-of-hospital setting .

1. For the BVM sample, 123 out of the 404 patients survived. For those receiving BVM, compute the sample odds of a patient who survived.
2. For the BVM sample, 123 out of the 404 patients survived. For those receiving BVM, compute an estimate of the population proportion of patients who survive.
3. Explain the difference between the meaning of the two above calculations.
4. In another sample of 404 patients who received the BVM treatment, would we expect to find exactly 123 surviving? Why or why not?

1. Compute the standard error, which indicates the sampling variability in the estimate of $$p$$. Explain what is meant by the term 'sampling variation' in this context.
2. Every time a new sample is chosen, the sample will likely yield a different value for $$\hat{p}$$. Sketch the distribution that shows how much the value of $$\hat{p}$$ is likely to change from one sample to the next.
3. Compute an approximate 95% confidence interval for the population proportion based on the sample proportion.
4. Write a sentence communicating this confidence interval.
5. Confirm that the conditions necessary for this calculation to be statistically valid are met.
6. If the researchers wished to estimate the true survival proportion to within give-or-take 0.01 with 95% confidence, would the sample size need to be larger or smaller?
7. For the ETI sample, 110 out of 416 patients survived. Use this information to construct a two-way table of treatment against survival.
8. Select a graphical summary that could be used to display the information. Sketch this display.
9. From this table, compute the odds ratio of a BVM patient not surviving compared to an ETI patient not surviving. Interpret this value.
10. What did you learn about using ETI on children? Would you prefer to recommend ETI or BVM on children? What other information would you need to help make your decision?

### References

Gausche M, Lewis RJ, Stratton SJ, Haynes BE, Gunter CS, Goodrich SM, et al. Effect of out-of-hospital pediatric endotracheal intubation on survival and neurological outcome: A controlled clinical trial. Journal of the American Medical Association. 2000;283(6):783–90.


text:
# Unity (UNET) Pass custom data when creating and joining a match in multiplayer

I've written some simple stuff to make a lobby for matchmaking. Now I want to pass some extra info besides the match name to the lobby. Something like Player's avatar and a number of players connected and what not. Thereto, I also want to pass information to the game from the players. For example, two players connect to a match and the character pick starts. For this I want to have the player's info regarding the characters they've picked and the character's weapons info (e.g. customized weapons info). I store all that in a json file and load from it to a class object. Is it ok to add these classes to, say, the player connection prefab that holds Network Identity or is it done somehow differently?

Can someone maybe help me with that in the context of Unity 2018 (i.e. give some advice or referrences to some relevant information)?

Appreciate all the help and thanks in advance.

• Hello and welcome to gamedevStackExchange please ask one question instead of asking many question inside one question. Oct 26, 2018 at 7:47

you can send your information to other players inside lobby:

instead of sending avatar image , send avatar index

using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.UI;
using UnityEngine.Networking;

public class SendInformation : NetworkBehaviour {
public class Soldier{
public int avatarId{get;set;}
public string playerName{get;set;}
}
public Soldier soldier;
public Sprite[] Avatars;
public Image image;

void Start () {
CmdSendData(0,"Jack",true);
}

[Command]
}

[ClientRpc]
soldier.avatarId = avatarId;
soldier.playerName = playerName;

image = Avatars[soldier.avatarId];
}
}

to get number of players connected use this:

var numOfConnectedPlayers = Network.connections.Length;

if you want to send json try this:

before using this script you should add Newtonsoft.Json.dll to your Plugins folder

using UnityEngine;
using System.Collections;
using UnityEngine.Networking;
using Newtonsoft.Json;

public class JsonTest : NetworkBehaviour {

public class Soldier{
public string id {get;set;}
public string Name {get;set;}
public bool Level {get;set;}
}
public Soldier soldier;

private void Start() {
string jsonString = "{\"id\":1, \"Name\":\"Jack\", \"Level\":0}";
CmdSendData(jsonString);
}

[Command]
public void CmdSendData (string json) {
RpcSendData(json);
}

[ClientRpc]
public void RpcSendData (string json) {
var information = JsonConvert.DeserializeObject<Soldier>(json);
soldier.id = information.id;
soldier.Level = information.Level;
soldier.Name = information.Name;
}
}


text:
# sum-sets in a finite field

Let $\mathbb{F}_p$ be a finite field, $A=\{a_1,\dots,a_k\}\subset\mathbb{F}_p^*$ a $k$-element set, for $k<p$. $\mathfrak{S}_k=$permutation gp.

Question. Is it true there is always a $\pi\in\mathfrak{S}_k$ such that the following are pair-wise distinct in $\mathbb{F}_p$? $$a_{\pi(1)}, \,a_{\pi(1)}+a_{\pi(2)},\,a_{\pi(1)}+a_{\pi(2)}+a_{\pi(3)},\,\dots, \,a_{\pi(1)}+\cdots+a_{\pi(k)}.$$

EDIT. Due to Julian Rosen's example, I change $A$ to be a subset of $\mathbb{F}_p^*$ (non-zero elements).

• $A=\{0,1,-1\}$ is a counterexample. – Julian Rosen Mar 19 '17 at 15:25
• What if we remove $0$? – T. Amdeberhan Mar 19 '17 at 16:15
• More generally, take A disjoint union -A for certain A: you won't get much more than half way without getting a repeat. (Actually, that may not hold. Hmm.) Gerhard "Wonders About Big Uncertain A" Paseman, 2017.03.19. – Gerhard Paseman Mar 19 '17 at 16:17
• This is actually a known open problem. I do not have any reference (and not sure anything has been published on it, just because there are no results to publish, as far as I am aware), but I remember for instance discussing it with Yong-Gao Chen and Zhi-Wei Sun a year and a half ago. – Seva Mar 19 '17 at 16:48
• is symmetric gp = $S_k$ the symmetric group on $k$ elements? – yberman Mar 19 '17 at 20:15

It took me some effort to find the references you were requesting in your comment, but here they are eventually:

As one can see, the problem is around for over 15 years at least.

• Wow! That is incredible. Thanks for the resources. – T. Amdeberhan Mar 20 '17 at 16:27

I first learned about this problem from Éric Balandraud (in 2013). So I wrote to him a couple of days ago, and he has just sent me an e-mail explaining that the question dates back (at least) to 1971. Éric attributes it to Erdős and Graham: He hasn't provided me with a reference (he is in the desert these days), but I will come back and update this answer as soon as I hear from him again.

Update (March 31, 2017). I've just got a new message from Éric Balandraud. Below is an excerpt.

Here is the reference:

R. Graham, On sums of integers taken from a fixed sequences, Proc. Wash. State Univ. Conf. on Number Theory (1971), 22-40.

The question is stated as Conjecture 10 on page 36. It also appears in:

P. Erdős and R. Graham, Old and new problems and results in combinatorial number theory, Monographie N28 de L'Enseignement Mathématiques, Université de Genève (1980).

The conjecture is stated there on page 95.


text:
Difference between revisions of "Math 587: Introduction to Analytic Number Theory."

Title

Introduction to Analytic Number Theory.

(3:3:0)

F

Prerequisite

(Math 352) or equivalent; instructor's consent.

Description

Arithmetical functions; distribution of primes; Dirichlet characters; Dirichlet's theorem; Gauss sums; primitive roots; Dirichlet L-functions; Riemann zeta-function; prime number theorem; partitions.

Desired Learning Outcomes

Students should gain a familiarity with the problems and tools of analytic number theory at beginning graduate level.

Prerequisites

A knowledge of complex analysis at the level of a first course such as Math 352 should suffice.

Minimal learning outcomes

Students should be familiar with the following concepts. They should know the technical terms, and be able to implement the methods taught in the course to work associated problems, including proving simple results.

1. Arithmetic functions
• convolution of arithmetic functions
• Möbius inversion
• multiplication function
• Euler's summation formula, Abel's identity
• average order of τ(n), σ(n) and φ(n)
2. Elementary theorems on distribution of prime numbers
• Chebyshev's inequalities
• Asymptotic formula for :$\sum_{p\le x} 1/p$


text:
# Missing coordinates?

Can someone just explain this to me; my teacher did a poor job doing so as usual...

I'm trying to find the missing coordinate of P, using the fact that P lies on the unit circle in the given quadrant.

The question looks like this: P( , -7/25), quadrant IV

Is there a proper way to find this using my TI-83? If so, how? Thanks.

-

HINTS: You’re given that $P$ is the point $\left(x,-\frac7{25}\right)$ on the unit circle in the fourth quadrant. The fact that $P$ is on the unit circle tells you that $$x^2+\left(-\frac7{25}\right)^2=1\;;$$ why? And what are the values of $x$ making this true?
The fact that $P$ is in the fourth quadrant tells you the algebraic sign of $x$; is $x$ positive, or is it negative?
All points on the unit circle obey the equation $x^2 + y^2 = 1$. You know $y=-\frac{7}{25}$, and can thus solve for $x$.
In case you forgot, in general, the circle around $(x_c,y_c)$ with radius $r$ is described by $$(x - x_c)^2 + (y - y_c)^2 = r^2$$


text:
# Mathematica can't compute this integral (but can a very similar one)

I am having a hard time to understand why Mathematica can't compute the following integral:

u2[z_] = 1/(1 + (Sqrt[2] - 1) Exp[z])^2
u2z[z_] = D[u2[z], z]
Rmono[z_] = Simplify[u2[z]*(1 - u2[z])]
Integrate[z*Rmono[z]*u2z[z], {z, y, \[Infinity]}]

while it can compute the very similar:

u1[z_] = 1/(1 + Exp[z])
u1z[z_] = D[u[z], z]
Rbistable[z_, a_] = Simplify[u1[z]*(1 - u1[z])*(u1[z] - a)]
Integrate[z*Rbistable[z, a]*u1z[z], {z, y, \[Infinity]}]

Is there a way to ask Mathematica to try harder? I know the integrand is more elaborate in the first integral but it looks like there is no conceptual barrier.

I am using version 12.1.

• As a side note, Mathematica definite integrals are often significantly slower than indefinite ones. If you evaluate the indefinite integral, it returns immediately. This is because by default, Mathematica works in the complex plane and can't assume analyticity. If you know that the Fundamental Theorem of Calculus applies, it's often faster to compute the indefinite integral and plug in this two endpoints. – Sami May 5 '20 at 10:19

Assumption seems to help it do it

  anti = Integrate[z*Rmono[z]*u2z[z], {z, y, Infinity}, Assumptions -> y >= 0]

  anti = Integrate[z*Rmono[z]*u2z[z], {z, y, Infinity},   Assumptions -> y <= 0]

Another way is

anti = Integrate[z*Rmono[z]*u2z[z], z];
sol3 = (Limit[anti, z -> Infinity] - Limit[anti, z -> y]) // Simplify

Update:

And another assumption which works, per suggestion given in the comment below is

anti=Integrate[z*Rmono[z]*u2z[z],{z,y,Infinity},
Assumptions->Element[y,Reals]]//Simplify

• Even Assumptions -> y \[Element] Reals helps. – user64494 May 5 '20 at 10:20


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# A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If

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A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If  [#permalink]

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A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If the median of these measurements is 6/7 times their arithmetic mean, what is the value of x?

A. 16
B. 15
C. 14
D. 13
E. 12

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Re: A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If  [#permalink]

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23 Sep 2010, 11:56
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A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If the median of these measurements is 6/7 times their arithmetic mean, what is the value of x?

A. 16
B. 15
C. 14
D. 13
E. 12

{4, 5, 6, 8, 10, x}

Median would be the average of two middle terms --> $$median=\frac{6+8}{2}=7$$;
$$mean=\frac{4+5+6+8+10+x}{6}=\frac{33+x}{6}$$;

Given: $$median=\frac{6}{7}*mean$$ --> $$7=\frac{6}{7}*\frac{33+x}{6}$$ --> $$x=16$$.

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Re: A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If  [#permalink]

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24 Sep 2010, 00:20
4, 5, 6, 8, 10 and x => median is : (6+8)/2 = 7
mean is = (4+5+6+8+10+x)/6 = (33+x)/6
since the median is 6/7 times of mean ==> 7= 6/7(33+x)/6 ==> 16
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Re: A list of measurements in increasing order is 4,5,6,8,10,x. If the med  [#permalink]

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20 Jul 2016, 01:49
bimalr9 wrote:
A list of measurements in increasing order is 4,5,6,8,10,x. If the median of these measurements is 6/7 times their arithmetic mean, What is the value of x?

A.16
B.15
C.14
D.13
E.12

This question was locked.

Given a list of measurements in increasing order is 4,5,6,8,10,x and then x is the greatest number in the list.

Median = (6+8)/2 ( since is even number of series)

AM = mean=(4+5+6+8+10+x)/6 = (33+x)/6

{(33+x) /6 }*6/7 =7

x=49-33=16.

Correction option is A.
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A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If  [#permalink]

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23 Jul 2016, 00:53
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udaymathapati wrote:
A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If the median of these measurements is 6/7 times their arithmetic mean, what is the value of x?

A. 16
B. 15
C. 14
D. 13
E. 12

Attachment:
Image1.JPG

Median of a set with even # of terms = Average of the middle two terms = $$\frac{(6+8)}{2} --->\frac{14}{2} ---> 7$$
Median is 7 ; Mean = $$\frac{(4+5+6+8+10+x)}{6}$$

Given that Median = $$\frac{6}{7}$$ of Mean

Median =$$\frac{6}{7}* \frac{(4+5+6+8+10+x)}{6}$$

$$7 = \frac{6}{7}* \frac{(4+5+6+8+10+x)}{6}$$

$$7=\frac{6}{7} * \frac{(33+x)}{6}$$

$$49=33+x$$

$$x=49-33$$$$x=16$$

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Re: A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If  [#permalink]

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26 Sep 2017, 16:34
udaymathapati wrote:
A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If the median of these measurements is 6/7 times their arithmetic mean, what is the value of x?

A. 16
B. 15
C. 14
D. 13
E. 12

We are given the following measurements in increasing order:

4, 5, 6, 8, 10, x

Let’s first calculate the mean:

average = sum/quantity

avg = (4 + 5 + 6 + 8 + 10 + x)/6

avg = (33 + x)/6

We also know that the median of the set is (6 + 8)/2 = 14/2 = 7

Since the the median of these measurements is 6/7 times the arithmetic mean, we can create the following equation:

(6/7)*[(33 + x)/6] = 7

6*(33 + x)/6 = 49

33 + x = 49

x = 16

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Re: A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If  [#permalink]

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# Problems from Relative positions of two circumferences in the plane

Given two circumferences $$C_1$$ and $$C_2$$ with given radius $$r_1 = 2$$ cm and $$r_2 = 10$$ cm, what is the relative position between $$C_1$$ and $$C_2$$ where the radius is given and the distance between the centers $$d$$ is given?

1. $$d = 0$$ cm
2. $$d = 9$$ cm
3. $$d = 8$$ cm
4. $$d = 13$$ cm
5. $$d = 12$$ cm
See development and solution

### Development:

Note: to resolve this exercise, it is very fortuitous to take paper and pencil and draw a picture of each case to see the solution clearly.

1. Distance between centers is $$0$$, and the radiuses are different, so these are inside concentric circles.
2. Distance between centers is $$9$$ so, as the radius of $$C_1$$ is $$2$$, the circumferences are secant.
3. Distance between centers is $$8$$ so, as the radius of $$C_1$$ is $$2$$, circumferences are internally tangent.
4. $$13$$ cm is greater than the sum of both radiuses, so they are external.
5. $$12$$ cm distance is equal to the sum of the two radiuses, so they are tangent interiors.

### Solution:

1. internally concentric
2. secants
3. interior tangents
4. external
5. internal tangents
Hide solution and development