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Best Time to buy a stock in a day 
You want to buy when the stock market is at an all-time low for that day. Unfortunately, you don't know the lowest time until the end of the day, and then you, uh can't buy the stock... Now the stock market is not random, but for your case, we can say that effectively, it is. So, when should you buy the stock to hopefully get the lowest price for the day? You should wait for 37% of the day, and then buy when it is lower than it has been for all of that day. Here is a quick example (with fake data): We have 18 points, and 37% of 18 is close to 7. So we discard the first 7 points - and just remember the lowest of those 7. We bear in mind that the lowest for the first 37% was 5. Now we wait until we find a stock which is lower than 5, and we buy at that point: This system is optimal for buying the stock at the lowest price for the day. Why? We want to find the  best position to stop automatically ignoring. Why 37%? We know the answer to P(Being in position n) - it's 1/N as there are N toilets, and we can select just 1. Now, what is the chance we select them, given we're in position n? The chance of selecting any of the toilets from 0 to K is 0 - remember we're never going to buy then. So let's move on to the toilets from K+1 and onwards. If K+1 is better than all before it, we have this: But, K+1 might not be the best price from all past and future prices. Maybe K+2 is better. Let's look at K+2 For K+2 we have K/K+1, for K+3 we have K/K+2... So we have: This is a close approximation of the area under 1/x - especially as x → ∞   So 0 + 0 + ... + (K/N) x (1/K + 1/K+1 + 1/K+2 ... + 1/N-1) ≈ (K/N) x ln(N/K) and so P(K) ≈ (K/N) x ln(N/K) Now to simplify, say that x = K/N We can graph this, and find the maximum point so we know the maximum P(K) - or we can use calculus. Here's the graph:  Here's the calculus: To apply this back to your situation with the stocks, if your stock updates every 30 seconds, and is open between 09:30 and 16:00, we have 6.5 hours = 390 minutes = 780 refreshes. You should keep track of the lowest price for the first 289 refreshes, and then buy your stock on the next best price. Because x = K/N, the chance of you choosing the best price is 37%. However, the chance of you choosing better than the average stock is above 50% for the day. Remember, this method just tries to mean you don't loose money within the day - if you want to try to minimise losses within the whole trading period, you should scale this up, so you wait 37% of the trading period (e.g. 37% of 3 months) and then select. The maths is taken from Numberphile - Mathematical Way to Choose a Toilet. Finally, one way to lose money a little slower and do some good is with Kiva.org - giving loans to people is developing countries. It's like a bank account with a -1% interest - which is only 1% lower than a lot of banks, and you do some good. I have no affiliation with them.